云南省师范大学附属中学2017届高考适应性月考(五)英语试题(解析版)

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云南省师范大学附属中学2017届高考适应性月考(五)英语试题含答案

本试卷分第I 卷（选择题）和第II 卷（非选择题）两部分，第I 卷第1页至第7页，第II 卷第7页至第8页。

考试结束后，请将本试卷和答题卡一并交回。

满分150分，考试时间120分钟。

第I 卷（选择题，共100分）注意事项：1.答题前，考生务必用黑色碳素笔自己的名字、准考证号、考场号、座位号在答题卡上填写清楚。

2.每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，在选涂其他答案标号。

在试题卷上作答无效。

第一部分：听力（共两节，满分30分）做题时，先将答案标在试卷上录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. When does the conversation probably take place?A. In the morning.B. In the afternoon.C. In the evening.2. What do we know about Jenny?A. She works hard on her study.B. She shouldn’t be proud.C. She is very clever.3. What does the woman think of driving?A. Dangerous.B. Safe.C. Comfortable.4. How does the man feel?A. Tired.B. worried.C. Calm.5. What is the correct time now?A. 2:40.B. 2:30.C. 2:20.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。

云南省2017届高三高考适应性月考五文数试题Word版含答案

云南省师范大学附属中学2017届高三高考适应性月考（五）文科数学试卷第Ⅰ卷（共60分）一、选择题：本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.1.集合2{|0}{|2}A x x a B x x =-≤=<，，若A B ⊆，则实数a 的取值范围是（） A ．(,4]-∞ B ．(,4)-∞ C ．[0,4] D ．(0,4)2.复数31i z i =-，则其共轭复数z 在复平面内对应的点位于（）A ．第一象限B ．第二象限C ．第三象限D ．第四象限3.某班有学生60人，将这60名学生随机编号为1-60号，用系统抽样的方法从中抽出4名学生，已知3号、33号、48号学生在样本中，则样本中另一个学生的编号为（） A ．28 B ．23 C ．18 D ．134.已知,x y 满足10,0,40,x x y x y -≥⎧⎪-≤⎨⎪+-≥⎩，则目标函数3z x y =+的最小值是（）A ．4B ．6 C. 8 D ．10 5.下列说法正确的是（）A ．“1x <”是“2log (1)1x +<”的充分不必要条件B ．命题“0x ∀>，21x>”的否定是“00021xx ∃≤≤，” C.命题“若a b ≤，则22ac bc ≤”的逆命题为真命题 D ．命题“若5a b +≠，则2a ≠或3b ≠”为真命题6.秦九韶算法是南宋时期数学家秦九韶提出的一种多项式简化算法，即使在现代，它依然是利用计算机解决多项式问题的最优算法，即使在现代，它依然是利用计算机解决多项式问题的最优算法，其算法的程序框图如图所示，若输入的012,,,,n a a a a L 分别为0,1,2,,n L ，若5n =，根据该算法计算当2x =时多项式的值，则输出的结果为（）A ．248B ．258 C.268 D ．278 7.已知函数()|sin |cos f x x x =•，则下列说法正确的是（） A ．()f x 的图象关于直线对称2x π=B ．()f x 的周期为πC.若12|()||()|f x f x =，则122()x x k k Z π=+∈ D ．()f x 在区间3[,]44ππ上单调递减8.在棱长为2的正方体1111ABCD A B C D -中任取一点M ，则满足90AMB ∠>°的概率为（） A ．24πB ．12πC.8πD ．6π9.某几何体的三视图如图所示，则该几何体的体积为（）A ．8B ．62 C.2 D ．4 10.已知函数322()()3f x x ax a b x c =+--+的两个极值点分别为12,x x ，且12(,1),(1,0)x x ∈-∞-∈-，点(,)P a b 表示的平面区域为D ，若函数log (2)(0,1)m y x m m =+>≠的图象经过区域D ，则实数m 的取值范围是（）A ．(3,)+∞B ． [3,)+∞ C. (1,3) D ．(1,3]11.椭圆22221(0)x y a b a b+=>>，12,F F 为椭圆的左、右焦点，O 为坐标原点，点P 为椭圆上一点，||OP =，且123||,||,||PF PF PF 成等比数列，则椭圆的离心率为（）A B 12.四面体PABC 的四个顶点都在球O 的球面上，84PA BC PB PC AB AC =====，，，且平面PBC ⊥平面ABC ，则球O 的表面积为（）A ．64πB ．65π C.66π D ．128π第Ⅱ卷（共90分）二、填空题（每题5分，满分20分，将答案填在答题纸上）13.已知函数3()xf x e x =+，若2()(32)f x f x <-，则实数x 的取值范围是． 14.点P 是圆22(3)(1)2x y ++-=上的动点，点(2,2)Q ，O 为坐标原点，则OPQ ∆面积的最小值是．15.已知数列{}n a 满足11a =，22a =，22(1sin )cos22n n n n a a n ππ+=++•，则该数列的前20项和为．16.抛物线22(0)x py p =>上一点)(1)A m m >到抛物线准线的距离为134，点A 关于y 轴的对称点为B ，O 为坐标原点，OAB ∆的内切圆与OA 切于点E ，点F 为内切圆上任意一点，则OE OF u u u r u u u r•的取值范围为．三、解答题（本大题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤.）17. （本小题满分12分）在ABC ∆中，角A ，B ，C 的对边分别为a ，b ，c ，已知223cos cos 2222B A a b c a b +==，．（1）证明：ABC ∆为钝角三角形；（2）若ABC ∆的面积为315，求b 的值． 18. （本小题满分12分）某公司即将推车一款新型智能手机，为了更好地对产品进行宣传，需预估市民购买该款手机是否与年龄有关，现随机抽取了50名市民进行购买意愿的问卷调查，若得分低于60分，说明购买意愿弱；若得分不低于60分，说明购买意愿强，调查结果用茎叶图表示如图所示.（1）根据茎叶图中的数据完成22⨯列联表，并判断是否有95%的把握认为市民是否购买该款手机与年龄有关？（2）从购买意愿弱的市民中按年龄进行分层抽样，共抽取5人，从这5人中随机抽取2人进行采访，求这2人都是年龄大于40岁的概率.附：22()()()()()n ad bc k a b c d a c b d -=++++.19. （本小题满分12分）如图，三棱锥P ABC -中，PA ⊥平面ABC ，90ABC ∠=°，2PA AC ==，D 是PA 的中点，E 是CD 的中点，点F 在PB 上，3PF FB =u u u r u u u r.（1）证明：//EF 平面ABC ；（2）若60BAC ∠=°，求点P 到平面BCD 的距离. 20. （本小题满分12分）已知抛物线2:2(0)C y px p =>，圆22:(2)4M x y -+=，圆心M 到抛物线准线的距离为3，点000(,)(5)P x y x ≥是抛物线在第一象限上的点，过点P 作圆M 的两条切线，分别与x 轴交于,A B 两点. （1）求抛物线C 的方程；（2）求PAB ∆面积的最小值. 21. （本小题满分12分）已知函数21()()2x f x e x a =-+. （1）若曲线()y f x =在点0x =处的切线斜率为1，求函数()f x 的单调区间；（2）若0x ≥时，()0f x ≥恒成立，求实数a 的取值范围.请考生在22、23两题中任选一题作答，如果多做，则按所做的第一题记分.22. （本小题满分10分）选修4-4：坐标系与参数方程在直角坐标系xOy 中，将曲线1cos :1sin 2x t C y t =+⎧⎪⎨=⎪⎩（t 为参数）上每一点的横坐标保持不变，纵坐标变为原来的2倍，得到曲线1C ；以坐标原点O 为极点，以x 轴的正半轴为极轴建立极坐标系，曲线2C 的极坐标方程为2cos()336πρθ-=.（1）求曲线1C 的极坐标方程；（2）已知点(1,0)M ，直线l 的极坐标方程为3πθ=，它与曲线1C 的交点为O ，P ，与曲线2C 的交点为Q ，求MPQ ∆的面积.23. （本小题满分10分）选修4-5：不等式选讲已知函数()|1|2|1|f x x x =+--.（1）求()f x 的图象与x 轴围成的三角形面积；（2）设24()x ax g x x-+=，若对(0,)s t ∀∈+∞，恒有()()g s f t ≥成立，求实数a 的取值范围.云南师大附中2017届高考适应性月考卷（五）文科数学参考答案第Ⅰ卷（选择题，共60分）一、选择题（本大题共12小题，每小题5分，共60分）题号 1 2 3 4 5 6 7 8 9 10 11 12 答案 B C C B D B D A A C D B1．当0a<时，集合A=∅，满足题意；当0a≥时，[]A a a=-，，若A B⊆，则2a<，∴0<4a≤，所以(4)a∈-∞，，故选B．2．∵i1ii12z--+==-，其共轭复数为1i2z--=，对应点为1122⎛⎫--⎪⎝⎭，在第三象限，故选C．3．抽样间隔为15，故另一个学生的编号为3+15=18，故选C．4．画出可行域如图1所示，当目标函数3y x z=-+经过点A(1，3)时，z的值为6；当目标函数3y x z=-+经过点B(2，2)时，z的值为8，故选B．5．选项A：2log(1)101211x x x+<⇔<+<⇔-<<，所以“1x<”是其必要不充分条件；选项B：命题“021xx∀>>，”的否定是“0021xx∃>，≤”；选项C：命题“若a b≤，则22ac bc≤”的逆命题是“若22ac bc≤，则a b≤”，当c=0时，不成立；选项D：其逆否命题为“若2a=且3b=，则5a b+=”为真命题，故原命题为真，故选D．6．该程序框图是计算多项式5432()5432f x x x x x x=++++当x=2时的值，故选B．7．作出函数()f x在区间[02π]，上的图象，由已知，函数()f x在区间[02π]，上的解析式为1sin20π2()1sin2π2π2x xf xx x⎧⎪⎪=⎨⎪-<⎪⎩，，，，≤≤≤且()f x是偶函数，画出图象可知，故选D．图18．以AB 为直径作球，球在正方体内部的区域体积为14ππ433V =⨯=，正方体的体积为8，所以π24P =，故选A ． 9．由三视图还原出该几何体为长方体切去一部分，如图所示，所以剩余部分体积为222383V =⨯⨯⨯=，故选A ．10．由2()22()f x x ax a b '=+--，故()0f x '=的两根分别为12x x ，，由二次方程根的分布得248()0(1)0(0)0a a b f f ⎧+->⎪'-<⎨⎪'>⎩，，，即223200a b a a b a b ⎧<+⎪⎪⎪-->⎨⎪-<⎪⎪⎩，，，画出该不等式组所表示的平面区域D ，当函数log (2)m y x =+的图象经过点(1，1)时，m =3，因此当13m <<时函数图象经过区域D ，故选C.11．设()P x y ，，则2222||8a OP x y =+=，由椭圆定义，2121||||2||PF PF a PF +=⇒+22||PF2122||||4PF PF a +=g ，又∵1122||||||PF F F PF ，，成等比数列，∴12||||PF PF =g 2212||4F F c =，∴222212||||84PF PF c a ++=，∴222()()x c y x c +++-22284y c a ++=，整理得222252x y c a ++=，即222223652884a c c c a e a a +=⇒=⇒==，故选D ．12．如图，D ，E 分别为BC ，PA 的中点，易知球心O 点在线段DE 上，因为PB =PC =AB =AC ，则PD BC AD BC PD AD ⊥⊥=，，．又∵平面PBC ⊥平面ABC ，平面PBC I 平面ABC =BC ，∴PD ⊥平面ABC ，∴PD AD ⊥，∴PD =42AD =．因为E 点是PA 的中点，∴ED PA ⊥，且DE =EA =PE =4．设球O 的半径为R ，OE =x ，则OD =4−x ，在Rt OEA△中，有2216R x =+，在Rt OBD △中，有224(4)R x =+-，解得2654R =，所以24π65πS R ==，故选B ．图3图2第Ⅱ卷（非选择题，共90分）二、填空题（本大题共4小题，每小题5分，共20分）题号 13 14 15 16答案 (12)，21033[333+3]-，13．因为2()e 30x f x x '=+>，所以函数f (x )为增函数，所以不等式2()(32)f x f x <-等价于232x x <-，即232012x x x -+<⇔<<，故(12)x ∈，．14．因为||22OQ =，直线OQ 的方程为y =x ，圆心(31)-，到直线OQ 的距离为|31|222d --==，所以圆上的动点P 到直线OQ 的距离的最小值为2222-=，所以OPQ △面积的最小值为122222⨯⨯=．15．当n 为奇数时，22n n a a +=，故奇数项是以11a =为首项，公比为2的等比数列，所以前20项中的奇数项和为10101221102312S -==-=-奇；当n 为偶数时，22(1)nn n a a n +=+-g ，前20项中的偶数项和为=10S 偶，所以201023101033S =+=． 16．因为点(3)A m ，在抛物线上，所以3322pm m p=⇒=，点A 到准线的距离为313224p p +=，解得12p =或6p =．当6p =时，114m =<，故6p =舍去，所以抛物线方程为2x y =，∴(33)(33)A B -，，，，所以OAB △是正三角形，边长为23，其内切圆方程为22(2)1x y +-=，如图4，∴332E ⎫⎪⎪⎭，．设点(cos 2sin )F θθ+，（θ为参数），则33π3sin 3326OE OF θθθ⎛⎫=++=++ ⎪⎝⎭u u u r u u u r g ， ∴[3333]OE OF ∈u u u r u u u rg ，．三、解答题（共70分．解答应写出文字说明，证明过程或演算步骤）17．（本小题满分12分）（Ⅰ）证明：由正弦定理：1cos1cos3sin sin sin222B AA B C+++=g g，∴sin sin cos sin sin cos3sinA AB B B A C+++=，∴sin sin sin()3sinA B A B C+++=．又∵sin()sinA B C+=，∴sin sin2sinA B C+=，即a+b=2c，a=2b，所以32c b=，所以2222229414cos032422b b bb c aAbc b b+-+-===-<g，所以A为钝角，故ABC△为钝角三角形．………………………………（6分）（Ⅱ）解：因为1cos4A=-，∴15sin4A=．又1sin2ABCS bc A=△，∴11531524bc=，∴24bc=．又32c b=，所以23242b=，∴4b=．……………………………（12分）18．（本小题满分12分）解：（Ⅰ）由茎叶图可得：购买意愿强购买意愿弱合计20~40岁20 8 28 大于40岁10 12 22 合计30 20 50由列联表可得：250(2012108)= 3.46 3.841 30202822K⨯-⨯≈<⨯⨯⨯．所以，没有95%的把握认为市民是否购买该款手机与年龄有关．……………（6分）（Ⅱ）购买意愿弱的市民共有20人，抽样比例为51 204=，所以年龄在20~40岁的抽取了2人，记为a，b，年龄大于40岁的抽取了3人，记为A，B，C，图4从这5人中随机抽取2人，所有可能的情况为（a ，b ），（a ，A ），（a ，B ），（a ，C ），（b ，A ），（b ，B ），（b ，C ），（A ，B ），（A ，C ），（B ，C ），共10种，其中2人都是年龄大于40岁的有3种情况，所以概率为310． ………………（12分） 19．（本小题满分12分）（Ⅰ）证明：法一：如图，过点F 作FM //PA 交AB 于点M ，取AC 的中点N ，连接MN ，EN ． ∵点E 为CD 的中点，∴EN 12AD ．又3PF FB =，∴MF12AD ，∴FM EN ，所以四边形MFEN 为平行四边形，∴//EF MN ，∵EF ⊄平面ABC ，MN ⊂平面ABC ， ∴//EF 平面ABC ．………………（6分）法二：如图，取AD 中点G ，连接GE ，GF ，则GE //AC ，GF //AB ，因为GE ∩GF =G ，AC ∩AB =A ，所以平面GEF //平面ABC ，所以EF //平面ABC ．……………………（6分）（Ⅱ）解：∵PA ⊥平面ABC ，∴PA BC ⊥．又BC AB AB PA A ⊥=I ，， ∴BC ⊥平面PAB ．又602BAC AC ∠=︒=，，∴132AB BC BD ===，，， ∴1622BCD S BC BD ==g △．记点P 到平面BCD 的距离为d ，则P BCD C PBD V V --=，∴1133BCD PBD S d S BC =g g △△，∴612222d PD AB BC d =⇒=g g g ，所以，点P 到平面BCD 的距离为22d =． ……………………（12分）20．（本小题满分12分）解：（Ⅰ）由题知2322pp +==，，所以抛物线方程为：24y x =．…………………………（4分）（Ⅱ）设切线方程为：00()y y k x x -=-，令y =0，解得00y x x k=-，所以切线与x 轴的交点为000y x k ⎛⎫- ⎪⎝⎭，，圆心(2，0)到切线的距离为002|2|21k y kx d k +-==+，∴2200(2)4(1)k y kx k +-=+，整理得：22200000(4)(42)40x x k y x y k y -+-+-=．设两条切线的斜率分别为12k k ，，则20000121222000024444x y y y k k k k x x x x --+==--g ，， ∴2200012000012120112221PABy y x k k S x x y y k k k k x ⎛⎫⎛⎫-=---== ⎪ ⎪-⎝⎭⎝⎭g △ 200000(1)2(1)1122(1)2.11x x x x x ⎡⎤-+-+==-++⎢⎥--⎣⎦记01[4)t x =-∈+∞，，则1()2f t t t=++．∵22211()10t f t t t -'=-=>，∴()f t 在[4)+∞，上单增，∴125()4244f t ++=≥，∴2525242PAB S ⨯=△≥， ∴PAB △面积的最小值为252． …………………………………………（12分）21．（本小题满分12分）解：（Ⅰ）∵()e x f x x a '=--，∴(0)11f a '=-=，∴0a =， ∴()e x f x x '=-，记()e x g x x =-，∴()e 1x g x '=-，当x <0时，()0()g x g x '<，单减；当x >0时，()0()g x g x '>，单增， ∴min ()(0)10g x g ==>，故()0f x '>恒成立，所以()f x 在()-∞+∞，上单调递增．…………………（4分）（Ⅱ）∵()e x f x x a '=--，令()e x g x x a =--，∴()e 1x g x '=-，当0x ≥时，()0g x '≥，∴()g x 在[0)+∞，上单增，∴min ()(0)1g x g a ==-． i ）当10a -≥即1a ≤时，()0g x ≥恒成立，即()0f x '≥，∴()f x 在[0)+∞，上单增， ∴2min()(0)10222a f x f a ==-⇒-≥≤≤，所以21a -≤≤．ii ）当10a -<即1a >时，∵()g x 在[0)+∞，上单增，且(0)10g a =-<，当21e 2a <<-时，(ln(2))2ln(2)0g a a +=-+>， ∴0(0ln(2))x a ∃∈+，使0()0g x =，即00e x x a =+．当0(0)x x ∈，时，()0g x <，即()0()f x f x '<，单减；当0()x x ∈+∞，时，()0g x >，即()0()f x f x '>，单增．∴0000022min 00111()()e ()e e e 1e 0222x x x x x f x f x x a ⎛⎫==-+=-=- ⎪⎝⎭≥，∴00e 20ln 2x x ⇒<≤≤，由00e x x a =+，∴00e x a x =-．记()e (0ln 2]x t x x x =-∈，，，∴()e 10x t x '=->，∴()t x 在(0ln 2]，上单调递增， ∴()(ln 2)2ln 2t x t =-≤，∴12ln 2a <-≤．综上，[22ln 2]a ∈-，．…………………………（12分）22．（本小题满分10分）【选修4−4：坐标系与参数方程】解：（Ⅰ）由题意知，曲线1C 的参数方程为1cos sin x t y t ⎨=+=⎧⎩，，(t 为参数)，∴曲线1C 的普通方程为22(1)1x y -+=，∴曲线1C 的极坐标方程为=2cos ρθ． ……………………………（4分）（Ⅱ）设点P ，Q 的极坐标分别为11()ρθ，，22()ρθ，，则由111π=3=2cos θρθ⎧⎪⎨⎪⎩，，可得P 的极坐标为π13⎛⎫ ⎪⎝⎭，．由222π=3π2cos =336θρθ⎧⎪⎪⎨⎛⎫⎪- ⎪⎪⎝⎭⎩，可得Q 的极坐标为π33⎛⎫ ⎪⎝⎭，．∵12θθ=，∴12||||2PQ ρρ=-=，又M 到直线l 的距离为32， ∴133=2=222MPQ S ⨯⨯△． ……………………………（10分） 23．（本小题满分10分）【选修4−5：不等式选讲】解：（Ⅰ）∵()|1|2|1|f x x x =+--， ∴31()311131x x f x x x x x -<-⎧⎪=--⎨⎪-+>⎩，，，，，，≤≤∴()f x 的图象与x 轴围成的三角形的三个顶点分别为103A ⎛⎫⎪⎝⎭，，(30)B ，，(12)C ，，∴1882=233ABC S =⨯⨯△， ∴()f x 的图象与x 轴围成的三角形面积是83．……………………（5分）（Ⅱ）∵(0)s ∀∈+∞，，2444()4s as g s s a s a a s s s-+==+-⨯-=-≥，∴当且仅当2s =时，()g s 有最小值4a -．又由（Ⅰ）可知，对(0)t ∀∈+∞，，()(1)=2f t f ≤． (0)s t ∀∈+∞，，恒有()()g s f t ≥成立，等价于(0)s t ∀∈+∞，，，min max ()()g s f t ≥，等价于42a -≥，即2a ≤， ∴实数a 的取值范围是(2]-∞，．………………………………（10分）。

