A common formula for the combined torsional mesh stiffness of spur gears

合集下载

rsi wr起爆点指标

rsi wr起爆点指标

rsi wr起爆点指标What is RSI?The Relative Strength Index (RSI) is a technical analysis indicator that measures the strength and speed of a price movement. Developed by J. Welles Wilder, the RSI is a common tool used by traders and analysts to identify potential entry and exit points in the market. In this article, we will explore the concept of RSI and its application in determining potential breakout points.Understanding RSI and its Calculation:The RSI is calculated using a mathematical formula that compares the average gains and losses over a specified time period. The formula is as follows:RSI = 100 - (100 / (1 + RS))Where RS represents the average gain divided by the average loss over a given period.The RSI is typically displayed as an oscillator chart, with valuesranging from 0 to 100. Readings above 70 are considered overbought, indicating that the asset may be due for a price correction. Conversely, readings below 30 are considered oversold, suggesting that the asset may be poised for a rebound.Identifying Potential Breakout Points:One popular application of the RSI is to identify potential breakout points in the market. A breakout occurs when the price of an asset moves beyond a specific resistance or support level, signaling a potential change in the prevailing trend.Here's a step-by-step guide on how to use the RSI to identify potential breakout points:Step 1: Determine the Timeframe:Choose a timeframe that aligns with your trading strategy and individual preferences. The RSI can be used effectively on various timeframes, including intraday, daily, weekly, or monthly charts.Step 2: Identify the Trend:Determine the prevailing trend by analyzing the price action andtrend indicators such as moving averages. A breakout is more significant when it occurs in the direction of the prevailing trend.Step 3: Set the RSI Period:The default period for RSI is typically 14, but you can adjust it to suit your trading style. Shorter periods, such as 7 or 9, provide more timely signals, while longer periods, such as 21 or 30, offer smoother and less frequent signals.Step 4: Monitor RSI Levels:Watch for overbought or oversold readings on the RSI chart. When the RSI reaches extreme levels (above 70 or below 30) and starts to reverse, it may indicate a potential breakout point.Step 5: Confirm with Price Action:Cross-check the RSI signals with the price action. Look for bullish or bearish chart patterns, trendline breaks, or other technical indicators that confirm the potential breakout.Step 6: Plan Entry and Exit Strategies:Based on the RSI signals and price confirmation, develop a trading plan including entry and exit points, stop-loss levels, and potentialprofit targets. This step is crucial to manage risk and maximize potential gains.Step 7: Execute and Monitor the Trade:Once the breakout occurs and your predetermined conditions are met, execute the trade and closely monitor its progress. Adjust your stop-loss levels and take profits based on changes in price action and further RSI readings.Conclusion:The RSI is an effective tool for identifying potential breakout points and initiating trades. By combining it with other technical indicators and price confirmation, traders can enhance their decision-making process and increase the probability of successful trades. However, like any technical indicator, the RSI should not be used in isolation and should always be complemented with additional analysis and risk management strategies.。

