电路原理课件讲义英文版 Chapter_7

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电路原理双语课件

电路原理双语课件

The transfer function can be written as
The transfer function H(ω) of a circuit is the frequency-dependent ratio of a phasor output Y(ω) (an element voltage or current) to a phasor input X(ω) (source voltage or current). Thus,
Vo 1/ jωC 1 H (ω ) = = = Vs R + 1/ jωC 1 + jω RC
The magnitude and phase of H(ω) are
Amplitude response 幅频特性
ω H= , φ = − tan 2 ω0 1 + (ω / ω 0 )
1
−1
where ω0 = 1/RC. At ω = 0, H = 1 and φ = 0. At ω = ∞, H = 0, and φ = − 90°. Also, at ω = ω0, H = 1/ 2 and φ = − 45°.
14.1 INTRODUCTION
In our sinusoidal circuit analysis, we have learned how to find voltages and currents in a circuit with a constant frequency source. If we let the amplitude of the sinusoidal source remain constant and vary the frequency, we obtain the circuit’s frequency response. The frequency response of a circuit is the variation in its behavior with change in signal frequency. The sinusoidal steady-state frequency responses of circuits are of significance in many applications, especially in communications and control systems.

《电路第七章》课件

《电路第七章》课件

诺顿定理
总结词
诺顿定理是电路分析中的另一个重要定 理,它与戴维南定理类似,可以将一个 有源二端网络等效为一个电流源和一个 电阻并联的形式。
VS
详细描述
诺顿定理的应用与戴维南定理类似,它也 可以简化复杂电路的分析过程。通过将有 源二端网络等效为简单的等效电路,我们 可以更容易地计算出电路中的电流和电压 。与戴维南定理不同的是,诺顿定理将网 络等效为一个电流源和电阻的形式,适用 于分析和计算动态响应和瞬态电流的情况 。
电路的作用与分类
总结词
电路的作用是实现电能的传输和转换,根据不同的分类标准,电路可分为多种类 型。
详细描述
电路的主要作用是实现电能的传输和转换,即将电能转换为其他形式的能量,如 机械能、光能等。根据不同的分类标准,电路可分为交流电路和直流电路、开路 和闭路、串联和并联等类型。
电路的基本物理量
总结词
叠加定理
总结词
叠加定理是线性电路的一个重要性质,它表明在多个独立电 源共同作用下,电路中某支路的电流或电压等于各个独立电 源单独作用于该支路产生的电流或电压的代数和。
详细描述
叠加定理是线性电路分析中常用的一个定理,它简化了多个 电源作用下的电路分析过程。通过应用叠加定理,我们可以 分别计算各个独立电源对电路的影响,然后将结果相加得到 最终结果。
电感元件
电流滞后电压90度相位, 相量模型为复数,虚部为 感抗。
电容元件
电压滞后电流90度相位, 相量模型为复数,虚部为 容抗。
复杂交流电路的分析与计算
串联电路
复杂电路的分析方法
各元件电流相同,总电压等于各元件 电压之和。
利用基尔霍夫定律和相量法进行电路 的分析与计算。
并联电路

电路基础理论英文版课件第一章

电路基础理论英文版课件第一章
Measurement
Resistance is measured in ohms (Ω) using a ohmmeter.
Definition
Definition
Capacitance is the ability of a capacitor to store electrical energy. It is measured by the capacity of the capacitor to hold a charge.
详细描述
04
Analysis methods for circuits
单击此处添加正文,文字是您思想的提炼,为了最终呈现发布的良好效果,请尽量言简意赅的阐述观点;单击此处添加正文,文字是您思想的提炼,为了最终呈现发布的良好效果,请尽量言简意赅的阐述观点;单击此处添加正文,文字是您思想的提炼,为了最终呈现发布的良好效果,请尽量言简意赅的阐述观点;单击此处添加正文 10*16
A circuit that allows the flow of AC current, typically used in household and industrial applications.
பைடு நூலகம்
Definition of Circuit
Components
01
Circuit components include resistors, capacitors, inductors, diodes, transistors, and power sources. These components are connected to form a complete circuit.
contents
目 录

