北京市朝阳区2015-2016学年度高三年级第一学期期中统一考试

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北京市朝阳区2015届高三上学期期中统一考试语文试题 Word版含答案

朝阳区2015届高三年级第一学期期中统一考试语文试卷（满分150分考试时长150分钟） 2014.11本试卷共8页。

考生务必将答案答在答题卡上，在试卷上作答无效。

考试结束后，将本试卷和答题卡一并交回。

一、本大题共7小题，共18分。

阅读下面的文字，完成1～4题。

中国园林集中了建筑、书画、文学、园艺等艺术的精华，在世界造园艺术中甲（别出心裁/独树一臶）。

中国园林在造园时，能利用天然的地形再加人工的设计，这样不但节约了人工物力，并且利于景物的安排，造园学上称为“乙（因地制宜/师法自然）”。

园林以山水为主体，水有散聚之分，山有平冈．峻岭之别。

园林四周有墙垣．（yuán），景物藏之于内。

大园中往往还包有小园，如颐和园的谐．（xié）趣园、北海的静心斋等。

这些小园是园中精华所在，宜静观盘桓．（hénɡ）。

园林多运用对比和衬托等手法，使景物曲折多变。

颐和园前山为华丽的建筑群，后山却是苍翠的自然景物，两者给人不同的感觉，却丙（相得益彰/相辅相成）。

北海团城承光殿前的松柏参差散植，疏密有致．，布臵得妥贴．宜人，松柏的姿态与附近的建筑物高低相称，掩映．成趣，苍翠虬．（qiú）枝与红墙碧瓦构成一幅极好的画面。

不同的季节，园林呈现不同的风光。

北宋画家郭熙说：“春山①，夏山②，秋山③，冬山④。

”造园者多少参用了这些画理。

很多园林亭阁，不但有很好的命名，有时还加上很好的对联。

《老残游记》中写老残在济南游大明湖，看了“□□□□□□□，□□□□□□□”的对联后，暗暗称道：“真个不错！”可见文学在园林中所起的作用。

1.在文中甲乙丙处依次填入词语，恰当的一项是（2分）A.别出心裁因地制宜相辅相成B.独树一臶因地制宜相得益彰C.独树一臶师法自然相辅相成D.别出心裁师法自然相得益彰2.文中加点字的注音和字形都不正确的一项是（2分）A.平冈．峻岭墙垣．（yuán）B.疏密有致．谐．（xié）趣园C.妥贴．宜人盘桓．（hénɡ）D.掩映．成趣虬．（qiú）枝3.在文中①②③④处依次填入语句，恰当的一项是（2分）A.①苍翠而如滴②明净而如妆③淡冶而如笑④惨淡而如睡B.①明净而如妆②苍翠而如滴③惨淡而如睡④淡冶而如笑C.①淡冶而如笑②苍翠而如滴③明净而如妆④惨淡而如睡D.①惨淡而如睡②明净而如妆③苍翠而如滴④淡冶而如笑4.在文中方格处填入下列语句，恰当的一项是（2分）A.寺古僧闲云作伴，山深世远月为朋B.最爱湖东行不足，绿杨阴里白沙堤C.日日扁舟藕花里，有心长做济南人D.四面荷花三面柳，一城山色半城湖5.下列句中加点词语的表现手法，不同于其他三句的一项是（3分）A.狂风紧紧抱起一层层巨浪，恶狠狠地将它们甩到悬崖上，把这些大块的翡翠．．．．．摔成尘雾和碎末。

北京市朝阳区2016届高三英语上学期期中试题

北京市朝阳区2015—2016学年度高三年级第一学期期中统一考试英语试卷本试卷共12页，共150分。

考试时长120分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

考试结束后，将本试卷和答题卡一并交回。

第一部分：听力理解（共三节，30分）第一节（共5小题；每小题1.5分，共7.5分）听下面5段对话。

每段对话后有一道小题，从每题所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你将有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话你将听一遍。

例：What is the man going to read?A. A newspaper.B. A magazine.C. A book.答案是A。

1. When will the man go for his holidays?A. In June.B. In July.C. In August.2. What does the woman suggest the man do?A. Go to see the doctor.B. Stop using headphones.C. Try listening to some music.3. Where does this conversation most probably take place?A. In a hotel.B. In a bank.C. In a park.4. What will the woman have to do first?A. Read the instructions.B. Try the buttons one by one.C. Have the machine repaired.5. What are the two speakers talking about?A. The weather forecast.B. An outdoor activity.C. The view of a lake.第二节（共10小题；每小题1.5分，共15分）听下面4段对话或独白。

