D_全国各省市-河南省中牟县第一高级中学2018-2019学年高二上学期第十次双周考数学(文)试卷
河南省中牟县第一高级中学19学年高二英语上学期第十二次双周考试题(含答案).doc
河南省中牟县第一高级中学2018-2019学年高二英语上学期第十二次双周考试题第二部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项，并在答题卡上将该选项涂黑。
AAs you grow older, you’ll be faced with some challenging decisions—like whether to cut class or try cigarettes. Making decisions on your own is hard enough, but when other people get involved and try to pressure you one way or another it can be even harder. People who are your age, like your classmates, are called peers. When they try to influence how you act, to get you to do something, it’s called peer pressure.Peers can have a positive influence on each other. Maybe another student in your science class taught youan easy way to remember the planets in the solar system. Maybe you got others excited about your new favorite book, and now everyone’s reading it. These are examples of how peers positively influence each other.Sometimes peers influence each other in negative ways. For example, a few kids in school might try to get you to cut class with them; your soccer friend might try to convince you to be mean to another player and never pass him the ball.It is tough to be the only one who says “no”to peer pressure, but you can do it. Paying attention to your own feelings and beliefs about what is right and wrong can help you know the right thing to do.You’ve probably had a parent or teacher advising you to“choose your friends wisely”. Peer pressure is a big reason why they say this. If you choose friends who don’t cut class, smoke cigarettes, or lie to their parents, then youprobably won’t do these things either, even if other kids do.If you continue to face peer pressure and you’re finding it difficult to handle, talk to someone you trust. Don’t feel guilty if you’ve made a mistake or two.21. For whom is the passage most probably written?A .Students B. Parents C. Teachers D. Doctors.22. In the last three paragraphs, the author mainly_____.A．explains why friendship is so importantB．gives advice on how to deal with peer pressureC．discusses how peers influence usD．shows how to make more good friends23. Which of following may help handle peer pressure?A．Spending more time with classmates. B．Taking up more relaxing hobbies.C．Choosing friends with no bad habits. D．Helpingothers who are in trouble.24. What is the topic of the passage?A．Friendship B．Making decisionsC．Self-confidence D．Peer pressureBI hated dinner parties. But I decided to give them another shot because I’m in London. And my friend Mallery invited me. And because dinner parties in London are very different from those in New York, “I’m having a dinner party”means: “I’m booking a table for 12 at a restaurant you can’t afford and we’ll be sharing the cheque evenly, no matter what you eat.”Worse, in Manhattan there is always someone who leaves before the bill arrives. They’ll throw down cash, half of what they owe, and then people like me, who don’t drink, end up paying even more. But if I try to use the same trick, the hostess will shout; “Where are you going?”And it’s notlike I can say I have somewhere to go: everyone knows I have nowhere to go.But in London, dinner parties are in people’s homes. Not only that, the guests are an interesting mix. The last time I went to one, the guests were from France, India, Denmark and Nigeria; it was like a gathering at the United Nations. In New York, the mix is less striking. It’s like a gathering at Bloomingdale’s , a well-known department store.For New Yorkers, talking about other parts of the world means Brooklyn and Queens in New Yorkers. But at Mallery’s, when I said that I had been to Myanmar recently, people knew where it was. In New York people would think it was a usual club.25. What does the word “shot”in Paragraph 1 probably mean?A. choiceB. tryC. styleD. goal26. What does the writer dislike most about dinner parties in New Yorkers?A. There is a strange mix of people.B. The restaurants are expensive.C. The bill is not fairly shared.D. People have to pay cash27. What does the author think of the parties in London?A. A bit unusualB. Full of tricksC. Less costlyD. More interesting28. What is the author’s opinion of some New Yorkers from her experience?A. Easy-goingB. Self-centred.C. GenerousD. ConservativeCHere is an astonishing and significant fact: Mentalwork alone can’t make us tired. It sounds absurd. But a few years ago, scientists tried to find out how long the human could labor without reaching a stage of fatigue(疲劳). To the amazement of these scientists, they discovered that blood passing through the brain, when it is active, shows no fatigue at all! If we took a drop of blood from a day labourer, we could find it full of fatigue toxins(毒素) and fatigue products. But if we took blood from the brain of Albert Einstein, it would show no fatigue toxins at the end of the day.So far as the brain is concerned, it can work as well and swiftly at the end of eight or even twelve hours of efforts as at the beginning. The brain is totally tireless. So what makes us tired.Some scientists declare that most of our fatigue come from our mental and emotional(情感的) attitudes. One of England’s most outstanding scientists J. A. Hadfield,says, “The greater part of the fatigue from which we suffer is of mental origin. In fact, fatigue of purely physical origin is rare.”Dr. Brill, a famous American scientist, goes even further. He declares, “One hundred percent of the fatigue of a sitting worker in good health is due to emotional problems.”What kinds of emotions make sitting workers tired? Joy? Satisfaction? No! A feeling of being bored, anger, anxiety, tenseness, worry, a feeling of not being appreciated---those are emotions that tire sitting workers. Hard work by itself seldom causes fatigue. We get tired because our emotions produce nervousness in the body.29.What surprised the scientists a few years ago?A. Fatigue toxins could hardly be found in a labour’s blood.B. Albert Einstein didn’t feel worn out after a day’s work.C. The brain could work for many hours without fatigue.D. A mental worker’s blood was filled with fatigue toxins.30. According to the author, which of the following can make sitting worker tired？A．Challenging mental work. B．Unpleasant emotions.C．Endless tasks. D．Physical labor.31. What’s the author’s attitude towards the scientists’ideas?A．He agrees with them. B．He doubts them.C．He argues against them. D．He hesitates to accept them.32. We can infer from the passage that in order to stay energeic, sitting workers need to ______.A．have some good blood B．enjoy their workC．exercise regularly D．