湖南省邵阳市二中2016届高三英语上学期第一次月考试题

合集下载

2024-2025学年邵阳市二中高三数学上学期第一次月考试卷附答案解析

2024-2025学年邵阳市二中高三数学上学期第一次月考试卷附答案解析

2024-2025学年邵阳市二中高三数学上学期第一次月考试卷时间:120分钟满分:150分2024.08一、单选题(本题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的)1.若非空集合A ,B 满足A B ⊂,U 为全集,则下列集合中表示空集的是()A.A B ⋂;B.A B ;C.A B ⋂;D.A B .2.sin40°(tan10°-3)=A.-12B.-1C.2D.-33.已知函数112y f x ⎛⎫=+ ⎪⎝⎭的定义域是[]2,4,则函数()()()ln 2f x g x x =-的定义域为()A.()2,3 B.(]2,3 C.()(]2,33,6 D.()(]2,33,4 4.下列求导数计算错误..的是()A.211x x '⎛⎫=-⎪⎝⎭B.222e e x x x x x'⎛⎫-= ⎪⎝⎭C.()ln 1ln x x x'=+ D.()21tan cos x x'=5.苏格兰数学家纳皮尔(J .Napier ,1550-1617)发明的对数及对数表(如下表),为当时的天文学家处理“大数”的计算大大缩短了时间.即就是任何一个正实数N 可以表示成10(110,Z)n N a a n =⨯≤<∈,则(lg lg 0l 1)g N n a a =+≤<,这样我们可以知道N 的位数.已知正整数31M 是35位数,则M 的值为()N23451112131415lg N0.300.480.600.701.041.081.111.151.18A.3B.12C.13D.146.一家商店使用一架两臂不等长的天平称黄金.一位顾客到店里购买10g 黄金,售货员先将5g 的砝码放在天平左盘中,取出一些黄金放在天平右盘中使天平平衡;再将5g 的砝码放在天平右盘中,再取出一些黄金放在天平左盘中使天平平衡;最后将两次称得的黄金交给顾客.你认为顾客购得的黄金()附:依据力矩平衡原理,天平平衡时有1122m L m L =,其中1m 、2m 分别为左、右盘中物体质量,1L 、2L 分别为左右横梁臂长.A.等于10gB.小于10gC.大于10gD.不确定7.如图,在ABC V 中,已知2,5,60,,AB AC BAC BC AC ==∠=︒边上的两条中线,AM BM 相交于点P ,求MPN ∠的余弦值.()A.69191B.49191C.59191D.791918.已知直线y kx b =+是曲线2(1)y x a =-+的切线,也是曲线ln 1y a x =-的切线,则k 的最大值是()A.2e B.4eC.2eD.4e二、多选题(本题共三小题,每小题6分,共18分.在每小题给出的选项中,有多项符合题目要求的.全部选对的得6分,部分选对的得部分分,有选错的得0分)9.已知函数()3113f x x x -=-,则()A.()f x 有一个零点B.()f x 的极小值为53-C.()f x 的对称中心为()0,1 D.直线=1y x --是曲线()y f x =的切线10.设点D 是ABC V 所在平面内一点,O 是平面上一个定点,则下列说法正确的有()A.若2133AD AB AC =+,则D 是BC 边上靠近B 的三等分点B.若cos cos AB AC AD AB B AC C λ⎛⎫ ⎪=+ ⎪⎝⎭,(R λ∈且0λ≠),则直线AD 经过ABC V 的垂心C.若AD xAB yAC =+ ,且x ,R y ∈,12x y +=,则BCD △是ABC V 面积的一半D.若平面内一动点P 满足AB AC OP OA AB AC λ⎛⎫ ⎪=++ ⎪⎝⎭,(R λ∈且0λ≠),则动点P 的轨迹一定通过ABC V 的外心11.设函数()()sin 0g x x ωω=>向左平移5πω个单位长度得到函数()f x ,已知()f x 在[]0,2π上有且只有5个零点,则下列结论正确的是()A.()f x 的图象关于直线2x π=对称B.在()0,2π上,方程()1f x =的根有3个,方程()1f x =-的根有2个C.()f x 在0,10π⎛⎫⎪⎝⎭上单调递增D.ω的取值范围是1229,510⎡⎫⎪⎢⎣⎭三、填空题(本大题共3小题,每小题5分,共15分)12.出入相补是指一个平面(或立体)图形被分割成若干部分后面积(或体积)的总和保持不变,我国汉代数学家构造弦图,利用出入相补原理证明了勾股定理,我国清代的梅文鼎、李锐、华蘅芳、何梦瑶等都通过出入相补原理创造了不同的面积证法证明了勾股定理.在下面两个图中,若AC b =,()BC a b a =≥,AB c =,图中两个阴影三角形的周长分别为1l ,2l ,则12l l a b++的最小值为________.13.某时钟的秒针端点A 到中心点O 的距离为5cm ,秒针均匀地绕点O 旋转,当时间0t =时,点A 与钟面上标12的点B 重合,将A ,B 两点的距离()cm d 表示成()s t 的函数,则d =______其中[]0,60t ∈.14.如图,在边长为1的正方形ABCD 中,E 为AB 的中点,P 点在正方形内(含边界),且AP AB →→=.①若BP AB →→=,则AP BP →→⋅的值是_______;②若向量AC DE AP λμ→→→=+,则λμ+的最小值为________.四、解答题(本题共5小题,共77分,解答应写出文字说明,证明过程或演算步骤)15.在ABC 中,内角,,A B C 的对边分别为s s ,且(12sin sin cos )sin cos B A C b a C B -=.(1)求ba的值;(2)若6a =,点D 是线段BC 上的一点,CAD BAD ∠=∠,DA DC =,求cos C 的值.16.如图所示,正方形11AA D D 与矩形ABCD 所在平面互相垂直,22AB AD ==,点E 为AB 的中点.(1)求证:1//BD 平面1A DE ;(2)在线段AB 上是否存在点M ,使二面角1D MC D --的平面角的大小为π4?若存在,求出AM 的长;若不存在,请说明理由.17.已知函数()()e 1ln xf x a x x x=--+,其导函数为()f x '.(1)若()f x 在()1,+∞不是单调函数,求实数a 的取值范围;(2)若()0f x ≥在()1,+∞恒成立,求实数a 的最小整数值.()2e 7.39≈18.已知函数() 2.f x x x a =-+(1)当2a =时,求()f x 的单调增区间;(2)若12,[0,2]x x ∃∈,使()()122f x f x ->,求实数a 的取值范围.19.如果数列{}n a 满足:1230n a a a a +++=⋅⋅⋅+且()12313N ,n a a a a n n *+++⋅⋅⋅+=≥∈,则称{}n a 为n 阶“归化”数列.(1)若某3阶“归化”数列{}n a 是等差数列,且单调递增,写出该数列的各项;(2)若某11阶“归化”数列{}n a 是等差数列,求该数列的通项公式;(3)若{}n a 为n 阶“归化”数列,求证12311111.2322n a a a a n n+++⋅⋅⋅+≤-【答案解析】1.D【分析】根据venn 图,对各个选项逐一分析,即可求得正确答案.【详解】根据venn可以看出对A ,A B A ⋂=≠∅;对B ,A B B ⋂=≠∅;对C ,A B ⋂≠∅;对D ,A B ⋂=∅.故选:D 2.B【分析】利用三角函数的切化弦及化一公式、诱导公式化简即可求解.【详解】解:sin 40(tan10︒︒-sin10sin 40(cos10︒=︒-︒sin10sin 40·cos10︒︒=︒︒132sin 40(sin10cos10)22cos10︒︒-︒=︒2sin 40sin(1060)cos10︒︒-︒=︒2sin 40sin 50cos10-︒︒=︒sin 40cos 402cos10-︒︒=⨯︒sin801cos10︒=-=-︒故选B.【点睛】本题主要考查了三角函数的切化弦及化一公式、诱导公式的综合应用.3.A【分析】由函数定义域的概念及复合函数定义域的求解方法运算求解即可.【详解】因为函数112y f x ⎛⎫=+ ⎪⎝⎭的定义域是[]2,4,所以24x ≤≤,所以12132x ≤+≤,所以函数()f x 的定义域为[]2,3,所以要使函数()()()ln 2f x g x x =-有意义,则有232021x x x ≤≤⎧⎪->⎨⎪-≠⎩,解得23x <<,所以函数()()()ln 2f x g x x =-的定义域为()2,3.故选:A.4.B【分析】利用导数的运算法则及简单复合函数求导法则计算即可.【详解】解:A .1211()()x x x-''==-,正确,不符合题意;B .22222e e 2(e (e )e x x x x xx x x x x --'==,错误,符合题意;C .(ln )ln (ln )ln 1x x x x x x x '''=⋅+⋅=+,正确,不符合题意;D .22222sin (sin )cos sin (cos )cos sin 1(tan )()cos cos cos cos x x x x x x x x x x x x''-⋅+''====,正确,不符合题意.故选:B .5.C【分析】根据所给条件列出不等式,结合对数的运算即可求解.