广东省广州市七区2009-2010学年高一下学期期末联考(必修4)

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2020-2021学年广东省部分名校高一下学期期末联考化学试题

C.只有 D.
9.某课外活动小组的同学设计了4个喷泉实验方案，下列有关操作不可能引发喷泉现象的是
A.挤压装置① 胶头滴管使NaOH溶液全部进入烧瓶，片刻后打开止水夹
B.挤压装置②的胶头滴管使NaOH溶液进入烧瓶，片刻后打开止水夹
C.用鼓气装置从装置③的a处不断鼓入空气并打开止水夹
D.向装置④的水槽中慢慢加入浓硫酸并打开止水夹
根据所学知识，回答下列问题：
(1)写出高温煅烧生成的化学方程式：___________，其中氧化产物为___________(填化学式)。
(2)“浸取液Ⅰ”中加入的目的是___________，发生反应的离子方程式为___________。
(3)“操作Ⅰ”的名称为___________。
(4)在加入氨水沉淀时，调节pH可使得沉淀而不沉淀。“滤液Ⅱ”中溶质的主要成分为___________(填化学式)。写出获得“滤渣Ⅱ”的离子方程式：___________。
一、选择题：本题共16小题，共44分。第1~10小题，每小题2分；第11~16小题，每小题4分。在每小题给出的四个选项中，只有一项是符合题目要求的。
1.2021年4月9日，我国在太原卫星发射中心用“长征四号”乙运载火箭，成功将试验六号03星发射升空，卫星顺利进入预定轨道。试验六号03星采用太阳能电池板提供能量，制造太阳能电池板的核心材料是
19.化学反应速率与限度在生产生活中的运用广泛。
(1)某学生为了探究锌与盐酸反应过程中的速率变化，他在100 mL稀盐酸中加入足量的锌粉，用排水集气法收集反应生成的氢气(标准状况)，实验记录如下表(累计值)：
时间/min
1
2
3
4
5
氢气体积/mL
50

广州市九区联考2023-2024学年高一上学期期末教学质量监测数学试卷(解析版)

2023—2024学年第一学期期末教学质量监测高一数学本试卷共6页，22小题，满分150分，考试用时120分钟.注意事项：1.答卷前，考生务必将自己的学校、班级、姓名、考生号和座位号填写在答题卡上，再用2B 铅笔将考生号、座位号对应的信息点涂黑.2.选择题每小题选出答案后，用2B 铅笔把答题卡上对应的题目选项的答案信息点涂黑；如需改动，用橡皮擦干净后，再填涂其他答案.答案不能答在试卷上.3.非选择题必须用黑色字迹的钢笔或签字笔作答，答案必须写在答题卡各题目指定区域内相应位置上；如需改动，先划掉原来的答案，然后再写上新的答案，不准使用铅笔和涂改液.不按以上要求作答无效.4.考生必须保证答题卡的整洁.考试结束后，将试卷和答题卡一并交回.一、选择题：本题共8小题，每小题5分，共40分.在每小题给出的四个选项中，只有一项是符合题目要求的.1. 已知x ∈R ，则“210x −>”是“1x >”的（）A. 充分不必要条件B. 必要不充分条件C. 充要条件D. 既不充分也不必要条件【答案】B 【解析】【分析】由一元二次不等式的解法及充分必要条件的定义可得结果. 【详解】由210x −>解得1x >或1x <−，所以当1x >时一定有210x −>成立，反之不一定成立，所以“210x −>”是“1x >”的必要不充分条件，故选：B.2. 已知集合{}2210A x axx =−+=只有一个元素，则实数a 的值为（）A. 1或0B. 0C. 1D. 1或2【答案】A 【解析】【分析】讨论a ，当0a =时，方程是一次方程，当0a ≠时，二次方程只有一个解，Δ0=，即可求.【详解】若集合{}2210A x axx =−+=只有一个元素，则方程2210ax x −+=只有一个解，当0a =时，方程可化为210x −+=，满足题意，当0a ≠时，方程2210ax x −+=只有一个解，则440a ∆=−=，解得1a =，所以0a =或1a =. 故选：A . 3. 方程2ln 0x x−=的根所在的区间是（） A. (0,1) B. (1,2)C. (2,3)D. (3,4)【答案】C 【解析】【分析】先判断出()2ln f x x x=−在()0,∞+上单调递增，结合零点存在性定理得到结论. 【详解】由于ln y x =在()0,∞+上单调递增，12y x=−在()0,∞+上单调递增，故()2ln f x x x=−在()0,∞+上单调递增，又()2ln 210f =−<，()223ln 31033f =−>−>，故方程2ln 0x x−=的根所在的区间是(2,3). 故选：C4. 设ln 0.8a =，0.8e b =，e 0.8c =，则（） A. a b c >> B. b c a >> C. c b a >> D. b a c >>【答案】B 【解析】【分析】由指数和对数函数的性质可得a<0，1b >，01c <<.【详解】ln 0.8ln10a =<=，0.80e e 1b =>=，e 000.80.81c <=<=，所以b c a >>. 故选：B . 5. 函数()22x xxf x −=+图象大致为（） A. B.C. D.【答案】A 【解析】【分析】判断函数的奇偶性，结合函数值的正负情况，以及结合函数特殊值的计算，一一判断各选项，即得答案.【详解】函数()22x xxf x −=+的定义域为R ，且()()f x f x −=−，故()f x =则函数图象关于原点对称，则B 错误；又0x >时，()022x xxf x −=>+，故C 错误；又2282161151765(1)(2)(34848)f f f =<=>==++=，即0x >时，()22x xxf x −=+不是单调函数，D 错误，结合函数性质和选项可知，只有A 中图象符合题意，故选：A6. 函数()sin()(0,0,0π)f x A x A ωϕωϕ=+>><<在一个周期内的图像如图所示,为了得到函数π()2sin 23g x x=+的图象,只要把函数()f x 的图象上所有的点（）A. 向左平移π3个单位长度 B. 向左平移π6个单位长度 C. 向右平移π3个单位长度D. 向右平移π6个单位长度【答案】D 【解析】【分析】由函数的图象的最大值求出A ,由周期求出ω,由五点作图法求出ϕ,从而可得()f x 的解析式.再结合函数sin()yA x ωϕ+的图象平移变换规律即可得出结论.【详解】由函数()sin()(0,0,0π)f x A x A ωϕωϕ=+>><<的部分图像可得 2.A = 125πππ=, 2.2212122T πωω =×=−−∴= 再根据五点法作图可得π2π2,.1223πϕϕ×−+=∴=()2π2sin 2.3f x x∴=+故把()2π2sin 23f x x =+的图象向右平移π6个单位长度,可得()22sin 22sin 2633y x x g x πππ=−+=+=的图象. 故选：D7. 函数()log (1)log (1)a a f x x x =++−（0a >，1a ≠，x ∈ ），若max min ()()1f x f x −=，则a 的值为（）.A. 4B. 4或14C. 2或12 D. 2【答案】C 【解析】【分析】将2()log (1)log (1)log (1)a a a f x x x x =++−=−，利用换元，化为()log a g t t =，分类讨论a 的取值范围，结合函数单调性以及最值的差，列式求解，即得答案.【详解】由题意得2()log (1)log (1)log (1)a a a f x x x x =++−=−，x ∈ ，令21t x =−，则1[,1]2t ∈，则函数2()log (1)a f x x =−，即为()log a g t t =，当1a >时，()log a g t t =在1[,1]2上单调递增，由max min ()()1f x f x −=可得：1log 1log 1,22a aa −=∴=；当01a <<时，()log a g t t =在1[,1]2上单调递减，由max min ()()1f x f x −=可得：11log log 11,22aa a −=∴=；故a 的值为2或12，故选：C8. 中国茶文化博大精深.茶水的口感与茶叶类型和水的温度有关.经验表明，有一种茶90℃的水泡制，再等到茶水温度降至60℃时饮用，可以产生最佳口感.某研究人员在室温下，每隔1min 测一次茶水温度，得到数据如下：放置时间/min 0 1 2 3 4 茶水温度/℃90.0084.0078.6273.7569.39为了描述茶水温度y ℃与放置时间min x 的关系，现有以下两种函数模型供选择：①()30R,0<<1,0x y ka k a x =+∈≥，②(,R,0)y mx b m b x =+∈≥.选择最符合实际的函数模型，可求得刚泡好的茶水达到最佳口感所需放置时间大约为（参考数据：lg 20.301≈，lg 30.477≈）（）A. 5.5minB. 6.5minC. 7.5minD. 8.5min【答案】B 【解析】【分析】根据表中数据确定模型，求得解析式，当60y =，求得x 即可. 【详解】由表格中数据可得，茶水温度下降的速度先快后慢，所以选①()30R,0<<1,0xy ka k a x =+∈≥，则0130903084ka ka += +=即30903084k ka +=+= ，解得60910k a = = ，所以9603010xy =×+ ，当60y =时，可得91102x=，即9101lg 1lg 2lg 20.3012log 6.5min 92lg 912lg 31120.477lg 10x−−====≈−−−×. 故选：B .二、选择题：本题共4小题，每小题5分，共20分.在每小题给出的选项中，有多项符合题目要求.全部选对的得5分，部分选对的得2分，有选错的得0分.9. 下列命题为真命题的是（） A. 若a b >，c d >，则a c b d −>− B. 若a b >> C. 若22a b c c >，则a b > D. 若0a b >>，0m >，则a m ab m b+>+ 【答案】BC 【解析】【分析】利用特殊值可判断A ；根据幂函数13y x =的单调性可判断B ；根据不等式的性质可判断C ；利用作差法比较大小可判断D.【详解】对于A ，当2a =，1b =，4c =，1d =时，不满足a c b d −>−，故A 错误；对于B ， 13y x =在R 上单调递增，∴当a b >时，1133a b >>，故B 正确；对于C ，22a b c c>，20c ≠，两边同时乘以2c ，得a b >，故C 正确；对于D ， 0a b >>，0m >，∴()()()0b a ma m a ab bm ab am b m b b b m b b m −++−−−==<+++，即a m ab m b+<+，故D 错误. 故选：BC.10. 设x ∈R ，用[]x 表示不超过x 的最大整数，则[]y x =称为高斯函数，也叫取整函数，例如[2.3]2=.令函数()[]f xx x =−，以下结论正确的有（） A. ( 1.7)0.3f −=− B. ()f x 的最大值为0，最小值为1−C. (1)()f x f x −=D. ()y f x =与1y x =−+的图象没有交点【答案】AC 【解析】【分析】对于A 选项，代入计算出()( 1.7)[ 1.7] 1.7(2) 1.70.3f −=−−−=−+=−；C 选项，根据定义得到(1)[]()f x x x f x −=−+=，C 正确；B 选项，由C 选项得到()f x 的周期为1，并得到当0x =时，(0)0f =，当01x <<时，()(0,1)f x x =−∈，当1x =时，(1)0f =，得到最值；D 选项，画出()y f x =的图象，数形结合得到交点个数.【详解】对于A ，由题意得()( 1.7)[ 1.7] 1.7(2) 1.70.3f −=−−−=−+=−，故A 正确；对于C ，(1)[1](1)([]1)1[]()f x x x x x x x f x −=−−−=−−+=−+=，故C 正确；对于B ，由选项C 可知，()f x 是周期为1的周期函数，则当0x =时，(0)[0]00f −，当01x <<时，()[]0(1,0)f x x x x x =−=−=−∈−，当1x =时，(1)[1]1110f =−=−=，综上，()f x 的值域为(]10−，，即()f x 的最大值为0，无最小值，故B 错误；对于D ，由选项B ，可知()0,0,010,1x f x x x x ==−<< = ，且()f x 的周期为1，作出()y f x =与1y x =−+的图象，如图所示，由图象可知()y f x =与1y x =−+的图象有无数个交点，故D 错误，故选：AC ．11. 已知函数()tan f x x =，下列命题正确的是（） A. 若1()2f x =，则sin cos 15cos sin 3x x x x +=− B.不等式()f x ≥解集是π2 C. 函数2()4()yf x f x =−+，ππ,44x∈−的最小值为5− D. 若π132f x −=，且π02x <<，则πsin 6x +【答案】ACD 【解析】【分析】利用弦化切可判断A ；根据正切函数的图象与性质可判断B ；利用换元法转化为二次函数的最小值问题可判断C ；根据π132f x −=和π02x <<得到ππ033x <−<和cos 3x −π，再利用诱导公式可判断D.【详解】对于A ， 1tan 2x =，∴11sin cos tan 11215cos sin 5tan 352x x x x x x +++===−−−，故A 正确；的对于B，tan x ≥πππ,π32k k ++ ，故B 错误；对于C ，当ππ,44x∈−时，令tan t x =，[]1,1t ∈−， ∴()22424y t t t =−+=−−+，∴当1t =−时，min 5y =−，故C 正确；对于D ，若π02x <<，则πππ633x −<−<，π1032f x −=> ，∴ππ033x <−<，ππ1tan 332f x x −=−=，且22ππsin cos 133x x −+−= ，解得πcos 3x −，∴ππππsin sin cos 6233x x x +=−−=−=. 故选：ACD12. 已知函数()()22, 2,ax x af x x x a−+≥ = − ，则下列结论正确的是（） A. 当0a =时，()f x 的最小值为0B. 若()f x 存在最小值，则a 的取值范围为(,0]−∞C. 若()f x 是减函数，则a 的取值范围为(0,2]D. 若()f x 存在零点，则a的取值范围为((,(2,)−∞+∞【答案】BCD 【解析】【分析】A 选项画出草图即可；B 选项算出左右两侧函数的最值比大小即可；C 选项判断左右两侧函数的增减性即可，D 选项分四种情况讨论即可解答. 【详解】对于A 选项：当0a =时，()()22,02,0x f x x x ≥ = −< 的图像如下：故此时，min 2f =.故A 选项不对. 对于B 选项：当(,0]a ∈−∞时，()()22,2,ax x af x x x a−+≥ = −< 当2x a <<时，()()22f x x =−单减，此时()()2min 2f f a a ==−，当x a ≥时，()002a a f x ax ≤⇒−≥⇒=−+单调增，故()2min 2f f a a ==−+，因为()2210a −>；所以22420a a −+>；所以22442a a a +−>−+；即()2222a a −>−+；当(,0]a ∈−∞时，()f x 的最小值为：()22,0a a −+≤.故B 选项正确. 对于C 选项：当02a <≤时，x a <时，()()22f x x =−单减，此时()2f x ax =−+的斜率为负，故此当x a ≥时，()f x 单减，故C 选项正确.对于D 选项：此时要对a 分类讨论；分类讨论一：当2a >时，()f x 一定有零点2x =；分类讨论二：当0a =时，由A 选项可知此时无零点；分类讨论三：当02a <≤时，当x a <时，()()()220,f x f a a >=−>此时左区段无零点；当x a ≥时，函数右区段表达式为()2f x ax =−+，此时直线单减，故()2max 20f f a a ==−+≥才会有零点；解不等式22202a a a −+≥⇒≤⇒≤≤.a ≤≤与02a <≤取交集有：0a <≤；分类讨论四：当a<0时，由B 选项的讨论过程可知：此时函数图像左区段单减，左区段单增；因为2x =不在左区段的定义域内，故()()()22,f x x x a =−<区段上无零点；要使()f x 存在零点，则零点必在右区段上；即右区段的最小值必然小于等零，即()22min 202f f a a a ==−+≤⇒≥即a ≥a ≤上式再与a<0取交集有：a ≤综上所述：若()f x 存在零点，则a 的取值范围为((,(2,)∞∞−∪∪+.故D 选项正确.故选：BCD. 三、填空题：本题共45分，共20分. 13. 2328log 32ln1++=__________. 【答案】9【解析】【分析】根据指数以及对数的运算法则，即可求得答案. 【详解】223533228log 32ln12log 2ln1×++=++4509=++=，故答案为：914. 已知幂函数()y f x =的图象过点(，则12f =__________.【解析】【分析】根据幂函数的定义分析求解.【详解】设幂函数(),αα=∈f x x R ，由题意可得：1222α=，解得12α=，则()12f x x ==，所以12= f .15. 已知函数2()log (1)f x x =+，若1a b −<<，且()()f a f b =，则2a b ++的取值范围是__________.【答案】(2,)+∞【解析】【分析】去绝对值，结合对数运算及对勾函数的单调性即可求解. 【详解】函数2()log (1)f x x =+，当0x ≥时，2()log (1)=+f x x ，当10x −<<时，2()log (1)f x x =−+，则()f x 在(1,)+∞单调递增，在(1,0)−单调递减，故10a −<<，0b >，由()()f a f b =，则22log (1)log (1)a b +=+，即22log (1)log (1)a b −+=+，所以2log (1)(1)0a b ++=，即(1)(1)1a b ++=，则111b a +=+，所以12(1)(1)(1)(1)a b a b a a ++=+++=+++，令1x a =+，则01x <<，则设函数1()g x x x=+，任取12,(0,1)x x ∈，不妨设1201x x <<<，因为()()12121211g x g x x x x x −=+−−()()1212121x x x x x x −−=，当1201x x <<<，所以120x x −<，120x x >，1210x x −<，所以()()12121210x x x x x x −−>，所以()()120g x g x −>，即()()12g x g x >，所以()g x 在区间(0,1)上单调递减．则当1x →时， (1)2f →，当x →+∞时，()f x →+∞，故2a b ++的取值范围是(2,)+∞故答案为：()2,+∞ 16. 设()f x 是定义在R 上的奇函数，对任意的1x ，2(0,)x ∈+∞，12x x ≠，满足：()()2112120x f x x f x x x −>−，若(2)4f =，则不等式()20f x x −≤的解集为__________. 【答案】(](]0,2,2−∞−【解析】【分析】先得到()()f x g x x =在()0,∞+上单调递增，且()()f x g x x =为偶函数，故()()f x g x x =在(),0∞−上单调递减，分0x >与0x <两种情况，结合(2)4f =，得到不等式的解集.【详解】不妨设120x x >>，由()()2112120x f x x f x x x −>−得()()21120x f x x f x −>，即()()()()12211212f x f x x f x x f x x x >⇒>，故()()f xg x x=在()0,∞+上单调递增，因为()f x 为R 上的奇函数，所以()()f x f x −=−， ()()f x g x x =的定义域为()(),00,∞−+∞ ，且()()()()f x f x g x g x x x−−−===−−，故()()f x g x x =为偶函数，()()f x g x x=在(),0∞−上单调递减，当0x >时，()()()2022f x f x x f x x x−≤⇒≤⇒≤，因为()24f =，所以()()2222f g ==，故()()22f x x f ≤，即()()2g x g ≤，解得02x <≤，当0x <时，()()()2022f x f x x f x x x−≤⇒≤⇒≥，因为()22g =，所以()22g −=，故()()2g x g ≥−，解得2x ≤−，故不等式的解集为(](]0,2,2−∞− .故答案为：(](]0,2,2−∞−四、解答题：本题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤. 17. 若角θ的终边经过点()1,02P m m −>，且sin θ=. （1）求m ；（2）求()()πcos tan π2sin πθθθ +++−的值. 【答案】（1（2）1+【解析】【分析】（1）根据三角函数的定义直接求解即可；（2）利用诱导公式化简，然后求值即可.【小问1详解】角θ的终边经过点1,(0)2P m m −>，∴sin θ=，∴m =；【小问2详解】由（1）知角θ的终边经过点12P − ，∴sin θ==，tan θ==， ∴()()πcos tan πsin tan 21sin πsin θθθθθθ +++ −+ ==+−−18. 设全集为R ，集合{}2560A x x x =−−>，{}121B x a x a =+<<−（1）若4a =，求A B ∪，A B ∩R ；（2）若()A B =∅R ，求实数a 的取值范围. 【答案】（1）{}15A B x x x ∪=−或；{}=17A B x x x ∩<−≥R 或（2）(][),25,−∞∪+∞【解析】【分析】（1）求出集合A ，B ，再利用交并补运算求解即可；（2）讨论B =∅和B ≠∅. 【小问1详解】 {}{}256016A x x x x x x =−−>=−或，当4a =时，{}57Bx x =<<，{}=57B x x x ≤≥R 或， ∴{}15A B x x x ∪=−或，{}=17A B x x x ∩<−≥R 或；【小问2详解】{}=16A x x −≤≤R ，当B =∅时，121a a +≥−，即2a ≤，符合()A B =∅R ；当B ≠∅时，121,16,a a a +<− +≥ 或121,211,a a a +<− −≤−解得5a ≥，综上2a ≤或5a ≥.∴实数a 的取值范围为(][),25,−∞∪+∞.19. 已知函数2()121x a f x =+−为奇函数. （1）求a 的值；（2）判断函数()f x 在(0,)+∞内的单调性，并用函数单调性的定义证明你的结论.【答案】（1）1a =（2）函数()f x 在(0,)+∞内单调递减，证明见解析【解析】【分析】（1）由奇函数的定义()()f x f x −=−，通过变形即可求解；（2）任取120x x <<，可证()()120f x f x −>，从而得出结论.【小问1详解】函数的定义域为()(),00,∞−+∞ ，由()()f x f x −=−得22112121x x a a − +=−+ −−，整理可得1a =；【小问2详解】函数()f x 在(0,)+∞内单调递减；证明如下：由（1）知2()121x f x =+-，在()0,∞+上任取1x ，2x ，且12x x <，()()()()()()()()()2121121212122212212222211212121212121x x x x x x x x x x f x f x −−−−−=+−−==−−−−−−，由120x x <<，得1210x −>，2210x −>，21220x x −>，所以()()120f x f x −>，即()()12f x f x >，所以函数2()121x f x =+-在()0,∞+内单调递减. 20. 已知函数π()2sin 23f x x=− ，x ∈R . （1）求函数()f x 的单调递增区间；（2）若函数()()g x f x m =−在区间π0,2上有两个零点，求m 的取值范围. （3）若函数π()()()6h x f x k x k=−−∈R 有且仅有3个零点，求所有零点之和. 【答案】（1）()π5ππ,πZ 1212k k k−+∈（2）m ∈ （3）π2【解析】【分析】（1）根据正弦函数的单调增区间即可得出答案；（2）由题可知()f x m =在区间π0,2内有两个相异的实根，即()y f x =图像与y m =的图像有两个不同的交点结合图像可得结果. （3）π6y k x=− 关于π,06 成中心对称，而π()2sin 23f x x =− 关于π,06成中心对称，设三个零点为123,,x x x ，则13ππ,266x x x +==，即可得出答案. 【小问1详解】由()πππ2π22πZ 232k x k k −≤−≤+∈，得()π5πππZ 1212k x k k −≤≤+∈. 故函数()f x 的单调递增区间为：()π5ππ,πZ 1212k k k −+∈【小问2详解】若函数()()g x f x m =−在区间π0,2上有两个零点，令()0g x =，即()y f x =与y m =在区间π0,2上有两个交点，令π23t x =−，由π0,2x ∈ ，则ππ2π2,333x −∈− ，即sin y t =与y m =在区间π2π,33 −上有两个交点，画出sin y t =与y m =在区间π2π,33 −上的图象，如下：由图可知：m ∈. 【小问3详解】函数π()()()6h x f x k x k=−−∈R 有且仅有3个零点，因为π6y k x=− 关于π,06成中心对称，而π()2sin 23f x x =−关于π,06 成中心对称，设三个零点为123,,x x x ，则132ππ,266x x x +==，所以所有零点之和πππ2662+×=. 21. 某食品企业为了提高其生产的一款食品的收益，拟在下一年度开展促销活动，已知该款食品年销量x 吨与年促销费用t 万元之间满足函数关系式22k x t =−+（k 为常数），如果不开展促销活动，年销量是1吨.已知每一年生产设备折旧、维修等固定费用为3万元，每生产1吨食品需再投入32万元的生产费用，通过市场分析，若将每吨食品售价定为：“每吨食品平均生产成本的1.5倍”与“每吨食品平均促销费的一半”之和，则当年生产的该款食品正好能销售完.（1）求k 值；（2）将下一年的利润y （万元）表示为促销费t （万元）的函数；（3）该食品企业下一年的促销费投入多少万元时，该款食品的利润最大？（注：利润=销售收入−生产成本−促销费，生产成本=固定费用+生产费用）【答案】（1）=2k（2）()321670222y t t t =−−+≥+ （3）该食品企业下一年的促销费投入6万元时，该款食品的利润最大为26.5万元.【解析】【分析】（1）依题意当=0t 时，=1x 代入计算可得；（2）依题意求出当年生产x 吨时，求出年生产成本和为年销售收入，从而可表示出食品的利润；（3）由（2）可得32269222t y t + =−++ + ，利用基本不等式计算可得. 小问1详解】由题意可知，当=0t 时，=1x ，所以122k =−，解得=2k ；小问2详解】由于=2k ，故222x t =−+，由题意知，当年生产x 吨时，年生产成本为：232332232x t+=−+ +，当销售x 吨时，年销售收入为：3213223222t t −++ + ，由题意，3212322332232222y t t t t =−++−−+− ++ ，即()321670222y t t t =−−+≥+. 【小问3详解】由（2）知：()321670222y t t t =−−+≥+，即3226932269222222t t y t t ++ =−−+=−++ ++6926.52≤−=，当且仅当32222t t +=+，又22t +≥，即6t =时，等号成立. 此时，max 26.5y =该食品企业下一年的促销费投入6万元时，该款食品的利润最大为26.5万元.【【.22. 已知函数π()2sin()(0,||)2f x x ωϕωϕ=+><图象的对称轴与对称中心之间的最小距离为π4，且满足ππ()()1212f x f x +=−−. （1）求()f x 的解析式；（2）已知函数2()23h x tx x =++，若有且只有一个实数a ，对于1ππ[,]123x ∀∈，2[0,2]x ∃∈，使得21)()(2h x a f x =−，求实数t 的值.【答案】（1）π()2sin(2)6f x x =−；（2）12−. 【解析】【分析】（1）根据给定条件，结合“五点法”作图求出,ωϕ即可. （2）求出函数()f x 在ππ[,]123上的值域，再根据给定条件，借助集合的包含关系分类讨论求解. 【小问1详解】依题意，函数()f x 的周期π4π4T =×=，则2π2Tω==，由ππ()()1212f x f x +=−−，得函数()f x 图象的一个对称中心为π(,0)12，即有π2π,Z 12k k ϕ×+=∈，而π||2ϕ<，则π0,6k ϕ==−，所以()f x 的解析式为π()2sin(2)6f x x =−. 【小问2详解】由（1）知，π()2sin(2)6f x x =−，当ππ[,]123x ∈时，ππ2[0,]62x −∈，因此()f x 在ππ[,]123上单调递增，函数值集合为[0,2]，2()a f x −值域为[22,2]a a −，由有且只有一个实数a ，对于1ππ[,]123x ∀∈，2[0,2]x ∃∈，使得21)()(2h x a f x =−，得函数()h x 在[0,2]上的值域包含[22,2]a a −，并且实数a 唯一，当0t ≥时，函数2()23h x tx x =++在[0,2]上单调递增，()h x 的值域为[3,47]t +，由[22,2][3,47]a a t −⊆+，得223247a a t −≥ ≤+ ，解得57222a t ≤≤+，显然符合条件的实数a 不唯一；第21页/共21页当0t <时，函数()h x 的图象对称轴为1x t =−，当12t −≥，即102t −≤<时，()h x 在[0,2]上单调递增，()h x 的值域为[3,47]t +，于是223247a a t −≥ ≤+ ，解得52722a a t ≥ ≤+ ，显然57222t ≤+，当且仅当12t =−时，52a =且唯一，因此12t =−；当102t <−<，即21t <−时，max 11()()3h x h t t =−=−，(0)3h =，(2)47h t =+，当()0h 是最小值时，而1133(0,2)t t −−=−∈，不满足函数()h x 在[0,2]上的值域包含[22,2]a a −，则()0h 不是最小值，必有13(47)2t t −−+≥，得t ≤，于是1232247a t a t ≤− −≥+ ，解得3122922a t a t ≤− ≥+，当t =时，31322t −=9232t +=−3a =且唯一，并且当t <时，9312222t t +<−，9312222t a t +≤≤−，实数a不唯一，因此t = 所以实数t的值是t =12t =−. 【点睛】结论点睛：函数()[],,y f x x a b ∈，()[],,y g x x c d ∈，若[]1,x a b ∀∈，[]2,x c d ∃∈，有()()12f x g x =，则()f x 的值域是()g x 值域的子集．。