discover fatigue toxinD“Indeed,”George Washington wrote in his diary in 1785, “some kind of fly, or bug, had begun to eat the leaves before I left home.”But the father of America was not the father of bug. When Washington wrote that, Englishmen had been referring to insects as bugs for more than a century, and Americans had already created lightning-bug(萤火虫). But the English were soon to stop using the bugs in their language, leaving it to the Americans to call a bug a bug in the nineteenth and twentieth centuries.The American bug could also be a person, referring to someone who was crazy about a particular activity. Although fan became the usual term, sports fans used tobe called racing bugs, baseball bugs, and the like.Or the bug could be a small machine or object, for example, a bug-shaped car. The bug could also be a burglar alarm, from which comes the expression to bug, that is, “to install (安装) an alarm”. Now it means a small piece of equipment that people use for listening secretly to others’conversation. Since the 1840s, to bug has long meant “to cheat”, and since the 1940s it has been annoying.We also know the bug as a flaw in a computer program or other design. That meaning dates back to the time of Thomas Edison. In 1878 he explained bugs as “little problems and difficulties”that required months of study and labor to overcome in developing a successful product. In 1889 it was recorded that Edison “had been up the two previous nights discovering ‘a bug’in his invented record player.”33. We learn from Paragraph 1 that ________.A. Americans had difficulty in learning to use the word bugB. George Washington was the first person to call an insect a bugC. the word bug was still popularly used in English in the nineteenth centuryD. both Englishman and Americans used the word bug in the eighteenth century34. What does the word “flaw”in the last paragraph probably mean________.A. Explanation.B. Finding.C. Origin.D. Fault.35. The passage is mainly concerned with________.A. the misunderstanding of the word bugB. the development of the word bugC. the public views of the word bugD. the special characteristics of the word bug第二节（共5小题：每小题2分，满分10分）根据短文内容,从短文后的七个选项中选出能填入空白处的最佳选项.选项中有两项为多余选项。
河南省中牟县第一高级中学2018-2019学年高二上学期第十次双周考生物试卷
2018--2019学年第十次生物周测试题出题人：王丛孙玉旺审题人：梁亚楠刘娜一、选择题（共30题，每题2分，共60分）1.假说﹣演绎法是现代科学研究中常用的一种科学方法，下列属于孟德尔在发现分离定律时“演绎”过程的是（）A．生物的性状是由遗传因子决定的B．由F出现了“3：1”推测生物体产生配子时，成对遗传因子彼此分离2产生配子时成对遗传因子分离，则测交后代会出现两种性状的比接近1：C．若F11D．通过测交实验证明测交后代出现两种性状的比接近1：1中高茎和矮茎的比为787:277,上述实2.在豌豆杂交实验中,高茎与矮茎杂交,F2验结果出现的根本原因是( )自交,后代出现性状分离A.显性遗传因子对隐性遗传因子有显性作用 B.F1C.雌雄配子的结合是随机的产生配子时,显性遗传因子和隐性遗传因子彼此分离D.F13.丈夫的哥哥患有半乳糖血病(一种常染色体隐性遗传病)，妻子的外祖母也有此病，家庭的其他成员均无此病。
经调查，妻子的父亲可以视为基因型纯合。
可以预测，这对夫妻的儿子患半乳糖血病的概率是 ( )A．1/12 B．1/4 C．3/8 D．1/24.在完全显性及每对基因独立遗传的条件下,AaBbCC与aaBbcc进行杂交,其子一代中表现型与双亲相同的个体占全部子代的( )A. 1/4B. 3/8C. 5/8D. 3/45.牡丹的花色种类多种多样，其中白色的不含花青素，深红色的含花青素最多，花青素含量的多少决定着花瓣颜色的深浅，由两对独立遗传的基因(A和a，B和b)所控制；显性基因A和B可以使花青素含量增加，两者增加的量相等，并且可以累加。
若一深红色牡丹与一白色牡丹杂交，就能得到中等红色的个体，若这些个体自交，其子代将出现的花色种类和比例分别是( )A． 3种，9∶6∶1 B． 4种，9∶3∶3∶1C． 5种，1∶4∶6∶4∶1 D． 6种，1∶4∶3∶3∶4∶16.某二倍体生物处于正常细胞分裂后期的某细胞内含有10条染色体。
中牟县第一高级中学2018-2019学年高二上学期数学期末模拟试卷含解析
中牟县第一高级中学2018-2019学年高二上学期数学期末模拟试卷含解析班级__________ 座号_____ 姓名__________ 分数__________一、选择题1． 某班设计了一个八边形的班徽（如图），它由腰长为1，顶角为α的四个等腰三角形，及其底边构成的正方形所组成，该八边形的面积为（）A ．2sin 2cos 2αα-+ B．sin 3αα-+C. 3sin 1αα+ D ．2sin cos 1αα-+2． 设集合A={x||x ﹣2|≤2，x ∈R}，B={y|y=﹣x 2，﹣1≤x ≤2}，则∁R （A ∩B ）等于（）A ．RB ．{x|x ∈R ，x ≠0}C ．{0}D ．∅3． 在等差数列中，，公差，为的前项和.若向量，，{}n a 11a =0d ≠n S {}n a n 13(,)m a a =133(,)n a a=-且，则的最小值为（ ）0m n ×=2163n n S a ++A ． B ．C ．D ．43292【命题意图】本题考查等差数列的性质，等差数列的前项和，向量的数量积，基本不等式等基础知识，意在n 考查学生的学生运算能力，观察分析，解决问题的能力．4． 双曲线=1（m ∈Z ）的离心率为（）A ．B ．2C ．D ．35． i 是虚数单位，计算i+i 2+i 3=（）A ．﹣1B ．1C ．﹣iD ．i6． 已知集合M={x|x 2＜1}，N={x|x ＞0}，则M ∩N=（）A ．∅B ．{x|x ＞0}C ．{x|x ＜1}D ．{x|0＜x ＜1}可．7． 已知命题p ：“∀∈[1，e]，a ＞lnx ”，命题q ：“∃x ∈R ，x 2﹣4x+a=0””若“p ∧q ”是真命题，则实数a 的取值范围是（）A ．（1，4]B ．（0，1]C ．[﹣1，1]D ．（4，+∞）8． 设函数f ′（x ）是奇函数f （x ）（x ∈R ）的导函数，f （﹣2）=0，当x ＞0时，xf ′（x ）﹣f （x ）＜0，则使得f （x ）＞0成立的x 的取值范围是（ ）A ．（﹣∞，﹣2）∪（0，2）B ．（﹣∞，﹣2）∪（2，+∞）C ．（﹣2，0）∪（2，+∞）D ．（﹣2，0）∪（0，2）9． 设等差数列{a n }的前n 项和为S n ，已知S 4=﹣2，S 5=0，则S 6=（ ）A ．0B ．1C ．2D ．310．设1m >，在约束条件,,1.y x y mx x y ≥⎧⎪≤⎨⎪+≤⎩下，目标函数z x my =+的最大值小于2，则m 的取值范围为（）A．(1,1+B．(1)++∞ C. (1,3)D ．(3,)+∞11．已知是球的球面上两点，，为该球面上的动点，若三棱锥体积的最大,A B O 60AOB ∠=︒C O ABC -值为，则球的体积为（）O A ． B ． C ． D ．81π128π144π288π【命题意图】本题考查棱锥、球的体积、球的性质，意在考查空间想象能力、逻辑推理能力、方程思想、运算求解能力．12．设f （x ）在定义域内可导，y=f （x ）的图象如图所示，则导函数y=f ′（x ）的图象可能是（）A ．B ．C ．D ．二、填空题13．如果定义在R 上的函数f （x ），对任意x 1≠x 2都有x 1f （x 1）+x 2f （x 2）＞x 1f （x 2）+x 2（fx 1），则称函数为“H 函数”，给出下列函数①f （x ）=3x+1 ②f （x ）=（）x+1③f （x ）=x 2+1④f （x ）=其中是“H 函数”的有 （填序号） 14．过椭圆+=1（a ＞b ＞0）的左焦点F 1作x 轴的垂线交椭圆于点P ，F 2为右焦点，若∠F 1PF 2=60°，则椭圆的离心率为 ． 15．如图，P 是直线x ＋y －5＝0上的动点，过P 作圆C ：x 2＋y 2－2x ＋4y －4＝0的两切线、切点分别为A 、B ，当四边形PACB 的周长最小时，△ABC 的面积为________．16．设m 是实数，若x ∈R 时，不等式|x ﹣m|﹣|x ﹣1|≤1恒成立，则m 的取值范围是 ．17．【盐城中学2018届高三上第一次阶段性考试】已知函数有两个极值点，则实数的()()ln f x x x ax =-a 取值范围是．18．一个正四棱台，其上、下底面均为正方形，边长分别为2cm 和4cm ,侧棱长为2cm ,则其表面积为__________2cm .三、解答题19．（本小题满分10分）已知集合{}2131A x a x a =-<<+，集合{}14B x x =-<<．（1）若A B ⊆，求实数的取值范围；（2）是否存在实数，使得A B =？若存在，求出的值；若不存在，请说明理由．20．（本小题满分10分）已知函数.()|||2|f x x a x =++-（1）当时，求不等式的解集；3a =-()3f x ≥（2）若的解集包含，求的取值范围.()|4|f x x ≤-[1,2]21．（本小题满分12分）成都市某中学计划举办“国学”经典知识讲座.由于条件限制，按男、女生比例采取分层抽样的方法，从某班选出10人参加活动，在活动前，对所选的10名同学进行了国学素养测试，这10名同学的性别和测试成绩（百分制）的茎叶图如图所示.（1）根据这10名同学的测试成绩，分别估计该班男、女生国学素养测试的平均成绩；（2）若从这10名同学中随机选取一男一女两名同学，求这两名同学的国学素养测试成绩均为优良的概率.（注：成绩大于等于75分为优良）22．（本题12分）已知数列{}n x 的首项13x =，通项2n n x p nq =+（*n N ∈，p ，为常数），且145x x x ，，成等差数列，求：（1）p q ，的值；（2）数列{}n x 前项和n S 的公式.23．如图，已知五面体ABCDE ，其中△ABC 内接于圆O ，AB 是圆O 的直径，四边形DCBE 为平行四边形，且DC ⊥平面ABC ．（Ⅰ）证明：AD ⊥BC（Ⅱ）若AB=4，BC=2，且二面角A ﹣BD ﹣C 所成角θ的正切值是2，试求该几何体ABCDE 的体积．24．设函数．（Ⅰ）求函数的最小正周期；（Ⅱ）求函数在上的最大值与最小值．中牟县第一高级中学2018-2019学年高二上学期数学期末模拟试卷含解析（参考答案）一、选择题1． 【答案】A 【解析】试题分析：利用余弦定理求出正方形面积()ααcos 22cos 2-11221-=+=S ；利用三角形知识得出四个等腰三角形面积ααsin 2sin 112142=⨯⨯⨯⨯=S ；故八边形面积2cos 2sin 221+-=+=ααS S S .故本题正确答案为A.考点：余弦定理和三角形面积的求解.【方法点晴】本题是一道关于三角函数在几何中的应用的题目，掌握正余弦定理是解题的关键；首先根据三角形面积公式ααsin 21sin 1121=⨯⨯⨯=S 求出个三角形的面积αsin 24=S ；接下来利用余弦定理可求出正方形的边长的平方()αcos 2-1122+，进而得到正方形的面积()ααcos 22cos 2-11221-=+=S ，最后得到答案.2． 【答案】B【解析】解：A=[0，4]，B=[﹣4，0]，所以A ∩B={0}，∁R （A ∩B ）={x|x ∈R ，x ≠0}，故选B ． 3． 【答案】A【解析】4． 【答案】B【解析】解：由题意，m 2﹣4＜0且m ≠0，∵m ∈Z ，∴m=1∵双曲线的方程是y 2﹣x 2=1∴a 2=1，b 2=3，∴c 2=a 2+b 2=4∴a=1，c=2，∴离心率为e==2．故选：B．【点评】本题的考点是双曲线的简单性质，考查由双曲线的方程求三参数，考查双曲线中三参数的关系：c2=a2+b2．5．【答案】A【解析】解：由复数性质知：i2=﹣1故i+i2+i3=i+（﹣1）+（﹣i）=﹣1故选A【点评】本题考查复数幂的运算，是基础题．6．【答案】D【解析】解：由已知M={x|﹣1＜x＜1}，N={x|x＞0}，则M∩N={x|0＜x＜1}，故选D．【点评】此题是基础题．本题属于以不等式为依托，求集合的交集的基础题，7．【答案】A【解析】解：若命题p：“∀∈[1，e]，a＞lnx，为真命题，则a＞lne=1，若命题q：“∃x∈R，x2﹣4x+a=0”为真命题，则△=16﹣4a≥0，解得a≤4，若命题“p∧q”为真命题，则p，q都是真命题，则，解得：1＜a≤4．故实数a的取值范围为（1，4]．故选：A．【点评】本题主要考查复合命题与简单命题之间的关系，利用条件先求出命题p，q的等价条件是解决本题的关键．8．【答案】A【解析】解：设g（x）=，则g（x）的导数为：g′（x）=，∵当x＞0时总有xf′（x）﹣f（x）＜0成立，即当x＞0时，g′（x）＜0，∴当x＞0时，函数g（x）为减函数，又∵g（﹣x）====g（x），∴函数g（x）为定义域上的偶函数，∴x＜0时，函数g（x）是增函数，又∵g（﹣2）==0=g（2），∴x＞0时，由f（x）＞0，得：g（x）＜g（2），解得：0＜x＜2，x＜0时，由f（x）＞0，得：g（x）＞g（﹣2），解得：x＜﹣2，∴f（x）＞0成立的x的取值范围是：（﹣∞，﹣2）∪（0，2）．故选：A．9．【答案】D【解析】解：设等差数列{a n}的公差为d，则S4=4a1+d=﹣2，S5=5a1+d=0，联立解得，∴S6=6a1+d=3故选：D【点评】本题考查等差数列的求和公式，得出数列的首项和公差是解决问题的关键，属基础题． 10．【答案】A【解析】考点：线性规划.【方法点晴】本题是一道关于线性规划求最值的题目，采用线性规划的知识进行求解；关键是弄清楚的几何意义直线z x my =+截距为zm，作0my x :L =+,向可行域内平移,越向上,则的值越大,从而可得当直线直线z x my =+过点A 时取最大值，⎩⎨⎧==+00001mx y y x 可求得点A 的坐标可求的最大值,然后由z 2,>解不等式可求m 的范围.11．【答案】D【解析】当平面平面时，三棱锥的体积最大，且此时为球的半径．设球的半径为OC ⊥AOB O ABC -OC，则由题意，得，解得，所以球的体积为，故选D ．R 211sin 6032R R ⨯⨯︒⋅=6R =342883R π=π12．【答案】D【解析】解：根据函数与导数的关系：可知，当f ′（x ）≥0时，函数f （x ）单调递增；当f ′（x ）＜0时，函数f （x ）单调递减结合函数y=f （x ）的图象可知，当x ＜0时，函数f （x ）单调递减，则f ′（x ）＜0，排除选项A ，C 当x ＞0时，函数f （x ）先单调递增，则f ′（x ）≥0，排除选项B故选D【点评】本题主要考查了利用函数与函数的导数的关系判断函数的图象，属于基础试题二、填空题13．【答案】 ①④ 【解析】解：∵对于任意给定的不等实数x 1，x 2，不等式x 1f （x 1）+x 2f （x 2）≥x 1f （x 2）+x 2f （x 1）恒成立，∴不等式等价为（x 1﹣x 2）[f （x 1）﹣f （x 2）]≥0恒成立，即函数f （x ）是定义在R 上的不减函数（即无递减区间）；①f （x ）在R 递增，符合题意；②f （x ）在R 递减，不合题意；③f （x ）在（﹣∞，0）递减，在（0，+∞）递增，不合题意；④f （x ）在R 递增，符合题意；故答案为：①④．14．【答案】 ． 【解析】解：由题意知点P 的坐标为（﹣c ，）或（﹣c ，﹣），∵∠F 1PF 2=60°，∴=，即2ac=b 2=（a 2﹣c 2）．∴e 2+2e ﹣=0，∴e=或e=﹣（舍去）．故答案为：．【点评】本题主要考查了椭圆的简单性质，考查了考生综合运用椭圆的基础知识和分析推理的能力，属基础题．15．【答案】【解析】解析：圆x 2＋y 2－2x ＋4y －4＝0的标准方程为（x －1）2＋（y ＋2）2＝9.圆心C （1，－2），半径为3，连接PC ，∴四边形PACB 的周长为2（PA ＋AC ）＝2＋2AC ＝2＋6.PC 2－AC 2PC 2－9当PC 最小时，四边形PACB 的周长最小．此时PC ⊥l .∴直线PC 的斜率为1，即x －y －3＝0，由，解得点P 的坐标为（4，1），{x ＋y －5＝0x －y －3＝0)由于圆C 的圆心为（1，－2），半径为3，所以两切线PA ，PB 分别与x 轴平行和y 轴平行，即∠ACB ＝90°，∴S △ABC ＝AC ·BC ＝×3×3＝.121292即△ABC 的面积为.92答案：9216．【答案】 [0，2] ．【解析】解：∵|x ﹣m|﹣|x ﹣1|≤|（x ﹣m ）﹣（x ﹣1）|=|m ﹣1|，故由不等式|x ﹣m|﹣|x ﹣1|≤1恒成立，可得|m ﹣1|≤1，∴﹣1≤m ﹣1≤1，求得0≤m ≤2，故答案为：[0，2]．【点评】本题主要考查绝对值三角不等式，绝对值不等式的解法，函数的恒成立问题，体现了转化的数学思想，属于基础题．17．【答案】.