河南省镇平县第一高级中学2017-2018学年高一上学期综
河南省镇平县第一高级中学高一年级上册生物期末模拟试卷
河南省镇平县第一高级中学高一年级上册生物期末模拟试卷一、单选题1．科研人员测定甲、乙两植物CO2吸收速率随CO2浓度的变化如图所示。
下列说法正确的是（）A．甲更适合在CO2浓度较低的大棚中种植B．碳反应中固定CO2的酶的活性甲植物高于乙植物C．乙植物达到CO2饱和点时既不吸收O2也不释放CO2D．M点时甲植物光反应产生ATP和NADPH的速率达到最大2．N个氨基酸组成了M个多肽，其中有Z个是环状肽。
据此分析下列表述错误的是（）A．这些多肽一定都含有C、H、O、N这些元素B．形成这些多肽，至少脱去了N-M+Z个水分子C．这M个多肽至少含有N-M+Z个氧原子D．这些多肽至少含有的游离氨基数和游离羧基数均为M-Z3．离体的叶绿体在光照下进行稳定光合作用时，如果突然撤去光照，短暂时间内叶绿体中物质相对含量的变化是（）A．ATP增多，NADPH减少B．ATP减少，NADPH增多C．C3化合物减少，C5化合物增多D．C3化合物增多，C5化合物减少4．下列实验中，加入试剂后不能产生特定颜色的是（）A．取成熟香蕉匀浆，用斐林试剂加热检测还原糖B．黑暗中放置24h的天竺葵叶片，用碘液检测淀粉C．口腔上皮细胞经健那绿染色后，在显微镜下观察线粒体D．花生子叶经苏丹III染色后，在显微镜下观察脂肪颗粒5．某三十九肽中共有丙氨酸4个，现去掉其中的丙氨酸得到4条长短不等的多肽(如图)，与原三十九肽对比，下列有关该过程的叙述中，不正确的是( )A．肽键数目减少8个B．C原子减少12个C．氨基和羧基分别增加3个D．O原子数目减少1个6．图为某动物细胞合成的分泌蛋白运输到细胞外的过程图。
下列叙述错误的是（）A．研究分泌蛋白的形成过程可用同位素标记法B．结构③在分泌蛋白运输中起交通枢纽的作用C．分泌蛋白的合成和分泌与④有密切关系D．此图所示结构①能进行细胞间的信息交流7．下列关于“用高倍显微镜观察叶绿体和细胞质的流动”实验的叙述，错误的是（）A．可选用藓类叶、黑藻叶或者紫色洋葱鳞片叶的外表皮作为实验材料B．为防止叶绿体失水，在实验过程中临时装片要始终保持有水状态C．观察细胞质流动之前，供观察的黑藻应放在光照、室温条件下培养D．观察细胞质流动，先找到细胞中的叶绿体，然后以叶绿体为参照物8．运用光合作用原理，科学种植作物，可有效提高产量。
河南省镇平县第一高级中学2017-2018学年高一上学期综合检测地理试题 Word版含解析
镇平一高2017秋高一地理综合检测一．选择题(共25题，每小题2分）读图，完成下面小题。
1. 下列说法正确的是( )①石灰岩是岩浆岩，大理岩是沉积岩②石灰岩是由化学沉淀物或生物遗体堆积而成的③大理岩是由石灰岩变质后形成的④石灰岩是矿产，大理岩不是矿产A. ①③B. ②④C. ②③D. ①④2. 下列说法正确的是( )A. 岩浆侵入地壳，冷却凝固形成大理岩B. 岩浆侵入地壳产生的高压，使石灰岩变质成大理岩C. 长石、方解石组成了大理岩D. 在石灰岩中能够找到化石3. 下列岩石中，与图示岩石类型无关的是( )A. 花岗岩B. 砂岩C. 煤D. 板岩【答案】1. C 2. D 3. A【解析】考查三大类岩石及相互转化。
1. 石灰岩是由化学沉淀物或生物遗体堆积而成的，是沉积岩，②正确；大理岩属于变质岩，也属于矿产，③正确。
选C。
2. 石灰岩为沉积岩，在该岩石中能够找到化石；大理岩是由石灰岩经变质作用形成的，它是由方解石组成的岩石。
D正确。
3. 图中岩石有沉积岩和变质岩，而花岗岩属于岩浆岩。
A正确。
下图为岩石圈物质循环简图，图中b类岩石中含有化石。
读图回答下面小题。
4. 图中a、b、c、d最可能代表岩浆的是( )A. aB. bC. cD. d5. 图中表示变质作用的是( )A. ①B. ②C. ③D. ④【答案】4. C 5. C【解析】考查岩石圈物质循环。
4. 根据图中各箭头的指向可知，c只能形成a，故c为岩浆，a为岩浆岩。
C正确。
5. 图中①为岩浆活动，②为外力作用，③为变质作用，④为重熔再生。
C正确。
6. 日本御岳火山喷发的能量主要来自( )A. 太阳辐射能B. 重力能C. 核聚变反应D. 放射性元素衰变【答案】D【解析】火山喷发主要是地球内能的释放，能量主要来自地球内部放射性元素衰变。
故选D。
7. 下列地形区中，主要由内力作用形成的是( )①安第斯山②青藏高原③黄土高原④珠江三角洲⑤东非大裂谷A. ①②③B. ④⑤C. ①③⑤D. ①②⑤【答案】D【解析】黄土高原是风力沉积作用形成，珠江三角洲是流水堆积作用形成，均属于外力作用形成；安第斯山脉和青藏高原属于板块碰撞挤压形成，东非大裂谷属于板块内部张裂形成，①②⑤属于内力作用形成。
河南省镇平县第一高级中学2017-2018学年高一上学期期末考前训练语文试题
镇平一高2017——2018高一上学期期末语文考前训练一、选择题1.下列词语中，加点字注音全都正确的一项是（）A. 遒劲．（jìn）浑身解．数（xiâ）弄．堂（lîng）否．极泰来（pĭ）B. 木讷．（nâ）叱咤．风云（zhà）匏．樽（páo）浩浩汤．汤（shāng）C. 侘傺．（chì）流觞．曲水（shāng）创．伤（chuāng）咄．咄逼人（duï）D. 觊．觎（jì）大腹便．便（pián）犒．劳（kào）溯．流而上（shuî）2. 下面加点字的注音完全正确的一项是（）A．袅．（niǎo）娜敛裾．（jū）涸．（hã）辙媛．（yuán）女B．霎．（chà）时一椽．（chuán）面颊．（jiá）混沌．（dùn）C．鞭挞．（tà）船舶．（pō）隽．（juàn）永漪．（yī）澜D．黝．（yǒu）黑蕈．（xùn）菌瞥．（piē）见吞噬．（shì）3. 下列加点字的读音，全部正确的一组是( )A．愆．期(yán) 垝．垣(ɡuǐ) 陨．落(yǔn) 帷裳．(chánɡ)B．攘诟．(ɡîu) 溘．死(hã) 侘傺．(chì) 公姥．(mǔ)C．伶俜．(pīnɡ) 遗．施(wâi) 否．泰(pǐ) 鲑．珍(xiã)D．拾掇．(chuî) 吐哺．(bǔ) 羁．鸟(jī) 樊．笼(fán)4. 下列加点字读音全都正确的一项是（）A．壬．（rãn）戌窈窕．（tiǎo）桂棹．（zhào）冯．（fãng）虚御风B．嫠．（lí）妇愀．（qiǎo）然舳．（yïu）舻山川相缪．（liáo）C．酾．（shī）酒横槊．（shuî）江渚．（zhǔ）正襟．（jīn）危坐D．匏．（páo）樽枕藉．（jí）蜉．（fú）蝣一叶扁．（piān）舟5. 下列加点的字注音全部正确的一项是( )A．商榷．（quâ）估量．(liánɡ) 芜．杂(wú) 豁．(huō)然开朗B．会晤．（wǔ）诚挚．(zhì) 端倪．(ní) 永葆．生机(bǎo) C．陶冶．(yě) 砥．砺(dǐ) 萎．缩(wěi) 卓．有成效(zhuï) D．剥．夺(bāo) 戳．子(chuō) 蜕．变(tuì) 骇．人听闻(hài)6. 下列词语中，没有错别字的一项是（）A. 葳蕤踯躅普陀山嘉言懿行B. 指摘猗郁居心叵测降龙服虎C. 訾詈弭乱责无旁待相形见拙D. 彭殇敷衍旁证博引绿草如荫7.下列各组词语中，没有错别字的一组是（）A．消受斑驳点缀悠远迁延顾步B．颓废萧索喇叭嬉游梳梳落落C．攀缘骄弱宛然犹疑繁茂苍绿D．凝滑黯淡玷污鼓膜慢不经心8. 下列各组词语中，书写全部正确的一组是( )A．尔卜尔噬夙兴夜寐信誓旦旦雨雪霏霏B．鸷鸟不群芳泽杂揉屈心抑志欲盖弥彰C．踯躅不前情投意和窈窕无双藕断丝联D．同心离居越陌度阡譬如朝露守拙田园9. 下列各组词语中，书写全部正确的一组是( )A. 放浪形骸游目聘怀曲水流殇若合一契B. 临文嗟悼修禊事也清流急湍举酒嘱客C. 酾酒临江横槊赋诗舳舻千里沧海一栗D. 愀然不乐山川相缪倚歌而和浅尝辄止10. 下列词语字形全都正确的一项是 ( )A．肤浅忌恨繁芜从杂义愤填赝B．暇想履行心急如焚安之若素C．飘渺携手祟山峻岭汹涌澎湃D．承诺磐石不能自拔摇摇欲坠11. 与下面例句修辞不同的一项是（）例句：塘中的月色并不均匀；但光与影有着和谐的旋律，如梵婀玲上奏着的名曲。
河南省镇平县第一高级中学2017—2018学年高一上学期期
河南省镇平县第一高级中学2017—2018学年高一上学期期末测试 数学试题第Ⅰ卷（共60分）一、选择题：本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.1. 设(){},46A x y y x ==-+，(){},53B x y y x ==-，则A B ⋂等于（ ）A ．{}1,2B ．(){}1,2C ．{}1,2x y ==D ． ()1,2 2.如果1,1a b ><-，那么函数()x f x a b =+的图象在（ ） A.第一、二、三象限 B.第一、三、四象限 C.第二、三、四象限 D.第一、二、四象限3.设{}{}12,A x x B x x a =<<=<，若A B Þ，则a 的取值范围是（ ） A ．2a ≥ B ．1a ≤ C ．1a ≥ D ．2a ≤4.设()()2log 20x f x x =>，则()3f 的值是（ ） A ．128 B ．256 C ．512 D ．85.已知函数()2x y f =的定义域是[]1,1-，则函数()2log y f x =的定义域是（ ）A ．()0,+∞B ．()0,1C ．[]1,2D ．4⎤⎦6.若函数()y f x =的值域是1,32⎡⎤⎢⎥⎣⎦，则函数()()()1F x f x f x =+的值域是（ ）A ．1,32⎡⎤⎢⎥⎣⎦B ．102,3⎡⎤⎢⎥⎣⎦C ．510,23⎡⎤⎢⎥⎣⎦D ．103,3⎡⎤⎢⎥⎣⎦7.已知幂函数()a f x x =的图像过点11,42⎛⎫⎪⎝⎭，则式子4a 的值为（ ）A ．1B ．2C ．12 D ．148.定义在R 上的函数()f x 满足()()()()2,f x y f x f y xy x y R +=++∈，()12f =，则()3f -等于（ ）A ．2B ．3C ．6D ．99.设1a >，且()()()2log 1,log 1,log 2a a a m a n a p a =+=-=，则,,m n p 的大小关系为（ ） A ．n m p >> B ．m p n >> C ．m n p >> D ．p m n >>10.定义运算a b *，()(),,a a b a b b a b ⎧≤⎪*=⎨>⎪⎩例如121*=，则函数12x y =*的值域为（ ）A ．()0,1B ．(),1-∞C ．[)1,+∞D ．(]0,111.某种细胞在生长过程中，每10分钟分裂一次（由一个分裂为两个），经过2小时后，此细胞可由一个繁殖成（ ）A ．511个B ．512个C ．112个D ．122个 12.方程2121x x x++=（ ） A.无实根B.有异号两根C.仅有一负根D.仅有一正根第Ⅱ卷（共90分）二、填空题（每题5分，满分20分，将答案填在答题纸上）13. 函数()()1log 3x y x -=-的定义域是 ． 14.函数()212log 56y x x =--的递减区间是 ．15.用二分法求函数()y f x =在区间()2,4上的近似解，验证()()240f f <，给定精度为0.1，需将区间等 分 次.16.已知函数()f x 满足:（1）对任意12x x <，都有()()12f x f x <；（2）()()()1212f x x f x f x +=⋅.写出一个同时满足这些条件的函数解析式 ．三、解答题 （本大题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤.）17.（1）求值：lg 2lg50lg5lg 20lg100lg5lg 2+-； （2）已知55log 3,log 4a b ==，用,a b 表示25log 12.18.已知()f x 是定义在()2,2-上的减函数，并且()()1120f m f m --->，求实数m 的取值范围.19.设函数()y f x =（x R ∈且0x ≠）对定义域内任意的12,x x ，恒有()()()1212f x x f x f x ⋅=+.（1）求证：()()110f f =-=； （2）求证：()y f x =是偶函数；（3）若()f x 为()0,+∞上的增函数，解不等式()102f x f x ⎛⎫+-≤ ⎪⎝⎭.20.已知函数()()221xf x a a R =-∈+. （1）判断()f x 在定义域上的单调性；（2）要使()0f x ≥恒成立，求实数a 的取值范围. 21.如过函数()f x 对于定义域内的任意两个数12,x x 都满足:()()1212122x x f f x f x +⎛⎫≤+⎡⎤ ⎪⎣⎦⎝⎭，那么称函数()f x 为下凸函数；而总有()()1212122x x f f x f x +⎛⎫≥+⎡⎤ ⎪⎣⎦⎝⎭时，那么称函数()f x 为上凸函数.根据以上定义，判断指数函数()x f x a =（0a >且1a ≠）在R 上是否为下凸函数，并说明理由.22.定义在R 上的函数()f x 满足()()2f x f x +=，且()()f x f x -=-.当()0,1x ∈时，()241xxf x =+. （1）求()f x 在[]1,1-上的解析式； （2）证明()f x 在()0,1上是减函数；（3）当λ取何值时，方程()f x λ=在[]1,1-上有解.试卷答案一、选择题1-5: BBABD 6-10: BBCBD 11、12：DD二、填空题13. ()()1,22,3⋃ 14. ()6,+∞ 15. 5 16.2x y =三、解答题17.（1）原式()()lg2lg252lg5lg 452lg5lg2=⨯+⨯- ()()lg22lg5lg2lg52lg2lg52lg5lg2=+++-()()222lg2lg5lg22lg2lg5lg52lg5lg2=+++- ()()22lg2lg5lg101=+== （2）55525255log 12log 3log 4log 12log 25log 52a b++===.18.由()()1120f m f m --->可得()()112f m f m ->-. 又()f x 是定义在()2,2-上的减函数， ∴112,212,22m m m m -<-⎧⎪-<-<⎨⎪-<1-2<⎩2,313,13,22m m m ⎧<⎪⎪⇒-<<⎨⎪⎪-<<⎩1223m ⇒-<<，即12,23m ⎛⎫∈- ⎪⎝⎭.19.（1）∵0x ≠，()()()1212f x x f x f x ⋅=+， 令121x x ==，()()121f f =，∴()10f =， 令121x x ==-，()()121f f -=-，∴()10f -=. （2）∵x R ∈且0x ≠，恒有()()()1212f x x f x f x ⋅=+， 令121,x x x =-=，∴()()()11f x f f x -⋅=-+， ∴()()f x f x -=，∴()y f x =是偶函数.（3）∵()f x 在()0,+∞上为增函数，则在(),0-∞上是减函数，又()102f x f x ⎛⎫+-≤ ⎪⎝⎭，∴()112f x x f ⎡⎤⎛⎫-≤ ⎪⎢⎥⎝⎭⎣⎦或()112f x x f ⎡⎤⎛⎫-≤- ⎪⎢⎥⎝⎭⎣⎦，∴1012x x ⎛⎫<-≤ ⎪⎝⎭，①或1012x x ⎛⎫>-≥- ⎪⎝⎭，②0x ≤<或12x <≤20.（1）显然对任意x R ∈且210x +≠， ∴()f x 的定义域为R . 设12,x x R ∈，且12x x <，则()()2121222121x x f x f x a a -=--+++ 12222121x x =-++ ()()()21122222121x x x x -=++∵2x y =为增函数，且21x x >，∴212x x >2.而()()12121x x 2++>0恒成立， 于是()()21f x f x ->0，即()()21f x f x >， 故()f x 是R 上的增函数. （2）由()0f x ≥恒成立，可得221x a ≥+恒成立. ∵对任意的,20x x R ∈>， ∴211x +>， ∴10121x<<+， ∴20221x <<+. 要使221xa ≥+恒成立，只需2a ≥即可，即a 的取值范围是[)2,+∞. 21.因为2212222222x x x x x x f a a a ++⎛⎫==⋅ ⎪⎝⎭，()()12121122x x f x f x a a ⎡⎤+=+⎡⎤⎣⎦⎣⎦， 所以()()1212222212112222x x x x x x f f x f x a a a a ⎡⎤+⎛⎫-+=-+-⎡⎤⎢⎥ ⎪⎣⎦⎝⎭⎣⎦12222102x x a a ⎛⎫=--≤ ⎪⎝⎭，所以()()2212122x x f f x f x +⎛⎫≤+⎡⎤ ⎪⎣⎦⎝⎭对于R 上的任意两个数恒成立，所以指数函数在R 上为下凸函数.22.（1）设()1,0x ∈-，则()0,1x -∈.∵()()f x f x -=-，且()0,1x ∈时，()241x x f x =+，∴()1,0x ∈-时，有()()224114x xx xf x f x --=--=-=-++. 在()()f x f x -=-中，令0x =得 ()()()0000f f f -=-⇒=.∵()()2f x f x +=，()()f x f x -=-，令1x =-， 得()()()()121,11f f f f -+=--=-，∴()()()1110f f f =-⇒=，从而()10f -=， ∴当[]1,1x ∈-时，有 ()()(){}2,0,1,412,1,0,410,1,0,1.xxxx x f x x x ⎧∈⎪+⎪⎪=-∈-⎨+⎪⎪∈-⎪⎩（2）设1201x x <<<，则210x x ->，()()212121224141x x x x f x f x -=-++()()()()12121222214141x x x x x x +--=++. ∵1201x x <<<，∴1202x x <+<， ∴1221x x +>，且2122x x >， ∴122x x +-1>0，1222x x -<0. 又∵12410,410x x +1>>+1>>， ∴()()()()121212222104141x x x x x x +--<++，即()()210f x f x -<，∴()f x 在()0,1上是减函数.（3）方程()f x λ=在[]1,1-上有解的充要条件是，λ在函数()f x ，[]1,1x ∈-的值域内取值.∵()0,1x ∈时，()241x x f x =+是减函数，∴()0,1x ∈时，()()()01f f x f >>， 即()21,52f x ⎛⎫∈ ⎪⎝⎭.∵()()f x f x -=-，∴()1,0x ∈-时， ()12,25f x ⎛⎫∈-- ⎪⎝⎭.又()()()1010f f f -===，∴[]1,1x ∈-时，函数()f x 的值域为{}1221,0,2552⎛⎫⎛⎫--⋃⋃ ⎪ ⎪⎝⎭⎝⎭.∴当1225λ-<<-，或0λ=，或2152λ<<时，方程()f x λ=在[]1,1-上有解.。
