通信高级工试题
通信高级工电子题库
一、选择题1、数字传输系统与数字交换系统采用的标准接口是（B ）。
A、64Kb/SB、2048Kb/SC、139264Kb/SD、155.520Mb/S2、直埋通信光缆与管孔30--50CM给水管平行时最小净距为（B）。
A、0.5MB、1.0MC、1.5MD、2.0M3、直埋通信光缆与管径大于50CM给水管平行时最小净距为（C）。
A、0.5MB、1.0MC、1.5MD、2.0M4、直埋通信光缆与排水管平行时最小净距为（D）。
A、0.5MB、0.6MC、0.7MD、0.8M5、TDCS系统每块CDIB采集板可以采集到（B）路交流24V信号。
A、16B、32C、48D、646、TDCS系统AIO主板上集成（B）个RS232接口。
A、1B、2C、3D、47、TDCS机柜温控器温度一般选择为（A）左右。
A、20°B、25°C、27°D、30°8、TDCS机柜安装在（D）。
A、通信机械室B、运转室C、信号工区D、信号机械室9、计算机系统中“防火墙”可以（C）。
A、放电源断电B、防火C、防黑客攻击D、防网线断线10、在施工现场最终评价一个接头，确定是否需要重新接续，是靠（ D ）。
来测定接头损耗值来确定的。
A、光功率计B、熔接机C、红光笔D、OTDR11、对于接头质量评价描述错误的是（B ）。
A、如工程要求平均连接损耗为0.1dB，内控指标可按0.08dB要求B、对测试值大于0.08dB的接头，一般不要求重新连接C、对于测试值为负的接头，一般应看其绝对值大小。
D、对损耗较大时，应作重新接续。
12、在光纤线路损耗测量中，哪两中仪表不可缺少（ C ）。
A、熔接机、光源B、光功率计、OTDRC、光源、光功率计D、OTDR、熔接机13、光纤信号曲线完整正确的叫法为（ C）A、光纤前向散射信号曲线B、光纤后向发射信号曲线C、光纤时域反射波形D、光纤曲线14、一个典型的电话网络是由互相连接的端局组成的。
(完整word版)铁路通信工题库技能鉴定高级(现场综合维护)
82.雅企610(E1/V.35)按下DIG 为向邻站环回，从本端的V.35(不包括V.35接口电缆)向E1口方向环回，用于68-68+固有损耗302.SDH传输中，最基本的传送模块是_________ STM- 1306.铁路调度指挥系统我们通常用_________表示TDCS309.铁塔单独设置防雷接地体时，接地电阻应不大于_________ 10Ω310.通道测试的最主要指标是_________、衰耗误码率322.800HZ时，会议电话总机的输出输入阻抗应为_________ 600+120325.影响视频比特率的因素: 图像宽度、图像高度、颜色深度、帧率、__________ 压缩因子327.电视电话会议系统呼叫频率是_________HZ 1920353.会议设备所用电源应采用单独供电,供电电源需设总开关，并加__________电源保UPS357. ____________负责小区中的信道分配BSC 基站控制器363.STM-1帧结构由: 段开销、信息净负荷、________________三部分组成管理单元指针366.雅企610(E1/V.35)在面板上打环时,按下__________为向本地环回，从本端的E1口向V.35口环回，用于检测本端设备及连接线是否正常ANA368.直放站漏缆监控接收最低门限值为__________.dBm -60371.基站无线系统中距载频200 kHz以外处绝对功率电平不大于_______dBm -36376.GSM-R维规要求漏缆驻波比测试周期为__________ 1次/年383.目前建成的铁路IP骨干网分为分为核心层、汇聚层、__________三层结构接入层389.分系统环路接口要求外线阻抗为_______W 75390.用以太网方式做网管时，需要接____________接口Ethernet393.视频前端设备主要由编码器、_______________和相关的线缆组成摄像机396.华为0ptix 155/622设备在插板区IU1~IU4槽位不可以插__________。
通信高级工技能鉴定试题.docx
保护接零是指电气设备在正常悄况下不帶电的 ________ 部分与电网的保护接零相互连接。
答案：金属从人体触及带电体的方式和电流通过人体的途径，触电可分为：_________ 、两相触电和跨步电压触电。
答案：单相触电在1S0/0S1参考模熨屮，数据链路层是第______ 层。
答案：2G. 652光纤是零色散波长在_______ 的单模光纤。
答案：1310nmSDH是指________ o答案：准同步数字体系要将交流220V电源转换成稳定的-48V «流电源输出，一般需经过___________ 、幣流、滤波和稳压四个步骤。
答案：变压按信令的作用区域划分，可分为 __________ 和局间信令。
答案：用户线信令光纤按传输总模数对分为 ________ 和多模光纤。
答案：单模光纤OST参考模型中的第一层为。
答案：物理层模拟通信可采用 _______ 、调频、调相等多种调制方式答案：调幅SDH传输网屮所采用的网络结构冇很多种，其屮_______ 结构方具冇其正意义上的H愈功能。
答案：环形所谓调制即是用话音信号公控制连续高频波的 ________ 或相位，或频率等参数的过程。
答案：幅度如信号最高频率是f=3400HZ,那么抽样频率应等于或大于__________ ,才能满足抽样定理的要求。
答案：6800HZ使用压扩技术，充分利用了载波机发信的 ____________ 。
答案：功率容量采用电平调节系统，能保证电路传输电平能经常处于状态。
答案：良好在电力载波系统中，为了保证通话消晰度，要求通路信号杂音比最低不得小于_____________ 答案：26dB所谓载波设备处丁•极限条件工作，一般是指 _______ 处丁•绘人值。
答案：衰耗电力载波通信的传输介质为 _______ 。
答案：电力线阻波器的作用为阻止高频信号流向与通道 __________ 方向。
答案：反按现行装备来看，通道结合设备主耍是指 __________ 和接地刀闸。
高级通信工程师考试复习题
通信英语强化训练试题（一）Ⅰ 单项选择题：(Choose the best one)( )1.Furthermore, we shall prove that a minimum theoretical sampling frequency of order 6. 8 kHz is required _________a voice channel_________the range 300Hz to 3. 4 kHz.A. convey, occupyB. to convey, occupyingC. conveying, occupiedD. convey, to occupy( )2.For example, the signal _________from a satellite, _________in far outer space, is very weak.A. received, locatedB. receive, locateC. receiving, locatingD. to receive, to locate ( )3.If we consider binary transmission, the complete information about a particular message will always _________by simply_________the presence or absence of the pulse.A. obtain, detectB. be obtained, detectingC. obtained, detectedD. obtaining, detected ( )4. 4. There is an inherent advantage for _________noisy environments by _________digital transmission.A. overcoming, chooseB. overcome, choosingC. overcome, chooseD. overcoming, choosing( )5.Each voice channel has a separate coder，the unit _________converts sampled amplitude values to a set of pulses;And decoder, the unit _________performs the reverse operation.A. who, whoB. when, whenC. where, whereD. that, that( )6.The problem is easily overcome by _________a frame format, where at the start of each frame a unique sequence of pulsesis placed _________the start of the frame.A. specify, identifyB. specifying, so as toidentifyC. specified, identifiedD. specify, identifying ( )7.An asynchronous serial data link is said _________character oriented，as information is transmitted in the form of groupsof bits _________characters.A. be，callingB. to being，to callC. been，callD. to be，called( )8.This interface is so called because the _________data and the _________data are not synchronized over any