河南省扶沟县包屯高级中学2015-2016学年高二上学期第二次段考(期中)化学试题
河南省扶沟县包屯高中2015-2016学年高一上学期第二次段考(期中)政治试卷

包屯高中2015-2016学年度上期期中考试高一政治试题学校_________ 原班级______ 姓名__________考场号考号____________一、单项选择题(本大题共35小题,每题2分共70分)(下列各题的四个选项中,只有一个最符合题意。
)1、某市书法爱好者在春节前夕举行“献爱心,赠春联”活动。
市民不管捐赠多少,都可以获得一幅春联,而捐赠的钱则全部交给红十字会。
这些春联()A.是商品,因为它耗费了书法爱好者的劳动B.是商品,因为它是市民捐赠后获得的C.不是商品,因为它不具有使用价值D.不是商品,因为它不是商品交换2、2015年元旦前,一消费者在商场打折优惠活动中用2600元购买到一台标价为4000元的数码相机。
在这里货币执行的职能是()A.价值尺度和支付手段B.流通手段和价值尺度C.流通手段和支付手段D.价值尺度和贮藏手段3、2015年8月8日,小王花了4000元人民币给他的母亲买了一枚纯金戒指。
这4000元人民币()①是一般等价物②是这枚纯金戒指的价格③充当了商品交换的媒介④是代表现实的货币A.①②③B.①②④C.①③④D.②③④4、下列各项中,属于在经济往来结算中经常使用的信用工具是()①信用卡⑵支票③汇票④股票A.①②B.①②③C.②③④D.①③④5、中国人民银行外汇牌价显示:2013年1月4日,100美元兑换628.91元人民币;2014年5月1日,100美元兑换619.65元。
这表明()A.人民币汇率跌落,美元贬值B.人民币汇率升高,美元升值C. 美元汇率升高,人民币贬值D. 美元汇率跌落,人民币升值6、人民币升值对我国居民生活可能产生的有利影响是()A.有利于企业扩大进口B.有利于降低出境旅游的成本C.有利于扩大就业、提高物价D.有利于使我国外汇储备增值7、价格变动会引起需求量变动。
在日常生活中,价格变动对需求量影响较小的一组商品是()A.电视机、食用油、禽蛋B.蔬菜、米面、日用调味品C.金银首饰、液化气、家用摄像机D.海鲜产品、电脑、轿车8、由于冬季蔬菜供不应求,价格较高,所以农民主动建大棚生产蔬菜,及时解决了冬季“吃菜难”的问题。
【历史】河南省扶沟县包屯高级中学2015-2016学年高一上学期第二次段考(期中)试题

包屯高中2015—2016学年度高一上期第二次段考历史试题一、单项选择题(本题35小题,共70分,请把答案填涂在答题卡上)1、《荀子·富国》载:“故天子朱裷衣冕,诸侯玄裷衣冕,大夫裨冕,士皮弁服。
”与这一现象直接相关的政治制度是A.分封制B.宗法制C.郡县制D.封建礼制2、新版电视剧《红楼梦》中有“宝玉抢读贾环四不象灯谜”的场景。
贾宝玉和贾环(宝玉之弟,为贾政的妾室所生)是同父异母的兄弟,但在剧中两人的地位却有天壤之别。
从传统观念上看,导致两人地位悬殊的主要原因是A.分封制的影响B.个人素质的差异C.宗法制的影响D.封建家长的喜好3、周武王灭商后,封弟弟召公奭于燕。
下列说法正确的是A.召公奭领有燕国土地和人口B.召公奭在周王室中属于大宗C.周王可在燕国直接任免官吏D.燕国物产全部归召公奭所有4、“新皇帝……废除了所有的封建国家和王国,将广阔的国土划分为若干行政区,每一行政区都配备一批由中央政府任命,并向中央政府负责的官员。
”这表明“新皇帝”的重大举措是A.建立皇帝制度B.废分封,立郡县C.设立三公九卿D.统一货币、度量衡5、西汉初年,地方推行封国与郡县并行制,但封国因势力增强对抗中央。
汉武帝于公元前140年即位,为限制封国势力膨胀,加强中央集权,他采取的措施是A.颁布“推恩令”B.在地方设节度使C.在地方设通判D.设立行省6、钱穆在《中国历代政治得失》中指出:“元代的行中书省,就是一个行动的中央政府,宰相府的派出所,分驻在这个地方来管事。
如是则地方绝无权,权只在中央。
元代是有中央无地方的,中国只是其征服地,像英国的香港。
”此言论反映的实质是A.元代中央最高行政机关是行中书省B.行省制度使地方行政机构形同虚设C.元代通过行省制度大大加强了中央集权D.元代中央政府与地方的矛盾十分尖锐7、有史学家认为:从秦汉起,官僚体制就是中国制度的核心问题,而这个核心问题又可以分成两个大的子问题,一是官僚的选拔问题,二是官僚体系内部的权力制衡。
河南省扶沟县包屯高级中学高三上学期第二次段考(期中)地理试题Word版含答案

2015-2016学年度上期高三期中考试地理试卷一、单项选择题(每题1.5分,共60分)南京青奥会,于2014年8月16日20时在中国南京开幕,8月28日结束。
南京青奥会是继北京奥运会后中国的又一个重大奥运赛事。
图为“太阳直射点在地球表面移动轨迹示意图”。
结合回答下面1-2小题。
1. 南京青奥会期间时,下列说法错误的是( )A. 北京的正午太阳高度比上海大B. 地球公转速度越来越快C. 郑州市昼渐短,夜渐长D. 哈尔滨昼长比海口长2. 住在美国旧金山的王先生要赶回来参加开幕式,飞机飞行约11小时后王先生于北京时间8月16日18点到达南京,请问王先生在旧金山(120︒W)是当地时间几点起飞的?( )A. 8月16日2点B. 8月15日15点C. 8月16日7点D. 8月15日18点下图中K岛于1983年火山爆发,植被消失殆尽。
1987年,该岛上已有64种植物生长旺盛。
据研究,百年之内该岛上的天然植被就可以恢复。
据此完成3-4问题。
3. K岛天然植被类型属于( )A. 热带雨林B. 热带草原C. 亚热带常绿硬叶林D. 亚热带常绿阔叶林4. 与相同植被类型的大陆地区相比,K岛植被恢复迅速的独特条件是( )A. 海拔高B. 种源丰富C. 火山灰深厚D. 光照充足5.下图为某区域地质剖面示意图。
图中甲地层褶皱后,该区域先后发生了A.沉积作用、侵蚀作用、岩浆侵入 B.岩浆侵入、侵蚀作用、沉积作用c.岩浆侵入、沉积作用、侵蚀作用 D.侵蚀作用、沉积作用、岩浆侵入图a、图b分别是“某两个大洲大陆的地形剖面图”,读图完成下列6-8题。
6. 图中表示安第斯山脉的数字是 ( )A. ①B. ②C. ③D. ④7. 流经山脉①西侧的洋流是 ( )A. 加利福尼亚寒流B. 北太平洋暖流C. 秘鲁寒流D. 本格拉寒流8. 能反映③山脉形成的是下列哪幅图( )人类活动会导致某些自然要素的变化,进而带动其他要素的变化,其中水是比较容易受人类干扰的自然要素。
河南省扶沟县包屯高中2015-2016学年高二上学期第二次段考(期中)数学试卷

包屯高中2015-2016学年度上期高二期中数学试卷一、选择题(每小题5分共60分)1.在等差数列{a n }中,若,23=a ,85=a ,则9a 等于 ( ) A .16 B .18 C .20 D .22 2.不等式13x<等价于A .103x <<B .103x x ><或C .13x > D .0x <3.已知点),(y x P 在直线12=+y x 上运动,则yx42+的最小值是A .2B .2C .22D .424.与曲线2212449x y +=共焦点,而与曲线2213664x y -=共渐近线的双曲线方程为A .191622=-y xB .191622=-x yC .116922=-x yD .116922=-y x5.已知命题p x R x p ⌝>+∈∀则,012,:2是 ( )A .012,2≤+∈∀x R x B .012,2>+∈∃x R xC .012,2<+∈∃x R xD. 012,2≤+∈∃x R x6. 若互不相等的实数a 、b 、c 成等差数列, c 、a 、b 成等比数列,且a +3b +c =10, 则a 等于A .4B .2C .-2D .-47.若110,a b <<,则下列不等式(1)a b ab +<,(2)a b >,(3)a b <,(4)2b a a b+>中,正确的有( )A .1个B .2个C .3个D .4个8、在ABC ∆中,60,2,A AB =︒=且ABC S ∆=,则BC=( )A B .3 C D .79、设:11p x x <->或; :21q x x <->或,则p q ⌝⌝是的( ) A .充分不必要条件 B .必要不充分条件 C .充要条件 D .既充分也不必要条件10.已知双曲线x 2a 2-y 2b 2=1(a >0,b >0)的右焦点为F ,若过点F 且倾斜角为60°的直线与双曲线的右支有且只有一个交点,则此双曲线的离心率的取值范围是( )A .(1,2]B .(1,2)C .[2,+∞)D .(2,+∞)11.若方程2210ax x ++=至少有一个负的实根,则a 的取值范围是( )A .1≤aB .1a <C .01≤a <D .01≤a < 或0a <12.已知F 1、F 2的椭圆)0(12222>>=+b a by a x 的焦点,M 为椭圆上一点,MF 1垂直于x 轴,且,6021︒=∠MF F 则椭圆的离心率为( )A .33B .23 C .21 D .22 二.填空题,20分13. 双曲线16422=-y x 的焦点坐标是_________________.14. 设等差数列{}n a 的公差d ≠0,又139,,a a a 成等比数列,则1392410a a a a a a ++=++15. .在ABC ∆中,若()C a A c b cos cos 3=-,则=A cos .16.有下列命题:①双曲线192522=-y x 与椭圆13522=+y x 有相同的焦点;②“-21<x <0”是“2x 2-5x -3<0”必要不充分条件;③若a 、b 共线,则a 、b所在的直线平行;④等轴双曲线的离心率是错误!未找到引用源。
河南省扶沟县包屯高中2015-2016学年高二上学期第二次段考(期中)历史试卷剖析

2015-2016学年度上期高二历史期中考试试题一、选择题(本大题共35小题,每小题2分,共70分)1 这是一位生活于公元前4世纪前后的伟大的思想家,后成为仅次于孔子的一代儒学宗师。
他的思想中一个重要的内容是( )A.克己复礼B.仁者无敌C.天人感应D.格物致知2 温家宝总理曾说:“民安了国才能安,国安了领导人的心才能安。
”此语体现了“民至上”的思想。
古代先哲中首次明确提出类似思想的是 ( )A.孔子 B.孟子 C.庄子 D.韩非子3 (2013.湖南永州一模)哈佛大学杜维明教授在《儒学创新的契机》一书中指出:东亚的发展“深受西欧和美国的影响,但却不只是西方发展模式的翻版,(东亚各国)都和传统有血肉相连的关系。
……(在东亚发展过程中)儒家可发挥积极的作用。
”材料表明 ( )A.儒家学说始终对东亚文明起决定作用B.儒家学说难以与经济全球化的趋势融合C.西方发展模式必须以儒家思想为基础D.东亚发展既汲取西方文明,又继承儒家文明4 孟子日:“老而无妻日鳏,老而无夫日寡,老而无子日独,幼而无父日孤。
此四者,天下之穷民而无告者。
文王发政施仁,必先斯四者。
”材料所体现的政治思想是( )A.礼治 B.仁爱 C.仁政 D.兼爱5 战国时期诸子百家的思想观点实质上反映了战国时期,流行“得士者存,失士者亡”的说法。
这主要说明了 ( )A.各国都重视发展军事力量B.尊重知识、尊重人才成为社会风尚C.新兴知识分子阶层受到统治者的重用D.代表新兴地主阶级利益的知识分子掌握国家政权6 孔子说:“天何言哉?四时行焉,百物生焉,天何言哉?”老子说:“人法地,地法天,天法道,道法自然。
”韩非子说:“唯夫与天地之剖判也俱生,至天地之消散也不死不衰者谓常。
”从以上儒家、道家、法家言论来推断,三家都 ( )A.针对先秦的社会现状提出了共同的政治主张B.认为自然界的存在不以人的意志为转移C.表现出人对自然及其规律的尊崇D.认为自然是可以认识的7 . 儒家经典强调:“上好礼,则民莫敢不敬;上好义,则民莫敢不服;上好信,则民莫敢不用情。
河南省扶沟县高级中学2015-2016学年高二上学期开学考试化学试卷 Word版含答案.pdf

13.除去甲烷气体中含有的少量乙A.蒸馏水
B.溴水
C.浓硫酸
D.酸性KMnO4溶液
14.分子式为C4H9Cl 的同分异构体共有(不考虑立体异构)
()
A.4
B.5
C.6
D.7
15.下列关于有机物的说法正确的是
()
①C5H12有2种同分异构体 ②甲烷和氯气光照条件下可制得纯净的一氯甲烷 ③乙烯、聚氯乙烯均能使溴的
感,同学们每天用“84”消毒液(NaClO溶液)消毒,下列说法不正确的是
()
A.NaClO溶液的消毒原理是使蛋白质变性
B.1 mol Cl2与足量NaOH溶液反应转移2 mol电子
C.NaClO溶液的漂白原理与Na2O2相同,与SO2不同
D.“84”消毒液与“洁厕灵”(盐酸)混合使用可能会产生有毒的氯气
4.本卷可能用到的相对原子质量:H-1 C-12 N-14 O-16 Na-23 Mg-24
Al-27 S-32 Cl-35.5 Zn-65 Fe-56 Cu-64 Ag-108
一、选择题(每题只有一个正确选项,每小题3分,共54分)
1.设NA为阿伏伽德罗常数的值,下列说法正确的是
()
R>M;④原子半径X小于Y的同一主族的两种元素,若X(OH)n是强碱,则Y(OH)n也是强碱;⑤除第一周期外,第n周期的最
后一种金属元素位于第n主族A.①②④ B.①③⑤ C.②③④ D.②④⑤
7.原电池反应是释放能量的氧化还原反应,下列可设计成原电池的化学反应是( )
A.H2O (l)+CaO(s) =Ca(OH)2(s)
11.下列金属中,通常采用热还原法冶炼的是
()
A.Na B.Al
C.Fe D.Ag
河南省扶沟县高级中学2015-2016学年高二上学期开学考试英语试题 Word版含答案