【新】河南省镇平县第一高级中学2017-2018学年高一英语暑强化训练试题(二)
高一英语暑强化训练试题（二）第一部分听力理解（略）第二部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的四个选项（A 、B 、C和D ）中，选出最佳选项，并在题卡上将该项涂黑。
ACourse No. 1406 12 Lectures (30 Minutes/Lecture)In The Secrets of Mental Math, award-winning Professor Arthur T. Benjamin teaches you the basic knowledge of mental mathematics. This powerful ability to perform mental calculations will give you an edge in business, at school, at work, or anywhere else that you meet with math.Course No. 7175 12 Lectures (30 Minutes/Lecture)In Museum Masterpieces: The Louvre, expert art critic and historian Professor Richard Brertell takes you on an unforgettable journey through one of the world's greatest museums. This 12-lecture series explores some of the most beautiful and renowned, examples from the museum's remarkable collection of masterworks.Course No. 158 12 Lectures (30 Minutes/Lecture)In My Favorite Universe, world-famous physicist and director of the Hayden Pknetarium Neil dcGrassc Tyson takes you on a spirited and intellectually interesting journey through the universe and all its history, from before the big bang to the most likely ways in which the entire universe might end.Course No. 6299 12 Lectures (30 Minutes/Lecture)In The History of the Bible: The Making of the New Testament Canon, New York Times best-selling author and professor Bart D. Ehrman reveals the secret history behind the making of the New Testament, including how and when each book was written and why it was chosen to be included.SPECIAL INTRODUCTORY OFFER!Order any one of theseBEST-SELLING COURSES for only:$199.95 $9.95 on DVD$134.95 $6.95 on CD+$5 Shipping and HandlingORDER TODAY! Sale Ends Friday!21. Who can tell you something about the space?A. Bart D. Ehrman.B. Neil dcGrassc Tyson.C. Arthur T. Benjamin.D. Richard Brertell.22. How much is Course No.158 on DVD delivered to your house?A. $6.95.B. $9.95.C. $11.95 .D. $14.95.23. What is the passage mainly about?A. College courses studied in home.B. College courses learned on line.C. Some world-famous lectures.D. Four interesting books in discount.BMatthew Layton was 20 minutes from home in Sevierville, Tennessee, on a cold November night in 2016 when he got a cell phone call from his mother. "The mountain’s on fire,” she screamed, “and Brian’s up there!”Layton’s family owned a dozen rental cabins(小屋) on Shields Mountain, and Layton’s friend and fellow rental-cabin owner, Brian McGee, age 56, was up there trying to put the fire out by himself. Layton, 32, hit the gas. He lived on the mountain too.Layton turned around and headed for a dirt road. He made it about halfway up the steep, winding path before his front-wheel-drive car gave up. He called McGee, who drove down in his pickup so they could fight the fire together.They headed first to Layton’s rental cabins. “I wanted to make sure our guests were gone. They were,” says Layton. At that point, he had a choice: try to save his cabins or resc ue people renting other cabins nearby. “On the moun tain, you don't have many locals. They’re mostly tourists who don’t know their way around,” he says.Over the next two hours, the two friends drove through the smoky mountain, knockingon doors and leadi ng panicked people to safety. “I know that mountain so well,” Layton says, “I could drive and know exactly where I am just by time traveled.” Thanks to their brave and immediate action, the two helped 14 people out of the danger.Fourteen people died that night in Sevier County. But the fire didn’t take away a single life on Shields Mountain. And though his home and business were destroyed, Layton remains calm. “I wasn’t worried about my loss, not when I saw those families trapped on the mountain,” he says,“I knew I was gonna help them.”24. Where was Layton when the fire broke out?A. Visiting his mother.B. Away from his home.C. Heading for the cabins.D. Driving on a dirt road.25. What can we learn from Para.2-3?A. Layton’s car broke down ha lfway.B. Brian was in charge of Layton’s cabins.C. Layton picked up Brian on the path.D. Brian lived in the mountain alone.26. Why could the two friends rescue the people?A. They put out the fire before it spread.B. They turned to locals for help.C. Layton was familiar with the area.D. Brian gave up his own cabins.27. What did Layton mean in the last paragraph?A. He blamed himself.B. He suffered a lot.C. He was relieved.D. He felt sorry.CIf your friends are happy—turns out you’re more likely to be happy too.If your friends are overweight, that too ups the chances you’ll gain weight. Those effects have been shown in studies. And now researchers have identified another seemingly contagious quality: exercise.The researchers analyzed the running activity of more than a million people worldwide who used an exercise tracking device(装置) for five years. And they used weather patterns as a way to randomly examine different parts of that global network.Cities have different weather patterns, Sinan Aral, a computational social scientist at MIT says, this experiment allowed them to ask: Does a rainy day in New York affect running in San Diego? “If the weather in New York causes changes in the running behavior in San Diego, it can really only be happening through the influences of the friends who live between New York and San Diego.”And that is exactly what he and his colleague saw: that the behavior of one city’s runners could indeed affect the behavior of runners in another socially connected city. Women tended to be influenced more by the female runners in their networks. And less active runners tended to influence more active runners to run more, but not so much the other way around.Still, this could be valuable for health professionals. “We have to start thinking about consumers and citizens as networked consumers and citizens. Where they are influenced by and influence their social network in very strong ways, that will change the way a particular intervention(干涉) succeeds or fails.”In other words—if your prescription is more exercise? The doctors might want to write a prescription for your friends and family, too.28. Which does the underlined word “contagious” in Para. 1 mean?A. Affected.B. Excellent.C. Beneficial.D. Different.29. What can we conclude from the experiment?A. Weather changes people’s feelings.B. People’s behaviour affects each other.C. Exercise has something to do with weather.D. P eople’s connection depends on distance.30. What does “this” in Para. 5 refer to?A. Women are easier influenced by male runners.B. People in the same city affect each other more.C. Friends tend to influence each other in exercising.D. A rainy day in one city affects running in another.31. Which of the following can be the best title for the text?A. Think twice before running.B. More exercise benefits health.C. Weather patterns affect running behavior.D. Healthy behavior can spread like illness.DMany Americans think of driverless cars as a futuristic technology that will revolutionize travel in cities and along state highways. But recent experiments are proving that autonomous vehicles also have the potential to improve the quality of life for millions of Americans underserved by traditional modes of transportation, such as the elderly and disabled, so long as lawmakers make smart policies that pave the way for innovation.A retirement community in San Jose, Calif. , which has been transformed by a small fleet of driverless taxis, shows the potential of self-driving cars to transform people’s