extended period.A. transmit，receiveB. to transmit，to receiveC. transmitting，receivingD. transmitted，received ( )9.Serial data transmission systems _________in the telephone，Morse code, and even the smoke signals once _________by nativeAmericans.A. are finding，usingB. are found，usedC. find, useD. be found, using( )10.Traditionally，the idle state _________the mark level. Byconvention this corresponds _________a logical 1 level.A. is referred to, asB. is referred as, inC, is referred to as, to D. is referred，within ( )11.The transmitter then sends the character，1 bit at a time，by _________each successive bit on the line for a duration ofT seconds, _________all bits have been transmitted.A. place, stillB. placed，sinceC. placing, untilD. placing，because( )12.When the data link connects a CRT terminal _________a computer，_________problems arise, as the terminal is itself characteroriented.A. into, manyB. on，a fewC. in, a fewD. to，few( )13._________the receiving end of a synchronous serial data link，the receiver continually monitors the line _________a startbit.A. On，lookingB. Within，look forC. In, look atD. At，looking for( )14.As companies realized they could save money and gain productivity by _________networking technology, they addednetworks and expanded _________networks almost as rapidly asnew network technologies and products could be introduced.A. use, existB. using, existingC. to use, to existD. used, existed( )15.The OSI reference model allows you _________the network functions that occur at each layer. More importantly, the OSIreference model is a framework you can use _________howinformation travels throughout a network.A. view, understandB. viewing, understandingC. viewed, understoodD. to view, to understand ( )16.The transport layer segments data from the _________host’s system and reassembles the data into a data stream on the_________host’s system.A. sending, receivingB. to send, to receiveC. sent, receivedD. send, receive( )17.The data link layer provides the transit of data _________a physical link. In so doing, the data link layer is concerned_________physical addressing, network topology, network mediaaccess, and error detection.A. with, acrossB. at, inC. between, inD. across, withⅡ短语英译汉：(Translate the following phrases into Chinese)1.the schemes for performing these three functions2. a series of amplitude values3. a speech channel of telephone quality4. a sequence of 8-binary digits5. a minimum theoretical sampling frequency6. a voice channel occupying the range 300 Hz to 3. 4 kHz7.8-digits per sample value8.the sparking of a car ignition system9.the stream of the pulses with a repetition rate of 64 kHz10.the relationship of the true signal to the noise signal11.the signal received from a satellite12.the complete information about a particular message13.the shape of the transmitted signal14.the attenuation introduced by transmission path15.the unit that converts sampled amplitude value to a set of pulses16. a sequence relating to channel 1,2 and so on17. a unique sequence of pulses called synchronization word18.terrestrial system19.the presence or absence of the pulse20. a high-speed electronic switch21.the time division multiplexer22.Time Division Multiplexing23.asynchronous serial data transmission24.the most popular serial interface25.the transmitted data26.the clocks at the transmitter and receiver27.the era of teleprinter28.the dots and dashes of a character29.three times the duration of intersymbol space30.the group of bits called characters31.the invariable units comprising 7 or 8 bits of information32. a clock generated locally by the receiver33.the received parity bit following the character34.the falling edge of the start bit35.the character-oriented nature of the data linkworking technology37.proprietary networking system38.the International Organization for Standardizationpatibility between the various types of networks40.seven numbered layers41.standardization of network components42.error recovery43.receiving host's system44.connection-oriented circuitsrmation flow controlwork topologywork media access48.electrical specification49.maximum transmission distanceⅢ短语汉译英：(Translate the following phrases into English)1.抽样量化与编码2.话路3.幅值4.抽样频率5.抽样速率6.脉冲流7.重复率8.编码过程9.模拟信号10.传输质量11.数字通信12.数字传输13.含噪声的环境14.传输路由15.信噪比16.信号电平17.地面系统18.噪声功率19.二进制传输20.反向操作21.8位码序列22.接收端23.