北京市东城区2013—2014学年度高三第一学期期末教学统一检测

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东城高三语文第一学期期末试卷2014附答案

东城区2013——2014学年度第一学期期末教学统一检测高三语文2014.1本试卷共8页，150分。

考试时间150分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

考试结束后，将本试卷和答题卡一并交回。

一、本大题共3小题，共15分。

1．阅读下面的语句，完成⑴—⑶题。

①．与古希腊戏剧和古典梵．语戏剧相比，中国古代戏曲更倾向于表现世俗的内容。

②．王国维在《宋元戏曲考》一书中对《窦娥冤》和《赵氏孤儿》有很高的评价，称它们“即列之于世界大悲剧中亦无愧色也”。

③．同样是反抗暴虐．的悲剧主人公，埃斯库罗斯的普罗米修斯是个神话人物，而关汉卿．笔下的窦娥是个普通民女。

④．人类历史上的三大古典戏剧——古希腊戏剧、印度梵语戏剧和中国古代戏曲，都是在各自民族文化土壤上生成的，因此也带有各自的民族审美的和文化心里的特征。

⑴．文中加点字的读音正确的一项是（3分）A．梵．（fán）语暴虐．（nüa）关汉卿．（qīn）B．梵．（fán）语暴虐．（ni a）关汉卿．（qīng）C．梵．（fàn）语暴虐．（nüa）关汉卿．（qīng）D．梵．（fàn）语暴虐．（ni a）关汉卿．（qīn）⑵．给上面语句排序，衔接恰当的一项是（3分）A．①②③④B．②③①④C．③②④①D．④①③②⑶．下面有关文学常识的表述有错误的一项是（3分）A．关汉卿，号己斋叟，金末元初大都（今北京市）人，元代杂剧的代表作家，与汤显祖、白朴、马致远一同被称为“元曲四大家”。

B．王国维，浙江人，是中国近现代之交的著名学者，学贯中西的国学大师，有《红楼梦评论》《人间词话》《宋元戏曲考》等著作。

C．窦娥，是善良的，同时又是战斗的、反抗的。

她的善良用在对待自己的亲人、受迫害者；她的反抗用在对付做恶的坏人、压迫者。

D．悲剧主要以剧中主人公与现实之间不可调和的冲突及其悲惨的结局构成基本内容，如莎士比亚的《哈姆雷特》、老舍的《茶馆》。

北京市东城区2014届高三第一学期期末教学统一检测历史试题

北京市东城区2014届高三第一学期期末教学统一检测历史试题本试卷共8页，共100分。

考试时长100分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

第Ⅰ卷选择题（共48分）一、选择题（本大题共32小题，每小题1．5分，共48分。

在每小题给出的四个选项中只有一项是符合题目要求的。

）1．《左传》：“天有十日，人有十等。

下所以事上，上所以共神也。

故王臣公，公臣大夫，大夫臣士”。

上述材料反映了西周社会结构的基本特点是A．严格的等级关系B．嫡长子继承制C．垄断神权强化王权D．王位世袭制2．“王道既微，诸侯力政，时君世主，好恶殊方，是以九家之术，蜂出并作，各引一端，崇其所善，以此驰说，取合诸侯。

”上述现象出现的社会文化背景是A．礼崩乐坏，思想观念多元B．尊黄老之学，学术环境宽松C．儒、释、道并存，儒学遭遇挑战D．拜金逐利盛行，传统道德观念被冲击3．柳宗元《封建论》中说：“汉有天下，矫秦之枉，徇周之制”。

基于这种认识汉朝实行的是A．分封制B．宗法制C．郡县制D．郡国并行制4．两宋时期共有正副枢密使724人，其中文臣659人。

该做法的目的是A．重视文教B．防止武将危及皇权C．解决武将割据地方的弊端 D．缓解“冗兵”问题5．19世纪30年代松江棉布大量行销欧洲，英国绅士风行以中国杭纺做衬衫，以天然棕色的松江紫花棉布做裤子。

紫花布以南京为集散地，外商称它为南京布。

上述材料反映当时A．南京是政府开放的对外贸易口岸B．中国传统手工业品尚有竞争优势C．英国棉纺织业发展缓慢D．世界市场最终形成6．下列古代出现的商业现象，按照顺序排列正确的是①私商成为商人的主体②流通领域出现纸币③实行“工商食官”政策④大量商业市镇兴起A．②③①④B．①②③④C．①④③②D．③①②④7．下列主张，出自王阳明的是A．“中庸之为德也，其至矣乎”B．“屈民而伸君，屈君而伸天”C．“心外无理、心外无物”D．“致知之道，在乎即事观理以格夫物”8．《本草纲目》被认为是一部蕴含近代科学思想和方法的著作，主要指它A．是集我国历代医药学之大成的药典B．是涉及多领域的百科全书式的巨著C．采用先进的药物分类方法D．是产生广泛影响的世界性书籍9．第二次鸦片战争后，“美收中国入口之米税，每包二角二分，每年五十万包计，税银已百余万两；而美之麦粉入中国，竟不纳税。

北京市东城区2013-2014学年高三年级第一学期期末文科数学

东城区2013-2014学年第一学期期末教学统一检测高三数学（文科） 2014.1本试卷共5页，共150分。

考试时长120分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

考试结束后，将本试卷和答题卡一并交回。

第一部分（选择题共40分）一、选择题共8小题，每小题5分，共40分。

在每小题列出的四个选项中，选出符合题目要求的一项。

（1）已知集合{|02}A x x =<<，{1,0,1}B =-，则A B =（A ）{1}- （B ）{0} （C ）{1} （D ）{0,1} （2）在复平面内，复数i(2i)+对应的点位于（A ）第一象限（B ）第二象限（C ）第三象限（D ）第四象限（3）下列函数中，既是偶函数又在区间(0,)+∞上单调递减的是（A ）ln ||y x =- （B ）3y x = （C ）||2x y = （D ）cos y x = （4）“1x >”是“21x >”的（A ）充分而不必要条件（B ）必要而不充分条件（C ）充分必要条件（D ）既不充分也不必要条件（5）执行如图所示的程序框图，输出的a 值为（A ）3 （B ）5 （C ）7 （D ）9（6）直线3y kx =+与圆22(2)(3)4x y -+-=相交于A ，B两点，若||AB =k = （A）（B）（C（D（7）关于平面向量,,a b c ，有下列三个命题： ①若⋅=⋅a b a c ，则=b c ；②若(1,)k =a ，(2,6)=-b ，a ∥b ，则3k =-；③非零向量a 和b 满足||||||==-a b a b ，则a 与+a b 的夹角为30．其中真命题的序号为（A ）①② （B ）①③ （C ）②③ （D ）①②③俯视图侧(左)视图正(主)视图（8）已知函数25,0,()e 1,0.x x x x f x x ⎧+≥⎪=⎨-+<⎪⎩若()f x kx ≥，则k 的取值范围是（A ）(,0]-∞ （B ）(,5]-∞（C ）(0,5] （D ）[0,5]第二部分（非选择题共110分）二、填空题共6小题，每小题5分，共30分。

北京市东城区2013届高三上学期期末教学统一检测数学理试题-含答案

东城区2012-2013学年度第一学期期末教学统一检测高三数学（理科）学校_____________班级_______________姓名______________考号___________本试卷分第Ⅰ卷和第Ⅱ卷两部分，第Ⅰ卷1至2页，第Ⅱ卷3至5页，共150分。