恒清Ⅴ号方联合丙戊酸钠缓释片治疗

恒清Ⅴ号方联合丙戊酸钠缓释片治疗

恒清Ⅴ号方联合丙戊酸钠缓释片治疗癫痫的临床研究陈慧泽1,孟胜喜1,霍清萍1,王兵1,李文涛2,潘卫东3,曹健美4摘要:目的探讨恒清Ⅴ号方联合丙戊酸钠缓释片治疗癫痫(EP)的临床疗效,并探讨其作用机制㊂方法选取2020年1月 2021年1月于上海市第六人民医院就诊的90例癫痫病人作为研究对象,采用随机数字表法分为对照组和干预组,每组45例㊂对照组给予丙戊酸钠缓释片治疗,干预组给予恒清Ⅴ号方联合丙戊酸钠缓释片治疗,疗程均为2个月㊂观察两组的临床疗效,评估治疗前后两组病人的生活质量,观察治疗前后两组病人癫痫持续时间㊁癫痫发作次数㊁脑电相对功率,测定治疗前后两组病人血清S-100β㊁高迁移率族蛋白-1(HMGB-1)㊁脑源性神经营养因子(BDNF)㊁神经元特异性烯醇化酶(NSE)㊁肿瘤坏死因子-α(TNF-α)㊁白细胞介素-6 (IL-6)㊁C反应蛋白(CRP)及白细胞介素-8(IL-8)水平,并记录试验过程中出现的不良反应㊂结果对照组总有效率为69.77%,干预组总有效率为88.64%,干预组明显优于对照组(P<0.01)㊂治疗后,两组病人癫痫持续时间㊁癫痫发作次数均较治疗前减少,且干预组明显少于对照组(P<0.05或P<0.01);对照组的发作间期癫痫样放电(IEDs)消失比例为25.58%,而干预组IEDs消失比例为43.18%,干预组明显高于对照组(P<0.01);治疗后两组病人血清S-100β㊁HMGB-1㊁BDNF㊁NSE㊁IL-6㊁CRP㊁IL-8㊁TNF-α水平均较治疗前降低,且干预组明显低于对照组(P<0.05或P<0.01)㊂干预组不良反应总发生率为4.54%,对照组为6.99%,两组比较差异无统计学意义(P>0.05)㊂结论恒清Ⅴ号方联合丙戊酸钠缓释片可以显著提高癫痫病人临床疗效,明显抑制IEDs,改善癫痫病人的认知功能㊂其可能通过降低癫痫病人血清S-100β㊁HMGB-1㊁BDNF㊁NSE㊁IL-6㊁CRP㊁IL-8及TNF-α水平而发挥作用㊂关键词:癫痫;恒清Ⅴ号方;丙戊酸钠缓释片;作用机制d o i:10.12102/j.i s s n.1672-1349.2022.23.024Clinical Study of HengqingⅤFormula Combined with Compound Sodium Valproate and Valproic Acid Sustained Release Tablets in the Treatment of EpilepsyCHEN Huize,MENG Shengxi,HUO Qingping,WANG Bing,LI Wentao,PAN Weidong,CAO JianmeiShanghai Sixth People's Hospital Affiliated to Shanghai Jiao Tong University School of Medicine,Shanghai200233,China Corresponding Author:MENG Shengxi,E-mail:*****************Abstract:Objective To investigate the clinical efficacy of HengqingⅤformula combined with compound sodium valproate and valproic acid sustained release tablets in the treatment of epilepsy(EP),and to explore its mechanism.Methods A total of90epileptic patients were selected as the research objects and divided into control group and intervention group by random number table method, with45cases in each group.The control group was treated with compound sodium valproate and valproic acid sustained release tablets,and the intervention group was treated with HengqingⅤformula combined with compound sodium valproate and valproic acid sustained release tablets for2months.The clinical efficacy and the quality of life,the duration of epilepsy,the number of seizures,and the relative EEG power were observed before and after treatment.Serum S-100β,high mobility group protein-1(HMGB-1),brain-derived neurotrophic factor(BDNF),neuron-specific enolase(NSE),tumor necrosis factor-α(TNF-α),interleukin-6(IL-6),C-reactive protein(CRP), and interleukin-8(IL-8)were measured before and after treatment.The adverse reactions during the trial were recorded.Results The total effective rate of the control group was69.77%,and that of the intervention group was88.64%,the intervention group was significantly better than that in the control group(P<0.01).After treatment,the duration of epilepsy and the number of seizures in both groups were decreased than those before treatment,and the intervention group was significantly less than that in the control group(P< 0.05or P<0.01).After treatment,the disappearance rate of interepisodic epileptic discharges(IEDs)was25.58%in the control group, and that was43.18%in the intervention group,which was significantly higher than that in the control group(P<0.01).After treatment,the serum levels of S-100β,HMGB-1,BDNF,NSE,IL-6,CRP,IL-8,and TNF-αin both groups were decreased than those before treatment,and the intervention group was significantly lower than that in the control group(P<0.05or P<0.01).The total incidence of adverse reactions was4.54%in the intervention group and that was6.99%in the control group,and there was no statistical significance between two groups(P>0.05).Conclusion HengqingⅤformula combined with compound sodium valproate and valproic acid sustained release tablets can significantly improve the clinical efficacy of patients with epilepsy,significantly inhibit IEDs,improve the cognitive function of patients with epilepsy.It may play its role by reducing the serum levels of S-100β,HMGB-1,BDNF,NSE,IL-6,CRP,IL-8,and TNF-αin epileptic patients.Keywords:elilepsy;HengqingⅤformula;compound sodium valproate and valproic acid sustained release tablets;mechanism基金项目上海市科委2019年度 科技创新行动计划 临床医学领域科技支撑项目(No.19401970600);上海市科委中医引导类项目(No. 19401932500);上海市第六人民医院2022年度抗击新冠肺炎疫情应急专题项目(No.ynxg202218);上海市进一步加快中医药传承创新发展三年行动计划(2021年 2023年)[No.ZY(2021-2023)-0205-04)];华东片区及市级中医专科专病联盟建设项目[No.ZY(2021-2023)-0302)]作者单位 1.上海交通大学医学院附属第六人民医院(上海200233);2.上海市中医医院;3.上海中医药大学附属曙光医院;4.上海中医药大学研究生院通信作者孟胜喜,E-mail:*****************引用信息陈慧泽,孟胜喜,霍清萍,等.恒清Ⅴ号方联合丙戊酸钠缓释片治疗癫痫的临床研究[J].中西医结合心脑血管病杂志,2022,20(23):4346-4350.癫痫(elilepsy,EP)是以反复性㊁发作性㊁短暂性㊁刻板性的中枢神经系统功能失常为特征的脑部神经元高度同步化且具自限性的异常放电所导致的综合征,由于异常放电神经元的位置不同,放电和扩散的范围不等,病人发作可表现为感觉㊁运动㊁意识㊁精神㊁行为㊁自主神经功能障碍或兼而有之[1-2]㊂目前,全球有7000万例以上的癫痫病人[3],我国则有900万例以上的癫痫病人,其中活动性癫痫病人有500万~600万例,同时每年新发癫痫病人65万~70万例[4],给社会和家庭造带来沉重的社会负担㊁照顾负担和经济负担㊂中医药具有多层次㊁多靶点㊁多途径及副作用少的优势和特点,在防治癫痫方面发挥着越来越重要的作用㊂本研究探讨中药复方恒清Ⅴ号方联合丙戊酸钠缓释片对癫痫病人的作用及其机制㊂1资料与方法1.1一般资料选取2020年1月 2021年1月于上海市第六人民医院就诊的90例癫痫病人作为研究对象,采用随机数字表法分为对照组和干预组,每组45例㊂在试验过程中,对照组有2例因自行停药而退出试验(1例因出现恶心㊁胃脘部不适而自行停药,1例因出现头晕而自行停药),共完成43例;干预组有1例因病人依从性差未完成试验,共完成44例㊂两组病人一般资料比较,差异均无统计学意义(P>0.05)㊂详见表1㊂表1两组病人一般资料比较组别对照组(n=43)干预组(n=44)P 性别(例)男2325>0.05女2019年龄(岁)43.16ʃ11.2545.26ʃ12.58>0.05体质指数(BMI,kg/m2)25.15ʃ5.1324.03ʃ5.74>0.05病程(年) 6.35ʃ1.22 6.04ʃ1.37>0.05发作类型[例(%)]简单部分发作17(39.53)16(36.36)复杂部分发作11(25.58)12(27.27)>0.05强直阵挛性发作10(23.26)9(20.45)强直发作5(11.63)7(15.92)病因[例(%)]遗传22(51.16)23(52.27)疾病11(25.58)12(27.27)>0.05其他10(23.26)9(20.46)1.2诊断标准符合中华医学会神经病学分会癫痫与脑电图学组2006年‘成人癫痫诊断和药物治疗规范(草案)“[5]中癫痫的诊断标准㊂1.3纳入与排除标准纳入标准:年龄20~65岁,性别不限;癫痫发作次数ȡ4次/月;近4周内未使用抗癫痫药物或影响癫痫发作的药物;依从性好;自愿参与本研究并签署知情同意书㊂排除标准:合并心㊁肺㊁肝㊁肾等严重器质性疾病;合并严重精神疾病或精神障碍;治疗期间不耐受;治疗后失访㊂1.4治疗方法对照组给予口服丙戊酸钠缓释片[商品名:德巴金,赛诺菲(杭州)制药有限公司生产,规格:每片500mg,国药准字H20010595,批准文号: BHG0357],每次500mg,每日2次,口服㊂干预组在对照组基础上服用中药复方恒清Ⅴ号方,组方:胆南星15g,僵蚕10g,全蝎2g,石菖蒲15g,蝉蜕10g,川芎15g,由上海交通大学附属第六人民医院中药房提供,水煎250mL,早晚分服,每日1剂㊂两组疗程均为2个月㊂1.5观察指标1.5.1临床疗效临床疗效分为临床控制㊁显效㊁有效和无效㊂临床控制为症状显著改善,脑电图明显改善且病人癫痫发作次数减少ȡ90%;显效为症状有所改善,脑电图明显改善且病人癫痫发作次数减少75%~< 90%;有效为症状稍有改善,脑电图明显改善且病人癫痫发作次数减少50%~<75%;无效为症状无改善,甚至加重,脑电图明显改善且病人癫痫发作次数减少的比例减少<50%[6]㊂1.5.2生活质量采用癫痫病人生活质量评定量表(QOLIE-31)进行生活质量评估㊂QOLIE-31量表包括以下7个方面:发作担忧㊁整体健康状态㊁情感情绪㊁精力㊁认知功能㊁药物作用㊁社会功能,共31个条目,每项分值为1~6分,分值越高表明其生活质量越好㊂1.5.3癫痫发作情况记录治疗前后两组癫痫持续时间㊁发作次数㊂1.5.4脑电相对功率采用脑电图仪(型号: NOTION2800,美国尼高力公司生产)进行视频脑电图检查,记录常规脑电图20min内发作间期癫痫样放电(interictal epileptiform discharges,IEDs)次数㊂分别统计IEDs数目消失㊁减少ȡ50%㊁IEDs数目减少25%~49%以及无变化的病例数㊂1.5.5实验室指标分别于治疗前后采集两组病人空腹静脉血5mL,以3000r/min室温离心10min,取上清液,采用双抗体夹心固相酶联免疫吸附实验检测癫痫病人血清S-100β㊁高迁移率族蛋白-1(HMGB-1)㊁脑源性神经营养因子(BDNF)㊁神经元特异性烯醇化酶(NSE)㊁肿瘤坏死因子-α(TNF-α)㊁白细胞介素-6(IL-6)㊁C反应蛋白(CRP)及白细胞介素-8(IL-8)水平,试剂盒均购自上海信裕生物科技有限公司㊂1.5.6不良反应记录两组病人恶心㊁腹胀㊁腹痛㊁头晕㊁乏力㊁皮疹等不良反应发生情况㊂1.6统计学处理采用SPSS25.0软件进行数据分析㊂两样本总体方差齐性检验采用F检验;定量资料以均数ʃ标准差(xʃs)表示,组间比较采用独立样本t检验,组内比较采用配对t检验;定性资料以例数或百分比(%)表示,采用χ2检验㊂以P<0.05为差异有统计学意义㊂2结果2.1两组临床疗效比较对照组总有效率为69.77%,干预组总有效率为88.64%,干预组明显优于对照组,差异有统计学意义(P<0.01)㊂详见表2㊂表2两组临床疗效比较单位:例(%)组别例数临床控制显效有效无效总有效对照组4314(32.56)10(23.26)6(13.95)13(30.23)30(69.77)干预组4418(40.91)13(29.55)8(18.18)5(11.36)39(88.64)注:两组总有效率比较,P<0.01㊂2.2两组治疗前后癫痫发作情况比较治疗前,两组病人癫痫持续时间㊁癫痫发作次数比较,差异均无统计学意义(P>0.05);治疗后,两组病人癫痫持续时间㊁癫痫发作次数均较治疗前减少,且干预组明显少于对照组,差异均有统计学意义(P<0.05或P<0.01)㊂详见表3㊂2.3两组治疗前后生活质量比较治疗前,两组病人QOLIF-31评分比较,差异无统计学意义(P>0.05);治疗后,两组病人QOLIF-31评分较治疗前升高,且干预组病人QOLIF-31评分明显高于对照组,差异均有统计学意义(P<0.05或P<0.01)㊂详见表4㊂表3两组治疗前后癫痫持续时间㊁癫痫发作次数比较(xʃs)组别例数时间癫痫持续时间(min)癫痫发作(次/月)对照组43治疗前32.58ʃ4.367.96ʃ2.06治疗后25.74ʃ2.15① 4.27ʃ1.08①干预组44治疗前33.02ʃ5.137.63ʃ2.14治疗后19.42ʃ2.39②③ 1.93ʃ0.41②③与同组治疗前比较,①P<0.05,②P<0.01;与对照组治疗后比较,③P<0.01㊂表4两组病人治疗前后QOLIE-31评分比较(xʃs)单位:分组别例数时间发作担忧整体健康状态情感情绪对照组43治疗前45.56ʃ14.2351.12ʃ15.3941.41ʃ14.65治疗后52.37ʃ16.34①58.22ʃ11.08①50.14ʃ15.12①干预组44治疗前46.41ʃ15.3652.43ʃ16.1142.60ʃ15.02治疗后65.23ʃ17.26②③69.67ʃ15.13②③68.46ʃ16.08②③组别时间精力认知功能药物作用社会功能对照组治疗前39.25ʃ12.7141.02ʃ13.1148.17ʃ10.1451.36ʃ12.88治疗后52.33ʃ14.32①52.35ʃ12.42①53.26ʃ13.24①60.25ʃ14.34①干预组治疗前40.37ʃ11.2543.14ʃ14.5847.42ʃ11.6353.47ʃ14.05治疗后66.87ʃ15.10②③63.30ʃ18.44②③66.34ʃ15.90②③71.46ʃ16.15②③与同组治疗前比较,①P<0.05,②P<0.01;与对照组治疗后比较,③P<0.01㊂2.4两组治疗后IEDs变化比较对照组IEDs消失比例为25.58%,干预组IEDs消失比例为43.18%,干预组IEDs消失比例明显高于对照组,差异有统计学意义(P<0.01)㊂详见表5㊂表5两组治疗后IEDs变化比较单位:例(%)组别例数消失减少>50%减少25%~49%无变化对照组4311(25.58)10(23.26)9(20.93)13(30.23)干预组4419(43.18)①14(31.82)10(22.73)1(2.27)与对照组比较,①P<0.01㊂2.5两组治疗前后血清S-100β㊁HMGB-1㊁BDNF㊁NSE㊁IL-6㊁CRP㊁IL-8㊁TNF-α水平比较治疗前,两组病人血清S-100β㊁HMGB-1㊁BDNF㊁NSE㊁IL-6㊁CRP㊁IL-8㊁TNF-α水平比较,差异均无统计学意义(P>0.05)㊂治疗后,两组病人血清S-100β㊁HMGB-1㊁BDNF㊁NSE㊁IL-6㊁CRP㊁IL-8㊁TNF-α水平均较治疗前降低,且干预组以上指标明显低于对照组,差异均有统计学意义(P<0.05或P<0.01)㊂详见表6㊂表6两组治疗前后血清S-100β㊁HMGB-1㊁BDNF㊁NSE㊁IL-6㊁CRP㊁IL-8㊁TNF-α水平比较(xʃs)组别例数时间S-100β(μg/L)HMGB-1(μg/L)BNDF(ng/mL)NSE(μg/L)对照组43治疗前0.98ʃ0.289.1ʃ2.737.23ʃ7.9618.36ʃ4.25治疗后0.88ʃ0.20① 6.9ʃ2.1①32.26ʃ6.21①15.36ʃ3.26①干预组44治疗前0.99ʃ0.258.9ʃ2.338.12ʃ7.0518.47ʃ4.72治疗后0.63ʃ0.18②③ 4.7ʃ1.6②③25.02ʃ6.14②③9.36ʃ2.02②③组别时间IL-6(pg/mL)CRP(mg/L)IL-8(pg/mL)TNF-α(pg/mL)对照组治疗前14.52ʃ2.0328.42ʃ6.2315.79ʃ4.03 4.06ʃ0.88治疗后11.07ʃ3.06①25.56ʃ4.75①11.15ʃ2.36① 2.37ʃ0.32①干预组治疗前15.11ʃ3.3629.13ʃ6.8815.14ʃ4.61 4.12ʃ0.76治疗后 6.15ʃ3.24②③19.71ʃ3.26②③7.02ʃ1.03②③0.84ʃ0.10②③与同组治疗前比较,①P<0.05,②P<0.01;与对照组治疗后比较,③P<0.01㊂2.6两组不良反应发生率比较对照组不良反应发生率为6.99%,干预组为4.54%,两组比较差异无统计学意义(P>0.05)㊂详见表7㊂表7两组病人不良反应发生率比较组别例数恶心[例(%)]腹胀[例(%)]头晕[例(%)]皮疹[例(%)]总发生率(%)对照组431(2.33)1(2.33)0(0.00)1(2.33) 6.99干预组441(2.27)0(0.00)1(2.27)0(0.00) 4.543讨论癫痫属中医学 癫疾 痫证 等范畴㊂其病因与痰㊁火㊁惊㊁风㊁气关系密切,特别是以痰邪作祟为主㊂肝风内动㊁痰瘀互结是癫痫的夙根,因此熄风化痰㊁活血化瘀应作为本病的主要治法㊂现代医学研究表明,神经胶质细胞与癫痫发生密切相关,星形胶质细胞在癫痫发作中有重要作用[7]㊂S-100β是神经胶质细胞损伤标志物[8],癫痫发作后脑胶质细胞发生坏死㊁激活㊁增生等一系列改变㊂S-100β作为一种钙结合蛋白参与了Ca2+介导的信号转导通路,而Ca2+在癫痫发病中有重要作用,癫痫发作可使S-100β升高,后者升高后可改变神经元的电活动,从而促使癫痫发作[9]㊂在动脉粥样硬化的形成过程中,血管内皮细胞㊁内膜平滑肌细胞及巨噬细胞均大量表达HMGB1[10]㊂HMGB1可通过与血小板㊁巨噬细胞㊁少突胶质细胞中Toll样受体(TLRs)和晚期糖基化终产物受体(RAGE)的相互作用,诱导白细胞介素和基质金属蛋白酶的表达,从而引发动脉粥样硬化,促进神经细胞的炎症以及脑部动脉血管中血栓的形成㊂研究显示,癫痫发作后,动物大脑皮层中BDNF含量明显增加,表明BDNF可能在癫痫发病过程中有非常重要的作用[11]㊂在海马BDNF过度表达的转基因小鼠中,苔藓纤维(mossyfiber)向CA3区扩增,并随着年龄的增长将会发展为自发性癫痫,表明内源性BDNF的慢性增加改变了海马的组织结构,随着时间的变化,可能会促进癫痫的发生[12]㊂NSE是神经元受损后的特异性标志物,当机体处于癫痫状态,由于神经细胞不同程度损伤, NSE将大量释放到脑脊液之中[13]㊂IL-6㊁CRP㊁IL-8㊁TNF-α均为炎性因子㊂目前研究表明,炎症和免疫反应在癫痫的病理生理机制中有重要作用,且癫痫持续状态所致脑损伤引起的炎性应答与癫痫复发关系密切[14]㊂炎性反应在脑组织癫痫病灶形成中的作用,已在颞叶癫痫耐药和灰质发育异常有关的癫痫病人中体现[15]㊂动物研究也表明,炎性介质(细胞因子㊁补体因子等)参与了癫痫的发作,干预以上分子或其相应的受体可减轻癫痫发作的频率和程度[16]㊂恒清Ⅴ号方是本课题组经过长期临床实践总结㊁归纳和验证的治疗癫痫疗效确切的中药经验复方㊂恒清Ⅴ号方的组成为:胆南星15g,僵蚕10g,全蝎2g,石菖蒲15g,蝉蜕10g,川芎15g㊂胆南星,性凉,味苦微辛,归肺㊁肝㊁脾经,清热化痰㊁息风定惊;僵蚕,咸㊁辛㊁平,归肝㊁肺㊁胃经,息风止痉㊁祛风化痰,两者共为君药㊂全蝎,辛㊁平,归肝经,息风止痉㊁解毒散结㊁通络止痛;石菖蒲,辛㊁温,归心㊁胃经,祛痰开窍㊁化湿㊁宁神益智;蝉蜕,甘㊁寒,归肺㊁肝经,疏散风热㊁息风止痉;川芎,辛㊁温,归肝㊁胆㊁心包经,活血行气㊁祛风止痛,以上四味药物共为臣药㊂全方有息风化痰㊁定惊㊁活血化瘀之效,从而可有效治疗癫痫㊂现代药理学研究发现,高剂量胆南星抗惊厥作用显著[17]㊂白僵蚕醇提物可以抑制由戊四氮惊厥模型(MET)建立的最大电休克模型(MES)癫痫大发作试验模型[18]㊂赵晋炜等[19]提取分离了18种单味中药,发现全蝎醇提物的抗MES能力最佳㊁效价最大,可持续作用7h㊂王坤芳等[20]建立4种动物惊厥模型,发现石菖蒲挥发油可以将大鼠电刺激皮层惊厥阈值明显提高,持续作用时间较长,并呈剂量依赖性㊂何欣嘏[21]研究发现,蝉蜕醇提物对MES模型㊁MET发作和青霉素点燃惊厥发作均有对抗作用㊂川芎嗪联用苯妥英钠可以提高癫痫大鼠脑内苯妥英钠的浓度并提高苯妥英钠治疗癫痫的效果,川芎嗪对苯妥英钠抗不同时间(急性期)癫痫等级评分有明显的降低作用[22]㊂本研究结果显示,对照组总有效率为69.77%,干预组总有效率为88.64%,干预组明显优于对照组(P<0.01)㊂治疗后,两组病人癫痫持续时间㊁癫痫发作次数均少于治疗前,且干预组明显少于对照组(P< 0.05或P<0.01);对照组的发作间期IEDs消失比例为25.58%,而干预组IEDs为43.18%,干预组明显高于对照组(P<0.01);治疗后两组病人血清S-100β㊁HMGB-1㊁BDNF㊁NSE㊁IL-6㊁CRP㊁IL-8㊁TNF-α水平均较治疗前降低,且干预组明显低于对照组(P<0.05或P<0.01)㊂干预组不良反应总发生率为4.54%,对照组为6.99%,两组比较差异无统计学意义(P>0.05)㊂综上所述,恒清Ⅴ号方联合丙戊酸钠缓释片可明显提高癫痫病人的临床疗效㊁抑制IEDs㊁改善病人的认知功能,其可能通过降低癫痫病人血清S-100β㊁HMGB-1㊁BDNF㊁NSE㊁IL-6㊁CRP㊁IL-8及TNF-α水平而发挥其作用㊂参考文献:[1]THIJS R D,SURGES R,O'BRIEN T J,et al.Epilepsy in adults[J].The Lancet,2019,393(10172):689-701.[2]VAURIO L,KARANTZOULIS S,BARR W B.The impact of epilepsyon quality of life[J].Changes in the Brain,2016:167-187. [3]LANCET T.From wonder and fear:make epilepsy a global healthpriority[J].Lancet,2019,393(10172):612.[4]魏惠,赵文艳,高学军.癫痫药物治疗研究进展[J].临床误诊误治,2017,30(6):108-112.[5]中华医学会神经病学分会癫痫与脑电图学组.成人癫痫诊断和药物治疗规范(草案)[J].中华内科杂志,2006,45(10):875-877. [6]中华医学会神经病学分会脑电图与癫痫学组.抗癫痫药物应用专家共识(节选)[J].中华医学信息导报,2011,26(4):20-21. [7]WETHERINGTON J,SERRANO G,DINGLEDINE R.Astrocytes inthe epileptic brain[J].Neuron,2008,58(2):168-178.[8]NAEIMI Z S,WEINHOFER A,SARAHRUDI K,et al.Predictivevalue of S-100B protein and neuron specific-enolase as markersof traumatic brain damage in clinical use[J].Brain Injury,2006,20(5):463-468.[9]SAKA T ANI S,SETO-OHSHIMA A,SHINOHARA Y,et al.Neural-activity-dependent release of S100B from astrocytes enhances kainate-inducedgamma oscillations in vivo[J].The Journal of Neuroscience,2008,28(43):10928-10936.[10]KALININA N,AGROTIS A,ANTROPOV A Y,et al.Increased expression ofthe DNA-binding cytokine HMGB1in human atheroscleroticlesions:role of activated macrophages and cytokines[J].Arteriosclerosis,Thrombosis,and Vascular Biology,2004,24(12):2320-2325.[11]DESOUZA BERNARDINO T C,TEIXEIRA A L,MIRANDA A S,et al.Wistar Audiogenic Rats(WAR)exhibit altered levels of cytokinesand brain-derived neurotrophic factor following audiogenicseizures[J].Neuroscience Letters,2015,597(4):154-158. [12]ISGOR C,PARE C,MCDOLE B,et al.Expansion of the dentatemossy fiber-CA3projection in the brain-derived neurotrophicfactor-enriched mouse hippocampus[J].Neuroscience,2015,288:10-23.[13]HUCHTEMANN T,KÖRTVÉLYESSY P,FEISTNER H,et al.Progranulinlevels in status epilepticus as a marker of neuronal recovery andneuroprotection[J].Epilepsy&Behavior,2015,49(6):170-172. [14]BARTFAI T,SANCHEZ-ALA VEZ M,ANDELL-JONSSON S,et al.Interleukin-1system in CNS stress:seizures,fever,and neurotrauma[J].Annalsof the New York Academy of Sciences,2007,1113:173-177. [15]BOER K,JANSEN F,NELLIST M,et al.Inflammatory processes incortical tubers and subependymal giant cell tumors of tuberoussclerosis complex[J].Epilepsy Research,2008,78(1):7-21. [16]VEZZANI A,BALOSSO S,RAVIZZA T.The role of cytokines in thepathophysiology of epilepsy[J].Brain,Behavior,and Immunity,2008,22(6):797-803.[17]李瑶.胆南星炮制前后成分变化及质量标准研究[D].南京:南京中医药大学,2018.[18]姚宏伟,何欣嘏,何巧燕,等.僵蚕和蜈蚣醇提物抗惊厥作用的药效学比较研究[J].中国药物与临床,2006,6(3):221-223. [19]赵晋炜,程景民.18种单味中药提取物抗惊厥作用的药效学比较研究[J].中西医结合心脑血管病杂志,2015,13(5):593-596. [20]王坤芳,杨育同,梁志刚,等.石菖蒲挥发油抗惊厥作用及对癫痫大鼠海马PKC表达的影响[J].中药药理与临床,2015,31(1):97-100.[21]何欣嘏.五种中药醇提物抗惊厥作用的药效学比较研究[D].太原:山西医科大学,2006.[22]赖伟华,许百虹,夏晨.川芎嗪对癫痫大鼠脑内苯妥英钠浓度与疗效的影响研究[J].中药材,2015,38(3):598-600.(收稿日期:2021-07-20)(本文编辑邹丽)。