大学英文版电磁学讲义1-7

大学英文版电磁学讲义1-7

Example What is the resistance for a radial current between concentric conducting spheres with radii a and b. if there is a material with conductivity between the spheres? Divide the conducting volume into spherical shells(球壳) of radius r and thickness dr. The surface area of the shell is the cross-section 2 area(截面积) of the current. A= 4 r . The resistance of the shell at r is d R= dr 4 r2
I= dQ dt
(7.1)
Charge carrier(载流子): Charges q moving with mean velocity v, and linear density(线密度) nL , I = qn L v nL: number of charge carriers per unit length. (7.2)
∫A J 2 n− J 1 n dA
.
87
7.2 Current density and the continuity equation The surface charge enclosed by Σ is The boundary condition on J(x) is J 2 n− J 1 n=− ∂ ∂t (7.8)
7.5 Joule's Law 焦尔定律

电路原理第7章

电路原理第7章

1
总目录 章目录 返回 上一页 下一页
• 稳定(steady state)状态:
电路原理
在指定条件下电路中电压、电流已达到稳定值。
•暂态(transient state)过程: 电路从一种稳态变化到另一种稳态的过渡过程。
•电路暂态分析的内容 (1) 暂态过程中电压、电流随时间变化的规律。 (2) 影响暂态过程快慢的电路的时间常数。
(7-5)
电路原理
(7-6)
在换路瞬间,电感 磁链、电流不跃变
换路定律:式(7-3) ~(7-6)及其成立条件所表示 的规律称为换路定律。
换路瞬间,若 i 为有限值,
换路瞬间,若 u为有限值,
10
总目录 章目录 返回 上一页 下一页
• 初始值的确定
电路原理
1) 先由换路前瞬间t =0-的电路求出 uC ( 0– ) 、 iL ( 0– )。 2) 根据换路定律求出换路后瞬间uC( 0+)、iL ( 0+); 若uC(0+)=0, 可视电容元件短路, iL(0+)=0,可视电 感元件开路;若uC(0+)0, 电容可用一理想电压源 替代, 其电压为uc(0+); 若iL(0+)0 , 电感可用一理 想电流源替代,其电流为iL(0+)。
我们以图 (a)电路为例来说明 RL 电路零
输入响应的计算过程。
(a)
RL放电电路
(b)
电感电流原来等于电流 I0,电感中储存
一定的磁场能量,在 t=0 时开关由1端倒向2
端,换路后的电路如图(b)所示。
28
总目录 章目录 返回 上一页 下一页
换路后,由KVL得:
RiL uL 0

Teaching Materials of Analog Circuits - chp (7)

Teaching Materials of  Analog  Circuits - chp (7)
circuit would necessitate a large chip area. Also, the
resistor biasing uses coupling and bypass capacitors
§6.1 Current Sources Circuits and its Application
on-chip applications. In general, these op-amps are
designed to drive other CMOS circuits, which form high capacitive loads.
§6.0 Preview
一、Characteristics Of Analog IC
used for discrete circuits,it is not suitable for integrated
circuits. Resistors require relatively large areas on an
IC compared to transistors; therefore, a resistor-intensive
§6.0 Preview
The 741 is an example of an all-bipolar general-
purpose op-amp.Even though this op-amp is considered
classic, it still provides a good case study in which we perform a detailed analysis to dertimine both the dc and the small signal characteristics of the circuit. All-CMOS Op-amps can be designed for special

chapter 7信号与系统 奥本海默 华科 电信系 英文 课件

chapter 7信号与系统 奥本海默 华科 电信系 英文 课件



1/3 1/2
1 3/2
Re
z
1 2
Example 7.4 n 1 Consider the signal x[n] 3 sin 4 n u[n].

x[n]
The z-transform of this signal is n n 1 1 1 j / 4 1 1 j / 4 1 X ( z) 3 e z 2 j 3 e z 2 j n 0 n 0
7.1 THE Z-TRANSFORM
The z-transform of a general discrete-time signal x[n] is defined as
X ( z)
n
x[n]z n


where z is a complex variable.
z re j , Expressing the complex variable z in polar form as
Example 7.2 Determine the z-transform of
X ( z ) a nu[n 1]z n
n
x[n] a nu[n 1].

a z
n
1
n n
a z
n n 1

n
1 (a z )
1 1 j / 4 1 1 e u[n] e j / 4 u[n] 2j3 2j3
n
n
1 1 1 1 Im j / 4 1 2 j 1 1 e z 2 j 1 1 e j / 4 z 1 3 3