【详解】由题意可知3431351010M ≤<,两边同时取对数可得3431lg 35M ≤<,所以3435lg 3131M ≤<,故3435lg 3131M ≤<,则1.09lg 1.13M ≤<,由表中数据可知13M =,故选:C 6.C【分析】设天平左臂长1x ,右臂长2x ,且12x x ≠,根据已知条件求出1a 、2a 的表达式,利用基本不等式比较12a a +与10的大小关系,即可得出结论.【详解】设天平左臂长1x ,右臂长2x ,且12x x ≠,设天平右盘有1a 克黄金,天平左盘有2a 克黄金,所以11221255x a x a x x =⎧⎨=⎩,所以1125x a x =,2215x a x =,则1212215510x x a a x x +=+>.故选:C .7.B【分析】先求三角形中线AM ,BN 的长度,根据三角形重心的性质求得PA ,PB ,在PAB 中,利用余弦定理求APB ∠的余弦,即为所求结果.【详解】因为25cos 605AB AC ⋅=⨯⨯︒=,24AB = ,225AC = .因为()12AM AB AC =+ ⇒AM =2==12BN AC AB =-⇒BN =212==.由P 为ABC V 的重心,所以23933PA AM ==,22133PB AN ==.在PAB 中,由余弦定理,得:222cos cos 2PA PB ABMPN APB PA PB+-∠=∠=⋅392149933+-=49191=.故选:B【点睛】关键点点睛:熟悉三角形重心得性质是解决问题得关键.8.B【分析】设切点分别为211(,(1))x x a -+和22(,ln 1)x a x -,则()()12f x g x k ''==,根据题意转化为211n02l a x x a +=有解,设()2112ln h a a a x x +=,求得()11ln ln(2)h a a x '=+-,得出函数的单调性和极小值12(e x h ,结合12()0exh ≤,即可求解.【详解】因为y kx b =+是()2(1)f x x a =-+和()ln 1g x a x =-的公切线,设切点分别为211(,(1))x x a -+和22(,ln 1)x a x -,则()()12f x g x k ''==,由()2(1)f x x a =-+,可得()2f x x '=,则()112k f x x '==又由()ln 1g x a x =-,可得()a g x x'=,且0x >,则()22a k g x x '==,所以2211221ln 2a x x a a x k x x x -+===-,可得211111ln222aa x a x x k ax x -+==-,即211n02l ax x a +=,显然1,a x 同号,不妨设10,0a x >>,设()2112lnh a a ax x +=,(其中10,0a x >>),可得()11ln ln(2)h a a x '=+-,令()0h a '=,可得12ex a =,当12(0,e x x ∈时,()0h a '<,()h a 单调递减;当12(,)exx ∈+∞时,()0h a '>,()h a 单调递增,要使得()0h a =有解,则需要12(0e x h ≤,即211111222e (ln 0e e 2x x x x x h =+≤即21120e x x -+≤,解得12e x ≤,所以142e k x =≤,即k 的最大值为4e.故选:B.【点睛】方法技巧:对于利用导数研究不等式的恒成立与有解问题的求解策略:1、通常要构造新函数,利用导数研究函数的单调性,求出最值,从而求出参数的取值范围;2、利用可分离变量,构造新函数,直接把问题转化为函数的最值问题.3、根据恒成立或有解求解参数的取值时,一般涉及分离参数法,但压轴试题中很少碰到分离参数后构造的新函数能直接求出最值点的情况,进行求解,若参变分离不易求解问题,就要考虑利用分类讨论法和放缩法,注意恒成立与存在性问题的区别.9.ABD【分析】对于A ,由函数求导后,由导数的正负可求出函数的单调区间,再结合零点存在性定理分析判断,对于B ,由选项A 的得到函数的单调区间分析判断,对于C ,令()313h x x x =-,可判断()h x 的图象关于原点对称,从而可判断出()f x 的对称中心,对于D ,利用导数的几何意义分析判断即可.【详解】对于A ,由()3113f x x x -=-,得()()()2111f x x x x =-=+-',令()0f x '<,得11x -<<;令()0f x '>,得1x <-或1x >,则函数()f x 在()1,1-上单调递减,在()(),1,1,-∞-+∞上单调递增,且()()()1510,10,35033f f f -=-<=-<=>,所以当1x ≤时,()()10f x f ≤-<,当1x >时,()f x 存在唯一零点,故函数()f x 在R 上只有一个零点,故A 正确;对于B ,由选项A 可知,函数()f x 的极小值为()513f =-,故B 正确;对于C ,令()313h x x x =-,定义域为R ,则()()313h x x x h x -=-+=-,所以函数()h x 为奇函数,对称中心为()0,0,将函数()h x 图象向下平移1个长度单位,得函数()f x 的图象,所以()f x 的对称中心为()0,1-,故C 错误;对于D ,由选项A 知,()21f x x '=-,令()10f x x =-⇒=',又()01f =-,所以切线方程为()10y x +=--,即=1y x --,所以直线=1y x --是曲线()y f x =在点()0,1-处的切线,故D 正确,故选:ABD.【点睛】关键点点睛:此题考查导数的综合问题,考查利用导数解决函数零点问题,考查导数解决函数极问题,考查导数的几何意义,解题的关键是对函数求导,然后由导数的正负求出函数的单调区间,再分析判断,考查计算能力,属于较难题.10.ABC【分析】对于A ,化简等式成13BD BC = ,即可判断;对于B ,将等式两边与BC作点乘,化简得出结果为0即可判断;对于C ,利用平面向量基本定理推出三点共线,结合图形和共线向量即得结论;对于D ,化简向量等式,利用单位向量作出00AB DC 即得菱形,推得AP AD λ=,即得结论.【详解】对于A ,由2133AD AB AC =+ 可得,)13311(3AD AB AB AC AC AB =--=-+,即得13BD BC =,故点D 是BC 边上靠近B 的三等分点,故A 正确;对于B ,因()cos cos AB AC AD AB B AC C λ=+,则()()cos cos cos cos AB AC AB BC AC BC AD BC BC AB B AC C AB B AC C λλ⋅⋅⋅=+⋅=+cos cos ()()0cos cos AB BC B AC BC C BC BC AB B AC Cλλ-⋅⋅=+=-+=,即AD BC ⊥,故直线AD 经过ABC V 的垂心,即B 正确;对于C ,因AD xAB yAC =+ ,12x y +=,则222AD x AB y AC =+ ,设2AM AD =,则22AM x AB y AC =+ ,因221x y +=,故,,M B C 三点共线,如图1所示,12DM AM =,故DBC △的BC 边上的高是ABC V 的BC 边上的高的一半,故BCD △是ABC V 面积的一半,即C 正确;对于D ,由()AB AC OP OA AB AC λ=++ 可得,()AB AC AP AB ACλ=+,如图2,取00,||||AB AC AB AC AB AC ==,则有00||||1AB AC ==,以00,AB AC 为两邻边作00AB DC ,易知00AB DC 是菱形,故AD 平分BAC ∠,且00AD AB AC =+ 故得,AP AD λ=,故动点P 的轨迹为BAC ∠的平分线,即动点P 的轨迹一定通过ABC V 的内心,故D 错误.故选:ABC.【点睛】关键点点睛:本题主要考查平面向量的线性运算和数量积的应用,属于难题.对于向量等式,要结合图形,和选项的启发,有时从构造平面向量基本定理的条件入手;有时通过与其他向量的点乘为0判断线线垂直;有时通过两单位向量的和作平行四边形,推得菱形.11.CD【分析】根据函数的零点的个数,求出参数ω的范围,再判断函数的单调性、对称性和方程根的个数.【详解】由题意,()sin ()sin()55f x x x ππωωω=+=+,由题意,2x π=不一定是函数的对称轴,所以A 错误;当[0,2]x πÎ时,得[,2555x πππωωπ+∈+,故5265ππωππ≤+<;1229510ω≤<,所以D 正确.因为5265ππωππ≤+<,则()1f x =的根分别可由52x ππω+=或552x ππω+=或952x ππω+=求出,共有3个根;当115252πππωπ≤+≤时,()1f x =-的根分别可由352x ππω+=或752x ππω+=求出,共2个根;当112625ππωππ<+<时,()1f x =-的根分别可由352x ππω+=或752x ππω+=或1152x ππω+=求出,共3个根;所以B 错误;当(0,10x π∈时,得(,)55105x ππωππω+∈+,由1229510ω≤<,得1149[,10525100ωππππ+∈,所以1052ωπππ+<,此时()f x 在(0,10π上单调递增,所以C 正确.故选:CD.【点睛】本题重点考查三角函数()sin()f x A x ωϕ=+的图象与性质,难度较大,做题时注意利用整体法判断:即通过将x ωϕ+作为整体,借助sin y x =的图象和性质来进行判断.12.12+【分析】根据图形中的相似关系先表示出12l l +,然后利用基本不等式求解出最小值.