(完整版)新视野大学英语(第三版)视听说教程2完整答案

(完整版)新视野大学英语(第三版)视听说教程2完整答案

新视野大学英语(第三版)视听说教程 2答案Unit 1 (1)Sharing ........................................................................................... 1...Listening ......................................................................................... 2...Viewing .......................................................................................... 3...Role-play ........................................................................................ 3...Conversations ................................................................................ 4...Passage ......................................................................................... 4 .Unit test .......................................................................................... 5... Unit 2 . (6)Sharing ........................................................................................... 6...Listening ......................................................................................... 7...Viewing .......................................................................................... 7...Role-play ........................................................................................ 8...Presenting ...................................................................................... 9...Conversations ................................................................................ 9...Passage ............................................................................................................... 1.0 ...Unit test ........................................................................................ 1..1. Unit 3 .. (12)Sharing ......................................................................................... 1..2.Listening ....................................................................................... 1..2.Viewing ........................................................................................ 1..3.Presenting .................................................................................... 1..5.Conversations ............................................................................... 1.5.Passage .............................................................................................................. 1.6. ..Unit test ........................................................................................ 1..7. Unit 4 . (18)Sharing ......................................................................................... 1..8.Listening ....................................................................................... 1..9.Viewing ........................................................................................ 1..9.Role-play ...................................................................................... 2..0.Presenting .................................................................................... 2..1.Conversations ............................................................................... 2.2.Passage .............................................................................................................. 2.2. ..Unit test ........................................................................................ 2..3. Unit 5 . (24)Sharing .............................................................................................................. 2..4 .Listening .............................................................................................................. 2..5 .Viewing .............................................................................................................. 2..6 .Role-play .............................................................................................................. 2..6 .Passage .............................................................................................................. 2.7. ..Unit test ........................................................................................ 2..8. Unit 6 (29)Sharing ......................................................................................... 2..9.Listening ....................................................................................... 3..0.Viewing ........................................................................................ 3..0.Role-play ...................................................................................... 3..1.Presenting .................................................................................... 3..2.Conversations ............................................................................... 3.2.Passage .............................................................................................................. 3.2. ..Unit test ........................................................................................ 3..3. Unit 7 (34)Sharing ......................................................................................... 3..4.Listening ....................................................................................... 3..5.Viewing ........................................................................................ 3..6.Role-play ...................................................................................... 3..6.Presenting .................................................................................... 3..7.Conversations ............................................................................... 3.8.Passage .............................................................................................................. 3.9. ..Unit test ........................................................................................ 3..9. Unit 8 (41)Listening ....................................................................................... 4..2.Viewing .............................................................................................................. 4..2 .Role-play .............................................................................................................. 4..3 .Presenting .............................................................................................................. 4..4 .Conversations ............................................................................... 4.4.Passage .............................................................................................................. 4.5. ..Unit test .............................................................................................................. 4..6 .Unit 1 SharingTask 2(1) new things(2) At the moment(3) quite difficult Task 31, 3, 7, 8Task 41. (1) ever learned2. (1) a combination3. Learning to drive4. (1) nine cases5. French6. hated ListeningTask 2Activity 1e-c-a-g-d-h-b-f (2) found(2) body movements (2) by most standards(1) speak(2) saying the wrong(3) native speakers(4) pronunciation(5) talking to himself(6) making mistakes(7) listening skills(8) listeningActivity 31. (1) embarrassed (2) hear2. anything you like3. (1) voice (2) pronunciation4. (1) how it sounds (2) the news (3) English television5. on the Internet6. sound likeViewingTask 2Activity 1BABADABADRole-playTask 2Activity 11Activity 2G:1, 3, 5 R:2, 4, 6, 7 Activity 31. (1) you should eat (2) a good2. (1) should not spend (2) You're3. (1) Why don't (2) am not sure that's4. (1) it's a good (2) suppose so ConversationsTask 1BDDCATask 2CDACPassageTask 1DACDTask 2(1) alternative(2) numerous(3) traditional(4) academic(5) countryside(6) athletes(7) take advantage of(8) Secondary(9) in a collective effort(10) serve as Unit testPart ICBBCCPart IIBADCBPart IDAADBCPart IV(1) political(2) Traditional(3) acquire(4) bear in mind(5) difficult(6) invented(7) successful(8) reason for(9) thousands of(10) brainsUnit 2SharingTask 2(1) different countries(2) home(3) places(4) culturesTask 31, 4, 5Task 41. mature2. airport3. theater4. scenery5. culture6. languageTask 5 b-a-d-f-c-e Listening Task 2Activity 11. slowly sinking2. two and a half3. try and stop4. temporary5. permanentActivity 23, 4, 5ViewingTask 2Activity 1DBBCDActivity 21. busy2. bars3. friendliness4. elegant5. views6. (1) beaches (2) cheap7. (1) changing (2) sunset8. criedRole-play Task 2Activity 13Activity 2(1) trying to(2) takes(3) looking for(4) right way(5) the first left(6) until you reach(7) get to(8) Is it far(9) Go left(10) on the left Presenting Task 1(1) isolated(2) far(3) plane(4) three months(5) culture(6) way of life(7) speak to(8) find out(9) history(10) dreams Conversations Task 1ADBCDTask 2ADCA PassageTask 1DABDTask 2(1) scared(2) perceive(3) negative(4) result in(5) lose faith in(6) goes down(7) depressed(8) preferably(9) adapt(10) revealUnit testPart IABBAAPart IIBCADPart IDCADBPart IV(1) vacation(2) walks of life(3) routine(4) adventure(5) treat(6) popularity(7) gain a better understanding of(8) similarities(9) perspective(10) marvelousUnit 3SharingTask 2(1) concerts(2) a bar(3) bandTask 31. (1) keep fit (2) theaterTask 41, 6ListeningTask 2(1) free art exhibition(2) a concert2. (1) small children3. (1) eating and drinking4. (1) friends around5. (1) love to read6. (1) playing the guitar (2) seeing friends (2) houses (2) a jazz club (2) oil painting (2) watching films(3) dinner(4) bus home(5) museum(6) paintings(7) entertainers(8) comedy(9) comedy club(10) Covent Garden ViewingTask 2Activity 1(1) sightseeing(2) beach(3) get away from(4) relaxing(5) a dozen(6) fantastic(7) attitude(8) perfectActivity 2Activity 3c-e-f-b-a-dRole-playTask 2Activity 1(1) Book a table(2) 4(3) Saturday(4) 10 o'clock(5) two tickets(6) Starr(7) June the fifth(8) June the ninth(9) dinner with friends(10) eight-thirty(11) Saturday(12) dinner tonight(13) 098845673 Activity 2(1) repeat(3) catch(4) slow down(5) speak up Presenting Task 1Activity 1e-d-b-f-a-c Activity 2b-a-c-e-dConversations Task 1DCCBCTask 2DAAD PassageTask 1AADDTask 2(1) objectives(2) farthest(3) recognized(4) separated into(5) involves(6) is referred to(7) life-threatening(8) designed(9) endurance(10) putting themselves at risk Unit testPart IACBBBPart IIDBDCAPart IDCDCCPart IV(1) have a passion for(2) looked upon(3) take risks(4) probably(5) ignore(6) attractive(7) familiar(8) obviously(9) powerful(10) requiresUnit 4 SharingTask 2(1) finding out(2) a normal person(3) feel about fame Task 32, 3, 4Task 41. exciting2. worthwhile3. a model4. real fame5. invention6. in the street Task 5b-a-c-f-e-d ListeningTask 2(1) advertising(2) enjoy the job(3) travel(4) chance(5) go traveling(6) a doctor(7) have time(8) play the piano(9) writing songs(10) make more time ViewingTask 2Activity 11. (1) the attitude (2) the talent2. speed3. (1) Formula One (2) big guys4. ambitious driversActivity 2(1) speed(2) survive(3) October(4) richest(5) track(6) bank(7) glory(8) betterActivity 3(1) 7(2) 4(3) everythingRole-playTask 2Activity 1(1) White House(2) tomorrow afternoon(3) a space flight(4) next week(5) her husband(6) 80(7) three or four(8) organize(9) this weekend(10) restaurant service(11) French(12) Paris(13) directions(14) bookActivity 2R:1, 2, 4 O:3, 5, 6 PresentingTask 11. South Wales2. a rock star3. his dream4. (1) drum kit (2) write songs5. apart fromConversations Task 1BBCDDTask 2ABBDPassageTask 1BDACTask 2(1) commentators(2) exaggerated(3) focus on(4) lead an active life(5) laid the foundation(6) annual(7) a series of(8) advocating(9) abolish(10) influential Unit testPart ICACCCPart IICBBAPart IDBCCBAPart IV(1) champion(2) challenges(3) Regardless of(4) inspiration(5) remarkable(6) legendary(7) dominance(8) appeal in(9) aspire to(10) magnificentUnit 5SharingTask 2(1) cities(2) mix of people(3) peace and quietTask 3d-e-a-c-f-bTask 41, 2, 5Task 51. horribly2. get round3. (1) on the go (2) take time out (3) missing out4. green transport5. (1) crime (2) committing crimesListeningTask 2(1) shopping(2) good nightlife(3) safe(4) cheap(5) terrible(6) restaurants(7) fantastic(8) fast(9) green(10) crowded(11) friendly(12) atmosphere(13) clean(14) safe(15) see(16) do(17) beautiful(18) perfect(19) culture(20) too much ViewingTask 21. a combined age2. (1) forgotten(4) 16 times3. 404. (1) available online Role-playTask 2Activity 1 Conversation 11. a hotel2. The air conditioning3. send someone up Conversation 21. a restaurant2. (1) 20 minutes3. busy time (2) stuck indoors(5) closure(2) 2 million(2) the service charge(3) felt right(6) meetConversation 31. a train station2. an hour3. wrong type of snowActivity 2C:1, 2, 5 R:3, 4, 6 ConversationsTask 1AABADTask 2AADBPassageTask 1BDCDTask 2(1) join up(2) reaction(3) makes increasing sense(4) sustainable(5) aims(6) monitored(7) access to(8) experimenting with(9) eye-catching(10) commutingUnit testPart IBCDABPart IIBCDACPart IDDCBDDPart IV(1) widespread(2) property(3) penetrates(4) robbed(5) victim(6) argue about(7) contribute to(8) population(9) remains unsolved(10) proposed Unit 6 SharingTask 2(1) a researcher(2) gets too busy(3) relax(4) flatTask 33, 4Task 4c-e-a-d-b-f ListeningTask 2(1) a free bus(2) a dentist(3) Lunch(4) a cheap(5) a surprise holiday(6) free coffee(7) bring their children(8) free drinks(9) go fishing(10) all the fish ViewingTask 2(1) traveling to work(2) live abroad(3) cheap houses(4) an online map company(5) working(6) drive(7) 700(8) 38 pounds(9) quality of life(10) the trafficRole-playTask 2Activity 11, 3Activity 21. like2. can't stand3. absolutely love4. (1) don't like5. don't mind6. keen on7. hate8. (1) not very keen on (2) prefer (2) want to bePresentingTask 1Activity 11. (1) shaped (2) faces2. (1) personal (2) special message3. at home4. beautiful websiteActivity 2c-e-a-b-dConversationsTask 1BDACCTask 2ADBBPassageTask 1BBADTask 2(1) evaluate(2) compensation(3) negotiating(4) confirm(5) schedule(6) circumstances(7) turn down(8) start over(9) work out(10) informed Unit testPart IBACCDPart IIBDDCCPart IDCADBC(1) opportunities(2) practical(3) define(4) compassion(5) focusing on(6) significance(7) think big(8) plays a huge role(9) attend(10) Contented Unit 7 SharingTask 2(1) enjoy(2) live without(3) plan my life(4) listening to musicb-e-f-a-d-cTask 51. (1) on it all the time (2) my husband2. (1) my laptop (2) phone (3) essential3. beyond that4. (1) computer (2) InternetListeningTask 2Activity 11, 2Activity 21. on the Internet2. videos3. (1) a break (2) someone in the office (3) looking through4. reading books5. (1) the computer (2) sports and going out (3) live in the real worldViewi ng Task 2 Activity 1 1,4Activity 2 CBDDC Role-play Task 2 Activity 1Reasons(1) all the time(2) text ing(3) watch much television(4) terrible(5) for work(6) an emerge ncy(7) a problem with(8) go on the Internet(9) Some one else Activity 2Speaker 1: c-a-b Speaker 2:b-a-cPrese ntingTask 1(1) 2(2) n ear the sea(3) real achievement(4) 12(5) talked online(6) hello(7) lonely(8) a new girl(9) bored(10) my real friends(11) a club(12) good-looking(13) start talking to him(14) on the dance floor(15) haven't been dancing ConversationsTask 1BCDDCTask 2BBACPassageTask 1DAADTask 2(1) response(2) illegal(3) in charge of(4) consequently(5) relied heavily on(6) linked to(7) anticipate(8) familiar with(9) remedy(10) betraying Unit testPart IADBCBPart IIBCADCPart IDABCDDPart IV(1) refer to(2) involves(3) unique(4) valuable(5) at your expense(6) associated with(7) responsible(8) minimize(9) regularly(10) maintainUnitSharingTask 2(1) come from(2) most of my family(3) talking to peopleTask 3c-e-a-f-b-dTask 41. (1) height (2) same traits (3) think aboutthings2. (1) my sister (2) similar to (3) mathematical3. (1) a younger version (2) organized (3) louder4. quite calm5. (1) my brothers (2) quite differentTask 52, 6ListeningTask 2(1) 1689(2) advisor(3) soldiers(4) sailors(5) dull(6) incredibly(7) surname(8) great fun ViewingTask 2(1) islands(2) There are no rules(3) an account(4) a digital(5) male(6) half animal(7) edit(8) short(9) face(10) features(11) pick(12) personality(13) online stores(14) over three million(15) chatRole-playTask 2Activity 1Conversation 11. speaking and listening2. conversationConversation 21. summer camp2. Different agesConversation 31. online classes2. demandingActivity 2(1) So for me the most important thing is to(2) I suppose I'd have to say(3) In my opinion(4) One thing I'd like to say is that PresentingTask 1Activity 1(1) BBC breakfast TV(2) hair color(3) businesswoman(4) personality(5) buildingActivity 21, 3, 4, 5, 6ConversationsTask 1BCCDATask 2CDABPassageTask 1CCABTask 2(1) infancy(2) assumed(3) inherited(4) rooted in(5) fairs(6) compensate for(7) cement(8) witness(9) exposed to(10) contributed to Unit testPart IBBCCBPart IIBDAAPart IDBCCAAPart IV(1) kicked out of(2) hang out(3) involved(4) useless(5) failure(6) fell in love with(7) positive(8) especially(9) took off(10) succeed。

