四川省成都市五校2013-2014学年高二下学期期中联考 物理 Word版含答案

合集下载

四川省成都市五校2013-2014学年高二下学期期中联考 化学 Word版含答案

四川省成都市五校2013-2014学年高二下学期期中联考 化学 Word版含答案

成都市“五校联考”高2012级第四学期期中试题化 学I 卷(42分)一、选择题(下列各题只有一个选项合乎题意)1.化学与生产、生活密切相关,下列叙述不正确的是( )A. 食品保鲜膜按材质分为聚乙烯、聚氯乙烯,它们都属于链状高分子,受热易熔化B. 食用植物油的重要成分是高级不饱和脂肪酸甘油酯,是人体的营养物质C. 人造纤维、合成纤维和光导纤维都是有机高分子化合物,符合C n (H 2O)m 的组成D. 控制含磷洗涤剂的使用,为了防止水体富营养化,保护水资源2.有关下列叙述不正确..的是 A . 纤维素、蔗糖、葡萄糖和脂肪在一定条件下都可发生水解反应B .干馏煤可以得到甲烷、苯和氨等重要化工原料C .用于奥运“祥云”火炬的丙烷是一种清洁燃料D .油脂的皂化反应生成高级脂肪酸钠和丙三醇3.已知反应4NH3+5O 24NO +6H 2O ,若在反应开始后5s~10s 之间的反应速率分别用v (NH 3)、v (O 2)、v (NO)、v (H 2O)表示,则下列判断正确的关系是( )。

A.45v (NH 3)=v (O 2)B.56v (O 2)=v (H 2O)C.23v (NH 3)=v (H 2O)D.45v (O 2)=v (NO)4.氯原子对O 3的分解有催化作用:O 3+Cl===ClO +O 2 ΔH 1,ClO +O===Cl +O 2 ΔH 2。

大气臭氧层的分解反应是:O 3+O===2O 2 ΔH ,该反应的能量变化如图所示,则下列叙述正确的是( )。

①反应O3+O===2O 2的ΔH =E 1-E 3 ②反应O 3+O===2O 2是放热反应 ③ΔH =ΔH 1+ΔH 2 ④大气层中的臭氧无法再生A .①②B .②③ C.③④ D.②④5.为检验某卤代烃(R -X)中的X 元素,采用下列实验操作:①加热煮沸 ②加入AgNO 3溶液 ③取少量卤代烃 ④加入稀硝酸酸化 ⑤加入NaOH 溶液 ⑥冷却。

四川省成都市五校2013-2014学年高二下学期期中联考生物试题

四川省成都市五校2013-2014学年高二下学期期中联考生物试题

成都市“六校联考”高2012级第四学期期中试题生物(全卷满分:90分)第Ⅰ卷一、选择题 (每题6分,共42分,每题一个正确答案)1.下列关于细胞知识的叙述,不正确的是()①硝化细菌、霉菌、颤藻的细胞都含有核糖体、DNA和RNA②细胞学说揭示了“细胞为什么要产生新细胞”③柳树成熟的筛管细胞中的细胞核和线粒体均能发生碱基互补配对现象④草履虫可遗传变异只有基因突变⑤蛙红细胞、人肝细胞、洋葱根尖分生区细胞并不都有细胞周期,但这些细胞内的化学成分都不断更新A.①③④ B.②④⑤ C.②③④ D.②③⑤2. 汉堡包是现代西式快餐中的主要食物,已经成为畅销世界的方便食物之一。

制作的原料有鸡胸肉、面包、鸡蛋、生菜等。

下列说法正确的是( )A.面包中含有的淀粉不能作为植物细胞的储能物质B.生菜中含有的纤维素能够被人类吸收利用C.鸡蛋中含有的蛋白质可直接承担人体的生命活动D.鸡胸肉中含有的糖原是动物细胞的储能物质3.下列有关细菌培养的叙述,正确的是( )A.在琼脂固体培养基上长出的单个菌落含有多种细菌B.在培养基中加入青霉素可抑制真菌而促进细菌生长C.向液体培养基中通入氧气能促进破伤风杆菌的生长D.在以尿素为唯一氮源的培养基中加入酚红指示剂可以初步鉴定细菌能否分解尿素。

4.下列关于果酒和果醋的制作原理、发酵过程的叙述中,错误的是( )A.果酒和果醋的发酵菌种不同,但代谢类型相同B. 当糖源不足时, 醋酸菌先将酒精转变成乙醛, 再将乙醛变为醋酸C.变酸果酒的表面观察到的菌膜可能是醋酸菌的菌落D.果酒和果醋的制作可用同一装置,但需控制不同发酵条件5.关于核酸的叙述,正确的是( )A.只有细胞内的核酸才是携带遗传信息的物质B.DNA分子中两条脱氧核苷酸链之间的碱基一定是通过氢键连接的C.分子大小相同、碱基含量相同的核酸分子所携带的遗传信息一定相同D.大肠杆菌同时含有RNA和DNA,组成其遗传物质的核苷酸有8种6. 关于果胶酶的说法正确的是()A.果胶酶可以分解细胞壁的主要纤维素B.果胶酶是由半乳糖醛酸聚合而成的一种高分子化合物C.果胶酶不特指某酶,而是分解果胶的一类酶的总称D.果胶酶的化学本质是蛋白质或RNA7.下列有关胡萝卜素的叙述,错误的是 ( )A.胡萝卜素的化学性质稳定,溶于水,不溶于乙醇B.胡萝卜是提取天然β­胡萝卜素的原料C.微生物的发酵生产是工业提取β­胡萝卜素的方法之一D.提取后,干燥过程中,时间不能太长,温度不能太高第Ⅱ卷二、非选择题(共48分)1、(11分,,除标注外,其余每空1)回答下列有关植物组织培养的问题。

13-14学年第一学期五校联考_高二物理试题

13-14学年第一学期五校联考_高二物理试题

2013—2014学年度第一学期期末模块考试五校联考高二年级物理科试题 2013年12月试题说明:本试卷分选择题和非选择题两部分,满分为100分,考试时间为90分钟。

第一部分 选择题(共48分)一、单项选择题:本题共8小题,每小题3分,共24分。

每小题给出的四个选项中,只有一个选 项最符合题目要求。

1.下列说法错误的是( ) A .元电荷e =1.6×10-19 CB .牛顿总结出磁场对运动电荷的作用力公式C .奥斯特发现通电导线周围存在磁场D .库仑通过实验研究确定了点电荷之间的作用规律2.在真空中有a 、b 两个点电荷,b 的电荷量是a 的3倍,如果a 受到的静电力是F ,则b 受到的静电力是 ( )A .FB .F /3C .3FD . 4F3.如图,在正点电荷Q 形成的电场中,在某点M 放入一电荷量为q 的正点电荷,P 受到的库仑力为F ,下列表述正确的是( )A .P 、Q 之间相互吸引B .若将P 移走,则M 点的电场强度为零C .若将P 移近Q ,则P 所受库仑力减小D .若只将P 的电荷量增大为2q ,则P 所受库仑力增大为2F4.如图所示,实线表示电场线,虚线表示只受电场力作用的带电粒子从M 点运动到N 点的轨迹,可以判定( )A .粒子带负电B .M 点的电势低于N 点的电势C .粒子在M 点受到的电场力大于在N 点受到的电场力D .粒子在M 点的动能小于在N 点的动能5.一束正离子沿x 轴正方向高速运动,如图所示,则正离子流产生的磁场在z 轴上的点P 处的方向是( )A .沿y 轴负方向B .沿y 轴正方向C .沿z 轴负方向D .沿z 轴正方向6.如图所示为两电阻R 1和R 2的伏安特性曲线。

两电阻串联后,在它们两端加一定的电压,下列说法正确的是 ( )A .通过电阻R 1的电流较大B .通过电阻R 2的电流较大C .电阻R 1的阻值较大D .电阻R 2的阻值较大7.下图中标出了磁场B 的方向、通电直导线中电流 I 的方向,以及通电直导线所受磁场力F的方Qa bDD∽ E r向,其中正确的是( )8.回旋加速器是加速带电粒子的装置,其主体部分是两个D 形金属盒,两金属盒处在垂直于盒底的匀强磁场中,a 、b 分别与高频交流电源两极相连接,下列说法正确的是( )A .离子从磁场中获得能量B .带电粒子的运动周期是变化的C .离子由加速器的中心附近进入加速器D .增大金属盒的半径,粒子射出时的动能不变二、双项选择题:本题共5小题,每小题4分,共20分。

四川省成都市五校协作体高二上学期期中考试物理试题 W

四川省成都市五校协作体高二上学期期中考试物理试题 W

成都市五校协作体2014-2015学年高二第一学期期中试题物 理(全卷满分:100分 完成时间:100分钟)一、选择题(本题包括8个小题,每小题3分,共24分,每小题只有一个选项符合题意)1.下列说法正确的是:( )A .只有体积很小的带电体才能看作点电荷B .电场强度是矢量,方向就是电荷在该点的受力方向C .电容器的电容跟它两极所加电压成反比,跟它所带电量成正比D .外电路断开时,电动势数值上等于电源两极的电压2.两个分别带有电荷量为-Q 和+3Q 的相同金属小球(均可视为点电荷),固定在相距为r 的两处,它们间库仑力的大小为F 。

两小球相互接触后将其固定距离变为2r,则两球间库仑力的大小( ) A .112F B .34F C .43F D .12F 3.三个点电荷电场的电场线分布如图所示,图中a 、b 两点处的场强大小分别为E a 、E b ,电势分别为a ϕ、b ϕ,则 ( ) A. E a >E b ,a ϕ<b ϕ B .E a <E b ,a ϕ<b ϕ C .E a >E b ,a ϕ>b ϕ D .E a <E b ,a ϕ>b ϕ4.如图所示,在A 板附近有一电子由静止开始向B 板运动,则关于电子到达了B 板时的速率,下列解释正确的是 ( )A .两板间距越大,加速的时间就越长,则获得的速率越大B .两板间距越小,加速度就越大,则获得的速率越大C .与两板间的距离无关,仅与加速电压U 有关D .以上解释都不正确5.平行板间加如图a 所示周期性变化的电压,重力不计的带电粒子静止在平行板中央,从t=0时刻开始将其释放,运动过程无碰板情况.图b 中,定性描述粒子运动的v-t 图象正确的是 ( )6.热敏电阻是传感电路中常用的电子元件,其电阻R 随温度t 变化的图线如图甲所示.如图乙所示电路中,热敏电阻R t 与其它电阻构成的闭合电路中,当R t 所在处温度升高时,两电表读数的变化情况是 ( )A .A 变大,V 变大B .A 变小,V 变小C.A变小,V变大D.A变大,V变小7.电流表的内阻足R g = 100Ω,满刻度电流值是I g= 1mA,现欲把这电流表改装成量程为3V的电压表,正确的方法是( )A.应串联一个2900Ω的电阻B.应并联一个0.1Ω的电阻C.应串联一个0.1Ω的电阻D.应并联一个2900Ω的电阻8.如图所示,实线表示电场线,虚线表示只受电场力作用的带电粒子的运动轨迹。

四川省成都市五校2013-2014学年高二下学期期中联考政治试题.pdf

四川省成都市五校2013-2014学年高二下学期期中联考政治试题.pdf

②具有创造性,能创造出独立于物质之外的精神 ③具有反作用,能对人体生理活动进行调节和控制 ④具有指导性
,能够将人们的愿望变成现实A.①② B.③④ C.①③ D.②④
4.2013年6月20日,中国首次太空授课活动成功举行,“神舟十号”航天员在“天空一号”展示了失重环境下的物
理现象。地面上的单摆运动在太空中竟然成为神奇的圆周运动,这表明①一定条件下人们可以突破客观规律的限制
本卷每小题4分,共48分。在每小题给出的四个选项中,只有一项是符合题目要求的。
1.2013年3月14日,欧洲核子研究中心宣布,在大型强子对撞机里发现的新粒子确系希格斯玻色子;4月3日,宣布
探测到多余的正电子;11月21日,冰立方中微子天文台首次发现了源自太阳系外的超高能中微子。这些科学发现共同佐
在结构化学等领域的研究又可更进一步,高中化学课本上的分子结构图旁,终于可以为化学键配上货真价实的“素颜照
”。这表明
①思维和存在具有同一性
②发展是一个事物对另一事物的否定
③认识工具延伸了人类的认识器官 ④实践是获得认识的唯一途径
A.①③ B.①④
C.②③
D.③④
6.建设“丝绸之路经济带’’要实现政策沟通、道路联通、贸易畅通、货币流通、民心相通,使我们欧亚各国经
C.要坚持辩证否定,勇于改革创新
D.要坚持一切从实际出发,实事求是
.小时候,幸福是一件实物;长大后,幸福是一种状态;今天,我发现,幸福既不是实物也不是状态,是一种领悟
。以下与这句话蕴含的哲理相同的是 A.古人学问无遗力,少壮功夫老始成 .蝉噪林愈静,鸟鸣山更幽
C.人病则忧惧,忧惧见鬼出 D.横看成岭侧成峰,远近高低各不同
五洋捉鳖”的豪言壮语,在今天已变为现实!在今天的中国,前瞻性研究尤为可贵。想获得准确的预测就要①运用发展

成都七中2013-2014学年高二下学期期中考试物理试题及答案试题

成都七中2013-2014学年高二下学期期中考试物理试题及答案试题

四川省成都七中2013-2014学年高二下学期期中考试物理试题第Ⅰ卷(42分)一.单项选择题(每题3分,共18分;每小题所给的四个选项中,只有一个选项符合题意)1.下列关于机械振动和机械波的说法正确的是()A.有机械波一定有机械振动,有机械振动一定有机械波B.机械波在介质中的传播速度由介质本身的性质决定,与频率无关C.纵波在波传播方向上的某个质点的振动速度和波的传播速度是一样的D.机械波发生干涉时,振动加强处的位移一定大于振动减弱处位移2.在电能的输送过程中,若输送的电功率一定、输电线电阻一定时,对于在输电线上损失的电功率,有如下四种判断,正确的是()A.和输送电压成正比B.和输送电线上的电流成正比C.和输送电线上的电压降成正比D.和输送电压的平方成反比3. 闭合线圈上方有一竖直放置的条形磁铁,磁铁的N极朝下。