云南省师范大学附属中学高三上学期高考适应性考试月考

云南师大附中2017届高考适应性月考卷（二）英语参考答案第一部分：听力（共两节，满分30分）1~5 BBCCA 6~10 CAABA 11~15 CCBAB 16~20 ABCAA 第二部分：阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）21~25 BBDCC 26~30 CBDBB 31~35 CBBAC第二节（共5小题；每小题2分，满分10分）36~40 CAGEB第三部分：英语知识运用（共两节，满分45分）第一节：完形填空（共20小题；每小题1.5分，满分30分）41~45 ABBBD 46~50 CCAAD 51~55 BDACC 56~60 DCBAC 第二节（共10小题；每小题1.5分，满分15分）61．and 62．which/that 63．specialties 64．moving 65．to explore 66．a 67．on 68．spoken 69．Additionally 70．it第四部分：写作（共两节，满分35分）第一节：短文改错（共10小题；每小题1分，满分10分）Children have their own rules in playing games．They seldom need the referee and rarely trouble①ato keeping scores．We don’t care much about who wins or loses，but it do esn’t seem to worry them②keep ③They ④andif the game is not finished．Yet，they like games that depend a lot of on luck，so that their personal abilities⑤cannot∧directly compared．They also enjoy games that move in stage，in which each stage，the⑥be ⑦stageschoosing of leaders，the picking-up of sides，or the deciding of which side shall started，is almost⑧starta game itself．Grown-ups can hard find childre n’s games exciting，and they often feelpuzzled at⑨hardlyhow their kids play such simple games again and again．⑩why第二节：书面表达（满分25分）【参考范文】Dear Issac，I remember you are interested in teaching in China．Recently I have startedan English-dedicated school．Our school now is looking for a native-speaker to teach some courses，which are related to spoken and written English．And the courses are intended for local undergraduate students．If you accept our teaching offer，you will be allowed flexibility in organizing your syllabus，and teaching 12 hoursa week．Your guaranteed wage would be 200 RMB per hour．The students who are goingto take these courses have at least nine years of English learning experience．Besides，you would also work as an adviser for either our Students English club or the Students English Newspaper Department．The choice would be yours．Please let me know if you are interested or if you have any other questions，I’d be more than happy to help．Best regards，Li Hua 【解析】第二部分：阅读理解第一节A【语篇导读】本文是一篇记叙文。