广东省广州市天河区2023-2024学年高二下学期期末物理试题

广东省广州市天河区2023-2024学年高二下学期期末物理试题一、单选题1．下列有关电磁场和电磁波的说法正确的是（）A ．变化的磁场周围一定存在着电场，与是否有闭合电路无关B ．只要空间某处的电场或磁场发生变化，就会在其周围产生电磁波C ．电磁波传播过程中，电场和磁场是独立存在的，没有关联D ．电磁波也可以传播能量，具有干涉、衍射现象，没有反射现象2．物理知识在生活中有广泛的应用，下列说法正确的是（）A ．如图甲，阳光下观察竖直放置的肥皂膜，看到彩色条纹是光的衍射产生的B ．如图乙，光纤通信是一种现代通信手段，它是利用光的全反射原理来传递信息的C ．如图丙，采用红灯图作为各种交通警示，原因是红光产生了多普勒效应D ．如图丁，立体电影利用了光的干涉现象3．密闭容器内封闭一定质量的理想气体，经历A B →的等压过程和B C →的绝热过程，下列说法正确的是（）A ．BC →过程中，气体内能增加B ．BC →过程中，分子平均动能不变C ．A B →过程中，气体从外界吸收热量D ．A B →过程单位时间内对单位面积器壁碰撞的分子次数不变4．如图所示为一款玩具“弹簧小人”，由头部、弹簧及底部组成，弹簧质量不计、开始弹簧小人静止于桌面上，现轻压头部后由静止释放，小人开始上下振动，头部上升至最高点时，底部不离开桌面，不计阻力，该过程可近似为简谐运动，下列判断中正确的是（）A ．头部上升的时间比下降的时间短B ．头部上升过程速度先变大再变小C ．头部上升过程中所受合力越来越小D ．头部处于平衡位置时弹簧弹性势能最小5．我国自主研发的“华龙一号”反应堆技术利用铀235发生核裂变释放的能量发电，典型的核反应方程为235114192192056360U n Ba Kr n k +→++。

光速取83.010m/s ⨯，若核反应的质量亏损为1g ，释放的核能为E ∆，则k 和E ∆的值分别为（）A ．2，169.010J ⨯B ．3，139.010J ⨯C ．2，164.510J ⨯D ．3，134.510J ⨯ 6．行驶中的汽车如果发生剧烈碰撞，车内的安全气囊会被弹出并瞬间充满气体。

