2013上高三期中考试题

合集下载

2013届高三上期中考试试题

2013届高三上期中考试试题

北京十二中2013届高三上学期期中考试化学试卷相对原子质量:C 12,H 1,O 16,N 14,F 19,Al 27,S 32,Na 23,Cl 35.5,Zn 65一、选择题(每小题只有一个选项符合题意,每小题3分,共42分)1、2007年诺贝尔化学奖得主Gerhard Ertl 对金属Pt 表面催化CO 氧化反应的模型进行了深入研究。

下列关于202 78Pt 和198 78Pt 的说法正确的是A .202 78Pt 和198 78Pt 的质子数相同,互称为同位素B .202 78Pt 和198 78Pt 的中子数相同,互称为同位素C .202 78Pt 和198 78Pt 的核外电子数相同,是同一种核素D .202 78Pt 和198 78Pt 的质量数不同,不能互称为同位素2、下列判断正确的是A .向饱和FeCl 3溶液中滴加过量氨水,可制取Fe(OH)3胶体B .依据丁达尔现象可将分散系分为溶液、胶体与浊液C .AgI 胶体的胶粒在电场中自由运动D .江河入海口三角洲的形成通常与胶体的性质有关3、分子式为C 3H 2Cl 6的同分异构体共有(不考虑立体异构)A .3种B .4种C .5种D .6种4、常温常压下,两个容积相同的瓶中分别盛满X 和Y 两种气体,打开开关a ,使两瓶内的气体相通,最后容器内的压强由大到小的顺序排列正确的是A .②>③>①>④B .③>①=④>②C .③>①>④>②D .①>④>③>②5、已知N A 表示阿伏伽德罗常数的值,下列说法正确的是A .常温常压下,3.2gO 3所含的原子数为0.2N AB.10g46%的乙醇水溶液中所含H原子个数为0.6N AC.1L 1mol·L-1饱和FeCl3溶液滴入沸水中完全水解生成Fe(OH)3胶粒N A个D.标准状况下,22.4 L己烷中含共价键数目为19N A6、25 ℃和101 kPa时,乙烷、乙炔和丙烯组成的混合烃32 mL与过量氧气混合并完全燃烧,除去水蒸气,恢复到原来的温度和压强,气体总体积缩小了64 mL,原混合烃中乙炔的体积分数为A.12.5% B.25% C.50% D.75%7、下列离子方程式正确的是A.向NaAlO2溶液中通入过量CO22AlO-2+CO2+3H2O===2Al(OH)3↓+CO32-B.醋酸钠水溶液中通入足量CO2CH3COO-+CO2+H2O===CH3COOH+HCO3-C.FeBr2溶液与等物质的量的Cl2反应2Fe2++2Br-+2Cl2===2Fe3++4Cl-+Br2 D.等体积、等浓度的Ca(HCO3)2溶液和NaOH溶液混合Ca2++2HCO-3+2OH-―→CaCO3↓+CO2-3+2H2O8、下列说法不正确的是A.向无色溶液中滴加氯水和CCl4,振荡、静置,下层溶液显紫色,说明原溶液中有I-B.某钾盐溶于盐酸,产生使澄清石灰水变浑浊的无色无味气体,说明该钾盐是K2CO3 C.利用HNO3能够鉴别MgI2、AgNO3、Na2CO3、NaAlO2四种溶液D.利用金属钠可区分乙醇和乙醚9、Na2S x在碱性溶液中可被NaClO氧化为Na2SO4,而NaClO被还原为NaCl,若反应中Na2S x与NaClO的物质的量之比为1∶13,则x的值为A.2 B.3 C.4 D.510、将0.01 mol下列物质分别加入100 mL 蒸馏水中,恢复至室温,所得溶液中阴离子浓度的大小顺序是(溶液体积变化忽略不计) ①Na2O2②Na2O③Na2CO3④NaCl A.①>②>③>④B.②>①>④>③ C.①=②>③>④ D.①=②>③=④11、Al、Fe、Cu都是重要的金属元素,下列说法正确的是A.电解AlCl3、FeCl3、CuCl2的混合溶液时阴极上依次析出Cu、Fe、AlB.三者的单质放置在空气中均只生成氧化物C.常温下都可以溶解在足量的浓硝酸中D.制备AlCl3、FeCl3、CuCl2均不能采用将溶液直接蒸干的方法12、下列说法正确的是A.在稀硫酸中加入铜粉,铜粉不溶解;再加入Cu(NO3)2固体,铜粉仍不溶解B.a(HNO3)、b(NO)、c(NO2)可实现间的转化C.左图:微热稀HNO3片刻,溶液中有气泡产生,广口瓶内始终保持无色D.将SO2通入石蕊试液中,则溶液先变红后褪色13、甲、乙、丙、丁4种物质分别含2种或3种元素,它们的分子中各含18个电子。

江苏省徐州市2013届高三上学期期中考试试题(扫描版)物理

江苏省徐州市2013届高三上学期期中考试试题(扫描版)物理

2012-2013学年度第一学期期中考试高三物理参考答案一、单项选择题:(共15分) 1.C 2.D 3.B 4.D 5.B 二、多项选择题:(共16分)6.A C7.B D8.A D9. B C D 三、简答题(共20分) 10、 6.124 (±0.002)(3分)11、(6分)(1)B (2分)(2)图1:m 过大(或M 过小),造成m 不是远小于M (2分)图2:没有平衡摩擦力或木板的倾角过小(2分)12、(5分)(1)(1分)(如右图) (2)10 (2分) 25 (± 3)(2分)13、(共6分)(1)A 1、 V 1 (每空各1分) (2)(2分)(3) 偏小(2分)四.计算题:(共69分) 14、(12分)(1)A R R EI 121=+=(4分)(2)S 断开前:)(108.16103046211C U C Q --⨯=⨯⨯==(2分) 02=Q (1分)S 断开后:)(100.310103046/21/1C U C Q --⨯=⨯⨯==(2分))(100.34/1/2C Q Q -⨯==(1分))(102.441/2/1C Q Q Q Q -⨯=-+=∆(2分)15、(12分) (1)由S= r θ(1分) h= r -R (1分) 得: h =S /θ-R (2分)(2)由v=S/t (1分) GMm/r 2 = m v 2 / r (1分) 得: M = S 3 / θG t 2 (2分) (3)由GMm/R 2 = m v 12 / R (2分)得v 1= ( S 3 /θt 2 R )1/2 (2分) 16、(15分) (1)在14s-18s 时间段 tva ∆= 由图象可得: 2206/ 1.5/1418a m s m s -==-- (2分)F f =ma=1.0×1.5N=1.5N (2分 )(2)在10s-14s 小车作匀速直线运动,牵引力F =F f ( 2分)P=Fv =1.5×6W=9W (2分)(3)速度图象与横轴之间的“面积”的数值等于物体运动的位移大小0-2s 内 m m x 332211=⨯⨯=( 2分) 2s-10s 内根据动能定理 212222121mv mv x F Pt f -=-解得 x 2=39m (3分)开始加速过程中小车的位移大小为: x = x 1+x 2=42m (2分)17、(14分) (1)小球从ABC 轨道下滑,机械能守恒,设到达C 点时的速度大小为υ。

山东省烟台市2013届高三上学期期中考试

山东省烟台市2013届高三上学期期中考试

山东省烟台市2013届高三上学期期中考试山东省烟台市2013届高三上学期期中考试语文试题第卷(选择题共36分)一、(15分,每小题3分)1.下列各组词语中,加点字的读音完全相同的一组是A.瑕疵/龇牙饮恨/营利滞纳金/栉风沐雨B.悄然/愀然痉挛/劲敌八宝粥/胡谄八扯C.噱头/矍铄堙没/殷红歼击机/草菅人命D.伺候/肆意纤夫/翩跹庇护权/刚愎自用2.下列各项中,没有错别字的一组是A.通牒挖墙角仗义执言骨鲠在喉,不吐不快B.吊销百叶窗察言观色明枪易躲,暗剑难防C.博弈座右铭铩羽而归盛名之下,其实难副D.枉费股份制改弦更章嬉笑怒骂,皆成文章3.依次填入下列句中横线处的词语,最恰当的一组是市房管局加大了对乱喷涂、乱书写小广告行为的打击力度,有效了违法小广告蔓延反弹趋势,为建设生态文明城市做出了贡献。

对于景区假期井喷式客流,各地假日办游客高峰应急预案,交警、辅警、志愿者全力以赴保障旅游平稳运行。

今年以来,市文化局以维护未成年人合法权益和规范文化市场秩序为主要目标,加大了对文化市场重点领域的力度。

A.遏制启用监督B.遏制启动监管C.遏止启用监督D.遏止启动监管4.下列各句中,加点的成语使用恰当的一句是A.在奥运会期间,观众和游客都扎堆在伦敦市东区的奥运场馆观赛和旅游,伦敦市中区和西区持续低迷的客流量和不景气的生意,让商家和业主不置可否。

