上海12校联考

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上海各种上联考参加的学校名单

【十校】：复旦附中、交大附中、华师大二附中、上海中学、上师大附中、上外附中、复兴高级中学、向明中学、南洋模范、延安中学 ps:控江？建平哪去了？（99%的肯定是这些学校 0.0）
【十一校】：三林中学、上南中学、南汇一中、大团中学、周浦中学、曙光中学、中光中学、嘉定二中、张堰中学、莘庄中学
【六校】：光明中学、东昌中学、卢湾高级中学、六十中学、北虹中学、同济二附中
【七校】：曹杨二中、市西中学、市三女子、控江中学、华师大一附中、格致中学、市北中学
【八校】：虹口中学、长青中学、继光中学、澄衷中学、五十二中、（运光中学、曲阳二中Байду номын сангаас市五中学）
又一说：虹口中学、长青中学、继光中学、澄衷中学、五十二中、（北郊中学、北虹中学、鲁迅中学）这个有待考察...
【十三校】：进才中学、上海市第二中学、位育中学、金山中学、行知中学、南洋中学、奉贤中学、行知中学，七宝中学、市二中学、、进才、青浦中学、南汇中学、、崇明中学、嘉定一中

【恒心】2015届上海市十二校高三12月联考英语试题及参考答案【word版】

2014学年第一学期十二校联考高三英语考试试卷学校：周浦中学学校:曹杨中学第I卷（共103分）I. Listening ComprehensionSection ADirections: In Section A, you will hear ten short conversations between two speakers. At the end of each conversation, a question will be asked about what was said. The conversations and the questions will be spoken only once. After you hear a conversation and the question about it, read the four possible answers on your paper, and decide which one is the best answer to the question you have heard.1. A. $100. B. $40. C. $20. D. $60.2. A. Go to see a movie. B. Leave for Chicago.C. Meet her aunt at the station.D. Prepare a party.3. A. She doesn’t have any time. B. It doesn’t bother her to wait.C. She’s never had to wait before.D. She hasn’t seen anyone at all.4. A. History. B. Mathematics. C. Literature. D. Politics.5. A. She is only too pleased to come. B. She was an excellent mountain-climber.C. She didn’t go in for mountaineering.D. She was too busy to come.6. A. Read an article on political science. B. Read more than one article.C. Present a different theory to the class.D. Choose a better article to read.7. A. Place another order. B. Call on to check on it.C. Wait patiently.D. Go and find the furniture.8. A. She regards it as an exercise. B. She wants to save money.C. She loves doing anything that is new.D. Her office isn’t very far.9. A. At home. B. At the riverside.C. At the health center.D. At his office.10. A. He needs to find a new job. B. He can’t find his keys.C. His car needs to be repaired.D. He doesn’t know where his keys are.Section BDirections: In Section B, you will hear two short passages, and you will be asked three questions on each of the passages. The passages will be read twice, but the questions will be spoken only once. When you hear a question, read the four possible answers on your paper and decide which one would be the best answer to the question you have heard.Questions 11 through 13 are based on the following passage.11. A. The doctor was not very experienced.B. The doctor hadn’t seen the medical reports.C. The patient didn’t work well with the doctor.D. The patient was misunderstood by the doctor.12. A. The doctor treated her with the help of her previous doctors.B. The doctor always listened to her and believed her.C. The doctor treated her as a hopeless patient.D. The doctor treated her with strong medicines.13. A. To change her job.B. To keep a closer relationship with her family.C. To send him a note every day.D. To get married.Questions 14 through 16 are based on the following passage.14. A. A piece of equipment.B. The workbook of the laboratory course.C. The framework of the laboratory course.D. One experiment of the laboratory course.15. A. The students must follow the instructions carefully.B. A great deal of equipment is available to all the students.C. Students can make their own choices about the activities.D. Homework must be handed in according to instructions.16. A. The activities are to be done in class.B. The activities take less time than the experiment.C. The students are not required to do the activities.D. Few detailed instructions are given for the activities.Section CDirections:In Section C, you will hear two longer conversations. The conversations will be read twice. After you hear each conversation, you are required to fill in the numbered blanks with the information you hear.Blanks 17 through 20 are based on the following conversation:II. Grammar and VocabularySection ADirections: After reading the passages below, fill in the blanks to make the passages coherent and grammatically correct. For the blanks with a given word, fill in each blank with the proper form of the given word; for the other blanks, use one word that best fits each blank.(A)Learning in ChinaWe can always hear voices comparing the educational systems in China and the US. It’s true that there exist a lot of differences, but this cannot be an excuse (25) ______ having a passive attitude toward studying in China.When I came back from the US last year and continued my senior middle school education in China, I sensed many great differences. I thought that school in China was too hard, and that we didn’t do enough fun exercise except running around playgrounds together. I was not patient enough and I couldn’t help but (26)______(cry) to my mom. In short, I (27) ______ not face the changes and the pressure.After a long talk with my mother, I realized that though high school life in China is (28) ______ (hard), it can give us more. The pressure helps us learn the true meaning of competition before we step into society, which gives us a (29) ______ (determine) heart and teaches us to step forward (30) ______ ______ ______ the reality is. It’s like climbing a mountain, which might make you dizzy and nervous, but the top is always there waiting for you as long as you are strong enough (31) ______ (take) one more step.Meanwhile, an easy life is not always good for us. Even some of my American friends call (32)______ “lazy Americans”, because the school in the US is not always easy. When they go to college, they also need to work very hard. We complain mainly because we can’t see the whole picture.Sometimes we just simply listen to others’ words without thinking about (33) ______they’re true. We can’t always complain. Instead, we all need to understand that success takes efforts and tears.(B)Science – A way of ThinkingMany scientists, from their earlier work, have enough knowledge to make good guess as to the solution to a problem which (34) ______(work) on. In making new discoveries, they may use the trial-and-error method, they may draw on past experiences, or they may try to find out (35) ______others have discovered. They may design new investigations and new ways of testing their results. Scientists have to train themselves to use their brains efficiently.For example, when Thomas A. Edison was trying to make an electric lamp, he needed the only substance inside the bulb (36) ______would glow brightly without burning up quickly. He tried more than one thousand times (37) ______he found the exact substance he could use. After he had experimented for a long time, someone asked Mr. Edison whether he was discouraged at the waste of time. He replied, “I have not been wasting time. I (38)______ (find) one thousand materials that won’t work. Now I can look for others.” Edison’s statement is very important. Above all, scientists demand to know when and where they are wrong. A good question to ask in science is not “Am I right?” but “Am I wrong?”.Scientists spend many years of study (39) ______ (train) themselves to use their brains and the tools of investigation. They also use each other’s work. Isaac Newton, (40) who is ______ uniqueBritish scientist, said he saw further than others because he stood on the shoulders of giants.Section BDirections: Complete the following passage by using the words in the box. Each word can only beGrammar is universal and plays a vital part in every language. So the question which has puzzled many linguists is: who created grammar?In order to answer the question of how complex languages are ＿41＿formed, the researcher needs to observe how languages are started from scratch. To find out how grammar is created, someone needs to be present at the time of a language’s creation, documenting its ＿42＿. At first, it seems that this question is impossible to answer. Amazingly, this is possible.Some of the most recent languages ＿43＿due to the Atlantic slave trade, when slaves from a number of different ethnicities were forced to work together under the colonizer’s ＿44＿. Since they had no opportunity to learn each other’s lang uages, they developed a make-shift language called a pidgin (混杂语). Pidgins are strings of words ＿45＿from the language of the landowner. Interestingly, however, all it takes for a pidgin to become a complex language is for a group of children to be exposed to it at the time when they learn their mother tongue. Slave children did not ＿46＿copy the strings of words uttered by their elders, they ＿47＿their words to create a new language.Further evidence of this can be seen in studying sign languages for the deaf. Previously, all deaf people were isolated from each other, but in 1979 a government introduced schools for the deaf. Although children were taught speech and lip reading in the classroom, in the playgrounds they began to invent their own sign system, which was basically a pidgin. Each child used the signs differently, and there was no ＿48＿grammar. However, when this inventive sign system was already around, a quite different sign language was developed.Therefore it would appear that even the most widespread languages were partly created by children. Children appear to have innate (天生的) grammatical machinery in their brains, which springs to life when they are first trying to make ＿49＿of the world around them. Their minds can serve to create ＿50＿, complex structures, even when there is no existing grammar for them to copy.III. Reading ComprehensionSection ADirections: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context.Ancient Greek philosopher Aristotle viewed laughter as “a bodily exercise precious to health.” But ＿51＿some claims to the contrary, laughing quietly probably has little influence on physical fitness. Laughter does ＿52＿short-term changes in the activity of the heart and its blood vessels, boosting heart rate and oxygen consumption. But because hard laughter is difficult to ＿53＿, agood laugh is unlikely to have ＿54＿benefits the way, say, walking or jogging does.＿55＿, instead of stretching muscles tightly to build them, as exercise does, laughter apparently accomplishes the ＿56＿. Studies dating back to the 1930s indicate that laughter57＿muscles, decreasing muscle tone for up to 45 minutes after the noisy laugh dies down.Such bodily reaction might imaginably help moderate the effects of psychological stress. After all, the act of laughing probably does give rise to other types of ＿58＿feedback that improve an individual’s emotional state. ＿59＿one classical theory of emotion, our feelings are partially rooted in physical reactions. It was argued at the end of the 19th century that humans do not cry because they are sad but they become sad when the tears begin to flow.Although sadness also comes before tears, evidence suggests that emotions can flow from muscular ＿60＿. In an experiment published in 1988, social psychologist Fritz Strack of the University of würzburg in Germany and his colleagues asked volunteers to ＿61＿a pen either with their teeth – thereby creating an artificial smile – or with their lips, which would cause a(n) ＿62＿expression. Those forced to exercise their smiling muscles ＿63＿more cheerfully to funny cartoons than did those whose mouths were contracted in a frown, ＿64＿that expressions may influence emotions rather than just the other way around. ＿65＿, the physical act of laughter could improve mood.51. A. among B. except C. despite D. like52. A. reflect B. demand C. indicate D. produce53. A. release B. maintain C. evaluate D. observe54. A. measurable B. manageable C. affordable D. renewable55. A. In turn B. In fact C. In addition D. In brief56. A. opposite B. reverse C. function D. average57. A. hardens B. weakens C. tightens D. relaxes58. A. physical B. mental C. subconscious D. internal59. A. Owing to B. According to C. Due to D. As for60. A. stimulus B. responses C. reflection D. operation61. A. fetch B. bite C. pick D. hold62. A. disappointed B. excited C. joyful D. funny63. A. alerted B. contributed C. turned D. reacted64. A. suggesting B. requiring C. mentioning D. supposing65. A. Eventually B. Consequently C. Similarly D. CoincidentallySection BDirections: Read the following three passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage you have just read.(A).Working with a group of baboons (狒狒) in the Namibian desert, Dr. Alecia Carter of the Department of Zoology, Cambridge University set baboons learning tasks involving a novel food and a familiar food hidden in a box. Some baboons were given the chance to watch another baboon who already knew how to solve the task, while others had to learn for themselves. To work out howbrave or anxious the baboons were, Dr. Carter presented them either with a novel food or a threat in the form of a model of a poisonous snake.She found that personality had a major impact on learning. The braver baboons learnt, but the shy ones did not learn the task although they watched the baboon perform the task of finding the novel food just as long as the brave ones did. In effect, despite being made aware of what to do, they were still too shy to do what the experienced baboon did.The findings may impact how we understand the formation of culture in societies through social learning. If some individuals are unable to get information fr om others because they don’t associate with the knowledgeable individuals, or they are too shy to use the information once they have it, information may not travel between all group members, preventing the formation of a culture based on social learning.66. What is the first paragraph mainly about?A. The design of Dr. Carter’s research.B. The results of Dr. Carter’s research.C. The purpose of Dr. Carter’s research.D. The significance of Dr. Carter’s research.67. According to the research, which baboons are more likely to complete a new learning task?A. Those that have more experience.B. Those that can avoid potential risks.C. Those that like to work independently.D. Those that feel anxious about learning.68. Which best illustrates the “mismatch” mentioned in Paragraph 4?A. Some baboons are intelligent but slow in learning.B. Some baboons are shy but active in social activities.C. Some baboons observe others but don’t follow them.D. Some baboons perform new tasks but don’t concentrate.69. D r. Carter’s findings indicate that our culture might be formed through ______.A. storing informationB. learning from each otherC. understanding different peopleD. travelling between social groups(B).CityCabA Member of COMFORT DELGROComfortable airport & city transfers:MaxiCab (seats 6 passengers)Booking Hotline: +65 6542 8297… or book at the Airport Shuttle counter at Terminal 1 or Terminal 2MaxiCab Service RatesTransfer to Airport/other destination $35 Hourly Service (per hour – minimum 2 hours) $35Applicable additional charges:-- Between midnight to 6 am, an additional $12 per transfer or per hour-- For en-route stop to final destination, an additional $5 per stopapply otherwise $20-- Administrative charges of 10% of total fare for all Credit CardpaymentsPersonalized tours:SingaporeCabby Tour✓ Conducted by licensed taxi tourist guides approved by the Singapore Tourism Board ✓ Exclusive private tours in 6-seater MaxiCabs, 4-seater Mercedes LimoCabs and normal cabs ✓ Flexible pick-up times and locations✓ Extension of additional attractions and restaurants upon request.sg70. What taxi services can a tourist to Singapore have according to the passage?a. specially-tailored tours around Singaporeb. transfers between the terminals at the airportc. personalized tours beyond Singapored. transfers between the airport and the citye. hourly private Singapore taxi servicef. airport & city goods deliveryA. a, d, eB. a, b, fC. b, c, eD. c, d, f71. If a tourist goes to the airport in a MaxiCab at 5 a.m. and pays by credit card, he / she has to pay _________.A. $47B. $38.5C. $55D. $51.772. If a tourist group intends to book one of the suggested tours in a 6-seater MaxiCab, it ________.A. has to register at .sgB. can choose the time and place to collect the groupC. may apply to the Singapore Tourism BoardD. must first pay at least $105 as deposit73. Which of the following is NOT true according to the passage?A. A MaxiCab driver can stop on the way on request with extra charges.B. The cabby tour can show you around Singapore in the night time.C. A MaxiCab taxi tourist guide isn’t allowed to add scenic spots en route.D. Specially-trained taxi drivers operate various tours around Singapore.(C)Because I am extremely vulnerable to both slick advertising and peer pressure, I’ve been thinking about getting an iPad. But here’s the problem: I’m cheap, and the iPad’s not. If I’m going to fork over at least $499 for a new device, I want to try it out and make sure it’s not just a larger, shinier version of my iPhone. But if I went to my local Apple Store, I’d get to spend only a few minutes testing out the machine. I wanted more time than that, so I rented one for $15 a day from a guy on SnapGoods.The Internet start-up in Brooklyn runs on simple reasoning: there are people who want to borrow stuff – camping equipment, food processors, robot vacuums, etc. – and there are people who have stuff they want to lend. SnapGoods helps these two groups connect over the Web. SnapGoods is one of many sites that have sprung up to facilitate offline sharing. Some sites have a narrow, obvious focus (like ) while others are more obscure (Neighborhood Fruit helps people share what’s growing in their yards or find fruit trees on public land). But regardless of whether the sharing is free or involves a fee, these transactions often come with a stick-it-to-the-man attitude. “Borrow these things from your neighbors,” reads one earnest request on , “The owner-ship has SAILED!”All of these sites are encouraging something academics call collaborative consumption –in other words, peer-to-peer sharing or renting. Renting something you don’t need to use very often makes a lot more sense than buying it and letting it collect dust in your garage. There’s a green aspect as well, since sharing helps cut down on overall use of resources. But one of collaborative consumption’s most surprising benefits turns out to be social. In an era when families are scattered around the country and we may not know the people down the street from us, sharing things –even with strangers we’ve just met online – allows us to make meaningful connections.“This isn’t just about saving the environment or saving a dollar,” says SnapGoods CEO RonWilliams, who came up with the idea after renting a stranger’s motorcycle via Craigslist. “This is about saving yourself by making informed consumer decisions.”I’m not sure if I got a thrill when I borrowed Goodwin’s iPad, but it did feel good to make a connection. In the end, though, I decided not to purchase an i Pad. Sorry, Steve Jobs. I’m just not that into owning things anymore.74. Which of the following is NOT a reason for the author’s renting an iPad instead of buying one?A. The iPad is expensive and the author wants to make sure an iPad is worthy.B. He has already got an iPhone and expects to test the better quality of iPad.C.The local Apple Store only offters limited time to test out the machine.D. The iPad is so expensive that he cannot afford it.75. SnapGoods is a website which________.A. facilitates online sharingB. helps people borrow things from their neighborsC. connects borrowers and lenders for stuff sharingD. sells iPad online76. What is Ron Williams’ attitude towards collaborative consumption?A. FavorableB. CriticalC. IndifferentD. Not known77. Which of the following can best serve as the title of the passage?A. SnapGoods: a Good Place For ShoppingB. Borrow, Don’t Buy: Websites That Let Strangers ShareC. Why Do I RentD. Tips For Selling Things On the InternetSection CDirections: Read the passage carefully. Then answer the questions or complete the statements in the fewest possible words.Ambitious “go getters” (people energetic and eager to succeed) earn more money throughout their lives –but the “price” is that they have poorer health and die younger. They are also not much happier than less ambitious people.A new study tracked 717 high achievers who attended universities such as Oxford, Harvard and Yale, as well as high ability indi viduals who didn’t attend universities. The researchers assume that highly ambitious people may devote so much time to their jobs that they neglect areas of life proven to help people live long, happy life.The study focused on people born in the first half of the 20th century, and tracked them to the end of their lives. “Ambitious kids had higher educational attainment, attended highly esteemed universities, worked in more prestigious (有声望的) occupations, and earned more,” says Timothy Judge, professor of m anagement at the University of Notre Dame’s Mendoza College of Business.“So, it would seem that they are prepared to ‘have it all.’ However, we determined that ambition has a much weaker effect on life satisfaction and actually a slightly negative impact on longevity (how long people lived).“So, yes, ambitious people do achieve more successful careers, but that doesn’t seem to translate into leading happier or healthier lives.” Judge used a complex formula to judge ambition at every stage of life –and to divide high-ability individuals into “ambitious” and “less ambitious”groups. “If ambition has its positive effects, and in terms of career success it certainly seems that it does, our study also suggests that it carries with it some cost,” Prof Judge say s.“Despite their many accomplishments, ambitious people are only slightly happier than their less-ambitious counterparts, and they actually live somewhat shorter lives.”“Perhaps the investments they make in their careers come at the expense of the things we know affect longevity: healthy behaviors, stable relationships and deep social networks.”“If your biggest wish for your children is that they lead happy and healthy lives, you might not want to overemphasize professional success. There are limits to what our ambitions bring us – or our children.(Note: Answer the questions or complete the statements in NO MORE THAN TWELVE WORDS) 78. According to the passage, ambitious people have greater earning power in their life, but at thecost of their ___________.79. Who were followed and studied by the researchers in the new study?_______________________________________________.80. What are the factors that affect people’s longevity?_______________________________________________.81. Parents who expect their children to live a happy and healthy life should __________.第II卷（共47分）I. TranslationDirections: Translate the following sentences into English, using the words given in the brackets. 1．新出台的高考政策将在一定程度上影响我国教育的发展。