【详解】如图1,易知BDE V ∽ACB △,且BD CD BC b a =-=-,所以1l BD b a AC b a b c -==++,所以()1b al a b c b -=⨯++;如图2,易知GFH ∽ACB △,且FG a =,所以2l FG a AC b a b c ==++,所以()2al a b c b=⨯++,所以1211l l a b c a b a b a b +++==+=++++1=,又因为222a b ab +≥,所以2221ab a b +≤,当且仅当a b =时取等号,所以12112l l a b +≥+=++,所以最小值为12+,故答案为:12+.13.πt10sin60,[]0,60t ∈【分析】可以求出π30t AOB ∠=,从而由余弦定理可以得到d =即可化简得πt10sin 60.【详解】如图,πt 2π=6030t AOB ∠=⋅;在AOB V 中,由余弦定理得,由[0t ∈,60]知,πsin 060tππt 52sin 10sin 6060t AB d =====⨯=故答案为:πt10sin 60.14.①.12##0.5②.12##0.5【分析】①由题知ABP 是边长为1的等边三角形,进而根据向量数量积求解即可;②考虑到该题为高一题目,不能使用导数,故提供了另一种解法,法二仅供参考.法一:结合图像,作AF DE →→=,连接PF ,设1PF AC C ⋂=,利用1A C C 、、三点共线可得1AC AF t AP t →→→=+μλ,又1P C F 、、三点共线,故可得1t+=λμ,因此只需要考虑t 值最大的情况即可得到λμ+的最小值.法二:由题知点P 的轨迹为以A 为圆心,AB 为半径的圆在正方体ABCD 内的圆弧部分,进而建立直角坐标系,设点()cos ,sin ,0,2P πααα⎡⎤∈⎢⎣⎦,再利用向量坐标运算得2sin 2cos 3,2cos sin 2cos sin ααλμαααα-==++,进而构造函数,利用导数研究函数最值即可得答案.【详解】解:①因为AP AB →→=,BP AB →→=,所以ABP 是边长为1的等边三角形,所以1cos ,11cos 32AP BP AP BP AP BP π⋅=⋅=⨯⨯=.②法一:如图,作AF DE →→=,连接PF ,设1PF AC C ⋂=,由于1A C C 、、共线,不妨设1AC t AC=,又AC DE AP λμ→→→=+故1t A D t t t t C AC E AP DE AP AF AP t →→→→→→→→⎛⎫==+=+=+ ⎪⎝⎭μλλμλμ,又由于1P C F 、、共线,所以1t t =+λμ,故1t+=λμ,结合图像可知,当P B 、两点重合时,PF AC 、交于2C 处,此时t 值最大,易知//BC AG ,故1max 2AC AGt AC BC===,故()min max 112t =+=μλ..法二:因为AP AB →→=,所以点P 的轨迹为以A 为圆心,AB 为半径的圆在正方体ABCD 内的圆弧部分,所以以点A 为坐标原点,如图建立坐标系,因为正方体ABCD 的边长为1,所以设点()cos ,sin ,0,2P πααα⎡⎤∈⎢⎥⎣⎦,()()()10,0,1,1,0,1,,02A C D E ⎛⎫⎪⎝⎭,所以由AC DE AP λμ→→→=+得()()11,1,1cos ,sin 2λμαα⎛⎫=-+ ⎪⎝⎭,所以11cos 21sin λμαλμα⎧=+⎪⎨⎪=-+⎩,解得2sin 2cos 3,2cos sin 2cos sin ααλμαααα-==++,所以2sin 2cos 32sin 2cos 32cos sin 2cos sin 2cos sin ααααλμαααααα--++=+=+++,令()2sin 2cos 33sin 31,0,2cos sin 2cos sin 2f αααπαααααα-++⎡⎤==-+∈⎢⎥++⎣⎦,所以()()266sin 3cos '0,22cos sin f ααπαααα+-⎡⎤=∈⎢⎥⎣⎦+因为0,2απ⎡∈⎤⎢⎥⎣⎦,所以66sin 3cos 0αα+->,所以()()266sin 3cos '02cos sin f ααααα+-=>+在区间0,2απ⎡∈⎤⎢⎥⎣⎦恒成立,所以函数()f α在区间0,2π⎡⎤⎢⎥⎣⎦单调递增,所以()min23122f α-+==,所以λμ+的最小值为12.故答案为:12;12..【点睛】本题考查向量坐标运算,数量积运算,导数求解函数最值,考查运算求解能力,是难题;本题第二空解题的关键在于灵活利用向量共线的性质与结论,将λμ+转化为1t 1AC t AC ⎛⎫=⎪⎝⎭,进而考虑特殊位置点即可;而法二,将利用了导数的知识,根据题意设点()cos ,sin ,0,2P πααα⎡⎤∈⎢⎣⎦,进而利用坐标运算得2sin 2cos 3,2cos sin 2cos sin ααλμαααα-==++,再结合函数性质求解最值即可.15.(1)36b a =(2)cos 3C =【分析】(1)由正弦定理及三角恒等变换即可求解;(2)由,ADB ADC 的面积比值得AB BD AC CD=(角平分线定理),设(0)AB BDm m AC CD ==>,则AB =,61m BD m =+,61CD m=+,再通过余弦定理列式即可求解.【小问1详解】因为(12sin sin cos )sin cos B A C b a C B -=,由正弦定理得(12sin sin cos )sin sin sin cos B A C B A C B -=,所以212sin sin sin cos sin cos sin sin (sin cos cos sin )B AC B A C B A C B C B =+=+2sin sin()sin sin(π)sin A B C A A A =+=-=.即2212sin sin B A =,由正弦定理得2212b a =,又0a >、0b >,则36b a =或36b a =-(舍去).所以36b a =.【小问2详解】因为CAD BAD ∠=∠,设ABC V 中BC 边上的高为h ,所以11sin 2211sin 22ADB ADC AD AB BAD BD hS S AD AC CAD CD h ⋅∠⋅==⋅∠⋅ ,所以AB BDAC CD =,设(0)AB BDm m AC CD==>,由6a =,6b a =,6BD CD BC +==,所以b =,则AB =,61m BD m =+,61CD m=+,在ABC V 中,由余弦定理得222222cos2CA CB AB C CA CB +-==⋅,设AC 的中点为E ,连接DE ,如图所示,由DA DC =,则DE AC ⊥,在Rt CED 中,3(1)cos 12CE m C CD +==,所以222)12m +=解得3m =或4m =-(舍去),所以cos 3C =.16.(1)证明见解析(2)存在,2AM =-【解析】【分析】(1)由面面垂直的性质得1DD ⊥平面ABCD ,以D 为坐标原点,1,,DA DC DD 所在直线分别为x 轴、y 轴、z 轴,建立空间直角坐标系,求出平面1A DE 的法向量、1BD,利用11BD n ⊥ 可得答案;(2)假设在线段AB 上存在点M ,设()()001,,002M y y ≤≤,求出平面1D MC 、平面MCD 的一个法向量,由二面角的向量求法可得答案.【小问1详解】平面11AA D D ⊥平面ABCD ,平面11AA D D ⋂平面ABCD AD =,11,⊥⊂DD AD DD 平面111,AA D D DD ∴⊥平面ABCD ,则以D 为坐标原点,1,,DA DC DD 所在直线分别为x 轴、y 轴、z 轴,建立如图所示的空间直角坐标系D xyz -,则()()()()()()110,0,0,0,2,0,1,0,1,0,0,1,1,2,0,1,1,0D C A D B E .()()11,0,1,1,1,0DA DE ∴==,设平面1A DE 的法向量为1 =1,1,1,则11111110n DA x z n DE x y ⎧⋅=+=⎪⎨⋅=+=⎪⎩ ,令11x =,解得:()1111,1,1,1,1y z n =-=-∴=--,又()1111,2,1,0BD BD n =--∴⋅= ,即11BD n ⊥ ,又1⊄BD 平面11//,∴A DE BD 平面1A DE ;【小问2详解】假设在线段AB 上存在点M ,使二面角1D MC D --的大小为π4.设()()001,,002M y y ≤≤,则()()011,2,0,0,2,1MC y D C =--=-.设平面1D MC 的一个法向量为()2222,,n x y z =,则()222021222020n MC x y y n D C y z ⎧⋅=-+-=⎪⎨⋅=-=⎪⎩ ,令21y =,解得:()202202,2,2,1,2x y z n y =-=∴=-,又平面MCD 的一个法向量为()10,0,1D D =-,212121πcos cos ,42n D D n D D n D D⋅∴=⋅==,即200410yy -+=,解得:02y =-或02y=+(舍去),此时2AM =,∴在线段AB 上存在点M ,使二面角1D MC D --的平面角的大小为π4,此时2AM =.17.