盐城市20092010学年度高三年级第二次调研考试(含答案)

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2010年盐城市高三第二模拟考试语文试题

2010年盐城市高三第二模拟考试语文试题

盐城市2009/2010学年度高三年级第二次调研考试语文试题一、语言文字运用(15分)1.下列词语中加点的字,每对读音都不相同的一组是(3分)A.瘦削/削足适履挺括/概括大意寒颤/颤颤巍巍B.蹊跷/独辟蹊径积攒/万头攒动囤聚/囤积居奇C.稽首/无稽之谈折耗/百折不挠摩天/摩肩接踵D.褪色/和颜悦色呜咽/狼吞虎咽恫吓/杀鸡吓猴2.下列各句中,加点的成语使用恰当的一句是(3分)A.锦绣家园社区的张大妈是大家公认的热心人,一听说南方遭受严重旱灾,马上义形于色,不仅自己带头捐款,还积极协助动员社区群众参加赈灾行动。

B.这个企业成功的秘诀就在于时时刻刻把消费者的利益放在第一位,做出的质量承诺从来都是一言九鼎,决不允许有任何糊弄甚至坑害消费者的事情发生。

C.“我们要坚定信心,华山再高,顶有过路。

解决困难唯一的办法、出路和希望在于我们自己的努力。

”李坚的话每个字都掷地有声,震撼了与会者的心灵。

D.目前整个房地产行业正扮演一个巨大的吸金“黑洞”角色,引起“两会”代表的热议,大家见仁见智,一致认为必须用断腕的手段,才能遏制住高房价。

3.用一句话概括下面这则新闻的主要内容。

(4分)(不超过35个字)2月下旬,商务部、工信部已联合展开针对劳动密集型行业应对人民币升值的压力测试。

3月下旬财政部或将派出调研组赴广东、浙江、江苏三省及上海市进行范围更广的人民币汇率压力测试,以期掌握不同贸易类型行业、不同贸易企业在应对人民币升值问题上的压力差异。