当磁铁向下运动时(但未插入线圈内部),以下结论中正确的是()A.线圈中感应电流的方向与图中箭头方向相同,磁铁与线圈相互吸引B.线圈中感应电流的方向与图中箭头方向相同,磁铁与线圈相互排斥C.线圈中感应电流的方向与图中箭头方向相反,磁铁与线圈相互吸引D.线圈中感应电流的方向与图中箭头方向相反,磁铁与线圈相互排斥4.如图,(a)为一波源的共振曲线,(b)图中的a表示该波源的振动沿x轴传播过程中形成的机械波在t=0时刻的波形曲线。

则下列说法错误..的是()A.(a)图中,若驱动力周期变小共振动曲线的峰值将向频率f大的方向移动B.(b)图中,波速一定为1.2m/sC.(b)图中,a、b波形时间间隔可能为2.5sD.(b)图中的波遇到宽度为2m的狭缝能发生明显的衍射现象5.如图所示,理想变压器原、副线圈的匝数比为10:1,b是原线圈的中心抽头,电压表和电流表均为理想电表,从某时刻开始在原线圈c、d两端加上交变电压,其瞬时值表达式为u1=2202sin100πt(V),则()A. 当单刀双掷开关与a连接时,电压表的示数为222VB. 当单刀双掷开关由a拨到b后,原线圈的输入功率变为原来的4倍C. 单刀双掷开关与a连接,在滑动变阻器触头P向上移动的过程中,电压表和电流表的示数均变小D. 当单刀双掷开关由a拨向b时,电压表和电流表的示数均变小6.如图为小型旋转电枢式交流发电机的原理图,其矩形线圈在磁感应强度为B的匀强磁场中绕垂直于磁场方向的固定轴OO′匀速转动.磁场的磁感应强度B=1.0×10-2T,线圈的边长ab=20cm、bc=10cm,匝数n=400,线圈总电阻r=2.0Ω,线圈的两端经集流环和电刷与电阻R=18Ω连接,与电阻R并联的交流电压表为理想电表,线圈的转速n0=50r/s.在t=0时刻,线圈平面与磁场方向平行,则下列说法正确的是()A.交流发电机产生电动势随时间的变化关系是e=8πcos50t(V)B.交流电压表的示数为8πVC.从t=0时刻开始转过90°的过程中,通过电阻的电量为4.0×10-3CD.t=0时刻,通过线圈的磁通量为零,线圈中的感应电动势也为零二、不定项选择题(每小题所给的四个选项中,有的可能不止一个符合题意,每题全选正确得4分,漏选得2分,不选或有错得0分,共24分)7. 以下说法正确的是:()A.LC回路中线圈磁场能最大时,电容器两极板所带电荷量最少B.只要存在变化的电场就一定会产生电磁波C.雷达利用了X射线探测目标,因为X射线的波长更短,更利于直线传播D.发射电磁波时,把低频的声音、图像信号加载到高频电磁波上的过程叫调制8. 做课间操时,我校操场上的两个相隔30米的喇叭同时播放着相同的音乐,以下说法正确的是:()A.喇叭发出的声音是横波B. 坐在教室里的同学也能听到音乐,主要是因为声波发生衍射C. 如果在喇叭中持续播放某一频率的声音,根据波的干涉现象,我们可以判断,操场上有的地方听到的声音大,有的地方听到的声音小D. 当同学们跑向操场时, 因为没有发生多普勒效应, 所以听到的音乐不会有任何变化.9.如图所示交流电,下列说法正确的是()A.周期为0.02sB.有效值为200VC.将该电压加在交流电压表两端时,电压表读数为2002VD.将该交流电压加在起辉电压为150V的氖管上,氖管未被击穿,氖管1分钟发光次数为60次10.如图甲所示为一列沿水平方向传播的简谐横波在时刻t的波形图,如图乙所示为质点b 从时刻t开始计时的振动图象.若设振动正方向为沿+ y 轴方向,则下列说法中正确的是()A.该简谐横波沿x轴正方向传播B.该简谐横波波速为0.4 m/sC.在时刻t,质点a的加速度比质点b的大D .再经过2s ,质点a 随波迁移0.8 m11. 如图所示线圈在匀强磁场中绕垂直于磁场的轴匀速转动,电容器两极板水平放置.在两极板间,不计重力的带正电粒子Q 在t=0时由静止释放,若两板间距足够宽,则下列运动可能的是( )A.若t=0时,线圈平面与磁场垂直,粒子一定能到达极板B.若t=0时,线圈平面与磁场平行,粒子在两极间往复运动C.若t=0时,线圈平面与磁场垂直,粒子在两极间往复运动D.若t=0时,线圈平面与磁场平行,粒子一定能到达极板12. 如图所示,竖直放置的两根平行、光滑、无电阻金属导轨之间接有定值电阻R ,质量不能忽略的金属棒与两导轨始终保持垂直并良好接触且无摩擦,棒的电阻也为R ,整个装置放在匀强磁场内,磁场方向与导轨平面垂直,棒在竖直向上的恒力F 作用下加速上升的一段时间内,以下说法中正确的是 ( )A .力F 做的功与安培力做的功的代数和等于棒的机械能增加量B .力F 做的功与安培力做的功的代数和等于棒的动能增加量C .安培力做的功的大小等于金属棒上产生的焦耳热D .力F 做的功等于棒的机械能增加量与电路中总焦耳热的和第Ⅱ卷(68分)三.实验题(13题6分,14题8分,共14分)13、(1) 我校有五组同学用单摆测成都的重力加速度g ,各组实验器材和实验数据如下表所示,若各组同学实验操作水平一样,那么第 组同学测定的结果最准确。

四川省成都市20142015学年高二物理下学期期中试题

四川省成都市20142015学年高二物理下学期期中试题

成都七中实验学校高二半期考试物理试题考试时间:90分钟 总分:100分一.选择题( 4分/题 共48分 说明:1-6题为单选题;7-12题为不定项选择题) (一)单选题1.如图是同一地点两个不同单摆甲、乙的振动图像,下列说法中不正确的是( ).A .甲、乙两单摆的摆长相等B .甲摆的振幅比乙摆大C .甲摆的机械能比乙摆大D .在t = s 时,乙摆有最大正向的加速度2.如图所示是一个单摆做受迫振动时的共振曲线,表示振幅A 与驱动力的频率f 的关系,下列说法正确的是( )A .若增大摆长,共振曲线的“峰”将向右移动B .若改变摆长,共振曲线的“峰”将不会移动C .该单摆的摆长约为1 mD .若将该单摆移到月球上,其共振曲线的“峰”将向右移动3.如图所示,金属棒ab 置于水平放置的金属导体框架cdef 上,棒ab 与框架接触良好.从某一时刻开始,给这个空间施加一个斜向上的匀强磁场,并且磁场均匀增加,ab 棒仍静止,在磁场均匀增加的过程中,ab 棒受到的摩擦力,下列说法正确的是 ( )A .感应电流I 的流向沿aedba ,大小均匀增大B .ab 棒受到框架的支持力逐渐均匀减小C .ab 棒受到的摩擦力大小不变,方向向右D .ab 棒受到的摩擦力变大,方向向右4. 图中T 是绕有两组线圈的闭合铁心,线圈的绕向如图所示,D 是理想的二极管,金属棒ab 可在两条平行的金属导轨上沿导轨滑行,磁场方向垂直纸面向里。

若电流计G 中有电流通过,则ab 棒的运动可能是( )A .向左匀速运动B .向左匀减速运动C .向右匀减速运动D .向右匀速运动5.如图,图线a 是线圈在匀强磁场中匀速转动时所产生正弦交流电的图像,当调整线圈转速后,所产生正弦交流电的图像如图线b 所示。

以下关于这两个正弦交流电的说法正确的是 ( )A .在图中t =0时刻穿过线圈的磁通量均为零B .线圈先后两次转速之比为3∶2C .交流电a 的瞬时值表达式为u =5√2sin 5πt (V) 6. 如图为一理想变压器,原、副线圈的匝数比为n 。

四川省成都市六校协作体高二物理下学期期中联考试题

四川省成都市六校协作体高二物理下学期期中联考试题

成都市六校协作体高2013级第四学期期中试题物理(全卷满分:100分 完成时间:90分钟) 第Ⅰ卷(选择题,共 47 分) 一、(27分)选择题。

本大题共9小题,每小题3分。

每小题给出的四个答案中,只有一个是正确的。

把正确答案全选出来,用铅笔把答题卡上对应题目的答案标号涂黑。

1.一水平弹簧振子作简谐振动,周期为T ,则( )A .若t 时刻和t+△t 时刻振子位移大小相等,方向相同,则△t 一定等于T 的整数倍B .若t 时刻和t+△t 时刻振子位移大小相等,方向相反,则△t 一定等于T/2的整数倍C .若△t=T ,则在t 时刻和t+△t 时刻振子运动的加速度一定相等D .若△t=T/2、则在t 时刻和t+△t 时刻时刻,弹簧的长度一定相等2.一个面积S=4×10-2m2、匝数N=102匝的线圈,放在匀强磁场中,磁场方向垂直线圈平面,磁场的磁感应强度B 随时间t 的变化规律如图所示.则 ( ) A .在开始2s 内穿过线圈磁通量的变化率等于8wb/sB .在开始2s 内穿过线圈磁通量的变化量等于零C .在开始2s 内线圈中产生的感应电动势等于8VD .在第3s 末线圈中产生的感应电动势为零3.矩形线圈在匀强磁场中匀速转动产生的电动势e-t 图像如图,则在( ) A .t1,t3时刻线圈通过中性面 B .t2,t4时刻线圈中磁通量最大C .t1,t3时刻线圈中磁通量变化率最大D .t2,t3时刻线圈平面与中性面垂直4.在张紧的绳子上挂了a 、b 、c 、d 四个单摆,摆长关系为Lc > Lb = Ld > La ,如图所示,先让d的是( )A .b 摆发生振动其余摆均不动B .所有的摆均以g L d2的周期振动C .所有的摆均以相同摆角振动D .a 、b 、c 中c 摆振动幅度最大5. 劲度系数为k 的轻弹簧竖直悬挂,在其下端挂一质量为m 的砝码,然后从弹簧原长处自静止释放砝码,不计摩擦阻力。

四川省成都七中2013-2014高二下学期期中考试物理试题(含答案解析)(2014.04)

四川省成都七中2013-2014高二下学期期中考试物理试题(含答案解析)(2014.04)

成都七中2013年~2014年学年度下期期中考试
高二物理试卷
考试时间:100分钟试题满分:110分命题人:高二物理备课组
第Ⅰ卷(42分)
一.单项选择题(每题3分,共18分;每小题所给的四个选项中,只有一个选项符合题意)
1.下列关于机械振动和机械波的说法正确的是()
A.有机械波一定有机械振动,有机械振动一定有机械波
B.机械波在介质中的传播速度由介质本身的性质决定,与频率无关
C.纵波在波传播方向上的某个质点的振动速度和波的传播速度是一样的
D.机械波发生干涉时,振动加强处的位移一定大于振动减弱处位移
2.在电能的输送过程中,若输送的电功率一定、输电线电阻一定时,对于在输电线上损失的电功率,有如下四种判断,正确的是()
A.和输送电压成正比
B.和输送电线上的电流成正比
C.和输送电线上的电压降成正比
D.和输送电压的平方成反比
3. 闭合线圈上方有一竖直放置的条形磁铁,磁铁的N极朝下。

当磁铁向下运动时(但未插入线圈内部),以下结论中正确的是()Array A.线圈中感应电流的方向与图中箭头方向相同,磁铁与线圈相互吸引
B.线圈中感应电流的方向与图中箭头方向相同,磁铁与线圈相互排斥
C.线圈中感应电流的方向与图中箭头方向相反,磁铁与线圈相互吸引
D.线圈中感应电流的方向与图中箭头方向相反,磁铁与线圈相互排斥
4.如图,(a)为一波源的共振曲线,(b)图中的a表示该波源的振动沿x轴传播过程中形成的机械波在t=0时刻的波形曲线。