扶沟高中2015-2016学年度(上)高二开学考试英语试题第一部分听力略第二部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下面短文,从短文后各题所给的四个选项(A、B、C和D)中,选出可以填入空白处的最佳选项,并在答题卡上将该项涂黑。
AAre you a saver or a spender?"A penny saved is a penny earned." This old saying calls attention to the wisdom of saving money. "________________" is another way to talk about saving for the future.People who hate to spend money are known as "tightwads," while those who like to get the most value for their money are called "thrifty." A thrifty person is different from a "spendthrift." A spendthrift is someone who spends wastefully. People like that are often said to spend money "like a drunken sailor" or "like there's no tomorrow."In the United States, people who want to start a savings account have different choices of where to put their money. These include banks and credit unions. Credit unions are cooperatives for people who have some kind of connection. For example, the members might work for a university or a government agency. Most credit unions are nonprofit organizations.Credit unions, banks and other financial institutions pay interest on savings accounts. But the interest rates are low. Certificates of deposit(存款证)pay higher returns. With a certificate of deposit, or CD, a person agrees not to withdraw the money for a certain period of time. This term could be anywhere from a few months to several years. Longer terms, and larger amounts, pay higher interest. People can withdraw their money early but they have to pay a fine.In a number of countries, people have been saving less over the years. The Organization for Economic Cooperation and Development is a group of thirty-four countries. The OECD says in 1990, Americans had a household savings rate of seven percent. This year, that rate is expected to be a little more than four percent and many European countries have higher rates like the UK and France , but Americans save more than families in countries like Japan and South Korea. 21.Which of the following proverbs can be filled in the blank in Paragraph 2?A.Health is wealth.B.Money is a good servant but a bad masterC.Put money away for a rainy day.D.Money doesn’t grow on trees.22.If you have $10,000, which of the following may help you get higher interest ?A.Choose certificates of deposit for one year.B.Put the money in banks for one year.C.Put the money in credit unions for one year.D.Choose certificates of deposit for one year but withdraw the money ahead of time. 23.What does the passage mainly talk about ?A.Different choices of putting money away in the US.B.The importance of saving money.C.How to put money into banks.D.The household savings rate in the US.BEverybody needs bloodHave you ever seen buses on the street for donating blood? Medical workers on board collect blood from volunteers. The blood is then stored up and given to people who have lost a large amount of it due to accidents or diseases.Blood is one of the most important substances (物质) supporting our lives. But for now, the only way we can get more of it is through donation. And donated blood has its own problems. First of all, certain blood types are extremely rare. Type O negative blood (O-), for example, only exists in 7 percent of people, according to Sunday Times. There are fewer donors and therefore there isn’t enough of this type of blood for everybody who needs it. In addition, donated blood comes from various people, which means that it has to be examined carefully for disease such as hepatitis (肝炎) and HIV to make sure that it’s safe for transfusion.This is why scientists all over the world have been trying to make blood in labs. And now, someone finally succeeded—Marc Turner at the Scottish National Blood Transfusion Service has produced blood fit for transfusion, reported Forbes.Unlike many other scientists, who have tried to make blood substitutes by mixing up different ingredients together, Turner chose to grow blood directly from human stem cells (干细胞). He developed a special technique to create a chemical environment similar to that in our bone marrow (骨髓). This environment encourages stem cells to develop fully into red blood cell.According to Turner, his version of artificial blood is unlikely to contain disease viruses or produce side effects. And the best part is that what he managed to produce was type O- blood. Not only is it a rare blood type, it’s also a universal type, which means it can be transfused into any patient.The new blood is scheduled for human tests in 2016. However, Turner stressed that the new study should not be taken as a signal for people to stop donating blood because it could be another 20 years before the artificial blood can be manufactured on a large scale. “It is one thing to bake a cake and another thing to bake a cake 100 times the size,” said Turner. “It’s not just a matter of putting in 100 times the ingredients.”24.According to the text, a potential danger of blood transfusion is that_____.A. it is impossible to store up large amounts of bloodB. blood transfusion may lead to some terrible infectionsC. it is very hard to find matches for certain blood typesD. blood transfusion often leads to serious side effects25.The study Marc Turner did is different from those of many other scientists in that _____.A. he grew artificial blood using human stem cellsB. he was able to discover the special function of type O- bloodC. he produced the first artificial blood in the worldD. he used special ingredients to produce artificial blood cells26.We can know from the text that__________.A. people with type O- blood can receive blood transfusion from anyoneB. the practice of blood transfusion will end in 20 yearsC. the new blood produced by Turner has been experimented on human beingsD. the artificial blood produced by Turner will be a safe and universal type27. Which of the following words best describes Turner’s attitude towards the application of hisartificial blood?A. Pessimistic.B. Doubtful.C. Cautious.D. Uninterested.CAs we know, there are differences between western culture and Chinese culture. We can see differences when we pay attention to the way words are used. Let’s look at the words about animals and plants. Most expressions in Chinese about the dog, for example, “a homeless dog”, “a mad dog”, “a running dog”and “a dog catching a mouse”, have negative meanings. But in western countries, dogs are thought to be honest and good friends of humans. In English, people use the dog to describe positive actions. For example, “you are a lucky dog” means you are a lucky person. And “every dog has its day”means each person has good luck sometimes. To describe a person’s serious illness, they say “sick as a dog”. The word “dog-tired” means very tired. However, Chinese love cats very much. But in western culture, “cat” is often used to describe a woman who is cruel. There are many other examples of how “cat” is used differently as well.The rose is regarded as a symbol of love in both China and some western countries. People think the rose stands for love, peace, courage and friendship. And the rose is the national flower of England, America and many other countries.The words about plants and animals are used in positive or negative ways in different cultures. We can learn about many differences in cultures by comparing how some words are used.28. “Every dog has its day.” means “_______”.A. Everybody in the world is lucky.B. Each person lives his own way of life.C. If one works hard, he’s sure to succeed.D. Everybody has a time in life to be lucky.29 Western people usually use “cat” to refer to “_______”.A. a tired personB. a brave manC. a homeless personD. an unkind woman30. Which of the following is true according to the passage?A. Words show differences in culture.B. Chinese people prefer dogs to cats.C. Western people think cats to be good friends.D. Rose is the national flower of all western countries.31. What’s the best title for the passage?A. Negative and Positive wordsB. Different Countries Have Different CultureC. Rose Means the Same In Chinese and EnglishD. What Dog and Cat Mean in English and ChineseDA gentle breeze blew through Jenny’s hair. The golden red sun was setting. She was on the beach, looking up the ball. She was amazed by its color.The atmosphere relaxed her. After all she had been through, this is what she needed.” It’s getting late,’’ she thought,” I must go home, my parents will be wondering where I am.”She wondered how her parents would react, when she got home after the three days she was missing. It was getting dark now, the sun had set a few minutes before and it was getting cold too. She wished she had her favorite sweater on. She imagined having it with her. This thought dissipated when she finally saw her front door. It seemed different. Nobody had taken care of the outside garden for a few days. She was shocked: Her father was usually so strict about keeping everything clean and tidy, and now … It all seemed deserted. She couldn’t understand what was going on.She entered the house. First, she went into the kitchen and saw a note by her father . It said;” Dear Ellen, there is some coffee ready, I went looking.” Entering her parents room she noticed he r mother was lying on the bed, sleeping. Her face looked so tried, as if she hadn’t slept for days.Jenny would have wanted to wake her up but she looked too tried. So Jenny just fell asleep beside her. When Jenny woke up something was different… she wasn’t in her mother’ room and she wasn’t wearing the old clothes she ran away in. She was in her bed in her parents.It felt so good being back home. Suddenly she heard a voice. “Are you feeling better now, dear? You know you got us very, very scared.”32.What can be said about Jenny’ f father?A.He was too strict with her daughter.B. He was a careless man.C. He didn’t love his wife in fact.D. He loved Jenny very much.33.What was the most probable reason why nobody took care of the garden for a few days?A.Henny’s parents were too worried about her to do it .B.Jenny’s parents were too lazy to do it .C.Jenny’s parent were too busy to do it .D.There was nobody at home during the time .34.The underlined word “dissipated” in paragraph 3 can be re placed be ______A. spreadB. came trueC. appearedD. disappeared35.The best title for the passage can be “_______”.A. Fleeing homeB.A warm homeC. Back homeD. A cold home第二节((共5小题;每小题2分,满分10分)You should make thorough plans before you do a camping trip. Just follow these simple camping suggestions to make trip safe and rewarding.Selecting a suitable tent36 When determining the size of your tent , you should take into account the number of campers as well as the camping equipment necessary for your trip. There should be enough room in the tent for the camping equipment 37 .Importance of foodWhile camping, you will need enough food to give you enough energy for your outdoor work.38 You should use a two burner stove to do all your cooking. Insist on simple cooking during your trip to reduce cooking time.Enough sleep39 Nights are generally cooler than the days so you need to have enough warm clothes to feel comfortable enough to sleep during the night. When buying a sleeping bag, check that you feel comfortable in it. Extra air mattresses (气垫) may be included in your camping equipment to make your bed more comfortable40 Keep these camping guidelines in mind and make sure you are fully prepared to enjoy your camping trip.A.All campers should have adequate sleep during the night.B.Thus you must have an efficient arrangement for your food preparation.C.The best camping trips are had by those people who prepare the best.D.Take healthy food with you to meet energy demands during your trip.E.The comfort level in a tent determines the success of a camping trip.F.The size is the most important thing you should carefully consider when choosing a tent.G.It will destroy the mood of the entire camping trip if you don’t have a good sleeping bag.第三部分:英语知识运用(共两节,满分45分)第一节:完形填空(共20小题,每小题.1.5分, 满分30分)阅读下面短文,从短文后各题所给的四个选项(A、B、C和D)中,选出可以填入空白处的最佳选项,并在答题卡上将该项涂黑。
河南省扶沟县包屯高级中学2016届高三语文上学期第二次段考(期中)试题

包屯高中2015—2016学年上期期中高三语文试题(考试时间:150分钟试卷满分:150分)本试卷分第Ⅰ卷(阅读题)和第Ⅱ卷(表达题)两部分。
请将全部答案写在答题卡上,答在本试卷上无效。
第Ⅰ卷阅读题(共70分)甲必考题一、现代文阅读(9分,每小题3分)阅读下面的文字,完成1~3题。
汉字危机王小峰中国的书写交流进入键盘划时代只有十几年,任何一个初次接触电脑的人通过简单的学习都能迅速掌握文字输入。
随着电脑的普及,现在很多人写字总是提笔忘字,尤其是经常使用的汉字往往一下想不起来了,这跟他受过高等教育掌握无数信息和知识的身份有点不符。
很多人纷纷惊呼汉字危机来了,拯救汉字刻不容缓。
书写是记忆汉字的最好方式,只有经常书写,才能记住一个字该怎么写。
过去用笔书写汉字基本上是音,形、义同时进行,键盘输入就出现问题了,它不是直接写汉字,而是让你在候选的重码中去选择正确的那个字。
这就是汉字在键盘输入时代面临的一个问题,换句话说,这就是音素文字和语素文字的最大区别。
所有音素文字(英语、德语、法语、西班牙语等)它们只有音和形,而且音形基本统一,打字本身就是书写过程。
我们是拼音解决汉字输入问题,而不是在键盘上打笔画.五笔字型不会让你忘记一个汉字怎么写,但是可能会让你忽略它该怎么读;拼音输入可以让你知道一个字怎么读,却让你慢慢忘记它怎么写。
在信息时代,中国人开始遇到能说能读能输入但可能不会写的问题了。
这也暴露了汉字的自身局限问题。
网络时代屡屡出现新词,人们对“雷”、“囧”这类汉字就赋予新的含义。
从每年出现的网络流行语中不难看出,新的词语越来越多,看上去也越来越没文化含量,继而还可能导致汉语的使用环境和美感越来越差。
网络语言通过互联网的病毒式传播迅速扩散全球,但死得也非常快。
它只是迎合某一类信息某一种情绪在传播的当口被创造出来,并随着这种氛围的消失而慢慢消亡,能留下来的凤毛麟角。
为了提高书写效率,方便学习和交流,开始出现俗字、新字,汉字的数量在不断增加,但却有不断简化的趋势。
河南省扶沟县包屯高中2015-2016学年高二上学期第二次段考(期中)地理试卷

包屯高中2015---2016上期期中考试高二地理一、单项选择题(本题共35小题,每小题2分,共70分)1、当代世界经济的两大发展趋势是:()①区域经济一体化②经济全球化③世界政治多极化④地缘合作与冲突并存A、①②B、②③C、③④D、①④读“我国能源调运图”,回答2—3题:2.图中①②③三条运输路线输送的主要能源分别是()A.煤炭、天然气和水电B.石油、天然气和煤炭C.天然气、石油和水电D.煤炭、石油和天然气3.“西电东送”设想的主要目的是()A.保护西部地区的生态环境B.治理东部地区的大气污染C.解决中东部地区的能源短缺问题D.增加西部地区的河流航运能力读下图,完成4~5题。
4.下图能正确反映珠江三角洲城市发展一般规律的是( )A.① B.② C.③ D.④5.在珠江三角洲城市化发展的第Ⅲ阶段( )A.城市化发展以小城镇为主导B.城乡一体化地带初步形成C.广州和深圳的带动作用减弱D.城市化向核心城市引导下的城市群模式转变6.企业将产品生产的部分或全部原产地转移到其他地区的现象称为产业转移。
我国台湾电子企业生产工厂大量西移至广东东尧等地,其考虑的因素是()①劳动成本②土地成本③科技成本④原料成本A. ②③B. ①②C. ①③D.①④7.下列关于区域发展水平的叙述,正确的是()A.国内生产总值高的地区,一定是发达地区B. 高收入的地区,一定是发达地区C.发达地区人均国民收入一般较高D.第三产业产值比重较高,区域发展水平越低8.20世纪50年代以后,德国鲁尔区一度衰落,其内部原因主要在于( ) A.单一的重型工业结构B.廉价石油的竞争C.环境污染严重D.技术的发展,劳动力需求减少9.德国鲁尔区衰落最为明显的工业部门是( )①机械工业②钢铁工业③化学工业④煤炭工业A.①③ B.②④ C.①④ D.②③10.现在,鲁尔区的很多钢铁企业将高炉建在荷兰海边,再将炼出来的生铁运到鲁尔区炼钢、轧材。
这样做的目的是( )A.就近获得通过荷兰鹿特丹港进口的铁矿石B.荷兰的劳动力成本低C.荷兰海边煤铁资源丰富D.荷兰的炼铁技术更高“微笑曲线”(下图)是台湾宏基公司董事长施振荣先生最早提出的,它起初被用于说明电脑行业不同环节与所实现的附加价值之间的关系,后来被广泛应用于其他领域。
河南省扶沟县包屯高级中学2015-2016学年高一上学期第二次段考(期中)化学试卷.pdf

D.H2 + Cl2
2HCl离子方程式CO32- +2H+ CO2↑ + H2O 中
的CO32- 代表的物质可以是( )
A.CaCO3
B.NaHCO3
C.Na2CO3
D.BaCO3
.下列有关氧化还原反应的叙述中,正确的是( )
A.一定有氧元素参加
______________考号_________________
------------------------------------------------密-----------------------------------封-------------
--------------------------线---------------------------------
D.稀H2SO4能导电,所以稀H2SO4是电解质
1.下列离子方程式书写正确的是( )
A.铁跟稀硫酸反应:2Fe + 6H+ 2Fe3+ + 3H2 ↑
B.:O2- + 2H+ 2Cl-- + H2O
C.碳酸钙与稀盐酸反应: CO32- +2H+ CO2↑ + H2O
D.盐酸与澄清石灰水反应:H+ + OH- H2O
包屯高中2015-2016学年度上期高一期中考试
高一化学试卷
可能用到的相对原子量:H: C:12 N14 O:16 Na:23S:第Ⅰ卷一、选择题(本题包括小题,每小题只有一
个选项符合题意,每小题分共分1、以下是一些常用的危险品标志,装运氢氧化钡溶液的包装箱应贴的图标是( )
【化学】河南省扶沟县包屯高级中学2016届高三上学期第二次段考(期中)化学试题

包屯高中2015—2016学年上期期中考试高三化学试题说明: 1.本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)满分100分,考试时间90分钟。
2.将第Ⅰ卷的答案代表字母填在答案卷的答题表中。
第Ⅰ卷 (选择题,共48分)可能用到的相对原子质量:H-1 C-12 O-16 Mg-24 Al-23 Ca-40 Fe-56一、单项选择题:本题共16小题,每小题3分,共48分。
1.下列实验或生产操作,其中没有新物质生成的是①蛋白质溶液中加入硫酸铵后形成沉淀 ②将饱和氯水滴到蓝色石蕊试纸上 ③二氧化氮经加压凝成无色液体 ④溴水滴入植物油中振荡褪色 ⑤胆矾风化 ⑥除去混在氢氧化铁胶体中的氯化铁A .①②③B .①④⑥C .③⑤D .①⑥2.下列有关NaClO 和NaCl 混合溶液的叙述正确的是A .该溶液中,H +、NH 4+、SO 42-、Br -可以大量共存 B .该溶液中,Ag +、K +、NO 3-、CH 3CHO 不能大量共存 C .向该溶液中滴入少量FeSO 4溶液,反应的离子方程式为:2Fe 2++ClO -+2H +=== Cl -+2Fe 3++H 2O D .向该溶液中加入浓盐酸,每产生22.4LCl 2,转移电子约为6.02×1023个3.甲、乙、丙、丁四种物质,甲、乙、丙含同一种元素。
下列各组物质可按下图转化的是A .①②B .②③C .①④D .③④4.用N A 表示阿伏加德罗常数的值。
下列叙述正确的是A .电解精炼铜时,若转移了N A 个电子,则阳极质量减少32 gB .1molSiO 2中有2N A 个硅氧键C .1 mol FeCl 3跟水反应,完全转化为氢氧化铁胶体后,其中胶体粒子的数目小于N AD .1mol Cl 2与过量的铁反应,转移3N A 个电子5.下列各组物质充分反应后过滤,将滤液加热、蒸干、灼烧至质量不变,最终不能得到纯净物的是A.向漂白粉浊液中通入过量的CO2B.向带有氧化膜的铝片中加入盐酸C.向含有1molCa(HCO3)2的溶液中加入1molNa2O2D.向含有1molKAl(SO4)2的溶液中加入2molBa(OH)26.某实验小组对一含有Al3+的未知溶液进行了如下分析:(1)滴入少量氢氧化钠,无明显变化;(2)继续滴加NaOH溶液,有白色沉淀;(3)滴入过量的氢氧化钠,白色沉淀明显减少。
河南省扶沟县包屯高级中学高三物理上学期第二次段考(