2023-2024学年广东省广州市九区联考高一上学期期末教学质量监测数学试卷+答案解析

2023-2024学年广东省广州市九区联考高一上学期期末教学质量监测数学试卷❖一、单选题：本题共8小题，每小题5分，共40分。

在每小题给出的选项中，只有一项是符合题目要求的。

1.已知，则“”是“”的()A.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件2.已知集合只有一个元素，则实数a的值为()A.1或0B.0C.1D.1或23.方程的根所在的区间是()A. B. C. D.4.设，，，则()A. B. C. D.5.函数的图象大致为()A. B.C. D.6.函数在一个周期内的图象如图所示，为了得到函数的图象，只要把函数的图象上所有的点()A.向左平移个单位长度B.向左平移个单位长度C.向右平移个单位长度D.向右平移个单位长度7.函数若，，则a的值为()A.4B.4或C.2或D.28.中国茶文化博大精深.茶水的口感与茶叶类型和水的温度有关，经验表明，有一种茶用的水泡制，再等到茶水温度降至时饮用，可以产生最佳口感.某研究人员在室温下，每隔测一次茶水温度，得到数据如下：放置时间01234茶水温度为了描述茶水温度y与放置时间x min的关系，现有以下两种函数模型供选择：①，②选择最符合实际的函数模型，可求得刚泡好的茶水达到最佳口感所需放置时间大约为参考数据：，()A. B.C. D.二、多选题：本题共4小题，共20分。

在每小题给出的选项中，有多项符合题目要求。

全部选对的得5分，部分选对的得2分，有选错的得0分。

9.下列命题为真命题的是()A.若，，则B.若，则C.若，则D.若，，则10.设，用表示不超过x的最大整数，则称为高斯函数，也叫取整函数，例如令函数，则()A.B.的最大值为0，最小值为C.D.与的图象没有交点11.已知函数，则()A.若，则B.不等式的解集是C.函数，的最小值为D.若，且，则12.已知函数，则()A.当时，的最小值为0B.若存在最小值，则a的取值范围为C.若是减函数，则a的取值范围为D.若存在零点，则a的取值范围为三、填空题：本题共4小题，每小题5分，共20分。

2010-2011学年度高一第二学期期末考试试题(必修4-必修5)

2010 -2011 学年度第二学期高一级数学科期末考试试卷本试卷分选择题和非选择题两部分，共10页，满分为150分。

考试用时120分钟。

注意事项：1、答卷前，考生务必用黑色字迹的钢笔或签字笔将自己的姓名和学号填写在答题卡和答卷密封线内相应的位置上，用2B 铅笔将自己的学号填涂在答题卡上。

2、选择题每小题选出答案后，有2B 铅笔把答题卡上对应题目的答案标号涂黑；如需改动，用橡皮擦干净后，再选涂其他答案；不能答在试卷上。

3、非选择题必须用黑色字迹的钢笔或签字笔在答卷纸上作答，答案必须写在答卷纸各题目指定区域内的相应位置上，超出指定区域的答案无效；如需改动，先划掉原来的答案，然后再写上新的答案；不准使用铅笔和涂改液。

不按以上要求作答的答案无效。

4、考生必须保持答题卡的整洁和平整。

第一部分选择题(共50分)一．选择题（本大题共10小题. 每小题5分，共50分. 在每小题给出的四个选项中，只有一项是符合题目要求的.） 1. sin(300)-的值是（* ）A ．;21B ．;21-C ．;23-D ． ;23 2．已知(1,2),(2,1)a b x ==-，若b a ⊥，则=xA ．2B ．1C.21D.03．在直角坐标系中，若α与β的终边关于y 轴对称，则下列各式成立的是 A ．sin sin αβ= B ．cos cos αβ= C ．tan α= tan β D ．cot α= cot β4．在等差数列}{n a 中,1280a a +=,3460a a +=,那么=+65a a A.30 B.40 C.50 D.605．若a 、b 、c 为实数，则下列命题正确的是（* ）A.若a ＞b ，则ac 2＞bc 2B.若a ＜b ＜0，则a 2＞ab ＞b 2C.若a ＜b ＜0，则a 1＜b 1 D.若a ＜b ＜0，则a b ＞ba6．函数5cos(2)6y x π=+图象的一条对称轴方程是（* ）A ．;12x π=B ．;6x π=C ． 5;12x π=D ．;3π=x 7．函数sin(2)3y x π=-的单调递减区间是（* ）A ．2,;63k k k Z ππππ⎡⎤++∈⎢⎥⎣⎦ B ．5112,2;1212k k k Z ππππ⎡⎤++∈⎢⎥⎣⎦ C ．22,2;63k k k Z ππππ⎡⎤++∈⎢⎥⎣⎦ D ．511,;1212k k k Z ππππ⎡⎤++∈⎢⎥⎣⎦ 8．若a 、b 、c 成等比数列，则函数f (x )＝ax 2+bx +c 的图象与x 轴的交点个数是（* ） A ．2 B ．1 C ．0 D ．不确定9．若y x ,满足条件⎪⎪⎩⎪⎪⎨⎧≥≥≤-+≤-+10042052y x y x y x目标函数y x z -=2，则A ．25max =z B ．1max -=z C ． 2max =z D ．0min =z 10．设集合y x y x y x A --=1,,|),{(是三角形的三边长}，则A 所表示的平面区域（不含边界的阴影部分）是（* ）A B C D第二部分非选择题(共100分)二．填空题（本大题共4小题，每小题5分，共20分.） 11．半径为a （0>a ）的圆中，6π弧度圆心角所对的弧长是_____* ______，长为a 2的弧所对的圆周角为______* ______弧度。

广东省广州市天河区2023-2024学年学年高一下学期期末考试数学试卷

广东省广州市天河区2023-2024学年学年高一下学期期末考试数学试卷一、单选题1．设x ∈R ,向量(),1a x =r ，()4,2b =-r ，若//a b r r ，则x =（）A ．2-B ．12-C ．12 D ．22．已知一个矩形较长边长为2用斜二测画法画出矩形的直观图是菱形，则直观图的面积为（）A B C ．D ．3．将函数()()sin f x x ωϕ=+的图象向左平移π4个单位后，与函数()()cos g x x ωϕ=+的图象重合，则ω的值可以是（）A ．1B ．2C ．3D ．44．已知两条不同的直线m ，n 及三个不同的平面α，β，γ则下列推理正确的是（） A ．,n αβαβ⊥⋂=，m n m β⊥⇒⊥B ．,αγβγαβ⊥⊥⇒⊥C ．m αβ=I ，//n α，////n m n β⇒D ．m n ⊥，//n m αα⊥⇒5．抛掷两枚质地均匀的硬币，记事件A =“第一枚硬币正面朝上”，事件B =“第二枚硬币反面朝上”，事件C =“两枚硬币都正面朝上”，事件D =“至少一枚硬币反面朝上”则（） A ．C 与D 独立 B ．A 与B 互斥 C ．()12P D =D ．()34P A B ⋃= 6．已知样本数据12345,,,,x x x x x 都为正数，其方差12251(80)5i i s x ==-∑，则样本数据的平均数为（）A ．2B ．C ．4D ．7．ABC V 的内角A ，B ，C 所对的边分别为a ，b ，c ，已知2a =，30A =︒，若三角形有唯一解，则整数b 构成的集合为（）A ．{}3B ．{}1,2C ．{}1,2,4D ．{}1,2,3,4 8．如图，弹簧挂着的小球做上下运动，它在t 秒时相对于平衡位置的高度h 厘米由关系式()()sin h t A t ωϕ=+确定，其中0A >，0ω>，π<ϕ.小球从最低点出发，经过2秒后，第一次回到最低点，则下列说法中正确的是（）A ．()πsin π2h t A t ⎛⎫=+ ⎪⎝⎭ B ．9t =秒与53t =秒时小球偏离于平衡位置的距离之比为2 C ．当00t t <<时，若小球有且只有三次到达最高点，则[]05,7t ∈D ．当1220t t <<<时，若12,t t 时刻小球偏离于平衡位置的距离相同，则12πsin 1t t ⎛⎫= ⎪+⎝⎭二、多选题9．已知一组数据6，13，14，15，18，13，则特征量为13的是（）A ．极差B ．众数C ．中位数D ．第40百分位数 10．已知i 为虚数单位，以下四个说法中正确的是（）A ．234i i i z =++的虚部为1-B ．若z 是复数，满足()1i 1i z -=+，则z 在复平面内对应的点位于第一象限C ．若1z 、2z 是非零复数，且12=z z ，则2212z z =D ．若1z 、2z 是非零复数，且2112z z z =，则12z z =11．如图,在棱长为2的正方体1111ABCD A B C D -中，M 为11B C 的中点，则下列说法中正确的是（）A ．若点O 为11C D 的中点，则//MO 平面1A DBB ．连接BM ，则直线BM 与平面11BDD BC ．若点N 为线段BC 上的动点（包含端点），则MN DN +D ．若点Q 在侧面正方形11ADD A 内（包含边界），且1MQ AC ⊥，则点Q三、填空题12．在复数范围内方程2450x x -+=的一个根为0x ，则0x =.13．在ABC V 中，已知2AB AC AB AC AB +=-=u u u r u u u r u u u r u u u r u u u r ，则向量CA u u u r 在向量CB u u u r 上的投影向量为.14．已知一个圆台的上、下底面直径分别为2、8，母线长为6，则在圆台内部放置半径最大的球的表面积为.四、解答题15．某企业进入中学参与学校举办的模拟招聘会，设置了笔试、面试两个环节，先笔试后面试，笔试通过了才可以进入面试，面试通过后即可录用，李明参加该企业的模拟招聘.笔试关：有4道题，应聘者随机从中选择2道，两道题均答对即可通过笔试，否则淘汰不予录用.已知李明能答对其中的3道题；面试关：有2道题，面试者答对第一道题，则面试通过被企业录用，否则就继续答第二道题，答对第二道题则面试通过被企业录用，否则淘汰不予录用.已知李明答对每道面试题的概率都是14，两道题能否答对相互独立. (1)李明笔试关中能答对的3道题记为1a ，2a ，3a ，不能答对的题记为b ，请写出李明参加笔试关所有可能结果构成的样本空间，并求出李明通过笔试关的概率；(2)求李明被录用的概率.16．已知ABC V 的内角A ，B ，C 所对的边分别为a ，b ，c ，且22cos 0a c b C +-=.(1)求B ∠；(2)若2c =，D 为线段AC 的中点，且1BD =，求ABC V 的面积.17．为推动习近平新时代中国特色社会主义思想深入人心，促进全社会形成爱读书、读好书、善读书的新风尚，培育有坚定理想信念、爱党爱国、堪当民族复兴大任的有为青年，某学校举办了读书节活动.现从该校的2000名学生中发放调查问卷，随机调查了100名学生一周的课外阅读时间，将统计数据按照[)0,20，[)20,40，…[)100,120，[]120,140组后绘制成如图所示的频率分布直方图（单位：分钟，同一组中的数据用该组区间的中点值作代表）.(1)求a 的值，若每周课外阅读时间60分钟以上（含60分钟）视为达标，试估计该校达标的人数；(2)估计该校学生每周课外阅读的平均时间；(3)若样本数据在[)0,20与[)20,40内的方差分别为213s =，2253s =，计样本数据在[)0,40内的方差2s .18．如图，已知三棱台111ABC A B C -，底面ABC V 是以B 为直角顶点的等腰直角三角形，体11ABB A ⊥平面ABC ，且111112AA A B BB AB ===.(1)证明：BC ⊥平面11ABB A ；(2)求点B 到面11ACC A 的距离；(3)在线段1CC 上是否存在点F ，使得二面角F AB C --的大小为π6，若存在，求出CF 的长，若不存在，请说明理由.19．如图，已知ABC V ，21AB AC BC ===，且点P 是ABC V 的重心.过点P 的直线l 与线段AB 、AC 分别交于点E 、F .设AE AB λ=u u u r u u u r ，AF AC μ=u u u r u u u r （0λ≠，0μ≠）.(1)求AB AC ⋅uu u r uu u r 的值，并判断11λμ+是否为定值，若是则求出定值，若不是请说明理由； (2)若AEF △的周长为1C ，ABC V 的周长为2C .设x λμ=，记()12C f x x C =-，求()f x 的取值范围.。

2012-2013学年下学期期末调研考试高一数学试题(含答案)(必修3+必修4)

第 3 页共 7 页

19．（本小题满分14分）从3名男生和2名女生中任选两人参加演讲比赛，试求：（1）所选2人都是男生的概率；（2）所选2人恰有1名女生的概率；（3）所选2人至少有1名女生的概率．
20.（本小题满分15分）设 x R ，函数 f ( x ) cos ( x ) 为，且 f ( )
2012-2013学年下学期期末调研考试
高一数学
本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分．试卷满分150分．考试时间 100分钟．注意事项： 1．答题前，考生在答题卡上务必用直径0.5毫米黑色墨水签字笔将自己的姓名、准考证号填写清楚． 2．第Ⅰ卷，每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号，在试题卷上作答无效． 3．第Ⅱ卷，请务必用直径0.5毫米黑色墨水签字笔在答题卡上各题的答题区域内作答，
15.已知 a 4 ， e 为单位向量，当 a 与 e 之间的夹角为 1200 时， a 在 e 方向上的投影为 16.对于函数 f ( x ) 3sin(2 x ①图像关于原点成中心对称 ②图像关于直线 x

6
) ，给出下列命题：

6
对称
③函数 f ( x ) 的最大值是3 ④函数的一个单调增区间是 [

, ] 4 4
其中正确命题的序号为．三.解答题(本大题5个小题，共70分.解答应写出说明文字，证明过程或演算步骤) 17．（本小题满分12分）已知 tan( ) 2 .
sin cos 的值； sin cos （2）求 sin 2 的值.

