2017-2018学年黑龙江省五常市雅臣中学度高三上学期第一次强化训练文数试卷

数学---黑龙江省哈尔滨市五常市雅臣中学2018届高三(上)第一次强化训练试卷(文)

黑龙江省哈尔滨市五常市雅臣中学2018届高三（上）第一次强化训练数学试卷（文科）一、选择题1．（5分）设全集U=R，集合A={x|1og2x≤2}，B={x|（x﹣3）（x+1）≥0}，则（∁U B）∩A=（）A．（﹣∞，﹣1] B．（﹣∞，﹣1]∪（0，3）C．[0，3）D．（0，3）2．（5分）复数在复平面上对应的点位于（）A．第一象限B．第二象限C．第三象限D．第四象限3．（5分）已知向量和，若，则=（）A．64 B．8 C．5 D．4．（5分）如图，侧棱垂直于底面的三棱柱ABC﹣A1B1C1的各棱长均为2，其正视图如图所示，则此三棱柱侧视图的面积为（）A．2 B．4 C．D．25．（5分）为了了解某校今年准备报考飞行员的学生的体重情况，将所得的数据整理后，画出了频率分布直方图（如图），已知图中从左到右的前3个小组的频率之比为1：2：3，第1小组的频数为6，则报考飞行员的学生人数是（）A．36 B．40 C．48 D．506．（5分）双曲线x2﹣=1的离心率e=，则双曲线的渐近线方程为（）A．B．C．y=±2x D．y=±5x7．（5分）已知等差数列{a n}的前n项和为S n，若a3+a4+a5=12，则S7的值为（）A．56 B．42 C．28 D．148．（5分）已知函数f（x）=sin2x﹣cos2x+1，下列结论中错误的是（）A．f（x）的图象关于（，1）中心对称B．f（x）在（，）上单调递减C．f（x）的图象关于x=对称D．f（x）的最大值为39．（5分）某程序框图如图所示，运行该程序输出的k值是（）A．4 B．5 C．6 D．710．（5分）已知直线l的斜率为k，它与抛物线y2=4x相交于A，B两点，F为抛物线的焦点，若，则|k|=（）A．B．C．D．11．（5分）若△P AD所在平面与矩形ABCD所在平面互相垂直，P A=PD=AB=2，∠APD=60°，若点P，A，B，C，D都在同一个球面上，则此球的表面积为（）A．πB．πC．πD．π12．（5分）已知定义在（﹣1，1）上的奇函数f（x），其导函数为f′（x）=l+cos x，如果f（1﹣a）+f（l﹣a2）＜0，则实数a的取值范围为（）A．（0，1）B．（1，）C．（﹣2，﹣）D．（1，）∪（﹣，﹣1）二、填空题13．（5分）设实数x，y满足约束条件，则z=y﹣x的最大值等于．14．（5分）甲每次解答一道几何体所用的时间在5至7分钟，乙每次解答一道几何体所用的时间在6至8分钟，现甲、乙各解同一道几何体，则乙比甲先解答完的概率为．15．（5分）若正数a，b满足，则的最小值为．16．（5分）甲乙丙三人代表班级参加校运会的跑步，跳远，铅球比赛，每人参加一项，每项都要有人参加，他们的身高各不同，现了解到已下情况：（1）甲不是最高的；（2）最高的是没报铅球；（3）最矮的参加了跳远；（4）乙不是最矮的，也没参加跑步．可以判断丙参加的比赛项目是．三、解答题17．（10分）在△ABC中，角A、B、C所对的边分别为a、b、c．已知a=2a cos A cos B﹣2b sin2A．（1）求C；（2）若△ABC的面积为，周长为15，求c．18．（12分）如图，在四棱锥P﹣ABCD中，底面ABCD是菱形，∠DAB=60°，PD⊥平面ABCD，PD=AD=1，点E，F分别为AB和PD的中点．（Ⅰ）求证：直线AF∥平面PEC；（Ⅱ）求三棱锥P﹣BEF的体积．19．（12分）20名学生某次数学考试成绩（单位：分）的频率分布直方图如图．（1）求频率分布直方图中a的值；（2）分别求出成绩落在[50，60）与[60，70）中的学生人数；（3）从成绩在[50，60）的学生中任选2人，求这两人的成绩都在[60，70）中的概率．20．（12分）设数列{a n}满足a1=2，a n+1=2a n﹣n+1，n∈N*．（1）求数列{a n﹣n}的通项公式；（2）若数列b n=，求数列{b n}的前n项和S n．21．（12分）已知椭圆C：，离心率为．（I）求椭圆C的标准方程；（Ⅱ）设椭圆C的下顶点为A，直线l过定点，与椭圆交于两个不同的点M、N，且满足|AM|=|AN|．求直线l的方程．22．（12分）已知函数f（x）=x2+ax﹣ln x，a∈R．（Ⅰ）当a=1时，求f（x）的单调区间；（Ⅱ）当函数f（x）在[1，2]上是减函数，求实数a的取值范围；（Ⅲ）令g（x）=f（x）﹣x2，是否存在实数a，当x∈（0，e]（e是自然对数的底数时，函数g（x）的最小值是3，若存在，求出a的值；若不存在，说明理由．【参考答案】一、选择题1．D【解析】∵集合A={x|1og2x≤2}=（0，4]，B={x|（x﹣3）（x+1）≥0}=（﹣∞，﹣1]∪[3，+∞），∴C U B=（﹣1，3），∴（C U B）∩A=（0，3），故选：D2．A【解析】===+i，对应点的坐标为（，）位于第一象限，故选：A．3．C【解析】向量和，若，则•=0，即﹣2t+（t+2）=0，解得t=2；∴+=（2﹣2，1+4）=（0，5），∴=5．故选：C．4．D【解析】易得三棱柱的底面为等边三角形，边长为2，作出等边三角形的高后，组成直角三角形，底边的一半为1，∴等边三角形的高为，∴侧视图的面积为2×=2，故选：D．5．C【解析】设报考飞行员的人数为n，根据前3个小组的频率之比为1：2：3，可设前三小组的频率分别为x，2x，3x；由题意可知所求频率和为1，即x+2x+3x+（0.037+0.013）×5=1解得x=0.125则0.125=，解得n=48故选C．6．C【解析】双曲线x2﹣=1的离心率e=，可得，可得b=2，双曲线方程为：x2﹣，则双曲线的渐近线方程为：y=±2x．故选：C．7．C【解析】由题意可得a3+a4+a5=3a4=12，解得a4=4，故S7===28故选C8．B【解析】f（x）=sin2x﹣cos2x+1=2sin（2x﹣）+1，A．当x=时，sin（2x﹣）=0，则f（x）的图象关于（，1）中心对称，故A正确，B．由2kπ+≤2x﹣≤2kπ+，k∈Z，得kπ+≤x≤kπ+，k∈Z，当k=0时，函数的递减区间是[，]，故B错误，C．当x=时，2x﹣=2×﹣=，则f（x）的图象关于x=对称，故C正确，D．当2sin（2x﹣）=1时，函数取得最大值为2+1=3，故D正确，故选：B9．B【解析】模拟程序的运行，可得S=100，k=0满足条件S＞0，执行循环体，S=99，k=1满足条件S＞0，执行循环体，S=96，k=2满足条件S＞0，执行循环体，S=87，k=3满足条件S＞0，执行循环体，S=60，k=4满足条件S＞0，执行循环体，S=﹣21，k=5此时，不满足条件S＞0，退出循环，输出k的值为5．故选：B．10．A【解析】设直线l的方程为y=kx+m（k≠0），与抛物线y2=4x相交于A（x1，y1），B（x2，y2）．联立，得k2x2+（2km﹣4）x+m2=0．所以△=（2km﹣4）2﹣4k2m2=16﹣16km＞0，即km＜1．，．由y2=4x得其焦点F（1，0）．由，得（1﹣x1，﹣y1）=2（x2﹣1，y2）．所以，由①得，x1+2x2=3 ③由②得，．所以m=﹣k．再由，得，所以x1+1=2（x2+1），即x1﹣2x2=1④联立③④得．所以=．把m=﹣k代入得，解得，满足mk=﹣8＜1．所以．故选A．11．B【解析】设球心为O，如图，∵△P AD所在平面与矩形ABCD所在平面互相垂直，P A=PD=AB=2，∠APD=60°，∴AD=2，BD==2，设AC∩BD=E，则BE=，∵点P，A，B，C，D都在同一个球面上，∴OP=OB=R，设OE=x，在Rt△BOE中，OB2=BE2+OE2=2+x2，过O作线段OH⊥平面P AD于H点，H是垂足，∵O点到面P AD的距离与点E到平面P AD的距离相等，∴OH=1，∴在Rt△POH中，PO2=OH2+PH2=1+（﹣x）2=x2﹣2+4，∴2+x2=x2﹣2+4，解得x=，∴R=，∴此球的表面积S=4πR2=4π×=．故选：B．12．B【解析】f（x）的导函数为f′（x）=l+cos x，则f′（x）＞0在（﹣1，1）恒成立，即有f（x）在（﹣1，1）递增，又f（x）为奇函数，即有f（﹣x）=﹣f（x），则f（1﹣a）+f（l﹣a2）＜0即为f（1﹣a）＜﹣f（l﹣a2）=f（a2﹣1），即，即有，解得，1＜a＜．故选：B．二、填空题13．﹣2【解析】由z=y﹣x得y=x+z，作出不等式组对应的平面区域如图（阴影部分ABC）：平移直线y=x+z由图象可知当直线y=x+z经过点A时，直线y=x+z的截距最大，此时z也最大，由，解得，即A（3，1）．将A代入目标函数z=y﹣x，得z=1﹣3=﹣2．故答案为：﹣214．【解析】设两个人解答一道几何题所用的时间为分别为x，y，则5＜x＜7，6＜y＜8，对应区域的面积为4，甲、乙各解同一道几何题，则乙比甲先解答完的满足x＞y，对应区域面积=，由几何概型的个数得到所求概率为；故答案为：．15．2【解析】正数a，b满足，则=1﹣=，或=1﹣=则=，由正数a，b满足，则=1﹣=，则=，=+≥2=2，当且仅当a=b=3时取等号，故的最小值为2，故答案为：216．跑步【解析】由（4）可知，乙参加了铅球比赛，由（2）可知乙不是最高的，所以三人中乙身高居中；再由（1）可知，甲是最矮的，参加了跳远，所以丙最高，参加了跑步比赛．故答案为跑步．三、解答题17．解：（1）由正弦定理可得sin A=2sin A cos A cos B﹣2sin B sin2A=2sin A（cos A cos B﹣sin B sin A）=2sin A cos（A+B）=﹣2sin A cos C．所以cos C=﹣，故C=．（2）由△ABC的面积为得ab=15，由余弦定理得a2+b2+ab=c2，又c=15﹣（a+b），解得c=7．18．解：（Ⅰ）证明：作FM∥CD交PC于M，连接ME．∵点F为PD的中点，∴，又，∴，∴四边形AEMF为平行四边形，∴AF∥EM，∵AF⊄平面PEC，EM⊂平面PEC，∴直线AF∥平面PEC．（Ⅱ）连接ED，在△ADE中，AD=1，，∠DAE=60°，∴ED2=AD2+AE2﹣2AD×AE×cos60°=，∴，∴AE2+ED2=AD2，∴ED⊥AB．PD⊥平面ABCD，AB⊂平面ABCD，∴PD⊥AB，PD∩ED=D，PD⊂平面PEF，ED⊂平面PEF，∴AB⊥平面PEF．，∴三棱锥P﹣BEF的体积：V P﹣BEF=V B﹣PEF===．19．解：（1）根据直方图知组距=10，由（2a+3a+6a+7a+2a）×10=1，解得a=0.005．（2）成绩落在[50，60）中的学生人数为2×0.005×10×20=2，成绩落在[60，70）中的学生人数为3×0.005×10×20=3．（3）记成绩落在[50，60）中的2人为A，B，成绩落在[60，70）中的3人为C，D，E，则成绩在[50，70）的学生任选2人的基本事件有AB，AC，AD，AE，BC，BD，BE，CD，CE，DE共10个，其中2人的成绩都在[60，70）中的基本事件有CD，CE，DE共3个，故所求概率为P=．20．解：（1）∵a n+1=2a n﹣n+1，n∈N*，∴a n+1﹣（n+1）=2（a n﹣n），∴{a n﹣n}是等比数列，首项为1，公比为2，∴a n﹣n=2n﹣1．（2）由（1）可得：a n﹣2n﹣1=n．∴b n===，∴数列{b n}的前n项和S n=+++…++==﹣．21．解：（I）由题意可得e==，+=1，且a2﹣b2=c2，解得a=，b=1，即有椭圆的方程为+y2=1；（Ⅱ）若直线的斜率不存在，M，N为椭圆的上下顶点，即有|AM|=2，|AN|=1，不满足题设条件；设直线l：y=kx+（k≠0），与椭圆方程+y2=1联立，消去y，可得（1+3k2）x2+9kx+=0，判别式为81k2﹣4（1+3k2）•＞0，化简可得k2＞，①设M（x1，y1），N（x2，y2），可得x1+x2=﹣，y1+y2=k（x1+x2）+3=3﹣=，由|AM|=|AN|，A（0，﹣1），可得=，整理可得，x1+x2+（y1+y2+2）（）=0，（y1≠y2）即为﹣+（+2）•k=0，可得k2=，即k=±，代入①成立．故直线l的方程为y=±x+．22．解：（Ⅰ）a=1时，f（x）=x2+x﹣ln x，x＞0∴f′（x）=，令f′（x）＞0，解得：x＞，x＜﹣1（舍），令f′（x）＜0，解得：0＜x＜，∴f（x）在（0，）递减，在（，+∞）递增；（Ⅱ）∵f′（x）=，当函数f（x）在[1，2]上是减函数时，得f′（1）=2+a﹣1≤0①，f′（2）=8+2a﹣1≤0②，由①②得：a≤﹣，∴a的范围是（﹣∞，﹣）；（Ⅲ）∵f（x）=x2+ax﹣ln x，∴g（x）=f（x）﹣x2=ax﹣ln x，x∈（0，e]．∴g′（x）=a﹣=（0＜x≤e），①当a≤0时，g（x）在（0，e]上单调递减，g（x）min=g（e）=a e﹣1=3，解得a=（舍去）；②当0＜＜e时，g（x）在（0，）上单调递减，在（，e]上单调递增，∴g（x）min=g（）=1+ln a=3，解得a=e2，满足条件；③当≥e时，g（x）在（0，e]上单调递减，g（x）min=g（e）=a e﹣1=3，解得a=（舍去）；综上，存在实数a=e2，使得当x∈（0，e]时，g（x）有最小值3．。