上海市十二校2014届高三2014月联考历史试卷(含答案)

上海市十二校2014届高三12月联考历史试卷(含答案)高考文综2014-12-16 1627给大家推荐一份好资料>上海市十二校2014届高三12月联考试卷(含答案)上海市十二校2014学年第一学期高三历史考试试卷命题人：陆兵峰学校：张堰中学 2014年12月审题人：顾月仙学校：朱家角中学审题人：檀新林学校：嘉定二中一、选择题（共75分；第1～30题每题2分，第31～35题每题3分；每题只有一个正确的选项。

）1、《唐律名例疏议释义》说：“中华者，中国也。

亲被王教，自属中国，衣冠威仪，习俗孝悌，居身礼仪，故谓之中华。

”“中华”的主要内涵是（）A．地域 B．文化 C．法律 D．种族2、某学者所著的历史论文中先后呈现如下材料：“芒芒禹迹，划为九州”（《左传》襄公四年）；“夏有乱政，而作禹刑”（《左传》昭公六年）；“鲧作城郭”（《世本·作篇》）。

据此推断，这位学者所引材料最有可能是为了说明（）A．阶级的产生 B．王的出现 C．早期国家诞生 D．世袭制的确立3、观察中国古代的农耕经济中耕作方式演变的示意图，推断空缺方框中填写正确的是（）A．农奴生产 B．集体劳动 C．自给自足 D．地主剥削4、当我们看到某最高一级地方行政长官向秦始皇汇报工作的场景时，我们能知这一地方行政长官是（）A．诸侯 B．县令 C．郡守 D．太尉5、2014年初山东淄博陈庄遗址出土一件青铜器，上有“丰般作文祖甲齐公尊彝”（“丰”国名，“般”：人名，“作”：制作，“文祖甲”：对先辈的尊称，）该青铜器及铭文可用于研究（）①西周分封制②当时的冶铸业③秦朝的郡县制④文字的特点A.①②B. ②③④C. ②③D. ①②④6、唐初以三省长官为宰相。

高宗时，打破宰相任用资历限制，允许三省中四品以下官员以“同中书门下平章事”名义行宰相权，参与朝政。

其目的是（）A．重用人才，推行科举取士 B．分割相权，加强君主专制C．分工协作，提高行政效率 D．缓和矛盾，抑制权力斗争7、唐代文成公主远嫁他乡，留下了一段民族友谊的佳话。