高中英语试题-广东省四校2023-2024学年高三上学期联考(二)英语答案

2023－2024学年第一学期高三四校联考（二）英语试题参考答案第二部分阅读第一节21-23CAC24-27DABD28-31BCDC32-35CADC第二节36-40FDGEB第三部分语言知识运用第一节41-45DBCDC46-50ABDAC51-55ADACB第二节56.uncovered57.Dating58.as59.where60.to preventid62.original63.technologically64.the65.tools第四部分写作第一节应用文写作Dear Jim,How is everything going?Regarding your request for book recommendations in Chinese culture,I’d be more than happy to assist you.My first recommendation is the type of books centering on Chinese Civilization.These books provide a comprehensive overview of China’s rich history,including its ancient civilization,dynasties,and cultural developments.Moreover,books on“Chinese Traditions and Customs”are highly recommended,which delves into the unique Chinese customs,traditions,and rituals that shape Chinese society.By reading them,readers will definitely gain valuable insights into China’s cultural heritage,and its societal norms.Hopefully,my recommendation will greatly contribute to your school’s collection and provide students with a broader perspective on Chinese culture.Yours,Li Hua第二节读后续写Everett did as he was told.At first,Everett stood on the side of the road in a daze.As a five-year-old boy,he did not know how to stop the passing car.However,thinking of his father and brother struggling in the well,he gathered his courage again and shouted bravely for help.Although a couple didn‘t quite understand what Everett was saying,the repeated words like“danger”“well”“help”quickly attracted their attention.They realized the seriousness of the problem.They called119immediately and drove Everett to the farm.The couple hurried to the well with Everett.When they reached the top of the well,they were shocked by what they saw.In the well,Brandon's hand was shaking constantly,and Louie was crying with fear.The couple kept encouraging them and went to the trunk to get a rope to help them out.Hardly had they used the rope to pull Louie out when the rescuers arrived.After getting out,Brandon expressed his gratitude to every rescuer.They said that if it hadn’t been for Everett’s efforts,they would not have been able to come to their assistance in time.Of course, God helps those who help themselves,what really saved them was their own spirit of not giving up in the face of difficulties.2023－2024学年第一学期高三四校联考（二）英语试题答案详解阅读A篇【导语】这是一篇应用文。

广东省广州市2023-2024学年高一10月月考英语试题

2023年第一学期阶段性考试（10月月考）高一年级英语试卷命题时间：2023.9本试卷分第I卷和第II卷两部分，共150分。

考试时间120分钟。

第I卷（选择题共70分）注意事项：1、答卷前，考生务必将自己的姓名、考号等信息填写在答题纸上。

2、答案必须填写在答题纸的相应位置上，答案写在试题卷上无效。

第一部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）请阅读下列短文，从短文后各题所给的A、B、C、D四个选项中，选出最佳选项，并在答题卡上将该项涂黑。

AThe Cambridge Science Festival Curiosity ChallengeDare to Take the Curiosity Challenge!The Cambridge Science Festival (CSF) is pleased to inform you of the sixth annual Curiosity Challenge. The challenge invites, even dares school students between the ages of 5 and 14 to create artwork or a piece of writing that shows their curiosity and how it inspires them to explore their world.Students are being dared to draw a picture, write an article, take a photo or write a poem that shows what they are curious about. To enter the challenge, all artwork or pieces of writing should be sent to the Cambridge Science Festival, MIT Museum, 265 Mass Avenue, Cambridge 02139 by Friday, February 8th.Students who enter the Curiosity Challenge and are selected as winners will be honored at a special ceremony during the CSF on Sunday, April 21st. Guest speakers will also present prizes to the students. Winning entries will be published in a book. Student entries will be exhibited and prizes will be given. Families of those who take part will be included in celebration and brunch will be served.Between March 10th and March 15th, each winner will be given the specifics of the closing ceremony and the Curiosity Challenge celebration. The program guidelines and other related information are available at: http:// .1. Who can take part in the Curiosity Challenge?A. School students.B. Cambridge locals.C. CSF winners.D. MIT artists.2. When will the prize-giving ceremony be held?A. On February 8th.B. On March 10th.C. On March 15thD. On April 21st.3. What type of writing is this text?A. An exhibition guide.B. An art show review.C. An announcement.D. An official report.Arriving in Sydney on his own from India, my husband, Rashid, stayed in a hotel for a short time while looking for a house for me and our children.During the first week of his stay, he went out one day to do some shopping. He came back in the late afternoon to discover that his suitcase was gone. He was extremely worried as the suitcase had all his important papers, including his passport.He reported the case to the police and then sat there，lost and lonely in a strange city, thinking of the terrible troubles of getting all the paperwork organized again from a distant country while trying to settle down in a new one.Late in the evening, the phone rang. It was a stranger. He was trying to pronounce my husband’s name and was asking him a lot of questions. Then he said they had found a pile of papers in their trash can(垃圾桶) that had been left out on the footpath.My husband rushed to their home to find a kind family holding all his papers and documents. Their young daughter had gone to the trash can and found a pile of unfamiliar papers. Her parents had carefully sorted them out, although they had found mainly foreign addresses on most of the documents. At last they had seen a half-written letter in the pile in which my husband had given his new telephone number to a friend.That family not only restored the important documents to us that day but also restored our faith and trust in people. We still remember their kindness and often send a warm wish their way.4. What did Rashid plan to do after his arrival in Sydney?A. Go shoppingB. Find a houseC. Join his familyD. Take his family5. The girl’s parents got Rashid’s phone number from _______.A. a friend of his familyB. a Sydney policemanC. a letter in his papersD. a stranger in Sydney6. What does the underline d word “restored” in the last paragraph mean?A. ShowedB. Sent outC. DeliveredD. Gave back7. Which of the following can be the best title for the text?A. From India to Australia.B. Living in a New Country.C. Turning Trash to Treasure.D. In Search of New Friends.More students than ever before are taking a gap year(间隔年) before going to university. It used to be the “year off” between school and university. The gap-year phenomenon originated(起源) with the months left over to Oxbridge applicants between entrance exams in November and the start of the next academic year.This year, 25,310 students who have accepted places in higher education institutions have put off their entry until next year, according to statistics on university entrance provided by the University and College Admissions Service (UCAS).That is a record 14.7% increase in the number of students taking a gap year. Tony Higgins from UCAS said that the statistics are good news for everyone in higher education. “Students who take a well-planned year out are more likely to be satisfied with, and complete, their chosen course. Students who take a gap year are often more mature and responsible,” he said.But not everyone is happy. Owain James, the president of the National Union of Students (NUS), argued that the increase is evidence of student hardship –young people are being forced into earning money before finishing their education. “New students are now aware that they are likely to leave university up to￡15,000 in debt. It is not surprising that more and more students are taking a gap year to earn money to support their study for the degree. NUS statistics show that over 40% of students are forced to work during term time and the figure incr eases to 90% during vacating periods,” he said.8. What do we learn about the gap year from the text?A. It is flexible in length.B. It is a time for relaxation.C. It is increasingly popular.D. It is required by universities.9. According to Tony Higgins, students taking a gap year _______.A. are better prepared for college studiesB. know a lot more about their future jobC. are more likely to leave university in debtD. have a better chance to enter top universities10. How does Owain James feel about the gap-year phenomenon?A. He’s puzzledB. He’s worriedC. He’s surprisedD. He’s annoyed11.What would most students do on their vacation according to NUS statistics?A. Attend additional courses.B. Make plans for the new term.C. Earn money for their educationD. Prepare for their graduate studies.DInstead of hitting the beach, fourteen high school students traded swimming suits for lab coats last summer and turned their attention to scientific experiments.The High School Research Program offers high school students guidance with researchers in Texas A&M’s College of Agriculture and Life Sciences. Jennifer Funkhouser, academic adviser for the Department of Rangeland Ecology and Management, directs this four-week summer program designed to increase understanding of research and its career potential(潜能).Several considerations go into selecting students, including grades, school involvement and interest in science and agriculture. And many students come from poorer school districts, Funkhouser says. “This is their chance to learn techniques and do experiments they never would have a chance to do in high school.Warner Ervin of Houston is interested in animal science and learned how to tell male from female mosquitoes(蚊子). His adviser, Craig Coates, studies the genes(基因) of mosquitoes that allow them to fight against malaria and yellow fever. Coates thought this experience would be fun and helpful to the high school students.The agricultural research at A&M differs from stereotypes. It’s “molecular(分子) science on the cutting edge,” Funkhouser says. The program broadened students’ knowledge. Victor Garcia of Rio Grande City hopes to become a biology teacher and says he learned a lot about chemistry from the program.At the end of the program, the students presented papers on their research. They’re also paid $600 for their work — another way this program differs from others, which often charge a fee.Fourteen students got paid to learn that science is fun, that agriculture is a lot more than milking and plowing and that research can open many doors.12. The research program is mainly designed for ________.A. high school advisers from HoustonB. college students majoring in agricultureC. high school students from different placesD. researchers at the College of Agriculture and Life Sciences13. It can be inferred from the text that the students in poorer areas ________.A. had little chance to go to collegeB. could often take part in the programC. found the program useful to their futureD. showed much interest in their high school experiments14. When the program was over, the students ________.A. entered that collegeB. wrote research reportsC. paid for their researchD. found a way to make money15.What would be the best title for the text?A. A Program for Agricultural Science StudentsB. A Program for Animal Science StudentsC. A Program for Medical Science LoversD. A Program for Future Science Lovers第二节七选五 (共5小题；每小题2分，满分10分)根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。