CHAPTER 7 .ppt(1)

CHAPTER 7 .ppt(1)

R
i=iL C
KVL: uL+uR+uC=uS VCR: i C duC dt duC u R Ri RC dt
(1) (2)
(3)
(4)
d 2uc d d Li di uL L LC 2 dt dt dt dt
(3)、(4)代入(1)
d uC duC LC RC uC u S 2 dt dt
2. Determining The Initial Value First-order circuit:y(0+);
0 0+
Second-order circuit:y(0+),y’(0+); 0-
N-order circuit:y(0+),y’(0+) … y(n-1)(0+)。
t=0 denotes the time just before switching event, and t=0+ is the time just after switching event, assuming that the switching event takes place at t=0.
i(0+)=3-1=2A
2Ω 3A 3Ω 4Ω + 1A uC(0+) - i(0+)
∴uC(0+)=3A
i(0+)=2A
(c)
例:开关 K 打开前电路处稳态,给定 R1=1Ω ,R2=2Ω ,R3=3Ω , L=4H,C=5F,US=6V,t=0 开关 K 打开,求 iC ,iL,i,uC ,uL, duC diC diL d 2iL , , , 在 0+时的值。 dt dt dt dt 2
1 2 i U0 C

《电路原理》双语教学大纲(英文版)

《电路原理》双语教学大纲(英文版)

Teaching ProgramCourse Code: 101C0040Course Name: Electric Circuits (Ⅰ)Weekly Hours: 4.0-0 Credits: 4.0Teaching Goal and Basic Requirements:This course introduces the principles of circuits and their role in electrical engineering, then introduces and demonstrates the power of the fundamental circuit laws and analysis methods. This is followed by an introduction to the principle of operational amplifier properties and operational amplifier circuits. The properties and applications of reactive circuit elements are introduced along with first and second order circuits. The basics of AC circuit analysis follow, the course will show how the sinusoidal steady state problem can be solved using phasor analysis. Students are prepared to analyze circuit properties with these tools and methods for each circuit type using both manual methods and PSpice tools.Content of Courses & Hours Allocation:Autumn QuarterWeek 1: Introduction; Chapter 1-- Basic concepts;Week 2: Chapter 2-- Basic laws; Chapter 3--Nodal analysis;Week 3: Chapter 3--Mesh analysis; Chapter 4--Linearity property, superposition, source transformation;Week 4: National Holiday;Week 5: Chapter 4--Thevenin’s theorem, Norton’s theorem, Maximum power transfer;Week 6: Chapter 5--Operational amplifiers; Quiz 1;Week 7: Chapter 6--Capacitors and inductors; Chapter 7--First-order circuits: Source-free circuit;Week 8: Chapter 7--Step response; Chapter 8--Second-order circuits;Week 9: Chapter 9--Sinusoids and phasors;Winter QuarterWeek 1: Chapter 10--Sinusoidal steady-state analysis; Quiz 2;Week 2: Circuit analysis with Pspice; Lab exercise--Circuit analysis with Pspice;Week 3: Chapter 11--AC power analysis: Effective or RMS value, Power factor;Week 4: Chapter 12--Three-phase circuits; Power in a system;Week 5: Chapter 13--Magnetically coupled circuits: Mutual inductance; Linear transformers, Ideal autotransformers;Week 6: Chapter 14--Frequency response: Transfer function, Resonance; Quiz 3;Week 7: New Year Holiday; Chapter 14--Passive filters; Circuit applications;Week 8: Chapter 16--The Fourier series: Average and RMS value; Review;Week 9: Review;Teaching Plan:The course grade is calculated based on:Homework 10%, Quiz 30% (two top scores from 3 quiz, 15% each), PSpice Assignment 5%, Final Exam: 55%Homework will be given full credit if the work is completed and the solutions understandable.Recommended Textbooks and Other References: (books, editors, publishing company,publishing time)1.Fundamentals of Electric Circuits,Charles K. Alexander, Matthew N.O. Sadiku,McGraw-Hill Companies Inc,2000.122.PSpice and MATLAB for Electric Circuit Analysis,Tong Mei,Machine Industry Press,2005.73.Principles of Electric Circuits,Fan Chengzhi,Sun Dun,Tong Mei,Machine Industry Press,2005.74.Electric Circuits (Four Edition),Qiu Guanyuan,High Education Press,1999.65.Electric Circuits (Six Edition),James W. Nilsson, Susan A. Riedel, Publishing House of Electronics Industry,2002.6Teaching ProgramCourse Code: 101C0050Course Name: Electric Circuits (II)Weekly Hours: 4.0-0 Credits: 2.0Teaching Goal and Basic Requirements:Transient response analysis, network functions, poles and zeros; solution of network equations using Laplace transforms, inverse transforms, convolution integral, two-port networks. Matrix formulation of circuit equations, nodal Analysis and mesh analysis. Introduction of distributed circuits, distributed circuits of finite length, traveling wave, lossless transmission line of finite length. Analysis of nonlinear circuits, linearized circuit models, small signal analysis. Circuit analysis with MATLAB.Content of Courses & Hours Allocation:Spring QuarterWeek 1: Chapter 15--Definition of Laplace transform; Properties of the Laplace transform; The inverse Laplace transform; Application to circuits; Transfer function;Week 2: The convolution integral; Network function and step response;Week 3: State variables and state equations; Circuit analysis with MATLAB;Week 4: Chapter 18--Two-port networks; Supplement 1: Matrix equations for network--Nodal Analysis;Week 5: Supplement 1: Matrix equations for network--Mesh Analysis;Week 6: Supplement 2: Distributed Circuits--Introduction, distributed circuits of finite length;Week 7: Supplement 2: Traveling wave; Lossless transmission line of finite length; Circuit analysis with MATLAB; Midterm exam;Week 8: Supplement 3: Simple nonlinear circuits--Introduction, Nonlinear resistor circuits, Small signal analysis; Review;Week 9: Review;Teaching Plan:The course grade is calculated based on:Homework 10%, Quiz 5%, Midterm 15%, MATLAB Assignment 10%, Final Exam 60%Homework will be given full credit if the work is completed and the solutions understandable.Recommended Textbooks and Other References: (books, editors, publishing company,publishing time)1.Fundamentals of Electric Circuits,Charles K. Alexander, Matthew N.O. Sadiku,McGraw-Hill Companies Inc,2000.122.Principles of Electric Circuits,Fan Chengzhi, Sun Dun, Tong Mei,Machine Industry Press,2004.73.PSpice and MATLAB for Electric Circuit Analysis,Tong Mei,Machine Industry Press,2005.74.Electric Circuits (Four Edition),Qiu Guanyuan,High Education Press,1999.65.Electric Circuits (Six Edition),James W. Nilsson, Susan A. Riedel, Publishing House of Electronics Industry,2002.6。