包屯高中2015-2016学年度上期第二次月考试卷高三物理试题考试范围:必修1 2 试卷满分100分 考试时间 90分钟一、选择题(本题共12小题.每小题4分,共48分。
每小题给出的四个选项中,1-8小题只有一个选项正确,9-12小题有多个选项正确,全部选对的得4分,选对但不全的得2分,有错选的得0分。
)1、小球做下列各种运动中,属于匀变速曲线运动的是( )A.自由落体运动B.竖直上抛运动C.斜上抛运动D.匀速圆周运动2、A 和B 两物体在同一直线上运动的v-t 图线如图所示。
已知在第3s 末两个物体在途中相遇,则下列说法正确的是( ) A .两物体从同一地点出发 B .出发时B 在A 前3m 处C .3s 末两个物体相遇后,两物体可能再相遇D .运动过程中B 的加速度大于A 的加速度3、如图所示,小车内有一固定光滑斜面,一个小球通过细绳与车顶相连,小车在水平面上做直线运动,细绳始终保持竖直,关于小球的受力情况,下列说法中正确的是( ) A .若小车静止,绳对小球的拉力可能为零 B .若小车静止,斜面对小球的支持力一定为零 C .若小车向右运动,小球一定受两个力的作用 D .若小车向右运动,小球一定受三个力的作用4、如图所示,一小车上有一个固定的水平横杆,左边有一轻杆与竖直方向成ϑ角与横杆固定,下端连接一小铁球,横杆右边用一根细线吊一小铁球,当小车向右做加速运动时,细线保持与竖直方向成α角,若ϑ≠α,则下列说法正确的是( ) A .轻杆对小球的弹力方向与细线平行 B .轻杆对小球的弹力方向沿着轻杆方向向上C .轻杆对小球的弹力方向既不与细线平行,也不沿着轻杆方向D .小车匀速时,α=ϑ5、如图所示,电梯与水平地面成θ角,一人站在电梯上,电梯从静止开始匀加速上升,到达一定速度后再匀速上升.若以N F 表示水平梯板对人的支持力,G 为人受到的重力,f F 为电梯对人的静摩擦力,则下列结论正确的是( ). A .加速过程中f F ≠0,N F 、f F 、G 都做功 B .加速过程中f F ≠0,N F 不做功 C .加速过程中f F =0,N F 、G 都做功 D .匀速过程中f F =0,N F 、G 都不做功6、“嫦娥二号”是我国月球探测第二期工程的先导星.若测得“嫦娥二号”在月球(可视为密度均匀的球体)表面附近圆形轨道运行的周期为T ,已知引力常量为G ,半径为R 的球体体积公式V =43πR 3,则可估算月球的( ).A .半径B .质量C .密度D .自转周期7、质量m =4 kg 的质点静止在光滑水平面上的直角坐标系的原点O 处,先用沿x 轴正方θα向的力F1=8 N作用了2 s,然后撤去F1;再用沿y轴正方向的力F2=24 N作用了1 s.则质点在这3 s内的轨迹是( ).8、位于水平面上的物体在水平恒力F1作用下,做速度为v1的匀速运动;若作用力变为斜向上的恒力F2,物体做速度为v2的匀速运动,且F1与F2功率相同。
河南省周口市扶沟县包屯高中2015-2016学年高二上学期期中物理试卷【解析版】