高一下学期期末数学考试试卷(含答案)——广东省广州市

广东省广州市荔湾区高一（下）期末数学试卷一、选择题：本大题共12小题，每小题5分，共60分，在每小题所给的四个选项中，只有一个是正确的．1．与﹣60°角的终边相同的角是（）A．300°B．240°C．120° D．60°2．不等式x﹣2y+4＞0表示的区域在直线x﹣2y+4=0的（）A．左上方B．左下方C．右上方D．右下方3．已知角α的终边经过点P（﹣3，﹣4），则cosα的值是（）A．﹣ B．C．﹣ D．4．不等式x2﹣3x﹣10＞0的解集是（）A．{x|﹣2≤x≤5}B．{x|x≥5或x≤﹣2}C．{x|﹣2＜x＜5}D．{x|x＞5或x＜﹣2} 5．若sinα=﹣，α是第四象限角，则cos（+α）的值是（）A．B．C．D．6．若a，b∈R，下列命题正确的是（）A．若a＞|b|，则a2＞b2B．若|a|＞b，则a2＞b2C．若a≠|b|，则a2≠b2D．若a＞b，则a﹣b＜07．要得到函数y=3sin（2x+）图象，只需把函数y=3sin2x图象（）A．向左平移个单位B．向右平移个单位C．向左平移个单位D．向右平移个单位8．已知M是平行四边形ABCD的对角线的交点，P为平面ABCD内任意一点，则+++等于（）A．4 B．3 C．2 D．9．若cos2α=，则sin4α+cos4α的值是（）A．B．C．D．10．已知直角三角形的两条直角边的和等于4，则直角三角形的面积的最大值是（）A．4 B．2 C．2 D．11．已知点（n，a n）在函数y=2x﹣13的图象上，则数列{a n}的前n项和S n的最小值为（）A．36 B．﹣36 C．6 D．﹣612．若钝角三角形三内角的度数成等差数列，且最大边长与最小边长的比值为m，则m的范围是（）A．（1，2） B．（2，+∞）C．[3，+∞）D．（3，+∞）二、填空题：本大题共4小题，每小题5分，满分20分.把答案填在答题卡上.13．若向量=（4，2），=（8，x），∥，则x的值为．14．若关于x的方程x2﹣mx+m=0没有实数根，则实数m的取值范围是．15．已知x，y满足，则z=2x+y的最大值为．16．设f（x）=sinxcosx+cos2x，则f（x）的单调递减区间是．三、解答题：本大题共6小题，满分70分．解答应写出文字说明，证明过程或演算步骤．17．已知等比数列{a n}的前n项和为S n，公比为q（q≠1），证明：S n=．18．已知平面向量，满足||=1，||=2．（1）若与的夹角θ=120°，求|+|的值；（2）若（k+）⊥（k﹣），求实数k的值．19．在△ABC中，内角A，B，C的对边分别为a，b，c，已知c=acosB+bsinA．（1）求A；（2）若a=2，b=c，求△ABC的面积．20．已知数列{a n}的前n项和为S n，且a1=2，a n=S n（n=1，2，3，…）．+1（1）证明：数列{}是等比数列；（2）设b n=，求数列{b n}的前n项和T n．21．某电力部门需在A、B两地之间架设高压电线，因地理条件限制，不能直接测量A、B两地距离．现测量人员在相距km的C、D两地（假设A、B、C、D在同一平面上）测得∠ACB=75°，∠BCD=45°，∠ADC=30°，∠ADB=45°（如图），假如考虑到电线的自然下垂和施工损耗等原因，实际所须电线长度为A、B距离的倍，问施工单位应该准备多长的电线？22．已知A，B，C为锐角△ABC的内角，=（sinA，sinBsinC），=（1，﹣2），⊥．（1）tanB，tanBtanC，tanC能否构成等差数列？并证明你的结论；（2）求tanAtanBtanC的最小值．广东省广州市荔湾区高一（下）期末数学试卷参考答案与试题解析一、选择题：本大题共12小题，每小题5分，共60分，在每小题所给的四个选项中，只有一个是正确的．1．与﹣60°角的终边相同的角是（）A．300°B．240°C．120° D．60°【考点】G2：终边相同的角．【分析】与﹣60°终边相同的角一定可以写成k×360°﹣60°的形式，k∈z，检验各个选项中的角是否满足此条件．【解答】解：与﹣60°终边相同的角一定可以写成k×360°﹣60°的形式，k∈z，令k=1 可得，300°与﹣60°终边相同，故选：A．2．不等式x﹣2y+4＞0表示的区域在直线x﹣2y+4=0的（）A．左上方B．左下方C．右上方D．右下方【考点】7B：二元一次不等式（组）与平面区域．【分析】根据题意，作出直线x﹣2y+4=0的图形，分析可得原点在直线右下方，将原点坐标（0，0）代入x﹣2y+4，分析即可得答案．【解答】解：根据题意，作出直线x﹣2y+4=0，分析可得：原点（0，0）在直线右下方，将原点坐标（0，0）代入x﹣2y+4可得，x﹣2y+4＞0，故不等式x﹣2y+4＞0表示的区域在直线x﹣2y+4=0的右下方；故选：D．3．已知角α的终边经过点P（﹣3，﹣4），则cosα的值是（）A．﹣ B．C．﹣ D．【考点】G9：任意角的三角函数的定义．【分析】由题意利用任意角的三角函数的定义，求得cosα的值．【解答】解：∵角α的终边经过点P（﹣3，﹣4），∴x=﹣3，y=﹣4，r=|OP|=5，则cosα==﹣，故选：C．4．不等式x2﹣3x﹣10＞0的解集是（）A．{x|﹣2≤x≤5}B．{x|x≥5或x≤﹣2}C．{x|﹣2＜x＜5}D．{x|x＞5或x＜﹣2}【考点】74：一元二次不等式的解法．【分析】把不等式化为（x+2）（x﹣5）＞0，求出解集即可．【解答】解：不等式x2﹣x﹣2＞0可化为（x+2）（x﹣5）＞0，解得x＜﹣2或x＞5，∴不等式的解集是{x|x＜﹣2或x＞5}．故选：D．5．若sinα=﹣，α是第四象限角，则cos（+α）的值是（）A．B．C．D．【考点】GI：三角函数的化简求值．【分析】利用同角三角函数的基本关系，两角和的余弦公式，求得cos（+α）的值．【解答】解：∵sinα=﹣，α是第四象限角，∴cosα==，则cos（+α）=cos cosα﹣sin sinα=﹣•（﹣）=，故选：B．6．若a，b∈R，下列命题正确的是（）A．若a＞|b|，则a2＞b2B．若|a|＞b，则a2＞b2C．若a≠|b|，则a2≠b2D．若a＞b，则a﹣b＜0【考点】R3：不等式的基本性质．【分析】根据题意，由不等式的性质易得A正确，利用特殊值法分析可得B、C、D错误，即可得答案．【解答】解：根据题意，依次分析选项：对于A、若a＞|b|，则有|a|＞|b|＞0，则a2＞b2，故A正确；对于B、当a=1，b=﹣2时，a2＜b2，故B错误；对于C、当a=﹣1，b=1时，满足a≠|b|，但有a2=b2，故C错误；对于D、若a＞b，则a﹣b＞0，故D错误；故选：A．7．要得到函数y=3sin（2x+）图象，只需把函数y=3sin2x图象（）A．向左平移个单位B．向右平移个单位C．向左平移个单位D．向右平移个单位【考点】HJ：函数y=Asin（ωx+φ）的图象变换．【分析】由题意利用函数y=Asin（ωx+φ）的图象变换规律，得出结论．【解答】解：把函数y=3sin2x图象向左平移个单位，可得y=3sin2（x+）=3sin（2x+）的图象，故选：C．8．已知M是平行四边形ABCD的对角线的交点，P为平面ABCD内任意一点，则+++等于（）A．4 B．3 C．2 D．【考点】9A：向量的三角形法则．【分析】根据向量的三角形的法则和平行四边形的性质即可求出答案【解答】解：∵M是平行四边形ABCD的对角线的交点，P为平面ABCD内任意一点，∴=+，=+，=+，=+，∵M是平行四边形ABCD对角线的交点，∴=﹣，=﹣，∴+++=+++++++=4，故选：A9．若cos2α=，则sin4α+cos4α的值是（）A．B．C．D．【考点】GH：同角三角函数基本关系的运用．【分析】利用同角三角函数的基本关系、二倍角的余弦公式，求得sin2α和cos2α 的值，可得sin4α+cos4α的值．【解答】解：∵cos2α=2cos2α﹣1=，∴cos2α=，∴sin2α=1﹣cos2α=，则sin4α+cos4α=+=，故选：A．10．已知直角三角形的两条直角边的和等于4，则直角三角形的面积的最大值是（）A．4 B．2 C．2 D．【考点】3W：二次函数的性质；7F：基本不等式．【分析】本题考查二次函数最大（小）值的求法．设一条直角边为x，则另一条为（4﹣x），则根据三角形面积公式即可得到面积S和x之间的解析式，求最值即可．【解答】解：设该三角形的一条直角边为x，则另一条为（4﹣x），则其面积S=x（4﹣x）=﹣（x﹣2）2+2，（x＞0）分析可得：当x=2时，S取得最大值，此时S=2；故选：C．11．已知点（n，a n）在函数y=2x﹣13的图象上，则数列{a n}的前n项和S n的最小值为（）A．36 B．﹣36 C．6 D．﹣6【考点】8E：数列的求和．【分析】点（n，a n）在函数y=2x﹣13的图象上，的a n=2n﹣13，a1=﹣11，=n2﹣12n由二次函数性质，求得S n的最小值【解答】解：∵点（n，a n）在函数y=2x﹣13的图象上，则a n=2n﹣13，a1=﹣11=n2﹣12n∵n∈N+，∴当n=6时，S n取得最小值为﹣36．故选：B12．若钝角三角形三内角的度数成等差数列，且最大边长与最小边长的比值为m，则m的范围是（）A．（1，2） B．（2，+∞）C．[3，+∞）D．（3，+∞）【考点】HQ：正弦定理的应用．【分析】设三个角分别为﹣A，， +A，由正弦定理可得m==，利用两角和差的正弦公式化为，利用单调性求出它的值域．【解答】解：钝角三角形三内角A、B、C的度数成等差数列，则B=，A+C=，可设三个角分别为﹣A，， +A．故m====．又＜A＜，∴＜tanA＜．令t=tanA，且＜t＜，则m=在[，]上是增函数，∴+∞＞m＞2，故选B．二、填空题：本大题共4小题，每小题5分，满分20分.把答案填在答题卡上.13．若向量=（4，2），=（8，x），∥，则x的值为4．【考点】9K：平面向量共线（平行）的坐标表示．【分析】利用向量平行的性质直接求解．【解答】解：∵向量=（4，2），=（8，x），∥，∴，解得x=4．故答案为：4．14．若关于x的方程x2﹣mx+m=0没有实数根，则实数m的取值范围是（0，4）．【考点】3W：二次函数的性质．【分析】由二次函数的性质可知：△＜0，根据一元二次不等式的解法，即可求得m的取值范围．【解答】解：由方程x2﹣mx+m=0没有实数根，则△＜0，∴m2﹣4m＜0，解得：0＜m＜4，∴实数m的取值范围（0，4），故答案为：（0，4）．15．已知x，y满足，则z=2x+y的最大值为3．【考点】7C：简单线性规划．【分析】先根据约束条件画出可行域，再利用几何意义求最值，z=2x+y表示直线在y轴上的截距，只需求出可行域直线在y轴上的截距最大值即可．【解答】解：，在坐标系中画出图象，三条线的交点分别是A（﹣1，﹣1），B（，），C（2，﹣1），在△ABC中满足z=2x+y的最大值是点C，代入得最大值等于3．故答案为：3．16．设f（x）=sinxcosx+cos2x，则f（x）的单调递减区间是[kπ+，kπ+]，（k∈Z）．【考点】GL：三角函数中的恒等变换应用．【分析】推导出f（x）=sin（2x+）+，由此能求出f（x）的单调递减区间．【解答】解：∵f（x）=sinxcosx+cos2x==sin（2x+）+，∴f（x）的单调递减区间满足：，k∈Z，∴，k∈Z．∴f（x）的单调递减区间是[kπ+，kπ+]，（k∈Z）．故答案为：[kπ+，kπ+]，（k∈Z）．三、解答题：本大题共6小题，满分70分．解答应写出文字说明，证明过程或演算步骤．17．已知等比数列{a n}的前n项和为S n，公比为q（q≠1），证明：S n=．【考点】89：等比数列的前n项和．【分析】由，得，利用错位相减法能证明S n=．【解答】证明：因为，…所以，…qS n=，…所以（1﹣q）S n=，…当q≠1时，有S n=．…18．已知平面向量，满足||=1，||=2．（1）若与的夹角θ=120°，求|+|的值；（2）若（k+）⊥（k﹣），求实数k的值．【考点】9S：数量积表示两个向量的夹角；9T：数量积判断两个平面向量的垂直关系．【分析】（1）利用两个向量数量积的定义，求得的值，可得|+|=的值．（2）利用两个向量垂直的性质，可得（k+）•（k﹣）=k2•a2﹣=0，由此求得k的值．【解答】解：（1）||=1，||=2，若与的夹角θ=120°，则=1•2•cos120°=﹣1，∴|+|====．（2）∵（k+）⊥（k﹣），∴（k+）•（k﹣）=k2•﹣=k2﹣4=0，∴k=±2．19．在△ABC中，内角A，B，C的对边分别为a，b，c，已知c=acosB+bsinA．（1）求A；（2）若a=2，b=c，求△ABC的面积．【考点】HP：正弦定理．【分析】（1）由已知及正弦定理，三角形内角和定理，两角和的正弦函数公式，同角三角函数基本关系式可得：tanA=1，结合范围A∈（0，π），可求A的值．（2）由三角形面积公式及余弦定理可求b2的值，进而利用三角形面积公式即可计算得解．【解答】（本小题满分12分）解：（1）由c=acosB+bsinA及正弦定理可得：sinC=sinAcosB+sinBsinA．…在△ABC中，C=π﹣A﹣B，所以sinC=sin（A+B）=sinAcosB+cosAsinB．…由以上两式得sinA=cosA，即tanA=1，…又A∈（0，π），所以A=．…（2）由于S△ABC=bcsinA=bc，…由a=2，及余弦定理得：4=b2+c2﹣2bccosB=b2+c2﹣，…因为b=c，所以4=2b2﹣b2，即b2==4，…故△ABC的面积S=bc=b2=．…20．已知数列{a n}的前n项和为S n，且a1=2，a n+1=S n（n=1，2，3，…）．（1）证明：数列{}是等比数列；（2）设b n=，求数列{b n}的前n项和T n．【考点】8H：数列递推式；8E：数列的求和．【分析】（1）a n+1=S n+1﹣S n=S n，整理为=2．即可证明．（2）由（1）得：=2n，即S n=n•2n．可得b n====﹣，利用裂项求和方法即可得出．【解答】（1）证明：因为，a n+1=S n+1﹣S n=S n，所以=2，又a1=2，故数列{}是等比数列，首项为2，公比为2的等比数列．（2）解：由（1）得：=2n，即S n=n•2n．所以b n====﹣，故数列{b n}的前n项和T n=++…+=1﹣=．21．某电力部门需在A、B两地之间架设高压电线，因地理条件限制，不能直接测量A、B两地距离．现测量人员在相距km的C、D两地（假设A、B、C、D在同一平面上）测得∠ACB=75°，∠BCD=45°，∠ADC=30°，∠ADB=45°（如图），假如考虑到电线的自然下垂和施工损耗等原因，实际所须电线长度为A、B距离的倍，问施工单位应该准备多长的电线？【考点】HU：解三角形的实际应用．【分析】在△ACD中求出AC，在△BCD中求出BC，在△ABC中利用余弦定理求出AB．【解答】解：在△ACD中，∵∠ADC=30°，∠ACD=75°+45°=120°，∴∠CAD=30°，∴AC=CD=，在△BCD中，∵∠BDC=30°+45°=75°，∠BCD=45°，∴∠CBD=60°，由正弦定理得：，∴BC===．在△ABC中，由余弦定理得：AB2=AC2+BC2﹣2AC•BC•cos∠ACB=3+（）2﹣2••=5，∴AB=．故施工单位应该准备电线长为=5km．22．已知A，B，C为锐角△ABC的内角，=（sinA，sinBsinC），=（1，﹣2），⊥．（1）tanB，tanBtanC，tanC能否构成等差数列？并证明你的结论；（2）求tanAtanBtanC的最小值．【考点】9T：数量积判断两个平面向量的垂直关系．【分析】（1）依题意有sinA=2sinBsinC，从而2sinBsinC=sinBcosC+cosBsinC，再由cosB＞0，cosC ＞0，能推导出tanB，tanBtanC，tanC成等差数列．（2）推导出tanAtanBtanC=tanA+tanB+tanC，从而tanAtanBtanC≥8，由此能求出tanAtanBtanC 的最小值为8．【解答】（本小题满分12分）解：（1）依题意有sinA=2sinBsinC．…在△ABC中，A=π﹣B﹣C，所以sinA=sin（B+C）=sinBcosC+cosBsinC，…所以2sinBsinC=sinBcosC+cosBsinC．…因为△ABC为锐角三角形，所以cosB＞0，cosC＞0，所以tanB+tanC=2tanBtanC，…所以tanB，tanBtanC，tanC成等差数列．…（2）在锐角△ABC中，tanA=tan（π﹣B﹣C）=﹣tan（B+C）=﹣，…即tanAtanBtanC=tanA+tanB+tanC，…由（1）知tanB+tanC=2tanBtanC，于是tanAtanBtanC=tanA+2tanBtanC≥，…整理得tanAtanBtanC≥8，…当且仅当tanA=4时取等号，故tanAtanBtanC的最小值为8．…。