帧格式24.同步字25.串行接口26.显示终端27.发送器与接收器28.数据传输29.数据流30.闲置状态31.传号电平32.空号电平33.起始位34.停止位35.T秒的持续时间36.奇偶校验位37.错误标记38.传输错误39.下降沿40.符号间的空格41.接收机的定时42.本地时钟43.磁带44.限制比特45.逻辑1电平46.二进制数据47.明显的缺点48.联网技术49.国际标准化组织50.参考模型51.数据分组52.应用程序53.网络媒体54.分层55.硬件和软件56.表示层57.传输层58.数据链路层59.网络服务60.文件接入61.数据格式62.主机63.协议64.连接65.逻辑选址Ⅳ请将下述短文译成中文（短文英译汉）：(Translate the following passages into Chinese)1.If we consider binary transmission, the complete informationabout a particular message will always be obtained by simply detecting the presence or absence of the pulse. By comparison, most other forms of transmission system convey the message information using the shape, or level of the transmitted signal; parameters that are most easily affected by the noise and attenuation introduced by the transmission path. Consequently there is an inherent advantage for overcoming noisy environments by choosingdigital transmission.2.The reader may ask, how does the demultiplexer know which group of 8-digits relates to channel 1, 2, and so on? Clearly this is important! The problem is easily overcome by specifying a frame format, where at the start of each frame a unique sequence of pulses called the frame code, or synchronization word, is placed so as to identify the start of the frame. A circuit of the demultiplexer is arranged to detect the synchronization word, and thereby it knows that the next group of 8-digits corresponds to channel 1.3.Noise can be introduced into transmission path in many different ways; perhaps via a nearby lightning strike, the sparking of a car ignition system, or the thermal low-level noise within the communication equipment itself. It is the relationship of the true signal to the noise signal, known as the signal-to-noise ratio, which is of most interest to the communication engineer.4.Basically, if the signal is very large compared to the noise level, then a perfect message can take place; however, this is not always the case. For example, the signal received from a satellite, located in far outer space, is very weak and is at a level only slightly above that of the noise. Alternative examples may be. Found within terrestrial systems where, although the message signal is strong, so is the noise power.5.So far we have assumed that each voice channel has a separate coder, the unit that converts sampled amplitude values to a set of pulses; and decoder, the unit that performs the reverseoperation. This need not be so, and systems are in operation where a single codes is shared between 24, 30, or even 120 separate channels.6. A high-speed electronic switch is used to present the analog information signal of each channel, taken in turn, to the codec. The codec is then arranged to sequentially sample the amplitude value, and code this value into the 8-digit sequence. Thus the output to the codec may be seen as a sequence of 8 pulses relating to channel 1, then channel 2, and so on. This unit is called a time division multiplexer.7.An asynchronous serial data link is said to be character-oriented, as information is transmitted in the form of groups called characters. These characters are invariable units comprising 7 or 8 bits of information plus 2 to 4 control bits and frequently correspond to ASCII-encoded characters. Initially, when no information is being transmitted, the line is in an idle state. The idle state is referred to as the mark level and corresponds to a logical 1 level.8.When the transmitter wishes to send data, it first places the line in a space level for one element period. The transmitter then sends the character, 1 bit at a time, by placing each successive bit on the line for a duration of T seconds, until all bits have been transmitted. Then a single parity bit is calculated by the transmitter and sent after the data bits. Finally, the transmitter sends a stop bit at a mark level for one or two bit period.9.At the receiving end of an asynchronous serial data link, the receiver continually monitors the line looking for a start bit. Once the start bit has been detected, the receiver waits until the end of the start bit and then samples the next N bits at their centers, using a clock generated locally by the receiver. As each incoming bit is sampled, it is used to construct a new character.10.The most obvious disadvantage of asynchronous data transmission is the need for a start, parity, and