如此频繁的压力测试背后,是中国与西方国家特别是美国在贸易问题上的激烈交锋。

美国国会130名议员致信财长盖特纳和商务部长骆家辉,要求奥巴马政府在4月份发布有关汇率操纵的定期报告时,将中国列为汇率操纵国之一。

4.元宵灯会上,不少对联没人能对上。

有人说,现在谁还会对对联啊;也有人说,是因为上联拟得不好。

请细读右面这幅题为“请对下联”的漫画,按要求回答后面的问题。

(5分)(1)从不同角度说说这幅漫画反映了怎样的文化现象。

江苏省盐城市2008-2009学年度高三年级第二次调研考试数学2009.4

江苏省盐城市2008-2009学年度高三年级第二次调研考试数学2009.4

江苏省盐城市2008-2009学年度高三年级第二次调研考试数 学 试 题(总分160分,考试时间120分钟)参考公式:球的体积公式343V R π=(R 为球的半径). 柱体的体积公式V Sh =(其中S 为底面积,h 为高).线性回归方程的系数公式为1122211()(),()n ni iiii i nniii i x y nx y x x y y b a y bx xnxx x ====---===---∑∑∑∑.一、填空题:本大题共14小题,每小题5分,计70分.不需写出解答过程,请把答案写在答题纸的指定位置上. 1.设复数3z i =-,则||z = ▲ . 2.已知函数y =A ,N 为自然数集,则A N = ▲ .3.直线1:210l x my ++=与直线2:31l y x =-平行的充要条件是m = ▲ . 4.执行如图所示的伪代码,输出的结果是 ▲ .5.某几何体的三视图如图所示,主视图与左视图中两矩形的长和宽分别为4与2,俯视图中两同心圆的直径分别为4与2,则该几何体的体积等于 ▲ .6.双曲线221169x y -=的顶点到它的渐近线的距离为 ▲ . 7.已知5cos(),(0,)6132ππθθ+=∈,则cos θ= ▲ .8.已知,x y 之间的一组数据如下表:(第4题) 俯视图左视图主视图(第5题)x 2 3 4 5 6 y34689对于表中数据,现给出如下拟合直线:①1y x =+、②21y x =-、③8255y x =-、④32y x =,则根据最小二乘思想得拟合程度最好的直线是 ▲ (填序号). 9.数列{}n a 满足11(*)2n n a a n N ++=∈,11a =,n S 是{}n a 的前n 项和,则21S = ▲ . 10.国际上钻石的重量计量单位为克拉.已知某种钻石的价值V (美元)与其重量ω(克拉) 的平方成正比,若把一颗钻石切割成重量 分别为,()m n m n ≥的两颗钻石,且价值损失的百分率=100⨯%原有价值-现有价值原有价值(切割中 重量损耗不计),则价值损失的百分率的最大值为 ▲ .11.如图所示的三角形数阵中,满足:(1)第1行的数为1;(2)第n (n ≥2)行首尾两数均为n ,其余的数都等于它肩上的两个数相加,则第1n +行中第2个数是 ▲ (用n 表示). 12.已知函数()ln xf x ex -=+(e 是自然对数的底数),若实数0x 是方程()0f x =的解,且1020x x x <<<,则1()f x ▲ 2()f x (填“>”,“≥”,“<”,“≤”). 13.已知,,O A B 是平面上不共线三点,设P 为线段AB 垂直平分线上任意一点,若||7OA =,||5OB = ,则()OP OA OB - 的值为 ▲ .14. 已知关于x 的方程3||3x kx x =+有三个不同的实数解,则实数k 的取值范围是 ▲ .二、解答题:本大题共6小题,计90分.解答应写出必要的文字说明,证明过程或演算步骤,请把答案写在答题纸的指定区域内. 15.(本小题满分14分)等可能地取点),(y x P ,其中[3,3],[0,3]x y ∈-∈. (Ⅰ)当,x Z y Z ∈∈时,求点P 满足||y x ≤的概率; (Ⅱ)当,x R y R ∈∈时,求点P 满足y x >的概率.16.(本小题满分14分)如图,在直三棱柱111ABC A B C -中,090ACB ∠=,,,E F G 分别是11,,AA AC BB 的中点,且1223434774511141156162525166(第11题)1CG C G ⊥.(Ⅰ)求证://CG BEF 平面; (Ⅱ)求证:CG ⊥平面11AC G .17.(本小题满分14分)已知ABC ∆的三个内角,,A B C 所对的边分别为,,a b c ,且tan tan tan )1B C B C +=.(Ⅰ)求角A 的大小;(Ⅱ)现给出三个条件:①1a =;②2sin b B =;③21)0c b -=.试从中选择两个条件求ABC ∆的面积(注:只需选择一个方案答题,如果用多种方案答题,则按第一种方案给分).18.(本小题满分16分)已知椭圆2221x y m m m+=+的右焦点为F ,右准线为l ,且直线y x =与l 相交于A 点. (Ⅰ)若⊙C 经过O 、F 、A 三点,求⊙C 的方程;(Ⅱ)当m 变化时, 求证:⊙C 经过除原点O 外的另一个定点B ;(Ⅲ)若5AF AB <时,求椭圆离心率e 的范围.19.(本小题满分16分)设首项为1a 的正项数列{}n a 的前n 项和为n S ,q 为非零常数,已知对任意正整数,n m ,m n m m n S S q S +=+总成立.(Ⅰ)求证:数列{}n a 是等比数列;(Ⅱ)若不等的正整数,,m k h 成等差数列,试比较m hm ha a ⋅与2k k a 的大小; (Ⅲ)若不等的正整数,,m k h 成等比数列,试比较11m h m h a a ⋅与2k ka 的大小.20.(本小题满分16分)已知12()|31|,()|39|(0),x x f x f x a a x R =-=⋅->∈,且112212(),()()()(),()()f x f x f x f x f x f x f x ≤⎧=⎨>⎩.(Ⅰ)当1a =时,求()f x 在1x =处的切线方程;(Ⅱ)当29a ≤<时,设2()()f x f x =所对应的自变量取值区间的长度为l (闭区间[,]m n 的长度定义为n m -),试求l 的最大值;(Ⅲ)是否存在这样的a ,使得当[)2,x ∈+∞时,2()()f x f x =?若存在,求出a 的取值范围;若不存在,请说明理由.盐城市2008/2009学年度高三年级第二次调研数学试题参考答案一、填空题:本大题共14小题,每小题5分,计70分.{}0,1,2 3.23- 4.25 5.283π6.1258.③ 9.6 10.50%(填0.5,12都算对)11.222n n++12.< 13.12 14.0k>或14k<-二、解答题:本大题共6小题,计90分.15.解:(Ⅰ)当,x Z y Z∈∈时,点P共有28个,而满足||y x≤的点P有19个,从而所求的概率为11928P=………………………………………………………………………(7分)(Ⅱ)当,x R y R∈∈时,由[3,3],[0,3]x y∈-∈构成的矩形的面积为18S=,而满足y x>的区域的面积为1272S=,故所求的概率为1234SPS==……………………………………(14分) 16.证:(Ⅰ)连接AG交BE于D,连接,DF EG.∵,E G分别是11,AA BB的中点,∴AE∥BG且AE=BG,∴四边形AEGB是矩形.∴D是AG的中点………………………………………………………………………………(3分) 又∵F是AC的中点,∴DF∥CG……………………………………………………………(5分)则由DF BEF⊂面,CG BEF⊄面,得CG∥BEF面………………………………………(7分)(注:利用面面平行来证明的,类似给分)(Ⅱ) ∵在直三棱柱111ABC A B C-中,1C C⊥底面111A B C,∴1C C⊥11AC.又∵011190AC B ACB∠=∠=,即11C B⊥11AC,∴11AC⊥面11B C CB………………………(9分)而CG⊂面11B C CB,∴11AC⊥CG……………………………………………………………(12分)又1CG C G⊥,∴CG⊥平面11AC G……………………………………………………………(14分)17. 解:(Ⅰ)由tan tan tan)1B C B C+=,得tan tan1tan tanB CB C+=-,所以t a n()B C+=………………………………………………(4分)则tan tan()A B C=-+=,所以6Aπ=……………………………………………………(7分)(Ⅱ)方案一:选择①③.∵A=30°,a=1,2c -(3+1)b=0,所以c =,则根据余弦定理,得2221)2b b =+-,解得b=2,则c=226+…………………(11分) ∴41321226221sin 21+=⨯+⨯⨯==∆A bc S ABC …………………………………(14分) 方案二:选择②③. 可转化为选择①③解决,类似给分.(注:选择①②不能确定三角形)18. 解:(Ⅰ)22222,,a m m b m c m =+=∴= ,即c m =,(,0)F m ∴,准线1x m =+,(1,1)A m m ∴++……………………………………………………(2分)设⊙C 的方程为220x y Dx Ey F ++++=,将O 、F 、A 三点坐标代入得:200220F m Dm m D E =⎧⎪+=⎨⎪+++=⎩,解得02F D m E m =⎧⎪=-⎨⎪=--⎩………………………………………………………(4分) ∴⊙C 的方程为22(2)0x y mx m y +--+=……………………………………………………(5分)(Ⅱ)设点B 坐标为(,)p q ,则22(2)0p q mp m q +--+=,整理得:222()0p q q m p q +--+=对任意实数m 都成立……………………………………………(7分)∴2220p q p q q +=⎧⎨+-=⎩,解得00p q =⎧⎨=⎩或11p q =-⎧⎨=⎩,故当m 变化时,⊙C 经过除原点O 外的另外一个定点B (1,1)-……………………………(10分) (Ⅲ)由B (1,1)-、(,0)F m 、(1,1)A m m ++得(1,1)AF m =--- ,(2,)AB m m =---∴2225AF AB m m ⋅=++< ,解得31m -<<……………………………………………(12分)又200m m m ⎧+>⎨>⎩ ,∴01m <<………………………………………………………………(14分)又椭圆的离心率e ===01m <<)……………………(15分)∴椭圆的离心率的范围是02e <<………………………………………………………(16分) 19. (Ⅰ)证:因为对任意正整数,n m ,mn m m n S S q S +=+总成立,令1n m ==,得211S S qS =+,则21a qa =…………………………………………(1分) 令1m =,得11n n S S qS +=+ (1) , 从而211n n S S qS ++=+ (2),(2)-(1)得21n n a qa ++=,(1)n ≥ (3))综上得1n n a qa +=(1)n ≥,所以数列{}n a 是等比数列…………………………………………(4分)(Ⅱ)正整数,,m k h 成等差数列,则2m h k +=,所以22221()22m h m h k +>+=, 则22222111m h m mm hhhk mh m hm h a a a q a q a q --+--⋅==……………………………………………………(7分)①当1q =时,221m h k km hka a a a ⋅==………………………………………………………………(8分) ②当1q >时,2222222122111()m h k mh m hk k k k k k m h k a a a q a q a q a +----⋅=>==…………………………(9分)③当01q <<时,2222222122111()m h k mh m hk k k k k k m h k a a a q a qa q a +----⋅=<==……………………(10分)(Ⅲ)正整数,,m k h 成等比数列,则2m h k ⋅=,则112m h k+>=, 所以111111111121121111()()()m h m h mhm h m hm h mha a a a qa q aqq q +--+--⋅===,2221()k k k a a q q=……………(13分) ①当1a q =,即11a q =时,112mh k m h k a a a ⋅=22k k q a ==……………………………………………(14分)②当1a q >,即11a q >时,111122211()()mh m h k m h a a a a q q q q+⋅=>2k k a =………………………………(15分)③当1a q <,即11a q <时,111122211()()m h m h k m h a a a a q q q q+⋅=<2kk a =………………………………(16分)20. 解: (Ⅰ)当1a =时,2()|39|x f x =-.因为当3(0,log 5)x ∈时,1()31x f x =-,2()93x f x =-, 且3log 512()()2310231025100x f x f x -=⋅-<⋅-=⋅-=,所以当3(0,log 5)x ∈时,()31x f x =-,且31(0,log 5)∈……………………………………(3分) 由于()3ln3x f x '=,所以(1)3ln 3k f '==,又(1)2f =,故所求切线方程为2(3ln3)(1)y x -=-,即(3ln3)23ln30x y -+-=…………………………………………………………………(5分) (Ⅱ) 因为29a ≤<,所以33990log log 2a <≤,则当39log x a≥时,因为390x a ⋅-≥,310x->, 所以由21()()(39)(31)(1)380xxxf x f x a a -=⋅---=--≤,解得38log 1x a ≤-, 从而当3398log log 1x a a ≤≤-时,2()()f x f x = ……………………………………………(6分) ① 当390log x a≤<时,因为390x a ⋅-<,310x-≥,所以由21()()(93)(31)10(1)30x x xf x f x a a -=-⋅--=-+≤,解得310log 1x a ≥+,从而当33109log log 1x a a≤<+时,2()()f x f x = …………………………………………(7分) ③当0x <时,因为21()()(93)(13)8(1)30x x x f x f x a a -=-⋅--=-->,从而2()()f x f x = 一定不成立………………………………………………………………(8分)综上得,当且仅当33108[log ,log ]11x a a ∈+-时,2()()f x f x =, 故33381042log log log [(1)]1151l a a a =-=+-+- …………………………………………(9分) 从而当2a =时,l 取得最大值为312log 5…………………………………………………(10分)(Ⅲ)“当[)2,x ∈+∞时,2()()f x f x =”等价于“21()()f x f x ≤对[)2,x ∈+∞恒成立”,即“|39||31|31x x x a ⋅-≤-=-(*)对[)2,x ∈+∞恒成立” ……………………………………(11分)① 当1a ≥时,39log 2a≤,则当2x ≥时,39log 39390xa a a ⋅-≥⋅-=,则(*)可化为3931x x a ⋅-≤-,即813x a ≤+,而当2x ≥时,8113x +>,所以1a ≤,从而1a =适合题意………………………………………………………………(12分)② 当01a <<时,39log 2a >.⑴ 当39log x a >时,(*)可化为3931x xa ⋅-≤-,即813x a ≤+,而8113x +>,所以1a ≤,此时要求01a <<…………………………………………………………(13分)⑵ 当39log x a =时,(*)可化为90311xa≤-=-,所以a R ∈,此时只要求01a <<………………………………………………………(14分)(3)当392log x a ≤<时,(*)可化为9331x xa -⋅≤-,即1013x a ≥-,而101139x -≤, 所以19a ≥,此时要求119a ≤<…………………………………………………………(15分)由⑴⑵⑶,得119a ≤<符合题意要求.综合①②知,满足题意的a 存在,且a 的取值范围是119a ≤≤………………………………(16分)数学附加题部分21.A .解:因为PA 与圆相切于点A,所以2MA MB MC =⋅.而M 为PA 的中点,所以PM=MA,则2,PM MBPM MB MC MC PM=⋅∴=. 又BMP PMC ∠=∠,所以BMP PMC ∆∆ ,所以MPB MCP ∠=∠……………………(5分)在PMC ∆中,由0180CMP MPC MCP ∠+∠+∠=,即02180CMP BPC MPB ∠+∠+∠=,所以000100402180MPB ++∠=,从而020MPB ∠=……………………………………………………………………………(10分)B .解:11002M -⎡⎤=⎢⎥⎣⎦,所以1M N -=11100022020102⎡⎤⎡⎤⎡⎤⎢⎥⎢⎥=⎢⎥⎢⎥⎢⎥⎣⎦⎣⎦⎣⎦……………………………(5分) 即在矩阵1M N -的变换下有如下过程,122x x x y y y ⎡⎤'⎡⎤⎡⎤⎢⎥→=⎢⎥⎢⎥⎢⎥'⎣⎦⎣⎦⎣⎦,则1cos 22y x ''=,即曲线cos y x =在矩阵1M N -的变换下的解析式为2cos 2y x =……(10分)C .解:由题设知,圆心(2,0),C P ,故所求切线的直角坐标方程为60x +=……………………………………………………………………………(6分)从而所求切线的极坐标方程为cos sin 60ρθθ+=………………………………(10分)D .证:因为,0m n >,利用柯西不等式,得222()()()a b m n a b m n++≥+…………………………(8分)即222()a b a b m n m n++≥+………………………………………………………………………(10分) 22.解: (Ⅰ)以A 为原点,AB 、AC 、AP 分别为x 轴、y 轴、z 轴建立空间直角坐标系A -xyz , 则A(0,0,0),B(2,0,0),C(0,2,0),E(0,1,0),P(0,0,1),所以(2,1,0),(0,2,1)BE PC =-=- ,2cos(,)5||||BE PC BE PC BE PC ==……………………………(4分) 故异面直线BE 与PC 所成角的余弦值为2|cos(,)|5BE PC = ……………………………………(5分)(Ⅱ)作PM⊥BE 交BE(或延长线)于M,作CN⊥BE 交BE(或延长线)于N,则存在实数m 、n,使得(1)PM mPB m PE =+- ,(1),CN nCB n CE =+- 即(2,1,0).CN n n =--因为,PM BE CN BE ⊥⊥ ,所以150,510PM BE m CN BE n =-==--=,解得11,55m n ==-,所以2424(,,1),(,,0)5555PM CN =-=-- …………………………………(8分)所以2cos(,)3||||PM CN PM CN PM CN ==-,即为所求二面角的平面角的余弦值………………(10分) 23.解:(Ⅰ) 当m n =时,()2(1)n f x x =+,所以2x 的系数为22n C ,则由2210n C =,解得5n =……………………………………………………………………(4分) (Ⅱ) ①由0122(1)m k k m m m m m m m x C C x C x C x C x +=+++⋅⋅⋅++⋅⋅⋅+,求导得 11211(1)2m k k m m m m m m m x C C x kC x mC x ---+=++⋅⋅⋅++⋅⋅⋅+(m ≥3).令1x =-,得121102(1)(1)k k mm m m m m C C kC mC --=-+⋅⋅⋅+-+⋅⋅⋅+-,即11(1)0mk kmk kC +=-=∑,同理11(1)0nk kn k kC +=-=∑, ∴1111(1)(1)0nmk kk knm k k kC kC ++==-+-=∑∑………………………………………………………(7分)③ 将0122(1)m k k m mm m m m m x C C x C x C x C x +=+++⋅⋅⋅++⋅⋅⋅+,两边在[0,2]上积分,得2201220(1)()m k k m mm m m m m x dx C C x C x C x C x dx +=+++⋅⋅⋅++⋅⋅⋅+⎰⎰,根据微积分基本定理,得1102211(1)()0011mm k k m k x C x m k ++=+=++∑,即110131211m mk k m k C k m ++=-=++∑,同理可得110131211n nk k n k C k n ++=-=++∑, 所以111100113131221111n m nm k k k k n m k k C C k k n m ++++==--+=+++++∑∑………………………………(10分)。

09届盐城中学高三物理第二次调研考试

09届盐城中学高三物理第二次调研考试

09届盐城中学高三物理第二次调研考试物 理 试 题讲明:本试卷分第一卷(选择题)和第二卷(非选择题)两部分,共120分.考试时刻100分钟.第一卷(选择题 共31分)一、单项选择题,共5小题,每题3分,共15分。

每题只有一个选项符合题意 1、以下讲法中不正确的选项是〔 〕A .依照速度定义式tx v ∆∆=,当t ∆专门专门小时,tx ∆∆就能够表示物体在t 时刻的瞬时速度,该定义应用了极限思想方法。