系统辨识(英文版),教材Chapter 7

系统辨识(英文版),教材Chapter 7

Non-stationary continuous components
y (t ) − y (t − 1) u (t ) − u (t − 1)
The I/O signals are replaced by their corresponding variations (eventually filtered).
I.D. Landau, G. Zito - "Digital Control Systems" - Chapter 7
8
Over-sampling
Digital anti-aliasing filter For n > 3 a moving-average filter is sufficient
Plant operated in closed loop with excitation added to the controller output
PRBS y0 y1
reference
+
Controller Physical u(t) system
+ output
y(t)
• PRBS superposed to the controller output • Identification of the transfer function between y0 and y
I.D. Landau, G. Zito - "Digital Control Systems" - Chapter 7
Use of a controller with integral action but limited proportional and derivative actions

人教版高中英语选修计算机英语课件 CHAPTER 7 Storage 6. PC Cards 课件

人教版高中英语选修计算机英语课件 CHAPTER 7 Storage 6. PC Cards 课件

Flash is used to make less frequent disk power down and up. Advantages

Reliability, Power-Efficient, and Improved Performance
• Experiment
• • •
Run Office Applications Spun up every three and four minutes 10% power saving
CHAPTER 7 STORAGE
PC CARDS
DISK DRIVE VS. FLASH MEMORY
Read / Write
(+) Lost cost per bit (-) Mechanical movement (SPM & VCM) (-) High power consumption (10-15W) (-) Heavy weight compared to flash
Application
Code Storage
NOR -Intel/Sharp -AMD/Fujitsu/Toshiba
Program Storage -Cellular Phone -DVD, Set TOP Box for BIOS
File Storage
NAND -Samsung/Thoshiba
2
HISTORY OF FLASH MEMORY
3
NAND FLASH MEMORY – PROGRAM/ERASE

F-N tunneling

Give a higher voltage and electrons are trapped through gate into floating gate transistor.