朝阳期中文科

北京市朝阳区2015-2016学年度高三年级第一学期期中统一考试数学试卷（文史类） 2015.11（考试时间120分钟满分150分）本试卷分为选择题（共40分）和非选择题（共110分）两部分第一部分（选择题共40分）一、选择题：本大题共8小题，每小题5分，共40分．在每小题给出的四个选项中，选出符合题目要求的一项.1. 已知集合}2{>=x x A ，B ＝{(1)(3)0}x x x --<，则A ∩B =A ．{1}x x >B ．{23}x x <<C ．{13}x x <<D ．{2x x >或1}x < 2. 设平面向量(,1)x =a ，(4,)x =b , 且⋅a b 1=-, 则实数x 的值是 A ．2- B ．1- C ．13-D ．15- 3.下列函数在(,0)(0,)-∞+∞ 上既是偶函数，又在),0(+∞上单调递增的是A ．2y x =-B ．1y x -=C ．2log y x =D ．2x y =-4．已知1tan 3θ=，那么πtan ()4θ+等于 A ．2 B ．2- C ．12D ． 12-5. 要得到函数sin(2)3y x π=-的图象，只需将函数sin 2y x =的图象A ．向左平移π6个单位 B ．向右平移π6个单位 C ．向左平移π3个单位 D ．向右平移π3个单位6. 下列命题正确的是A. “1<x ”是“0232>+-x x ”的必要不充分条件B. 若给定命题p ：x ∃∈R ，使得210x x +-<，则p ⌝：,x ∀∈R 均有012≥-+x x C. 若q p ∧为假命题，则q p ,均为假命题D. 命题“若0232=+-x x ，则2=x ”的否命题为“若 ,0232=+-x x 则2≠x7.在ABC ∆中，已知4AB AC ⋅=3=，,M N 分别是BC 边上的三等分点，则⋅的值是A ．5B ．421C ．6D ．88. 已知函数2,()2.x x x a f x x a ⎧≤<=⎨≥⎩, 0, 若存在实数b ，使函数()()g x f x b =-有两个零点，则实数a 的取值范围是A ．(0,2)B ．(2,)+∞C ．(2,4)D ．(4,)+∞第二部分（非选择题共110分）二、填空题：本大题共6小题，每小题5分，共30分.把答案填在答题卡上. 9.若集合{}1,0,a ={}1,1,-bc ，则_____,_______.a b ==10.设等差数列{}n a 的前n 项和为n S ，若3612a a +=，48S =，则9a 的值是． 11.给出四个命题：①平行于同一平面的两个不重合的平面平行；②平行于同一直线的两个不重合的平面平行；③垂直于同一平面的两个不重合的平面平行；④垂直于同一直线的两个不重合的平面平行；其中真命题的序号是________．12．已知函数()2sin f x x ω=(0>ω)的最小正周期为π，则=ω ，在(0,)π内满足0)(0=x f 的0x ＝．13. 若函数()sin cos f x a x x =+在区间ππ(,)64上单调递增，则实数a 的取值范围是 .14.如图，在ABC ∆中，4A B A C==，90BAC ∠= ，D 是BC 的中点，若向量14AM AB mAC =+（m ∈R ），且点M 在ACD ∆的内部（不含边界），则AM BM ⋅ 的取值范围是．三、解答题：本大题共6小题，共80分.解答应写出文字说明，演算步骤或证明过程. 15. （本小题满分13分）已知函数2()cos 2cos 222x x x f x =+. （Ⅰ）求)(x f 的最小正周期；（Ⅱ）求)(x f 的单调递减区间. 16. （本小题满分13分）设等差数列{}n a 的前n 项和为n S ，n *∈N ，公差30,15,d S ≠=已知1341,,a a a 成等比数列.（Ⅰ）求数列{}n a 的通项公式；（Ⅱ）设2n n b a =，求数列{}n b 的前n 项和n T . 17. （本小题满分14分）如图, 在三棱柱111A B C A B C-中，1CC ⊥底面ABC ,CB AC ⊥,点D 是AB 的中点．（Ⅰ）求证：1AC BC ⊥；（Ⅱ）求证：1AC ∥平面1CDB .(Ⅲ)设12AB AA =,AC BC =,在线段11A B 上是否存在点M ，使得1BM CB ⊥?若存在,确定点M 的位置;若不存在，说明理由. 18. （本小题满分13分）在ABC ∆中，角C B A ,,所对的边分别为c b a ,,．已知21cos -=B ．（Ⅰ）若322==b a ,，求ABC ∆的面积；（Ⅱ）求C A sin sin ⋅的取值范围． 19. （本小题满分13分）已知函数2()ln (1)2x f x a x a x =+-+，a ∈R ．（Ⅰ）若函数()f x 在区间(1,3)上单调递减，求a 的取值范围；（Ⅱ）当1a =-时，证明1()2f x ≥. 20. （本小题满分14分）已知函数2()e (1)xf x ax bx =++(其中a ，b ∈R ),函数()f x 的导函数为()f x '，且(1)0f '-=．(Ⅰ)若1b =，求曲线()y f x =在点(0,(0))f 处的切线方程； (Ⅱ)若函数()f x 在区间[1,1]-上的最小值为0，求b 的值．北京市朝阳区2015-2016学年度高三年级第一学期期中统一考试数学答案（文史类） 2015.11一、选择题：（满分40分）二、填空题：（满分30分）（注：两空的填空，第一空3分，第二空2分）三、解答题：（满分80分） 15. （本小题满分13分）（I ）由已知可得：()cos 1f x x x ++ 2sin()16x π=++.所以)(x f 的最小正周期为2π. …………………..7分（II ）由2222k x k ππ3ππ+≤+≤π+6，k ∈Z , 得2233k x k π4ππ+≤≤π+,k ∈Z .因此函数)(x f 的单调递减区间为[2,2]33k k π4ππ+π+,k ∈Z .…………………..13分 16. （本小题满分13分）解：（I ）依题意，1211132315,2(3)(12).a d a d a a d ⨯⎧+=⎪⎨⎪+=+⎩ 解得13,2.a d =⎧⎨=⎩因此1(1)32(1)21,21n n a a n d n n a n =+-=+-=+=+即. …………………..6分 (Ⅱ)依题意，1212212+=+⨯==+n n n n a b .12n n T b b b =+++ 231(21)(21)(21)n +=++++++=23122...2n n +++++4(12)12n n-=+-22 4.n n +=+- …………………..13分17.（本小题满分14分）（I ）在三棱柱111ABC A B C -中，因为1CC ⊥底面ABC ，AC ⊂底面ABC ，所以1CC AC ⊥.又AC BC ⊥，1BC CC C = , 所以11AC BCC B ⊥平面．而111BC BCC B ⊂平面，则1AC BC ⊥. …………………..4分 (Ⅱ)设1CB 与1C B 的交点为E ，连结DE ，因为D 是AB 的中点，E 是1BC 的中点，所以DE ∥1AC .因为1DE CDB ⊂平面，11AC CDB ⊄平面，所以1AC ∥1CDB 平面.…………………..9分(Ⅲ)在线段11A B 上存在点M ，使得1BM CB ⊥,且M 为线段11A B 的中点.证明如下：因为1AA ⊥底面ABC ，CD ⊂底面ABC ,所以1AA CD ⊥.由已知AC BC =，D 为线段AB 的中点，所以CD AB ⊥.EEM又1AA AB A = ，所以CD ⊥平面11AA B B .取线段11A B 的中点M ，连接BM . 因为BM ⊂平面11AA B B ，所以CD BM ⊥.由已知12AB AA =，由平面几何知识可得1BM B D ⊥. 又1CD B D D = ,所以BM ⊥平面1B CD . 又1B C ⊂平面1B CD ，所以1BM CB ⊥.…………………..14分18. （本小题满分13分）（I ）在ABC ∆中，因为1cos 2B =-，所以2π3B =，sin B = 由正弦定理,sin sin a bA B=可得2sin A =则1sin 2A =. 又A 为锐角，则6A π=，所以6C π=. 所以1sin 2ABC S ab C ∆=11222=⨯⨯.……………………………………………………………6分（II ）sin sin sin()sin 3A C C C π⋅=-⋅=1sin sin )2C C C ⋅-12(1cos 2)4C C --11sin(2)264C π=+-. 因为(0,)3C π∈，所以52(,)666C πππ+∈.则1sin(2)(,1]62C π+∈.所以C A sin sin ⋅的取值范围是1(0,]4. ………………………………………13分19. （本小题满分13分）解：（I ）函数的定义域为(0,)+∞.因为2(1)(1)()()(1)a x a x a x x a f x x a x x x-++--'=+-+==.又因为函数()f x 在(1,3)单调减，所以不等式(1)()0x x a --≤在(1,3)上成立. 设()(1)()g x x x a =--，则(3)0g ≤，即93(1)0a a -++≤即可，解得3a ≥. 所以a 的取值范围是[3,)+∞. …………………………………7分（Ⅱ）当1a =-时，2()ln 2x f x x =-+，211(1)(1)()x x x f x x x x x-+-'=-+==.令()0f x '=，得1x =或1x =-（舍）. 当x 变化时，(),()f x f x '变化情况如下表：所以1x =时,函数()f x 的最小值为(1)2f =. 所以1()2f x ≥成立. ………………………………13分20. （本小题满分14分）解：因为2()e (1)xf x ax bx =++，所以2()e [(2)1]xf x ax a b x b '=++++．因为(1)0f '-=，所以(2)10a a b b -+++=．所以1a =． ……………………2分 (Ⅰ)当1a =时，1b =时， (0)1,(0)2f f '==，所以曲线()y f x =在点(0,(0))f 处的切线方程为12(0)y x -=-．即210x y -+=． ……………………4分 (Ⅱ)由已知得2()e (1)x f x x bx =++，所以2()e [(2)1]e (1)(1)x x f x x b x b x x b '=++++=+++．（1）当11b --<-，即0b >时，令()e (1)(1)0x f x x x b '=+++>得，1x >-或1x b <--；令()e (1)(1)0x f x x x b '=+++<得，11b x --<<-．所以函数()f x 在(1,)-+∞和(,1)b -∞--上单调递增，在(1,1)b ---上单调递减．所以函数()f x 在区间[1,1]-上单调递增．所以函数()f x 在区间[1,1]-上的最小值为1(1)e (2)0f b --=-=．解得2b =．显然合题意．（2）当11b --=-时，即0b =时，2()e (1)0x f x x '=+≥恒成立，所以函数()f x 在(,)-∞+∞上单调递增．所以函数()f x 在区间[1,1]-上单调递增．所以函数()f x 在区间[1,1]-上的最小值为1(1)e (2)0f b --=-=．解得2b =．显然不符合题意．（3）当11b -->-时，即0b <时，令()e (1)(1)0xf x x x b '=+++>得，1x <-或1x b >--；令()e (1)(1)0xf x x x b '=+++<得，11x b -<<--．所以函数()f x 在(,1)-∞-和(1,)b --+∞上单调递增，在(1,1)b ---上单调递减． ①若11b --≥，即2b ≤-时，函数()f x 在区间[1,1]-上单调递减．所以函数()f x 在区间[1,1]-上的最小值为(1)e(2)0f b =+=．解得2b =-．显然合题意．②若11b --<，即20b -<<时，函数()f x 在在(1,1)b ---上单调递减，在(1,1)b --上单调递增．此时，函数()f x 在区间[1,1]-上的最小值为1(1)e(2)0b f b b ----=+=．解得2b =-．显然不合题意．综上所述，2b =或2b =-为所求． ……………………14分关注课外100网，及时获得最新教研资料。