B.今年中秋月虽然在上午11点达到最圆,但夜晚时分的明月依然珠圆玉润,人们观月赏月,皎洁的银辉洒满夜空,为到来的两节送来温馨的祝福。

C.在中网四分之一决赛中,彭帅并没有像赛前某些人所担心的那样放水,而是和李娜展开了一场紧锣密鼓的对抗,这场比赛堪称本赛季激动人心的巅峰对决。

D.面对疯狂失控的中国楼市,决策者们已不宜再首鼠两端,应以矫枉必须过正的姿态,采取措施促进房地产市场理性回归,彻底消除房地产市场的投机炒作行为。

5.下列各句中,没有语病的一句是A.针对日本右翼人员再次进入我国钓鱼岛领海的非法行为,由中国海监50、15、26、27船组成的中国海监巡航编队10月3日继续进入我钓鱼岛领海内进行维权巡航。

2013学年高三第一学期期中考试数学(文科)

2013学年高三第一学期期中考试数学(文科)

2013学年第一学期联谊学校期中考试高三数学(文科)考试卷本试题卷分选择题和非选择题两部分。

全卷共5页,选择题部分1至2页,非选择题部分3至4页。

满分150分,考试时间120分钟。

请考生按规定用笔将所有试题的答案涂、写在答题纸上。

注意事项:1.答题前,考生务必将自己的姓名、准考证号用黑色字迹的签字笔或钢笔填写在答题纸规定的位置上。

2.每小题选出答案后,用2B 铅笔把答题纸上对应题目的答案标号涂黑,如需改动,用橡皮擦干净后,再选涂其它答案标号。

不能答在试题卷上。

选择题部分(共50分)一、选择题:本大题共10小题,每小题5分,共50分,在每小题给出的四个选项中,只有一项是符合题目要求的。

1.已知集合{}{},5,3≤*∈=<=x N x B x x A 则()=⋂B A C R ( )A .{}5,4,3B .{}5,4C .{}5,4,3,2,1D .以上都不对2. 设[]x 为表示不超过x 的最大整数,则函数lg[]y x =的定义域为 ( )A .(0,)+∞B .[1,)+∞C . (1,)+∞D . (1,2)3.条件“11a b>”是“b a <”的 ( ) A .充分而不必要条件B .必要而不充分条件C .充要条件D .既不充分也不必要条件 4. 对于向量a,b,e 及实数12,,,,x y x x λ给出下列四个条件: ①3+=a b e 且5-=a b e ; ②12x x +=0a b③()λ≠0a =b b 且λ唯一; ④)1(=++=y x b y a x c其中能使a 与b 一定共线的是 ( )A .①②B .②④C .①③D .③④5. 已知函数()cos()f x x ϕ=+(0<ϕ<π)在3x π=时取得最小值,则()f x 在[,0π-]上的单调减区间是 ( )A .[,3ππ--]B .[2,33ππ--] C .[23π-,0] D .[π-,23π-] 6. 函数x x x f ln )(=在e x = 处的切线方程为 ( ) A .x y = B . e y = C .ex y = D . 1+=ex y7. 设31312121,41log ,3log ⎪⎭⎫ ⎝⎛===c b a ,则 ( ) A .c b a << B .a c b <<C .c a b <<D .b c a << 8. 下列函数中零点不.唯一的是 ( ) A.)(x f =2x B. )(x f =1323++x xC. )(x f =xx 1- D. )(x f =2log 22-+x x 9.在ABC ∆中,P 是BC 边中点,角C B A ,,的对边分别是c b a ,,,若0cAC aPA bPB ++=,则ABC ∆的形状为 ( )A.等边三角形B.钝角三角形C.直角三角形D.等腰三角形但不是等边三角形10. 周期为2的奇函数,当)1,0(∈x 时,12)(+=x x f ,则=)12(log 2f ( )A .31-B .37-C .31D . 37非选择题部分(共100分)二,填空题:本大题共7小题,每小题4分,共28分。

山东省青岛市2013届高三上学期期中考试 化学试题

山东省青岛市2013届高三上学期期中考试 化学试题

青岛市2013届高三上学期期中考试化学试题第Ⅰ卷(选择题42分)本卷共14小题,每题3分,共42分。

在下列各题的四个选项中,只有一个选项是符合题目要求的。

可能用到的相对原子质量:H 1 N 14 O 16 Na 23 Al 27 1.下列叙述合理的是A.构成普通钢和不锈钢的主要元素都是铁,因此它们的化学性质完全相同B.金属材料都是导体,非金属材料都是绝缘体C.我国规定商家不得无偿提供塑料袋,目的是减少“白色污染”D.煤的脱硫主要作用是防止酸雨加剧和光化学烟雾的形成【答案】C【解析】A、普通钢和不锈钢都是合金,所以其化学性质不同,故错误。

B、非金属材料不都是绝缘体,如石墨是导体,故错误。

D、形成酸雨的成分是二氧化硫和氮氧化合物,形成光化学烟雾的成分是氮的氧化物,故错误。

2.用下图表示的一些物质或概念间的从属关系中不.正确的是X Y ZA.氧化物化合物纯净物B.胶体分散系混合物C.金属氧化物碱性氧化物氧化物D.离子化合物电解质化合物【答案】C【解析】金属氧化物不都是碱性氧化物,所以Y包含X,故C错误。

3.设N A为阿伏伽德罗常数的值。

下列叙述正确的是A.20mL 10mol·L-1的浓硝酸或浓硫酸与足量铜加热反应转移电子数均为0.2N AB.标准状况下,11.2 L氦气中含有N A原子C.在精炼铜或电镀铜的过程中,当阴极析出铜32g转移电子数均为N AD.标准状况下,2.24L Cl2通入足量H2O中发生反应转移的电子数为0.1N A【答案】D【解析】A、浓硝酸和稀硝酸与铜反应的生成物不同,浓硫酸和铜反应但稀硫酸和铜不反应,所以转移电子数均不是0.2N A,故错误。

B、氦是氮原子分子,所以标准状况下,11.2 L氦气中含有0.5 N A原子,故错误。

C、在精炼铜的过程中,当阴极析出铜32g转移电子数大于N A,故错误。

4.为预防“H1N1”甲型流感,同学们每天用“84”消毒液(NaClO溶液)消毒,下列说法不正确的是A.NaClO溶液的消毒原理是使蛋白质变性B.1 mol Cl2与足量NaOH溶液反应转移2 mol电子C.NaClO溶液的漂白原理与Na2O2相同,与SO2不同D.“84”消毒液与“洁厕灵”(盐酸)混合使用可能会产生有毒的氯气【答案】B【解析】A、次氯酸钠有强氧化性,次氯酸钠能使蛋白质变性,故正确。

江苏省无锡市2013届高三上学期期中考试化学试题.pdf

江苏省无锡市2013届高三上学期期中考试化学试题.pdf

江苏省无锡市2013届高三期期中考试 化 学 试 题 第Ⅰ卷 选择题(共40分) 注意事项: 1.本试卷满分120分,考试时间100分钟. 2.请将答案填写在答题卷上,凡填写在试卷上一律无效;交卷只需交答题卷. 可能用到的相对原子质量:H-l C-12 0-16 Na-23 Al-27 Ca-40 Zn-65 一、单项选择题:本题包括10小题,每小题2分,共计20分。

每小题只有一个选项符合题意。

1.化学与人类生活、社会可持续发展密切相关,下列措施不利于节能减排、保护环境的是( ) A.加快化石燃料的开采与使用 B.研发易降解的生物农药 C.推广使用节能环保材料 D.应用高效洁净的能源转换技术 2.下列有关化学用语表示正确的是( ) A.乙烯的结构简式:C2H4B.F-的结构示意图: C.N2的电子式:NN D.中子数为21的钾原子: K 3.常温下,下列各组离子在指定溶液中一定能大量共存的是( ) A. 0.1 mloI·L-1H2SO4溶液:K+、Ba2+、NO3-、Cl- B. 0.1 mol·L-1NaOH溶液:K+、Na+、SO42-、HCO3- C.0.l mol·L-lNaClO溶液:Fe2+、K+、I一、Cl- D.c(OH-)/c(H+)=lxl014的溶液:Ba2+、Na+、Cl-、NO3- 4.下列有关物质的性质与应用不相对应的是( ) A.SO2具有氧化性,可用于漂白纸浆 B.淀粉溶液遇碘变成蓝色,可用于检验碘单质的存在 C. Fe在常温下遇浓硫酸发生钝化,可用铁制容器盛放冷的浓硫酸 D.Zn具有还原性和导电性,可用作锌锰干电池的负极材料 5.科学家最近研究出一种环保、安全的储氢方法,其原理可表示为: NaHCO3+H2 HCOONa+H2O 下列有关说法正确的是 ( ) A.储氢过程中,NaHCO3被氧化 B.释氢过程的本质是盐类的水解 C.储氢、释氢过程均无能量变化 D. HCOONa晶体中既含有离子键又含有共价键 6.下列说法正确的是( ) A.催化剂可以改变某反应的焓变 B.置换反应不一定是氧化还原反应 C.氨基酸溶液既显酸性又显碱性 D.催化剂不可能提高可逆反应中反应物的转化率 7.NA为阿伏加德罗常数的数值,下列说法中正确的是( ) A.常温常压下,在空气中燃烧0.l molH2,转移的电子总数为0.2 NA B.常温常压下,2.24 L NO和NO2混合气体中含有的氮原子数目为0.lNA C. 1.0 L的0.1 mol·L-lNa2S溶液中含有的S2-离子数为0.1 NA D.标准状况下,22.4 L的CCl4中含有的CCl4分子数为NA。