上海市十二校2014届高三数学12月联考试题文沪教版

2013学年第一学期十二校联考高三数学（文）考试试卷一、填空题（本大题满分56分，每题4分）1．已知全集U {}5,4,3,2,1=，A {}3,1=，B {}4,3,2=，那么=⋃)(B C A U __． 2．函数)12arcsin(-=x y 的定义域为．3．若数列{}n a 满足：111,2()n n a a a n N *+==∈，则前6项的和6S = .（用数字作答） 4. 计算：2(1)(13)lim(2)(1)n n n n n n →∞+-=-++________．5．集合{}12-<<=x x A ，{}0<-=a x x B ，若B A ⊆，则实数a 的取值范围是．6. 设()887872x a x a x -=++…10a x a +，则+++210a a a …+8a = .7. 已知函数)(x f 有反函数)(1x f -，且[),,0,24)(1+∞∈-=+x x f x x 则=-)0(1f ． 8. 某地自行车的牌照号码由六个数字组成，号码中每个数字可以是0到9这十个数字中的任一个。

那么某人的一辆自行车牌照号码中六个数字中5恰好出现两次的概率是 _______（精确到0001.0）. 9. 已知函数32t a n s i n )(x xx x f ++=，)1,1(-∈x ，则满足不等式0)12()1(<-+-a f a f 的实数a 的取值范围是 .10. 在等差数列{}n a 中，中若01<a ，n S 为前n 项之和，且177S S =，则n S 为最小时的n的值为 .11．已知x 是7,6,5,,3,2,1x 这7个数据的中位数，且y x -,,2,12这四个数据的平均数为1，则xy 1-的最小值为 . 12.设ω>0，若函数)(x f = sin 2x ω cos 2x ω 在区间[－3π，4π]上单调递增，则ω的范围是 .13．函数)(x f y =的图像与直线b x a x ==,及x 轴所围成图形的面积称为函数)(x f 在[]b a ,上的面积，已知函数nx y sin =在⎥⎦⎤⎢⎣⎡n π,0上的面积为)(2*∈N n n，则函数1)3sin(+-=πx y 在⎥⎦⎤⎢⎣⎡34,3ππ上的面积为 .14．函数)(x f 的定义域为A ，若A x x ∈21,且)()(21x f x f =时总有21x x =，则称)(x f为单函数，例如，函数)(12)(R x x x f ∈+=是单函数．下列命题： ①函数)()(2R x x x f ∈=是单函数； ②指数函数)(2)(R x x f x ∈=是单函数；③若)(x f 为单函数，A x x ∈21,且21x x ≠，则)()(21x f x f ≠； ④在定义域上具有单调性的函数一定是单函数；其中的真命题是________．(写出所有真命题的编号) 二、选择题（本大题满分20分，每题5分）15. 命题:p 1a =;命题:q 关于x 的方程20x a -+=有实数解,则p 是q 的( ).(A) 必要不充分条件 (B) 充分不必要条件 (C)充要条件 (D)既不充分也不必要条件 16．下列函数中，最小正周期为π的偶函数为（） (A) )4cos()4sin(ππ++=x x y (B)xxy 2sin 2cos 1+=(C) x y 2tan 2= (D)x x y cos sin =17. 定义函数D x x f y ∈=),(（定义域），若存在常数C ，对于任意D x ∈1,存在唯一的D x ∈2，使得C x f x f =+2)()(21,则称函数)(x f y =在D 上的“均值”为C 。

上海市十二校2017届高三下学期3月联考英语试题 (部分答案)

2017届高三十二校英语联考试卷第I卷I. Listening ComprehensionSection A1. A. He thought it was fascinating. B. He agreed with the woman.C. He thought it should have been longer.D. He thought it was boring.2. A. There is still time to finish. B. She cannot do it quickly.C. He needs the letters tomorrow.D. He doesn’t know what time it is.3. A. She lives far away. B. She wants the man to walk with her.C. She has a new car.D. Her car is close.4. A. See the manager immediately. B. Wait for the manager to arrive.C. Arrange to meet the manager the next day.D. Break her appointment with the manager.5. A. She likes some of them. B. She isn’t sure what she thinks about them.C. She agrees with the man’s opinio n of them.D. She hasn’t read any of them.6. A. Tell him the time. B. Take care of his bag.C. Help him find his books.D. Go with him.7. A. Doctor and patient. B. Coach and athlete.C. Boss and secretary.D. Teacher and student.8. A. Chemistry 402 was worse than Chemistry 502.B. He has only had one chemistry course.C. Both chemistry courses are difficult.D. Few chemistry courses are hard.9. A. She doesn’t have an apartment. B. Her problem is complicated.C. She must live somewhere else.D. Her apartment isn’t far away.10. A. The man should watch the program too. B. The man should leave the television on.C. The program will be over soon.D. She’ll watch television later.Section BQuestions 11 through 13 are based on the following passage.11. A. It gets its water from the ocean. B. It is a little saltier than the ocean.C. It is far from the ocean.D. It is larger than any state.12. A. The lake is too deep. B. The speaker was too heavy.C. The water held up the speaker.D. The speaker’s eyes hurt.13. A. Interesting B. Painful. C. Useful. D. Surprising.Questions 14 through 16 are based on the following report.14. A. Her mother doesn’t love her as much as her grandfather did.B. Her mother was the subject of talks with her grandfather.C. Her mother will misunderstand her problems.D. She missed her grandfather.15. A. Co-workers cannot be your close friends.B. People will be pleased if you call them at 2:00 am.C. You can’t discuss your problems with a distant family.D. The one you can call at 2:00 am. is someone close to you in spirit.16. A. Parents should understand their kids.B. The earth is an inhabited garden if you have close friends.C. There are many ways to make friends.D. There is difference between a lonely desert and inhabited garden.Questions 14 through 16 are based on the following report.17. A. Because he is too foolish.B. Because he hasn’t put much time on study.C. Because he doesn’t think study performance is important.D. Because the subjects are difficult.18. A. 1 hour. B. 2 hours. C. 3 hours. D. 4 hours19. A. Soccer practice. B. V olunteering.C. Part-time job.D. Watching TV.20. A. Soccer practice. D. Volunteering.C. Part-time job.D. Studying.II. Grammar and VocabularySection ADirections: After reading the passages below, fill in the blanks to make the passages coherent and grammatically correct. For the blanks with a given word, fill in each blank with the proper form. of the given word; for the other blanks, use one word that best fits each blank.how to find Happiness without Buying it ?Our materialistic society has led us to believe that happiness cannot obtained without having money .Rather than learning to be satisfied with what we have ,we are taught to want more . We learn from advertising , and from the media , ____21____ we need to buy some toys in order to make ourselves happy , or ______22_____(fulfill ) emotional needs , and that the purchase they are trying to talk us into will provide us with the psychological comfort we are looking ____23_______.Unfortunately , as a society we have bought into these _______24____ (misguide) messages and have come to believe that spending money on certain items ____25________(bring ) us fame ,fortune ,happiness , beauty ,or popularity . As a result , we trade hours of our lives working ,sacrificing time that _______26_____ have been spent with our families ,for the pursuit of the almighty (万能的) dollar.Actually ,there are a number of ways to enjoy life without the need for a great deal of money . For example , think about __27_______ you would spend your time , and what you would do for enjoyment . Change your focus form material possessions to ____28_____that bring you enjoyment ,such as spending quality time with your family and friends. Certainly ,it is important to work and earn enough to provide for our basic needs and the needs of our families , but it is important to recognize ______29_____ the desire for personal possessions becomes overly consuming , _____30_______otherwise will upset a balance between a satisfying work life and a rich home life. The best way to achieve such a balance is to ensure the drive for material possessions does not become all consuming.Section BDirections: Complete the following passage by using the words in the box. Each word can only be used once. Note that there is one word more than you need.A access B. anxious C . concentrate D. negatively E. permittedF. previousG. satisfactionH.sufferI. touchJ. objectivelyK. vitalToo much time spent on your cell phone doesn’t mean you’re more connected and happier.A new research from scientist at Ken State University in Kent , Ohio shows that the more time college students spend on their cell phones , the more ______41_____ they are and the more their academic performance will ____42______.Jacob Barkley , Aryn Karpinsiki and Andrew Lepp studied 500 Kent State University students , each of whom reported their daily cell phone use for the year as well as their level of anxiety and ______43_____with their life.At the end of the year , the students also _____44_____ the researchers to see their official school records for their whole grade point average (GPA) . Not only was greater cell phone use ______45________related to satisfaction and happiness indicators , it was also associated with lower GPAs------ mainly because the students were more anxious and unable to __46______on their studies.While _______47_____research found that cell phones can improve social ineractions and reduce feelings of isolation ,the latest findings ,published in the journal Computers in Human Behavior , suggest that constant ______48____ to information and people may be a double edged-sword（双刃剑）。

2025届上海市12校联考高三第一次模拟考试数学试卷含解析

2025届上海市12校联考高三第一次模拟考试数学试卷注意事项1．考试结束后，请将本试卷和答题卡一并交回．2．答题前，请务必将自己的姓名、准考证号用0．5毫米黑色墨水的签字笔填写在试卷及答题卡的规定位置． 3．请认真核对监考员在答题卡上所粘贴的条形码上的姓名、准考证号与本人是否相符．4．作答选择题，必须用2B 铅笔将答题卡上对应选项的方框涂满、涂黑；如需改动，请用橡皮擦干净后，再选涂其他答案．作答非选择题，必须用05毫米黑色墨水的签字笔在答题卡上的指定位置作答，在其他位置作答一律无效． 5．如需作图，须用2B 铅笔绘、写清楚，线条、符号等须加黑、加粗．一、选择题：本题共12小题，每小题5分，共60分。