黑龙江省五常市雅臣中学2018届高三上学期第一次强化训练历史

历史强化试卷第I卷（选择题共48分）―、选择题{本大题共24小题，每小题2分，共48分。

在每小题给出的四个选项中，只有一项是符合题目要求的。

)1.西周时期，许多彝铭(刻在青铜器上的文字）载有“铸兹宝策，以享以孝于大宗皇祖、皇妣、皇考、皇母”和“其万年子子孙孙永用享孝于大宗”等辞语。

这些铭文反映了当时A.宗法关系与皇权相结合B.血缘关系影响政治生活C.祭祀旨在宣扬君权神授D.僭越周礼的行为被遏制2.外藩首领或使臣携贡品来朝参见皇帝，唐朝必回赠丰厚物产回馈时必须先估定所得贡物的价值，并以此为依据来决定回馈多少，这些回赠物品多系手工业精品，有不少出自官府手工业部门，这些回馈的手工业品A.都来自官营手工业B.旨在加强与少数民族联系C.与市场联系紧密D.其政治价值大于经济价值3.朱元库即位之初，“严私铸之禁”，甚至将严禁私铸铜钱一项载人《大明律》此后不久下诏凡私铸铜钱，准许作为废铜送至官府，官府每斤给制钱一百九十文(官対披铸钱每斤160文)偿之。

”这一变化A.反映出铜矿资源的丰富B.表明私铸法令被严格执行C.说明私人冶铸获利丰厚D.客观上鼓励了私人铸钱4.下表反映了 1913年和1936年中国进出口格局的变化，据表可知这一阶段中国类别进口 (％) 出口（％)1913年1936年变化净比1913年1936年变化净比原料 5.3 13.4 +8.1 29.1 35.8 +6.7 制成品（包括半制成品）品）67.1 66.5 -0.6 50.9 39.5 -11.4A.近代工业发展比较迅速B.仍以进口制成品为主C.经济结构已发生根本变化D.国际市场得以拓展·1·5.民国成立第一天，上海《申报》上登了这样一则新闻新国成立，百度维新。

余友喜，新君、新话连篇，呼其妻曰新娘子。

妻不应，还呼之曰新相公，亦觉赧然无以应。

余友忽发新思想，夫妇二人张新国旗，穿新冠服，新头新脑，在室中行新婚。

这在客观上可以反映A.部分民众对新生政权的认同B.社会习俗已完成了近代化C.民主共和观念已深入人心D.民众仍具有浓厚保守思想6.有学者认为中国某部法律文件规定国家机构存在一个集中权力的中央人民政府委员会，在中央人民政府委员会下面设立备个职能机构，政务院和法院都是其职能机构，这一文件A.为新中国成立奠定基础B.规划了社会主义建设蓝图C.推动政协制度职能转变D.适应了经济体制改革需要7.1952年，周恩来认为当今世界应划分为两大阵营(帝国主义阵营和社会主义阵营)、三类国家(帝国主义国家、民族主义国家和社会主义国家），并指出世界局势“不是简单的两大阵营对立，没有什么工作可做”。

黑龙江省五常市雅臣中学2018届高三上学期第一次强化训练语文

五常市雅臣中学高三期末第一次强化语文试卷考生注意：1.本试卷满分150分，考试时间150分钟。

2.回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。

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一、现代文阅读（35分）（一）论述类文本阅读（本题共3小题，9分）阅读下面的文字，完成1-3题。

我觉得，中国文化似乎有一个特征，是主体和客体往往会合而为一，按照今天的话来说，很像“行为艺术”。

它体现在操守、品行、生活方式、礼仪活动上，当我们看见天坛、地坛，还有那些巨大的青铜器时，也许我们就不难想象，古代那些祭祀的仪式该是多么的宏伟壮观。

孔子周游列国，在一个交通特别不发达、人对于距离相当敬畏的年代，一个人坐着马车上路，一个国家接一个国家地宣传他的理论，这不也正像行为艺术吗？《史记·刺客列传》中有这样一个故事：豫让曾臣事智伯，智伯死后他决意为其报仇，第一次刺杀赵襄子未果，被赵放了，豫让将自己毁容弄哑，企图再次刺杀。

朋友问：你要报仇，何苦用这种方法，尽可以假装臣服于赵乘机行刺。

豫让答：我不能为人臣怀二心。

第二次要刺杀赵时被抓住,赵问:你曾是范氏、中行氏的人,他们都被智伯杀死,你为什么只是忠于智伯?豫让答:他们是以奴仆待我,而智伯却是以国士待我,是有知遇之恩,我亦要以国士的品级回报。