山东省临沂市2013届高三上学期期中考试英语试题

山东省临沂市2013届高三上学期期中考试英语试题

山东省临沂市2013届高三上学期期中考试英语试题本试卷分第I卷和第II卷两部分,满分150分。

考试用时120分钟。

考试结束后,将本试卷和答题卡一并交回。

注意事项:1.答题前,考生务必用0.5毫米黑色签字笔将自己的姓名、座号、考生号、县区和科类填写在答题卡和试卷规定的位置上。

2.第I卷每小题选出答案后,用2B铅笔在答题卡上把对应题目的答案标号涂黑,如需要改动,用橡皮擦干净后,再选涂其他答案标号。

3.第II卷必须用0.5毫米黑色签字笔作答,答案必须写在答题卡各题目指定区域内相应的位置,不能写在试卷上;如需改动,先划掉原来的答案然后再写上新的答案;不能使用涂改液、胶带纸、修正带。

不按以上要求作答的答案无效。

第I卷(共105分)第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。

录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题,每段对话仅读一遍。

1.Which language does Smith speak best?A.Spanish.B.English.C.Russian.2.What will the weather be like tomorrow?A.Cold.B.Windy.C.Mild.3.Where does the conversation most probably take place?A.In the garden.B.In the living room.C.In the kitchen.4.What does the man mean?A.He refuses the wonlan's invitation.B.He will go to the woman's home.C.He'll stay with his parents during the holiday.5.Where does the woman probably work?A.In a restaurant.B.At a hotel.C.In a hospital.第二节(共15小题:每小题1.5分,满分22.5分)听下面5段对话。

山东省青岛市2013届高三上学期期中考试数学(理)试题

山东省青岛市2013届高三上学期期中考试数学(理)试题

山东省青岛市2013届高三上学期期中考试数学(理)试题第Ⅰ卷(选择题 共60分)一、选择题:本大题共12小题.每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.已知全集R U =,集合{}{}237,7100A x x B x x x =≤<=-+<,则()U A B ⋂=ðA.()()+∞⋃∞-,53,B.(]()+∞⋃∞-,53,C.(][)+∞⋃∞-,53,D.()[)+∞⋃∞-,53, 2.在ABC ∆中,“A B >”是“tan tan A B >”的A .充分不必要条件B .必要不充分条件C .充要条件D .既不充分也不必要条件 3.给出下列三个结论:(1)若命题p 为真命题,命题q ⌝为真命题,则命题“p q ∧”为真命题;(2)命题“若0xy =,则0x =或0y =”的否命题为“若0xy ≠,则0x ≠或0y ≠”; (3)命题“,20xx ∀∈>R ”的否定是“ ,20xx ∃∈≤R ”.则以上结论正确的个数为A .3个B .2个C .1个D .0个 4.已知等比数列{}n a 的前n 项和为13n n S a +=+,N *n ∈,则实数a 的值是A .3-B .3C .1-D .15.已知非零向量a 、b ,满足a b ⊥ ,则函数2()()f x ax b =+ (R)x ∈是A. 既是奇函数又是偶函数B. 非奇非偶函数C. 偶函数D. 奇函数 6.已知函数1()cos f x x x =,则()()2f f ππ'+= A .2π-B .3πC .1π-D .3π-7.已知等差数列{}n a 的前n 项和为n S ,且3100(12)S x dx =+⎰,则56a a +=A .125B .12C .6D .658.已知函数()sin()f x A x ωϕ=+(其中0,2A πϕ><)的图象如图所示,则函数()f x的解析式为 A .()sin(2)3f x x π=- B .()sin(2)6f x x π=+ C .()sin(2)3f x x π=+D. ()sin(4)6f x x π=+ 9.已知O 是ABC △所在平面内一点,D 为BC 边中点,且20OA OB OC ++=,则A .2AO OD = B .AO OD = C .3AO OD = D .2AO OD =10.若函数a ax x f 213)(-+=在区间)1,1(-上存在一个零点,则a 的取值范围是 A .51>a B .51>a 或1-<a C .511<<-a D .1a <- 11.已知函数2()cos()f n n n π=,且()(1)n a f n f n =++,则123100a a a a ++++= A . 0 B .100- C .100 D .1020012.已知定义在R 上的奇函数()f x 满足(4)()f x f x -=-,且[]0,2x ∈时,2()l o g (1)f x x =+,甲、乙、丙、丁四位同学有下列结论:甲:()31f =;乙:函数()f x 在[]6,2--上是减函数;丙:函数()f x 关于直线4x =对称;丁:若()0,1m ∈,则关于x 的方程()0f x m -=在[]8,8-上所有根之和为8-,其中正确的是A .甲、乙、丁B .乙、丙C .甲、乙、丙D .甲、丙第Ⅱ卷(非选择题 共90分)二、填空题:本大题共4小题,每小题4分,共16分. 13.15tan4π= ; 14.已知函数⎪⎩⎪⎨⎧<+≥=4),1(4,)21()(x x f x x f x,则2(1log 5)f +的值为 ;15.设正项等比数列{}n a 的前n 项和为n S ,若12,3693=-=S S S ,则=6S ; 16.已知函数()f x 的定义域为R ,若存在常数0m >,对任意R x ∈,有()f x m x ≤,则称函数()f x 为F -函数.给出下列函数:①2()f x x =;②2()1xf x x =+;③()2xf x =;④()sin 2f x x =. 其中是F -函数的序号为 .三、解答题:本大题共6小题,共74分,解答时应写出必要的文字说明、证明过程或演算步骤. 17.(本小题满分12分)在ABC ∆中,c b a ,,分别是角C B A ,,的对边,已知bc a c b 23)(3222+=+. (Ⅰ)若C B cos 2sin =,求C tan 的大小;(Ⅱ)若2=a ,ABC ∆的面积22=S ,且c b >,求c b ,. 18.(本小题满分12分)设{}n a 是公差大于零的等差数列,已知12a =,23210a a =-.(Ⅰ)求{}n a 的通项公式;(Ⅱ)设{}n b 是以函数214sin ()12y x π=+-的最小正周期为首项,以3为公比的等比数列,求数列{}n n a b -的前n 项和n S .19.(本小题满分12分)已知向量22(cos sin ,sin )a x x x ωωω=- ,(3,2cos )b x ω= ,设函数()(R)f x a b x =⋅∈ 的图象关于直线2x π=对称,其中ω为常数,且(0,1)ω∈.(Ⅰ)求函数()f x 的表达式;(Ⅱ)若将()y f x =图象上各点的横坐标变为原来的16,再将所得图象向右平移3π个单位,纵坐标不变,得到()y h x =的图象, 若关于x 的方程()0h x k +=在区间[0,]2π上有且只有一个实数解,求实数k 的取值范围.20.(本小题满分12分) 已知函数2))(1()(xa x x x f ++=为偶函数. (Ⅰ)求实数a 的值;(Ⅱ)记集合{(),{1,1,2}}E y y f x x ==∈-,21lg 2lg 2lg5lg54λ=++-,判断λ与E 的关系; (Ⅲ)当x ∈]1,1[nm ()0,0>>n m 时,若函数()f x 的值域为]32,32[n m --,求n m ,的值.21.(本小题满分13分)已知函数()ln f x x =的图象是曲线C ,点*(,())(N )n n n A a f a n ∈是曲线C 上的一系列点,曲线C 在点(,())n n n A a f a 处的切线与y 轴交于点(0,)n n B b . 若数列{}n b 是公差为2的等差数列,且1()3f a =.(Ⅰ)分别求出数列{}n a 与数列{}n b 的通项公式;(Ⅱ)设O 为坐标原点,n S 表示n n OA B ∆的面积,求数列{}n n a S 的前n 项和n T .22.(本小题满分13分)已知函数⎩⎨⎧≥<+++-=1,ln 1,)(23x x a x c bx x x x f ,当23x =时,函数()f x 有极大值427.(Ⅰ)求实数b 、c 的值;(Ⅱ)若存在0x ∈[1,2]-,使得0()37f x a ≥-成立,求实数a 的取值范围.即3122222⨯-+=bc c b由直线2x π=是()y f x =图象的一条对称轴,可得2sin()23ππω+=±,所以()32k k z πππωπ+=+∈,即1()6k k z ω=+∈.又(0,1)ω∈,k z ∈,所以0k =,故16ω=.20.(本小题满分12分)解: (Ⅰ))(x f 为偶函数 ()()f x f x ∴=- 22))(1())(1(xa x x x a x x +-+-=++∴,0)1(2=+∴x a ∈x R 且0≠x ,1-=∴a ………………………………………4分(Ⅱ)由(Ⅰ)可知:221)(xx x f -= 当1x =±时,()0f x =;当2x =时,3()4f x =304E ,⎧⎫∴=⎨⎬⎩⎭, ……………………………………………………………………………6分21.(本小题满分13分) 解:(Ⅰ)()1f x x'=, ∴曲线C 在点()(),n n n A a f a 处的切线方程:()1ln n n ny a x a a -=- 令0ln 1n x y a =⇒=-,该切线与y 轴交于点()0,n n B b ,ln 1n n b a ∴=-………………………………………3分①当11<≤-x 时,22()323()3f x x x x x '=-+=--,令0)(='x f 得320==x x 或 当x 变化时,)(),(x f x f '的变化情况如下表:x)0,1(-0 )32,0( 32 )1,32( )(x f ' - 0+ 0- )(x f单调递减极小值单调递增极大值单调递减根据表格,又2)1(=-f ,274)32(=f ,0)0(=f。