在每小题给出的四个选项中，只有一项是符合题目要求的。

1．已知函数()f x 满足当0x ≤时，2(2)()f x f x -=，且当(2,0]x ∈-时，()|1|1f x x =+-；当0x >时，()log (0a f x x a =>且1a ≠).若函数()f x 的图象上关于原点对称的点恰好有3对，则a 的取值范围是（）A ．(625,)+∞B ．(4,64)C ．(9,625)D ．(9,64)2．已知函数()222ln 02x x e f x e x x e⎧<≤=⎨+->⎩，，，存在实数123x x x <<，使得()()()123f x f x f x ==，则()12f x x 的最大值为（）A ．1eB ．1eC ．12eD ．21e 3．已知当m ，[1n ∈-，1)时，33sin sin22mnn m ππ-<-，则以下判断正确的是( )A ．m n >B ．||||m n <C ．m n <D ．m 与n 的大小关系不确定4．已知集合A={x|y=lg （4﹣x 2）}，B={y|y=3x ，x ＞0}时，A∩B=（） A ．{x|x ＞﹣2} B ．{x|1＜x ＜2} C ．{x|1≤x≤2} D ．∅ 5．函数的定义域为（）A ．[，3）∪（3，+∞）B ．（-∞，3）∪（3，+∞）C ．[，+∞）D ．（3，+∞）6． “幻方”最早记载于我国公元前500年的春秋时期《大戴礼》中．“n 阶幻方()*3,n n ≥∈N ”是由前2n 个正整数组成的—个n 阶方阵，其各行各列及两条对角线所含的n 个数之和（简称幻和）相等，例如“3阶幻方”的幻和为15（如图所示）．则“5阶幻方”的幻和为（）A ．75B ．65C ．55D ．457．抛物线24y x =的焦点为F ，点(,)P x y 为该抛物线上的动点，若点(1,0)A -，则PFPA的最小值为（） A ．12B ．22C ．32D ．2238．已知α是第二象限的角，3tan()4πα+=-，则sin 2α=( ) A ．1225B ．1225-C ．2425D ．2425-9．已知数列满足，且，则数列的通项公式为（） A ．B ．C ．D ．10．已知复数，则的共轭复数在复平面对应的点位于（） A ．第一象限B ．第二象限C ．第三象限D ．第四象限11．如图，平面α与平面β相交于BC ，AB α⊂，CD β⊂，点A BC ∉，点D BC ∉，则下列叙述错误的是（）A ．直线AD 与BC 异面B ．过AD 只有唯一平面与BC 平行 C ．过点D 只能作唯一平面与BC 垂直 D ．过AD 一定能作一平面与BC 垂直12．设全集U =R ，集合{}221|{|}xM x x x N x =≤=，＜，则UM N =（）A ．[]0,1B ．(]0,1C ．[)0,1D ．(],1-∞二、填空题：本题共4小题，每小题5分，共20分。

【恒心】2015届上海市十二校高三12月联考地理试题及参考答案【word版】

2014学年第一学期十二校联考高三地理考试试卷三林中学上南中学曙光中学（完卷时间120分钟，满分150分） 2014.12一、单项选择题：（每小题2分，共60分）（一）2014年北京时间6月13日凌晨2时15分，巴西世界杯开幕式在圣保罗竞技场隆重举行。

据此回答1～2题。

1. 开幕式时巴西的当地时间（西三区区时）是A.6月12日13时15分B.6月12日15时15分C.6月13日13时15分D.6月13日15时15分2. 开幕式时段A．江淮地区适逢梅雨季节B．亚洲大陆被高压控制C．华北平原正值小麦播种期D．北印度洋洋流呈逆时针流动（二）近年来，随着全球气候变暖，我国部分地区的自然环境出现了一系列反常现象。

回答3-4题。

3．下列现象中，与全球气候变暖有关的是：①天山博格达峰雪线下降②东海出现南海的鱼种③华北地区树枝提前抽芽④灾害性天气出现频繁A．②③④ B．①②③ C．①③④ D．①②④4．自然界中某种因素的变化会引起其他一系列因素的变化，例如青藏高原积雪面积减小，会引起该地域自然环境的连锁变化。

这种变化包括：①地表温度年变化增大②风化加速导致岩崩现象加剧③羊八井地热温度升高④山地针叶林带海拔高度降低A．①④ B．②③ C．③④ D．①②（三）臭氧层保护是当今全球最重要的环保议题之一。

下图反映了9月份30°S～80°S平流层臭氧总量多年变化状况。

读图回答5—6题。

5.随年份的推移，臭氧总量A．最大值所在位置南移B．随纬度的增高而递减C．在高纬地区递减明显D．随大气CO2浓度而增6.臭氧总量减少直接导致A．太阳紫外线辐射减小B．平流层气温降低C．酸雨区面积缩小D．地面辐射强度减弱（四）读云南路南石林地区不同植被下土层空气中CO2浓度示意图，完成7-8题。

7．如果水分条件相同，下列植被分布区中土层最容易被溶蚀的是A．无植被耕地B．人工草坡C．柏树林D．天然草坡8.如果当地植被遭到破坏，可能会产生一系列的环境问题或自然灾害.但不会引起A.水土流失B.荒漠化C.滑坡、泥石流D.土壤盐碱化（五）陕北高原南部过去以种粮为主，产量低。

上海市十二校联考2015届高三第一学期历史考试试卷

上海市十二校联考2015届高三第一学期历史试卷2014年11月一、选择题（共75分：第1～30题每题2分，第31～35题每题3分；每题只有一个正确的选项。

）1、“夫五千年以前，人户稀微，制作未备，何以能成此大工？”这是针对古代哪一建筑物而发出的疑问（）A．中国秦长城B．古希腊帕特农神庙C．汉穆拉比法典石柱D．古埃及的金字塔2、罗马法中有句名言，即“没有告诉人就没有法官”，这就是由“控诉式诉讼”派生出来的“不告不理”的审判原则。

这说明古罗马（）A．减少诉讼案件B．注重法律程序C．维护贵族利益D．强调证据作用3、对“雅典城邦”（Athens Polis）一词中“城邦”的解释，更接近本质特征的是（）A．城市国家B．公民国家C．独立国家D．联邦制国家4、在沙特阿拉伯王国国旗上，用阿拉伯文写着：“万物非主，惟有真主，穆罕默德是安拉的使者。

”这表明在沙特阿拉伯王国具有特殊地位的宗教是（）A．佛教B．基督教C．伊斯兰教D．东正教5、一位学者评论某一政权，认为：这个政权中，君主不能直接控制地方，犹如全身瘫痪，中枢神经不能直接控制四肢，身体各部位只能有限的互相牵动。

这个政权最可能是指（）A．二世纪初的罗马帝国B．九世纪中叶的法兰克王国C．十五世纪下半叶的英国D．十九世纪下半叶的德国6、17世纪以前，英国议会拥有的权力是（）A．任命政府的首相B．决定是否向民众征收新税C．决定王位的继承D．否决国王增加常备军提议7、“譬犹从一大树中截枝分栽，别成一独立之新根干。

”这形容的是（）A．封邦建国制B．王位世袭制C．郡县制D．三省六部制8、下列改革中，实现了富国强兵，“倾邻国而雄诸侯”的是（）A．商鞅变法B．汉武帝改革C．北魏孝文帝改革D．王安石变法9、春秋战国时期一位思想家认为：“今夫天下之人牧，未有不嗜杀人者也。

如有不嗜杀人者，则天下之民皆引领而望之矣！诚如是也，民归之，由水之就下，沛然谁能御之？”该思想家的核心观点应是（）A．清静无为B．唯法为治C．仁政治国D．非攻兼爱10、“事在四方，要在中央。

上海市十二校2015届高三12月联考数学(文)试题 Word版含答案

上海市十二校2015届高三12月联考数学（文）试题学校：上海市朱家角中学学校：三林中学南汇一中 2014年12月一、填空题（本大题满分56分，每题4分）1．设集合21{|2},{1}2A x xB x x =-<<=≤，则A B =_______.2. 已知{}n a 为等差数列，1a +3a +5a =9，246a a a ++=15，则=+43a a .3．在行列式3541113a --中，元素a 的代数余子式值为．4．如果函数⎩⎨⎧<>-=)0( )()0( 32　x x f x x y 是奇函数，则=-)2(f ．5．设()f x 的反函数为1()f x -，若函数()f x 的图像过点(1,2)，且1(21)1f x -+=，则x = ．6．一个正三棱柱的底面的边长为6，侧棱长为4，则这个棱柱的表面积为___________．7. 方程cos2x+sinx=1在),0(π上的解集是_______________. 8.已知数列{}n a 满足⎩⎨⎧-=为奇数为偶数n n n a n n212，且1222321)(--+++++=n n a a a a a n f ,()*∈N n ,则()()34f f -的值为 .9．函数()x x x f 2cos 222cos 3-⎪⎭⎫ ⎝⎛-=π在区间2π03⎡⎤⎢⎥⎣⎦，上的取值范围是 .10．已知2==b a ，a 与b 的夹角为3π，则b a +在a 上的投影为 . 11. 数列{}n a 的通项公式)(2,)1(11,1*∈⎪⎩⎪⎨⎧≥+==N n n n n n a n ，前n 项和为n S ，则n n S ∞→lim = .12. 在锐角ABC ∆中，角B 所对的边长10=b ，ABC ∆的面积为10，外接圆半径13=R ，则ABC ∆的周长为 . 13．已知函数()23sin()(0)3f x x πωω=+>，若()(3)g x f x =在(0 )3π，上是增函数，则ω的最大值．14. 记数列{}n a 是首项1a a =，公差为2的等差数列；数列{}n b 满足2(1)n n b n a =+，若对任意*n N ∈都有5n b b ≥成立，则实数a 的取值范围为 .二、选择题（本大题满分20分，每题5分）15. 设,p q 是两个命题，1:0,:|21|1,x p q x p q x+≤+<则是（）A ．充分非必要条件B ．必要非充分条件C ．充要条件D ．既非充分又非必要条件16. 某流程图如图所示，现输入如下四个函数，则可以输出的函数是（）A .2)(x x f = B .xx x f =)(C .xx xx e e e e x f --+-=)( D .x x f =)(17.已知函数x x f πsin )(=的图象的一部分如下方左图，则下方右图的函数图象所对应的函数解析式为（）A .)212(-=x f y B .)12(-=x f yC .)12(-=x f y D .)212(-=x f y 18. 关于函数31)212()(x x f x x⋅-=和实数n m 、的下列结论中正确的是（）A.若n m <<-3，则)()(n f m f <B.若0<<n m ，则)()(n f m f <C.若)()(n f m f <，则22n m <D.若)()(n f m f <，则33n m <三、简答题 (本大题满分74分)19．(本题满分12分) 本题共有2个小题,第1小题满分6分, 第2小题满分6分.如图，四棱锥ABCD S -中，底面ABCD 为正方形，⊥SA 平面ABCD ， AB=3，SA=4（1）求异面直线SC 与AD 所成角；（2）求点B 到平面SCD 的距离20．（本题满分14分）本题共有2个小题，第一小题满分7分，第二小题满分7分）．在ABC ∆中，角C B A ,,的对边分别为c b a ,,，已知向量)23sin ,23(cosAA m =，)2sin ,2(cosAA n =且3=+n m （1）求角A 的大小；（2）若A CB sin 3sin sin =+，求证ABC ∆是直角三角形。

2024届上海市文达校十校联考最后语文试题含解析

2024届上海市文达校十校联考最后语文试题考生须知：1．全卷分选择题和非选择题两部分，全部在答题纸上作答。

选择题必须用2B铅笔填涂；非选择题的答案必须用黑色字迹的钢笔或答字笔写在“答题纸”相应位置上。

2．请用黑色字迹的钢笔或答字笔在“答题纸”上先填写姓名和准考证号。

3．保持卡面清洁，不要折叠，不要弄破、弄皱，在草稿纸、试题卷上答题无效。

一、积累1．把下列句子组合成语意连贯的一段话，正确的一项是( )①美国著名画家麦克唐纳还根据基姆的描述，画出了万户飞天的插图。

②因此这次实验，被6个世纪以后的国际航天史学家公认为人类试图利用火箭升空的首次壮举。

③由于万户想象得太简单，风筝和椅子也不符合飞行原理，飞行试验最终失败是情理之中的。

④基姆在《火箭与喷气发动机》一书中引用这条史料后，引起了欧美各国火箭学者的注意。

⑤但万户这种大胆而天才的技术构思，比后来俄罗斯有“火箭之父”称号的齐奥尔科夫斯基1903年提出的利用火箭进行星际交通的设想早了几百年。

A．①③②④⑤B．③⑤②④①C．①④⑤②③D．③⑤④②①2．下列词语中没有错别字的一项是（）A．逞能撮弄盘缠三顾茅芦B．恪守尴尬盲从附庸风雅C．拮据应酬戮破前仆后继D．秘决尴尬困厄李代桃僵3．下列对病句的修改不正确的一项是（）A．今天“数字阅读”企业成功的关键，是能否让年轻人体会到经典文章的魅力。