则下列说法错误
..的是
第 1 页共11 页。

四川省成都市五校2013-2014学年高二下学期期中联考英语试题

四川省成都市五校2013-2014学年高二下学期期中联考英语试题

四川省成都市五校2013-2014学年高二下学期期中联考英语试题(全卷满分:150分完成时间:120分钟)第I卷(选择题共90分)第一部分英语知识运用(共两节,共40分)第一节单项填空(共10小题;每小题1分,共10分)1. -- I heard that you lost your wallet and your i-Phone.--- Oh,__________ !A.never mind B.that’s all right C.just my luck D.thank you2. I was blessed with a happy childhood, _____ most people would want to have.A. thatB. itC. the oneD. one3. At long last the child was found on top of _____ we call the museum of science and technology.A. whichB. thatC. whatD. where4. Although her disease her eyesight and forced her to leave the dance floor, she refuses to fall into self-pity.A. has affectedB. affectedC. affectsD. had affected5. ----He thinks that girls are smarter than boys when it comes to learning English.----But two years ago he thought_______.A. soB. otherwiseC. oppositeD. different6. Will was stupefied with exhaustion, and he _____ his head on the grass under one of the trees and slept, but he saw a cat acting strangely.A. should have liedB. ought to have layC. might have laidD. must have laid7. The new policy allows a couple to have a second birth _____either is an only child.A. thoughB. ifC. unlessD. until8. With our country entering an aging society, ______ the retirement age is probably unavoidable.A. having delayedB. delayingC. being delayedD. to be delayed9. This restaurant has an inviting, homelike atmosphere ___ many others are short of.A. whereB. whenC. thatD. what10. “I hope the dialogue,” said the spokesman, “______ between the two presidents next week will give us some active signals.A. makingB. to makeC. to be madeD. made第二节完形填空(共20小题,每小题1.5分,共30分)Music to My EarsRobby was 10 for his first piano lesson in my class. Much as he tried, he __11__ even the basic rhythm. However, he dutifully reviewed the pieces that I required.Over the months he tried and tried while I __12__ and encouraged him. At the end of each lesson he'd always say, "My mom's going to hear me play some day." __13__ it seemed hopeless.I only knew his mother from a __14__as she waited in her aged car to pick him up. Then one day Robby stopped coming. I was secretly __15__ that he stopped because of his lack of ability.Weeks later I informed the students, including Robby, of the coming recital(独奏). To my __16__, Robby asked me if he could be included. I told him he really did not qualify because he had __17__ out. He said his mom had been sick and unable to take him to lessons but he was still __18__ .“I've just got to play!" he __19__. Somet hing inside me let me allow him to.Then came the recital night. The gym was __20__ with parents. I put Robby up __21__, thinking that I could save his poor performance through my “curtain closer(谢幕).”The recital went off smoothly. Then Robby came up on stage. His clothes were wrinkled andhis hair was __22__. "Why didn't his mother at least make him comb his hair for this special night?" I thought.Robby pulled out the piano bench and began. I was not __23__ for what I heard next. His fingers were __24__ on the keys. Never had I heard Mozart played so well by people of his age. After he ended, everyone was __25__ their feet in wild applause.In __26__ I ran up on stage and put my arms around Robby. "I've never heard you play like that, Robby! How did you __27__ it?"Robby explained, "Well, Miss Hondorf…remember I told you my mom was sick? …__28__ she had cancer and passed away yesterday. She was born deaf, so tonight she could hear me play in heaven. I wanted to make it special."There wasn’t a __29__ e ye in the house. That night I felt he was the teacher and I was the pupil, for it was he who taught me the meaning of perseverance and __30__.11. A. had B. lacked C. showed D. got12. A. learned B. checked C. listened D. played13. A. And B. But C. So D. Or14. A. conversation B. performance C. distance D. picture15. A. guilty B. anxious C. glad D. sad16. A. surprise B. relief C. pleasure D. satisfaction17. A. stepped B. worn C. run D. dropped18. A. acting B. practicing C. performing D. recording19. A. insisted B. suggested C. complained D. threatened20. A. packed B. lined C. piled D. covered21. A. least B. most C. first D. last22. A. cool B. messy C. neat D. dull23. A. eager B. concerned C. prepared D. grateful24. A. hesitating B. crawling C. touching D. dancing25. A. over B. under C. in D. on26. A. chaos B. return C. silence D. tears27. A. find B. feel C. make D. like28. A. Gradually B. Suddenly C. Frequently D. Actually29. A. bright B. curious C. dry D. wet30. A. love B. talent C. regret D. courage第二部分阅读理解(共两节,共50分)第一节阅读理解(共20小题;每小题2分,共40分)ADreams can be familiar and strange, fantastical or boring, but some dreams might be connected to the mental processes that help us learn. In a recent study, scientists found a connection between nap-time dreams and better memory in people who were learning a new skill.In the study,99 college students between the ages of 18 and 30 each spent an hour on a compute, trying to get through a virtual maze(迷宫).The maze was different place each time they tired—making it even more difficult. They were also told to find a particular picture of a tree and remember where it was.For the first 90 minutes of a five-hour break, half of the participants stayed awake and an half were told to take a short nap .Participants who stayed awake were asked to describe their thoughts. Participants who took a nap were asked about their dreams before sleep and after sleep—and they were awakened within a minute of sleep to describe their dreams.Stickgold, a neuroscientist(神经科学家),wanted to know what people were dreaming about when their eyes weren't moving during sleep.Four of the 50 people who slept said their dreams were connected to the maze. Some dreamedabout the music that had been playing when they were working ; others said they dreamed about seeing people in the maze. When these four people tried the computer maze again, they were able to find the tree faster than before their naps.Stickgold suggests the dream itself doesn‘t help a person learn—it's the other way around.He suspects that the dream was caused by the brain processes associated with learning.All four of the people who dreamed about the task had done poorly the first time, which makes Stickgold wonder if the dreams show up when a person finds a new task particularly difficult. People who had other dreams, or people who didn't take a nap, didn't show the same improvement.31. Before having a short nap, participants of the experiment were asked to .A. stay in a different place in the mazeB. design a virtual maze which is difficult to get throughC. experience the experiment and try to remember somethingD. get through a virtual maze on a computer from the same place32. What can we learn from the text?A. Participants who took a nap were required to express their thoughts.B. Some dreams may encourage people to invent something new.C. Participants who dreamed about films could finish the task more easily.D. Participants whose dreams had something to do with the maze could findthe tree faster.33. According to Stickgold, .A. every person may dream about what they learnedB. people's brain processes may still be connected with their learningin their dreamsC. once people's eyes stop moving, they are sure to dream about somethingD. no matter how fantastical or boring, dreams are connected with people's life34.What is the best title for this text?A. Dreams Are StrangeB. Not All Dreams Are TrueC. Dreaming Makes PerfectD. Stickgold, a Dream ExpertBFarmers, especially in developing countries, are often criticized for cutting down forests. But a new study suggests that many farmers recognize the value of keeping trees.Researchers using satellite images found at least ten percent tree cover on more than one billion hectares of farmland. That is almost half the farmland in the world. Earlier estimates were much lower but incomplete. The authors of the new study say it may still underestimate the true extent worldwide.The study found the most tree cover in South America. Next comes Africa south of the Sahara, followed by Southeast Asia. North Africa and West Asia have the least.The study found that climate conditions alone could not explain the amount of tree cover in different areas. Nor could the size of nearby populations, meaning people and trees can live together. There are areas with few trees but also few people, and areas with many trees and many people. The findings suggest that things like land rights, markets or government policies can influence tree planting and protection.Dennis Garrity, who heads the World Agroforestry Center, says farmers are acting on their own to protect and plant trees. The problem, he says, is that policy makers and planners have been slow to recognize this and to support such efforts.The satellite images may not show what the farmers are using the trees for, but trees provide nuts, fruit, wood and other products. They also help prevent soil loss and protect water supplies. Even under drought(干旱)conditions, trees can often provide food and a way to earn money until the next growing season.Some trees act as natural fertilizers. They take nitrogen(氮气)out of the air and put it in the soil. Scientists at the Center say the use of fertilizer trees can re-duce the need for chemical nitrogen by up to three-fourths. Trees also capture carbon dioxide, a gas linked to climate change.35. Through the study, the researchers found that .A. there are more trees on farmlands than expectedB. fewer trees are being cut in developing countriesC. most farmers still don’t realize the value of treesD. trees play a key role in preventing climate change36. Which of the following has the least tree cover?A. Southeast AsiaB. West Asia.C. South America.D. Africa south of the Sahara.37. In Dennis Garrity’s opinion, .A. most farmers care about nothing but their own interestsB. there are usually few people living in areas with few treesC. government plays a small role in tree planting and protectionD. government should support farmers in planting and protecting trees38. The sixth paragraph mainly tells about .A. how farmers plant treesB. what products trees can bringC. the importance of trees to farmersD. the environmental value of tree coverCNuclear power’s danger to health, safety, and even life itself can be summed up in one word radiation.Nuclear radiation has a certain mystery about it, partly because it cannot be detected by human senses. It can’t be seen or heard, or touched or tasted, even though it may be all around us. There are other things like that. For example, radio waves are all around us but we can’t detect them, sense them, without a radio receiver. Similarly, we can’t sense rad ioactivity without a radiation detector. But unlike common radio waves, nuclear radiation is not harmless to human beings and other living things.At very high levels, radiation can kill an animal or human being immediately by killing masses of cells in vital organs. But even the lowest levels can do serious damage. There is no levels of radiation that is completely safe. If the radiation does not hit anything important, the damage may not be serious. This is the case when only a few cells are hit, and if they are killed immediately, your body will replace the dead cells with healthy ones. But if the few cells are only damaged, and if they reproduce themselves, you may be in trouble. They can grow into cancer. Sometimes this does not show up for many years.This is another reason for some of the mystery about nuclear radiation. Serious damage can be done without the victim being aware at the time that damage has occurred. A person can be irradiated(辐射)and feel fine, then die for cancer five, ten, or twenty years later as a result. Or a child can be born weak as a result of radiation absorbed by its grandparents.Radiation can hurt us. We must know the truth.39. What is the main idea of the passage?A. How to detect nuclear radiation.B. How radiation kill a man.C. The mystery about nuclear radiation.D. Serious damage caused by nuclear radiation.40. Which of the following statements is true?A. Nuclear radiation can cause cancer to human beings.B. Nuclear radiation can be safe to human beings if its level is low.C. Nuclear radiation can be detected by human senses.D. Nuclear radiation is just like common radio waves.41. What is not the reason why nuclear radiation has a certain mystery?A. The hurt cells can stay in the body many years and then grow into cancer.B. It can do harm to a person while the victim isn't aware the damagehas occurred.C. Nuclear radiation can kill a person very easily.D. Radiation can seldom kill a person immediately.42. If a human being is hit by nuclear radiation, he may _______.A. die of cancer after many yearsB. die immediatelyC. have a child who may be born weakD. all of the aboveDFrom good reading we can derive pleasure, companionship, experience, and instruction. A good book may absorb our attention so completely that for the time being we forget our surroundings and even our identity. Reading good books is one of the greatest pleasures in life. It increases our contentment when we are cheerful, and lessens our troubles when we are sad. Whatever may be our main purpose in reading, our contact with good books should never fail to give us enjoyment and satisfaction.With a good book in our hands we need never be lonely. Whether the characters portrayed are taken from real life or are purely imaginary, they may become our companions and friends. In the pages of books we can walk with the wise and the good of all lands and all times. The people we meet in books may delight us either because they resemble human friends whom we hold dear or because they present unfamiliar types whom we are glad to welcome as new acquaintances. Our human friends sometimes may bore us, but the friends we make in books need never weary us with their company. By turning the page we can dismiss them without any fear of hurting their feelings. When human friends desert us, good books are always ready to give us friendship, sympathy, and encouragement.One of the most valuable gifts bestowed by books is experience. Few of us can travel far from home or have a wide range of experiences, but all of us can lead varied lives through the pages of books. Whether we wish to escape from the seemingly dull realities of everyday life or whether we long to visit some far-off place, a book will help us when nothing else can. To travel by book we need no bank account to pay our way; no airship or ocean liner or stream-lined train to transport us; no passport to enter the land of our heart's desire. Through books we may get the thrill of hazardous adventure without danger. We can climb lofty mountains, brave the perils of an Antarctic winter, or cross the scorching sands of the desert, all without hardship. In books we may visit the studios of Hollywood; we may mingle with the gay throngs of the Paris boulevards; we may join the picturesque peasants in an Alpine village or the kindly natives on a South Sea island. Indeed, through books the whole world is ours for the asking. The possibilities of our literary experiences are almost unlimited. The beauties of nature, the enjoyment of music, the treasures of art, the triumphs of architecture, the marvels of engineering, are all open to the wonder and enjoyment of those who read.43. Why is it that we sometimes forget our surroundings and even our identity while reading?A. No one has come to disturb you.B. The book you are reading is so interesting and attractive.C. Everything is so quiet and calm around you.D. Your book is overdue; you are finishing it at a very fast speed.44. How would you account for the fact that people like their acquaintances in books even more?A. They resemble human friends exactly.B. They are unfamiliar types we like.C. They never desert us.D. They never hurt our feelings.45. Which of the following is true?A. Your wish to visit some far-off place can be realized through the pages of the books.B. To escape from the dull realities of everyday life you should take up reading.C. You may obtain valuable experience from reading good books.D. Books can always help you to live a colorful life.46. The word “weary” means ______.A. “to attract someone’s attention”B. “to distract someone’s attention”C. “to make someone interested”D. “to make someone very tired”EHave you ever picked a job based on the fact that you were good at it but later found it made you feel very uncomfortable over time? When you select your career, there's a whole lot more to it than assessing your skills and matching them with a particular position. If you ignore your personality, it will hurt you long-term regardless of your skills or the job's pay. There are several areas of your personality that you need to consider to help you find a good job. Here are a few of those main areas;1) Do you prefer working alone or with other people?There are isolating(使孤立)jobs that will drive an outgoing person crazy and also interactive jobs that will make a shy person uneasy. Most people are not extremes in either direction but do have a tendency that they prefer. There are also positions that are sometimes a combination of the two, which may be best for someone in the middle who adapts easily to either situation.2) How do you handle change?Most jobs these days have some elements of change to them, but some are more than others. If you need stability in your life, you may need a job where the changes don't happen so often. Other people would be bored of the same daily routine.3) Do you enjoy working with computers?I do see this as a kind of personality characteristic. There are people who are happy to spend more than 40 hours a week on a computer, while there are others who need a lot of human interaction throughout the day. Again, these are extremes and you'll likely find a lot of positions somewhere in the middle as well.4) What type of work environment do you enjoy?This can range from being in a large building with a lot of people you won't know immediately to a smaller setting where you'll get to know almost all the people there fairly quickly.5) How do you like to get paid?Some people are motivated by the pay they get, while others feel too stressed to be like that. The variety of payment designs in the sales industry is a typical example for this.Anyway, these are a great starting point for you. I've seen it over and over again with people that they make more money over time when they do something they love. It may take you a little longer, but making a move to do what you have a passion for can change the course of your life for the better.47. Which of the following is TRUE according to the passage?A. Isolating jobs usually drive people mad.B. Almost everyone has a tendency in jobs.C. Interactive jobs make people shy easily.D. Extreme people tend to work with others.48. What does the underlined sentence in paragraph one mean?A. Before you select your job, you should assess your skills and match them withyour positionB . You should ignore your skills when you select job.C. Nothing is important than assessing skills and match them with the positionwhen you select job.D. There are more important things than assessing skills and match them with theposition when you select job.49. What is the missing word about a job search in the following chart?A. Design.B. Changes.C. Cooperation.D. Hobbies.A. Lifestyles and Job PayB. Jobs and EnvironmentC. Personalities and JobsD. Job Skills and Abilities第二节根据对话内容,从对话后的选项中选出能填入空白处的最佳选项,并在答题卡上将该项涂黑。