B .在探究加速度、力和质量三者之间关系时,先保持质量不变研究加速度与力的关系,再保持力不变研究加速度与质量的关系,该实验应用了操纵变量法。

C .在推导匀变速运动位移公式时,把整个运动过程划分成专门多小段,每一小段近似看作匀速直线运动,然后把各小段的位移相加,那个地点采纳了微元法。

D .在不需要考虑物体本身的大小和形状时,用质点来代替物体的方法叫假设法2、如下图的速度—时刻和位移—时刻图像中给出了四条图线,关于它们的物理意义,以下描述正确的选项是〔 〕 A .图线1表示物体做曲线运动 B .s —t 图线中t 1时刻v 1>v 2C .v —t 图线中0至t 3时刻内3和4平均速度相等D .两图像中t 2和t 4时刻分不表示2和4开始反向运动3、如下图,水平面上停放着A 、B 两辆小车,质量分不为M 和m ,M>m ,两车相距为L 。

人的质量也是m ,另有不计质量的一根竹竿和一根细绳。

第一次人站在A 车内,竿插在B 车内;第二次人站在B 车内,竿插在A 车内。

两种情形下,人用同样大小的力拉绳子,使两车相遇。

设阻力可忽略不计,两次小车从开始运动到相遇的时刻分不为t 1和t 2,那么〔 〕A .t 1>t 2B .t 1<t 2C .t 1=t 2D .条件不足,无法判定4、从空中A 点以E 1 = 1J 的初动能水平抛出一小球,小球刚要落地时的动能E 2 = 5J ,落地点在B 点。

