2012上海无纸化试题

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2012上海市数学会考卷(含答案)

2012年上海市普通高中学业水平考试数学试卷考生注意：1．本试卷共4页，满分120分，考试时间90分钟。

2．本考试分设试卷和答题纸。

试卷包括三大题，第一大题为填空题，第二大题为选择题，第三大题为解答题。

3．答题前，务必在答题纸上填写姓名、报名号、考场号和座位号，并将核对后的条形码贴在指定位置上。

4．作答必须涂或写在答题纸上，在试卷上作答一律不得分。

第二答题的作答必须涂在答题纸上相应的区域，第一、第三答题的作答必须写在答题纸上与试卷题号对应的位置。

一、填空题：（本答题满分36分）本答题共有12题．考生应在答题纸相应编号的空格内直接填写结果，每个空格填对得3分，否则一律得零分．1．已知集合{}=1,2A ，{}2,B a =．若{}1,2,3AB =，则a = ．2．函数()21f x x =-的定义域为．3．满足不等式01x x <+的x 的取值范围是．4．若球的体积为36π，则球的半径为．5．若直线220x my ++=与直线4610x y +-=平行，则m = ．6．若向量a 与b 的夹角为60°，2a =，1b =，则a b ⋅= ．7．在△ABC 中，角A B C 、、所对的边长分别为a b c 、、．若45A =，30C =，2c =，则a = ．8．若无穷等比数列{}()n a n N *∈的首项为l 、公比为13，则该数列各项的和为． 9．在61x x ⎛⎫+ ⎪⎝⎭的二项展开式中，常数项的值为．10．若12i +（i 为虚数单位）是关于x 的方程230x mx ++=的根，则实数m = ．11．执行右图所示算法，输出的结果是．12．已知圆n O ：()2221x y n N n*+=∈与圆C ：()2211x y -+=．设圆n O 与y 轴正半轴的交点为n R ，圆n O 与圆C 在x 轴上方的交点为n Q ，直线n n R Q 交x 轴于点n P ．当n 趋向于无穷大时，点n P 无限趋近于定点P ，定点P 的横坐标为．二、选择题：（本大题满分36分）本大题共有12题，每题有且只有一个正确答案．考生应在答题纸的相应编号上，将代表答案的小方格涂黑，选对得3分，否则一律得零分．13．若矩阵12a b ⎛⎫- ⎪ ⎪⎝⎭是线性方程组321x y x y -=⎧⎨-=⎩，的系数矩阵，则（）． A ．11a b ==-，； B ．11a b ==，； C ．11a b =-=，；D ．11a b =-=-，．14．函数()21xf x =+的反函数是（）． A ．()12log 1f x x -=+； B ．()1log 21x f x -=+； C ．()()12log 1f x x -=-；D ．()12log 1f x x -=-．15．抛物线24y x =的焦点到其准线的距离是（）． A ．1； B ．2； C ．4； D ．8．16．某校高一、高二、高三分别有学生400名、300名、300名．为了解他们课外活动情况，用分层抽样的方法从中抽取50名学生进行调查，应抽取高二学生人数为（）．A ．50；B ．30；C ．20；D ．15．17．函数()32f x x x =+（）．A ．是奇函数且为增函数；B ．是偶函数且为增函数；C ．是奇函数且为减函数；D ．是偶函数且为减函数．18．已知扇形的圆心角为3π，半径为3，该扇形的面积为（）． A ．3π； B ．32π； C ．π； D ．2π．19．函数()sin 3cos 1f x x x =++的最大值是（）．A ．1-；B ．2；C ．3；D ．23+．20．函数12x y =的大致图象是（）．A ．B ．C ．D ．21．若椭圆221164x y +=与x 轴正半轴、y 轴正半轴的交点分别为A 、B ，则直线AB 的方程为（）．A ．240x y +-=；B ．240x y --=；C ．240x y -+=；D ．240x y ++=．22．设1l 、2l 是空间两条直线．“1l 、2l 没有公共点”是“1l 、2l 为异面直线”的（）．A ．充分但非必要条件；B ．必要但非充分条件；C ．充分必要条件；D ．既非充分又非必要条件．23．从17名男同学和21名女同学中随机抽取3名，组成环保志愿者小组，这个小组中必有男同学的概率（精确到0.001）为（）．A ． 0.141；B ． 0.335；C ． 0.423；D ．0.842．24．实数a 、b 满足0ab >且a b ≠，由a 、b 、2a b +、ab 按一定顺序构成的数列（）． A ．可能是等差数列，也可能是等比数列； B ．可能是等差数列，但不可能是等比数列；C ．不可能是筹差数列，但可能是等比数列；D ．不可能是等差数列，也不可能是等比数列．三、解答题：（本大题满分48分）本大题共有5题．解答下列各题必须在答题纸相应编号的规定区域内写出必要的步骤．25．（本题满分7分）已知3cos 3α=，化简并求值：()21tan 2cos 2cos 233ππααα⎡⎤⎛⎫⎛⎫+++- ⎪ ⎪⎢⎥⎝⎭⎝⎭⎣⎦．26．（本题满分7分）如图所示，正四棱柱1111ABCD A B C D -的底面边长为2，表面积为32，求异面直线1DA与11B C 所成角的大小（结果用反三角函数值表示）．27．（本题满分7分）已知等比数列{}()n a n N *∈满足12a =，454a =，等差数列{}n b ()n N *∈满足11b a =，32b a =．求数列{}n b 的前n 项和n S ．28．（本题满分13分）本题共有2个小题，第1小题满分5分，第2小题满分8分．己知双曲线C 的两个焦点分别为()130F -，、()230F ，，渐近线方程为2y x =±．（1）求双曲线C 的方程；（2）若过点()130F -，的直线l 与双曲线C 的左支有两个交点，且点()01M ，到l 的距离小于1，求直线l 的倾斜角的范围．29．（本题满分14分）本题共有2个小题，第1小题满分5分，第2小题满分9分．设函数()f x 、()g x 有相同的定义域D ．对任意x D ∈，过点(),0x 并垂直于x 轴的直线与()f x 、()g x 的图像分别交于点A 、B ，向量OA 、OB 满足OA OB ⊥（O 为坐标原点）．（1）若()1f x x =-+，()1x ∈∞，，求()g x 的解析式，并作出其大致图像；（2）若()[](]22log 62,46346x x f x x x x ⎧-∈⎪=⎨-++∈⎪⎩，，，，，求()g x 的最大值和最小值．简易版答案：一、填空题3； 2. [1,1]-； 3. (1,0)-； 4. 3； 5. 3； 6. 1； 7. 2； 8. 32； 9. 20； 10. 2-； 11. 31； 12. 4；二、选择题13. A ； 14. C ； 15. B ； 16. D ； 17. A ； 18. B ；19. C ； 20. C ； 21. A ； 22. B ； 23. D ； 24. D ；三、解答题25. 3-；26. 3arctan 2； 27. (1)n n ⋅+；28. （1）2212y x -=；（2）(arctan 2,arctan 3)；29. （1）2(),(1)1x g x x x =>-，图略（NIKE 函数，最低点是(2,4)，分别以直线1x =和直线1y x =+为渐近线）；（2）max ()4g x =，min ()12g x =-1.。

2012(上海卷)试题及答案

2012年上海高考试卷本试卷共7页，满分150分，考试时间120分钟。

全卷包括六大题，第一、二大题为单项选择题，第三大题为多项选择题，第四大题为填空题，第五大题为实验题，第六大题为计算题。

考生注意：1．答卷前，考生务必在试卷和答题卡上用蓝色或黑色的钢笔或圆珠笔填写姓名、准考证号.并将条形码贴在指定的位置上。

2．第一、第二和第三大题的作答必须用2B 铅笔涂在答题纸上相应区域内与试卷题号对应的位置，需要更改时，必须将原选项用橡皮擦去，重新选择。

第四、第五和第六大题的作答必须用蓝色或黑色的钢笔或圆珠笔写在答题纸上与试卷题号对应的位置（作图可用铅笔）.3．第30、31、32、33题要求写出必要的文字说明、方程式和重要的演算步骤。

只写出最后答案，而未写出主要演算过程中，不能得分。

有关物理量的数值计算问题，答案中必须明确写出数值和单位。

一．单项选择题.（共16分，每小題2分，每小题只有一个正确选项）1．在光电效应实验中，用单色光照射某种金属表面，有光电子逸出，则光电子的最大初动能取决于入射光的（）A ，（A ）频率（B ）强度（C ）照射时间（D ）光子数目 2．下图为红光或紫光通过双缝或单缝所呈现的图样，则（）B ，（A ）甲为紫光的干涉图样（B ）乙为紫光的干涉图样（C ）丙为红光的干涉图样（D ）丁为红光的干涉图样 3．与原子核内部变化有关的现象是（）C ，（A ）电离现象（B ）光电效应现象（C ）天然放射现象（D ）α粒子散射现象4．根据爱因斯坦的“光子说”可知（）B ，（A ）“光子说”本质就是牛顿的“微粒说”（B ）光的波长越大，光子的能量越小（C ）一束单色光的能量可以连续变化（D ）只有光子数很多时，光才具有粒子性5．在轧制钢板时需要动态地监测钢板厚度，其检测装置由放射源、探测器等构成，如图所示。

该装置中探测器接收到的是（）D ，（A ）X 射线（B ）α射线（C ）β射线（D ）γ射线 6．已知两个共点力的合力为50N ，分力F 1的方向与合力F 的方向成30︒角，分力F 2的大小为30N 。

2012年上海市普通高中学业水平考试试卷和答案

2012年上海市普通高中学业水平考试生命科学试卷一选择题（共30分，每小题1分。

每小题只有一个正确答案）1．赫尔希和蔡斯的噬菌体侵染细菌实验（噬菌体结构如图l所示）证明了DNA是遗传物质。

该实验涉及32P标记，标记的部位是A．④B．②C．①和②D．①或②2．下列结构中，能接受化学信息的是A．视网膜上的视细胞B．内耳中的耳蜗C．皮肤中的压力感受器D．舌上的味细胞3．青少年摄入脂质过少不利于健康与生长，这是因为脂质A．是细胞代谢反应的辅酶B．是直接能源物质C．可以全部转化为维生素D．是性激素合成的原料4．为验证胚芽鞘弯曲生长的原理，某同学在暗室中按图2设计进行实验，其结果应为A．胚芽鞘不生长B．胚芽鞘向左弯曲生长C．胚芽鞘直立生长D．胚芽鞘向右弯曲生长5．蚕豆体细胞有12条染色体，则有丝分裂后期细胞中的染色体数目是A．6条B．12条C．24条D．36条6．无机盐在生物体内起重要作用。