【解析】由题意,y ′=ln x +1−2mx令f ′（x ）=ln x −2mx +1=0得ln x =2mx −1，函数有两个极值点,等价于f ′（x ）=ln x −2mx +1有两个零点，()()ln f x x x mx =-等价于函数y =ln x 与y =2mx −1的图象有两个交点，，当m =时，直线y =2mx −1与y =ln x 的图象相切，12由图可知,当0<m <时，y =ln x 与y =2mx −1的图象有两个交点，12则实数m 的取值范围是（0,），12故答案为：（0,）.1218．【答案】20+【解析】考点：棱台的表面积的求解.三、解答题19．【答案】（1）[](2]01a ∈-∞- ，，；（2）不存在实数，使A B =．【解析】试题分析：（1）对集合A 可以分为A =∅或A ≠∅两种情况来讨论；（2）先假设存在实数，使A B =，则必有21103141a a a a -=-=⎧⎧⇒⎨⎨+==⎩⎩，无解．考点：集合基本运算.20．【答案】（1）或；（2）.{|1x x ≤8}x ≥[3,0]-【解析】试题解析：（1）当时，，当时，由得，解得；3a =-25,2()1,2325,3x x f x x x x -+≤⎧⎪=<<⎨⎪-≥⎩2x ≤()3f x ≥253x -+≥1x ≤当时，，无解；当时，由得，解得，∴的解集为23x <<()3f x ≥3x ≥()3f x ≥253x -≥8x ≥()3f x ≥或.{|1x x ≤8}x ≥（2），当时，，()|4||4||2|||f x x x x x a ≤-⇔---≥+[1,2]x ∈|||4|422x a x x x +≤-=-+-=∴，有条件得且，即，故满足条件的的取值范围为.22a x a --≤≤-21a --≤22a -≥30a -≤≤[3,0]-考点：1、绝对值不等式的解法；2、不等式恒成立问题.21．【答案】【解析】【命题意图】本题考查茎叶图的制作与读取，古典概型的概率计算，是概率统计的基本题型，解答的关键是应用相关数据进行准确计算，是中档题.22．【答案】（1）1,1==q p ；（2）2)1(221++-=-n n S n n .考点：等差，等比数列通项公式，数列求和.23．【答案】【解析】（Ⅰ）证明：∵AB是圆O的直径，∴AC⊥BC，又∵DC⊥平面ABC∴DC⊥BC，又AC∩CD=C，∴BC⊥平面ACD，又AD⊂平面ACD，∴AD⊥BC．（Ⅱ）解：设CD=a，以CB，CA，CD所在直线分别为x轴，y轴，z轴，建立空间直角坐标系，如图所示．则C（0，0，0），B（2，0，0），，D（0，0，a）．由（Ⅰ）可得，AC⊥平面BCD，∴平面BCD的一个法向量是=，设=（x，y，z）为平面ABD的一个法向量，由条件得，=，=（﹣2，0，a）．∴即，不妨令x=1，则y=，z=，∴=．又二面角A﹣BD﹣C所成角θ的正切值是2，∴．∴=cosθ=，∴==，解得a=2．∴V ABCDE=V E﹣ADC+V E﹣ABC=+=+==8．∴该几何体ABCDE的体积是8．【点评】本题考查了向量相互垂直与数量积的关系证明线面垂直、利用法向量的夹角求出二面角的方法、三棱锥的体积计算公式，考查了空间想象能力，考查了推理能力与计算能力，属于难题．24．【答案】【解析】【知识点】三角函数的图像与性质恒等变换综合【试题解析】（Ⅰ）因为．所以函数的最小正周期为．（Ⅱ）由（Ⅰ），得．因为，所以，所以．所以．且当时，取到最大值；当时，取到最小值．。
中牟县第一高级中学2018-2019学年上学期高二数学12月月考试题含答案
中牟县第一高级中学2018-2019学年上学期高二数学12月月考试题含答案班级__________ 座号_____ 姓名__________ 分数__________一、选择题1． 设F 1，F 2为椭圆=1的两个焦点，点P 在椭圆上，若线段PF 1的中点在y 轴上，则的值为（）A ．B ．C ．D ．2． 已知函数f （x ）=x （1+a|x|）．设关于x 的不等式f （x+a ）＜f （x ）的解集为A ，若，则实数a 的取值范围是（ ）A ．B ．C ．D ．3． 函数y=2|x|的定义域为[a ，b]，值域为[1，16]，当a 变动时，函数b=g （a ）的图象可以是（）A ．B ．C ．D ．4． 在中，，，，则等于（ ）ABC ∆b =3c =30B =A B ．C D ．25． 现准备将7台型号相同的健身设备全部分配给5个不同的社区，其中甲、乙两个社区每个社区至少2台，其它社区允许1台也没有，则不同的分配方案共有（ ）A ．27种B ．35种C ．29种D ．125种6． 圆上的点到直线的距离最大值是（ ）012222=+--+y x y x 2=-y x A ．B ．C ．D ．12+122+122+7． 已知函数f （x ）=1+x ﹣+﹣+…+，则下列结论正确的是（ ）A ．f （x ）在（0，1）上恰有一个零点B ．f （x ）在（﹣1，0）上恰有一个零点C ．f （x ）在（0，1）上恰有两个零点D ．f （x ）在（﹣1，0）上恰有两个零点8． 已知集合A={x|﹣1≤x ≤1}，B={x|x 2﹣2x ≤0}，则A ∪B=（ ）A ．{x|﹣1≤x ≤2}B ．{x|﹣1≤x ≤0}C ．{x|1≤x ≤2}D ．{x|0≤x ≤1}9． 定义在R 上的偶函数在[0，7]上是增函数，在[7，+∞）上是减函数，又f （7）=6，则f （x ）（ ）A ．在[﹣7，0]上是增函数，且最大值是6B ．在[﹣7，0]上是增函数，且最小值是6C ．在[﹣7，0]上是减函数，且最小值是6D ．在[﹣7，0]上是减函数，且最大值是610．已知命题且是单调增函数；命题，.:()(0xp f x a a =>1)a ≠5:(,44q x ππ∀∈sin cos x x >则下列命题为真命题的是（ ）A ．B ．C. D ．p q ∧p q ∨⌝p q ⌝∧⌝p q⌝∧11．已知直线 a A 平面α，直线b ⊆平面α，则（ ）A ．B ．与异面C ．与相交D ．与无公共点a b A 12．已知函数f(x)是定义在R 上的奇函数，当x ≥0时，.若,f(x-1)≤f(x),则实数a 的取值范围为A[]B[]C[]D[]二、填空题13．当下社会热议中国人口政策，下表是中国人民大学人口预测课题组根据我过2000年第五次人口普查预测的15﹣64岁劳动人口所占比例：年份20302035204020452050年份代号t 12345所占比例y6865626261根据上表，y 关于t 的线性回归方程为 附：回归直线的斜率和截距的最小二乘估计公式分别为： =， =﹣．14．log 3+lg25+lg4﹣7﹣（﹣9.8）0= ．15．如果实数满足等式，那么的最大值是 ．,x y ()2223x y -+=yx16．已知[2,2]a ∈-，不等式2(4)420x a x a +-+->恒成立，则的取值范围为__________.17．抛物线的准线与双曲线的两条渐近线所围成的三角形面积为__________18．定义在R 上的可导函数()f x ，已知()f x y e=′的图象如图所示，则()y f x =的增区间是 ▲ ．已知二次函数为偶函数且图象经过原点，()f x （2）设函数，其中m 为常数，求函数的最小值．()()()'g x f x f x m =+-()g x 20．【常州市2018届高三上武进区高中数学期中】已知函数，．()()221ln f x ax a x x =+--R a ∈⑴若曲线在点处的切线经过点，求实数的值；()y f x =()()1,1f ()2,11a ⑵若函数在区间上单调，求实数的取值范围；()f x ()2,3a ⑶设，若对，，使得成立，求整数的最小值．()1sin 8g x x =()10,x ∀∈+∞[]20,πx ∃∈()()122f x g x +≥a21．记函数f （x ）=log 2（2x ﹣3）的定义域为集合M ，函数g （x ）=的定义域为集合N ．求：（Ⅰ）集合M ，N ；（Ⅱ）集合M ∩N ，∁R （M ∪N ）．22．（本小题满分12分）若二次函数满足,()()20f x ax bx c a =++≠()()+12f x f x x -=且.()01f =（1）求的解析式；()f x （2）若在区间上，不等式恒成立，求实数的取值范围．[]1,1-()2f x x m >+m 23．如图所示，在四棱锥中，底面为菱形，为与的交点，平P ABCD -ABCD E AC BD PA ⊥面，为中点，为中点．ABCD M PA N BC （1）证明：直线平面；//MN ABCD（2）若点为中点，，，，求三棱锥的体积．Q PC 120BAD ∠=︒PA =1AB =A QCD -24．【南师附中2017届高三模拟一】已知是正实数，设函数.,a b ()()ln ,ln f x x x g x a x b ==-+（1）设 ，求 的单调区间；()()()h x f x g x =-()h x （2）若存在，使且成立，求的取值范围.0x 03,45a b a b x ++⎡⎤∈⎢⎥⎣⎦()()00f x g x ≤b a中牟县第一高级中学2018-2019学年上学期高二数学12月月考试题含答案（参考答案）一、选择题1．【答案】C【解析】解：F1，F2为椭圆=1的两个焦点，可得F1（﹣，0），F2（）．a=2，b=1．点P在椭圆上，若线段PF1的中点在y轴上，PF1⊥F1F2，|PF2|==，由勾股定理可得：|PF1|==．==．故选：C．【点评】本题考查椭圆的简单性质的应用，考查计算能力．2．【答案】A【解析】解：取a=﹣时，f（x）=﹣x|x|+x，∵f（x+a）＜f（x），∴（x﹣）|x﹣|+1＞x|x|，（1）x＜0时，解得﹣＜x＜0；（2）0≤x≤时，解得0；（3）x＞时，解得，综上知，a=﹣时，A=（﹣，），符合题意，排除B、D；取a=1时，f（x）=x|x|+x，∵f（x+a）＜f（x），∴（x+1）|x+1|+1＜x|x|，（1）x＜﹣1时，解得x＞0，矛盾；（2）﹣1≤x≤0，解得x＜0，矛盾；（3）x＞0时，解得x＜﹣1，矛盾；综上，a=1，A=∅，不合题意，排除C，故选A．【点评】本题考查函数的单调性、二次函数的性质、不等式等知识，考查数形结合思想、分类讨论思想，考查学生分析解决问题的能力，注意排除法在解决选择题中的应用．3．【答案】B【解析】解：根据选项可知a≤0a变动时，函数y=2|x|的定义域为[a，b]，值域为[1，16]，∴2|b|=16，b=4故选B．【点评】本题主要考查了指数函数的定义域和值域，同时考查了函数图象，属于基础题．4．【答案】C【解析】考点：余弦定理．5．【答案】B【解析】排列、组合及简单计数问题．【专题】计算题．【分析】根据题意，可将7台型号相同的健身设备看成是相同的元素，首先分给甲、乙两个社区各台设备，再将余下的三台设备任意分给五个社区，分三种情况讨论分配方案，①当三台设备都给一个社区，②当三台设备分为1和2两份分给2个社区，③当三台设备按1、1、1分成三份时分给三个社区，分别求出其分配方案数目，将其相加即可得答案．【解答】解：根据题意，7台型号相同的健身设备是相同的元素，首先要满足甲、乙两个社区至少2台，可以先分给甲、乙两个社区各2台设备，余下的三台设备任意分给五个社区，分三种情况讨论：①当三台设备都给一个社区时，有5种结果，②当三台设备分为1和2两份分给2个社区时，有2×C 52=20种结果，③当三台设备按1、1、1分成三份时分给三个社区时，有C 53=10种结果，∴不同的分配方案有5+20+10=35种结果；故选B ．【点评】本题考查分类计数原理，注意分类时做到不重不漏，其次注意型号相同的健身设备是相同的元素．6． 【答案】B 【解析】试题分析：化简为标准形式，圆上的点到直线的距离的最大值为圆心到直线的距离加半()()11122=-+-y x 径，，半径为1，所以距离的最大值是，故选B.22211=--=d 12+考点：直线与圆的位置关系 17． 【答案】B【解析】解：∵f ′（x ）=1﹣x+x 2﹣x 3+…+x 2014=（1﹣x ）（1+x 2+…+x 2012）+x 2014；∴f ′（x ）＞0在（﹣1，0）上恒成立；故f （x ）在（﹣1，0）上是增函数；又∵f （0）=1，f （﹣1）=1﹣1﹣﹣﹣…﹣＜0；故f （x ）在（﹣1，0）上恰有一个零点；故选B ．【点评】本题考查了导数的综合应用及函数零点的个数的判断，属于中档题． 8． 【答案】A【解析】解：由x 2﹣2x ≤0，解得0≤x ≤2．∴B={x|0≤x ≤2}，又集合A={x ﹣|1＜x ≤1}，∴A ∪B={x|﹣1≤x ≤2}，故选：A ． 9． 【答案】D【解析】解：∵函数在[0，7]上是增函数，在[7，+∞）上是减函数，∴函数f（x）在x=7时，函数取得最大值f（7）=6，∵函数f（x）是偶函数，∴在[﹣7，0]上是减函数，且最大值是6，故选：D10．【答案】D【解析】考点：1、指数函数与三角函数的性质；2、真值表的应用.11．【答案】D【解析】//a b试题分析：因为直线a A平面α，直线b⊆平面α，所以或与异面，故选D.考点：平面的基本性质及推论.12．【答案】B【解析】当x≥0时，f（x）=，由f（x）=x﹣3a2，x＞2a2，得f（x）＞﹣a2；当a2＜x＜2a2时，f（x）=﹣a2；由f（x）=﹣x，0≤x≤a2，得f（x）≥﹣a2。
河南省中牟县第一高级中学2018-2019学年高二上学期第十次双周考地理试卷
2018---2019学年上期高二第十次周考地理试题出题人：胡伟兰贺鹰审题人：尹银昌王鸿雁一、选择题：（每题2分，共60分）2010年5月1日，41届世界博览会在上海举行，期间约有7000万人次的游客，其中海外游客约有350万，世博会为上海创造了3100亿人民币的旅游收入。
据此答1-2题1．材料反映了现代旅游的一个特点（）A．旅游主体的大众化B．旅游空间的扩大化C．旅游形式的多样性D．旅游目的的娱乐化2．入境旅游对中国的重要意义表现为（）①回笼货币，稳定市场②增加外汇收入③平衡国际收支④促进经济发展A．①②③④B．②③④ C．①②D．②④位于山西省中部略偏南的世界文化遗产平遥古城，是中国迄今保存最为完整的明清时期的中国县城的原型，它是由完整的城墙和街巷、店铺、民居组成的大型古建筑群，有“中国古建筑的荟萃和宝库”之称。
据此完成3～5题。
3．作为旅游资源，平遥古城的（）特点对吸引旅游者起到了重要作用A．可创造性B．长存性C．非凡性D．多样性4．作为旅游资源，平遥古城有多方面的价值，其中它的（）对吸引旅游者起到了最主要的作用A．经济价值B．美学价值C．历史文化价值D．科学价值5．现在平遥古城一带存在的突出环境问题是( )A．现代基础设施的建设对部分古建筑的破坏B．滑坡C．开采煤矿对古建筑的破坏及燃煤等引起的酸雨D．水土流失下表为我国的世界文化与自然遗产，据表回答6～7题。
6.对于表中世界文化与自然遗产，叙述正确的是( )A．都位于温带季风气候区B．植被都以亚热带常绿阔叶林为主C．都位于东部季风区D．山地类型都属于褶皱山7.峨眉山—乐山大佛风景名胜区与其他名胜区相比，其发展的限制性因素是( )A．自然条件恶劣B．旅游人口众多C．交通不便，距离旅游消费市场较远D．旅游资源无特色永定土楼是典型的客家民居，它用生土夯筑而成，依山偎翠，错落有致。
土楼遍布该县的每个乡村，它们布局合理，与大自然和谐地融为一体，构成了神奇、古朴、壮观、美丽的画卷。
河南省中牟县第一高级中学2018-2019学年高二上学期第十次双周考历史---精校Word版含答案
2018-2019学年上期高二第十次周考历史试题一．选择题（每题2分，共60分）1．《礼记·礼运》认为，在“天下为公，选贤任能”的“大同”之世后，社会进入“小康”之世，其基本特点有“天下为家，各亲其亲”、“大人世及以为礼”。
这表明“小康”之世( )A ．国家统一安定B ．王权高度集中C ．实行血缘政治D ．违背历史潮流2．历史解释是以史料为依据，以历史理解为基础，对历史事物进行理性分析和评判的能力。
基于下列史料可以得出的历史解释是( )A ．封邦建国，众星拱月B ．王室衰微，诸侯兼并C ．礼崩乐坏，等级不存D ．宗法破坏，贵族内讧3．下表反映了中国古代地方管理制度演变的过程表格中①②应填入的内容是( )A ．①分封制②贵族政治B ．①宗法制②贵族政治C ．①宗法制②中央垂直管理地方D ．①分封制②中央垂直管理地方4．嬴政认为，给死去的王上谥号是子议父、臣议君，是很不合适的事情。
称帝时，他尊其父庄襄王为太上皇，并下令今后不再给死去的皇帝上“文、昭、武、惠、襄”之类的封号，“朕为始皇帝，后世以计数，二世三世至于万世，传之无穷”。
这一做法( )A ．正式终结了古代谥号制度B ．旨在确立皇帝的无上权威C ．是宗法制发展的必然趋势D ．实现了对全国的直接管辖5．“周秦之变” 是指西周到秦朝(有些方面甚至到汉武帝时期)中国社会发生的一系列深刻变化，是中国历史上第一次真正意义上的社会转型。
下列内容属于周秦之变的是A．从封建政制到帝国政制 B．从“公天下”到“家天下”C．从土地公有到土地私有 D．从百家争鸣到儒释道合流6．春秋以前，各君王的外戚都来自一些拥有政治实力的诸侯国。
自从秦统一以后，特别是在汉代以后，皇帝的外戚便从其臣民中遴选了。
据此推知，汉代的外戚()A．始终把持着中央政权 B．与三公九卿平起平坐C．擅权根源是皇权专制 D．决定历任皇位的更替7．空间观念是历史学习的一项基本能力素养。
元史载：“国家置中书省以治内，分行省以治外。
河南省中牟县第一高级中学2018-2019学年高二上学期第十二次双周考物理(实验班)试卷