2015-2016学年河南省周口市扶沟县包屯高中高二(上)期中物理试卷一、选择题:(1-12题为单项选择题,每小题3分;13-15题为多项选择题,每小题3分.本题共15小题,共48分.)1.关于点电荷的说法,正确的是( )A.只有体积很小的电荷,才能作为点电荷B.体积很大的电荷,一定不能作为点电荷C.点电荷一定是带电量很小的电荷D.两个带电的金属小球,不一定能将它们作为电荷集中在球心的点电荷处理2.小华有一次不小心购买了盗版的物理参考书,做练习时,他发现有一个关键数字看不清,拿来问老师,如果你是老师,你认为可能是下列几个数字中的那一个( )A.6.2×10﹣19C B.6.4×10﹣19C C.6.6×10﹣19C D.6.8×10﹣19C3.下列关于物体带电的说法,正确的是( )A.静电感应不是创造电荷,只是电荷从物体的一部分转移到另外一部分B.摩擦起电前,两物体都不带电,说明两物体内都没有电荷C.摩擦起电时,一个物体得到一些电子而带正电,另一物体失去一些电子而带负电D.一个带电体跟一个不带电物体接触,两物体可能带上异种电荷4.对于库仑定律,下面说法中正确的是( )A.凡计算两个点电荷间的相互作用力,就可以使用公式F=kB.两个带电小球即使相距非常近,也能用库仑定律C.相互作用的两个点电荷,不论它们电量是否相同,它们之间的库仑力大小一定相等D.两个点电荷的电量各减为原来的一半,它们之间的距离保持不变,则它们之间库存仑力减为原来的一半5.由电场强度的定义式E=可知,在电场中的同一点( )A.电场强度E跟F成正比,跟q成反比B.无论检验电荷所带的电量如何变化,始终不变C.不同电荷在电场中某点所受的电场力大小不同,该点的电场强度在不断改变D.一个不带电的小球在P点受到的电场力为零,则P点的场强一定为零6.如图所示,当滑动变阻器的滑动触头向左移时,灯泡L1、L2、L3的亮度将( )A.都变亮B.都变暗C.L1、L2变亮,L3变暗D.L1、L3变亮,L2变暗7.如图所示,有三个电阻,已知R l:R2:R3=1:3:6,则电路工作时,电压U l:U2为( )A.1:6 B.1:9 C.1:3 D.1:28.如图所示,因线路故障,按通K时,灯L1和L2均不亮,用电压表测得U ab=0,U bc=0,U cd=4V.由此可知开路处为( )A.灯L1B.灯L2C.变阻器D.不能确定9.对电容C=,以下说法正确的是( )A.电容器充电荷量越大,电容增加越大B.电容器的电容跟它两极板所加电压成反比C.电容器的电容越大,所带电荷量就越多D.对于确定的电容器,它所充的电荷量跟它两极板间所加电压的比值保持不变10.电路中有一段金属丝长为L,电阻为R,要使电阻变为4R,下列可行的方法是( ) A.将金属丝拉长至2LB.将金属丝两端的电压提高到原来的4倍C.将金属丝对折后拧成一股D.将金属丝拉长至4L11.如今家用电器越来越多,它们在待机状态下也会耗电.为了节约电能和用电安全,你将选择( )①切断长期不使用的空调机的电源②电视机在不使用时,可以不断开电源③合理使用节能灯具④尽量避免同时使用大功率家用电器.A.①②③ B.②③④ C.①③④ D.①②④12.2011年8月13日强雷电袭击绍兴,威力之猛近期少有.雷暴天气和雷击事件,引起了绍兴市委、市政府的高度重视,要求有关部门加大防雷避雷知识的宣传,提高广大人民群众的防范意识,做好防雷工作,保障人民群众安全.假如在户外我们遭遇雷电,下列防雷措施可行的是( )①在大树下避雷雨②停留在山顶、山脊的凉亭等地方避雷雨③切勿站立于楼顶上或接近导电性高的物体④在空旷地带,最好关掉手机电源.A.①③B.②③C.①④D.③④13.如图是某一点电荷的电场线分布图.下列表述正确的是( )A.a点的电势低于b点的电势B.该点电荷带负电C.a点和b点电场强度的方向相同D.a点的电场强度大于b点的电场强度14.有一段直导线长1cm,通以5A电流.当把导线置于磁场中某点时,受到的磁场力为0.1N,则该点磁感应强度B的值可能为( )A.1 T B.1.5 T C.2 T D.2.5 T15.不考虑温度对电阻的影响,对一个“220V,40W”的灯泡,下列说法正确的是( ) A.接在110 V的电路上时的功率为20 WB.接在110 V的电路上时的功率为10 WC.接在440 V的电路上时的功率为160 WD.接在220 V的电路上时的功率为40 W二、实验题(每空2分,画图4分,共18分.)16.在“测定金属丝电阻率”的实验中,需要测出其长度L、直径d和电阻R.(1)用螺旋测微器测金属丝直径时读数如图甲,则金属丝的直径为__________mm.(2)若用图乙测金属丝的电阻,则测量结果将比真实值__________.(选填“偏大”或“偏小”)(3)用电压表和电流表测金属丝的电压和电流时读数如图丙,则电压表的读数为__________V,电流表的读数为__________A.17.在“测定电源的电动势和内阻”的实验中,已连接好部分实验电路.(1)按如图甲所示的实验电路,把图乙中剩余的电路连接起来.(2)在图乙的电路中,为避免烧坏电表,闭合开关前,滑动变阻器的滑片应置于__________端(选填“A”或“B”).(3)图丙是根据实验数据作出的U﹣I图象,由图可知,电源的电动势E=__________ V,内阻r=__________Ω三、计算题:(18题10分,19题12分,20题12分,共34分.)18.如图所示,匀强电场的场强E=1.2×102N/C,方向水平向右,一点电荷q=4×10﹣8C沿半径为R=20cm的圆周,从A运动到B点,已知∠AOB=90°,求(1)这一过程电场力做多少功?是正功还是负功?(2)A、B两点间的电势差U AB为多大?19.如图所示,电源电动势E=14V,内电阻r=1Ω,小灯泡标有“2V 4W”字样,电动机M 的内阻r′=0.5Ω,当滑动变阻器的阻值R调到1Ω时,电灯和电动机均能正常工作.求:(1)电动机两端的电压;(2)电动机输出的机械功率;(3)电路消耗的总功率.20.磁场中放一与磁场方向垂直的电流元,通入的电流是2.5A,导线长1cm,它受到的安培力为5×10﹣2 N.问:(1)这个位置的磁感应强度是多大?(2)如果把通电导线中的电流增大到5A时,这一点的磁感应强度是多大?(3)如果通电导线在磁场中某处不受磁场力,是否可以肯定这里没有磁场?2015-2016学年河南省周口市扶沟县包屯高中高二(上)期中物理试卷一、选择题:(1-12题为单项选择题,每小题3分;13-15题为多项选择题,每小题3分.本题共15小题,共48分.)1.关于点电荷的说法,正确的是( )A.只有体积很小的电荷,才能作为点电荷B.体积很大的电荷,一定不能作为点电荷C.点电荷一定是带电量很小的电荷D.两个带电的金属小球,不一定能将它们作为电荷集中在球心的点电荷处理【考点】元电荷、点电荷.【专题】电场力与电势的性质专题.【分析】物理学上把本身的线度比相互之间的距离小得多的带电体简化为一个点,叫做点电荷.同一个电荷能否看作点电荷,不仅和带电体本身有关,还取决于问题的性质和精度的要求,即需要具体问题具体分析.【解答】解:A、体积很小的带电体,如果相对于研究的问题,体积不能忽略不计,将其简化为点产生的误差较大,那么就不能简化为点,故A错误;B、体积较大的带电体,如果相对于研究的问题,体积可以忽略不计,将其简化为点产生的误差较小,那么可以简化为点电荷,故B错误;C、点电荷是将物体简化为点,带电物体能否简化为点关键是看物体的大小对于研究的问题能否忽略不计,而不是看电荷量的大小,故C错误;D、当电荷在球上均匀分布时,可以将其看成是电荷全部集中于球心的点电荷,否则会产生较大的误差,故D正确;故选D.【点评】如果在研究的问题中,带电体的形状、大小以及电荷分布可以忽略不计,即可将它看作是一个几何点,则这样的带电体就是点电荷.一个实际的带电体能否看作点电荷,不仅和带电体本身有关,还取决于问题的性质和精度的要求,即需要具体问题具体分析.2.小华有一次不小心购买了盗版的物理参考书,做练习时,他发现有一个关键数字看不清,拿来问老师,如果你是老师,你认为可能是下列几个数字中的那一个( )A.6.2×10﹣19C B.6.4×10﹣19C C.6.6×10﹣19C D.6.8×10﹣19C【考点】元电荷、点电荷.【专题】电场力与电势的性质专题.【分析】元电荷又称“基本电量”,在各种带电微粒中,电子电荷量的大小是最小的,人们把最小电荷叫做元电荷,常用符号e表示,任何带电体所带电荷都是e的整数倍,据此可正确解答【解答】解:电子电荷量的大小是最小的,人们把最小电荷叫做元电荷,任何带电体所带电荷都是e的整数倍,因此该带电量为电子电量e=1.6×10﹣19C的整数倍,将四个选项中的电量除以电子电量得数为整数倍的便是可能正确的数字,故ACD错误,B正确.故选:B.【点评】本题是基础的题目,考查的就是学生对基本知识的应用情况,平时要注意提高应用所学知识解决实际问题的能力.3.下列关于物体带电的说法,正确的是( )A.静电感应不是创造电荷,只是电荷从物体的一部分转移到另外一部分B.摩擦起电前,两物体都不带电,说明两物体内都没有电荷C.摩擦起电时,一个物体得到一些电子而带正电,另一物体失去一些电子而带负电D.一个带电体跟一个不带电物体接触,两物体可能带上异种电荷【考点】电荷守恒定律.【专题】定性思想;推理法;电场力与电势的性质专题.【分析】摩擦起电的实质是电子从一个物体转移到另一个物体,并没有创造电荷.感应起电的实质是电荷可以从物体的一部分转移到另一个部分.【解答】解:A、感应起电是利用静电感应,使电荷从物体的一部分转移到物体的另一部分的过程,静电感应不是创造电荷.故A正确;B、摩擦起电前,两物体都不带电,不是两物体内都没有电荷,而是物体总是同时带等量异种电荷,故B错误;C、摩擦起电时,一个物体得到一些电子而带负电,另一物体失去一些电子而带正电,故C 错误;D、一个带电体跟一个不带电物体接触,两物体可能带上同种电荷,故D错误;故选:A【点评】摩擦起电和感应起电的实质都电子发生了转移,只是感应起电是电子从物体的一部分转移到另一个部分.摩擦起电是电子从一个物体转移到另一个物体.4.对于库仑定律,下面说法中正确的是( )A.凡计算两个点电荷间的相互作用力,就可以使用公式F=kB.两个带电小球即使相距非常近,也能用库仑定律C.相互作用的两个点电荷,不论它们电量是否相同,它们之间的库仑力大小一定相等D.两个点电荷的电量各减为原来的一半,它们之间的距离保持不变,则它们之间库存仑力减为原来的一半【考点】库仑定律.【专题】电场力与电势的性质专题.【分析】清楚库仑定律的适用条件,了解点电荷这一个理想化的模型.两个带电体间的距离趋近于零时,带电体已经不能看成点电荷.运用牛顿第三定律解决B受到的静电力和A受到的静电力关系.【解答】解;A、库仑定律的适用条件是:真空和静止点电荷,故A错误.B、如果在研究的问题中,带电体的形状、大小以及电荷分布可以忽略不计,即可将它看作是一个几何点,则这样的带电体就是点电荷.一个实际的带电体能否看作点电荷,不仅和带电体本身有关,还取决于问题的性质和精度的要求,B中两个金属球不能看成点电荷,库仑定律不适用,故B错误.C、相互作用的两个点电荷之间的库伦力为作用力和反作用力的关系,大小始终相等,故C 正确.D、两个点电荷的电量各减为原来的一半,它们之间的距离保持不变,根据公式,则有它们之间库存仑力减为原来的,故D错误;故选:C.【点评】清楚书本中一些定理和定律的适用条件,知道在处理复杂物理问题时建立具有普遍意义的基本规律一些不可或缺的理想模型,使得问题处理更简便.5.由电场强度的定义式E=可知,在电场中的同一点( )A.电场强度E跟F成正比,跟q成反比B.无论检验电荷所带的电量如何变化,始终不变C.不同电荷在电场中某点所受的电场力大小不同,该点的电场强度在不断改变D.一个不带电的小球在P点受到的电场力为零,则P点的场强一定为零【考点】电场强度.【分析】电场强度与试探电荷所受电场力、电荷量无关,由电场本身决定.同一电荷在电场中某点所受的电场力大,该点的电场强度不一定大.电场对不带电的小球没有电场力作用,一个不带电的小球在P点受到的电场力为零,P点的场强不一定为零.【解答】解:A、电场强度等于试探电荷所受电场力与电荷量的比值,但电场强度E并不跟F成正比,跟q成反比,而F、q无关,E由电场本身决定.故A错误.B、在电场中的同一点,电场强度E是一定的,则无论试探电荷所带的电量如何变化,始终不变.故B正确.C、由F=Eq知,不同电荷在电场中某点所受的电场力大小不同,但场强E却是一定的.故C错误.D、电场对不带电的小球没有电场力作用,不带电的小球在P点受到的电场力为零,P点的场强可能为零,也可能不为零.故D错误.故选:B【点评】对于电场强度,要抓住它的比值定义法的共性,E与试探电荷所受电场力、电荷量无关,反映电场本身的强弱和方向.6.如图所示,当滑动变阻器的滑动触头向左移时,灯泡L1、L2、L3的亮度将( )A.都变亮B.都变暗C.L1、L2变亮,L3变暗D.L1、L3变亮,L2变暗【考点】闭合电路的欧姆定律.【专题】恒定电流专题.【分析】首先认识电路的结构:电灯L 2与变阻器串联后与灯泡L 3并联,最后再与L 1串联;当滑动变阻器的滑动触头P 向左移动时,变阻器接入电路的电阻变小,故总电阻变小,根据欧姆定律判断干路电流的变化情况,然后逐步判断各个各个部分的电流或电压情况,从而判断灯泡的亮度.【解答】解:当滑动变阻器的滑动触头P 向左移动时,变阻器有效电阻变小,故整个电路的总电阻变小,根据欧姆定律可知干路电流增大,故灯泡L 1变亮;并联电路的电压U 并=E ﹣I (R L1+r ),故并联电路电压变小,灯泡L 3变暗;干路电流变大,而通过灯泡L 3的电流变小,故通过灯泡L 2的电流增大,灯泡L 2变亮;故ABD 错误,C 正确.故选:C .【点评】解决动态电路的关键是:通常按照局部→整体→局部的思路进行分析,在灵活应用串并联电压和电流的关系,判断各支路的电压和电流的变化.7.如图所示,有三个电阻,已知R l :R 2:R 3=1:3:6,则电路工作时,电压U l :U 2为( )A .1:6B .1:9C .1:3D .1:2【考点】串联电路和并联电路.【专题】恒定电流专题.【分析】根据串并联电路特点求出电阻关系,然后再由串并联电路特点及欧姆定律求出电压关系.【解答】解:设R l =R ,由于R l :R 2:R 3=1:3:6,则R 2=3R ,R 3=6R ,R 并==2R ,通过串联电路的电流I 相等,则U l :U 2=IR l :IR 并=1:2;故选D .【点评】熟练应用串并联电路特点i 欧姆定律即可正确解题,本题难度不大,是一道基础题.8.如图所示,因线路故障,按通K 时,灯L 1和L 2均不亮,用电压表测得U ab =0,U bc =0,U cd =4V .由此可知开路处为( )A .灯L 1B .灯L 2C .变阻器D .不能确定【考点】闭合电路的欧姆定律.【专题】恒定电流专题.【分析】对于完好的电阻,阻值一定,电流I=0时,根据欧姆定律可知,其电压U=IR=0.若发生断路,其两端电压等于电源的电动势.【解答】解:A、B对于完好的电阻,阻值一定,电流I=0时,根据欧姆定律可知,其电压U=IR=0.由题:U ab=0,U bc=0,则可知:灯L1、L2没有发生断路.故AB错误C、由题U cd=4V,则变阻器发生断路,因为断路时,电流无电流,其两端的电势分别等于电源两极的电势,其电势差等于电源的电动势.故C正确.D、由上述分析可知D错误.故选:C【点评】本题是电路中故障分析问题,往往哪段电路的电压等于电源的电压,哪段电路发生断路,可用电压即为电势差来理解.9.对电容C=,以下说法正确的是( )A.电容器充电荷量越大,电容增加越大B.电容器的电容跟它两极板所加电压成反比C.电容器的电容越大,所带电荷量就越多D.对于确定的电容器,它所充的电荷量跟它两极板间所加电压的比值保持不变【考点】电容.【专题】电容器专题.【分析】电容器的电容由本身的性质决定,跟电容器两端所加的电压和所带的带电量无关.【解答】解:A、电容器的电容与所带电量和两端间的电压无关,由本身的性质决定.故A、B错误.C、根据Q=CU,电容越大,带电量不一定大.故C错误.D、对于确定的电容器,它所充的电量跟它两极板间所加电压的比值保持不变.故D正确.故选:D.【点评】解决本题的关键理解电容的定义式,知道电容器的电容与所带的电量和两端间的电势差无关.10.电路中有一段金属丝长为L,电阻为R,要使电阻变为4R,下列可行的方法是( ) A.将金属丝拉长至2LB.将金属丝两端的电压提高到原来的4倍C.将金属丝对折后拧成一股D.将金属丝拉长至4L【考点】电阻定律.【专题】定性思想;推理法;恒定电流专题.【分析】根据R=知,电阻与导线的长度和横截面积有关,根据该公式确定可行的方法.【解答】解:A、将金属丝拉长至2L,体积不变,则横截面积变为原来的,根据R=知,电阻变为原来的4倍.故A正确.B、电阻与电压和电流无关;将金属丝两端的电压提高到原来的4倍,电阻不变.故B错误.C、将金属丝对折后拧成一股,长度变为原来的一半,横截面积变为原来的2倍,根据R=知,电阻变为原来的.故C错误.D、将金属丝拉长至4L,体积不变,则横截面积变为原来的,根据R=知,电阻变为原来的16倍.故D错误.故选:A.【点评】解决本题的关键掌握电阻定律R=,知道导体的电阻与长度、横截面积有关,与所加的电压无关.11.如今家用电器越来越多,它们在待机状态下也会耗电.为了节约电能和用电安全,你将选择( )①切断长期不使用的空调机的电源②电视机在不使用时,可以不断开电源③合理使用节能灯具④尽量避免同时使用大功率家用电器.A.①②③ B.②③④ C.①③④ D.①②④【考点】家庭电路和安全用电知识;常见家用电器的基本工作原理.【分析】从节能的因素:有些家用电器不使用时,若不切断电源用电器依然存在小电流耗能,所以若长时间不用,要切断电源,避免能耗;同时使用大功率家用电器会使干路电流较大,增加电线耗能和所分电压也不安全.【解答】解:由节能的方面分析:①说法可避免不工作时的小电流耗能.正确②说法会存在小电流耗能,要断开电源,说法错误③说法注重节能,正确④可减小电线能耗,及用电安全,正确故可见②应不选,则C选项确.故选:C【点评】考查节能的常识,明确用电器不工作时若接在电源上依然会有能耗.12.2011年8月13日强雷电袭击绍兴,威力之猛近期少有.雷暴天气和雷击事件,引起了绍兴市委、市政府的高度重视,要求有关部门加大防雷避雷知识的宣传,提高广大人民群众的防范意识,做好防雷工作,保障人民群众安全.假如在户外我们遭遇雷电,下列防雷措施可行的是( )①在大树下避雷雨②停留在山顶、山脊的凉亭等地方避雷雨③切勿站立于楼顶上或接近导电性高的物体④在空旷地带,最好关掉手机电源.A.①③B.②③C.①④D.③④【考点】* 静电的利用和防止.【分析】表面具有突出尖端的导体,在尖端的电荷分布密度很大,使得其周围电场很强,就可能使其周围的空气发生电离而引发尖端放电.因此不要在大树下避雨;别停留在山顶、山脊的凉亭等地方,快速开摩托、快骑自行车和在雨中狂奔;身体的跨步越大,电压就越大,雷电也越容易伤人;在空旷地带使用手机通话,手机很有可能成为闪电的放电对象.【解答】解:大树、山顶、山脊的凉亭、楼顶等地方是表面具有突出尖端的导体,可能使其周围的空气发生电离而引发尖端放电,故不能避雷雨,故①②错③对;在空旷地带使用手机通话,手机很有可能成为闪电的放电对象.故④对.故选D.【点评】本题考查的是关于避雷雨的常识,属于基础性常识题,难度不大.13.如图是某一点电荷的电场线分布图.下列表述正确的是( )A.a点的电势低于b点的电势B.该点电荷带负电C.a点和b点电场强度的方向相同D.a点的电场强度大于b点的电场强度【考点】电场线.【专题】定性思想;推理法;电场力与电势的性质专题.【分析】利用电场线的特点分析即可.借助电场线可以形象直观表示电场这两方面的特性:电场线疏密表示电场强度的相对大小,切线方向表示电场强度的方向,电场线的方向反映电势的高低.【解答】解:A、根据电场线与等势线垂直,在b点所在电场线上找到与a点电势相等的,依据沿电场线方向电势降低,则知a点电势低于b点电势,故A正确.B、根据电场线的方向特点,可知该点电荷带负电,故B正确.C、由题图可看出a点和b点电场强度的方向不同,故C错误D、电场线越密的地方电场强度越大,则a点的电场强度大于b点的电场强度,故D正确.故选:ABD【点评】该题考查常见的电场的特点,熟悉正、负点电荷,等量同种、等量异种电荷周围电场分布情况往往是解题关键.14.有一段直导线长1cm,通以5A电流.当把导线置于磁场中某点时,受到的磁场力为0.1N,则该点磁感应强度B的值可能为( )A.1 T B.1.5 T C.2 T D.2.5 T【考点】安培力.【分析】根据F=BILsinθ,结合磁场力、电流、导线长度的大小得出磁感应强度的大小.【解答】解:根据F=BILsinθ得,B=,因0<sinθ≤1,则B≥2T.故C、D正确,A、B错误.故选:CD.【点评】解决本题的关键掌握安培力的大小公式,当B与I平行,磁场力为零,当B与I垂直,磁场力F=BIL.15.不考虑温度对电阻的影响,对一个“220V,40W”的灯泡,下列说法正确的是( )A.接在110 V的电路上时的功率为20 WB.接在110 V的电路上时的功率为10 WC.接在440 V的电路上时的功率为160 WD.接在220 V的电路上时的功率为40 W【考点】电功、电功率.【专题】定性思想;推理法;恒定电流专题.【分析】灯泡是纯电阻电路,根据P=判断实际功率,同时要注意不能超出额定功率;超出额定电压后灯泡将被烧坏,功率为零.=得灯泡的电阻R=1210Ω【解答】解:由P额A、电压为110V时,则功率P===10W,故A错误,B正确;C、电压为440V时,超过灯泡的额定电压一倍,故灯泡烧坏,P=0,故C错误.D、电压为220V为额定电压,故功率为额定功率,为40W,故D正确;故选:BD【点评】本题关键根据电功率公式P=UI==I2R列式判断,同时要注意额定功率是电器长时间工作的最大功率.二、实验题(每空2分,画图4分,共18分.)16.在“测定金属丝电阻率”的实验中,需要测出其长度L、直径d和电阻R.(1)用螺旋测微器测金属丝直径时读数如图甲,则金属丝的直径为0.697mm.(2)若用图乙测金属丝的电阻,则测量结果将比真实值偏小.(选填“偏大”或“偏小”)(3)用电压表和电流表测金属丝的电压和电流时读数如图丙,则电压表的读数为2.60V,电流表的读数为0.52A.【考点】测定金属的电阻率.【专题】实验题;恒定电流专题.【分析】(1)螺旋测微器固定刻度与可动刻度示数之和是螺旋测微器所示.(2)根据电路图应用欧姆定律分析实验误差.(3)由图象电表确定电表量程与分度值,读出电表示数.【解答】解:(1)由图甲所示螺旋测微器可知,固定刻度示数为0.5mm,可动刻度示数为19.7×0.01mm=0.197mm,螺旋测微器示数为0.5mm+0.197mm=0.697mm.(2)由图示电路图可知,电流表采用外接法,由于电压表的分流作用,所测电流偏大,由欧姆定律可知,电阻测量值小于真实值.(3)由图丙所示电压表可知,其量程为3V,分度值为0.1V,示数为2.60V;由图示电流表可知,其量程为0.6A,分度值为0.02A,示数为0.52A.故答案为:(1)0.697;(2)偏小;(3)2.60;0.52.。
河南省扶沟县包屯高级中学2016届高三上学期第二次段考(期中)生物试题Word版含答案

包屯高中2015------2016学年度高三期中考试生物试题一.选择题(共30题每题2分共60分)1.下列哪项不属于生命系统()A.一只青蛙B.青蛙的表皮细胞C.青蛙表皮细胞中的钾离子D.池塘中的水、阳光等环境因素以及生活的生物2.下列关于原核生物和真核生物的叙述,正确的是()A.原核生物细胞没有线粒体只进行无氧呼吸B.原核生物细胞无叶绿体,但可能进行光合作用C.真核生物以DNA为遗传物质,原核生物以DNA 或RNA为遗传物质D.原核生物细胞中没有核糖体,真核生物细胞中含有核糖体3.假如蛋白酶1作用于苯丙氨酸(C9H11NO2)羧基端的肽键,蛋白酶2作用于赖氨酸(C6H14N2O2)两侧的肽键,某四十九肽经酶1和酶2作用后的情况见如图,下列叙述正确的是()A.此多肽中含2个赖氨酸B.苯丙氨酸位于四十九肽的17、31、49位C.短肽D、E与四十九肽的氧原子数相同,N原子数减少2个D.适宜条件下酶1和酶2同时作用与此多肽,可形成5条短肽4.心房颤动(房颤)是临床上最常见并且危害严重的心律失常疾病。
最新研究表明,其致病机制是核孔复合物的运输障碍(核孔复合物是位于核孔上与核孔的结构和功能密切相关的物质)。
据此分析正确的是()A.核膜由两层磷脂分子组成,房颤的成因与核膜内外的信息交流异常有关B.人体成熟的红细胞中核孔数目很少,因此红细胞代谢较弱C.核孔运输障碍发生的根本原因可能是编码核孔复合物的基因发生突变D.tRNA在细胞核内合成,运出细胞核发挥作用与核孔复合物无关5.2014年6月,清华大学宣布首次解析了人源葡萄糖转运蛋白(GLUT1)的晶体结构,这在人类攻克重大疾病的探索道路上迈出了极为重要的一步。
下列叙述错误的是()A.葡萄糖转运蛋白的功能取决于氨基酸的序列,与空间结构无关B.人源葡萄糖转运蛋白的mRNA在细胞核中形成C.葡萄糖转运蛋白的基本连接键是肽键D.阻碍肿瘤细胞的葡萄糖转运蛋白的功能,可达到“饿死”肿瘤细胞的目的6.用相同的培养液培养水稻和番茄幼苗,一段时间后,测定培养液中各种离子的浓度,结果如图1所示。
河南省扶沟县包屯高级中学2015-2016学年高一语文上学期第二次段考(期中)试题不分版本