下列关于无机盐的叙述，错误的是A．缺钙易导致人体肌肉抽搐B．缺锌易造成人体生长发育不良C．碘吸收过少影响甲状腺素的合成D．铁是叶绿素分子必要的合成元素7．“无心插柳柳成荫”表述的生殖类型是A．营养繁殖B．出芽生殖C．孢子生殖D．有性生殖8．图3是基因型为Aa的某细胞处在某分裂时期的细胞形态图，则A和A基因的分离将发生在A．减数第一次分裂后期B．减数第二次分裂后期C．减数第一次分裂末期D．减数第二次分裂末期9．细胞分化后，浆细胞能合成抗体，肌肉细胞能合成肌动蛋白。

下列关于浆细胞和肌肉细胞的描述，正确的是A．DNA相同，蛋白质有所不同B．DNA不同，蛋白质有所不同C．DNA相同，蛋白质完全相同D．DNA不同，蛋白质完全相同10．表1为不同生物体的含水量(％)。

下列各项中，不属于表中内容所蕴含的信息是表l水母鱼类青蛙藻类高等植物哺乳动物休眠种子97 82 78 90 60-80 65 <10A．生物体含水量与其生存环境相关B．生物体中含量最多的化合物是水C．生物体含水量与其体重大小相关D．休眠种子含水量与其代谢水平有关11．糖尿病患者需要定期进行激素治疗，该激素为A．胰岛素B．生长激素C．雄性激素D．胰高血糖素12．在植物生长发育过程中，激素起重要作用，能够抑制细胞伸长和分裂的激素是A．生长素B．脱落酸C．赤霉素D．细胞分裂素13．1864年，德国植物生理学家萨克斯把紫苏先在暗处放置12h，然后将叶片的一部分用黑纸遮住（见图4）。

上海市普通高中信息科技学业考试2012年第一二套试卷及答案

上海市普通高中信息科技学业考试2012年第一套试卷说明：本模块总分75分。

第1——27题，单项选择题每题2.5分，填空题每空3分。

第28题，共6分。

1．关于信息，以下表述错误的选项是〔〕。

A．树木的“年轮”铭刻着树木生常年龄的信息B．信息论的创始人香农认为信息是能够用来消除不确定性的知识C．信息随着载体的物理形式变化而变化D．文字、声音、图像都可以作为信息的载体2.“天宫一号”机舱内设计了监测和净化装置，以确保航天员在太空家园里也能享受到春天般清新的无毒无害空气，这主要运用的信息技术是〔〕。

A．感测技术B．虚拟现实技术C．通讯技术D．遥控技术3．我国的“风云三号”气象卫星拍摄卫星云图的过程是〔〕。

A．表达信息B．获取信息C．加工信息D．存储信息4.Wi-Fi是一种可以将个人电脑、手持设备〔如PDA，〕等终端以无线方式互相连接的网络技术。

以下表述正确的选项是〔〕。

A．使用Wi-Fi技末的唯一优点是上网速度快B．Wi-Fi是唯一的无线连接技术C．Wi-Fi技术给人们带来了更为便捷的上网方式D．使用Wi-Fi技术上网不需要付费5．以下能实现信息数字化的操作是〔〕。

A．用电脑看影碟B．删除“回收站”里的垃圾文件C．在Word中输入一段文字D．用打印机打印文件6．一个七位二进制数1■10■01，其中有两位模糊不清。

在以下十进制数中，可能与此二进制数等值的是〔〕。

①79 ②81 ③111 ④113A．②③B．②④C．①③D．①④7．在电脑内部，用二进制代码存储信息，但为了简化冗长的二进制代码，一般使用八进制或十六进制代码表示。

根据下表所示的各数制间的转换规律，已知(325)10 = (101000101)2 = (145)16则十进制数325转换为八进制数是〔505〕。

8．在电脑内部，采用二进制编码存储字符和汉字。

关于信息的编码，以下表述错误的选项是〔〕。

A．将字符的ASCII编码从大到小排列，依次为：小写英文字母>大写英文字母>阿拉伯数字B．汉字在输入电脑后，必须使用统一的汉字内码，并以二进制形式存储和处理C．一个字节由8位二进制数组成，每个汉字的内码只能占用2个字节D．假设用3位二进制代码表示一个字符，则可表示256个不同字符9．对录音机输出的音频信号进行数字化，假设采样频率为47kHz，每个样本的值用16位二进制数量化，且为立体声双声道录制，则每秒录音需要占用〔188k〕字节。

2012年上海市初中学生学业考试

2012年上海市初中学生学业考试2012年上海市初中学生学业考试说明：1．本试卷包括闭卷与开卷两部分。

考试时间60分钟，满分100分。

闭卷部分答题时间为20分钟；开卷部分答题时间为40分钟。

2．考试成绩分优、良、及格和不及格4个等第。

Ⅰ．闭卷部分（共50分，答题时间20分钟）一、选择题（本大题检30分，每小题2分。

将下列各题中一个正确答案的编号填入括号内）1．下列实验操作正确的是（）A．滴加液体 B．读液体体积 C．点燃酒精灯 D．测定溶液的pH 2．能控制物质进出细胞的结构是（）A．细胞膜 B．细胞质 C．细胞核 D．细胞壁3．有人把一些动物分成两组，一组是“麻雀、苍蝇”；另一组是“蛇、蚯蚓”。

他是根据动物哪一部分的特征进行分类的？（）A．翅 B．眼睛 C．脊柱 D．肺4．含羞草受触动时小叶会合拢，蜗牛受醋刺激会避开，这些现象能说明生物具有的特征是（）A．能呼吸 B．能繁殖 C．能生长 D．能对刺激作出反应 5．下列现象中，与大气压强有关的是（）A．压路机压路 B．风吹落树叶 C．钢笔吸墨水 D．热气球升空6．在房间里只要有一个人吸烟，整个房间很快就会充满刺鼻的烟味，这是因为（）A．粒子之间有斥力 B．粒子之间有引力 C．粒子之间有间隙 D．粒子在不停地运动 7．右图表示某班学生脉搏的直方图，下列结论正确的是（）A．每分钟脉搏高于90次的学生共有15人B．该班学生共有31人C．每分钟脉搏低于75次的学生共有3人D．每分钟脉搏在95～100次之间的学生最多8．东海大桥跨越杭州海域，通往洋山深水港，这是利用了（）A．海洋生物资源 B．海滨旅游资源 C．海洋空间资源 D．海水资源9．在海边观察远处来的轮船，会出现图中①至③所示的现象，这现象反映（）A．地球是个球体B．海平面上升C．地球上洪水泛滥D．地球是个“水球”10．根据下表，你认为胃酸过多的患者不宜多吃的食物是（）食物苹果葡萄牛奶玉米粥鸡蛋清11．下列属于青春期发育最突出特征的是（）A．体重迅速增加 B．运动能力加强 C．神经系统快速发育 D．性发育和性成熟12．下列四幅图，能分别表示近视眼成像情况和矫正方法的是（）A．①③ B．②④ C．①④ D．②③13．下列电器设备中，主要利用电流热效应的是（）A．电动机 B．电饭锅 C．电风扇 D．电视机14．关于一杯蔗糖水，下列说法正确的是（）A．蔗糖是溶质，水是溶液 B．蔗糖是溶剂，水是溶液C．水是溶质，蔗糖水是溶液 D．水是溶剂，蔗糖水是溶液15．将一塑料块放在水中，塑料块浮在水面上；将这个塑料块放在煤油中，塑料块沉了下去，那么塑料块、水、煤油三者密度大小关系为（）A．塑料块＞煤油＞水 B．煤油＞塑料块＞水B．C．水＞塑料块＞煤油 D．水＞煤油＞塑料块二、填空与连线题（本大题共20分，每项1分）16．如图1所示的温度计的示数为℃；17．图2 a、b中的情景表示了力的作用效果，其中（填“a”或“b”）主要表示力能使物体的运动状态发生改变；（填“a”或“b”）主要表示力能使物体发生形状改变。

上海市(2006-2012)历年中考数学试卷(含答案)