豫让“请赵之衣而击之”后伏剑自杀。

豫让的忠诚有着人性、尊严、情感的美学内容,他的复仇也像是一个艺术仪式,只是这种艺术行为会在时间的流逝中消失,不可能客观地保存下来。

许多民间的习俗也是艺术化的。

我曾目睹过一场葬礼。

村子中最壮的十六个男子，先是喝酒，然后大喝一声“起杠”，拾起厚重无比的棺材出发了。

在后面跟随的，第一批是家中的男眷，他们用三寸的棍子拄地，弓着腰，发出低沉的呜咽的声音；接下来一批是家中的女眷，她们身披重孝以高音的啼泣诉说着。

2017-2018学年高三一模考试文科数学测试卷及答案

2017-2018 学年度咼三年级第一次模拟考试文科数学试卷一、选择题：本大题共 12个小题，每小题5分，共60分.在每小题给出的四个选项中，只有一项是符合题目要求的A. 2 _2iB. 2 2iC. _2 _ 2 iD. -2 2i2. 已知命题p : -i n 三N , 3n .2018，则一p 为( )A. —n. N , 3n £；20 18B . —n^N , 3n .2018C.n N, 3n ^2 018 D. -I n 三 N , 3“ ：：： 2 01 8f1~]3. 设集合 M ={x|x —x,0} , N = x| 1 ，则是()IxJA. M ? NB. N ? MC. M =ND. M U N =R4.某校高中三个年级人数饼图如图所示，按年级用分层抽样的方法抽取一个样本，已知样本中高一年级学生有8人，则样本容量为（边过点 P (1, -2)，则 sin 2 v = ()3 3 4A.B .-C .—D5556.等腰直角三角形 ABC 中，A =90、，该三角形分别绕 AB , BC 所在直线旋转，则2个几何体的体积之比为（1.2(1 —i)5.以角v 的顶点为坐标原点，始边为 x 轴的非负半轴，建立平面直角坐标系 xOy ,若角二终2A. 向右平移生个单位长度2B. 向右平移二个单位长度4C. 向左平移二个单位长度2D. 向左平移二个单位长度4B .求 135 - ... - (2 n - 1)C.求12 - 22・32亠亠nA .1 :、、.、C7. 已知a =45c A. a ::: c ::.aC.b :::c ::8.为了得到yIx_可yD . 2 :1该程序所能实现的功能是（）sin 2x •丄的图象（） I 3丿设计的程序框图,210.某几何体的三视图如图所示，则该几何体的表面积是（D.求12 ■■■■■ (n -1)A. 5 4、、2B. 9C. 6 5、, 2D. 2 3 4 5311. 已知P为抛物线亍二x上异于原点0的点，PQ _ x轴，垂足为Q ,过PQ的中点作x轴一P Q的平行线交抛物线于点M，直线QM交y轴于点N，则 ----------- =()N O2 3A. B. 1C. — D. 23 212. 已知函数f (x) =x -2xcosx，则下列关于f(x)的表述正确的是( )A. f (x)的图象关于y轴对称 B . f (x)的最小值为-1C. f (x)有4个零点 D . f (x)有无数个极值点二、填空题：本题共4小题，每小题5分，共20分.13. 已知 a =(_1,1) , b =(1, _2)，贝U (a 2b) a =.x - y _ 0I14. 设x , y满足约束条件x・2y_3_0，则z = 2x 3 y的最小值是.x - 2 y -1 乞02 2x y15. 已知双曲线C : 1 (m .0)，则C的离心率的取值范围是.1 亠m 1 —mc a b16. 在八ABC中，角A , B , C的对边分别为a, b, c,若S ABC，贝V 的最大4 b a值是.三、解答题：共70分.解答应写出文字说明、证明过程或演算步骤.第17〜21题为必考题，每个试题考生都必须作答.第(22)、(23)题为选考题，考生根据要求作答(一)必考题：共60分.17.已知数列｛ a n ｝是以1为首项的等差数列，数列｛X ｝是以q （q =1）为公比的等比数列（1）求｛a n ｝和｛b n ｝的通项公式;天进货当天销售•如果当天卖不出去，未售出的全部降价处理完，平均每公斤损失 3元.根据以往的销售情况，按［0,100），［1 00,200），［200,300），［3 00,400），［400,500］进行分组,得到如图所示的频率分布直方图（1）根据频率分布直方图计算该种鲜鱼日需求量的平均数 X （同一组中的数据用该组区间中点值代表）；（2）该经销商某天购进了 300公斤这种鲜鱼，假设当天的需求量为 X 公斤（0乞X 空500），利润为Y 元.求Y 关于x 的函数关系式，并结合频率分布直方图估计利润 Y 不小于700元的概率•19.如图，在三棱柱 ABC -A 1B 1C 1中，平面 A ’B ’C _平面 AA 1C 1C ，乙BAC =90-（2）若.'^1 B 1C 是边长为2的等边三角形，求点 B 1到平面ABC 的距离.(2)若 S 、= a 1b n 6"丄亠亠％丄b 2-，求S n .18.某水产品经销商销售某种鲜鱼，售价为每公斤 20元，成本为每公斤15元.销售宗旨是当2 220.已知椭圆-:X2 - y2=1 （a b - 0）的左焦点为F，上顶点为A，长轴长为2 6，B为a b（1）若椭圆:的方程；（2）若C为椭圆:上一点，满足AC//BM , AMC=6 0；，求m的值.x 121. 已知函数 f （x）% ，g （x） = e* " .. .. In x —a .x（1）求f （x）的最大值；（2）若曲线y=g（x）与x轴相切，求a的值.（二）选考题：共10分•请考生在（22）、（23）题中任选一题作答，如果多做，则按所做的第一题记分•22. 选修4-4 :坐标系与参数方程在直角坐标系xOy中，圆6 : （x-1）2 - / =1，圆C 2 : （X-3）2 ・y2=9.以坐标原点为极点，x轴的正半轴为极轴建立极坐标系.（1）求6， C2的极坐标方程；「X =t CO S 0（（2）设曲线C3 : （t为参数且t式0），C3与圆6，C2分别交于A，B，求S少cy =t sin a的最大值.23. 选修4-5 :不等式选讲设函数f（x）=|x+1| — x的最大值为m.（1）求m的值；2 2（2）若正实数a，b满足a • b = m，求—一-——的最小值.b 十1 a +1②一①可得，S= 2n +1 + (2n + 2n —1 + ・・・ +=2n +2— 2n — 4.(18) 解:(I) x = 50 x 0.001 O X 100 + 150X 0.002 0x 100 + 250 x 0.003 0 x 100+ 350 x 0.002 5x 100+ 450 x 0.001 5 x 100 = 265 .…4 分(H)当日需求量不低于 300公斤时，利润 Y = (20 — 15) x 300 = 1 500元；当日需求量不足 300公斤时，利润 Y = (20 — 15) x — (300 — x ) x 3 = 8x — 900元；故 Y =°x- 900, 0< X V 300,…8 分故丫= 1 500, 300W x < 500. 分由 Y 》700 得，200W x < 500, 所以 F ( Y > 700) = P (200 w x w 500)=0.003 0x 100 + 0.002 5x 100 + 0.001 5x 100=0.7 .(19) 解:参考答案•选择题:A 卷: DACCD BDBCA CDB 卷: AACCD DBBCA CD •填空题： (13)— 4 (14)— 5(15) (1 ,2)(16) 2 2三•解答题: (17) 解:(I)设｛a n ｝的公差为 d , ｛6｝的首项为 b,贝 U a n = 1 + (n — 1) d , b n = bg n —1 •卩 + d= b,依题意可得孑2d = b 1(q — 1),2K1 + d ) bq = bq ,d =1,解得b 1= 2,q = 2,所以 a n = n , b n = 2.S= 1X 2n+ 2X 2n —1+ - +1n x 2 ,所以 n +12S = 1 x 2.. 2+ 2x 2 +•••+ n x 2 ,2 12) — n x 2…12分…12分(I)过点B作AC的垂线，垂足为0,由平面 ABC 丄平面 AACC,平面 ABC n 平面 AACC = AC 得BO ±平面AACQ,又AC 平面AACC 得B0丄AC. 由/BAC= 90°, AB// AB ，得 AB 丄 AC 又 BOd A 1B 1 = B i ,得 AC 丄平面 A i B i C. 又CA 平面ABC,得ACLCA .又 AML BM , AC// BM 所以 k BM = k AC =所以AB //平面ABC所以B 到平面ABC 的距离等于 A 到平面ABC 的距离，设其为 d , 由 Vq -AB = V B-AA 1 C 得，1 1 1 1 X-X ACX ABX d = ；x ：x ACX A C x B O,3 23 2所以 d = B 0= <;3.即点B 到平面ABC 的距离为，3. (20) 解：(I)依题意得 A (0 , b ) , F ( — c , 0)，当 ABL l 时，B ( — 3, b ),,r b b 2 2由 AF 丄 BF 得 k AF • k BF = • =— 1，又 b + c = 6.c — 3 + c解得 c = 2, b = ,2.2 2所以，椭圆r 的方程为x 6+2 =1.(n)由(I)得A (0 ,寸2)，所以 k AM =—…7分m厂所以直线AC 的方程为y =(^+羽,2 2m xv — 12my = —x + 订2与—+ — = 1 联立得(2 + 3m )x + 12mx= 0,所以 x c = ?十 §m ，—12m 乔（叶0），在直角△ AM （中，由/ AMC 60° 得，|AC = ,3|AM ，整理得：（，3m+ 2） 2= 0, 解得m=—晋.…10分…12分当X V 1时，f (x ) > 0, f ( x )单调递增;当X > 1时，f (X )V 0 , f ( x )单调递减,1 故x = 1时，f (X )取得最大值f (1) = e . e ,,, x —1 1 1(n)因为 g (x ) = e + -2— x — 1,X X 设切点为(t , 0)，则 g (t ) = 0,且 g (t ) = 0,t — 1 1 1 t —1 1即 e + 严一 -—1 = 0, e — t ■一 In t — t + a = 0,1 t 一!所以 a = - + In t +1 — e .人 X —1 1 1令 h ( x ) = e + 2— — 1, x x1 X 1 x — !由(I )得f ( X )<e ，所以g w e ，即e >x ，等号当且仅当x = 1时成立,21 1 (X — 1) (X + 1)所以h (x ) >x + T — - — 1 = - >0,等号当且仅当 x = 1时成立, X X X故 a = 1.(22)解:依题意得 I AB = 6cos a — 2cos C 2(3 , 0)到直线 AB 的距离 d = 3|sin a | ,1(21)解:1 — x(X )二丁所以当且仅当 x = 1 时，h ( x ) = 0, 所以t = 1.…11分 …12分 C 1：cos 0 , y = p sin 0 2 . 2 一 -2 2 2.2 p cos 0 + p sin 0 — 2 p cos 可得,+ 1= 1，所以2cosG: 2 2 2.2 p cos 0 + p sin 0 — 6 p cos + 9= 9，所以p = 6cos a = 4COS a ,所以S\ABC>= x d x | AB = 3|sin 2 a | ,故当a=±丁时，&AB(2取得最大值3. …10分4(23)解：丁一1, X W一1,(I) f (x) = |x + 1| —| x| = 2X + 1, —1 v X V 1,、1, X> 1,由f(x)的单调性可知，当x> 1时，f(x)取得最大值1.所以m= 1. …4分（n ）由（i ）可知， a + b = 1, bh +吕=3（bh +h b +1）+（a +1）] 2 . 2 . 1 22 a （a +1） b （b +1） =-[a + b ++] 3 b +1=1（a + b ）2 1 a = b = g 时取等号.b 21 —-的最小值为 a +1 3 > 1（a2 + b 2 + 2a （a + 1）b （b +1） b + 1 a +1 ） a + 1 当且仅当 …10分。

2017-2018学年黑龙江省五常市雅臣中学度高三上学期第一次强化训练化学试卷

高三第一次强化化学试题可能用到的原子量：H :1 C:12 Fe:56 Cu:64 O:16 S:32一、选择题：每小题只有一个选项符合题意，本题共14小题，每小题3分，共42分。

1．生活处处有化学，下列说法正确的是：A．棉花与淀粉互为同分异构体B．豆浆煮沸后，蛋白质变成了氨基酸C．纤维素与蛋白质都是天然高分子化合物D．油脂在酸性条件下可水解为高级脂肪酸盐和甘油2．下列说法错误的是：A．中子数为20的氯原子：37Cl B．乙酸的分子式为：C2H4O217C．乙醛的结构简式：CH3COH D．比例模型可以表示CO2分子3．设NA为阿伏伽德罗常数的值，下列说法不正确的是：A．15 g ﹣CH3(甲基)含有中子数为6 NAB．5.6 g Fe粉完全溶于HCl和H2SO4的混合稀溶液，生成气体分子的数目为0.1 NA C．标准状况下，2.24 L NO2与N2O4的混合气体中含有氮原子的数目为0.1 NAD．在过氧化钠与CO2的反应中，每生成0.1 mol氧气，转移电子的数目为0.2NA4.乙烯的相关转化关系如图。