河南省扶沟县包屯高级中学2015-2016学年高一语文上学期第二次段考(期中)试题不分版本包屯高中2015—2016学年度高一上期第二次段考语文试卷一.课内古诗文检测(每题3分,共33分)1、以下各句中不含通假字的一项为哪一项〔〕A. 今日往而不反者,竖子也! B 共其乏困C 秦王还柱而走。
D 偏袒扼腕而进。
2. 以下句子中加点词的解释,错误的一项为哪一项〔〕A. 今行而无信,那么秦未可亲也。
信:信物。
B. 荆轲顾笑武阳,前为谢曰。
顾:回头看C. 秦王还柱而走走:步行。
D. 进兵北略地略:掠夺、夺取。
3、以下句子中加点词的解释,正确的一项为哪一项〔〕A.然那么将军之仇报,而燕国见陵之耻除矣。
见陵:看见陵墓B.夺项王天下者必沛公也。
吾属今为之虏矣!〞属:属下C.微夫人之力不及此,因人之力而敝之,不仁。
敝:破败D.闻大王有意督过之,脱身独去,已至军矣。
〞过:责备4、以下加点的字解释有误的一项为哪一项〔〕A、晋军〔驻扎〕函陵假设亡郑而有益〔好处〕于君素(平素,一向)善留侯张良B、焉用亡郑以陪〔增加〕邻籍〔登记〕吏民范增数〔屡次〕目项王C、假设〔你〕入前为寿. 函〔匣子〕封之.因〔因为〕人之力而敝之,不仁D、将焉〔哪里〕取之荆轲取图奉之,发〔翻开〕图君安与项伯有故〔交情〕5、以下加点的字解释有误的一项为哪一项〔〕A、肉食者鄙,未能远谋鄙:鄙陋B、项伯乃夜驰之沛公军之:到C、燕王诚振怖大王之威诚:果真D、父母宗族皆为戮没为:被6、指出以下句子句式与例句相同的一项为哪一项:〔〕例句:夫晋,何厌之有?A、沛公安在?B、太子及宾客知其事者,皆白衣冠以送之C、吾属今为之虏矣D、楚左尹项伯者,项羽季父也7、下面句中划线词解释全都正确的一项为哪一项〔〕A.匪来贸丝,来即我谋。
即:接近,靠近将子无怒,秋以为期。
以为:认为B.却与小姑别却:退出可怜体无比可怜:可爱C.乘彼垝垣,以望复关。
乘:乘坐适得府君书适:恰好,适逢D.不吾知其亦已兮,已:罢了苟余情其信芳信:确实8、对以下句子中加点词含义解释完全正确的一组是( )A.自前世而固〔原本〕然汝心之固〔巩固〕,固不可彻B.故作不良计(成心) 大人故嫌迟(特地)C.渐见〔看见〕愁煎迫府吏见〔我〕丁宁D.始适还家门(女子出嫁) 适得府君书(刚刚)9、对以下加点词解释全正确的一项为哪一项( )①自我徂尔,三岁〔多年〕食贫。
河南省扶沟县包屯高级中学高三数学上学期第二次段考(期中)试题 理(扫描版)

参考答案1.A2.D3.B4.D5.C6.D 7A 8.D 9A 10.A 11.D 12.D13.1 14. 24 15. 16.(1,2 -∞-)17.(Ⅰ)(3分)由题意知,,.(4分)由,解得:, 的单调增区间为.(6分)(Ⅱ)由题意,若的图像向左平移个单位,得到,再纵坐标不变,横坐标缩短为原来的倍,得到,(8分),,函数的值域为.(10分)18.解:(Ⅰ)由已知得2cos B=-,(2分)由于△ABC为斜三角形,∴cos B≠0,∴sin2A=1.(4分)∵A∈(0,π),∴2A=,∴A=.(6分)(Ⅱ)∵A=,由(1)知,即,(9分)∴tan C>1,∵0<C<,∴<C<. (12分)19解:(Ⅰ)法一:设正项等差数列{}n a的首项为1a,公差为d,0na>,则2111124(2)772163a a d a d a d ⎧++=+⎪⎨⎪+=⎩………………2分 得132a d =⎧⎨=⎩………………………4分 3(1)221n a n n ∴=+-⨯=+. …………………6分法二:{}n a Q 是等差数列且215327a a a +=,233227a a ∴=,又30,7.n a a >∴=Q …………………2分17747()7632a a S a +===Q ,49a ∴=, ………………3分 432d a a ∴=-=, …………………………4分 3(3)21n a a n d n ∴=+-=+. ……………………6分(Ⅱ)11n n n b b a ++-=Q ,且21n a n =+,123n n b b n +∴-=+.当2n ≥时,112211()()()n n n n n b b b b b b b b ---=-+-++-+L(21)(21)53(2)n n n n =++-+++=+L ,………8分当1n =时,13b =满足上式,(2)n b n n =+. ……………9分11111()(2)22n b n n n n ∴==-++. …………………10分 1211111n n nT b b b b -∴=++++L 1111111111[(1)()()()()]232435112n n n n =-+-+-+-+--++L 11113111(1)()22124212n n n n =+--=-+++++.……………12分 20..(1)当时,.即(2分)∴=又∵0∴∴数列为等差数列(5分)(2)由(1)可求得. (7分)进而求得(9分)再裂项求和得(12分)21.(1)ax ax ax x f cos sin cos 3)(2-==)32sin(23π--ax ………………3分 由题意,函数)(x f 的周期为π,且最大(或最小)值为m ,而0>m ,0123<- 所以,,1=a 123+=m ………… ……………………6分 (2)∵()232,A 是函数)(x f 图象的一个对称中心 ∴0)3sin(=-πA 又因为A 为⊿ABC 的内角,所以3π=A ………… ……………………9分⊿ABC 中, 则由正弦定理得:3383sin4sin sin sin ====πAc c B b a, []4)6sin(84)3sin(sin 3384sin sin 3384++=+⎥⎦⎤⎢⎣⎡++=++=++=++∴ππB B B C B c b a c b320π<<B Θ ∴b+c+a ]12,8(∈ ………… ……………………12分22.解:(1),,切线过点,(2分)(3分)① 当时,单调递增,单调递减;② 当时,单调递减,单调递增.(5分)(2)等价方程在只有一个根,即在只有一个根,(6分)令,等价于在与轴只有唯一的交点,;(7分)①当时,在递减,递增,当时,,要函数在与轴只有唯一的交点,或,或;(9分)②当时,在递增,递减,递增,当时,,, 在与轴只有唯一的交点;(11分)③当,在递增, ,,在与轴只有唯一的交点.故的取值范围是或或.(12分)。
河南省扶沟县包屯高级中学高二英语上学期第二次段考(期中)试题

包屯高中高二期中英语试题本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分,考生作答时,将答案答在答题卡上(答题注意事项见答题卡),在本试题卷上做答无效。
考试结束后,将本试题卷和答题卡一并交回。
第Ⅰ卷第二部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项,并在答题卡上将该项涂黑。
AIt’s summer movie time again. Check out our list of four films.Harry Potter and the Prisoner of AzkabanRelease Date: November 4Story: It’s the summer before Harry Potter’s third year at Hogwarts School of Witchcraft and Wizardry. A dangerous murderer, Sirius Black, has escaped from the Wizards’ Priso n. And he was ordered to kill Harry Potter.Around the World in 80 DaysRelease Date: November 16Story: This version of the classic novel set in 1872 focuses on Passepartout (Hong Kong actor Jackie Chan), a Chinese thief who seeks refuge (庇护)with a strange London adventurer, Phileas Fogg. Passepartout uses his martial art skills to defend Fogg from danger as he travels around the world in 80 days.Spider-Man 2Release Date: November 30Story: Peter Parker is still coming to accept his dual identity (双重身份)as the crime superhero Spider-Man. He wants to reveal his secret identity to Mary Jane, meanwhile, his Aunt May is in trouble. It is Dr Otto Octavius who has appeared to bring her a lot of troubles.King ArthurRelease Date: November 7Story: King Arthur is presented as a clever ruler who manages to unite all the knights in Britain. Under the guidance of Merlin and the beautiful, brave Guinevere, Arthur will struggle to realize his dreams.21. When can you see the film acted by Jackie Chan?A. November 4.B. November 16.C. November 30.D. November 7.22. In Spider-Man 2, Aunt Mays trouble is caused by ________.A. Spider-ManB. Peter ParkerC. Mary JaneD. Dr Otto Octavius23. What kind of article is this passage?A. A news report.B. A funny diary.C. An advertisement.D. A composition.BJohnny was three when he ran away from home for the first time. Somebody left the garden gate open. Johnny wandered out, crossed some fields and two hours later, reached the next village. He could only give his name and address.By the time he was seven, Johnny used to disappear from home two to three times a year. Sometimes he covered quite long distances on foot. Sometimes he got on a bus or even a train, and simply sat there until someone asked for his ticket. Generally the police brought him home. “Why do you do it?” they used to ask. “I just want to see new places in the world, which makes me v ery happy.” Johnny told them.Johnny continued to “see new places” although everyone tried to stop him. His parents used to watch him closely, and so did his teachers; but sooner or later Johnny managed to slip away. Sometimes he travelled hundreds of miles before anyone discovered him.It is hardly surprising that Johnny managed to board a plane with lots of goods. He was only twelve at that time. A few hours later, Johnny found himself in Cairo. How did he get on board? No one knows. According to Johnny himself, it was easy: he just went into the airport, walked along some passages and got on board the nearest plane.In spite of all this, Johnny did well at school. He enjoyed mathematics and languages and, perhaps not surprisingly, he was especially go od at geography. “What do you want to be when you grow up?” his teachers asked him. “I want to be an explorer!” he answered. “But it’s difficult to become an explorer in this modern age,” they tried to tell him. But it was no use. Johnny knew what he wanted!Just before he left school, Johnny saw a notice in a daily paper. A long journey was about to go to Brazil to travel up the Amazon River. There were jobs for three young people “willing to work hard and with a sense of adventure”. Johnny applied, and two months later, he was on his way to Brazil.24. Why did Johnny frequently leave home?A. He enjoyed seeing new places.B. He liked geography very much.C. He was tired of going to school.D. His parents were strict with him.25. What did Johnny’ parents and teachers do with him?A. Kept following him to get him back.B. Encouraged him to travel abroad.C. Tried to stop him from slipping away.D. Booked tickets for him if necessary.26. What was Johnny going to do?A. Work for a daily paper.B. Have a holiday abroad.C. Travel to Brazil alone.D. Explore the Amazon River.27. Which of the following best describes Johnny?A. Naughty.B. Adventurous.C. Disappointing.D. Generous.CA terrible competition is going on in England, with billions of dollars and hundreds of lives at risk. OK, that’s not true. But competitors from around the world gathered on Thursday for the annual competition to compete for the world’s biggest person who tells lies.Each participant is given up to five minutes to make up the best fib in the contest,which was founded in honor of 19th-century Bridge Inn landlord Will Ritson, who was reportedly famous for his lies. Competitors gather at the Bridge Inn every year for the competition, a small pub in northwestern England. Anyone but lawyers and politicians can take part in the competition.A study found that nearly all lies are detectable(可检测的)through visible facial muscle reactions in the person telling a lie. “Thus, while interpersonal cheat often is highly successful, signs of hidden emotional states are communicated clearly to the informed observer,” the study concluded.A churchman of Carlisle reportedly holds what may be the greatest lie of all time in the competition, simply stating, “I have never told a lie in my life.”In 2003, Abrie Krueger from South Africa became the first one to win the competition. In 2006, comedian Sue Perkins became the first female to win the competition, telling a tale about people riding camels to work as a result of climate change.28. Why does the author tell a lie at the beginning of the passage?A. He likes telling lies.B. Nearly everyone has told lies.C. Lies can be detected by someone.D. He intends to talk about a contest.29. What does the underlined word “fib” in Paragraph 2 probably mean?A. Lie.B. Story.C. Experience.D. Plot.30. Who can’t take part in the competition?A. Doctors and teachers.B. Reporters and editors.C. Lawyers and politicians.D. Students and managers.31. What’s the author’s main purpose of this passage?A. To explain how to deal with lies.B. To introduce a strange competition.C. To discuss how to avoid telling lies.D. To invite people to take part in the competition.DWhy do Chinese people love hot pot so much? As the winter months are coming in, more and more people are sitting around a table, enjoying this kind of traditional meal. I find myself wondering what it is about this traditional meal, which has existed for more than 1,000 years. What makes it a Chinese food favorite? It seems that the answer lies beyond the dish itself.Hot pot isn’t just designed to keep you warm during the cold months; it’s also a social experience. It’s a “theater” cooked food that turns a meal into an event. There is a lot of fun for everyone to have in adding some foods to the hot pot. Hot pot is eaten over two to three hours. For this reason, it is often considered an evening’s entertainment, and a time to spend with friends and families. However, many westerners would be put off by the idea of other people sticking chopsticks in their food. When we come to eat at the table in the UK, we tend to have our own shares, although the experience is still a social one.A similar experience to the hot pot can be found in Korean barbecue restaurants, which let you cook your own meat. This allows people to have their meat done however they want to.For most westerners, the idea of going to a restaurant to cook their own foodis very strange. But having a go, I find it’s now one of my favorite meals in Beijing. The steam from the pot left my clothes smelling of food when I got home, but perhaps this was also part of the experience. When the cold wind is blowing outside, I am sitting around with my good friends, eating and drinking. For me, it’s like a dinner party where my taste buds(味蕾)and my appetite are equally satisfied in the warm company of friends.32. What is the main reason why hot pot is popular in China?A. It has a history of over 1,000 years.B. It is a fun social experience.C. It serves people with many kinds of foods.D. It keeps people very warm in winter.33. We can conclude from the article that British people generally _________.A. enjoy cooking their own food in restaurantsB. prefer a Korean barbecue to Chinese hot potC. don’t like sharing food with others in resta urantsD. don’t mind the smell of food staying on their clothes34. How long do people spend in enjoying the traditional meal?A. More than four hours.B. Over one hour.C. About three hours.D. All the evening.35. What is the author’s attitude to hot pot?A. Serious. B Tired. C. Humorous. D. Appreciative.第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
河南省扶沟县包屯高级中学高三英语上学期第二次段考(期中)试题