山东省荣成市第六中学2013届高三上学期期中考试物理试题

山东省荣成市第六中学2013届高三上学期期中考试物理试题

时间:2012.11.20 命题人:李祝一、选择题(每题4分,共40分,漏选得2分,错选不得分)1、对下列物理公式的理解,说法正确的是A、由公式a=Δv/Δt可知,加速度a由速度的变化量Δv和时间Δt决定B、由公式a=F/m可知,加速度a由物体所受合外力F和物体的质量m决定C、由公式E=F/q可知,电场强度E由电荷受到的电场力F和电荷的电量q决定D、由公式C=Q/U可知,电容器的电容C由电容器所带电量Q和两极板间的电势差U决定2、质量均为m的a、b两木块叠放在水平面上,如图所示,a受到斜向上与水平面成θ角的力F作用,b受到斜向下与水平面成θ角等大的力F作用,两力在同一竖直平面内,此时两木块保持静止,则A、b对a的支持力一定等于mgB、水平面对b的支持力可能大于2mgC、a、b之间一定存在静摩擦力D、b与水平面之间可能存在静摩擦力3.小球从空中自由下落,与水平地面相碰后弹到空中某一高度,其速度随时间变化的关系如图所示,则:()A.小球下落时的加速度为5m/s2B.小球第一次反弹初速度的大小为3m/sC.小球是从5m高处自由下落的D.小球能弹起的最大高度为0.45m4、如图所示,质量为M的盒子放在水平面上,盒的顶端挂一轻质弹簧,弹簧下端吊一质量为m的小球P,P与盒底用细线相连,静止时细线拉力为F,今将细线剪断,则细线剪断瞬间A、地面支持力不变B 、地面的支持力增加了FC 、小球P 的加速度大小为F/mD 、小球P 的加速度大小为(F-mg )/m5、如图所示,质量为m 的物块从A 点由静止开始下落,加速度是g/2,下落H 到B 点后与一轻弹簧接触,又下落h 后到达最低点C ,在由A 运动到C 的过程中,空气阻力恒定,则A 、 物块机械能守恒B 、物块和弹簧组成的系统机械能守恒C 、物块机械能减少mg (H+h )/2D 、物块和弹簧组成的系统机械能减少mg (H+h )/26.如图所示,电源内阻不可忽略,已知R 1为半导体热敏电阻,R 2为锰铜合金制成的可变电阻,若发现灯泡L 的亮度变暗,可能的原因是( )A .R 1的温度逐渐降低B .R 1受到可见光的照射C .R 2的阻值逐渐增大D .R 2的阻值逐渐减小7、“神州六号”飞船在圆形轨道上正常运行的过程中,飞船距地面的高度为h ,已知地球的半径为R ,地球表面的重力加速度为g ,则质量为m 的宇航员A 、受到地球的吸引力为零B 、他无法用弹簧秤去测力C 、受到地球的吸引力为mgR/(R+h )2D 、绕地球一周的时间为g h R Rh R /)()(2++π8、如图所示,A 板发出的电子经加速后,水平射入水平放置的两平行金属板间,金属板间所加的电压为U ,电子最终打在光屏P 上,关于电子的运动,下列说法中正确的是A、滑动触头向右移动时,电子打在荧光屏上的位置上升B、滑动触头向左移动时,电子打在荧光屏上的位置上升C、电压U增大时,电子打在荧光屏上的速度大小不变D、电压U增大时,电子从出发到打在荧光屏上的时间不变9、下图是云室中某粒子穿过铅板前后的轨迹,室内匀强磁场的方向与轨迹所在平面垂直(图中垂直纸面向里),铅板上有标度,由此可知此粒子A、此粒子一定带正电B、此粒子一定带负电C、穿过铅板的过程中,粒子损失了1/9的初动能D、穿过铅板的过程中,粒子损失了8/9的初动能10、两个电荷量分别为q和-q的带电粒子分别以速度v a和v b射入匀强磁场,两粒子的入射方向与磁场边界的夹角分别为30°和60°,磁场宽度为d,两粒子同时由A点出发,同时到达B点,如图所示,则( )A.a粒子带正电,b粒子带负电B.两粒子的轨道半径之比R a∶R b=3∶1C.两粒子的质量之比m a∶m b=1∶2D.两粒子的速度之比v a∶v b=1∶2二、实验题(11题4分,12题10分,共14分)请把本题答案写在Ⅱ卷上11.(1)某工人用一游标尺上标有20等分刻度的游标卡尺测一工件的长度,测得的结果如图所示,则该工件的长度L= cm 。

山东省枣庄市2013届高三年级期中考试

山东省枣庄市2013届高三年级期中考试

山东省枣庄市2013届高三年级期中考试语文试题第Ⅰ卷(36分)一、(24分,每小题3分)1.下列词语中加点的字,每对读音都不相同的一项是A.菲薄/绯闻秸秆/笔杆子提挈/锲而不舍B.菁华/腈纶褒贬/电饭煲沆瀣/引吭高歌C.蒜薹/舌苔胳膊/胳肢窝艾蒿/自怨自艾D.摭拾/蛰居干练/干细胞下载/车载斗量2.下列词语中,没有错别字的一组是A.赔笑天然气仗义直言里应外合B.诡秘亲合力以偏概全风华正茂C.炫烂消火栓入不敷出回光返照D.寒暄吊脚楼书声琅琅一筹莫展3.依次填人下列各句中横线处的词,最恰当的一项是①当同学们和着青春的节拍步入大学时,成长的欢乐一定在胸间。

②临近节假日,省市物价局常常要启动价格临时政策来稳定市场物价。

③只有人们爱护瓦尔登湖,这个充满着神秘和活力的林中湖泊才会永远。

A.充斥干预年轻 B.充溢干预年轻C.充溢干涉年青 D.充斥干涉年青4.下列各句中,加点的成语使用恰当的一项是A.我吃惊地发现,每个人留在纸上的“生命中最宝贵的五样”物件,绝不雷同,有些简直让人目不暇接。