考试时长120分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

考试结束后，将本试卷和答题卡一并交回。

第Ⅰ卷（选择题共40分）一、本大题共8小题，每小题5分，共40分。

在每小题列出的四个选项中，选出符合题目要求的一项。

（1）设集合{1,2}A =，则满足{1,2,3}AB =的集合B 的个数是（A ）1 (B) 3 (C)4 (D)8 （2）已知a 是实数，i1ia +-是纯虚数，则a 等于（A ）1- （B ）1 （C（D）（3）已知{}n a 为等差数列，其前n 项和为n S ，若36a =，312S =，则公差d 等于（A ）1 （B ）53（C ）2 （D ）3 （4）执行如图所示的程序框图，输出的k 的值为（A ）4 （B ）5 （C ）6 （D ）7（5）若a ，b 是两个非零向量，则“+=-a b a b ”是“⊥a b ”的（A ）充分不必要条件（B ）必要不充分条件（C ）充要条件（D ）既不充分也不必要条件（6）已知x ，y 满足不等式组0,0,,2 4.x y x y s y x ≥⎧⎪≥⎪⎨+≤⎪⎪+≤⎩当35s ≤≤时，目标函数y x z 23+=的最大值的变化范围是（A ）[6,15]（B ）[7,15] （C ）[6,8]（D ）[7,8]（7）已知抛物线22y px =的焦点F 与双曲线22179x y -=的右焦点重合，抛物线的准线与x 轴的交点为K ，点A在抛物线上且|||AK AF =，则△AFK 的面积为（A ）4 （B ）8 （C ）16 （D ）32（8）给出下列命题：①在区间(0,)+∞上，函数1y x -=,12y x =,2(1)y x =-,3y x =中有三个是增函数；②若log 3log 30m n <<，则01n m <<<；③若函数()f x 是奇函数，则(1)f x -的图象关于点(1,0)A 对称；④已知函数233,2,()log (1),2,x x f x x x -⎧≤=⎨->⎩则方程 1()2f x =有2个实数根，其中正确命题的个数为（A ）1 （B ）2 （C ）3 （D ）4第Ⅱ卷（共110分）二、填空题：本大题共6小题，每小题5分，共30分。

东城区2013-2014第一学期英语期末测试题(附答案)