【物理】四川省成都树德中学2013-2014学年高二下学期期中考试试题

【物理】四川省成都树德中学2013-2014学年高二下学期期中考试试题

高2012级第四学期期中考试物理试题(考试时间:120分钟,总分:150分)一、不定项选择题(本题包括12小题,共60分;全对得5分,选不全得3分)1.下列关于电磁场的说法中,正确的是A.法拉第首先提出了场的概念,麦克斯韦建立了系统的电磁场理论B.电荷之间的相互作用都是通过电场发生的C.变化的电场一定在其周围产生变化的磁场D.变化的磁场可以在其周围产生匀强电场【答案】ABD【解析】A、为了解释电磁感应现象,法拉第提出“力线”和“场”的概念,认为电和磁的作用必须通过某种物质媒介——以太,这在人们面前展示出物质实体在间断的粒子存在形式之外还存在着连续的“场”的形式。

麦克斯韦在法拉第和W.汤姆生的研究基础上,以深邃的洞察力前后历程达十余年开创了物理学的新领域——创建电磁场理论,故A正确;B、每个电荷在其周围都会产生电场,电荷之间的相互作用都是通过电场发生的,故B正确;CD、根据麦克斯韦电磁场理论,变化的电场产生磁场,变化的磁场产生电场,均匀变化的电场产生恒定的磁场,均匀变化的磁场产生恒定的电场,故C错误D正确。

故选ABD。

【考点】物理学史2.如图所示为置于成都地区的某单摆的共振曲线,则A.该单摆做受迫振动的周期一定等于2sB.该单摆的摆长约为1mC.单摆做简谐运动时的回复力一定不等于合外力D.单摆悬挂在静止的电梯中自由振动时,若电梯突然自由下落,则单摆必相对于电梯静止【答案】B【解析】A、受迫振动的频率等于驱动力的频率;单摆做受迫振动的周期等于驱动力的周期,不一定等于2s,故A错误;B、由单摆的共振曲线可知,当驱动力频率为0.5Hz时单摆产生了共振现象,则单摆的固有频率即为0.5Hz,固有周期为T=2s,摆长22gTL1m4π≈=,故B正确;C、单摆做简谐运动时的回复力在最大位移处等于合外力,故C错误;D、单摆悬挂在静止的电梯中自由振动时,若电梯突然自由下落,则单摆可能相对于电梯静止,也可能相对于电梯做匀速圆周运动,故D错误;故选B。

四川省成都市五校2013-2014学年高二下学期期中联考 英语 Word版含答案

四川省成都市五校2013-2014学年高二下学期期中联考 英语 Word版含答案

成都市“五校联考”高2012级第四学期期中试题英语(全卷满分:150分完成时间:120分钟)第I卷(选择题共90分)第一部分英语知识运用(共两节,共40分)第一节单项填空(共10小题;每小题1分,共10分)1. -- I heard that you lost your wallet and your i-Phone.--- Oh,__________ !A.never mind B.that’s all right C.just my luck D.thank you2. I was blessed with a happy childhood, _____ most people would want to have.A. thatB. itC. the oneD. one3. At long last the child was found on top of _____ we call the museum of science and technology.A. whichB. thatC. whatD. where4. Although her disease her eyesight and forced her to leave the dance floor, she refuses to fall into self-pity.A. has affectedB. affectedC. affectsD. had affected5. ----He thinks that girls are smarter than boys when it comes to learning English.----But two years ago he thought_______.A. soB. otherwiseC. oppositeD. different6. Will was stupefied with exhaustion, and he _____ his head on the grass under one of the trees and slept, but he saw a cat acting strangely.A. should have liedB. ought to have layC. might have laidD. must have laid7. The new policy allows a couple to have a second birth _____either is an only child.A. thoughB. ifC. unlessD. until8. With our country entering an aging society, ______ the retirement age is probably unavoidable.A. having delayedB. delayingC. being delayedD. to be delayed9. This restaurant has an inviting, homelike atmosphere ___ many others are short of.A. whereB. whenC. thatD. what10. “I hope the dialogue,” said the spokesman, “______ between the two presidents next week will give us some active signals.A. makingB. to makeC. to be madeD. made第二节完形填空(共20小题,每小题1.5分,共30分)Music to My EarsRobby was 10 for his first piano lesson in my class. Much as he tried, he __11__ even the basic rhythm. However, he dutifully reviewed the pieces that I required.Over the months he tried and tried while I __12__ and encouraged him. At the end of each lesson he'd always say, "My mom's going to hear me play some day." __13__ it seemed hopeless.I only knew his mother from a __14__as she waited in her aged car to pick him up. Then one day Robby stopped coming. I was secretly __15__ that he stopped because of his lack of ability.Weeks later I informed the students, including Robby, of the coming recital(独奏). To my __16__, Robby asked me if he could be included. I told him he really did not qualify because he had __17__ out. He said his mom had been sick and unable to take him to lessons but he was still __18__ .“I've just got to play!" he __19__. Somet hing inside me let me allow him to.Then came the recital night. The gym was __20__ with parents. I put Robby up __21__, thinking that I could save his poor performance through my “curtain closer(谢幕).”The recital went off smoothly. Then Robby came up on stage. His clothes were wrinkled and his hair was __22__. "Why didn't his mother at least make him comb his hair for this special night?"I thought.Robby pulled out the piano bench and began. I was not __23__ for what I heard next. His fingers were __24__ on the keys. Never had I heard Mozart played so well by people of his age. After he ended, everyone was __25__ their feet in wild applause.In __26__ I ran up on stage and put my arms around Robby. "I've never heard you play like that, Robby! How did you __27__ it?"Robby explained, "Well, Miss Hondorf…remember I told you my mom was sick? …__28__ she had cancer and passed away yesterday. She was born deaf, so tonight she could hear me play in heaven. I wanted to make it special."There wasn’t a __29__ e ye in the house. That night I felt he was the teacher and I was the pupil, for it was he who taught me the meaning of perseverance and __30__.11. A. had B. lacked C. showed D. got12. A. learned B. checked C. listened D. played13. A. And B. But C. So D. Or14. A. conversation B. performance C. distance D. picture15. A. guilty B. anxious C. glad D. sad16. A. surprise B. relief C. pleasure D. satisfaction17. A. stepped B. worn C. run D. dropped18. A. acting B. practicing C. performing D. recording19. A. insisted B. suggested C. complained D. threatened20. A. packed B. lined C. piled D. covered21. A. least B. most C. first D. last22. A. cool B. messy C. neat D. dull23. A. eager B. concerned C. prepared D. grateful24. A. hesitating B. crawling C. touching D. dancing25. A. over B. under C. in D. on26. A. chaos B. return C. silence D. tears27. A. find B. feel C. make D. like28. A. Gradually B. Suddenly C. Frequently D. Actually29. A. bright B. curious C. dry D. wet30. A. love B. talent C. regret D. courage第二部分阅读理解(共两节,共50分)第一节阅读理解(共20小题;每小题2分,共40分)ADreams can be familiar and strange, fantastical or boring, but some dreams might be connected to the mental processes that help us learn. In a recent study, scientists found a connection between nap-time dreams and better memory in people who were learning a new skill.In the study,99 college students between the ages of 18 and 30 each spent an hour on a compute, trying to get through a virtual maze(迷宫).The maze was different place each time they tired—making it even more difficult. They were also told to find a particular picture of a tree and remember where it was.For the first 90 minutes of a five-hour break, half of the participants stayed awake and an half were told to take a short nap .Participants who stayed awake were asked to describe their thoughts. Participants who took a nap were asked about their dreams before sleep and after sleep—and they were awakened within a minute of sleep to describe their dreams.Stickgold, a neuroscientist(神经科学家),wanted to know what people were dreaming about when their eyes weren't moving during sleep.Four of the 50 people who slept said their dreams were connected to the maze. Some dreamed about the music that had been playing when they were working ; others said they dreamed about seeing people in the maze. When these four people tried the computer maze again, they were able to find the tree faster than before their naps.Stickgold suggests the dream itself doesn‘t help a person learn—it's the other way around.He suspects that the dream was caused by the brain processes associated with learning.All four of the people who dreamed about the task had done poorly the first time, which makes Stickgold wonder if the dreams show up when a person finds a new task particularly difficult. People who had other dreams, or people who didn't take a nap, didn't show the same improvement.31. Before having a short nap, participants of the experiment were asked to .A. stay in a different place in the mazeB. design a virtual maze which is difficult to get throughC. experience the experiment and try to remember somethingD. get through a virtual maze on a computer from the same place32. What can we learn from the text?A. Participants who took a nap were required to express their thoughts.B. Some dreams may encourage people to invent something new.C. Participants who dreamed about films could finish the task more easily.D. Participants whose dreams had something to do with the maze could findthe tree faster.33. According to Stickgold, .A. every person may dream about what they learnedB. people's brain processes may still be connected with their learningin their dreamsC. once people's eyes stop moving, they are sure to dream about somethingD. no matter how fantastical or boring, dreams are connected with people's life34.What is the best title for this text?A. Dreams Are StrangeB. Not All Dreams Are TrueC. Dreaming Makes PerfectD. Stickgold, a Dream ExpertBFarmers, especially in developing countries, are often criticized for cutting down forests. But a new study suggests that many farmers recognize the value of keeping trees.Researchers using satellite images found at least ten percent tree cover on more than one billion hectares of farmland. That is almost half the farmland in the world. Earlier estimates were much lower but incomplete. The authors of the new study say it may still underestimate the true extent worldwide.The study found the most tree cover in South America. Next comes Africa south of the Sahara, followed by Southeast Asia. North Africa and West Asia have the least.The study found that climate conditions alone could not explain the amount of tree cover in different areas. Nor could the size of nearby populations, meaning people and trees can live together. There are areas with few trees but also few people, and areas with many trees and many people. The findings suggest that things like land rights, markets or government policies can influence tree planting and protection.Dennis Garrity, who heads the World Agroforestry Center, says farmers are acting on their own to protect and plant trees. The problem, he says, is that policy makers and planners have been slow to recognize this and to support such efforts.The satellite images may not show what the farmers are using the trees for, but trees provide nuts, fruit, wood and other products. They also help prevent soil loss and protect water supplies. Even under drought(干旱)conditions, trees can often provide food and a way to earn money until the next growing season.Some trees act as natural fertilizers. They take nitrogen(氮气)out of the air and put it in the soil. Scientists at the Center say the use of fertilizer trees can re-duce the need for chemical nitrogen by up to three-fourths. Trees also capture carbon dioxide, a gas linked to climate change.35. Through the study, the researchers found that .A. there are more trees on farmlands than expectedB. fewer trees are being cut in developing countriesC. most farmers still don’t realize the value of treesD. trees play a key role in preventing climate change36. Which of the following has the least tree cover?A. Southeast AsiaB. West Asia.C. South America.D. Africa south of the Sahara.37. In Dennis Garrity’s opinion, .A. most farmers care about nothing but their own interestsB. there are usually few people living in areas with few treesC. government plays a small role in tree planting and protectionD. government should support farmers in planting and protecting trees38. The sixth paragraph mainly tells about .A. how farmers plant treesB. what products trees can bringC. the importance of trees to farmersD. the environmental value of tree coverCNuclear power’s danger to health, safety, and even life itself can be summed up in one word: radiation.Nuclear radiation has a certain mystery about it, partly because it cannot be detected by human senses. It can’t be seen or heard, or touched or tasted, even though it may be all around us. There are other things like that. For example, radio waves are all around us but we can’t detect them, sense them, without a radio receiver. Similarly, we can’t sense ra dioactivity without a radiation detector. But unlike common radio waves, nuclear radiation is not harmless to human beings and other living things.At very high levels, radiation can kill an animal or human being immediately by killing masses of cells in vital organs. But even the lowest levels can do serious damage. There is no levels of radiation that is completely safe. If the radiation does not hit anything important, the damage may not be serious. This is the case when only a few cells are hit, and if they are killed immediately, your body will replace the dead cells with healthy ones. But if the few cells are only damaged, and if they reproduce themselves, you may be in trouble. They can grow into cancer. Sometimes this does not show up for many years.This is another reason for some of the mystery about nuclear radiation. Serious damage can be done without the victim being aware at the time that damage has occurred. A person can be irradiated (辐射)and feel fine, then die for cancer five, ten, or twenty years later as a result. Or a child can be born weak as a result of radiation absorbed by its grandparents.Radiation can hurt us. We must know the truth.39. What is the main idea of the passage?A. How to detect nuclear radiation.B. How radiation kill a man.C. The mystery about nuclear radiation.D. Serious damage caused by nuclear radiation.40. Which of the following statements is true?A. Nuclear radiation can cause cancer to human beings.B. Nuclear radiation can be safe to human beings if its level is low.C. Nuclear radiation can be detected by human senses.D. Nuclear radiation is just like common radio waves.41. What is not the reason why nuclear radiation has a certain mystery?A. The hurt cells can stay in the body many years and then grow into cancer.B. It can do harm to a person while the victim isn't aware the damagehas occurred.C. Nuclear radiation can kill a person very easily.D. Radiation can seldom kill a person immediately.42. If a human being is hit by nuclear radiation, he may _______.A. die of cancer after many yearsB. die immediatelyC. have a child who may be born weakD. all of the aboveDFrom good reading we can derive pleasure, companionship, experience, and instruction. A good book may absorb our attention so completely that for the time being we forget our surroundings and even our identity. Reading good books is one of the greatest pleasures in life. It increases our contentment when we are cheerful, and lessens our troubles when we are sad. Whatever may be our main purpose in reading, our contact with good books should never fail to give us enjoyment and satisfaction.With a good book in our hands we need never be lonely. Whether the characters portrayed are taken from real life or are purely imaginary, they may become our companions and friends. In the pages of books we can walk with the wise and the good of all lands and all times. The people we meet in books may delight us either because they resemble human friends whom we hold dear or because they present unfamiliar types whom we are glad to welcome as new acquaintances. Our human friends sometimes may bore us, but the friends we make in books need never weary us with their company. By turning the page we can dismiss them without any fear of hurting their feelings. When human friends desert us, good books are always ready to give us friendship, sympathy, and encouragement.One of the most valuable gifts bestowed by books is experience. Few of us can travel far from home or have a wide range of experiences, but all of us can lead varied lives through the pages of books. Whether we wish to escape from the seemingly dull realities of everyday life or whether we long to visit some far-off place, a book will help us when nothing else can. To travel by book we need no bank account to pay our way; no airship or ocean liner or stream-lined train to transport us; no passport to enter the land of our heart's desire. Through books we may get the thrill of hazardous adventure without danger. We can climb lofty mountains, brave the perils of an Antarctic winter, or cross the scorching sands of the desert, all without hardship. In books we may visit the studios of Hollywood; we may mingle with the gay throngs of the Paris boulevards; we may join the picturesque peasants in an Alpine village or the kindly natives on a South Sea island. Indeed, through books the whole world is ours for the asking. The possibilities of our literary experiences are almost unlimited. The beauties of nature, the enjoyment of music, the treasures of art, the triumphs of architecture, the marvels of engineering, are all open to the wonder and enjoyment of those who read.43. Why is it that we sometimes forget our surroundings and even our identity while reading?A. No one has come to disturb you.B. The book you are reading is so interesting and attractive.C. Everything is so quiet and calm around you.D. Your book is overdue; you are finishing it at a very fast speed.44. How would you account for the fact that people like their acquaintances in books even more?A. They resemble human friends exactly.B. They are unfamiliar types we like.C. They never desert us.D. They never hurt our feelings.45. Which of the following is true?A. Your wish to visit some far-off place can be realized through the pages of the books.B. To escape from the dull realities of everyday life you should take up reading.C. You may obtain valuable experience from reading good books.D. Books can always help you to live a colorful life.46. The word “weary” means ______.A. “to attract someone’s attention”B. “to distract someone’s attention”C. “to make someone interested”D. “to make someone very tired”EHave you ever picked a job based on the fact that you were good at it but later found it made you feel very uncomfortable over time? When you select your career, there's a whole lot more to it than assessing your skills and matching them with a particular position. If you ignore your personality, it will hurt you long-term regardless of your skills or the job's pay. There are several areas of your personality that you need to consider to help you find a good job. Here are a few of those main areas;1) Do you prefer working alone or with other people?There are isolating(使孤立)jobs that will drive an outgoing person crazy and also interactive jobs that will make a shy person uneasy. Most people are not extremes in either direction but do have a tendency that they prefer. There are also positions that are sometimes a combination of the two, which may be best for someone in the middle who adapts easily to either situation.2) How do you handle change?Most jobs these days have some elements of change to them, but some are more than others. If you need stability in your life, you may need a job where the changes don't happen so often. Other people would be bored of the same daily routine.3) Do you enjoy working with computers?I do see this as a kind of personality characteristic. There are people who are happy to spend more than 40 hours a week on a computer, while there are others who need a lot of human interaction throughout the day. Again, these are extremes and you'll likely find a lot of positions somewhere in the middle as well.4) What type of work environment do you enjoy?This can range from being in a large building with a lot of people you won't know immediately to a smaller setting where you'll get to know almost all the people there fairly quickly.5) How do you like to get paid?Some people are motivated by the pay they get, while others feel too stressed to be like that. The variety of payment designs in the sales industry is a typical example for this.Anyway, these are a great starting point for you. I've seen it over and over again with people that they make more money over time when they do something they love. It may take you a little longer, but making a move to do what you have a passion for can change the course of your life for the better.47. Which of the following is TRUE according to the passage?A. Isolating jobs usually drive people mad.B. Almost everyone has a tendency in jobs.C. Interactive jobs make people shy easily.D. Extreme people tend to work with others.48. What does the underlined sentence in paragraph one mean?A. Before you select your job, you should assess your skills and match them withyour positionB . You should ignore your skills when you select job.C. Nothing is important than assessing skills and match them with the positionwhen you select job.D. There are more important things than assessing skills and match them with theposition when you select job.49. What is the missing word about a job search in the following chart?50. What is the best title for this passage?A. Lifestyles and Job PayB. Jobs and EnvironmentC. Personalities and JobsD. Job Skills and Abilities第二节根据对话内容,从对话后的选项中选出能填入空白处的最佳选项,并在答题卡上将该项涂黑。