stop bit for each transmitted character. If 7 bit characters are used, the overall efficiency is only 70 percent. A less obvious disadvantage is due to the character-oriented nature of the data link. Whenever the data link connects a CRT terminal to a computer, few problems arise,as the terminal is itself character oriented.11.The most critical aspect of the system is the receiver timing. The falling edge of the start bit triggers the receiver's local clock, which samples each incoming bit at its nominal center. Suppose the receiver clock waits T/2 seconds from the falling edge of a start bit and samples the incoming data every T seconds thereafter until the stop bit has been sampled. As the receiver's clock is not synchronized with the transmitter clock, the sampling is not exact.12.By far the most popular serial interface between a computer and its CRT terminal is the asynchronous serial interface. This interface is so called because the transmitted data and the receiveddata are not synchronized over any extended period and therefore no special means of synchronizing the clocks at the transmitter and receiver is necessary. In fact, the asynchronous serial data link is a very old form of data transmission system and has its origin in the era of the teleprinter.13.Most computer terminals transmit and receive ASCII characters, and we know that the ASCII characters require 7 bits. Therefore, 7 bits of data plus a parity bit are sent each time a character is transmitted or received by the terminal. The two most obvious ways to send the characters are by parallel transmission or by serial transmission. Most terminals have been designed to transmit and receive ASCII characters as serial data.14.The early development of LANs, MANs, and WANs was chaotic in many ways. The early 1980s saw tremendous increases in the numbers and sizes of networks. As companies realized they could save money and gain productivity by using networking technology, they added networks and expanded existing networks almost as rapidly as new network technologies and products could be introduced.15.Proprietary systems are privately developed, owned, and controlled. In the computer industry, proprietary is the opposite of open. Proprietary means that one or a small group of companies controls all usage and evolution of the technology. Open means that free usage of the technology is available to the public.16.The OSI reference model allows you to view the network functions that occur at each layer. More importantly, the OSI reference model is a framework you can use to understand how information travels throughout a network. In addition, the OSI reference model can be used to visualize how information, or data packets, travels from application programs, through a network medium, to other application programs that are located in another computer on a network, even if the sender and the receiver have different types of network media.17.The application layer is the OSI layer that is closest to the user. It provides network services, such as and printing, to the user’s applications. It differs from the other layers in that it does not provide services to any other OSI layer, but rather, only to applications outside the OSI model. The application layerestablishes the availability of intended communication partners. It also synchronizes and establishes an agreement on procedures for error recovery and control of data integrity.18.The transport layer attempts to provide a data transport service that shields the upper layers from transport implementation details. Specifically, such issue as how reliable transport between two hosts is accomplished in the concern of the transport layer. In providing communication service, the transport layer establishes, maintains, and properly terminates connection-oriented circuits. In providing reliable service, transport errordetection-and-recovery and information flow control are used.19.The physical layer defines the electrical, mechanical,procedural, and functional specifications for activating, maintaining, and deactivating the physical link between end systems. Such characteristics as voltage levels, timing of voltage changes, physical data rates, maximum transmission distances, physical connectors, and other, similar, attributes are defined by physical layer specifications.