东城区2013—2014学年度第一学期期末教学统一检测英语试卷2014.121. Everyone tells me I‟m a good speaker, _____ I really don‟t like speaking in public.A. andB. soC. butD. or22. Try not to wake up the baby if you _____ into the bedroom.A. goB. wentC. have goneD. will go23. John seemed puzzled about _____ the question meant.A. howB. whyC. whatD. which24. — Do you like the school? — Yeah. I only wish the classes _____ a little smaller.A. beB. wereC. had beenD. should have been25. According to the factory safety rules, all accidents _____ be reported to the safety officer.A. mayB. canC. wouldD. must26. We can‟t go ahead with the plan because very few people _____ any interest so f ar.A. had shownB. showC. will showD. have shown27. We climbed higher _____ we might see the scenes better.A. so thatB. even thoughC. in caseD. as if28. Most of my friends shop at the stores _____ the goods are very cheap.A. whichB. whereC. whoseD. why29. At first I regretted _____ them to stay, but we soon became great friends.A. to inviteB. invitedC. to have invitedD. inviting30. The visiting professor was interested in the teaching methods _____ in the classroom.A. useB. to useC. usingD. used31. Mr. Carter will be the main speaker ______ the graduation ceremony.A. atB. toC. amongD. about32. The painting ______ to someone who later donated it to the college.A. had soldB. was soldC. will sellD. is sold33. —Joe, don‟t forget to bring your laptop with you tomorrow, OK?—Oh, thank you. I wouldn‟t bring it if you _____ me.A. wouldn‟t remindB. h aven‟t remindedC. hadn‟t remindedD. shouldn‟t have reminded34. _____ more effectively with others, more and more people equip themselves with a higher education.A. CompeteB. Being competedC. To competeD. Competing35. Health experts believe that even a little exercise is far better than _____at all.A. noneB. littleC. everythingD. anything第二节完形填空（共20小题；每小题1.5分，共30分）My father and I disagreed about curfew (晚间在家的时间). He‟d say I was to be in by 9:30 on weekdays, and 11:00 on weekends, no exceptions without my first asking. I told him it made me 36 like a junior-high kid. He explained that while a curfew 37 sound like a restriction, it‟s really about people looking out for one another.The very next Friday after that pretty heated 38 , my dad and I had tickets to see our town‟s professional football game. On that day he was 39 to a nearby city to meet with some major clients and 40 me that his getting home and our leaving for the game would be tight.To make sure we could 41 off the moment he walked in, I got everything prepared. When a half hour had passed from the time he said he‟d be home, I understood that he was a little 42 . But then, nearly a whole hour passed. I was getting 43 . We were going to miss the kick-off! And why hadn‟t he 44 me and let me know he was going to be really late? As I anxiously 45 the floor, another half hour passed. That‟s when I got really angry. How inconsiderate of my father! Now we were going to 46 the whole game! When yet another half hour passed, my anger turned to 47 . What if something terrible had happened to my dad, like he had a heart attack or had been in an accident, or something? I began to really 48 . I‟d already called his cellphone about ten times, but no 49 .I was beside myself, assuming the worst had happened.Finally, the phone rang, and my dad said 50 , “Son, I‟m so sorry about the game, but…there was a terrible accident…on the freeway coming home, and I 51 to help… and ended up going to the hospital. I52 my cellphonein the car, so I couldn‟t call until now.”I was so relieved to hear from my father and to 53 that he was safe that I actually cried. That was 54 I “got” the importance of a curfew: Checking in! It‟s about knowing that someone you love is 55 . It was one more proof of my father‟s loving me as much as he does.36. A. go B. feel C. turn D. grow37. A. might B. must C. needed D. should38. A. speech B. match C. description D. exchange39. A. cycling B. driving C. flying D. walking40. A. allowed B. advised C. informed D. ordered41. A. pay B. hold C. cut D. move42. A. late B. lazy C. forgetful D. careless43. A. upset B. sorry C. rude D. puzzled44. A. warned B. signalled C. phoned D. showed45. A. hit B. paced C. cleared D. measured46. A. play B. watch C. miss D. start47. A. sadness B. surprise C. doubt D. fear48. A. envy B. worry C. regret D. cry49. A. excuse B. way C. time D. answer50. A. strangely B. casually C. breathlessly D. angrily51. A. stopped B. forgot C. failed D. refused52. A. left B. lost C. saw D. got53. A. wonder B. guess C. expect D. learn54. A. what B. when C. whether D. why55. A. confident B. great C. safe D. honest第三部分：阅读理解（共两节，40分）A“Thanks for coming,” Everett said, shaking hands with Mr. Hanson, the town c ouncillor(议员).“I‟m curious about the ideas in your letter.” Mr. Hanson nodded toward the parking lot near where they stood. “Please tell me more.”Everett took a deep breath. “Ever since the school closed two years ago, this area has become worse. But if we clean up the litter and repair the fence, it will be a great place for a skateboard park.” Mr. Hanson scanned the broken concrete, nodding. “The old school is being adapted to a community arts centre. This area could become a vital part of the neighbourhood again.”“Here‟s a picture of a skateboard park in another town. Look how busy it is.” Everett was relieved that the community representative seemed receptive to the idea. Mr. Hanson studied the photograph, and then asked, “If town council provides the money, how will you and your friends contribute?” Everett felt optimistic now. “We‟ll help design and build the ramps(坡道). More experienced boarders could give lessons to raise money!” Everett‟s voice was enthusiastic.However, Mr. Hanson said, “We‟ll still need parking spaces, and the neighbours will not like late-night noise. They might worry about the crime of deliberately damaging public property and….”“The skateboard park would use only the back corner, which isn‟t near any houses. Since young people already hang out here, why not give them something fun and physically active to do in their free time?” The lines over Mr. Hanson‟s forehead unwrinkled(舒展), and Everett‟s hopes rose again. “If everyone works together,” Everett thought, “maybe this idea will become reality.”56. Where were Everett and Mr. Hanson talking?A. In the city hall.B. Outside a park.C. Near the parking lot.D. In the art centre.57. Everett was trying to persuade Mr. Hanson to _____.A. beautify the neighbourhoodB. cut the area of the parking lotC. build an art centre for childrenD. provide money for a skateboard park58. How did Mr. Hanson finally feel about Everett‟s suggestion?A. Curious.B. Hopeful.C. Enthusiastic.D. Receptive.B1234 PENS is your No. 1 source for promotional pens, advertising pens, and logo pens. We have been in business since 1976, so you can be confident that you‟re dealing wit h a trusted name in the industry.Everyone loves a free pen, and by providing your customers with a pen featuring your company name, logo, or message, you can be sure that your company name will always be on their mind! Our custom imprinting service comes atno extra charge, so the price you see is the price you pay for the personalized pens.★ Do you need pens fast? In a RUSH for trade shows or a corporate events? Try our 48 hour promotional pens rush service free of charge. We present you with many styles and types of printed pen. Let us know which promotional pen you like and within 48 hours you will have the pens.★ Want to use the traditional method of promotional pens to reach out to customers, but don‟t want to cause more damageto the environment? 1234 PENS now offers eco-friendly advertising pens to suit any company‟s promotional needs. 1234 PENS can confidently offer products which are made from eco-friendly materials, including paper, cardboard, cornstarch, pine, bamboo and even recycled plastic water bottles. 1234 PENS offers a selection of eco-friendly retractable and stick-type ballpoint pens, mechanical pencils and highlighters, all for less than $2.00 each. Imprinting of logos and corporate information is available in sixteen different colors. Each pen has the universal recycling symbol printed on it, showing clients the company‟s commitment to the environment.Feel free to call us at 8447367 or email us info@ if you have any questions.59. What do we know about 1234 PENS?A. It has a history of over 30 years.B. It has built up a large pen market.C. It has its name printed on each pen.D. It charges a low price for extra service.60. What is mainly discussed in Paragraph 3?A. The different types of the products.B. The high qualityofthe products.C. The quick service of 1234 PENS.D. The trade showsof1234 PENS.61. What is special about the pens produced in 1234 PENS?A. They are designed in 16 styles.B. They come in 48 different colours.C. Their material is less harmful to the earth.D. Their price is much lower in the pen market.62. The main purpose of the passage is to _____.A. persuade people to order the productsB. explain the process of making logo pensC. show people how to choose different pensD. introduce the different services of 1234 PENSCThe extraordinary Eastgate Building in Harare, Zimbabwe‟s capital city, is said to be the only one in the world to use the same cooling and heating principles as the termite mound(白蚁堆).Architect Mick Pearce used precisely the same strategy when designing the Eastgate Building, which has no air-conditioning and almost no heating. The building—the country‟s largest commercial and shopping complex—uses less than 10% of the energy of a conventional bu ilding of its size. The Eastgate‟s owners saved $3.5 million on a $36 million building because an air-conditioning plant didn‟t have to be imported.The complex is actually two buildings linked by bridges across a shady, glass-roofed atrium(天井) open to the air. Fans suck fresh air in from the atrium, blow it upstairs through hollow spaces under the floors and from there into each office through baseboard vents(通风口). As it rises and warms, it is drawn out via ceiling vents and finally exists through forty-eight brick chimneys.During summer‟s cool nights, big fans blow air through the building seven times an hour to cool the empty floors. By day, smaller fans blow two changes of air an hour through the building, to circulate the air which has been in contact with the cool floors. For winter days, there are small heaters in the vents.This is all possible only because Harare is 1600 feet above sea level, has cloudless skies, little dampness and rapid temperature swings—days as warm as 31℃commonly drop to 14℃at night. “You couldn‟t do this in New York, with its fantastically hot summers and fantastically cold winters,” Pearce said.The engineering firm of Ove Arup&Partners monitors daily temperatures. It is found that the temperature of the building has generally stayed between 23℃ and 25℃, with the exception of the annual hot period just before the summer rains in October and three days in November, when a doorkeeper accidentally switched off the fans at night. And the air is fresh—far more so than in air-conditioned buildings, where up to 30% of the air is recycled.63. Why was Eastgate cheaper to be built than a conventional building?A. It was designed in a smaller size.B. No air conditioners were fixed in.C. Its heating system was less advanced.D. It used rather different building materials.64. What does “it” refer to in Paragraph 3?A. Fresh air from outside.B. Heat in the building.C. Hollow space.D. Baseboard vent.65. Why would a building like Eastgate Not work efficiently in New York?A. New York has less clear skies as Harare.B. Its dampness affects the circulation of air.C. New York covers a larger area than Harare.D. Its temperature changes seasonally rather than daily.66. The data in the last paragraph suggests Eastgate‟s temperature control system_____.A. allows a wide range of temperaturesB. functions well for most of the yearC. can recycle up to 30% of the airD. works better in hot seasonsDIs the …Go to College‟ Message Overdone?Even in a weak job market, the old college try isn‟t the answer for everyone. A briefing paperfrom the Brookings Institution warns that “we may have overdone the message” on college, senior fellow Isabel Sawhill said.“We‟ve been telling students and their families for years that college is the only way to succeed in the economy and of course there‟s a lot of truth to that,” Ms. Sawhill said. “On average it does pay off… But if you load up on a whole lot o f student debt and then you don‟t graduate,that is a very bad situation.”One comment that people often repeat among the years of slow job growth has been the value of education for landing a job and advancing in a career. April‟s national unemployment rate stood at 7.5%, according to the L abor Department. The unemployment rate for high-school graduates over 25 years old who hadn‟t attended college was 7.4%, compared with 3.9% for those with a bachelor‟s degree or more education. The difference is even bigger among those aged 16-24. The jobless rate for those with only a high school diploma in that age group is about 20%. At the same time, recent research by Canadian economists cautions that a college degree is no guarantee of promising employment.Ms. Sawhill pointed out that among the aspects that affect the value of a college education is the field of one‟s major: Students in engineering or other sciences end up earning more than ones who major in the arts or education. The cost of tuition and the availability of financial aid are other considerations, with public institutions generally a better financial bargain than private ones.She suggested two avenues for improving the situation: increasing vocational(职业的)-technical training programs and taking a page from Europe‟s focus on early education rather than post-secondary learning. “The European countries put a little more attention to getting people prepared in the primary grades,” she said. “Then they have a higher bar for whoever goes to college—but once you get into college, you‟re more likely to be highly subsidized(资助).”She also is a supporter of technical training—to teach students how to be plumbers, welders and computer programmers—because “employers are desperate” for workers with these skills.67. People usually think that _____.A. the cost of technical schooling is a problemB. one will not succeed without a college degreeC. technical skills are most important for landing a jobD. there is an increased competition in getting into a college68. What does the underlined part “taking a page from” mean?A. Hearing from.B. Changing from.C. Differing from.D. Learning from.69. What can we infer from the passage?A. Public institutions charge more for education.B. European universities are stricter with students.C. Students with certain skills are in great demand.D. Canadian students prefer to major in engineering.70. Ms. Sawhill may probably agree that _____.A. too much stress has been put on the value of college degreesB. technical training is more important than college educationC. a college degree will ensure promising employmentD. it‟s easier for art students to find favorite jobs第二节（共5小题；每小题2分，共10分）The Importance of Accessibility AwarenessAt a recent Teen Leadership of Jewish Family Services meeting, people with disabilities talked about their lives. 71 However, what amazed me most was the great importance of education about handicap accommodations (残疾人便利设施).One school-teacher who is blind, and a woman who has used a wheelchair all her life are two important members of the National Group for Disabled Persons, devoted to raising awareness about disabilities. 72 These include handicap parking spots, handrails, and wheelchair ramps. One big concern is the people who take advantage of aids, such as handicap parking spaces. 73 And the meeting focused on educating the public.Some handicap spots have extra room next to them, marked with the “No Parking” signs. “As long as I'm not in the spot, I can take the no-parking area next to it,” some people say. However, t he woman who uses a wheelchair disagrees to this. The space exists to allow someone in a wheelchair to have room to get in or out of their car. 74Some walkways have handrails next to them to help those who require extra assistance. Whether it is a blind person seeking guidance or an elderly person seeking support, the rail is there for walking. Sometimes the rail is blocked, by a parked bicycle for instance, and consequently made useless. 75 People who are informed of the rail‟s use would be less likely to mistake it for a bike rack.Meeting some of the people who are affected by the lack of education about accommodations made me see that there is work to be done. If more people were educated about the proper uses of accommodations, there would be fewer challenges for people with physical disabilities.A. Accommodations will vary according to the needs of the disabled.B. As with the parking spot, this is more likely a case of lack of education.C. They educate about all the accommodations for people with disabilities.D. Improvement must be made so that disabled people can fully participate.E. If there is a car in that space, the handicap parking spot is no longer useful.F. So people without disabilities need to be educated about these accommodations.G. I was amazed to hear about the challenges faced by people with physical disabilities.第四部分：书面表达（共两节，35分）第一节（15分）你校将要组织美国交换生参观中国美术馆（National Art Museum of China）。

北京市东城区2014届高三第一学期期末练习英语试题及答案（WORD精校版..