验部高二第十二次双周考物理试题一、选择题（1-8为单选，9-12为多选）1． 在电磁学发展过程中，许多科学家做出了贡献，下列说法符合史实的是： A. 安培发现了电流的磁效应，总结出直线电流、圆环电流和通电螺线管的磁场方向与电流方向之间的关系B. 库仑发现了点电荷之间的相互作用规律，并测出静电引力常量为k=9×109N·m²/C²C. 法拉第经过十余年的研究，总结出电磁感应规律可以用公式来表示D. 法拉第提出了场的概念，认为电、磁作用都是通过场来传递的 2． 一个带电粒子在匀强电场中运动的轨迹如图中曲线AB 所示，平行的虚线a 、b 、c 、d 表示该电场中的四个等势面。
不计粒子重力，下列说法中正确的是：（ ） A. 该粒子一定带正电B. 四个等势面中a 等势面的电势一定最高C. 该粒子由A 到B 过程中动能一定逐渐增大D. 该粒子由A 到B 过程中电势能一定逐渐增大3.如图所示，图甲和图乙分别表示正弦脉冲波和方波的交变电流与时间的变化关系．若使这两种电流分别通过两个完全相同的电阻，则经过1 min 的时间，两电阻消耗的电功之比W 甲∶W 乙为( )A ．1∶B ．1∶2C ．1∶3D ．1∶64． 如图所示是一个火警报警装置的逻辑电路图。
要做到低温时电铃不响，火警时产生高温，电铃响起。
结合你所学过的知识，判断下列说法中正确的是：A. Rt 必须是热敏电阻，低温时电阻值很小，高温时电阻值很大B. 当高温时Rt 阻值减小，X 、P 之间电压升高，电铃响起C. 虚线处应该接入一个“非”门元件D. 为了提高灵敏度，应适当减小可变电阻R 的阻值5．如图所示，变压器的输入电压U 一定，两个副线圈的匝数分别是n 2和n 3，当把电热器接a 、b ，让c 、d 空载时，电流表读数为I 2；当把同一电热器接c 、d ，而a 、b 空载时，电流表读数为I3，则I2∶I3等于( )A．n2∶n3B．n3∶n2C．n∶n D．n∶n6． 1831年10月28日，法拉第在一次会议上展示了他发明的圆盘发电机。
河南省中牟县第一高级中学高三上学期第十次双周考数学(理)---精校Word版含答案
2018-2019学年高三第十次双周考数学(理)试题一、选择题： 1．设全集，，则图中阴影部分表示的集合是（） A ．{1，3，5}B ．{1，5，6}C ．{6，9}D ．{1，5}2．已知复，则复数的共轭复数（）A ．B ．C ．D ．3．已知焦点在轴上的双曲线的渐近线方程为，则该双曲线的离心率为（）A ．B ．C ．或D ．2或4．已知空间几何体的三视图如图所示，则该几何体的体积是（）A ．B ．C ．4D ．5．已知函数，且，又，则函数的图象的一条对称轴是（）A ．B ．C ．D ．6．在等比数列{}n a 中，已知5712411,8a a a a a +==+，则5a 的值为（ ）A ．12B ．14C ．18D ．1167．已知，满足约束条件，则的最大值是（） A ．3B ．5C ．6D ．78．如图，半径为1的扇形中，，是弧上的一点，且满足，，分别是线段，上的动点，则的最大值为（）A ．B ．C ．1D ． 9．已知定义在上的偶函数满足，且当时，，则函数的零点个数是（）A ．0B ．2C ．4D ．610．()()5212x x -+展开式中，含2x 项的系数为（ ） A ．30 B ．70 C ．90 D ．150-11．某学校食堂早餐只有花卷、包子、面条和蛋炒饭四种主食可供食用，有5名同学前去就餐，每人只选择其中一种，且每种主食都至少有一名同学选择.已知包子数量不足仅够一人食用，甲同学肠胃不好不会选择蛋炒饭，则这5名同学不同的主食选择方案种数为 A. 48 B. 96 C. 132 D.14412. 已知)(x f 是定义在R 上的偶函数，对于R x ∈∀,都有0)()2(=++x f x f ,当时，，若在[-1,5]上有五个根，则此五个根的和是（ ）A ．7B ．8C ．10D ．12 二、填空题：本大题共4小题，每小题5分．13．已知平面内三个不共线向量,,a b c 两两夹角相等，且||||1a b ==，||3c =，则||a b c ++=．14．如图是某算法的程序框图，则程序运行后输出的结果是__________．15．已知圆：和圆：，若点（，）在两圆的公共弦上，则的最小值为__________．16． 如图所示，在等腰梯形ABCD 中，2AB CD == 60=∠DAB ，E 为AB 的中点，将ADE ∆与BEC ∆分别沿EC ED ,向上翻折，使B A ,重合，则形成的三棱锥的外接球的表面积为_______． 三、解答题：解答应写出文字说明、证明过程或演算步骤． 17．各项均为正数的等比数列，前项和为，且满足，．（1）求数列的通项公式；（2）若，求数列的前项和．18．交强险是车主必须为机动车购买的险种，若普通6座以下私家车投保交强险第一年的费用（基准保费）统一为元，在下一年续保时，实行的是费率浮动机制，保费与上一年度车辆发生道路交通事故的情况相联系，发生交通事故的次数越多，费率也就越高，具体浮动情况如表：某机构为了研究某一品牌普通6座以下私家车的投保情况，随机抽取了60辆车龄已满三年的该品牌同型号私家车的下一年续保时的情况，统计得到了下面的表格：以这60辆该品牌车的投保类型的频率代替一辆车投保类型的概率，完成下列问题： （1）按照我国《机动车交通事故责任强制保险条例》汽车交强险价格的规定， ．某同学家里有一辆该品牌车且车龄刚满三年，记为该品牌车在第四年续保时的费用，求的分布列与数学期望值；（数学期望值保留到个位数字）（2）某二手车销售商专门销售这一品牌的二手车，且将下一年的交强险保费高于基本保费的车辆记为事故车．假设购进一辆事故车亏损5000元，一辆非事故车盈利10000元： ①若该销售商购进三辆（车龄已满三年）该品牌二手车，求这三辆车中至多有一辆事故车的概率；②若该销售商一次购进100辆（车龄已满三年）该品牌二手车，求他获得利润的期望值． 19．如图，已知多面体的底面是边长为的菱形，底面，，且． （1）证明：平面平面； （2）若直线与平面所成的角为，求二面角的余弦值．21. （12分）已知椭圆()2222:1,0x y C a b a b +=>>过点31,2⎛⎫⎪⎝⎭, 离心率为12,左右焦点分别为12,F F , 过点1F 的直线l 交椭圆于,A B 两点.（1）求椭圆C 的方程；（2）当2F AB ∆时, 求以2F 为圆心且与直线l 相切的圆的方程. 21．（12分）已知函数()()21ln 2f x a x x a R ⎛⎫=-+∈ ⎪⎝⎭（1）当1a =时，求函数()f x 在区间[]1,e 上的最大值和最小值； （2）若()0f x >有解, 求a 的取值范围.（二）选考题（共10分．请考生在第22、23题中任选一题作答．如果多做，则按所做第一题计分）22．已知直线的参数方程为（，为参数），曲线的极坐标方程为．（1）将曲线的极坐标方程化为直坐标方程，并说明曲线的形状； （2）若直线经过点，求直线被曲线截得的线段的长．23．已知，，函数的最小值为4．（1）求的值；（2）求的最小值．2018-2019学年高三第十次双周考数学(理)答案一、选择题：DCABA DCCDB CC13、2 14、10 15、8 16 3三、解答题．17．（1）设等比数列的公比为，由得，解得或，∵数列为正项数列，∴，代入，得，∴． 6分（2），此时，∴． 12 分18．（1）由题意可知的可能取值为，，，，，．由统计数据可知：，，，，，．所以的分布列为：所以6分（2）①由统计数据可知任意一辆该品牌车龄已满三年的二手车为事故车的概率为，三辆车中至少有一辆事故车的概率为． 9分②设为该销售商购进并销售一辆二手车的利润，的可能取值为－5000，10000．所以的分布列为：所以．所以该销售商一次购进100辆该品牌车龄已满三年的二手车获得利润的期望为万元． 12分19．【解析】（1）证明：连接，交于点，设中点为，连接，．因为，分别为，的中点，所以，且，因为，且，所以，且．所以四边形为平行四边形，所以，即．因为平面，平面，所以．因为是菱形，所以．因为，所以平面．因为，所以平面．因为平面，所以平面平面． 6分 （2）解：因为直线与平面所成角为，所以，所以．所以，故为等边三角形．设的中点为，连接，则．以为原点，，，分别为轴，建立空间直角坐标系（如图）．则，，，， ，，．设平面的法向量为，则，即，，则，所以．设平面的法向量为，则，即，令，则，所以． 设二面角的大小为，由于为钝角，所以．所以二面角的余弦值为． 12分20．解：（1）因为椭圆()2222:1,0x y C a b a b+=>>过点31,2⎛⎫ ⎪⎝⎭所以221914a b +=…………○1 又因为离心率12e =所以12c a =…………○2解○1、○2得224,3a b ==所以椭圆C 的方程为22143x y += …………(4’) （2）○1当直线l 与x 轴垂直时，可得331,,1,22A B ⎛⎫⎛⎫--- ⎪ ⎪⎝⎭⎝⎭2F AB ∆的面积为3，不符合题意 …………(5’)○2当直线l 与x 轴不垂直时，设直线l 的方程为()1y k x =+代入椭圆的方程得()22223484120k xk x k +++-=显然0∆>成立，设()()1122,,,A x y B x y则221212228412=3+434k k x x x x k k -+=-+， …………(7’) 所以()212212134k AB x x k+⎤=⎦+用点到直线距离公式可得圆2F的半径r =所以AB F 2∆的面积41122k AB r ===化简得4217180k k +-=解得1k =± …………(10’) 所以r =()2212x y -+= …………(12’)21．解：（1）由题可知()f x 的定义域为()0,+∞， …………(1’) 当1a =时，函数()()211ln ,'02f x x x f x x x=+=+> ………… (2’) 所以函数()f x 在区间[]1,e 上是增函数。
2018—2019学年河南省中牟县第一高级中学高三毕业班第十次双周考英语试卷及答案
绝密★启用前河南省中牟县第一高级中学2018～2019学年高三年级第十次双周考英语试题AI was sure that I was to be killed. I became terribly nervous. I fumbled(摸索) in my pockets to see if there were any cigarettes, which had escaped their search.I found one and because of my shaking hands, I could barely get it to my lips. But I had no matches; they had taken those. I looked through the bars at the guard. He did not make eye contact with me. I called out to him “Have you got a light？” He looked at me, shrugged and came over to light my cigarette. As he came close and lit the match, his eyes unconsciously locked with mine. At that moment, I smiled. I don't know why I did that. Perhaps it was nervousness; perhaps it was because, when you get very close, one to another, it is very hard not to smile. In any case, I smiled. In that instant, it was as though a spark jumped across the gap between our two hearts, our two human souls. I know he didn't want to, but my smile leaped through the bars and caused a smile on his lips, too. He lit my cigarette but stayed near, looking at me directly in the eyes and continuing to smile.I kept smiling at him, now thinking of him as a person and not just a guard. “Do you have kids？” he asked. “Yes, here, here.” I took out my wallet and nervously fumbled for the pictures of my family. He, too, took out the pictures of his family and began to talk about his plans and hopes for them. My eyes were filled with tears.I said that I feared that I'd never see my family again, never have the chance to see them grow up. Tears came to his eyes, too. Suddenly, without another word, he unlocked my cell and silently led me out. Out of the prison, quietly and by back routes, out of the town. There, at the edge of town, he released me. And without another word, he turned back toward the town.21．What had happened to the man before?A．He had been badly treated. B．He had killed someone.C．He had been searched. D．He had been forbidden to get in touch with anyone. 22．Why did the man want to smoke cigarettes?A．Because he was sure he was to be killed. B．Because he wanted to ease hisnervousness.C．Because he wanted to talk to the guard. D．Because he was used to smoking cigarettes.23．Which of the following is true according to the passage?A．The man was a heavy smoker.B．The man smiled to please the guard.C．The guard set the man free with permission.D．The man hadn't thought the guard would set him free.24．What do you think finally saved the man's life?A．The smile. B．The cigarette. C．The tears. D．The wallet.BThe editor of the new Cool Camping Britain guide chooses some of his favorite new finds in England, Wales and Scotland.Cleadale, Isle of Eigg, Inner HebridesIs this Britain’s most beautiful campsite? From the grassy point looking seaward to the mountains, it’s not hard for campers to see how the island inspired The Lord of the Rings author’s fantasy landscapes. The campsite itself is as wild and wonderful as its setting.Open April — September, from ￡5 per tent per night.Swattesfield, Thornham Magna, SuffolkDeep in the wilds of north Suffolk, this seven-acre campsite has only been open for a few years, with two fields separated by a lake and surrounded by woodland. The position is perfect. It’s a great place to do nothing but get into nature. You can put up your tent in the bottom field or the woodland beyond.Open Easter —October, from ￡10 per tent per night.Pleasant Streams Farm, near St Austell, CornwallThis site, by a lake, is all about simple pleasures. Located in the former mining village, it has a summerhouse（凉亭）with books and games for a rainy day. There are many animals including pigs, hens, goats and ducks on the farm and a pub just a 10- mi nute stroll away. There’s very little to do here, no bells and no whistles. Campfires are encouraged.。