（删去“能否”）B．中学生要提升文学素养，养成爱读书，尤其是阅读经典、让书香浸润心灵。

（在“浸润心灵”后加“的习惯”）C．由于对志愿者精神理解不深，使得部分志愿者还不能主动投入到“全国文明城市”创建活动中。

（去掉“由于”）D．经过表决、推举、讨论等程序，学生会的人选顺利产生。

（把“推举、讨论”移到“表决”的前面）4．下列关于名著的表述，不正确．．．的一项是 ( )A．《草房子》中细马在养父病逝、养母疯后，毅然挑起了家的重任，在校门口摆起小摊。

B．《老人与海》中圣地亚哥不屈服于命运，凭着自己的勇气、毅力和智慧与鲨鱼搏斗。

【恒心】2015届上海市十二校高三12月联考物理试题及参考答案【word版】

2014学年第一学期十二校联考高三物理考试试卷命题人：上南中 2014年12月第I 卷一．单选题（本大题共8小题，每小题2分，共16分）1．以下是力学中的三个实验装置，由图可知这三个实验共同的物理思想方法是：（A ）极限的思想方法（B ）放大的思想方法（C ）控制变量的方法（D ）猜想的思想方法2．下列关于分子运动和热现象的说法中正确的是：（A ）对于一定量的理想气体，如果压强不变，体积增大，那么它的内能一定增大（B ）气体如果失去了容器的约束会散开，这是因为气体分子之间存在势能的缘故（C ）一定量100℃的水变成100℃的水蒸汽，其分子之间的势能不变（D ）如果气体温度升高，那么所有分子的速率都增大3．如图所示,粗细均匀的U 形管竖直放置,管内由水银柱封住一段空气柱.如果沿虚线所示的位置把开口一侧的部分截掉,保持弯曲部分管子位置不动,则封闭在管内的空气柱将：（A ）体积变小（B ）体积变大（C ）压强变小（D ）压强不变4．如图所示，木块m 放在木板AB 上，在木板的A 端用一个竖直向上的力F 使木板绕固定支点B 逆时针缓慢转动。

在此过程中，m 与AB 保持相对静止，则：（A ）竖直向上的拉力F 逐渐减小（B ）拉力F 的力矩逐渐减小（C ）木板对木块m 的作用力逐渐减小（D ）木块m 受到的静摩擦力逐渐减小5．如图所示，A 、B 为带电量分别为＋Q 和－Q 的两个等量异种电荷，c 、d 为A 、B 连线上的两点，且Ac =Bd ，关于c 、d 两点间电场强度的情况是：（A ）由c 到d 电场强度由大变小（B ）由c 到d 电场强度由小变大（C ）由c 到d 电场强度不变显示桌面受力形变装置A Q（D ）由c 到d 电场强度先变小后变大6．如图所示，正在匀速转动的水平转盘上固定有三个可视为质点的小物块A 、B 、C ，它们的质量关系为m A =2m B =2m C ，到轴O 的距离关系为r C =2r A =2r B 。

2021-2022学年上海市浦东新区多校联考八年级(上)期末数学试卷(解析版)