lives. Built by a tech start-up called Voyage, the modified Ford Fusions are currently limited to a two-mile road, but residents are already having the benefits of these autonomous vehicles, which allow them to participate in social activities they would otherwise be unable to enjoy simply because they could not get to them.When the trial run finally expands to 15 miles of road, these residents—whose average age is 76—will also have a convenient and reliable new way to appointments. As these cars continue to serve residents there, it is easy to understand why California is moving to simplify regulations for the industry.In Michigan, forward-thinking policies have the potential to unlock other hidden benefits of autonomous vehicles, especially for those with physical disabilities. The Michigan Disability Rights Coalition has strongly advocated for the development of this technology, saying that it could give people with disabilities greater opportunities in the workforce and enable them to lead more fulfilling, independentlives.Many recognize that autonomous vehicles will be the future of transportation, but it is too often overlooked that this future cannot arrive fast enough for millions of Americans who are forced to depend on others for day-to-day travel. The policymakers should follow the lead of places like California and Michigan, and pass rules and regulations to unlock these hidden benefits of driverless cars.32. Wha t’s the attitude of most American people to the future of autonomous vehicles?A. Curious.B. Doubtful.C. Indifferent.D. Optimistic.33. What is the modified Ford Fusion?A. A kind of autonomous vehicle.B. A fleet of driverless taxis.C. A road for driverless cars.D. A retirement community.34. What are examples in California and Michigan to prove?A. Driverless cars’ disadvantages.B. Governments’ right decisions.C. Benefits to the aged and the disabled.D. The regulations are forward-thinking.35. What does the author attempt to inform us in the last paragraph?A. The benefits of driverless cars have been fully unlocked.B. Regulations should go hand in hand with driverless technology.C. The concept of autonomous vehicles has been widely recognized.D. The weak groups are often overlooked despite technology advances.阅读附加题：Cities usually have a good reason for being where they are, like a nearby port or river. People settle in these places because they are easy to get to and naturally suited to communications and trade. New York City, for example, is near a large harbour at the mouth of the Hudson River. Over 300 years its population grew gradually from 800 people to 8 million. But not all cities develop slowly over a long period of time. Boom towns grow from nothing almost overnight. In 1896, Dawson, Canada, was unmapped wilderness (荒野). But gold was discovered there in 1897, and two years later, it was one of the largest cities in the West, with a population of 30,000.Dawson did not have any of the natural conveniences of cities like London or Paris. People went there for gold. They travelled over snow-covered mountains and sailed hundreds of miles up icy rivers. The path to Dawson was covered with thirty feet of wet snow that could fall without warning. An avalanche (雪崩) once closed the path, killing 63 people. For many who made it to Dawson, however, the rewards were worth the difficult trip. Of the first 20,000 people who dug for gold, 4,000 got rich. About 100 of these stayed rich men for the rest of their lives.But no matter how rich they were, Dawson was never comfortable. Necessities like food and wood were very expensive. But soon, the gold that Dawson depended on had all been found. The city was crowded with disappointed people with no interest in settling down, and when they heard there were new gold discoveries in Alaska, they left Dawson City as quickly as they had come. Today, people still come and go — to see where the Canadian gold rush happened. Tourism is now the chief industry of Dawson City — its present population is 762.1. What attracted the early settlers to New York City?A. Its business culture.B. Its small population.C. Its geographical position.D. Its favourable climate.2. What do we know about those who first dug for gold in Dawson?A. Two-thirds of them stayed there.B. One out of five people got rich.C. Almost everyone gave up.D. Half of them died.3. What was the main reason for many people to leave Dawson?A. They found the city too crowded.B. They wanted to try their luck elsewhere.C. They were unable to stand the winter.D. They were short of food.4. What is the text mainly about?A. The rise and fall of a city.B. The gold rush in Canada.C. Journeys into the wilderness.D. Tourism in Dawson.第二节（共5小题，每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。
河南省镇平县第一高级中学2018届高三上学期期中考试][][][]
![河南省镇平县第一高级中学2018届高三上学期期中考试][][][]](https://img.taocdn.com/s3/m/3a15ac55c850ad02de8041d6.png)
河南省镇平县第一高级中学2018届高三上学期期中考试][][][]一、现代文阅读（35分）（一）论述类文本阅读（9分，每小题3分）阅读下面的文字，完成1—3题。
中国香文化是中国独具特色的传统文化之一。
它的起源甚早，据考古学家的考证，甚至可以追溯到石器时代。
距今6000多年前的新石器晚期，古人就以燃烧木柴和其他祭品的方式来祭祀天地诸神。
近几十年考古发现的各类文物（如陶熏炉）表明，早在四五千年前，古人就已经使用香品了。
作为活化石的殷商甲骨文，早在3000多年前就已经有了“柴”字，意为“手持燃烧的祭礼”，堪称祭祀用香的形象注解。
春秋战国时，由于地域所限，中土气候温凉，不太适宜香料植物的生长，所用香木香草的种类尚不如后世丰富，但关于香木香草的使用方法已有很多，有熏烧（如蕙草、艾蒿），佩带（香囊、香花香草）、煮汤（泽兰）、熬膏（兰膏）、入酒等方法。
在我国第一部诗歌总集《诗经》中，不乏记述采掇香药香草的歌谣，如“彼采萧兮，一日不见，如三秋兮。
彼采艾兮，一日不见，如三岁兮”。
我国第一部医学典籍《黄帝内经》，总结了我国人民与疾病长期斗争的医疗经验，其中就提出了艾灸、熏燎等治病方法。
人们对香木香草不仅取之用之，而且歌之咏之，托之寓之。
《尚书》有“至治馨香，感于神明”之语，《孔子家语﹒六本》说：“入芝兰之室，久而不闻其香。
”在伟大诗人屈原的《离骚》、《九歌》等名篇中，他用香草来歌颂忠贤，以莸草来痛斥奸邪，我们可以从中了解战国时期香文化的一些梗概。
秦汉时期，封建社会的巩固，华夏大地的大统一，特别是汉朝张骞通西域后，丝绸之路的开通，使中外文化出现了空前的大交融。
当时东南亚、南亚和欧洲等地的各种香料开始传入我国，丰富了我国的香料种类，推动了香文化的发展。
班固给其弟班超的书信中有“窦侍中令载杂丝七百尺，市月氏马、苏合香”等语句，可见当时香料是丝绸之路中外贸易的主要商品之一。
《汉官曲制》还规定，“尚书郎怀香握兰，趋走丹墀”，“含鸡舌香伏奏事”。
河南省镇平县第一高级中学2017_2018学年高一英语暑强化训练试题三201808010177
高一英语暑强化训练试题（三）第一部分听力（略）第二部分第二部分阅读理解（共两节，满分40分）第一节（共15小题; 每小题2分，满分30分）AWhat’s on in Beijing(Sept 2—8) Taking the baton(指挥棒)You may know Li Yundi as one of the leading Chinese pianists, but he is about to take on another role. The pianist will pick up the baton for the first time, leading the Warsaw Philharmonic Orchestra for a five-city tour in China, which started in Chongqing on Aug. 29, followed by Guangzhou, Shenzhen, Beijing and Shanghai through September.If you go: 7:30 pm, Sept. 3. Concert Hall, National Center for the Performing Arts. 010-6655-0000.Ticket: 300—1,380 yuan ($45—200)Dutch masters exhibition is closingAn exhibition showcasing masterpieces of the 17th century Dutch Golden Age will come to an end duringthe weekend. The 17th century Dutch Golden Age had several significant artists and a range of great pieces produced during the period, including Jan Vermeer’s A Y oung W oman Seated at a V irginal, Jan Lievens’ Boy in a Cape, and Turban and Rembrandt’s Self-Portrait with Shaded Eyes. It is the first time some of the most refined examples of the time have been shown in China.If you go: 9 am—5 pm, through Sept. 3 (closed on Mondays). National Museum of China. 010-6400-1476.Ticket: 50 yuanWhen art is a partyBeijing-born artist Zhao Bandi says he uses a party as a metaphor（隐喻）for society. The 51-year-old addsthat at a party he is able to observe what is happening and keep some distance from it. His exhibition, Zhao Bandi: China Party, is now being held at the 798 area in Beijing.If you go: 10 am—7 pm, closed on Mondays, through Oct. 22. UCCA, 798 Art Zone, Jiuxianqiao, ChaoyangDistrict, Beijing. 