(1)(),e -∞-(2)7-【分析】(1)求出函数的导数,根据题意可知'在1,+∞有变号零点,由此结合函数的单调性,解不等式即可求得答案;(2)法一:采用分离参数法,将原不等式变为即为2e ln xa x x x x ≥-+在1,+∞恒成立,构造函数()2e ln xm x x x x x=-+,求函数的导数,利用导数求其最小值,即可求得答案;法二:求函数()()e 1ln xf x a x x x=--+的导数,利用导数判断其单调性,求得函数最小值,结合解不等式即可求得答案.【小问1详解】()()()()()22e 11e 1e 111x x xx a x x ax x x f x a x x x x ⎛⎫-+ ⎪--+-⎛⎫⎝⎭=--+== ⎪⎝⎭';因为()f x 在1,+∞不是单调函数,所以'在1,+∞有变号零点;因为10x x ->恒成立,令()e xg x a x=+,则()g x 在1,+∞有变号零点;因为()()21e 0xx g x x-'=>,所以()g x 在1,+∞单调递增,因为()1e g a =+,当x 的值趋近正无限大时,exx趋近于正无限大,a 为待定的参数,故()g x 趋近于正无限大,故只需e 0a +<,即e a <-,所以实数a 的取值范围是(),e ∞--.【小问2详解】(法一)令()1ln (1)x x x x ϕ=-+>,因为()110x xϕ'=-<在1,+∞恒成立,所以在1,+∞单调递减,所以()()10x ϕϕ<=,所以()0f x ≥在1,+∞恒成立,即为2e ln xa x x x x ≥-+在1,+∞恒成立,令()2e ln xm x x x x x=-+,则()()()222e ln 12ln 1ln xm x x xx x x x x xx x=-+-+--'-+()()()22e 1ln 2ln xx x x x xx x=⋅--+-+,令()ln 2h x x x =-+,则()110h x x-'=<在1,+∞恒成立,所以ℎ在1,+∞单调递减;因为()()110,4ln420h h =>=-<;所以ℎ有唯一零点0x ,且()0200001,4,ln 2,e ex x x x x ∈=-∴=当()01,x x ∈时,ℎ>0,即()0m x '>,所以()m x 在()01,x 单调递增;当∈0,+∞时,ℎ<0,即()0m x '<,所以()m x 在()0,x ∞+单调递减;所以()()220max02200000000e e ()e 7.39ln 2x x m x m x x x x x x x x x ====-≈--+-+-;所以实数a 的最小整数值为7-.(法二)()()e 1x x a x f x x⎛⎫-+ ⎝'⎪⎭=由(1)得,当e a -≥时,()f x 在1,+∞上单调递增,所以()()1e 0f x f >=>成立.当e a <-时,存在()01,x ∞∈+,使得()0e 0,xf x a x ==-'当()01,x x ∈时,'<0,当∈0,+∞时,'>0,所以()f x 在()01,x 上单调递减,在()0,x ∞+上单调递增;所以()()()000min0000e ()1ln 1ln 2ln e x x x f x f x a x x a a a a x ⎛⎫⎡⎤==--+=--+=--- ⎪⎣⎦⎝⎭,令()2ln 0a a ⎡⎤---≥⎣⎦得()ln 2a -≤;解之得2e e a -≤<-.综上,2e 7.39a ≥-≈-,所以实数a 的最小整数值为7-.【点睛】方法点睛:解决不等式恒成立问题,常用方法有:(1)将原不等式变形整理,分离参数,继而构造函数,转化为求解函数的最值问题解决;(2)直接构造函数,求导数,求解函数的最值,使得最小值恒大于(或大于等于)0或恒小于(或小于等于)0,解不等式即可.18.(1)单调递增区间为(),1-∞和()2,+∞(2)(,1))-∞⋃+∞【分析】(1)根据已知及分段函数,函数的单调性与单调区间的计算,求出()f x 的单调增区间;(2)根据已知及二次函数的性质求最值,结合不等式和绝对值不等式的计算求出实数a 的取值范围.【小问1详解】当2a =时,()2222,22222,2x x x f x x x x x x ⎧-+≥=-+=⎨-++<⎩,2x ≥时,()f x 单调递增,2x <时,()f x 在(),1∞-上单调递增,在()1,2上单调递减,所以()f x 的单调递增区间为(),1∞-和()2,∞+,【小问2详解】12,[0,2]x x ∃∈,使()()122f x f x ->所以()()12max 2f x f x ->,即()()max min 2f x f x ->,①当2a ≥时,()22f x x ax =-++,对称轴2a x =,(i)当122a ≤≤即24a ≤≤时,()2max 224a a f x f ⎛⎫==+ ⎪⎝⎭,()()min 02f x f ==,所以()20224a a f f ⎛⎫-=> ⎪⎝⎭,所以a >a <-,因为24a ≤≤,所以4a <≤,(ii)当22a>即4a >时,()()max 222f x f a ==-,()()min 02f x f ==,所以()()20242f f a -=->,3a >,因为4a >,所以4a >,②当0a ≤时,()22f x x ax =-+,对称轴02a x =<,所以()()max 262f x f a ==-,()()min 02f x f ==,所以()()20422f f a -=->,1a <,所以0a ≤,③当02a <<时,()222,02,2x ax x a f x x ax a x ⎧-++<<=⎨-+<<⎩,因为()()()min 02f x f f a ===,因为()220124a a f f ⎛⎫-=< ⎪⎝⎭,所以2a f ⎛⎫ ⎪⎝⎭不可能是函数的最大值,所以()()max 262f x f a ==-,所以()()20422f f a -=->,所以01a <<,综上所述:a 的取值范围是(,1))-∞⋃+∞.【点睛】关键点点睛:本题主要考查了分段函数,函数的单调性与单调区间,函数的最值,不等式和绝对值不等式的应用,属于较难题,解题的关键是将12,[0,2]x x ∃∈,使()()122f x f x ->,转化为()()max min 2f x f x ->,然后分类利用二次函数的性质求出其最值即可,考查了分类思想和计算能力19.(1)11,0,22-(2)6,(N ,11)30n n a n n +-=-∈≤(3)证明见解析【分析】(1)设123,,a a a 成公差为r 的等差数列,显然0r >,由1230a +a +a =得到11330,0a r a +=<,2310,0,a a a ==->由123++=1a a a 得到112a =-,得到答案;(2)设公差为d ,根据等差数列求和公式得到60a =,当0d =,0d >和0d <,求出首项和公差,得到通项公式;(3)设12,,p i i i a a a ,为i a 中所有大于0的数,12m j j j a a a ,,,为j a 中所有小于0的数,故1212p i i i a a a = ++,1212m j j j a a a =- ++,所以12111111111222k k kk p p m m i j n i j k k k k k k a a a a a a a n i j n n====+=+≤+=-∑∑∑∑ ++.【小问1详解】设123,,a a a 成公差为r 的等差数列,显然0r >,则由1230a +a +a =得111330,0,0a r a r a +=∴-=>∴<,213110,20,a a r a a r a ∴=+==+=->由123++=1a a a 得121a -=,解得112a =-,∴数列11,0,22-为所求3阶“归化”数列.【小问2详解】设等差数列12311,a a a a ⋯,,,的公差为d ,因为123110a a a a ⋅⋅⋅+=+++,所以11110112da ⨯+=0,,所以150a d +=,即60a =.当0d =时,此时()12303N n a a a a n n *+++⋅⋅⋅+=≥∈,,与归化数列的条件()12313N n a a a a n n *+++⋅⋅⋅+=≥∈,相矛盾.当0d >时,由12561,02a a a a ++⋅⋅⋅+=-=,故1541522a d ⨯=-+,又150a d =+,联立解得111,306d a ==-,所以()116N ,11.63030n nn a n n +--=-+=∈≤当0d <时,由12512a a a ++⋅⋅⋅+=,60a =,同理解得111,306d a =-=,所以()116N ,1163030n n n a n n +--=-=-∈≤.综上,当0d >时,()6N ,1130n n a n n +-=∈≤;0d <当时,()6,N ,11.30n n a n n +-=-∈≤【小问3详解】由已知可得:必有0i a >,也必有0j a <({},1,2,3,,i j n ∈ ,i j ≠),设12,,p i i i a a a ,为i a 中所有大于0的数,12m j j j a a a ⋯,,,为j a 中所有小于0的数,由已知得1212p i i i X a a a =++= ,12j 12m j j Y a a a =++=- ,所以11111211111222k k k k k k k k i j n i j p m p m k ka a a a a a a n i j n n ∑∑∑∑====+++=+≤+= .【点睛】数列不等式问题,常常需要进行放缩,放缩后变形为等差数列或等比数列,在结合公式进行证明,又或者放缩后可使用裂项相消法进行求和,常常使用作差法和数学归纳法,技巧性较强.。