【精品】电子信息工程专业英语课后答案

【精品】电子信息工程专业英语课后答案

电子信息工程专业英语课后答案电子信息工程专业英语-教师用书Part 1第一课关于电子技术一、课文习题参考答案Ⅰ. (1) alternating current circuits (2) semiconductor diodes(3) passive component(4) the combinatory logic electric circuit(5) rectification(6) Laplace transform(7) inductor(8) Fourier series and Fourier transformⅡ.(1)控制理论(2)场效应管三极管(3)布尔代数(4)稳压(5)相关性和功率谱密度(6)滤波器类型(7)模/数转换器(8)时序逻辑电路的分析与综合Ⅲ.(1)Electronics is a part of the larger field of electricity. The basic principles of electricity are also common to electronics. Modern advances in the field of computer, control system, communications have a close relationship with electronics. The field of electronics includes the electron tube, transistor, integrated circuit and so on.(2) Direct current circuits & Alternating current circuits,Analog electronics,Digital electronics,signal and systems,Circuit theory and design, Control theory, Microcontrollersystems,Computer programming for engineering applications.(3) This curriculum mainly introduces the characteristics of semiconductor devices in linear application scope.The content involved in semiconductor diodes (PN junction diodes, special purpose diodes), transistors (field effects and bipolar transistors), signal amplifiers, practical amplifiers, biasing circuits, operationalamplifiers circuit and other circuits (rectification, regulation and DC power supplies).(4) This partial studies take the basicelectric circuit theory and the operational amplifier knowledge as the foundation. The main study goal is to enhance understanding of the electric circuit theory. Its main content includes the elementary theory in circuit theory (network functions, characteristic frequencies), types offilter (lowpass,bandpass), review of operational amplifiers (design of first and second order using operational amplifiers, cascade design), filter characteristics(Butterworth, Chebyshev, frequency transformations in design, sensitivity design of passive LC ladder filters and a brief introduction to switched capacitor filters).(5) Perfect.二、参考译文电子学的发展电子学是电学的一部分。

21世纪英语读写译。b4-u01-a幻灯片PPT课件

21世纪英语读写译。b4-u01-a幻灯片PPT课件

Language Points
4 Who is great Defining who is great depends on how one measures success. But there are some criteria. “Someone who has made a lasting contribution to human civilization is great,” said Dean Keith Simonton, a professor of psychology at the University of California at Davis and author of the 1994 book Greatness: Who Makes History and Why. But he added a word of caution: “Sometimes great people don’t make it into history books. A lot of women achieved great things or were influential but went unrecognized.”
Language Points
5 In writing his book, Simonton combined historical knowledge about great figures with recent findings in genetics, psychiatry and the social sciences. The great figures he focused on include men and women who have won Nobel Prizes, led great nations or won wars, composed symphonies that have endured for centuries, or revolutionized science, philosophy, politics or the arts. Though he doesn’t have a formula to define how or why certain people rise above (too many factors are involved), he has come up with a few common characteristics.

Guide to the Expression of Uncertainty in Measurement

Guide to the Expression of Uncertainty in Measurement

Input and Output Quantities
In the generic model Y = f(X1,…,XN), the measurand is denoted by Y
Also called the output quantity
The quantities X1,…,XN are called input quantities
Remember: the correction term or factor itself has uncertainty
A small residual systematic error generally remains after all known corrections have been applied
Benefits
Much flexibility in the guidance Provides a conceptual framework for
evaluating and expressing uncertainty Promotes the use of standard terminology and
Stated Purposes
Promote full information on how uncertainty statements are arrived at
Provide a basis for the international comparison of measurement results
Uncertainty is a more practical concept Evaluating uncertainty allows you to place a

存在位置误差时运动多平台时差定位CRLB分析

存在位置误差时运动多平台时差定位CRLB分析

存在位置误差时运动多平台时差定位CRLB分析骆卉子;曲长文【摘要】存在平台位置测量误差时,已有研究未涉及运动多平台时差(TDOA)连续定位的性能评价.为此,选择克拉美-罗限(CRLB)作为对目标定位性能的评价指标,将不同时刻的运动多平台真实位置向量构成扩维向量后由CRLB定义得出了其通用计算式,并根据运动多平台TDOA连续定位的特点,推导了适合此应用场景的具体计算式.仿真结果表明了所推导的CRLB能有效用于上述场景中的定位性能评价,对近场及远场目标都需要在系统技术指标及定位算法设计等方面考虑平台位置测量误差的影响.%In moving multi-platform time-difference-of-arrival (TDOA) continuous localization,precise platform locations are often not available in practice.The localization performance evaluation for such scene is not researched.Aiming at this,the Cramér-Rao lower bound(CRLB) is chosen as the evaluation index for the target localization.A augmented vector is composed using all true platform positions at different instants and the common calculation formula for the CRLB is got by its definition.According to the characteristics of the moving multi-platform TDOA continuous localization,the specific calculation formula is derived.Simulation results indicate the effectiveness of the derived index for the performance evaluation in the aforementioned scene.The influence of the platform's position error should be considered in system technical index and localization algorithm design for both the near-field target and the far-field target.【期刊名称】《现代防御技术》【年(卷),期】2017(045)002【总页数】5页(P130-133,155)【关键词】多平台;定位;平台位置误差;时差;克拉美-罗限;仿真【作者】骆卉子;曲长文【作者单位】海军航空工程学院电子信息工程系,山东烟台264001;海军航空工程学院电子信息工程系,山东烟台264001【正文语种】中文【中图分类】TN953+.7;TN958.97现代战争中战场电磁环境复杂,分布着各种电磁辐射源,确定它们的位置来获取完整的战场态势对战争胜负至关重要。

EFM32 微控制器应用指南说明书

EFM32 微控制器应用指南说明书

...the world's most energy friendly microcontrollers USART/UART - AsynchronousmodeAN0045 - Application NoteThis application note describes how to configure the EFM32 UART or USART tooperate in asynchronous mode.An included software example for the EFM32GG-DK3750 Giant Gecko DevelopmentKit shows how to implement interrupt driven receive and transmit, utilizing the on-board RS-232 transceiver.This application note includes:•This PDF document•Source files (zip)•Example C-code•Multiple IDE projects1 Universal Asynchronous Receive Transmit (UART)1.1 Basic TheoryA UART is a well established standard for low cost, low speed serial communications over a simple 2-wire (plus ground) interface.Asynchronous communications differs from synchronous communications in that synchronization between transmitter and receiver are encoded into the transmitted signal, rather than using a separate wire to transfer the transmitter clock to the receiver.Embedding the synchronization information in the data reduces the cost of cables and connectors, and may also be beneficial on a space constrained PCB or if one wants to keep the pin-usage low. On the other side adding synchronization information to the datastream increases overhead, causing the effective data rate to be lower than the baud rate.Normally, asynchronous communication modes facilitate somewhat lower data rates compared with synchronous modes. Some of the reason is the above mentioned overhead, but also because asynchronous communications may impose stronger requirements on the transceivers and the transmission lines between receiver and transmitter.Low cost and low power transceivers usually don't have advanced clock recovery mechanisms, but simply rely on the combination of oversampling and that the receiver and transmitter clock frequencies are sufficiently close.1.2 RS-232UART does not specify any electrical characteristics such as signal levels etc. Instead, several separate electrical interface standards can be applied. Most common is RS-232, but other well known standards include RS-422, RS-485, and also some standards that don't use electrical signalling such as IrDA.In this application note, the included software example uses the RS-232 transceiver that is included on the Development Kit.1.3 Using the EFM32 UART/USARTThe information necessary to configure and use the UART/USART modules on an EFM32 microcontroller are contained in the device family reference manual. This application note also presents some further details and clarifications.1.3.1 Clock SourceOften, the HFRCO is too unprecise to be used for communications. So using the HFXO with an external crystal is recommended when using the EFM32 UART/USART.In some cases, the internal HFRCO can be used. But then careful considerations should be taken to ensure that the clock performance is acceptable for the communication link.1.3.2 Baud Rate CalculationThe baud rate is given by the following expression:Baud rate(1.1)Where•br is baud rate,•f HFPERCLK is the frequency of the HFPERCLK branch of the high frequency clock tree (See figure on CMU Overview in device family specific reference manual),•OVS is the oversampling factor, and•DIV is the configurable part of the fractional divider in the UART/USART module.When rearranged, one can compute a clock divider setting that will obtain a wanted baud rate by the following formula:Clock divisor(1.2) The clock divider is a fractional divider dividing by (1+DIV/4) where DIV is a 15 bit value ranging from 0 to 32767. I.e. the clock can be divided by a factor from 1 to 8192.75. Depending on the configurable oversampling factor the baud rate is given by a further division by a factor of 4, 6, 8 or 16. This results in a baud rate that is the clock frequency divided by 4 to 131,084. If the HFXO is run at 32 MHz, baudrates between 8 Mbps and 244.11 bps can be generated as long as the HFPERCLK prescaler is set to 1.It is worth noting that the equations in this application note differs somewhat from the reference manual. The reason is that the reference manual refers to CLKDIV which is the entire 32-bit register value, of which only the 15-bit wide bitfield DIV is actually used to control the fractional divider. In this document, the bitfield DIV is consistently used.2 Software ExampleThe included software example is made for the EFM32 Giant Gecko Development Kit, EFM32GG-DK3750. However, with minor modifications the project will also work on our other EFM32 development kits. It can also be ported to the starter kits. But because the starter kits don't include RS-232 line drivers, please ensure that signal levels are compatible before establishing a communication link between two parties. Connecting the EFM32 UART directly to a PC serial port will damage the EFM32.The kit's on-board RS-232 transceiver is used to demonstrate a possible interrupt based asynchronous mode configuration of an EFM32 U(S)ART peripheral.The example uses interrupt driven transmit and receive. When transmitting a block of data, the data is first copied into a transmit queue. The U(S)ART TXBL interrupt is enabled. When the UART is ready to transmit, the TXBL interrupt goes high. The interrupt handler function fetches one byte from the transmit queue and copies it to the UART transmit buffer (UARTn->TXDATA). While transmitting, the CPU is free to perform other tasks. In the example project, the MCU spends this time in Sleep Mode (EM1).The same principle is used on receive. When an RXDATAV interrupt is received, the Rx interrupt handler copies the incoming data to a receive queue.2.1 Kit ConfigurationThe development kit's on-board RS-232 line driver is used. This transceiver is normally disconnected from the MCU, so before it can be used, it must be enabled by software. To do this, the kit library functions are used. The kit libraries are included in the kit software packages that can be installed via Simplicity Studio. Documentation can be found in a sub-folder of the Energy Micro library installation folder. It is usually located at: [energymicro]\kits\EFM32GG_DK3750\bspdoc\html\index.html where [energymicro] is the Simplicity Studio data folder. The location of this folder is system dependent, and can be found through "Simplicity Studio->File->Browse Installed Files"The RS-232 transceiver is connected to UART1, location 2 on the EFM32.2.2 InstructionsA serial cable and terminal emulator software is required to try this example. On Windows, the OpenSource terminal Tera Term can be used.First, connect a serial cable between a computer and the 9-pin RS-232 connector on the development kit. Configure the serial port as follows•Baud rate = 115 200•Data bits = 8•Parity = none•Stop bits = 1•Flow control = nonebefore opening a connection with the terminal emulator.One should also configure the terminal emulator to handle new line in the same way as the SW example.In Tera Term the proper configuration is to use LF on receive and CR+LF on transmit. If this can't be configured on the chosen emulator, the example can of course be altered to match the emulator settings.When connected, start typing. After entering some characters, press '.' which is predefined as a "termination character" causing the MCU to echo the contents of the RX queue back out on the UART.2.3 TransmitTransmit is handled by two functions: uartPutData() and UART1_TX_IRQHandler().uartPutData() copies data to send into a transmit queue. The queue is implemented as a circular buffer.The data is copied into the queue starting at the write index (wrI). When finished, the pending byte counter is updated. Finally the TX interrupt for the UART is enabled.UART1_TX_IRQHandler() reacts when the TXBL interrupt goes high, signalling that the UART transmit buffer is empty. When this happens, one byte is copied from the read index (rdI) position in the TX queue into the UART transmit buffer. The read index is updated, and the pending byte counter is decremented.If the transmit queue becomes empty, the TXBL interrupt is disabled.2.4 ReceiveIn the same way, receive is also handled by two functions: UART1_RX_IRQHandler and uartGetData.UART1_RX_IRQHandler()reacts on the RXDATAV interrupt, meaning that the UART RX buffer contains valid data. When this happens, the incoming byte is copied from the UART RX buffer into the RX queue. The queue write index (wrI) is updated, and the pending byte counter is incremented. The IRQ handler will also disable the TXBL interrupt if the transmit queue becomes empty.uartGetData() pulls a number of bytes from the receive queue. The copy starts at the read index (rdI).When data is copied, the read index is updated and the pending byte counter is decremented.Also, for the sake of the example, the RX interrupt handler checks if the received byte is a predefined termination character.3 Revision History3.1 Revision 1.032013-09-03New cover layoutRemoved unnecessary read of IF in TX IRQ Handler3.2 Revision 1.022013-05-08Added software projects for ARM-GCC and Atollic TrueStudio.3.3 Revision 1.012012-11-12Adapted software projects to new kit-driver and bsp structure.3.4 Revision 1.002012-06-28Initial revision.A Disclaimer and TrademarksA.1 DisclaimerSilicon Laboratories intends to provide customers with the latest, accurate, and in-depth documentation of all peripherals and modules available for system and software implementers using or intending to use the Silicon Laboratories products. Characterization data, available modules and peripherals, memory sizes and memory addresses refer to each specific device, and "Typical" parameters provided can and do vary in different applications. Application examples described herein are for illustrative purposes only. Silicon Laboratories reserves the right to make changes without further notice and limitation to product information, specifications, and descriptions herein, and does not give warranties as to the accuracy or completeness of the included information. Silicon Laboratories shall have no liability for the consequences of use of the information supplied herein. This document does not imply or express copyright licenses granted hereunder to design or fabricate any integrated circuits. The products must not be used within any Life Support System without the specific written consent of Silicon Laboratories.A "Life Support System" is any product or system intended to support or sustain life and/or health, which,if it fails, can be reasonably expected to result in significant personal injury or death. Silicon Laboratories products are generally not intended for military applications. Silicon Laboratories products shall under no circumstances be used in weapons of mass destruction including (but not limited to) nuclear, biological or chemical weapons, or missiles capable of delivering such weapons.A.2 Trademark InformationSilicon Laboratories Inc., Silicon Laboratories, the Silicon Labs logo, Energy Micro, EFM, EFM32, EFR, logo and combinations thereof, and others are the registered trademarks or trademarks of Silicon Laboratories Inc. ARM, CORTEX, Cortex-M3 and THUMB are trademarks or registered trademarks of ARM Holdings. Keil is a registered trademark of ARM Limited. All other products or brand names mentioned herein are trademarks of their respective holders.B Contact InformationSilicon Laboratories Inc.400 West Cesar ChavezAustin, TX 78701Please visit the Silicon Labs Technical Support web page:/support/pages/contacttechnicalsupport.aspx and register to submit a technical support request.Table of Contents1. Universal Asynchronous Receive Transmit (UART) (2)1.1. Basic Theory (2)1.2. RS-232 (2)1.3. Using the EFM32 UART/USART (2)2. Software Example (4)2.1. Kit Configuration (4)2.2. Instructions (4)2.3. Transmit (4)2.4. Receive (5)3. Revision History (6)3.1. Revision 1.03 (6)3.2. Revision 1.02 (6)3.3. Revision 1.01 (6)3.4. Revision 1.00 (6)A. Disclaimer and Trademarks (7)A.1. Disclaimer (7)A.2. Trademark Information (7)B. Contact Information (8)B.1. (8)List of Equations1.1. Baud rate (2)1.2. Clock divisor (3)。

化学专业英语

化学专业英语
•Class n, 类别 •Classify Vt.分类 • Classification n. 分类
普通化合物分类 我们可以根据化学式按着下面的方法分类许多普
通化合物。
1. Acids, in the conventional sense, may be recognized by noting that the H is written first in the formula and that the rest of the compound is generally nonmetallic. Ex., HCl, H2SO4, HClO.
• become (be) familiar with…熟悉,通晓
例如,盐酸归类为酸,由于已熟悉作为不同类别 的酸的性质,我们就会立即知道这一化合物的一 般性质。
A great many of the compounds we are to study may be classified as acids, bases, salts, metallic oxides, or nonmetallic oxides. Of these five classes of compounds, the first three-acids, bases, and salts-are by far the most important.
• be aware of 知道,意识到……
那么,如果我们能够恰当地将一个化合物归类,我们立 刻就能从这类化合物的性质来了解这个化合物的一般性 质。
For example, HCl is classed as an acid, and by becoming familiar with the behavior of acids as a distinct class, we are at once aware of the general properties of the compound.