010-5780-0200.Ticket: 30—50 yuanGintamaAdapted from the popular manga(漫画) series, Gintama, the Japanese action-comedy film of the same namehits screens in the Chinese mainland today.Click here to learn more.21.When might T aking the baton be on in Shenzhen?A. On Aug. 29.B. On Sept. 1.C. On Sept. 3.D. On Oct. 1.22.If you are fond of the 17th century art works, where can you go to enjoy one?A. On a website.B. In the National Museum of China.C. In the National Center for the Performing Arts.D. In UCCA, 798 Art Zone, Jiuxianqiao, Chaoyang District, Beijing.23.If you are free on a Monday after Sept. 3, you’d better consult more_____.A. by dialing 010-6655-0000B. by dialing 010-6400-1476C. by dialing 010-5780-0200D. by clicking the link on itswebsiteBWhen I was nine years old I lived in a small town. I found an ad for selling greeting cards in the back of a children’s magazine. I thought to myself I could do this. I begged my mother to let me send for the kit (成套工具).Two weeks later the kit arrived. The next three hours later, I returned home withno card and a pocket full ofmoney shouting, “Mama, all the people couldn’t wait to buy my cards!” A salesperson was born.When I was twelve years old, my father took me to see Zig Ziegler. I remember sitting in the dark hall listening to Mr. Ziegler raise everyone’s spirits up to ceiling. I left there feeling like I could do anything. When we got to the car, I turned to my father and said, “Dad, I want to make people feel like that.” My father asked me what I meant. “I want to be a motivational speaker just like Mr. Ziegler,”I replied. A dream was born.Recently, I began pursuing my dream of motivating others. I realized that everything I had accomplished —the graduate degree, the successful sales career, speaking appointments, training and managing for a major fortune100 company as a senior manager— had prepared me for this moment. I told my boss who was a great leader I would leave the company though I might not reach such a height in career. He told me to proceed and he believed I would succeed.Having made that decision, I was immediately tested. One week after I gave notice, my husband was laid offfrom his job. We had recently bought a new home and needed both incomes to make the monthly mortgage (抵押) payment and now we were done to no income. I even planned to turn back to my former company, knowing they wanted me to stay but I was certain that if I went back, I would never leave. I decided I still wanted to move forward rather than end up with a mouth full of “if onlys” later on. A motivational speaker was born.When I held fast to my dream, even during the tough times, the miracles（奇迹）really began to happen. In ashort time period my husband found a better job. We didn’t miss a mortgage payment. And I was able to book several speaking appointments with new clients (客户). I discovered the incredible power of dreams. I loved my old job, my workmates and the company I left, but it was time to get on with my dream. To celebrate my success I had a local artist paint my new office as a garden. At the top of one wall she marked, “The world always makes way for the dreamer.”24.Why was the kit sent for?A. Selling greeting cards.B. Collecting greeting cards.C. Buying greeting cards.D. Sending greeting cards.25.When did the author decide to become a motivational speaker?A. After buying a new home by mortgage.B. After giving notice to leave her secure position in the company.C. After finding a job in a major fortune 100 company.D. After listening to Mr. Ziegler’s inspiring speech.26.The following statements about the author are correct EXCEPT ________ .A. She was once an excellent manager.B. She left her post at the height of her career.C. She was not sure whether the former company could accept her.D. She didn’t miss paying the monthly mortgage payment.27.What does the underlined sentence mean in the last paragraph?A. Carry on with your dreams and you will be successful.B. Risk everything you have for a dream and you will succeed.C. The world belongs to all dreamers.D. Everyone will find their dreams.CLong before iphones, the cigarette was the companion of choice for restlessness. And long before Facebook and WeChat, it was tobacco that promised to better your social life. Now, quitting smartphones has become the new quitting smoking.Of course, technology does not yellow your teeth, cause disease or lead to cancer.But some individuals are soconcerned that device addiction is damaging their mental health. In order to reduce their dependence, even in Silicon Valley, people are turning off the messages that constantly buzz for their attention, banning smartphones from the bedroom and, curiously, changing the colors on their screens to a less tempting scale of gray.The big tech companies will have to work out how to respond to this new generation of quitters. Facebook isthe first to go public with its attempt, hoping its recent move can make the social network more homely.Last year the tech industry got a bad name—Big Tech—with unfortunate echoes(共鸣) of other industries that have faced fierce opposition, including Big Tobacco. Like them, the tech industry has to reduce concern from a new generation of activist shareholders(股东) that are questioning its role in the world. These campaigns are never as fierce as those faced by Big Tobacco. In the 1990s, socially responsible investors refused to put money in tobacco stocks.It is far difficult for investors to challenge Big Tech and hard to separate the good these companies do in theworld—connecting old friends and giving space for people to share their ideas—from the bad. In the meantime, stopping using technology remains problematic. In The W orld W ithout Mind: The Existential Threat of Big T ech, Franklin Foer argues that tech should be seen in a similar way to junk food: a convenience that some reject for more continuing nutrition.So we need to do more to turn the tide. In the same way that public service announcements made smokingaround your children taboo(禁忌),we can warn parents against losing themselves in their smartphones while taking care of kids.We can also create no-smartphone zones at dinner. Eventually smartphones could be banned from all public places and help us give our attention to the people around us instead.28.How did people keep close relationships with others in the past?A. By smoking.B. By drinking.C. By phoningD. By diningout.29.Why is the tech industry called Big Tech?A. It plays a bad role in the world.B. It is as big as Big Tobacco.C. It has an unfortunate name.D. It is a giant in Silicon Valley.30.What can we infer from Franklin Foer’s argument about the tech?A. It promotes social development.B. It is still favored by some people.C. It is worse than Big Tobacco.D. It offers continuing nutrition.31.Which can be the best title for the passage?A. Creating a No Smartphone LifeB. Smartphones Enrich Our Social LifeC. Smoking Does Greater Harm Than Smartphones DoD. Quitting Smartphones Is the New Quitting SmokingDComedy and PsychologyEarlier this year I did a part-time comedy course. The class was taught by Ryan,a professional comedian.Ihad performed a show, which wasn’t originally meant to be a comedy. However, the audience laughed at my first joke, then continued to laugh throughout the routines that were meant to be serious. So it was the audience who told me I was funny, but I didn’ t understand why or how to control the comic (滑稽的) moments. So, I joined the course to learn.