英语英语第 1 页（共页（共 12 页）东城区20132013——2014学年度第一学期期末教学统一检测英语试卷 2014.1 第二部分：知识运用（共两节，45分）第一节第一节单项填空（共15小题；每小题1分，共15分）分）从每题所给的A 、B 、C 、D 四个选项中，选出可以填入空白处的最佳选项，并在答题卡上将该项涂黑。

并在答题卡上将该项涂黑。

例：It‟s so nice to hear from her again. _____, we last met more than thirty years ago. A ．What‟s more B ．That‟s to sayC ．In other words D ．Believe it or not 答案是D 。

21. Everyone tells me I‟m a good speaker, _____ I really don don‟‟t like speaking in public. A. and B. so C. but D. or 22. Try not to wake up the baby if you _____ into the bedroom. A. go B. went C. have gone D. will go 23. John seemed puzzled about _____ the question meant. A. how B. why C. what D. which 24. — Do you like the school? — Yeah. I only wish the classes _____ a little smaller. A. be B. were C. had been D. should have been 25. According to the factory safety rules, all accidents _____ be reported to the safety officer. A. may B. can C. would D. must 26. We can‟t go ahead with the plan because very few people _____ any interest so far. A. had shown B. show C. will show D. have shown 27. We climbed higher _____ we might see the scenes better. A. so that B. even though C. in case D. as if 28. Most of my friends shop at the stores _____ the goods are very cheap. A. which B. where C. whose D. why 29. At first I regretted _____ them to stay, but we soon became great friends. A. to invite B. invited C. to have invited D. inviting 30. The visiting professor was interested in the teaching methods _____ in the classroom. A. use B. to use C. using D. used 31. Mr. Carter will be the main speaker ______ the graduation ceremony. A. at B. to C. among D. about 32. The painting ______ to someone who later donated it to the college. A. had sold B. was sold C. will sell D. is sold 英语英语第 2 页（共页（共 12 页） 33. — Joe, don‟t forget to bring your laptop with you tomorrow, OK? —Oh, thank you. I wouldn‟t bring it if you _____ me. A. would n‟t remind B. haven ‟t reminded C. hadn‟t reminded t reminded D. shouldn ‟t have reminded 34. _____ more effectively with others, more and more people equip themselves with a higher education. A. Compete B. Being competed C. To compete D. Competing 35. Health experts believe that even a little exercise is far better than _____at all. A. none B. little C. everything D. anything 第二节第二节完形填空（共20小题；每小题1.5分，共30分）分）阅读下面短文，掌握其大意，从每题所给的A 、B 、C 、D 四个选项中，选出最佳选项，并在答题卡上将该项涂黑。

2013-2014东城区语文期末试卷参考答案

东城区2013—2014学年度第一学期期末教学统一检测高三语文参考答案一、（本大题共3小题，共15分）1．⑴（3分）C ⑵（3分）D ⑶（3分）A 2．（3分）B 3．（3分）C 二、（本大题共5小题，共16分）4．（3分）D 5．（3分）C 6．（3分）C 7．（3分）D8．（4分）一是朝廷通过广泛征召和推荐选拔人才，不限于生员身份。

二是让生员制度同时存在，但对生员要有一定的限额，取消岁贡和举人两种办法，要挑选那些博学多才的人参加考试。

三、（本大题共4小题，共33分）9．（8分）①（3分）对仗颔（或第二）颈（或第三）②（4分）C、E10．（12分）可供选择的角度有：①视觉角度，②动静结合，③借景抒情，④选择的意象（明月、松、泉流），⑤对偶（或对仗）等。

11．（5分）在都时/曾见一人作剧于市/携木盒作格/凡十有二孔/每孔伏蛙/以细杖敲其首/辄哇然作鸣/或与金钱/则乱击蛙顶/如拊云锣之乐/宫商词曲/了了可辨。

12．（8分）①羁鸟恋旧林池鱼思故渊②落霞与孤鹜齐飞秋水共长天一色③霓为衣兮风为马虎鼓瑟兮鸾回车④万里悲秋常作客百年多病独登台⑤常在于险远故非有志者不能至也四、本大题共3小题，共12分。

13．（3分）D14．（4分）A、E15．（5分）①提升智力需要增加新生神经元，但无限制地增加神经元会使大脑不堪重负。

②建立神经元间的连接占用了大部分新增脑容量，大脑的信息处理能力没有真正提升。

③要保证神经元传递信息的相对稳定，就不能减少离子通道的数量。

④要减少噪音，神经元必须保持足够的直径。

（答对一点得1分，答对两点得3分，答对三点得4分，答对四点得5分）五、本大题共3小题，共14分。

16．（4分）D、E（答D、E各给2分，答B给1分，答A、C不给分。

回答三项或三项以上，本题不给分）17．（6分）①（3分）要点：将情义商品化,将情义官位化,疑心太重。

（每点1分）②（3分）要点：找出能表现文章主题或人物性格的细节,分析此细节传达出的如金子般珍贵的人的品格。

北京市东城区2013—2014学年度高三第一学期期末教学统一检测-含答案

东城区2013—2014学年度第一学期期末教学统一检测高三物理 2014.01本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分，共120分。

考试时长100分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

第Ⅰ卷（选择题，共48分）一．单项选择题（本题共12小题，每小题4分，共48分。

每小题只有一个选项正确。

)1．已知两个质点相距为r 时，它们之间的万有引力大小为F 。

若只将它们之间的距离变为2r ，则它们之间的万有引力大小为 A ． 4F B ．2F C ．41F D ．21F 2．人站在电梯中随电梯一起运动。

下列过程中人处于超重状态的是A ．电梯加速上升B ．电梯加速下降C ．电梯匀速上升D ．电梯匀速下降3．如图所示，在粗糙水平地面上放一质量为M 的斜面，质量为m 的木块沿斜面匀速下滑，此过程中斜面保持静止，则A ．地面对斜面有水平向右的摩擦力B ．地面对斜面有水平向左的摩擦力C ．地面对斜面的支持力等于（M+m ）gD ．地面对斜面的支持力小于（M+m ）g 4．正点电荷的电场线如图所示，a 、b 是电场中的两点。

下列说法中正确的是A ．a 点的电场强度一定等于b 点的电场强度B ．a 点的电场强度一定大于b 点的电场强度C ．a 点的电势一定小于b 点的电势D ．a 点的电势一定等于b 点的电势5．我国家庭照明电路用的交流电的电压瞬时值随时间变化的规律为u =311sin100πt V ，关于此交流电下列说法中正确的是 A . 电压的最大值是311V B . 电压的有效值是311V C . 交流电的频率为100Hz D . 交流电的周期为100s6．如图所示电路，电源内阻不可忽略。

开关S 闭合后，在滑动变阻器R 0的滑片向下滑动的过程中A ．电压表的示数增大，电流表的示数减小B ．电压表的示数减小，电流表的示数增大C ．电压表与电流表的示数都增大D ．电压表与电流表的示数都减小mM a b7．一列简谐横波某时刻波形如图所示，此时质点P 的速度方向沿y 轴正方向，则A ．这列波沿x 轴负方向传播B ．质点a 此时动能最大，加速度最小C ．再经过一个周期，质点P 运动到x=6m 处D ．当质点P 运动到最低点时，质点b 恰好运动到平衡位置8．质量为m 的物体由静止开始下落，由于空气阻力影响物体下落的加速度为g 54，在物体下落高度为h 的过程中，下列说法正确的是A ．物体的动能增加了mgh 54B ．物体的机械能减少了mgh 54C ．物体克服阻力所做的功为mgh 54D ．物体的重力势能减少了mgh 549．如图所示，小车静止在光滑水平地面上，小车的上表面由光滑的斜面AB 和粗糙的平面BC 组成（它们在B 处由极短的光滑圆弧平滑连接），小车右侧与竖直墙壁之间连接着一个力传感器，当传感器受压力时，其示数为正值；当传感器受拉力时，其示数为负值。