双星运动公式

双星运动公式

双星运动公式The study of binary stars has always fascinated astronomers and astronomers for centuries. From observing the motion of these stellar pairs, we can gain valuable insights into the nature of gravity, mass, and the dynamics of celestial bodies. One of the key concepts in understanding the motion of binary stars is the binary star motion formula, which describes the orbital motion of these stellar systems.双星的运动研究一直让天文学家和天文学家们着迷了几个世纪。

通过观察这些恒星对的运动,我们可以深入了解重力、质量和天体动力学的本质。

在理解双星运动的关键概念之一是双星运动公式,它描述了这些恒星系统的轨道运动。

The binary star motion formula is derived from the principles of classical mechanics and gravitation. It takes into account the masses of the two stars, their separation distance, and their relative velocities to determine their orbital paths. The formula is based on Newton's law of universal gravitation and Kepler's laws of planetary motion, providing a mathematical framework for predicting and analyzing the motion of binary stars.双星运动公式是从古典力学和引力原理中推导出来的。

CytoSelect 24 -Well Anoikis Assay 说明书

CytoSelect 24 -Well Anoikis Assay 说明书

Product ManualCytoSelect™ 24-Well Anoikis AssayCatalog NumberCBA-080 24 assaysFOR RESEARCH USE ONLYNot for use in diagnostic proceduresIntroductionAdhesion to the extracellular matrix (ECM) is essential for survival and propagation of many adherent cells. Apoptosis that results from the loss of cell adhesion to the ECM, or inappropriate adhesion is defined as “anoikis”. Anoikis, from the Greek word for homelessness, is involved in the physiological processes of tissue renewal and cell homeostasis.A common feature of carcinoma development and growth is the ability of transformed cells to survive under “anchorage independent” or “spheroid” growth conditions. This resistance to anoikis has been shown to be involved in the loss of cell homeostasis, cancer growth, and metastasis. The inhibition of cell adhesion, spreading, and growth on the ECM is an impediment to the cellular healing process, thus making it a possible therapeutic target. Preventing anoikis and enhancing cell adhesion and spreading is a major goal in the development of cell transplantation techniques, including the therapeutic use of progenitor cells. Further studies aimed at controlling the molecular mechanisms of anoikis resistance will serve to define effective therapies for the treatment of many human malignancies.The CytoSelect™ 24-well Anoikis Assay Kit provides a colorimetric and fluorometric format to measure anchorage-independent growth and monitoring anoikis propelled cell death. The kit contains sufficient reagents for the assay of 24 samples in a Poly-Hema coated 24-well plate. Live cells are detected with MTT or Calcein AM. Cell death is detected with the Ethidium Homodimer (EthD-1). Assay PrincipleCells are cultured in poly-Hema coated plate or control plate. Cell viability is determined by MTT or Calcein AM. Anoikis propelled cell death is measured by Ethidium Homodimer (EthD-1). EthD-1 is an excellent marker for measuring dead cells. EthD-1 is a red fluorescent dye that can only penetrate damaged cell membranes. EthD-1 will fluoresce with a 40-fold enhancement upon binding ssDNA, dsDNA, RNA, oligonucleotides, and triplex DNA. Background fluorescence levels are very low because the dyes are virtually non-fluorescent before interacting with cells.Related Products1.CBA-081: CytoSelect™ 96-Well Anoikis Assay2.CBA-230: Cellular Senescence Detection Kit (SA-β-Gal Staining)3.CBA-231: 96-Well Cellular Senescence Assay (SA β-Gal Activity)4.CBA-232: Quantitative Cellular Senescence Assay (SA β-Gal)5.CBA-240: CytoSelect™ Cell Vi ability and Cytotoxicity AssayKit Components1.Anchorage Resistant Plate (Part No. 108001): One 24-well Poly-Hema coated plate.2.Calcein AM (500X) (Part No. 108002): One vial – 50 µL in DMSO.3.Ethidium Homodimer (EthD-1) (500X) (Part No. 108003): One vial – 50 µL.4.Detergent Solution (Part No. 108004): One bottle – 25.0 mL.5.MTT Solution (Part No. 113502): Three tubes – 1.0 mL each.Materials Not Supplied1.Cells for measuring anoikis2.Cell culture medium3.Inverted fluorescence/light microscope4.Fluorometer capable of reading Calcein AM (485 nm/515 nm) and EthD-1 (525 nm/590 nm)fluorescence.StorageStore the Calcein AM and Ethidium Homodimer at -20ºC. Store all other components at 4ºC.Assay Protocol1.Prepare a cell suspension containing 0.1-2.0 x 106 cells/ml in culture media. Cells can be treatedwith anoikis enhancing or inhibiting reagents.2.Add 0.5 mL cell suspension to each well of the Anchorage Resistant Plate or a control 24-well cellculture plate. Culture the cells 24-72 hours at 37ºC and 5% CO2. The time and culture conditions will depend on the cell line used and may need to be adjusted by the user.3.Proceed with MTT Colorimetric or Calcein AM/EthD-1 Fluorometric detection.MTT Colorimetric Detection1.Add the 50 µL of the MTT Reagent to each well of the Anchorage Resistant Plate or control 24-well plate.2.Incubate the wells 2-4 hours or overnight at 37ºC. Monitor the cells occasionally with an invertedmicroscope for the presence of a purple precipitate.3.Add 500 µL of Detergent Solution to each well. Gently mix the solution by pipetting.4.Cover the plate to protect it from light and incubate in the dark for 2-4 hours at room temperature.5.Transfer 200 µL to a 96-well plate and measure the absorbance in each well at 570 nm in amicrotiter plate reader.Calcein AM / EthD-1 Fluorometric Detection1.Add 1 µL of Calcein AM (500X) and 1 µL of Eth-D1 (500X) to each well of the 24-wellAnchorage Resistant Plate or control plate to be detected.2.Incubate the plate 30-60 minutes at 37ºC.3.Monitor the cells microscopically for the presence of the green Calcein AM (Ex: 485 nm and Em:515 nm) or red EthD-1 (Ex: 525 nm and Em: 590 nm) fluorescence. The fluorescence can be quantitatively measured with a fluorescence microplate reader.Example of Results The following figures demonstrate typical results with the CytoSelect™ 24-well Anoikis Assay Kit. One should use the data below for reference only. This data should not be used to interpret actual results.00.20.40.60.8Control Poly-HemaO D 560 n mFigure 1. Anoikis Assay of Human Foreskin Fibroblast BJ-TERT Cells. BJ-TERT cells were seeded at 50,000 cells/well in a tissure culture control plate or a Poly-Hema coated plate. Cells were allowed to culture for 24 hours. Cell viability was determined by MTT and Calcein AM, while anoikis-like cell death was stained with EthD-1.References1.Bates RC, Buret A, van Helden DF, Horton MA, Burns GF. (1994) J Cell Biol125, 403-415.2.Frisch SM, Francis H. (1994) J Cell Biol124, 619-626.3.Frisch SM, Screaton RA. (2001) Curr Opin Cell Biol13, 555-562.4.Meredith JE, Jr Fazeli B, Schwartz MA. (1993) Mol Biol Cell 4, 953-961.5.Rak J, Mitsuhashi Y, Erdos V, Huang SN, Filmus J, Kerbel RS. (1995) J Cell Biol131, 1587-1598. Recent Product Citations1.Mao, C.G. et al. (2021). BCAR1 plays critical roles in the formation and immunoevasion ofinvasive circulating tumor cells in lung adenocarcinoma. Int J Biol Sci. 17(10):2461-2475.doi:10.7150/ijbs.61790.2.Zheng, J.L. et al. (2021). Ursolic acid induces apoptosis and anoikis in colorectal carcinoma RKOcells. BMC Complement Med Ther. 21(1):52. doi: 10.1186/s12906-021-03232-2.3.Liu, L.Q. et al. (2019). MiR-92a antagonized the facilitation effect of extracellular matrix protein 1in GC metastasis through targeting its 3'UTR region. Food Chem Toxicol. 133:110779. doi:10.1016/j.fct.2019.110779.4.Xu, J. et al. (2019). ProNGF siRNA inhibits cell proliferation and invasion of pancreatic cancercells and promotes anoikis. Biomed Pharmacother. 111:1066-1073. doi:10.1016/j.biopha.2019.01.002.5.Tan, Y. et al. (2018). Adipocytes fuel gastric cancer omental metastasis via PITPNC1-mediatedfatty acid metabolic reprogramming. Theranostics. 8(19):5452-5468. doi: 10.7150/thno.28219. 6.Hu, L. et al. (2018). G9A promotes gastric cancer metastasis by upregulating ITGB3 in a SETdomain-independent manner. Cell Death Dis. 9(3):278. doi: 10.1038/s41419-018-0322-6.7.Hu, B. et al. (2018). Herbal formula YGJDSJ inhibits anchorage-independent growth and inducesanoikis in hepatocellular carcinoma Bel-7402 cells. BMC Complement Altern Med. 18(1):17. doi:10.1186/s12906-018-2083-2.8.Chen, H.Y. et al. (2018). Integrin alpha5beta1 suppresses rBMSCs anoikis and promotes nitricoxide production. Biomed Pharmacother. 99:1-8. doi: 10.1016/j.biopha.2018.01.038.9.Fu, X.T. et al. (2018). MicroRNA-30a suppresses autophagy-mediated anoikis resistance andmetastasis in hepatocellular carcinoma. Cancer Lett. 412:108-117. doi:10.1016/j.canlet.2017.10.012.10.Yu, M. et al (2017). Interference with Tim-3 protein expression attenuates the invasion of clear cellrenal cell carcinoma and aggravates anoikis. Mol Med Rep. 15(3):1103-1108. doi:10.3892/mmr.2017.6136.11.Lu, S. et al. (2016). Expression of α-fetoprotein in gastric cancer AGS cells contributes to invasionand metastasis by influencing anoikis sensitivity. Oncol Rep.35:2984-2990.12.Lee, H.W. et al. (2013). Tpl2 kinase impacts tumor growth and metastasis of clear cell renal cellcarcinoma. Mol Cancer Res.11:1375-1386.13.Sisto, M. et al. (2009). Fibulin-6 expression and anoikis in human salivary gland epithelial cells:implications in Sjogren's syndrome. Int. Immunol.21:303-311.14.Liu, H. et al. (2008). Cysteine-rich protein 61 and connective tissue growth factor induce de-adhesion and anoikis of retinal pericytes. Endocrinology 149:1666-1677.WarrantyThese products are warranted to perform as described in their labeling and in Cell Biolabs literature when used in accordance with their instructions. THERE ARE NO WARRANTIES THAT EXTEND BEYOND THIS EXPRESSED WARRANTY AND CELL BIOLABS DISCLAIMS ANY IMPLIED WARRANTY OF MERCHANTABILITY OR WARRANTY OF FITNESS FOR PARTICULAR PURPOSE. CELL BIOLABS’ sole obligation and purchaser’s exclusive remedy for breach of this warranty shall be, at the option of CELL BIOLABS, to repair or replace the products. In no event shall CELL BIOLABS be liable for any proximate, incidental or consequential damages in connection with the products.Contact InformationCell Biolabs, Inc.7758 Arjons DriveSan Diego, CA 92126Worldwide: +1 858-271-6500USA Toll-Free: 1-888-CBL-0505E-mail: ********************©2007-2021: Cell Biolabs, Inc. - All rights reserved. No part of these works may be reproduced in any form without permissions in writing.。

一种中药的作用和价值的英语作文

一种中药的作用和价值的英语作文

一种中药的作用和价值的英语作文The Multifaceted Effects and Inestimable Value of Banxia.In the vast pharmacopeia of traditional Chinese medicine, a remarkable herb stands out for its versatile therapeutic applications and profound medicinal significance: Banxia. This multifaceted botanical has been revered for centuries for its ability to alleviate a wide spectrum of ailments, earning it a cherished place in the healing traditions of the East.Botanical Identity and Traditional Usage.Banxia, also known by its botanical name Pinellia ternata, is a perennial herbaceous plant native to eastern Asia. Its main medicinal component is derived from the dried and processed rhizome, which possesses a pungent odor and a slightly bitter taste.In traditional Chinese medicine, Banxia has been employed for millennia to treat a diverse range of conditions, including respiratory ailments such as coughs, asthma, and bronchitis; digestive issues like nausea, vomiting, and diarrhea; and neurological disorders like dizziness and vertigo. Its versatility stems from its complex chemical composition, which includes alkaloids, terpenoids, and starch.Pharmacological Effects.Modern scientific research has substantiated many of the traditional uses of Banxia, revealing a host of pharmacological properties that contribute to its therapeutic efficacy.Expectorant and Anti-inflammatory: Banxia exhibits expectorant and anti-inflammatory effects, effectively reducing phlegm production and soothing inflamed respiratory tissues. This makes it an ideal remedy for conditions like coughs and bronchitis.Anti-nausea and Anti-emetic: The herb contains compounds that act as anti-nausea and anti-emetics, suppressing the vomiting reflex and preventing nausea. Itis often used to alleviate these symptoms associated with motion sickness, chemotherapy, and other conditions.Anti-diarrheal: Banxia's astringent properties help to reduce diarrhea by regulating intestinal motility and promoting fluid absorption.Neurological Effects: Some studies suggest that Banxia may have neuroprotective and anti-vertigo effects, potentially benefiting conditions like Alzheimer's disease and Meniere's disease.Clinical Applications.The therapeutic applications of Banxia are numerous and well-documented. It is commonly used in the following clinical scenarios:Respiratory Conditions: Banxia is a key ingredient inmany herbal formulas for treating coughs, asthma, bronchitis, and other respiratory ailments. Its expectorant and anti-inflammatory properties help to clear congestion and soothe airways.Gastrointestinal Disorders: Banxia is employed to alleviate nausea, vomiting, and diarrhea. It is often combined with other herbs to enhance its efficacy.Neurological Conditions: Banxia may be beneficial in reducing dizziness and vertigo, potentially improving balance and coordination.As an Adjuvant: Banxia is frequently used as an adjuvant in herbal formulas to enhance the therapeutic effects of other herbs. It promotes absorption, reduces toxicity, and modulates the overall action of the formula.Combinations and Preparations.Banxia is rarely used alone in traditional Chinese medicine. It is often combined with other herbs to createsynergistic formulas that target specific conditions. Some common combinations include:For cough and asthma: Banxia is often combined with almonds, ephedra, and ginger.For nausea and vomiting: Banxia is frequently paired with ginger, mint, and licorice.For diarrhea: Banxia is combined with atractylodes, angelica, and ginseng.Banxia can be prepared in various forms, including decoctions, pills, powders, and tinctures. The specific preparation depends on the condition being treated.Safety Considerations.Banxia is generally considered safe for most people when used in appropriate doses. However, it is crucial to note the following precautions:Contraindications: Banxia should be avoided during pregnancy and lactation.Drug Interactions: Banxia may interact with certain medications, such as blood thinners. It is advisable to consult with a healthcare professional before using Banxiaif you are taking any medications.Toxicity: Excessive consumption of Banxia can causeside effects like skin irritation, diarrhea, and vomiting.Conclusion.Banxia is a time-honored medicinal herb with a wide range of therapeutic applications. Its multifaceted effects, from expectorant to anti-emetic to neurological, make it a valuable addition to the traditional Chinese medicine armamentarium. When used appropriately, Banxia caneffectively alleviate a variety of ailments and promote overall health and well-being. However, it is essential to exercise caution, adhere to recommended dosages, and seek professional advice when necessary. By respecting thewisdom of traditional Chinese medicine and embracing the power of nature's remedies, we can harness the healing benefits of Banxia and cultivate a healthier and more balanced life.。