北京市朝阳区2015届高三上学期期中统一考试英语试题 Word版含答案

北京市朝阳区2014—2015学年度高三年级第一学期期中统一考试英语试卷2014. 11（考试时间120分钟满分150分）本试卷共12页，共150分，考试时长120分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

考试结束后，将本试卷和答题卡一并交回。

第一部分：听力理解（共三节，30分）第一节（共5小题；每小题1.5分，共7.5分）听下面5段对话。

每段对话后有一道小题，从每题所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你将有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话你将听一遍。

例：What is the man going to read?A. A newspaper.B. A magazine.C. A book.答案是A。

1. How will the woman go to the hospital?A. By taxi.B. By motorcycle.C. By bus.2. When does the woman usually have breakfast?A. At 7:00.B. At 8:00.C. At 10:00.3. What does the man ask the woman to do?A. Park the car elsewhere.B. Drive along a quiet street.C. Stop here for a few minutes.4. Where does this conversation probably take place?A. At a bookstore.B. At a department shop.C. At the dry cleaner’s.5. What are the speakers discussing?A. Whether to work hard.B. How to pay for the house.C. Whether to go on a holiday.第二节（共10小题；每小题1.5分，共15分）听下面4段对话或独白。

北京市朝阳区2015届高三上学期期中统一考试英语试题及答案

北京市朝阳区2014—2015学年度高三年级第一学期期中统一考试英语试卷2014. 11（考试时间120分钟满分150分）本试卷共12页，共150分，考试时长120分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

考试结束后，将本试卷和答题卡一并交回。

第一部分：听力理解（共三节，30分）第一节（共5小题；每小题1.5分，共7.5分）听下面5段对话。

每段对话后有一道小题，从每题所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你将有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话你将听一遍。