国际贸易实务试卷A卷（英文）09.12

国际贸易实务试卷A卷（英文）09.12第一篇：国际贸易实务试卷A卷(英文)09.12广东外语外贸大学国际经济贸易学院《国际贸易实务》2009-2010学年第一学期期末考试试卷（A卷）考核对象：‘4+0’国贸084班‘4+0’国贸085班考试时间：2小时班级：_______ 学号：________ 姓名：_________ 成绩：________Ⅰ.Put T for true or F for false in the brackets at the end of each statement.(15%)1.（F）According to INCOTERMS 2000, if the seller exports ceramics using CIF term, he must insure the goods against All Risks plus Risk of Clash and Breakage.2.（F）According to INCOTERMS 2000, under CIF Liner T erms Hamburg, the buyer must pay the discharging fees in the port of destination.3.（F）International customs and practice is the international standard which is of some guiding significance to international business men.So all the international business men should abide by the international customs and practice.4.（T）When the charterer fails to load or unload the goods within the stipulated period of time, he has to pay demurrage to the ship-owner.5.（F）In order to avoid complications, we should try our best to usemuch more kinds of methods to stipulate the quality of the goods.6.（F）According to CISG, if the package of the goods is not in acordance with the terms and conditions of the contract, the buyer could lodge claims, bu t he couldn’t reject the goods.7.（F）According to CISG, if the seller delivers a quantity of goods greater than that provided for in the contract, the buyer may take delivery or refuse to take delivery of all the quantity(including theexcess quantity and the contracted quantity).8.（F）A chinese company exports 1500 bags of cement using CIF term in the contract and has insured the goods against F.P.A.before shipment.However five bags fall into water when loading in the port of shipment.Because the five bags have not been on board yet, the insurance company is not responsible for the loss of the five bags.9.（T）According to UCP 600, if there isn’t any other stipulation, the transshipment is allowed.10.（F）The clause of “ CIF London, New York or Tokyo, at buyer’s option” is reasonable and we could agree when exporting goods.11.（T）According to UCP 600, the L/C is independent of the underlying transactions.12.（F）According to CISG, the offeror can withdraw his offer, but he can not revoke it no matter what happened.13.（F）The colletcing bank should promise to get the money from the buyer under Collection.14.（T）According to UCP 600, the beneficiary should present full set clean on board B/Ls if the L/C requires B/Ls with no special terms and conditions.15.（F）Under Collec tion, the payer of the draft should be the buyer’s bank.Ⅱ.Please choose the best answer from the following choices of each question.(20%)1.An exporter in Guangzhou has agreed to sell goods to a company in New York.The exporter is responsible for arranging transport but not insurance.Which of the following shipping terms is correct?（）A.CIF New YorkB.FOB New YorkC.CFR New YorkD.FOB Guangzhou 2.According to UCP 600, if there is no special description about the form of the L/C in it, then this L/C is（）A.irrecovable and non-transferable B.recovable and transferable C.irrecovable and transferable D.recovable and non-transferable 3.Which term means the minimum cost coverage by the seller?（）A.EXWB.FCAC.FASD.FOB 4.According to CISG, when sale by sample and there are not any other detailed stipulations in contract, the goods delivered by the seller should be（）A.About same as the sampleB.same as the sampleC.different a little from sampleD.A, B, C are all right.5.A B/L acts as（）A.a receipt of goods by the carrier B.an evidence of the contract of carriageC.a document of title for the goodsD.A, B, C are all right.6.Under D/A, the draft must be（）A.sight draftB.time draftC.banker’s draftD.clean draft 7.According to CISG, the offer can be submitted （）A.in written formB.orallyC.in written form or be sent orally 8.The shipping Mark usually doesn’t contain（）A.the code name of shipper or consigneeB.number of packages of destinationD.chemical characteristics 9.In the following payment terms,（）is the safest term to the seller.A.sight payment L/C B.D/P at sight C.Payment at 30 days after delivery of goods D.Cash with order 10.In the following statements about loading and discharging charges in charter party,（）is correct.A.F.I.means the shipper should unload the goods by himself.B.F.O.means the shipper should load the goods by himself.C.The time charter party shouldn’t stipulate terms about these charges.D.The ship-owner isn’t responsible for these charges in tramp shipping.Ⅲ.Calculation(25%)1.A Company in Guangzhou quotes its exporting price, USD950 Per Metric Ton FOB Guangzhou, to a German company.But theGerman company requires the exporter to offer CIF Hamburg price(with the goods insured W.P.A.plus War Risk).If the freight from Guangzhou to Hamburg is USD180 Per Metric Ton, the insured amount is 110% of CIF value and the premium rate is 1.3% of W.P.A.plus War Risk.(1)Please calculate how much this exporting company should offer CIF Hamburg price per Metric Ton with the same profit.(10%)(2)If the German company requires the exporter to offer CIFC5% Hamburg price(with the goods insured W.P.A.plus War Risk).Please calculate how much this exporting company should offer CIFC5% Hamburg price per Metric Ton with the same profit.(5%)2.A company in Shanghai exports some garments to a foreign company.the total exporting amount is USD 70000 FOB Shanghai.If the domestic purchasing price of these garments is 450000 RMB.The domestic total charges(including all kinds of domestic fees and taxes)are 40000 RMB.And the export tax rebate is 3000 RMB.And the exchange rate is USD1:RMB7.Please calculate the rate of profit or loss of this export transaction.(10%) Ⅳ.Case Study(40%)A Chinese exporter exported 5000 sets electrical household appliances to an importer on the basis of USD 600 per set CFR Los Angeles.Both parties agreed to stipulate the following in the contract:“…… 40% payment by T/T in advance and 60% payment by D/P 90 days after sight.The buyer should remit the 40% of total value on or before September 30th, 2008.Shipment from Chinese port to Los Angeles, not later than Oct.21st, 2008.Packed in wooden box fumigated more over 12 hours with H2S gas.Partial shipment and transshipment are prohibited.……”After received buyer’s remittance money September 28th, the exporter shipped 3000 sets in Shanghai Port on Oct.4th, 2008, then sent shipping advice on time to the importer and got one set of clean on board B/Ls.Then the exporter shipped the other 2000 sets on board the same vessel in Guangzhou Port on Oct.8th, 2008, sent shipping advice on time to the importer and got other one set of clean on board B/Ls.And then the vessel began to sail to Los Angeles.1.Whether the seller has breached the contract provision of “Partial shipment and transshipment are prohibited” or not? Why?(5%)2.If during the transportation from Guangzhou to Los Angeles by sea, the ship struck on a rock and got stranded.Therefore, the ship arrived at Los Angeles after a delay(latter about 20 days than usual time)and part of goods have been damaged during transportation.According to INCOTERMS 2000, whether the importer has the right to make a claim against the seller because of transportation delay? Why?(5%)3.If these appliances had been insured against W.P.A as per China Insurance Clause before shipment.And if the Inspection Certificate states that: 1000 sets suffered losses at USD 30000 due to the above event;the other 4000 sets are in good conditions and quality.Whether the insurance company should compensate the damage or not? Why?(6%)4.If the importer became bankrupt Nov.2008, without paying money and taking the collection documents, what should the collecting bank do? Was the collecting bank responsible for receiving and keeping goods? Why? What should the exporter do? Why?(10%)5.If the exporter entrust bank for D/P, but importer borrowedthe full set of documents from collecting bank with T/R before payment and later the importer became bankrupt, what should the exporter do? Why?(7%)6.If the payment term in the contract was changed to “40% payment by T/T in advance and 60% payment by L/C 90 days after sight” and the importer became bankrupt Nov.2008, whether the exporter could receive payments on time provided that it had made complying presentation to issuing bank on time? Why?(7%)6第二篇：国际贸易实务试卷A卷2010(英文)及答案广东外语外贸大学国际经济贸易学院《国际贸易实务》2009-2010学年第二学期期末考试试卷（A卷）考核对象：金融081、082、083、084班保险081、082班考试时间：2小时班级：_______ 学号：________ 姓名：_________ 成绩：________Ⅰ.Put T for true or F for false in the corresponding blanks on your answer sheet.(20%)1.（）According to INCOTERMS 2000, under FOB contract, the buyer has no obligation to contract for insurance and pay the insurance premium.2.（）According to INCOTERMS 2000, under CIF contract, the seller must procure marine insurance, while under CFR contract, it is a common practice that the buyer contracts for insurance and pays the insurance premium.So under the CIF contract, the goods are seller’s risk during the internaitonal marine transport, while under the CFR contract, it is the buyer who should bear the risk of loss of or damage to the goods during the internaitonal marine transport.3.（）Under CIF contract, the seller would better ship the goods before the time of shipment stipulated in the contract for fear of the loss of late arrival of the goods to thebuyer.4.（）When the risk of loss of or damage to the goods is transferred from the seller to the buyer, all the charges and obligations of this internaional transaction will be transferred from the seller to the buyer immediately.5.（）According to INCOTERMS 2000, under E XW contract, the sellr’s obligation is minimum.6.（）International customs and practice is the international standard which is of some guiding significance to international business.So all the international business persons should abide by the international customs and practice.17.（）In order to avoid disputes, we should try our best to use much more kinds of methods to stipulate the quality of the goods in the international contract.8.（）According to CISG, if the package of the goods is not in acordance with the terms and conditions of the contract, the buyer could reject the goods and lodge claims.9.（T）If the goods are sold by weight, but there isn’t any stipulations about the method for calculating weight in the contract, then the payment for goods should be calculated according to its net weight.10.（）Partial loss or damage is not recoverable with FPA.11.（）In ocean marine insurance, general average should be borne by the carrier totally, who may, upon presentation of evidence of the loss, recover the loss from the insurance company.12.（）Demurrage is a fine imposed on the charterer for the delay in the loading and/or unloading of the goods.13.（）Order B/L can be transferred with endorsement.14.（）Unclean B/L will be accepted by the buyer or the issuing bank.15.（）A B/L, Rail Way Bill, or Air Way Bill could be negotiated or transferred because all of them are documents of title to the goods.16.（）According to INCOTERMS 2000, under CIF contract, the seller has no obligation to give the buyer prompt shipping advice after the goods are shipped on boardthe vessel, because the seller has insured the goods for the buyer before shipment.17.（）According to UCP 600, the issuing bank shall have a maximum of five banking days following the day of presentation to determine if a presentation is complying.When the issuing bank decides to refuse to honour, it must give a single notice to that effect to the presenter.18.（T）According to UCP 600, all the credits are irrevocable and thereby constitute a definite undertaking of the issuing bank to honour a complying presentation.19.（）Under D/P, the remitting bank and the collecting bank offer their collection service with discretion but they usually don’t promise to get the sales proceeds for the seller.20.（）Under D/A, the collecting bank should be responsible for the goods(inculding take and store the goods, etc.)if the buyer doesn’t accept the seller’s draft(s)and documents.Ⅱ.Please choose the best answer from the following choices of each question and write them on your answer sheet.(15%)21.The term of FOB should be followed by（）in a international trade d place of origind port of shipmentd port of destinationd place of destination 22.According to UCP 600, the confirming bank must negotiate and/or honor（）A.if the issuing bank agrees to negotiate and/or honor B.if the applicant agrees to negotiate and/or honor C.if it has received a complying presentation from the presenter D.if the beneficiary has shipped the stipulated goods on time 23.Under documentary collection, the draft must be（）A.sight draft B.time draft C.banker’s draft mercial draft 24.According to CISG, the international business person can（）before the offer reaches the offeree.A.withdraw his/her offerB.revoke his/her offerC.withdraw his/her contractD.revoke his/her contract 25.According to UCP 600, under L/C, the payer of the draft is（）.A.the buyerB.the advising bankC.the negotiating bankD.the issuing bank 26.If the CIF value in a international contract is USD 9 000 000, and there isn’t any special terms and conditions about insurance, then according to INCOTERMS 2000, the seller could insure the goods for（）D 9 000 000 against FPAD 10 000 000 against WPAD 9 000 000 against WPAD 9 900 000 against TPND 27.According to CISG, the acceptance can be submitted（）A.in written formB.orallyC.in written form or be sent orally 28.In the following payment terms,（）is the safest term to the seller.A.Payment against documents, at 30 days after sight B.Payment by T/T, at 30 days after arrival of goods C.Payment against documents, at 30 days from the date of B/LD.Payment by acceptance L/C, at 30 days after sight 29.Under CFR contract, the goods are damaged during marine transport and the buyer suffers losses estimated at USD 1 000 due to natural calamity, USD 800 due to fortuitous accidents, and USD 2 000 due to extraneous risks.If the buyer has insured the goods for USD 1 000 000 against WPA before shiment, then the insurer should pay（）compensation to the D 3800D 1800D 3000D 2800 30.In the following statements about loading and discharging charges in charter party,（）is correct.A.F.I.means the shipper should unload the goods by himself.B.F.O.means the shipper should load the goods byhimself.C.The time charter p arty shouldn’t stipulate terms about these charges.D.The ship-owner isn’t responsible for these charges in tramp shipping.31.Counter sample is made by（）which can help avoid disputes over the quality of goods in the future transaction.A.the buyerB.the sellerC.the carrierD.the offerer 32.The more or less clause is a clause that stipulates that（）.A.the quantity delivered can be more or less within 5 percent.B.the quantity delivered can be more or less within 10 percent C.the quantity delivered can be more or less within 3 percent D.the quantity delivered can be more or less within certain extent 33.Sales by description and illustration is applicable to（）most.A.wheatB.medical apparatusC.mineral oreD.ordinary stainless steel cup 34.Neutral packing is adopted to（）.A.prevent corrosion by acids or alkali B.break tariff and non-tariff barriers of exporting countries C.break tariff and non-tariff barriers of importing countries D.A, B and C are all right 35.Merchant vessels can be divided into liners and tramps, and to the owner of cargo,（）proved to be a more convenient means of international cargo distribution.A.liners B.trampsC.none of themⅢ.Calculation(Please write your answers on your answer sheet, and the results should be rounded off to two decimals.20%)36.A Company in Shenzhen quotes its exporting price, USD1000 Per Metric Ton FOB Shenzhen, to a Japanese company.But the Japanese company requires the exporter to offer CIF Yokohama price(with the goods insured F.P.A.).If the freight from Shenzhen to Yokohama is USD 200 per Metric Ton,the insured amount is 110% of CIF value and the premium rate is 1% of F.P.A..(1)Please calculate how much this exporting company should offer CIF Yokohama price per Metric Ton with the same profit.(8%)(2)If the Japanese company requires the exporter to offer CIFC5% Yokohama price(with the goods insured F.P.A.).Please calculate how much this exporting company should offer CIFC5% Yokohama price per Metric Ton with the same profit.(4%)(3)If the exporting quantity is 100 Metric Tons, the domestic purchasing price of these goods is 6000 RMB per Metric Ton.The domestic total charges(including all kinds of domestic fees and taxes)are 13000 RMB.And the export tax rebate is 3000 RMB totally.And the exchange rate is USD1:RMB6.8.Please calculate the rate of profit or loss of this export transaction.(8%) Ⅳ.Case Study(Please write your answers on your answer sheet, 10%)37.On 15th May, 2010, a chinese company offered to a french company, “sell 10000 Qing Yan Brand bicycles, Article No.171069, FOB Shanghai USD 100 per set, shipment during July, 2010.Subject reply here on or before 20th May, 2010.......”.On 17th May, 2010, the french company replied by FAX, “ we accept your offer dated 15th May, 2010, but at the price of FOB Shanghai USD 80 per s et, shipment during October, 2010.”The chinese company hadn’t replied to the french company and sold their bicycles to another foreign company.However, on 19th May, 2010, the french company replied by FAX again, “ we completely accept your offer dated 15t h May, 2010.” The chinese company replied to the french company at once by FAX, “we have sold the bicycles to others.We will offer you in the future as possible as we can.”But the french company thought that the contract has beenconcluded and required the chinese company to ship the bicycles during July, 2010 at Shanghai port.According to CISG, do you think the above two companies have conculded a contract? Why?V.Write your answers on your answer sheet to the following question 38, which is based on the following L/C.(35%) -------------RECEIVED MESSAGE Status: MESSAGE DELIVERED Station: 1 BEGINNING OF MESSAGE Own Address : BOCOZOXXXXX: BANK OF CHINA : GUANGZHOU Output Message Type : 700 ISSUE OF A DOCUMENTARY CREDIT Sent by : ACNZ2WXXX WESTPAC BANK COPROPATION WELLINGTON :(FOR ALL NEW ZEALAND BRANCH)Output Date/Time : 061207/0928 Priority : Normal 27/ SEQUENCE OF TOTAL: 1/1 40A/ FORM OF DOCUMENTARY CREDIT: IRREVOCABLE 20/ DOCUMENTARY CREDIT NUMBER: 0612/20487923 31C/ DATE AND PLACE OF EXPIRY: 070121 P.R.O.C.50/ APPLICANT: NEW CHEM INC.AUCKLAND, NEW ZEALAND 59/ BENEFICIARY: GUANGZHOU FOREIGN TRADE CORP.GUANGZHOU, P.R.OF CHINA 32B/ CURRENCY CODE AMOUNT: USD 34870,00 41D/ AVAILABLE WITH … BY … : ANY BANK BY NEGOTIATION 42C/ DRAFTS AT …… : SIGHT FOR FULL INVOICE VALUE 42A/ DRAWEE: WPACNZZWAKL WESTPAC BANKING CORPORATION, AUCKLAND 43P/ PARTIAL SHIPMENTS: NOT ALLOWED 43T/ TRANSSHIPMENT: ALLOWED 44A/ ON BOARD/DISP/TAKING CHARGE: ANY P.R.C.PORT 44B/ ROF TRANSPORTATION TO: AUCKLAND NEW ZEALAND 44C/ LATEST DATE OF SHIPMENT: 061213 45A/ DESCP OF GOODS AND/OR SERVICE: BLACK SILICON CARBIDE CIF AUCKLAND 46A/ DOCUMENTS REQUIRED: +COMMERCIAL INVOICES +FULL SET CLEAN “ON BOARD”BILLS OF LADING MADE OUT TO ORDER BLANK ENDORSED MARKED “FREIGHT PREPAID” AND NOTIFYAPPLICANT +INSURANCE POLICY OR CERTIFICATE COVERING OCEAN MARINE TRANSPORTATION ALL RISKS AND WAR RISKS.+PACKING LIST +CERTIFICATE OF ANALYSIS +BENEFICIARY CERTIFICATE STATING BATCH NUMBERS APPEAR ON ALL DOCUMENTS AND PACKAGES 47A/ ADDITIONAL CONDITIONS: DRAFTS DRAWN HEREUNDER MUST BEAR DOCUMENTARY CREDIT NUMBER AND DATE.EACH PRESENTATION OF DISCREPANCIES DOCUMENTS UNDER THIS CREDIT,A FEE OF NZD70.00(OR ITS EQUIVALENT IN THE CURRENCY OF YOUR DRAWING)IS FOR ACCOUNT OF BENEFICIARY AND MUST BE DEDUCTED FROM YOUR REIMBURSEMENT CLAIM OR WILL BE DEDUCTED FROM THE PROCEEDS(IN THE EVENT CLAIM IS PAID BY OURSELVES).ALL DOCUMENTS IN DUPICATE UNLESS OTHERWISE STATED.71B/ CHARGES: 6ALL BANK CHARGES OUTSIDE COUNTRY OF ISSUING BANK ARE FOR ACCOUNT OF BENEFICIARY.48/ PERIOD FOR PRESENTATION: DOCUMENTS TO BE PRESENTED WITHIN 21 DAYS AFTER ISSUANCE OF BILL OF LADING BUT WITHIN THE VALIDITY DATE OF THIS DOCUMENTARY CREDIT 49/ CONFIRMATION INSTRUTIONS: WITHOUT 78/ INSTRUCS TO PAY/ACCPT/NEGOT BANK: UPON RECEIPT OF COMPLIANT DOCUMENTS, WE UNDERTAKE TO REMIT PROCEEDS BY TELEGRAPHIC TRANSFER IN TERMS OF YOUR INSTRUCTONS, WITHIN TWO BUSINESS DAYS, LESS OUR REIMBURSEMENT CHAREGES AND COSTS OF NZD80.00, THE EQUIVALENT OF WHICH WILL BE DEDUCTED FROM YOUR CLAIM.DRAFT AND DOCUMENTS ARE TO BE COURIERED IN ONE LOT TO WESTPAC BANKING CORPORATION, NEW ZEALAND.SAC: SWIFT Authentication Correct38.（1）本信用证的申请人和受益人？（4%）（2）本信用证的种类(至少写出两种)？（4%）（3）本信用证的到期日及到期地点？（4%）（4）本信用证是否允许转运，是否允许分批装运？（4%）（5）本信用证的最迟装运日？（2%）（6）本信用证对汇票有何要求？（6%）（7）本信用证对提单有何要求？（6%）（8）本信用证对保险单据有何要求？（5%）广东外语外贸大学国际经济贸易学院《国际贸易实务》2009-2010学年第二学期期末考试试卷（A卷）参考答案考核对象：金融081、082、083、084班保险081、082班考试时间：2小时班级：_______ 学号：________ 姓名：_________ 成绩：________Ⅰ.Put T for true or F for false in the corresponding blanks.(20%)1.T2.F3.F4.F5.T6.F7.F8.F9.T 10.F11.F 12.T 13.T 14.F 15.F 16.F 17.T 18.T 19.T 20.FⅡ.Please write the best answer in the corresponding blanks.(15%)21.B 22.C 23.D 24.A 25.D 26.B 27.C 28.D 29.B 30.C31.B 32.D 33.B 34.C 35.AⅢ.Calculation(The results should be rounded off to two decimals.20%)36.（1）CIF=(FOB+F)/(1-premium rate×110％）＝(1000+200)/(1-1%×110％)=1200/(1-0.011)＝1200/0.989 ≈1213.35 USD per metric tonI.e.this exporting Company should offer CIF Yokohama USD1213.35 per Metric Ton to its customer with the same profit.(2)CIFC5%＝CIF/（1－5％）＝1213.35/0.95 ≈ 1277.21 USD per metric tonSo, the exporting Company should offer CIFC5% Yokohama USD 1277.21 per metric ton to its customer with the same profit.(3)The domestic purchasing price plus domestic total charges minus the export tax rebate is domestic cost of export.I.e.the total domestic cost = 6000×100 + 13000 －3000= 610000 RMBThe revenue in RMB = foreign exchange earning × exchange rate= FOB ×100×exchange rate=1000×100× exchange rate=100000 × 6.8= 680000 RMBSo, the rate of profit =(revenue－domestic cost)÷ domestic cost × 100%=(680000－610000)÷ 610000 × 100% ≈ 11.48%Ⅳ.Case Study(10%)37.(1)According to CISG, the two companies have not conculded a contract.(2)CISG Article 19, “1）A reply to an offer which purports to be an acceptance but contains additions, limitations or other modifications is a rejection of the offer and constitutes a counter-offer.2）However, a reply to an offer which purports to be an acceptance but contains additional or different terms which do not materially alter the terms of the offer constitutes an acceptance，unless the offeror, without undue delay, objects orally to the discrepancy or dispatches a notice to that effect.If he does not so object, the terms of the contract are the terms of the offer with the modifications contained in the acceptance.3)Additional or different terms relating, among otherthings, to the price, payment, quality and quantity of the goods, place and time of delivery, extent of one party's liability to the other or the settlement of disputes are considered to alter the terms of the offer materially.”(3)On 17th May, 2010, the french company replied by FAX, “ we accept your offer dated 15th May, 2010, but at the price of FOB Shanghai USD 80 per set, shipment during October, 2010.”That is to say, the french company altered the price and the time of shipment in the chinese company’s offer dated 15th May, 2010.So the reply made by the french company dated 17th May 2010 was a counter-offer and a new offer.Then, the offer made by the chinese company dated 15th May 2010 became invalid.The chinese company hasn’t accepted the new offer made by the french company dated 17th May 2010.The reply made by the french company dated 19th May 2010 was a new offer too.And the chinese company hasn’t ac cepted the new offer made by the french company dated 19th May 2010 too.So the two companies have not conculded a contract.V.Write your answers in the corresponding blanks.(35%)38.（1）Applicant: NEW CHEM INC.，AUCKLAND, NEW ZEALAND Beneficiary: GUANGZHOU FOREIGN TRADE CORP.GUANGZHOU, P.R.OF CHINA（2）Irrevocable，Sight, Negotiable, Unconfirmed, Non-transferable,Documentary（3）21th January,2007 in china（4）PARTIAL SHIPMENTS: NOT ALLOWED TRANSSHIPMENT: ALLOWED（5）LATEST DATE OF SHIPMENT: 13th December,2006（6）DRAFTS AT SIGHT FOR FULL INVOICE VALUE, DRAWEE: WPACNZZWAKL, WESTPAC BANKING CORPORATION,AUCKLAND DRAFTS DRAWN HEREUNDER MUST BEAR DOCUMENTARY CREDIT NUMBER AND DATE.（7）FULL SET CLEAN “ON BOARD”BILLS OF LADING MADE OUT TO ORDER BLANK ENDORSED, MARKED “FREIGHT PREPAID” AND NOTIFY APPLICANT, IN DUPICATE（8）INSURANCE POLICY OR CERTIFICATE COVERING OCEAN MARINE TRANSPORTATION ALL RISKS AND WAR RISKS, IN DUPICATE第三篇：国际贸易实务试卷课程名称：国际贸易实务适用对象：本科试卷代号：一、单项选择题（每题1分，共15分）1、与进出口贸易关系最大，也是最重要的一项国际条约是（）。