人教版各省市-河南省中牟县第一高级中学2018-2019学年高二上学期第十次双周考数学(文)试卷
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河南省中牟县第一高级中学2018-2019学年高二上学期第十次双周考物理(实验班)试卷
2018-2019上期中牟一高实验部高二第十次周考物理试卷一、选择题（1-6为单选，7-12为多选。
每小题4分，共48分）。
1.物理实验都需要有一定的控制条件.奥斯特做电流磁效应实验时，应排除地磁场对实验的影响.关于奥斯特的实验，下列说法中正确的是（）A．该实验必须在地球赤道上进行B．通电直导线应该竖直放置C．通电直导线应该水平东西方向放置D．通电直导线应该水平南北方向放置2．如图所示，圆形线圈P静止在水平桌面上，其正上方悬挂一相同的线圈Q，P 和Q共轴，Q中通有变化的电流，电流变化的规律如图(b)所示，P所受的重力为G，桌面对P的支持力为F N，则()A．t1时刻，F N>G B．t2时刻，F N>GC．t3时刻，F N<G D．t4时刻，F N>G3．在磁场中的同一位置放置一条直导线，导线的方向与磁场方向垂直．先后在导线中通入不同的电流，导线所受的力也不一样，图中几幅图象表现的是导线受的力F与通过的电流I 的关系．a，b各代表一组F，I的数据．下列图中正确的是（）4．图1和图2是教材中演示自感现象的两个电路图，L1和L2为电感线圈。
实验时，断开开关S1瞬间，灯A1突然闪亮，随后逐渐变暗；闭合开关S2，灯A2逐渐变亮，而另一个相同的灯A3立即变亮，最终A2与A3的亮度相同。
下列说法正确的是（）A．图1中，A1与L1的电阻值相同B．图1中，闭合S1，电路稳定后，A1中电流大于L1中电流C．图2中，变阻器R与L2的电阻值相同D．图2中，闭合S2瞬间，L2中电流与变阻器R中电流相等5．在一空间有方向相反，磁感应强度大小均为B的匀强磁场，如图所示，向外的磁场分布在一半径为a的圆形区域内，向内的磁场分布在除圆形区域外的整个区域，该平面内有一半径为b(b＞a)的圆形线圈，线圈平面与磁感应强度方向垂直，线圈与半径为a的圆形区域是同心圆．从某时刻起磁感应强度开始减小到，则此过程中该线圈磁通量的变化量的大小为()A．πB(b2－a2) B．πB(b2－2a2)C．πB(b2－a2) D．πB(b2－2a2)6．如图，在水平面(纸面)内有三根相同的均匀金属棒ab、Ac和MN其中ab、ac在a点接触，构成“v”字型导轨。
D_河南省中牟县第一高级中学2018-2019学年高二上学期第十次双周考数学(理)试卷含答案
高二十一月数学周考试卷（理科）一．选择题（每小题5分，共60分）１．函数的导函数是 （ ）)52sin(2)(+=x x x f A B )52sin(2)52sin(2)(+++=x x x x f )52sin(2-)52sin(2)(++=x x x x f CD )52sin(4-)52sin(2)(++=x x x x f )52sin(4)52sin(2)(+++=x x x x f 2. 设，则是的 （ ）a R ∈1a >11a<（A ）充分但不必要条件 （B ）必要但不充分条件（C ）充要条件（D ）既不充分也不必要条件3.与椭圆1422=+y x 共焦点且过点(2,1)Q 的双曲线方程是 （ ）A. 1222=-y x B. 1422=-y x C. 1222=-y x D. 13322=-y x 4.已知是椭圆的两个焦点，过且与椭圆长轴垂直的弦交椭圆与,两点，12,F F 1F A B 则是正三角形，则椭圆的离心率是（ ）2ABF ∆AB CD123135.有以下命题：①如果向量与任何向量不能构成空间向量的一组基底，那么的关系是不共线；,,②为空间四点，且向量不构成空间的一个基底，则点一定共,,,O A B C ,,,,,O A B C 面；③已知向量是空间的一个基底，则向量也是空间的一个基底。
正确的命题c b a ,,c b a b a ,,-+是 （ ）（A ）①② （B ）①③ （C ）②③ （D ）①②③6.如图：在平行六面体中，为与的交点。
若，1111D C B A ABCD -M 11C A 11D B =，则下列向量中与相等的向量是（ ）=AA =1（A ） （B b a ++-11b a ++11（C ） （D b a +--11b a +-117. 已知△ABC 的周长为20，且顶点B(0，－4)，C (0，4)，则顶点A 的轨迹方程是（ ）（A ）（x ≠0） 1203622=+y x （B ）（x ≠0） 1362022=+y x （C ）（x ≠0） 120622=+y x （D ）（x ≠0）162022=+y x 8.已知向量==),0,1,1(互相垂直,则实数k 的值是( ) A ．1B ． C ．D ．5153579.在正方体中，是棱的中点，则与所成角的余弦值为（1111ABCD A B C D -E 11A B 1A B 1D E ）A B C D 1051010. 一位运动员投掷铅球的成绩是，当铅球运行的水平距离是时，达到最大高度.14m 6m 4m 若铅球运行的路线是抛物线，则铅球出手时距地面的高度是（ ）A ．B ． 1.75m 1.85mC ．D ． 2.15m 2.25m11.下列判断正确的是（ ）. A.若方程有解，则.022=++a x x 2<a B.“对任意”的否定是“存在”.02,>∈x R x 02,00≥∈x R x C.“菱形的对角线互相垂直”的否命题是假命题. D.方程.仅有两解22x x =二．填空题（每小题5分，共20分）14．斜率为1的直线经过抛物线＝4x 的焦点，且与抛物线相交于A,B 两点，则等于___2y AB 15．已知平行六面体中，底面是边长为2的正方形，，1111D C B A ABCD -11=AA ，则的长度是_____011120=∠=∠AD A AB A 1AC 16．若方程所表示的曲线为C ，给出下列四个命题：11422=-+-t y t x ①若C 为椭圆，则1<t<4; ②若C 为双曲线，则t>4或t<1；③曲线C 不可能是圆； ④若C 表是椭圆，且长轴在x 轴上，则.231<<t 其中真命题的序号为 （把所有正确命题的序号都填在横线上）三．解答题（17题10分，其余每题12分共70分）17.已知函数 xxx f sin )(=（1）求的导函数。
河南省中牟县第一高级中学2018_2019学年高二英语上学期第十次双周考试题
河南省中牟县第一高级中学2018-2019学年高二英语上学期第十次双周考试题第二部分阅读理解（共两节，满分40分）第一节（共15小题：每小题2分，满分30分）AOnce upon a time, a man was walking on a mountain when he found an incredible cave with all kinds of treasure inside it. So he gave up his job, his home, and his friends, and spent all his time guarding the cave.He was so dedicated to it that he hardly ate or drank, and before long he fell ill. One day, when he could hardly move at all, he decided to share the treasure.He crawled into the cave to get a handful of jewels, but discovered, to his horror, that it was empty except for a small emerald (绿宝石). The man took it and gave it to the first person to come by, a woman.Then an old man came by. “What bad luck!” the man said. “Just a moment ago I gave a woman the last of t he treasure I was guarding.”“Are you sure there is nothing left?” the old man asked.The man took him into the cave, where they found a chest with jewels and some bags of gold. The man was shocked, and the old man explained to him, “At last! At last! At last someone has broken the spell of this cave. This is the Cave of Treasure, and you’re the first to have passed its great test. Many have dedicated their lives to this cave, only to end up realizing there was nothing here …”“And why does this happen?” t he man asked.“This magic cave has only as many riches as your own heart. When someone discovers it, the cave fills with the treasure they bring with them, but later, when they have devoted themselves to guarding the treasure, their hearts become empty, as does the cave. The only way to fill it is by filling your heart with all that is good, as you did by giving the woman that last jewel.”From that day on, the man understood that it was better to share than to keep. Thanks to the cave and the old man, he became noble and generous.21. Why did the man give up his job, home and friends?A. Because he possessed a variety of treasure.B. Because he devoted himself to a great test.C. Because he had to guard the treasure cave.D. Because he wanted to find the treasure cave.22. What did the man find when he showed his cave to the old man?A. All kinds of treasure.B. A chest with jewels and gold.C. A small emerald.D. A handful of jewels.23. What do we learn about the people who dedicated their lives to the cave before?A. They all found the cave empty at last.B. The old man freed them from its spell.C. They all filled the cave with the treasure they had.D. They thought it was better to share than to enjoy the treasure alone.24. What can we learn from the text?A. Different people have different views.B. Treasure only belongs to those who possess it.C. Some people never learn what is really valuable.D. Purely material things cannot make us truly wealthy.BWalt Disney is credited for creating such wonderful things as Donald Duck and Mickey Mouse. However, he cannot take the credit for creating other well-loved characters, such as Cinderella and Snow White. They are almost automatically associated with Disney because Disney turned old fables(寓言) into cartoon movies.The original Cinderella varies very much from the Disney version we know today. It started off with the girl mourning her mother’s death and going to her tomb three times a day. In addition, there were only birds that helped Cinderella; there was no such thing as a fairy godmother or helpful mice, nor was there mention of a horse and carriage.The stepsisters were cruel: they always threw Cinderella’s food into the ashes of the fire and made her sleep on the ashes on the floor, hence（因此）her name.In the original story, the king’s ball actually lasted for three days. With the help of the birds, the girl, beautifully dressed, danced with the prince on all three nights and the prince fell in love with her. However, she broke away from him to rush back home each night. On the last night, the prince placed something sticky on the stairs; as Cinderella made her escape, a shoe got stuck on it.Here now is where the story becomes unpleasant: when the prince went to the house looking for the girl whose foot fit the shoe, the wicked(邪恶的) stepmother told one of her two daughters to cut off her big toe to fit into the shoe. The daughter did as told. So the prince took her away to be his bride. But，when they passed the tomb of Cinderella’s mother, the birds called out to the prince,“Turn and peep, there’s blood within the shoe;The shoe is too small, the true bride waits for you.”Realizing he had been