2021-2022学年上海市浦东新区多校联考八年级第一学期期末数学试卷一、选择题（本大题共6小题，每小题2分，共12分）1．下列二次根式中，与是同类二次根式的是（）A．B．C．D．2．下列三个数为边长的三角形不是直角三角形的是（）A．3，3，3B．4，8，4C．6，8，10D．5，5，53．已知正比例函数y＝kx（k≠0），y的值随x的值的增大而减小，那么它和反比例函数y ＝﹣（k≠0）在同一直角坐标平面内的大致图象是（）A．B．C．D．4．下列命题中，逆命题不正确的是（）A．两直线平行，同旁内角互补B．对顶角相等C．直角三角形的两个锐角互余D．直角三角形两条直角边的平方和等于斜边的平方5．如图，在等腰Rt△ABC中，∠A＝90°，AB＝AC，BD平分∠ABC，交AC于点D，DE ⊥BC，若BC＝10cm，则△DEC的周长为（）A．8cm B．10cm C．12cm D．14cm6．在反比例函数y＝的图象上有三点A1（x1，y1）、A2（x2，y2）、A3（x3，y3），已知x1＜x2＜0＜x3，则下列各式中，正确的是（）A．y1＜y2＜y3B．y3＜y2＜y1C．y2＜y1＜y3D．y3＜y1＜y2二、填空题（本大题共12小题，每小题3分，共36分）7．已知函数f（x）＝，那么f（2）＝．8．计算：＝．9．函数：的定义域是．10．已知关于x的方程mx2﹣3x﹣1＝0有两个不相等的实数根，那么m的取值范围是．11．随着网络购物的兴起，增加了快递公司的业务量．一家今年刚成立的小型快递公司业务量逐月攀升，今年9月份和11月份完成投送的快递件数分别是20万件和24.2万件，若该公司每月投送的快递件数的平均增长率是x，由题意列出关于x的方程：．12．在实数范围内因式分解：2x2﹣4x﹣1＝．13．到点A的距离等于6cm的点的轨迹是．14．已知：点A坐标为（3，4），点B坐标为（﹣1，1），那么点A和点B两点间的距离是．15．已知：如图，在△ABC中，AB＝AC，线段AB的垂直平分线分别交AB、AC于点D、E，如果∠EBC＝42°，那么∠A＝．16．如图，在△ABC中，∠ABC＝52°，三角形的两个外角∠DAC和∠ACF的平分线交于点E，则∠ABE＝．17．如图，P是正方形ABCD内的一点，将△ABP绕点B顺时针方向旋转到与△CBQ重合，若PB＝5cm，则PQ＝cm．18．如图，在平面直角坐标系中，直线AB与x轴交于点A（﹣2，0），与x轴夹角为30°，将△ABO沿直线AB翻折，点O的对应点C恰好落在双曲线y＝（k≠0）上，则k的值为．三、简答题（本大题共5小题，每小题5分，满分25分）19．计算：．20．解方程：2y（y﹣2）＝y2﹣2．21．已知y＝y1+y2，并且y1与x成正比例，y2与x﹣2成反比例．当x＝3时，y＝7；当x＝1时，y＝1，求：y关于x的函数解析式．22．某中学初二年级游同学在学习了勾股定理后对《九章算术》勾股章产生了学习兴趣．今天，他学到了勾股章第7题：“今有立木，系索其末，委地三尺．引索却行，去本八尺而索尽．问索长几何？”本题大意是：如图，木柱AB⊥BC，绳索AC比木柱AB长三尺，BC的长度为8尺，求：绳索AC的长度．23．初二年级小王同学坚持环保理念，每天骑自行车上学，学校离家3000米．某天，小王上学途中因自行车发生故障，修车耽误了一段时间后继续骑行，还是按时赶到了学校、如图描述的是他离家的距离和离家的时间t之间的函数图象，根据图象解决下列问题：（1）修车时间为分钟；（2）到达学校时共用时间分钟；（3）小王从离家时到自行车发生故障时，离家的距离S和离家的时间t之间的函数关系式为，定义域为；（4）自行车故障排除后他的平均速度是每分钟米．四、解答题（本大题共4小题，第24、25、26每小题6分，第27题9分，共27分）24．如图，已知△ABC，（1）根据要求作图，在边BC上求作一点D，使得点D到点AB、AC的距离相等，在边AB上求作一点E，使得点E到A、D的距离相等；（不要求写作法，但需要保留作图痕迹和结论）（2）在第（1）小题所作的图中，求证：DE∥AC．25．Rt△ABC中，∠ACB＝90°，点D、E分别为边AB、BC上的点，且CD＝CA，DE⊥AB，联结AE交CD与点F，点M是AE的中点，联结CM并延长与AB交于点H．（1）点F是CD中点时，求证：AE⊥CD；（2）求证：MH2+HD2＝AM2．26．如图，在平面直角坐标系内，双曲线y＝（k≠0）上有A，B两点，且与直线y＝ax （a＞0）交于第一象限内的点A，点A的坐标为（4，2），点B的坐标为（n，1），过点B作y轴的平行线，交x轴与点C，交直线y＝ax（a＞0）与点D，（1）求：点D的坐标；（2）求：△AOB的面积；（3）在x轴正半轴上是否存在点P，使△OAP是以OA为腰的等腰三角形？若不存在，请说明理由；若存在，请直接写出P的坐标．27．如图，△ABC中，AC＝2，BC＝4，AB＝6．点P是射线CB上的一点（不与点B 重合），EF是线段PB的垂直平分线，交PB与点F，交射线AB与点E，联结PE、AP．（1）求∠B的度数；（2）当点P在线段CB上时，设EF＝x，△APE的面积为y，求y关于x的函数解析式，并写出函数的定义域；（3）如果EF＝1，请直接写出△APE的面积．参考答案一、选择题（本大题共6小题，每小题2分，共12分）1．下列二次根式中，与是同类二次根式的是（）A．B．C．D．【分析】把各个选项化简，判断是否与是同类二次根式即可．解：A、＝＝，故选项错误；B、是最简二次根式，故选项错误；C、＝，故正确；D、＝，故选项错误．故选：C．2．下列三个数为边长的三角形不是直角三角形的是（）A．3，3，3B．4，8，4C．6，8，10D．5，5，5【分析】根据勾股定理的逆定理判断即可．解：A．∵32+32＝18，（）2＝18，∴32+32＝（）2，∴以3，3，三个数为边长的三角形是直角三角形，故A不符合题意；B．∵42+（）2＝64，82＝64，∴42+（）2＝82，∴以4，8，三个数为边长的三角形是直角三角形，故B不符合题意；C．∵62+82＝100，102＝100，∴62+82＝102，∴以6，8，10三个数为边长的三角形是直角三角形，故B不符合题意；D．∵52+52＝50，（）2＝75，∴52+52≠（）2，∴以5，5，三个数为边长的三角形不是直角三角形，故D符合题意；故选：D．3．已知正比例函数y＝kx（k≠0），y的值随x的值的增大而减小，那么它和反比例函数y ＝﹣（k≠0）在同一直角坐标平面内的大致图象是（）A．B．C．D．【分析】首先由“y＝kx（k≠0）中y随x的增大而减小”判定k＜0，然后根据k的符号来判断函数y＝﹣所在的象限．解：∵函数y＝kx（k≠0）中y随x的增大而减小，∴k＜0，该函数图象经过第二，四象限；∴函数y＝﹣的图象经过第一、三象限；故选：C．4．下列命题中，逆命题不正确的是（）A．两直线平行，同旁内角互补B．对顶角相等C．直角三角形的两个锐角互余D．直角三角形两条直角边的平方和等于斜边的平方【分析】首先写出各个命题的逆命题，然后进行判断即可．解：A、逆命题是：同旁内角互补，两直线平行，正确，故本选项错误；B、逆命题是相等的角是对顶角，为假命题，故本选项正确；C、逆命题是：若一个三角形两锐角互余，则为直角三角形，正确，故本选项错误；D、逆命题是：若一个三角形两条直角边的平方和等于斜边的平方则为直角三角形，正确，故本选项错误．故选：B．5．如图，在等腰Rt△ABC中，∠A＝90°，AB＝AC，BD平分∠ABC，交AC于点D，DE ⊥BC，若BC＝10cm，则△DEC的周长为（）A．8cm B．10cm C．12cm D．14cm【分析】根据角平分线上的点到角的两边距离相等可得DE＝AD，利用“HL”证明Rt△ABD和Rt△EBD全等，根据全等三角形对应边相等可得AB＝AE，然后求出△DEC的周长＝BC，再根据BC＝10cm，即可得出答案．解：∵BD是∠ABC的平分线，DE⊥BC，∠A＝90°，∴DE＝AD，在Rt△ABD和Rt△EBD中，∵，∴Rt△ABD≌Rt△EBD（HL），∴AB＝AE，∴△DEC的周长＝DE+CD+CE＝AD+CD+CE，＝AC+CE，＝AB+CE，＝BE+CE，＝BC，∵BC＝10cm，∴△DEC的周长是10cm．故选：B．6．在反比例函数y＝的图象上有三点A1（x1，y1）、A2（x2，y2）、A3（x3，y3），已知x1＜x2＜0＜x3，则下列各式中，正确的是（）A．y1＜y2＜y3B．y3＜y2＜y1C．y2＜y1＜y3D．y3＜y1＜y2【分析】根据反比例函数解析式画出草图，再找出符合条件的点，可以直观的得到答案．解：如图所示：根据函数图象可得y2＜y1＜y3，故选：C．二、填空题（本大题共12小题，每小题3分，共36分）7．已知函数f（x）＝，那么f（2）＝﹣1．【分析】把x＝2代入函数关系式即可解答．解：当x＝2时，f（2）＝＝＝﹣1，故答案为：﹣1．8．计算：＝3﹣．【分析】直接利用二次根式的性质化简得出答案．解：＝3﹣．故答案为：3﹣．9．函数：的定义域是x≥2．【分析】根据二次根式的性质，被开方数大于等于0，可知：x﹣2≥0，解得x的范围．解：根据题意得：x﹣2≥0，解得：x≥2．10．已知关于x的方程mx2﹣3x﹣1＝0有两个不相等的实数根，那么m的取值范围是m＞﹣且m≠0．【分析】根据一元二次方程的定义以及根的判别式的意义可得Δ＝9+4m＞0且m≠0，求出m的取值范围即可．解：∵关于x的方程mx2﹣3x﹣1＝0有两个不相等的实数根，∴Δ＞0且m≠0，∴9+4m＞0且m≠0，∴m＞﹣且m≠0，故答案为：m＞﹣且m≠0．11．随着网络购物的兴起，增加了快递公司的业务量．一家今年刚成立的小型快递公司业务量逐月攀升，今年9月份和11月份完成投送的快递件数分别是20万件和24.2万件，若该公司每月投送的快递件数的平均增长率是x，由题意列出关于x的方程：20（1+x）2＝24.2．【分析】利用11月份完成投送的快递件数＝9月份完成投送的快递件数×（1+平均增长率）2，即可得出关于x的一元二次方程，此题得解．解：依题意得：20（1+x）2＝24.2．故答案为：20（1+x）2＝24.2．12．在实数范围内因式分解：2x2﹣4x﹣1＝2（x﹣）（x﹣）．【分析】令原式为0求出x的值，即可确定出因式分解的结果．解：令2x2﹣4x﹣1＝0，这里a＝2，b＝﹣4，c＝﹣1，∵△＝16+8＝24，∴x＝＝，则原式＝2（x﹣）（x﹣），故答案为：2（x﹣）（x﹣）13．到点A的距离等于6cm的点的轨迹是以点A为圆心，6cm为半径的圆．【分析】根据圆的定义直接得出答案即可．解：由题知，到点A的距离等于6cm的点的轨迹是以点A为圆心，6cm为半径的圆，故答案为：以点A为圆心，6cm为半径的圆．14．已知：点A坐标为（3，4），点B坐标为（﹣1，1），那么点A和点B两点间的距离是5．【分析】根据勾股定理、两点间的距离公式计算即可．解：由勾股定理得：AB＝＝5，则点A和点B两点间的距离是5，故答案为：5．15．已知：如图，在△ABC中，AB＝AC，线段AB的垂直平分线分别交AB、AC于点D、E，如果∠EBC＝42°，那么∠A＝32°．【分析】由线段垂直平分线的性质可得AE＝BE，可得∠A＝∠EBA，且可得∠ABC＝∠C，在△ABC中利用三角形内角和可求得∠A．解：∵DE为AB的垂直平分线，∴EA＝EB，∴∠A＝∠EBA，∵AB＝AC，∴∠ABC＝∠C，又∵∠EBC＝42°，∴∠C＝42°+∠EBA＝42°+∠A，又∵∠A+∠C+∠ABC＝180°，∴∠A+2（42°+∠A）＝180°，∴∠A＝32°．故答案为：32°．16．如图，在△ABC中，∠ABC＝52°，三角形的两个外角∠DAC和∠ACF的平分线交于点E，则∠ABE＝26°．【分析】过点E作EM⊥AB于M、EN⊥BC于N、EO⊥AC于O，根据角平分线的性质即可得出EM＝EO＝EN，结合EM⊥AB于M、EN⊥BC于N，即可得出BE平分∠ABC，再根据角平分线的定义即可得出结论．解：过点E作EM⊥AB于M、EN⊥BC于N、EO⊥AC于O，如图所示．∵三角形的外角∠DAC和∠ACF的平分线交于点E，∴EM＝EO，EN＝EO，∴EM＝EN，∵EM⊥AB于M，EN⊥BC于N，∴BE平分∠ABC，∴∠ABE＝∠ABC＝26°．故答案为：26°．17．如图，P是正方形ABCD内的一点，将△ABP绕点B顺时针方向旋转到与△CBQ重合，若PB＝5cm，则PQ＝5cm．【分析】依题意得，旋转中心为点B，旋转角∠PBQ＝∠ABC＝90°，对应点P、Q到旋转中心的距离相等，即PB＝BQ＝5，可证△BPQ为等腰直角三角形，由勾股定理求PQ．解：根据旋转的性质可知，∠PBQ＝∠ABC＝90°，PB＝BQ＝5，∴△BPQ为等腰直角三角形，由勾股定理，得PQ＝＝5．故答案为：5．18．如图，在平面直角坐标系中，直线AB与x轴交于点A（﹣2，0），与x轴夹角为30°，将△ABO沿直线AB翻折，点O的对应点C恰好落在双曲线y＝（k≠0）上，则k的值为﹣．【分析】先过点C作CD⊥x轴于D，作CE⊥y轴于E，构造矩形CDOE，再根据折叠的性质求得AC＝2，∠ACD＝30°，根据直角三角形的性质以及勾股定理，求得AD与CD 的长，得出点C的坐标，最后计算反比例函数解析式即可．解：过点C作CD⊥x轴于D，作CE⊥y轴于E，则CE＝DO，CD＝EO，∵A（﹣2，0），∴AO＝2，由折叠得，AC＝AO＝2，∠CAO＝2∠BAO＝60°，∴Rt△ACD中，∠ACD＝30°，∴AD＝AC＝1，CD＝＝，∴DO＝AO﹣AD＝2﹣1＝1，OE＝，又∵点C在第二象限，∴C（﹣1，），∵点C在双曲线y＝（k≠0）上，∴k＝﹣1×＝﹣，故答案为：﹣三、简答题（本大题共5小题，每小题5分，满分25分）19．计算：．【分析】化简二次根式，然后先算乘除，再算加减．解：原式＝+9×﹣+＝3+﹣（）+＝3+﹣﹣+＝2+．20．解方程：2y（y﹣2）＝y2﹣2．【分析】先整理为一般式，再利用公式法求解即可．解：∵2y（y﹣2）＝y2﹣2，∴y2﹣4y+2＝0，∵a＝1，b＝﹣4，c＝2，∴△＝（﹣4）2﹣4×1×2＝8＞0，则y＝＝2±，∴y1＝2+，y2＝2﹣．21．已知y＝y1+y2，并且y1与x成正比例，y2与x﹣2成反比例．当x＝3时，y＝7；当x＝1时，y＝1，求：y关于x的函数解析式．【分析】设所求的函数解析式为y＝k1x+（k1≠0，k2≠0），再将所给的点代入可求得，即可求函数解析式．解：设所求的函数解析式为y＝k1x+（k1≠0，k2≠0），当x＝3时，y＝7；当x＝1时，y＝1，代入y＝k1x+，∴，解得，∴函数解析式是y＝2x+．22．某中学初二年级游同学在学习了勾股定理后对《九章算术》勾股章产生了学习兴趣．今天，他学到了勾股章第7题：“今有立木，系索其末，委地三尺．引索却行，去本八尺而索尽．问索长几何？”本题大意是：如图，木柱AB⊥BC，绳索AC比木柱AB长三尺，BC的长度为8尺，求：绳索AC的长度．【分析】设AC＝x尺，则AB＝（x﹣3）尺，由勾股定理得出方程（x﹣3）2+82＝x2，解方程即可．解：设AC＝x尺，则AB＝（x﹣3）尺，∵AB⊥BC，∴△ABC是直角三角形，由勾股定理得：AB2+BC2＝AC2，即（x﹣3）2+82＝x2，解得：x＝12（尺），答：绳索AC的长度是12尺．23．初二年级小王同学坚持环保理念，每天骑自行车上学，学校离家3000米．某天，小王上学途中因自行车发生故障，修车耽误了一段时间后继续骑行，还是按时赶到了学校、如图描述的是他离家的距离和离家的时间t之间的函数图象，根据图象解决下列问题：（1）修车时间为5分钟；（2）到达学校时共用时间20分钟；（3）小王从离家时到自行车发生故障时，离家的距离S和离家的时间t之间的函数关系式为S＝150t，定义域为0≤t≤10；（4）自行车故障排除后他的平均速度是每分钟300米．【分析】（1）观察图象，线段AB对应的这段时间为修车时间；（2）根据C点横坐标为20，得出到达学校时共用时间；（3）利用待定系数法解答即可；（4）根据线段BC表示修车后行使情况：5分钟行使了1500米，即可求出行驶速度．解：（1）由图知，线段AB对应的这段时间为修车时间，故修车时间为：15﹣10＝5（分钟）；故答案为：5；（2）利用C点横坐标为20，得出从家到学校用时20分钟，故答案为：20；（3）小王从离家时到自行车发生故障时，离家的距离S和离家的时间t之间的函数关系式为为S＝kt，则10t＝1500，解得：k＝150，∴S＝150t（0≤t≤10），故答案为：S＝150t；0≤t≤10；（4）线段BC表示修车后行使情况：5分钟行使了1500米，故速度为1500÷5＝300（米/秒）；故答案为：300．四、解答题（本大题共4小题，第24、25、26每小题6分，第27题9分，共27分）24．如图，已知△ABC，（1）根据要求作图，在边BC上求作一点D，使得点D到点AB、AC的距离相等，在边AB上求作一点E，使得点E到A、D的距离相等；（不要求写作法，但需要保留作图痕迹和结论）（2）在第（1）小题所作的图中，求证：DE∥AC．【分析】（1）由题意可知，D是∠BAC的角平分线与BC的交点，点E是AD的中垂线与AB的交点；（2）根据角平分线的性质和线段垂直平分线的性质可得∠CAD＝∠ADE，再根据平行线的判定即可求解．【解答】（1）解：如图所示：（2）证明：∵AD是∠BAC的角平分线，∴∠CAD＝∠BAD，∵EF是AD的中垂线，∴ED＝EA，∴∠ADE＝∠BAD，∴∠CAD＝∠ADE，∴DE∥AC．25．Rt△ABC中，∠ACB＝90°，点D、E分别为边AB、BC上的点，且CD＝CA，DE⊥AB，联结AE交CD与点F，点M是AE的中点，联结CM并延长与AB交于点H．（1）点F是CD中点时，求证：AE⊥CD；（2）求证：MH2+HD2＝AM2．【分析】（1）利用直角三角形斜边上的中线等于斜边的一半，得出MD＝MC，再利用点F是CD中点，即可得出结论；（2）根据直角三角形斜边上中线的性质可以得到C，M在线段AD的垂直平分线上，从而得到CH⊥AD，再利用勾股定理得出结论．【解答】证明：（1）连接MD，∵DE⊥AB，∴∠EDA＝90°，∵M是AE的中点，∴MD＝AE，同理可证：CM＝AE，∴CM＝MD，∵点F是CD中点，AE⊥CD；（2）∵DE⊥AB，∴∠EDA＝90°，∵点M是AE的中点，∴MD＝MA＝AE，∵CD＝CA，∴点M，点C在线段AD的垂直平分线上，∴CM是线段AD的垂直平分线，∴CH⊥AD，HA＝HD，∴∠MHA＝90°，在Rt△MAH中，MH2+HA2＝AM2，∴MH2+HD2＝AM2．26．如图，在平面直角坐标系内，双曲线y＝（k≠0）上有A，B两点，且与直线y＝ax （a＞0）交于第一象限内的点A，点A的坐标为（4，2），点B的坐标为（n，1），过点B作y轴的平行线，交x轴与点C，交直线y＝ax（a＞0）与点D，（1）求：点D的坐标；（2）求：△AOB的面积；（3）在x轴正半轴上是否存在点P，使△OAP是以OA为腰的等腰三角形？若不存在，请说明理由；若存在，请直接写出P的坐标．【分析】（1）求出直线OA解析式，根据反比例函数确定B点坐标，再根据B点和D 点横坐标相同求出D点坐标即可；（2）连接AB、OB，过A点作AH⊥BD于H，根据S△AOB＝S△OCD﹣S△COB﹣S△ADB计算即可；（3）分OA＝OP和OA＝AP两种情况分别求出P点坐标即可．解：（1）∵直线y＝ax（a＞0）与双曲线y＝交于第一象限内的点A（4，2），∴a＝，∴直线OA的解析式为y＝x，∵点B（n，1）在双曲线y＝上，∴n＝8，即B（8，1），由题知D点与B点横坐标相同都为8，当x＝8时，y＝，∴D（8，4）；（2）连接AB、OB，过A点作AH⊥BD于H，由（1）知C（8，0），B（8，1），D（8，4），A（4，2），∴OC＝8，CD＝4，BD＝3，BC＝1，AH＝4，∴S△AOB＝S△OCD﹣S△COB﹣S△ADB＝OC•CD﹣OC•BC﹣BD•AH＝×8×4﹣﹣＝16﹣4﹣6＝6，即△AOB的面积为6；（3）存在点P，使△OAP是以OA为腰的等腰三角形，分以下两种情况：①当OA＝OP时，∵A（4，2），∴OA＝＝2，∴OP＝2，即P（2，0）；②当OA＝AP时，OP＝2x A＝2×4＝8，即P（8，0），综上，符合条件的B点坐标为（2，0）或（8，0）．27．如图，△ABC中，AC＝2，BC＝4，AB＝6．点P是射线CB上的一点（不与点B 重合），EF是线段PB的垂直平分线，交PB与点F，交射线AB与点E，联结PE、AP．（1）求∠B的度数；（2）当点P在线段CB上时，设EF＝x，△APE的面积为y，求y关于x的函数解析式，并写出函数的定义域；（3）如果EF＝1，请直接写出△APE的面积．【分析】（1）先根据勾股定理逆定理判断出△ABC是直角三角形，再由AC＝BC即可得出答案；（2）作AD⊥BC，垂足为点D．由直角三角形30°角所对边等于斜边一半知AD＝AB ＝3，BE＝2EF＝2x，根据勾股定理知BF＝x，继而由S△APE＝S△APB﹣S△EPB可得出答案．（3）①当点P在线段BC上时，②当点P在线段CB的延长线上时，由三角形的面积公式可得出答案．解：（1）在△ABC中，∵AC＝2，BC＝4，AB＝6，∴AC2+AB2＝48，BC2＝48，∴AC2+AB2＝BC2．∴∠BAC＝90°．又∵AC＝2，BC＝4，∴AC＝BC，∴∠B＝30°．（2）过点A作AD⊥BC，垂足为点D．在△ADB中，∵∠ADB＝90°，∠B＝30°，∴AD＝AB＝3，同理，BE＝2EF＝2x．在Rt△EFB中，EF2+FB2＝EB2，∴BF＝x，∴BP＝2FB＝2x，∴S△EPB＝，S△APB＝x，∴S△APE＝S△APB﹣S△EPB＝3x﹣，所求的函数解析式为y＝﹣x2+3x，函数的定义域为0≤x＜．（3）①当点P在线段BC上时，由（2）可知，S△APE＝S△APB﹣S△EPB ＝3x﹣＝3﹣＝2．②当点P在线段CB的延长线上时，S△APE＝S△APB+S△EPB＝3x+＝3+＝4．综合以上可得，△APE的面积为2或4．。