包屯高中高三英语期中试题第Ⅰ卷第一部分阅读理解(共两节,40分)第一节(共15小题;每小题2分,共30分)阅读下列短文,从每题所给A、B、C、D四个选项中,选出最佳选项,并在答题卡上将该项涂黑。
AFamily Photo Competition: The Winners!Adult winner: Anan Marriage, 42, from HertfordshireThis is just one photograph from a huge collection I have of my four children growing up. It was taken with a camera fastened to my husband’s chest. I think it conveys all the joy and spirit of our family while also being wonderfully creative and powerfully visual.Adult runner-up: Chris Evans, 49, from LondonThis photo was taken on the beach of Norfolk. We've been going there as a family for the last six years—the kids always look forward to a traditional holiday with sandy beaches, picnics and ice creams. This picture has our three children playing in a sand hole on the beach. It took them less time to dig the hole than it would to complete a level of Sonic the Hedgehog—a video game—but they had twice as much fun!Under-18s winner: Rhine Cunningham, 17,from ColchesterI thought up the idea while watching my dog sit near our boots, wanting to go for a walk. It took quite a few attempts to get her to stay still, but I finally got this one. I really like this photo because it looks as if my dog is saying, “Can we go for a walk now?”Under-18s runner-up: Hope Simpson, 13, from County DurhamThis is a photo of me, my mum and dad, my brother and our dog. I took it with my cell phone. It’s a special picture because it was the first time we’d been able to go out for a walk in over a year — I was recovering from CRPS (复杂性局部疼痛综合征)and had been in a wheelchair. But myfamily got me through a really tough time.1. What makes Anna Marriage’s photo special?A. Why it was taken.B. How it was taken.C. When it was taken.D. Where it was taken.2. Which of the following can we see in Chris Evans’ picture?A. A sandy beachB. Ice creams.C. A video game.D. The sights of London.3. Whose photo features a pet?A. Anna Marriage’sB. Chris Evans’C. Rhine Cunningham’sD. Hope Simpson’sBDuring the Second World War, I met a housewife from Chicago who told me how she discovered for herself that “the cure for worry is to get completely occupied doingsom ething constructive.” I met this woman and her husband in the dining car while I was traveling from New York to my farm in Missouri.This couple told me that their son had joined the armed forces the day after Pearl Harbour. The woman told me that she had almost mined her health worrying over that only son. where was he? Was he safe? Or in action? Would he be wounded? Killed?When I asked her how she overcame her worry, she replied: “I got busy.” She told me that at first she had dismissed her maid and tried to keep busy by doing all her housework herself. But that didn’t help much. “The trouble was,” she said, “that I could do my housework almost mechanically. So I kept on worrying. While making the beds and washing the dishes, I realized I needed some new kind of work that would keep me busy both mentally and physically. So I took a job as a saleswoman in a store.”“That did it,” she said. “I immediately found myself in a lot of activities: customers crowding around me, asking for prices, sizes, colors. Never a second to think of anything except my immediate duty; And when night came, I could think of nothing except getting off my aching feet. As soon as I ate dinner, I fell into bed and instantly became unconscious. I had neither the time nor the energy to worry.”4. What made the woman feel worried?A. Her son’s getting lost.B. Her son’s health condition.C. Her son’s joining the army.D. Her son’s situation in the war.5. Doing housework failed to work on the woman because ________.A. she needn’t use her mind to do housework.B. she didn’t like doing housework at all.C. there wasn’t much housework to do.D. it was too boring to do housework.6. Why did the woman take a job as a saleswoman?A. She had to work to support her family.B. She enjoyed being surrounded by people.C. She wanted being to make her life more colorful.D. She needed a more effective way to defeat her worry.7. After a day’s work as a saleswoman, the woman ________.A. seemed quite disappointedB. fell into unconsciousnessC. felt extremely tiredD. lost her appetiteCThe people of Austria call their country Osterreich, which can be translated as “eastern realm.” The origin of the name goes back to the 10th century, when Austria was an eastern border area of the Holy Roman Empire. From this early beginning, Austria itself grew into a great empire. During the 16th century, its emperor was the ruler of about ten countries. Today Austria is a small but rich nation in Central Europe.Religious holidays and other festivals are joyful occasions in Austria. In some religions, for example, there is an exciting festival for scaring away the winter. Wedding are very special occasions in the villages. These are days of much singing and dancing. One of the most exciting dances to watch is the Schuhplatter. In this dance the men slap(拍打)their bodies while the girls twirl(旋转)around them in their bright dresses. They dance to the music of the violin. The musicians play faster and faster toward the end of the dance until the dancers are out of breath.A favorite holiday throughout Austria is December 6, or Nikolo(Santa Claus)visits Austrian children. The night before, the children always remember to leave their shoes where Nikolo will find them. In the morning, the good children find presents in their shoes, but the bad children find only pieces of coal and potatoes. Krampus, a black-faced monster who is half human and often half horse, is supposed to company Saint Nicholas on his travels. Bad children are especially afraid of Krampus. It is said that he carries a broom to hit very bad boys and girls.In Austria, there are three music festivals each year that attract thousands of music lovers from all over the world. Tickets to operas, concerts, and plays in Austria are often sold out weeks in advance. Even rehearsals(排练)are usually well attended by students. When the old Vienna Opera House was bombed during World War Two, thousands of desperately poor Austrians contributed small amounts of money to repair the building.8. Austria was named Osterreich according to its ________.A. traditionB. locationC. populationD. expansion9. We know from the text that the Schuhplatter is performed ________.A. by both men and womanB. along with religious musicC. at the beginning of the winterD. with dancers playing instruments10. On Nikolo Day, ________.A. kids always hide their shoesB. kids should behave themselvesC. Nikolo only give gifts to good childrenD. Nikolo plays hide-and-seek with children11. The last paragraph mainly shows ________.A. Austrians’ love of musicB. the attractiveness of musicC. the influence of music on AustriaD. three world-famous music festivalsDIn life, you are given many chances to make a choice between a creator and a victim. Those who choose to be creators look at life quite differently. They know there are individuals who might love to control their lives, but they don’t let this get in the way. They are aware that they have their weaknesses, but they don’t blame themselves when they fail. Whatever happens, they have choice in the matter. They believe their dance with each holy moment of life is a gift and that storms are a natural part of life which can bring the rain needed for emotional and spiritual growth.If you choose to be a victim, the world is a cold and difficult place. “They”did things to you that caused all of yo ur hardship and sadness. “They” are wrong and bad, and life is terrible as long as “they” are around. Or you may blame yourself for all your problems, thus internalizing(内化)your victimization. The truth is, your life is likely to stay that way as long as you feel a need to blame yourself or others.Creators and victims live in the same physical world and handle many of the same physical realities, but their experience of life is worlds apart. Victims relish (沉溺)in anger, guilt, and other emotions that cause others—and even themselves—tofeel like victims, too. Creators consciously choose love, inspiration, and other qualities which inspire not only themselves, but all around them. Both victims and creators always have choice to determine the direction of their lives.Actually, all of us play the victim or the creator at all sorts of points in our lives. One person, on losing a job or a special relationship, may feel as though it is the end of the world and be trapped in terrible suffering for months, years, or even a lifetime. Another with the same experience may choose to first experience the grief, then accept the loss and soon move on to be a powerful creative force in his life. In every moment and every circumstance, you can choose to have a fuller, richer life by setting a clear intention to transform the victim within, and by inviting into your life the powerful creator that you are.12. According to Paragraph 1, creators ________.A. seem willing to experience failures in lifeB. possess the ability to predict future lifeC. have potential to create something newD. handle ups and downs of life wisely13. What does the word “they” in Paragraph 2 probably refer to?A. Opportunities and problems.B. People and things around you.C. Creators and their choices.D. Victims and their sufferings.14. What can we learn from Paragraph 3?A. Creators and victims are masters of their lives.B. Creators and victims face quite different things in life.C. Victims can influence more people than creators.D. Compared with victims, creators are more emotional.15. What is the author’s purpose in writing this passage?A. To define victims and creators.B. To evaluate victims against creators.C. To suggest the transformation from victims to creators.D. To explain the relationship between victims and creators.第二节(共5小题;每小题2分,共10分)根据短文内容,从短文后的七个选项中选出能填入空白处的最佳选项,选项中有两项为多余选项。
语文上学期期中试题-周口市扶沟县包屯高级中学2015-2016学年高二上学期第二次段考语文试题及答案(期中)

河南省周口市扶沟县包屯高级中学2015-2016学年高二上学期第二次段考(期中)语文试题一、现代文阅读(9分,每小题3分)阅读下面的文字,完成3题。
老子其人其书的时代,自司马迁《史记》以来即有异说。
清代学者崇尚考据,对此议论纷纷,如汪中作《老子考异》,力主老子为战国时人,益启争端。
钱穆先生说:“老子伪迹不彰,真相不白,则先秦诸子学术思想之系统条贯始终不明,其源流派别终无可言。
”大家都期待这个问题有新的解决线索。
过去对于古书真伪及年代的讨论,只能以纸上材料证明纸上材料,没有其他的衡量标准,因而难有定论。
用来印证《老子》的古书,大多受到辨伪家的怀疑,年代确不可移的,恐怕要数到《韩非子》、《吕氏春秋》和《淮南子》,但这几本书成书太晚,没有多少作用。
近年战国秦汉简帛佚籍大量出土,为学术界提供了许多前所未见的地下材料,这使我们有可能重新考虑《老子》的时代问题。
1973年长沙马王堆三号汉墓出土的帛书,内有《老子》两种版本,甲本字体较早,不避汉高祖讳,应抄写于高祖即帝位前,乙本避高祖讳,可能抄写于文帝初。
这两本《老子》抄写年代都晚,无益于《老子》著作年代的推定,但乙本前面有《黄帝书》四篇,系“黄”、“老”合抄之本,则从根本上改变了学术界对早期道家的认识。
郭沫若先生曾指出,道家都是以“发明黄老道德意”为其指归,故也可称之为黄老学派。
《老子》和《黄帝书》是道家的经典,在汉初被抄写在《老子》前面的《黄帝书》显然在当时公众心目中已据有崇高位置,不会是刚刚撰就的作品。
同时,《黄帝书》与《申子》、《慎子》、《韩非子》等有许多共通文句,而申不害、慎到、韩非三人均曾学黄老之术,这些共通之处可认作对《黄帝书》的引用阐发。
申不害和慎到的年代,前人推为战国中期,《黄帝书》不应更晚。
至于《黄帝书》与《老子》的共通之处也甚多,如《黄帝书·经法》篇云“王天下者有玄德”,什么是“玄德”,文中未见解释。
查《老子》五十一章:“生而不有,为而不恃,长而不宰,是谓玄德。
河南省周口市扶沟县包屯高中2016届高三数学上学期期中试卷理含解析