下列有关说法正确的是:A.聚乙烯是纯净物B.X为Cl2C．CH3OCH3与甲互为同分异构体 D.甲→乙反应类型为取代反应5．下列物质性质与应用对应关系正确的是:A．火碱能与酸反应，可用于治疗胃酸过多B．晶体硅硬度大，可用于制作半导体材料C．SO2具有还原性，可用于漂白纸浆D．MgO、Al2O3熔点高，它们都可用于制作耐火材料6．将51.2gCu完全溶于适量浓硝酸中，收集到氮的氧化物（N2O、N2O4、NO2）的混合物，这些气体恰好能被500mL、2mol/LNaOH溶液完全吸收，生成NaNO3和NaNO2两种盐溶液，其中NaNO2的浓度为A．0.4 mol/L B．1.2 mol/L C．1.6mol/L D．2.0 mol/L 7．在由水电离的c(H+) = 10-12mol/L的溶液中，下列离子组一定能大量共存的是: A．Na+、K+、Cl‾、NO 3‾B．K+、Na+、ClO‾、SO42-C．Al3+、Cu2＋、Cl‾、S2-D．Na+、Fe2＋、NO3－、Cl－8．下列关于电解质溶液的叙述正确的是：A．在pH=3的溶液中，Na+、Cl﹣、Fe2+、ClO﹣可以大量共存B．pH=11的NaOH溶液与pH=3的醋酸溶液等体积混合，滴入石蕊溶液呈红色C．常温下，pH=7的NH4Cl与氨水的混合溶液中：c（Cl﹣）＞c（NH4+）＞c（H+）=c（OH﹣）D．向0.1molL﹣1的氨水中加入少量硫酸铵固体，则溶液中c（OH﹣）/c（NH3·H2O）增大9．用下列实验装置进行相应实验，不能．．达到实验目的的:图1 图2 图3 图4 A．图1: 实验室制备Fe(OH)2 B．图2: 从NaCl与I2的混合物中回收I2C．图3: 收集NO气体D．图4: 检验铁粉与水蒸气反应产生的氢气10、如图甲是利用一种微生物将废水中的尿素[CO(NH2)2]的化学能直接转化为电能，并生成环境友好物质的装置，同时利用此装置的电能在铁上镀铜，下列说法中不正确的是:A．铜电极应与X相连接B．H＋透过质子交换膜由左向右移动C．M电极反应式为CO(NH2)2＋H2O－6e－===CO2↑＋N2↑＋6H＋D．当N电极消耗0.25 mol气体时，则理论上铁电极增重32 g11．下列说法正确的是:A．用惰性电极电解含酚酞的饱和食盐水，阳极附近溶液先变红B．铜的电解精炼过程中，有0.2 mol 电子发生转移时，阳极一定有6.4 g铜溶解C．将地下钢管与直流电源的正极相连，称为外加电源的阴极保护法D．在中性环境中，每生成35.6 g铁锈(Fe2O3·H2O)，消耗的氧气为6.72 L(标准状况)12.下列有关说法正确的是()A.若在海轮外壳上附着一些铜块,则可以减缓海轮外壳的腐蚀B.2NO(g)+2CO(g)N2(g)+2CO2(g)在常温下能自发进行,则该反应的ΔH>0C.加热0.1 mol·L-1 Na2CO3溶液,C的水解程度和溶液的pH均增大D.对于乙酸与乙醇的酯化反应(ΔH<0),加入少量浓硫酸并加热,该反应的反应速率和平衡常数均增大13．在2 L恒容绝热(不与外界交换能量)容器中进行2A(g)＋B(g) 2C(g)＋D(s)反应，按下表数据投料，反应10 s后达到平衡状态，测得体系压强升高，前10 s内v(A) = 0.025 mol/(L·s)。

【解析】黑龙江省五常市雅臣中学2018届高三上学期第一次强化训练历史试卷含解析

历史强化试卷第I卷（选择题共48分）―、选择题{本大题共24小题，每小题2分，共48分。

在每小题给出的四个选项中，只有一项是符合题目要求的。

）1. 西周时期，许多彝铭（刻在青铜器上的文字）载有“铸兹宝策，以享以孝于大宗皇祖、皇妣、皇考、皇母”和“其万年子子孙孙永用享孝于大宗”等辞语。

这些铭文反映了当时A. 宗法关系与皇权相结合B. 血缘关系影响政治生活C. 祭祀旨在宣扬君权神授D. 僭越周礼的行为被遏制【答案】B.....................点睛：抓住材料关键信息“铸兹宝策，以享以孝于大宗皇祖、皇妣、皇考、皇母” “其万年子子孙孙永用享孝于大宗”等，结合宗法制的相关内容，分析选项即可知道答案。

2. 外藩首领或使臣携贡品来朝参见皇帝，唐朝必回赠丰厚物产回馈时必须先估定所得贡物的价值，并以此为依据来决定回馈多少，这些回赠物品多系手工业精品，有不少出自官府手工业部门，这些回馈的手工业品A. 都来自官营手工业B. 旨在加强与少数民族联系C. 与市场联系紧密D. 其政治价值大于经济价值【答案】D【解析】根据材料可知，外藩首领或使臣携贡品来朝参见唐朝皇帝，皇帝回赠精美手工业品，宣传王朝的富强，其政治价值大于经济价值，D项正确。

材料体现回赠物品有不少来自官营手工业，不是都来自官营手工业，排除A。

回馈的手工业品的目的不是加强与少数民族联系，而是宣扬中原王朝的富强，排除B。

回赠物品有不少来自官营手工业，官营手工业产品没有进入市场流通，排除C。

3. 朱元璋即位之初，“严私铸之禁”，甚至将严禁私铸铜钱一项载人《大明律》此后不久下诏凡私铸铜钱，准许作为废铜送至官府，官府每斤给制钱一百九十文（官対披铸钱每斤160文）偿之。

”这一变化A. 反映出铜矿资源的丰富B. 表明私铸法令被严格执行C. 说明私人冶铸获利丰厚D. 客观上鼓励了私人铸钱【答案】D【解析】根据材料可知，朱元璋由禁止私铸铜钱到官府对私铸铜钱的宽容甚至奖励“废铜送至官府”，故这一变化客观上鼓励了私人铸钱，D项正确。

黑龙江省五常市雅臣中学2017-2018学年高三上学期11月月考数学(理)试卷+Word版含答案

雅臣学校高三数学试卷（理科）数学（理）试卷第I卷（选择题）一、选择题：本题共12小题，每小题5分，共60分。

在每小题给出的四个选项中，只有一项是符合题目要求的。

1.设集合A={y|y=2x，x∈R}，B={x|x2﹣1＜0}，则A∪B=（）A．（﹣1，1） B．（0，1） C．（﹣1，+∞）D．（0，+∞）2.等比数列{}中，＞0，则“＜”是“＜”的（）A．充分而不必要条件 B．必要而不充分条件C．充分必要条件 D．既不充分也不必要条件3.若实数x，y满足约束条件，则x﹣y的最大值是（）A．﹣7 B．C．﹣1 D．74.在等差数列{a n}中，S n为它的前n项和，若a1＞0，S16＞0，S17＜0，则当S n最大时，n的值为（）A．7 B．8 C．9 D．105.m，n是两条不同的直线，α，β是两个不同的平面，下列命题是真命题的是（）A．若m∥α，m∥β，则α∥β B．若m∥α，α∥β，则 m∥βC．若m⊂α，m⊥β，则α⊥β D．若m⊂α，α⊥β，则 m⊥β6.函数f（x）=（x2﹣2x）e x的图象大致是（）A． B．C． D．7.若实数a，b满足a+b=2，则3a+3b的最小值是（）A．18 B．6 C．2 D．28.如图，在△ABC中，∠BAC=90°，AB=AC=2，E是边BC的中点，D是边AC上一动点，则•的取值范围是（）A．[0，2] B．[﹣2，0] C．[0，2] D．[﹣2，0]9.一个几何体的三视图如图所示，则该几何体的表面积是（）A．4+2B．4+ C．4+2 D．4+10.我国南宋著名数学家秦九韶发现了从三角形三边求三角形面积的“三斜公式”，设△ABC三个内角A、B、C所对的边分别为a、b、c，面积为S，则“三斜求积”公式为．若a2sinC=4sinA，（a+c）2=12+b2，则用“三斜求积”公式求得△ABC的面积为（）A．B．2 C．3 D．11.设方程5﹣x=|lgx|的两个根分别为x1，x2，则（）A．x1x2＜0 B．x1x2=1 C．x1x2＞1 D．0＜x1x2＜112.设函数f（x）满足2x2f（x）+x3f′（x）=e x，f（2）=，则x∈[2，+∞）时，f（x）（）A．有最大值B．有最小值C．有最大值D．有最小值二、填空题：本题共4小题，每小题5分，共20分。

黑龙江省五常市2017-2018学年高三第一学期11月月考数学试卷文

黑龙江省五常市2017-2018学年高三数学11月月考试题文一．选择题.（每题5分，共12道，共计60分）1．已知集合{}2log 2<=x x A ，{}R x y y B x ∈+==,23，则A B = （）A ．（1，4）B ．（2，4）C ．（1，2）D ．),1(+∞2．在复平面内，复数ii z +=1（i 是虚数单位）对应的点位于（） A.第一象限 B. 第二象限 C. 第三象限 D. 第四象限 3. 将函数)62sin(π+=x y 的图象向右平移6π个单位，再纵坐标不变，横坐标变为原来的2倍，所得新图象的函数解析式是( )A.x y 4sin =B.x y sin =C.)64sin(π-=x y D. )6sin(π-=x y4.已知()f x 是定义在R 上的奇函数，当0x >时，2()log f x x =，则(8)f -值为（）A.3-B.13C.13- D.3 5．已知直线l 的方程为0263=+-y x ，直线⊥l 直线/l ，且直线/l 过点)3,1(-，则直线/l 的方程为（）A ．012=-+y xB ．052=-+y xC ．052=-+y xD ．072=+-y x6.已知{}n a 为等比数列，472a a +=，568a a =-，则110a a +=（）A.7B. 5C. -7D.-5 7．执行如图所示的程序框图，则输出的S 值为（[]x 表示不超过x 的最大整数）（）A ．4B ．6C ．7D ．98．一个几何体的三视图如图所示，则这个几何体的体积等于 ( )A. 12B. 4C. 356 D. 338 9.若圆C 的半径为1，圆心在第一象限，且与直线430x y -=和x 轴都相切，则该圆的标准方程( ) A. 227(3)()13x y -+-= B. 22(2)(1)1x y -+-= C. 22(1)(3)1x y -+-= D.223()(1)12x y -+-= 10.矩形ABCD 中，AB ＝4，BC ＝3，沿AC 将矩形ABCD 折起，使平面BAC ⊥平面DAC ，则四面体A －BCD 的外接球的体积为( )A . 12512π B. 1259π C. 1256π D. 1253π 11. 椭圆2222:1(0)x y C a b a b+=>>的左焦点为F ，若F0y +=的对称点A 是椭圆C 上的点，则椭圆C 的离心率为（）A ．12 B1 12．函数3223,0(),0x x x x f x ax x e⎧+≤⎪=⎨>⎪⎩在[]2,2-上的最大值为1，则实数a 的取值范围 ( )A ．[)0,+∞B ．[]0,eC ．(],0-∞D ．(],e -∞二、填空题（本大题共4小题，每小题5分，共20分）13. 设实数,x y 满足约束条件⎪⎩⎪⎨⎧≥+-≤-≥-+010101y x x y x ，若y x z +-=2，则z 的最小值是14. 设向量与的夹角为θ，若)3,3(=，)1,1(2-=-a b ，则=θcos15. 如图，已知椭圆C 的中心为原点O，()0F -，为C 的左焦点，P 为C 上一点，满足OP OF =且4PF =，则椭圆C 的方程为16. 给出下列关于互不相同的直线m 、l 、n 和平面α、β的四个命题：① 若α⊂m ，A l =α ，点m A ∉，则l 与m 不共面；② 若m 、l 是异面直线，α//l ，α//m ，且l n ⊥，m n ⊥，则α⊥n ；。