tricked, the prince returned the daughter to her mother. The other then had to cut off part of her heel in order to fit into the shoe, with the same result. Only Cinderella’s foot fit perfectly and so the prince chose to marry her. The story ends with the wedding day: as Cinderella’s two stepsisters followed her, pretending to be devoted to her so that they could enjoy the king’s riches, two birds flew by and plucked(啄) out their eyes. Because of their wickedness and falsehood, they had to spend the rest of their days blind.The original Cinderella is so different from the Disney version. Thank goodness Disney made such changes; it indeed was a wise move.25. What dose the underlined word “They” in the first paragraph refer to?A. Such wonderful things.B. Other well-loved characters.C. Old fables.D. Cartoon movies.26. How did Cinderella get her name?A. The birds came up with it.B. It was given by Disney.C. It came from the word “ash”.D. She got it from her mother.27. Which of the following is TRUE according to the original story?A. Helpful mice got Cinderella a beautiful dress.B. The ball was held to celebrate the prince’s wedding.C. Cinderella left her shoe on the stairs on purpose.D. The birds told the prince that he had been cheated.28. The moral of the original story is that ____________.A. a wicked person cannot escape punishment.B. a devoted person certainly deserves respect.C. a well-behaved child earns a great reward.D. a dishonest child cannot get mother love.29. What does the author think of the Disney version?A.Excellent.B. OrdinaryC. Dull.D. Ridiculous.CThe elephant was lying heavily on its side, fast asleep. A few dogs started barking at it. The elephant woke up in a terrible anger: it chased the dogs into the village where they ran for safety.That didn't stop the elephant. It destroyed a dozen houses and injured several people. The villagers were scared and angry. Then someone suggested calling Parbati, the elephant princess.Parbati Barua's father was a hunter of tigers and an elephant tamer. He taught Parbati to ride an elephant before she could even walk. He also taught her the dangerous art of the elephant round-up -- how to catch wild elephants.Parbati hasn't always lived in the jungle. After a happy childhood hunting with her father, she was sent to boarding school in the city. But Parbati never got used to being there and many years later she went back to her old life. "Life in the city is too dull. Catching elephants is an adventure and the excitement lasts for days after the chase," she says.But Parbati doesn't catch elephants just for fun. "My work," she says, "is to rescue man from the elephants, and to keep the elephants safe from man. " And this is exactly what Parbati has been doing for many years. Increasingly, the Indian elephant is angry: for many years, illegal hunters have attacked it and its home in the jungle has been reduced to small pieces of land. It is now fighting back. Whenever wild elephants enter a tea garden or a village, Parbati is called to guide the animals back to the jungle before they can kill.The work of an elephant tamer also involves love and devotion. A good elephant tamer will spend hours a day singing love songs to a newly captured elephant. "Eventually they grow to love their tamers and never forget them. They are also more loyal than humans," she said, as she climbed up one of her elephants and sat on the giant, happy animal. An elephant princess indeed!30. Before Parbati studied in a boarding school,________ .A. she spent her time hunting with her fatherB. she learned how to sing love songsC. she had already been called an elephant princessD. she was taught how to hunt tigers31. Indian elephants are getting increasingly angry and they revenge because __________.A. they are caught and sent for heavy workB. illegal hunters capture them and kill themC. they are attacked and their land gets limitedD. dogs often bark at them and chase them32. The passage starts with an elephant story in order to explain that in India _________.A. people easily fall victim to elephants' attacksB. the man-elephant relationship is getting worseC. elephant tamers are in short supplyD. dogs are as powerful as elephantsDIf doctors want to test you for something, they’ll usually take a blood or urinesample. But wouldn’t it be much more convenient if they just asked you to breathe through a special instrument?In fact, your breath can say a lot about you. In traditional Chinese medicine, doctors draw a conclusion about the health state of a patient based on the smell of his or her breath; trained dogs and rats can identify the smells of the breaths of people suffering from certain cancer s; traffic police also monitor drivers’ alcohol consumption by testing their breaths.Just like blood and urine, your breath contains lots of “metabolites” —the waste chemicals that the body produces, which vary from person to person. They are like personal health fingerprints, which is why scientists sometimes call them “breathprints”, according to Science Daily.Compared to blood or urine testing, breath testing takes only seconds instead of hours, and it requires neither a needle nor a container to hold the body fluids(液). This means the test can be taken frequently to better detect early signs of diseases and monitor the progress of a medical treatment.On the other hand, as an identifier, you might think that breaths are not as reliable as fingerprints since they might change based on what you eat. However, researchers in Zurich, Switzerland mapped 11 healthy volunteers’ chemical patterns by having them breathe through a special instrument, and they found that each pattern was unique and the patterns did n’t change much throughout the day, reported BBC.“Our goal is to develop breath analysis to the point where it becomes competitive with the established analysis of blood and urine,” said Malcolm Kohler, professor at the University Hospital Zurich.33.According to the text we know that______.A. breath varies from person to person based on food.B. your breath may give you away if you are not careful.C. doctors can test one’s breath to find about his illness.D. trained dogs can identify people with certain cancers.34. In comparison with blood or urine testing, breath testing is _______.A. comfortable and convincing .B. traditional and reliable.C. accurate and competitive.D. quick and convenient.35. What can we infer from the text?A. Breath testing is reliable and may have a bright future.B. Blood or urine testing will be less used in medical treatment.C. Doctors have found the best way to detect early signs of diseases.D. Traditional Chinese medicine is becoming more and more popular.第二节 (共5小题；每小题2分，满分10分)据短文内容，从短文后选项中选出能填入空白处的最佳选项。
河南省中牟县第一高级中学2019届高三数学上学期第十次双周考试题理