例：What is the man going to read?A. A newspaper.B. A magazine.C. A book.答案是A。

北京市朝阳区2015届高三上学期期中英语试题

北京市朝阳区2014—2015学年度高三年级第一学期期中统一考试英语试卷2014. 11第二部分：知识运用（共两节，45分）第一节单项填空（共15小题; 每小题1分，共15分）21. Being ______ highly skilled reader is ______ key to becoming successful in the Information Age.A. a; 不填B. 不填; aC. the; aD. a; the22. Food and fruit are forbidden in the library, ______ you are allowed to have drinks and sweets with you.A. andB. butC. soD. or23. Mr. Smith had to go to work by bus this morning as his car ______.A. would repairB. was repairingC. had been repairedD. was being repaired24. Some countries have banned smoking in public places ______ public health.A. improveB. to improveC. improvingD. improved25. Harry Potter has made reading popular again, ______ is why parents and teachers like the book, too.A. thatB. whoC. whichD. what26. We still have some other ways to solve the problem. You ______ be worried.A. mustn’tB. can’tC. don’t have toD. may not27. ______ the sight was impressive on the top of the mountain, I made an effort to climb onto it.A. To knowB. KnowC. KnownD. Knowing28. ______ Tina cares about most is whether the company provides opportunities for further education.A. WhichB. WhatC. ThatD. Why29. ______ the price of gas is starting to come down, many people are choosing to take the bus or the train instead.A. Even thoughB. Now thatC. In caseD. As though30. —Can you tell me how many people will go to the exhibition?—Of course. About 3,000 students from 15 schools ______, and I think two-thirds will come.A. inviteB. will inviteC. have been invitedD. had been invited31. —Excuse me, Miss Jones. Do you know where the sales report is?—Isn’t it on your desk? I ______ it back in the file after I read it.A. putB. have putC. had putD. will put32. —Where would you like to sit? In the corner or near the platform?—______. I would like to sit by the piano so that I can watch the musician play.A. EitherB. NeitherC. NoneD. Both33. More people are choosing to work ______ retirement age.A. atB. inC. forD. beyond34. Passers-by rescued a motorcycle driver ______ under a burning car.A. was trappedB. trappingC. having trappedD. trapped35. If Susan ______ for ten more minutes at the party last night, she might have met Johnny Depp, the famousHollywood star.A. stayedB. would stayC. had stayedD. would have stayed第二节完形填空（共20小题；每小题1.5分，共30分）Make the Most of What You Have GotFor Nick Vujicic, life was going to be difficult from the day he was born. When Nick arrivedinto this world, he 36 everyone. He was not like the other babies and it was 37 obvious to his parents and to the doctors in the hospital.There was no 38 or answers for his condition. Nick was born without any limbs—that is he was born without any arms or legs. But despite being physically 39 , he was mentally 40 and the rest of his body was functioning fine.41 he had loving parents, Nick would find school hard as he would often be looked down upon by the other children and at the young age of 10, he considered 42 his life by drowning himself in a bathtub. These dark thoughts were 43 by his negative attitude to being disabled and at the time, he thought that he would never be able to do 44 by himself, that he would never have a job and that he would always have to 45 on his parents for help.Nick was wrong.As an adult, Nick is a successful public speaker and is famous for his motivational 46 which focus on life with a disability, hope and finding meaning in life worldwide. He 47 so many people with the story of his life, how he has 48 so many difficulties and most importantly how he is happy every day.Despite having no arms or legs, Nick lives 49 , even finding ways to do almost 50 things like brushing his teeth on his own and swimming. He has to work harder than a full bodied person and he achieves his goals.At the first impression, you may look at Nick and feel 51 . You may feel sad that this man has no arms or legs and you might feel his 52 and upset that he could find everyday situations difficult. But we should 53 Nick, as he is extremely positive and he gets on with life. He 54 every day and makes the best of what he has: a positive attitude, a creative mind and a powerful 55 . He also has a very kind and very beautiful wife and they are truly happy and in love.36. A. shocked B. pleased C. inspired D. accepted37. A. nervously B. painfully C. hopefully D. cautiously38. A. surprise B. worry C. explanation D. apology39. A. active B. sick C. disabled D. abused40. A. disturbed B. challenged C. calm D. normal41. A.Since B. If C. Although D. Unless42. A. changing B. ending C. risking D. sharing43. A. expressed B. collected C. given D. driven44. A. something B. nothing C. everything D. anything45. A. call B. rely C. cheat D. look46. A. lessons B. poems C. speeches D. posters47. A. convinces B. touches C. puzzles D. judges48. A. faced B. created C. met D. overcome49.A.independently B. comfortably C. hopelessly D. lonely50. A. impossible B. dangerous C. crazy D. regretful51. A. pain B. guilt C. panic D. pity52. A. annoyance B. selfishness C. courage D. confidence53. A. encourage B. admire C. comfort D. correct54. A. cries B. shouts C. smiles D. struggles55. A. voice B. body C. family D. position第三部分：阅读理解（共两节，40分）第一节（共15小题；每小题2分，共30分）ATraveling Museum ExhibitionsIn the past, if a person wanted to see the national treasures of a country, one had to go there in person. Therefore, very few people were able to enjoy some of history’s most important and interesting artifacts (手工艺品). This has changed with an increase in the number of traveling museum exhibitions.King Tutankhamen ArtifactsA traveling exhibition of artifa cts from the tomb of King Tutankhamen, popularly known as “King Tut”, toured the United States from November 1976 to April 1979. The 55 objects were shown in six cities and were seen by around eight million museum-goers. The second touring exhibit was started in 2007, this time with 130 artifacts and stops in London and three different American cities. However some objects, like the king’s golden face mask, are too valuable or too delicate to be transported long distances, so “replicas” (exact copies of som ething) are on show.Japanese Color Woodblock PrintsThe Art Museum at University of Virginia, in Charlottesville, Virginia, has an extraordinary collection of Japanese color woodblock prints (木刻版画). These prints document the period from about 1850 to 1900, a time when Japan was opening itself to Western influences. Before this point, Japan was a closed society that had little communication with the world outside of its borders. These works of art beautifully show the feeling of change and the trend toward modernization. The museum has put together a traveling exhibition of 60 of these prints, which can be borrowed and exhibited worldwide for periods of eight weeks or more.Face-to-face with “Lucy”One of the world’s most famous archaeological (考古学的) finds in history are the 3.2 million-year-old bones of a 106-centimeter-tall female found in the Ethiopian desert in 1974. Lucy, a name given to her by the discovery team, is a “hominid”, or a creature that scientists believe is the earliest ancestor of modern human beings. Rarely is an artifact this valuable allowed to travel widely, but Lucy has been taken to several museums in the U.S. while a detailed replica remains at the Ethiopian Natural History Museum.56. What d o we learn about King Tutankhamen’s artifacts?A. The artifacts were shown in London first.B. The artifacts were on show in the United States once.C. The second touring exhibit showed more artifacts than the first one.D. The king’s golden face mask w as also shown in the traveling exhibitions.57. What do the Japanese woodblock prints show about the society from 1850 to 1900?A. Japan had little communication with other countries.B. The whole country refused changes in the society.C. Japan was opening itself up to Western ideas.D. Japan achieved modernization.58. Who is Lucy according to the passage?A. An archaeologist.B. The ancestor of modern human beings.C. A 106-centimeter-tall female who died in 1974.D. The first woman who visited the Ethiopian desert.B（Published March 30, 2011）Albert Einstein’s Theory of Relativity might have a few mistakes—and Jake Barnett has set out to prove it. Between attending college classes at Indiana University-Purdue University Indianapolis (IUPUI) and tutoring his fellow students, Jake is also working on a new theory about the creation of the universe. He happens to be 12 years old.From an early age, Jake showed an extraordinary interest in stars. When he was 3, his parents took him