B.电子商务市场的发展登峰造极,据工信部预计,2012年前10个月我国电子商务交易额将超过7万亿元。

C.黄果树瀑布水大时,如银河倒倾,奔流直下,声若雷鸣,震颤山谷。

这一幕惊世骇俗,令人难以忘怀。

D.褪去了翠绿的外衣,披上了金秋的盛装,漫山红叶依山起伏,枣庄抱犊崮景区天然植被仍是秀色可餐。

5.下列各句中没有语病、句意明确的一项是A.在打击知识产权和伪劣商品犯罪的“亮剑”行动中,公安局经侦大队顺藤摸瓜,破获了一起制售假冒“南山牌”铝合金案件。

B.要想让中小学生练习书法并藉此传承和发扬传统文化,就必须从根本上改变当前以升学为目的的教育教学现状。

C.超过七成希腊人质疑欧盟获得2012年度诺贝尔和平奖,最直接的原因是因为希腊民众不满欧盟对希腊财政紧缩的强硬态度。

D.为遏制不断攀升的事故数量,新版《机动车驾驶证申领和使用规定》通过提高违法成本的方式引导司机文明驾驶,确实必要。

江苏省徐州市2013届高三上学期期中考试数学(理)试题

江苏省徐州市2013届高三上学期期中考试数学(理)试题

徐州市2013届高三上学期期中考试数学(理)试题一、填空题:本大题共14小题,每小题5分,共计70分.请把答案填写在答题卡相应位置上......... 1.已知集合A = {-1,0,1},B = {0,1,2,3},则A ∩B = ▲ . 2.命题“)2,1(∈∀x ,12>x ”的否定是 ▲ . 3.设iibi a R b a 432,,--=+∈(i 为虚数单位),则b a += ▲ . 4.在等差数列}{n a 中,已知该数列前10项的和为10S =120,那么65a a += ▲ .5.已知=(1,2m ),= (2,-m ) ,则“1=m ”是“⊥”的 ▲ 条件.(填“充分不必要”、“必要不充分”、“充分必要”、“既不充分也不必要”之一)6.设直线是b x y +=3是曲线x e y =的一条切线,则实数b 的值是 ▲ . 7.在△ABC 中,67,14==b a ,B = 60°,则边c = ▲ . 8.(理)已知函数x x x f 5)(2-=,数列{}n a 的通项公式为)(6*N n nn a n ∈+=.当14)(-n a f 取得最小值时,n 的所有可能取值集合为 ▲ .(文)动点(,)P a b 在不等式组⎪⎩⎪⎨⎧≤≥+≥+-3004x y x y x 表示的平面区域内部及其边界上运动,则34a b w a +-=-的取值范围是 ▲ .9.下列四个命题:①函数x x x f sin )(=是偶函数;②函数x x x f 44cos sin )(-=的最小正周期是π;③把函数)32sin(3)(π+=x x f 的图象向右平移6π个单位长度可以得到x x f 2sin 3)(=的图象;④函数)2sin()(π-=x x f 在区间],0[π上是减函数.其中是真命题的是 ▲ (写出所有真命题的序号).10.(理)若函数)4(log )()3(2+=-ax x f a 在[-1,1]上是单调增函数,则实数a 的取值范围是 ▲ . (文)函数0(1)3(log >-+=a x y a ,且1≠a )的图象恒过点A ,若点A 在直线01=++ny mx 上,其中0>mn ,则nm 21+的最小值是 ▲ .11.已知数列}{n a 满足2,121==a a ,对于任意的正整数n 都有21211,1+++++++=≠⋅n n n n n n n n a a a a a a a a ,则2012S = ▲ .12.已知△ABC 中, AB 边上的中线CM = 2,若动点P 满足)(cos sin 2122R AC AB AP ∈⋅+⋅=θθθ,则⋅+)(的最小值是 ▲ .13.若函数)0()(3>-=a ax x x f 的零点都在区间[-10,10]上,则使得方程1000)(=x f 有正整数解的实数a 的取值的个数为 ▲ .14.设a 、b 均为大于1的自然数,函数x a ab x f sin )(+=,b x x g +=cos )(,若存在实数k ,使得)()(k g k f =,则=+b a ▲ .二、解答题:本大题共6小题,共计90分.请在答题卡指定区域.......内作答,解答时应写出文字说明、证明过程或演算步骤. 15.(本题满分14分)已知数列}{n a 满足:12=1,=(>0)a a a a ,数列{}n b 满足:+1=()n n n b a a n N *∈. (1)若数列}{n a 是等差数列,且3=12b ,求a 的值及}{n a 的通项公式; (2)若数列}{n a 是等比数列,求数列{}n b 的前n 项和n S .16.(本题满分14分)在锐角△ABC 中,角A ,B ,C 的对边分别为c b a ,,,且满足C b B c a cos cos )2(=-. (1)求角B 的大小;(2)设)2cos ,3(),1,(sin A A ==,试求⋅的取值范围.17.(本题满分14分)在边长为a 的正三角形铁皮的三个角切去三个全等的四边形,再把它的边沿虚线折起(如图),做成一个无盖的正三角形底铁皮箱,当箱底边长为多少时,箱子容积最大?最大容积是多少?18.(理)(本题满分16分)设函数a x x x f -+=2)(2(R x ∈,a 为常数). (1)当a = 2时,讨论函数)(x f 的单调性;(2)若a >-2,且函数)(x f 的最小值为2,求a 的值;(3)若2≥a ,不等式2)(ab x f ≥恒成立,求实数b 的取值范围. (文)(本题满分16分)已知二次函数1)(2+-=bx ax x f .(1)若0)(<x f 的解集是)31,41(,求实数b a ,的值;(2)若a 为正整数,2+=a b ,且函数)(x f 在[0,1]上的最小值为-1,求a 的值.19.(本题满分16分)已知数列}{n a 的前n 项和为n S ,且)(*2N n n S n ∈=. (1)求n a ;(2)设函数⎪⎩⎪⎨⎧=为偶数,为奇数,n n f n a n f n ),2(,)())(42(*N n f c n n ∈+=,求数列}{n c 的前n 项和n T ;(3)设λ为实数,对满足k n m 3=+且n m ≠的任意正整数k n m ,,,不等式k n m S S S ⋅>+λ恒成立,试求实数λ的最大值.20.(理)(本题满分16分)已知函数)1ln()(2++=x a x x f .(1)若函数)(x f 在定义域内既有极大值又有极小值,求实数a 的取值范围; (2)证明:1=a 时,对于任意的),1[,21+∞∈x x ,且21x x ≠,都有25)()(2121>--x x x f x f ;(3)是否存在最小的正整数N ,使得当N n ≥时,不等式311ln nn n n ->+恒成立. (文)(本题满分16分)设函数1)(2+-==bx x x f y ,且)1(+=x f y 的图象关于直线1-=x 对称.又)(x f y =的图象与一次函数)0(2)(<+=k kx x g 的图象交于两点A 、B ,且10=AB .(1)求b 及k 的值;(2)记函数)()()(x g x f x F =,求)(x F 在区间[0,1]上的最小值;(3)若∈γβαsin ,sin ,sin [0,1],且1sin sin sin =++γβα,试根据上述(1)、(2)的结论证明:αα2sin 1sin + + ββ2sin 1sin + + γγ2sin 1sin +≤109.2012~2013学年度第一学期期中考试高三数学参考答案与评分标准一、填空题1.{0,1} 2.)2,1(∈∃x ,12≤x 3.534.24 5.充分不必要 6.3ln 33- 7.)31(7+ 8.(文)[-7,3] (理){1,6} 9.①②③10.(文)8 (理))4,2()3,2( -- 11.4023 12.-2 13.3 14.4 二、解答题15. 解:(1){}n a 是等差数列,)0(,121>==a a a a ,∴)1)(1(1--+=a n a n ,……2分 又123=b ,∴1243=a a ,即12)23)(12(=--a a , 解得:65-=a (舍去)或2=a , ……4分 ∴n a n =; ……6分 (2){}n a 是等比数列,)0(,121>==a a a a ,∴1-=n n a a ,有121-+==n n n n a a a b ,…8分 ∴21a b b nn =+,即数列{}n b 是首项为a ,公比为2a 的等比数列, ……10分 ∴当1=a 时,n S n =; 当1a ≠时,22122(1)11n n n a a a aS a a +--==--. ……14分16. 解:(1)因为C b B c a cos cos )2(=-,所以C B B C A cos sin cos )sin sin 2(=-,…2分即A B C C B B C B A sin )sin(cos sin cos sin sin sin 2=+=+=, ……4分 而0sin >A ,所以21cos =B ,故060=B ; ……6分 (2)因为)2cos ,3(),1,(sin A A ==,所以817)43(sin 2sin 21sin 32cos sin 322+--=-+=+=⋅A A A A A n m , ……10分 由⎪⎩⎪⎨⎧<<=<<000090060900C B A 得⎩⎨⎧<-<<<00000901200900A A , 所以009030<<A ,从而)1,21(sin ∈A , ……12分故n m ⋅的取值范围是]817,2(. ……14分 17. 解:设箱底边长为x ,则箱高为)0(233a x x a h <<-⨯=, ……2分 箱子的容积为)0(818160sin 21)(3202a x x ax h x x V <<-=⨯⨯=. ……6分由08341)(2'=-=x ax x V 解得01=x (舍),a x 322=, ……8分且当)32,0(a x ∈时,0)('>x V ;当),32(a a x ∈时,0)('<x V ,所以函数)(x V 在a x 32=处取得极大值, ……10分这个极大值就是函数)(x V 的最大值:332541)32(81)32(81)32(a a a a a V =⨯-⨯=.……12分答:当箱子底边长为a 32时,箱子容积最大,最大值为3541a . ……14分18. (文)解:(1)不等式0)(<x f 的解集是)31,41(,故方程0)(=x f 的两根是31,4121==x x ,所以⎪⎩⎪⎨⎧=+-=+-01)31()31(01)41()41(22b a b a ,解得7,12==b a ; ……6分 (2)因为2+=a b ,所以14)2()22(1)2()(222++-+-=++-=aa a a x a x a ax x f , …8分 对称轴为a a a x 12122+=+=,当2≥a 时,a a a x 12122+=+=]1,21(∈, ……10分所以14)2(1)22()(2min -=+-=+=a a a a f x f ,解得2=a , ……12分 当1=a 时,a a a x 12122+=+=23=,所以1)1()(min -==f x f 成立. ……14分综上可得:2=a 或1=a . ……16分(理)解:(1)2=a 时,11,,222222)(222<≥⎩⎨⎧+--+=-+=x x x x x x x x x f , ……2分结合图象知,函数)(x f y =的单调增区间为),1[+∞,减区间为]1,(-∞. ……6分(2)22,,22)(22ax a x a x x a x x x f <≥⎩⎨⎧+--+=, ……8分 12,2->∴->aa ,当2≥a 时,函数)(x f y =的最小值为1)1(-=a f = 2,解得a = 3符合题意; ……10分当22<<-a 时,函数)(x f y =的最小值为24)2(2==a a f ,无解; 综上,a = 3. ……12分(3)由(2)知,当2≥a 时函数)(x f y =的最小值为1)1(-=a f ,所以)2(12≥≥-a ab a 恒成立,令)2(1)1()(2≥+-=a b a a g , ……14分有:⎩⎨⎧≤+-≤-01)1(20122b b ,故2222≤≤-b . ……16分 19. 解:(1)当2≥n 时,12)1(221-=--=-=-n n n S S a n n n , ……2分 当1=n 时,111==S a ,满足上式,所以12-=n a n ; ……4分(2)由分段函数⎪⎩⎪⎨⎧=为偶数为奇数n n f n a n f n ),2(,)(可以得到:,1)1()2()4()8(,5)3()6(1231==========a f f f f c a f f c ……6分当*,3N n n ∈≥时,121)12(2)12()22()42(1221+=-+=+=+=+=----n n n n n n f f f c , ……8分故当*,3N n n ∈≥时,)12()12()12(15132++++++++=-n n Tn n n n +=-+--+=-2)2(21)21(462, ……10分所以⎩⎨⎧≥+==2,21,5n n n T n n ; ……12分(3)由2n S n =,及k n m S S S ⋅>+λ得222k n m ⋅>+λ,mnn m n m n m n m k n m k n m 2)(9)()(9,32222222222+++=++=+∴=+ , ……14分29)(92)(9),(2222222222222222=++++>+++=+∴≠+<nm n m n m mn n m n m k n m n m n m mn , 要222k n m +<λ恒成立,只要29≤λ,∴λ的最大值为29. ……16分 20. (文)(1)由已知,1)(2+-==bx x x f y 为偶函数,所以b = 0; ……2分 设方程212+=+kx x 的两根为1x ,2x ,由10=AB 得:2122122124)(11x x x x k x x k -++=-+=10)4)(1(22=++k k解得1-=k ; ……4分 (2)由(1)知1)(2+=x x f ,2)(+-=x x g ,故)()()(x g x f x F ==2223+-+-x x x , 由0143)(2=-+-='x x x F ,解得31,121==x x , ……6分 列表如下:所以,函数)(x F 在区间[0,1]上的最小值为2750)31(=f ; ……10分(3)由(2)知,当]1,0[∈x 时,有不等式)2)(1(2x x -+≥2750恒成立,所以211x +≤)2(5027x -,有21x x +≤)2(50272x x -, ……12分 当∈γβαsin ,sin ,sin [0,1],且1sin sin sin =++γβα时,αα2sin 1sin ++ββ2sin 1sin ++γγ2sin 1sin +≤)]sin sin (sin )sin sin (sin 2[5027222γβαγβα++-++ =)]sin sin (sin 2[5027222γβα++- ……14分 又1 = 2)sin sin (sin γβα++≤3)sin sin (sin 222γβα++, ∴γβα222sin sin sin ++≥31,∴αα2sin 1sin ++ββ2sin 1sin ++γγ2sin 1sin +≤109)312(5027=-, 当且仅当31sin sin sin ===γβα时,等号成立. ……16分(理)解:(1)由题意012212)(2'=+++=++=x ax x x a x x f 在),1(+∞-有两个不等实根, 即0222=++a x x 在),1(+∞-有两个不等实根, ……2分设a x x x F ++=22)(2,则⎩⎨⎧>->-=∆0)1(084F a ,解之得210<<a ; ……4分(2)1=a 时,)1ln()(2++=x x x f , 令)1(25)1ln(25)()(2≥-++=-=x x x x x x f x g , ……6分 则)1(2)1)(34()1(23425112)(2'+-+=+--=-++=x x x x x x x x x g , 当1≥x 时,0)('≥x g ,所以函数)(x g 在),1[+∞上是增函数. ……8分 由已知,不妨设+∞<<≤211x x ,则)()(21x g x g <, 所以221125)(25)(x x f x x f -<-,即25)()(2121>--x x x f x f ; ……10分 (3)令函数)1ln()(23++-=x x x x h , ……12分则1)1(31123)(232'+-+=++-=x x x x x x x h , 当),0[+∞∈x 时,0)('>x h ,函数)(x h 在),0[+∞上单调递增. ……14分 又0)0(=h ,所以当),0(+∞∈x 时,恒有0)0()(=>h x h ,即32)1ln(x x x ->+恒成立. 取),0(1+∞∈=nx ,则有3211)11ln(n n n ->+恒成立,故存在最小的正整数1=N ,使得当N n ≥时,不等式311ln nn n n ->+恒成立.……16分。