云南省云南师范大学附属中学2017届高三高考适应性月考(五)文数试题 Word版含答案

云南省师范大学附属中学2017届高三高考适应性月考（五）文科数学试卷第Ⅰ卷（共60分）一、选择题：本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.1.集合2{|0}{|2}A x x a B x x =-≤=<，，若A B ⊆，则实数a 的取值范围是（） A ．(,4]-∞ B ．(,4)-∞ C ．[0,4] D ．(0,4)2.复数31i z i =-，则其共轭复数z 在复平面内对应的点位于（）A ．第一象限B ．第二象限C ．第三象限D ．第四象限3.某班有学生60人，将这60名学生随机编号为1-60号，用系统抽样的方法从中抽出4名学生，已知3号、33号、48号学生在样本中，则样本中另一个学生的编号为（） A ．28 B ．23 C ．18 D ．134.已知,x y 满足10,0,40,x x y x y -≥⎧⎪-≤⎨⎪+-≥⎩，则目标函数3z x y =+的最小值是（）A ．4B ．6 C. 8 D ．10 5.下列说法正确的是（）A ．“1x <”是“2log (1)1x +<”的充分不必要条件B ．命题“0x ∀>，21x>”的否定是“00021xx ∃≤≤，” C.命题“若a b ≤，则22ac bc ≤”的逆命题为真命题 D ．命题“若5a b +≠，则2a ≠或3b ≠”为真命题6.秦九韶算法是南宋时期数学家秦九韶提出的一种多项式简化算法，即使在现代，它依然是利用计算机解决多项式问题的最优算法，即使在现代，它依然是利用计算机解决多项式问题的最优算法，其算法的程序框图如图所示，若输入的012,,,,n a a a a 分别为0,1,2,,n ，若5n =，根据该算法计算当2x =时多项式的值，则输出的结果为（）A ．248B ．258 C.268 D ．278 7.已知函数()|sin |cos f x x x =•，则下列说法正确的是（） A ．()f x 的图象关于直线对称2x π=B ．()f x 的周期为πC.若12|()||()|f x f x =，则122()x x k k Z π=+∈ D ．()f x 在区间3[,]44ππ上单调递减8.在棱长为2的正方体1111ABCD A B C D -中任取一点M ，则满足90AMB ∠>°的概率为（） A ．24πB ．12πC.8πD ．6π9.某几何体的三视图如图所示，则该几何体的体积为（）A ．8B ．62 C.2 D ．4 10.已知函数322()()3f x x ax a b x c =+--+的两个极值点分别为12,x x ，且12(,1),(1,0)x x ∈-∞-∈-，点(,)P a b 表示的平面区域为D ，若函数log (2)(0,1)m y x m m =+>≠的图象经过区域D ，则实数m 的取值范围是（）A ．(3,)+∞B ． [3,)+∞ C. (1,3) D ．(1,3]11.椭圆22221(0)x y a b a b+=>>，12,F F 为椭圆的左、右焦点，O 为坐标原点，点P 为椭圆上一点，||OP =，且123||,||,||PF PF PF 成等比数列，则椭圆的离心率为（）A B 12.四面体PABC 的四个顶点都在球O 的球面上，84PA BC PB PC AB AC =====，，，且平面PBC ⊥平面ABC ，则球O 的表面积为（）A ．64πB ．65π C.66π D ．128π第Ⅱ卷（共90分）二、填空题（每题5分，满分20分，将答案填在答题纸上）13.已知函数3()xf x e x =+，若2()(32)f x f x <-，则实数x 的取值范围是． 14.点P 是圆22(3)(1)2x y ++-=上的动点，点(2,2)Q ，O 为坐标原点，则OPQ ∆面积的最小值是．15.已知数列{}n a 满足11a =，22a =，22(1sin )cos22n n n n a a n ππ+=++•，则该数列的前20项和为．16.抛物线22(0)x py p =>上一点)(1)A m m >到抛物线准线的距离为134，点A 关于y 轴的对称点为B ，O 为坐标原点，OAB ∆的内切圆与OA 切于点E ，点F 为内切圆上任意一点，则OE OF •的取值范围为．三、解答题（本大题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤.）17. （本小题满分12分）在ABC ∆中，角A ，B ，C 的对边分别为a ，b ，c ，已知223cos cos 2222B A a b c a b +==，．（1）证明：ABC ∆为钝角三角形；（2）若ABC ∆的面积为315，求b 的值． 18. （本小题满分12分）某公司即将推车一款新型智能手机，为了更好地对产品进行宣传，需预估市民购买该款手机是否与年龄有关，现随机抽取了50名市民进行购买意愿的问卷调查，若得分低于60分，说明购买意愿弱；若得分不低于60分，说明购买意愿强，调查结果用茎叶图表示如图所示.（1）根据茎叶图中的数据完成22⨯列联表，并判断是否有95%的把握认为市民是否购买该款手机与年龄有关？（2）从购买意愿弱的市民中按年龄进行分层抽样，共抽取5人，从这5人中随机抽取2人进行采访，求这2人都是年龄大于40岁的概率.附：22()()()()()n ad bc k a b c d a c b d -=++++.19. （本小题满分12分）如图，三棱锥P ABC -中，PA ⊥平面ABC ，90ABC ∠=°，2PA AC ==，D 是PA 的中点，E 是CD 的中点，点F 在PB 上，3PF FB =.（1）证明：//EF 平面ABC ；（2）若60BAC ∠=°，求点P 到平面BCD 的距离. 20. （本小题满分12分）已知抛物线2:2(0)C y px p =>，圆22:(2)4M x y -+=，圆心M 到抛物线准线的距离为3，点000(,)(5)P x y x ≥是抛物线在第一象限上的点，过点P 作圆M 的两条切线，分别与x 轴交于,A B 两点. （1）求抛物线C 的方程；（2）求PAB ∆面积的最小值. 21. （本小题满分12分）已知函数21()()2x f x e x a =-+. （1）若曲线()y f x =在点0x =处的切线斜率为1，求函数()f x 的单调区间；（2）若0x ≥时，()0f x ≥恒成立，求实数a 的取值范围.请考生在22、23两题中任选一题作答，如果多做，则按所做的第一题记分.22. （本小题满分10分）选修4-4：坐标系与参数方程在直角坐标系xOy 中，将曲线1cos :1sin 2x t C y t =+⎧⎪⎨=⎪⎩（t 为参数）上每一点的横坐标保持不变，纵坐标变为原来的2倍，得到曲线1C ；以坐标原点O 为极点，以x 轴的正半轴为极轴建立极坐标系，曲线2C 的极坐标方程为2cos()336πρθ-=.（1）求曲线1C 的极坐标方程；（2）已知点(1,0)M ，直线l 的极坐标方程为3πθ=，它与曲线1C 的交点为O ，P ，与曲线2C 的交点为Q ，求MPQ ∆的面积.23. （本小题满分10分）选修4-5：不等式选讲已知函数()|1|2|1|f x x x =+--.（1）求()f x 的图象与x 轴围成的三角形面积；（2）设24()x ax g x x-+=，若对(0,)s t ∀∈+∞，恒有()()g s f t ≥成立，求实数a 的取值范围.云南师大附中2017届高考适应性月考卷（五）文科数学参考答案第Ⅰ卷（选择题，共60分）一、选择题（本大题共12小题，每小题5分，共60分）题号 1 2 3 4 5 6 7 8 9 10[ 11 12 答案 BCCBDBDAACDB1．当0a <时，集合A =∅，满足题意；当0a ≥时，[]A a a =-，，若A B ⊆，则2a <，∴0<4a ≤，所以(4)a ∈-∞，，故选B ． 2．∵i 1i i 12z --+==-，其共轭复数为1i 2z --=，对应点为1122⎛⎫-- ⎪⎝⎭，在第三象限，故选C ． 3．抽样间隔为15，故另一个学生的编号为3+15=18，故选C ．4．画出可行域如图1所示，当目标函数3y x z =-+经过点A (1，3)时，z 的值为6；当目标函数3y x z =-+经过点B (2，2)时，z 的值为8，故选B ．5．选项A ：2log (1)101211x x x +<⇔<+<⇔-<<，所以“1x <”是其必要不充分条件；选项B ：命题“021x x ∀>>，”的否定是“00021x x ∃>，≤”；选项C ：命题“若a b ≤，则22ac bc ≤”的逆命题是“若22ac bc ≤，则a b ≤”，当c =0时，不成立；选项D ：其逆否命题为“若2a =且3b =，则5a b +=”为真命题，故原命题为真，故选D ． 6．该程序框图是计算多项式5432()5432f x x x x x x =++++当x =2时的值，故选B ． 7．作出函数()f x 在区间[02π]，上的图象，由已知，函数()f x 在区间[02π]，上的解+析式为1sin 20π2()1sin 2π2π2x x f x x x ⎧⎪⎪=⎨⎪-<⎪⎩，，，，≤≤≤且()f x 是偶函数，画出图象可知，故选D ．图18．以AB 为直径作球，球在正方体内部的区域体积为14ππ433V =⨯=，正方体的体积为8，所以π24P =，故选A ． 9．由三视图还原出该几何体为长方体切去一部分，如图所示，所以剩余部分体积为222383V =⨯⨯⨯=，故选A ．10．由2()22()f x x ax a b '=+--，故()0f x '=的两根分别为12x x ，，由二次方程根的分布得248()0(1)0(0)0a a b f f ⎧+->⎪'-<⎨⎪'>⎩，，，即223200a b a a b a b ⎧<+⎪⎪⎪-->⎨⎪-<⎪⎪⎩，，，画出该不等式组所表示的平面区域D ，当函数log (2)m y x =+的图象经过点(1，1)时，m =3，因此当13m <<时函数图象经过区域D ，故选C.11．设()P x y ，，则2222||8a OP x y =+=，由椭圆定义，2121||||2||PF PF a PF +=⇒+22||PF2122||||4PF PF a +=，又∵1122||||||PF F F PF ，，成等比数列，∴12||||PF PF = 2212||4F F c =，∴222212||||84PF PF c a ++=，∴222()()x c y x c +++-22284y c a ++=，整理得222252x y c a ++=，即222223652884a c c c a e a a +=⇒=⇒==，故选D ．12．如图，D ，E 分别为BC ，PA 的中点，易知球心O 点在线段DE 上，因为PB =PC =AB =AC ，则PD BC AD BC PD AD ⊥⊥=，，．又∵平面PBC ⊥平面ABC ，平面PBC平面ABC =BC ，∴PD ⊥平面ABC ，∴PD AD ⊥，∴PD =42AD =．因为E 点是PA 的中点，∴ED PA ⊥，且DE =EA =PE =4．设球O 的半径为R ，OE =x ，则OD =4−x ，在Rt OEA △中，有2216R x =+，在Rt OBD △中，有224(4)R x =+-，解得2654R =，所以24π65πS R ==，故选B ．图3图2第Ⅱ卷（非选择题，共90分）二、填空题（本大题共4小题，每小题5分，共20分）题号 13[学*科 14 15 16答案 (12)，21033[333+3]-，13．因为2()e 30x f x x '=+>，所以函数f (x )为增函数，所以不等式2()(32)f x f x <-等价于232x x <-，即232012x x x -+<⇔<<，故(12)x ∈，．14．因为||2OQ =OQ 的方程为y =x ，圆心(31)-，到直线OQ 的距离为|31|222d --=所以圆上的动点P 到直线OQ 的距离的最小值为2222-=所以OPQ △面积的最小值为12222⨯=．15．当n 为奇数时，22n n a a +=，故奇数项是以11a =为首项，公比为2的等比数列，所以前20项中的奇数项和为10101221102312S -==-=-奇；当n 为偶数时，22(1)nn n a a n +=+-，前20项中的偶数项和为=10S 偶，所以201023101033S =+=． 16．因为点(3)A m ，在抛物线上，所以3322pm m p=⇒=，点A 到准线的距离为313224p p +=，解得12p =或6p =．当6p =时，114m =<，故6p =舍去，所以抛物线方程为2x y =，∴(33)(33)A B -，，，，所以OAB △是正三角形，边长为23，其内切圆方程为22(2)1x y +-=，如图4，∴3322E ⎫⎪⎪⎭，．设点(cos 2sin )F θθ+，（θ为参数），则33π3sin 33226OE OF θθθ⎛⎫=++=++ ⎪⎝⎭， ∴[3333]OE OF ∈，．三、解答题（共70分．解答应写出文字说明，证明过程或演算步骤）17．（本小题满分12分）（Ⅰ）证明：由正弦定理：1cos1cos3sin sin sin222B AA B C+++=，∴sin sin cos sin sin cos3sinA AB B B A C+++=，∴sin sin sin()3sinA B A B C+++=．又∵sin()sinA B C+=，∴sin sin2sinA B C+=，即a+b=2c，a=2b，所以32c b=，所以2222229414cos032422b b bb c aAbc b b+-+-===-<，所以A为钝角，故ABC△为钝角三角形．………………………………（6分）（Ⅱ）解：因为1cos4A=-，∴15sin4A=．又1sin2ABCS bc A=△，∴11531524=，∴24bc=．又32c b=，所以23242b=，∴4b=．……………………………（12分）18．（本小题满分12分）解：（Ⅰ）由茎叶图可得：购买意愿强购买意愿弱合计20~40岁20 8 28 大于40岁10 12 22 合计30 20 50由列联表可得：250(2012108)= 3.46 3.841 30202822K⨯-⨯≈<⨯⨯⨯．所以，没有95%的把握认为市民是否购买该款手机与年龄有关．……………（6分）（Ⅱ）购买意愿弱的市民共有20人，抽样比例为51 204=，所以年龄在20~40岁的抽取了2人，记为a，b，年龄大于40岁的抽取了3人，记为A，B，C，图4从这5人中随机抽取2人，所有可能的情况为（a ，b ），（a ，A ），（a ，B ），（a ，C ），（b ，A ），（b ，B ），（b ，C ），（A ，B ），（A ，C ），（B ，C ），共10种，其中2人都是年龄大于40岁的有3种情况，所以概率为310． ………………（12分） 19．（本小题满分12分）（Ⅰ）证明：法一：如图，过点F 作FM //PA 交AB 于点M ，取AC 的中点N ，连接MN ，EN ． ∵点E 为CD 的中点，∴EN 12AD ．又3PF FB =，∴MF12AD ，∴FM EN ，所以四边形MFEN 为平行四边形，∴//EF MN ，∵EF ⊄平面ABC ，MN ⊂平面ABC ， ∴//EF 平面ABC ．………………（6分）法二：如图，取AD 中点G ，连接GE ，GF ，则GE //AC ，GF //AB ，因为GE ∩GF =G ，AC ∩AB =A ，所以平面GEF //平面ABC ，所以EF //平面ABC ．……………………（6分）（Ⅱ）解：∵PA ⊥平面ABC ，∴PA BC ⊥．又BC AB ABPA A ⊥=，，∴BC ⊥平面PAB ．又602BAC AC ∠=︒=，，∴132AB BC BD ===，，， ∴1622BCD S BC BD ==△．记点P 到平面BCD 的距离为d ，则P BCD C PBD V V --=，∴1133BCD PBD S d S BC =△△，12d PD AB BC d =⇒=，所以，点P 到平面BCD 的距离为d =． ……………………（12分）20．（本小题满分12分）解：（Ⅰ）由题知2322pp +==，，所以抛物线方程为：24y x =．…………………………（4分）（Ⅱ）设切线方程为：00()y y k x x -=-，令y =0，解得00y x x k=-，所以切线与x 轴的交点为000y x k ⎛⎫- ⎪⎝⎭，，圆心(2，0)到切线的距离为2d ==，∴2200(2)4(1)k y kx k +-=+，整理得：22200000(4)(42)40x x k y x y k y -+-+-=．设两条切线的斜率分别为12k k ，，则20000121222000024444x y y y k k k k x x x x --+==--，， ∴2200012000012120112221PABy y x k k S x x y y k k k k x ⎛⎫⎛⎫-=---== ⎪ ⎪-⎝⎭⎝⎭△200000(1)2(1)1122(1)2.11x x x x x ⎡⎤-+-+==-++⎢⎥--⎣⎦记01[4)t x =-∈+∞，，则1()2f t t t=++．∵22211()10t f t t t -'=-=>，∴()f t 在[4)+∞，上单增，∴125()4244f t ++=≥，∴， ∴PAB △面积的最小值为252． …………………………………………（12分）21．（本小题满分12分）解：（Ⅰ）∵()e x f x x a '=--，∴(0)11f a '=-=，∴0a =， ∴()e x f x x '=-，记()e x g x x =-，∴()e 1x g x '=-，当x <0时， ()0()g x g x '<，单减；当x >0时，()0()g x g x '>，单增， ∴min ()(0)10g x g ==>，故()0f x '>恒成立，所以()f x 在()-∞+∞，上单调递增．…………………（4分）（Ⅱ）∵()e x f x x a '=--，令()e x g x x a =--，∴()e 1x g x '=-，当0x ≥时，()0g x '≥，∴()g x 在[0)+∞，上单增，∴min ()(0)1g x g a ==-． i ）当10a -≥即1a ≤时，()0g x ≥恒成立，即()0f x '≥，∴()f x 在[0)+∞，上单增，∴2min()(0)102a f x f a ==-⇒≥，所以1a ≤．ii ）当10a -<即1a >时，∵()g x 在[0)+∞，上单增，且(0)10g a =-<，当21e 2a <<-时，(ln(2))2ln(2)0g a a +=-+>， ∴0(0ln(2))x a ∃∈+，使0()0g x =，即00e x x a =+．当0(0)x x ∈，时，()0g x <，即()0()f x f x '<，单减；当0()x x ∈+∞，时，()0g x >，即()0()f x f x '>，单增．∴0000022min 00111()()e ()e e e 1e 0222x x x x x f x f x x a ⎛⎫==-+=-=- ⎪⎝⎭≥，∴00e 20ln 2x x ⇒<≤≤，由00e x x a =+，∴00e x a x =-．记()e (0ln 2]x t x x x =-∈，，，∴()e 10x t x '=->，∴()t x 在(0ln 2]，上单调递增， ∴()(ln 2)2ln 2t x t =-≤，∴12ln 2a <-≤．综上，[2ln 2]a ∈-．…………………………（12分）22．（本小题满分10分）【选修4−4：坐标系与参数方程】解：（Ⅰ）由题意知，曲线1C 的参数方程为1cos sin x t y t ⎨=+=⎧⎩，，(t 为参数)，∴曲线1C 的普通方程为22(1)1x y -+=，∴曲线1C 的极坐标方程为=2cos ρθ． ……………………………（4分）（Ⅱ）设点P ，Q 的极坐标分别为11()ρθ，，22()ρθ，，则由111π=3=2cos θρθ⎧⎪⎨⎪⎩，，可得P 的极坐标为π13⎛⎫ ⎪⎝⎭，．由222π=3π2cos 6θρθ⎧⎪⎪⎨⎛⎫⎪- ⎪⎪⎝⎭⎩，可得Q 的极坐标为π33⎛⎫ ⎪⎝⎭，．∵12θθ=，∴12||||2PQ ρρ=-=，又M 到直线l，∴1=2MPQ S △． ……………………………（10分） 23．（本小题满分10分）【选修4−5：不等式选讲】解：（Ⅰ）∵()|1|2|1|f x x x =+--， ∴31()311131x x f x x x x x -<-⎧⎪=--⎨⎪-+>⎩，，，，，，≤≤∴()f x 的图象与x 轴围成的三角形的三个顶点分别为103A ⎛⎫⎪⎝⎭，，(30)B ，，(12)C ，，∴1882=233ABC S =⨯⨯△， ∴()f x 的图象与x 轴围成的三角形面积是83．……………………（5分）（Ⅱ）∵(0)s ∀∈+∞，，244()4s as g s s a a a s s -+==+--=-≥，∴当且仅当2s =时，()g s 有最小值4a -．又由（Ⅰ）可知，对(0)t ∀∈+∞，，()(1)=2f t f ≤． (0)s t ∀∈+∞，，恒有()()g s f t ≥成立，等价于(0)s t ∀∈+∞，，，min max ()()g s f t ≥，等价于42a -≥，即2a ≤， ∴实数a 的取值范围是(2]-∞，．………………………………（10分）。