2015-2016学年河南省周口市扶沟县包屯高中高三(上)期中数学试卷(理科)一、选择题(共12小题,每小题5分,满分60分)1.已知全集U=R,A={y|y=2x+1},B={x|lnx<0},则A∩B=( )A.{x|0<x<1} B.{x|<x≤1}C.{x|x<1} D.∅2.如果点P在平面区域上,点Q在曲线x2+(y+2)2=1上,那么|PQ|的最小值为( )A.﹣1 B.﹣1 C.2﹣1 D.﹣13.已知x0是函数f(x)=2x+的一个零点.若x1∈(1,x0),x2∈(x0,+∞),则( )A.f(x1)<0,f(x2)<0 B.f(x1)<0,f(x2)>0 C.f(x1)>0,f(x2)<0 D.f(x1)>0,f(x2)>04.直线x=,x=2,y=0,及曲线y=所围图形的面积为( )A.B.C.D.2ln25.已知函数f(x)对定义域R内的任意x都有f(x)=f(4﹣x),且当x≠2时其导函数f′(x)满足xf′(x)>2f′(x),若2<a<4则( )A.f(2a)<f(3)<f(log2a)B.f(3)<f(log2a)<f(2a)C.f(log2a)<f(3)<f(2a)D.f(log2a)<f(2a)<f(3)6.在锐角三角形ABC中,BC=1,B=2A,则的值等于( )A.3 B.2 C.﹣2 D.07.已知函数f(x)是R上的单调增函数且为奇函数,数列{a n}是等差数列,a3>0,则f(a1)+f(a3)+f(a5)的值( )A.恒为正数 B.恒为负数 C.恒为0 D.可正可负8.若函数f(x)=2sin()(﹣2<x<10)的图象与x轴交于点A,过点A的直线l 与函数的图象交于B、C两点,则(+)•=( )A.﹣32 B.﹣16 C.16 D.329.已知O是△ABC所在平面上一点,满足||2+||2=||2+||2,则点O( )A.在与边AB垂直的直线上B.在∠A的平分线所在直线上C.在边AB的中线所在直线上D.以上都不对10.以下判断正确的是( )A.命题“在锐角△ABC中,有sinA>cosB”为真命题B.命题“存在x∈R,x2+x﹣1<0”的否定是“任意x∈R,x2+x﹣1>0”C.函数y=f(x)为R上可导函数,则f′(x0)=0是x0为函数f(x)极值点的充要条件D.“b=0”是“f(x)=ax2+bx+c是偶函数”的充分不必要条件11.已知等比数列{a n}的公比q>0且q≠1,又a6<0,则( )A.a5+a7>a4+a8B.a5+a7<a4+a8C.a5+a7=a4+a8D.|a5+a7|>|a4+a8|12.已知函数f(x)=e x﹣1,g(x)=﹣x2+4x﹣3,若存在f(a)=g(b),则实数b的取值范围为( )A.[1,3] B.(1,3)C.D.二、填空题(共4小题,每小题5分,满分20分)13.若函数f(x)=xln(x+)为偶函数,则a=__________.14.已知点P是边长为4的正三角形ABC的边BC上的中点,则•(+)=__________.15.已知方程sinx+cosx=m+1在x∈[0,π]上有两个不相等的实数解,则实数m的取值范围是__________.16.定义在R上的函数f(x)=ax3+bx2+cx(a≠0)的单调增区间为(﹣1,1),若方程3a(f (x))2+2bf(x)+c=0恰有6个不同的实根,则实数a的取值范围是__________.三、解答题(共6小题,满分70分)17.已知向量(ω>0),函数f(x)=,若函数f(x)的图象的两个相邻对称中心的距离为.(Ⅰ)求函数f(x)的单调增区间;(Ⅱ)将函数f(x)的图象先向左平移个单位,然后纵坐标不变,横坐标缩短为原来的倍,得到函数g(x)的图象,当时,求函数g(x)的值域.18.在斜三角形ABC中,角A、B、C所对的边分别是a、b,c,且=﹣.(Ⅰ)求角A的大小;(Ⅱ)若,求角C的取值范围.19.已知正项等差数列{a n}的前n项和为S n且满足a1+a5==63.(Ⅰ)求数列{a n}的通项公式a n;(Ⅱ)若数列{b n}满足b1=a1且b n+1﹣b n=a n+1,求数列的前n项和T n.20.已知正项数列{a n}的首项a1=1,前n项的和为S n,且满足:当n≥2时,a n=+.(1)证明:数列{}为等差数列.(2)若数列{}前n项的和为T n,求T n的表达式.21.若f(x)=cos2ax﹣sinaxcosax(a>0)的图象与直线y=m(m>0)相切,并且切点横坐标依次成公差为π的等差数列.(1)求a和m的值;(2)△ABC中a、b、c分别是∠A、∠B、∠C的对边.若(,)是函数f(x)图象的一个对称中心,且a=4,求△ABC周长的取值范围.22.已知函数f(x)=(其中a≤2且a≠0),函数f(x)在点(1,f(1))处的切线过点(3,0).(Ⅰ)求函数f(x)的单调区间;(Ⅱ)若函数f(x)与函数g(x)=a+2﹣x﹣的图象在(0,2]有且只有一个交点,求实数a 的取值范围.2015-2016学年河南省周口市扶沟县包屯高中高三(上)期中数学试卷(理科)一、选择题(共12小题,每小题5分,满分60分)1.已知全集U=R,A={y|y=2x+1},B={x|lnx<0},则A∩B=( )A.{x|0<x<1} B.{x|<x≤1}C.{x|x<1} D.∅【考点】交集及其运算.【专题】计算题;函数思想;数学模型法;集合.【分析】求解函数的值域化简A,求解对数不等式化简B,然后取交集得答案.【解答】解:∵A={y|y=2x+1}=R,B={x|lnx<0}=(0,1),∴A∩B=(0,1).故选:A.【点评】本题考查交集及其运算,考查了函数值域的求法,训练了对数不等式的解法,是基础题.2.如果点P在平面区域上,点Q在曲线x2+(y+2)2=1上,那么|PQ|的最小值为( )A.﹣1 B.﹣1 C.2﹣1 D.﹣1【考点】简单线性规划的应用.【专题】计算题;数形结合.【分析】先画出满足的平面区域,再把|PQ|的最小值转化为点P到(0,﹣2)的最小值减去圆的半径1即可.【解答】解:由题可知不等式组确定的区域为阴影部分包括边界,点P到Q的距离最小为到(0,﹣2)的最小值减去圆的半径1,点(0,﹣2)到直线x﹣2y+1=0的距离为=;由图可知:|PQ|min=﹣1,故选A.【点评】本题属于线性规划中的延伸题,对于可行域不要求线性目标函数的最值,而是求可行域内的点与(0,﹣2)之间的距离问题3.已知x0是函数f(x)=2x+的一个零点.若x1∈(1,x0),x2∈(x0,+∞),则( )A.f(x1)<0,f(x2)<0 B.f(x1)<0,f(x2)>0 C.f(x1)>0,f(x2)<0 D.f(x1)>0,f(x2)>0【考点】函数零点的判定定理.【专题】函数的性质及应用.【分析】因为x0是函数f(x)=2x+的一个零点可得到f(x0)=0,再由函数f(x)的单调性可得到答案.【解答】解:∵x0是函数f(x)=2x+的一个零点∴f(x0)=0∵f(x)=2x+是单调递增函数,且x1∈(1,x0),x2∈(x0,+∞),∴f(x1)<f(x0)=0<f(x2)故选B.【点评】本题考查了函数零点的概念和函数单调性的问题,属中档题.4.直线x=,x=2,y=0,及曲线y=所围图形的面积为( )A.B.C.D.2ln2【考点】定积分在求面积中的应用.【专题】计算题;导数的综合应用.【分析】用定积分表示出图形的面积,求出原函数,即可求得结论.【解答】解:由题意,直线x=,x=2,y=0,及曲线y=所围图形的面积为=lnx=ln2﹣ln=2ln2故选:D.【点评】本题考查定积分知识的运用,考查导数知识,考查学生的计算能力,属于基础题.5.已知函数f(x)对定义域R内的任意x都有f(x)=f(4﹣x),且当x≠2时其导函数f′(x)满足xf′(x)>2f′(x),若2<a<4则( )A.f(2a)<f(3)<f(log2a)B.f(3)<f(log2a)<f(2a)C.f(log2a)<f(3)<f(2a)D.f(log2a)<f(2a)<f(3)【考点】抽象函数及其应用;导数的运算.【专题】计算题;函数的性质及应用.【分析】由f(x)=f(4﹣x),可知函数f(x)关于直线x=2对称,由xf′(x)>2f′(x),可知f(x)在(﹣∞,2)与(2,+∞)上的单调性,从而可得答案.【解答】解:∵函数f(x)对定义域R内的任意x都有f(x)=f(4﹣x),∴f(x)关于直线x=2对称;又当x≠2时其导函数f′(x)满足xf′(x)>2f′(x)⇔f′(x)(x﹣2)>0,∴当x>2时,f′(x)>0,f(x)在(2,+∞)上的单调递增;同理可得,当x<2时,f(x)在(﹣∞,2)单调递减;∵2<a<4,∴1<log2a<2,∴2<4﹣log2a<3,又4<2a<16,f(log2a)=f(4﹣log2a),f(x)在(2,+∞)上的单调递增;∴f(log2a)<f(3)<f(2a).故选C.【点评】本题考查抽象函数及其应用,考查导数的性质,判断f(x)在(﹣∞,2)与(2,+∞)上的单调性是关键,属于中档题.6.在锐角三角形ABC中,BC=1,B=2A,则的值等于( )A.3 B.2 C.﹣2 D.0【考点】正弦定理.【专题】计算题.【分析】利用正弦定理表示出=,把BC的长及B=2A代入,其中的sin2A利用二倍角的正弦函数公式化简后,变形可得所求式子的值.【解答】解:由BC=1,B=2A根据正弦定理得=,即==,则=2.故选B【点评】此题考查了正弦定理,二倍角的正弦函数公式,熟练掌握定理及公式是解本题的关键.7.已知函数f(x)是R上的单调增函数且为奇函数,数列{a n}是等差数列,a3>0,则f(a1)+f(a3)+f(a5)的值( )A.恒为正数 B.恒为负数 C.恒为0 D.可正可负【考点】等差数列的性质;函数单调性的性质;函数奇偶性的性质.【专题】计算题.【分析】由函数f(x)是R上的奇函数且是增函数数列,知取任何x2>x1,总有f(x2)>f (x1),由函数f(x)是R上的奇函数,知f(0)=0,所以当x>0,f(0)>0,当x<0,f (0)<0.由数列{a n}是等差数列,a1+a5=2a3,a3>0,知a1+a5>0,所以f(a1)+f(a5)>0,f(a3)>0,由此知f(a1)+f(a3)+f(a5)恒为正数.【解答】解:∵函数f(x)是R上的奇函数且是增函数数列,∴取任何x2>x1,总有f(x2)>f(x1),∵函数f(x)是R上的奇函数,∴f(0)=0,∵函数f(x)是R上的奇函数且是增函数,∴当x>0,f(0)>0,当x<0,f(0)<0.∵数列{a n}是等差数列,a1+a5=2a3,a3>0,∴a1+a5>0,则f(a1)+f(a5)>0,∵f(a3)>0,∴f(a1)+f(a3)+f(a5)恒为正数.【点评】本题考查等差数列的性质和应用,是中档题.解题时要认真审题,仔细解答,注意合理地运用函数的性质进行解题.8.若函数f(x)=2sin()(﹣2<x<10)的图象与x轴交于点A,过点A的直线l与函数的图象交于B、C两点,则(+)•=( )A.﹣32 B.﹣16 C.16 D.32【考点】平面向量数量积的运算;正弦函数的图象.【专题】计算题;三角函数的图像与性质;平面向量及应用.【分析】由f(x)=2sin()=0,结合已知x的范围可求A,设B(x1,y1),C(x2,y2),由正弦函数的对称性可知B,C 两点关于A对称即x1+x2=8,y1+y2=0,代入向量的数量积的坐标表示即可求解【解答】解:由f(x)=2sin()=0可得∴x=6k﹣2,k∈Z∵﹣2<x<10∴x=4即A(4,0)设B(x1,y1),C(x2,y2)∵过点A的直线l与函数的图象交于B、C两点∴B,C 两点关于A对称即x1+x2=8,y1+y2=0则(+)•=(x1+x2,y1+y2)•(4,0)=4(x1+x2)=32故选D【点评】本题主要考查了向量的数量积的坐标表示,解题的关键正弦函数对称性质的应用.9.已知O是△ABC所在平面上一点,满足||2+||2=||2+||2,则点O( )A.在与边AB垂直的直线上B.在∠A的平分线所在直线上C.在边AB的中线所在直线上D.以上都不对【考点】平面向量数量积的运算.【专题】平面向量及应用.【分析】根据向量的减法分别设=,=,=,表示,利用数量积运算和题意代入式子进行化简,证出OC⊥AB.【解答】解:设=,=,=,则=,.由||2+||2=||2+||2,∴||2+||2=||2+||2,化简可得,即())•=0,∴∴AB⊥OC.故选A.【点评】本题考查了向量在几何中应用,主要利用向量的线性运算以及数量积进行化简证明,证明垂直主要根据题意构造向量利用数量积为零进行证明.10.以下判断正确的是( )A.命题“在锐角△ABC中,有sinA>cosB”为真命题B.命题“存在x∈R,x2+x﹣1<0”的否定是“任意x∈R,x2+x﹣1>0”C.函数y=f(x)为R上可导函数,则f′(x0)=0是x0为函数f(x)极值点的充要条件D.“b=0”是“f(x)=ax2+bx+c是偶函数”的充分不必要条件【考点】命题的真假判断与应用.【专题】转化思想;数学模型法;简易逻辑.【分析】A.在锐角△ABC中,有>0,可得sinA>=cosB,即可判断出正误;B.利用命题的否定定义即可判断出正误;C.f′(x0)=0是x0为函数f(x)极值点的必要不充分条件,例如函数f(x)=x3,f′(0)=3x2|x=0=0,而函数f(x)在x=0处无极值,即可判断出正误;D.“b=0”⇔“f(x)=ax2+bx+c是偶函数”,即可判断出正误.【解答】解:A.在锐角△ABC中,有,∴>0,∴sinA>=cosB,因此为真命题;B.“存在x∈R,x2+x﹣1<0”的否定是“任意x∈R,x2+x﹣1≥0”,因此不正确;C.函数y=f(x)为R上可导函数,则f′(x0)=0是x0为函数f(x)极值点的必要不充分条件,例如函数f(x)=x3,f′(0)=3x2|x=0=0,而函数f(x)在x=0处无极值,因此不正确;D.“b=0”⇔“f(x)=ax2+bx+c是偶函数”,因此不正确.故选:A.【点评】本题查克拉简易逻辑的判定方法、函数的奇偶性、三角函数单调性、利用导数研究函数的极值,考查了推理能力与计算能力,属于中档题.11.已知等比数列{a n}的公比q>0且q≠1,又a6<0,则( )A.a5+a7>a4+a8B.a5+a7<a4+a8C.a5+a7=a4+a8D.|a5+a7|>|a4+a8|【考点】等比数列的性质.【专题】计算题.【分析】等比数列{a n}的公比q>0且q≠1,又a6<0,知此等比数列是一个负项数列,各项皆为负,观察四个选项,比较的是a5+a7,a4+a8两组和的大小,可用作差法进行探究,比较大小【解答】解:∵a6<0,q>0∴a5,a7,a8,a4都是负数∴a5+a7﹣a4﹣a8=a4(q﹣1)+a7(1﹣q)=(q﹣1)(a4﹣a7)若0<q<1,则q﹣1<0,a4﹣a7<0,则有a5+a7﹣a4﹣a8>0若q>1,则q﹣1>0,a4﹣a7>0,则有a5+a7﹣a4﹣a8>0∴a5+a7>a4+a8故选A【点评】本题主要考查了等比数列的性质.属基础题.12.已知函数f(x)=e x﹣1,g(x)=﹣x2+4x﹣3,若存在f(a)=g(b),则实数b的取值范围为( )A.[1,3] B.(1,3)C.D.【考点】函数的零点与方程根的关系.【专题】综合题.【分析】确定两个函数的值域,根据f(a)=g(b),可得g(b)∈(﹣1,1],即可求得实数b的取值范围.【解答】解:由题可知f(x)=e x﹣1>﹣1,g(x)=﹣x2+4x﹣3=﹣(x﹣2)2+1≤1,若有f(a)=g(b),则g(b)∈(﹣1,1],即﹣b2+4b﹣3>﹣1,即 b2﹣4b+2<0,解得.所以实数b的取值范围为故选D.【点评】本题考查函数的值域,考查解不等式,同时考查学生分析解决问题的能力.二、填空题(共4小题,每小题5分,满分20分)13.若函数f(x)=xln(x+)为偶函数,则a=1.【考点】函数奇偶性的性质.【专题】函数的性质及应用.【分析】由题意可得,f(﹣x)=f(x),代入根据对数的运算性质即可求解.【解答】解:∵f(x)=xln(x+)为偶函数,∴f(﹣x)=f(x),∴(﹣x)ln(﹣x+)=xln(x+),∴﹣ln(﹣x+)=ln(x+),∴ln(﹣x+)+ln(x+)=0,∴ln(+x)(﹣x)=0,∴lna=0,∴a=1.故答案为:1.【点评】本题主要考查了偶函数的定义及对数的运算性质的简单应用,属于基础试题.14.已知点P是边长为4的正三角形ABC的边BC上的中点,则•(+)=24.【考点】平面向量数量积的运算.【专题】整体思想;向量法;平面向量及应用.【分析】由中点的向量表示形式可得=(+),再由向量数量积的定义和性质,化简整理即可得到所求值.【解答】解:由P为边长为4的正三角形ABC的边BC上的中点,可得=(+),•=||•||•cosA=4×4×=8,则•(+)=(+)2=(2+2+2•)=×(16+16+16)=24.故答案为:24.【点评】本题考查向量的数量积的定义和性质,考查向量的中点的表示形式,以及运算能力,属于基础题.15.已知方程sinx+cosx=m+1在x∈[0,π]上有两个不相等的实数解,则实数m的取值范围是.【考点】函数恒成立问题;三角函数的最值.【专题】函数的性质及应用;三角函数的求值;三角函数的图像与性质.【分析】通过两角和与差的三角函数化简左侧表达式,通过三角函数的最值,得到表达式,然后求解m的范围.【解答】解:m+1=sinx+cosx=2sin(x+),x∈[0,π],x+[],如图:方程sinx+cosx=m+1在x∈[0,π]上有两个不相等的实数解,2sin(x+)∈.∴m+1∈,可得m∈.故答案为:.【点评】他考查函数的恒成立,三角函数的最值函数的图象的应用,考查分析问题解决问题的能力.16.定义在R上的函数f(x)=ax3+bx2+cx(a≠0)的单调增区间为(﹣1,1),若方程3a(f (x))2+2bf(x)+c=0恰有6个不同的实根,则实数a的取值范围是a<﹣.【考点】利用导数研究函数的极值;根的存在性及根的个数判断.【专题】导数的综合应用.【分析】根据函数的单调区间求出a,b,c的关系,然后利用导数研究三次函数的极值,利用数形结合即可得到a的结论.【解答】解:∵函数f(x)=ax3+bx2+cx(a≠0)的单调增区间为(﹣1,1),∴f'(x)>0的解集为(﹣1,1),即f'(x)=3ax2+2bx+c>0的解集为(﹣1,1),∴a<0,且x=﹣1和x=1是方程f'(x)=3ax2+2bx+c=0的两个根,即﹣1+1=,,解得b=0,c=﹣3a.∴f(x)=ax3+bx2+cx=ax3﹣3ax=ax(x2﹣3),则方程3a(f(x))2+2bf(x)+c=0等价为3a(f(x))2﹣3a=0,即(f(x))2=1,即f(x)=±1.