盐城2010年高三二模数学(理)试题及答案

盐城2010年高三二模数学(理)试题及答案

盐城市2009/2010学年度高三年级第二次调研考试数 学 试 题(总分160分,考试时间120分钟)一、填空题:本大题共14小题,每小题5分,计70分.不需写出解答过程,请把答案写在答题纸的指定位置上. 1. 已知全集{}4,3,2,1=U ,集合{}1,2P =,{}2,3Q =,则()U P Q ð等于 ▲ . 2.已知(1)2z i i ⋅+=+,则复数z = ▲ .3.已知数列}{n a 是等差数列,且1713a a a π++=-,则7sin a = ▲ .4.已知向量()0,1,(1,3),(,)OA OB OC m m ===,若//AB AC ,则实数m = ▲ .5.某人有甲、乙两只密码箱,现存放两份不同的文件,则此人使用同一密 码箱存放这两份文件的概率是 ▲ .6.一个社会调查机构就某地居民的月收入情况调查了10000人,并根据 所得数据画出样本的频率分布直方图(如图所示). 为了分析居民的收 入与年龄、学历、职业等方面的关系,再从这10000人中用分层抽样 方法抽出100人作进一步调查,则在[)2500,3500(元/月)收入段应 抽出 ▲ 人.7.已知圆229x y +=的弦PQ 的中点为(1,2)M ,则弦PQ 的长为 ▲ . 8.按如图所示的流程图运算,若输入8x =,则输出的k = ▲ .9.中心在坐标原点,焦点在x 轴上的双曲线的一条渐近线方程为430x y +=,则该双曲线的离心率为 ▲ .10.已知l 是一条直线,,αβ是两个不同的平面. 若从“①l α⊥;②//l β;③αβ⊥”中选取两个作为条件,另一个作为结论,试写出一个你认为正确的命题 ▲ .(请用代号表示)0.0.0.0.0.第6题第8题11.请阅读下列材料:若两个正实数12,a a 满足22121a a +=,那么12a a +≤证明:构造函数2221212()()()22()1f x x a x a x a a x =-+-=-++,因为对一切实数x ,恒有()0f x ≥,所以0∆≤,从而得2124()80a a +-≤,所以12a a +≤根据上述证明方法,若n 个正实数满足222121n a a a ++⋅⋅⋅+=时,你能得到的结论为▲ .(不必证明)12.设等差数列{}n a 的首项及公差均是正整数,前n 项和为n S ,且11a >,46a >,312S ≤,则2010a = ▲ .13.若二次函数2()4f x ax x c =-+的值域为[0,)+∞,则2244a cc a +++的最小值为 ▲ .14.设函数()||f x x x bx c =++,则下列命题中正确命题的序号有 ▲ . (请将你认为正确命题的序号都填上)①当0b >时,函数()f x 在R 上是单调增函数; ②当0b <时,函数()f x 在R 上有最小值;③函数()f x 的图象关于点(0,)c 对称; ④方程()0f x =可能有三个实数根. 二、解答题:本大题共6小题,计90分.解答应写出必要的文字说明,证明过程或演算步骤,请把答案写在答题纸的指定区域内. 15.(本小题满分14分)在△ABC 中,角A 、B 、C 所对的边分别为a 、b 、c ,且ab b a c -+=222.(Ⅰ)若tan tan tan tan )A B A B -=+⋅,求角B ; (Ⅱ)设(sin ,1)m A = ,(3,cos2)n A =,试求⋅的最大值.16.(本小题满分14分)如图,等腰梯形ABEF 中,//AB EF ,AB =2,1AD AF ==,AF BF ⊥,O 为AB 的中点,矩形ABCD 所在的平面和平面ABEF 互相垂直.(Ⅰ)求证:AF ⊥平面CBF ;(Ⅱ)设FC 的中点为M ,求证://OM 平面DAF ; (Ⅲ)求三棱锥C BEF -的体积.17.(本小题满分14分)如图,互相垂直的两条公路AM 、AN 旁有一矩形花园ABCD ,现欲将其扩建成一个更大的三角形花园APQ ,要求P 在射线AM 上,Q 在射线AN 上,且PQ 过点C ,其中30=AB 米,20=AD 米. 记三角形花园APQ 的面积为S. (Ⅰ)当DQ 的长度是多少时,S 最小?并求S 的最小值.第16题 A B CD EF MO ABP MD QNC第17题(Ⅱ)要使S 不小于1600平方米,则DQ 的长应在什么范围内?18.(本小题满分16分)已知在△ABC 中,点A 、B 的坐标分别为)0,2(-和)0,2(,点C 在x 轴上方. (Ⅰ)若点C 的坐标为)3,2(,求以A 、B 为焦点且经过点C 的椭圆的方程; (Ⅱ)若∠45=ACB ,求△ABC 的外接圆的方程; (Ⅲ)若在给定直线y x t =+上任取一点P ,从点P 向(Ⅱ)中圆引一条切线,切点为Q .问是否存在一个定点M ,恒有PM PQ =?若存在,求出t 的取值范围;若不存在,请说明理由.19.(本小题满分16分)设等比数列{}n a 的首项为12a =,公比为q (q 为正整数),且满足33a 是18a 与5a 的等差中项;数列{}n b 满足232()02n n n t b n b -++=(*,t R n N ∈∈). (Ⅰ)求数列{}n a 的通项公式;(Ⅱ)试确定t 的值,使得数列{}n b 为等差数列;(Ⅲ)当{}n b 为等差数列时,对每个正整数k ,在k a 与1k a +之间插入k b 个2,得到一个新数列{}n c . 设n T 是数列{}n c 的前n 项和,试求满足12m m T c +=的所有正整数m .20.(本小题满分16分)设函数2()f x x =,()ln (0)g x a x bx a =+>.(Ⅰ)若(1)(1),'(1)'(1)f g f g ==,求()()()F x f x g x =-的极小值;(Ⅱ)在(Ⅰ)的结论下,是否存在实常数k 和m ,使得()f x kx m ≥+和()g x kx m ≤+?若存在,求出k 和m 的值.若不存在,说明理由.(Ⅲ)设()()2()G x f x g x =+-有两个零点12,x x ,且102,,x x x 成等差数列,试探究0'()G x 值的符号.盐城市2009/2010学年度高三年级第二次调研考试数学附加题部分(本部分满分40分,考试时间30分钟)21.[选做题] 在A 、B 、C 、D 四小题中只能选做2题,每小题10分,计20分.请把答案写在答题纸的指定区域内.A.(选修4—1:几何证明选讲)如图,圆O 的直径8=AB ,C 为圆周上一点,4=BC ,过C 作圆的切线l ,过A 作直线l 的垂线AD ,D 为垂足,AD 与圆O 交于点E ,求线段AE 的长.B .(选修4—2:矩阵与变换)已知二阶矩阵A 有特征值31=λ及其对应的一个特征向量111轾犏=犏臌α,特征值12-=λ及其对应的一个特征向量211轾犏=犏-臌α,求矩阵A 的逆矩阵1A -.C .(选修4—4:坐标系与参数方程)以平面直角坐标系的原点O 为极点,x 轴的正半轴为极轴,建立极坐标系(两种坐标系中取相同的单位长度),已知点A 的直角坐标为)6,2(-,点B 的极坐标为)2,4(π,直线l 过点A 且倾斜角为4π,圆C 以点B 为圆心,4为半径,试求直线l 的参数方程和圆C 的极坐标方程.D.(选修4—5:不等式选讲) 设d c b a ,,,都是正数,且22b a x +=,22d c y +=.求证:))((bc ad bd ac xy ++≥.[必做题] 第22、23题,每小题10分,计20分.请把答案写在答题纸的指定区域内. 22.(本小题满分10分)已知正项数列{}n a 中,n S 是其前n 项的和,且12n n nS a a =+,n N +∈. (Ⅰ)计算出123,,a a a ,然后猜想数列{}n a 的通项公式; (Ⅱ)用数学归纳法证明你的猜想.23(本小题满分10分)甲、乙两人进行一项游戏比赛,比赛规则如下:甲从区间]1,0[上随机等可能地抽取一个实数记为b ,乙从区间]1,0[上随机等可能地抽取一个实数记为c (c b ,可以相等),若关于x 的方程022=++c bx x 有实根,则甲获胜,否则乙获胜. (Ⅰ)求一场比赛中甲获胜的概率;(Ⅱ)设n 场比赛中,甲恰好获胜k 场的概率为k nP (,,)k n k N n N *N?,求k n nk P nk∑=0的值.盐城市2009/2010学年度高三年级第二次调研数学参考答案一、填空题:本大题共14小题,每小题5分,计70分.1.{}42.3122i -3.-4.-15.126.407.48.39.53 10.①②→③ 11.12n a a a ++⋅⋅⋅+1214. ①③④二、解答题:本大题共6小题,计90分.15.解:由ab b a c -+=222,得2221c o s 22a b c C ab +-==,又()0,C π∈,3C π∴=………3分(Ⅰ)由t at a n A B A B-=+⋅,tan tan tan()1tan tan A B A B A B -=∴-=+⋅得, 2233A B ππ-<-< ,6A B π∴-=……6分,又23A B C ππ+=-=,4B π∴=……8分(Ⅱ)⋅(s A A =⋅==23172(sin )48A --+………………11分 又ABC ∆中,3C π=,得2(0,)3A π∈,(]sin 0,1A ∈,m n ∴⋅ 的最大值为178…………14分16.证明:(Ⅰ) 平面⊥ABCD 平面ABEF ,AB CB ⊥,平面 ABCD 平面ABEF =AB , ⊥∴CB 平面ABEF ,⊂AF 平面ABEF ,CB AF ⊥∴……………………………………3分又AF BF ⊥,且BF BC B ⋂=,,BF BC ⊂平面CBF ,⊥∴AF 平面CBF ……………5分(Ⅱ)设DF 的中点为N ,则MN //CD 21,又AO //CD 21,则MN //AO ,MNAO为平行四边形,//OM ∴AN ……………………………………………………………………………8分 又⊂AN 平面DAF ,⊄OM 平面DAF ,//OM ∴平面DAF ……………………………10分(Ⅲ)过点E 作EH AB ⊥于H ,则060EBH ∠=,所以2EH =,21EF AB HB =-=,故11224BEF S ∆=⨯⨯=………12分,13C BEF BEF V S BC -∆=⨯⨯=…………14分 17.解:(Ⅰ)设DQ x =米()0x >,则20AQ x =+,∵AP AQ DC QD =,∴2030x x AP+=, ∴30(20)x AP x +=,则2115(22x S A P A Qx+=⨯⨯=……………………………………5分 40015(40)1200x x=++≥,当且仅当20x =时取等号 ……………………………………9分(Ⅱ)由1600S ≥,得2320012000x x -+≥,解得2003x <≤或60x ≥………………13分答:(Ⅰ)当DQ 的长度是20米时,S 最小,且S 的最小值为1200平方米;(Ⅱ)要使S 不小于1600平方米,则DQ 的取值范围是2003DQ <≤或60DQ ≥…14分 18.解:(Ⅰ)因为AC=5,BC=3,所以椭圆的长轴长28a AC BC =+=……………………3分又c=2,所以b=,故所求椭圆的方程为2211612x y +=……………………………………5分(Ⅱ)因为2sin ACR C=,所以2R =R =7分又圆心在AB 的垂直平分线上,故可设圆心为(0,s )(s>0),则由248s +=,解得2s =,所以△ABC 的外接圆的方程为22(2)8x y +-=…………10分(Ⅲ)假设存在这样的点M (m,n ),设点P 的坐标为(,)x x t +,因为恒有PM PQ =,所以2222()()(2)8x m x t n x x t -++-=++--,即22(224)(244)0m n x m n nt t +--+-++=对x R ∈恒成立 …………………………13分 从而2222402440m n m n nt t +-=⎧⎨+-++=⎩,消去m ,得2(2)(24)0n t n t -+++= (*), 因为方程(*)的判别式为2412t t ∆=--,所以(1)当26t -<<时,因为方程(*)无实数解,所以不存在这样的点M …………………14分(2)当6t ≥或2t ≤-时,因为方程(*)有实数解,且此时直线y x t =+与圆相离或相切,故此时这样的点M 存在……………………………………………………………………16分 19.解:(Ⅰ)因为31568a a a =+,所以2468q q =+,解得2242q q ==或(舍),则2q =…3分又12a =,所以2n n a =…………………………………………………………………………5分(Ⅱ)由232()02n n n t b n b -++=,得2232n n t n b n -=-,所以12324,164,122b t b t b t =-=-=-,则由12b bb+=,得3t =……………………………………………………………………8分而当3t =时,2n b n =,由12n n b b +-=(常数)知此时数列{}n b 为等差数列…………10分(Ⅲ)因为1232c c c ===,易知1m =不合题意,2m =适合题意………………………11分当3m ≥时,若后添入的数21m c +=,则一定不适合题意,从而1m c +必是数列{}n a 中的某一项1k a +,则231123(2222)()22k k k b b b b ++++⋅⋅⋅+++++⋅⋅⋅+=⨯, 所以1(22)2(21)22kk k k ++⨯-+=⨯,即12220k k k +--+=…………………………13分记()f k =12222222k k k k k k +--+=⨯--+,则'()2(ln 2)212k f k k =⋅--,因为21211222(3)21k k k --+++⋅⋅⋅+=≥-, 所以当3k ≥时,2312(12222)112k k k -=++++⋅⋅⋅++>+,又2ln 2ln 41=>, 从而'()0f k >,故()f k 在[3,)∞+递增.则由(3)1693260f =--+=>知()f k =0在[3,)∞+无解,即3m ≥都不合题意 …15分综上知,满足题意的正整数仅有m=2…………………………………………………………16分 20.解:(Ⅰ)由(1)(1),'(1)'(1)f g f g ==,得12b a b =⎧⎨+=⎩,解得1a b ==……………………2分则()()()F x f x g x =-=2ln x x x --,利用导数方法可得()F x 的极小值为(1)0F =……5分(Ⅱ)因()f x 与()g x 有一个公共点(1,1),而函数2()f x x =在点(1,1)的切线方程为21y x =-,下面验证()21()21f x xg x x ≥-⎧⎨≤-⎩都成立即可……………………………………………………………7分由2210x x -+≥,得221x x ≥-,知()2f x x ≥-恒成立…………………………………8分设()ln (21)h x x x x =+--,即()l n 1h x x x =-+,易知其在(0,1)上递增,在(1,)+∞上递减,所以()ln (21)h x x x x =+--的最大值为(1)0h =,所以ln 21x x x +≤-恒成立.故存在这样的k 和m ,且2,1k m ==-………………………………………………………10分(Ⅲ)0'()G x 的符号为正. 理由为:因为2()2ln G x x a x bx =+--有两个零点12,x x ,则有211122222ln 02ln 0x a x bx x a x bx ⎧+--=⎪⎨+--=⎪⎩,两式相减得22212121(ln ln )()0x x a x x b x x -----=……12分即212121(ln ln )a x x x x b x x -+-=-,于是00120122'()2()a aG x x b x x b x x x =--=+--+ 212112(ln ln )2a x x a x x x x -=--+221211122()[ln ]x x x ax x x x x -=--+221221112(1)[ln ]1xx x a x x x x x -=--+…14分①当120x x <<时,令21x t x =,则1t >,且0212(1)'()(ln )1a t G x t x x t -=--+.设2(1)()ln (1)1t u t t t t -=->+,则22214(1)'()0(1)(1)t u t t t t t -=-=>++,则2(1)()l n 1t u t t t-=-+在(1,)+∞上为增函数.而(1)0u =,所以()0u t >,即2(1)l n 01t t t-->+. 又因为210,0a x x >->,所以0'()0G x >.②当210x x <<时,同理可得:0'()0G x >.综上所述:0'()G x 的符号为正…………………………………………………………………16分数学附加题部分21.A 、解:连结AC BE OC ,,,则AE BE ⊥.∵4=BC ,∴4===BC OC OB , 即OBC ∆为正三角形, ∴60=∠=∠COB CBO ……………………………………………4分又直线l 切⊙O 与C , ∴60DCACBO ?? ,∵AD l ^, ∴906030DAC ?-=………………………6分而 3021=∠=∠=∠COB ACO OAC , ∴60=∠EAB ……………………………………8分在Rt △BAE 中,∠EBA=30°,∴421==AB AE (10)分B.解:设二阶矩阵⎢⎣⎡=c a A ⎥⎦⎤d b (,,,)a b c d R Î,则有⎢⎣⎡c a⎥⎦⎤d b ⎥⎦⎤⎢⎣⎡=⎥⎦⎤⎢⎣⎡11311,且⎢⎣⎡c a ⎥⎦⎤d b ⎥⎦⎤⎢⎣⎡--=⎥⎦⎤⎢⎣⎡-1111, 即⎩⎨⎧-=-=+13b a b a ,且⎩⎨⎧=-=+13d c d c ,解得A1,2,2,1====d c b a ………………………………5分∴⎢⎣⎡=21A ⎥⎦⎤12,从而11323A -⎡-⎢=⎢⎢⎢⎣2313⎤⎥⎥⎥-⎥⎦………………………………………………………10分C.解:∵直线l 过点(-2,6),倾斜角为4π,∴直线l 的参数方程为⎪⎪⎩⎪⎪⎨⎧+=+-=ty t x 226222(t 为参数)5分又圆心B 的直角坐标为(0,4),半径为4,∴圆C 的直角坐标方程为22(4)16x y +-= ,将cos ,sin x y ρθρθ=??代入化简得圆C 的极坐标方程为8s i n ρθ=?……………10分D.证明:∵222222()()()()0a b c d ac bd ad bc ++-+=-?,∴22222()()()a b c d acbd ++?, 又,,,a b c d 均为正数,∴02222>+≥++bd ac d c b a ① ,同理02222>+≥++bc ad d c b a②…6分①×②得:2222()()()()0a b c d ac bd ad bc ++?+>,∴))(())((2222bc ad bd ac d c b a ++≥++,即))((bc ad bd ac xy ++≥………10分22.解:(Ⅰ)在12n n nS a a =+中分别令1,2n =,可得1231,1,a a a ==3分由此猜想:n a n n =--5分 (Ⅱ)数学归纳法证明(略)………………………………………………………………………10分23.解:(Ⅰ)方程022=++c bx x 有实根的充要条件为0442≥-=∆c b ,即c b ≥2; 由题意知,每场比赛中甲获胜的概率为31110121=⨯=⎰dbbP ……………………………………5分(Ⅱ)∵k n k k n k n C P -=)32()31(,∴001110012112()()()()3333nk n n n n n k k P C C nn n -==⋅⋅+⋅∑222212()()33n n C n -+⋅+ 0)32()31()32()31(n n n r n r r n n n C n r C ++⋅+- , (其中n r ,,2,1,0 =)又11)!()!1()!1()!(!!--=---=⋅-=⋅r n r n C r n r n n r r n r n n r C ,(1)r ³(0r =时0r n r C n ?)……………8分 ∴0111221101111012121212()()()()()()()()33333333nk n n r r n r n n n n n n n k k P C C C C n -=-------==+++++å001112111101111112121212()()()()()()()()333333333n n r r n r n n n n n n C C C C -----------轾=+++++犏臌 313231311=⎪⎭⎫ ⎝⎛+=-n ………………………………………………………………………………10分。

江苏省盐城市-度高三年级第二次调研考试英语试题

江苏省盐城市-度高三年级第二次调研考试英语试题

盐城市2008/2009学年度高三年级第二次调研考试英语试题第I卷(三部分,共85分)第一部分:听力(共两节,满分20分)第一节(共5小题;每小题1分,满分5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

听下面5段对话,回答1-5 题。

1. What does the woman mean?A. She cannot go with the man.B. She will work with the man.C. She will go shopping.2. What’s the probable relationship between the two speakers?A. Manager and secretary.B. Professor and assistant.C. Boss and salesgirl.3. What happened to Mary?A. She stole some money.B. She lost her money.C. She met a careless thief on the bus.4. What do you learn from the conversation?A. The girl studies very well.B. The father finds his daughter under water.C. The daughter gets worse than C level.5. What does the man mean about his job as an airline attendant(乘务员)?A. He has enjoyed his job.B. He has enjoyed staying at the hotel.C. He is not interested in flying.第二节(共15小题;每小题1分,满分15分)听下面5段对话或独白。