山东省济宁邹城市2013届高三上学期期中数学理(附答案)

山东省济宁邹城市2013届高三上学期期中数学理(附答案)

山东省济宁邹城市2013届高三上学期期中考试数学(理)试题本试卷分第I 卷(选择题)和第Ⅱ卷(非选择题)两部分,满分150分,考试时间120分钟,第I 卷(选择题60分)注意事项:1.答第I 卷前,考生务必将自己的姓名、准考证号、考试科目涂(写)在答题卡(纸)上.2.每题选出答案后,用2B 铅笔把答题卡对应题目的答案标号涂黑,如需改动,用橡皮擦干净后,再改涂在其它答案标号.一、选择题:(本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的)1.若a ,b 是任意实数,且a>b ,则A .22a b >B .1b a <C .11()()22a b < D .lg()0a b ->2.已知平面向量(1,2),(2,),//,23a b m a b a b ==-+且则=A .(-5,-10)B .(-4,-8)C .(-3,-6)D .(-2,-4) 3.已知12732log [log (log )]0,x x =那么等于A .13B C D 4.已知t>0,若10(21)6x dx -=⎰,则实数t 的值等于 A . 2 B .3 C .6 D .85.已知角α的终边过点4(8,6sin 30),cos 5P m α--=-且,则m 的值为A .12B .—12CD 6.设曲线11x y x +=-在点(3,2)处的切线与直线10ax y ++=直,则a= A .2 B .-2 C .-12 D .12 7.在AABC 中,若sinA=2 sinBcos C ,222sin sin sin A B C =+,则△ABC 的形状是A .等边三角形B .等腰三角形C .直角三角形D .等腰直角三角形 8.已知f (x )是以2为周期的偶函数,且当x ∈(0,1)时,2()21,(log 12)x f x f =-则=A .13B . 43C .2D .119.己知函数y=f (x )在定义域[-4,6]内可导,其图象如图,记y=f (x )的导函数为()y f x '=,则不等式()0f x '≥的解集为A .411[,1][,6]33-B .7[3,0][,5]3-C .411[4,][1,]33-- D .[4,3][0,1][5,6]- 10.已知△ABC 和点M 满足关系式0MA MB MC ++=,若存在实数m 使得AB AC mAM +=,则实数m 等于A . 2B . 3C . 4D . 5 11.以下有关命题的说法错误的是A .命题“若2320,1x x x -+==则”的逆否命题为“若x ≠l ,则x 2-3x+2≠0”B .“x=2”是“x 2 -5x+6=0”的充分不必要条件C .若p q ∧为假命题,则p ,q 均为假命题D .对于命题p :22,10,:,10x R x x p x R x x ∃∈++<⌝∀∈++≥使得则均有 12.设x ,y 满足条件20360,(0,0)0,0x y x y z ax by a b x y -+≥⎧⎪--≤=+>>⎨⎪≥≥⎩若目标函数的最大值为12,则32a b +的最小值为A .256B .83C .113D .4第Ⅱ卷(非选择题共90分)注意事项:1.第Ⅱ卷包括填空题和解答题共两个大题.2.第II 卷所有题目的答案考生需用黑色签字笔答在数学答题纸指定的位置.二、填空题:(本大题共4个小题,每小题.4分,共16分)13.当1{1,,1,3},2∈-时幂函数a y x =的图象不奇能经过第 象限。

山东省青岛市2013届高三上学期期中考试英语试题

山东省青岛市2013届高三上学期期中考试英语试题

山东省青岛市2013届高三上学期期中考试英语试题第Ⅰ卷(共105分)第一部分:听力(共两节,满分30分)该部分分为第一、第二两节。

注意:回答听力部分时,请先将答案标在试卷上。

听力部分结束前,你将有两分钟的时间将你的答案转涂到客观题答题卡上。

第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. How does the man feel about Yorkshire?A. He doesn't enjoy the weather.B. He likes everything about it.C. He likes the rain there.2. What are the two speakers doing?A. Complaining about the weather.B. Discussing which month is the hottest.C. Talking about their favorite month.3. Where does the conversation most probably take place?A. At a hospital.B. At a library.C. At a bookstore.4. What will the woman do first?A. Send the e-mail.B. Type the paper.C. Make a call.5. What can we learn from the conversation?A. The plane crashed into the sea.B. Wood survived the air-crash.C. Wood has just been back from a holiday.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。