2017-2018学年黑龙江省五常市雅臣中学度高三上学期第一次强化训练物理试卷

高三物理上学期第一次强化考试试题一．选择题：（4×14=56分，1——9单选，10——14多选）1.将地面上静止的货物竖直向上吊起,货物由地面运动至最高点的过程中,图象如图所示.以下判断正确的是( )A.前3内货物处于超重状态B.最后2内货物只受重力作用C.前3内与最后4内货物的平均速度相同D.第3末至第5末的过程中,货物的机械能守恒2.两个带等量正电的点电荷，固定在图中P、Q两点，MN为PQ连线的中垂线，交PQ于O点，A点为MN上的一点．取无限远处的电势为零，一带负电的试探电荷q，在静电力作用下运动，则（）A．O点的电场强度E0=0,电势φ0=0VB．若在A点给q一个合适的初速度，它可以做类平抛运动C．若q从A点由静止释放，其将以O点为对称中心做往复运动D．若q从A点由静止释放，由A点向O点运动的过程中，速度一定先增大再减小，加速度大小一定先变大再减小到零，然后再变大再减小3.如图，OA、OB两绳结于圆心处，A B两点在圆周上，OA绳水平，现使A点不动，B点沿圆周从如图位置移到OB绳竖直的过程中，OA、OB两绳的拉力的变化情况是A .都变大B .都变小C . OA绳的张力一直减小，OB绳的张力一直增大D . OA绳的张力一直增大，OB绳的张力先减小后增大4.在同一光滑斜面上放同一导体棒，右图所示是两种情况的剖面图。

它们所在空间有磁感应强度大小相等的匀强磁场，但方向不同，一次垂直斜面向上，另一次竖直向上；两次导体棒A分别通有垂直纸面向里的电流I1和I2，都处于静止平衡。

已知斜面的倾角为θ，则：A．I1：I2=cosθ：1 B．I1：I2=1：1C．导体棒A所受安培力大小之比F1：F2=sinθ:cosθD．斜面对导体棒A的弹力大小之比N1：N2= 1：cos2θ5.如下图所示,已知,不计滑轮及绳子的质量,物体和恰好做匀速运动,若将与互换,、与桌面的动摩因数相同,则( )A.物体与仍做匀速运动B.物体与做加速运动,加速度C.物体与做加速运动,加速度D.绳子中张力不变6.如图所示，两平行的虚线间的区域内存在着有界匀强磁场，有一较小的三角形线框abc的ab边与磁场边界平行．现使此线框向右匀速穿过磁场区域，运动过程中始终保持速度方向与ab边垂直．则下列各图中哪一个可以定性地表示线框在上述过程中感应电流随时间变化的规律？7.质量为、速度为的球与质量为3的静止球发生正碰,碰撞后球的速度可能有不同的值.碰撞后球的速度大小可能是( )A.0.2B.0.4C.0.6D.0.88如图所示,a、、c是在地球大气层外圆形轨道上运动的3颗人造地球卫星,b,C在同一轨道,下列判断不正确的是( )A.卫星的向心加速度大于卫星a的向心加速度B.b,c卫星所受万有引力相等C.卫星的角速度等于卫星c的角速度D.卫星a的周期大于卫星的周期9.某公司为了测试摩托车的性能，让两驾驶员分别驾驶摩托车在一平直路面上行驶，利用速度传感器测出摩托车A、B的速度随时间变化的规律并描绘在计算机中，如图所示，发现两摩托车在t＝25 s时同时到达目的地．则下列叙述正确的是( )A．摩托车B的加速度为摩托车A的4倍B.在0～25 s 时间内，两辆摩托车间的最远距离为400 m C ．两辆摩托车从同一地点出发，且摩托车B 晚出发10 s D ．在0～25 s 时间内，两辆摩托车间的最远距离为180 m10.如图所示，带电平行板间匀强电场竖直向上，匀强磁场方向垂直纸面向里，某带电小球从光滑轨道上的ａ点自由滑下，经轨道端点Ｐ进入板间后恰好沿水平方向做直线运动．现使小球从稍低些的ｂ点开始自由滑下，在经过Ｐ点进入板间后的运动过程Ａ．其动能将会增大Ｂ．小球的机械能将会增加Ｃ．小球所受的洛伦兹力将会增大Ｄ．其电势能将会增大11.如图所示，质量为m 的物体在水平传送带上由静止释放，传送带由电动机带动，始终保持以速度v 匀速运动，物体与传送带间的动摩擦因数为μ，物体过一会儿能保持与传送带相对静止，对于物体从静止释放到相对静止这一过程，下列说法正确的是（）A ．传送带对物体做的功为221mvB ．传送带克服摩擦力做的功为221mvC ．电动机多做的功为2mvD ．物体在传送带上的划痕长gv 2212.核能作为一种新能源在现代社会中已不可缺少,我国在完善核电安全基础上将加大核电站建设。