云南省高考英语适应性月考试题(五)(扫描版)

云南省2017届高考英语适应性月考试题（五）（扫描版）云南师大附中2017届高考适应性月考卷（五）英语参考答案第一部分：听力（共两节，满分30分）1~5 BAABC 6~10 CCBAC 11~15 AABBC 16~20 BBCCA第二部分：阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）21~25 CDABD 26~30 CBACC 31~35 DABCB第二节（共5小题；每小题2分，满分10分）36~40 GCDFB第三部分：英语知识运用（共两节，满分45分）第一节：完形填空（共20小题；每小题1.5分，满分30分）41~45 ABCBA 46~50 CABAD 51~55 BCABA56~60 DBDCD第二节（共10小题；每小题1.5分，满分15分）61．as 62．and/where 63．published 64．latest 65．did66．toget 67．a 68．which69．assistant 70．have been working第四部分：写作（共两节，满分35分）第一节：短文改错（共10小题；每小题1分，满分10分）Yesterday was my father’s birthday．We made many preparation for it．Early in the morning，①preparationsmy mother and I set off for the department store to find∧gift for Father．We chose very careful，②a ③carefully eventually a warm sweater caught our eye but was purchased．④andTo showing my love for my father，I made a birthday cake under the help of my mother．In the⑤show ⑥withevening，we got together to celebrate her birthday．With candles lit，we sang happy birthday out loud⑦hisand clapped，that made the room alive with the sound of cheering．⑧whichThen we take a family photo to record the happy moment．When I saw tears of joy in Father’s eyes，⑨tookI was filled in with a feeling of accomplishment and happiness．⑩第二节：书面表达（满分25分）【参考范文】Dear Peter，How are you doing? Recently I can always catch sight of some of my classmates using mobile phones to copy the teacher’s lecture notes，their notebooks left behind．There exist different opinions on this issue．Some students hold the view that by taking notes with a mobile phone instead of taking notes by hand，they can save much time and effort，which can be used in studies efficiently．Many other students insist that though mobile phones are much easier for students to copy the teachers’ lecture notes，and also easier to search for certain content they need，they should not overlook the fact that mobile phones in the classroom can lead to laziness and distraction，which interferes with learning．For my part，on its own，mobile phone is neither good nor bad．It depends on how we use it．What we need to do is to make proper use of mobile phones．Yours，Li Hua【解析】第二部分：阅读理解第一节A【语篇导读】本文是一篇记叙文，讲述了作者在晨练的时候总会遇到一个老太太在湖边擦洗乌龟的故事，说明了如若每个人从身边的小事做起也能使这个世界大不同的道理。

云南省师范大学附属中学2017届高三高考适应性月考(六)英语.doc

云南省师范大学附属中学2017届高三高考适应性月考（六）英语试题本试卷第I 卷（选择题）和第II卷（非选择题）两部分，第I 卷第I 页至第7页，第II 卷第7页至第8页。

考试结束后，请将本试卷和答题卡一并交回。

满分120分，考试用时100分钟。

第I卷（选择题，共70分）注意事项：1.答题前，考生必用黑色碳素笔将自己的姓名、准考证号、考场号、座位号在答题卡上填写清楚。

2.每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，在选涂其他答案标号。

在试题卷上作答无效。

第一部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项，并在答题卡上将该项涂黑。

ADuring my third and fourth grade years, my family moved to Louisville, Kentucky. To our surprise we soon discovered the World’s Boxing Champion’s m other lived less than one mile from our home. Ali was my dad’s idol.During one of Ali’s visits to stay with his mother, my dad urged us to get in the car with his camera in hand. “Why?” we asked. “I know Ali is at his mother’s house. I want you boys to me et the champion!” he firmly replied.My brother hopped(单脚跳)in an I was seriously forced to get in. I was scared to be so stupid as to go to this big man’s childhood home. Ali had a tight schedule and limited time with his mom and, honestly my dad’s over-asser-tive manner embarrassed me.My brother was game(勇敢的); I was entirely too tame! I realized as a small potato my father was in his greatest strength. He killed fear by taking action in spite of it. Ali told my father that the was the “only cat” who was brave enough to knock on his mama’s door. I didn’t realize we were rude but we made it. The confident man who boxed and beat many big men down with his fistscouldn’t resist the same confidence of a man with a camera and his boy.Now looking a the picture of Ali’s big fist raised in good humor and against my brother’s left jaw, I thanked my dad for his devoting himself to bringing us up. My dad is a retired soldier and has a big heart. My brother is a lawyer and has won more cased of considerable currency t han he’s lost, of which my father is proud. Not being as good as my brother, I am now studying in the top university of the world. My dad learned that in order to be a champion you must be willing to hand with championsNow I recall when we got to Ali’s mom’s house, we kept knocking on the door but no one else replied. We knocked long enough and we realized our goal. If you knock long enough and wait patiently, the door of happiness will be open to you. People have peepholes(窥视孔)now, but don’t doubt your beliefs and if you must you will reach your goal.1. What do we know about the author before the visit?A. He was afraid that he was stupid and embarrassedB. He was afraid of calling on the famous man AliC. He was afraid that he couldn’t behave wellD. He was afraid that Ali wouldn’t meet them2. We can infer from the text that______.A. Ali and the author’s dad became friendsB. the author’s father only loved his brotherC. the author’s father was a successful businessmanD. the author’s brother was active while he was shy3. Why did the author’s father want to see Ali?A. He wanted his boys to learn from AliB. Ali was their neighbor and close relativeC. He wanted his children to learn about boxingD. Ali was one of his close fellows in the army4. What can we learn from the last paragraph?A. Be patient and perseverant, you will succeedB. It is very difficult for you to see a great manC. Visiting a great man is very important in lifeD. One should believe others can succeedBA California teen has attracted the attention of tech giants Google for her potentially revolutionary invention which charges a phone in 20 seconds flat.The super-fast charging device has been called a supercapacitor(超级电容器)by 18-year-old EshaKhare, of Saratoga—as she took $ 50,000 from the Intel International Science and Engineering Fair, which took place in Phoenix.The device will make waiting hours for a phone to charge a thing of the past and the invention packs energy into a smaller space than traditional phone batteries and holds the charge for longer.The supercapacitor is flexible and tiny, and is able to handle 10,000 recharge eyeles, more than normal batteries by a factor of 10. So far, Khare has only used her supereapacitor to power an LED—but she sees a bright future that one day will see her invention powering cell phones, cars and any device that requires a rechargeable battery.Heading to Harvard, Khare told CBS San Francisco that this is only the start and that she will be “ setting the world on fire” from here. “My cell phone battery always dies,” she told NBC News when asked what inspired her to work on the energy-storage technology. Specializing in nanochemistry(纳米化学) allowed Khare to reduce the size of her invention.EshaKhare, lon utBudisteanu and Henry Wangjune Lin got the top three prizes at this year’s IntclInernational Science and Engineening Fair in Phoenix. Khare explained her award-winning revolutionary invention. “ It is also flexible, so it can be used in rollup(卷曲)displays and clothing and fabric,” she added. “ It has different applications and advantages over batteries in that sense.”An 18-year-old girl has managed to figure out something that multi-national corporations have not. This has led to.5. The reason that the device attracted the attention of Google is that it______.A. can be bentB. can power carsC. can charge a phone in 20 secondsD. can handle 1,000 recharge cycles6. What inspired EshaKhare to invent the device?A. The market demandsB. Cash prize of $ 50,000C. Heavy weight of her cell phone B. Frequent death of her cell phone battery7. The underlined phrase “ setting the world on fire” in Paragraph 5 means_______A. meeting with many difficultiesB. making more breakthroughsC. improving her inventionD. troubling the world8. What can we infer about the future of EshaKhare’s device?A. It will have a brilliant futureB. It will be donated to the worldC. It will have narrow applicationsD. It will only be used in cell phonesCMary Cassatt, the only American to ever exhibit with the Impressionists, was raised at a time in the United States when the thought of a woman artist was considered unconventional. To study art seriously, learning from the model and working in a studio of one’s own, was nearly impossible for a woman of her social status. However, at the age of 22. in complete challenging of conventions, Cassatt moved to Paris in 1866, settling in the studio of Carlo Raimndi, a local professor of engraving (雕刻)and etching (蚀刻).Throughout her time in Paris, Cassatt built lasting bonds with many of the contemporary artists in France, and remained a lifelong friend and colleague of Degas’. In fact, it was Degas who invited Cassatt to exhibit with the Impressionists in 1877. Though she absorbed herself in the movement completely, and was even accepted equaled with the men of the group, she never overstepped the bounds of tradition. Her world was a charming and graceful one, limited to her circle of family and friendsCassatt’s subjects are chosen from her immediate environment, and her incomparable rendering(表达) of the mother and the child theme will always be considered her main contribution to the history of art. It is important to note, however, that her mothers and children are wholly of this world, and offer no religious suggestions. They are modern women portrayed with realistic honesty and directness, whose features compose a deep psychological portrait. Her style was very much influenced by the Japanese woodblock prints that she and Degas viewed in 1890 at the Ecole des Beaux-Arts. She adapted the stylistic characteristics of those works, erasing unnecessary details and changing her perspective, and translated it into her etchings Cassatt successfully made a place for herself in the history of art through her brave decisions and her remarkable performances. She is truly a master of the 19th century, and will always be considered an important component of Impressionist movement.9. What caused Cassatt to move to Paris in 1866?A. Escaping from the United StatesB. Meeting Professor Carlo RaimondiC. Learning art seriouslyD. Being invited by Carlo Raimondi to work in his studio10. The third paragraph is mainly about______.A. mother s and children featuresB. the subjects and style of Cassatt’s worksC. the effect of Japanese prints on CassattD. Cassatt’s contribution to the history of art11. What does the underlined word “ those” in Paragraph 3 refer to ?A. Japanese woodblock printsB. The Ecole des Beaux-Arts.C. Stylistic characteristicsD. Features.12. From the text we can learn that______.A. Cassatt was invited to exhibit with the Impressionists at 30B. Cassatt was a famous master of art in the 20th centuryC. Cassatt themes contributed a lot to the artD. Cassatt’s subjects were often honest and directD13. To participate in Mother Daugher Outdoors you______.A. must carry your own foodB. should be able to hunt or fishC. must be nine years oldD. need to do a lot of outdoor exercise14. Which event offers participants an opportunity to enjoy the natural wonder?A. Outdoor FestivalB. Mother Daughter OutdoorsC. Fishing Workshop at Bear Creek LakeD. Eastern Shore Birding and Wildlife Festival15. To find more information about a one-day family trip, you’d better send your e-mail to______.A. dunnavant @dgif.virginia. govB. moots @ dgif. virginia. govC. claybuster @ dgif.virginia. govD. info @ esvachamben. Org第二节（共．．．．．5．小题；每小题．．．．．．10．．分）．．．．．．2．分，满分根据短文内容，从短文后的选项中选出能填入空白处的最佳选项，并在答题卡上将该项涂黑。

【云南省师范大学附属中学】2017届高考适应性训练月考英语试卷(七)