“Turn off your editor that makes you say the right thing and remember how to be a child,” explained Ryan. “Don’t try to be clever. Don’t try too hard to be funny…and knowing all about the theory of humor is unlikely to help you much. Just behave in a silly way. That’s what people want to see on stage.” Ryan would help us loosen up by saying things like, “Wander around talking to others, but make sure that you’re the lowest status person here.”I’d say that understanding the psychology of humor has actually helped. RecentlyI came across the bookInside Jokes: Using Humor to Reverse-Engineer the Mind. Its main idea is that any self-directed intelligent system will need to correct its own fault. There’s a risk that the occasional error will be made. If this was boring or burdensome, we’d be less willing to do it. However, evolution has made the process fun.Here’s a joke in the book: Two fish are in a tank. One says to the other, “Do you know how to drive thisthing?” It works on the principle that we have started to imagine one thing—that the tank is the typical container people keep fish in—and, just in time, the following words tell us that our first assumption was wrong—it’s a heavy vehicle. For correctlyfiguring out the error, we are rewarded with a pleasurable feeling. The joke is an efficient way of encouraging this natural reaction, and comedians have become experts in slightly touching this mental funny-bone in order to make us laugh.Ryan was right when he said that knowing the theory of humor wouldn’t help us that much as acomedy.During one exercise in the course, four of us were told to perform an opera. Susan and Caroline sang earnestly on either side of the stage, and I brought Henry to the floor, where we wrestled (摔跤) each other likeout-of-control teenagers. The rest of the group was in uncontrollable fits of laughter. As a performer, I’ ll neverappreciate just why it seemed so funny. But the point is that I would never have written this on the paper. It was a joyous, found moment.32.Why did the author attend the comedy course?A. He wanted to see how the theories worked in practice.B. He discovered he had some natural ability in comedy.C. He worried about how other performers would find him.D. He got unpleasant experiences when performing a comedy.33.Ryan required the people on the comedy course to .A. copy their favorite performanceB. imagine other people’ s reactionsC. help themselves feel comfortableD. behave in a more playful manner34.What is the purpose of the joke mentioned in Paragraph 4?A. To discuss what humor brings about exactly.B. To give an example of another kind of humor.C. To prove the point about psychology of humor.D. To show why some people are funnier than others.35.What view does the author put forward in the end?A. Visual humor is what appeals to people most.B. What people find funny is often unpredictable.C. Theories explaining humor tend to be mistaken.D. Learning comic skills proves to be a difficult task.第二节（共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。
河南省镇平县第一高级中学2017-2018学年高一上学期期末考前诊断语文试题
【题文】作文。
请以“回眸”为题写一篇不少于800字的记叙文。
要求：①文体必须是记叙文；②不要套作，不得抄袭。
【答案】回眸余余落辉，我爱一抹最美；涓涓潺水，我掬一捧最清；回顾走过的树林，我独恋枫叶最红；回眸成长的足迹——-我不忘毅者无疆的坚强。
7岁时，我爱看《西游记》，而孙悟空便是我的信念。
纵然可以千变万化，也要忍受五指山下的嘲讽，一压就是五百年，一忍就是风吹雨打，谁能顶天立地，坚强，被一只猴神化得如此悲壮，这便是开始，即便寂寞也精彩，大丈夫能屈能伸，猴哥，就应该这样。
10岁时，我迷上《三国演义》，原先只是喜欢打打杀杀，敬佩关羽而怨恨曹操，那一夜，考试失利后难眠的一夜，心头一触，原来曹操才是英雄。
这位大将军在宛城丧子折兵后的痛定思痛；这位汉丞相败走华容道时的嘲笑诸葛亮、周瑜；这位魏王在割须弃泡后巧施反间计，连遭挫折到始终不忘统一天下的抱负，不像刘备，被火烧七百里联营，烧回白帝城后一病不起；不像孙权，夺会荆州，守者父兄的基业就面南称帝。
曹操把坚强演义到顶峰，“老骥伏枥，志在千里；烈士暮年，壮心不已”，曹公的诗好不令人痛快!那一夜，我醒了，困难打不败，挫折打不倒，我学会了坚强。
13岁，我张大了，渐渐孤傲了，但《名人传》却逆转了我，他们都有伟大的成就，而他们也都是磨难造就的人，他们在漫漫黑夜中摸索前进，而坚强是他们心中的航标，即使看不到光明，他们却将坚强表现得淋漓尽致。
贝多芬在双目失明后继续创作乐曲，坚强是他音乐的音符；米开朗琪罗在教堂中，即使心不情愿，也全神贯注的雕刻，坚强是他的灵感，直到生命最后仍在坚持。
我心中孤傲的火焰慢慢熄灭，化作一泓平静泉水。
今年我15岁了，回眸成长之间，我懂了一句话“天将降大任于是人也，必先苦其心志，劳其筋骨，饿其体肤，空乏其身，行拂乱其所为”，既然上天已降大任于你我，那么，就让我们带者坚强出发吧!去奋斗，去拼搏，去履行生命的诺言!【解析】试题分析：这是一篇命题作文。
写作要求：以“回眸”为题写一篇不少于800字的记叙文①文体必须是记叙文；②不要套作，不得抄袭。
河南省镇平县第一高级中学2017-2018学年高一生物第一章测试试题
高一生物第一章测试试题一、选择题（每题3分，共57分）1．下列属于相对性状的是 ( )A．玉米的黄粒与皱粒B．狗的长毛与直C．果蝇的长翅与残翅D．小麦的抗倒伏与抗锈病2.调查发现人群中夫妇双方均表现正常也能生出白化病患儿。
研究表明白化病由一对等位基因控制。
判断下列有关白化病遗传的叙述，错误的是 ( )A．致病基因是隐性基因B．如果夫妇双方都是携带者，他们生出白化病患儿的概率是1/4C．如果夫妇一方是白化病患者，他们所生表现正常的子女一定是携带者D．白化病患者与表现正常的人结婚，所生子女表现正常的概率是1/23.人类褐眼(A)对蓝眼(a)是显性，一对褐眼夫妇，生了4个褐眼男孩，则双亲的基因型是（ )A．AAX AA B．AA×Aa C．Aa×Aa D．无法确定4.蚕的黄色茧(Y)对白色茧(y)是显性，抑制黄色出现的基因(I)对黄色出现的基因(i)是显性，两对等位基因独立遗传。
现用杂合白色茧( IiYy)蚕相互交配，后代中白色茧对黄色茧的比是 ( ) A．3:l B.．13:3 C．1:l D．15:15.欲鉴别一株高茎豌豆是否是纯合子，最简便易行的方法是 ( )A．杂交 B．回交 C测交 D．自交6一对正常的夫妇生下了一个有白化病的女儿和一个正常的儿子，这个儿子如果与患有白化病的女人结婚，婚后生育出患有白化病女孩的几率为 ( )A. 1,/2 B．1／4 C．1/6 D．1／127.人的双眼皮对单眼皮是显性，一对双眼皮的夫妇生了四个孩子，三个单眼皮，对这一现象的最好解释是 ( )A．3：1符合基因的分离定律 B．单眼皮基因与双眼皮基因发生了互换C．基因不能自由组合，产生了突变D．这对夫妇都含有单眼皮基因，每一胎中都有出现单眼皮的可能，其概率为1／48. 一株杂合豌豆进行自花受粉，将得到的种子先播下15粒，都长成了高茎豌豆，那么原来那株豌豆的第16粒种子种下去，也长成高茎豌豆的可能性是 ( )A. OB. 12／16 C．4／16 D．100%9.德尔进行的两对相对性状的遗传实验中，具有1：1：1：1比例关系的是 ( )①杂种自交后代的性状分离比②杂种产生配子类型的比例③杂种测交后代的表现型比例④杂种自交后代的基因型比例⑤杂种测交后代的基因型比例A．①②④ B．②④⑤ C．①③⑤ D．②③⑤10.决定小鼠毛色为黑(B)/褐(b)色、有(s)/无(S)白斑的两对等位基因分别于两对同源染色体上。
2017-2018学年河南省镇平县第一高级中学高一上学期期末测试数学试题(解析版)
河南省镇平县第一高级中学2017—2018学年高一上学期期末测试数学试题第Ⅰ卷（共60分）一、选择题：本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.1. 设A=x,y y=−4x+6，B=x,y y=5x−3，则A∩B等于（）A. 1,2B. 1,2C. x=1,y=2D. 1,2【答案】B【解析】A=x,y y=−4x+6，B=x,y y=5x−3，两个集合均为点集，所以交集为直线的交点组成的集合.由y=−4x+6y=5x−3,解得x=1y=2，所以A∩B=1,2.故选B.2. 如果a>1,b<−1，那么函数f x=a x+b的图象在（）A. 第一、二、三象限B. 第一、三、四象限C. 第二、三、四象限D. 第一、二、四象限【答案】B【解析】∴y=a x的图象过第一、第二象限,且是单调增函数,经过(0,1)，f x=a x+b的图象可看成把y=a x的图象向下平移−b(−b>1)个单位得到的，故函数f x=a x+b的图象经过第一、第三、第四象限，不经过第二象限，故选B.3. 设A=x1<x<2,B=x x<a，若，则的取值范围是（）A. a≥2B. a≤1C. a≥1D. a≤2【答案】A【解析】因为A=x1<x<2,B=x x<a，且，则a≥2.故选A.4. 设f log2x=2x x>0，则f3的值是（）A. 128B. 256C. 512D. 8【答案】B【解析】设log2x=t，则x=2t，所以f(t)=22t，则f2=223=28=256，故选B.5. 已知函数y=f2x的定义域是−1,1，则函数y=f log2x的定义域是（）A. 0,+∞ B. 0,1 C. 1,2 D. 2,4【答案】D【解析】函数y=f2x的定义域是−1,1，所以x∈−1,1,2x∈[12,2]，所以函数y=f log2x中有：log2x∈[12,2]，解得x∈2,4.即函数y=f log2x的定义域是2,4.故选D.点睛：复合函数定义域的求法①若y=f x的定义域为a,b，则不等式a<g x<b的解集即为函数y=f g x的定义域；②若y=f g x的定义域为a,b，则函数g x在a,b上的的值域即为函数y=f x的定义域．6. 若函数y=f x的值域是12,3，则函数F x=f x+1f x的值域是（）A. 12,3 B. 2,103C. 52,103D. 3,103【答案】B【解析】令t=f x,则t∈12,3，则y =t +1t ，易知y =t +1t 在(0,1)单调递减，在(1,+∞)单调递增. 所以当t ∈ 12,3 时， t =1时，y 有最小值为2当t =12时，y =52，当t =3时，y =103. 则函数F x =f x +1f x 的值域是 2,103 . 故选项为B.7. 已知幂函数f x =x a 的图像过点 14,12 ，则式子4a 的值为（ ）A. 1B. 2C. 12D. 14【答案】B【解析】幂函数f x =x a 的图像过点 14,12 ，所以(14)a =12，所以a =12.即f x =x 12. 所以4a =412=2. 故选B.8. 定义在R 上的函数f x 满足f x +y =f x +f y +2x y x ,y ∈R ，f 1 =2，则f −3 等于（ ） A. 2 B. 3 C. 6 D. 9 【答案】C【解析】定义在R 上的函数f x 满足f x +y =f x +f y +2x y x ,y ∈R 令x =y =0，得f 0 =f 0 +f 0 +0，解得f 0 =0； 令x =1，y =−1得f 0 =f 1 +f −1 −2，解得f −1 =0； 令x =y =−1得f −2 =f −1 +f −1 +2，解得f −2 =2； 令x =−2，y =−1得f −3 =f −2 +f −1 +4，解得f −3 =6. 故选C.S9. 设a >1，且m =log a a 2+1 ,n =log a a −1 ,p =log a 2a ，则m ,n ,p 的大小关系为（ ） A. n >m >p B. m >p >n C. m >n >p D. p >m >n 【答案】B【解析】当a >1时,易知a 2+1>2a ，再由以a 为底对数函数在定义域上单调递增，从而可知m >p又∵(a2+1)−(a−1)=a2−a+2恒大于0(二次项系数大于0,根的判别式小于0,函数值恒大于0),即a2+1>a−1，再由以a为底对数函数在定义域上单调递增，从而可知m>n又∵当a>1时2a显然大于a−1，同上，可知p>n.综上∴m>p>n.故选B.10. 定义运算a∗b，a∗b=a a≤b,b a>b,例如1∗2=1，则函数y=1∗2x的值域为（）A. 0,1B. −∞,1C. 1,+∞D. 0,1【答案】D【解析】当1⩽2x时，即x⩾0时，函数y=1∗2x=1当1>2x时，即x<0时，函数y=1∗2x=2x∴f(x)=1,x⩾0 2x2x,x<0故选D.11. 某种细胞在生长过程中，每10分钟分裂一次（由一个分裂为两个），经过2小时后，此细胞可由一个繁殖成（）A. 511个B. 512个C. 211个D. 212个【答案】D【解析】依题意，10分钟后，个数为21个，20分钟后，个数为22个，所以2小时后，即为120分钟后，个数应为212个.故选D.12. 方程x2+2x+1=1x（）A. 无实根B. 有异号两根C. 仅有一负根D. 仅有一正根【答案】D【解析】在同一直角坐标系下画出两函数图象，如图所示：函数y=x2+2x+1和y=1x ，仅有一个交点，在第一象限，即方程x2+2x+1=1x仅有一正根.故选D.点睛：函数零点的求解与判断(1)直接求零点：令f(x)＝0，如果能求出解，则有几个解就有几个零点．(2)零点存在性定理：利用定理不仅要函数在区间[a，b]上是连续不断的曲线，且f(a)·f(b)＜0，还必须结合函数的图象与性质(如单调性、奇偶性)才能确定函数有多少个零点．(3)利用图象交点的个数：将函数变形为两个函数的差，画两个函数的图象，看其交点的横坐标有几个不同的值，就有几个不同的零点．第Ⅱ卷（共90分）二、填空题（每题5分，满分20分，将答案填在答题纸上）13. 函数y=log x−13−x的定义域是__________．【答案】1,2∪2,3【解析】要使函数y=log x−13−x有意义，则x−1>0x−1≠13−x>0，解得1<x<3，且x≠2.所以函数y=log x−13−x的定义域是1,2∪2,3.答案为;1,2∪2,3.点睛：常见基本初等函数定义域的基本要求(1)分式函数中分母不等于零．(2)偶次根式函数的被开方式大于或等于0.(3)一次函数、二次函数的定义域均为R.(4)y＝x0的定义域是{x|x≠0}．(5)y＝a x(a>0且a≠1)，y＝sin x，y＝cos x的定义域均为R.(6)y＝log a x(a>0且a≠1)的定义域为(0，＋∞)．x2−5x−6的递减区间是__________．14. 函数y=log12【答案】6,+∞x2−5x−6中，有x2−5x−6>0，解得x<−1或x>6.【解析】函数y=log12t为减函数，令t=x2−5x−6，则y=log12，又t=x2−5x−6，为开口向上的抛物线，对称轴为x=52所以在−∞,−1，t=x2−5x−6单调递减，在6,+∞，t=x2−5x−6单调递增，x2−5x−6的递减区间是6,+∞.由复合函数单调性“同增异减”的原则，知，函数y=log12答案为：6,+∞.15. 用二分法求函数y=f x在区间2,4上的近似解，验证f2f4<0，给定精度为0.1，需将区间等分__________次.【答案】5【解析】因为区间2,4的长度为2，所以第一次等分后区间长度为1，第二次等分后区间长度为0.5，……第四次等分后区间长度为0.125<0.2，第五次等分区间后区间长度为0.0625<0.1，所以需要将区间等分5次. 故答案为：5.16. 已知函数f x满足:（1）对任意x1<x2，都有f x1<f x2；（2）f x1+x2=f x1⋅f x2.写出一个同时满足这些条件的函数解析式__________．【答案】y=2x【解析】∵x1<x2时,f x1<f x2∴f (x )为增函数∵f x 1+x 2 =f x 1 ⋅f x 2 根据指数函数的性质，∴满足条件的函数可以是：y =a x(a >1)故答案为：y =2x (底数大于1的指数函数即可).