高二物理上学期期中-成都市五校协作体联考2014-2015学年高二上学期期中物理试题及答案

高二物理上学期期中-成都市五校协作体联考2014-2015学年高二上学期期中物理试题及答案

四川省成都市五校协作体联考2014-2015学年高二上学期期中物理试卷参考答案与试题解析一、选择题(本题包括8个小题,每小题3分,共24分,每小题只有一个选项符合题意)1.(3分)下列说法正确的是()A.只有体积很小的带电体才能看作点电荷B.电场强度是矢量,方向就是电荷在该点的受力方向C.电容器的电容跟它两极所加电压成反比,跟它所带电量成正比D.外电路断开时,电动势数值上等于电源两极的电压考点:电场强度;电容.分析:带电体看作点电荷的条件,当一个带电体的形状及大小对它们间相互作用力的影响可忽略时,这个带电体可看作点电荷,是由研究问题的性质决定.电场强度方向与正电荷所受的电场力方向相同.电容与电容器板间电压和电量无关.外电路断开时,电动势数值上等于电源两极的电压.解答:解:A、带电体能否看作点电荷是由研究问题的性质决定,与自身大小形状无具体关系,故A错误;B、电场强度是矢量,方向就是正电荷在该点的受力方向,而与负电荷在该点的受力方向相反,故B错误.C、电容表征电容器容纳电荷本领大小,与两极所加电压、带电量无关,故C错误.D、外电路断开时,电源的内电压为零,根据闭合电路欧姆定律可知电动势数值上等于电源两极的电压,故D正确.故选:D.点评:本题考查的知识点较多,关键要理解点电荷的条件、电容的物理意义和电动势与电压的关系.2.(3分)两个分别带有电荷量﹣Q和+3Q的相同金属小球(均可视为点电荷),固定在相距为r的两处,它们间库仑力的大小为F.两小球相互接触后将其固定距离变为,则两球间库仑力的大小为()A.B.C.D.12F考点:库仑定律;电荷守恒定律.专题:计算题.分析:清楚两小球相互接触后,其所带电量先中和后均分.根据库仑定律的内容,根据变化量和不变量求出问题.解答:解:接触前两个点电荷之间的库仑力大小为F=k,两个相同的金属球各自带电,接触后再分开,其所带电量先中和后均分,所以两球分开后各自带点为+Q,距离又变为原来的,库仑力为F′=k,所以两球间库仑力的大小为.故选C.点评:本题考查库仑定律及带电题电量的转移问题.3.(3分)三个点电荷电场的电场线分布如图所示,图中a、b两点处的场强大小分别为E a、E b,电势分别为φa、φb,则()A.E a>E b,φa<φb B.E a<E b,φa<φb C.E a>E b,φa>φb D.E a<E b,φa>φb考点:电场线.分析:电场线密的地方电场强度大,电场线稀的地方电场强度小,沿电场线电势降低,据此可正确解答本题.解答:解:电场线密的地方电场强度大,电场线稀的地方电场强度小,故E a>E b;根据电场线与等势线垂直,在b点所在电场线上找到与a点电势相等的,依据沿电场线电势降低,可知φa<φb,故BCD错误,A正确.故选:A.点评:本题考查了如何根据电场线的分布判断电场强度大小以及电势高低,对于不在同一电场线上的两点,可以根据电场线和等势线垂直,将它们转移到同一电场线上进行判断.4.(3分)如图所示,在A板附近有一电子由静止开始向B板运动,则关于电子到达了B 板时的速率,下列解释正确的是()A.两板间距越大,加速的时间就越长,则获得的速率越大B.两板间距越小,加速度就越大,则获得的速率越大C.与两板间的距离无关,仅与加速电压U有关D.以上解释都不正确考点:匀强电场中电势差和电场强度的关系.专题:电场力与电势的性质专题.分析:根据动能定理求出电子获得的速度,判断与什么因素有关,根据牛顿第二定律和运动学公式求出加速度和运动时间,判断与什么因素有关.解答:解:根据动能定理知,qU=,解得:v=,获得的速率与加速电压有关,与间距无关.加速度a=,知间距越小,加速度越大.根据d=,解得:t=,间距越大,时间越长,故A、B、D错误,C正确.故选:C.点评:根据电子的运动的规律,列出方程来分析电子的加速度、运动的时间和速度分别与哪些物理量有关,根据关系式判断即可.5.(3分)平行板间加如图所示周期变化的电压,重力不计的带电粒子静止在平行板中央,从t=0时刻开始将其释放,运动过程无碰板情况.图中,能定性描述粒子运动的速度图象正确的是()A.B.C.D.考点:带电粒子在匀强电场中的运动;牛顿第二定律.专题:带电粒子在电场中的运动专题.分析:不计重力的带电粒子在周期变化的电场中,在电场力作用下运动.速度随着时间变化的关系由加速度来确定,而加速度是由电场力来确定,而电场力却由电势差来确定.解答:解:开始粒子在匀强电场中从静止运动,前半个周期是匀加速运动,后半个周期是匀减速运动,在下一个周期中仍是这样:继续向前匀加速运动,再匀减速运动,这样一直向前运动下去.速度的方向不变,而大小先增大后减小,再增大,再减小.故选:A点评:带电粒子正好是从零时刻由静止开始运动,加速度、速度具有周期性与对称性.6.(3分)热敏电阻是传感电路中常用的电子元件,其电阻R随温度t变化的图线如图甲所示.如图乙所示电路中,热敏电阻R t与其它电阻构成的闭合电路中,当R t所在处温度升高时,两电表读数的变化情况是()A.A变大,V变大B.A变小,V变小C.A变小,V变大D.A变大,V变小考点:闭合电路的欧姆定律.专题:恒定电流专题.分析:当R t所在处温度升高时,R t减小,并联部分电阻减小,总电阻减小,根据闭合电路欧姆定律分析路端电压和总电流的变化,再分析R2电压的变化,确定通过R2的电流变化,根据总电流和通过R2的变化,确定电流表示数的变化.解答:解:当R t所在处温度升高时,R t减小,并联部分电阻减小,外电路的总电阻减小,根据闭合电路欧姆定律可知:干路电流I总增大,路端电压U变小,则V变小.R t和R2并联的电压U并=E﹣I总(R1+r),I总增大,E、R1、r均不变,则U并减小,通过R2的电流I2减小,则A变小.故B正确.故选:B.点评:本题首先要读懂图象,明确热敏电阻与温度的关系,其次按“分部→整体→分部”的顺序进行动态分析.7.(3分)电流表的内阻足R g=100Ω,满刻度电流值是I g=1mA,现欲把这电流表改装成量程为3V的电压表,正确的方法是()A.应串联一个2900Ω的电阻B.应并联一个0.1Ω的电阻C.应串联一个0.1Ω的电阻D.应并联一个2900Ω的电阻考点:把电流表改装成电压表.专题:实验题;恒定电流专题.分析:把电流表改装成电压表需要串联分压电阻,应用串联电路特点与欧姆定律求出电阻阻值.解答:解:把电流表改装成电压表需要串联一个分压电阻,串联电阻阻值:R=﹣R g=﹣100=2900Ω;故选:A.点评:本题考查了电压表的改装,知道电压表的改装原理,应用串并联电路特点即可正确解题.8.(3分)如图所示,实线表示电场线,虚线表示只受电场力作用的带电粒子的运动轨迹.粒子先经过M点,再经过N点,以下正确的是()A.无法判断带电粒子的电性B.粒子在M点的动能小于在N点的动能C.粒子在M点受到的电场力大于在N点受到的电场力D.粒子在M点的电势能小于在N点的电势能考点:电场线;电势能.分析:带电粒子的轨迹向下弯曲,则带电粒子所受的电场力沿电场线切线向下,则知带电粒子带正电,由电场线的疏密可判断场强的大小,再判断电场力的大小.由带电粒子的轨迹可判定电场力的方向,确定电场力做功情况,分析电势能和动能的变化,再分析速度的变化.带电粒子的动能和电势能总和守恒.解答:解:A、带电粒子的轨迹向下弯曲,则带电粒子所受的电场力沿电场线切线向下,则知带电粒子带正电,故A错误.B、粒子先经过M点,再经过N点,电场力做正功,动能增大,速度也增大,故带电粒子在N点的速度大于在M点的速度,粒子在N点的动能大于在M点的动能.故B正确.C、电场线的疏密表示场强大小,由图知粒子在M点的场强小于N点的场强,在M点的加速度小于N点的加速度.故C错误.D、粒子先经过M点,再经过N点,电场力做正功,电势能减小,粒子在M点的电势能大于在N点的电势能.故D错误.故选:B点评:此类轨迹问题,由轨迹的弯曲方向可判定电场力的方向,并判断电场力做功正负情况.二、不定项选择题(本题包括5个小题,每小题4分,共20分,每小题给出一个或多个选项符合题意.全部选对得4分,选对且不全的得2分,有选错的得0分.)9.(4分)如图所示,两个带等量正电荷的小球A、B(可视为点电荷),被固定在光滑绝缘的水平面上.P、N是小球A、B的连线的水平中垂线,且PO=ON.现将一个电荷量很小的带负电的小球C(可视为质点),由P点静止释放,在小球C向N点运动的过程中,下列关于小球C的速度图象中,可能正确的是()A.B.C.D.考点:电场的叠加.专题:电场力与电势的性质专题.分析:A、B为两个等量的正点电荷,其连线中垂线上电场强度方向O→P,负点电荷q 从P点到O点运动的过程中,电场力方向P→O,速度越来越大.但电场线的疏密情况不确定,电场强度大小变化情况不确定,则电荷所受电场力大小变化情况不确定,加速度变化情况不确定.越过O点后,负电荷q做减速运动,点电荷运动到O点时加速度为零,速度达最大值,加速度变化情况同样不确定.解答:解:在AB的垂直平分线上,从无穷远处到O点电场强度先变大后变小,到O点变为零,负电荷受力沿垂直平分线运动,电荷的加速度先变大后变小,速度不断增大,在O 点加速度变为零,速度达到最大,由速度与时间的图象的斜率先变大后变小,由O点到无穷远,速度变化情况与另一侧速度的变化情况具有对称性.如果PN足够远,则B正确,如果PN很近,则A正确,CD错误.故选:AB.点评:本题考查对等量异种电荷电场线的分布情况及特点的理解和掌握程度,要抓住电场线的对称性.10.(4分)某同学设计了一种静电除尘装置,如图甲所示,其中有一长为L、宽为b、高为d的矩形通道,其前、后面板为绝缘材料,上、下面板为金属材料.图乙是装置的截面图,上、下两板与电压恒定为U的高压直流电源相连.带负电的尘埃被吸入矩形通道的水平速度为v0,当碰到下板后其所带电荷被中和,同时被收集.将被收集尘埃的数量与进入矩形通道尘埃的数量的比值,称为除尘率.不计尘埃的重力及尘埃之间的相互作用.要增大除尘率,则下列措施可行的是()A.只增大电压UB.只增大高度dC.只增大长度LD.只增大尘埃被吸入水平速度v0考点:带电粒子在匀强电场中的运动.专题:带电粒子在电场中的运动专题.分析:带电尘埃在矩形通道内做类平抛运动,在沿电场的方向上的位移为y=,增大y便可增大除尘率.解答:解:增加除尘率即是让离下极板较远的粒子落到下极板上,带电尘埃在矩形通道内做类平抛运动,在沿电场的方向上的位移为y=即增加y即可.A、只增加电压U可以增加y,故A满足条件;B、只增大高度d,由题意知d增加则位移y减小,故不满足条件;C、只增加长度L,可以增加y,故C满足条件;D、只增加水平速度v0,y减小,故不足条件.故选:AC.点评:此题为结合生活背景的题目,考查频率较高,注意构建物理情景类平抛运动,应用运动的分解知识求解11.(4分)M、N是一对水平放置的平行板电容器,将它与一电动势为E,内阻为r的电源组成如图所示的电路,R是并联在电容器上的滑动变阻器,G是灵敏电流计,在电容器的两极板间有一带电的油滴处于悬浮状态,如图所示,现保持开关S闭合,将滑动变阻器的滑片向上滑动,则()A.在滑片滑动时,灵敏电流计中有从b向a的电流B.在滑片滑动时,灵敏电流计中有从a向b的电流C.带电油滴将向上运动D.带电油滴将向下运动考点:闭合电路的欧姆定律.专题:恒定电流专题.分析:电容器两极板的电压等于变阻器两端的电压.将滑动变阻器的滑片向上滑动时,根据欧姆定律分析电容器板间电压如何变化,判断电容器是充电还是放电,分析通过电流计的电流方向.