Ⅴ阅读理解：(True or false statement) According to the following text's decide whether the statements following the texts are true (T) or false (F)PASSAGE ONEDigital transmission provides a powerful method for overcoming noisy environments. Noise can be introduced into transmission path in many different ways: perhaps via a nearby lightning strike, the sparking of a car ignition system, or the thermal low-level noise within the communication equipment itself. It is the relationship of the true signal to the noise signal, known as the signal-to-noise ratio, which is of the most interest to the communication engineer. Basically, if the signal is very large compared to the noise level,then a perfect message can take place; however, this is not always the case. For example, the signal received from a satellite, located in far outer space, is very weak and is at a level only slightly above that of the noise. Alternative examples may be found within terrestrial systems where, although the message signal is strong, so is the noise power.If we consider binary transmission, the complete information about a particular message will always be obtained by simply detecting the presence or absence of the pulse. By comparison, most other forms of transmission systems convey the message information using the shape, or level of the transmitted signal; parameters that are most easily affected by the noise and attenuation introduced by the transmission path. Consequently there is an inherent advantage for overcoming noisy environments by choosing digital transmission. ( )1.If the true signal is very large compared to the noise level, then the information with higher quality can beobtained.( )2.If we consider binary transmission, the complete information about a particular message will always beobtained by detecting the shape of the transmitted signalor by calculating the parameters of the transmittedsignal.( )3.It is the signal-to-noise ratio which is of the most interest to the communication engineer.( )4.Digital transmission provides the signal-to-noise ratio, which is a very important parameter, for overcoming noisyenvironments.( )5.The signal gotten from a satellite is generally very weak. ( )6.The shape of the transmitted signal are most easily affected by the noise and attenuation introduced by thecodec.PASSAGE TWOSo far we have assumed that each voice channel has a separate coder, the unit that converts sampled amplitude values to a set of pulses; and decoder, the unit that performs the reverse operation. This need not be so, and systems are in operation where a single codec (i.e., coder and its associated decoder) is shared between 24, 30, or even 120 separate channels. A high-speed electronic switch is used to present the analog information signal of each channel, taken in turn, to the codec. The codec is then arranged to sequentially sample the amplitude value, and code this value into the 8-digit sequence. Thus the output, to the codec may be seen as a sequence of 8 pulses relating to channel 1, then channel 2, and so on. This unit is called a time division multiplexer (TDM). The multiplexing principle thatis used is known as word interleaving. Since the words, or 8-digit sequences, are interleaved in time.At the receive terminal a demultiplexer is arranged to separate the 8-digit sequences into the appropriate channels. The reader may ask, how does the demultiplexer know which group of 8-digits relates to channel 1, 2, and so on? Clearly this is important. The problem is easily overcome by specifying a frame format, where at the start of each frame a unique sequence of pulses called the frame code. Or synchronization word is placed so as to identify the start of the frame. A circuit of the demultiplexer is arranged to detect the synchronization word, and thereby it knows that the next group of 8-digits corresponds to channel 1. The synchronization word reoccurs once again after the last channel has been received.( )7.At the receive terminal the reverse operation to the multiplexing is needed to separate the 8-digit sequencesinto the appropriate channels.( )8.The codec in the transmitting terminal is to sample the amplitude value, and code this value into the 8-digitsequence.( )9.The demultiplexer knows which group of 8-digits relates to channel 1 as soon as it finds the synchronization word. ( )10.From above text, we understand each voice channel has acoder.