广东省广州市天河区2023~2024学年高二下学期期末考试英语试卷

广东省广州市天河区2023~2024学年高二下学期期末考试英语试卷一、阅读理解Ten years ago, Airbnb passed a milestone: the number of people who had used the service to book a night’s stay outnumbered 4 million. But it was still believed to be a small player. Over the past decade, staying in somebody else’s home, or second home, for a short-term break has become the first choice I (and my mates, and my mum, and her mates) made when planning to visit a city.We much prefer it. Away from the eyes of annoying tourists, our boys are free to treat the house as a genuine home-from-home: that is, using every surface, from bookshelf to boiler cupboard, as a huge wonderland. As there is always a separate living space (actually separate, unlike the open-plan “suites” offered by most hotels), we can chat and watch TV once they’ve gone to bed. We use the kitchen to make them dinner and breakfast, which saves us money; then we get a takeaway from Deliveroo (another technological marvel) once the kids are in bed.I’ll admit that this routine can still present challenges. Simply loading up the car with daily necessities, snacks and drinks, and appropriate “in-flight entertainment” is an activity that, itself, kills your desire for holiday. But it’s always worth it. How I look forward to the small success when I’ve located the parking space for our rented room, after ten minutes of aimlessly driving around a complex one-way system. How I love examining the owner’s art and books, piecing together my impression of their personality from the clues they’ve left behind in random handmade objects. “Look, he’s got a signed Bruce Springsteen poster and an entire library of Jeffrey Archer! Did he turn Shakespeare as he got older, or inherit (继承) the books from his dad?”Best of all, I enjoy waking up on Sunday morning and being somewhere new — yet not being constantly aware, as one is in a hotel, of the financial deal during the experience. Wandering around cities, I’ve often found myself idly imagining what it would be like to live there, and with Airbnb one gets quite a bit closer to actually knowing the answer. That is why, I suspect, it’s no “small player” anymore.1．What does the author prefer to do when travelling?A．Use home-sharing platforms.B．Book a hotel in advance.C．Choose long-term stays.D．Stay together with family.2．What does the author like about the home-from-home experience, according to paragraph 3?A．Loading up the car.B．Locating a parking space.C．Reading the owner’s books.D．Picturing the owner’s personality.3．Why does the author write the text?A．To popularize a service.B．To share personal experiences.C．To explore a social issue.D．To provide useful information.“Although I have been teaching Hao Hao how to say ‘mom’ every day, he is still unable to say the word. He is now 24 years old,” says Zhao Xinling. Having a child with autism(自闭症), the 64-year-old has worked hard to help her son.She is the founder and principal of the Loving Home for Children Special Education and Rehabilitation(康复)Center in Guiyang, the first of its kind in Guizhou province. Over the years, she has provided support to more than 7,000 children with autism and witnessed the autistic community flourish — from being under-recognized to being increasingly understood and accepted — and she has seen how the community is gaining more support from broader society.Born in 2000, Hao Hao lost his language abilities suddenly when he was 22 months old and was later diagnosed(诊断)with autism. To better understand the disease, Zhao visited rehabilitation institutions, hospitals and schools in cities like Beijing and Guangzhou. She saw many parents like her and realized that their families shared enormous pressure. Fortunately, she met Guan Fuqin, a doctor among the first in Guizhou to provide autism diagnosis services for children. Guan advised her to establish an institution where children with autism could learn locally and their parents could help one another. And Guan would act as a volunteer, offering medical support. In 2003, the center was established.Three years later, Zhao began trying her hand at integrated education. “In the past, we wanted autistic children to improve themselves and fit into the lifestyles of normal people. However, through integrated education, normal children can learn to understand, accept and care for autistic children. These two-way efforts can make the lives of autistic children easier, and theirfamilies happier,” she notes. The institute has carried out such practices with over 20 kindergartens, primary schools and high schools in the city, and more than 2,000 autistic children have been enrolled in regular schools.Although there are still many challenges ahead, Zhao is confident about the future, “We need to view autism positively, accept it, and enjoy the different life it offers.”4．What does the underline word “flourish” mean in paragraph 2?A．Unify.B．Progress.C．Change.D．Succeed.5．What is paragraph 3 mainly about?A．Hao Hao’s sudden disease.B．Special support from a doctor.C．The birth of the center.D．Great effort to treat Hao Hao.6．What is Zhao Xinling’s suggestion for normal people?A．Be an active volunteer.B．Show respect to every life.C．Treat autistic children differently.D．Help autistic people adapt to their life.By 2040, nearly one in four Swedes will be 65 years or older. In a country where life expectancy is very high and most care for the elderly is government funded, that means a strain on spending and resources is approaching. One concern is the supply of affordable yet comfortable accommodations.Furniture giant IKEA has one idea. The company is launching a new style of home for dementia (痴呆) patients through BoKlok, a joint enterprise with a construction company that makes sustainable and affordable housing.“We see a growing concern that people are ending up in institutions where they do not want to end up,” noted Jonas Spangenberg, BoKlok CEO. “If we can crack the code where you can continue to live at a home that is more suitable for you, even with various syndromes (症状), we believe we could do a good thing for society.”For the past three decades, the group has built more than 11,000 modular (组合式的) homes throughout Sweden, Finland and Norway using the IKEA model: cut down costs by producing large quantities of parts off-site. Lower income customers only pay what they canafford after taxes and living expenses.Now, the company thinks it can help people who struggle with memory loss to live at home — saving the government money it would otherwise spend on care. It’s just built a small pilot with six apartments, the first tailored homes, just outside Stockholm. Design adjustments include taking mirrors and dark-colored floor out of bathrooms and fitting kitchen appliances with old-fashioned knobs, rather than digital controls.The developments also highlight spending time outdoors, and will include “therapeutic” gardens and clubhouses for socializing. That could make it more appealing for a partner to move there, too. “To take care of elderly people, that cost is exploding,” Jonas Spangenberg told CNN Business. “It’s much cheaper for society and the public to give them service back home.”7．What problem do senior people in Sweden face?A．A high aging rate.B．No access to suitable housing.C．Separation from their family.D．Huge expenses on health care.8．Which words can best describe the six pilot apartments?A．Dark-colored and natural.B．Well-equipped and stylish.C．User-friendly and comfortable.D．Visually-appealing and safe.9．What does Spangenberg think of the project?A．It was launched too late to be effective.B．It can reduce population with memory loss.C．It remains to be seen whether it’s a wise decision.D．It enables the government to better spend its money.10．What could be a suitable title for the text?A．Aging population: a challenge for Sweden.B．The IKEA model: a sustainable construction plan.C．BoKlok project is better housing dementia elderly.D．House companies are helping fight memory loss.Money habits are the small daily decisions we make that influence how we spend and saveour money. 11 But with a little awareness and effort, we can make improvements that will help us achieve our financial goals.Taking a careful look at your existing spending habits is one of the first steps in improving your money habits. 12 It can make you realize the potential issues on your spending habits, and help you identify areas where you can adjust your spending patterns.Next, set up clear financial goals for yourself. Having a specific aim in mind will help you keep motivated and focused, whether it’s saving for a down payment on a home, removing credit card debt, or creating an emergency fund.13 A budget ensures that your spending is focused on your priorities and that you set aside enough cash to achieve your goals. Make sure to include a category for savings and use it consistently.Impulsive (冲动的) purchasing is a crucial habit to break. 14 Making a list of the items you require before you go shopping and sticking to it is one approach to achieve this. Additionally, waiting a day or two before making a purchase can help you determine if you still want the item.Finally, it’s critical to pay attention to your financial habits and adjust them as needed.15 Keep in mind that adjustıng your spendıng patterns is a process, and its effects might not be seen right away. With a little knowledge and effort, you can make positive changes, helping you achieve your financial objectives and strengthen your overall financial health. A．Besides, cutting your budget is essential.B．It is effective to adjust our financial behaviors.C．It might be challenging to change these habits.D．Setting and sticking to a budget is also crucial.E．Track your spending and goals, and be prepared to change if necessary.F．Take action to stop it so that your bank account will be significantly increased.G．This involves tracking all your spending for a month and then analyzing the data.二、完形填空As I prepared our Saturday night barbecue, my daughter Rikki stormed into the house andwent straight to her room. Then I saw our neighbor Amy walking home across the street.“Rikki, come here. I need your help with dinner,” I called. She came with a(n) 16 look on her face—the kind kids have when they know they are wrong but have convinced themselves they are right. “I noticed Amy 17 . Why didn’t she stay long?” I asked, watching her closely. “I don’t like her,” Rikki 18 . “She dresses terrible and smells bad. None of us like her.”“That’s not her 19 , Rikki. I don’t know what her family is like, but maybe she doesn’t have anyone to help her.” I reminded her that everyone is unique and worthy, 20 their circumstances. As I couldn’t 21 her to like someone, I let it go. Rikki’s Dad, who had been watching while grilling, asked what was going on. He wanted to know 22 Amy was leaving with her head down and looking so sad. Rikki explained that Amy just dropped over 23 . Her dad then said, “Rikki, would you like to come with me for a 24 trip?” Curiously, Rikki jumped in the truck.They went to Amy’s house and invited her over for 25 . Soon, they returned with a smiling Amy. The girls talked a lot and played 26 . We gathered around our picnic table under the huge oak tree. I could see Rikki had 27 her prejudice. They were unaware of what the world might throw at them as they grew up, but on this warm summer evening, everything was 28 . After Amy went home, Rikki’s eyes 29 . “I had fun today, Momma,” she said. “I’m proud of you, baby.” I smiled back.Later her dad told me what they talked on the way to Amy’s house. He explained how he felt for Amy because he had been in her 30 as a child. He didn’t want Rikki to be judgmental but 31 and helpful. Rikki apologized, and she started thinking 32 .Today, Rikki has a heart of gold. She is the first to 33 those whom others might turn away and is generous in helping others. She has the 34 to love the unloved. I believe that day 35 her.16．A．innocent B．stubborn C．surprised D．blank 17．A．break in B．turn around C．pass by D．come over 18．A．announced B．complained C．whispered D．bargained 19．A．choice B．idea C．business D．fault20．A．because of B．regardless of C．according to D．except for 21．A．force B．remind C．teach D．warn 22．A．when B．how C．why D．whether 23．A．uninvited B．uneducated C．unnoticed D．unwashed 24．A．regular B．quick C．summer D．pleasure 25．A．party B．dinner C．study D．fun 26．A．happily B．safely C．quietly D．carefully 27．A．deepened B．challenged C．overcome D．hidden 28．A．perfect B．unique C．reasonable D．possible 29．A．shone B．rounded C．watered D．wandered 30．A．house B．shoes C．dream D．eyes 31．A．grateful B．brave C．kind D．responsible 32．A．seriously B．slowly C．differently D．clearly 33．A．welcome B．inspire C．respect D．bless 34．A．right B．chance C．duty D．ability 35．A．pleased B．freed C．moved D．shaped三、语法填空阅读下面短文，在空白处填入1个适当的单词或括号内单词的正确形式。

江西省上进联考2023-2024学年高一下学期期末调研检测英语(含解析,含听力原文,无音频)

绝密★启用前2023—2024学年高一年级下学期期末调研测试高一英语试卷试卷共8页，67小题，满分150分。

考试用时120分钟。

注意事项：1.考查范围：必修第三册全册。

2.答卷前，考生务必将自己的姓名、准考证号等填写在答题卡指定位置上。

3.回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其他答案标号。

回答非选择题时，将答案写在答题卡上。

写在本试卷上无效。

4.考生必须保持答题卡的整洁。

考试结束后，请将答题卡交回。

第一部分听力(共两节，满分30 分)做题时，先将答案标在试卷上，录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节 (共5 小题;每小题1.5分,满分7.5分)听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有 10 秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例:How much is the shirt?A.£19.15.B.£9.18.C.£9.15.答案是 C。