由E=分析板间场强如何变化,判断油滴如何运动.解答:解:AB、电容器两极板间的电压U=,当将滑动变阻器的滑片向上滑动时,R增大,U增大,电容器的电量增加,处于充电状态,灵敏电流计中有电流,由于电容器上板带正电,则灵敏电流计中有从a向b的电流.故A错误,B正确.CD、U增大,由E=分析得知,板间场强增大,则带电油滴将向上运动.故C正确,D错误.故选:BC点评:本题是电容的动态分析问题,关键确定电容器的电压,电路稳定时,电容器的电压等于所并联电路两端的电压.12.(4分)如图所示的电路中,电源内阻不可忽略,若调整可变电阻R的阻值,可使电压表V的示数减小△U(电压表为理想电表),在这个过程中()A.通过R1的电流减小,减少量一定等于B.R2两端的电压增加,增加量一定等于△UC.路端电压减小,减少量一定等于△UD.通过R2的电流增加,但增加量一定小于考点:闭合电路的欧姆定律.专题:恒定电流专题.分析:由图可知,R1与R并联后与R2串联,电压表测并联部分的电压;由欧姆定律可知,通过R1的电流的变化量;由闭合电路欧姆定律可得出电路中电流的变化量,则可得出路端电压的变化量及R2两端电压的关系.解答:解:A、因电压表示数减小,而R1为定值电阻,故电流的减小量一定等于,故A正确;B、R1两端的电压减小,则说明R2及内阻两端的电压均增大,故R2两端的电压增加量一定小于△U,故B错误;C、因内电压增大,故路端电压减小,由B的分析可知,路端电压的减小量一定小于△U,故C错误;D、由B的分析可知,R2两端的电压增加量一定小于△U,故电流的增加量一定小于,故D正确;故选AD.点评:本题考查欧姆定律中的动态分析,因本题要求分析电流及电压的变化量,故难度稍大,要求学生能灵活选择闭合电路的欧姆定律的表达形式.13.(4分)如图所示,粗糙程度均匀的绝缘斜面下方O点处有一正点电荷,带负电的小物体以初速度v1从M点沿斜面上滑,到达N点时速度为零,然后下滑回到M点,此时速度为v2(v2<v l).若小物体电荷量保持不变,OM=ON,则()A.从N到M的过程中,小物体的电势能逐渐减小B.从M到N的过程中,电场力对小物体先做负功后做正功C.从N到M的过程中,小物体受到的摩擦力和电场力均是先增大后减小D.小物体上升的最大高度为考点:电势能;电场强度.分析:小物块带负电,正点电荷对它有吸引力,根据距离变化即可判断电场力做功和电势能的变化.分析小球受力情况,根据斜面对小球支持力的变化,分析摩擦力的变化.根据动能定理分别上升和下滑两个过程,求出物体上升的最大高度.解答:解:A、由题分析可知,正点电荷对物体有吸引力,从N到M的过程中,物体与正点电荷间的距离先减小后增大,则电场力先做正功后做负功,物体的电势能先减小后增加.故A错误.B、从M到N的过程中,物体与正点电荷间的距离先减小后增大,则电场力先做正功后做负功.故B错误.C、从N到M的过程中,小物体受到的电场力先增大后减小,电场力在垂直于斜面的分力也先增大后减小,根据物体在垂直于斜面方向力平衡得知,斜面对物体的支持力也先增大后减小,则物体受到的摩擦力先增大后减小.故C正确.D、设物体上升过程中,摩擦力做功为W,上升的最大高度为h.由于OM=ON,M、N两点的电势相等,上升和下滑过程中电场力做功都为0,则根据动能定理得,上升过程:W﹣mgh=0﹣mv12下滑过程:W+mgh=mv22﹣0联立解得,h=.故D正确.故选:CD点评:本题根据物体与正电荷间距离的变化,来判断电场力做功的正负.求物体上升的最大高度时,要抓住OM=ON这个条件,得到M、N的电势相等,则知上升和下降电场力做功为0.三、实验题(本题包括2个小题,共16分)14.(4分)用控制变量法,可以研究影响平行板电容器的因素(如图).设两极板正对面积为S,极板间的距离为d,静电计指针偏角为θ.实验中,极板所带电荷量不变,若()A.保持S不变,增大d,则θ变大B.保持S不变,增大d,则θ变小C.保持d不变,减小S,则θ变小D.保持d不变,减小S,则θ不变考点:影响平行板电容器电容的因素.分析:静电计指针偏角θ表示电容器两端电压的大小,根据电容的定义式C=,判断电容的变化,再根据C=,判断电压的变化,从而得知静电计指针偏角的变化.解答:解:根据电容的定义式C=,保持S不变,增大d,电容C减小,再根据U=,知U增大,所以θ变大.故A正确,B错误.保持d不变,减小S,电容减小,再根据C=,知U增大,所以θ变大.故CD错误.故选:A.点评:解决电容器的动态分析问题关键抓住不变量.若电容器与电源断开,电量保持不变;若电容器始终与电源相连,电容器两端间的电势差保持不变.15.(12分)在“测定金属的电阻率”实验中,所用测量仪器均已校准.待测金属丝接入电路部分的长度约为50cm.(1)用螺旋测微器测量金属丝的直径,其中某一次测量结果如图1所示,其读数应为0.397mm(该值接近多次测量的平均值).(2)用伏安法测金属丝的电阻R x.实验所用器材为:电池组(电动势3V,内阻约1Ω)、电流表(内阻约0.1Ω)、电压表(内阻约3kΩ)、滑动变阻器R(0~20Ω,额定电流2A)、开关、导线若干.某小组同学利用以上器材正确连接好电路,进行实验测量,记录数据如下:由以上实验数据可知,他们测量R x是采用图2中的甲(选填“甲”或“乙”).(3)如图3是测量R x的实验器材实物图,图中已连接了部分导线,滑动变阻器的滑片P置于变阻器的一端.请根据(2)所选的电路图,补充完成下图中实物间的连线,并使闭合开关的瞬间,电压表或电流表不至于被烧坏.(4)这个小组的同学在坐标纸上建立U、I坐标,如图4所示,图中已标出了与测量数据对应的4个坐标点.请在图4中标出第2、4、6次测量数据的坐标点,并描绘出U﹣I图线.由图线得到金属丝的阻值R x=4.5Ω(保留两位有效数字).(5)根据以上数据可以估算出金属丝电阻率约为C(填选项前的符号).A.1×10﹣2Ω•m B.1×10﹣3Ω•mC.1×10﹣6Ω•m D.1×10﹣8Ω•m.考点:测定金属的电阻率.专题:实验题.分析:(1)关于螺旋测微器的读数,要先读出固定刻度,再读出可动刻度,然后相加即可得出结果.(2)根据数据比较电压表、电流表和被测电阻的阻值关系,确定可采取的电路.(3)按照电路原理图进行实物图的连接,注意导线不能交叉和滑动变阻器的连接方式.(4)根据图上所标的点,做出U﹣﹣I图线,从而可得出电阻值(5)把以上数据代入电阻定律,可得出结果解答:解:(1)固定刻度读数为0,可动刻度读数为39.7,所测长度为0+39.7×0.01=0.397mm (0.395~0.399)(2)由记录数据根据欧姆定律可知金属丝的电阻R x约5Ω.则有R x<,属于小电阻,用外接法测量误差小,由(3)知是用伏安特性曲线来测量电阻的,就要求电压电流从接近0开始调节,所以应该采用分压接法故选甲.(3)注意连图时连线起点和终点在接线柱上并且不能交叉,结合(2)可知应该连接成外接分压接法(甲)那么在连线时断开开关且使R x两端的电压为0.先连外接电路部分,再连分压电路部分,此时滑片P必须置于变阻器的左端.实物图如右图所示,(4)描绘出第2、4、6三个点后可见第6次测量数据的坐标点误差太大舍去,然后出U﹣I 图线.如右图所示;其中第4次测量数据的坐标点在描绘出的U﹣I图线上,有:R x==4.5Ω(5)根据电阻定律R=ρ,得ρ=R,代入数据可计算出ρ=1×10﹣6Ω•m,故选C.故答案为:(1)0.397 (2)甲(3)如图(4)4.5 (5)C点评:该题是综合性较强的题,解答时注意一下几方面:1、对于长度的测量注意高中所要求的游标卡尺和螺旋测微器的使用方法,读书时是固定刻度的值与可动刻度的值得和.2、会根据电压表、电流表及被测电阻的阻值关系,确定电流表是内接还是外接.3、实物连接时,注意导线不能相交叉,并且要注意闭合电建时,分压电路的输出端电压要为零.4、会用电阻定律来求解导线的电阻率四、计算题16.(8分)在真空中的O点放一点电荷Q=1.0×10﹣9C,直线MN过O点,OM=30cm,M 点放有一点电荷q=﹣2×10﹣10C,如图所示.求:(1)M点的场强大小;(2)若M点的电势比N点的电势高15V,则电荷q从M点移到N点,电势能变化了多少?(k=9.0×109N•m2/C2)考点:电势能;电场强度.专题:电场力与电势的性质专题.分析:(1)知道点电荷的电荷量及M点到点电荷的距离,由点电荷的场强公式E=k可以直接求得结果.(2)根据电场力做功的公式可以直接求得电场力做的功的大小,从而可以知道电势能的变化.解答:解:(1)由点电荷的场强公式E=k可知:M点的场强大小E=k=9.0×109×N/C=100N/C,所以电荷Q在M点的电场强度大小是100N/C.(2)电荷q从M点移到N点,电场力做的功为:W MN=qU MN=q(φM﹣φN)=﹣2×10﹣10×15J=﹣3×10﹣9J,所以电势能增加了3×10﹣9J.答:(1)M点的场强大小100N/C;(2)电势能增加了3×10﹣9J.点评:本题是对点电荷的场强公式和电场力做的功与电势能的转化之间关系的考查,掌握住基本内容就可以解决这道题.17.(10分)质量都是m的两个完全相同、带等量异种电荷的小球A、B分别用长L的绝缘细线悬挂在同一水平面上相距为2L的M、N两点,平衡时小球A、B的位置如图甲所示,线与竖直方向夹角α=37°,当外加水平向左的匀强电场时,两小球平衡位置如图乙所示,线与竖直方向夹角也为α=37°,(sin37°=,cos37°=)求:(1)A、B小球电性及所带电荷量Q;(2)外加匀强电场的场强E.考点:库仑定律;共点力平衡的条件及其应用.分析:(1)根据小球在匀强电场中受电场力的方向可得出小球所带电性;因两球均受重力、拉力及库仑力而处于平衡,由共点力的平衡规律可得出小球的电性及电荷量;(2)外加匀强电场后,小球仍然处于平衡状态,则由共点力的平衡条件可得出电场强度的大小.解答:解:(1)A球带正电,B球带负电,两小球相距d=2l﹣2lsin37°=l由A球受力平衡可得mgtanα=k解得Q=(2)外加匀强电场时两球相距d′=2l+2lsin37°=根据A球受力平衡可得QE﹣k=mgtanα解得:E=答:(1)A、B小球电性及所带电荷量Q为;(2)外加匀强电场的场强E为.点评:小球在电场中的受力平衡和力学中物体的平衡处理方法类似,只要正确做好受力分析,可根据题意选用共点力的平衡或牛顿第二定律求解.18.(10分)如图所示的电路中,两平行金属板A、B水平放置,极板长L=80cm,两板间的距离d=40cm.电源电动势E=40V,内电阻r=1Ω,电阻R=15Ω,闭合开关S,待电路稳定后,将一带负电的小球从B板左端且非常靠近B板的位置以初速度v0=4m/s水平向右射入两板间,该小球可视为质点.若小球带电量q=1×10﹣2C,质量为m=2×10﹣2kg,不考虑空气阻力,电路中电压表、电流表均是理想电表.若小球恰好从A板右边缘射出(g取10m/s2).求:(1)滑动变阻器接入电路的阻值为多少?(2)此时电流表、电压表的示数分别为多少?(3)此时电源的输出功率是多少?考点:带电粒子在匀强电场中的运动;闭合电路的欧姆定律.专题:带电粒子在电场中的运动专题.分析:(1)小球进入电场中做类平抛运动,小球恰好从A板右边缘射出时,水平位移为L,竖直位移为d,根据运动学和牛顿第二定律结合可求出板间电压,再根据串联电路分压特点,求解滑动变阻器接入电路的阻值.(2)根据闭合电路欧姆定律求解电路中电流,由欧姆定律求解路端电压,即可求得两电表的读数.(3)电源的输出功率P=UI,U是路端电压,I是总电流.。