2012年上海市初中毕业统一学业考试- 1 -2006年上海市初中毕业生统一学业考试数学试卷（满分150分，考试时间100分钟）题号一二三四总分 17 18 19 20 21 22 23 24 25 得分考生注意：1．本卷含四大题，共25题；2．除第一、二大题外，其余各题如无特别说明，都必须写出证明或计算的主要步骤．一．填空题：（本大题共12题，满分36分）【只要求直接写出结果，每个空格填对得3分，否则得零分】 1．计算：4=__________． 2．计算：12x x+=__________．3．不等式60x ->的解集是__________． 4．分解因式：2x xy +=__________． 5．函数13y x =-的定义域是__________．6．方程211x -=的根是__________．7．方程2340x x +-=的两个实数根为1x ，2x ，则12x x = __________．8．用换元法解方程2221221xx x x-+=-时，如果设221xy x =-，那么原方程可化为__________．9．某型号汽油的数量与相应金额的关系如图1所示，那么这种汽油的单价是每升__________元．10．已知在A B C △和111A B C △中，11AB A B =，1A A =∠∠，要使111ABC A B C △≌△，还需添加一个条件，这个条件可以是__________．11．已知圆O 的半径为1，点P 到圆心O 的距离为2，过点P 引圆O 的切线，那么切线长是__________．12．在中国的园林建筑中，很多建筑图形具有对称性．图2是一个破损花窗的图形，请把它补画成中心对称图形．金额（单位：元）509100 数量（单位：升）图1图22012年上海市初中毕业统一学业考试- 2 -二．选择题：（本大题共4题，满分16分）【下列各题的四个结论中，有且只有一个结论是正确的，把正确结论的代号写在题后的圆括号内，选对得4分；不选、错选或者多选得零分】 13．在下列方程中，有实数根的是（）Ａ．2310x x ++=Ｂ．411x +=- Ｃ．2230x x ++=Ｄ．111x x x =--14．二次函数()213y x =--+图象的顶点坐标是（）Ａ．()13-，Ｂ．()13，Ｃ．()13--，Ｄ．()13-，15．在A B C △中，A D 是B C 边上的中线，G 是重心．如果6A G =，那么线段D G 的长为（）Ａ．2 Ｂ．3 Ｃ．6 Ｄ．12 16．在下列命题中，真命题是（）Ａ．两条对角线相等的四边形是矩形Ｂ．两条对角线互相垂直的四边形是菱形Ｃ．两条对角线互相平分的四边形是平行四边形Ｄ．两条对角线互相垂直且相等的四边形是正方形三．（本大题共5题，满分48分） 17．（本题满分9分）先化简，再求值：2111x x x -⎛⎫+÷ ⎪⎝⎭，其中2x =．18．（本题满分9分）解方程组：23010x y x y --=⎧⎨++=⎩，．2012年上海市初中毕业统一学业考试- 3 -19．（本题满分10分，每小题满分各5分）已知：如图3，在A B C △中，A D 是边B C 上的高，E 为边A C 的中点，14B C =，12AD =，4sin 5B =．求（1）线段D C 的长；（2）tg EDC ∠的值．20．（本题满分10分，第（1）小题满分3分，第（2）小题满分4分，第（3）小题满分3分）某市在中心城区范围内，选取重点示范路口进行交通文明状况满意度调查，将调查结果的满意度分为：不满意、一般、较满意、满意和非常满意，依次以红、橙、黄、蓝、绿五色标识．今年五月发布的调查结果中，橙色与黄色标识路口数之和占被调查路口总数的15%．结合未画完整的图4中所示信息，回答下列问题：（1）此次被调查的路口总数是__________；（2）将图4中绿色标识部分补画完整，并标上相应的路口数；（3）此次被调查路口的满意度能否作为该市所有路口交通文明状况满意度的一个随机样本？答：____________________．21．（本题满分10分）本市新建的滴水湖是圆形人工湖．为测量该湖的半径，小杰和小丽沿湖边选取A ，B ，C 三根木柱，使得A ，B 之间的距离与A ，C 之间的距离相等，并测得B C 长为240米，A 到B C 的距离为5米，如图5所示．请你帮他们求出滴水湖的半径．AECDB图 340 30 20 10 01 841红橙黄蓝绿路口数标识图 4BAC图52012年上海市初中毕业统一学业考试- 4 -四．（本大题共4题，满分50分）22．（本题满分12分，第（1）小题满分5分，第（2）小题满分7分）如图6，在直角坐标系中，O 为原点．点A 在第一象限，它的纵坐标是横坐标的3倍，反比例函数12y x=的图象经过点A ．（1）求点A 的坐标；（2）如果经过点A 的一次函数图象与y 轴的正半轴交于点B ，且O B A B =，求这个一次函数的解析式．23．（本题满分12分，每小题满分各6分）已知：如图7，在梯形A B C D 中，A D B C ∥，A B D C =．点E ，F ，G 分别在边A B ，B C ，C D 上，A E G F G C ==．（1）求证：四边形A E F G 是平行四边形；（2）当2F G C E F B =∠∠时，求证：四边形A E F G 是矩形．24．（本题满分12分，第（1）小题满分5分，第（2）小题满分3分，第（3）小题满分4分）如图8，在直角坐标系中，O 为原点．点A 在x 轴的正半轴上，点B 在y 轴的正半轴上，tg 2OAB =∠．二次函数22y x m x =++的图象经过点A ，B ，顶点为D ．（1）求这个二次函数的解析式；yAxO 图6BE A DGC图7F2012年上海市初中毕业统一学业考试- 5 -（2）将O A B △绕点A 顺时针旋转90 后，点B 落到点C 的位置．将上述二次函数图象沿y 轴向上或向下平移后经过点C ．请直接写出点C 的坐标和平移后所得图象的函数解析式；（3）设（2）中平移后所得二次函数图象与y 轴的交点为1B ，顶点为1D ．点P 在平移后的二次函数图象上，且满足1PBB △的面积是1PD D △面积的2倍，求点P 的坐标．25．（本题满分14分，第（1）小题满分4分，第（2）小题满分7分，第（3）小题满分3分）已知点P 在线段A B 上，点O 在线段A B 延长线上．以点O 为圆心，O P 为半径作圆，点C 是圆O 上的一点．（1）如图9，如果2A P P B =，P B B O =．求证：C AO BC O △∽△；（2）如果A P m =（m 是常数，且1m >），1BP =，O P 是O A ，O B 的比例中项．当点C 在圆O 上运动时，求:A C B C 的值（结果用含m 的式子表示）；（3）在（2）的条件下，讨论以B C 为半径的圆B 和以C A 为半径的圆C 的位置关系，并写出相应m 的取值范围．yB AxO图8CA PB O图92012年上海市初中毕业统一学业考试- 6 -2006年上海市初中毕业生统一学业考试数学试卷答案要点与评分标准说明：1．解答只列出试题的一种或几种解法．如果考生的解法与所列解法不同，可参照解答中评分标准相应评分． 2．第一大题只要求直接写出结果，每个空格填对得3分，否则得零分；第二大题每题选对得4分，不选、错选或者多选得零分；17题至25题中右端所注的分数，表示考生正确做对这一步应得分数．评分时，给分或扣分均以1分为单位．答案要点与评分标准一．填空题：（本大题共12题，满分36分）1．2； 2．3x ； 3．6x >； 4．()x x y +；5．3x ≠；6．1；7．4-；8．2210y y -+=（或12y y+=）； 9．5.09；10．1B B =∠∠（或1C C =∠∠，或11AC A C =）； 11．3；12．答案见图1．二．选择题：（本大题共4题，满分16分） 13．Ａ； 14．Ｂ； 15．Ｂ；16．Ｃ．三．（本大题共5题，满分48分） 17．解：原式211x x x x+-=÷················································································（2分）()()111x x x x x +-+=÷····································································（2分）()()111x xxx x +=+-·······································································（1分）11x =-， ·························································································（2分）当2x =时，原式12121==+-． ·····················································（2分） 18．解：消去y 得220x x +-=， ········································································（3分）图12012年上海市初中毕业统一学业考试- 7 -得12x =-，21x =， ··············································································（3分）由12x =-，得15y =-， ········································································（1分）由21x =，得22y =-， ··········································································（1分） ∴原方程组的解是1125x y =-⎧⎨=-⎩，；2212x y =⎧⎨=-⎩，．····················································（1分） 19．解：（1）在R t B D A △中，90BDA = ∠，12AD =，4sin 5A DB A B==， ····（1分）15AB ∴=． ······························································································（1分） 222215129B D A B A D ∴=-=-=． ··················································（2分） 1495D C B C B D ∴=-=-=． ································································（1分）（2）［方法一］过点E 作EF D C ⊥，垂足为F ，EF AD ∴∥． ·············（1分）A E E C = ，1522D F D C ∴==，162E F A D ==． ······························（2分）∴在R t E F D △中，90EFD = ∠，12tg 5E F E D C D F==∠． ····················（2分）［方法二］在R t A D C △中，90ADC = ∠，12tg 5A D C D C==． ··············（2分）D E 是斜边A C 上的中线，12D E A C E C ∴==． ··································（1分）E D CC ∴=∠∠． ·····················································································（1分）12tg tg 5E D C C ∴==∠． ·········································································（1分）20．（1）60； ·······································································································（3分）（2）图略（条形图正确，得2分；标出数字10，得2分）； ····························（4分）（3）不能． ·····································································································（3分） 21．解：设圆心为点O ，连结O B ，O A ，O A 交线段B C 于点D ． ·····················（1分） A B A C =， AB AC ∴=．O A B C ∴⊥，且11202B D DC B C ===．················································································································（1分）由题意，5D A =． ··················································································（1分）在R t BD O △中，222OB OD BD =+， ··················································（2分）设O B x =米， ························································································（1分）则()2225120x x =-+， ·········································································（2分）1442x ∴=． ·······················································································（1分）答：滴水湖的半径为1442.5米． ·····························································（1分）四．（本大题共4题，满分50分） 22．解：（1）由题意，设点A 的坐标为()3a a ，，0a >． ······································（1分）2012年上海市初中毕业统一学业考试- 8 -点A 在反比例函数12y x=的图象上，得123a a=， ·································（1分）解得12a =，22a =-， ··············································································（1分）经检验12a =，22a =-是原方程的根，但22a =-不符合题意，舍去． ·····（1分） ∴点A 的坐标为()26，． ·············································································（1分）（2）由题意，设点B 的坐标为()0m ，． ···················································（1分） 0m > ，()2262m m ∴=-+． ····························································（2分）解得103m =，经检验103m =是原方程的根，∴点B 的坐标为1003⎛⎫⎪⎝⎭，．····（1分）设一次函数的解析式为103y kx =+，··························································（1分）由于这个一次函数图象过点()26A ，，10623k ∴=+，得43k =．···············（1分）∴所求一次函数的解析式为41033y x =+． ·················································（1分）23．证明：（1）在梯形A B C D 中，A B D C =，B C ∴=∠∠．························（2分）G F G C = ，C G F C ∴=∠∠．······························································（1分）B G FC ∴=∠∠，A B G F ∴∥，即A E G F ∥． ······································（1分） A E G F = ，∴四边形A E F G 是平行四边形．··········································（2分）（2）过点G 作G H F C ⊥，垂足为H ．····················································（1分） G F G C =，12F G H F G C ∴=∠∠．·····················································（1分）2F G CE F B = ∠∠，F G H E F B ∴=∠∠． ···········································（1分）90FGH GFH +=∠∠，90EFB GFH ∴+=∠∠． ···························（1分） 90EFG ∴=∠． ·······················································································（1分）四边形A E F G 是平行四边形，∴四边形A E F G 是矩形． ························（1分） 24．解：（1）由题意，点B 的坐标为()02，， ························································（1分）2O B ∴=，tg 2OAB = ∠，即2O B O A=．1O A ∴=．∴点A 的坐标为()10，． ····························································（2分）又二次函数22y x m x =++的图象过点A ，2012m ∴=++．解得3m =-， ····························································································（1分） ∴所求二次函数的解析式为232y x x =-+． ·············································（1分）2012年上海市初中毕业统一学业考试- 9 -（2）由题意，可得点C 的坐标为()31，， ····················································（2分）所求二次函数解析式为231y x x =-+． ·····················································（1分）（3）由（2），经过平移后所得图象是原二次函数图象向下平移1个单位后所得的图象，那么对称轴直线32x =不变，且111BB D D ==． ···········································（1分）点P 在平移后所得二次函数图象上，设点P 的坐标为()231x x x -+，．在1PBB △和1PD D △中，112PBB PD D S S = △△，∴边1B B 上的高是边1D D 上的高的2倍．①当点P 在对称轴的右侧时，322x x ⎛⎫=-⎪⎝⎭，得3x =，∴点P 的坐标为()31，； ②当点P 在对称轴的左侧，同时在y 轴的右侧时，322x x ⎛⎫=- ⎪⎝⎭，得1x =， ∴点P 的坐标为()11-，； ③当点P 在y 轴的左侧时，0x <，又322x x ⎛⎫-=-⎪⎝⎭，得30x =>（舍去）， ∴所求点P 的坐标为()31，或()11-，． ························································（3分）25．（1）证明：2A P P B P B B O P O ==+= ，2A O P O ∴=．2A OP OP O B O∴==．·····················································································（2分）P O C O = ， ····························································································（1分） A O C O C OB O∴=．C O A B O C = ∠∠，C AO BC O ∴△∽△． ····················（1分）（2）解：设O P x =，则1OB x =-，O A x m =+，O P 是O A ，O B 的比例中项， ()()21x x x m ∴=-+， ·············································································（1分）得1m x m =-，即1m O P m =-． ··································································（1分）11O B m ∴=-．··························································································（1分）O P 是O A ，O B 的比例中项，即O A O P O PO B=，O P O C = ，O A O C O CO B∴=． ····································································（1分）设圆O 与线段A B 的延长线相交于点Q ，当点C 与点P ，点Q 不重合时，。