黑龙江省五常市学高三数学上学期第一次强化训练试题

黑龙江省五常市2017-2018学年度高三数学上学期第一次强化训练试题理时间;120分钟满分：150分第I 卷（选择题）一、选择题（每题5分，共60分）1. 已知集合{|30}M x x =-<<，{|11}N x x =-≤≤，则图中阴影部分表示的集合为A.[1,1)-B. (3,1)--C.(,3][1,)-∞--+∞UD. (3,1]- 2．已知,x y R ∈，i 为虚数单位，若()123xi y i +=--，则x yi +=（） A. 2 B. 5 C. 3 D. 103．设随机变量X ～B （10，0.8），则D （2X+1）等于（） A ．1.6 B ．3.2 C ．6.4 D ．12.8 4.两个相关变量满足如表关系： x 2 3 4 5 6 y25●505664根据表格已得回归方程：=9.4x+9.2，表中有一数据模糊不清，请推算该数据是（）A ．37B ．38.5C ．39D ．40.5 5．若将函数()1cos22f x x =的图像向左平移6π个单位长度，则平移后图像的一个对称中心可以为（） A. ,012π⎛⎫ ⎪⎝⎭ B. ,06π⎛⎫ ⎪⎝⎭ C. ,03π⎛⎫ ⎪⎝⎭D. ,02π⎛⎫⎪⎝⎭6.若如图所示的程序框图输出的S 的值为126，则条件①为( )A ．n ≤5?B ．n ≤6?C ．n ≤7? D. n ≤8?M NU7.在矩形ABCD中，AB＝4，BC＝3，沿AC将矩形ABCD折叠，其正视图和俯视图如图所示. 此时连结顶点B、D形成三棱锥B－ACD，则其侧视图的面积为A.125B.1225C.7225D.144258．设点(),P x y在不等式组2030xx yx y≥⎧⎪-≤⎨⎪+-≤⎩表示的平面区域上，则2221z x y x=+-+的最小值为（）A. 1B.55C. 2D.2559．函数()()1cos0f x x x x xxππ⎛⎫=--≤≤≠⎪⎝⎭且的图象可能为10．在平行四边形ABCD中，AC与BD交于点O，E是线段OD的中点，AE 的延长线与CD相交于点F若AB=2，2,45,AD BAD AF BE=∠=⋅=ou u u r u u u r则A．12-B．1- B．1 D.1211．如图，过抛物线22(0)y px p=>的焦点F的直线l交抛物线于点A B、，交其准线于点C，若3BC BF=，且4AF=，则p为（）DA BC正视图俯视图A.43 B. 2 C. 83 D. 16312．若存在两个正实数,x y ，使得等式()()324ln ln 0x a y ex y x +--=成立，其中e 为自然对数的底数，则实数a 的取值范围是( ) A. (),0-∞ B. 30,2e ⎛⎤ ⎥⎝⎦ C. 3,2e ⎡⎫+∞⎪⎢⎣⎭D. ()3,0,2e ⎡⎫-∞⋃+∞⎪⎢⎣⎭ 第II 卷（非选择题）二、填空题（每题5分，共20分）13. 某市有三类医院，甲类医院有4000病人，乙类医院有2000病人，丙类医院有3000病人，为调查三类医院的服务态度，利用分层抽样的方法抽取900人进行调查，则从乙类医院抽取的人数为_____________人． 14．在812x x ⎛⎫- ⎪⎝⎭的展开式中，2x 项的系数为______________15、已知在等差数列{}n a 中，{}n a 的前n 项和为n S ，1131,91a S ==，若6kkS a =，则正整数k =.16.1234212,21334,2135456,213575678,⨯=⨯⨯=⨯⨯⨯⨯=⨯⨯⨯⨯⨯⨯=⨯⨯⨯…依此类推，第n 个等式为 . 三、解答题（共70分，解答应写出文字说明，证明过程或演算步骤）17．（本小题满分10分）已知等差数列{}n a 的前n 项和为n S ，*310,5,100n N a S ∈==．（1）求数列{}n a 的通项公式；（2）设，求数列{}n b 的前n 项和n T .18. （本小题满分12分）已知函数43)3cos(sin 3)(++=πx x x f ． (Ⅰ) 求函数)(x f 的单调递增区间；(Ⅱ) 已知ABC ∆中，角C B A ,,所对的边长分别为c b a ,,，若0)(=A f ，2,3==b a ，求ABC ∆的面积S ．19．（本小题满分12分）已知三棱柱111C B A ABC -，底面三角形ABC 为正三角形，侧棱1AA ⊥底面ABC ，4,21==AA AB ，E 为1AA 的中点，F 为BC 中点．(Ⅰ)求证：直线//AF 平面1BEC ；（Ⅱ）求平面1BEC 和平面ABC 所成的锐二面角的余弦值．20、(本小题12分)某学校实行自主招生，参加自主招生的学生从8个试题中随机挑选出4个进行作答，至少答对3个才能通过初试．已知甲、乙两人参加初试，在这8个试题中甲能答对6个，乙能答对每个试题的概率为34，且甲、乙两人是否答对每个试题互不影响．（Ⅰ）求甲通过自主招生初试的概率；（Ⅱ）试通过概率计算，分析甲、乙两人谁通过自主招生初试的可能性更大；（Ⅲ）记甲答对试题的个数为X ，求X 的分布列及数学期望．21、（12分）设椭圆M ：()222210y x a b a b+=>>的离心率与双曲线221x y -=的离心率互为倒数，且椭圆的长轴长为4. （1）求椭圆M 的方程；（2）若直线y m =+交椭圆M 于A ，B 两点，(p 为椭圆M 上的一点，求PAB ∆面积的最大值.22．（12分）已知函数()2ln pf x px x x=--. （1）若2p =，求曲线()y f x =在点(1,(1))f 处的切线；（2）若函数()f x 在其定义域内为增函数，求正实数p 的取值范围；（3）设函数2()eg x x=，若在[1,]e 上至少存在一点0x ，使得00()()f x g x >成立，求实数p 的取值范围.高三数学试题（理科）强化一一选择题题号 1 2 3 4 5 6 7 8 9 10 11 12 答案BDCCABCDDACD13. 200 14.-7 15.11 16.213(21)(1)(2)(2)nn n n n ⨯⨯⨯⨯-=+⨯+⨯⨯…… 三解答题17．解：（1）设等差数列{}n a 的公差为d ，由题意知1125{1045100a d a d +=+=解得11,2a d ==.所以数列{}n a 的通项公式为21n a n =- （2）18（Ⅰ）43)3sin sin 3cos(cos sin 3)(+-=ππx x x x f 43sin 23cos sin 232+-=x x x x x 2cos 432sin 43+=)32sin(23π+=x ……………………………………………… 3分令Z k k x k ∈+≤+≤-,223222πππππ，得Z k k x k ∈+≤≤-,12125ππππ，所以函数)(x f 的单调递增区间为Z k k k ∈⎥⎦⎤⎢⎣⎡+-,12,125ππππ…… 6分（Ⅱ）Θ0)(=A f ，0)32sin(23=+∴πA ，解得3π=A 或65π=A ，又b a <，故3π=A …………………………………………8分由B b A a sin sin =，得1sin =B ，则2π=B ,6π=C ,………… 10分所以23sin 21==C ab S ．……………………………………12分 19．法一（Ⅰ）取1BC 的中点为R ，连接RF RE ,，则1//CC RF ，1//CC AE ，且RF AE =，…………………………3分则四边形AFRE 为平行四边形，则RE AF //，即//AF 平面1REC ．………………………………6分（Ⅱ）延长E C 1交CA 延长线于点Q ，连接QB ，则QB 即为平面1BEC 与平面ABC 的交线，且BQ B C BQ BC ⊥⊥1,，则BC C 1∠为平面1BEC 和平面ABC 所成的锐二面角的平面角．……8分在1BCC ∆中，55522cos 1==∠BC C ．…………………………12分法二取11C B 中点为S ，连接FS ，以点F 为坐标原点，FA 为x 轴，FB 为y 轴，FS 为z 轴建立空间直角坐标系，则)0,1,0(),0,0,0(),0,1,0(),0,0,3(-C F B A ，)2,0,3(),4,1,0(),4,1,0(),4,0,3(11E C B A -，……………………2分（Ⅰ）则)0,0,3(-=AF ，)4,2,0(),2,1,3(1-=-=BC BE ，设平面1BEC 的法向量为),,(111z y x m =，则0,01=⋅=⋅BC m BE m ，即⎩⎨⎧=+-=+-04202311111z y z y x ………………4分令21=y ，则1,011==z x ，即)1,2,0(=m ，所以0=⋅m AF ，故直线//AF 平面1BEC ．………………………………………………6分（Ⅱ）设平面ABC 的法向量)1,0,0(=，则55cos ==θ．…………………………………………… 20、解：（Ⅰ）依题意，所求概率31462644881114C C C P C C =+=．………………2分（Ⅱ）乙通过自主招生初试的概率3434313189'444256P C ⎛⎫⎛⎫⎛⎫=+= ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭；因为1118914256>，故甲通过自主招生初试的可能性更大．………………6分（Ⅲ）依题意，X 的可能取值为2,3,4；()2262483214C C P X C ===；()316248843=147C C P X C ===；()46483414C P X C ===；故X 的分布列为：所以()3234314714E X =⨯+⨯+⨯=． ………………12分21、（1c e a == 则22224,c a b a c a ===-得2,a cb ===椭圆M 的方程为22142y x +=. （2）由22124x y ym ⎧+=⎪⎨⎪=+⎩得22440x m ++-=()()221640m ∆=-->得m -<<设()()1122,,,A x y B x y212124,24m x x m x x-∴+=-⋅=12||||AB x x ∴=-===又点P 到直线AB 的距离d =11||22ABPS AB d ∆∴=⋅==2282m m ⎛⎫+-≤= ⎪⎝⎭当且仅当2m =±时(()m ∈-时取等号()max PAB S ∆∴=22．解：已知函数()2ln pf x px x x=--. （1）2()22ln f x x x x=--，(1)0f =， '222()2f x x x=+-，'(1)2f =，故切线方程为：22y x =-. （3分）（2）2'2222()p px x pf x p x x x -+=+-=，由()f x 在定义域(0,)+∞内为增函数，所以'()0f x ≥在(0,)+∞上恒成立，∴220px x p -+≥即221xp x ≥+，对0x ∀>恒成立，设22()(0)1x h x x x =>+，222'222222422()(1)(1)x x x h x x x +--==++，易知，()h x 在(0,1)上单调递增，在(1,)+∞上单调递减，则max ()(1)1h x h ==， ∴(1)1p h ≥=，即[1,)p ∈+∞. （8分）（3）设函数2()()()2ln p ex f x g x px x xϕ+=-=--，[1,]x e ∈，则原问题⇔在[1,]e 上至少存在一点0x ，使得0max ()0()0x g x ϕ>⇔>2'22222(2)()p e px x p e x p x x xϕ+-++=+-=， 01当0p =时，'222()0x ex x ϕ-+=>，则()x ϕ在[1,]x e ∈上单调递增，max ()()40x e ϕϕ==-<，舍；02当0p <时，12()()2ln ex p x x x x ϕ=---，∵[1,]x e ∈，∴10x x-≥，20e x >，ln 0x >，则()0x ϕ<，舍；3当0p >时，2'2(1)2()()0p x e x x x ϕ++-=>，则()x ϕ在[1,]x e ∈上单调递增，max ()()40px e pe eϕϕ==-->，整理得241e p e >-，综上，24(,)1e p e ∈+∞-.11．【解析】设,A B 在准线上的射影分别为','A B ，则由于3'BC BB =，则直线l 的斜率为，4,'4AF AA =∴=Q ，故3'12AC AA ==，从而2,6,8,12BF CB CF CA ====，故'P CF AA CA =，即83p =，故选C. 12．【解析】由3x+a(2y −4ex)(lny −lnx)=0得3x+2a(y −2ex)ln yx=0，即322ln 0y ya e x x ⎛⎫+-=⎪⎝⎭，即设y t x =，则t>0，则条件等价为3+2a(t −2e)lnt=0，即(t −2e)lnt=−32a 有解，设g(t)=(t −2e)lnt ，()2'ln 1eg t t t=+-为增函数， ∵()2'ln 11120eg e e e=+-=+-=，∴当t>e 时,g′(t)>0，当0<t<e 时,g′(t)<0，即当t=e 时,函数g(t)取得极小值为：g(e)=(e −2e)lne=−e ，即g(t)⩾g(e)=−e ，若()32ln 2t e t a -=-有解，则32e a --…,即32e a „，则a<0或32a e…，实数a 的取值范围是()3,0,2e ⎡⎫-∞⋃+∞⎪⎢⎣⎭。

黑龙江省五常市雅臣中学2017-2018学年高三上学期11月月考数学(文)试卷含答案

雅臣中学第四次月考试题（文科数学）一．选择题。

（每题5分，共12道，共计60分）1．已知集合{}2log 2<=x x A ，{}Rx y y B x∈+==,23，则AB = （ )A ．（1，4）B ．（2，4)C ．（1，2）D ．),1(+∞ 2．在复平面内,复数i iz +=1（i 是虚数单位）对应的点位于（）A.第一象限B. 第二象限C. 第三象限D 。

第四象限 3。

将函数)62sin(π+=x y 的图象向右平移6π个单位，再纵坐标不变，横坐标变为原来的2倍，所得新图象的函数解析式是（） A.xy 4sin = B 。

xy sin = C 。

)64sin(π-=x y D 。

)6sin(π-=x y4.已知()f x 是定义在R 上的奇函数，当0x >时，2()log f x x =,则(8)f -值为（）A.3-B.13C.13-D 。

35．已知直线l 的方程为0263=+-y x ，直线⊥l 直线/l ，且直线/l 过点)3,1(-,则直线/l 的方程为（）A ．012=-+y xB ．052=-+y xC ．052=-+y xD ．072=+-y x6。

已知{}na 为等比数列，472a a +=，568a a =-,则110a a +=（）A 。

7 B. 5 C.-7D.-57．执行如图所示的程序框图，则输出的S 值为（[]x 表示不超过x 的最大整数）（）A ．4B ．6C ．7D ．98．一个几何体的三视图如图所示，则这个几何体的体积等于（）A. 12 B 。

4 C. 356 D.3389。

若圆C 的半径为1，圆心在第一象限，且与直线430x y -=和x 轴都相切，则该圆的标准方程( ) A 。

227(3)()13x y -+-= B.22(2)(1)1x y -+-= C.22(1)(3)1x y -+-= D 。

223()(1)12x y -+-=10.矩形ABCD 中，AB ＝4，BC ＝3，沿AC 将矩形ABCD 折起，使平面BAC ⊥平面DAC ，则四面体A －BCD 的外接球的体积为( ） A 。