1. What is the weather like now?A. Cold.B. Hot.C. Warm.2. What is Steven doing?A. Gathering firewood.B. Having dinner.C. Preparing meat.3. Who does the man want to call?A. Tom.B. His secretary.C. The woman.4. How will the speakers go to the cinema?A. On foot.B. By car.C. By bus.5. What is the conversation mainly about?A. An expression.B. The Internet.C. A competition.第二节 (共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白，每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

高一联考各科考试说明

一、考试性质:考查高一年级学生在语文学科的学习上是否达到国家高中语文课程标准对考试内容要求的以合格标准为目的的水平性测试。

依据《普通高中语文课程标准（实验）》和与之配套的高中《语文》必修3和必修4命制试题。

二、考试范围：全卷课内、课外相结合，课内主要包括粤教版高中《语文》必修3和必修4。

三、考试形式：考试采用闭卷笔试形式。

全卷满分150分，考试用时150分钟。

四、试卷结构：与2011-2012学年第一学期高一语文试卷相似。

第一部分语言文字运用（4小题，12分）第二部分课内、课外古诗文阅读（7小题，33分）第三部分课内、课外现代文阅读（6小题，33分）第四部分语言表达（2小题，12分）第五部分写作（1小题，60分）五、试卷难度0.65一、考试性质本次测试是考查学生在数学学科学习上是否达到国家新课程标准对考试内容要求的合格标准为目的水平性测试，考试以《普通高中数学课程标准（实验）》相关内容的教学目标为参照，面向绝大多数学生，按照“以考查基础知识为主，适度考查能力”的命题原则，做到既有利于有效评价学生的学习水平，也有利于促进中学数学教学质量的提高。

二、考试范围必修4和必修5各章节分数所占比例大致分别为：三角函数45%，向量15%，数列15%，不等式25%（制定标准参照新课标中各章节所要求的课时数）三、考试形式考试采用闭卷形式，考试时间为120分钟，全卷满分150分四、试卷结构（1）全卷包括选择题、填空题、解答题三种题型。

选择题是四选一的单项选择题；填空题只要求直接填写结果，不必写出解答过程，每题可设置一个空或多个空；解答题要求写出文字说明、证明过程或演算步骤。

具体结构：选择题10题，满分50分填空题4题，满分20分解答题6题，满分80分（2）试题难度：全卷难度为0.6左右，其中容易题60%，中等题为30%，难题为10%高一英语笔试考试说明一. 考试性质本次考试属于学生学业成绩测试，贯彻学什么，考什么的原则。

2023-2024学年广东省广州市衡美高级中学高一下学期英语期中联考质量分析教学设计

- The students were waiting for the teacher outside the classroom.
3.过去进行时态的标志性词语
一些特定的时间状语和副词可以帮助我们判断句子是否需要使用过去进行时态。常见的标志性词语包括：
- at that time
- at the moment
引导学生关注学科前沿动态，培养学生的创新意识和探索精神。
情感升华：
结合过去进行时态内容，引导学生思考学科与生活的联系，培养学生的社会责任感。
鼓励学生分享学习过去进行时态的心得和体会，增进师生之间的情感交流。
（六）课堂小结（预计用时：2分钟）
简要回顾本节课学习的过去进行时态内容，强调重点和难点。
肯定学生的表现，鼓励他们继续努力。
5.教学工具：准备投影仪、计算机、音响等教学设备，确保教学过程中的多媒体资源能够正常播放。同时，准备白板、黑板等书写工具，以便于板书和讲解。
6.网络资源：确保教室网络畅通，以便于查找和分享在线教学资源。可以提前收藏一些与过去进行时态相关的英语学习网站、博客、论坛等，以便在教学中引导学生进行在线学习。
- I was reading a book.
- He was playing football.
- They were watching a movie.
2.过去进行时态的用法
过去进行时态主要用于描述在过去某个时间点正在进行的动作或状态。它强调的是动作的持续性。例如：
- While I was reading a book, she was cooking dinner.
- Fill in the blank with the correct past continuous tense form of the verb: "_____ (eat) they were watching TV."

广东省广州市七区2021-2022学年高二下学期期末教学质量监测英语试卷

2021学年第二学期期末教学质量监测高二英语试题本试卷满分130分。

考试用时120分钟。

注意事项：1. 答卷前，考生务必在答题卡上用黑色字迹的钢笔或签字笔填写学校、班级、姓名、试室号、座位号及准考证号，并用2B铅笔填涂准考证号。

因笔试不考听力，选择题从第二部分的“阅读”开始，试题序号从“21”开始。

2. 全部答案必须在答题卡上完成，答在本试卷上无效。

3. 选择题每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑。

如需要改动，用橡皮擦干净后，再选涂其他答案。

不能答在试卷上。

4. 非选择题必须用黑色字迹的钢笔或签字笔作答，答案必须写在答题卡各题目指定区域的相应位置上；如需要改动，先划掉原来的答案，然后再写上新的答案，改动的答案也不能超出指定的区域；不准使用铅笔、圆珠笔和涂改液。

不按以上要求作答的答案无效。

5. 考生必须保持答题卡的整洁，考试结束将试卷和答题卡一并交回。

第二部分阅读（共两节，满分50分）第一节（共15小题；每小题2.5分，满分37.5分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项。

AHOW TO FIND WATER IN THE WILDGetting lost in the wild is something that could happen to just anyone. The single most important thing you need to live is water. If you’re resourceful and know where to look, you can find or collect good drinking water in just about any environment on earth. Here are four top tips: Find a muddy areaDig a hole about a foot deep and one foot in diameter(直径) and wait. You may be surprised to find that the hole is soon filled with water, which will be muddy, but straining it through some cloth will clean it up, and it will get you by in the short term. It’s crucial to remember that any time you drink found water without purifying it, you’re taking a risk.Look for plantsIn a desert, look for where plants are growing, as they need water. Try to get up high and look downwards, as water is often found in low shaded areas.Desalinate seawaterOn an island you’re surrounded by undrinkable water. You can boil it and capture the steam in a cloth. When it’s soaking wet, you can wring out pure water.Cut the iceIf you are in Arctic eating snow doesn’t actually get you much water. And melting ice needs lots of fuel. One good way to get water is cutting through a frozen lake or river surface.Warning: Beware of bad waterNever drink from water that has dead animals or animal remains in it. The water probably has lots of minerals in it and has become toxic. You have the same problem with seawater—it’s too salty to be healthy to drink. Sadly, bir ds and animals can sometimes drink water that’s unsafe for people, so you can’t ignore other clues if they’re drinking water that looks bad.1. How do people get water in the muddy area?A. Capture the steam in a cloth.B. Look for some plants.C. Dig a hole about a foot deep.D. Cut through a frozen lake.2. What is probably the major concern of water seekers after finding water?A. How to store.B. How to purify.C. How to boil.D. How to melt.3. Water will be badly harmful to human health if it contains ________.A. living creaturesB. few mineralsC. salty elementsD. poisonous materialsBOur house was across the street from a hospital. We rented the upstairs rooms to outpatients at the clinic. One summer evening as I was preparing supper, there was a knock at the door. I opened it to see a truly awful looking man hardly taller than my eight-year-old daughter.But the frightening thing was his swollen face. He told me he’d been hunting for a room since noon but no one seemed to offer. For a moment I hesitated, but his next words convinced me, “I could sleep on the porch(门廊). My bus leaves early in the morning.” Having let him in, I went inside and asked him to join us for supper. But he politely refused. When I had finished the dishes, I went out to talk with him for a few minutes.He told me he fished for a living to support his daughter’s family. He didn’t tell it by way of complaint. In fact, he was thankful that no pain accompanied his disease. He thanked life for giving him the strength to keep going.At bedtime, we put a small camp bed in the children’s room for him. When I got up in themorning, the bed linens were neatly folded and the little man was out on the porch. He refused breakfast, but just before he left, he smiled, “Your children mad e me feel at home. Grownups are bothered by my face, but children don’t seem to mind.” I told him he was welcome to come again.In the years he came to stay overnight with us, there was never a time that he did not bring us fish or vegetables. Other times we received packages. Knowing how far he must walk to mail these and how little money he had made the gifts more precious. I know our family always will be thankful to have known him.4 What might lead to the old man’s failure to get a room before?A. His fishing job.B. His lack of money.C. His ugly appearance.D. His disabled daughter.5. Why did the author finally accept the old man?A. He was in very bad condition.B. He agreed to sleep on the porch.C. He wouldn’t leave until accepted.D. He wouldn’t bother them too much.6. What can we know about the old man from the text?A. He suffered a lot from his disease.B. He made efforts to send the author gifts.C. He pretended to like the author’s children.D. He was embarrassed a lot to stay in the author’s house.7. Which was of the following is a suitable title for the text?A. An Unforgettable GiftB. An Odd FishermanC. A Grateful HeartD. A Silent ComplaintCThis fall, students can monitor occupancy rates in Pearl Campus Library（PCL）spaces through the Waitz App that shows how busy the library is in real time without having to physically visit it themselves.“Waitz shows how busy each floor of the library is before they leave their dorm or house,” Mandy, Social Media Manager of Waitz’s parent company Occuspace, said. “Now, students never have to waste time pacing the halls of libraries looking for an open seat again.”“The beauty of Waitz lies in helping anyone who’s walked into one of our popular spacesonly to discover that they can’t find a space,” Maurini, a director of the university said. “Using the app or looking at one of the dashboards, they can identify their best bets for an alternative space—and, in the ideal scene, to know before they go to the library where’s the best place to find a spot.”Occuspace employs the Internet of Things to determine how many people are in a given space. They installed sensors into the walls of PCL spaces that scan for Bluetooth and Wi-Fi signals. The signals are then changed into live occupancy data which are displayed in the monitors within PCL and on the mobile app. According to Occuspace CEO Nic Stephenson, the sensors have at least a 90% accuracy rate and do not collect any personally identifiable information. The algorithm（算法）also takes into account the number of devices an average student uses when calculating the occupancy rate of a space.Stephenson launched Occuspace in 2017 with his roommates after being frustrated by the lack of open spaces at the University’s library. “I was walking up and down the eight floors trying to find a seat to study one night only to see zero spaces available,” Stephenson said. “I literally said to myself out loud, ‘I wish I knew how busy every floor was before I came!’ That’s when Occuspace was born.”8. What can students do with the Waitz App?A. Visit the library online.B. Save time when finding books.C. See seats available in the library.D. Learn how busy students in the library are.9. What can we know from the fourth paragraph?A. The signals can be transformed instantly.B. The sensors can be shown on the mobile app.C. The algorithm considers the number of students.D. The users’ identifiable information is kept secret.10. What inspired Stephenson to develop Occuspace?A. His roommates’ encouragement.B. His unpleasant experience at the library.C. His intention of improving learning efficiency.D. His hope of seeking an empty space at the university.11. Which is the main idea of the text?A. Stephenson develops an app for a library.B. An Algorithm calculates the number of seats.C. Occuspace collects accurate personal information.D. Waitz helps students know occupancy of library spaces.DSome yogurt containers in your grocery store might be looking a little different soon. Pure Dairy yogurt will be sold in cups made mostly of paper. Pure Dairy is a food company which specializes in making yogurt which is often sold in plastic containers. But plastic, unlike paper, can take hundreds of years to break down, leading to long-lasting waste. Now, Pure Dairy’s first-ever paper cups will replace the plastic cups previously used to hold its yogurt products.“People have been asking for a paper cup, and we welcome this challenge to start reducing our plastic use, and to spark a conversation about how we can drive change together. I think we all have a role to play in protecting our planet.” said Hamdi Ulukaya, Pure Dairy’s founder and chief executive officer.Pure Dairy currently produces yogurt, creamers, coffee and plant-based drinks. Many of these products already come in paper-based, recyclable packaging. But its yogurt products had always been sold in plastic. That’s why the company has spent the past two years working to create a paper cup. They wanted it to hold yogurt just as well as the plastic cups do. The paper cup is expected to hit grocery shelves at the end of this year, which is 80 percent paperboard made from renewable materials.The new paper cup still has a thin plastic lining to maintain the quality of the product and prevent the yogurt from seeping into the packaging. Although packaging with mixed materials is often not recyclable, Pure Dairy will continue working with partners to make it happen. This group works with businesses to make their products and packaging more sustainable, meaning they want to use resources so that they will continue to be available in the future. The yogurt company says it hopes to put more sustainable packaging on shelves all over the country which will use less plastic and more paper.12. Why will the company sell yogurt in paper containers?A. To reduce waste.B. To create a new packaging.C. To recycle the plastic containers.D. To specialize in making paper cups.13. What does the underlined word “spark” mean in the second paragraph?A. Share.B. Continue.C. Dominate.D. Activate.14. What can we say about the latest paper cup?A. It can be recyclable.B. It is made of plastic and paper.C. It doesn’t satisfy the public’s demands.D. It is not the joint effort of the companies.15. What can be inferred from the passage?A. Paper cups may replace the plastic cups.B. A lot of paper products will be available.C. A renewable material will replace yogurt.D. The company hopes to produce more packaging.第二节（共5小题；每小题2.5分，满分12.5分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。

2023-2024学年广东省广州市(四中、三中、培正)三校联考高一下学期期中考试物理试题

2023-2024学年广东省广州市（四中、三中、培正）三校联考高一下学期期中考试物理试题1.下列对相关情景的描述，符合物理学实际的是（）A．图（a）中，摩天轮做匀速圆周运动，所以摩天轮是匀变速曲线运动B．图（b）中，医务人员借助离心机从血液中分离出血浆和红细胞，是离心力的作用C．图（c）中，圆形拱桥半径为R，若在最高点车速刚好为时，车对桥面的压力为零D．图（d）中，当火车以规定速度通过此倾斜弯轨时，火车所受重力、轨道面支持力和外轨对轮缘弹力的合力提供向心力2.如图所示，P、Q为质量均为m的两个质点，分别置于地球表面上的不同纬度上，如果把地球看成一个均匀球体，P、Q两质点随地球自转做匀速圆周运动，则说法正确的是（）A．P、Q所受重力大小相等B．P、Q受地球引力大小相等C．P、Q的向心力大小相等D．运动过程中质点P线速度不变3. 2023年1月21日，中国宇宙空间站的3名航天员在距地高的空间站里挂起春联、系上中国结，通过视频向祖国人民送上新春祝福。

空间站的运行轨道可近似看作圆形轨道Ⅰ，椭圆轨道Ⅱ为神舟十五号载人飞船与空间站对接前的运行轨道，两轨道相切与P 点，下列说法正确的是（）A．空间站的线速度大于地球同步卫星的线速度B．春联和中国结处于完全失重状态，不受任何力的作用C．载人飞船在P点经点火减速才能从轨道Ⅱ进入轨道ⅠD．载人飞船沿轨道Ⅱ过P点的加速度大于沿轨道Ⅰ过P点的加速度4.各种大型的货运站中少不了悬臂式起重机。

如图甲所示，某起重机的悬臂保持不动，可沿悬臂行走的天车有两个功能，一是吊着货物沿竖直方向运动，二是吊着货物沿悬臂水平方向运动。

现天车吊着质量为100kg的货物在x方向的位移时间图像和y方向的速度-时间关系图像如图乙、丙所示，下列说法正确的是（）A．2s末货物的速度大小为3m/s B．货物的运动轨迹是图丙中的抛物线QC．货物所受的合力大小为150N D．0到2s末这段时间内，货物的合位移大小为11m5.如图所示，a、b是两颗绕地球做匀速圆周运动的人造卫星，它们距地面的高度分别是R和2R（R为地球半径）。

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广州市九区联考2023-2024学年高一上学期期末教学质量监测数学试卷(解析版)

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