2012年上海市普通高中学业水平考试

2012年上海市普通高中学业水平考试化学试卷考生注意：1.试卷满分100分，考试时间90分钟。

2.本考试分设试卷和答题纸3.答题前，务必在答题纸上跳墙那些姓名、报名号、考场号和座位号，并将核对后的条形码贴在指定位置上。

作答必须涂或写在答题纸上，在试卷上作答一律不得分。

选择题的作答必须涂在答题纸上相应的区域，其余各大题的作答必须写在答题纸上与试卷题号对应的位置。

相对原子质量：H-1 O-16 Na-23 S-32 Cl-35.5 Cu-64 A．B．C．D．一、选择题（本题共40分，每小题2分，每小题只有一个正确答案）1．海水中含量最多的卤素是A．氟B．氯C．溴D．碘2．12C与14C互为A．同素异形体B．同分异构体C．同位素D．同系物3．某直链烷烃分子中有18个氢原子，它的分子式是A．C8H18B．C9H18C．C10H18D．C11H184．加入水能抑制水的电离的物质是A．碘化钾B．氯化钠C．硝酸钠D．硫酸5．NA表示阿伏伽德罗常数，1molNaOH固体含有A．2N A个阳离子B．10N A个电子个氢氧根离子D．2N个共价键C．N7．将盐酸逐滴加入到氨水中，发生反应的离子方程式正确的是A．OH—+H+→H2O B．H++NH3∙H2O→NH4++H2OC．HCl+OH—→Cl—+H2O D．HCl+NH3∙H2O→Cl—+NH4++H2O 8．红热的炭和水蒸气反应生成1mol氢气和1mol一氧化碳气体，吸收131.3KJ热量。

能表示该反应热化学方程式的是A．C+H2O→H2+CO—131.3KJB．C(s)+H2O(l)→H2(g)+CO(g)+131.3KJC．C(s)+H2O(g)→H2(g)+CO(g)+131.3KJD．C(s)+H2O(g)→H2(g)+CO(g)—131.3KJ9．下列反应中，二氧化碳既不是氧化剂又不是还原剂的是A．SO2 + NO2→SO3 + NO B．SO2 + 2NaOH→H2O + Na2SO3C．SO2 2MgO + S D．SO2 + Br2 + 2H2O→H2SO4 + 2HBrCH2—CH310．烷烃的命名是其他种类有机物命名的基础，CH2—CH2—CH2—CH—CH3的名称是3A．1-甲基-4-乙基戊烷B．2-乙基戊烷C．1,4二甲基己烷D．3-甲基庚烷11．常温下，0.1mol/LCH3COONa溶液中离子浓度最大的是A．OH—B．H+C．Na+D．CH3COO—12．与MgCl2晶体中所含化学键类型相同的物质是A．Na2S B．SiO2C．HCl D．NH4Cl13．密闭容器中反应CO(g)+H2O(g)CO2(g)+H2(g)+Q（Q>0）达到平衡，在其他条件不变的情况下，下列措施不能使正反应速率加快的是A．通入水蒸气B．缩小容器体积C．分离出CO2D．升高温度14．溶于水能使溶液温度降低的物质是A．浓硫酸B．氢氧化钠固体C．氯化钠固体D．氯化铵固体15．配置250mL 0.100mol/L的氯化钠溶液，操作不正确的是16．右图是电解饱和食盐水的装置，a、b为石墨电极。