2013年学业考试十二校联考数学模拟试卷和答案

2013年学业考试十二校联考数学模拟试卷试题卷考生须知： 2013.5.281．全卷共三大题，24小题，满分为 120分，考试时间120分钟．2．全卷分卷Ⅰ（选择题）和卷Ⅱ（非选择题）两部分，全部在答题纸上作答，卷Ⅰ的答案必须用2B 铅笔填涂；卷Ⅱ的答案必须用黑色字迹钢笔或签字笔答在答题纸的相应位置上．3．请用黑色字迹钢笔或签字笔在答题纸规定位置上填写姓名、考号．4．作图时，可先使用2B 铅笔，确定后必须使用黑色字迹的钢笔或签字笔描黑．5.本次考试不得使用计算器.卷Ⅰ说明：本卷共有1大题，10小题，共30分.请用2B 铅笔在答题纸上将你认为正确的选项对应的小方框涂黑、涂满.一、选择题（本大题有10小题,每小题3分,共30分）1.当1=x 时，代数式12+x 的值是A ．1B ．2C ．3 D.42.保护水资源，人人有责任，我国是缺水的国家，目前可利用的淡水资源的总量仅为899000亿米3.数899000用科学记数法表示为A ．0.899×106B ．8.99×105C ．8.99×104D ．89.9×1033.下列运算正确的是A ．2x ＋3y ＝5xyB ．a 3–a 2＝aC ．a –(a –b )＝–bD ．(a –1)(a ＋2)＝a 2＋a –24.在图中有两圆的多种位置关系，请你找出还没有的位置关系是A ．外离B ．内含C ．内切D ．外切5.下列图形中，既是中心对称图形又是轴对称图形的是A ．等边三角形B ．平行四边形C ．抛物线D ．双曲线6.在平面直角坐标系中，若点P (3+m ,1-m )点在第四象限，则m 的值可能是A ．2B ．2-C ．3-D ．4-7.在正方形网格中，△ABC 的位置如图所示，则∠A 的正切值为A ．21 B ．31 C ．23 D ．33 8.如图是根据某班40名同学一周的体育锻炼情况绘制的条形统计图.那么关于该班40名同学一周参加体育锻炼时间的说法错误．．的是 A ．极差是3 B ．众数为8 C ．中位数是8 D ．锻炼时间超过8小时的有21人9.已知函数232+-=x x y 与x 轴交点是)0,(),0,(n m ，则)53)(43(22+-+-n n m m 的值是A ．6B ．7C ．8D ．910.如图，OA ⊥OB ，等腰直角三角形CDE 的腰CD 在OB 上，∠ECD =45°，将三角形CDE 绕点C 逆时针旋转75°，点E 的对应点N 恰好落在OA 上，则CD OC 的值为A ．12B ．13C ．22D ．33 卷 Ⅱ说明：本卷共有2大题，14小题，共90分.请用黑色字迹钢笔或签字笔将答案写在答题纸的相应位置上.二、填空题（本题有6小题，每小题4分，共24分）11. 分解因式：2422+-x x = ▲ ．12.定义一种运算，符号为※，规定：当a ＞b 时，a ※b ＝a b ；当a ≤b 时，a ※b ＝a －b ，其他运算符号的意义不变.按上述规定，计算：5※2＝ ▲ .13.初三数学课本上，用―描点法‖画二次函数2y ax bx c =++的图象时，列了如下表格： x …2- 1- 0 1 2 … y … 162- 4- 122- 2- 122- … 根据表格上的信息回答问题：该二次函数2y ax bx c =++在3x =时，y = ▲ ．14.每位同学都能感受到日出时美丽的景色。