云南省师范大学附属中学2017届高考适应性训练月考英语试卷（七）第Ⅰ卷（选择题共70分）第一部分阅读理解（共两节,满分40分）第一节（共15小题;每小题2分,满分30分）阅读下列短文,从每题所给的四个选项（A、B、C、D）中,选出最佳选项,并在答题卡上将该项涂黑.AIt seems the more time we have, the longer we put off living the life we see in our heads, because we feel like we’ve got some time to kill.I know where you think I’m going with this, and I also know you’ve heard it all before: seize the day, make the most of it, live life to its fullest, and so on. But that’s the problem. You’ve heard it all before. These ideas have their impact and have become a cliché. Luckily, that’s not my thing.The real answers wake something up inside you. They make you think. That’s what I want to give you today, the story of Bobby Darin, which wakes you up to the truth.If you haven’t heard of the man, I know you’ve heard his songs. Among his many hits are Mack the Knife, Beyond the Sea, Dream Lover, and Splish Splash.If seven years, Darin had several top ten hit songs, was nominated（提名）for four Grammy Awards（winning two）, nominated for four Golden Globes（winning one）, and even nominated for an Oscar.So what was his secret?All his life, Darin had a heart condition that developed from a childhood illness. The doctors at the time said he would be lucky to live to 16. In other words, his time was limited. And this was secret. He knew the truth. He knew that we all have such a hard time accepting: Life is short. You can’t just say it; you can’t just hear it. You have to know it, believe it, and feel it. Because Darin knew his time was limited, he packed as much life as he could into the time he had. But he had an unfair advantage. He knew, without a doubt, his time was limited.There was no fooling himself, no putting it off. It was now or never.1．Why do we all have the habit of delaying doing things? ________A．Because we think we have time to count our thumb.B．Because we want to live our life to its fullest.C．Because we think time and tide wait for no man.D．Because it takes time to build castle.2．The underlined word “cliché” in the second paragraph probably means? ________A．mottoB．legendC．often-made remarkD．long-lost verse3．What can we know about Bobby Darin from the passage? ________A．He was nominated and won the Oscar Reward.B．He committed suicide at home at last.C．He got involved I not only music field but directing.D．He took a positive attitude towards his illness.4．What is the secret to Bobby Darin’s success? ________A．He knew his life expectancy was short.B．He was too eager to become famous.C．He was so devoted to music.D．He was talented.BQueensland is one of the most amazing states in Australia. It has some of the most beautiful natural scenery on the planet, with the Great Barrier Reef, rainforests and impressive beaches.The Great Barrier ReefIt is one of the world’s largest natural features. It stretches more that 2, 300 km along the north eastern coast of Australia from the northern tip of Queensland to just north of Bundaberg. The things that most surprise visitors to the reef are the colors.Without doubt, the best way to see the Great Barrier Reef is by diving. If you have a little extra money and you are feeling a bit lazy, you can fly over the reef in a plane.Fraser IslandAnother area of natural beauty is Fraser Island. This is the world’s largest sand island. It’s best visited from Hervey Bay on the mainland, where there are a number of places offering trips around the island. To fully appreciate Fraser Island you should go for three or four days. Attractions include some beautiful fresh-water lakes, particularly Lake Wabby and Lake Mckenzie. You can walk around these on white sands untouched by human footprints. Indian Head also has some beautiful views. Braver travelers can go and watch sharks circling the water hundreds of meters below.The Whitsunday IslandsIt would be a pity to travel around Queensland without taking a trip around the Whitsunday Islands. They were named by Captain Cook in 1 770, after the day on which he arrived. Here are some of the great things you can do there.●Cruise around them on a relaxing trip.●Take a sailing course.●Look at the aboriginal（土著的）paintings in caves on Hook Island.●Have fun in the water doing lots of water sports.So, will you be going to Queensland?5．The best way to admire the beauty of the Great Barrier Reef is ________A．diving in the seaB．taking a boatC．flying in a planeD．driving6．What can we infer from Fraser Island? ________A．Few places on the mainland can offer trips around the island.B．One should have at least 2days to fully explore Fraser Island.C．Lake Wabby and Lake Mckenzie are rarely visited places.D．Only brave ones can watch sharks in the deep ocean.7．If you want to learn sailing, you can go to ________A．Hook IslandB．The Whitsunday IslandsC．Fraser IslandD．the Great Barrier Reef8．The purpose of writing this passage is ________A．to adverse for QueenslandB．to inform the latest newsC．to call on people to protect QueenslandD．to break a world recordCWhile the U. S. is still debating about getting rid of the penny, Sweden is rapidly moving towards abolishing currency altogether. Though this may sound radical（过激的）, it is a natural evolution in this digital society.Sweden, which was the first European country to introduce banknotes in 1661, has just been working harder to convince its residents that digital payments are a safer alternative to carrying cash.Over the years, the idea has gained popularity with residents, especially the younger generation that is much more comfortable with technology. Today many banks don’t even have ATMs and some have stopped handling cash altogether!Tickets to ride public buses in most Swedish cities can only be purchased via cell phones. Numerous businesses are also moving towards accepting only digital payments. Even the homeless that sell street paper to make ends meet have to start accepting this mode of payment!But despite its growing popularity, some people don’t like this radical idea. They include the homeless, elderly people as well as those living in rural areas who are still uncomfortable with mobile phones and computers. But the officials are confident that in the very near future, they will be able to convince everyone to move this safe and more cost-effective payment system.Sweden is not the only country trying to abolish paper currency and coins. The movement is rapidly gainingground in Denmark and Finland as well. In 2014, Israel announced a three-step plan to go cashless and just last week the vendors（小贩）of a popular street in Sydney declared they would stop accepting currency from customers. Whether this phenomenon spreads remains to be seen. But one thing is for sure—With increasingly advanced payment systems being introduced every day, pulling out cash is rapidly becoming “uncool”.9．What can we infer from Paragraph 3and 4? ________A．Many banks in Sweden don’t have ATMs.B．You don’t have to buy tickets when riding buses.C．People don’t give the homeless money but food.D．People can just take cell phones when shopping.10．According to the passage, which information is RIGHT? ________A．Sweden was the first country to get the idea to abolish currency.B．The younger generation is opposed to the measures.C．Bus fare can only be purchased via cell phones in most Swedish cities.D．Banks in Sweden have stopped dealing with cash completely.11．Which of the following can be the best title for the text? ________A．An Advanced Country –SwedenB．A Controversial Government PolicyC．Sweden to Influence the World’s Cash PaymentD．Sweden to Become the World’s First Cashless Society12．Which of the following categories does this passage belong to? ________A．Education.B．Economy.C．Travel.D．Insurance.DAugusto Esquivel is a sculptor who, in his own words, is “crazy with comparisons of reality and potential and the balance between them.” Perhaps the best example of what he’s talking about are his most famous creations: the suspended（悬挂的）button sculptures.Made entirely from buttons hanging on various lengths of string, Esquivel’s sculptures are made to look like common objects: a piano, a gumball machine, and even a toilet. If it wasn’t for the clear string hanging above, these objects, these sculptures, would look solid, yet you can put your hands right through them. The process starts with him deciding on a subject and setting the acrylic（丙烯酸树脂）from where the buttons are being suspended. He buys buttons of different shapes and sizes, paints them with spray paint, and carefully hangs them. After that, it’s a manner of hanging each individual button, which takes a lot of time. For his piano, for example, he individually hung over 60 pounds worth of tiny buttons.Esquivel’s sculptures, while mostly housed inside art galleries, perfectly capture one of the main principles ofstreet art: something that is eye-catching and something that invites interaction. Often the best sculptures outside the art galleries aren’t the ones behind guards and fencing, but the ones people can go right up to and touch. In Vancouver, a series of laughing old men are attracting people for pictures and to just generally hang around, but the people who simply walk by and see the sculptures almost always leave with a smile on their face. That’s good street art: it draws the viewer in rather than relying on a gallery to draw in an audience and point them to certain pieces.Esquivel’s art is not only a presentation of talent, something that mentions larger philosophical questions, like the ones he stated above, but also just the right combination of interesting idea and painstaking work. One can look at his work in a critical way, or simply appreciate his idea and execution（艺术品的制作）.13．What are Esquivel’s sculptures mainly made of? ________A．Clay.B．Iron.C．Gum.D．Buttons.14．Which statement is WRONG according to Paragraph 3? ________A．Some of Esquivel’s sculptures are displayed outside art galleries.B．Esquivel’s art is good street art.C．People can’t touch Esquivel’s sculptures involve interaction.D．Esquivel’s sculptures can catch people’s eye and involve interaction.15．Which of the following in NOT what Esquivel’s art wants to present? ________A．Talent.B．Idealism.C．Philosophical questions.D．Painstaking work.第二节（共5小题;每小题2分,满分10分）根据短文内容,从短文后的选项中选出能填入空白处的最佳选项.选项中有两项为多余选项.London has become a cycle-friendly zone after the launch of a new bike hire scheme. 1617 First you have to sign up to the scheme to be sent a key. The key will unlock one of the bikes, which are kept at docking stations in and around central London. You have to pay an access fee for the key and then you pay as you go, for the length of time you use the bike.Transport for London, which runs the scheme, are hoping to have 6, 000 bikes and 400 docking stations in place by the end of the year. 18 London Mayor Boris Johnston launched the scheme and said London has been “fi lled with thousands of gleaming（发光的）machines that will transform the look and feel of our street and become as commonplace on our roads as b lack cabs and red buses”.19 On the first day some people found they couldn’t dock their bike properly and their usage of the bike had not registered. Transport for London did admit they had been expecting a few “teething problems” and have said they would not charge for the first day as a “gesture of goodwill”. Some other people have criticized the lack ofdocking stations and locks for the bikes as well as the price it costs to hire the bicycles.“My crusade for the capital to become the grea test big cycling city in the world has taken a great20pedal-powered push forwards.” A ．So how does it work? B ．How do you like it?C ．However, there have been a few problems since the scheme was launched last Friday.D ．Despite the comments, the green-thinking London Mayor still says with certainty.E ．However, the London Mayor is confident of the scheme.F ．It has been designed to encourage more people to cycle in and around central London.G ．The new hire system is hoping to ease congestion （拥挤） in London and is expected to create up to 40, 000 extra cycle trips a day into the city Centre. 第二部分英语知识运用（共两节,满分 45分）第一节完形填空（共 20小题;每小题 1.5分,满分 30分）阅读下面短文,从短文后所给各题四个选项（A 、B 、C 和 D ）中,选出可以填入空白处的最佳选项.并在答题卡上将该项涂黑.More than three decades ago, I was a student at a high school in Southern California. The student body of 3, 200 was a melting pot of ethnic groups. The environment wasOne day I was walking down the side walk when someone kicked me from behind. Turning discovered the local gang. Fists came from every as the 15gang members surrounded me. have an operation. My doctor told me that if I had been hit in the head , I probably would have died. After I , some friends said, “Let’s get these guys!” That was the way were “resolved”. A part of me said, “Yes!” But another part of me and said no. History has proved time and again that revenge only the conflict. We needed to do something different to break the counter-productive （适得其反的） chain of 21.22, I2324I had to2526 27 28 29 30.Working with various ethnic groups, we 31what we called a “Brotherhood Committee” to work onimproving32relationships. I was amazed to learn how much 33 fellow students had in building abrighter future.Two years later, Iand the other a popular “big man of the campus”, a significant majority of the 3, 200 students joined me in theof doing things differently. We made significant progress in building bridges between , learning how to talk with and different ethnic groups, resolving differences without and learning how to build trust in the most difficult of circumstances.Being stacked by the gang was clearly one of my toughest life moments. What I learned,responding with love rather than returning hate has been a force in my life. Turning up our light in the presence of those whose light is dim （昏暗的） becomes the difference that makes the difference. 34Student Body President. Even though I ran against two friends, one a football hero3536 37 38 39, about40 21．A ．clearB ．toughC ．protectiveD ．dirty22．A．around 23．A．means B．on C．into D．out B．situationB．RegularlyB．one more timeB．recoveredB．atmospheresB．agreedC．approachC．EventuallyC．ahead of timeC．sufferedC．fantasiesC．startedD．directionD．FrequentlyD．in no timeD．calmedD．problemsD．proceededD．proves24．A．Gradually 25．A．over time 26．A．treated 27．A．conditions 28．A．paused29．A．remains 30．A．accidents B．finishesB．itemsC．continuesC．events D．scenes31．A．put together B．put aside C．put backC．civil D．put down D．national D．interest D．called for D．way32．A．political 33．A．sympathy 34．A．voted for 35．A．need B．racialB．knowledgeB．ran forC．honorC．fought forC．processC．banks B．danger36．A．cultures 37．A．belong to 38．A．agreement 39．A．hence B．schoolsB．lead toD．ranksC．relate toC．justiceD．devote toD．violenceD．then B．demonstrationB．howeverB．peacefulC．moreoverC．careful40．A．powerful D．thoughtful第Ⅱ卷（非选择题,共50分）第二部分英语知识运用（共两节,满分45分）第二节（共10小题;每小题 1.5分,满分15分）阅读下面材料,在空白处填入适当的内容（1个单词）或括号内单词的正确形式,并填在答题卡的相应位置.Two weeks after the conclusion of the hit show Chinese Poetry Competition, a new program, Readers, has become a nationwide stir. 41 （broadcast）on CCTV over the weekend, it is arousing fresh 42 （enthusiastic）for literature in China.The weekly talk show, produced and hosted by famous TV personality Dong Qing, 43 （invite）people from all walks of life 44 （read）aloud parts of poems, essays and books that they like or wrote. The participants also share stories from their own life explainingtheir lives.45 particular pieces touched their hearts or shapedFive days after 46 （it）first show on CCTV-1on Saturday, Readers has been rated 9.2points out of 10on Douban, one of China’s most popular review sites. Internet 47 （use）have praised it as a breath of fresh air among variety shows in China, a refreshing change from the usual dance and singing shows that dominate live television.But the success of these programs is just like a vane, through which we can see that there is huge demand of cultural show in the public. In today ’s television world reality shows have dominated, this is （encourage ）.48 49 very50第三部分写作（共两节,满分 35分）第一节:短文改错（共 10小题;每小题 1分,满分 10分）51．假定英语课上老师要求同桌之间交换修改作文,请你修改你同桌写的以下作文.文中共有 10处语言错误, 每句中最多有两处.每处错误仅涉及一个单词的增加、删除或修改. 增加:在缺词处加一个漏字符号（∧）,并在其下面写出该加的词. 删除:把多余的词用斜线（＼）划掉.修改:在错的词下划一横线,并在该词下面写出修改后的词. 注意:1．每处错误及其修改均限一词;2．只允许修改 10处,多者（从第 11处起）不计分.The other day I ran into an old schoolmate of my, Sally Barber, while I was at the cashpoint. I hadn ’t seen her for age. I wanted to catch up with her, so I suggested go for a cup of coffee. Unfortunately, Sally ’s a very busy woman, but she didn ’t have time for a coffee. Let ’s meet late in the week, I suggested. That is often the case, Sally looked in her diary, and said we could get together for lunch at 1pm on Friday at her favorite restaurant. I thought it was a very much smart place, so I had dress in for the occasion. I arrived at a restaurant in good time. I finished my dessert by the time she turned up –she was an hour late! 第二节书面表达（满分 25分）52．假设你是美国洛杉矶高中留学的中国学生,在 “Our County’s Culture”课上,你向全班同学及老师介绍中国的传统节日-----端午节.请你写一篇稿子,包括以下要点: 端午节的时间及起源（农历五月初五）; 端午节的习俗;邀请大家在端午节那天一起包粽子. 注意:1．词数 100左右;2．可以适当增加细节,以使行文连贯; 3．开头已写好,不包含在字数内. Dear class,I am very honored to have the chance to。