盐城市2009年度高三年级第二次调研考试

盐城市2009年度高三年级第二次调研考试

盐城市2009年度高三年级第二次调研考试历史试题第I卷(选择题共60分)一、选择题:本大题共20小题,每小题3分,共计60分。

在每小题列出的四个选项中,只有一项最符合题目要求。

1、《荀子·儒效》:“(周公)兼制天下,立七十一国,姬姓独居五十三人焉。

周之子孙,苟不狂惑者莫不为天下之显诸侯。

”材料不能说明A.王族是分封的主要对象B.王权借助神权维护统治C.诸侯必须服从周王命令D.血缘是连结政治关系的纽带2、汉武帝时期以汉民族为主体的文化共同体基本形成。

与此相关事件的表述不正确的是A.儒学教育官方化和制度化B.大一统的文化体制形成C.民间私人办学蔚然成风D.选官方式和程序排斥民意’3、乾隆《元和县志》“(安徽)歙人阮弼在芜湖创立染局,招来‘染人’,分工操作,费用省而获利多,其产品行销于全国各地。

”材料说明①地域性商人群体较为活跃②新的生产关系迅速发展③长途贸易比较发达④生产的专业化程度提高A.①③④B.①②③C.②③④D.①②③④4、孟德斯鸠在《论法的精神》中曾这样评价当时中国的君主专制:“中国政府只有在施用棍棒才能让人民做些事情,政府与其说是管理民政,毋宁说是管理家政。

”下列措施最能体现这一论断的是A.实施行省制度B.废丞相,权分六部C.设立内阁制D.增没军机处5、下列作品中,绘画风格从注重写实变为注重意境的是A B C D6、“自同光以迄宣统,妇女服饰,以上海为最入时,流风所被,几及全国。

富贵之家,莫不尤而效之,其人辄顾影自怜,私心窃喜,贫贱者亦步趋恐后。

”上述现象出现的主要原因是A.女性审美观念发生变化B.外来文化被广泛接受C.近代社会发生剧烈变革D.上海开近代风气之先7、下列表格反映了1918-1920年间中国日本纱和印度纱的进口变化情况。

导致这种变化的主要因素是C.群众性反帝斗争的开展D.一战后日本经济萧条8、南京国民政府统治前期,民族工业的增长速度创历史最高纪录。

造成这一局面的主要原因是A.政府政策导向B.外部环境有利C.实业家自强不息D.自然经济解体9、中共提出开辟—一条与苏联不同的社会主义建设道路始于A.过渡时期总路线的提出B.《论十大关系》的发表C.中共八大的召开D.中共十一届三中全会的召开10、列宁说:“一个民主国家必须承认各地区的自治权,特别是居民的民族成分复杂的地区和专区的自治权,这种自治区同民主集中制一点也不矛盾;相反地,一个民族成分复杂的大国只有通过地区的自治才能够实现真正民主的集中制。

盐城市20092010学年度高三年级第二次调研考试

盐城市20092010学年度高三年级第二次调研考试

盐城市2009——2010学年度高三年级第二次调研考试语文试题一、语言文字运用 (15分)1.下列词语中加点的字,每对读音都不相同的一组是 (3分)A.瘦削/削足适履挺括/概括大意寒颤/颤颤巍巍B.蹊跷/独辟蹊径积攒/万头攒动囤聚/囤积居奇C.稽首/无稽之谈折耗/百折不挠摩天/摩肩接踵D.褪色/和颜悦色呜咽/狼吞虎咽恫吓/杀鸡吓猴D。

shǎi/sè;yè/yàn;hè/xià。

A.xuē;guā/kuò;zhàn/chàn。

B.q ī/xī;zǎn/cuán;tún。

C. qǐ/jī;shé/zhé;mó。

2.下列各句中,加点的成语使用恰当的一句是 (3分)A.锦绣家园社区的张大妈是大家公认的热心人,一听说南方遭受严重旱灾,马上义形于色,不仅自己带头捐款,还积极协助动员社区群众参加赈灾行动。

B.这个企业成功的秘诀就在于时时刻刻把消费者的利益放在第一位,做出的质量承诺从来都是一言九鼎,决不允许有任何糊弄甚至坑害消费者的事情发生。

C.“我们要坚定信心,华山再高,顶有过路。

解决困难唯一的办法、出路和希望在于我们自己的努力。

”李坚的话每个字都掷地有声,震撼了与会者的心灵。

D.目前整个房地产行业正扮演一个巨大的吸金“黑洞”角色,引起“两会”代表的热议,大家见仁见智,一致认为必须用断腕的手段,才能遏制住高房价。

C。

掷地有声:义形于色:形:表现;色:面容。

正义之气显现于神色。

也指义愤的心情显露在脸上。

一言九鼎:九鼎:古代国家的宝器,相传为夏禹所铸。

一句话抵得上九鼎重。

比喻说话力量大,能起很大作用。

掷地有声:掷:投、扔。

比喻文章文辞优美,语言铿锵有力。

义同“掷地金声”。

见仁见智:对同一个问题,不同的人从不同的立场或角度有不同的看法。

与后文“一致认为”矛盾。

3.用一句话概括下面这则新闻的主要内容。

江苏省盐城市高三年级第二次调研考试

江苏省盐城市高三年级第二次调研考试

2009届江苏省盐城市高三年级第二次调研考试物理试题一、单项选择题:本题共5小题,每小题3分,共计15分。

每小题只有一个选项符合题意。

1.如图所示,有一带电的微粒,在电场力的作用下沿曲线从M点运动到N点,则微粒A.带负电,电势能增加B.带负电,电势能减小C.带正电,电势能增加D.带正电,电势能减小2.交流电压表和电流表都有一定的量度范围,不能直接测量过高的电压和过大的电流,用变压器就可解决这个问题,这样的变压器叫电压互感器或电流互感器。

下列关于电流互感器和电压互感器的说法中正确的是A.电流互感器应串联在电路中使用,电压互感器应并联在待测电路上使用B.电流互感器和电压互感器副线圈的电流都小于原线圈的电流C.电流互感器和电压互感器副级线圈都是绝对不能短路的D.电流互感器和电压互感器原线圈的匝数都大于副线圈的匝数3.如图所示,一架在500 m高空以200 m/s的速度水平匀速飞行的轰炸机,要用两枚炸弹分别炸山脚和山顶的目标A和B。

已知山高180 m,山脚与山顶的水平距离为600 m,若不计空气阻力,g 取10 m/s2,则投弹的时间间隔应为A.6 SB.5 SC.3 SD.2 S4.一个质量为m的质点,在外力F和重力的作用下,由静止开始斜向下作匀加速直线运动,加速度方向与竖直方向成θ角。

为使质点机械能保持不变,F的大小必须等于A.mg B.mg sinθC.mg tanθD.mg cosθ5.如图所示,质量都为m的A、B两物体叠放在竖直弹簧上并保持静止,用大小等于mg的恒力F向上拉B,运动距离h时B与A分离。

则下列说法中正确的是A.B和A刚分离时,弹簧为原长B.B和A刚分离时,它们的加速度为gC.弹簧的劲度系数等于mg/hD.在B与A分离之前,它们作匀加速运动二、多项选择题:本题共4小题,每小题4分,共计16分。

每小题有多个选项符合题意,全部选对的得4分,选对但不全的得2分,错选或不答的得0分。

6.嫦娥一号在撞击月球之前,进行了多次变轨,先由200km圆轨道降到100km圆轨道,继而降到远月点100km、近月点15km的椭圆轨道。

2009届盐城高三年级第二次调研考试

2009届盐城高三年级第二次调研考试

2009届江苏省盐城市高三年级第二次调研考试地理试卷说明:本试卷分第一卷(选择题)和第二卷(综合题)两部分,满分120分,考试时间100分钟。

第一卷(选择题,共60分)一、单项选择题:在下列各小题的四个选项中,只有一个选项是最符合题目要求的。

请在答题卡上相应的方框内填涂(18小题,每题2分,共36分)。

宇宙探测是一个国家综合国力的象征,2020年中国有望实现载人登月。

据此回答1-2题。

1、我国正在海南文昌建设航天基地。

与其他基地相比,其优势条件主要表现在A.晴天多B.水资源丰富C.纬度低D.科技实力强2、研究月球对人类未来的意义表述不正确的是A.研究月表的沉积岩利于探索太阳系的形成B.在月球建天文观测站效果更好C.从月球发射航天器会节省很多燃料D.开发氦-3资源,缓解地球能源紧张状况一架飞机在下图所示地区飞行,图中P点为极点,阴影表示黑夜。

据此完成3-5题。

3、当飞机途径图中Q地时,服务员提醒乘客变更日期并核对时间。

若当地时间是21时,则北京时间是A.3时B.7时C.17时D.23时4、这架飞机的航线最有可能是A.巴黎——新加坡B.摩尔曼斯克——温哥华C.东京——悉尼D.惠灵顿——开普敦5、这期间可信的是A.南极昆仑站建设正忙B.墨累河流域剪羊毛正忙C.西湖桃花正红D.长江抗洪正忙读某地等高线地形图(水平距离单位:千米,等高距为10米),完成6-8题。

6、图示区域的位于A.青藏高原B.江南丘陵C.内蒙古高原D.云贵高原7、与图示地貌相符的描述诗句是A.横看成林侧成峰,远近高低各不同B.会当凌绝顶,一览众山小C.水作青罗带,山如碧玉簪D.天苍苍,野茫茫,风吹草地现牛羊8、造成图示地貌的地质作用主要是A.风力侵蚀B.冰川堆积C.流水侵蚀D.火山喷发读漫画“把云留住”,完成9-10题。

9、与该漫画主题最贴切的环境问题是A.土地盐碱化B.大气污染C.森林破坏D.温室效应10、此图体现了区域地理环境的A.整体性B.差异性C.开放性D.同一性受全球金融风暴的影响,我国返乡民工达2200多万人,结合产业模式图,回答11-13题。

江苏省盐城中学09届高三年级第二次模拟考试

江苏省盐城中学09届高三年级第二次模拟考试

江苏省盐城中学09届高三年级第二次模拟考试物理试题(2009.5.18)一、单项选择题:本题共5小题,每小题3分,共计15分。

每小题只有一个选项符合题意。

1、如图所示,分别是物体运动的位移x、速度v、加速度a和物体受到的合外力F随时间t的变化图象,其中表示物体在做匀加速运动的是()2、图甲是一逻辑电路,在其A端输入U A的信号如图乙所示,在其B端输入U B的信号如图丙所示,则其输出端y的输出信号U Y是图丁中的()3、卫星甲、乙、丙在如图所示的三个椭圆轨道上绕地球运行,卫星甲与卫星乙的运行轨道在P点相切.不计大气阻力.以下说法正确的是()A.卫星甲运行时的周期最大B.卫星乙运行时的机械能最大C.卫星丙的加速度始终大于卫星乙的加速度D.卫星甲、乙分别经过P点时的速度相等4、如图所示的真空空间中,仅在正方体中的黑点处存在着电荷量大小相等的点电荷,则图中a、b两点电场强度和电势均相同的是()5、如图所示,固定斜面倾角为θ,整个斜面分为AB、BC两段,且2AB=BC。