要使方程3a(f(x))2+2bf(x)+c=0恰有6个不同的实根,即f(x)=±1.各有3个不同的根,∵f(x)=ax3+bx2+cx=ax3﹣3ax=ax(x2﹣3),∴f'(x)=3ax2﹣3a=3a(x2﹣1),∵a<0,∴当f'(x)>0得﹣1<x<1,此时函数单调递增,当f'(x)<0得x<﹣1或x>1,此时函数单调递减,∴当x=1时,函数取得极大值f(1)=﹣2a,当x=﹣1时,函数取得极小值f(﹣1)=2a,∴要使使方程3a(f(x))2+2bf(x)+c=0恰有6个不同的实根,即f(x)=±1各有3个不同的根,此时满足f极小(﹣1)<1<f极大(1),f极小(﹣1)<﹣1<f极大(1),即2a<1<﹣2a,且2a<﹣1<﹣2a,即,且,解得即a且a,故答案为:a.【点评】本题主要考查方程根的个数的应用,利用方程和函数之间的关系,作出函数的图象,利用数形结合是解决本题的关键.利用导数研究函数的极值是解决本题的突破点.三、解答题(共6小题,满分70分)17.已知向量(ω>0),函数f(x)=,若函数f(x)的图象的两个相邻对称中心的距离为.(Ⅰ)求函数f(x)的单调增区间;(Ⅱ)将函数f(x)的图象先向左平移个单位,然后纵坐标不变,横坐标缩短为原来的倍,得到函数g(x)的图象,当时,求函数g(x)的值域.【考点】函数y=Asin(ωx+φ)的图象变换;正弦函数的单调性.【专题】三角函数的图像与性质.【分析】(Ⅰ)由条件利用两个向量的数量积公式,三角恒等变换求得f(x)的解析式,再利用正弦函数的单调性求得f(x)的单调增区间.(Ⅱ)由题意根据y=Asin(ωx+φ)的图象变换规律,求得g(x)的解析式,再利用定义域和值域,求得函数g(x)的值域.【解答】解:(Ⅰ)由题意可得sin2ωx﹣2cos2ωx+1=sin2ωx﹣cos2ωx=sin(2ωx﹣),由题意知,,∴ω=1,∴.由,解得:,∴f(x)的单调增区间为.(Ⅱ)由题意,把f(x)的图象向左平移个单位,得到,再纵坐标不变,横坐标缩短为原来的倍,得到,∵,∴,∴,函数g(x)的值域为.【点评】本题主要考查两个向量的数量积公式,三角恒等变换,y=Asin(ωx+φ)的图象变换规律,正弦函数的单调性、定义域和值域,属于基础题.18.在斜三角形ABC中,角A、B、C所对的边分别是a、b,c,且=﹣.(Ⅰ)求角A的大小;(Ⅱ)若,求角C的取值范围.【考点】正弦定理;余弦定理.【专题】解三角形.【分析】(I)由已知可得2cosB=,求得sin2A=1,可得A的值.(II)由B+C=,且==+tanC>,求得tanC>1,从而得到C的范围.【解答】解:(I)由已知=﹣,可得2cosB=.而△ABC为斜三角形,∴cosB≠0,∴sin2A=1.∵A∈(0,π),∴2A=,A=.(II)∵B+C=,且===+tanC >,即tanC>1,∴<C<.【点评】本题主要考查正弦定理和余弦定理的应用,两角和差的正弦公式、诱导公式,属于基础题.19.已知正项等差数列{a n}的前n项和为S n且满足a1+a5==63.(Ⅰ)求数列{a n}的通项公式a n;(Ⅱ)若数列{b n}满足b1=a1且b n+1﹣b n=a n+1,求数列的前n项和T n.【考点】数列的求和;等差数列的性质.【专题】等差数列与等比数列.【分析】(Ⅰ)根据已知条件建立方程组,通过解方程求出首项和公差,进一步求出数列的通项公式.(Ⅱ)首先利用叠加法求出数列的通项公式,进一步利用裂项相消法求数列的和.【解答】解:(Ⅰ)法一:设正项等差数列{a n}的首项为a1,公差为d,a n>0则,得∴a n=2n+1法二:∵{a n}是等差数列且,∴,又∵a n>0∴a3=7.…∵,∴d=a4﹣a3=2,∴a n=a3+(n﹣3)d=2n+1.(Ⅱ)∵b n+1﹣b n=a n+1且a n=2n+1,∴b n+1﹣b n=2n+3当n≥2时,b n=(b n﹣b n﹣1)+(b n﹣1﹣b n﹣2)+…+(b2﹣b1)+b1=(2n+1)+(2n﹣1)+…+5+3=n(n+2),当n=1时,b1=3满足上式,b n=n(n+2)∴=.【点评】本题考查的知识要点:数列的通项公式的求法,利用裂项相消法求数列的和,属于基础题型.20.已知正项数列{a n}的首项a1=1,前n项的和为S n,且满足:当n≥2时,a n=+.(1)证明:数列{}为等差数列.(2)若数列{}前n项的和为T n,求T n的表达式.【考点】数列的求和;等差关系的确定.【专题】综合题;转化思想;综合法;等差数列与等比数列.【分析】(1)当n≥2时,a n=+,可得S n﹣S n﹣1=+.又数列{a n}的各项为正数,可得=1,即可证明.(2)由(1)可得:可得S n.可得a n.再利用“裂项求和”即可得出.【解答】(1)证明:∵当n≥2时,a n=+,∴S n﹣S n﹣1=+.又数列{a n}的各项为正数,∴+>0.∴=1,∴数列{}为等差数列,首项为1,公差为1.(2)解:由(1)可得:=1+(n﹣1)=n,可得S n=n2.∴当n≥2时,a n==2n﹣1,当n=1时也成立,∴a n=2n﹣1.∴==.数列{}前n项的和T n=+…+==.【点评】本题考查了等差数列的通项公式、“裂项求和”、递推关系的应用,考查了推理能力与计算能力,属于中档题.21.若f(x)=cos2ax﹣sinaxcosax(a>0)的图象与直线y=m(m>0)相切,并且切点横坐标依次成公差为π的等差数列.(1)求a和m的值;(2)△ABC中a、b、c分别是∠A、∠B、∠C的对边.若(,)是函数f(x)图象的一个对称中心,且a=4,求△ABC周长的取值范围.【考点】正弦定理;两角和与差的正弦函数;二倍角的正弦;y=Asin(ωx+φ)中参数的物理意义.【专题】综合题;解三角形.【分析】(1)由题意,函数f(x)的周期为π,且最大(或最小)值为m,利用三角恒等变换可化简f(x),从而可求结果;(2)由(,)是函数f(x)图象的一个对称中心可求A,利用正弦定理可把周长化为三角函数,进而可求答案;【解答】解:(1)=,由题意,函数f(x)的周期为π,且最大(或最小)值为m,而m>0,,∴a=1,;(2)∵(是函数f(x)图象的一个对称中心,∴,又∵A为△ABC的内角,∴,△ABC中,则由正弦定理得:,∴,∵,∴b+c+a∈(8,12].【点评】该题考查正弦定理、两角和与差的正弦函数、倍角公式等知识,考查学生综合运用知识解决问题的能力.22.已知函数f(x)=(其中a≤2且a≠0),函数f(x)在点(1,f(1))处的切线过点(3,0).(Ⅰ)求函数f(x)的单调区间;(Ⅱ)若函数f(x)与函数g(x)=a+2﹣x﹣的图象在(0,2]有且只有一个交点,求实数a的取值范围.【考点】利用导数研究函数的单调性;利用导数研究曲线上某点切线方程.【专题】导数的综合应用.【分析】(1)利用导数的几何意义可得切线方程,对a分类讨论、利用导数研究函数的单调性即可;(2)等价方程在(0,2]只有一个根,即x2﹣(a+2)x+alnx+2a+2=0在(0,2]只有一个根,令h(x)=x2﹣(a+2)x+alnx+2a+2,等价函数h(x)在(0,2]与x轴只有唯一的交点.由,对a分类讨论、结合图象即可得出.【解答】解:(1),∴f(1)=b,=a﹣b,∴y﹣b=(a﹣b)(x﹣1),∵切线过点(3,0),∴b=2a,∴,①当a∈(0,2]时,单调递增,单调递减,②当a∈(﹣∞,0)时,单调递减,单调递增.(2)等价方程在(0,2]只有一个根,即x2﹣(a+2)x+alnx+2a+2=0在(0,2]只有一个根,令h(x)=x2﹣(a+2)x+alnx+2a+2,等价函数h(x)在(0,2]与x轴只有唯一的交点,∴①当a<0时,h(x)在x∈(0,1)递减,x∈(1,2]的递增,当x→0时,h(x)→+∞,要函数h(x)在(0,2]与x轴只有唯一的交点,∴h(1)=0或h(2)<0,∴a=﹣1或.②当a∈(0,2)时,h(x)在递增,的递减,x∈(1,2]递增,∵,当x→0时,h(x)→﹣∞,∵h(e﹣4)=e﹣8﹣e﹣4﹣2<0,∴h(x)在与x轴只有唯一的交点,③当a=2,h(x)在x∈(0,2]的递增,∵h(e﹣4)=e﹣8﹣e﹣4﹣2<0,或f(2)=2+ln2>0,∴h(x)在x∈(0,2]与x轴只有唯一的交点,故a的取值范围是a=﹣1或或0<a≤2.【点评】本题考查了利用导数研究函数的单调性极值与最值、导数的几何意义,考查了恒成立问题的等价转化方法,考查了分类讨论的思想方法,考查了推理能力与计算能力,属于难题.。
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包屯高中2015—2016学年度期中考试高二化学试题时间:90分钟总分:100分友情提醒:化学试题共分第Ⅰ卷和第Ⅱ卷两部分,请将本试卷答案按规定填入答题纸相应的位置可能用到的相对原子质量: H-1 C-12 N-14 O-16 Na-23 Mg-24 S-32 Cl-35.5第Ⅰ卷选择题一、选择题(20小题,每小题3分,共计60分)1.下列对化学反应的认识正确的是( ) A.化学反应过程中,分子的种类和数目一定发生改变B.如果某化学反应的ΔH和ΔS均小于0,则反应一定能自发进行C.化学反应过程中,一定有化学键的断裂和形成D.反应物的总焓大于反应产物的总焓时,ΔH>02、下列离子方程式正确的是 ( )A.硫酸镁溶液跟氢氧化钡溶液反应:SO2-4+Ba2+===BaSO4↓B.过量的NaHSO4与Ba(OH)2溶液反应:Ba2++2OH-+2H++SO2-4===BaSO4↓+2H2OC.铜片插入硝酸银溶液中:Cu+Ag+===Cu2++AgD.澄清石灰水中加入盐酸:Ca(OH)2+2H+===Ca2++2H2O3、下列依据热化学方程式得出的结论正确的是 ( )A.已知2H2(g)+O2(g)===2H2O(g) ΔH=-483.6 kJ· mol-1说明2 mol H2(g)和1 mol O2(g)的能量总和小于2 mol H2O(g)的能量B.已知C(s,石墨)===C(s,金刚石) ΔH>0,则金刚石比石墨稳定C.已知NaOH(aq)+HCl(aq)===NaCl(aq)+H2O(l) ΔH=-57.4 kJ·mol-1,则含20 g NaOH的稀溶液与稀盐酸完全中和,放出28.7 kJ的热量D.已知2C(s)+2O2(g)===2CO2(g) ΔH12C(s)+O2(g)===2CO(g) ΔH2,则ΔH1>ΔH24、(2011·海南高考)对于可逆反应H 2(g)+I2(g) 2HI(g),在温度一定下由H2(g)和I2(g)开始反应,下列说法正确的是 ( ) A.H2(g)的消耗速率与HI(g)的生成速率之比为2∶1B.达到平衡时,各组分的浓度相等 C.正、逆反应速率的比值是恒定的D.达到平衡时,正、逆反应速率相等5、下列实验操作或对实验事实的叙述中存在错误的是( )A.用50 mL酸式滴定管准确量取25.00 mL酸性KMnO4溶液,放入锥形瓶中待用B.室温下,测定浓度为0.1 mol·L-1 NaClO溶液和0.1 mol·L-1CH3COONa溶液的pH,比较HClO和CH3COOH的酸性强弱C.实验室配制氯化亚铁溶液时,将氯化亚铁先溶解在盐酸中,然后用蒸馏水稀释并加入少量铁粉D.配制1 mol·L-1的NaOH溶液时,下列操作会造成所配浓度偏低:定容时仰视刻度线;容量瓶中原有少许蒸馏水6、如图为PCl5(g)PCl3(g)+Cl2(g)(正反应为吸热反应)从平衡状态Ⅰ移动到平衡状态Ⅱ的反应速率(v)与时间(t)的曲线,此图表示的变化是( )A.降温B.降压C.增加PCl5的量D.增加PCl3的量7.(2011·泰安高二期末考试)下列各选项所述的两个量中,前者一定大于后者的( ) A.纯水在100℃和25℃时pH B.NH4Cl溶液中NH+4和Cl-的数目C.相同温度下,pH相同的NaOH溶液和Na2CO3溶液中由水电离出的c(OH-)D.用0.1 mol/L的盐酸中和pH、体积均相同的氨水和NaOH溶液,所消耗盐酸的体积8.在25℃时,密闭容器中X、Y、Z三种气体的初始浓度和平衡浓度如下表:下列说法错误的是( )A.反应达平衡时,X的转化率为50%B.反应可表示为:X+3Y2Z,其平衡常数为1600C.增大压强使平衡向生成Z的方向移动,平衡常数增大D.改变温度可以改变此反应的平衡常数9、(2011·重庆高考)一定条件下,下列反应中水蒸气含量随反应时间的变化趋势符合如图的是 ( )H<0A.COH>0B.COH>0C.CHD.2C6H5CH2CH3(g)+O2(g)===2C6H5CH===CH2(g)+2H2O (g) ΔH<010、下列物质的水溶液能导电,但属于非电解质的是 ( )A.CH3CH2COOHB.Cl2C.NH4HCO3D.SO211、取浓度相同的NaOH和HCl溶液,以3︰2体积比相混合,所得溶液的pH等于12,则原溶液的浓度为()A.0.01mol/LB. 0.017mol/LC.0.05mol/LD.0.5mol/L12、在pH=1时,可大量共存且形成无色溶液的一组离子或分子是()A.Ca2+、CH3COOH、Br-、Na+、B.NO3-、 Fe3+、 Mg2+、 SO42-C.H CO3-、Ba2+、Na+、Cl-D.K+、Cl-、Al3+、SO32-13、在蒸发皿中加热蒸干下列物质的溶液并灼烧,可得原有物质的固体是()A. 氯化铝B.碳酸氢镁C.硫酸亚铁D.碳酸钠14、下列关于盐酸与醋酸两种稀溶液的说法中正确的是()A.相同浓度的两溶液中相同B.100 mL 0.1mol/L的两溶液能中和等物质的量的氢氧化钠C.pH=3的两溶液稀释100倍,pH都为5D.两溶液中分别加入少量对应的钠盐,都明显减小15.下列关于沉淀溶解平衡的说法中不正确的是()A.难溶电解质在溶液中存在沉淀溶解平衡,且是一种动态平衡B. K sp只与难溶电解质的性质与温度有关,而与沉淀的量和溶液中离子的浓度无关C. K sp反映了物质在水中的溶解能力,可直接根据K sp的大小比较电解质在水中溶解能力的大小D.可通过Q和K sp的相对大小,来判断沉淀溶解平衡的移动方向16. pH=3的盐酸a L分别与下列三种溶液混合后,溶液均呈中性:①1×10-3mol·L-1的氨水b L②=1×10-3mol·L-1的氨水c L③=1×10-3mol·L-1的Ba(OH)2溶液d L。
其中a、b、c、d 的关系正确的是()A.b>a>d>cB. b>a=d>cC.a=b>c>dD. c>a=d>b17.室温时,下列混合溶液的pH一定小于7的是()A. pH=3盐酸和pH=11的氨水溶液等体积混合B. pH=3盐酸和pH=11的氢氧化钡溶液等体积混合C. pH=3醋酸和pH=11的氢氧化钡溶液等体积混合D. pH=3硫酸和pH=11的氨水溶液等体积混合18、向醋酸溶液中滴加NaOH溶液,则()A 醋酸的电离平衡向左移动B 溶液的pH减小C 醋酸根离子的物质的量减小D 醋酸的浓度减小19、下列事实可证明氨水是弱碱的是()A 氨水能跟氯化铁溶液反应生成氢氧化铁B 铵盐受热易分解C 0.1mol•L-1氨水可以使酚酞试液变红D 0.1mol•L-1氯化铵溶液的pH约为520、下列叙述正确的是()A 强电解质水溶液的导电性不一定比弱电解质强B 氯气的水溶液能导电,所以氯气属于电解质C 硫酸铜晶体含有一定量的结晶水,所以硫酸铜晶体能导电D 在一定条件下,电解质的电离都能达到电离平衡第Ⅱ卷非选择题二、填空题(4小题,共计32分)19、(4分)某温度(t℃)时,水的离子积为Kω=1×10-13mol2·L-2,则该温度(选填大于、小于或等于)25℃,其理由是。
20、(14分)常温下,将0.01 mol的NH4Cl和0.002 mol NaOH溶于水配成溶液。
(1)该溶液中存在的平衡体:;;。
(2)溶液中共有种不同的粒子。
(3)这些粒子中浓度为0.01 mol·L-1的是,浓度为0.002 mol·L-1是。
(4)物质的量之和是0.01 mol的三种微粒是:。
21、某学生用0.1mol/L KOH溶液滴定未知浓度的盐酸溶液,其操作可分解为如下几步:(A)移取20.00mL待测的盐酸溶液注入洁净的锥形瓶,并加入2-3滴酚酞(B)用标准溶液润洗滴定管2-3次(C)把盛有标准溶液的碱式滴定管固定好,调节液面使滴定管尖嘴充满溶液(D)取标准KOH溶液注入碱式滴定管至0刻度以上2-3cm(E)调节液面至0或0刻度以下,记下读数(F)把锥形瓶放在滴定管的下面,用标准KOH溶液滴定至终点,记下滴定管液面的刻度完成以下填空:(1)正确操作的顺序是(用序号字母填写)______________________.(2)上述(B)操作的目的是___________________________________。
(3)上述(A)操作之前,如先用待测液润洗锥形瓶,则对测定结果的影响是(填偏大、偏小、不变,下同)_________________________。
(4)实验中用左手控制_________(填仪器及部位),眼睛注视_______,直至滴定终点。
判断到达终点的现象是___________。
(5)若称取一定量的KOH固体(含少量NaOH)配制标准溶液并用来滴定上述盐酸,则对测定结果的影响是___________________________________。
(6)滴定结束后如仰视观察滴定管中液面刻度,则对滴定结果的影响是______。
22、(6分)下表是不同温度下水的离子积数据:试回答以下几个问题:(1)若25< t1< t2,则a 1×10-14(填“<”、“>”或“=”),由此判断的理由是:。
(2)在t1℃下,pH=10的NaOH溶液中,水电离产生的为:。
温度包屯高中2014—2015学年度期中考试高二化学试题答题卡一、选择题二、填空题(4小题,共计40分)19、(每空2分,共4分);。
20、(每空2分,共14分)(1) ;;。
(2) ; (3) ;。
(4)。
21、(每空2分,共16分)(1) ; (2) ; (3) ;(4) ;;;(5) ;(6) 。
22、(每空2分,共6分)(1) ;。
(2) 。
包屯高中2015—2016学年度期中考试高二化学试题参考答案一、选择题19.(4分,每空2分)大于;室温时水的K W=1×10-14mol2·L-2(小于1×10-13)水的电离是吸热的,升温时水的电离平衡正向移动,K W增大。
20.(14分,每空2分)(1)H2O H++OH- NH3·H2O NH4++OH-NH4++ H2O NH3·H2O+OH-(2)8 (3)Cl-、Na+(4) NH3 NH4+ NH3·H2O21.(16分,每空2分)(1)BDCEAF (2)防止将标准液稀释(3)偏大(4)滴定管活塞;锥形瓶中溶液的颜色变化;锥形瓶中溶液的颜色由无色变浅红且保持30秒内不褪色。