to a space observatory. He tried to learn as much as he could about astron omy. Jake’s IQ measured remarkably high at 170.As a baby, Jake was found out with Asperser’s syndrome, a form of autism (孤独症). Autism causes difficulties in communication and social abilities. People with autism may also have strong interests—like Jake’s interest in the stars at a young age.The symptoms of autism can range from mild to extremely severe. Asperser’s is one of the milder forms of autism. Sometimes people with Asperser’s, like Jake, develop extremely advanced skills in science, music or art.When Jake was in elementary school, his parents worried that the effects of his Asperser’s were worsening. Headvanced subjects, like math and physics.Jake’s mother asked an astronomy professor to let Jake sit in on his class. Now, Jake studies advanced sciences like electromagnetic physics at IUPUI.But Jake thinks it’s important to have a normal life too. He likes to play Guitar Hero with his friends and watch science fiction movies. He also enjoys playing classical music on the piano. But for Jake, studying physics is the most important thing. Jake’s professor, John Ross, is working on get ting a large sum of money for him to do research at the university.Doctors have said Jake’s autism symptoms have lessened over time. Still, Jake proudly refers to himself as an “Aspy”, or someone with Asperser’s. In an interview with his university student newspaper, he said, “I think the autism is the reason I’m even at IUPUI.”59. What did Jake want to do at IUPUI?A. Get a degree in astronomy.B. Put forward his own theory in physics.C. Become an Albert Einstein in the future.D. Teach his fellow students Theory of Relativity.60. Which of the following is the correct order of the events that happened to Jake?a. He set out to disprove Einstein’s theory.b. He was interested in astronomy.c. He began to study math and physics.d. He was found out with a mild form of autism.A. b-d-c-aB. d-b-c-aC. b-a-c-dD. d-c-b-a61. The underlined sentence in the passage means ______.A. he was unable to help othersB. he was impolite to other peopleC. he was afraid of seeing other peopleD. he was only concerned about learning62. In the eyes of Jake, autism is something ______.A. not worth worrying aboutB. annoyingC. not necessary to know aboutD. embarrassingCScientists have produced new evidence suggesting eating lots of red and processed meat damages health. They found big meat eaters had a raised risk of death from all causes over a 10-year period. In contrast, a higher intake of white meat was associated with a slightly reduced risk of death over the same period.The US study, based on more than 500,000 people, found those whose diet contained the highest proportion (比例) of red or processed meat had a higher overall risk of death, and specifically a higher risk of cancer and heart disease than those who ate the least.People eating the most meat were eating about 160g of red or processed meat per day— approximately a 6oz steak. Those who ate the least were only getting about 25g per day— approximately a small piece of bacon. Just the opposite, those who ate the highest proportion of white meat had a lower risk of overall death, and a lower risk of fatal cancer or heart disease than those who ate the lowest proportion.Meat is a major source of saturated (饱和的) fat, which has been associated with breast and colorectal cancer. In addition, lower meat intake has been linked to a reduction in risk factors for heart disease, including lower blood pressure and cholesterol (胆固醇) levels. The latest study adds to a growing body of research linking high red and processed meat consumption to an increased risk of ill health. Ed Yong, of the charity Cancer Research UK, said, “Evidence from large studies tells us that cutting down on processed food, such as bacon or burge rs, can reduce the risk of dying from cancer and other diseases.”Dr Barry Popkin of the University of North Carolina stressed there were health benefits from eating some red meat. But he added: “The need is for a major reduction in total meat intake, an e ven larger reduction in processed meat and other highly processed and salted animal source food products and a reduction in total saturated fat.” Dr Mark Wahlqvist, a nutrition expert from Australia, said eating small amounts of red meat—around 30g a day—provided a good source of key nutrients. He said, “Fresh, lean red meat of these amounts is likely to be of more benefit than harm.”63. According to the passage, we know ______.A. big meat eaters eat a 6oz steak per dayB. big meat eaters have heart disease ten years earlierC. people eating more meat will suffer from a heart attackD. people eating more red meat have a higher risk of death64. Processed meat is a kind of ______.A. red meatB. white meatC. vegetable with a similar taste of meatD. meat prepared by producers65. According to the passage, how should we eat red meat in a healthy way?A. We should eat red meat as we like.B. We should eat proper amount of red meat per day.C. We should reduce the amount of fresh, red lean meat.D. We should completely cut out red meat from our diet.66. What does the passage mainly talk about?A. Too much red meat consumption contributes to ill health.B. A well-balanced diet accounts for a healthy life.C. A higher intake of white meat brings benefits.D. Red meat contains saturated fat.DAre you single or married? Are you a cat or a dog owner? Do you exercise, or are you a “couch potato” (a person who sits on the sofa all day watching TV, eating and basically doing nothing)? These questions and many others are about your lifestyle.People in the United States feel that they can choose their lifestyles and even shape their own identities. The great variety of lifestyles leads to constant national discussion of choices that people make. This freedom of choice is fun and exciting, but it also creates stress and uncertainty. In newspapers, lifestyle issues are discussed in the features or style section. In The Chicago Tribune this s ection is called “Tempo”. People turn to this section for lively discussion on lifestyle choices they face with regard to their personal identities, their families, and their social lives.Many American people believe that they can make their lives happy and satisfying despite their problems. If they lack confidence or tend to feel anxious, shy, angry, or depressed, they believe that they can change themselves. Self-help books, magazines, and feature articles are filled with advice from experts about steps to take to become a happier or more satisfied person and to improve one’s self-respect. Part of this research for self-improvement is a belief that even one’s own appearance can be controlled. This is why there are so many articles in the newspaper about l ooking young, wearing the latest fashions, and becoming physically fit.Lifestyle choices also involve moral and social issues. How should children be raised? How should people behave on a date? How should elderly people be treated? How can people stay happily married? All these kinds of issues are constantly discussed and are constantly changing. Not only are experts such as psychologists consulted, but stars from the political and entertainment worlds are held up as lifestyle leaders as well. In the newspaper, feature articles called profiles discuss in detail the personal lives or public work of movie stars, authors, artists, and exceptional individuals who are not stars. The lifestyle choices these people make contribute to the public discussion of all the issues that people think about.A well-known advertising slogan is “Just do it.” In the culture of the United States, people believe that they can take action and become the kind of people they want to be and live the way they want to live.67. The section “Tempo” in The Chicago Tribune mainly discusses ______.A. lifestyle choicesB. current affairsC. experts’ opinions on lifeD. how to improve one’s self-respect68. According to the author, Americans are pretty sure that they can ______.A. control their own appearanceB. solve all the problems in their lifeC. live a happy life in spite of their problemsD. improve their life by following the elders’ advice69. According to the passage, p eople’s opinions on moral or social issues can be influenced by ______.A. their superiorsB. family membersC. friends and colleaguesD. experts and famous people70. Which is the best title for the passage?A. Just Do ItB. Make Our Lives HappyC. Lifestyles in the United StatesD. Choosing the Way We Live第二节（共5小题；每小题2分，共10分）根据短文内容，从短文后的七个选项中选出能填入空白处的最佳选项。