2016届高三上学期英语第一次月考试题(有答案)

2016届高三上学期英语第一次月考试题(有答案)

2016届高三上学期英语第一次月考试题(有答案)上饶中学2016届高三上学期第一次月考英语试题考试时间:120分钟分值:150分注意事项: 1. 本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。

2. 答题前,考生务必将自己的姓名,准考证号填写在本试卷相应的位置。

3. 全部答案在答题卡上完成,答在本试卷上无效。

4. 考试结束后,将本试卷和答题卡一并交回。

第Ⅰ卷第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。

录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从试题所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例:How much is the shirt? A. £19.15 B. £9.18 C. £9.15 答案是C。

1.What time is it now? A. 9:10 B. 9:50 C. 10:002.What does the woman think of the weather? A. It’s nice B. It’s warm C. It’s cold3.What will the man do? A. Attend a meeting B. Give a lecture C. Leave his office4.What is the woman’s opinion about the course? A. Too hard B. Worth taking C. Very easy5. What does the woman want the man to do ? A. Speak louder. B. Apologize to her. C. Turn off the radio. 第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。

湖南省邵阳市第二中学2022-2023学年高三上学期入学考试(第一次月考)英语试题

湖南省邵阳市第二中学2022-2023学年高三上学期入学考试(第一次月考)英语试题

2020级高三第一次月考总分:150分时间:120分钟出题人:Ebony审题人:Stephanie第一部分听力(共20小题:每小题1.5分,满分30分)第一节听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.How many kilos does the man weigh now?A.62.B.54.C.50.2.What does the man need to do?A.Look up a word.B.Borrow a dictionary.C.Deal with his email.3.Why does the woman need new sheets?A.The old ones were worn.B.The old ones were ugly.C.The old ones were too small.4.What are the speakers mainly talking about?A.Their futures.B.Their family.C.Their travel plans.5.What is the man mostly worried about?A.The noisy passengers.B.The safety of the airplane.C.The service of the flight attendant.第二节听下面5段对话或独白。

每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项。

听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料,回答第6、7题。

6.How many dogs do the speakers have?A.One.B.Two.C.Three.7.Why does the woman change her mind about the cat?A.She doesn’t want it to die.B.She wants more animals.C.She has enough money and room for it.听第7段材料,回答第8、9题。

湖南省邵阳市2025届高三上学期8月月考试题 英语含答案

湖南省邵阳市2025届高三上学期8月月考试题  英语含答案

邵阳市2025届高三第一次月考英语试题命题人:时间:120分钟(答案在最后)第一部分听力(共两节,满分30分)第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What color is the dress the woman is trying on?A.Yellow.B.Orange.C.Blue.2.What is the man's job probably?A.A novelist.B.A cartoonist.C.A reporter.3.What kind of occasion are the speakers probably celebrating?A.A wedding.B.A holiday.C.A birthday.4.How does the woman prefer to learn?A.By reading books.B.By watching videos.C.By using the Internet.5.Who was the man angry with?A.The cinema staff.B.The woman.C.Some other audiences.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。

每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项。

听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟,听完后,各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料,回答第6、7题。

6.What are the speakers doing?A.Having a picnic.B.Preparing a meal.C.Shopping in a supermarket.7.What did the man want to eat at first?A.A salad.B.A sandwich.C.Noodles.听第7段材料,回答第8至10题。

湖南省邵阳市二中高三英语上学期第一次月考试题

湖南省邵阳市二中高三英语上学期第一次月考试题

邵阳市二中高三第一次月考试题英语第I卷第一部分听力(共两节,满分30分)第一节(共5小题;每小题l .5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、c三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有l0秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What do we know about the man?A. He slept late last nightB..He didn’t sleep wel l last night.C. He didn’t win the game.2. What is Tom doing?A. He is doing his homework.B.He is sleeping.C. He is helping his mother.3. What does Mike mean?A. He wants to have a rest for a few days.B. The final exams were easy.C. It’s to o early for him to make plans.4. What does the man mean at the end of the conversation?A. He already has a roommate.B. He dislikes having a roommate.C. He is glad to have a roommate.5. What does the woman ask the man to do?A. To buy a bottle of wine for her.B. To come to her home for supper.C. To come to her home for a meeting.第二节(共15小题;每小题1. 5分,满分22 .5分)听下面5段对话或独自。