北京市东城区2013届高三上学期期末教学统一检测数学理试题

AEB
（18）（本小题共 13 分）
已知 a R ，函数 f (x) a ln x 1． x
（Ⅰ）当 a 1时，求曲线 y f (x) 在点 (2, f (2)) 处的切线方程；（Ⅱ）求 f (x) 在区间0,e 上的最小值．
（19）（本小题共 13 分）
在平面直角坐标系 xOy 中，动点 P 到两点 ( ， 3，0) ( 的 3，0) 距离之和等于4，设点 P的轨迹为曲线C，直线l过点 E (1,0) 且与曲线C 交于 A ， B 两点．（Ⅰ）求曲线C 的轨迹方程；（Ⅱ）是否存在△ AOB 面积的最大值，若存在，求出△
即
x 4y 4ln 2 4 0 ．……………………………………………
6分
（Ⅱ）因为 f (x) a ln x 1，所以 f (x) a 1 x a ．
x
x2 x x2
令
， f (x) 0
得
x a ． ……………………………………………8 分 ①若 a≤0，则 f (x) 0 ， f x 在区间 0,e 上单调递增，此时
第Ⅱ卷 3 至 5 页，共 150 分。考试时长 120 分钟。考
生务必将答案答在答题卡上，在试卷上作答无效。考
试结束后，将本试卷和答题卡一并交回。
第Ⅰ卷（选择题共 40 分）一、本大题共 8 小题，每小题 5 分，共 40 分。在每
小题列出的四个选项中，选出符合题目要求的一项。
（1）设集合 A {1,2}，则满足 A B {1,2,3}的集合 B 的个数
a1 an (n 2)
求证： . n ai xi i 1
1 2
(a1
an
)
东城区 2012-2013 学年度第一学期期末教学统一检测高三数学参考答案及评分标准（理科）

北京市东城区2013—2014学年度第一学期期末试卷高三数学(理科)