  1. 1、下载文档前请自行甄别文档内容的完整性,平台不提供额外的编辑、内容补充、找答案等附加服务。
  2. 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
  3. 3、如文档侵犯您的权益,请联系客服反馈,我们会尽快为您处理(人工客服工作时间:9:00-18:30)。

上海市三林中学2013学年度第一学期高三期中考试英语试题第Ⅰ卷(共103分)I. Listening ComprehensionPart A Short ConversationsDirections: In Part A, you will hear ten short conversations between two speakers. At the end of each conversation, a question will be asked about what was said. The conversations and the questions will be spoken only once. After you hear a conversation and the question about it, read the four possible answers on your paper, and decide which one is the best answer to the question you have heard.1. A .Student and teacher B. Secretary and bossC. Librarian and readerD. Patient and nurse2. A. The food will arrive shortly B. He‘ll order his food later.C. He‘s ready to order now.D. He has many friends.3. A. At 10:20 B. At 10:30 C. At 10:50 D. At 11:204. A. Have a celebration party B. Interview a personC. Accept a new jobD. Go for a job interview5. A. Not to quit baseball practice B. Not to worry about his gradesC. To get them baseball game ticketsD. To spend more time on his studies6. A. Towels cannot be taken out of the room. B. Towels can be bought at the poolside.C. Towels are offered at the poolside.D. Towels cannot be taken out of the pool.7. A. Make the request some other day B. Comfort the boss firstC. Have lunch with the bossD. Pay for the lunch8. A. The car is faulty. B. The car looks funny.C. The garage is too noisy.D. The car needs washing.9. A. She‘s still looking for an apartment. B. She was told the dormitory was full.C. She doesn‘t plan to move back at all.D. She wants to move out of the dormitory.10. A. The woman wants to use the phone. B. The man is disturbing others.C. Mobile phones are banned inside.D. Phone signals are weak inside.Part B Passages Questions 11 through 13 are based on the following passage.11. A. The plane was stuck in a tree B. The pilot worried about the strong wind.C. The plane lost both its wheels.D. The pilot was injured in the air crash.12. A. On top of a tree B. On top of a fire engineC. On top of the airport buildingD. On top of a lorry13. A. An unusual air crash B. A magic landingC. A brave firemanD. A damaged lorryQuestions 14 through 16 are based on the following news14. A. 87 billion dollars B. 87 million dollarsC. Hundreds of billions of dollarsD. One billion dollars15. A. By developing foreign markets B. By providing financial aidC. By cutting labour and material costsD. By reducing income taxes16. A. Produce more cars B. Buy more booksC. Try to regain creditD. Start to save moneyPart C Longer ConversationsComplete the form. Write ONE WORD for each answer.Complete the form. Write NO MORE THAN THREE WORDS for each answer.II. Grammar and VocabularySection ADirections:Read the following two passages. Fill in the blanks to make the passage coherent. For the blanks with a given word, fill in each blank with the proper form of the given word. For the other blanks, fill in each blank with one proper word. Make sure that your answers are grammatically correct. (16)AA boy was walking home from school (25) ____ he saw a large, tempting apple on one of the branches of an apple tree hanging out over a tall fence. The boy wasn‘t much of a fruit-eater, preferring a bar of chocolate if (26) ____( give) the choice, but, as they say, the forbidden fruit can be tempting. Seeing the apple, the boy wanted it. The more he looked at it, the (27) ______( hungry )he felt and the more he wanted that apple.He stood on tiptoe(脚尖), stretching as high as he could , but even at his tallest length, he was unable to touch It. He began to jump up and down, as high as he could, at the top of each jump stretching his arms to get the apple. Still it remained (28) _____ ______ reach.Not giving up, he thought, if only he had something to stand on. (29) _____(look) around, he hoped he might find an old box, a rock, or with luck, even a ladder, but it was a tidy neighborhood and there was nothing he could use. He had tried everything he could think to do. Without seeing any other choices, he gave up and started to walk (30) _____. At first he felt angry and disappointed thinking about how hungry he had become from his efforts, and how he really wanted that apple. The more he thought like this, the more unhappy he became.However ,the boy of our story was a pretty smart guy, even if he couldn‘t always get (31) ____ he wanted .He started to say to (32) _____ .This isn‘t helpful , I don‘t have the apple and I‘m feelingmiserable as well. There‘s nothing more I can do to get the apple —that is unchangeable —but we are supposed to be able to change our feelings. If that‘s the case, what can I do to feel better?BA Love Note to My MomWhen I was a little girl, I would often accompany you as you modeled for fashion photographers.It was years later (33)_____ I finally understood what role modeling played in your life.Little did I know you were saving every penny you earned (34)____ (go) to law school.I cannot thank you enough (35)_____ what you told me one autumn afternoon when I was nine.After finishing my homework, I wandered into the dining room where you (36)____(bury) under piles of law books.I was puzzled.Why were you doing what I do—memorizing textbooks and studying for tests? When you said you were in law school, I was more puzzled.I didn‘t know Moms (37)_____ be lawyers too.You smiled and said, ―In life, you can do anything you want to do.‖As young as I was ,that statement kept ringing in my ears.I watched as you faced the challenges of completing your studies, starting companies with Dad, while still being a model and (38) _____ Mom of five kids.I was exhausted just watching you in action.With your words of wisdom in my youthful mind, I suddenly felt unlimited freedom to dream.My whole world opened up.I set out(39)____ ( live) my life filled with hope ,seeing endless possibilities for personal and professional achievements.Your words became my motto.I constantly found myself in the unique position of being either the first (woman doctor in Maryland Rotary)(40)____ one of the few women (chief medical reporters)in my field.I gained strength every time I said , ―Yes, I‘ll try that.‖Encouraged by your statement, I have forged ahead (毅然前行)with my life‘s journey, less afra id to make mistakes, and eagerly meeting each challenge.You did it, and now I‘m doing it.Sorry, got to run.So much to do, so many dreams to liveSection B: Vocabulary (10)Directions: Complete the following passage by using the words in the box. Each word can only be used―True creativity often starts where language ends.‖---Arthur KoestlerThe net plays another, more active, role on the linguistic(语言学的)front, a role that is 41by many people who believe English victory is on the go. Since the advent of World Wide Web, many minority languages,those spoken by single nations or ethnic groups, have enjoyed a dramatic upsurge(急剧上升)in vitality. Many such tongues were 42 endangered just a decade ago. Late-century 43 and economic currents were taking more and more speakers out of their communities and away from fellow speakers. Languages were 44at an alarming rate.Like biological extinction, linguistic extinction is a serious loss for all of humankind. Languages are some of the 45ways people maintain their culture and are crucial to understanding other cultures. When fewer and fewer people share a 46language, it may die, and when it does, part of our collective human culture dies with it.Surprisingly, though, the Internet has become a valuable tool for 47 endangered languages. Speakers of these languages not only have been particularly active in putting up web pages in theirvarious languages, but also in mounting (配置) 48effective, large-scale dictionary and language-learning projects online. There is no reason why ___49___ languages cannot live together with a common social language like English. Indeed, the Internet offers more hope for their 50 than they have ever known before, especially as translation tools become more effective.III. Reading ComprehensionSection A: Cloze test: (15)Directions: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context.The concept of solitude (独处) in the digital world is almost non-existent. In the world of digital technology, e-mail, social networking and online video games, information is meant to be _51___. Solitude can be hard to discover once it has been given up. In this respect, new technologies have _52___ our culture.The desire to be connected has brought solitude to an end as we've known it. People have become so __53___ in the world of networks and connections that one can often be contacted __54___ they'd rather not be. Today we can talk, text, e-mail, chat and blog(写博客), not only from our _55____ but from our mobile phones as well.Most developed nations have become 56 on digital technology simply because they've grown accustomed to it, and at this point not using it would make them an outsider. 57 , many jobs and careers require people to be__58___. From this point of view, technology has changed the culture of work. Being reachable might feel like a 59 to those who may not want to be able to be contacted at all times.I suppose the positive side is that solitude is still possible for anyone who really wants it. Computers can be shut 60 and mobile phones can be turned off. The ability to be "connected" and "on" has many advantages as well as disadvantages. Travelers have ended up 61 on mountains, and mobile phones have saved countless lives. They can also make people feel 62 and forced to answer unwanted calls or 63 to unwanted texts.Attitudes towards our connectedness as a society 64 across generations. Some find today's technology a gift. Others consider it a curse. Regardless of anyone's view on the subject, it's hard to imagine what life would be like 65 daily advancements in technology.51. A. updated B. received C. shared D. collected52. A. respected B. shaped C. ignored D. preserved53. A. sensitive B. intelligent C. considerate D. reachable54. A. even if B. only if C. as if D. if only55. A. media B. computers C. databases D. monitors56. A. bent B. hard C. keen D. dependent57. A. Also B. Instead C. Otherwise D. Somehow58. A. connected B. trained C. recommended D. interested59. A. pleasure B. benefit C. burden D. disappointment60. A. out B. down C. up D. in61. A. hidden B. lost C. relaxed D. deserted62. A. trapped B. excited C. confused D. amused63. A. turn B. submit C. object D. reply64. A. vary B. arise C. spread D. exist65. A. beyond B. within C. despite D. withoutSection BDirections: Read the following three passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage you have just read. (24)ASome years ago, writing in my diary used to be a usual activity. I would return from school and spend the expected half hour recording the day‘s