四川省成都市五校高二物理下册第二学期期中联考试题(有答案)【精选】.doc

四川省成都市五校高二物理下册第二学期期中联考试题(有答案)【精选】.doc

成都市五校联考高2014级第四学期期中试题物理(全卷满分:100分完成时间:90分钟)第Ⅰ卷选择题部分 (共42分)一、单选题(每个小题只有一个选项符合题意,每小题3分,共18分)1、下列说法正确的是:A、库仑通过大量实验分析,得到了真空中两个静止点电荷相互作用规律,并引入电场线形象地描述电荷周围的电场B、物理学家法拉第通过实验证实了“磁生电”现象的存在,并总结出判断感应电流方向的规律C、安培首先发现电流磁效应,总结了电流周围磁场方向的判断方法――安培定则D、美国物理学家密立根利用实验,确定了电荷的不连续性,并测定了元电荷的数值2、关于机械振动,下列说法正确的是:A、振动物体的回复力一定等于振动物体所受到的合外力B、做简谐运动的物体通过平衡位置时其合力一定为0C、火车过桥要慢行,目的是使驱动力频率远小于桥梁的固有频率,以免发生共振损坏桥梁D、有机械振动一定能形成机械波3、如图所示,在暴雨前,地面上空有一带电云团(可近似看作带电绝缘球),某野外地面附近有一质量较小的带电体被吸上天空。

在带电体上升过程中,下列说法正确的是A.带电体所经过的不同位置的电场强度一定越来越大B.带电体所经过的不同位置的电势一定越来越高C.电体距离带电云团越近,它的电势能一定越来越大D.带电体的加速度一定越来越小4、某同学为了验证自感现象,自己找来带铁芯的线圈L(线圈的自感系数很大,构成线圈导线的电阻可以忽略)、两个相同的小灯泡A和B、开关S和电池组E,用导线将它们连接成如图所示的电路。

经检查,各元件和导线均是完好的,检查电路无误后,开始进行实验操作。

他可能观察到的现象是A.闭合S瞬间,A比B先亮B.闭合S瞬间,B比A先亮C.断开S瞬间,B比A先熄灭D.断开S瞬间,B先“闪亮”一下再熄灭5、如图甲所示,理想变压器的原线圈电路中接有量程为0.5 A的交流电流表,原、副线圈匝数比n1:n2=6:1。

将原线圈接在如图乙所示的交流电源上,要使整个电路的用电器或元件都能正常工作,则副线圏两端可以A. 并联两盏“110V 40 W”的灯泡B. 接量程为30V的直流电压表C. 接工作频率为100Hz的用电设备D. 接阻值为20Ω的电阻6、如图所示为某住宅区的应急供电系统,由交流发电机和副线圈匝数可调的理想降压变压器组成.发电机中矩形线圈所围的面积为S,匝数为N,电阻不计,它可绕水平轴OO′在磁感应强度为B的水平匀强磁场中以角速度ω匀速转动.矩形线圈通过滑环连接降压变压器,滑动触头P上下移动时可改变输出电压,R0表示输电线的电阻.以线圈平面与磁场平行时为计时起点,下列判断正确的是A.当发电机线圈某时刻处于图示位置时,变压器原线圈的电流瞬时值为零B.发电机线圈感应电动势的瞬时值表达式为e=NBSωcosωtC.当滑动触头P向下移动时,变压器原线圈两端的电压将升高D.当用电量增加时,为使用户电压保持不变,滑动触头P应向下滑动二、多选题(每个小题有多个选项符合题意,每小题4分,共24分)7、如图所示的弹簧振子做简谐运动时,下列说法正确的是A、振子在振动过程中,速度相同时,弹簧的长度一定相同B、振子在向平衡位置运动的过程中,弹簧的弹力始终做负功C、振子在振动过程中,系统的机械能一定守恒D、振子在振动过程中,经过半个周期,弹簧的弹力做功一定为08、如图,1、2、3、4……是均匀介质中x轴上的一系列质点,相邻两点的间距均为1 m.一列简谐横波以1 m/s的波速沿x轴正向传播,在t=0时刻到达质点1处,质点1由平衡位置开始竖直向下运动,t=3s时质点1第一次到达最高点.下列说法正确的是A.在t=6 s时刻波恰好传到质点6处B.质点6开始振动后,其振动周期为4 sC.在6 s<t<8 s的时间间隔内质点6的振动速度先变大再变小D.从t=0时刻到质点6刚开始向下运动的过程中,质点1一定向右移动了6m9、如图甲为远距离输电示意图,变压器均为理想变压器。

四川省成都市五校2013-2014学年高二数学下学期期中联考 理

四川省成都市五校2013-2014学年高二数学下学期期中联考 理

成都市“五校联考”高2012级第四学期期中试题数学(理科)(全卷满分:150分完成时间:120分钟)一选择题(本题共10个小题,每小题5分)1.“”是“方程表示焦点在y轴上的椭圆”的()(A)充分而不必要条件(B)必要而不充分条件(C)充要条件(D) 既不充分也不必要条件2.双曲线的虚轴长是( )(A)2 (B) (C) 4 (D) 43.已知命题:,则()A. B.C.D.4.下列命题中的假命题是( )A.∀x∈R,2x-1>0 B.∀x∈N*,(x-1)2>0C.∃x∈R,lg x<1 D.∃x∈R,tan x=25.设曲线在点处的切线斜率为,则点的坐标为()A、B、C、D、6.下列说法中正确的是( )A.一个命题的逆命题为真,则它的逆否命题一定为真B.“a>b”与“a+c>b+c”不等价C.“a2+b2=0,则a,b全为0”的逆否命题是“若a,b全不为0,则a2+b2≠0” D.一个命题的否命题为真,则它的逆命题一定为真7.已知点P()满足,则点P运动后得到的图象为()A.一直线和一椭圆 B.一线段和一椭圆C.一射线和一椭圆 D.两射线和一椭圆8.过双曲线的右焦点且与右支有两个交点的直线,其倾斜角范围是()( A ) ( B )( C ) ( D )9.过点(2,-1)引直线与抛物线只有一个公共点,这样的直线共有( )条A. 1B.2C. 3D.410.已知椭圆的内接三角形有一个顶点在短轴的顶点处,其重心是椭圆的一个焦点,该椭圆离心率e的取值范围是( )A. B. C. D.二.填空题(每小题5分,共25分)11. 已知F1,F2是椭圆的两焦点,过点F2的直线交椭圆于A,B两点,在中,若有两边之和是10,则第三边的长度为________12.设双曲线的渐近线方程为,则的值为________13.双曲线的一个焦点为,则的值为__________。

14.已知f1(x)=sin x+cos x,记f2(x)=f1′(x),f3(x)=f2′(x),…,f n(x)=f n-1′(x)(n∈N*,n≥2),则= 。

四川省成都市六校协作体2013-2014学年高二上学期期中考试物理试题 Word版含答案.pdf

四川省成都市六校协作体2013-2014学年高二上学期期中考试物理试题 Word版含答案.pdf

成都市六校高201级第学期期中试题 物 理一、单项选择题(本大题共小题,每小题3分,共分,本题给出的四个选项中,有且只有一个正确答案,请将所选项前的字母填写在答题卡中对应题号下的空格中)关于电场强度和电场线,下列说法正确的 ( ) ? A.在电场中某点放一检验电荷后,该点的电场强度会发生改变? B.由电场强度的定义式E=F/q可知,电场中某点的E与q成反比,与q所受的电场力F成正比 C.电荷在电场中某点所受力的方向即为该点的电场强度方向 D.初速为零、重力不计的带电粒子在电场中运动的轨迹可能不与电场线重合两个大小相同、带等量异种电荷的导体小球A和B,彼此间的引力为F另一个不带电的与A、B大小相同的导体小球C, 先与A接触,再与B接触,然后移开,这时A和B之间的作用力为F',则F与F'之比为? A.8:3? B.8:1? C.1:8 D.4:1....kΩ1/8W”的电阻和一个“300kΩ1/8W”的电阻串联,作为400 kΩ的电阻使用,此时两只串联电阻允许消耗的最大功率为 ( ) 5.如图所示电路中,电压表的读数为9V,电流表的读数为0.1A。

已知电压表的内阻为900Ω,电流表的内阻为20Ω,则电阻R的阻值为( )A. 90ΩB.100ΩC.110ΩD.120Ω 6.如图所示,a,b,c为电场中同一条水平方向电场线上的三点,c为ab中点.a,b电势分别为,,下列叙述正确的是 ( ) A.该电场在c点处的电势一定为4V B.a点处的场强一定大于b点处的场强 C.一正电荷从c点运动到b点电势能一定减少 D.一正电荷运动到c点时受到的电场力由c指向a 二、项选择题(本大题共小题,每小题4分,共2分,本题给出的四个选项中,至少有个正确答案,少选得2分,多选不得分请将所选项前的字母填写在答题卡中对应题号下的空格中)( ) A.点电荷是一种理想化的物理模型 B.点电荷所带电荷量一定是元电荷电荷量的整数倍 C.点电荷所带电荷量一定很小 D.点电荷、元电荷、试探电荷是同一种物理模型 8、真空中有带电粒子P1、P2,先后以相同的初速度v0从同一位置进入电场,初速度方向垂直电场,偏转后打在B、C两点,且AB=BC,P1的电量为P2电量的3倍,则P1、P2的质量之比为( )A. 3:2B.2:3C. 4:3D.3:4 9.在如图所示的电路中,R1、R2、R3均为可变电阻。

四川省成都市五校2013-2014学年高一下学期期中联考 生物 Word版含答案

四川省成都市五校2013-2014学年高一下学期期中联考 生物 Word版含答案

成都市“五校联考”高2013级第二学期期中试题生物(全卷满分:100分完成时间:90分钟)一、选择题(每小题只有一个选项符合题意,本题包括45小题,1-30每小题1分,31-45每小题两分,共60分。