基于修正的G-K公式的组合机构自由度的计算

基于修正的G-K公式的组合机构自由度的计算

2023年第47卷第5期Journal of Mechanical Transmission基于修正的G-K公式的组合机构自由度的计算许兆棠(三江学院机械与电气工程学院,江苏南京210012)摘要用修正的Grübler-Kutzbach的机构自由度计算公式,计算组合机构的自由度,有时会产生错误的结果。

为了正确计算组合机构的自由度,并考虑计算组合机构自由度的方法便于工程技术人员学习和应用,根据修正的Grübler-Kutzbach的机构自由度计算公式,导出组合机构自由度的计算公式,得到机构自由度的一般计算公式;提出计算组合机构自由度的注意事项,给出了组合机构划分为基本机构的方法,并给出了算例。

修正的Grübler-Kutzbach的机构自由度计算公式只能用于1个基本机构的自由度计算及各个基本机构的公共约束相同的机构自由度计算;对于一般的组合机构,要用组合机构自由度的公式计算其自由度。

组合机构自由度等于各个基本机构自由度的和。

关键词组合机构自由度计算基本机构公共约束Calculation of Mobility on Combined Mechanisms Based on theModified G-K's FormulaXu Zhaotang(School of Mechanical and Electrical Engineering, Sanjiang University, Nanjing 210012, China)Abstract Using the modified Grübler-Kutzbach's formula of mechanism mobility, the calculation of the mobility of combined mechanism may produce wrong results. In order to correctly calculate the mobility of com⁃bined mechanism, and to consider that the calculation method of the mobility of combined mechanism is conve⁃nient for engineers for study and application, according to the modified Grübler-Kutzbach's formula of the mech⁃anism mobility, the calculation formula of mobility of combined mechanism is deduced. The general calculation formula of mobility of mechanism is obtained. The attentions of calculating mobility of combined mechanism are proposed. The method of dividing the combined mechanism into basic mechanisms is given. Numerical examples are given. The modified Grübler-Kutzbach's formula of mechanism mobility can only be used to calculate mobil⁃ity of a basic mechanism, and to calculate mobility of combined mechanism in that each basic mechanism has the same common constraint. The mobility of general combined mechanism should be calculated by the calcula⁃tion formula of mobility of combined mechanism. The mobility of combined mechanism is equal to the sum of the mobility of each basic mechanism.Key words Combined mechanism Mobility Calculation Basic mechanism Common constraint0 引言修正的Grübler-Kutzbach的机构自由度计算公式(简称修正的G-K公式)早已编入中外许多教科书中[1]115-116[2]42-48,并已为众多工程师所熟悉和运用。

tsai-wu失效准则公式

tsai-wu失效准则公式

tsai-wu失效准则公式The Tsai-Wu failure criterion is a mathematical formula used to predict the failure of composite materials under complex loading conditions. It is named after its developers, Tsai and Wu, who introduced this criterion in 1971. The criterion is widely used in the field of engineering and materials science to assess the safety and reliability of composite structures.The Tsai-Wu failure criterion takes into account both the strength and stiffness properties of the composite material. It is based on the assumption that failure occurs when the combined stresses in the material exceed certain predefined limits. These limits are determined by the material's strength properties, such as the ultimatetensile and compressive strengths, as well as thematerial's stiffness properties, such as the modulus of elasticity.The criterion is expressed in the form of an inequality,where the left-hand side represents the combined stressesin the material, and the right-hand side represents the predefined limits. If the left-hand side is greater than the right-hand side, it indicates that the material is in a state of failure. Conversely, if the left-hand side is less than the right-hand side, it suggests that the material is still within its safe operating limits.The Tsai-Wu failure criterion is particularly usefulfor predicting the failure of composite materials under complex loading conditions, such as those encountered in aerospace and automotive applications. These materials are often subjected to a combination of tensile, compressive, and shear stresses, which can be difficult to analyze using other failure criteria.From a practical standpoint, the Tsai-Wu failure criterion can be implemented using computer-aided engineering (CAE) software. By inputting the material properties and the loading conditions into the software, engineers can obtain a numerical value for the left-hand side of the inequality. By comparing this value to theright-hand side, they can determine whether the material is likely to fail or not.In conclusion, the Tsai-Wu failure criterion is a valuable tool for assessing the failure of composite materials. It provides engineers with a quantitative measure of the material's safety and reliability under complex loading conditions. By considering both the strength and stiffness properties of the material, itoffers a comprehensive approach to failure analysis. Its implementation through CAE software enables efficient and accurate predictions, aiding in the design and optimization of composite structures.。

数学代号及表达式简化指南说明书

数学代号及表达式简化指南说明书

Expressions can be simplified by collecting together any terms that are made up of the same letters.4Expressions with different terms2Sometimes expressions have two or more terms which Combine the like terms. There are four t s so write this as 4t.Add or subtract the coefficients on like terms. 2 + 4 - 3 = 3There are two different sets of like terms in this expression. Collect all the d terms together and all the c terms together.Collect the like termsand then combinethem. The like terms for y 2 should be combined, and then z added to the expression.Combine x 2 terms in the same way you would combine x . Add or subtract the coefficients on the like terms.Collect the x and the x 2 terms separately. x and 4x 2 are not like terms because the powers of x are different.You need to be able to simplify algebraic expressions that include multiplication signs and division signs.7689To simplify an algebraic expression that includes a division 4Dividing expressions2xy a × a × a = a 3 (not 3a )12 Simplify c × d × 5 [1 mark] Simplify 3 × w × 2[1 mark]Exam-style practice 4Grades 1–210Remember that x is the same as x 1. Use the rule a m ÷ a n = a m - n to simplify the expression.a is multiplied by itself 6 times so, using the laws ofindices (a m× a n= a m + n), you can write it as a 6Find the HCF of the number at the top and the number atthe bottom. Divide by that number to simplify the expression as much as possible, and give your answer as a fraction.Letters in algebra can be simplified so that they are written next to each other in alphabetical order.Divide the numbers as much as possible, thencancel any common letters on the top and bottom of the fractions.Write the division as a fraction.5x means 5 × x . You can multiply in any order and get the same answer, so multiply the numbers and then the letters.It is important to be able to interpret information and then write it in terms of algebraic expressions.where n is the number of lines of text.If there are 25 crayons in the tub to start with, then the number left must be p crayons less than this.Sandeep, Pavan and Jake sell toy cars.Sandeep sells x cars. Pavan sells 6 more cars than Sandeep. Jake sells twice as many cars as Sandeep.Write an expression, in terms of x , for the totalnumber of toy cars sold by Sandeep, Pavan and Jake.Sandeep Pavan Jakex x + 6 2x4Worked example 5Grade 3Remember that 5 × x is written as 5x .The order of operations means that multiplication comes before addition.In order for this expression to be correct, d + 4 must happen before × 15. Place brackets around thed + 4 expression to make sure this part of the formula is calculated first.Exam focusWhen you have finished working out an expression, make sure that you have collected all of the like terms and cancelled the number parts or the indices to simplify the equation.‘6 more than’ means adding 6 and ‘twice as many’means multiply by 2, or double it.Made a start Feeling confident 24Peter advertises his business in the local magazine.Peter’s PawsDog walking service£5 to walk your dog Plus each hour walked £3To write this as an algebraic formula, substitute the variables for letters.For example, if the total cost is £T , and the number of hours is n , then the formula Peter can use is:total cost = (number of hours × £3) + £5T = 3n + 5When you define your variables, you must give their units.If you have a value for n you can now solve this formula. If Peter takes his neighbour’s dog on a two-hour walk, how much will he charge?T = 3 × 2 + 5= 6 + 5 = 11He will charge £114Writing a formula5A formula is a mathematical rule. You use algebra to write a formula (the plural of formula is formulae). A formula issimilar to an algebraic expression, but it has an equals sign, and more than one variable. You need to be able to substitute numbers into formulae to solve them.= 3x + 12y(b) K amran buys 4 packets and 2 boxes of bulbs. How many bulbs does he buy?N = 3 × 4 + 12 × 2 = 12 + 24= 36 He buys 36 bulbs.when t = 3The variables are N (the total number of bulbs), x (the number of packets) and y (the number of boxes).Substitute the values given in the question into the formula you worked out in part (a).1L = 2x +3yExam-style practiceGrade 410Order of operations is very important when you are evaluating formulae. Remember to use BIDMAS. Substitute the valueof t into the formula. When substituting, you might use brackets. You could write 10t as 10(t ) or 10(3). If there are numbers or letters outside brackets, without an operation in between, this means that you multiply the term outside the brackets with whatever is inside the brackets.For example: 10(3) means 10 * 3Made a startFeeling confidentIndices are also called powers. They represent how many times a number has been multiplied by itself. Examples include squaring and cubing numbers.Learn the basic rules of indices.a m × a n = a m + na m ÷ a n = a m - n (a m )n = a mn-n =1n a 0 = 1a a 4Basic rules of indices5x 4*x 6=x 4+6=x 10x 4,x 6=x 4-6=x -2(x 4)6=x 4*6=x 24x -4=1x 4x 0=1 O nly combine powers (indices) when the basenumbers are the same. W hen you multiply, add the powers. W hen you divide, subtract the powers. W hen you raise a power to a power, multiply the powers together.Indices checklist27y 5y 89The base is the same, p , so you can combine the indices.9789Work out the value of t given that Add the indices then setthis equal to 10.1Exam-style practice 4Grades 4–510Since the base is the same on both sides, the powersmust be equal so form an equation and solve it. Deal with each baseletter separatelyTreat the numbers andeach base separately. 24 ÷ 8 = 3 x 4 ÷ x 2 = x 2 y 3 ÷ y = y 2A negative power shows that the value is a reciprocal and can be written as a fraction, -n = 1nSubstitute 2-3into-n =1n a a a aSometimes mathematical expressions include terms written in brackets. You can remove the brackets by expanding them.4Removing brackets2To remove brackets, you expand them. This means multiply .An expression such as 2(x + 4) can be expanded by multiplying 2 and x, and 2 and 4. There is an invisible multiplication sign between the 2 and (x + 4).2(x + 4) = 2 × (x + 4)= 2 × x + 2 × 4= 2x + 84Negative terms2When the term outside is negative, you have to multiply the terms inside the bracket by a negative number. For example:-5(a - 2) = -5 × (a - 2)= -5 × a + -5 × -2 = -5a + 10xpand and simplify x - 2) + 5 × 7 + 3 × x - 3 × 2 6 When multiplying out brackets, always multiply every term inside thebracket by the term outside.Draw arrows from the termoutside the brackets to each term inside, so you know which terms you need to multiply.After multiplying out the brackets, collect the like terms and combine them.A negative multiplied by another negative gives a positive number: -5 × -2 = +10Go to page 2 to revise multiplying negative numbers.Made a startFeeling confidentSometimes you will need to multiply out two sets of brackets and then simplify the result to find the correct expression.4Double brackets10You can often multiply out two sets of brackets to obtain a simplified expression. There are three different methods for doing this.Box methodThe box method is a visualrepresentation of multiplying out brackets.Collect and simplify the terms: x 2 + 2x + 4x + 8 = x 2 + 6x + 8Expansion methodMultiply each term in the first bracket by the whole of the second bracket: (x + 4)(x + 2) = x (x + 2) + 4(x + 2) = x 2 + 2x + 4x + 8 FOILIn the FOIL method, you multiply out the brackets in a particular order.(x + 4)(x + 2)F: x × x = x 2O: x × 2 = 2xI: 4 × x = 4xL: 4 × 2 = 8Collect and simplify the terms: x 2 + 2x + 4x + 8 = x 2 + 6x + 8(x + 4)FirstOuterInnerLast (x + 2)123 Expand and simplify (a) (x + 3)2 [2 marks] (b) (x - 4)2 [2 marks]Exam-style practice 4Grade 410Problem solvingFind the missing length, then split the shape into twoparts and find their areas.(x + 3)2 = (x + 3)(x + 3)After you have expanded the brackets, always simplify the expression.28To factorise an expression first find the highest commonfactor (HCF) of all the terms in the expression. 4a + 8Both terms are divisible by 2 and 4, so 4 is the HCF. Write 4 on the outside of your brackets.4( )Then work out the terms inside the bracket by dividing the terms in the original expression by the HCF.4a ÷ 4 = a and 8 ÷ 4 = 2Factorising is the opposite of expanding brackets.You can check your answer, by expanding the brackets; it should give you the original expression.3p)2 and 6 are the common factors, so the HCF is 6Show that the perimeter of this triangle can be written as 3b (2a + 3c + d ).Grade 54Worked example 5The terms 4x and 10xy have 2 as a common factor. x appears in both terms, so it is also a common factor. Divide the expression by 2 first, and then by x .Find the common factors of both terms. 6 and p willdivide into each term. t is only in one term of the expression, so it is not a factor.The HCF is 2x It can help to write out p 3 as (p × p × p )The HCF is 6pExpand the brackets to check your answer.6p(2p 2t - 3) = 12p 3t - 18pWhen you solve a linear equation your aim is to find the value of the unknown. You can often do this by rearranging the equation and using inverse operations.4Unknown on one side5You may be asked to solve an equation that involves an unknown on one side, such as 6x + 10 = 34You will often need to use inverse operations , which are ‘opposite’ calculations.The term +10 can be removed from the equation by subtracting 10 from each side. This gives:6x + 10 - 10 = 34 - 10 6x = 24To get x by itself, divide both sides by 64Unknown on both sides5Sometimes an equation has unknowns on both sides. To solve such an equation, rearrange it so that all the unknowns are on one side. 3 - 4x = 15 - x 3 - 4x + 4x = 15 - x + 4x 3 = 15 + 3x3 - 15 = 15 -12 = 3x-12=3x Problem solvingAssign a letter to the unknown value and create analgebraic equation using this letter.Set up the equation by adding all the expressions and equating them to the total number of goals.Formulae show the relationship between two or more variables. These formulae can be rearranged to make a different letter the subject.4Finding the subject5The subject of a formula is the letter on its own on one side of the equals sign.This is often on the left-hand side (LHS) of the equals sign. For example, this is the formula for the area of a circle:A = πr 2In this formula, A is the subject.Rearranging formulae is very similar to solving equations where inverse operations are used. If there is another letter or number on the same side of the equals sign as the subject, then you need to use inverse operations to remove it.9There are two separate inverse operations here: +7 to each side, and then divide both sides by 34T wo or more inverse operations5 (÷ 2)the subject of the formula Y = 3X 2 - 10(+ 10)(÷ 3)The inverse operation of ‘squared’ is ‘square root’.Here you can take 2L across to the LHS as part of thefirst inverse operation.1234 M ake h the subject of the formula x = 5h + 8[2 marks]123 M ake g the subject of the formula t = gh 10[2 marks] the subject of the formula v 2 = u 2 + 2a s [2 marks]Exam-style practice4Grades 2–410For most formulae, start by adding or taking away any numbers or letters that are on the same side of the formula as the subject. Then complete any multiplication or division you need to do.This example involves just one inverse operation.The inverse operation of + is -, so subtract 5 from each side of the formula to get h on its own.The inverse operation of × is ÷, so divide both sides by 4 to make m the subject.。