小物块P(可视为质点)与AB、BC两段斜面之间的动摩擦因数分别为μ1、μ2。

已知P由静止开始从A点释放,恰好能滑动到C点而停下,那么θ、μ1、μ2间应满足的关系是()A.tanθ=μ1+2μ23B.tanθ=2μ1+μ23C.tanθ=2μ1-μ2D.tanθ=2μ2-μ1二、多项选择题:本题共4小题,每小题4分,共计16分.每小题有多个选项符合题意,全部选对的得4分,选不全的得2分,错选或不答的得0分.6、2008年5月12日14时18分汶川发生了8.0级大地震.先期到达灾区武警战士利用千斤顶解救了大量压在废墟的群众.如图所示是剪式千斤顶,当摇动把手时,螺纹轴就能迫使千斤顶的两臂靠拢,从而将预制板顶起.当预制板刚被顶起时对千斤顶的压力为1.0×105N,此时千斤顶两臂间的夹角为120°,则下列判断正确的是()A.此时两臂支持力大小均为1.0×105NB.此时千斤顶对预制板的支持力为1.0×105NC.若继续摇动手把,千斤顶对预制板的支持力将增大D.若继续摇动手把,千斤顶对预制板的支持力将减小7、如图所示,理想变压器初级线圈接一交变电流,交变电流的电压有效值恒定不变。

盐城2009年高三第二次调研考试语文答案(含文言译文)

盐城2009年高三第二次调研考试语文答案(含文言译文)

盐城2009年高三第二次调研考试语文答案(含文言译文)新高考新题目2009-04-17 21525cc149a20100ctfg盐城市2008/2009学年度高三第二次调研考试语文参考答案一、语言文字运用(15分)1.BA.sài / sâ,háng / xíng,bïB.tà/ tuî,mî/ mãi,dù/ duïC.kē,qī/ xī,shāo / qiàoD.ài/ yì,chán ,huái/ kē2.CA.人言啧啧,指人们不满地纷纷议论开来。

句中曲解词义,把意思用反了。

B.师心自用,师心,以心为师,指只相信自己;自用,按自己的主观意图行事。

形容自以为是,固执己见,不肯接受别人的正确意见。

感情色彩不当。

C.众矢之的,许多支箭所指的靶子,比喻大家攻击的对象。

符合语境。

D.鼎力相助,敬词,指请托或感谢别人对自己大力帮助。

句中误用为表示自己对他人的帮助,用错对象。

3.②“拟”改为“准备”(书面语色彩太浓,不合广播稿的要求)③改为“希望全校同学踊跃投稿”(不合启事的文体要求)⑤“日新月异”后加“的变化”(成分残缺)11改为“从即日起至5月30日截止”。

(表意不明)(每一处1分,指出序号并修改正确得1分,只指出序号修改不正确不得分)4.①网络是人类的工具,但人类不应该成为网络的工具②网络是人类的得力助手,但人类不能成为网络的奴隶;③游戏是人生的点缀,但游戏不应该成为人生的追求;④虚拟世界奇妙无穷,但人的灵魂不能变得空虚。

(写出一句得2分,写出两句即得5分)二、文言文阅读(19分)5.D(讯,审问,审讯)6.B(③是允则爱民带来的结果;④允则善于早作准备的结果;⑤是说允则“洞知人情”的原因;)7.D(“处理上下级关系上能得心应手”文中无据)8.(1)转运使又控制着不答应,允则请求用自家的资产作抵押品,才能够拨发公家仓库的粮食便宜地卖给(灾民)。

【精品】江苏省盐城市届高三第二次调研—试题

【精品】江苏省盐城市届高三第二次调研—试题

盐城市2010-2011学年度高三年级第二次调研考试数学试题(总分160分,考试时间120分钟)一、填空题:本大题共14小题,每小题5分,计70分.不需写出解答过程,请把答案写在答题纸的指定位置上。

1.复数z i =的共轭复数为▲.2.已知集合{10}A x x =+>,{30}B x x =-<,则A B =▲.3.从{}1,2,3中随机选取一个数a ,从{}2,3中随机选取一个数b ,则b a >的概率是▲.4.已知c b a ,,是非零实数,则“c b a ,,成等比数列"是“b =”的▲条件(从“充要”、“充分不必要”、“必要不充分”、“既不充分又不必要"中选择一个填空)。

5.将参加数学夏令营的100名学生编号为001,002,…,100,现采用系统抽样方法抽取一个容量为25的样本,且第一段中随机抽得的号码为004,则在046号至078号中,被抽中的人数为▲.6.如图,运行伪代码所示的程序,则输出的结果是▲. 7.函数sin(2)cos(2)63y x x ππ=++-的最大值为▲.8.已知公差不为0的等差数列{}n a 满足139,,a a a 成等比数列,n S 为数列{}n a 的前n 项和,则11976S S S S --的值为▲.9.已知命题:“若,x y y ⊥∥,z 则x z ⊥”成立,那么字母,,x y z在空间所表示的几何图形有可能是:①都是直线;②都是平面;③,x y 是直线,z 是平面;④,x z 是平面,y 是直线。

上述判断中,正确的有▲(请将你认为正确的判断的序号都填上).10.已知函数()xf x a x b =-+的零点0(,1)()x k k k Z ∈+∈,其中常数,a b 满足932,34a b==,则k =▲。

上一点,l 为左准线,PQ l ⊥,垂足为Q ,若四边形PQFA 为平行四边形,则椭圆的离心率e的取值范围是▲。

盐城市2009-2010学年度高三年级第二次调研考试英语

盐城市2009-2010学年度高三年级第二次调研考试英语

盐城市2009/2010学年度高三年级第二次调研考试英语试题第I卷(三部分,共85分)第一部分:听力(共两节,满分20分)第一节(共5小题;每小题1分,满分5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

听下面5段对话,回答第1至5 题。

1. Why does the woman start smoking again?A. She likes it.B. She feels happy.C. She‟s in anxiety.2. Where does the conversation probably take place?A. At a restaurant.B. At the woman‟s home.C. At a hotel.3. What is the woman doing?A. Complaining.B. Apologizing.C. Explaining.4. What can we learn about the woman?A. She is very eager for her new car. [来源:]B. She is pleased to have a new garage.C. She is dissatisfied with the man‟s work.5. What does the man want the woman to do?A. To meet a friend for him.B. To go out with him.C. To do his work.第二节(共15小题;每题1分,满分15分)听下面5段对话或独白。

每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

盐城高三第二次调研考试语文试卷

盐城高三第二次调研考试语文试卷

盐城市2008/2009学年度高三第二次调研考试语文试题2009.4.10 一、语言文字运用(15分)1.下列词语中加点的字,每对读音都不相同....的一组是(3分) ( )A.塞.外/闭目塞.听行.情/高山景行.弹.劾/弹.冠相庆B.拓.本/开拓.进取出没./没.轻没重劲.头/疾风劲.草C.苛.求/南柯一梦果脯./匍.匐前进艄.公/宝剑出鞘.D.关隘./溢.于言表坐禅./金蝉.脱壳脚踝./不落窠.臼2.下列各句中,加点的成语使用恰当..的一句是(3分) ( )A.唐山市人大常委会推行“阳光”财政,在网上向社会公开政府预算,接受社会各界的监督,赢得人言啧啧....,取得了较好的社会效果和反响。

B.窦玉明同学在介绍自己的经验时说,学习要坚持师心自用....,上课要认真听讲,课后有不懂的问题要多问老师,这样才能不断取得进步。

C.一场金融危机似乎让包括瑞士在内的“避税天堂”成了众矢之的....。

迫于外界的压力,它们不得不承诺在银行保密制度等方面做出让步。

D.我国对非洲的鼎力相助....使中非关系越来越热,这让一些西方国家非常眼红,不断抛出“新殖民主义”等言论,对中国进行肆意诬蔑和攻击。

3.下面是盐达中学校园广播站播出的一则征文启事的正文内容,在语言表述上有四处错误,请指出并加以改正。

(4分)为迎接中华人民共和国成立六十周年①,学校团委拟举办一次国庆征文活动②,要求全校同学每人都要撰写一篇征文③。

内容反映祖国的悠久历史④,讴歌祖国在改革开放中日新月异⑤,文体不限⑥,不超过1500字⑦。

学校团委将在征文中评出一、二、三等奖⑧,佳作将在校园文学《新芽》上发表⑨。

来稿请投入征文稿箱⑩,从即日起截止到5月30日○11。

错误▲(只填序号)改正▲错误▲(只填序号)改正▲错误▲(只填序号)改正▲错误▲(只填序号)改正▲4.某中学学生董××因沉迷于网吧,严重影响了学习,人也变得萎靡不振,不愿与同学交往。

江苏省盐城市2010届高三第二次调研考试(物理)word版含答案

江苏省盐城市2010届高三第二次调研考试(物理)word版含答案

盐城市2009/2010学年度高三年级第二次调研考试物 理 试 题(本试卷卷面总分120分,考试时间100分钟)第一卷(选择题 共31分)一、单项选择题:本题共5小题,每小题3分,共15分。

每小题只有一个选项符合题意。

1.下列关于传感器说法中正确的是A .霍尔元件能够把电学量转换为磁学量B .干簧管是一种能够感知电场的传感器C .电子秤应用的是光传感器D .电饭锅通过温度传感器实现温度的自动控制2.如图所示,两个小球从水平地面上方同一点O 分别以初速度1υ、2υ水平抛出,落在地面上的位置分别是A 、B ,O ′是O 在地面上的竖直投影,且O ′A :AB =1:3。

若不计空气阻力,则两小球 A .抛出的初速度大小之比为1:4B .落地速度大小之比为1:3C .落地速度与水平地面夹角的正切值之比为1:3D .通过的位移大小之比为1:33.如图是横截面积、长度均相同的甲、乙两根电阻丝的R I -图像。

现将甲、乙串联后接入电路中,则A .甲电阻丝两端电压比乙电阻丝两端的电压小B .甲电阻丝的电阻率比乙电阻丝的电阻率小C .在相同时间内,电流通过乙电阻丝产生的焦耳热少D .甲电阻丝消耗的电功率比乙电阻丝消耗的电功率小4.如图所示电路中,L 为电感线圈,C 为电容器,当开关S 由断开变为闭合时,则A .A 灯有电流通过,方向由a 到bB .A 灯中无电流通过,不可能变亮C .B 灯立即熄灭,c 点电势低于d 点电势D .B 灯逐渐熄灭,c 点电势低于d 点电势5.如图所示,固定的倾斜光滑杆上套有一个质量为m 的圆环,圆环与竖直放置的轻质弹簧一端相连,弹簧的另一端固定在地面上的A 点,弹簧处于原长h 。