三、解答题 （本大题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤.）17. （1）求值：lg 2lg 50+lg 5lg 20−lg 100lg 5lg 2； （2）已知log 53=a ,log 54=b ，用a ,b 表示log 2512. 【答案】（1）1；（2）a +b 2.【解析】试题分析：（1）都化为与lg2有关的式子，log 34利用换底公式化为常用对数，求解即可．注意lg2lg5≠1． （2）利用换底公式将log 2512化为以5为底的对数，再将真数用4和6表达求解即可． 试题解析：（1）原式=lg 2 lg 25×2 +lg 5lg 4×5 −2lg 5lg 2=lg 2 2lg 5+lg 2 +lg 5 2lg 2+lg 5 −2lg 5lg 2 =2lg 2lg 5+ lg 2 2+2lg 2lg 5+ lg 5 2−2lg 5lg 2= lg 2+lg 5 2= lg 10 2=1（2）log 2512=log 512log 525=log 53+log 54log 552=a +b 2.18. 已知f x 是定义在 −2,2 上的减函数，并且f m −1 −f 1−2m >0，求实数m 的取值范围. 【答案】m ∈ −12,23 .【解析】试题分析：由题设条件知，可先将不等式f （m-1）-f （1-2m ）＞0可变为f （m-1）＞f （1-2m ），再利用函数是减函数的性质将此抽象不等式转化为关于m 的不等式组，解不等式组即可得到m 的取值范围． 试题解析：由f m −1 −f 1−2m >0可得f m −1 >f 1−2m . 又f x 是定义在 −2,2 上的减函数，∴ m −1<1−2m ,−2<m −1<2,−2<1−2m <2 ⇒ m <23,−1<m <3,−12<m <32,⇒−12<m <23，即m∈ −12,23.点睛：本题属于对函数单调性应用的考察，若函数f x在区间上单调递增，则x1,x2∈D,且f x1>f x2时，有x1>x2，事实上，若x1≤x2,则f x1≤f x2，这与f x1>f x2矛盾，类似地，若f x在区间上单调递减，则当x1,x2∈D,且f x1>f x2时有x1<x2；据此可以解不等式，由函数值的大小，根据单调性就可以得自变量的大小关系.本题中可以利用对称性数形结合即可.19. 设函数y=f x（x∈R且x≠0）对定义域内任意的x1,x2，恒有f x1⋅x2=f x1+f x2. （1）求证：f1=f−1=0；（2）求证：y=f x是偶函数；（3）若f x为0,+∞上的增函数，解不等式f x+f x−12≤0.【答案】（1）见解析；（2）见解析；（3）{x|1−174≤x<0或12<x≤1+174}.【解析】试题分析：（1）利用赋值法求解，令x1，x2=1或x1，x2=-1即可得证．（2）令x2=-x，x1=-1，结合奇偶性的定义即可判断．（3）利用y=f（x）在（0，+∞）上为增函数，f（1）=0，f（x）为偶函数；即可求解不等式；试题解析：（1）∵x≠0，f x1⋅x2=f x1+f x2，令x1=x2=1，f1=2f1，∴f1=0，令x1=x2=−1，f−1=2f−1，∴f−1=0.（2）∵x∈R且x≠0，恒有f x1⋅x2=f x1+f x2，令x1=−1,x2=x，∴f−1⋅x=f−1+f x，∴f−x=f x，∴y=f x是偶函数.（3）∵f x在0,+∞上为增函数，则在−∞,0上是减函数，又f x+f x−12≤0，∴f x x−12≤f1或f x x−12≤f−1，∴0<x x−12≤1，①或0>x x−12≥−1，②∴由①②得：1−4≤x<0或12<x≤1+4.点睛：本题属于对函数单调性应用的考察，若函数f x在区间上单调递增，则x1,x2∈D,且f x1>f x2时，有x1>x2，事实上，若x1≤x2,则f x1≤f x2，这与f x1>f x2矛盾，类似地，若f x在区间上单调递减，则当x1,x2∈D,且f x1>f x2时有x1<x2；据此可以解不等式，由函数值的大小，根据单调性就可以得自变量的大小关系.本题中可以利用对称性数形结合即可.20. 已知函数f x=a−22x+1a∈R.（1）判断f x在定义域上的单调性；（2）要使f x≥0恒成立，求实数的取值范围.【答案】（1）见解析；（2）2,+∞.【解析】试题分析：（1）根据单调性的定义即可判断f（x）在定义域上的单调性；（2）利用参数分离法，结合指数函数的性质进行求解．试题解析：（1）显然对任意x∈R且2x+1≠0，∴f x的定义域为R.设x1,x2∈R，且x1<x2，则f x2−f x1=a−22x2+1−a+22x1+1=22x1+1−22x2+1=22x2−2x12x1+12x2+1.∵y=2x为增函数，且x2>x1，∴2x2>2x1.而2x1+12x2+1>0恒成立，于是f x2−f x1>0，即f x2>f x1，故f x是R上的增函数.（2）由f x≥0恒成立，可得a≥22x+1恒成立.∵对任意的x∈R,2x>0，∴2x+1>1，∴0<12x+1<1，∴0<22x+1<2.要使a≥22x+1恒成立，只需a≥2即可，即的取值范围是2,+∞.21. 如过函数f x对于定义域内的任意两个数x1,x2都满足:f x1+x22≤12f x1+f x2，那么称函数f x 为下凸函数；而总有fx 1+x 22≥12 f x 1 +f x 2 时，那么称函数f x 为上凸函数.根据以上定义，判断指数函数f x =a x （a >0且a ≠1）在R 上是否为下凸函数，并说明理由. 【答案】见解析.【解析】试题分析：根据凹函数的定义，结合指数函数的图象和性质，用作差法比较大小，可得结论． 试题解析： 因为fx 2+x 22=ax 2+x 22=ax 12⋅a x 22，12f x 1 +f x 2 =12a x 1+a x 2 ，所以fx 2+x 22−12 f x 1 +f x 2 =−12 a x 1+a x 2−2ax 12a x 22=−12 a x 12−a x 222≤0，所以fx 2+x 22≤12 f x 1 +f x 2 对于R 上的任意两个数恒成立，所以指数函数在R 上为下凸函数22. 定义在R 上的函数f x 满足f x +2 =f x ，且f −x =−f x .当x ∈ 0,1 时，f x =2x 4x +1.（1）求f x 在 −1,1 上的解析式； （2）证明f x 在 0,1 上是减函数；（3）当取何值时，方程f x =λ在 −1,1 上有解.【答案】（1）f x =2x4x +1,x ∈ 0,1 ,−2x 4x +1,x ∈ −1,0 ,0,x ∈ −1,0,1 .；（2）见解析；（3）−12<λ<−25，或λ=0，或25<λ<12. 【解析】试题分析：（1）设x ∈ −1,0 ，则−x ∈ 0,1 结合f （-x ）=-f （x ），及x ∈（0，1）时，f x =2x4x +1，，可求x ∈（-1，0）时得f （x ），在f （-x ）=-f （x ）中可求f （0）=0 （2）利用函数的单调性的定义证明即可．（3）方程f x =λ在 −1,1 上有解的充要条件是，在函数f x ，x ∈ −1,1 的值域内取值，只需求出函数的值域，然后求解k 的范围． 试题解析：（1）设x ∈ −1,0 ，则−x ∈ 0,1 . ∵f −x =−f x ，且x ∈ 0,1 时，f x =2x 4x +1，∴x ∈ −1,0 时，有f x =−f −x =−2−x4−x +1=−2x1+4x .在f−x=−f x中，令x=0得f−0=−f0⇒f0=0.∵f x+2=f x，f−x=−f x，令x=−1，得f−1+2=f−1,f−1=−f1，∴f1=−f1⇒f1=0，从而f−1=0，∴当x∈−1,1时，有f x=2x4x+1,x∈0,1,−2x4x+1,x∈−1,0, 0,x∈−1,0,1..（2）设0<x1<x2<1，则x2−x1>0，f x2−f x1=2x24x2+1−2x14x1+1=2x1−2x22x1+x2−14x1+14x2+1.∵0<x1<x2<1，∴0<x1+x2<2，∴2x1+x2>1，且2x2>2x1，∴2x1+x2−1>0，2x1−2x2<0.又∵4x1+1>1>0,4x2+1>1>0，∴2x1−2x22x1+x2−14x1+14x2+1<0，即f x2−f x1<0，∴f x在0,1上是减函数.（3）方程f x=λ在−1,1上有解的充要条件是，在函数f x，x∈−1,1的值域内取值.∵x∈0,1时，f x=2x4x+1是减函数，∴x∈0,1时，f0>f x>f1，即f x∈25,12.∵f−x=−f x，∴x∈−1,0时，f x∈ −12,−25.又f−1=f0=f1=0，∴x∈−1,1时，函数f x的值域为 −12,−25∪0∪25,12.∴当−12<λ<−25，或λ=0，或25<λ<12时，方程f x=λ在−1,1上有解.。
河南省镇平县第一高级中学高一年级上册生物期末模拟试卷
河南省镇平县第一高级中学高一年级上册生物期末模拟试卷一、单选题1．下列关于蛋白质的叙述，正确的是A．含有羧基和氨基的化合物都是组成蛋白质的单体B．低温、高温、过酸或过碱都可以破坏蛋白质的空间结构C．所含氨基酸的种类和数目相同的蛋白质一定是同一种蛋白质D．蛋白质和多肽都可以与双缩脲试剂发生紫色反应2．光合作用和呼吸作用的原理在生产中具有广泛的应用。
下列相关叙述正确的是（）A．长期施用化肥比施用农家肥更有利于作物生长B．合理密植有利于改善田间CO2浓度和光能利用率C．降低温度、保持干燥有利于绿色蔬菜的保鲜D．给稻田定期排水、晒田的主要目的是抑制水稻生长3．在有丝分裂的一个细胞周期中，最可能发生在同一时期的是（）A．染色体数加倍和DNA分子数加倍B．染色体复制和染色单体的形成C．着丝点的分裂和核膜核仁形成D．赤道板的出现和纺锤体的出现4．以下关于细胞核的叙述，正确的是（）A．核仁与核糖体的形成有关B．细胞核是细胞代谢的主要场所C．核孔是DNA等大分子进出的通道D．染色质是细胞核内的重要结构，由RNA和蛋白质组成5．英国医生塞达尼・任格在对离体蛙心进行的实验中发现，用不含钙和钾的生理盐水灌注蛙心，其收缩不能维持；用含有少量钙和钾的生理盐水灌注蛙心时，蛙心可持续跳动数小时。
该实验说明钙盐和钾盐（）A．对维持细胞的形态有着重要作用B．是细胞中某些复杂化合物的重要组成部分C．为蛙心的持续跳动提供能量D．对维持生物体的生命活动有重要作用6．某生物体内能发生如下反应：淀粉→麦芽糖→葡萄糖→糖原。
则下面的说法不正确的是（）A．此生物一定是动物，因为能合成糖原B．淀粉和糖原都属于多糖C．此生物一定是动物，因为能利用葡萄糖D．糖类在生物体内是主要的能源物质7．图是研究物质A和物质B对某种酶活性影响的曲线，下列叙述错误的是（）A．底物浓度不能改变酶催化活性B．物质B能通过破坏酶的空间结构，使酶变性而降低反应速度C．减小底物浓度不能消除物质A对该种酶的影响D．增大底物浓度可以消除物质B对该种酶的影响8．下图为氨基酸和Na+进出肾小管上皮细胞的示意图，下表选项中正确的是选项管腔中氨基酸→上皮细胞管腔中Na+→上皮细胞上皮细胞中氨基酸→组织液A主动运输被动运输主动运输B被动运输被动运输被动运输C被动运输主动运输被动运输D主动运输被动运输被动运输A．A B．B C．C D．D9．下列各种物质与功能不相符合的是（）A．叶绿素---光合作用B．血红蛋白---运输氧气C．胰岛素—调节功能D．唾液淀粉酶—催化H2O2分解10．伞藻是一种能进行光合作用的单细胞绿藻，由伞帽、伞柄和假根三部分构成，细胞核在假根内。
河南省镇平县第一高级中学2017-2018学年高一(实验班)上学期第一次月考数学试题(解析版)
2017年秋期镇平一高高一第一次月考数学试题（本试卷满分150分，考试时间为120分钟）一、选择题（共12小题，每题5分，共60分，每题只有一个选项是正确的）1.设全集,2，3，4，且,,,,则等于（）A. B. C. D.【答案】B【解析】全集,2，3，4，且,,,.所以.故选B.2.下列五个写法：①；②；③；④；⑤，其中错误写法的个数为（）A. 1B. 2C. 3D. 4【答案】C【解析】①中两集合应为包含关系，故错误；②中空集是任何集合的子集，故正确；③任何一个集合都是其本身的子集，故正确；④中空集不含任何元素，故错误；⑤中交集是两集合间的运算，故错误；综上可知错误写法共有3个，故选C.3.已知集合，,则（）A. B. C. D.【答案】A【解析】集合，..故选A.4.集合，,若,则的取值范围为（）A. B. C. D.【答案】C【解析】【详解】集合，,若，则.故选C.5. 下列四个图像中，是函数图像的是（）A. （1）B. （1）、（3）、（4）C. （1）、（2）、（3）D. （3）、（4）【答案】B【解析】试题分析：根据函数的定义，对于x在某一范围内的每一个确定的值，y都有唯一确定的值与它对应，所以(1)(2)不对．考点：函数的概念．6.定义, 若，，则等于（）A. BB.C.D.【答案】B【解析】由题意可得={1，4，5}，又, 所以={2，3}，故选B．点睛：本题主要考查对新定义的理解及应用，分析集合要抓住元素的特征，对的处理，分清层次，先求集合A-B，再把它看成新的集合根据定义求出.7.下列函数中满足在（，0）是单调递增的是（）A. B.C. D.【答案】D【解析】对于A. ，在和上单调递减，不满足；对于B. ，在单调递增，在上单调递减，不满足；对于C. ，在单调递减，在上单调递增，不满足；对于D. ，在单调递增，在上单调递减，满足.故选D.8.如果函数在区间(－∞，4]上是减函数，那么实数a的取值范围是（）A. a≥－3B. a≤－3C. a≤5D. a≥3【答案】B【解析】主要考查函数单调性的概念及二次函数单调区间判定方法。
河南省镇平县第一高级中学2017-2018学年高一上学期期末考前诊断语文试题 Word版含解析
2017秋期期末高一考前诊断语文试题1. 下列词语中加点的字，读音有错误的一组是（）A. 赎．罪（shú）驯．顺（xùn）潭柘．寺（zhâ）蓊．蓊郁郁（wěng）B. 商榷．(quâ) 枷．锁(jiā) 吐蕃．族(bō) 含情脉脉．（mò）C. 砥砺．(lì) 蜷．缩(juǎn) 应．声虫(yìng) 放浪形骸．(hã)D. 惦．记（diàn）袅娜．（nuó）普陀．山(tuó) 游目骋．怀(chěn g)【答案】C【解析】试题分析：题干是“下列词语中加点的字，读音有错误的一组是”。
本题考查汉字字音的识记和辨析。
要看准题目要求，是选择“有错误”的一项。
C项，蜷．缩（quán ）放浪形骸．（hái）点睛：高考字音考查的对象主要有多音字、形声字和异形（包括形似）同音（包括近音）字三种。
由于生活中那些容易读错的字往往也就是高考字音考查的重点内容，因此，归纳出误读的常见类型对我们复习备考是很有帮助的。
同时。
针对每一种误读类型，我们都要采取积极的措施，从而能够有的放矢地掌握好字音这个考点。
字音的误读的原因主要有以下几种。
（1）把多音字的甲音误读成乙音。
（2）形声字类推偏旁引起误读。
（3）习惯误读字，如“玫瑰”中的“瑰”，“气氛”中的“氛”。
（4）生僻字。
生僻字，因其不常见而容易被忽略，易误读。
考生平时要做有心人，注意积累。
2. 下列词语中，字形全正确的一项是（）A. 弥望稀疏遗误战机安之若素B. 倩影饱尝锋芒必露汹涌澎湃C. 落漠窈窕义愤填赝销声匿迹D. 干涸切磋汗流浃背正襟危坐【答案】D【解析】试题分析：题干是“下列词语中，字形全正确的一项是”。
本题考查字形的识记、辨析和理解。
要看准题目要求，是选择“字形全正确”的一项。
A项，遗．误战机（贻） B 项，锋芒必．露（毕） C项，义愤填赝．（膺）3. 下列各句中，加点的成语使用恰当的一项是（）A. 方博士到场时，整个大厅都坐满了和颜悦色．．．．的大学生，大家都为有机会聆听这位科学家的演讲而兴奋不已。
2017-2018学年河南省镇平县第一高级中学高一10月月考化学试题(解析版)
河南省镇平县第一高级中学2017-2018学年高一10月月考化学试题可能用到的相对原子质量：H:1 C: 14 O:16 N: 14 Na: 23 S :32 Cl :35.5 Ba:137 Mg 24 Fe 56第Ⅰ卷（选择题共48 分）一、选择题（本题包括16小题，每小题3分。
每小题只有一个选项符合题意）1. 下列说法中，错误的是（）A. 有了化学科学，人类能够更好利用能源和资源B. 化学科学将为环境问题的解决提供有力的保障C. 化学研究会造成严重的环境污染，最终人类将会毁灭在化学物质中D. 化学家可以制造出自然界中不存在的物质【答案】C【解析】试题分析：有了化学科学，人类能够合理开发和安全应用能源和资源，既能得到充足的能源和资源，又能处理好能源和资源的开发利用与生态环境保护之间的关系，A正确；化学为解决环境问题提供了有力保障，使人类能够使用无害的化妆品和生活用品，既优化了环境，又提高了生活质量，B正确；化学研究不会造成严重的环境污染，C错误；化学家可以制造出自然界中不存在的物质，如新型有机高分材料，医药等，D正确。
考点：化学对工农业生产和社会生活的作用2. 下列说法正确的是（）A. 铜与氯气反应时，剧烈燃烧并产生蓝色的烟B. 将金属钠投入硫酸铜溶液中可观察到有红色的铜生成C. 生活中常用的“84” 消毒液中的有效成分是NaClD. 次氯酸不如次氯酸盐稳定，故通常用次氯酸盐作为漂白剂和消毒剂的主要成分【答案】D【解析】A、铜在氯气中燃烧产生棕黄色烟，生成物是氯化铜，故A错误；B、钠投入硫酸铜溶液时，钠和水反应生成氢氧化钠和氢气，氢氧化钠再和硫酸铜发生复分解反应生成氢氧化铜蓝色沉淀，所以得不到金属单质铜，故B错误；C、“84”消毒液中的有效成分是NaClO，故C错误；D、次氯酸见光易分解，所以次氯酸不如次氯酸盐稳定，故通常用次氯酸盐作为漂白剂和消毒剂的主要成分，故D正确；故选D．【点评】本题考查了氯气及其钠的化学性质，要注意的是：钠和盐溶液反应时，先和水反应．3. 在研究某气体的性质时，发现有刺激性气味，得出这一结论所用的方法属于（）A. 实验法B. 观察法C. 分类法D. 比较法【答案】B4. 在下列溶液中Cl- 物质的量浓度最大的是（）A. 500mL0.1mol/L的NaCl溶液B. 50mL0.6mol/L的MgCl2溶液C. 100mL0.2mol/L的AlCl3 溶液D. 400mL1mol/L的盐酸溶液【答案】B【解析】A项，Cl-物质的量浓度为0.1mol/L；B项，Cl-物质的量浓度为1.2mol/L；C项，Cl-物质的量浓度为0.6mol/L；D项，Cl-物质的量浓度为1mol/L；Cl-物质的量浓度由大到小的顺序为B D C A，答案选B。