【云南省师范大学附属中学】2017届高考适应性训练月考英语试卷(七)-答案

云南省师范大学附属中学2017届高考适应性训练月考英语试卷（七）答案1~5．ACDAA 6~10．CBADC26~30．BDACC 11~15．DBDCB31~35．ABDBC16~20．FAGCD36~40．ACDBA21~25．BADCB41．Broadcast/ Broadcasted 42．Enthusiasm46．Its 43．invites47．users44．to read48．a45．Why49．where51．50．encouraging52.Dear class,I am very honored to have the chance to introduce to all of you a traditional Chinese festival—Dragon Boat Festival.The 5th day of the 5th lunar month is a traditional Chinese festival dedicated to the great poet Qu Yuan for his devotion to his native state in ancient China. It is a celebration to which every family has attached great importance. People in many ways pay their respects to Qu Yuan such as eating songs, racing dragon boats and so on. The festival was long marked as a cultur al holiday in China. Now it is also celebrated as “Poets’ Day” in honor of Qu Yuan, whois known as China’s first poet. Most excitingly, we can enjoy a three-day holiday together with weekends.Maybe you’re curious to know something about songs. Just sit straight, I will show you how to make it and we will enjoy the songs we make together next class!Thank all you guys, see you next time!云南省师范大学附属中学2017届高考适应性训练月考英语试卷（七）解析【解析】这是类教育类文章,文章主要通过讲鲍比达林知道自己生命不长所以从不浪费,而是努力生活来告诉我们生命虽长不要浪费生命,不要推延时间,好好享受生命.1．细节理解题,根据文章第一段“It seems the more time we have, the longer we put off living the life we see in our heads, because we feel like we’ve got some time to kill. ”意思是我们似乎有很多时间,时间越长我们推迟的越久, 因为我们觉得我们应该可以消磨时间,而选项A的意思是因为我们有时间数拇指,意思也是消磨时间,故选A．但没有特指瑞典,故A错误,根据“Tickets to ride public buses in most Swedish cities can only be purchased via cell phones. ”购买车票只能通过手机,但不是说不用买票.故B错误,根据“Even the homeless th at sell street paper to make ends meet have to start accepting this mode of payment!”即使是无家可归的卖报人也得接受这一方式,故 C 错误,故选D．14．细节理解题,根据“his sculptures, while mostly housed inside art galleries, perfectly capture one of the main principles of street art”意思是埃斯基韦尔的雕塑,虽然大部分都被收藏在艺术画廊里,完美地捕捉到了街头艺术的主要原则之一:一些引人注目的东西,以及一些吸引人的东西.判断A正确“Often the best sculptures outside the art galleries aren’t the ones behind guards and fencing, but the ones people can go right up to and touch. ”意思是艺术画廊外面最好的雕塑往往不是守卫和围栏后面的雕塑,而是人们可以直接接触和触摸的.判断B．D正确,故选C．15．细节理解题,根据最后一段“his a rt is not only a presentation of talent, something that mentions larger philosophical questions, like the ones he stated above, but also just the right combination of interesting idea and painstaking work. ”意思是埃斯基韦尔的艺术不仅是一种才华的展示,它还涉及更大的哲学问题,就像他上面所说的那样,但也仅仅是有趣的想法和艰苦的工作的正确结合.故选B．18．根据后文“ London Mayor Boris Johnston launched the scheme and said London has been “filled with thousands of gleaming (发光的) machines that will transform the look and feel of our street and become as commonplace on our roads as black cabs and red buses ”意思是伦敦市长鲍里斯•约翰逊发起了方案和表示,伦敦已经“充斥着成千上万的闪闪发光的(发光的)机器将改变的外观和感觉我们的街道在我们的道路,成为司空见惯的黑色出租车和红色巴士”.明白他的意思是伦敦交通工具太多,太拥挤,故推测上文是讲实行政策的原因,即The new hire system is hoping to ease congestion (拥挤) in London and is expected to create up to 40, 000 extra cycle trips a day into the city Centre.故选 G.19．根据第三段的关键词“problem,can not”知道主要讲政策实行过程中遇到的问题,其中部分句子“ On the first day some people found they couldn’t dock their bike properly and their usage of the bike had not registered. Transport for London did admit they had been expecting a few “teething problems”“的意思是第一天,一些人发现他们的自行车不能正常停靠,自行车的使用也没有登记.伦敦交通局承认,他们一直在期待一些“暂时的问题”故选C．20．根据第三段和第四段的主要大意,即出现的问题以及人们所评论不好的方面,而最后一段““My crusade for the capital to become the greatest big cycling city in the world has taken a great pedal-powered push forwards. ””意思是我为成为世界上最大的自行车城市而进行的改革运动已经取得了巨大的进步.”这两者之间构成了转折关系,故选D．25．考察固定短语,A:随着时间的推移,B:又一次,再一,C:提前,D:没有时间,My doctor told me that if I had been hit in the head ___5___, I probably would have died.意思是我的医生告诉我如果我的头部在再受伤的话,有可能造成死亡.故根据句意故,故选B．26．考察动词词义,A治疗B恢复C遭受D平静下来根据“After I ___6___, some friends said, “Let’s get these guys!”意思是等我康复了,我的朋友告诉我:我们一起去干他,故选B．27．考察名词,A:条件B:大气压,C:幻想D:问题,前文朋友们告诉我以暴制暴,说这是解决问题的方法,即That was the way ___7___were “resolved”.故选D．28．考察动词,A停顿,拒绝,B同意C开始D进行前后文讲朋友给我出主意后,自己陷入纠结,一部分赞成,一部分不同意,故选 A32．考察形容词,A政治B种族的, C民事的D国家的,根据前文我们聚在一起,努力维护民族间的感情,故选B．33．考察名词,根据“I was amazed to learn how much ___13___fellow students had in building a brighter future. ”意思是我惊讶地发现,同学们在建设一个更光明的未来上有多么有趣.而选项A:同情B知识C荣誉D兴趣,这空讲的是同学们在一起很开心.故选D．34．考察固定短语,根据“Two years later, I ___14___Student Body President. ”句子推测句子意思是两年后,我竞选了学生干部,选项A支持B竞选C争取D呼吁,故选B．35．考察语境,根据“a significant majority of the 3, 200 students joined me in the ___15___of doing things differently. ”推测句意是一个很大的大多数的3200个学生在这个过程中加入了我的行列,选项A需要B危险C进程,过程.D方法,路程.故选C．36．考察名词,A文化B学校C银行D排名,根据文章内容主要讲通过学生团结来促进各个民族之间文化的交流,如倒数第三段第一句,“improve national relationship”意思是提高民族的关系,故选A．37．考察固定短语,选项A属于B导致C与…有关D致力于“We made significant progress in building bridges between culture, learning how to talk with and ___17___different ethnic groups, ”意思是我们在不同文化之间搭建桥梁的过程中取得了显著的进步,学习如何与不同的民族进行交谈,并与不同的民族建立联系,.40．考察形容词,选项A强大的B和平的C小心的,D深思熟虑的.根据“responding with love rather than returning hate has been a ___20___force in my life. ”意思是用爱来回应不是恨是而是一种力量,形容力量即名词用形容词,powerful force意思是强大的力量.【名师点睛】完形填空的考点:一、重语境完形填空着眼于整体理解,必须在对短文大意进行了解的基础上才能较准确地推知答案.因此,需要注意上下句的逻辑关系以及整篇文章的情节,尤其是在需要填连接性词语时更需要上下文提供的线索,把自己置身于情景当中进行填空,这样才能比较顺利且有把握地捕捉到正确信息.如（15）小题,你只有通读全文,你才会明白作者是通过团体来促进民族关系,从而选出possess这个答案.二、重实词完形填空的命题是在一句话中的关键词语上做文章.这种词语大多是名词、动词、形容词、副词等实词, 当然也不排除能左右文章内容的一些虚词,如介词、连词等.如题中（1-4．6-10）都是考察关键词,首先你要明确词性以及词义,如12．考察形容词,A政治B种族的, C民事的D国家的,根据前文我们聚在一起,努力维护民族间的感情,故选 B完形填空主要是对文章意思的全体把握.【解析】本文主要讲在《中国的诗歌》节目结束两周后,新的节目《读者》引起人们热烈的喜欢,介绍了这个节目的主持人以及节目内容,由此引出线代社会真人综艺节目是很受欢迎的.41．考察被动语态,Broadcasted on CCTV over the weekend意思是在周末的CCTV上被播出,节目与播出之间形成被动形式,故填 Broadcasted.42．考察名词, fresh意思是新的,形容词,形容词修饰的意思是名词,并且文章最后一句话的意思是它引起了新的热情,故填enthusiasm .43．考察动词形式,The weekly talk show, produced and hosted by famous TV personality Dong, invites people from, 这句话的意思是这个每周的节目是由著名的主持人董卿主持,并且邀请了很多的人.这句话的主语是The weekly talk show是单数,其谓语invite应该用三单形式,故填 invites.47．考察名词,此空是做句子的主语,所以应该用名词,Internet users have praised it as a breath of fresh air among variety shows in China, a refreshing change from the usual dance and singing shows that dominate live television. 意思是在中国的综艺节目中,互联网用户称赞它是一种清新的空气,这是一种令人耳目一新的变化,从以往的舞蹈和歌唱节目中,电视节目占主导地位.故填 users48．考察冠词,But the success of these programs is just like a vane, through which we can see that there is a huge demand of cultural show in the public.意思是但是,这些节目的成功就像一个vane,通过它我们可以看到公众对文化节目的巨大需求.名词前加冠词,此处表示泛指,故填 a.49．考察连词,In today’s television world where reality shows have dominated意思是在今天的电视世界里,电视真人秀节目占主导地位,从句中缺地点状语,故填 where.50.考察动词作形容词,文章最后一句话的意思是它是很受人鼓舞的. be encouraging表示令人受到鼓舞,根据句意故填encouraging.。

高三英语上学期适应性考试试题(一)

云南省师范大学附属中学2017届高三英语上学期适应性考试月考试题（一）（扫描版）云南师大附中2017届高考适应性月考卷（一）英语参考答案第一部分：听力（共两节，满分30分）1~5 ACBAC 6~10 BCCAB 11~15 CBBAB 16~20 CBAAB第二部分：阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）21~25 DCBAD 26~30 CABBC 31~35 AABDA第二节（共5小题；每小题2分，满分10分）36~40 ACEGF第三部分：英语知识运用（共两节，满分45分）第一节：完形填空（共20小题；每小题1.5分，满分30分）41~45 CBACD 46~50 ABCAB 51~55 DACDD 56~60 AABBD第二节（共10小题；每小题1.5分，满分15分）61．made 62．but 63．an 64．trying 65．highly 66．them 67．who 68．fails 69．without 70．how第四部分：写作（共两节，满分35分）第一节：短文改错（共10小题；每小题1分，满分10分）According to a study lead by NT University in Britain，the average person look at their phones①led ②looks85 times a day，browsing the Internet or using apps．Our phones might be changed the way we③changing interact with people right next to us．Is it rude to check his phone when someoneis talking to you?④yourActually，if you a re clever enough you might use your phone as∧tool to connect with p eople next⑤ato you．How about showing them picture stored in its memory? Sharing a bit of your life with them⑥picturescan bring you more closer together．And you can also invite someone to take a selfie with you．But⑦⑧Sothe best thing to deal with mobile phone addiction is to leave the machine out occasionally or just switch⑨behindit off．Who knows life might be that happens when you are too busy staring at a smal l screen．⑩what第二节：书面表达（满分25分）【参考范文】As we know，when senior students graduate from school，most of their reference books as well as textbooks are thrown away，which are still in good condition．What a great waste it is!I suggest that we should recycle these books．On the one hand，recycling them can save a lot of natural resources，which are used to make textbooks．On the other hand，senior students may have made plenty of useful notes on the pages．They are very helpful to the following users．At present，the whole nation is called on to build an energy-saving society．I think it is certainly meaningful to our long-term interests．In fact，in Australia and some other countries，recycling textbooks is popular，which gives us a goodexample．【解析】第二部分：阅读理解第一节A【语篇导读】本文是一篇记叙文，讲述了“我”的父亲在摔断腿而做手术后，由于对妻子的爱而很快恢复的故事。

云南省师范大学附属中学2017届高三上学期高考适应性考

云南师范大学附属中学高三上学期第五次月考英语试题含答案

云南师大附中2020届高考适应性月考卷（五）英语参考答案第一部分听力（共两节，满分30分）1~5 ABBCA 6~10 ACBBC 11~15 ABCBB 16~20 ACCAA第二部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）21~25 ADCBC 26~30 ABDBC 31~35 ADAAD第二节（共5小题；每小题2分，满分10分）36~40 CGADF第三部分语言知识运用（共两节，满分45分）第一节（共20小题；每小题1.5分，满分30分）41~45 BCDAB 46~50 ACDCA 51~55 BBACD 56~60 CDBAD第二节（共10小题；每小题1.5分，满分15分）61．second 62．served 63．videos 64．whether 65．the 66．who/that 67．under 68．has started 69．physically 70．to heal第四部分写作（共两节，满分35分）第一节短文改错（共10小题；每小题1分，满分10分）Dear Ms. Wood，I was a guest who stayed in your hotel a week ago．First of all，I want to express my sincerethanks for your good service which makes my stay in Australia more enjoyable．Therefore，you can①made ②Howeverdo better in some aspects．To begin with，I found out only one Chinese dish on the menu，that gave me a big surprise．Is③④whichit possible for you to provide Chinese dishes with more variety? In addition，it took me∧long time⑤varieties ⑥ato find the emergency exit．Please make the signs well-marking．Finally，the clerk at the front desk⑦well-markedcould be more patiently．When asking about where to find the nearest swimming pool，she seemed⑧patient ⑨askedrather annoyed．I do hope you will take their advice into consideration．Thanks for your time．⑩myYours，Li Hua 第二节书面表达（满分25分）【参考范文】Dear Peter，I sincerely invite you to participate in the“National Day”English speaking competition，serving as a judge．Our activity will be held in Academic Reporting Hall at 3：00 p. m. on September 30. The theme of the English speaking competition is“I love China”. When each speaker ends，each judge will comment on the speaker’s speech content and skills，and give a mark comprehensively. According to the scores，the competition has one first prize，two second prizes，three third prizes，and ten outstanding awards．At the end of the competition，all the judges will go on stage to give awards to the winners and take photos．Looking forward to your coming！Yours，Li Hua 【解析】第二部分阅读理解第一节A【语篇导读】本文是一篇应用文，讲述了四个2019年值得推荐的四款洗衣机，以及每个洗衣机的特征、优点、价格、容量等指标，供读者参考，以选择最适合自己那款。

云南省高考理综适应性月考试题(五)(扫描版)