【数学】北京市朝阳区2016届高三上学期期中考试(文).docx

北京市朝阳区 2016 届高三上学期期中考试数学试卷（文科）（考试时间120 分钟满分150 分）本试卷分为选择题（共40 分）和非选择题（共110 分）两部分第一部分（选择题共40 分）一、选择题：本大题共8 小题，每小题 5 分，共 40 分．在每小题给出的四个选项中，选出符合题目要求的一项 .1. 已知集合A{ x x2} ，B＝{ x (x1)(x3)0} ，则A∩B=（）A ． { x x 1}B．{ x 2 x 3}C．{ x 1 x 3}D． { x x 2 或x 1}2. 设平面向量a( x,1) ，b (4, x) , 且a b1,则实数x的值是（）A ．2B ．111 C． D ．353.下列函数在(,0)(0, ) 上既是偶函数，又在(0, ) 上单调递增的是（）A ．y x2B ．y x 1C．y log 2 x D． y2x4．已知tan 1，那么 tan(π3) 等于（）4A ．2B．2C．1D．1 225.要得到函数y sin(2 x) 的图象，只需将函数y sin 2x 的图象（）3A ．向左平移个单位B．向右平移个单位66 C．向左平移个单位D．向右平移个单位336.下列命题正确的是（）A.“x 1”是“x23x 2 0 ”的必要不充分条件1C. 若 p q 为假命题，则 p, q 均为假命题D. 命题 “若 x 23x 20 ，则 x2 ”的否命题为 “若 x 2 3x 20, 则 x 27.在 ABC 中，已知 AB AC4 ， BC3 ， M , N 分别是 BC 边上的三等分点，则AM AN的值是（）21 C ． 6D ． 8A ． 5B ．48. 已知函数 f (x)x 2, 0 x a,若存在实数 b ，使函数 g(x)f ( x) b 有两个零点，2x ,xa.则实数 a 的取值范围是（）A ． (0, 2)B ． (2, )C ． (2, 4)D ． (4, )第二部分（非选择题共110 分）二、填空题：本大题共6 小题，每小题 5 分，共 30 分 .把答案填在答题卡上 .1 9.若集合 { a,0,1} ={ c, , 1} ，则 a _____,b_______.b10.设等差数列a n 的前 n 项和为 S n ，若 a 3 a 6 12 ， S 4 8 ，则 a 9 的值是．11.给出四个命题：①平行于同一平面的两个不重合的平面平行；②平行于同一直线的两个不重合的平面平行；③垂直于同一平面的两个不重合的平面平行；④垂直于同一直线的两个不重合的平面平行；其中真命题的序号是 ________．12．已知函数 f (x) 2sinx (0 )的最小正周期为，则，在 0,( ) 内满足 f ( x 0 ) 0的 x 0＝．π π13. 若函数 f (x) a sin xcosx 在区间 ( ,) 上单调递增，则实数 a 的取值范围是 .6 414. 如图，在 ABC 中， A B A C 4 ，BAC 90 ， D 是 BC 的中点，若向量AM1AB mAC （ m R ），且点 M 在 ACD 的内部（不含边界），则 AM BM 的取值范4围是．三、解答题：本大题共 6 小题，共80 分 .解答应写出文字说明，演算步骤或证明过程.15. （本小题满分13 分）已知函数 f ( x) 2 3sin xcosx2cos 2x. 222（Ⅰ）求 f ( x) 的最小正周期；（Ⅱ）求 f ( x) 的单调递减区间.16.（本小题满分 13 分）设等差数列a n的前n项和为 S n，n N ，公差d0, S315, 已知a1, a4, a13成等比数列 .（Ⅰ）求数列a n的通项公式；（Ⅱ）设 b n a2n，求数列b n的前n项和T n.17.（本小题满分14 分）如图 , 在三棱柱ABC A1B1C1中，CC1底面ABC ,AC CB ,点 D 是 AB 的中点．（Ⅰ）求证：AC BC1；（Ⅱ）求证：AC1∥平面 CDB1.(Ⅲ )设AB2AA1, AC BC ,在线段A1 B1上是否存在点M ，使得 BM CB1?若存在,确定点 M 的位置;若不存在，说明理由.18.（本小题满分 13 分）在 ABC 中，角A,B,C所对的边分别为a,b,c．已知 cos B 1 ．2（Ⅰ）若 a 2, b 2 3 ，求 ABC 的面积；（Ⅱ）求 sin A sin C 的取值范围．19. （本小题满分13 分）已知函数 f ( x) a ln x x2( a 1) x ，a R．2（Ⅰ）若函数 f ( x) 在区间 (1,3) 上单调递减，求 a 的取值范围；（Ⅱ）当 a 1 时，证明1 f ( x).220.（本小题满分 14 分）已知函数 f ( x) e x (ax2bx 1) (其中 a ，b R ),函数f ( x)的导函数为f ( x)，且f ( 1)0．(Ⅰ )若b 1 ，求曲线 y f (x) 在点 (0, f (0)) 处的切线方程；(Ⅱ )若函数 f (x) 在区间 [ 1,1] 上的最小值为0 ，求 b 的值．参考答案一、：（分 40分）号12345678答案B D C A B B C C 二、填空：（分 30分）号91011121314答案1,115①④ 2 ,[1, )2,62（注：两空的填空，第一空 3 分，第二空 2 分）三、解答：（分 80 分）15.（本小分 13 分）（I ）由已知可得：f ( x)3sin x cosx 12sin( x)1 .6所以 f (x) 的最小正周期 2 .⋯⋯⋯⋯⋯⋯⋯ ..7 分（II ）由2k x2k， k Z ,22得 2k x2k, k Z .33因此函数 f (x) 的减区 [2 k,2 k] , k Z.33⋯⋯⋯⋯⋯⋯⋯..13分16.（本小分 13 分）解：（ I）依意，3a32 d15,12( a13d)2a1 ( a1 12d ).a13,解得d2.因此 a n a1( n 1)d 3 2(n 1) 2n 1, 即a n2n 1 .⋯⋯⋯⋯⋯⋯⋯..6分(Ⅱ )依意，b n a2n22n12n 11.T n b1 b2b n(221)(231)(2n 1 1)=2223...2n1n4(1 2 n )n122n2n 4.⋯⋯⋯⋯⋯⋯⋯ ..13分17.（本小分14 分）（ I）在三棱柱ABC A1 B1 C1中，因 CC1底面ABC，AC底面ABC，所以 CC1AC .又 AC BC ，BC CC1 C ,所以 AC平面BCC1B1．而BC1平面BCC1B1，AC BC1.⋯⋯⋯⋯⋯⋯⋯..4分(Ⅱ )CB1与 C1 B 的交点E，DE，因 D 是 AB 的中点， E 是BC1的中点，E 所以 DE ∥AC1.因 DE平面CDB1，AC1平面CDB1，所以AC1∥平面CDB1.⋯⋯⋯⋯⋯⋯⋯ ..9分(Ⅲ )在段A1B1上存在点M，使得BM CB1,且M段A1B1的中点 .明如下：因 AA1底面 ABC ， CD底面 ABC ,M 所以 AA1CD .E 由已知 AC BC ，D段AB的中点，所以 CD AB .又 AA 1 AB A ，所以 CD 平面 AAB B .1 1取段 A 1 B 1 的中点 M ，接 BM . 因 BM 平面 AA 1B 1 B ，所以 CD BM .由已知 AB 2AA 1 ，由平面几何知可得 BM B 1 D .又 CD B 1D D ,所以 BM 平面 B 1CD .又 11BC平面 B CD ，所以 BMCB 1 .⋯⋯⋯⋯⋯⋯⋯..14分18. （本小分 13 分）（I ）在ABC 中，因 cos B1 ，2所以 B2π， sin B3 .32由正弦定理ab ,sin A sin B可得2 2 31 sin A, sin A.322又 A 角， A，所以 C .66所以 S ABC1ab sin C211 22 3223 .. ⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯6分（II ） sin A sinCsin( C) sinC3= sin C3cosC 1 ( sin C)22=3sin 2C1(1 cos2C )441sin(2C) 1 .264因 C(0,) ，3所以2C5( ,) .666 sin(2C)( 1 ,1].62所以 sin A sin C 的取范是1⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯13分(0, ] .419.（本小分 13 分）解：（ I）函数的定域(0,) .因 f ( x)a(ax2(a 1)x a( x1)( x a) x1)x x. x又因函数 f ( x) 在(1,3)减，所以不等式( x1)(x a)0 在(1,3)上成立.g( x) ( x1)(x a) ， g (3)0 ，即 93(a1)a0 即可，解得 a 3.所以a的取范是[3,) .⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯7 分（Ⅱ）当 a 1 ， f ( x)ln x x2，2f (x)1xx21(x1)(x 1) x x x.令 f(x)0 ，得x1或 x 1 （舍）.当 x 化， f ( x), f ( x) 化情况如下表：x(0,1)1(1, )f ( x)0+f (x)极小所以 x 1,函数f ( x)的最小f (1)1 . 2所以 f (x)1⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯13分成立 .220.（本小分 14 分）解：因 f (x)e x (ax2bx1) ，所以f( x)e x[ ax2(2a b) x b 1] ．因 f(1)0 ，所以 a(2 a b)b10 ．所以 a 1 ．⋯⋯⋯⋯⋯⋯⋯⋯2 分( Ⅰ)当a1， b1，f (0)1, f (0) 2 ，所以曲 y f (x) 在点(0, f (0)) 的切方程y12( x0) ．即 2x y 10．⋯⋯⋯⋯⋯⋯⋯⋯4 分(Ⅱ )由已知得f ( x)e x (x2bx 1)，所以f ( x) e x[ x2(2b) x b 1]e x ( x 1)(x b1)．（ 1）当b11，即 b0，令 f(x) e x (x1)(x b1) 0 得，x 1 或 x b1 ；(x1)(1)0 得，．令) e (f x x x b b 1 x1所以函数 f (x) 在 (1,) 和 (,b1)上增，在( b1, 1) 上减．所以函数 f (x) 在区 [1,1] 上增．所以函数 f ( x) 在区 [1,1] 上的最小 f ( 1) e 1 (2b)0 ．解得 b 2 ．然合意．（ 2）当b11，即 b0 ，f ( x)e x( x1)20 恒成立，所以函数 f ( x) 在 (,) 上增．所以函数 f (x) 在区 [ 1,1] 上增．所以函数 f ( x) 在区 [ 1,1]上的最小 f (1) e 1 (2b) 0 ．解得 b 2 ．然不符合意．（ 3）当b11，即 b0 ，令 f ( x) e x ( x1)(x b1) 0 得，x1或 x b 1 ；x1)(1) 0得，．令( ) e (f x x x b1x b 1所以函数 f (x) 在 (, 1) 和 ( b 1,) 上增，在 (1, b1) 上减．①若 b 11，即 b 2 ，函数 f ( x) 在区 [ 1,1] 上减．所以函数 f (x) 在区 [ 1,1] 上的最小 f (1)e(2b)0 ．解得 b 2 ．然合意．②若 b 11，即 2b0 ，函数 f ( x) 在在 (1,b1) 上减，在( b 1,1) 上增．此，函数 f ( x) 在区 [1,1] 上的最小 f ( b1) e b 1(b2)0 ．解得 b 2 ．然不合意．上所述， b 2 或b 2 所求．⋯⋯⋯⋯⋯⋯⋯⋯14分。

