C语言操作题常考编程试题(库)

C语言编程题覆盖到的算法：1、个人所得税计算；2、求一组数的正、负数（或奇、偶数）的个数和平均值；3、二维数组主、次对角线之和；4、求素数（用函数实现）；5、级数有限项求和问题；6、两个一维数组相加（用函数实现）；7、求最大、最小值；8、判断闰年（用函数实现）；9、求水仙花数；10、百钱百鸡；11、求最大公约数、最小公倍数。

12、求回文数；13、排序；14、二维数组的转置；15、递归函数求阶乘；16、求斐波那契数列；17、求和：a+aa+aaa+aaaa+....；18、求符合条件的整数（如：是某个二位数的平方，个位、十位、百位数各不相同等）；(包括素数，回文，完数，等等)19、字符串加密；20、统计字符串中字母和数字的个数；/*1.个人所得税计算，以实验指导P24T5为标准*/ #include<>void main(){int i,n;double a,b,c;n=i/400;printf("please input income:\n");scanf("%d",&i);a=(i-800)*,b=20+(i-1200)*,c=84+(i-2000)*;switch(n){case 0:case 1:printf("不需缴税\n");break;case 2:printf("需交纳%lf元\n",a);break;case 3:case 4:printf("需交纳%lf元\n",b);break;default:printf("需交纳%lf元\n",c);break;}}/*2. 求一组数的奇数个数，偶数个数和平均值#include<>#define N 10void main(){int a[N];int i,m=0,n=0,sum=0;double average;printf("please input 10 numbers:\n");for(i=0;i<N;i++){scanf("%d",&a[i]);if(a[i]%2==0)m++;elsen++;sum+=a[i];}average=(double)sum/N;printf("we have %d odds and %d evens\n",n,m);printf("average=%lf\n",average);}*//*2'.求一组数的正数个数和负数个数与平均值*/#include<>#define N 10void main(){int a[N];int i,m=0,n=0,sum=0;double average;printf("please input 10 numbers:\n");for(i=0;i<N;i++){scanf("%d",&a[i]);if(a[i]>0)m++;elsen++;sum+=a[i];}average=(double)sum/N;printf("we have %d positive numbers and %d nagetive numbers\n",m,n);printf("the average =%lf",average); }/*3.求二维数组的主次对角线之和*/ #include<>#define M 5#define N 5void main(){int a[M][N];int i,j,sum1=0,sum2=0;printf("please input the matrix:\n");for(i=0;i<M;i++){for(j=0;j<N;j++){scanf("%d",&a[i][j]);}}for(i=0,j=0;i<M;i++,j++){sum1+=a[i][j];}for(i=0,j=N-1;i<M;i++,j--){sum2+=a[i][j];}printf("主对角线和为%d\n",sum1);printf("次对角线和为%d\n",sum2); }/*4.调用函数判断素数*/#include<>#include<>int isPrime(int n){int i;for(i=1;i<sqrt(n);i++){if(n%i==0)return 0;}return 1;}void main(){int n,i;printf("please input a number\n");scanf("%d",&n);i=isPrime(n);if(i)printf("%d is a prime\n",n);elseprintf("%d is not a prime\n",n);}数有限项求和(以格里高利公式求π为例)个一维数组相加一组数的最大最小值*/ /*#include<>void main(){int i,max,min;int a[10];printf("please input ten numbers\n");for(i=0;i<10;i++){scanf("%d",&a[i]);}max=a[0];min=a[0];for(i=1;i<10;i++){if(a[i]>max){max=a[i];}{min=a[i];}}printf("max is %d,min is %d\n",max,min); }*//*随机数*/#include<>#include<>void main(){int i,max,min;int a[10];for (i=0;i<10;i++){a[i]=rand()%90+10;printf("%d\t",a[i]);}max=a[0];min=a[0];for(i=1;i<10;i++){if(a[i]>max)max=a[i];if(a[i]<min)}printf("max=%d\tmin=%d\n",max,min);}/*8.判断闰年*/#include<>int f(int n){if(n%4==0&&n%100!=0||n%400==0)return 1;elsereturn 0;}void main(){int n;printf("please input year:\n");scanf("%d",&n);if(f(n))printf("%d是闰年\n",n);elseprintf("%d不是闰年\n",n);}/*可能会有要输出某一范围内所有闰年，思想一样，用循环调用函数即可*//*9.判断水仙花数（运用循环）#include<>void main(){int n,a,b,c,m;printf("please input a number:\n");scanf("%d",&n);a=n/100;b=n/10%10;c=n%10;m=a*a*a+b*b*b+c*c*c;if(m==n)printf("%d is the number we want\n",n);elseprintf("%d is not the number\n",n);}*//*9'.输出所有水仙花数（调用函数(书P108为循环做法)）*/ #include<>int f(int n){int a,b,c,m;a=n/100;b=n/10%10;c=n%10;m=a*a*a+b*b*b+c*c*c;if(m==n)return 1;elsereturn 0;}void main(){int i,t;for(i=100;i<1000;i++){t=f(i);if(t==1)printf("%d\t",i);}}钱买百鸡（题目见书P115）最大公约数和最小公倍数，函数实现*/ #include<>int f(int m,int n){int i=1,t;if(m<n){t=m;m=n;n=t;}while((i=m%n)!=0){m=n;n=i;}return n;}int g(int m,int n){int i,j;i=f(m,n);j=m*n/i;return j;}void main(){int m,n,a,b;printf("please input two numbers:\n");scanf("%d %d",&m,&n);a=f(m,n);b=g(m,n);printf("最大公约数为%d\n",a);printf("最小公倍数为%d\n",b);}序用递归函数求阶乘用递归函数求斐波拉契数列（前30项）*/ #include<>int f(int n){if (n==1||n==2)return 1;elsereturn f(n-1)+f(n-2);}void main(){int i,k=0;for (i=1;i<=30;i++){printf("%d\t",f(i));k++;if(k%5==0)printf("\n");}printf("\n");}a+aa+aaa+aaaa...符合条件的整数（如是某个二位数的平方，个位、十位、百位数各不相同等）符串加密计字符串中字母和数字的个数//#include<>#include<>#include<>#define N 100void main(){char str[N];int i=0;int a=0,b=0;printf("please input a string:\n");gets(str);while(str[i]!='\0'&&str[i]!='\n'){if(isdigit(str[i]))a++;else if(isalpha(str[i]))b++;i++;}printf("there are %d letters and %d numbers\n",b,a);}。