云南省2017届高考理综适应性月考试题（五）（扫描版）云南师大附中2017届高考适应性月考卷（五）理科综合参考答案第Ⅰ卷（选择题，共126分）一、选择题：本题共13小题，每小题6分。

二、选择题：本题共8小题，每小题6分。

在每小题给出的四个选项中，第14～17题只有一项符合题目要求；第18～21题有多项符合题目要求，全部选对的给6分，选对但不全的给3分，有选错的给0分。

【解析】1．在噬菌体侵染细菌的实验中，搅拌的目的是使吸附在细菌表面的噬菌体与细菌分离，离心的目的是让上清液中析出重量较轻的T2噬菌体颗粒，而离心管的沉淀物中留下被感染的大肠杆菌，D错误。

2．植物的向光性不能说明生长素的作用具有两重性，①错误；顶芽产生的生长素向下运输的方式是主动运输，③错误；赤霉素能促进果实发育，但会促进植物种子的萌发，使贮藏时间变短，④错误；用生长素处理二倍体番茄幼苗后，得到的还是二倍体番茄，⑤错误；对成熟期的植物喷洒一定浓度的细胞分裂素会延缓叶片衰老和脱落，⑥错误。

3．图乙中，a、b两点有氧呼吸消耗葡萄糖的速率不相等，B错误。

图丙若表示有丝分裂的时期，a、b两点对应的细胞中核DNA数不相等；图丙若表示减数分裂的时期，a、b两点对应的细胞中核DNA数相等，C错误。

图丁中，λ<1时说明种群数量下降，a、b两点对应的该种群的数量不相同，b的数量少于a的数量，D错误。

4．若甲为催化剂，a为H2O2溶液，Fe3+催化和过氧化氢酶催化等量的a产生b、c的总量相同，D错误。

5．位于脊髓内的低级中枢受脑中相应高级中枢的调控体现了分级调节，A错误。

下丘脑不能产生渴觉，C错误。

类风湿性关节炎不属于过敏反应，属于自身免疫病，D错误。

6．遗传物质复制时所需酶不相同，A错误。

子代病毒增殖过程中模板由亲代病毒提供，B错误。

用带有放射性物质的培养基培养病毒，不能使其子代被放射性元素标记，因为病毒的生活方式是活细胞寄生，C错误。

7．蜜蜂、蚂蚁蛰咬后释放的甲酸等酸性物质可用小苏打溶液消除，A正确。

云南师范大学附属中学2017届高三英语上学期适应性考试试题(一)(扫描版)

云南省师范大学附属中学2017届高三英语上学期适应性考试月考试题（一）（扫描版）云南师大附中2017届高考适应性月考卷（一）英语参考答案第一部分：听力（共两节，满分30分）1~5 ACBAC 6~10 BCCAB 11~15 CBBAB 16~20 CBAAB第二部分：阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）21~25 DCBAD 26~30 CABBC 31~35 AABDA第二节（共5小题；每小题2分，满分10分）36~40 ACEGF第三部分：英语知识运用（共两节，满分45分）第一节：完形填空（共20小题；每小题1.5分，满分30分）41~45 CBACD 46~50 ABCAB 51~55 DACDD 56~60 AABBD第二节（共10小题；每小题1.5分，满分15分）61．made 62．but 63．an 64．trying 65．highly 66．them 67．who 68．fails 69．without 70．how第四部分：写作（共两节，满分35分）第一节：短文改错（共10小题；每小题1分，满分10分）According to a study lead by NT University in Britain，the average person look at their phones①led ②looks85 times a day，browsing the Internet or using apps．Our phones might be changed the way we③changing interact with people right next to us．Is it rude to check his phone when someoneis talking to you?④yourActually，if you are clever enough you might use your phone as∧tool to connect with people next⑤ato you．How about showing them picture stored in its memory? Sharing a bit of your life with them⑥picturescan bring you more closer together．And you can also invite someone to take a selfie with you．But⑦⑧Sothe best thing to deal with mobile phone addiction is to leave the machine out occasionally or just switch⑨behindit off．Who knows life might be that happens when you are too busy staring at a small screen．⑩what第二节：书面表达（满分25分）【参考范文】As we know，when senior students graduate from school，most of their reference books as well as textbooks are thrown away，which are still in good condition．What a great waste it is!I suggest that we should recycle these books．On the one hand，recycling them can save a lot of natural resources，which are used to make textbooks．On the other hand，senior students may have made plenty of useful notes on the pages．They are very helpful to the following users．At present，the whole nation is called on to build an energy-saving society．I think it is certainly meaningful to our long-term interests．In fact，in Australia and some other countries，recycling textbooks is popular，which gives us a goodexample．【解析】第二部分：阅读理解第一节A【语篇导读】本文是一篇记叙文，讲述了“我”的父亲在摔断腿而做手术后，由于对妻子的爱而很快恢复的故事。

高三英语上学期适应性考试试题(四)

云南省师范大学附属中学2017届高三英语上学期适应性考试月考试题（四）（扫描版）云南师大附中2017届高考适应性月考卷（四）英语参考答案第一部分：听力（共两节，满分30分）1~5 BACBA 6~10 BCCBC 11~15 CACBC 16~20 ABACC第二部分：阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）21~25 CCDDB 26~30 CBBCA 31~35 DCBCB第二节（共5小题；每小题2分，满分10分）36~40 DAFCE第三部分：英语知识运用（共两节，满分45分）第一节：完形填空（共20小题；每小题1.5分，满分30分）41~45 BDACB 46~50 ADCBB 51~55 CADBA 56~60 DCACB第二节（共10小题；每小题1.5分，满分15分）61．on 62．thinner 63．proves 64．entirely 65．started 66．pioneering 67．treatment 68．a 69．as 70．its第四部分：写作（共两节，满分35分）第一节：短文改错（共10小题；每小题1分，满分10分）One day，little Charlie went by a candy shop with his grandparents．It was very cold inside but①outsidethey didn’t enter the shop，just stood at the shop window．Suddenly，Charlie found a large chocolate②standingbar in the shop window．He liked it very much that he asked his grandparents to buy ∧．They shook③so ④ittheir head，but their family was too poor to afford even a chocolate bar．Charlie was frustrated and⑤heads ⑥because/forbegan to cry．A shopkeeper saw him crying and telling him to calm down．At that moment，the⑦toldkeeper turned around and fetched a bar he wanted．The keeper said，“If you want it，you can take it⑧theby free.”Charlie smiled happy，so did his grandparents.⑨for ⑩happily第二节：书面表达（满分25分）【参考范文】Good afternoon，everyone! Today I’m going to share with you my dream．As we all know，people like to use the word“dream”to express the strong desires they have for their future．Some young people dream of becoming scientists while others wish to become astronauts like Yang Liwei．Of course，there are many that would love to be rich．In my opinion，no matter what we end up being in the future，what matters most is that we are responsible for our society and its citizens．I want to be a man who is self-dependent and has a full sense of responsibility，a man who is helpful to those in trouble．Furthermore，I will strive to be someone who is always thankful to those who love and are loved．Thank you for listening．【解析】第二部分：阅读理解第一节A【语篇导读】本文推荐了三个适宜青少年课外活动的夏令营。