【英语】湖南省邵东三中2016届高三第二次月考

【英语】湖南省邵东三中2016届高三第二次月考

2016届高三第二次月考英语试卷(120分钟150分)第Ⅰ卷第一部分听力(共两节, 满分30分)第一节(共5小题; 每小题1. 5分, 满分7. 5分)听下面5段对话。

每段对话后有一个小题, 从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。

听完每段对话后, 你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What language is the woman’s brother learning ?A. French.B. German.C. Russian .2. When will the man’s flight take off?A. At 11:10 a.m.B. At 10 a.m .C. At 9:30 a.m.3. What are the two speakers talking about?A. Habits.B. Hobbies .C. Customs .4. Where does the man probably come from?A. America .B. China .C. Japan .5. What are the two speakers talking about?A. A building.B. A film .C. A book.第二节(共15小题; 每小题1. 5分, 满分22. 5分)听下面5段对话或独白。

每段对话或独白后有几个小题, 从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。

听每段对话或独白前, 你将有时间阅读各个小题, 每小题5秒钟; 听完后, 各小题给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料, 回答第6、7题。

6. What does the woman think of smoking?A. Acceptable .B. Intolerable .C. Cool .7. Why do smokers stand around the building’s entrance smoking?A. They aren’t allowed to smoke in the office.B. They don’t want to do harm to others.C. It’s too early to go into the office.听第7段材料, 回答第8、9题。

高三英语月考试题及答案-邵东三中2016届高三第一次月考

高三英语月考试题及答案-邵东三中2016届高三第一次月考

邵东三中2016届高三第一次月考英语试题第Ⅰ卷(选择题满分100分)第一部分听力(共两节,满分30分)第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10称钟的时间来回答有关小题如阅读下一小题。

每段对话仅读一遍。

1.What does the man want to do?A. Take photos.B. Buy a camera.C. Help the woman.2. What are the speakers talking about?A.A noisy night.B. Their life in town.C.A place of living.3. Where is the man now?A. On his way.B. In a restaurant.C. At home.4. What will Celia do?A. Find a player.B. Watch a game.C. Play basketball.5. What day is it when the conversation takes place?A. Saturday.B. Sunday.C. Monday.第二节(共15小题:每小题1.5分,满分22.5分)听下面5段对话或独白。

每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项。

每段对话或独白读两遍。

听第6段材料,回答6、7题。

6. What is Sara going to do?A. Buy John a gift.B. Give John a surprise.C. Invite John to France.7. What does the man think of Sara’s plan?A. Funny.B. Exciting.C. Strange.听第7段材料,回答第8、9题。

湖南省邵阳市二中2016-2017学年高二上学期十二月月考英语试卷(解析,听力无答案)

湖南省邵阳市二中2016-2017学年高二上学期十二月月考英语试卷(解析,听力无答案)

2016年邵阳市二中高二上学期十二月月考试卷英语(时间:120分钟分值:120分)命題、制卷:陈小红2016.12.10第Ⅰ卷第一部分听力(共两节, 满分30分)第一节(共5小题; 每小题1. 5分, 满分7. 5分)听下面5段对话。

每段对话后有一个小题, 从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。

听完每段对话后, 你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What does the man want to do?A. Take photos.B. Buy a camera.C. Help the woman.2. What are the speakers talking about?A. A noisy night.B. Their life in town.C. A place of living.3. Where is the man now?A. On his way.B. In a restaurant.C. At home.4. What will Celia do?A. Find a player.B. Watch a game.C. Play basketball.5. What day is it when the conversation takes place?A. Saturday.B. Sunday.C. Monday.第二节(共15小题; 每小题1. 5分, 满分22. 5分)听下面5段对话。

每段对话后有几个小题, 从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。

听每段对话前, 你将有时间阅读各个小题, 每小题5秒钟; 听完后, 各小题给出5秒钟的作答时间。

每段对话读两遍。

听第6段材料, 回答第6、7题。

6. What is Sara going to do?A. Buy John a gift.B. Give John a surprise.C. Invite John to France.7. What does the man think of Sara’s plan?A. Funny.B. Exciting.C. Strange.听第7段材料, 回答第8、9题。

2016届湖南省株洲市第二中学高三上学期第一次月考英语试题

2016届湖南省株洲市第二中学高三上学期第一次月考英语试题

湖南省株洲市第二中学2016届高三上学期第一次月考英语试题本试卷分为第I卷(选择题)和第II卷(非选择题)两部分第一部分听力(共两节,满分30分)听下面5段对话。

每段对话后有一道小题,从每题所给的ABC三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What will the woman do next ?A.Walk her dog.B. Take the dog to her friends.C. Go swimming.2.Why did the man return early ?A.His mother didn’t feel well.B.He hadn’t planned the trip well.C.His mother was unhappy about his trip.3.What is the woman probably ?A.An actress.B. A writer.C. A host.4.What is the woman doing ?A.Checking in.B. Doing cleaning.C. Making a complaint.5.What are the speakers mainly talking about ?A. Work.B. Health.C. Lifestyle.第二节听下面5段对话或独白。

每段对话后有几个小题,从题中所给的三个选项中选择出最佳选项,并标在试卷的相应位置。

听完每段对话后,各小题将有5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料,回答第6、7题。

6.What does the woman think of the dress at first ?A.It’s too long.B. It’s too tight.C. It’s too expensive.7.How much will the woman pay ?A.$ 90.B. $ 63.C. $ 30.听第7段材料,回答第8至10题。

湖南省邵阳市第二中学高三英语上学期第一次月考试题(含解析)

湖南省邵阳市第二中学高三英语上学期第一次月考试题(含解析)

湖南省邵阳市第二中学2016届高三英语上学期第一次月考试题(含解析)第I卷第一部分听力(共两节,满分30分)第一节(共5小题;每小题l .5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、c三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有l0秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What do we know about the man?A. He slept late last nightB..He did n’t sleep well last night.C. He didn’t win the game.2. What is Tom doing?A. He is doing his homework.B.He is sleeping.C. He is helping his mother.3. What does Mike mean?A. He wants to have a rest for a few days.B. The final exams were easy.C. It’s too early for him to make plans.4. What does the man mean at the end of the conversation?A. He already has a roommate.B. He dislikes having a roommate.C. He is glad to have a roommate.5. What does the woman ask the man to do?A. To buy a bottle of wine for her.B. To come to her home for supper.C. To come to her home for a meeting.第二节(共15小题;每小题1. 5分,满分22 .5分)听下面5段对话或独自。

高三英语月考试题及答案-邵阳市邵阳县石齐学校2016届高三上学期第一次月考

高三英语月考试题及答案-邵阳市邵阳县石齐学校2016届高三上学期第一次月考

石齐学校2016届高三上学期第一次月考英语试题本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分,共150分。

注意事项:1.答题前,考生务必将自己的姓名、考号用铅笔涂写在答题卡上。

2.每小题选出答案后,用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动,用橡皮擦干净后,再选涂其它答案标号。

3.二卷试题用黑色中性笔作答。

第一卷(选择题共100分)第一部分:听力(共两节,满分30分)(共5小题:每小题1.5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What impressed the man about the new theater?A. The ticket price.B. The sound.C. The seats.2. What are the speakers going to do tonight?A. Go out for pizza.B. Listen to a lecture.C.Work in the garden.3. Why has the man been staying at home?A. He is out of work.B. He works at home.C. He’s been sick.4. How many students had planned to take the exam?A. 15.B. 25.C. 50.5. What does the man think of the cheese?A. It has gone bad. B .It smells better than it tastes. C. It is delicious.第二节(共15 小题;每小题1.5分,满分22.5分)听下面5段对话或独白。

湖南邵阳市2016高考英语(二轮)完形填空摸底选练(1)及答案

湖南邵阳市2016高考英语(二轮)完形填空摸底选练(1)及答案

湖南邵阳市2016高考英语(二轮)完形填空摸底选练(1)及答案完形填空In my early childhood, my parents and teachers taught me to be persistent(执着的)in every task I devoted myself to。