黑龙江省五常市雅臣中学2018届高三上学期第一次强化训练英语

高三强化训练一第Ⅰ卷第一部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项。

AWhen I was 12, I got a part-time job on a dairy farm, miling cows. We miled 65 cows twice a day. One day, I complained to my father about having to mil those cows, saying it was tiring. He said, “you now, boy, to wor is a blessing.” I looed at the men who’d wored harder. I had a feeling I had been told something really important, but it too many years before it sun in.Bac then, going to college was a rare privilege. My father told me if I’d piced something to study that I lied doing, I’d always loo forward to my wor. But he also added, even having a job you hate is better than not having a job at all. I wanted to be a farmer, but I joined a military program to help pay for college. And what started out as an obligation to the Army became a way of life that I stayed committed to for 37 years.In the late 1980s, during a visit to Bangladesh, I saw a woman with her baby on her bac, breaing brics with a hammer. I ased a local officer why they weren’t using a machine to mae the wor easier. He told me a machine would put that lady out of wor. And as bad as that woman’s job was, it was enough to eep a small family alive. It reminded me of my father’s words to wor is a blessing.After seeing a lot of people lie that woman in Bangladesh, I’ve come to believe that people without jobs are not free. They’re victims of crime, poor health, and depression. People who have jobs can have a home, send their ids to school, develop a sense of pride, contribute to the good of the community and even help others. When we can wor, we are free. We are blessed.1. Which can be the best title of the tet?A. To Wor Is a BlessingB. My Chosen Way of LifeC. Why Should I WorD. Inspiration from a Woman2. What can we learn from the first paragraph?A.The writer’s parents were rich farmers.B. The writer admired his father’s job.C. The writer didn’t enjoy his part-time job.D. The writer disagreed with his father.3. The writer joined a military program because _______.A. his parents forced him to do soB. he intended to find a lifetime jobC. he could travel abroad with the armyD. he couldn’t afford his college education4. According to Paragraph 3, machines were not used because _______.A. machines were too epensiveB. people needed jobs to liveC. women could do the wor betterD. machines were hard to operateBWhich tablet computer should YOU be buying? They are this year’s must… and there’s a style to suit everyone.A. quarrel withB. compete withC. compare withD. meet with6. Which of the following about Surface is TRUE?A. The eyboard is not included in it.B. The eyboard can serve as a cover.C. It is specially designed for parents.D. You cannot surf the Internet with it.7. If you are a game lover, which tablet is liely to be your choice?A. Amaon indle Paperwhite.B. LeapPad Eplorer2.C. Microsoft Surface.D. iPad 4th generation.CThe TV program, A Bite of China, featuring delicious Chinese food, has attracted countless viewers, and moved many to tears.A Bite of China is a serious documentary providing a unique view of Chinese as well as the relations between people and food and between people and society from the view of food. The touching documentary reminds some people of their mother, and maes some realie that every grain comes from hard and laborious wor. Some people see patriotism (爱国精神) in the documentary, and some consider it a great cultural eport.How did this documentary achieve a great influence beyond its subject matter in such a short time?“It is not empty propaganda (宣传) ab out China’s splendid food culture. Instead, it shows the techniques used in maing food and their production process as well as the lives of ordinary people, thus striing a chord (共鸣) with the audience,” an Internet user said. The success of the documentary should be attributed to sincerity and reality. Nowadays, many wors of art that have high investment, high technology, and magnificent scenes lac nothing but sincerity and reality.A Bite of China shows that a commercial documentary promoting patriotism can be full of touching details, that the emotions of ordinary Chinese people should be ehibited even in publiciing China overseas, and that even a completely commercial program can achieve both artistic and commercial success.“We made this documentary with our respect and love for food,” said director Chen iaoqing. Being sincere is the most important thing for artists because they cannot move others unless they themselves are first moved, and cannot convince others unless they themselves arefirst con vinced. Sincerity is the “secret” for maing this documentary so popular, and every cultural creator should learn from its success.8. The underlined words “be attributed to” in paragraph 4 can be replaced by .A.be caused byB. contribute toC. be devoted toD. result in9. What can you mainly find in A Bite of China?A. Relations between people and food.B. Real lives of all Chinese people.C. Patriotic stories of Chinese people.D. Process of preparing food.10. What can we infer from the passage?A. The documentary is so successful that no one can surpass it.B. Different people can get different messages from the documentary.C. The documentary should have shown China’s splendid food culture.D. Many art wors fail to reflect reality and high technology.11. What is the main idea of the last paragraph?A. Director’s respect and love for food.B. The secret of the documentary’s success.C. The influence of the documentary.D. The popularity of the documentary.DWhen Shaespeare was twenty-one, he went to London to try his fortune in that great city, and a very interesting place was the London of his day.There was the famous London Bridge and St. Paul’s Cathedral, and palaces and marets and long streets full of shops.Then, too, there were the daily crowds where could be seen people from all over the world. nights，scholars and the highwayman (拦路强盗）or thief，who had been infamous for his clever robberies, passed by each other.Here, also, were noblemen dressed in gold, from Italy and Spain and France; slaves from Spanish America, sea captains and ministers, soldiers and servants — all held by chance or interest within the gray walls which circled London, and whose gates gave welcome to as strange a crowd as could be found in the world.Into this curious crowd came Shaespeare, quic to see and eager to learn. And before long all these strange sights were as familiar to him as the faces of his own town’s residents. Each one told its story to him so plainly that, as before he had learned the secrets of the fields and woods, so now he learned men and men’s interests that mae up the great world.And he learned these lessons so well that when he came to write his plays, he made such use of them as no writer ever made before or since; for it is the use of this nowledge of the world, combined with his own genius, that maes Shaespeare the greatest dramatist that has ever lived.12. What was London lie in Shaespeare’s eyes when he first went there?A. Dirty and small.B. Infamous and terrible.C. Strange and interesting.D. Familiar and modern.13. Which of the following best describes Shaespeare?A. Shaespeare got inspiration to write from his hometown, London.B. Shaespeare was eager to mae friends with the noblemen in London.C. Shaespeare became the greatest dramatist owing to his own genius.D. Shaespeare was good at observing and learning from the daily life.14. What does the word “one” in paragraph 5 refer to?A. Sight.B. CrowdC. Face.D.Resident15. What will be taled about in the following paragraph?A. How Shaespeare became familiar with the best plays of the day.B. How Shaespeare applied what he’d learned to his writing.C. How Shaespeare spent his childhood and boyhood.D. How Shaespeare combined his eperience with London第二节（共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。

黑龙江省五常市度高三英语上学期第一次强化训练试题-人教版高三全册英语试题

黑龙江省五常市2017-2018学年度高三英语上学期第一次强化训练试题第1卷第一局部阅读理解〔共两节，总分为40分〕第一节〔共15小题；每一小题2分，总分为30分〕阅读如下短文，从每题所给的四个选项〔A、B、C和D〕中，选出最优选项。

AWhen I was 12, I got a part-time job on a dairy farm, milking cows. We milked 65 cows twice a day. One day, I complained to my father about having to milk those cows, saying it was tiring. He said, “you know, boy, to work is a blessing.〞 I looked at the men who’d worked harder. I had a feeling I had been told something really important, but it took many years before it sunk in.Back then, going to college was a rare privilege. My father told me if I’d picked something to study that I liked doing, I’d always look forward to my work. But he also added, even having a job you hate is better than not having a job at all. I wanted to be a farmer, but I joined a military program to help pay for college. And what started out as an obligation to the Army became a way of life that I stayed committed to for 37 years.In the late 1980s, during a visit to Bangladesh, I saw a woman with her baby on her back, breaking bricks with a hammer. I asked a local officer why they weren’t using a machine to make the work easier. He told me a machine would put that lady out of work. And as bad as that woman’s job was, it was enough to keep a small family alive. It reminded me of my father’s words: to work is a blessing.After seeing a lot of people like that woman in Bangladesh, I’ve come to believe that people without jobs are not free. They’re victims of crime, poor health, and depression. People who have jobs can have a home, send their kids to school, develop a sense of pride, contribute to the good of the community and even help others. Whenwe can work, we are free. We are blessed.1. Which can be the best title of the text?A. To Work Is a BlessingB. My Chosen Way of LifeC. Why Should I WorkD. Inspiration from a Woman2. What can we learn from the first paragraph?A.The writer’s parents were rich farmers.B. The writer admired his father’s job.C. The writer didn’t enjoy his part-time job.D. The writer disagreed with his father.3. The writer joined a military program because _______.A. his parents forced him to do soB. he intended to find a lifetime jobC. he could travel abroad with the armyD. he couldn’t afford his college education4. According to Paragraph 3, machines were not used because _______.A. machines were too expensiveB. people needed jobs to liveC. women could do the work betterD. machines were hard to operateBWhich tablet compu ter should YOU be buying? They are this year’s must… and there’s a style to suit everyone.5. The underlined phrase “stumble across〞 most probably means _______.A. quarrel withB. compete withC. compare withD. meet with6. Which of the following about Surface is TRUE?A. The keyboard is not included in it.B. The keyboard can serve as a cover.C. It is specially designed for parents.D. You cannot surf the Internet with it.7. If you are a game lover, which tablet is likely to be your choice?A. Amazon Kindle Paperwhite.B. LeapPad Explorer2.C. Microsoft Surface.D. iPad 4th generation.CThe TV program, A Bite of China, featuring delicious Chinese food, has attracted countless viewers, and moved many to tears.A Bite of China is a serious documentary providing a unique view of Chinese as well as the relations between people and food and between people and society from the view of food. The touching documentary reminds some people of their mother, and makes somerealize that every grain comes from hard and laborious work. Some people see patriotism (爱国精神) in the documentary, and some consider it a great cultural export.How did this documentary achieve a great influence beyond its subject matter in such a short time?“It is not empty propaganda (宣传) about China’s splendid food culture.Instead, it shows the techniques used in making food and their production process as well as the lives of ordinary people, thus striking a chord (共鸣) with the audience,〞 an Internet user said. The success of the documentary should be attributed to sincerity and reality. Nowadays, many works of art that have high investment, high technology, and magnificent scenes lack nothing but sincerity and reality.A Bite of China shows that a commercial documentary promoting patriotism can be full of touching details, that the emotions of ordinary Chinese people should be exhibited even in publicizing China overseas, and that even a completely commercial program can achieve both artistic and commercial success.“We made this documentary with our respect and love for food,〞 said director Chen Xiaoqing. Being sincere is the most important thing for artists because they cannot move others unless they themselves are first moved, and cannot convince others unless they themselves are first convinced. Sincerity is the “secr et〞 for making this documentary so popular, and every cultural creator should learn from its success.8. The underlined words “be attributed to〞 in paragraph 4 can be replaced by .A.be caused byB. contribute toC. be devoted toD. result in9. What can you mainly find in A Bite of China?A. Relations between people and food.B. Real lives of all Chinese people.C. Patriotic stories of Chinese people.D. Process of preparing food.10. What can we infer from the passage?A. The documentary is so successful that no one can surpass it.B. Different people can get different messages from the documentary.C. The documentary should have shown China’s splendid food culture.D. Many art works fail to reflect reality and high technology.11. What is the main idea of the last paragraph?A. Director’s respect and love for food.B. The secret of the documentary’ssuccess.C. The influence of the documentary.D. The popularity of the documentary.DWhen Shakespeare was twenty-one, he went to London to try his fortune in that great city, and a very interesting place was the London of his day.There was the famous London Bridge and St. Paul’s Cathedral, and palaces and markets and long streets full of shops.Then, too, there were the daily crowds where could be seen people from all over the world. Knights，scholars and the highwayman (拦路强盗〕or thief，who had been infamous for his clever robberies, passed by each other.Here, also, were noblemen dressed in gold, from Italy and Spain and France; slaves from Spanish America, sea captains and ministers, soldiers and servants — all held by chance or interest within the gray walls which circled London, and whose gates gave welcome to as strange a crowd as could be found in the world.Into this curious crowd came Shakespeare, quick to see and eager to learn. And before long all these strange sights were as familiar to him as the faces of his own town’s residents. Each one told its story to him so plainly that, as before he had learned the secret s of the fields and woods, so now he learned men and men’s interests that make up the great world.And he learned these lessons so well that when he came to write his plays, he made such use of them as no writer ever made before or since; for it is the use of this knowledge of the world, combined with his own genius, that makes Shakespeare the greatest dramatist that has ever lived.12. What was London like in Shakespeare’s eyes when he first went there?A. Dirty and small.B. Infamous and terrible.C. Strange and interesting.D. Familiar and modern.13. Which of the following best describes Shakespeare?A. Shakespeare got inspiration to write from his hometown, London.B. Shakespeare was eager to make friends with the noblemen in London.C. Shakespeare became the greatest dramatist owing to his own genius.D. Shakespeare was good at observing and learning from the daily life.14. What does the word “one〞 in paragraph 5 refer to?A. Sight.B. CrowdC.Face. D.Resident15. What will be talked about in the following paragraph?A. How Shakespeare became familiar with the best plays of the day.B. How Shakespeare applied what he’d learned to his writing.C. How Shakespeare spent his childhood and boyhood.D. How Shakespeare combined his experience with London第二节〔共5小题；每一小题2分，总分为10分〕根据短文内容，从短文后的选项中选出能填入空白处的最优选项。