让圆环沿杆滑下,滑到杆的底端时速度为零。

则在圆环下滑过程中A .圆环机械能守恒B .弹簧的弹性势能先增大后减小C .弹簧的弹性势能变化了mghD .弹簧的弹性势能最大时圆环动能最大 二、多项选择题:本题共4小题,每小题4分,共16分。

盐城市2009学年度高三年级第二次调研考试化学试题

盐城市2009学年度高三年级第二次调研考试化学试题

盐城市2008/2009学年度高三年级第二次调研考试化学试题,第Ⅰ卷 (选择题共48分)可能用到的相对原子质量:H-1 C-12 N-14 O-16 AI-27 S-32 Cl-35.5一、单项选择题;(本题包括8小题,每小题3分,共24分。

每小题只有一个选项符合题意)1.美国化学家诺塞拉研制出一种可以将水分解成氢气和氧气的催化剂,这将使氢气生产成为可能,并使太阳能使用步入新的时代,被称为“水发电技术”。

下列有关说法正确的是A.“水发电技术”是指水分解生成氢气和氧气,同时放出能量来发电B.“水发电技术”的能量转换形式为:化学能+热能+电能C.若水分解产生的H2和O2分别通入燃料电池的两极,通H2的极为电源正极D.“水发电技术”可实现发电过程中的零排放2.下列文字表述与对应的化学用语或名称关系正确的是3.石墨烯(graphene)是目前科技研究的热点,可看作将石墨的层状结构一层一层的剥开得到的单层碳原子。

将氢气加入到石墨烯排列的六角晶格中可得最薄的导电材料石墨烷(graphane,如下图),下列说法中正确的是(N A表示阿伏伽德罗常数)A.石墨烯与石墨烷互为同素异形体B.石墨烯转变为石墨烷可看作取代反应C.12g石墨烯所含碳碳键数目为1.5N AD.12g石墨烯完全转变为石墨烷需氢气11.2L4.下列有关说法不正确的是A.光导纤维的成分为二氧化硅B.被酸雨污染的农田及湖泊可洒石灰石粉末,减轻其危害C.轮船浸在水下部分可镶上一些钢锭,以防止船体表面铁的腐蚀D.天然气管道在运输天然气前需先通氮气,将空气排出,然后再输送天然气5.著名化学家徐光宪获得2008年度“国家最高科学技术奖”,以表彰他在稀土串级萃取理论方面作出的贡献。

稀土铈(Ce)元素主要存在于独居石中,金属铈在空气中易氧化变暗,受热时燃烧,遇水很快反应。

已知:铈常见的化合价为+3和+4,氧化性:Ce4+>Fe3+。

下列说法正确的是A.电解熔融Ce02制Ce,铈在阳极获得B.铈溶于氢碘酸的化学方程式可表示为:Ce+4HI=CeI4+2H2↑C.用Ce(S04)2溶液滴定硫酸亚铁溶液,其离子方程式为:Ce4++2Fe2+=Ce3++2Fe3+D.四种稳定的核素13658Ce、13858Ce、14058Ce、14258Ce,它们互称为同位素6.下列装置或操作能达到实验目的的是A.①②③④ B.②③④ C.③④ D.①②7.下列排列顺序正确的是A.还原性:F—>Cl->Br—>I— B.碱性:KOH>NaOH>Mg(OH)2>Be(OH)2C.原子半径:Na>S>F>O D.NaHC03溶液:c(HC03-)>c(C032-)>c(OH-)8.下列各组离子一定能够大量共存的是A.Na+、Mg2+、S042—、N03— B.Fe2+、H+、S042—、N03—C.K+、Al3+、Cl-、A102— D.Na+、Ca2+、OH—、HC03—二、不定项选择题(本题包括6小题,每小题4分,共24分。