河南省中牟县第一高级中学2019届高三数学上学期第十次双周考试题 理一、选择题： 1．设全集，，则图中阴影部分表示的集合是（） A ．{1，3，5}B ．{1，5，6}C ．{6，9}D ．{1，5}2．已知复，则复数的共轭复数（）A ．B ．C ．D ．3．已知焦点在轴上的双曲线的渐近线方程为，则该双曲线的离心率为（）A ．B ．C ．或D ．2或4．已知空间几何体的三视图如图所示，则该几何体的体积是（）A ．B ．C ．4D ．5．已知函数，且，又，则函数的图象的一条对称轴是（）A ．B ．C ．D ．6．在等比数列{}n a 中，已知5712411,8a a a a a +==+，则5a 的值为（ ）A ．12B ．14C ．18D ．1167．已知，满足约束条件，则的最大值是（） A ．3B ．5C ．6D ．78．如图，半径为1的扇形中，，是弧上的一点，且满足，，分别是线段，上的动点，则的最大值为（）A ．B ．C ．1D ． 9．已知定义在上的偶函数满足，且当时，，则函数的零点个数是（）A ．0B ．2C ．4D ．610．()()5212x x -+展开式中，含2x 项的系数为（ ） A ．30 B ．70 C ．90 D ．150-11．某学校食堂早餐只有花卷、包子、面条和蛋炒饭四种主食可供食用，有5名同学前去就餐，每人只选择其中一种，且每种主食都至少有一名同学选择.已知包子数量不足仅够一人食用，甲同学肠胃不好不会选择蛋炒饭，则这5名同学不同的主食选择方案种数为 A. 48 B. 96 C. 132 D.14412. 已知)(x f 是定义在R 上的偶函数，对于R x ∈∀,都有0)()2(=++x f x f ,当时，，若在[-1,5]上有五个根，则此五个根的和是（ ）A ．7B ．8C ．10D ．12 二、填空题：本大题共4小题，每小题5分．13．已知平面内三个不共线向量,,a b c 两两夹角相等，且||||1a b ==，||3c =，则||a b c ++=．14．如图是某算法的程序框图，则程序运行后输出的结果是__________．15．已知圆：和圆：，若点（，）在两圆的公共弦上，则的最小值为__________．16． 如图所示，在等腰梯形ABCD 中，2AB CD == 60=∠DAB ，E 为AB 的中点，将ADE ∆与BEC ∆分别沿EC ED ,向上翻折，使B A ,重合，则形成的三棱锥的外接球的表面积为_______． 三、解答题：解答应写出文字说明、证明过程或演算步骤． 17．各项均为正数的等比数列，前项和为，且满足，．（1）求数列的通项公式；（2）若，求数列的前项和．18．交强险是车主必须为机动车购买的险种，若普通6座以下私家车投保交强险第一年的费用（基准保费）统一为元，在下一年续保时，实行的是费率浮动机制，保费与上一年度车辆发生道路交通事故的情况相联系，发生交通事故的次数越多，费率也就越高，具体浮动情况如表：某机构为了研究某一品牌普通6座以下私家车的投保情况，随机抽取了60辆车龄已满三年的该品牌同型号私家车的下一年续保时的情况，统计得到了下面的表格：以这60辆该品牌车的投保类型的频率代替一辆车投保类型的概率，完成下列问题： （1）按照我国《机动车交通事故责任强制保险条例》汽车交强险价格的规定， ．某同学家里有一辆该品牌车且车龄刚满三年，记为该品牌车在第四年续保时的费用，求的分布列与数学期望值；（数学期望值保留到个位数字）（2）某二手车销售商专门销售这一品牌的二手车，且将下一年的交强险保费高于基本保费的车辆记为事故车．假设购进一辆事故车亏损5000元，一辆非事故车盈利10000元： ①若该销售商购进三辆（车龄已满三年）该品牌二手车，求这三辆车中至多有一辆事故车的概率；②若该销售商一次购进100辆（车龄已满三年）该品牌二手车，求他获得利润的期望值． 19．如图，已知多面体的底面是边长为的菱形，底面，，且． （1）证明：平面平面； （2）若直线与平面所成的角为，求二面角的余弦值．21. （12分）已知椭圆()2222:1,0x y C a b a b +=>>过点31,2⎛⎫⎪⎝⎭, 离心率为12,左右焦点分别为12,F F , 过点1F 的直线l 交椭圆于,A B 两点.（1）求椭圆C 的方程；（2）当2F AB ∆时, 求以2F 为圆心且与直线l 相切的圆的方程. 21．（12分）已知函数()()21ln 2f x a x x a R ⎛⎫=-+∈ ⎪⎝⎭（1）当1a =时，求函数()f x 在区间[]1,e 上的最大值和最小值； （2）若()0f x >有解, 求a 的取值范围.（二）选考题（共10分．请考生在第22、23题中任选一题作答．如果多做，则按所做第一题计分）22．已知直线的参数方程为（，为参数），曲线的极坐标方程为．（1）将曲线的极坐标方程化为直坐标方程，并说明曲线的形状； （2）若直线经过点，求直线被曲线截得的线段的长．23．已知，，函数的最小值为4．（1）求的值；（2）求的最小值．2018-2019学年高三第十次双周考数学(理)答案一、选择题：DCABA DCCDB CC13、2 14、10 15、8 16 3三、解答题．17．（1）设等比数列的公比为，由得，解得或，∵数列为正项数列，∴，代入，得，∴． 6分（2），此时，∴． 12 分18．（1）由题意可知的可能取值为，，，，，．由统计数据可知：，，，，，．所以的分布列为：所以6分（2）①由统计数据可知任意一辆该品牌车龄已满三年的二手车为事故车的概率为，三辆车中至少有一辆事故车的概率为． 9分②设为该销售商购进并销售一辆二手车的利润，的可能取值为－5000，10000．所以的分布列为：所以．所以该销售商一次购进100辆该品牌车龄已满三年的二手车获得利润的期望为万元． 12分19．【解析】（1）证明：连接，交于点，设中点为，连接，．因为，分别为，的中点，所以，且，因为，且，所以，且．所以四边形为平行四边形，所以，即．因为平面，平面，所以．因为是菱形，所以．因为，所以平面．因为，所以平面．因为平面，所以平面平面． 6分 （2）解：因为直线与平面所成角为，所以，所以．所以，故为等边三角形．设的中点为，连接，则．以为原点，，，分别为轴，建立空间直角坐标系（如图）．则，，，， ，，．设平面的法向量为，则，即，，则，所以．设平面的法向量为，则，即，令，则，所以． 设二面角的大小为，由于为钝角，所以．所以二面角的余弦值为． 12分20．解：（1）因为椭圆()2222:1,0x y C a b a b+=>>过点31,2⎛⎫ ⎪⎝⎭所以221914a b +=…………○1 又因为离心率12e =所以12c a =…………○2解○1、○2得224,3a b ==所以椭圆C 的方程为22143x y += …………(4’) （2）○1当直线l 与x 轴垂直时，可得331,,1,22A B ⎛⎫⎛⎫--- ⎪ ⎪⎝⎭⎝⎭2F AB ∆的面积为3，不符合题意 …………(5’)○2当直线l 与x 轴不垂直时，设直线l 的方程为()1y k x =+代入椭圆的方程得()22223484120k xk x k +++-=显然0∆>成立，设()()1122,,,A x y B x y则221212228412=3+434k k x x x x k k -+=-+， …………(7’) 所以()212212134k AB x x k+⎤=⎦+用点到直线距离公式可得圆2F的半径r =所以AB F 2∆的面积41122k AB r ===化简得4217180k k +-=解得1k =± …………(10’) 所以r =()2212x y -+= …………(12’)21．解：（1）由题可知()f x 的定义域为()0,+∞， …………(1’) 当1a =时，函数()()211ln ,'02f x x x f x x x=+=+> ………… (2’) 所以函数()f x 在区间[]1,e 上是增函数。
河南省中牟县第一高级中学2018_2019学年高二英语上学期第十二次双周考试题
河南省中牟县第一高级中学2018-2019学年高二英语上学期第十二次双周考试题第二部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项，并在答题卡上将该选项涂黑。
AAs you grow older, you’ll be faced with some challenging decisions—like whether to cut class or try cigarettes. Making decisions on your own is hard enough, but when other people get involved and try to pressure you one way or another it can be even harder. People who are your age, like your classmates, are called peers. When they try to influence how you act, to get you to do something, it’s called peer pressure. Peers can have a positive influence on each other. Maybe another student in your science class taught you an easy way to remember the planets in the solar system. Maybe you got others excited about your new favorite book, and now everyone’s reading it. These are examples of how peers positively influence each other.Sometimes peers influence each other in negative ways. For example, a few kids in school might try to get you to cut class with them; your soccer friend might try to convince you to be mean to another player and never pass him the ball.It is tough to be the only one who says “no” to peer pressure, but you can do it. Paying attention to your own feelings and beliefs about what is right and wrong can help you know the right thing to do.You’ve probably had a parent or teacher advising you to“choose your friends wisely”. Peer pressure is a big reason why they say this. If you choose friends who don’t cut class, smoke cigarettes, or lie to their parents, then you probably won’t do these things either, even if other kids do.If you continue to face peer pressure and you’re finding it difficult to handle, talk to someone you trust. Don’t feel guilty if you’ve made a mistake or two.21. For whom is the passage most probably written?A .Students B. Parents C. Teachers D. Doctors.22. In the last three paragraphs, the author mainly_____.A．explains why friendship is so importantB．gives advice on how to deal with peer pressureC．discusses how peers influence usD．shows how to make more good friends23. Which of following may help handle peer pressure?A．Spending more time with classmates. B．Taking up more relaxing hobbies. C．Choosing friends with no bad habits. D．Helping others who are in trouble. 24. What is the topic of the passage?A．Friendship B．Making decisions C．Self-confidence D．Peer pressureBI hated dinner parties. But I decided to give them another shot because I’m in London. And my friend Mallery invited me. And because dinner parties in London are very different from those in New York, “I’m having a dinner party” means: “I’m booking a table for 12 at a restaurant you can’t afford an d we’ll be sharing the cheque evenly, no matter what you eat.” Wors e, in Manhattan there is always someone who leaves before the bill arrives. They’ll throw down cash, half of what they owe, and then people like me, who don’t drink, end up paying even more. But if I try to use the same trick, the hostess will shout; “Where are you going?” And it’s not like I can say I have somewhere to go: everyone knows I have nowhere to go.But in London, dinner parties are in people’s homes. Not only that, the guests are an interesting mix. The last time I went to one, the guests were from France, India, Denmark and Nigeria; it was like a gathering at the United Nations. In New York, the mix is less striking. It’s like a gathering at Bloomingdale’s , a well-known department store.For New Yorkers, talking about other parts of the world means Brooklyn and Queens in New Yorkers. But at Mallery’s, when I said that I had been to Myanmar recently, people knew where it was. In New York people would think it was a usual club.25. What does the word “shot” in Paragraph 1 probably mean?A. choiceB. tryC. styleD. goal26. What does the writer dislike most about dinner parties in New Yorkers?A. There is a strange mix of people.B. The restaurants are expensive.C. The bill is not fairly shared.D. People have to pay cash27. What does the author think of the parties in London?A. A bit unusualB. Full of tricksC. Less costlyD. More interesting28. What is the author’s opinion of some New Yorkers from her experience?A. Easy-goingB. Self-centred.C. GenerousD. ConservativeCHere is an astonishing and significant fact: Mental work alone can’t make ustired. It sounds absurd. But a few years ago, scientists tried to find out how long the human could labor without reaching a stage of fatigue(疲劳). To the amazement of these scientists, they discovered that blood passing through the brain, when it is active, shows no fatigue at all! If we took a drop of blood from a day labourer, we could find it full of fatigue toxins(毒素) and fatigue products. But if we took blood from the brain of Albert Einstein, it would show no fatigue toxins at the end of the day.So far as the brain is concerned, it can work as well and swiftly at the end of eight or even twelve hours of efforts as at the beginning. The brain is totally tireless. So what makes us tired.Some scientists