北京市东城区2013—2014学年度第一学期期末试卷高三数学(理科)一、选择题（共8小题；共40分）1. 已知集合A=x0<x<2，B=x x−1x+1>0，则A∪B=A. 0,1B. 1,2C. −∞,−1∪0,+∞D. −∞,−1∪1,+∞2. 在复平面内，复数2+ii对应的点位于A. 第一象限B. 第二象限C. 第三象限D. 第四象限3. 设a∈R，则" a=−1 "是" 直线ax+y−1=0与直线x+ay+5=0平行"的A. 充分而不必要条件B. 必要而不充分条件C. 充分必要条件D. 既不充分也不必要条件4. 执行如图所示的程序框图，输出的a值为A. 3B. 5C. 7D. 95. 在△ABC中，a=15，b=10，A=60∘，则cos B=A. 13B. 33C. 63D. 2236. 已知直线y=kx+3与圆x−22+y−32=4相交于M，N两点，若 MN ≥23，则k的取值范围为A. −33,33B. −13,13C. −∞,−33D. 33,+∞7. 在直角梯形ABCD中，∠A=90∘，∠B=30∘，AB=23，BC=2，点E在线段CD上，若AE=AD+μAB，则μ的取值范围是A. 0,1B. 0,C. 0,12D. 12,28. 定义max a,b=a,a≥b,b,a<b，设实数x，y满足约束条件x ≤2,y≤2，则z=max4x+y,3x−y的取值范围是A. −6,10B. −7,10C. −6,8D. −7,8二、填空题（共6小题；共30分）9. 若函数f x为奇函数，且当x≥0时，f x=x2+x，则f−2的值为．10. 一个几何体的三视图如图所示，则该几何体的体积为．11. 若点P4,4为抛物线y2=2px上一点，则抛物线焦点坐标为；点P到抛物线的焦点的距离为．12. 函数y=x+1−x的最大值为．13. 如图，已知点A0,14，点p x0,y0x0>0在曲线y=x2上，若阴影部分面积与△OAP面积相等，则x0=．14. 设等差数列a n满足：公差d∈N∗，对任意n∈N∗，有a n∈N∗，且a n中任意两项之和也是该数列中的一项．①若a1=1，则d=；②若a1=25，则d的所有可能取值之和为．三、解答题（共6小题；共78分）15. 已知函数f x=23sin x cos x−2sin2x+1．（1）求fπ12；（2）求f x在区间0,π2上的最大值和最小值．16. 已知a n是公差大于0的等差数列，且满足a3a5=45，a2+a6=14．（1）求数列a n的通项公式；（2）若数列b n满足：b12+b22+⋯+b n2=a n+1n∈N∗，求数列b n的前n项和．17. 如图，在三棱柱ABC−A1B1C1中，B1B⊥平面A1B1C1，AC=CB=CC1=2，∠ACB=90∘，D，E分别是A1B1，CC1的中点．（1）求证：C1D∥平面A1BE；（2）求证：平面A1BE⊥平面AA1B1B；（3）求直线BC1与平面A1BE所成角的正弦值．18. 已知a∈R，函数f x=ln x+1x+ax．（1）当a=0时，求f x的最小值；（2）若f x在区间2,+∞上是单调函数，求a的取值范围．19. 已知椭圆x2a2+y2b2=1（a>b>0）上的点到其两焦点距离之和为4，且过点0,1．（1）求椭圆的方程；（2）O为坐标原点，斜率为k的直线过椭圆的右焦点，且与椭圆交于点A x1,y1，B x2,y2，若x1x2a +y1y2b=0，求△AOB的面积．20. 若无穷数列a n满足：（i）对任意n∈N∗，a n+a n+22≤a n+1；（ii）存在常数M，对任意n∈N∗，a n≤M，则称数列a n为“ T数列”．（1）若数列a n的通项为a n=8−2n（n∈N∗），证明：数列a n为“ T数列”；（2）若数列a n的各项均为正整数，且数列a n为“ T数列”，①证明：对任意n∈N∗，a n≤a n+1，②证明：存在n0∈N∗，数列a n0，a n0+1，a n0+2，⋯为等差数列．答案第一部分1. C2. D3. A4. C 【解析】a=3，S=3；a=5，S=15；a=7，S=105，结束循环，输出a=7．5. C【解析】根据正弦定理asin A =bsin B，得sin B=33，因为b<a，所以B<60∘，则cos B=63．6. A 【解析】圆的半径为r=2，由题可求得圆心2,3到直线y=kx+3的距离为d=1+k2，所以MN=2 r2−d2=24−4k21+k ，由 MN ≥23，解得k∈ −33,33．7. C 【解析】过C作CP AD交AB于点P，由BC=2，∠B=30∘得CP=1，即AD=1，又AB=23，所以PB=3，所以DC=3．以A点为原点建立直角坐标系如图所示，则A0,0，B 23,0，C 3,1，D0,1．设E x,1，所以由AE=AD+μAB得x,1=0,1+μ 23,0，所以x=23μ，又因为x∈0,3，所以μ∈0,12．8. B 【解析】提示：由题意等价于当 x ≤2,y≤2,x+2y≥0,时，求z=4x+y的范围；当x ≤2,y≤2,x+2y≤0,时，求z=3x−y的范围；然后再求两者的并集．第二部分9. −6【解析】由函数f x为奇函数，知f−2=−f2=−6．10. 12+π【解析】该几何体是一个长方体和一个圆柱的组合体．由三视图可知长方体的长、宽、高分别为4、3、1，圆柱的底面半径为1，高为1，故该组合体的体积为V=4×3×1+π×1×1=12+π．11. 1,0；5【解析】将点P4,4代入抛物线y2=2px，得p=2；因此，抛物线的焦点为1,0，准线方程为x=−1；故点P4,4到抛物线y2=4x的焦点的距离等于它到准线的距离，为4−−1=5．12. 2【解析】由题可知，原函数的定义域为0,1，令x=sin2θ,θ∈0,π2，则原函数化为y=sinθ+cosθ=2sin θ+π4，θ∈0,π2，故当 θ=π4 时，原函数取得最大值为 2． 13. 64【解析】由题可知，S △AOP =12⋅ OA ⋅x 0=18x 0；阴影部分面积为： x 2d x x00=13x 03；所以 18x 0=13x 03，再结合 x 0>0，解得 x 0= 64．14. 1；63【解析】①若 a m 为数列 a n 中任意一项，则 a m +1 为 a m 的下一项，结合 d ∈N ∗，知 a m +1>a m ；又任意两项之和也是该数列中的一项，所以 a m +a 1 为数列 a n 中的一项，且 a m +a 1≥a m +d ；所以 d ≤1，结合 d ∈N ∗，可知 d =1； ②在数列 a n 中任取两项 a m ，a n ；由等差数列，得 a m =a 1+ m −1 d ，a n =a 1+ n −1 d ；所以 a m +a n =2a 1+ m +n −2 d 也为数列 a n 中的一项，假设为第 t 项，则 a t =a 1+ t −1 d =2a 1+ m +n −2 d ；整理得 d t +1−m −n =25，即 d =25t +1−m−n，结合 d ，m ，n ，t 均为正整数，知 d 可取 1,2,4,8,16,32，所以 d 的所有可能取值的和为 63．第三部分15. （1）由 f x =2 3sin x cos x −2sin 2x +1= 3sin2x +cos2x ．得 f x =2sin 2x +π6 ．所以 f π12 =2sin π3= 3．（2）因为 0≤x ≤π2，所以 π6≤2x +π6≤7π6，当 2x +π6=π2 时，即 x =π6 时，函数 f x 在区间 0,π2 上的最大值为 2．当 2x +π6=7π6时，即 x =π2 时，函数 f x 在区间 0,π2 上的最小值为 −1．16. （1）设等差数列 a n 的公差为 d ，则依题意设 d >0．由 a 2+a 4=14，可得 a 4=7．由 a 3a 5=45，得 7−d 7+d =45，可得 d =2．所以 a 1=7−3d =1．可得 a n =2n −1．（2）设 c n =bn 2n ，则 c 1+c 2+⋯+c n =a n +1．即 c 1+c 2+⋯+c n =2n ．可得 c 1=2，且 c 1+c 2+⋯+c n−1=2 n −1 ．所以c n=2n∈N∗．所以b n=2n+1．所以数列b n是首项为4，公比为2的等比数列．所以数列b n的前n项和S n=41−2n1−2=2n+2−4．17. （1）取AB的中点F，连接DF，交A1B于点M，可知M为DF中点，连接EM．易知四边形C1DME为平行四边形，所以C1D∥EM．又C1D⊄平面A1BE，EM⊂平面A1BE，所以C1D∥平面A1BE．（2）因为A1C1=C1B1，且D是A1B1的中点，所以C1D⊥A1B1，因为BB1⊥平面A1B1C1，所以BB1⊥C1D，所以C1D⊥平面AA1B1B．又C1D∥EM，所以EM⊥平面AA1B1B．又EM⊂平面A1BE，所以平面A1BE⊥平面AA1B1B．（3）如图建立空间直角坐标系C−xyz，则B0,2,0，C10,0,2，E0,0,1，A12,0,2．BC1=0,−2,2，EA1=2,0,1，EB=0,2,−1，设平面A1BE的法向量为n=x,y,z，则EA1⋅n=0,EB⋅n=0,所以2x+z=0,2y−z=0,令x=1．则n=1,−1,−2．设向量n与BC1的夹角为θ．则cosθ=BC1⋅nBC1⋅ n =−36，所以直线BC1与平面A1BE所成角的正弦值为36．18. （1）当a=0时，f x=ln x+1x （x>0），fʹx=1x−1x2=x−1x2．所以，当0<x<1时，fʹx<0；当x>1时，fʹx>0．所以，当x=1时，函数有最小值f1=1．（2）fʹx=1x −1x+a=ax2+x−1x．当a≥0时，ax2+x−1在x∈2,+∞上恒大于零，即fʹx>0，符合要求．当a<0时，要使f x在区间2,+∞上是单调函数，当且仅当x∈2,+∞时，ax2+x−1≤0恒成立，即a≤1−xx恒成立．设g x=1−xx ，则gʹx=x−2x，又x∈2,+∞，所以gʹx≥0，即g x在区间2,+∞上为增函数，g x的最小值为g2=−14，所以a≤−14．综上，a的取值范围是a≤−14或a≥0．19. （1）依题意有a=2，b=1，故椭圆方程为x24+y2=1．（2）因为直线AB过右焦点3,0，设直线AB的方程为y=k x−3．联立方程组x24+y2=1,y=k x−3,消去y并整理得4k2+1x2−83k2x+12k2−4=0. ⋯⋯①故x1+x2=83k22,x1x2=12k2−42,又x1x2a2+y1y2b2=0，即x1x24+y1y2=0．所以3k2−14k+1+−k24k+1=0，可得k2=12，即k=±22．方程①可化为3x2−43x+2=0，由 AB =1+k2x1−x2，可得 AB =2，原点O到直线AB 的距离d=3kk2+1=1．所以S△AOB=12AB ⋅d=1．20. （1）由a n=8−2n，可得a n+2=8−2n+2，a n+1=8−2n+1，所以a n+a n+2−2a n+1=8−2n+8−2n+2−28−2n+1=−2n<0，所以对任意n∈N∗，a n+a n+22≤a n+1．又数列a n为递减数列，所以对任意n∈N∗，a n≤a1=6．所以数列a n为“ T数列”．（2）①假设存在正整数k，使得a k>a k+1，由数列a n的各项均为正整数，可得a k≥a k+1+1．由a k+a k+22≤a k+1，可得a k+2≤2a k+1−a k≤2a k−1−a k=a k−2．且a k+2≤2a k+1−a k<2a k+1−a k+1=a k+1．同理a k+3≤a k+1−2≤a k−3．依此类推，可得，对任意n∈N∗，有a k+n≤a k−n．因为a k为正整数，设a k=m，则m∈N∗．在a k+n≤a k−n中，设n=m，则a k+m≤0．与数列a n的各项均为正整数矛盾．所以，对任意n∈N∗，a n≤a n+1．②因为数列a n为“ T数列”，所以，存在常数M，对任意n∈N∗，a n≤M．不妨设M∈N∗（否则可取比M大的一个正整数M0，对任意n∈N∗，a n≤M0）．由①可知，对任意n∈N∗，a n≤a n+1，则a1≤a2≤a3≤⋯≤a n≤a n+1≤⋯．若a n=a n+1，则a n+1−a n=0；若a n<a n+1，则a n+1−a n≥1．而n≥2时，有a n=a1+a2−a1+a3−a2+⋯+a n−a n−1．所以a1，a2−a1，a3−a2，⋯，a n−a n−1，⋯，中最多有M个大于或等于1，否则与a n≤M矛盾．所以，存在n0∈N∗，对任意的n>n0，有a n−a n−1=0．所以，对任意n∈N∗，a n0+n −a n0+n−1=0．所以，存在n0∈N∗，数列a n0，a n0+1，a n0+2，⋯为等差数列．。

北京市东城区2014届高三上学期期末统一检测英语试题

北京市东城区2014届高三上学期期末统一检测英语试题高考英语2014-01-07 1957给大家推荐一份好资料">北京市东城区2014届高三上学期期末统一检测试题东城区2014—2014学年度第一学期期末教学统一检测英语试卷 2014.1本试卷共14页，共150分。