( )11.The time division multiplexer is so called since there is a special word called synchronization word.( )12.He group of 8-digits following the synchronization word relates to chart e1 1.PASSAGE THREEBy far the most popular serial interface between a computer and its CRT terminal is the asynchronous serial interface. This interface is so called because the transmitted data and the received data are not synchronized over any extended period and therefore no special means of synchronizing the clocks at the transmitter and receiver is necessary. In fact, the asynchronous serial data link is a very old form of data transmission system and has its origin in the era of teleprinter.An asynchronous serial data link is said to be character-oriented, as information is transmitted in the form of groups of bits called characters. These characters are invariable units comprising 7 or 8 bits of "information" plus 2 to 4 control bits and frequently correspond to ASCII-encoded characters.The most critical aspect of the system is the receiver timing. The falling edge of the start bit triggers the receiver's local clock,which samples each incoming bit at its nominal center. Suppose the receiver clock waits T/2 seconds from the falling edge of the start bit and samples the incoming data every T seconds thereafter until the stop bit has been sampled. As the receiver's clock is not synchronized with the transmitter clock, the sampling is not exact.The most obvious disadvantage of asynchronous data transmission is the need for a start, parity, and stop bit for each transmitted character. If 7 bit characters are used, the overall efficiency is only 70%. A less obvious disadvantage is due to the character-oriented nature of the data link. Whenever the data link connects a CRT terminal to a computer, few problems arise, as the terminal is itself character oriented. However, if the data link is being used to, say, dump binary data to a magnetic tape, problems arise.( )13.The most obvious disadvantage of asynchronous data transmission is about the lower transmission efficiency. ( )14.In fact, the asynchronous serial data link is the teleprinter.( )15.The falling edge of the start bit triggers the receiver's local clock, which samples each bit sent from thetransmitter.( )16.From above text we understand the characters are variableunits.( )17.For each transmitted character, a start, parity, and stop bit are needed.( )18.Special means is needed to synchronize the clocks at the transmitter and receiver.PASSAGE FOURAn asynchronous serial data link is said to be character-oriented, as information is transmitted in the form of groups of bits called characters. These characters are invariable units comprising 7 or 8 bits of "information" plus 2 to 4 control bits and frequently correspond to ASCII-encoded characters. Initially, when no information is being transmitted, the line is in an idle state. Traditionally, the idle state is referred to as the mark level. By convention this corresponds, to a logical l level.When the transmitter wishes to send data, it first places the line in a space level (1.e., the complement of a mark) for one element period. This element is called the start bit and has duration of T seconds. The transmitter then sends the character, 1 bit at a time, by placing each successive bit on the line for duration of T seconds, until all bits have been transmitted. Then a single parity bit is calculated by the transmitter and sent after the data bits. Finally, the transmitter sends a stop bit at a mark level (I. e., the samelevel as the idle state) for one or two bit periods. Now the transmitter may send another character whenever it wishes.At the receiving end of an asynchronous serial data link, the receiver continually monitors the line looking for a start bit. Once the start bit has been detected, the receiver waits until the end of the start bit and then samples the next N bits at their centers, using a clock generated locally by the receiver. As each incoming bit is sampled, it is used to construct a new character. When the received character has been assembled, its parity is calculated and compared with the received parity bit following the character. If they are not equal, a parity error flag is set to indicate a transmission error. ( )19.An asynchronous serial data link is said to be character oriented, because a duration of T seconds is needed foreach character.