I was 1 that persistence is the only way towards success. But a small 2 made me change my mind。

One day my two—year-old son, 3 at a dozen of“stood”color marker-pens, cheered excitedly,“Mummy, look! I did it。

”Afterwards, he collected some ballpoint pens, 4 to do the same. Hard though he tried,the ballpoint pens just lay 5 . He turned to me for help。

Noticing they had either sharp or round ends,I said 6 ,“Mummy can't help you。

"To my surprise, he wouldn’t listen and continued trying. 。

. I was dumbfounded by his persistence.My son's behaviour reminded me of George who was always 7 in his work and rarely talked to anyone。

To him, 8 , there was no such thing called weekends or holidays。

湖南省邵阳市邵东县创新实验学校2025届高三英语上学期第一次月考试题

湖南省邵阳市邵东县创新实验学校2025届高三英语上学期第一次月考试题

湖南省邵阳市邵东县创新试验学校2025届高三英语上学期第一次月考试题(时量120分钟;满分150分)听力1. What does the woman want to do?A. Buy some furniture.B. Take a walk.C. Go downtown.2. How much will the man receive from his parents?A. $2,500.B. $3,000.C. $5,000.3. How does the man probably feel now?A. Angry.B. Upset.C. Nervous.4. Why did the man put up the fence?A. To attract passers-by.B. To decorate his garden.C. To protect his garden.5. What kind of tea does the woman usually drink?A. English tea.B. Japanese tea.C. Chinese tea.请听第6段材料,回答第6、7题。

6. Why did the woman come back late?A. She had a drink at a bar.B. She went for a drive.C. She visited her brother.7. How did the woman get home?A. In her dad’s car.B. In Mike’s car.C. In Lydia’s car.请听第7段材料,回答第8、9题。

8. What is the woman probably doing?A. Buying a jacket.B. Sending a package.C. Getting through customs.9. How many coins will the woman give to the man?1A. Three.B. Four.C. Five.请听第8段材料,回答第10至12题。

高三英语月考试题及答案-岳阳县第一中学2016届高三上学期第一次月考

高三英语月考试题及答案-岳阳县第一中学2016届高三上学期第一次月考

岳阳县一中2016届高三第一次阶段考试英语试题分值:150分时量:120分钟第I卷第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。

录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5小题:每小题1.5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What does the man advise the woman to do ?A. Clear up the room .B. See the weather report.C. Fetch no raincoat .2. Where is the conversation most probably taking place ?A. In the hotel .B. In the supermarket .C. At the book office .3. What will the woman probably do next ?A. Wash the dishes .B. Go to rest .C. Eat some food .4. Why was James sad ?A. He was afraid his team would fail in the match.B. He thought that he might be forced to leave the team.C. He was taken off the team by other members.5. What does the man mean ?A. He agrees to have a party if the woman arranges everything well.B. He doesn’t agree to have a party .C. He doesn’t like the woman’s friends .第二节(共15小题:每小题1.5分,满分22.5分)听下面5段对话或独白。

【英语】湖南省邵东三中2016届高三第二次月考

【英语】湖南省邵东三中2016届高三第二次月考

2016届高三第二次月考英语试卷(446、447)(满分:150分,时间:120分钟)第Ⅰ卷(选择题共100分)第一部分:听力(共两节,满分30分)第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有十秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. Where did the woman get the earring?A. From a family member.B. From a friend.C. From a shop.2. How many people are going on the boat?A. 4.B. 5.C. 6.3. What are the speakers doing?A. Building a house.B. Camping.C. Climbing mountains.4. Why hasn’t the woman seen the man lately?A. He has been preparing for the final exam.B. He went out of town.C. His mom didn’t let him go out.5. When did the lecture end?A. At 9:00B. At 9:30C. At 10:00第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。

每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各个小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料,回答第6、7题。

6. What was the guy who took the bag wearing?A. A sweat-shirt.B. A cap.C. A T-shirt.7. What might the woman do next?A. Look for the old lady.B. Leave her numberC. Ask some questions.听第7段材料,回答8、9题。

  1. 1、下载文档前请自行甄别文档内容的完整性,平台不提供额外的编辑、内容补充、找答案等附加服务。
  2. 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
  3. 3、如文档侵犯您的权益,请联系客服反馈,我们会尽快为您处理(人工客服工作时间:9:00-18:30)。

邵阳市二中高三第一次月考试题英语第I卷第一部分听力(共两节,满分30分)第一节(共5小题;每小题l .5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、c三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有l0秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What do we know about the man?A. He slept late last nightB..He didn’t sleep wel l last night.C. He didn’t win the game.2. What is Tom doing?A. He is doing his homework.B.He is sleeping.C. He is helping his mother.3. What does Mike mean?A. He wants to have a rest for a few days.B. The final exams were easy.C. It’s to o early for him to make plans.4. What does the man mean at the end of the conversation?A. He already has a roommate.B. He dislikes having a roommate.C. He is glad to have a roommate.5. What does the woman ask the man to do?A. To buy a bottle of wine for her.B. To come to her home for supper.C. To come to her home for a meeting.第二节(共15小题;每小题1. 5分,满分22 .5分)听下面5段对话或独自。

每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题给出5秒钟的作答时间。

每段对话或独自读两遍。

听第6段材料,回答第6至7题。

6. Who is the woman talking to?A. Her husband.B. Her neighbor.C. Her student.7. What is her husband doing?A. He is painting a picture.B. He is painting a bottleC. He is painting the sitting room.听第7段材料,回答第8至10题。

8. What is the possible relationship between the two speakers?A. Husband and wife.B. Brother and sister.C. Babysitter and master.9. What can we learn from the conversation?A. The woman is not successful in her job.B. The man is out of work.C. The woman isn’t satisfied with her life.10. What day was it yesterday? A. Monday. B. Sunday C. Tuesday听第8段材料,回答第11至13题。

11. What does Mary ask John to do?A. To help her.B. To look for their baby.C. To do somewashing.12. Where is the baby? A. In the sitting room. B. In the kitchen C. In the washroom13. What is the baby doing?A. He is playing games.B. He is watching TV.C. He is cleaning his shoes with his mother’s toothbrush.听第9段材料,回答第14至17题。

14. Why does the girl borrow money from her father?A. To see a film.B. To watch a play.C. To go to a concert.15. How much money does the girl need in all?A. Eighteen dollars.B. Thirty-six dollars.C. Fifty-four dollars.16. How many children want to go to the concert? A. One B. Two C. Three17. Who is going to get the tickets? A. Bob B. The girl C. Jenny听第10段材料,回答第18至20题。

18. Why did the man refuse to buy a TV set in the past?A. He thought it was strange.B. He thought it was a waste of time.C. He thought it was too expensive.19. Who bought him a TV set after he retired? A. His son. B. His friend. C. He himself.20. What made the man angry when watching TV?A. Eating snacks.B. Playing gamesC. Being interrupted by others.第二部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下面短文,从短文后各题所给的四个选项(A、B、C和D)中,选出可以填入空白处的最佳选项,并在答题卡上将该项涂黑。