2012年上海市初中毕业试卷

2012年上海市初中毕业统一学业考试数学3A(满分:150分时间:100分钟)第Ⅰ卷(选择题,共24分)一、选择题(本大题共6题,每题4分,满分24分)1.在下列代数式中,次数为3的单项式是( )A.xy 2B.x 3+y 3C.x 3yD.3xy 2.数据5,7,5,8,6,13,5的中位数是( ) A.5 B.6 C.7 D.8 3.不等式组- -的解集是( ) A.x>-3 B.x<-3 C.x>2 D.x<24.在下列各式中,二次根式 - 的有理化因式是( ) A. B. + C. - D. -5.在下列图形中,为中心对称图形的是( )A.等腰梯形B.平行四边形 C .正五边形 D.等腰三角形6.如果两圆的半径分别为6和2,圆心距为3,那么这两圆的位置关系是( ) A.外离 B.相切 C.相交 D.内含第Ⅱ卷(非选择题,共126分)二、填空题(本大题共12题,每题4分,满分48分)7.计算: - = . 8.因式分解:xy-x= .9.已知正比例函数y=kx(k≠0),点(2,-3)在函数图象上,则y随x的增大而(选填“增大”或“减小”).10.方程=2的根是.11.如果关于x的一元二次方程x2-6x+c=0(c是常数)没有实数根,那么c的取值范围是.12.将抛物线y=x2+x向下平移2个单位,所得新抛物线的解析式为.13.布袋中装有3个红球和6个白球,它们除颜色外其他都相同,如果从布袋里随机摸出一个球,那么所摸到的球恰好为红球的概率是.14.某校500名学生参加生命安全知识测试,测试分数均大于或等于60且小于100,分数段的频率分布情况如下表所示(其中每个分数段可包括最小值,不包括最大值),结合表格的信息,可得测试分数在80~90分数段的学生有名.15.如图,已知梯形ABCD,AD∥BC,BC=2AD,如果=a,=b,那么=(用a,b表示).16.在△ABC中,点D,E分别在AB,AC上,∠AED=∠B,如果AE=2,△ADE的面积为4,四边形BCED的面积为5,那么边AB的长为.17.我们把两个三角形的重心之间的距离叫做重心距,在同一平面内有两个边长相等的等边三角形,如果当它们的一边重合时重心距为2,那么当它们的一对角成对顶角时重心距为.18.如图所示,Rt△ABC中,∠C=90°,BC=1,∠A=30°,点D为边AC上的一动点,将△ADB沿直线BD翻折,点A落在点E处,如果DE⊥AD,那么DE=.三、解答题(本大题共7题,满分78分)19.(本题满分10分)计算:×(-1)2+-+--.20.(本题满分10分)解方程:+-=-.21.(本题满分10分,第(1)小题满分4分,第(2)小题满分6分)如图,在Rt△ABC中,∠ACB=90°,D是边AB的中点,BE⊥CD,垂足为E.已知AC=15,cos A=.(1)求线段CD的长;(2)求sin∠DBE的值.22.(本题满分10分,第(1)小题满分5分,第(2)小题满分5分)某工厂生产一种产品,当生产数量至少为10吨,但不超过50吨时,每吨的成本y(万元)与生产数量x(吨)的函数关系式如图所示.(1)求y与x的函数关系式,并写出其定义域;(2)当生产这种产品的总成本为280万元时,求该产品的生产数量.(注:总成本=每吨的成本×生产数量)3B23.(本题满分12分,第(1)小题满分5分,第(2)小题满分7分)如图所示,在菱形ABCD中,点E、F分别在边BC、CD上,∠BAF=∠DAE,AE与BD交于点G.(1)求证:BE=DF;(2)当=时,求证:四边形BEFG是平行四边形.24.(本题满分12分,第(1)小题满分3分,第(2)小题满分5分,第(3)小题满分4分)如图,在平面直角坐标系中,二次函数y=ax2+6x+c过点A(4,0)和B(-1,0),并与y轴交于点C,点D在线段OC上,设DO=t,点E在第二象限,∠ADE=90°,tan∠DAE=,EF⊥OD于F.(1)求二次函数的解析式;(2)用含t的代数式表示EF和OF的长;(3)当∠ECA=∠CAO时,求t的值.25.(本题满分14分,第(1)小题满分3分,第(2)小题满分5分,第(3)小题满分6分)已知扇形AOB中,∠AOB=90°,OA=OB=2,C为上的动点,且不与A、B重合,OE⊥AC于E,OD⊥BC于D.(1)若BC=1,求OD的长;(2)在△DOE中,是否存在长度保持不变的边?若存在,求出该边的长;若不存在,请说明理由;(3)设BD=x,△DOE的面积为y,求y与x的函数关系式及定义域.2012年上海市初中毕业统一学业考试一、选择题1.A根据单项式定义,可知选项A、C、D中的代数式均为单项式,又由单项式的次数定义可知次数为3的单项式是xy2,故选A.评析本题主要考查了单项式和单项式次数的定义,属于容易题.正确理解两个概念是解决此类问题的关键,易混易错之处是当计算单项式的次数时,常常忽略指数是1的字母,导致确定单项式的次数有误.2.B根据中位数的定义,先把该组数据排序,若有奇数个,则中位数是中间的那个数;若有偶数个,则中位数是中间两个数的平均数.显然在给出的7个数据中,排序后最中间的数据是6,故选B.3.C解不等式-2x<6得x>-3,解不等式x-2>0得x>2,∴不等式组-的解集为x>2.故选C.-4.C根据有理化因式的定义,只要二次根式-乘一个适当的因式,能将其转化为有理式即可.而-·-=a-b,故选C.评析本题主要考查有理化因式的概念,有理化因式的形式分为两种:①的有理化因式是;②±的有理化因式是∓,属简单题.5.B因为绕一个点旋转180度后能与自身重合的图形是中心对称图形,所以选项中的四种图形,只有平行四边形是中心对称图形,故选B.6.D设R=6,r=2,d=3,则R-r=6-2=4>3,即R-r>d,所以两圆内含.故选D.二、填空题7.答案解析根据有理数的运算法则和绝对值的意义,得-=-=.8.答案x(y-1)解析本题运用提取公因式法进行因式分解,所以xy-x=x(y-1).9.答案减小解析∵点(2,-3)在函数图象上,∴把(2,-3)代入y=kx(k≠0)中,得-3=2k,解得k=-,显然k<0,故y 随x的增大而减小.评析本题综合考查了待定系数法求函数的解析式、正比例函数的性质等知识点.熟练掌握正比例函数的性质是解题关键,属容易题.10.答案x=3解析可以把无理方程转化成算术平方根,2是x+1的算术平方根,则x+1=4,易得x=3. 11.答案c>9解析由题意得Δ=b2-4ac<0,即(-6)2-4×1×c<0,解得c>9..12.答案y=x2+x-2解析因为二次函数的图象平移时遵循“上加下减,左加右减”的规律,所以向下平移2个单位后,所得抛物线的解析式是y=x2+x-2.13.答案解析P(恰好为红球)=红球的个数==.白球的个数红球的个数14.答案150解析根据频数、频率分布的知识可知,所有的频数之和等于总数,所有频率之和等于1,则得分数在80~90分数段分数在80~90分数段的学生的频率为1-0.2-0.25-0.25=0.3,由频率=频数总数的学生有0.3×500=150(名).15.答案2a+b解析利用向量的加法法则易知=+=2a+b.16.答案3解析∵∠AED=∠B,∠A是公共角,∴△ADE∽△ACB,∴S △ADE∶S△ACB=AE2∶AB2,即4∶9=22∶AB2,∴AB=3..17.答案4解析如图1和图2所示,等边三角形的重心是它三条中线的交点,交点分每一条中线得到的两条线段的比值(短∶长)为1∶2,当两个等边三角形一边重合时,重心距是两条短线段之和,所以每条短线段的长度为1,长线段的长度为2.因此当两个等边三角形的一对角成对顶角时,重心距为2+2=4.评析本题主要考查了等边三角形的重心及其性质,属中等难度题.18.答案-1解析如图,由翻折的性质可知AD=DE,∠ADP=∠EDP.又由AD⊥ED 得,∠ADP=∠EDP=45°,所以∠BDC=45°,因为∠C=90°,所以BC=CD=1,又因为∠A=30°,BC=1,所以AB=2,AC=,所以DE=AD=-1.评析本题涉及的知识点有对折、等腰直角三角形、垂直、解直角三角形,有一定区分度,属中等难度题.三、解答题19.解析原式=×(4-2)++1+-(8分)=2-++1+-=3.(10分)评析本题主要考查了实数的混合运算、分数指数、负指数以及分母有理化、完全平方公式等,均是中考常考的基础知识,但是学生容易马虎丢分,属中等难度题.20.解析去分母,得x(x-3)+6=x+3,(3分)整理,得x2-4x+3=0,(5分)解得x1=1,x2=3.(9分)经检验,x=3是增根,x=1是原方程的根.所以原方程的根是x=1.(10分)21.解析(1)在Rt△ABC中,∠ACB=90°,AC=15,cos A==,(1分)∴AB=25.(2分)∵D是AB的中点,∴CD==.(4分)(2)在Rt△ABC中,BC=-=20.(5分)∵BD=CD==,∴∠DCB=∠DBC.(6分)∴cos∠DCB=cos∠ABC==.(7分)在Rt△CEB中,∠E=90°,CE=BC·cos∠BCE=16.(8分)∴DE=CE-CD=.(9分)在Rt△DEB中,∠DEB=90°,∴sin∠DBE==.(10分)22.解析(1)设函数解析式为y=kx+b,(1分)得(2分)解得-(3分)∴y与x的函数关系式为y=-x+11,(4分)定义域是10≤x≤50.(5分)(2)由题意,得xy=280,(6分)即x-=280,(7分)整理,得x2-110x+2800=0,(8分)解得x1=40,x2=70.(9分)x=70不合题意,舍去.答:该产品的生产数量为40吨.(10分)评析本题主要考查了利用函数图象获取信息、建立函数模型、确定函数解析式和定义域.属中等难度题.23.证明(1)∵∠BAF=∠DAE,∴∠BAE+∠EAF=∠DAF+∠EAF,∴∠BAE=∠DAF.(1分)∵四边形ABCD是菱形,∴AB=AD,∠ABE=∠ADF.(3分)∴△ABE≌△ADF,(4分)∴BE=DF.(5分)(2)∵=,DF=BE,∴=.(6分)∵AD∥BC,∴=,(7分)∴=,(8分)∴GF∥BC.(9分)∵BE=DF,BC=DC,∴=,(10分)∴EF∥BD.(11分)∴四边形BEFG是平行四边形.(12分)24.解析(1)由二次函数y=ax2+6x+c过点A(4,0)、B(-1,0),(1分)得-解得-(2分)∴二次函数的解析式为y=-2x2+6x+8.(3分)(2)∵点D在线段OC上,点E在第二象限,∠ADE=90°,EF⊥OD,∴∠EDF+∠ADO=∠DAO+∠ADO=90°,∴∠EDF=∠DAO,∴Rt△DFE∽Rt△AOD,(4分)∴==.(5分)在Rt△ADE中,∠ADE=90°,tan∠DAE==,∴==,∴EF=DO,DF=AO.(6分)∵DO=t,∴EF=,(7分)∵点A的坐标为(4,0),∴AO=4,DF=2,∴OF=t-2.(8分)(3)由(1)得,点C的坐标为(0,8).延长CE交x轴于点G,设点G的坐标为(x,0).∵∠ECA=∠CAO,∴CG=AG,(9分)∴=-,解得x=-6,∴GO=6.(10分)由已知,可得点F在线段OD上,又∵OF=t-2,∴FC=OC-OF=10-t.(11分)∵EF∥GO,∴=,∴=-,解得t=6.(12分)评析本题主要考查了二次函数解析式的确定、相似三角形的判定与性质、三角函数、勾股定理等知识的综合应用.本题共有3个小题,第(1)小题较易,第(2)小题难度适中,把相似三角形和三角函数结合起来求解较为简便,第(3)小题偏难,利用勾股定理列方程是解题关键.25.解析(1)在扇形AOB中,∵OD⊥BC,∴BD=BC.(1分)∵BC=1,∴BD=.(2分)∵OB=2,∴OD=-=.(3分)(2)存在,边DE的长度保持不变.(4分)连结AB,∵∠AOB=90°,OA=OB=2,∴AB==2.(5分)∵OD⊥BC,OE⊥AC,∴CD=BD,CE=AE,(7分)∴DE=AB=.(8分)(3)连结OC,∵点C在上,∴OC=OB.∵OD⊥BC,∴∠COD=∠BOC,同理,∠COE=∠AOC,(9分)∴∠DOE=∠BOC+∠AOC=∠AOB,∵∠AOB=90°,∴∠DOE=45°.(10分)过点D作DH⊥OE,垂足为H.在Rt△OBD中,OD=-=-.在Rt△ODH中,∠DOH=45°,OH=DH=OD·sin45°=-.(11分)在Rt△DEH中,HE=-=x.(12分)∴OE=OH+HE=-+x.∵S△DOE=OE·DH,∴函数解析式为y=--,(13分)定义域为0<x<.(14分)评析本题是几何与代数综合的压轴题,综合考查了垂径定理、勾股定理、三角形的中位线的性质、等腰直角三角形的性质以及利用三角形面积进行函数建模,综合性比较强,尤其是第(2)问存在性问题设计得比较巧妙.。

产品质量检验工考技师无纸化试题及答案2

A．财务管理 B．物流管理
C．生产计划与控制管理 D．人力资源管理
正确答案:C 您的答案:
46 、
数据库系统的核心组成部分是（）。
A数据库 B数据库系统 C数据库管理系统 D数据库技术
A.不登记 B. 登记备案 C. 不备案 D.上报国家技术监督局
正确答案:B 您的答案:
49 、
按照随机抽样的原则，从总体中抽取部分个体组成样本，根据对样品进行检测的结果，推断总体质量水平的方法称为（）。
A、随机抽样检验 B、简单随机抽样 C、整群抽样 D、等距抽样
27 、轧制时，带钢出现双边浪，这时应加大负弯。
正确答案:× 您的答案:
28 、 SPCCT-S D中T代表保证拉伸试验值，后边S代表标准调质，D表示毛面加工。
正确答案:√ 您的答案:
29 、国际标准中低合金高强度钢牌号为E355—E690。
正确答案:√ 您的答案:
20 、 D1100001X表示2012年一钢轧厂1#转炉第10001炉回精炼炉钢水在小方坯连铸机浇铸的连铸方坯。
正确答案:× 您的答案:
21 、仓库废品、丢失品、返修品管理制度规定：车间的退修品，需经质保部门鉴定后，方可由责任单位退回库房，库房进行登记，待处理。库房要对退修品设立专门存放区，以防同合格产品混淆。
C是否具有爱岗敬业的职业道德只与服务行业有关 D市场经济条件下不要求爱岗敬业
正确答案:B 您的答案:
42 、
( )表示轧制一吨合格钢材需要的原料吨数。
A.金属消耗系数 B.金属平衡表 C.合格率 D．钢材理论重量系数
正确答案:A 您的答案:
正确答案:√ 您的答案:

2012年全国普通高等学校招生统一考试上海物理试卷 (WORD版,含答案)-推荐下载

物理 2012 第 2 页（共 7 页）
对全部高中资料试卷电气设备，在安装过程中以及安装结束后进行高中资料试卷调整试验；通电检查所有设备高中资料电试力卷保相护互装作置用调与试相技互术通关，1系电过，力管根保线据护敷生高设产中技工资术艺料0不高试仅中卷可资配以料置解试技决卷术吊要是顶求指层，机配对组置电在不气进规设行范备继高进电中行保资空护料载高试与中卷带资问负料题荷试2下卷2，高总而中体且资配可料置保试时障卷，各调需类控要管试在路验最习；大题对限到设度位备内。进来在行确管调保路整机敷使组设其高过在中程正资1常料中工试，况卷要下安加与全强过，看度并22工且22作尽22下可22都能22可地护以缩1关正小于常故管工障路作高高；中中对资资于料料继试试电卷卷保破连护坏接进范管行围口整，处核或理对者高定对中值某资，些料审异试核常卷与高弯校中扁对资度图料固纸试定，卷盒编工位写况置复进.杂行保设自护备动层与处防装理腐置，跨高尤接中其地资要线料避弯试免曲卷错半调误径试高标方中高案资等，料，编试要5写、卷求重电保技要气护术设设装交备备置底4高调、动。中试电作管资高气，线料中课并敷3试资件且、设卷料中拒管技试试调绝路术验卷试动敷中方技作设包案术，技含以来术线及避槽系免、统不管启必架动要等方高多案中项；资方对料式整试，套卷为启突解动然决过停高程机中中。语高因文中此电资，气料电课试力件卷高中电中管气资壁设料薄备试、进卷接行保口调护不试装严工置等作调问并试题且技，进术合行，理过要利关求用运电管行力线高保敷中护设资装技料置术试做。卷到线技准缆术确敷指灵设导活原。。则对对：于于在调差分试动线过保盒程护处中装，高置当中高不资中同料资电试料压卷试回技卷路术调交问试叉题技时，术，作是应为指采调发用试电金人机属员一隔，变板需压进要器行在组隔事在开前发处掌生理握内；图部同纸故一资障线料时槽、，内设需，备要强制进电造行回厂外路家部须出电同具源时高高切中中断资资习料料题试试电卷卷源试切，验除线报从缆告而敷与采设相用完关高毕技中，术资要资料进料试行，卷检并主查且要和了保检解护测现装处场置理设。备高中资料试卷布置情况与有关高中资料试卷电气系统接线等情况，然后根据规范与规程规定，制定设备调试高中资料试卷方案。

中级产品质量检验工无纸化试题及答案

正确答案:C 您的答案:
54 、
钢中元素氮的元素符号是( )。
A.P B.S C.N D.Si
正确答案:C 您的答案:
55 、
企标规定热轧酸洗钢带的尺寸、外形应符合( )标准的规定。
A.GB/T 708 B.Q/TB204 C.GB/T12754 D.GB/T709
49 、
.对于型钢轧机，其规格用（）表示。
A. 轧辊辊身长度 B. 轧辊工作直径 C. 轧辊名义直径 D.轧辊原始直径
正确答案:C 您的答案:
50 、
角度尺的读数机构是根据游标原理制成的。主尺刻线每格为1°。游标的刻线是取主尺的29°等分为30格，因此游标刻线角格为29°/30，即主尺与游标一格的差值为（）,也就是说其读数准确度为（），其读数方法与游标卡尺完全相同。
C.拉伸矫直机 D.拉伸弯曲矫直机
正确答案:A 您的答案:
43 、
检验工必备的专业素质是（）。
A语言表达能力 B社交能力 C 较强的颜色分辨能力 D 良好的嗅觉辨味能力
正确答案:C 您的答案:
正确答案:× 您的答案:
12 、产品（材料）验收管理制度规定：产成品的入库要严格按《产品（材料）跟踪追溯管理办法》执行，以合格单和过程标识卡为凭证，无合格单和过程标识卡的产品严禁入库。
正确答案:√ 您的答案:
13 、 Word打印纸张设置用的命令是页面设置。
48 、
钢材的产品质量证明书包括以下内容：公司名称、产品名称、牌号、规格、质量记录编号、生产许可证号、车号、合同编号、签发日期等，有( )，并加盖质量专用章。
A. 公司经理签字 B.厂长名字 C.签证人签字 D. 公司经理名字

会计试题

2012年会计从业资格无纸化考试系统《会计基础》试卷一一、单选题（下列各小题备选答案中，只有一个符号题意的正确答案。

本类型题共20分，每小题1分。

多选、错选、不选均不得分）1、某记账人员将记账凭证贷记应付账款的金额36000元，记账时错记为3600元。

下列各种更正方法中，适用于此情况的是( A )。

A、划线更正法B、红字冲销法C、补充登记法D、消除字迹法2、下列各项中，适用于出纳所登的库存现金账的类型是（C ）A、备查账簿B、卡片式账簿C、序时账簿D、分类账簿3、下列各项中，不应计入营业成本的是（ B ）A、商品销售成本B、计提应收账款坏账准备C、出租包装物的成本D、原材料销售成本4、汇总付款凭证应按（ A ）定期进行归类汇总。

A、现金和银行存款科目B、借方科目C、贷方科目D、总分类科目5、“应收账款”科目所属明细科目如有贷方余额，应在资产负债表中反映的项目是（ C ）A、预付账款B、应收账款C、预收账款D、应付账款6、下列关于会计档案移交清册保管期限的表述中，正确的是（ D ）A、10年B、5年C、20年D、15年7、会计档案保管期限的始算日期，应从（ C ）算起。

A、本年会计年度末B、会计年度终了的当天C、会计年度终了后的第一天D、会计档案归档的当天8、在以下的会计假设中，哪项是规定了会计工作的空间范围（ A ）A、会计主体假设B、持续经营假设C、会计分期假设D、货币计量假设9、明确企业产权关系的重要标志是（ B ）A、投资B、资本C、借款额D、利润10、科目汇总表的汇总方法是（ C ）。

A、把所有账户的借方发生额分别汇总B、把所有账户的贷方发生额分别汇总C、汇总各个账户的借、贷方发生额D、汇总各个账户的借、贷方余额11、下列属于静态报表的是（B ）A、利润表B、资产负债表C、现金流量表D、所有者权益变动表12、由于管理不善导致存货的盘亏一般应作为（ B ）处理。

A、营业外支出B、管理费用C、财务费用D、其他应收款13、某企业出售产品一批，售价15000元，收到一张转账支票。

产品质量检验工考技师无纸化试题及答案3

在ERP系统的主要功能中，（）是ERP系统的核心所在，它将企业的整个生产过程有机地结合在一起，使得企业能够有效地降低库存，提高效率。
A．财务管理 B．物流管理
C．生产计划与控制管理 D．人力资源管理
正确答案:C 您的答案:
正确答案:× 您的答案:
41 、
检验工进入现场“两穿一戴” 着装整洁，符合规定。一戴指戴好（）
A手套 B围巾 C 安全帽 D发卡
正确答案:C 您的答案:
42 、
某轧钢厂2012年三月份产量为19600t，检验量为19640t，中间甩废为60t，投料20500t，该厂三月份的成材率完成( )。
15 、 6S现场要求“一畅”场地平整、通道畅通。
正确答案:√ 您的答案:
16 、在ERP系统中，钢材质量检验工需要录入钢的化学成分等。
正确答案:× 您的答案:
17 、在培训时要求师傅负责指导和解答技术上的有关问题，及时发现和纠正存在的问题。
无纸化考试体验标答对照
共计 100 道题 (注:标记红色的题目为您答错的题目。)
1 、质量检验工作人员应坚持持证上岗制度，以保证检验工作的质量。（）
正确答案:√ 您的答案:
2 、带钢热镀锌的主要目的是防腐。
正确答案:√ 您的答案:
3 、内部质量保证是指向顾客或第三方认证机构提供信任。
正确答案:× 您的答案:
4 、线材成品头尾均需要切掉几圈的目的是切去尺寸超差部分。
正确答案:√ 您的答案:
5 、次品材外发需出具质量保证书。
A、随机抽样检验 B、简单随机抽样 C、整群抽样 D、等距抽样
正确答案:A 您的答案:

2012年全国普通高等学校招生统一考试上海卷

2012年全国普通高等学校招生统一考试上海英语试卷考生注意：1．考试时间120分钟，试卷满分150分。

2．本考试设试卷和答题纸两部分。

试卷分为第1卷（第1-12页）和第II卷（第13页），全卷共13页。

所有答题必须涂（选择题）或写（非选择题）在答题纸上，做在试卷上一律不得分。

3．答题前，务必在答题纸上填写准考证号和姓名，并将核对后的条形码贴在指定位置上。

第1卷（共105分）I . Listening ComprehensionSection ADirections：In Section A, you will hear ten short conversations between two speakers. At the end of each conversation, a question will be asked about what was said. The conversations and the questions will be spoken only once. After you hear a conversation and the question about it, read the four possible answers on your paper, and decide which one is the best answer to the question you have heard.1. A. At a library. B. At a hotel. C. At a bank. D. At an airport.2. A. Relaxed. B. Annoyed. C. Worried. D. Satisfied3. A. Doctor and patient. B. Shop owner and customer.C. Secretary and boss.D. Receptionist and guest.4. A. He would have thrown $300 around. B. $300 is not enough for the concert.C. Sandy shouldn't have given that much.D. Dave must be mad with the money5. A. She lives close to the man. B. She changes her mind at last.C. She will turn to her manager.D. She declines the man's offer.6．A.2 B.3． C.4．D．57. A. Both of them drink too much coffee.B. The woman doesn't Like coffee at all.C. They help each other stop drinking coffee.D. The man is uninterested in the woman's story8. A. He doesn't. mind helping the woman.B. He hesitates whether to help or not.C. He'll help if the woman doesn't mindD. He can't help move the cupboard.9. A. He's planning to find a new job.B. He prefers to keep his house in a mess.C. He's too busy to clean his houseD. He has already cleaned his new house,10. A. She doesn't agree with the man.B. She is good at fmding a place to stay.C. She could hardly find the truth.D. She had no travel expei/ence in Britain.Section BDirections: In Section B, you will hear two short passages, and you will be asked three questions on each of the passages. The passages will be read twice, but the questions will be spoken only once. When you hear a question, read the four possible answers on your paper and decide which one would be the best answer to the question you have heard.Questions 11 through 13 are based on the following passage11. A. Use the company's equipment. B. Give orders to robotsC. Make decisions for the company.D. Act as Big Brother.12. A. Employees gain full freedom. B. Employees suspect one another.C. Employees' children are happy.D. Employees enjoy working there.13. A. Reward. B. Safety. C. Trust. D. HonestyQuestions 14 through 16 are based on the following passage14. A. Canada had a smaller population. B. Land was cheaper in Canada.C. They wanted to continue the Revolution.D. They were against Britain.15. A. They standardized Canadian English.B. They settled there after the Revolution.C. They enjoy a very high social position.D. They make up a small part of the population16. A. It is considered unique to some extent. B. It is greatly influenced by French.C. It is mainly linked to British culture.D. It dates back to the late 17th century.Section CDirections: In Section C, you will hear two longer conversations. The conversations will be read twice. After you hear each conversation, you are required to fill in the numbered blanks with the information you have heard. Write your answers on your answer sheet.Blanks 17 through 20 are based on the following conversation.Complete the form. Write ONE WORD for each answer.Blanks 21 through 24 are based on the following conversation.Complete the form. Write NO MORE THAN THREE WORDS for each answer.II. Grammar and VocabularySection ADirections: Beneath each of the following sentences there are four choices marked A, B, C and D. Choose the one answer that best completes the sentence.25. passion, people won't have the motivation or the joy necessary for creative thinking.A.For .B.WithoutC.BeneathD.By26. Is honesty the best policy? We _ that it is when we are little.A. will teachB. teachC. are taughtD. will be taught27. As Jack left his membership card at home, he wasn't allowedinto the sports club.A. goingB. to goC. goD. gone28. The new law states that people _ drive after drinking alcohol.A. wouldn'tB. needn'tC. won'tD. mustn't29. Only with the greatest ofluck_ to escape from the rising flood waters.A. managed sheB. she managedC. did she manageD. she did manage30. - I hear that Jason is planning to buy a car.-I know. By next month, he _ enough for a used one.A. will have savedB. will be savingC. has savedD. saves31. When he took his gloves off, I noticed thatone had his name written inside.A. eachB. everyC. otherD. another32. I have a tight budget for the trip, so I'm not going to fly _ the airlines lower ticket prices.A. onceB.ifC. afterD. unless33. When Peter speaks in public, he always has trouble _ the right things to say.A. thinking ofB. to think ofC. thought ofD. think of .34. There is much truth in the idea _ kindness is usually served by frankness.A. whyB. whichC. thatD. whether35. Have you sent thank-you notes to the relatives from _ _ you received gifts?A. whichB. themC.thatD. whom36. The club, _ _ 25 years ago, is holding a party for past and present members.A. foundedB. foundingC. being foundedD. to be founded37. - Was it by cutting down staff _ _she saved the firm?- No, it was by improving work efficiency.A.whenB.whatC.howD.that38. - We've only got this small bookcase. Will that do?- No, _ _ I am lookin g for is something much bigger and stronger.A. whoB. thatC. whatD. which39. "Genius" is a complicated concept, _ _ many different fac tors.A.involvedB.involving ,C.toinvolveD.beinginvolved40. The map is one of the best tools a man has _ _ he goes to a new place.A. wheneverB. whateverC. whereverD. howeverSection BDirections:Complete the following passage by using the words in the box. Each word can only be used once. Note that there is one word more than you need.A. maintainedB. seriousC. indicationsD. figuresE. anxiousF. concern G crisis H. decided I. available J. reversedFilmgoers should be told how many calories there are in the popcorn, ice cream and soft drinks that they buy in cinemas, according to the Food Standard Agency.Smaller popcorn buckets and drink cups should also be made 41 , the nutrition inspector said.Tim Smith, chief executive of the agency, told The 77mes that cinemas should help to deal with the country's overweight 42 ."There is a misbelief that popcorn is calorie-free, but that is not the case. It is a 43 to us," he said. "Portion sizes are also a big issue, and there seems to be increasingly big packs on sale."He spoke as a number of food chains such as Pret A Manger, Wimpey and The Real Greek44 to put calorie counts on all their menus.A trial scheme（试行方案）with 21 food companies took place last summer, and 45 are that consumers altered their buying habits when they realised the number of calories in a product.A consultation(征询意见) on the trial ends next month but Mr Smith is already planning the second drive for American-style calorie counts and is 46 to win support from cinemas and other entertainment places, from football grounds to concert halls.Government 47 suggest that two thirds of adults and a third of children are overweight. If trends are not 48 , this could rise to almost nine in ten adults and two thirds of children by 2050, putting them at 49 risk of heart disease, cancer and other diseases.III. Reading ComprehensionSection ADirections: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fillin each blank with the word or phrase that best fits the context.People on a college campus were more likely to give money to the March of Dimes if they were asked for a donation by a disabled woman in a wheelchair than if asked by a nondisabled woman. In another 50 , subway riders in New York saw a man carrying a stick stumble （绊脚）and fall to the floor. Sometimes the victim had a large red birthmark on his 51 ;sometimes he did not. In this situation, the victim was more likely t0 52 aid if his face was spotless than if he had an unattractive birthmark. In 53 these and other research findings,two themes are 54 : we are more willing to help people we like for some reason and people we think _ 55 _ assistance.In some situations, those who are physically attractive are more likely to receive aid. 56 , in a field study researchers placed a completed application to graduate school in a telephone box at the airport. The application was ready to be 57 , but had apparently been "lost" . The photo attached to the application was sometimes that of a very 58 person and sometimes that of a less attractive person.The measure of helping was whether the individual who found the envelope actually mailed it or not. Results showed that people were more likely to 59 the application if the person in the photo was physically attractive.The degree of _ 60 between the potential helper and the person in need is also important.For example, people are more likely to help a stranger who is from the same country rather than a foreigner. In one study, shoppers on a busy street in Scotland were more likely to help a person wearing a(n) 61 T-shirt than a person wearing a T-shirt printed with offensive words.Whether a person receives help depends in part on the "worth" of the case. For example,shoppers in a supermarket were more likely to give someone . 62 _ to buy milk rather than to buy cookies, probably because milk is thought more essential for 63 than cookies.Passengers on a New York subway were more likely to help a man who fell to the ground if he appeared to be 64 rather than drunk.50. A.studyB.wayC.wordD.college51. A. hand B. arm C. face D. back52. A.refuseB.begC.loseD.receive53. A. challenging B. recording C. understanding D. publishing54. A.important B. possible C. amusing D. missing55. A.seekB.deserveC.obtainD.accept56. A. At first B. Above al l C. In addition D. For example57. A.printedB.mailedC.rewrittenD.signed58. A. talented B. good-looking C. helpful D. hard-working59. A. send in B. throw away C. fill out D. turn down60. A. similarity B. friendship C. cooperation D. contact61. A.expensiveB.plainC.cheapD.strange62. A.timeB.instructionsC.moneyD.chances63. A. shoppers B. research C. children D. health64. A. talkative B. handsome C. calm D. sickSection BDirections: Read the following three passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D.Choose the one that fits best according to the information given in the passage you have just read.(A)Phil White has just returned from an 18,OOO-mile, around-the-world bicycle trip. White hadtwo reasons for making this epic journey. First of all, he wanted to use the trip to raise money for charity, which he did. He raised ~70,000 for the British charity, Oxfam. White's second reason for making the trip was to break the world record and become the fastest person to cycle around the world. He is still waiting to find out if he has broken the record or not.White set off from Trafalgar Square, in London, on 19th June 2004 and was back 299 days later. He spent more than l,300 hours in the saddle（车座）and destroyed four sets of tyres and three bike chains. He had the adv enture of his life crossing Europe, the Middle East, India, Asia, Australia, New Zealand and the Americas. Amazingly, he did all of this with absolutely no support team. No jeep carrying food, water and medicine. No doctor. Nothing! Just a bike and a very, very long road.The journey was lonely and desperate at times. He also had to fight his way across deserts, through jungles and over mountains. He cycled through heavy rains and temperatures of up t0 45 degrees, all to help people in need. There were other dangers along the road. In Iran, he was chased by armed robbers and was lucky to escape with his life and the little money he had. The worst thing that happened to him was having to cycle into a headwind on a road that crosses the south of Australia. For l,000kilometres he battled against the wind that was constantly pushing him. This part of the trip was slow, hard work and depressing, but he made it in the end. Now Mr.White is back and intends to write a book about his adventures.65. When Phil White returned from his trip, he _.A. broke the world recordB. collected money for OxfamC. destroyed several bikesD. travelled about l,300 hours66. What does the word "epic" in Paragraph l most probably mean?A. Very slow but exciting.B. Very long and difficult.C. Very smooth but tiring.D. Very lonely and depressing.67. During his journey around the world, Phil White _ .A. fought heroically against robbers in IranB. experienced the extremes of heat and coldC. managed to ride against the wind in AustraliaD. had a team of people who travelled with him68. Which of the following words can best describe Phil White?A. Imaginative.B. Patriotic.C. Modest.D. Determined.(B)The value-packed, all-inclusivesight-seeing package thatcombines the best of Sydney'sharbour, city, bay and beachhighlights.A SydneyPass gives you unlimited and flexible travel on the Explorer Buses: the 'red' Sydney Explorer shows you around our exciting city sights wlrile the 'blue' Bondi Explorer visits Sydney Harbour bays and famous beaches. Take to the water on one of three magnificent daily harbour cru/ses(游船). You can also travel free on regular Sydney Buses,Sydney Ferries or CityRail services (limited area), so you can go to every corner of this beautiful city.Imagine browsing at Darling Harbour, sampling the famous seafood at Watsons Bay or enjoying the city lights on an evening ferry cruise. The possibilities and plans are endless with a SydneyPass. Wherever you decide to go, remember that bookings are not required on any of our services so tickets are treated on a first in, first seated basis.SydneyPasses are avai-lable for 3, 5 0r 7 days for use over a 7 calendar day period. With a 3 or 5 day pass you choose on which days out of the 7 you want to use it. All SydneyPasses include a free Airport Express inward trip before starting your 3, 5 0r 7 da ys, and Lhe return trip is valid (育效的) for 2 months from the first day your ticket was used.SydneyPass Fares*A child is defined as anyone from the ages of 4 years to under ~6 yers. Children under 4 years travel free.**A family is defined as 2 adults and any number of children from 4 to under 16 years of age from the same family.69. A SydneyPass doesn7t offer unlimited rides onA. the Explorer BusesB. the harbour cruisesC. regular Sydney BusesD. CityRail services70. With a SydneyPass, a traveller can_.A. save fares from and to the airportB. take the Sydney Explorer to beachesC. enjoy the famous seafood for freeD. reserve seats easily in a restaurant71. If 5-day tickets were to be recommended to a mother who travelled with her colleague andher children, aged 3, 6 and 10, what would the lowest cost be?A. $225.B. $300.C. $360.D. $420.(C)Researchers in the psychology department at the University of California at Los Angeles (UCLA) have discovered a major difference in the way men and women respond to stress. This difference may explain why men are more likely to suffer from stress-related disorders.Until now, psychological research has maintained that both men and women have the same "fight-or-flight" reaction to stress. In other words, individuals eicher react with aggressive behavior, such as verbal or physical conflict ("fight"), or they react by withdrawing from the stressful situation ("flight"). However, the UCLA research team found that men and women have quite different biological and behavioral responses to stress. While men often react to stress in the fight-or-flight response, women often have another kind of reaction which could be called "tend and befriend." That is, they often react to stressful conditions by protecting and nurturing theiryoung ("tend"), and by looking for social contact and support from others - especially other females《'befriend").Scientists have long known that in the fight-or- flight reaction to stress, an important role is played by certain hormones(澈素) released by the body. The UCLA research team suggests that the female tend-or-befriend response is also based on a hormone. This hormone, called oxytocin,has been studied in the context of cFuldbirt.h, but now it is being studied for its role in the response of both men and women to stress. The principal investigator, Dr. Shelley E. Taylor,explained that "animals and people with high levels of oxytocin are calmer, more relaxed, more social, and less anxious." While men also secrete【分泌）oxytocin, its effects are reduced by male hormones.In terms of everyday behavior, the UCLA study found that women are far. more likely than men to seek social contact when they are feeling stressed. They may phone relatives or friends, or ask directions if they are lost.The study also showed how fathers and mothers responded differently when they came home to their family after a stressful day at work. The typical father wanted to be left alone to enjoy some peace and quiet. For a typical mother, coping with a bad day at work meant focusing her attention on her children and their needs.The differences in responding to stress may explain the fact that women have lower fr equency of stress-related disorders such as high blood pressure or aggressive behavior. The tend-and-befriend regulatory(调节的) system may protect women against stress, and this may explain why women on average live longer than men.72. The UCLA study shows that in response to stress, men are more likely than women to .A. turn to friends for helpB. solve a conflict calmlyC. find an escape from realityD. seek comfort from children73. Which of the following is true about oxytocin according to the passage?A. Men have the same level of oxytocin as women do.B. Oxytocin used to be studied in both men and women.C. Both animals and people have high levels of oxytocin.D. Oxytocin has more of an effect on women than on men.74. What can be learned from the passage?A. Male hormones help build up the body's resistance to stress.B. In a family a mother cares more about children than a father does.C. Biological differences lead to different behavioral responses to stress.D. The UCLA study was designed to confirm previous research findings.75. Which of the following might be the best ti.tle of the passage?A. How men and women get over stressB. How men and women suffer from stressC. How researchers overcome stress problemsD. How researchers handle stress-related disordersSection CDirections: Read the following text and choose the most suitable heading from A-F for each paragraph. There is one extra heading which you do not need.A. When a child should learn to readB. Why it is fun to teach a child readingC. What if a child has reading problemsD. How you prepare a young child for readingE. What is the best way to teach a child readingF. Whether reading early promises later achievements76.Learning to read early has become one of those indicators - in parents' minds at least – that their child is smart. In fact, reading early has very little to do with whether a child is successful academically. Research has shown that difficulty with reading is often due not to inferior intelligence but to differences in the developmental wiring of each individual child. In some cases, there are neurological problems and developmental lags that can be overcome with proper training.77.Traditionally, American schools teach children at age six, but many schools begin teaching informally in kindergarten and pre-kindergarten. If parents start too early to encourage reading,and a child does not immediately succeed, the parent has a hard time relaxing and letting the child go at his or her own pace.78.Over the years, research has proved that the use of both the e&whole language" method and the "phonic" method works best for a child to master reading. While the whole language approach, which includes reading to children and getting them interested in both the activity of reading and the story they are reading, is helpful, phonics must be taught. Children must be taught that one of the squiggles they see is a "p" and another a "b". Getting the print off the page requires a different ability than being able to understand the meaning of what is written.79.You can start developing the skills needed in reading at a very young age without putting any pressure on children. Besides reading to them, parents can start "ear training" their child by playing thyme games. This develops the child's ability to recognize different sounds. In reading to children, parents also can point to words as they go, teaching the child that the funny lines on the page are the words you are saying. All this should be a fun activity.80.Once a child is in school, the learning of reading is inevitably more serious. For children who have some kind of reading difficulty, you must get a professional diagnosis. While the teacher might say the child is merely disinterested but will get over it, disinterest or poor performance in reading can stem from a number of things, some being very specific learning disabilities that can be identified and worked on. But it is very tricky for parents to deal with their own child's learning disabilities.Section DDirections: Read the passage carefully. Then answer the questions or complete the statements in the fewest possible words.While contact between adolescents (between the ages of fifteen and nineteen) and their peers crd龄人) is a universal characteristic of all cultures, the nature and the degree of such contact varya great deal. In American contemporary society, adolescents spend much more time with their peers than with younger children or adults.This pattern of age segregation(隔离) in American society did not become usual until the beginning of the industrialized society. Changes in the workplac e separated children from adults,with adults worHng and children attending school. The dramatic increase of mothers in the wor kplace has further contributed to the reduction in the amount of time adolescents spend with adults. School reform efforts during the nineteenth century, which resulted in age-segregated schools and grades, have reduced the amount of time adolescents spend with younger children.Finally, the changes in population are considered a factor that may have contributed to the emergence of adolescent peer culture. From 1955 t0 1975, the adolescent population increased dramatically, from 11 percent t0 20.9 percent. This increase in the number of adolescents might be a contributing factor to the increase in adolescent peer culture in terms of growth in size.Research supports the view that adolescents spend a great deal of time with their peers. Reed Larson and his colleagues examined adolescents' daily activities and found that they spend more time talking to their friends than engaging in any other activity. In a typical week, high school students will spend twice as much time with their peers as with adults. This gradual withdrawal from adults begins in early adolescence. Ln sixth grade, adults (excluding parents) account for only 25 percent of adolescent social networks. Another important characteristic of adolescent peer culture is its increasingly autonomous (白治的) function. While childhood peer groups are conducted under the close supervision of parents, adolescent peer groups typically make an effort to escape adult supervision and usually succeed in doing so.(Note: Answer t.hequesnons or complete the statements in NO MORE THAN EIGHT WORDS.)81. "This pattern of age segregation" refers to the phenomenon that adolescents segregate themselves from82. Besides changes in the workplace,are the other two factors contributing to adolescent peer culture.83. When do adolescents start to spend less time with adults?84. How do adolescent peer groups differ from childhood peer groups?第II卷（共45分）I．TranslationDirections: Translate the following sentences into English, using the words given in the brackets. 1．她五年前开始拉小提琴。