考试时长120分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

考试结束后，将本试卷和答题卡一并交回。

第一部分：听力理解（共三节，30分）第一节（共5小题；每小题1.5分，共7.5分）听下面5段对话或独白。

每段对话或独白后有一道小题，从每题所给的A、B、C三个选项中选出最佳选项。

听完每段对话或独白后，你将有2014秒钟的时间来回答有关小题和阅读下一小题。

每段对话或独白你将听一遍。

例：What is the man going to read?A．A newspaper.B．A magazine.C．A book.答案是A。

1. What sport does the man like?A. Swimming.B.Tennis. C. Skating.2. Where are the speakers?A. In a supermarket.B. In a postoffice. C. At a ticket office.3. What is the man going to do?A. To take a flight.B. To see a friend off.C. To make a telephone call.4. Why is the announcement made?A. To advertise the “Crocodile” brand.B. To find the owner of a wallet.C. To welcome people to Java Mall.5. What does the woman suggest?A. They come to work earlier.B. They get more work done.C. They share one car to work.第二节（共2014小题；每小题1.5分，共15分）听下面4段对话或独白。

北京市东城区2013届高三上学期期末教学统一检测数学文试题

北京市东城区2013届高三上学期期末教学统一检测数学文试题学校_____________班级_______________姓名______________考号___________本试卷分第Ⅰ卷和第Ⅱ卷两部分，第Ⅰ卷1至2页，第Ⅱ卷3至5页，共150分。

考试时长120分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

考试结束后，将本试卷和答题卡一并交回。

第Ⅰ卷（选择题共40分）一、本大题共8小题，每小题5分，共40分。

在每小题列出的四个选项中，选出符合题目要求的一项。

（1）设集合{1,2,3,4,5}U =，{1,2,3}A =，{2,3,4}B =，则()U AB ð等于(A) {2,3} (B) {1,4,5} (C) {4,5} (D) {1,5} （2）复数21i-等于（A ）1i -- (B) 1i -+ ( C) 1i - ( D) 1i +（3）已知{}n a 为等差数列，其前n 项和为n S ，若36a =，312S =，则公差d 等于（A ）1 （B ）53（C ）2 （D ）3 （4）执行如图所示的程序框图，输出的k 的值为（A ）4 （B ）5 （C ）6 （D ）7（5）“2230x x -->成立”是“3x >成立”的（A ）充分不必要条件（B ）必要不充分条件（C ）充要条件（D ）既不充分也不必要条件（6）已知x ，y 满足不等式组28,28,0,0,x y x y x y +≤⎧⎪+≤⎪⎨≥⎪⎪≥⎩ 则目标函数3z x y =+的最大值为(A)332 (B)12 (C)8 (D)24（7）已知抛物线22y px =的焦点F 到其准线的距离是8，抛物线的准线与x 轴的交点为K ，点A 在抛物线上且|||AK AF =，则AFK ∆的面积为（A ）32 （B ）16 （C ）8 （D ）4（8）给出下列命题：①在区间(0,)+∞上，函数1y x -=,12y x =,2(1)y x =-, 3y x =中有三个是增函数；②若log 3log 30m n <<，则01n m <<<；③若函数()f x 是奇函数，则(1)f x -的图象关于点(1,0)A 对称；④若函数()323x f x x =--，则方程()0f x =有2个实数根，其中正确命题的个数为（A ）1 （B ）2 （C ）3 （D ）4第Ⅱ卷（共110分）二、填空题：本大题共6小题，每小题5分，共30分。

东城区2013~2014学年年度第一学期期末教学统一检测

东城区2013—2014学年度第一学期期末教学统一检测英语试卷2014.1本试卷共14页，共150分。

考试时长120分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

考试结束后，将本试卷和答题卡一并交回。

第一部分：听力理解（共三节，30分）第一节（共5小题；每小题1.5分，共7.5分）听下面5段对话或独白。

每段对话或独白后有一道小题，从每题所给的A、B、C三个选项中选出最佳选项。

听完每段对话或独白后，你将有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话或独白你将听一遍。

例：What is the man going to read?A．A newspaper.B．A magazine.C．A book.答案是A。

1. What sport does the man like?A. Swimming.B. Tennis.C. Skating.2. Where are the speakers?A. In a supermarket.B. In a post office.C. At a ticket office.3. What is the man going to do?A. To take a flight.B. To see a friend off.C. To make a telephone call.4. Why is the announcement made?A. To advertise the “Crocodile” brand.B. To find the owner of a wallet.C. To welcome people to Java Mall.5. What does the woman suggest?A. They come to work earlier.B. They get more work done.C. They share one car to work.第二节（共10小题；每小题1.5分，共15分）听下面4段对话或独白。

东城区普通校2013-2014学年第一学期联考试卷答案

东城区普通校2013-2014学年第一学期联考试卷答案初三数学2013年11月第Ⅰ卷一、选择题题号 1 2 3 4 5 6 7 8 答案CADCBADC第Ⅱ卷二、填空题9、_______(6,3)--________ 10、_______10_________ 11、______内切____________ 12、_____79144或或____ 三、解答题13、解方程：24120x x +-=22214124412 4 1 (2)16 2 2 4 3 2, 6 5x x x x x x x x +=++=++=+=±∴==-解：……分……分……分……分14、解：画图……2分 9042180l ππ⋅⋅== ……5分15、解：根据题意，由勾股定理在Rt △BCO 中，第14题 M 1BC 2=BO 2+CO 2．……2分∴BC=5cm ，……3分∴圆锥形漏斗的侧面积=π•OB•BC=15πcm 2．……5分16、解：∵AD 平分BAC ∠∴CAD BAD ∠=∠ ……1分 ∵AC DE //∴CAD EDA ∠=∠ ……2分 ∴BAD EDA ∠=∠ ∴AE BD = ……3分 ∴AB ED = ……4分 ∴.5cm AB DE ==……5分 17、解：由题意得： 2334930;4mm ∆=-⋅=->……3分 ∴ 3m < ……5分四、解答题：（本大题共6小题，每小题5分，共30分）18、解：过点P 作PA ⊥y 轴，连接PN ，PQ ；∵⊙P 与x 轴相切于点Q∴PQ ⊥x 轴 ……1分 ∵M （0，2），N （0，8）∴OM=2，ON=8，MN=6 ……2分 ∵PA ⊥y 轴∴AN ＝AM ＝12MN ＝3∴PQ=5 ……3分在Rt △PAN 中，∠PAN=90°，由勾股定理得：PA ＝2222534PN AN -=-= ……4分∴P 点坐标为（4，5）． ……5分第16题第18题A19、解：画树状图得：……2分∵共有12种等可能的结果，甲抽到的牌面数字比乙大的有5种情况，小于等于乙的有7种情况，∴P （甲胜）=512 P （乙胜）=712……3分∴甲、乙获胜的机会不相同． ……4分20、(1)证明：连接OC, ∵点C 在⊙0上，OA=O ，∴∠OCA=∠OAC ， ……1分 ∵CD ⊥PA ，∴∠CDA=90°，有∠CAD+∠DCA=90°， ∵AC 平分∠PAE ， ∴∠DAC=∠CAO 。

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东城区2013—2014学年度第一学期期末教学统一检测高三物理 2014.01本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分，共120分。

考试时长100分钟。

考生务必将答案答在答题卡上，在试卷上作答无效。

第Ⅰ卷（选择题，共48分）一．单项选择题（本题共12小题，每小题4分，共48分。

每小题只有一个选项正确。

)1．已知两个质点相距为r 时，它们之间的万有引力大小为F 。

若只将它们之间的距离变为2r ，则它们之间的万有引力大小为 A ． 4F B ．2F C ．41F D ．21F 2．人站在电梯中随电梯一起运动。

一个小滑块（可视为质点）从A 点由静止开始下滑，经B 至C 点的过程中，传感器记录到的力F 随时间t 变化的关系如下面四图表示，其中可能正确的是10．为了测量蹦床运动员从蹦床上跃起的高度，探究小组设计了如下的方法：他们在蹦床的弹性网上安装压力传感器，利用传感器记录运动员在运动过程中对弹性网的压力，来推测运动员跃起的高度。