churchill公式

churchill公式

churchill公式Winston Churchill's Leadership FormulaWinston Churchill, the renowned British statesman and prime minister, was a masterful leader who played a pivotal role during World War II. His leadership style and abilities are often summarized by what is now commonly known as the "Churchill Formula." This formula encapsulates the essential principles and values that guided Churchill throughout his career. Let's explore the three key elements of the Churchill Formula: determination, resilience, and courageous decision-making.Determination was at the core of Churchill's formula for leadership. He possessed an unwavering resolve to defend liberty and freedom, especially during times of adversity. Churchill's famous quote, "Never give in, never give in, never, never, never, never - in nothing, great or small, large or petty," exemplifies his relentless determination. This unwavering commitment inspired his countrymen and united them in the face of overwhelming odds.Resilience was another crucial aspect of Churchill's leadership. Despite facing numerous setbacks and challenges, Churchill remained resilient and steadfast in his convictions. He firmly believed that failure was not an option and encouraged others to persevere in the face of adversity. Churchill's ability to bounce back and inspire others to do the same was instrumental in maintaining morale and ultimately achieving victory.Courageous decision-making formed the third pillar of Churchill's formula. He was known for making bold and decisive choices when faced with critical situations. Churchill's ability to assess risks, gather information, and make timely decisions was crucial during the war. His leadership was defined by a willingness to take calculated risks and make tough choices, even when the outcome seemed uncertain. Churchill's determination and resilience, combined with his ability to make courageous decisions, made him a highly effective leader.Churchill's leadership formula remains relevant and inspiring even today. It serves as a reminder of the qualities that define exceptional leaders: unwavering determination, resilience in the face of challenges, and the courage to make difficult decisions. The Churchill Formula teaches us that true leadership requires a relentless pursuit of goals, the ability to overcome obstacles, and the strength to face adversity head-on.In conclusion, Winston Churchill's leadership formula, comprising determination, resilience, and courageous decision-making, provides invaluable lessons for leaders across generations. By embodying these principles, leaders can inspire and guide others to achieve extraordinary results, just as Churchill did during one of the most challenging periods in history.。

蜂花护发素生产工艺流程

蜂花护发素生产工艺流程

蜂花护发素生产工艺流程Hair conditioner is a common hair care product that is used to improve the texture, appearance, and manageability of hair. 护发素是一种常见的护发产品,用于改善头发的质地、外观和易于管理性。

It is an essential part of many people's hair care routine, as it helps to detangle hair, add moisture, and protect hair from damage. 它是许多人护发日常的重要组成部分,因为它有助于梳理头发、添加水分,并保护头发免受损坏。

Hair conditioners come in various forms, including creams, gels, and sprays, and are typically applied to clean, damp hair before styling. 护发素有各种形式,包括乳霜、凝胶和喷雾,通常在造型前涂抹在清洁的潮湿头发上。

One popular type of hair conditioner is honey hair conditioner, which is said to have moisturizing properties and can help improve the overall health of the hair. 一种常见的护发素是蜂蜜护发素,据说具有保湿作用,可以帮助改善头发的整体健康。

The production process of honey hair conditioner involves several key steps to ensure its quality and effectiveness. 蜂蜜护发素的生产过程涉及多个关键步骤,以确保其质量和有效性。

小学下册第4次英语第五单元自测题[含答案]

小学下册第4次英语第五单元自测题[含答案]

小学下册英语第五单元自测题[含答案]考试时间:90分钟(总分:140)A卷考试人:_________题号一二三四五总分得分一、综合题(共计100题共100分)1. 听力题:She __________ her bike to school.2. 选择题:What do we call a young pig?A. CalfB. PigletC. LambD. Kid答案:B3. 选择题:What do you call a young cat?A. PupB. KittenC. CubD. Calf答案:B4. 选择题:What is the term for a baby horse?A. CalfB. FoalC. PigletD. Chick答案:B5. 听力题:A chemical formula shows the types and numbers of ______ in a compound.6. 选择题:What is the name of the famous archaeological site in Italy?A. PompeiiB. HerculaneumC. Ostia AnticaD. All of the above答案: D. All of the above7. 选择题:What is the main ingredient in tzatziki?A. YogurtB. CucumberC. GarlicD. All of the above8. 选择题:What do you call a person who travels into space?A. PilotB. AstronautC. ScientistD. Engineer9. 填空题:Many __________ (游客) take photos at this site.10. 选择题:What is the name of the toy that can spin on a string?A. Yo-yoB. KiteC. FrisbeeD. Doll答案:A11. 填空题:When I was younger, my favorite toy was a ________ (玩具名). I played with it every day until it broke. I felt very ________ (形容词).12. 听力题:My cousin has a pet ____ (fish) in a tank.13. 填空题:The __________ (气候) affects how plants develop.14. 听力题:The Great Barrier Reef is found off the coast of __________.15. 听力题:The _______ is essential for the ecosystem's balance.16. 听力题:Acids have a sour ______.17. 填空题:The capital city of Kuwait is ________ (科威特的首都城市是________).18. 填空题:My brother is a __________ (创新型人才).19. 听力题:My birthday is in _____ (May/Wednesday).20. 填空题:The ______ (植物的适应性) is vital in changing climates.21. 听力题:The chemical formula for nitric acid is ________.22. 填空题:Cacti grow in _______ environments and need little care.23. 选择题:What do we call a place where animals are kept for public display?A. ZooB. SanctuaryC. HabitatD. Preserve答案: A24. 填空题:A _____ (猴子) is very curious about its environment.25. 填空题:The ________ (植物智能) helps in care.26. 选择题:What is the opposite of 'rich'?A. WealthyB. PoorC. AffluentD. Comfortable答案:B27. 选择题:What is the name of the famous lake in Africa?A. Lake SuperiorB. Lake VictoriaC. Lake BaikalD. Lake Powell28. 选择题:What do we wear on our feet?A. HatB. GlovesC. ShoesD. Scarf答案:C29. 填空题:A ______ (植物病害) can harm crops.30. 选择题:What is the capital of the United States?A. New YorkB. Los AngelesC. Washington,D.C.D. Chicago答案:C31. 听力题:A ______ is a type of animal that has a pouch.32. 选择题:What is the name of the famous American author known for "The Catcher in the Rye"?A. J.D. SalingerB. F. Scott FitzgeraldC. Ernest HemingwayD. John Steinbeck答案: A33. 选择题:What is the capital of England?英国的首都是什么?A. ParisB. LondonC. BerlinD. Madrid答案: B34. 听力题:The sun provides us with _______ energy.We saw a _______ (小鹿) in the woods.36. 填空题:My toy ________ can talk and sing.37. 听力题:The __________ is a famous area known for its celebrations.38. 听力题:The pH level of pure water is ______.39. 填空题:I listen to ______ (音乐) while studying.40. 听力填空题:I love reading fiction books. My favorite book is __________.41. 听力题:My aunt enjoys crafting ____ (scrapbooks).42. 听力题:The chemical formula for potassium sulfate is _____.43. 选择题:What do you call the sound a cat makes?A. BarkB. MeowC. RoarD. Moo答案:B44. 听力题:The _____ (cat/dog) is playful.45. 选择题:What is the capital of Egypt?A. CairoB. AlexandriaC. LuxorD. Giza答案:A46. 填空题:The __________ (历史的脚步声) echo throughout time.The __________ (历史的意义) can evolve over time.48. 填空题:My _______ (猫) enjoys chasing mice.49. 选择题:What is the name of the galaxy we live in?A. Milky WayB. AndromedaC. WhirlpoolD. Triangulum50. 填空题:I can't wait to __________ (动词) with my __________ (玩具名) again.51. 听力题:A _______ change affects only the form of a substance, not its composition.52. 听力题:A ____ is often seen hopping around in fields.53. 填空题:The squirrel's _______ (灵巧) allows it to climb trees.54. 填空题:The city of __________ is known as the "Big Apple." (纽约)55. 填空题:My favorite game is ______ (国际象棋). I enjoy thinking carefully about my ______ (策略).56. 听力题:A _____ occurs when a comet passes close to the sun.57. 听力题:The stars are out at ___. (night)58. 听力题:A non-metal typically has a ______ melting point.59. 选择题:What do you call a baby cat?A. PuppyB. KittenC. CalfD. Chick60. 填空题:Rabbits eat _______ (胡萝卜).61. 听力题:The clock is on the ___ (wall/table).62. 选择题:What is the name of the fairy tale character who had a sleeping curse?A. Snow WhiteB. Sleeping BeautyC. CinderellaD. Rapunzel答案:B63. 听力题:The study of how rocks and minerals interact is called ______ geology.64. 听力题:The ____ is a tiny insect that plays a vital role in pollination.65. 听力题:The flowers are ________ in the vase.66. 填空题:The ______ (小鸟) chirps happily in the morning light, welcoming a new ______ (一天).67. 填空题:The owl has exceptional ______ (视力) at night.68. 选择题:How many pairs of wings do most insects have?A. OneB. TwoC. ThreeD. Four69. 听力题:The __________ is known for its ancient ruins.70. 听力题:The bear is ______ (strong) and big.The __________ (历史的参与感) strengthens community ties.72. 填空题:The ocean is very _______ (广阔的).73. 听力题:There are five ___ on the tree. (birds)74. 听力题:The animals are ______ in the zoo. (playing)75. 填空题:My favorite food is ________ (比萨). I like it with ________ (蘑菇) and ________ (奶酪).76. 听力题:The Great Red Spot on Jupiter is a permanent ______.77. 填空题:The _____ (小狗) loves to play fetch with its owner. 小狗喜欢和主人玩接球游戏。

关于相向而行的相遇问题方程

关于相向而行的相遇问题方程

关于相向而行的相遇问题方程英文版The Problem of Meeting Each Other Heading Toward Each Other: Equations InvolvedIn the realm of mathematics, the problem of two objects moving towards each other from opposite directions, known as the "meeting problem," presents a unique challenge. This scenario involves the use of equations to determine the time and location at which the two objects will meet.Consider two individuals, Alice and Bob, who are walking towards each other from opposite ends of a straight road. Alice is walking at a speed of 5 kilometers per hour (km/h), while Bob is walking at a speed of 4 km/h. If the distance between them is 90 kilometers, how long will it take for them to meet?To solve this problem, we can use the formula for relative speed. The relative speed is the combined speed of the twoobjects when they are moving towards each other. In this case, the relative speed is 5 km/h + 4 km/h = 9 km/h.Now, let's set up an equation to find the time (t) it takes for them to meet. The equation is based on the concept of distance = speed × time. In this case, the distance is 90 kilometers, and the speed is the relative speed of 9 km/h.Therefore, the equation is:90 = 9 × tTo solve for t, we divide both sides by 9:t = 90 ÷ 9t = 10So, it will take Alice and Bob 10 hours to meet each other.This problem demonstrates the importance of equations in solving real-world scenarios involving motion and distance. By understanding the concept of relative speed and applying it to equations, we can accurately predict the outcome of such situations.中文版相向而行的相遇问题:涉及的方程在数学领域,两个物体从相对的方向朝彼此移动的问题,即“相遇问题”,提出了一个独特的挑战。