中级产品质量检验工无纸化试题及答案3

无纸化考试体验标答对照
共计 100 道题 (注:标记红色的题目为您答错的题目。)
1 、成分、性能检验是别人干的活儿，结果什么样，我们产品质量检验工不用管。
正确答案:× 您的答案:
正确答案:√ 您的答案:
9 、钢材的产品质量证明书要标明合同编号。
正确答案:√ 您的答案:
10 、公司关于产品标识和可追溯性的规定中，炼钢转炉钢水炉次号的编码规则是X+X+XXXXX，其代表的含义是年号+月份+流水号。
正确答案:× 您的答案:
11 、唐钢一钢轧厂热轧钢卷2610CY0190代表2012年6月10日丙班1700线轧制的190卷钢。
A四级 B三级 C 二级 D 一级
正确答案:B 您的答案:
44 、
钢材的产品质量证明书包括以下内容：公司名称、产品名称、牌号、规格、质量记录编号、生产许可证号、车号、合同编号、签发日期等，有( )，并加盖质量专用章。
A. 公司经理签字 B.厂长名字 C.签证人签字 D. 公司经理名字
2 、钢筋的每米理论重量=0.00617D2（其中D为钢筋直径单位毫米）。
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3 、 6S现场要求“一畅”场地平整、通道畅通。
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4 、热轧生成过程的基本工序为坯料准备，坯料加热，钢的轧制和精整。
正确答案:√ 您的答案:
正确答案:A 您的答案:
47 、
进口导板安装不当会出现( )问题。
A.轧件出孔后下弯 B.卡钢或辊环损坏 C.缠辊事故 D. 轧件出孔后上翘
正确答案:B 您的答案:
48 、
.对于型钢轧机，其规格用（）表示。