电路与电子技术课件(英文版)-第七章

电路与电子技术课件(英文版)-第七章
4
Thévenin Equivalent Resistance
5
Thévenin Equivalent Resistance -Example
Example 3.17 Thévenin Equivalent Resistance Find the Thévenin equivalent resistance seen by the load RL in the circuit of Figure 3.39.
▪ The Thévenin equivalent voltage is defined as follows:
22
Computing the Thévenin Voltage
▪ Figure 3.43 illustrates that the open circuit voltage vOC and the Thévenin voltage vT must be the same if the Thévenin theorem is to hold.
21
Computing the Thévenin Voltage
▪ Computation of the Thévenin equivalent voltage VT for an arbitrary linear resistive circuit containing independent voltage and current sources and linear resistors.
A short circuit === a voltage source An open circuit === a current source ▪ To set a current source equal to zero, replace it

ch7.1-7.4

ch7.1-7.4

τB =
RE ( RS + rπ )C E RS + rπ + (1 + β ) RE
3. Bypass Capacitor Effect
(C) Bode Plot
AV AV
ω→∞
Av
ω→ ∞
g m rπ RC = RS + rπ
AV
ω→0
fA fB f
Av
ω→ 0
g m rπ RC = RS + rπ + (1 + β ) RE
Vo ( s ) RP AVH ( s ) = = Vi ( s ) RS + RP 1 1 + s RS R P R +R P S
RS
+ +
Vi
RP
CP
Vo
substitute s = jω = j2π f
AVH Vo RP = = Vi RS + R P
assume
C P Low-pass RC network 1 fH =-point freq. 20dB/decade or –3dB freq.
f >> f H
RP = AVM RS + RP
AVH ≈ AVM ( f H / f )Bode plots of low-pass RC network
20 lg AVH ≈ 20 lg AVM + 20 lg( f H / f )
7.0 Preview
Amplifier Frequency Response
Amplifier gain is a function of signal frequency. The fL and fH is 3dB less than the maximum midband gain. Low-frequency range f < fL , high-frequency range f > fH , and midband range between fL <f < fH . Bandwidth BW= fH fL.

英文版大学物理 第七章

英文版大学物理 第七章

7-4 The Microscopic Interpretation of Temperature We can rewrite
1 2
2 1 p = n( mv 2 ), here n = N/V. as 3 2
mv 2 = K the average translational kinetic energy per molecule associated with random molecular motion.
1 2 3 K = mv = kT 2 2
provides a new definition of temperature in terms of the microscopic properties of a gas. Specifically, temperature is a measure of the average random translational kinetic energy of the molecules of a gas, T = 2 K / 3k . We can calculate how fast molecules are moving on average: 3kT 2 v = Checkpoint 2 m Root-mean-square speed
Ideal Gas Law
m pV = RT M
Here, p, V, and T stand for pressure, volume, and temperature, respectively; m is the mass of gas present; M is the molar mass (the mass of 1 mole); m/M is the number of moles of gas present. R = 8.31 J/mol⋅K. (the universal gas constant) ⋅ An alternative form of ideal gas law: m N Let n = N/V be the pV = RT = RT M NA number density of the The Boltzmann’s constant gas molecules, we get

汽车专业英语电子课件Unit 7

汽车专业英语电子课件Unit 7

Text A Battery




Charging and Discharging Principle (Fig.7.3) A battery charges and discharges electrical energy through the chemical reaction of the electrolyte. (a) Electrical energy is generated when the sulfuric acid of the electrolyte reacts with lead and turns into water. At this time, the sulfuric acid combines with the pole plates, causing the positive and negative pole plates to turn into lead sulfate. (b) Because sulfuric acid is discharged from the pole plates, the electrolyte turns into sulfuric acid, and the specific gravity of the electrolyte increases. The positive pole plates turn into lead dioxide and the negative pole plates turn into sponge lead.
Text C Charging System
Text A Battery

The starter battery supplies and stores the energy for the electrical systems in a motor vehicle. As it can be recharged, it is also referred to as an accumulator. The composition of a common battery is shown as Fig.7.2. When the engine is running, it stores the used electricity.