2014届上海市十二校高三第二次联考物理试题及答案

一、未分类（每空？分，共？分）1、放射性元素衰变时放出的三种射线，按穿透能力由弱到强的排列顺序是（）（A）γ射线、β射线、α射线（B）β射线、α射线、γ射线（C）α射线、β射线、γ射线（D）α射线、γ射线、β射线2、唐代大诗人李白的“飞流直下三千尺，疑是银河落九天”，描述了庐山瀑布的美景，如果三尺为1m，重力加速度g ＝10m/s2，根据诗中的描述可得水降落到地面时的速度约为（设初速度为零，忽略空气阻力）（）（A）100m/s （B）140m/s （C）200m/s （D）2000m/s3、下列核反应方程及其表述中错误的是（）（A）He＋H®He＋H是原子核的α衰变（B）He＋Al®P＋n 是原子核的人工转变（C）Na ®Mg＋e 是原子核的β衰变（D）U＋n ®Kr＋Ba＋3n是重核的裂变反应4、竖直放置的铁丝框中的肥皂膜，在太阳光的照射下会形成（）（A）黑白相间的水平干涉条纹（B）黑白相间的竖直干涉条纹（C）彩色的水平干涉条纹（D）彩色的竖直干涉条纹5、一个做简谐振动的弹簧振子，周期为T，振幅为A，已知振子从平衡位置第一次运动到x＝处所用的最短时间为t1，从最大的正位移处第一次运动到x＝处所用的最短时间为t2，那么t1与t2的大小关系正确的是（）（A）t1＝t2（B）t1＜t2（C）t1＞t2（D）无法判断6、如图所示，一个质量为m的小滑块静止于倾角为30°的粗糙斜面上，一根轻弹簧一端固定在竖直墙上的P点，另一端系在滑块上，弹簧与竖直方向的夹角为30°，重力加速度为g，则（）（A）滑块可能受到三个力作用（B）弹簧一定处于压缩状态（C）斜面对滑块的支持力大小可能为零（D）斜面对滑块的摩擦力大小可能等于mg7、如图所示，在匀强磁场中，MN、PQ是两根平行的金属导轨，而ab､cd为串接有理想电压表和理想电流表的两根金属棒。

在ab､cd同时以相同速度沿导轨向右运动时，下列结果正确的是（）（A）电压表有读数，电流表有读数（B）电压表无读数，电流表有读数（C）电压表有读数，电流表无读数（D）电压表无读数，电流表无读数8、如果“歼15”战机每次从“辽宁号”航母上起飞的过程中，滑行的距离和牵引力都相同，则（）（A）携带的弹药越多，加速度越大（B）携带的弹药越多，牵引力做功越多（C）携带的弹药越多，滑行的时间越长（D）携带的弹药越多，获得的起飞速度越大9、关于下列四幅示意图的说法中正确的是（）（A）在单分子油膜法测量分子直径d的大小时认为油酸分子是一个挨一个紧密排列的（B）光电效应实验现象说明了光具有波动性（C）α粒子轰击铍产生的粒子流x2是质子流（D）用中子轰击铀核使其发生聚变……，引起的链式反应会释放出巨大的核能10、如图所示为汽车发动机的冷却风扇设计的一个控制电路。

上海市十二校2014届高三下学期第二次联考语文试题(解析版)

上海市十二校2014届高三下学期第二次联考语文试题（解析版）（答题时间150分钟，试题满分150分）一阅读80分(一)阅读下文，完成后面题目。

(17分)爱因斯坦的悼词朱也旷①对于现代物理学，1905年是个有点特殊的年份。

在这年9月的德国《物理学杂志》上，发表了由一位默默无闻的专利审查员爱因斯坦所写的三篇论文。

三篇论文中的任何一篇，都足以使作者享有大物理学家的盛名。

而其中最有名的便是《论动体的电动力学》，此文宣告了相对论的诞生。

②在科学论文的最后，通常会有一大堆的引文索引，但这篇论文的结尾却是光秃秃的。

爱因斯坦没有提及任何同行的工作，只感谢同样默默无闻的专利审查员贝索的“热忱帮助”。

③对于爱因斯坦，贝索是个有点特殊的人物。

尽管终其一生，贝索也许连半个物理学家都算不上，但在当时他却是最理解爱因斯坦的人。

全欧洲都找不到比贝索更好的“思想共振器”，爱因斯坦后来曾这么评价。

④1955年3月15日，贝索在日内瓦病逝。

3月21日，爱因斯坦在给贝索亲属的吊唁信中，写下了如下一段话：“现在，他又比我先行一步，离开了这个奇怪的世界。

但这并不意味着什么。

对于我们笃信物理学的人来说，过去、现在和未来之间的区别只不过是一种幻觉而已，尽管这种幻觉有时还很顽固。

”⑤这是我所见到的最难以忘怀的悼词之一，它是由两种特殊的金属熔合成的合金，一种是高贵的情感，另一种是幽邃的智力。

它既包含着对友人的深厚感情，也包含着深刻的物理学思想。

此前一年，爱因斯坦曾与贝索在信中讨论过“时间箭头”的问题。

爱因斯坦指出，在相对论与量子力学中，均不存在所谓的时间箭头(在牛顿的经典力学中当然也不存在)，亦即基本的物理方程式均不提供过去和未来的区别。

这段悼词应该是源于这次讨论。

⑥但这也是一位聆听着死神脚步声的老人为自己撰写的悼词：他的妻子和妹妹已经走了，他的终生挚友贝索也走了，现在该他了，既然过去和未来并无区别，生与死又何足道哉! 不到一个月，爱因斯坦的病情就恶化了。

上海市十二校2014-2015学年高三第一学期12月联考生物试题含答案

2014学年第一学期十二校联考高三生命科学试卷命题人：曹杨中学唐黎萍审题：大团中学马建芳张堰中学韩君2014年12月本试卷分为第Ⅰ卷和第Ⅱ卷两部分，满分150分。

考试时间120分钟。

注意：请将答案写在答题纸上第Ⅰ卷（共60分）一、选择题（60分。

每题2分，每题只有一个正确答案）1．下列是几种常见的单细胞生物结构示意图。

有关该组生物的叙述错误．．的是………( )A.图中各细胞中都有两种核酸B.具有核膜、核仁的细胞是①②③⑤C.②③所代表的生物一定是异养生物D.③的摄食行为体现了细胞膜具有一定的流动性2．下列有关人体内物质的功能叙述，不正确的是…………………………………………( )A.Na＋和Cl－是决定细胞外液渗透压的主要物质B.自由水在体内的流动有利于细胞的新陈代谢C.胰岛素等蛋白类激素能调节机体的生命活动D.淀粉、糖原和脂肪都是人体细胞内的储能物质3．图I表示在胰岛B细胞中胰岛素原生成胰岛素的过程。

该过程……………………( )A.发生在细胞质内的核糖体上B.离不开内质网和高尔基体的作用C.至少断裂两个肽键生成两分子水D.需水参与，且水中氢全部用于形成—COOH4.病毒性肠胃炎多由“诺如病毒”引起，主要症状有呕吐、腹泻、发热等。

该病毒变异性强，极易造成反复感染。

下列说法错误．．的是……………………………………………………( )A.诺如病毒的变异来源最可能是基因突变B.严重的呕吐、腹泻会导致内环境稳态破坏C.反复感染该病的主要原因是机体免疫功能被损D.机体发热可能是产热过多或散热不畅造成5．下列有关酶的实验设计思路正确的是………………………………………………( )A.利用过氧化氢和过氧化氢酶探究温度对酶活性的影响B.利用淀粉、蔗糖、淀粉酶和碘液验证酶的专一性C.利用过氧化氢、新鲜的猪肝研磨液和氯化铁溶液研究酶的高效性D.利用胃蛋白酶、蛋清和pH 分别为3、7、11的缓冲液验证pH 对酶活性的影响6．下列有关人体内环境的叙述，不正确的是……………………………………………( )A.饥饿时，血液流经肝脏后血糖浓度会增加B.与淋巴相比，血浆中蛋白质的含量较髙C.突触前膜释放的神经递质可在内环境中被分解D.人体非特异性免疫不参与内环境稳态的调节7.下列有关微生物培养的叙述，不正确的是……………………………………………( )A.测定土壤样品中的细菌数目，常用稀释涂布平板法进行菌落计数B.在对微生物进行培养前，需要对微生物和培养基进行灭菌C.酵母菌发酵过程产生的酒精，对其他微生物生长有一定的抑制作用D.分离能分解尿素的细菌，要以尿素作为培养基中唯一的氮源8.科学家通过对大鼠脑神经细胞进行的实验发现，细胞内的一种名为“Rab33a ”的蛋白质会将合成细胞膜的成分运到轴突前端，从而使轴突向前生长．据此分析，下列叙述正确的是………………………………………………………………………( )A.“Rab33a ”是一种分泌蛋白B.“Rab33a ”是一种神经递质C.“Rab33a ”蛋白质促进神经干细胞增殖D.“Rab33a ”蛋白质有助于神经纤维修复9.如果人体组织细胞膜上缺乏胰岛素受体，则可能导致………………………………( )10. 下列对脂蛋白描述正确的是…………………………………………………………( )A.高密度脂蛋白中肯定含有甘油三酯B.乳糜微粒携带的甘油三酯是肝脏中合成的C.脂蛋白由脂肪酸、胆固醇、蛋白质和磷脂构成D.四种脂蛋白中极低密度脂蛋白的密度最小11．下图为在正常和干旱条件下观赏植物蝴蝶兰CO2吸收速率的日变化的曲线图。

长郡双语麓山梅溪湖12校联考八年级上册语文卷及答案

二、阅读：
（一）课内文言文阅读（10分）
三峡郦道元
自三峡七百里中，两岸连山，略无阙处。重岩叠嶂，隐天蔽日，自
非亭午夜分，不见曦月。
至于夏水襄陵，沿溯阻绝。或王命急宣，有时朝发白帝，暮到江
陵，其间千二百里，虽乘奔御风，不以疾也。
春冬之时，则素湍绿潭，回清倒影，绝巘多生怪柏，悬泉瀑布，飞
漱其间，清荣峻茂，良多趣味。
设计了可伸缩的太阳能电池帆板，白天工作时展开，夜晚则收起来，将
仪器设备包在里面。这种“包裹式睡眠”，有助于保护各种仪器不被冻
坏，确保月球车有剩余电力“自主醒来”，重新展开太阳能电池帆板迎
接阳光。
13、下列说法不符合文章意思的是（）（2分）
A、2013年12月15日，中国的第一台探测器——“玉兔号”终于成功登
每至晴初霜旦，林寒涧肃，常有高猿长啸，属引凄异，空谷传响，
哀转久绝。故渔者歌曰：“巴东三峡巫峡长，猿鸣三声泪沾裳。”
10、解释下列加点词语（4分）
（1）略无阙处（
）
（2）沿溯阻绝（）
（3）哀转久绝（
）
（4）其间千二百里（）
11、翻译下列句子（4分）
（1）虽乘奔御风，不以疾也。（2）清荣峻茂，良多趣味。 12、回答问题：三峡的秋景有怎样的特点？作者是如何表现这一特点的？（2分）
②在林的另一端，有一条莹洁的小河。
③水平如镜，水上有独木舟静静地横着。
④如镜的水面，静静地横着一只独木舟。
⑤绿得很浓很浓的树木的两岸郁郁葱葱。
⑥两岸的树木郁郁葱葱，绿得很浓。
A、①③⑥
B、②③⑥ C、①④⑤
D、②④⑤
6、综合性学习（6分）为丰富校园生活，陶冶学生情操，学校特举办第五届校园文化艺术