( )20.When the transmitter wishes to send data, it first places the line in logical 0 level.( )21.At the receiving terminal a single parity bit is calculated by the transmitter and compared with thereceived parity bit.( )22.At the receiving end of an asynchronous serial data link, the receiver continually monitors the line to search thestart bit.( )23.The receiver samples the bits sent from the transmitter using characters generated by the receiver.If the parity bit calculated by the receiver is not equal to the received one, transmission error occurs.勤劳的蜜蜂有糖吃( )24.。
微波通信(高级)试题
波总站批准。 ( ) 93.微波电路处理故障时,应由发端负责指挥,收端配合,电路故障段所属的中心站协 助。 ( ) 94.运行统计时,PCM终端设备(包括基群,二次群,三次群)每方向统计为一台。 () 95.如图是分压式稳定工作点原理图。 ( )
96.左图反馈电路是电压并联负反馈。 ( )
二、单项选择题(每小题1分，共86分)
8.若PCM基群误码率为5×10-7,则每秒误码数约( )个。 A.5 B.1 C.50 9.微波在自由空间的传播主要方式是( )传播。 A.绕射 B.折射和反射 C.直射 10.日本NEC数字微波异步复接中接收端判断正确的插入标志码是( )。 A.0 0 1 B.0 1 0 C.0 1 1 11.人耳对音频范围内不同频率具有不同的灵敏度,感觉最灵敏的频率是( )。 A.300HZ B.800～1000HZ C.3000～3400HZ 12.11 11 01 00 00是( )次群的祯同步码组。 A.一次群 B.一和二 C.二和三 13.30/32路PCM祯同步码在( )时隙发出。 A.偶祯Ts0 B.奇祯Ts0 C.奇偶祯Ts0都发 14.ZW60/120载波终端机群频侧阻抗是( )。 A.75 B.150 C.600 15.ZW60/120载波终端机中属于A B组对等转换的是( )。 A.主振 B.载频发生器 C.导频发生器 16.ZW60/120载波终端机属于主备用倒换的是( )。 A.主振 B.基振 C.载频发生器 17.需要进行线路编码的数字接口是( )。 A.近距离接口 B.远距离接口 C.都不要 18.人耳听觉的灵敏度近似( )。 A.与信号功率变化成正比 B.与声音强度的变化成平方关系 C.与信号功率变化成对数关系 19.ZW/60载波机中付站音终和日本NEC数字微波PCM设备中( )盘相对应。 A.FXO B.FXO C.R/D 20.如图属于( )。 A.电压并联负反馈 B.电压串联负反馈 C.电流串联负反馈
高级通信工考试复习题 (2)
高级通信工考试复习题2008年03月20日 星期四 07:57二、选择题1. 用"0""1"二进制编码来表示指令或数据的是计算机能直接识别的唯一语言，称为__B__ 语言。
A、汇编；B、机器；C、高级；2. 将十进制数（11）转换成二进制数= __A__。
A、（1011）2；B、（1110）2；C、（1101）2；3. 微机常用软盘有___C___ 种规格。
A、1；B、2；C、3；4. 将随时间连续变化的模拟信号变成时间上离散的脉幅调制信号，这种过程称为___B___ 。
A、量化；B、抽样；C、编码；5. 交流对地不平衡中继段指标是___A___ dB。
A、65；B、61；C、74；6. 光缆的弯曲半径在施工过程中应小于光缆外径__C___ 倍。
A、7.5；B、15；C、20；7. 单模光纤一般要求接续平均损耗每个为___C___ dB。
A、0.1；B、0.2；C、0.08；8. 无线列调天线避雷针上端与天线外端夹角应小于___B___ 。
A、30°；B、45°；C、60°；9. 光电数字传输设备竣工验收测试误码性能指标测试，统计时间为___C__ 。
A、2h；B、12h；C、24h；10. 光缆中继段在S点的最小回波损耗（包括连接器）STM-1 1550nm波长不小于___B__ dB。
A、15；B、20；C、30；11、电感量的单位是__A___ 。
A、亨利B、韦伯C、法拉12、 反馈可以使反大器的放大倍数__B___ 。
A、 增加B、下降C、不影响13、 CM系统中，每一位码占用的时长为__B___ 。
A、125/32=3.9μSB、1/2048KHZ=488μSC、1/8000KHZ=125μS14、 数字程控交换机的馈电电压一般为___A___ V。
A、-48VB、48VC、-24V15、 把接收到的脉码调制信号（PCM）还原成与发送端相同的脉幅调制信号（PAM）称为___B__ 。
高级通信工程师考试题(互联网)
3、阐述互联网应用扩展技术中网格计算系统的特点。
答:(1)具有单一映像空间。单一映像空间可屏蔽硬件边界,实现异构数据的格式转量换,提供虚拟文件服务,把分散在各地的主机节点映射成一个统一人口的虚拟机器。
第三章现代网络管理的技术实现
一、简答题
1、简述独立于协议的智能信息库(MIB)的开发过程。
答:(1)网络管理应用;
(2)查询访问协议和MIB间的映射(QAP-MIB);
(3)MIB;
(4)网络设备信息协议(NDIP)和数据访问接口(DAI)
A.论述无线局域网的概念、特点以及与有线局域网的相同点、不同点
2、阐述无线局域网的特点，以及与有线局域网络的比较。答：无线局域网是一个使用无线多址信道的分组交换网络，它的特点是在某个局域范围内，使用无线信道传输数据和采用分组交换技术进行信息交换。无线信道传输
技术由多址访问协议描述，分组交换技术由IEEE802.11协议描述。
无线局域网与有线局域网的作用基本相同，就是在网络的各设备之间传送分组信息。不同的是，无线局域网中所用的是便携设备，其中的分组传输包括移动站之间和移动站与固定站之间的传输。
一、简答题
1、简述无线局域网的物理介质？
答:(1)红外的。波长在850~950nm,数据率为1~2Mbit/s
(2)直接序列扩频。运行在2GHz ISM波段,最多可用七个通道,每个通道的数据率为1~2Mbit/s。
(3)跳频扩频。运行在2.4GHz ISM波段,数据率为1~2Mbit/S。两个正在进行的项目涉及运行在3Mbit/s的跳频扩频和8Mbit/s的直接序列扩频的2.4GHz选项,以及运行在20Mbit/s的5GHz扩频选项。
通信高级试题及答案
通信高级试题及答案一、选择题（每题2分，共20分）1. 在数字通信系统中，以下哪个参数不是衡量系统性能的指标？A. 信噪比B. 误码率C. 传输速率D. 传输距离答案：D2. 以下哪个不是数字调制技术？A. PSKB. QAMC. FSKD. PCM答案：D3. 在无线通信中，多径效应会导致以下哪种现象？A. 信号衰减B. 信号增强C. 信号失真D. 信号同步答案：C4. 以下哪个不是无线通信的频段？A. UHFB. VHFC. HFD. LF答案：D5. 在光纤通信中，以下哪个因素会影响信号的传输质量？A. 光纤长度B. 光纤直径C. 光源的波长D. 所有以上因素答案：D二、填空题（每空1分，共10分）1. 数字通信系统通常使用_______来表示信息。
答案：数字信号2. 在数字调制中，QAM调制技术可以表示为_______。
答案：正交幅度调制3. 无线通信中的多径效应是由于_______引起的。
答案：信号在不同路径上的反射和散射4. 光纤通信的基本原理是利用_______传输光信号。
答案：光导纤维5. 在通信系统中，信道容量受到_______的限制。
答案：香农-哈特利定理三、简答题（每题10分，共30分）1. 简述数字通信系统相对于模拟通信系统的优势。
答案：数字通信系统相较于模拟通信系统具有更高的抗干扰能力，更好的信号质量，可以实现更高效的频带利用率，以及更灵活的信号处理方式。
2. 解释多址接入技术在移动通信中的应用及其重要性。
答案：多址接入技术允许多个用户在同一频段上同时通信，而不会相互干扰。
在移动通信中，多址接入技术是实现大量用户接入的基础，它提高了频谱利用率并支持了高密度的用户接入。
3. 描述光纤通信的基本原理及其主要优点。
答案：光纤通信使用光信号在光纤中传输信息。
其基本原理是利用光的全反射原理，使光在光纤内部不断反射前进。
光纤通信的主要优点包括高带宽、低损耗、抗电磁干扰能力强、不受环境影响等。
2023通信工程师考试-高级通信工程师(精选试题)
2023通信工程师考试-高级通信工程师(精选试题)一、单选题1. 以下哪个频段可以用于5G通信？- A. 2.4GHz- B. 5GHz- C. 30GHz- D. 60GHz2. 下面哪个技术不属于物联网通信技术？- A. LoRa- B. ZigBee- C. LTE- D. Bluetooth3. 以下哪个协议用于无线局域网（WLAN）通信？- A. TCP/IP- C. FTP- D. IEEE 802.114. 以下哪个接口可以实现多台计算机之间的数据传输？- A. HDMI- B. USB- C. VGA- D. Ethernet5. 下面哪个编码方式可以提高数据传输的可靠性？- A. NRZ- B. Manchester- C. 8B/10B- D. RZ二、多选题1. 下面哪些是通信工程师需要掌握的网络协议？- A. TCP/IP- C. FTP- D. SMTP2. 以下哪些是无线通信中的调制方式？- A. AM- B. FM- C. BPSK- D. QPSK3. 以下哪些是光纤通信中常用的光模式？- A. MMF- B. SMF- C. SFP- D. QSFP三、判断题1. LTE可以提供比4G更高的网络速度和更低的延迟。