dianlu7

dianlu7

0+等效电路 1 4
+
+
10V -
2A uL
-
uL(0+)= -2×4=-8V
小结 求初始值的步骤:
1.由换路前电路(稳定状态)求uC(0-)和iL(0-)。 2.由换路定律得 uC(0+) 和 iL(0+)。 3.画0+等效电路。
(1)换路后的电路;
(2)电容(电感)用电压源(电流源)替代。
S
i1
5F + 2
i2
-uC
3 6 i3
等效电路 5F + i1
t >0
-uC 4
解 这是一个求一阶RC 零输入响应问题,有
t
uC U 0e RC
U0 24V RC 5 4 20s
S
i1
5F + 2
i2
-uC
3 6 i3
5F + i1 -uC 4
t
uC 24e 20 V t 0
第七章 一阶电路和二阶电路 的时域分析
7-1 动态电路的方程及其初始条件
7-7 一阶电路和二阶电路的阶跃响应
7-2 一阶电路的零输入响应
7-8 一阶电路和二阶电路的冲激响应
7-3 一阶电路的零状态响应
*7-9 卷积积分
7-4 一阶电路的全响应
*7-10 状态方程
7-5 二阶电路的零输入响应
*7-11 动态电路时域分析中的几个问题
动态
任意激励(本章主要研 究直流激励)
换路发生后的整个过程 微分方程的通解
3.电路的初始条件
初始条件为 t = 0+时,u 、i 及其(n-1)阶导数的 值(此时方程为n阶),用来确定解答中的积分常数

数字电路英文版 第七单元 医学课件教学提纲

数字电路英文版 第七单元 医学课件教学提纲

? OLMC Output logic marcocell. The programmable output logic in a GAL.
? PAL Programmable array logic. A PLD with a programmable AND array and a fixed OR array.
? Buffer A circuit that prevents loading of an input or output.
? Cell A fused cross point of a row and columnn in a PLD.
? Complier Software that translates from high-level language that uses words or symbols, such as HDL , into low-level machine language (1s and 0s).
? Documentation file The information from a computer that documents the final design after the input file has been processed.
? E2CMOS Electrically earsable CMOS ( EECMOS). The circuit technology used for the reprogrammable cells in GAL.
11
§7.1 PLD ARRAYS AND CLASSIFICATIONS
Programmable logic devices (PLDs) are used in many applications to replace SSI and MSI circuits; they save space and reduce the actual number and cost of devices in a given design.

Chap.7 Repeated Games 博弈论英文版教学课件

Chap.7 Repeated Games 博弈论英文版教学课件

P1 0+3,0+3 0+1/2,0+4 0+3,0+3 4+3,1/2+3 0+3,0+3 Q1 0+3,0+3 0+1/2,0+4 0+3,0+3 0+3,0+3 1/2+3,4+3
7.2 Infinitely repeated game
Definitionof strategy: In the finitelyrepeated game G(T) or the infinitely
2
L
R
U 1,1 5,0
1
D 0,5 4,4
2
L
R
U 1,1 5,0
1
D 0,5 4,4
2
L
R
U 1+1,1+1 5+1,0+1 1
D 0+1,5+1 4+1,4+1
• The unique subgame-perfect outcome of the two-stage Prisoners’ Dilemma is not the cooperation outcome!
2
L2
M2
R2
L1 1+1,1+1 5+1,0+1 0+1,0+1
1 M1 0+1,5+1 4+3,4+3 0+1,0+1
R1 0+1,0+1 0+1,0+1 3+1,3+1
Therearethreepure-strategyNashequilibria in the game:
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Conclusion qc (0+) = qc (0-) vC (0+) = vC (0-)
L (0+)= L (0 )

iL(0+)= iL(0-)
4. Determination of initial condition 例1
求 iC(0+) i 10k 40k 10V k iC (1) 由0-电路求 uC(0-)或iL(0-)
iC(0+)
例2
1 K
t = 0时闭合开关k , 求 uL(0+) 4 1

4
先求
i L (0 )
电 感 短 路
L
iL
+
uL
10V
0+电路
-
10V
1
4
10 i L (0 ) 2A 1 4

+
10V 2A
uL
uL (0 ) 0 uL (0 ) 0
由换路定律:
w p t
2. Derivation of differential Equations
RC circuit By KVL, there is vs(t) (t >0) R +
i
vC