北京市朝阳区2016届高三上学期期中考试物理试题(含答案)

所受的弹力。

下列说法中正确的是 A . N A 的方向由 B . N A 的方向由 A 指向 O ，N A >G A 指向 O ，N A < G 北京市朝阳区2015〜2016学年度高三年级第一学期期中统一考试物理试卷5. 如图所示，木板置于水平地面上，其上物块被水平绳子拴接在左端墙上，将木板水平向右匀速抽出的过程中绳子的拉力为 F ；现将木板水平向右加速抽出，则此过程中绳子的拉力 A .等于F B .小于F C .大于F D .无法确定6.如图所示，重为 G 的光滑半圆球对称地搁在两个等高的固定台阶上，A 、B 为半圆球上与台阶接触的点，半圆球的球心在 O 点，半圆球的重心 C 位于O 点正下方，v -120，N A 为半圆球上 A 点2015. 111. （考试时间90分钟满分100分）、本题共13小题，每小题 3分，共39分。

在每小题给出的四个选项中，只有一个选项是符合题目要求的。

把答案用 2B 铅笔填涂在答题卡上。

以下说法中符合事实的是A . 2. D . 比较 A .B .C . 汤姆生发现电子并提出了原子核式结构模型玻尔发现电子并提出了原子核式结构模型卢瑟福做了 a 粒子散射实验并提出了原子核式结构模型密里根做了 a 粒子散射实验并提出了原子核式结构模型 a 氏丫三种射线的电离作用和穿透能力B 射线的电离作用最强丫射线的电离作用最强 a 射线的穿透能力最强 Y 射线的穿透能力最强3.D .某飞机着陆时的速度是 60m/s ，随后减速滑行，如果飞机的平均加速度大小是则滑道的长度至少为 2m/s 。

为了使飞机能够安全地停下来, A . 900m 90m C . 1800m4.一辆汽车在水平公路上沿曲线由合力F 的四种方向，其中可能正确的是180mM 向 N 行驶，速度逐渐减小。

图中分别画出了汽车转弯所受.■VD2D . N A 的方向由A 指向C , N A = G7. 某质点做直线运动，其位移x 与时间t 的关系图像如图所示。

北京市朝阳区2015届高三上学期期中统一考试英语试卷

北京市朝阳区2014—2015学年度高三年级第一学期期中统一考试英语试卷2014. 11（考试时间120分钟满分150分）本试卷共12页，共150分，考试时长120分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

考试结束后，将本试卷和答题卡一并交回。

第一部分：听力理解（共三节，30分）第一节（共5小题；每小题1.5分，共7.5分）听下面5段对话。

每段对话后有一道小题，从每题所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你将有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话你将听一遍。

例：What is the man going to read?A. A newspaper.B. A magazine.C. A book.答案是A。

北京市朝阳区2015年届高中高三上学期期中统一考试英语试卷试题及答案

北京市旭日区 2014—2015 学年度高三年级第一学期期中一致考试英语试卷2014. 11（考试时间 120 分钟满分150分）本试卷共 12 页，共 150 分，考试时长120 分钟。

考生务势必答案答在答题卡上，在试卷上作答无效。

考试结束后，将本试卷和答题卡一并交回。

第一部分：听力理解（共三节，30 分）第一节（共 5 小题；每题 1.5 分，共7.5 分）听下边 5 段对话。

每段对话后有一道小题，从每题所给的A、 B、C三个选项中选出最佳选项。

听完每段对话后，你将有10 秒钟的时间往返答有关小题和阅读下一小题。

每段对话你将听一遍。

例： What is the man going to read?A. A newspaper.B. A magazine.C. A book.答案是 A。

1.How will the woman go to the hospital?A. By taxi.B. By motorcycle.C. By bus.2.When does the woman usually have breakfast?A. At 7:00.B. At 8:00.C. At 10:00.3.What does the man ask the woman to do?A.Park the car elsewhere.B.Drive along a quiet street.C.Stop here for a few minutes.4.Where does this conversation probably take place?A. At a bookstore.B. At a department shop.C. At the dry cleaner’ s.5.What are the speakers discussing?A.Whether to work hard.B.How to pay for the house.C.Whether to go on a holiday.第二节（共10 小题；每题 1.5 分，共15 分）听下边 4 段对话或独白。