黑龙江省五常市雅臣中学2018届高三上学期第一次强化训练英语

高三强化训练一第Ⅰ卷第一部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项。

AWhen I was 12, I got a part-time job on a dairy farm, miling cows. We miled 65 cows twice a day. One day, I complained to my father about having to mil those cows, saying it was tiring. He said, “you now, boy, to wor is a blessing.” I looed at the men who’d wored harder. I had a feeling I had been told something really important, but it too many years before it sun in.Bac then, going to college was a rare privilege. My father told me if I’d piced something to study that I lied doing, I’d always loo forward to my wor. But he also added, even having a job you hate is better than not having a job at all. I wanted to be a farmer, but I joined a military program to help pay for college. And what started out as an obligation to the Army became a way of life that I stayed committed to for 37 years.In the late 1980s, during a visit to Bangladesh, I saw a woman with her baby on her bac, breaing brics with a hammer. I ased a local officer why they weren’t using a machine to mae the wor easier. He told me a machine would put that lady out of wor. And as bad as that woman’s job was, it was enough to eep a small family alive. It reminded me of my father’s words to wor is a blessing.After seeing a lot of people lie that woman in Bangladesh, I’ve come to believe that people without jobs are not free. They’re victims of crime, poor health, and depression. People who have jobs can have a home, send their ids to school, develop a sense of pride, contribute to the good of the community and even help others. When we can wor, we are free. We are blessed.1. Which can be the best title of the tet?A. To Wor Is a BlessingB. My Chosen Way of LifeC. Why Should I WorD. Inspiration from a Woman2. What can we learn from the first paragraph?A.The writer’s parents were rich farmers.B. The writer admired his father’s job.C. The writer didn’t enjoy his part-time job.D. The writer disagreed with his father.3. The writer joined a military program because _______.A. his parents forced him to do soB. he intended to find a lifetime jobC. he could travel abroad with the armyD. he couldn’t afford his college education4. According to Paragraph 3, machines were not used because _______.A. machines were too epensiveB. people needed jobs to liveC. women could do the wor betterD. machines were hard to operateBWhich tablet computer should YOU be buying? They are this year’s must… and there’s a style to suit everyone.A. quarrel withB. compete withC. compare withD. meet with6. Which of the following about Surface is TRUE?A. The eyboard is not included in it.B. The eyboard can serve as a cover.C. It is specially designed for parents.D. You cannot surf the Internet with it.7. If you are a game lover, which tablet is liely to be your choice?A. Amaon indle Paperwhite.B. LeapPad Eplorer2.C. Microsoft Surface.D. iPad 4th generation.CThe TV program, A Bite of China, featuring delicious Chinese food, has attracted countless viewers, and moved many to tears.A Bite of China is a serious documentary providing a unique view of Chinese as well as the relations between people and food and between people and society from the view of food. The touching documentary reminds some people of their mother, and maes some realie that every grain comes from hard and laborious wor. Some people see patriotism (爱国精神) in the documentary, and some consider it a great cultural eport.How did this documentary achieve a great influence beyond its subject matter in such a short time?“It is not empty propaganda (宣传) ab out China’s splendid food culture. Instead, it shows the techniques used in maing food and their production process as well as the lives of ordinary people, thus striing a chord (共鸣) with the audience,” an Internet user said. The success of the documentary should be attributed to sincerity and reality. Nowadays, many wors of art that have high investment, high technology, and magnificent scenes lac nothing but sincerity and reality.A Bite of China shows that a commercial documentary promoting patriotism can be full of touching details, that the emotions of ordinary Chinese people should be ehibited even in publiciing China overseas, and that even a completely commercial program can achieve both artistic and commercial success.“We made this documentary with our respect and love for food,” said director Chen iaoqing. Being sincere is the most important thing for artists because they cannot move others unless they themselves are first moved, and cannot convince others unless they themselves arefirst con vinced. Sincerity is the “secret” for maing this documentary so popular, and every cultural creator should learn from its success.8. The underlined words “be attributed to” in paragraph 4 can be replaced by .A.be caused byB. contribute toC. be devoted toD. result in9. What can you mainly find in A Bite of China?A. Relations between people and food.B. Real lives of all Chinese people.C. Patriotic stories of Chinese people.D. Process of preparing food.10. What can we infer from the passage?A. The documentary is so successful that no one can surpass it.B. Different people can get different messages from the documentary.C. The documentary should have shown China’s splendid food culture.D. Many art wors fail to reflect reality and high technology.11. What is the main idea of the last paragraph?A. Director’s respect and love for food.B. The secret of the documentary’s success.C. The influence of the documentary.D. The popularity of the documentary.DWhen Shaespeare was twenty-one, he went to London to try his fortune in that great city, and a very interesting place was the London of his day.There was the famous London Bridge and St. Paul’s Cathedral, and palaces and marets and long streets full of shops.Then, too, there were the daily crowds where could be seen people from all over the world. nights，scholars and the highwayman (拦路强盗）or thief，who had been infamous for his clever robberies, passed by each other.Here, also, were noblemen dressed in gold, from Italy and Spain and France; slaves from Spanish America, sea captains and ministers, soldiers and servants — all held by chance or interest within the gray walls which circled London, and whose gates gave welcome to as strange a crowd as could be found in the world.Into this curious crowd came Shaespeare, quic to see and eager to learn. And before long all these strange sights were as familiar to him as the faces of his own town’s residents. Each one told its story to him so plainly that, as before he had learned the secrets of the fields and woods, so now he learned men and men’s interests that mae up the great world.And he learned these lessons so well that when he came to write his plays, he made such use of them as no writer ever made before or since; for it is the use of this nowledge of the world, combined with his own genius, that maes Shaespeare the greatest dramatist that has ever lived.12. What was London lie in Shaespeare’s eyes when he first went there?A. Dirty and small.B. Infamous and terrible.C. Strange and interesting.D. Familiar and modern.13. Which of the following best describes Shaespeare?A. Shaespeare got inspiration to write from his hometown, London.B. Shaespeare was eager to mae friends with the noblemen in London.C. Shaespeare became the greatest dramatist owing to his own genius.D. Shaespeare was good at observing and learning from the daily life.14. What does the word “one” in paragraph 5 refer to?A. Sight.B. CrowdC. Face.D.Resident15. What will be taled about in the following paragraph?A. How Shaespeare became familiar with the best plays of the day.B. How Shaespeare applied what he’d learned to his writing.C. How Shaespeare spent his childhood and boyhood.D. How Shaespeare combined his eperience with London第二节（共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。

度高三地理上学期第一次强化训练试题

黑龙江省五常市2017-2018学年度高三地理上学期第一次强化训练试题一、选择题（共40题，每题1.5分，共60分）全球低纬地区共有10个海拔在1000m以上的著名热带和亚热带大高原。

下图为某低纬高原的局部区域图，读图完成1～3题。

1. 图中M城市A. 全年皆夏B. 四季分明C. 全年湿润D. 气温年较差小2. 导致M城市上述特征的因素主要有A. 纬度、地形B. 赤道低气压带C. 暖流、纬度D. 地形、信风3. 若M城市昼达到一年最长时，则A. 甲地正午太阳高度达一年中最大B. 我国漠河可能出现“白夜”景象C. M城高楼日出时影子朝向西北D. 天山牧场转向山麓2017年2月8日，格陵兰岛北端的气温升至0℃以上，引发世人关注。

近30年来，北极地区不仅在变暖，而且变暖速度是全球平均速度的2倍，这种加速变暖现象被称为“北极放大效应”。

据此完成4～5题。

4. “北极放大效应”现象的形成机制是A. 受高气压带控制，晴朗天气多B. 极昼时间长，海水热量收入多C. 海冰消融，海面的反射率下降D. 周边国家的温室气体排放剧增5. 受“北极放大效应”的影响，下列北极地区的现象中，日期推迟的是A. 苔原植物的花期B. 驯鹿的南迁日期C. 入海河流的汛期D. 沿海港口的融冻一科研团队为解决某地区饮水问题设计了坝窖联蓄工程（如下图），利用淤地坝拦蓄沟道洪水，再用蓄水池、水窖加以存储。

据此完成6～8题。

6．图中进水口的独特设计，主要目的是为了A. 减少引水杂质B. 方便引水管自流C. 防止泥沙淤积D. 过滤水中污染物7．建设坝窖联蓄工程除了解决饮水问题，还可以A. 增加地表径流B. 降低土地盐碱化C. 缓解水土流失D. 增加水汽输送量8．最适合该工程推广的地区是A. 东南丘陵B. 河套平原C. 黄土高原D. 藏北高原读我国某山地垂直自然带分布图，回答9～10题。

9．该山地最有可能位于A．东北地区南部 B．华北地区北部C．西北地区西部 D．西南地区东部10．山地苔藓带在南坡位置较高的主要原因是A．气温较高，且为背风坡 B．气温较高，且为迎风坡C．气温较低，且为背风坡 D．气温较低，且为迎风坡大约3 000年前，秘鲁山区的农民采用一种培高田地农业技术(如下图)，科学家发现用这种方法种植当地作物的产量是现代种植方式的三倍。

黑龙江省五常市雅臣中学2017-2018学年高三上学期11月月考语文试卷含答案

2017年高三年级第四次语文月考第Ⅰ卷阅读题一、现代文阅读（9分，每小题3分）阅读下面的文字,完成1～3题。

①宋代的历史呈现着许多看似矛盾的现象,我们既看到两宋三百年经济、文化、制度建设方面的辉煌成就，也能感觉到王朝末日的苍凉。

一方面有宋徽宗这样酷爱艺术的帝王,对“太平盛世”刻意追求、大肆渲染;另一方面,这个时期实际并非“太平盛世",而是始终伴随着外部环境的挑战。

宋代的民庶、士人以及征战于疆场的军队将士，用他们的脊梁撑起了这样一个时代。

这些英雄人物，也有他们的生活寄托。

这个时期方方面面呈现出一种多重而复杂的生活情境.②宋代外部压力沉重，就国内政治局面而言,“稳定至上"是朝廷政治的核心目标。

对于民间文化发展、经济事业、社会生活等方面，宋廷因仍自然趋势而未予过多干预。

相对来说，宋代文化环境比较宽松,士人群体活跃，“开口揽时事，论议争煌煌”，正是在这样相对开明、宽松的环境下，宋代社会充满活力，大师、精英辈出。

由这种开放氛围，孕育出一种开创精神。

③葛兆光先生曾说,唐文化是“古典文化的巅峰”，而宋文化则是“近代文化的滥觞"。

这两者的区别，简单来概括,就是出现了“平民化、世俗化、人文化”的趋势。

比较唐宋两代都城，能直观感受到两类都市格局和它所呈现的不同气象。

唐代长安城的布局非常严整,而宋代开封相对来说商业气氛比较浓重.唐代居民住宅区基本上是坊式结构，“坊"在某种意义上接近于封闭的小区.而宋代城市结构，基本是一种长巷式、街区式的布局，是一种开敞式的氛围.南宋临安也是如此。

④两宋时期，文学重心逐渐下移，文学体裁从诗文扩大到词、曲、小说，与市井有了更密切的关系;创作主体从士族文人扩大到庶族文人乃至市井文人；文学的接受者扩大到市民以及社会大众。

当时都市的街头巷尾，活跃着一些讲史、说书的艺人，他们不仅是故事情节的传布者,也是文学作品的丰富者、参与创造者。

而生活在市井中的普通民众，也成为文学艺术的直接欣赏者和接受者。

2017-2018学年黑龙江省五常市雅臣中学度高三上学期第一次强化训练文数试卷

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