)1.下列关于细胞分化的说法错误的是()A.细胞分化发生在生物体的整个生命进程中B.细胞分化是生物界的一种普遍存在的生命现象C.细胞分化仅发生在胚胎时期D.细胞分化是细胞在形态、结构和功能上发生稳定性差异的过程2.下列有关细胞衰老和凋亡的说法中正确的是( )A.健康的成人体内,每天都有一定量的细胞凋亡B.细胞凋亡受环境影响大,机体难以控制C.老年人头发变白和白化病都是由酪氨酸酶活性降低引起的D.胚胎发育期生物体的细胞衰老总与机体衰老同步进行3.下列有关细胞凋亡和癌变的相关叙述,正确的是 ( )A.细胞凋亡过程中某些基因的表达可能会增强B.原癌基因突变促使细胞癌变,抑癌基因突变抑制细胞癌变C.动物在正常的生活环境中,体细胞不会发生凋亡D.凋亡细胞、癌细胞等细胞中基因组成都相同4.下列细胞中,可能已发生癌变的是( )A.细胞膜上糖蛋白减少的细胞B.细胞核增大的细胞C.自由水含量减少的细胞D.被细菌侵染的细胞5.下列有关“观察根尖分生组织细胞的有丝分裂”实验过程的叙述中,正确的一组是( )①解离的目的是用药液使组织细胞相互分离②漂洗的目的是洗去根尖上的解离液③压片的目的是使根尖细胞分散开来④应选取长方形的细胞进行观察⑤可以持续观察一个细胞,认识有丝分裂的完整过程A.①②③B.③④⑤C.①④⑤D.②③④6.某同学在光学显微镜下观察洋葱根尖细胞有丝分裂并绘制出下图。

据此推测高尔基体的活动明显增强的时期是( )7.成人体内细胞约有230多种,其中胰岛B细胞合成胰岛素,甲状腺细胞合成甲状腺激素,正常情况下,分化的细胞还具有一定的寿命。

例如,红细胞分化成熟后的寿命约是120 d,白细胞的寿命约是5~7 d,下列说法不正确的是( )A.现代分子生物学的证据表明,细胞分化是基因选择性表达的结果B.在个体发育过程中,有序的细胞分化能够增加细胞的类型C.由不同类型的细胞构成生物体的组织和器官,执行不同的功能D.自然选择学说认为,因为某种功能的需要而进化产生了各种细胞类型8.下列关于细胞分裂和细胞分化的叙述,错误的是( )A.生物体的生长发育是细胞分裂和细胞分化的结果B.生物体通过细胞分化,细胞之间逐渐发生了稳定的差异C.细胞分裂是细胞分化的基础D.细胞分化过程中细胞中的遗传物质种类发生变化9.绵羊的乳腺细胞是高度特化的细胞,但用乳腺细胞的细胞核与卵细胞的细胞质融合成一个细胞后,这个细胞核仍然保持着全能性,这主要是因为( )A.细胞核内含有保持物种发育所需要的全套遗传物质B.卵细胞的细胞质内含有物种发育所需要的全套遗传物质C.卵细胞的细胞质为细胞核提供营养物质D.细胞核与细胞质是相互依存的关系10.李白诗云:“君不见,高堂明镜悲白发,朝如青丝暮成雪。

  1. 1、下载文档前请自行甄别文档内容的完整性,平台不提供额外的编辑、内容补充、找答案等附加服务。
  2. 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
  3. 3、如文档侵犯您的权益,请联系客服反馈,我们会尽快为您处理(人工客服工作时间:9:00-18:30)。

四川省成都市“五校联考”2012级第四期期中试题物理本试卷分为第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分.第Ⅰ卷1至2页,第Ⅱ卷3至4页.全卷共110分.第Ⅰ卷(选择题,共42分)一、选择题(本题共7题,每小题6分,共42分。

有的小题只有一个选项正确,有的小题有多个选项正确,选对得6分,漏选得3分,错选得0分,把正确选项前的字母填在题后的括号内)1.下列说法正确的是()A.穿过线圈的磁通量为零时,感应电动势一定为零B.日光灯发出柔和的白光是涂在壁上的荧光粉在紫光照射下发出的可见光C.一个线圈的电流均匀增大,这个线圈的自感系数、自感电动势都不变D.容抗的大小跟电容有关,电容越大,容抗越大2.一个100匝矩形导线圈产生的正弦交流电的电压随时间变化的规律如图1所示.由图可知( )A.该交流电的电压瞬时值的表达式为u=100sin(25t) VB.当t =10-2s时,磁通量最大C.当t =10-2s时,线圈转动过程中磁通量变化率为100wb/s阻D.若将该交流电压加在阻值为R=100Ω的电阻两端,则电消耗的功率是50 W3.如图2所示电路中,当电键S断开瞬间( ).A.流经R2的电流方向向右,流经L的电流方向向左B.流经R2的电流方向向左,流经L的电流方向向右C.流经R2和L的电流方向都向右D.流经R2和L的电流方向都向左4.劲度系数为20 N/cm的弹簧振子,小球的质量0.5kg,它的振动图像如图所示,在图中A点对应的时刻()A.振子的加速度为10m/s2,方向指向x轴的负方向B.振子的速度方向指向x轴的负方向C.小球的振幅0.25cmD.在0~4s内振子通过的路程为0.35 cm,位移为05.如图所示,理想变压器副线圈通过输电线接两个相同的灯泡L1和L2.输电线的等效电阻为R.开始时,电键S断开,当S闭合时,下列说法中正确的是( ).(A)副线圈两端的输出电压减小 (B)通过灯泡L1的电流减小(C)原线圈中的电流减小(D)变压器的输入功率不变6.如图5所示,一电子以初速度v沿金属板平行方向飞入MN极板间,若突然发现电子向M 板偏转,则可能是( ).A.电键S闭合瞬间B.电键S由闭合到断开瞬间C.电键S是闭合的,变阻器滑片P向左迅速滑动D.电键S是闭合的,变阻器滑片P向右迅速滑动7.如图6所示,两足够长的平行光滑的金属导轨MN 、PQ 相距为d ,导轨平面与水平面的夹角θ=30°,导轨电阻不计,磁感应强度为B 的匀强磁场垂直于导轨平面向上。

长为d 的金属棒ab 垂直于MN 、PQ 放置在导轨上,且始终与导轨接触良好,金属棒的质量为m 、电阻为r =R 。

两金属导轨的上端连接一个灯泡,灯泡的电阻R L =R ,重力加速度为g 。

现闭合开关S ,给金属棒施加一个方向垂直于杆且平行于导轨平面向上的、大小为F =mg 的恒力,使金属棒由静止开始运动,当金属棒达到最大速度时,灯泡恰能达到它的额定功率。

下列说法正确的是( )A. 灯泡的额定功率22222d B Rg m P L = B. 金属棒能达到的最大速度22d B mgR v m= C.金属棒达到最大速度的一半时的加速度g a 41=D.若金属棒上滑距离为L 时速度恰达到最大,金属棒由静止开始上滑4L 的过程中,金属棒上产生的电热442232d B R g m mgL Q r -=第Ⅱ卷 (非选择题共68分)二、实验题(16分) 8.(1)(6分)某同学利用如图所示的装置测量当地的重力加速度。

实验步骤如下: A .按装置图安装好实验装置; B .用游标卡尺测量小球的直径d ;C .用米尺测量悬线的长度l ;D .让小球在竖直平面内小角度摆动。

当小球经过最低点时开始计时,并计数为1,此后小球每经过最低点一次,依次计数2、3……。

当数到 n 时,停止计时,测得时间为t ;E .多次改变悬线长度,对应每个悬线长度,都重复实验步骤C 、D ;F .计算出每个悬线长度对应的t 2;G .以t 2为纵坐标、l 为横坐标,作出t 2-l 图线。

结合上述实验,完成下列任务:①用游标为10分度的游标卡尺测量小球的直径。

某次测量的示数如下图7所示,读出小球直径d 的值为 cm 。

②根据实验步骤(D),可知此单摆的周期为③该同学根据实验数据,利用计算机作出t 2–l 图线如图8所示,从理论上分析图线没有过坐标原点的原因,下列分析正确的是 ( )A .不应在小球经过最低点时开始计时,应该在小球运动到最高点开始计时;B .开始计时后,不应记录小球经过最低点的次数,而应记录小球做全振动的次数;C .不应作t 2–l 图线,而应作t –l 图线; D .不应作t 2–l 图线,而应作t 2–(l +21d )图线。

(2).(10分)在“测定电源的电动势和内阻”的实验中,有以下器材: A .待测干电池组E (电动势约为4.5V ,内阻r 约2Ω)B .电压表(量程3V 、内阻很大)C .电流表(量程0.5A 、内阻很小)D .滑动变阻器(0~20Ω)E .电阻箱R 0(0~999.9Ω,用作定值....电阻..)F .电键、导线若干①若实验中调节滑动变阻器电压表示数变化不明显采用给电源 (“串联”或“并联)一个电阻箱,如图9甲中电阻箱面板显示其阻值R 0=_______Ω。

②图9乙为用以上器材连接的不完整的电路,为完成实验,请在乙图中补画出一根导线....构成完整实验电路。

③利用实验测得的多组电压表示数和对应的电流表示数,绘出了如图9丙所示的U -I 关系图线,若图线在U 轴的截距为U 0,在I 轴的截距为I 0,则可以求得电池组电动势E =__________,内阻r =______ _。

(用给定的物理量符号表示)。

三、计算题计算题(本题共3小题,共52分。

解答应写出必要的文字说明、方程式和重要的演算步骤,只写出最后答案的不能得分。

有数值计算的题,答案中必须明确写出数值和单位)9.(15分)如图11所示,MN 与PQ 是两条水平放置彼此平行的光滑金属导轨,导轨间距为l=0.5m 。

质量m=1kg ,电阻r=0.5Ω的金属杆ab 垂直跨接在导轨上,匀强磁场的磁感线垂直纸面向里,磁感应强度的大小为B=2T ,导轨左端接阻值R=2Ω的电阻,导轨电阻不计。

ab 杆受水平恒力F 的作用后由静止开始向右做变加速运动,后做匀速运动。

匀速时ab杆的速度为v=2m/s ,重力加速度g=10m/s 2。

求:(1)匀速时ab 杆受到的水平恒力F 的大小;(2)速度等于1m/s 时金属杆的加速度大小。

10.(18分)如图12所示,一个面积s=0.2m 2的单匝圆形线圈,M 、N 两端间距很小可以忽略,线圈处于变化的磁场中,磁场的磁感应强度按B=)100sin(5t ππT 的规律变化。

线圈中产生的感应电动势的瞬时值表达式为e =B m S ωcos(ωt),其中B m 为磁感应强度的最大值,ω为磁场变化的角速度,线圈的电阻r=2Ω,外接电阻R=18Ω.(电压表为理想交流电压表)求: (1).当s t 6001=时电压表的示数。

(2).变化的电流一个周期在电阻R 上产生的热量Q 。

图11 lbRM P(3).从t=0开始到s t 2001=这段时间通过圆形线圈的电量q.11. (19分)如图所示,两根粗细均匀的金属杆AB 和CD 的长度均为L ,电阻均为R ,质量分别为3m 和m ,用两根等长的、质量和电阻均不计的、不可伸长的柔软导线将它们连成闭合回路,悬跨在绝缘的、水平光滑的圆棒两侧,AB 和CD 处于水平。

在金属杆AB 的下方有水平匀强磁场,磁感强度的大小为B ,方向与回路平面垂直,此时CD处于磁场中。

现从静止开始释放金属杆AB ,经过一段时间(AB 、CD 始终水平),在AB 即将进入磁场的上边界时,其加速度为零,此时金属杆CD 还处于磁场中,在此过程中金属杆AB 上产生的焦耳热为Q . 重力加速度为g ,试求:(1)金属杆AB 即将进入磁场上边界时的速度v 1. (2)在此过程中金属杆CD 移动的距离h 和系统机械能减少量E ∆.(3)设金属杆AB 在磁场中运动的速度为v 2,通过计算说明v 2大小的可能范围.(设CD 始终在磁场中运动)四川省成都市“五校联考”2012级第四期期中试题物 理四川省成都市“五校联考”2012级第四期期中试题物 理一、选择题1 C2 D3 A4 A5 B6 AC7 BC 8.(1)① 1.62 ② 2t/n-1 ③ D (2)(1)串联 8.0(4分);(2)如图所示(2分,也可接在滑动变阻器金属杆右端);(3)U 0(3分),00-U R I (2分)。

评分标准:(1)问6分, ,每空2分;(2)问10分,其中①②③问每空2分,9.(15分)(1)由电动势 E =Blv , (1分)闭合电路欧姆定律rR EI +=, (2分) 安培力 rR vl B BIl F A +==22=0.8N (2分)得:F A =0.8N (1分) 所以 F=F A =0.8N (2分)(2)由牛顿第二定律 F- rR vl B +22=ma (5分)得:a=0.4m/ s 2(2分)10(18分) (1)由图象知,线圈中产生的交变电流E m =B m S ω=100 V. (2分)有效值U有=2Em=502V (2分)电压表的示数U=R R Er+有=452V (2分)(2) 交变电流的周期T=s 02.02=ωπ(2分)一个周期在电阻R 上产生的热量Q=J T RU5.42= (4分)(3)在0~s 2001时间内,电动势的平均值E =t Bs ∆∆ ①, (2分)平均电流I =ER +r② (1分)流过灯泡的电荷量q =I Δt . ③ (2分)得q =c π201(1分)11.(1)AB 杆达到磁场边界时,加速度为零,系统处于平衡状态, 对AB 杆: 3mg =2T (1分) 对CD 杆:2T =mg +BIL (1分)又 F =BIL =B 2L 2v 12R (2分)解得v 1=4mgRB 2L2 (2分)(2)以AB 、CD 棒组成的系统在此过程中,根据能的转化与守恒有:(3m -m )gh -2Q =12⨯4mv 12(3分)23224414416mv Q m g R QB L h mg mgB L++== (2分) 系统机械能减少量E ∆=2Q (2分)(3)AB 杆与CD 杆都在磁场中运动,直到达到匀速,此时系统处于平衡状态, 对AB 杆:3mg =2T +BIL (2分) 对CD 杆:2T ’=mg +BIL (2分)又 F =BIL =B 2L 2v 2R 解得 v 2=mgRB 2L 2 (2分)所以 mgR B 2L 2<v 2<4mgRB 2L2 (1分)。

相关文档
最新文档