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盐城市2009/2010学年度高三年级第二次调研考试第一节单项填空(共15小题;每小题1分,满分15分)21. It is believed that ______ European chemist called Felix Hoffmann first produced ASA whichcompletely changed ______ man’s understanding of aspirin.A. an; aB. the; aC. a; /D. an; /22. — How many pages have you covered of that book on financial crises?—I have given up, for it’s ______ me.A. ahead ofB. aboveC. apart fromD. on23. — Mom, can you give me an extra 200 yuan a month?— Son, we have just bought a house, and from now on we need to practice strict ______.A. economyB. medicineC. self-controlD. patience24. Lots of coal miners died on the job last year, ______ the government to shut nearly 800 smallmines in Shanxi Province alone.A. forcedB. to forceC. forcesD. forcing25. Who ______ the fight against the H1N1 flu ______ it not been for the Chinese scientists’great efforts?A. could have won; hadB. would win; hadC. would have won; hasD. could win; has26. Now that you have accepted the task, the only thing you can do now is ______ on how tofulfill it.A. reflectB. tryC. thinkD. act27. All the teachers are well aware of the fact that most students, especially teens, need help andencouragement ______ punishment.A. better thanB. rather notC. rather thanD. more often28. — Hey! Everyone in the office was at the dinner party in honor of Mr. Charles except you.What happened?— I ______ after Mike, my colleague. He was badly ill.A. have lookedB. was lookingC. would lookD. had looked29. — How is the test that you took yesterday?— Unfortunately, not even one of the hundred students who took the test ______ passed.A. hasB. haveC. areD. is30. I have just received an invitation from a good friend of mine, asking me to pay a visit to______ we used to study together.A. whatB. whereC. howD. which31. Journalists present at the press conference all wanted to know whether she had got marriedsecretly, but she ______ the subject throughout the conference.A. kept offB. kept awayC. kept asideD. kept out32. —Mary, you don’t look very happy today. What’s up?—Oh, ______. I don’t think I can get that new job.A. I’m finishedB. I’m fineC. I’m overD. I’m all right33. We firmly believe that ______ the new examination system comes into existence, completelynew situations will arise.A. consideringB. supposedC. providingD. given34. — How could you have trusted the online dictionary that much in translating your resume?— Well, I never expected it should translate it so ______.A. literallyB. originallyC. sufficientlyD. professionally35. At the United Nations Climate Change Conference, the UN Secretary General points out that,______, the climate situation will get worse and worse.A. if not dealing with properlyB. unless dealing with properlyC. if properly dealt withD. unless properly dealt with第二节完形填空(共20小题;每小题1分,满分20分)There are going to be moments in life when you must make very important decisions. You will find many people 36 to offer you advice if you ask for it (and even if you don’t), but always remember that the life you 37 is yours and nobody else’s. It’s important to decide for yourself what’s important to you and what you wan t before you 38 others. Because while there will be times 39 outside advice proves wise, there will be at least as many times when it proves completely 40 . The only way to really evaluate other folks’ advice is tofirst learn everything that you can about whatever challenge you are 41 . Once you’ve done that, in most cases you should be able to make a wise decision 42 anyway.You were 43 with the ability to decide what is and what isn’t in your best interest. Most of the time, you will make the right decision and 44 the appropriate actions, and in thinking for yourself, you will become far more successful than if you had gone against your own 45 .Early on in my investment career, I made the mistake of 46 a few important business decisions on colleagues’ opinions instead of conducting the 47 necessary to make a wise decision. It wasn’t due to 48 on my part; no one could ever accuse me of that. But, being 49 to Wall Street, I intended to assume that my more senior 50 knew more than I did, and so I 51 too much significance to their opinions.You know what happened? Each of those investments ended in 52 . Eventually I stopped allowing myself to be influenced by 53 and began doing the work myself and making my own decisions. It took me until I was almost 30 years old to 54 this—it’s never too late for a person to change his approach both to 55 and to life.36. A. easy B. ready C. unwilling D. hard37. A. lead B. lend C. take D. earn38. A. look at B. pick up C. turn to D. learn from39. A. that B. since C. when D. while40. A. useless B. useful C. priceless D. clever41. A. getting B. making C. suffering D. facing42. A. on one hand B. on your own C. on the whole D. on all sides43. A. born B. tired C. satisfied D. covered44. A. enjoy B. step C. plan D. take45. A. assumption B. judgment C. condition D. fortune46. A. basing B. depending C. relying D. focusing47. A. research B. search C. resources D. activity48. A. poverty B. laziness C. fear D. diligence49. A. used B. accustomed C. new D. old50. A. students B. brothers C. colleagues D. classmates51. A. owed B. paid C. gave D. held52. A. disaster B. progress C. failure D. success53. A. either B. another C. each D. others54. A. think B. remember C. realize D. recall55. A. payment B. dreams C. happiness D. business第三部分:阅读理解(共15小题;每小题2分,满分30分)AArrive EarlyPlan your trip so that you’re at the venue(place) well before the scheduled start of the event. Gates open one to two hours before the start of competition at city and Whistler venues. Gates open four hours prior to the start of the Opening Ceremony, three hours prior to the start of the Closing Ceremony and two hours prior to the start of the Victory Ceremonies.Travelling To VenuesIn Metro Vancouver, public transit is the best way to go. I f you’re heading to Whistler, options include commercial motorcoach and rideshare/carpool. Parking for spectators is at the Whistler Paralympic Park spectator(person who watches) parking lots.Dress AppropriatelyDress for cold and wet weather — warmly, in layers and in waterproof clothing. Remember to wear suitable footwear as you may have to walk on uneven, snowy or icy surfaces.Have Your Tickets ReadyBe sure to have your tickets with you as you must have a valid ticket to enter a venue. Treat your tickets like cash; lost or stolen tickets will not be replaced or refunded.Prepare For The Security ScreeningAvoid taking large bags to the venues. If you are unsure of what you can and cannot bring with you, check the prohibited and restricted items list.Your Payment OptionsVisa cards and cash are the only methods of payment accepted at Paralympic venues. AccessibilityAll venues have been reviewed for accessibility. If you have a specific need, see the nearest staff member for assistance.Be InformedAt the venue, look for way-finding signage (招牌), listen to announcements and read the message boards — this will provide you with the information you need to make the most of your experience. Is there still something you need to know? Don’t hesitate to visit o ur information booths located at each venue.56. This passage is most probably written ______.A. to attract more and more spectatorsB. for spectators to know clearly about dos and don'tsC. to remind players what to doD. for spectators to get to the venues more conveniently57. If you go to watch the games, you’d better not ______.A. take a busB. wear warm and waterproof clothesC. take large bags to the venueD. use your visa cards or cash for the payment58. Spectators must enter a venue ______.A. with valid ticketsB. with visa cardsC. with refunded ticketsD. with cashBHere’s an idyllic(田园风光的) scene: a small village where the sun always shines, crops always grow and your friends drop by to sweep your yard to the sound of guitar music. Animals do what they are told, there is no disease, and lending folks a helping hand makes you richer and wiser. Welcome to FarmVille — current population 69m and rising fast.“It reminds me of my childhood,” says one p layer, Lia Curran, 37, a chemist from London. “Right now I’m growing wheat and poinsettia, I’ve got a small orchard, and I’m keeping some chickens and some cows. I like having the animals. It’s comfortable.”Curran’s young animals, however, are nothing mor e than a collection of computer-controlled cartoons. FarmVille is an online computer game built into the social networking site Facebook and is described by its players as “addictive”. Launched last June by Zynga Game Network, FarmVille now has more player s than Twiter’s entire user base — or more than the population of the UK. The players are largely women over the age of 35.Jenny Glyn, 33, a London housewife, started playing in September. “I had a look at a friend’s farm and was hooked,” she says. “My fi rst motivation was to overtake her, but I did that pretty quickly. Now there’s something satisfying about growing crops.”FarmVille intellectually unites the worlds of social networking and gaming. Players are given a patch of ground with six fields, “cash”, a few seeds and a plough and have to build up wealth, skills and neighbors to create bigger, better, richer farms.Inviting your online friends to play means you earn more and get free gifts; you rise rapidly through the first levels but, once hooked, have to work harder and harder with no final level or goal in sight.“It’s very moreish,” says Curran. She hasn’t yet paid real-world money to advance in the game, but her friends do. One buys extra virtual currency at the exchange rate of $240 (£145) in FarmVille for $40 (£24) in the real world.“I’d expanded on FarmVille as much as I could, but I just wanted a pond and some bushes and trees around it,” says the woman, who is too embarrassed to be named. “I didn’t tell my husband I’d paid real money because he’d think I’m mad. But then he did keep me waiting in the car outside our house while he harvested his raspberries.”Brian Dudley, chief executive at Broadway Lodge, an addiction treatment centre, warns that this sort of obsessive(令人着魔的) play can lead to an addiction as severe as gambling.59. What does Curran do in the passage?A. She is a player.B. She is a farmer who grows wheat and poinsettia.C. She is a chemist.D. She is a housewife who raises chickens and cows.60. By FarmVille, the writer means ______.A. an addictive farm on which live 69 million farmersB. a London housewife’s farmC. an online computer game built into the social networking siteD. a farm on which people grow real crops and play as well61. In the last but one paragraph, the husband kept the woman waiting outside ______.A. because he was angry at his wife’s being mad about the farmB. because he himself was busy with his farmC. in order to punish his wife for her having paid real moneyD. so that his wife would wake up from her addiction to the farm62. According to the passage, which of the following is NOT true?A. The population of the UK is less than 69 million.B. This sort of obsessive play can cause very severe addiction.C. Once hooked, one has to make greater efforts to reach a higher level.D. Up till now, nobody has yet paid real-world money to advance in the play.CA Low-Carbon Economy (LCE) or Low-Fossil-Fuel Economy (LFFE) is an economy which has a smallest output of greenhouse gas (GHG) release into the atmosphere, but specifically refers to the greenhouse gas CO2. Recently, most of scientific and public opinion has come to the conclusion that there is such an accumulation of GHG (especially CO2) in the atmosphere due to human-related activities that the climate is changing. The over-concentration of these gases is producing global warming that affects long-term climate, with negative impacts on humanity in the foreseeable future. Globally performed LCEs therefore, are proposed as a means to avoid catastrophic climate change, and as a forerunner to the more advanced, zero-carbon society and renewable-energy economy.Some nations are low-carbon societies which are not heavily industrialized or populated. In order to avoid climate change at any point in the future, all nations considered carbon-thick societies and societies which are heavily populated, should become zero-carbon societies and economies. Several of these countries have promised to become ‘low carbon’ but not entirely zero carbon, and claim that release will be cut by 100% by offsetting release rather than stopping all release. In other words, some release will continue which will be offset, so they are not low-release.Nations seek to become low-carbon economies as part of a national global warming reduction strategy. A comprehensive strategy to manage global warming is carbon neutrality, geoengineering and adaptation to global warming.Nuclear power, or, the proposed strategies of carbon collection and storage (CCS) have been proposed as the primary means to achieve a LCE while continuing to exploit non-renewable resources; there is concern, however, with the matter of spent-nuclear-fuel storage, security and the uncertainty of costs and time needed to successfully carry out CCS worldwide and with guarantees that the stored release will not leak into the atmosphere. Alternatively, many have proposed renewable energy should be the main basis of a LCE, but, they have their associated problems of high-cost and inefficiency; this is changing, however, since investment and production have been growing significantly in recent times. Furthermore, regardless of the effect to the atmosphere by GHG releases, the growing issue of peak oil may also be reason enough fora change to a LCE.63. Low-carbon economy is encouraged for the following reasons except that ______.A. too much greenhouse gas CO2 is releasedB. the over-concentration of greenhouse gases is producing global warmingC. it can avoid catastrophic climate changeD. low carbon and zero carbon nations and societies claim for it64. The underlined word in the first paragraph probably means ______.A. warningB. pioneerC. symbolD. guide65. According to the passage, which of the following is NOT true?A. Nuclear power could act as one of the primary means to achieve a LCE.B. There’s worry about s pent-nuclear-fuel storage, security and the uncertainty of costs.C. The stored release will be likely to leak into the atmosphere.D. Renewable energy tends to become the only means to achieve a LCE.66. From the last paragraph, we can infer that the writer’s attitude toward the proposal ofadapting renewable energy is ______.A. negativeB. positiveC. self-confidentD. doubtfulDFor years Tom Anderson’s life was withered up(枯萎) by the memory of his part in a fraternity(友爱,互助会) adventure that resulted in the death of one of his classmates. He and his wife separated after six years of marriage. Then the news about Tom changed. His wife Betty came back; he earned a fine position. One day he told me what had changed his life. “I used to think, ‘Nothing can undo what I have done.’ The thought of my guilt would stop me in the middle of a smile or a handshake. It put a wall betw een my wife and me.”“Then I had an unexpected visit from the person I was most afraid to see — the mother of the college classmate who died. ‘Years ago’, she said, ‘I found it in my heart, through prayer, to forgive you. Betty forgave you. So did your fri ends and employers.’ She paused, and then said seriously, ‘You are the one person who hasn’t forgiven Tom Anderson. Who do you think you are to stand out against the people of this town and the Lord Almighty?’ I looked into her eyes and found there a kind of permission to be the person I might have been if her boy had lived. For the first time in my adult life I felt worthy to love and be loved.”It is only through forgiveness of our mistakes that we gain the freedom to learn from experience. But forgiving our shortcomings doesn’t mean denying that they exist. On the contrary, it means facing them honestly, realistically.Can a person be all-forgiving and still be human? A scientist I know spent four years as a slave laborer in Germany. His parents were killed by Nazi street bullies; his younger sister and older brother were sent to the gas chambers. This is a man who has every reason to hate. Yet he is filled with a love of life that he conveys to everyone who knows him. He explained it to me the other day: “In the beginning I was filled with hatred. Then I realized that in hating I had become my own enemy. Unless you forgive, you cannot love. And without love, life has no meaning.” Forgiveness is truly the saving grace.67. Tom Anderson and his wife separated after six years of marriage probably because ______.A. he had killed one of his classmatesB. he had cared more for his adventure than for his wifeC. his wife looked down upon his poor positionD. his life had been made in a great mess by his deep guilt68. The key reason for which Tom’s life changed back to normal may be that ______.A. his wife Betty came back to himB. the mother of his college classmate asked Betty to forgive him for his guiltC. he eventually learned to face his guilt honestly, realistically and forgave himselfD. he earned a fine position and finally made a lot of money69. The underlined part in the second paragraph means that ______.A. the mother of my college classmate permitted me to be a real personB. even my college classmate would permit me to be what I used to beC. I wouldn’t be a person unless my college classmate permitted me toD. I might have been a successful person if my college classmate had lived70. The best title for this passage could be ______.A. Forgiveness: the saving graceB. Hatred: unrealistic way of livingC. Love: a meaningful worthy lifeD. Guilt: unforgivable mistake第一节任务型阅读(共10小题; 每小题1分,满分10分)Even British People Can’t Speak English ProperlyThere are different regional accents across the UK, and a number of regions have several different dialects, that is, they have their own unique vocabulary and grammatical phrases. There were at least six different accents born to London the last time I counted.Worse than that, it is not just where a person is born in the UK that decides their accent. Forexample, a language and its accents often vary across class or level of education. Another example is how language can differ among age groups in the UK. The words and pronunciations used by young people in the UK can be radically different compared with those used by adults.Yoof cultureThe word ‘yoof’ is a slang spelling of ‘youth’. Some people consider ‘yoof’ to be a negative term, since its pronunciation is easier and lazier than ‘youth’. Other people see the term as positive, because it describes how young people are creating their own language, concepts and identity. When people find it difficult to understand their children, the children can say more things than without censorship(审查,检查) of their parents. In this way, young people are starting to find freedom, independence and self-expression. They are creating a ‘yoof culture’.It is not possible to come up with a complete list of words used by yoof. By the time the list was completed, it would be out of date. New words come and go like fashions. However, a few features of the yoof style of language are as follows:◆instead of saying something like ‘That’s good!’ or ‘I understand’, yoof will use a single adjective like ‘Safe!’, ‘Sorted!’, ‘Sound!’, ‘Cool!’ or ‘Wicked!’.◆instead of ‘He then said no!’, yoof will say ‘She was like: no!’◆Instead of ‘She’s attractive!’, yoof will say ‘She’s fine!’ or ‘She’s fit!’◆Instead of ‘I don’t care!’, a yoof will say ‘Whatever!’.New social and political languageCertain groups of society feel threatened by ‘yoof culture’ or by the British working classes having more social freedom. As a result, a negative term now commonly used in the UK is ‘chav’. It is insult and is meant to describe someone who is uneducated and anti-social (e.g. ‘He’s a chav!’). A young person who wears a jacket with a hood(风帽,头巾) (after all, it rains a lot in the UK) is sometimes called a ‘hoodie’. It is a negative term and suggests that the young person is interested in committing crime.Where does that leave us?Learners of English often feel that the best test of their English is how well they can talk to a native speaker. Yet learners should not worry about communicating with native speakers so much. Research conducted by the British Council shows that 94 per cent of the English spoken in the world today is spoken between non-native speakers of the language. In fact, when we think about ‘international English’, there is no such thing as native or non-native speakers. The UK no longer owns the English language.盐城市2009-2010学年度高三年级第二次调研考试单选填空:21-35 CBADA ACBAB AACAD完形填空:36-55 BACCA DBADB AABCC ACDCD阅读理解:56-70 BCACC BDDBD BDCBA任务型阅读:71. regional 72. levels/classes 73. education 74. pronounced 75. Another 76. interested 77. creative 78. Examples79. Whatever 80. international/universal/global。

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