events, feelings, and impressions in my l ittle blue diary.I did not really need to express my emotions by way of words, but I gained a certain satisfaction from seeing my experiences forever recorded on paper. After all, isn‘t accumulating memories a way of preserving the past?When I was thirteen years old, I went on a long journey on foot in a great valley, well-equipped with pens, a diary, and a camera. During the trip, I was busy recording every incident, name and place I came across. I felt proud to be spending my time productively, dutifully preserving for future generations a detailed description of my travels. On my last night there, I wandered out of my tent, diary in hand. The sky was clear and lit by the glare of the moon, and the walls of the valley looked threatening behind their screen of shadows. I automatically took out my pen….At that point, I understood that nothing I wrote could ever match or replace the few seconds I allowed myself to experience the dramatic beauty of the valley. All I remembered of the previous few days were the dull characterizations I had set down in my diary.Now, I only write in my diary when I need to write down a special thought or feeling. I still love to record ideas and quotations that strike me in books, or observations that are particularly meaningful. I take pictures, but not very often—only of objec ts I find really beautiful. I‘m no longer blindly satisfied with having something to remember when I grow old. I realize that life will simply pass me by if I stay behind the camera, busy preserving the present so as to live it in the future.I don‘t want to wake up one day and have nothing but a pile of pictures and notes. Maybe I won‘t have as many exact representations of people and places; maybe I‘ll forget certain facts, but at least the experiences will always remain inside me. I don‘t live to make memories—I just live, and the memories form themselves.66. Before the age of thirteen, the author regarded keeping a diary as a way of ______.A. observing her school routineB. expressing her satisfactionC. impressing her classmatesD. preserving her history67. What caused a change in the author‘s understanding of keeping a diary?A. A dull night on the journey.B. The beauty of the great valley.C. A striking quotation from a book.D. Her concerns for future generations.68. What does the author put in her diary now?A. Notes and beautiful pictures.B. Special thoughts and feelings.C. Detailed accounts of daily activities.D. Descriptions of unforgettable events.69. The author comes to realize that to live a meaningful life is ______.A. to experience itB. to live the present in the futureC. to make memoriesD. to give accurate representations of itBFinally, a cell phoneThat's… a phoneWith rates as low as $3.75 per week !―Well, I finally did it. I finally decided to enter the digital age and get a cell phone. My kids have been annoying me and the last straw was when my car broke down, and I was stuck by the highway for an hour before someone stopped to help. But when I went to the cell phone store, I almost changed my mind. The phones all have cameras, computers and a "global-positioning" something or other that's supposed to spot me from space. Goodness, all I want to do is to be able to talk to my grandkids !The people at the store weren't much help. They couldn't understand why someone wouldn't want a phone the size of a postage stamp. And the rate plans! They were confusing and expensive… and the contract (合同)lasted for two years! I'd almost given up until a friend told me about her new Jitterbug phone. Now, I have the convenience and safety of being about to stay in touch with a phone I can actually use.Affordable plans that I can understand and no contract to sign (签订)!Unlike other cell phones,Jitterbug has plans that make sense. Why shoul d I pay for minutes I‘m never going to use? And if I do talk more than I plan,I won‘t find myself with no minutes like my friend who has a prepaid phone. Best of all, there is no contract to sign, so I‘m not locked in for years at a time. The US-based customer servicet love it, just return it! Why wait, the Jitterbug comes ready to -use right out of the box. If you aren't as happy with it as I am, you can return it and get your money back. Call now, the Jitterbug product experts are ready to answer your questions.Call 1-888-809-8794 or visit www. jitterbugdirect. com.70. What made ―I‖ finally think of getting a cell ph one?A. Being stuck by the highway.B. Being urged by his grandkids.C. B eing persuaded by cell phone salespersons.D. Being attracted by the friendly return policy.71. On the monthly basis of 100 minutes, the Jitterbug weekly rate is about .A. $3.75B. $4.99C. $14.99D. $19.9972. An advantage of Jitterbug mentioned in the passage is .A. its discount price with a free giftB. its reasonable rate plans without a contractC. its M global-positioning" system with 911 accessD. i ts good customer service all over the world73. The main purpose of the passage is to .A. t ell a customer's story of JitterbugB. provide two ways to order JitterbugC. g ive a brief introduction of JitterbugD. attract potential customers to Jitterbug;CMany people think that listening is a passive business. It is just the opposite. Listening well is anactive exercise of our attention and hard work. It is because they do not realize this, or because they are not willing to do the work, that most people do not listen well.Listening well also requires total concentration upon someone else. An essential part of listening well is the rule known as ‗bracketing‘. Bracketing includes the temporary g iving up or setting aside of your own prejudices and desires, to experience as far as possible someone else‘s world from the inside, stepping into his or her shoes. Moreover, since listening well involves bracketing, it also involves a temporary acceptance of the other person. Sensing this acceptance, the speaker will seem quite willing to open up the inner part of his or her mind to the listener. True communication is under way and the energy required for listening well is so great that it can be accomplished only by the will to extend oneself for mutual growth.Most of the time we lack this energy. Even though we may feel in our business dealings or social relationships that we are listening well, what we are usually doing is listening selectively. Often we have a prepared list in mind and wonder, as we listen, how we can achieve certain desired results to get the conversation over as quickly as possible or redirected in ways more satisfactory to us. Many of us are far more interested in talkin g than in listening, or we simply refuse to listen to what we don‘t want to hear.It wasn‘t until toward the end of my doctor career that I have found the knowledge that one is being truly listened to is frequently therapeutic(有疗效的) In about a quarter of the patients I saw, surprising improvement was shown during the first few months of psychotherapy(心理疗法), before any of the roots of problems had been uncovered or explained. There are several reasons for this phenomenon, but chi ef among them, I believe, was the patient‘s sense that he or she was being truly listened to, often for the first time in years, and for some, perhaps for the first time ever.74. The phrase ―stepping into his or her shoes‖ in paragraph 2 probably means _______.A. preparing a topic list firstB. focusing on one‘s own mindC. directing the talk to the desired resultsD. experiencing the speaker‘s inside world75. What is mainly discussed in Paragraph 2 ?A. How to listen well.B. What to listen to.C. Benefits of listening.D. Problems in listening76. According to the author , in communication people tend to ________.A. listen activelyB. listen purposefullyC. set aside their prejudicesD. open up their inner mind77. According to the author , the patients improved mainly because _______.A. they were taken good care of.B. they knew they were truly listened to.C. they had partners to talk to.D. they knew the roots of problems.Section CDirections: Read the passage carefully. Then answer the questions or complete the statements in the fewest possible words. (8)This article is designed to help you understand why you should always call the authorities to the scene of an accident in which you were injured and why the insurance company you may be facing will hate that you did so!When you call the police to the scene of your accident, then the police will require the drivers involved to exchange insurance and identification information the police may also obtain witness information and preserve statements about the event, including descriptions of what occurred andcomplaints of injury. All of this information will very likely assist you in the future with your claim and hurt the insurance company‘s ability to deny your claim. By calling the police, you have made an official record of the event and can be relatively sure that the information you receive about the other driver is accurate and truthful.This official record will effectively prevent the other driver‘s insurance company from arguing that the incident did not occur or that their insured driver was not involved in the cause of your injuries. (Yes, insurance companies will deny responsibility at every opportunity, including whether their driver was even in the accident with you.) Finally, statements from witnesses or the other driver may contain valuable facts that may be later forgotten or can be used to make up a“changed story.‖ I don‘t know how many times I have been told by my clients that the other person admitted fault at the scene, but later hear from the insurance company that no such statement was made and that the cause of the accident was contested.(You may not be aware of this, but I will bet that your own automobile insurance card contains the following instruction: Do not admit fault for the accident Remember, the insurance companies hate it when their drivers take responsibility for the accident because it damages their ability to deny or effectively defend your claim. After all, these companies are in business to make lost of money not to pay it to you!) If you follow this rule, then you are a step ahead in the game and you will have a much better chance of successfully making you automobile accident personal injury claim.(Not: Answer the questions or complete the statements in NO MORE THAN TWELVE WORDS.)78. The information related to a car accident is collected by the police to ________.79. If witness statements are not recorded officially, the relevant facts may________.80. What can you do when you have called the police to the scene?81. Why don‘t the insurance companies want you to admit fault for the accident?第Ⅱ卷I. Translation (22)Directions: Translate the following sentences into English, using the words given in the brackets.1.任何为祖国建设做出贡献的人都值得尊敬。

相关文档
最新文档