declare that most of our fatigue come from our mental and emotional(情感的) attitudes. One of England’s most outstanding scientists J. A. Hadfield, says, “The greater part of the fatigue from which we suffer is of mental origin. In fact, fatigue of purely physical origin is rare.” Dr. Brill, a famo us American scientist, goes even further. He declares, “One hundred percent of the fatigue of a sitting worker in good health is due to emotional problems.”What kinds of emotions make sitting workers tired? Joy? Satisfaction? No! A feeling of being bored, anger, anxiety, tenseness, worry, a feeling of not being appreciated---those are emotions that tire sitting workers. Hard work by itself seldom causes fatigue. We get tired because our emotions produce nervousness in the body.29.What surprised the scientists a few years ago?A. Fatigue toxins could hardly be found in a labour’s blood.B. Albert Einstein didn’t feel worn out after a day’s work.C. The brain could work for many hours without fatigue.D. A mental worker’s blood was filled with fatigue toxins.30. According to the author, which of the following can make sitting worker tired？A．Challenging mental work. B．Unpleasant emotions.C．Endless tasks. D．Physical labor.31. What’s the author’s attitude towards the scientists’ ideas?A．He agrees with them. B．He doubts them.C．He argues against them. D．He hesitates to accept them.32. We can infer from the passage that in order to stay energeic, sitting workers need to ______.A．have some good blood B．enjoy their workC．exercise regularly D．discover fatigue toxinD“Indeed,” George Washington wrote in his diary in 1785, “some kind of fly, or bug, had begun to eat the leaves before I left home.” But the father of America was not the father of bug. When Washington wrote that, Englishmen had been referring to insects as bugs for more than a century, and Americans had already createdlightning-bug(萤火虫). But the English were soon to stop using the bugs in their language, leaving it to the Americans to call a bug a bug in the nineteenth and twentieth centuries.The American bug could also be a person, referring to someone who was crazy about a particular activity. Although fan became the usual term, sports fans used to be called racing bugs, baseball bugs, and the like.Or the bug could be a small machine or object, for example, a bug-shaped car. The bug could also be a burglar alarm, from which comes the expression to bug, that is, “to install (安装) an alarm”. Now it means a small piece of equipment that people use for li stening secretly to others’ conversation. Since the 1840s, to bug has long meant “to cheat”, and since the 1940s it has been annoying.We also know the bug as a flaw in a computer program or other design. That meaning dates back to the time of Thomas Edison. In 1878 he explained bugs as “little problems and difficulties” that required months of study and labor to overcome in developing a successful product. In 1889 it w as recorded that Edison “had been up the two previous nights discovering ‘a bug’ in his invented record player.”33. We learn from Paragraph 1 that ________.A. Americans had difficulty in learning to use the word bugB. George Washington was the first person to call an insect a bugC. the word bug was still popularly used in English in the nineteenth centuryD. both Englishman and Americans used the word bug in the eighteenth century34. What does the word “flaw” in the last paragraph probably mean________.A. Explanation.B. Finding.C. Origin.D. Fault.35. The passage is mainly concerned with________.A. the misunderstanding of the word bugB. the development of the word bugC. the public views of the word bugD. the special characteristics of the word bug第二节（共5小题：每小题2分，满分10分）根据短文内容,从短文后的七个选项中选出能填入空白处的最佳选项.选项中有两项为多余选项。
河南省中牟县第一高级中学2018_2019学年高二数学上学期第十二次双周考试题实验班
2018-2019学年高二年级第十二次周考数学试题一、选择题（本题共12小题，每小题5分，共60分）1.若函数3()63f x x bx b =-+在(0,1)内有极小值,则实数b 的取值范围是( ) A. (0,1) B. (,1)-∞ C. (0,)+∞ D. 10,2⎛⎫ ⎪⎝⎭2. 若21()ln(2)2f x x b x =-++∞在(-1,+)上是减函数，则b 的取值范围是（ ）A ．[1,)-+∞B ．(1,)-+∞C ．(,1]-∞-D ．(,1)-∞-3.已知椭圆2222:1(0)x y C a b a b+=>>的左焦点为F ,椭圆C 与过原点的直线相交于A 、B 两点,连接AF 、BF . 若|AB |=10,| BF |=8，cos ∠ABF =45,则C 的离心率为( )A. 35B. 57C. 45D. 674.设函数()'f x 是奇函数()()R f x x ∈的导函数,当0x >时, ,则使得成立的 x 的取值范围是( )A. ()(),11,-∞-⋃+∞B. ()(),10,1-∞-⋃C. ()()1,00,1-⋃D. ()()1,01,-⋃+∞ 5.函数()2f x sinx x =-,则( ) A. 3x π=是极小值点 B. 6x π=是极小值点 C. 3x π=是极大值点 D. 6x π=是极大值点6.已知()f x 是定义在R 上的偶函数,其导函数为'()f x ,若()()f x f x '<,且()()()13,20152f x f x f +=-=,则不等式()12x f x e -<的解集为( )A. (1,)+∞B. (,)e +∞C. (,0)-∞D. 1(,)e-∞7.设椭圆2222:1(0)x y C a b a b +=>>的左、右焦点分别为12,F F ,,过2F 的直线l 交C于,A B 两点.若1AF B ∆的周长为则C 的方程是( )A. 22132x y +=B. 2213x y += C. 221128x y += D. 221124x y +=8.已知椭圆()222210x y a b a b+=>>的一条弦所在的直线方程是50x y -+=弦的中点坐标是()4,1M -,则椭圆的离心率是( )A.129.在三棱柱111ABCA B C ﹣中, D 是1CC 的中点, F 是1A B 的中点,且DF AB AC αβ=+,则( )A. 1,12αβ==-B. 1,12αβ=-= C. 11,2αβ==- D. 11,2αβ=-=10设向量,,则“”是“”的A.充分但不必要条件B.必要但不充分条件C.充要条件D.既不充分也不必要条件11.已知0a b >>,椭圆1C 的方程为22221x y a b +=,双曲线2C 的方程为22221x y a b-=,1C 与2C则2C 的渐近线方程为( )A. 0x ±=0y ±= C. 20x y ±= D. 20x y ±= 12.已知圆C 的参数方程为1cos {?1sin y x αα=-+=+ (α为参数),当圆心C 到直线40kx y ++=的距离最大时, k 的值为( ) A.13 B. 15 C. 13- D. 15- 二、填空题(本题共4小题，每小题5分，共20分）13.已知函数()31f x ax x =++的图像在点()()1,1f 的处的切线过点(2,7),则a =__________.14.过双曲线的一个焦点的直线垂直于渐近线,且与双曲线的两支相交,则该双曲线的离心率的范围为 .15.设椭圆2222:1(0)x y C a b a b+=>>的左,右焦点为1F ,2F ,过2F 作x 轴的垂线与C 相交于A ,B 两点, 1F B 与y 轴相交于点D ,若1AD F B ⊥,则椭圆C 的离心率等于__________。
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2018-2019学年上期高二第十次周考
文科数学试题
一、选择题（共12小题；共60分）
1. 设，命题''若，则方程有实根"的逆否命题是
A. 若方程有实根，则
B. 若方程有实根，则
C. 若方程没有实根，则
D. 若方程没有实根，则
2. 命题“，，使得”的否定形式是
A. ，，使得
B. ，，使得
C. ，，使得
D. ，，使得
3. 下列命题中错误的个数为
①若为真命题，则为真命题；
②“”是“”的充分不必要条件；
③命题：，，则：，；
④命题“若，则或”的逆否命题为“若或，则
”．
A. B. C. D.
4. 双曲线的离心率为，则其渐近线方程为
A. B. C. D.
5. 已知双曲线的一条渐近线平行于直线，双曲线的一个焦
点在直线上，则双曲线的方程为
A. B. C. D.
6. 已知点是抛物线上的一个动点，则点到点的距离与点到该抛物
线准线的距离之和的最小值为
A. B. C. D.
7. 已知，是椭圆的两个焦点，是上的一点，若，且
，则的离心率为
A. B. C. D.
8. 函数在区间上的最大值为，最小值为，则的值
A. B. C. D.
9. 已知函数的导函数为，且满足，则
A. B. C. D.
10. 若函数在上单调递增，则的取值范围是
A. B. C. D.
11. 如图，，是椭圆与双曲线的公共焦点，，分别是，在
第二、四象限的公共点．若四边形为矩形，则的离心率是
A. B. C. D.
12. 设是函数的导函数，将和的图象画在同一个直角坐标系
中，不可能正确的是
二、填空题（共4小题；共20分）
13. 若“”是“”的必要不充分条件，则实数的最大值是．
14. 抛物线的焦点为椭圆的左焦点，顶点在椭圆中心，则抛物线方程为
．
15. 若函数在处取极值，则．
16. 过椭圆的右焦点作一条斜率为的直线与椭圆交于、两点，为坐
标原点，则的面积为．
三、解答题（共6小题；共70分）
17. 设命题：实数满足，其中，命题：实数满足．
（1）若，且为真，求实数的取值范围．
（2）若是的充分不必要条件，求实数的取值范围．
18. 根据下列条件求双曲线的标准方程．
（1）已知双曲线的渐近线方程为，且过点；
（2）与椭圆有公共焦点，且离心率．
19. 在平面直角坐标系中，，，动点满足，设动点
的轨迹为．
（1）求轨迹的方程；
（2）若上有一点满足，求的面积．
20. 已知函数；
（1）求在点处曲线的切线方程；
（2）求过点的曲线的切线方程．
21. 已知函数，．
（1）若在处取得极值，求实数的值；
（2）若不等式对任意恒成立，求实数的取值范围．
22. 已知函数．
（1）当时，求函数的单调区间和极值；
（2）求证：当时，关于的不等式在区间上无解．（其中
）
2018-2019学年双周考文科数学11.24答案
一选择题
1. D
2. D
3. B
4. A
5. A
6. A
7. D
8. C
9. B10. A11. D12. D
二填空题
13. 14. 15. 16.
三解答题
17. （1）由，得，
又，所以，
当时，，
又得，
由为真，所以满足即
则实数的取值范围是 .
（2）是的充分不必要条件，
记 { }，，则是的真子集
所以且，
则实数的取值范围是．
18. （1）因为双曲线的渐近线方程为，
所以可设双曲线的方程为．
又因为双曲线过点，
所以．
所以双曲线的方程为，
即．
（2）方法一（设标准方程）：由椭圆方程可得焦点坐标为，，
则且焦点在轴上，
所以可设双曲线的标准方程为，
且．
又，
所以，
所以．
所以双曲线的标准方程为．
方法二（设共焦点双曲线系方程）：
因为椭圆的焦点在轴上，
所以可设双曲线方程为．
又，
所以，
解得．
所以双曲线的标准方程为．
19. （1）由椭圆定义得动点的轨迹是以，为焦点，长轴长为的椭圆．
设轨迹的方程为，
则，，，
所以轨迹的方程为．
（2）在中，由余弦定理得
，
即
因为，
所以，
解得．
所以的面积．
20. （1）函数的导函数为，
所以，在点处切线为：．
1（2）设切点为，
切线方程为：，整理得：，
因为切线过点，
所以得，
解得：或，
切线方程为，．
21. （1），．
由，得．
经检验，当时取到极小值，故．
（2）由，即，对任意恒成立．
（）当时，有；
（）当时，，得．
令，得；
若，则；
若，则．
得在上递增，在上递减．
故的最大值为．
所以．
综合（）（）得．
22. （1）因为
所以
当时，．
令
1得，
所以随的变化情况如下表：
所以在处取得极大值，
在处取得极小值．
函数的单调递增区间为，，的单调递减区间为．
（2）证明：
不等式在区间上无解，等价于在区间上恒成立，
即函数在区间上的最大值小于等于．
因为
，
令，得，．
因为时，所以．
当时，，在上恒成立，则函数在区间上单调递减，
所以函数在区间上的最大值为，
所以不等式在区间上无解；
当时，随的变化情况如下表：
所以函数在区间上的最大值为或．
此时，，
所以
1
．
综上，当时，关于的不等式在区间上无解．。