【历史】河南省镇平县第一高级中学2017-2018学年高一上学期第一次月考试题 (解析版)
河南省镇平县第一高级中学2017-2018学年高一上学期第一次月考试题一、选择题（本大题共40小题，每小题1．5分，共60分，在每小题所给出的四个选项中，只有一项是符合题目要求的）1.商代统治者凡政治事务都要通过占卜进行决策，这说明我国古代早期政治制度的特点之一是A. 神权与王权结合B. 以血缘关系为纽带C. 权力的高度集中D. 以宗族关系为基础【答案】A【解析】根据题干可知，商朝通过占卜决定国家各项事务，说明统治者欲通过神化王权加强统治，维护王权的绝对权威，A项正确。
以血缘关系为纽带维系政治统治主要涉及到西周时期宗法制，与占卜无关，排除B。
商朝实行内外服制度，商王对参加联盟的附属国的控制力是有限的，并未实现权力的高度集中，排除C。
原始社会氏族成员共同管理的形式是以以宗族关系为基础，与迷信占卜有本质区别，排除D。
综上所述，本题正确答案为A。
2.王位世袭制代替禅让制是历史的进步，主要是因为王位世袭制A. 代表了先进阶级的利益B. 是文明时代开始的标志C. 是生产力发展的结果和进步的要求D. 是华夏族开始形成的标志【答案】C【解析】随着生产力的发展，原始社会公有制逐步被私有制所取代，与经济基础的变革相适应，禅让制被王位世袭制所取代。
因此，世袭制代替禅让制是生产力发展的必然结果和时代进步的要求。
故C项正确；王位世袭制取代禅让制是阶级对立的产物，并不能体现该制度代表了先进阶级的利益。
故A项错误；奴隶社会取代原始社会，标志着人类社会从愚昧时代进入文明时代。
因此中国古代文明时代开始的标志是第一个国家的建立，即夏朝的建立，并非王位世袭制。
故B项错误；华夏族的形成要追溯至炎黄时期，并非在夏朝形成，且不能简单以一项政治制度的更替作为华夏族形成的标志。
故D项错误。
3. “封建亲戚，以藩屏周。
”这句话指的是( )A. 分封制B. 井田制C. 郡县制D. 行省制【答案】A【解析】试题分析：材料中“封建亲戚，以藩屏周”，意思是将西周的宗族姻亲分封到各地，广建子国，构筑一道屏障,来捍卫周天子的中央权威。
河南省镇平县第一高级中学2017-2018学年高一上学期第二次月考英语试题(实验)
2017秋期高一第二次月英语考试题（实验）本试卷分第I卷(选择题)和第II卷(非选择题)两部分，共150分。
考试时间100分钟。
第一卷第一部分听力（共两节，满分30分）（略）第二部分：阅读理解（共两节，20小题，每小题2分，满分40分）第一节(共15小题，每小题2分，共30分)阅读下列短文，从每题所给的四个选项中选出最佳选项，并在答题卡上将之涂黑。
AMany years ago, when I was fresh out of school and working in Denver, I was driving to my parents’ home in Missouri for Christmas. I stopped at a gas station about 50 miles from Oklahoma City, where I was planning to stop and visit a friend. While I was standing in line at the cash register (收款台), I said hello to an older couple who were also paying for gas.I took off, but had gone only a few miles when black smoke poured from the back of my car. I stopped and wondered what I should do. A car pulled up behind me. It was the couple I had spoken t o at the gas station. They said they would take me to my friend’s. We chatted on the way into the city, and when I got out of the car, the husband gave me his business card.I wrote him and his wife a thank-you note for helping me. Soon afterward, I received a Christmas present from them. Their note that came with it said that helping me had made their holidays meaningful.Years later, I drove to a meeting in a nearby town in the morning. In late afternoon I returned to my car and found that I’d left the li ghts on all day, and the battery (电池) was dead. Then I noticed that the Friendly Ford dealership—a shop selling cars—was right next door. I walked over and found two salesmen in the showroom.“Just how friendly is Friendly Ford?” I asked and explained my t rouble. They quickly drove a pickup truck to my car and started it. They would accept no payment, so when I got home, I wrote them a note to say thanks. I received a letter back from one of the salesmen. No one had ever taken the time to write him and say thank you, and it meant a lot, he said.“Thank you” —two powerful words. They’re easy to say and mean so much.1. What happened when the author found smoke coming out of his car?A．He had it pulled back to the gas station. B．The couple sent him a business card.C．The couple offered to help him. D．He called his friend for help.2. The battery of the author’s car was dead because ________.A．something went wrong with the lights B．the meeting lasted a whole dayC．he forgot to turn off the lights D．he drove too long a distance3. By telling his own experiences, the author tries to show ________.A．how to write a thank-you letter B．how to deal with car problemsC．the kind-heartedness of older people D．the importance of expressing thanksBPeople in the United States honor their parents with two special days：Mother’s Day, on the second Sunday in May, and Father’s Day, on the third Sunday in June. These days are set aside to show love and respect for parents. They raise their children and educate them to be responsible (有责任感的) citizens. They give love and care. These two days make us think about the changing roles of mothers and fathers. More mothers now work outside the home. More fathers must help with child care.These two special days a re celebrated in many different ways. On Mother’s Day people wear carnations. A red one symbolizes a living mother. A white one shows that the mother is dead. Many people attend religious services to honor parents. It is also a day when people whose parents are dead visit the cemetery (墓地).On these days families get together at home, as well as in restaurants. They often have outdoor barbecues for Father’s Day. These are days of fun and good feelings and memories.Another tradition is to give cards and gifts. Children make them in school. Many people make their own presents. These are valued more than the ones bought in stores. It is not the value of the gift that is important, but it is “the thought that counts”. Greeting card stores, florists, candy makers, bakeries, telephone companies, and other stores do a lot of business during these holidays.4. Which of the following is NOT a reason for children to show love and respect for parents?A. Parents bring up children.B. Parents give love and care to children.C. Parents educate children to be good persons.D. Parents pass away before children grow up.5. What do you think “florists” do?A. They sell flowers.B. They make and sell bread.C. They offer enough room for having family parties.D. They sell special gifts for Mother’s Day and Father’s Day.6. What do you know from the passage?A. Mother’s Day and Father’s Day are both in May.B. Fewer women worked outside the home in the past.C. Not all the children respect their parentsD. Fathers are not as important as mothers at home.7. On Mother’s Day and Father’s Day, ________.A. people usually have family partiesB. everyone goes to visit the cemeteryC. children always go to parents’ homeD. hand-made cards are the most valuable giftsCFootball T-shirts are more commonly connected with boys than girls. This can often cause a problem when you want to find a cool shirt for a girl. That is not to say that there are no cool shirts out there for girls to wear. The problem is that they are often harder to find than the ones for boys.You can get custom (订制的) shirt printed for girls from a number of custom print stores. Of course you have to make sure that they are legally allowed to use the logos (商标) and colours of the team you want to support.You can also go through official channels to get the shirt you want. The official channels will generally be the large sportswear stores or the official stores of the teams. These stores will be able to use the colours of the teams and even put the name of the person who the shirt is for on it.If you do not feel like you have to try the T-shirts on, then an online store may be your best choice. The reason for this is that you can visit various stores and find the best ones.If you want to see what the T-shirt looks like in real life, then going to a store is the best choice. Large sportswear stores often have football shirts. These are the best places to go if you do not live close to an official store. And these stores usually have lower prices than the official stores.8. According to the text, football T-shirts ________.A. are all made by boysB. are seldom loved by girlsC. are only designed for boysD. are difficult to find for girls9. According to the text, custom print stores ________.A. could use any colours and logos as they likeB. should be operated by the football teamsC. could print anything that official stores sellD. should legally use your favourite logos10. If you don’t need to try the T-shirts on, you can visit ________.A. official storesB. online storesC. large sportswear storesD. custom print stores11. What kind of readers is this passage for?A. Football players.B. Clothes store owners.C. Female