云南省师范大学附属中学高三高考适应性月考五数学理试题含答案

云南省师范大学附属中学2017届高三高考适应性月考（五）理科数学试卷第Ⅰ卷（共60分）一、选择题：本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.1.集合2{|0}{|2}A x x a B x x =-≤=<，，若A B ⊆，则实数a 的取值范围是（） A ．(,4]-∞ B ．(,4)-∞ C ．[0,4] D ．(0,4)2.复数31i z i =-，则其共轭复数z 在复平面内对应的点位于（）A ．第一象限B ．第二象限C ．第三象限D ．第四象限 3. 下列说法正确的是（）A ．“1x <”是“2log (1)1x +<”的充分不必要条件B ．命题“0x ∀>，21x >”的否定是“00021x x ∃≤≤，” C.命题“若a b ≤，则22ac bc ≤”的逆命题为真命题 D ．命题“若5a b +≠，则2a ≠或3b ≠”为真命题4.已知函数()|sin |cos f x x x =•，则下列说法正确的是（） A ．()f x 的图象关于直线2x π=对称B ．()f x 的周期为πC.若12|()||()|f x f x =，则122()x x k k Z π=+∈D ．()f x 在区间3[,]44ππ上单调递减5. 秦九韶算法是南宋时期数学家秦九韶提出的一种多项式简化算法，即使在现代，它依然是利用计算机解决多项式问题的最优算法，即使在现代，它依然是利用计算机解决多项式问题的最优算法，其算法的程序框图如图所示，若输入的012,,,,n a a a a 分别为0,1,2,,n ，若5n =，根据该算法计算当2x =时多项式的值，则输出的结果为（） A ．248 B ．258 C.268 D ．2786. 在棱长为2的正方体1111ABCD A B C D -中任取一点M ，则满足90AMB ∠>°的概率为（） A ．24πB ．12πC.8πD ．6π7. 某几何体的三视图如图所示，则该几何体的体积为（）A ．8B ． C.．48. 已知实数,x y 满足2244x y +≤，则|24||3|x y x y +-+--的最大值为（） A ．6 B ．12 C. 13 D ．149.三棱锥A BCD -O 中，4AB CD ==，则三棱锥A BCD -的体积的最大值为（） A.43 B.83 C.163 D.32310.已知抛物线24x y =的焦点为F ，准线为l ，抛物线的对称轴与准线交于点Q ，P 为抛物线上的动点，||||PF m PQ =，当m 最小时，点P 恰好在以,F Q 为焦点的椭圆上，则椭圆的离心率为（）A ．3-B ． 2 D 1- 11.函数3|log |y x =的图象与直线1:l y m =从左至右分别交于点,A B ，与直线28:(0)21l y m m =>+从左至右分别交于点,C D .记线段AC 和BD 在x 轴上的投影长度分别为,a b ，则ba 的最小值为（）A ．B ． D ．12.若函数()ln f x x =与函数2()2(0)g x x x a x =++<有公切线，则实数a 的取值范围是（） A ． 1(ln,)2e+∞ B ．(1,)-+∞ C.(1,)+∞ D ．(ln 2,)-+∞ 第Ⅱ卷（共90分）二、填空题（每题5分，满分20分，将答案填在答题纸上）13.已知函数3()x f x e x =+，若2()(32)f x f x <-，则实数x 的取值范围是． 14.点P 是圆22(3)(1)2x y ++-=上的动点，点(2,2)Q ，O 为坐标原点，则OPQ ∆面积的最小值是．15.已知平面向量,,a b c 满足||112a a b b c a c ====，，•••，则||a b c ++的最小值是．16.已知数列{}n a 满足12a =，且*112(2)1n n n na a n n N a n --=≥∈+-，，则n a = ．三、解答题（本大题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤.） 17. （本小题满分12分）在ABC ∆中，角A ，B ，C 的对边分别为a ，b ，c ，已知223cos cos 2222B A a b c a b +==，．（1）证明：ABC ∆为钝角三角形；（2）若ABC ∆的面积为，求b 的值． 18. （本小题满分12分）某公司即将推车一款新型智能手机，为了更好地对产品进行宣传，需预估市民购买该款手机是否与年龄有关，现随机抽取了50名市民进行购买意愿的问卷调查，若得分低于60分，说明购买意愿弱；若得分不低于60分，说明购买意愿强，调查结果用茎叶图表示如图所示. （1）根据茎叶图中的数据完成22⨯列联表，并判断是否有95%的把握认为市民是否购买该款手机与年龄有关？（2）从购买意愿弱的市民中按年龄进行分层抽样，共抽取5人，从这5人中随机抽取2人进行采访，记抽到的2人中年龄大于40岁的市民人数为X ，求X 的分布列和数学期望.附：22()()()()()n ad bc k a b c d a c b d -=++++.19. （本小题满分12分）如图，三棱锥P ABC -中，PA ⊥平面ABC ，90ABC ∠=°，2PA AC ==，D 是PA 的中点，E 是CD 的中点，点F 在PB 上，3PF FB =.（1）证明：//EF 平面ABC ；（2）若60BAC ∠=°，求二面角B CD A --的余弦值. 20. （本小题满分12分）已知抛物线2:8E y x =，圆22:(2)4M x y -+=，点N 为抛物线E 上的动点，O 为坐标原点，线段ON 的中点P 的轨迹为曲线C . （1）求抛物线C 的方程；（2）点000(,)(5)Q x y x ≥是曲线C 上的点，过点Q 作圆M 的两条切线，分别与x 轴交于,A B 两点.求QAB ∆面积的最小值. 21. （本小题满分12分）已知函数2()x f x e x ax =--.（1）若曲线()y f x =在点0x =处的切线斜率为1，求函数()f x 在[0,1]上的最值；（2）令221()()()2g x f x x a =+-，若0x ≥时，()0g x ≥恒成立，求实数a 的取值范围；（3）当0a =且0x >时，证明2()ln 1f x ex x x x x -≥--+.请考生在22、23两题中任选一题作答，如果多做，则按所做的第一题记分. 22. （本小题满分10分）选修4-4：坐标系与参数方程在直角坐标系xOy 中，将曲线1cos :1sin 2x t C y t =+⎧⎪⎨=⎪⎩（t 为参数）上每一点的横坐标保持不变，纵坐标变为原来的2倍，得到曲线1C ；以坐标原点O 为极点，以x 轴的正半轴为极轴建立极坐标系，曲线2C的极坐标方程为2cos()6πρθ-=.（1）求曲线1C 的极坐标方程；（2）已知点(1,0)M ，直线l 的极坐标方程为3πθ=，它与曲线1C 的交点为O ，P ，与曲线2C 的交点为Q ，求MPQ ∆的面积.23. （本小题满分10分）选修4-5：不等式选讲已知函数()|1|2|1|f x x x =+--.（1）求()f x 的图象与x 轴围成的三角形面积；（2）设24()x ax g x x-+=，若对(0,)s t ∀∈+∞，恒有()()g s f t ≥成立，求实数a 的取值范围.云南师大附中2017届高考适应性月考卷（五）理科数学参考答案第Ⅰ卷（选择题，共60分）一、选择题（本大题共12小题，每小题5分，共60分）1．当0a <时，集合A =∅，满足题意；当0a ≥时，[A =，若A B ⊆，2<，∴0<4a ≤，所以(4)a ∈-∞，，故选B ． 2．∵i 1i i 12z --+==-，其共轭复数为1i 2z --=，对应点为1122⎛⎫-- ⎪⎝⎭，在第三象限，故选C ．3．选项A ：2log (1)101211x x x +<⇔<+<⇔-<<，所以“1x <”是其必要不充分条件；选项B ：命题“021x x ∀>>，”的否定是“00021x x ∃>，≤”；选项C ：命题“若a b ≤，则22ac bc ≤”的逆命题是“若22ac bc ≤，则a b ≤”，当c=0时，不成立；选项D ：其逆否命题为“若2a =且3b =，则5a b +=”为真命题，故原命题为真，故选D ．4．函数()f x 在区间[02π]，上的解+析式为1sin 20π2()1sin 2π2π2x x f x x x ⎧⎪⎪=⎨⎪-<⎪⎩，，，，≤≤≤且()f x 是偶函数，画出图象可知，故选D ．5．该程序框图是计算多项式5432()5432f x x x x x x =++++当x=2时的值，故选B ．6．以AB 为直径作球，球在正方体内部的区域体积为14ππ433V =⨯=，正方体的体积为8，所以π24P =，故选A ． 7．由三视图还原出该几何体为长方体切去一部分，如图所示，所以剩余部分体积为222383V =⨯⨯⨯=，故选A ． 8．实数x ，y 满足的区域为椭圆2214x y +=及其内部，椭圆的参数方程为2cos sin x y θθ=⎧⎨=⎩，，（θ为参数），记目标函数|24||3|z x y x y =+-+--，易知240x y +-≤，30x y --≥，故423723z x y x y x y =--+--=--．设椭圆上的点(2cos sin )P θθ，，则74cos 3sin 75sin()z θθθϕ=--=-+，其中4tan 3ϕ=，所以z 的最大值为12，故选B ． 9．如图，过CD 作平面ECD ，使AB ⊥平面ECD ，交AB 于点E ，设点E 到CD 的距离为EF ，当球心在EF 上时，EF 最大，此时E ，F 分别为AB ，CD 的中点，且球心O 为EF 的中点，所以EF=2，所以max 1116424323V =⨯⨯⨯⨯=，故选C ． 10．由已知，(01)(01)F Q -，，，，过点P 作PM 垂直于准线，则PM=PF ．记PQM α∠=，则图1||||sin ||||PF PM m PQ PQ α===，当α最小时，m 有最小值，此时直线PQ 与抛物线相切于点P ．设204x P x ⎛⎫ ⎪⎝⎭，，可得(21)P ±，，所以||||2PQ PF ==，则||||2PF PQ a +=，∴1a +，1c =，∴1ce a==-，故选D ． 11．在同一坐标系中作出y m =，8(0)21y m m =>+，3|log |y x =的图象，如图，设11()A x y ，，22()B x y ，，33()C x y ，，44()D x y ，，由3|log |x m =，得13m x -=，23m x =，由3|log |x =821m +，得82133m x -+=，82143m x +=．依照题意得821|33|m ma -+-=-，821|33|m mb +=-，821821|33||33|m m mmb a +-+--=- 882121333m mm m +++==，∴minb a⎛⎫= ⎪⎝⎭B ． 12．设公切线与函数()ln f x x =切于点111(ln )(0)A x x x >，，则切线方程为1111ln ()y x x x x -=-；设公切线与函数2()2g x x x a =++切于点22222(2)(0)B x x x a x ++<，，则切线方程为22222(2)2(1)()y x x a x x x -++=+-，所以有2121212(1)ln 1x x x x a ⎧=+⎪⎨⎪-=-+⎩，．∵210x x <<，∴1102x <<．又2211111111ln 11ln 2124a x x x x ⎛⎫⎛⎫=+--=-+-- ⎪ ⎪⎝⎭⎝⎭，令11t x =，∴2102ln 4t a t t t <<=--，．设21()ln (02)4h t t t t t =--<<，则211(1)3()1022t h t t t t --'=--=<，∴()h t 在(0，2)上为减函数，则1()(2)ln 21ln2e h t h >=--=，∴1ln 2e a ⎛⎫∈+∞ ⎪⎝⎭，，故选A ．第Ⅱ卷（非选择题，共90分）二、填空题（本大题共4小题，每小题5分，共20分）13．因为2()e30x f x x '=+>，所以函数f(x)为增函数，所以不等式2()(32)f x f x <-等价于232x x <-，即232012x x x -+<⇔<<，故(12)x ∈，．14．因为||OQ =，直线OQ 的方程为y=x ，圆心(31)-，到直线OQ 的距离为d ==所以圆上的动点P 到直线OQ 的距离的最小值为-=，所以OPQ △面积的最小值为122⨯=． 15．不妨设(10)()()a b m n c p q ===，，，，，，则m=1，p=2，211b c nq nq =+=⇒=-，1n q =-，∴11(2)b c q q ⎛⎫=-= ⎪⎝⎭，，，，2222||222a b c a b c ab bc ac ++=+++++2222111142241414216q q q q=+++++++=+++=≥，∴||4a b c ++≥，当且仅当21q =，即1q =±时“=”成立． 16．由1121n n n na a a n --=+-，得11122n n n n a a --=+，于是111112n n n n a a -⎛⎫--=- ⎪⎝⎭(2)n n *∈N ≥，．又11112a -=-，∴数列1n n a ⎧⎫-⎨⎬⎩⎭是以12-为首项，12为公比的等比数列，故112n n n a -=-，∴221nn nn a =-()n *∈N ．三、解答题（共70分．解答应写出文字说明，证明过程或演算步骤） 17．（本小题满分12分）解：（Ⅰ）由正弦定理：1cos 1cos 3sin sin sin 222B A AB C +++=， ∴sin sin cos sin sin cos 3sin A A B B B A C +++=， ∴sin sin sin()3sin A B A B C +++=．又∵sin()sin A B C +=，∴sin sin 2sin A B C +=，即a+b=2c ，a=2b ，所以32c b =，所以2222229414cos 032422b b b bc a A bc b b+-+-===-<，所以A 为钝角，故ABC △为钝角三角形． ………………（6分）（Ⅱ）因为1cos 4A =-，∴sin A=．又1sin 2S bc A =，∴12=，∴24bc =．又32c b =，所以23242b =，∴4b =．………………………………………（12分）18．（本小题满分12分）解：（Ⅰ）由茎叶图可得：由列联表可得：250(2012108)=3.46 3.84130202822K ⨯-⨯≈<⨯⨯⨯，所以，没有95%的把握认为市民是否购买该款手机与年龄有关． ……………（6分）（Ⅱ）购买意愿弱的市民共有20人，抽样比例为51204=，所以年龄在20~40岁的抽取了2人，年龄大于40岁的抽取了3人，则X 的可能取值为0，1，2，11222332222555C C C C 1633(0)(1)(2)C 10C 105C 10P X P X P X ==========，，，所以分布列为数学期望为1336()012105105E X =⨯+⨯+⨯=． …………………………（12分） 19．（本小题满分12分）（Ⅰ）证明：法一：如图，过点F 作FM //PA 交AB 于点M ，取AC 的中点N ，连接MN ，EN ． ∵点E 为CD 的中点，∴EN //12AD ．又3PF FB =，∴MF 12AD ，∴FM EN ，所以四边形MFEN 为平行四边形，∴//EF MN ，∵EF ⊄平面ABC ，MN ⊂平面ABC ， ∴//EF 平面ABC ． ………………（6分）法二：如图，取AD 中点G ，连接GE ，GF ，则GE//AC ，GF//AB ，因为GE ∩GF=G ，AC ∩AB=A ，所以平面GEF//平面ABC，所以EF//平面ABC ．………………（6分）（Ⅱ）解：作BO ⊥AC 于点O ，过点O 作OH//PA ，以O 为坐标原点，OB ，OC ，OH 所在直线为x 轴、y 轴、z 轴建立如图6所示的空间直角坐标系，则3100000122C B D ⎫⎛⎫⎛⎫-⎪ ⎪ ⎪⎪⎝⎭⎝⎭⎭，，，，，，，，图4∴33(021)02CD CB ⎛⎫=-=- ⎪⎪⎭，，，，，，则平面CDA 的一个法向量为(100)m =，，．设平面CDB 的一个法向量为()n x y z =，，，则2003002y z n CD y n CB -+=⎧⎧=⎪⇒⎨-==⎪⎩，，，可取(312)n =，，，所以6cos 4||||m n m n m n 〈〉==，，所以二面角B ?CD ?A …………………………（12分） 20．（本小题满分12分）解：（Ⅰ）设()P x y ，，则点(22)N x y ，在抛物线28y x =上，所以2416y x =，即24y x =，所以曲线C 的方程为：24y x =． ……………（4分）（Ⅱ）设切线方程为：00()y y k x x -=-，令y=0，解得00y x x k=-，所以切线与x 轴的交点为000y x k ⎛⎫- ⎪⎝⎭，，圆心(2，0)到切线的距离为2d ==， ∴2200(2)4(1)k y kx k +-=+，整理得：222000000(4)(42)40x x k y x y k y -+-+-=，设两条切线的斜率分别为12k k ，，则20000121222000024444x y y y k k k k x x x x --+==--，， ∴2200012000012120112221QABy y x k k S x x y y k k k k x ⎛⎫⎛⎫-=---== ⎪ ⎪-⎝⎭⎝⎭△记01[4)t x =-∈+∞，，则1()2f t t t=++，∵22211()10t f t t t-'=-=>，∴()f t 在[4)+∞，上单增，∴125()4244f t ++=≥，∴2525242S ⨯=≥， ∴QAB △面积的最小值为252． ………………………………（12分）21．（本小题满分12分）解：（Ⅰ）∵()e 2x f x x a '=--，∴(0)11f a '=-=，∴0a =，∴()e 2x f x x '=-，记()e 2x h x x =-，∴()e 2x h x '=-，令()0h x '=得ln 2x =．当(0ln 2)x ∈，时，()0()h x h x '<，单减；当(ln 21)x ∈，时，()0()h x h x '>，单增， ∴min ()(ln 2)22ln 20h x h ==->，故()0f x '>恒成立，所以()f x 在[01]，上单调递增， ∴min max ()(0)1()(1)e 1f x f f x f ====-，． ……………………（3分）（Ⅱ）∵21()e ()2x g x x a =-+，∴()e x g x x a '=--．令()e x m x x a =--，∴()e 1x m x '=-，当0x ≥时，()0m x '≥，∴()m x 在[0)+∞，上单增，∴min ()(0)1m x m a ==-．（i ）当10a -≥即1a ≤时，()0m x ≥恒成立，即()0g x '≥，∴()g x 在[0)+∞，上单增，∴2min()(0)102a g x g a ==-⇒≥，所以1a ≤．（ii ）当10a -<即1a >时，∵()m x 在[0)+∞，上单增，且(0)10m a =-<，当21e 2a <<-时，(ln(2))2ln(2)0m a a +=-+>， ∴0(0ln(2))x a ∃∈+，，使0()0m x =，即00e x x a =+．当0(0)x x ∈，时，()0m x <，即()0()g x g x '<，单减；当0(ln(2))x x a ∈+，时，()0m x >，即()0()g x g x '>，单增．∴022min 0011()()e ()e e 22x x x g x g x x a ==-+=-001e 1e 02x x ⎛⎫=- ⎪⎝⎭≥，∴00e 20ln 2x x ⇒<≤≤，由00e x x a =+，∴00e x a x =-，记()e (0ln 2]x t x x x =-∈，，，∴()e 10x t x '=->，∴()t x 在(0ln 2]，上单调递增， ∴()(ln 2)2ln 2t x t =-≤，∴12ln 2a <-≤，综上，[2ln 2]a ∈-． ………………………………（8分）（Ⅲ）2()e ln 1f x x x x x x ---+≥等价于22e e ln 1x x x x x x x ----+≥，即e e ln 1x x x x x --+≥．∵0x >，∴等价于e 1ln e 10x x x x---+≥．令e 1()ln e 1x h x x x x=---+，则2(1)(e 1)()x x h x x --'=． ∵0x >，∴e 10x ->．当01x <<时，()0h x '<，()h x 单减；当1x >时，()0h x '>，()h x 单增．∴()h x 在1x =处有极小值，即最小值，∴()(1)e 1e 10h x h =--+=≥，∴0a =且0x >时，不等式2()e ln 1f x x x x x x ---+≥成立． ………………（12分）22．（本小题满分10分）【选修4?4：坐标系与参数方程】解：（Ⅰ）由题意知，曲线1C 的参数方程为1cos sin x t y t ⎨=+=⎧⎩，，(t 为参数)， ∴曲线1C 的普通方程为22(1)1x y -+=，∴曲线1C 的极坐标方程为=2cos ρθ． ……………………………（4分）（Ⅱ）设点P ，Q 的极坐标分别为11()ρθ，，22()ρθ，，则由111π=3=2cos θρθ⎧⎪⎨⎪⎩，，可得P 的极坐标为π13⎛⎫ ⎪⎝⎭，，由222π=3π2cos 6θρθ⎧⎪⎪⎨⎛⎫⎪- ⎪⎪⎝⎭⎩，可得Q 的极坐标为π33⎛⎫ ⎪⎝⎭，． ∵12θθ=，∴12||||2PQ ρρ=-=，又M 到直线l，∴1=2MPQ S △ ……………………………（10分） 23．（本小题满分10分）【选修4?5：不等式选讲】解：（Ⅰ）∵()|1|2|1|f x x x =+--，∴31()311131x x f x x x x x -<-⎧⎪=--⎨⎪-+>⎩，，，，，，≤≤∴()f x 的图象与x 轴围成的三角形的三个顶点分别为103A ⎛⎫ ⎪⎝⎭，，(30)B ，，(12)C ，， ∴1882=233ABC S =⨯⨯△，∴()f x 的图象与x 轴围成的三角形面积是83．……………………………（5分）（Ⅱ）∵(0)s ∀∈+∞，，244()4s as g s s a a a s s -+==+-=-≥， ∴当且仅当2s =时，()g s 有最小值4a -．又由（Ⅰ）可知，对(0)t ∀∈+∞，，()(1)=2f t f ≤．(0)s t ∀∈+∞，，恒有()()g s f t ≥成立，等价于(0)s t ∀∈+∞，，，min max ()()g s f t ≥，等价于42a -≥，即2a ≤，∴实数a 的取值范围是(2]-∞，．……………………………（10分）。