【英语】北京市朝阳区普通高中校2016届高三上学期期中考试

北京市朝阳区普通高中校2015—2016学年第一学期期中考试高三年级英语班级学号姓名成绩第一卷（三大题，共115分）第一部分：听力理解（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例：What is the man going to read?A．A newspaper. B．A magazine. C．A book.答案是A。

1．What time is it now?A．6:10. B．6:50. C．5:30.2．Where does this conversation most probably take place?A．At a hospital. B．At the airport. C．At a library.3．What do you know about the woman in the conversation?A．She is a film director.B．She is an actress.C．She was awarded Best Actress at the Oscars.4．What are the speakers doing?A．Having a meeting. B．Talking about wars. C．Having a history class. 5．What do we know about Mary?A．She has some trouble with maths.B．She doesn’t like school.C．She does well in maths.第二节（共15小题；每题1.5分，满分22.5分）听下面6段对话或独白。

北京市朝阳区重点高中校2015-2016学年度第一学期期中测试高三化学试卷.pdf

（D）NaHSO4溶液中滴加NaHCO3溶液：H++HCO3－H2O+CO2↑
9．对于达到平衡的可逆反应：X + YW + Z，增大压强，正、逆反应速率（U）变化的情况如图所示。下列对X、Y、
W、Z四种物质状态的描述正确的是（A）W、Z均为气体，X、Y中只有一种为气体
（B）X、Y均为气体，W、Z中只有一种为气体
21．（分） A、B、C、D、E原子序数依次增大其中A与E同主族，B的最外层电子数是次外层电子数的2倍，C的最高
价氧化物对应的水化物与其氢化物反应生成一种盐XA、B、D、E可成A2D2、B2A2、E2D2都含有非极性共价键。
（1）C元素在周期表中的位置是_____________，写出B的最高价氧化物的电子式__________（2）X的水溶液显
_________（填酸、碱或中性，溶液中各种离子浓度大小顺序为_______________。
（3）A、B、D、E四种元素组成的化合物中原子个数最少的化合物化学式______________。
（4）火箭推进器中有液态的C2A4和液态A2D2，它们时和水蒸气，并放出大量的热。已知0.4 mol液态C2A4液态
的是（A）Al2O3 +3C===4Al+3CO2↑
（B）MgO + H2===Mg+H2O
（C）Fe3O4+4CO===3Fe+4CO2
（D）2HgO==2Hg + O2↑
6．卫生部下发紧急通知要求查处苏丹红红心鸭蛋红心鸭蛋红心鸭蛋红4号”的结构简式为：
。下列关于“苏丹红4号”说法中错误的是
五、（本题包括2小题，共1分）
25．（分）12g某液态有机化合物A完全燃烧14.4 g H2O和26.4 g有机化合物A蒸与的相对密度30，求：

北京市朝阳区2015届高三上学期期中统一考试英语试题

北京市朝阳区2015届高三上学期期中统一考试英语试题北京市朝阳区2014—2015学年度高三年级第一学期期中统一考试英语试卷 2014. 11（考试时间120分钟满分150分）本试卷共12页，共150分，考试时长120分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

考试结束后，将本试卷和答题卡一并交回。

第一部分：听力理解（共三节，30分）第一节（共5小题；每小题1.5分，共7.5分）听下面5段对话。

每段对话后有一道小题，从每题所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你将有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话你将听一遍。

例：What is the man going to read?A. A newspaper.B. A magazine.C. A book.答案是A。

北京市朝阳区2016届高三上学期期中考试物理试题

A
B
乙 1 关于本实验，以说法中确的是 A．若钩码的个数 N1＝N2＝2，N3＝4 时以完成实验 B．若钩码的个数 N1＝N2＝N3＝4 时以完成实验 C．拆钩码和绳子前应当用角器出段绳子之间的夹角 D．拆钩码和绳子前应当用天测出钩码的质 E．拆钩码和绳子前应当标记结点 O 的位置，并记录 OA OB OC 向 2 在作图时，图乙中确的是 15．图是用来探究小车质一时，其是该装置的视图选填 A 或 B 度和力之间关系的实验装置示意图，图乙
x/m
10
20 t/s
升h高度，在过程中 A．磅秤的示数等于mg B．磅秤的示数等于 0.1mg C．人的动能增了 0.9mgh D．人的机能增了 1.1mgh 10．某人地球卫星在似圆轨道行的过程中，于轨道所在处的空间在极其稀薄的空气，则 A．如预，卫星所的万有引力将越来越小 B．如预，卫星行一段时间后动能会增 C．卫星在似圆轨道常行时，于失现象卫星内的物体地球引力作用 D．卫星在似圆轨道常行时，其度介于第一度和第度之间 11．火车转弯时，如果铁路弯道的内外轨一高，外轨对轮缘如图 a 所示挤压的力 F 提供了火车转弯的向心力如图 b 所示，但是靠种法得到向心力，铁轨和车轮极易损在筑铁路时，弯道处的外轨会略高于内轨如图 c 所示，当火车以规的行驶度转弯时，内外轨均会到轮缘的挤压，设时的度大小为 v，以说法中确的是
段绳子的方
细绳
小车夹子
乙
本实验有以骤 A．将一端附有滑轮的长木板放在水桌面，两个质相等的小车，放在似滑的水长木板 B ．打开夹子，让两个小车同时从静开始动，小车动一段距离后，关夹子，让两个小车同时停来，用刻度尺别测出两个小车在一段时间内通过的位移大小 C．析所得到的两个小车在相同时间内通过的位移大小小车所的水拉力的大小关系，从而得到质相等的物体动的度物体所力的关系 D．在两小车的后端别系细绳，用一只夹子夹住两细绳 E．在两小车的前端别系细绳，绳的另一端跨过滑轮各一个小盘，盘内别放着质等的砝码，使砝码盘和盘内砝码的总质小于小车的质别用天测出两个砝码盘和盘内砝码的总质对于述实验骤，确的排列顺序是 2 若测得砝码盘和盘内砝码的总质别为 m1 m2，对应小车的位移大小别为 x1 x2，过多次复实验，在误差允许的范围内若关系式总成立，则表明小车的质一时，其小车的度合力成比 16．如图 1 所示，是利用自落体动行验证机能恒律的实验所用的打点计时器通以 50Hz 的交流电

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