紫杉醇与白藜芦醇联合用药对人肝癌细胞HepG-2活性的影响

紫杉醇与白藜芦醇联合用药对人肝癌细胞HepG-2活性的影响

紫杉醇与白藜芦醇联合用药对人肝癌细胞HepG-2活性的影响耿文峰;伍春莲;陈杨琼;张思楠;孙警辉【摘要】作为两种较常见的抗癌药物,紫杉醇与白藜芦醇在临床试验中均证实具有良好的抗癌效果.本文意在研究紫杉醇与白藜芦醇单独及联合用药时对人肝癌细胞HepG-2活性的影响,探索两种药物联合应用时的药效变化.实验中通过CCK.8法测定了不同浓度的紫杉醇和白藜芦醇单独及联合用药时对人肝癌细胞HepC-2的活性影响,计算出其抑制率和半抑制率浓度,并通过金氏修正公式进行药效判定.结果发现当紫杉醇和白藜芦醇单独用药时,两者对HepG-2细胞的生长均有较高的抑制作用,在设定的药物浓度范围内,前后两者的抑制率分别达到了45.81%-81.80%和34.43%-93.60%,并且呈现出明显的剂量依赖性.当二者联合作用时,紫杉醇与白藜芦醇分别在在5—20umol/L以及100—1000umol/L的浓度范围内呈现出相加效果,且药品的半抑率制浓度均出现不同程度的降低,分别由单独用药时的1.47和122.07umol/L下降至联合作用时的0.65和42.41umol/L.据此判断,紫杉醇与白藜芦醇联合作用确实可显著增强药物对HepG-2细胞的抑制作用.二者具有相加抗肿瘤效果.%Paclitaxel and resveratrol are two common anti-cancer drugs that have proved effective in clinical trials. In this study, we investigated the independent effect of the two drugs as well as their combined effect on the viability of HepG-2 cells, trying to elucidate the joint effect of the two drugs. The independent and combined effects of the two drugs on HepG-2 at various concentrations were measured by CCK-8 assay; inhibitory rates and IC50 were calculated and efficacies were judged according to the Revised Jin'sFormula. Both paclitaxel and resveratrol showed strong inhibitory effect on HepG-2 cells and at the tested concentration the inhibitory rates were up to 45.81% - 81.80% and 34.43% -96.30% respectively, showing an obvious dose-dependency. The two drugs showed combined effects when used together at the concentration of 5 -20 umol/L for paclitaxel and 100 - 1000umol/L for resveratrol. And their IC50 were also decreased from 1.47umol/L and 122.07umol/L when used independently to 0. 65umoL/L and 42.41 umol/L when used together. Our results confirmed that combination use of paclitaxel and resveratrol can significantly enhance their anti-cancer effect, that is to say, the two drugs have synergy effect.【期刊名称】《西华师范大学学报(自然科学版)》【年(卷),期】2012(033)003【总页数】5页(P261-264,269)【关键词】紫杉醇;白藜芦醇;人肝癌细胞HepG-2;CCK-8【作者】耿文峰;伍春莲;陈杨琼;张思楠;孙警辉【作者单位】西华师范大学生命科学学院西南野生动植物资源保护教育部重点实验室,四川南充637009;西华师范大学生命科学学院西南野生动植物资源保护教育部重点实验室,四川南充637009 三峡库区生态环境与生物资源省部共建国家重点实验室,重庆北培400715;西华师范大学生命科学学院西南野生动植物资源保护教育部重点实验室,四川南充637009;西华师范大学生命科学学院西南野生动植物资源保护教育部重点实验室,四川南充637009;西华师范大学生命科学学院西南野生动植物资源保护教育部重点实验室,四川南充637009【正文语种】中文【中图分类】R151当今社会,随着环境污染的日益加剧,人类的生活环境正不断恶化,与致癌因素的接触越发频繁,癌症的发病率也随之逐年升高.肝癌是死亡率仅次于胃癌和食道癌的人类第三大常见恶性肿瘤,在临床上一般多采取手术、放化疗与中药结合的方法进行治疗,但晚期患者因癌细胞扩散而治愈率较低,因此不断寻求新的更有效的肝癌治疗方法和抗肝癌药物配方成为了现今医学界面临的首要课题之一.紫杉醇(taxol,以下简称TAX)是红豆杉属植物产生的一种复杂的次生代谢产物,也是目前所知的惟一种可以促进微管聚合和稳定已聚合微管的药物.据相关研究表明:细胞在接触紫杉醇后会在细胞内积累大量的微管,这些微管的积累干扰了细胞的各项生理功能并阻断了细胞的正常有丝分裂进程[1],可以使细胞的生长趋于停滞,因而具有良好的抗癌功效.相关实验研究[2]表明:紫杉醇对多种体外培养的肿瘤细胞特别是肝癌细胞均具有较强的生长抑制作用,但紫杉醇与其它药物联合抗肝癌的研究目前却鲜有报道[3].本实验以人肝癌细胞HepG-2作为研究对象,结合另一种常规化疗药物[4]白藜芦醇(resveratrol,以下简称RES),通过CCK-8法检测紫杉醇和白藜芦醇单独以及联合用药时对人肝癌细胞HepG-2的抑制作用,并通过金氏修正公式定量分析两种药物合用时的相互作用效果,以求了解紫杉醇与白藜芦醇联合用药的特性以及应用于临床的可行性.细胞:人肝癌细胞株HepG-2(购于川北医学院生化与分子免疫研究所).试剂:RPMI1640培养基(购于Gibco公司,美国);胎牛血清(购于杭州四季青生物制品公司,中国);双抗(青霉素,链霉素,购于Gibco公司,美国);胰蛋白酶(购于Amresco公司,美国);TAX(HPLC≥99%)和RES(HPLC≥98%),均购于瑞芬思公司,中国;CCK-8(购于Dojindo化学研究,日本).仪器:自动酶标仪(购于Thermo公司,美国),倒置显徽镜(购于Olympus公司,日本),CO2培养箱(购于Sanyo公司,日本).1.2.1 细胞培养将人肝癌细胞HepG-2培养于含有10%的灭活的胎牛血清(fetalbovine serum,FBS)、100U/mL青霉素、100μg/mL链霉素、pH7.4的RPMI-1640完全培养液中,于37℃、5%CO2培养箱中进行培养.细胞贴壁生长,每3-4d分瓶一次,取处于对数生长期的细胞进行试验.1.2.2 CCK-8法测定药物对细胞活性的影响实验前用胰酶将处于对数生长期的HepG-2细胞进行消化处理,并吹打成均匀悬液,以5×104个/mL的浓度接种于96孔板中,每孔100μL培养液.经过24h后,依次加入不同浓度的药物进行试验,包括TAX单独用药组、RES单独用药组和TAX、RES联合用药组.使TAX单独用药组的最终浓度依次为1、2、5、10和20μmol/L,RES单独用药组的最终浓度依次为50、100、200、500和1000μmol/L,联合用药组的最终浓度分别为 TAX(1、2、5、10、20μmol/L)+RES(200μmol/L)和 RES(50、100、200、500、1000μmol/L)+TAX(5μmol/L),对照组不加药物,每组浓度均设5个平行孔.于37℃、5%的CO2培养箱内培养24h,弃上清,而后向每孔中依次加入10μl的CCK-8溶液,将96孔培养板放在培养箱内继续孵育4h.用酶标仪测定各孔在450nm处的吸光度,细胞生长抑制率=(1-实验组OD值/对照组OD值)×100%.实验重复3次,结果取平均值.1.2.3 数据统计根据公式lgIC50=Xm-I〔(P-(3-Pm-Pn)/4〕计算TAX和RES的半抑制率浓度(其中Xm:lg最大剂量;I:lg(最大剂量/相临剂量);P:阳性反应率之和;Pm:最大阳性反应率;Pn:最小阳性反应率).关于两种药品联合作用时的药效在本次实验中采用金氏修正公式:q=E(A+B)/(EA+EB-EAⅹEB)进行求算.公式中分子代表实测合并效应,分母是期望合并效应.若计算结果q<0.85则表示两药相互拮抗;q>1.15表示两药具有协同作用;q=0.85-1.15表示两药作用相加.由图1可知:用不同浓度(1,2,5,10,20μmol/L)的TAX单独作用于HepG-2细胞24h,5种浓度的药品对肿瘤细胞的生长均具有明显的抑制作用,且抑制率的大小随药物浓度的增加而增加.计算发现,TAX的半抑制率浓度为1.47μmol/L.RES对HepG-2细胞的生长也具有类似的作用规律,24h后,其半抑制浓度为122.07μmol/L(图 2).由图3、图4可知联合用药组在实验中对肿瘤细胞的抑制作用也表现出了明显的浓度依赖性,两组药品的半抑制率浓度分别达到了0.65μmol/L和42.41μmol/L.通过进一步对比发现与对应浓度的单独用药组相比,联合用药组对细胞的抑制率明显增加:TAX(1、2、5、10、20μmol/L)+RES(200μmol/L)联合用药组作用24h后,其对 HepG-2细胞的抑制率为58.99% -89.53%,明显高于TAX单独作用时的45.81% -81.80%,TAX的半抑制浓度也由单独用药时的1.47μmol/L 下降至联合作用时的0.65μmol/L.同样,RES(50、100、200、500、1000μmol/L)+TAX(5μmol/L)联合用药组的抑制率(61.71% -97.61%)也明显高于同浓度下RES单独用药组的抑制率(34.43% -93.60%),其半抑制浓度则由122.07μmol/L下降到了更小的42.41μmol/L.两药合用时,按金氏公式计算q值,判断两药之间是拮抗、相加或协同.详见表1、表2.结果表明当TAX的浓度处于1-2μmol/L之间时其与200μmol/L的RES联合作用表现为拮抗,作用效果优于单体而弱于两者之和,而在5-20μmol/L范围内时则表现为相加.RES则是在50μmol/L时与TAX联合作用表现为拮抗,而在100-1000μmol/L时表现为相加.由此判断,紫杉醇与白藜芦醇联合作用确实可显著增强药物对HepG-2细胞的抑制作用.肝癌作为目前世界上最常见的恶性肿瘤之一,其死亡率在所有消化系统相关的癌症中居于第三位,在我国每年因肝癌而致死的病患总数高达11万人,占全世界因肝癌死亡人数的45%.肝癌一般具有恶性度高、病情发展快等特点,病人早期身体往往不会感觉到明显的不适,但一旦出现症状就诊,就已属于中晚期,且治疗难度大、疗效差,术后5年生存率极低,一般病人发病后生存的时间仅为6个月左右,人称“癌中之王”,是一种非常可怕危险的恶性疾病.对于进展期肝癌,联合化疗是目前最常见的治疗手段之一[5],但是许多患者往往会因耐受不住化疗对机体的毒副作用而选择放弃治疗,甚至更有身体状况不佳的患者会出现因化疗而加速死亡的现象.因此,不断寻求新的更有效的肝癌治疗方法和抗肝癌药物配方成为了现今医学界面临的首要课题之一.紫杉醇作为目前世界上最热门也是最昂贵的广谱抗癌药物之一因其独特的抗癌机制和明显的药物疗效[6,7],已经引起了科学界的广泛重视.而白藜芦醇作为目前临床中最常用抗肿瘤药物之一,也具有极好的抗癌功效.本实验通过对紫杉醇和白藜芦醇联合抗癌的研究,初步探索了两种药物单独及联合作用时的药效变化,以期减少化学抗癌药物的用量,降低其对机体的毒副作用.本研究结果表明,紫杉醇和白藜芦醇单独用药时均可抑制人肝癌细胞株HepG-2的生长,并且呈现出明显的剂量依赖性.当二者联合作用时,紫杉醇与白藜芦醇分别在在5-20μmol/L以及100-1000μmol/L的浓度范围内呈现出相加效果,且药品的半抑率制浓度均出现不同程度的降低,说明两种药联合作用比单独作用具有更好的抗癌疗效.作用 24h 后,TAX(1、2、5、10、20μmol/L)+RES(200μmol/L)、RES(50、100、200、500、1000μmol/L)+TAX(5μmol/L)联合用药组中TAX和RES的半抑制浓度分别由单独用药时的1.47和122.07μmol/L下降至联合作用时的0.65和42.41μmol/L,明显降低了紫杉醇和白藜芦醇的用量及毒副作用,达到了预期效果,证实了多种单体药物联合抗癌的可行性.目前有关抗癌药物联合用药的研究,俨然已成为当今分子生物学领域和药物学领域一个新的研究热点,近年来相关研究表明多种类黄酮混合物联合用药时可显示出明显的加合效果[8,9],但有关紫杉醇类化合物与其它药物联合抗肝癌的研究目前却鲜有报道.因此本研究成果对目前临床相关药物的筛选及应用具有十分有效地指导意义,也为肝癌新综合治疗方案的出现提供了理论基础.【相关文献】[1]SYMMANS W F,VOLM M D,SHAPIRO R L,PERKINS A B,KIM A Y,DEMARIA S,YEE H T,MCMULLEN H,ORATZ R,KLEIN P,FORMENTI S C,MUGGIA F.Paclitaxel-Induced Apoptosis and Mitotic Arrest Assessed by Serial Fine-NeedleAspiration:Implications for Early Prediction of Breast Cancer Response to Neoadjuvant Treatment[J].Clin Cancer Res,2000,6(12):4610-4617.[2]余元龙,季明芳,何洁冰,李晓玲.紫杉醇对肝癌细胞增殖抑制和诱导凋亡的效应研究[J].中华实验外科杂志,2004,21(7):877-878.[3]潘洪明,费洪新,黄小义.紫杉醇与白藜芦醇联合应用对人胃癌MGC803细胞作用的研究.中华中医药杂志(原中国医药学报),2008,23(9):815-817.[4]KIMURA Y,OKUDA H.Resveratrol Isolated Form Polygonum Cuspidatum Root Prevents Tumor Growth and Metastasis to Lung and Tumor-Induced Neovascularivetionin Lewis Lung Carcinoma-Bearing Mice[J].J Nutr,2001,131(6):1844.[5]WYLLIE A H.Apoptosis:Death Gets a Brake[J].Nature,1994,369(6478):272 -273. [6]JESNOWSKI R,ZUBAKOV D,FAISSNER R,RINGEL J,HOHEISEL J D,L¨OSEL R,SCHN¨OLZER M,L¨OHR M.Genes and Proteins Differentiall y Expressed during in Vitro Malignant Transformation of Bovine Pancreatic Duct Cells[J].Neoplasia,2007,9(2):136-146.[7]TOIYAMA Y,INOUE Y,HIRO J,OJIMA E,WATANABE H,NARITA Y,HOSONO A,MIKI C,KUSUNOKI M.The Range of Optimal Concentration and Mechanisms of Paclitaxel in Radio-Enhancement in Gastrointestinal Cancer Cell Lines[J].Cancer Chemother Pharmaco,2007,59(6):733-742.[8]CUI Y Y,XIE H,WANG J F.Potential Biomedical Properties of Pinus MassonianaBark Extract[J].Phytother Res,2005,19:34-38.[9]TERI L,WADSWORTH,DENNIS R K.Effects of Ginkgo Biloba Extract(EGb 761)and Quercetin on Lipopolysaccharide-Induced Release of Nitric Oxide[J].Chem Bio Interact,2001,137:43 -58.。

  1. 1、下载文档前请自行甄别文档内容的完整性,平台不提供额外的编辑、内容补充、找答案等附加服务。
  2. 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
  3. 3、如文档侵犯您的权益,请联系客服反馈,我们会尽快为您处理(人工客服工作时间:9:00-18:30)。

Abstract: This paper presents the results of a detailed two-dimensional analysis of the torsional stiffness of several pairs of spur gears in mesh using finite element methods. The model on which this research is based allows the generation of pairs of spur gears in contact with several different parameters and includes an adaptive meshing algorithm for the contact zones. The FEA results from the various model settings are used to develop a common formula for the combined torsional stiffness of spur gears in mesh. The torsional mesh stiffness of gears in mesh consists of three main components which are the body, teeth and contact stiffnesses. The introduced formula uses these three parts to determine the stiffness for a wide range of gear and gear ratio combinations. Keywords: gear dynamic modelling, spur gear, finite element modelling, torsional mesh stiffness, contact stiffness.
constraints, contact elements and different torque loads to the model, solves and post processes the job.
2a Remeshed Contact for single contact
2b Remeshed Contacts for double contact
Figure 1 Result from the first APDL-Script; premeshed geometry of pinion and gear Thereafter the mesh of the model was refined at the co ntact points using another APDL-Script to keep computing time as low as possible. The result is shown in Figure 2. This script also adds the
3
The combined torsional mesh stiffness
In 2001, Jia introduced a common formula [2], which described the combined torsional mesh stiffness by body and tooth bending stiffness. This formula did not include the effect of the applied torque on the gearing's stiffness. The results of the current research, however, show that there is a significant influence of the torque on the resulting combined torsional mesh stiffness as shown in Figure 4. Further studies of the deformational behaviour of the gear wheels have shown that the deformation and therefore the stiffness of body and teeth are almost load-independent while the contact
Figure 2 Adaptive refining of the mesh at the contact point(s) The constraints used in the model are shown in Figure 3. The hub of the gear was completely constrained from motion; the nodes at the hub of the pinion could only rotate around the centre of the pinion. The torque was applied using a force on every node at the pinion's hub, adding up to the desired torque.
Figure 3 Constraints and loads used in the model (constraints: cyan, loads: red) The results extracted from the model include the combined torsional mesh stiffness, deformation of gear body, teeth and contact zone for both pinion and gear. These were written to a text file for further processing. When analysing gears with tooth shape errors or profile correction, an initial gap between the teeth can occur. In order to create a very flexible model which can be used in further studies, the model was built to be able to solve problems including an initial gap between meshing teeth. Typically a static FE model cannot be solved if some parts of the model do not have enough constraints. This can happen, for example, if a contact is not initially closed and in this case the pinion can rotate a small angle without any resistance or stiffness. To solve models with this rigid body motion, a spring was attached to the pinion to add a small stiffness which prevents any free rotational motion. In order not to falsify the simulation results, this spring is only used for the first simulation step with a very small torque just to get the teeth in contact. In the next simulation step, when applying the required torque, the spring is disabled using the death of elements co mmand. This approach can handle much bigger gaps (rigid body motion) than the automatic adjustment which tends to be used by default.
a
In cooperation with Prof. Dr.-Ing. Bernd Sauer, Institute of Machine Elements, Gears and Transmissions, University of Kaiserslautern b ANSYS Parametric Design Language
1
Introduction
ห้องสมุดไป่ตู้
Gears are used in many different kinds of rotating machinery and they are often a critical part to the function of the machinery. There have been many attempts in recent years to understand and describe the process of the meshing of spur gears. As the process of meshing is very complex and difficult to describe, the finite element analysis is the method of choice to investigate the underlying relationships. For the model presented in this paper an FEA model of the complete gear arrangement is used. Recent studies on this topic [1-4] have shown that these models produce the best results in comparison with single-tooth models or partial teeth models. As computer hardware and FEA software advances, working with these rather complex models is now feasible.
相关文档
最新文档