football fans.D. Physical education teacherDEnglish songs have been very popular for people around the world for many decades. Songs from Elvis Presley to Ricky Martin, from the Beatles to Eminem and from Natalie Cole to Britney Spears have all been enjoyed by people around the world, even for people who don’t speak English, and even for people who speak zero English.From my experience, some people listen to English songs for 20-30 years but still don’t achieve any good English skills. Some people choose English songs to be their main learning method, but most of them fail.Listening to English songs does not help you to speak English fluently. It does help you gain some vocabulary, but most of these words are unusua l ones that you don’t use in everyday life. You won’t learn the sentence “It is a difficult project. We really need to meet the deadline.” in any English songs. All you will hear are love, passion, affection, hate and blue, for the feeling, not the color.People like using English songs to practice English skills because it’s easy and enjoyable. They think that sitting in the car listening to English songs day after day will improve their English skills. It actually will not.You will definitely not improve your listening skills because normal people don’t speak with a tune. People don’t talk like Eminem’s songs. You can’t get yourself familiar with English pronunciation or accent just from listening to English songs. The words that they pronounce in the songs are not the words that you will hear in your everyday life. They can even confuse you more about how English is pronounced.I would fully encourage you to watch English movies and listen to radio news or other normal talks, but not music. Of course, you can consume it for fun but not with the aim of improving your English skills. Having good English skills is not that easy. Remember you should work hard to improve your English step by step.12. According to the passage, listening to English songs can help you _____A. improve your English grammarB. speak English more fluentlyC. gain the skills of writingD. learn more new words13. Which of the following statements is NOT true according to the passage?A. Most people think it is convenient to learn English by listening to English songs.B. It’s hard for people to improve their listening skills by listening to English songs.C. It’s a good idea to learn to speak with an English accent by listening to English songs.D. It’s rare to hear normal p eople speak English like they are singing.14. What can we learn about the words in English songs?A. Most of them are vivid and interesting.B. They are seldom used in people’s everyday life.C. English learners should learn more of them.D. They can help people improve their pronunciation.15. It can be inferred from the passage that the writer may be _____.A. an experienced English learnerB. a well-known pop singerC. a Chinese music fanD. an American teacher第二节（共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能入空白处的最佳选项。
河南省镇平县第一高级中学2017-2018学年高一10月月考
2017年秋期镇平一高高一第一次月考政治试题提示：1、本试卷分第I卷（选择题）和第II卷（非选择题）。
满分100分，考试时间90分钟。
2、选择题答案用铅笔涂在答题卷上，主观题答案写在答题卷相应位置上，否则不给分。
第I卷一、单项选择题：（30个小题，每小题2分，共60分，每小题只有一个最佳选项）1、在下列物品中，能够肯定是商品的是( )①大米②商店里过了保质期的饮料③买回来食用的面粉④送给人的鲜花⑤商店里待售的月饼A．①② B．②③ C．④⑤ D．⑤由吴京主演的电影《战狼2》自7月底上映以来，受到观众的一致好评，截至目前已创下56.5亿人民币票房。
据此回答2--3题。
2、《战狼2》这部电影（）A．是商品，因为它有使用价值B．不是商品，因为它不用于交换C．不是商品，因为它有价值没有使用价值D．是商品，因为它是使用价值和价值的统一体3、小明在网络上看到某影院《战狼2》电影票标价为50元人民币，打完折后他支付了45元人民币购买了电影票。
请问在此过程中，人民币执行的职能分别是( ) A．流通手段、价值尺度 B．价值尺度、流通手段C．流通手段、支付手段 D．价值尺度、支付手段4、国家质量监督检验检疫总局去年对跨境电商渠道进口的儿童用品质量进行了抽检，总计抽样654批，检出不合格217批，不合格率为33%。
其中，进口玩具和进口儿童服装存在小零件或绳带容易导致儿童窒息等问题。
之所以要注重商品的质量是因为（）①商品的使用价值是价值的物质承担者②商品质量关系到人民群众的切身利益③高质量的商品的使用价值大于其价值④商品的使用价值能够决定商品的价值量A．①② B．①③ C．②③ D．③④5、对货币的产生，认识正确的是( )①货币的出现要比商品晚②货币是商品交换发展到一定阶段的产物③有货币才能买到商品，所以货币的出现比商品早④有货币才能买到商品，货币和商品是一对孪生兄弟，是同时产生的A.①② B．②④ C．③ D．④6、历史上,货币出现以前,黄金与其他普通的商品没有区别；货币出现以后,人们把货币看得很神秘,并把作为货币的黄金看成是财富的象征。
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镇平一高2017年秋高一物理综合检测
（时间：100分钟 总分：110分）
一、选择题（本题共12小题；每小题4分，共48分。
在每小题给出的四个选项中，有的小题只有一个选项正确，有的小题有多个选项正确，全部选对的得4分，选不全的得2分，有选错或不答的得0分）
1．在国际单位制中，力学的基本单位是：（ ）
A ．N 、m 、s
B ．kg 、m 、s
C ．N 、kg 、s
D ．N 、kg 、m 2．对于静止在水平桌面上的物体，以下说法正确的是( ) A ．物体对桌面的压力就是物体的重力
B ．物体的重力和桌面对物体的支持力是一对平衡力
C ．物体对桌面的压力和物体的重力是一对作用力与反作用力
D ．物体对桌面的压力和桌面对物体的支持力是一对作用力与反作用力 3．关于摩擦力，下列说法中正确的是：（ ） A ．摩擦力的大小总是跟压力的大小成正比 B ．接触且相对静止的两个物体之间不会产生摩擦力 C ．滑动摩擦力大小跟物体相对运动的速度大小有关 D ．摩擦力的方向总是跟压力的方向垂直
4．如图所示，在倾角为θ的光滑斜面上，重为G 的物体受到水平推力F 的作用，物体静止不动，则物体对斜面的压力大小为：（ ） A ．Gsin θ B ．Gcos θ C ．Gcos θ+Fsin θ D ．Gcos θ+Fcos θ
5．关于运动状态与所受合外力的关系，下列叙述正确的是（ ） A ．力是维持物体运动状态的原因
B ．物体受到不为零的合外力作用时，它的运动状态要发生改变
C ．物体受到的合外力为零时，它一定处于静止状态
D ．物体的运动方向一定与所受的合外力的方向相同 6.质量为0.8kg 的物体在一水平面上运动，如图所示的两条直线分别表示物体受到水平拉力作用和不受拉力作用的v —t 图线。
由图线可知（ ）
A.
图线a 反映了物体受水平拉力的作用 B.图线b 反映了物体受水平拉力的作用
C.水平拉力为1.2N
D.水平拉力为1.8N
7．某物体由静止开始以恒定加速度运动，经t s 速度达到v ，则在这t s 内，物体在中间时刻的速度与物体位于中点位置时的速度大小之比为：（ ） A ．1∶2 B ．1∶2 C ．2∶1 D ．3∶1 8．如图所示，竖直圆环中有多条起始于A 点的光滑轨道，其中AB 通过环心O 并保持竖直。
一质点分别自A 点沿各条轨道下滑，初速度均为零。
那么，质点沿各轨道下滑的时间相比较：（ ） A ．质点沿着与AB 夹角越大的轨道下滑，时间越短 B ．质点沿着轨道AB 下滑，时间最短
C ．轨道与AB 夹角越小（AB 除外），质点沿其下滑的时间越短
D ．无论沿图中哪条轨道下滑，所用的时间均相同
9．A 、B 两球的质量均为m ，两球之间用轻弹簧相连，放在光滑的水平地面上，A 球左侧靠墙。
用力F 向左推B 球将弹簧压缩，如图所示。
然后突然将力F 撤去，在撤去力F 的瞬间，A 、B 两球的加速度分别为： （ ） A ．0 ， 0 B ．0 ， F/m C ．F/2m ， F/m D ．F/2m ，F/2m
10．在加速度为a 匀加速上升的电梯中，有一个质量为m 的人，下列说法正确的是：（ ） A ．此人对地球的吸引作用产生的力为m （g －a ） B ．此人对电梯的压力为m （g －a ）
C ．此人受到的重力为m （g + a ）
D ．此人的视重为m （g + a ）
11．如图所示，质量为M 、倾角为 的斜劈形物体固定在水平地面上，质量为m 的物块与斜面之间的动摩擦因素为 ．并以某一初速度沿劈的斜面向上滑，至速度为零后静止在斜面上，而斜劈始终保持静止．则下列选项中正确的是（ ） A ．物块在上滑过程中所受摩擦力大小为mg sin B ．物块在上滑过程中所受摩擦力大小为 mg cos C ．物块ｍ静止在斜面上后，所受的摩擦力大小为 mg cos D ．物块ｍ静止在斜面上后，所受的摩擦力大小为mg sin 12.如图所示，把球A 夹在竖直墙和木板BC 之间，不计摩擦。
球对墙的压力为N 1，球对板的压力为N 2，在将板BC 逐渐放至水平的过程中，下列说法正确的是（ ）
D
A 、N 1、N 2都增大
B 、N 1、N 2都减小
C 、N 1增大、N 2减小
D 、N 1减小、N 2增大
二、填空题（本题共3小题，每空2分，共22分。
把答案填在相应的横线上）
13．小华和小雨在进行课外活动中．他们利用学过的自由落体运动的知识估测各自的＂反应时间＂，开始时小华将直尺的下端＂60cm ＂刻度靠近小雨的大母指尖，要求小华释放直尺的同时，小雨要立即抓住尺．结果发现小雨抓住尺时，他的大母指尖在＂10cm ＂位置（g =10m/s 2
）。
小雨刚抓住尺时，尺已下落的高度是 m ；请你根据实验数据，估算一下小雨的反应时间是 s ．
14.(1)关于电磁打点计时器的使用，下列说法正确的是（ ） A.电磁打点计时器使用的是10V 以下的直流电源 B.在测量物体速度时，先让物体运动，后接通电源 C.使用的电源频率越高，打点的时间间隔就越小 D.纸带上打的点越密，说明物体运动的越慢
(2)电磁打点计时器是测量时间的仪器，其工作电压约为 V, 电源频率是50Hz, 它每隔 s 打一次点,在测定匀变速直线运动加速度实验中，某次实验纸带的记录如图所示，纸带上O 、A 、B 、C 、D 、E 、F 、G 为计数点，每相邻两个计数点间还有4个点没有画出，由图可知纸带的加速度等于 ，在打D 点时纸带的速度为 （保留两位有效数字），F 到G 的距离为 cm 。
15．探究物体的加速度与力、质量的关系实验如下：
（1）在探究物体的加速度与力．．．．．
的关系时，应保持 不变，分别改变施加在物体上的水平拉力F ，测出相对应的加速度a 。
（2）在探究物体的加速度与物体质量．．．．．．．．
的关系时，应保持 不变，分别改变物体的质量m ，测出相对应的加速度a 。
(3)如果m
a 1
图象是通过坐标原点的一条直线，则说明 。
A.物体的加速度a 与其质量m 成正比。
B.物体的加速度a 与其质量m 成反比。
C.物体的质量m与其加速度a成反比。
D.物体的质量m与其加速度a成反比。
三、计算题（本题共4小题，40分。
答题时请写出必要的文字说明、方程式和重要的演算步骤，只写出最后答案的不能得分。
）
16.（8分）如图所示，灯重G=20N，AO与天花板间夹角α=30°，
BO水平，试求AO、BO两绳受到的拉力各为多大？
17．（10 分）汽车从静止开始做匀加速直线运动,途中先后经过相距125米的A、B 两棵树，用了10秒时间，已知过B树位置时的速度为15m/s，求汽车到A树位置时的速度和从出发到A树所用的时间。
18.（12分）如图所示，一个人用与水平方向成θ＝37°角的斜向下的推力F推一个重G＝200Ｎ的箱子匀速前进，箱子与地面间的动摩擦因数为μ＝0.5（g =10m/s2）。
（1）求推力F的大小．
（2）若人不改变推力Ｆ的大小，只把力的
方向变为水平去推这个静止的箱子，推
力作用时间t =2s后撤去，求撤去推力
F后箱子还能滑行多远停下来?
19.（10分）质量m=20kg的物体，在大小恒定的水平外力F的
作用下，沿水平面做直线运动。
（0～2）s内F与运动方向相反，
（2～4）s内F与运动方向相同，物体的速度—时间图象如图
所示（g =10m/s2）。
求物体与水平间的动摩擦因数。
参考答案
一、选择题 二、填空题
13. 0.5 0.32 14.（1）CD （选不全扣1分） （2）4∽6V ； 0.02秒； 0.75 m/s 2
；0.40 m/s ； 5.90
15.（1）质量（2）力（3）B 三、计算题
16. 解：设 AO 、BO 两绳对O 点的拉力分别为1F 和2F ，则由平衡条件可得
G F =αsin 1，21cos F F =α 解得N F 401=，N F 3202=
所以AO 、BO 两绳受到的拉力分别为N 40和N 320。
17.解:依题意得，汽车在A 、B 两棵树之间运动的平均速度为V =
t
S AB = 10125
m/s=12.5m/s 根据平均速度公式V =
2
B
A V V +可得：汽车通过A 树的速度V A =2V -V
B =10 m/s 根据汽车做匀加速运动加速度为a=
t
V V A B -=101015- m/s 2=0.5 m/s 2
汽车从出发到A 树的时间为t=
a
V A 0-=5.010
s=20s 18. .解：（1）对物体受力分析如图，由平衡条件可得f F =θcos ，N F G F =+θsin 又有N F f μ=联立以上三式解得N F 200=。
（2）未撤去力F 前 1ma f F =-，G f μ=
2S 末物体的速度t a v 1= 设撤去力F 后，物体能够滑行的距离为x
2ma f =,G f μ=,2
2
2a v x = 联立以上各式解得m x 10= 19.解：（0～2）s 内，由牛顿第二定律可得 1ma mg F =+μ
（2～4）s 内，由牛顿第二定律可得 2ma mg F =-μ 由图可知21/5s m a =，22/1s m a =（大小） 解得2.0=μ。