C
dvc Ri vc vS (t ) i C dt dvc RC vc vS (t ) dt
Taking voltage as circuit variable:
(t >0) R + vs
i
vL

L
R vL dt vL vS (t ) L dvL dvS (t ) R vL L dt dt
Firstorder circuit
Ri vL vc vS (t )
dvc iC dt
2
(t >0) + vS(t) - - R +
i
di vL L dt
vC
C
vL
+ –
L
d vc dvc LC 2 RC vc vS (t ) dt dt
Taking current as circuit variable:
di 1 Ri L idt vS (t ) dt C
High-order circuit
dnx d n 1 x dx an n an1 n1 a1 a0 x e( t ) t 0 dt dt dt
3. Initial condition
(1) Concepts of t = 0+ and t = 0- A circuit is switched at t=0 0- : the moment just before switching 0+ : the moment just after switching
dvS (t ) di d i 1 R L 2 i dt dt C dt
2
Second -order circuit
First-order circuit
dx a1 a0 x e ( t ) t 0 dt
Second-order circuit
d2x dx a2 2 a1 a0 x e( t ) t 0 dt dt
1. The circuit comprises energy storage elements of capacitors or inductors.
2. Energy stored will change when the circuit changes, and it needs time to store or release energy
f (0 ) lim f ( t )
t 0 t 0

f (0 ) f (0 )
f(t)
f (0 ) lim f ( t )
t 0 t 0
f (0 ) f (0 )
t
0-0 0+
Initial condition: values of v, i and their derivative at t = 0+
Taking current as circuit variable:
Firstorder circuit
1 Ri idt vS (t ) C
di i dvS (t ) R dt C dt
RL circuit
di vL L Ri vL vS (t ) dt di Ri L vS (t ) dt
7.1 Introduction
RC circuits: a circuit comprising a resistor and capacitor RL circuits: a circuit comprising a resistor and an inductor
A first-order circuit: is characterized by a first-order

i() is finite, so
In addition,

0

0
i ( )d 0 vC (0+) = vC (0-)
q (0+) = q (0-)
(3) Initial condition of RL circuit
iL
+
v
L
1 iL (t ) L
1 L
0
t
v( )d
t 0

-
1 v( )d L

v( ))d
When t = 0+
1 t iL (0 ) v( )d L 0 1 0 iL (0 ) iL (0 ) v( )d L 0
0

v() is finite, so
v( )d 0 0 iL(0+)= iL(0-) LiL L (0+)= L (0-)
i
t
Former steady stateLeabharlann Transient Process
New steady state Transient term
Circuit switching
The construction or state of a circuit is changed
Why does transient process exit?
1. Analysis of transient process
RL circuit (t = 0) Vs
K
i
R +
The circuit is in steady state (稳定 状态)before switch K is closed.
i = 0 , vL = 0
L
vL

The circuit will reach new steady state after K has been closed for a long.

uL(0+)= - RIS
例3
求K闭合瞬间各支路电流和电感电压 由0-电路得: 2 解
+
48V
+
K
L
iL
uL 2
3 C
+
2 iL
3
-
-
48V
-
2 + uC -
由0+电路得:
i L (0 ) i L (0 ) 48 / 4 12 A
uC (0 ) uC (0 ) 2 12 24V
Recall
dvC Capacitor: iC C dt 1 t vC iC dt C diL vL L dt 1 t iL vL dt L 1 t vC iC dt vC (t0 ) C t0
Inductor:
1 t iL vL dt iL (t0 ) L t0
differential equation (一阶微分方程).
A second-order circuits: is characterized by a secondorder differential equation (二阶微分方程). It consists of resistors and the equivalent of two energy storage elements.
---Lord Kelvin
Chapter 7 First-order Circuits
7.1 Introduction 7.2 The Source-free RC Circuit 7.3 The Source-free RL Circuit 7.4 Singularity Functions 7.5 Step Response of an RC Circuit 7.6 Step Response of an RL Circuit
(t →) R + Vs
i
vL= 0, i=Vs /R
L
i
VS
vL

VS/R
?
VL
0 Transient process t1 New steady statet Former steady state (过渡过程) Transient term
RC circuit
(t = 0) Vs
K
i
R
The circuit is in steady state before switch K is closed.
(2) Initial condition of RC circuit
i
+ vc -
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