AHealth experts have long worried about the increasing rate of obesity in kids. It’s an important concern: Being weight or obese during childhood can lead to serious problems normally seen in adults, such as diabetes and high blood pressure. Poor diets and a lack of exercise are usually the causes. But would you ever have imagined there might be a connection between the bacteria that lived in your guts (内脏)when you were a baby and the chance that you would become overweight?Scientists in Finland recently found just such a link. In a recent study, they showed that overweight kids had different species of bacteria living in their guts. You probably think of bacteria only as germs that can make you sick. While it’s true that some bacteria can make people ill, your body actually depends on some types of bacteria to help you digest food and extract nutrients from it. These “good”bacteria live in your guts, where they process the food you eat.Human babies get these bacterial helpers from their moms. When a baby is born, some of the bacteria in the mother move into the baby’s body. Growing babies get additional “good” bacteria from the milk their mothers produce. And it turns out the bacteria might play an important role in regulating weight just six years later.So how could these bacteria affect weight? The researchers still haven’t tested that question, but future tests might lead to an answer.21. The “link” in Paragraph 2 refers to the relationship between _______.A. bacteria and the chance of being overweightB. obesity and diabetesC. diets and the chance of being overweightD. bacteria and exercise22. Which of the following is NOT the function of “good” bacteria?A. Helping to digest food.B. Helping to take nutrients from food.C. Helping to regulate weight.D. Making a person ill.23. The purpose of writing this passage is to _______.A. introduce the role of bacteria in children’s weightB. analyze the influence of obesity on kidsC. give advice on how to lose weight quicklyD. explain the function of bacteria in foodsBAbout ten years ago, a young and very successful businessman named Josh was traveling down a Chicago neighborhood street. He was going a bit too fast in his shiny, black, 12 cylinder Jaguar XKE, which was only two months old.He was watching for kids rushing out from between parked cars and slowed down when he thought he saw something. As his car passed, no child came out, but a brick sailed out and —WHUMP! —it hit the Jag’s shiny b lack side door! SCREECH...!!!! Immediately Josh stopped the car, jumped out, seized the kid and pushed him up against a parked car. He shouted at the kid, "What was that all about and who are you? Just what the heck are you doing?!" Building up a head of s team, he went on. " That’s my new Jag, that brick you threw is gonna cost you a lot of money. Why did you throw it?""Please, mister, please....I’m sorry! I didn’t know what else to do!" begged the youngster. "I threw the brick because no one else would stop!" tears were streaming down the boy’s face as he pointed around the parked car. "It’s my brother, mister," he said. "He rolled of the curb (路沿) and fell out of his wheelchair and I can’t lift him up. "Sobbing, the boy asked the businessman," Would you please help me get him back into his wheelchair? He’s hurt and he’s too heavy for me.Moved beyond words, the young businessman tried hard to swallow the rapidly swelling lump in his throat. Straining, he lifted the young man back into the wheelchair and took out his handkerchief and wiped the scrapers and cuts, checking to see that everything was going to be OK. He then watched the younger brother push him down the sidewalk toward their home.It was a long walk back to the black, shining 12 cylinder Jaguar XKE — a long and slow walk. Josh never did fix the side door of his Jaguar. He kept the dent (凹痕) to remind him not to go through life so fast that someone has to throw a brick at him to get his attention. Feel for the bricks of life coming at you. w.w.w.k.s.5.u.c.o.m24. The boy threw a brick at the businessman’s car because ________.A. the businessman drove at a high speedB. he envied the brand-new car very muchC. he wanted to ask for some moneyD. he wanted to get help from the driver25. Which of the following is the right order of the story?a. The younger brother threw a brick at Josh’s car.b. The elder brother fell out of his wheelchair.c. The younger brother begged Josh for help.d. Josh lifted the elder brother back into his wheelchair.e. Josh shouted at the younger brother.A. b, a, e, c, dB. a, c, d, b, eC. b, a, c, e, dD. a, c, b, e, d26. What can we learn from the passage? w.w.w.k.s.5.u.c.o.mA. Josh would accept the money from the kids.B. The two kids were Josh’s ne ighbors.C. Josh was a kind-hearted man.D. Josh’s new car broke down easily.27. According to the passage, the last sentence means ________.A. trying to get ready for the trouble in your future lifeB. driving fast in a neighborhood street is dangerousC. trying to be more understanding seeing others in troubleD. protecting oneself from being hurtCWashoe, a female chimpanzee (黑猩猩) believed to be the first non-human to acquire human language, has died of natural causes at the research institute where she was kept.The chimp died on Tuesday night, according to Roger and Deborah Fouts, co-founders of The Chimpanzee and Human Communications Institute in Washington, where she lived.Washoe was born in 1965 in Africa, where she was captured by the Air Force and taken to the US for research use in the space program. In 1966, she left the program and began living with two scientists, Allen and Beatrix Gardner, who led a project to teach the chimp American Sign Language (ASL) in Washoe, Nevada, for which it was named. Washoe had been living on Central Washington University’s Ellensburg Campus since 1980. She had a vocabulary of about 250 words. Also, Washoe taught sign language to three younger chimps: Tatu, 31, Loulis, 29, and Dar, 31Primate (灵长类) researcher Jane Goodall, in Fouts’ book Next of Kin, noted the importance of the work with Washoe. “Roger, through his ongoing conversations with Washoe and her extended family, has opened a window into a chimpanzee’s mind,”Goodall said.Though previous efforts to teach chimps spoken languages had failed, the researchers believed there was a better chance using signs. But Washoe’s language skills were disputed by scientists who believed that language is unique to humans.Among those who doubted that chimps could use language were linguist (语言学家) Noam Chomsky and Harvard scientist Steven Pinker. They believed primates simply learn to perform certain acts in order to receive rewards, and do not acquire true language.28. As for its first task, Washoe was involved with _______.A. some space researchB. a study on African animalsC. an ASL projectD. the program of training the Air Force29. In Goodall’s opinion, teaching Washoe ASL ______.A. was not successfulB. led to the book Next of KinC. won honor for FoutsD. made a difference30. In the last paragraph, the underlined word “disputed” probably means “______”.A. supportedB. studiedC. questionedD. discussed31. What can be inferred from the passage?A. The ASL project was first set up in Africa for the study on Washoe.B. Washoe may communicate with other chimps by signing.C. Washoe must have been able to speak 250 words or so.D. The researchers will prove that most chimps could use language.D“Children who eat less salt and drink fewer sugar-sweetened soft drinks may significantly lower their risks of obesity,” researchers recently reported in the journal Hypertension.“Sugar-sweetened soft drinks are a significant source of calorie intake in children,” said Feng J. He, a researcher at St George’s University of London, England. “It has been shown that sugar-sweetened soft drink consumption is related to obesity in young people.” They wanted to know whether there is a link between salt intake and sugar-sweetened soft drink consumption.Dr He and colleagues analyzed data from a 1997 national survey of more than 2,000 people between 4 and 18 in Britain. “We found that children eating a lower-salt diet drank less fluid,” said He. “From our research, we estimated that 1 gram of salt cut from their daily diet would reduce fluid intake by 100 grams per day.” The researchers also found that children eating a lower-salt diet drank fewer sugar-sweetened soft drinks. From their research, they predicted that reducing salt intake by 1 gram each day would reduce sugar-sweetened soft drink consumption by 27 grams per day, after. “If children aged 4 to 18 cut their salt intake by half, there would be a decrease of about two sugar-sweetened soft drinks per week per child, so each child would decrease calorie intake by almost 250 kilocalories per week,”Dr He said.In previous studies, researchers found that a low-salt diet lowers blood pressure in children, and prevents the development of high blood pressure later inlife. “Both high blood pressure and obesity increase the risk of having strokes and heart attacks,” Dr He said.Dr He recommends that parents check labels and choose low-salt food products. “Small reductions in the salt content of 10 to 20 percent cannot be detected by the human salt taste receptors (感受器) and do not cause any technological or safety problems,” Dr He said.32. According to the passage, obesity is directly linked to ______.A. high-salt foodsB. sugar-sweetened soft drinksC. high blood pressureD. strokes and heart attacks33. Compared with previous studies, the recent one found that ______.A. a lower-salt diet may mean less sugar-sweetened soft drink consumptionB. a low-salt diet keeps children out of high blood pressureC. children face the risk of having strokes and heart attacksD. low-salt food products do not do harm to people’s health34. Which of the following statements would Dr He agree to?A. The less salt people eat, the healthier people become.B. Children should reduce fluid intake in their daily life.C. No high-salt food products will be available in shops.D. A low-salt diet may prevent both high blood pressure and obesity.35. After reading the passage, who should take effective action?A. Children.B. Parents.C. Doctors.D. Researchers.第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项选出能填入空白处的最佳选项。

相关文档
最新文档