右图为某段时间内蹦床运动员的压力—时间图象。

运动员在空中仅在竖直方向上运动，且可视为质点，则可估算出运动员在这段时间内跃起的最大高度为（g 取10m/s 2）A ．1.5mB ．1. 8mC ． 5.0mD ．7.2m11．如图所示，界面MN 与水平地面之间有足够大正交的匀强磁场B 和匀强电场E ，磁感线和电场线都处在水平方向且互相垂直。

在MN 上方有一个带正电的小球由静止开始下落，经电场和磁场到达水平地面。

若不计空气阻力，小球在通过电场和磁场的过程中，下列说法中正确的是0 F /N t /s 1.1 2.3 3.8 4.9 6.9t F 0 A t F 0 B t F 0 C tF 0DABEm +q N M P b x/m1 y/cm0 4 -423 4 56a A力传感器 CBA ．小球做匀变速曲线运动B ．小球的电势能保持不变C ．洛伦兹力对小球做正功D ．小球的动能增量等于其电势能和重力势能减少量的总和12. 如图甲所示，垂直纸面向里的匀强磁场的区域宽度为2a ，磁感应强度的大小为B 。

一边长为a 、电阻为4R 的正方形均匀导线框CDEF 从图示位置开始沿x 轴正以速度v 匀速穿过磁场区域，在乙图中给出的线框E 、F 两端的电压U EF 与线框移动距离x 的关系的图象正确的是甲FyB2aED CxoBU EF3a a2 aOx4Bav43BavA3a a2aOxBav4BavU EF乙U EFCx3a a2aO-43Bav43Bav 4BavU EF3aa2a OxBavD4Bav 43Bav第Ⅱ卷（填空题、计算题，共72分）二．填空题（每小题6分，共18分）13．一小球从水平台面边缘以速度v 水平飞出，落到水平地面上需要时间为t ，落地点距台面边缘的水平距离为s 。

若使小球以速度2v 仍从同一位置水平飞出，落到水平地面上需要时间为；落地点距台面边缘的水平距离为。

14．如图所示，两条平行金属导轨ab 、cd 置于磁感应强度B =0.5T 的匀强磁场中，两导轨间的距离l =0.6m ，导轨间连有电阻R 。

金属杆MN垂直置于导轨上，且与轨道接触良好，现使金属杆MN 沿两条导轨向右匀速运动，产生的感应电动势为3V 。

由此可知，金属杆MN 滑动的速度大小为 m/s ；通过电阻R 的电流方向为（填“a R c ”或“c R a ”）。

15．如图所示，A 、B 和C 、D 为两对带电金属极板，长度均为l ，其中A 、B 两板水平放置，间距为d ，A 、B 间电压为U 1；C 、D 两板竖直放置，间距也为d ，C 、D 间电压为U 2。

有一初速度为0、质量为m 、电荷量为e 的电子经电压U 0加速后，平行于金属板进入电场，则电子进入该电场时的速度大小为；若电子在穿过电场的过程中始终未与极板相碰，电子离开该电场时的动能为_____________。

（A 、B 、C 、D 四块金属板均互不接触，电场只存在于极板间，且不计电子的重力）三．计算题（本题共5小题，共54分。

解答应有必要的文字说明、方程式和重要的演算步骤，只写出最后答案的不能得分。

有数值计算的，答案中必须写出数值和单位。

）16．（10分）如图所示，质量为m 的物体放在水平桌面上。

在水平恒力F 作用下，速度由v 1增大到v 2的过程中，发生的位移为s 。

已知物体与水平桌面的动摩擦因数为μ，重力加速度为g 。

（1）分别求出水平恒力F 和摩擦力所做的功；（2）若此过程中合外力所做的功用W 合表示，物体动能的增量用ΔE k 表示，证明W 合=ΔE k 。

F B v 1v 2F B s R cvMN la b BdvdlA CD d v B17．（10分）据人民网报道，北京时间2013年12月6日17时53分，嫦娥三号探测器成功实施近月制动，顺利进入环月轨道。

探测器环月运行轨道可视为圆轨道。

已知探测器环月运行时可忽略地球及其他天体的引力，轨道半径为r，运动周期为T，引力常量为G。

求：（1）探测器绕月运行的速度的大小；（2）探测器绕月运行的加速度的大小；（3）月球的质量。

18.（10分）有一种质谱仪的工作原理图如图所示。

静电分析器是四分之一圆弧的管腔，内有沿圆弧半径方向指向圆心O1的电场，且与圆心O1等距各点的电场强度大小相等。

磁分析器中以O2为圆心、圆心角为90°的扇形区域内，分布着方向垂直于纸面的匀强磁场，其左边界与静电分析器的右边界平行。

由离子源发出一个质量为m、电荷量为q的正离子（初速度为零，重力不计），经加速电场加速后，从M点沿垂直于该点的电场方向进入静电分析器，在静电分析器中，离子沿半径为R的四分之一圆弧做匀速圆周运动，并从N点射出静电分析器。

而后离子由P点射入磁分析器中，最后离子沿垂直于磁分析器下边界的方向从Q点射出，并进入收集器。

已知加速电场的电压为U，磁分析器中磁场的磁感应强度大小为B。

（1）请判断磁分析器中磁场的方向；（2）求静电分析器中离子运动轨迹处电场强度E的大小；（3）求磁分析器中Q点与圆心O2的距离d。

19．（12分）如图所示，有一质量为M =2kg 的平板小车静止在光滑的水平地面上，现有质量均为m =1kg 的小物块A 和B （均可视为质点），由车上P 处分别以初速度v 1=2m/s 向左和v 2=4m/s 向右运动，最终A 、B 两物块恰好停在小车两端没有脱离小车。

已知两物块与小车间的动摩擦因数都为μ=0.1，取g =10m/s 2。

求：（1）小车的长度L ；（2）A 在小车上滑动的过程中产生的热量；（3）从A 、B 开始运动计时，经5s 小车离原位置的距离。

20．（12分）在地面上方某处的真空室里存在着水平向左的匀强电场，以水平向右和竖直向上为x 轴、y 轴正方向建立如图所示的平面直角坐标系。

一质量为m 、电荷量为+q 的微粒从点P （33l ，0）由静止释放后沿直线PQ 运动。

当微粒到达点Q （0，-l ）的瞬间，撤去电场同时加上一个垂直于纸面向外的匀强磁场（图中未画出），磁感应强度的大小32m gB q l，该磁场有理想的下边界，其他方向范围无限大。

已知重力加速度为g 。

求：（1）匀强电场的场强E 的大小；（2）撤去电场加上磁场的瞬间，微粒所受合外力的大小和方向；（3）欲使微粒不从磁场下边界穿出，该磁场下边界的y 轴坐标值应满足什么条件?y xP QO A Bv 1v 2P东城区2013—2014学年度第一学期期末教学统一检测高三物理参考答案及评分标准一．单项选择题（本题共12小题，每小题4分，共48分）。

题号 1 2 3 4 5 6 7 8 9 10 11 12 答案 CACBADBADCDD第Ⅱ卷（填空题、计算题，共8题，共72分）二．填空题（每小题6分，共18分） 13．t ；2s （每空3分） 14．10；cRa （每空3分）15．meU 02；eU 0＋el 24d 2U 0 （U 12＋U 22）（每空3分）三．计算题：本题共5小题，共54分。

解答应有必要的文字说明、方程式和重要的演算步骤。

只写出最后答案的不能得分。

有数值计算的，答案中必须写出数值和单位。

16．（10分）（1）水平恒力所做的功 F W Fs=摩擦力所做的功f W mgsμ=-（2）物体在合外力作用下做匀加速直线运动，有as v v 22122=-由牛顿第二定律，合外力 F 合=ma 合外力对物体所做的功W 合=F 合s2222212111=222k v v W ma mv mv E a -=⋅=-∆合17．（10分）（1）探测器绕月运行的速度的大小Trv π2=（2）探测器绕月运行的加速度的大小 r Ta 2)2(π= （3）设月球质量为M ，嫦娥三号探测器的质量为m ，探测器运行时月球对它的万有引力提供向心力，根据万有引力定律和牛顿第二定律有r T m r GMm 22)2(π=可得 2324GTr M π= 18．（10分）解：（1）磁场方向垂直纸面向外。