(True / False)2. 蓝牙协议只支持短距离无线通信。
(True / False)3. 码分多址（CDMA）是一种常用的多址技术。
(True / False)4. 网络拓扑是指计算机网络中各节点之间的物理连接方式。
(True / False)四、简答题1. 请简要解释物联网（IoT）的概念和应用。
2. 请描述一下数据压缩的基本原理。
3. 什么是带宽？为什么带宽对通信性能有重要影响？4. 请简要解释TCP/IP协议栈中每个协议的作用。
以上就是2023通信工程师考试-高级通信工程师(精选试题)的部分题目。
祝您考试顺利！。
通信工(网络维护管理)高级工题库(含答案)
通信工技能鉴定题库高级（网络维护管理）一、选择1.在路由信息中，迂回路由查看用什么指令？（）[311010101]（A）DISPSIGDP （B）DISPSIGDLLTG （C）DISPTGRP （D）DISPSIGROUTE 2.下列哪项测试不属于基本呼叫测试？（）[311010101]（A）移动-移动（B）移动-固定（C）固定-移动（D）固定-固定3.LTG中模块（）与SN相连接。
[311010101]（A）LTU （B）LIU （C）GCG （D）SILC4.板件GPP中的功能单元是（）。
[311010101]（A）线路中继（B）数据业务（C）消息缓存器（D）交换网络5.诺西EBSC设备电源输入板卡为：（）。
[321010101]（A）ShMC （B）PEM （C）SAP （D）ACFC6.诺西EBSC设备机框管理器模块板卡为：（）。
[321010101]（A）ShMC （B）PEM （C）SAP （D）ACFC7.多方会议功能可先使用DISPLTU查询输出信息中TYPE域取值为（）的LTG 编号，然后使用STATCOU查询某个LTG的COU状态。
[311010102]（A）D30 （B）Y25 （C）U07 （D）V028.SSNC接收CCG输出的时钟信号，送给ACCG=（），作为外部参考时钟。
[311010102]（A）1 （B）2 （C）3 （D）49.下面子模块板件不在一个机柜中的单元是（）。
[311010102]（A）DSU （B）SSNC （C）SND （D）MBD10.SND中与MBD向连接的端口编号为（）[321010102]（A）0和1 （B）1和64 （C）1和32 （D）0和6411.天线应在避雷针保护区域内，避雷针保护区域是避雷针顶点下倾（）范围内。
[332010102]（A）30°（B）40°（C）50°（D）60°12.在维规中信令信道可用率统计的是什么信道？（）[332010102]（A）BCCH （B）SDCCH （C）PDCH （D）SACCH13.JDSU公司的863x系列便携式协议分析仪每块高密度E1卡提供____个E1接收器，可最多接___对E1（RX1/Rx2为一组）。
通信工(线路综合维护)高级技师实作试题
通信工（线路综合维护）高级技师实作试题试题1: ODF架上光缆尾纤的熔接（1）材料准备2、操作考核规定及说明（1）操作程序说明：1）准备工作2）制备光纤，选择熔接模式3）熔接光纤，盘好纤芯4）清理现场（2）考核规定说明：1）如操作违章,将停止考核；2）考核采用百分制，考核项目得分按组卷比重进行折算；（3）考核方式说明：该项目为实际操作题，全过程按操作标准结果进行评分。
（4）测量技能说明：本项目主要测量考生对ODF架上光缆尾纤熔接的熟练程度。
3、考核时限：（1）准备时间：1min（不计入考核时间）（2）正式操作时间：20min（3）考核时，提前完成操作不加分，超过规定操作时间按规定标准评分。
4、评分记录表铁路通信工高级技师操作技能考核评分记录表准考证号(现场号): 工位号: 性别:考评员：核分员：年月日试题2：用CAD绘制通信线路平面图2、操作考核规定及说明（1）操作程序说明：1）准备工作2）绘制边框线，绘制通信线路平面图3）标注相关内容，打印图纸4）清理现场（2）考核规定说明：1）如操作违章,将停止考核；2）考核采用百分制，考核项目得分按组卷比重进行折算；（3）考核方式说明：该项目为实际操作题，全过程按操作标准结果进行评分。
（4）测量技能说明：本项目主要测量考生对用CAD绘制通信线路平面图的熟练程度。
3、考核时限：（1）准备时间：1min（不计入考核时间）（2）正式操作时间：15min（3）考核时，提前完成操作不加分，超过规定操作时间按规定标准评分。
4、评分记录表铁路通信工高级技师操作技能考核评分记录表准考证号(现场号): 工位号: 性别:试题名称:用CAD绘制通信线路平面图考核时间:15min考评员：核分员：年月日试题3：7*4电缆气闭绝缘套管制作一、准备通知单：1.材料及工件准备2.设备准备3.工、量、刃、卡具准备1．考核内容：7*4电缆气闭绝缘套管制作2. 根据要求，浇灌制作完成后芯线绝缘良好，起到气闭作用。
铁路通信工高级理论知识资源库
铁路通信工（维护）高级理论知识资源库一、判断题，共233道。
1.(82993)( √ )光源器件和光检测器件可统称为光有源器件。
( )(1.0分)2.(82994)( × )光连接器、光衰耗器、光分路器也属于光有源器件。
( )(1.0分)3.(82995)( √ )在光缆线路中也可设置光中继器以增大传输距离。
( )(1.0分)4.(82996)( √ )在对称电缆回路中，电感很小电容很大。
( )(1.0分)5.(82997)( × )从减小衰减的角度出发，减小线间距离可减小衰减。
( )(1.0分)6.(82998)( √ )从减小衰减的角度出发，增大导线直径可减小衰减。
( )(1.0分)7.(82999)( √ )当回路的一次参数满足 时，回路衰减值最小。
( )(1.0分)8.(83000)( √ )在最佳传输条件下，α仅由R、G来决定，与频率无关。
( )(1.0分)9.(83001)( × )在最佳传输条件下，β与频率成反比。
( )(1.0分)10.(83002)( √ )在电缆施工时，用人工的办法在电缆回路中串接一个电感线圈，以增加线路的电感量，就可以取得减少传输衰减的效果。
( )(1.0分)11.(83003)( × )传输衰减越大，传输距离就越远。
( )(1.0分)12.(83004)( × )电缆回路加感后，传输衰减α值变小了，但传输特性没有改变。
( )(1.0分)13.(83005)( √ )在接近截止频率fj的较高频段上，当半节距终端时，特性阻抗的模值和辐值随着频率的增加而增加。
( )(1.0分)14.(83006)( √ )在接近截止频率fj的较高频段上，当半线圈终端时，特性阻抗的模值和辐值随着频率的增加而减小。
( )(1.0分)15.(83007)( × )回线加感后适用于传输高频模拟信号。
( )(1.0分)16.(83008)( √ )在对称电缆制造过程中，把四根芯线采用星形排列，主要是为了减少回路间的串音。
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通信高级工试题
一、填空题（将正确的答案填在横线空白处）
1、跨越一般河流时应在两端的电杆上安装三方拉线，其形式有（T型）和（Y 型）。
2、时分复用利用各种信号在信道上占有不同的时间间隙，同在一条信道上传输，且互不干扰。
3、衡量数字通信系统可靠性的主要指标是误码率。
4、程控分机0~29号对应音频分机__1至30_号。
5、数字信号与模拟信号的区别是看其__幅度__的取值是否离散。
6、长途电缆音频回线加感有两种方式：均匀加感和__集中__加感。
7、地温折返无人机的特点是采用地温调节电平，__远供电源__在此折返。
8、光纤通信系统中，短波长波段为__0.8~0.9um__波长。
9、单模光纤接续点的接续损耗平均值应不大于0.08dB/处。
10、SDH网同步结构采用主从同步方式，即所有网络单元时钟最终都能跟踪到全网的基准时钟。
二、选择题（选择正确答案的代码填入括号内）
1、铁路数字通信网以局枢纽至端站（ A ）公里为中级电路。
（A）1000 （B）3000 （C）4000 （D）5000
2、交换发给用户的拨号音是（C ）连续发送。
（A）150±15Hz （B）300±15Hz （C）450±25Hz （D）600±25Hz 3、如果广播喇叭太少，扩音机输出功率还有多余，就必须用（ B ）把多余的功率吸收掉。
（A）变压器（B）假负载（C）电容（D）衰耗器
4、下列不属于铁路专用通信设备的是：（ D ）
（A）干线调度电话（B）站间行车电话（C）会议电话（D）用户自动电话
5、同轴配线电缆SFF-75-2用1000V兆欧表测量时其绝缘电阻应不小于（D ）ＭΩ。
（A）25 （B）100 （C）50 （D）1000
6、设在会议室内的终端设备应不包括（A ）
（A）多点控制设备（MCU）（B）编解码器（CODEC）
（C）电子白板（D）摄像机
7、PCM30/32四次群（140Mbit/s信号）所包含的电话话路数为（B ）路。
（A）1670 （B）1920 （C）2048 （D）2180
8、用于抽样与分路的脉冲信号是（B ）。
（A）位脉冲（B）路脉冲（C）帧脉冲（D）
复帧脉冲
9、光传输设备安装高频、音频回线布线的单线对地绝缘电阻应大于（ C ）。
（采用250v兆欧表进行测量）
（A）200MΩ（B）100MΩ（C）50MΩ（D）30MΩ
10、下列对线路衰耗频率特性说法正确的是（C ）。
（A）电缆和线路是一条射线（B）明线线路是一条斜直线（C）对称电缆是呈现弯曲线（D）同轴电缆基本是斜直线
三、判断题（下列说法正确的请在括号内打“√”，错误的打“×”）
1、操作直流电桥测试环绕电阻时，调节测定臂（平衡臂）观看表针的偏转情况，若表针偏向“+”方向，说明测定臂不得减电阻，若表针偏向“-”方向，则应增加测定臂电阻，直至检流计表针指零。
（×）
2、电平符号“dBV”表示功率电平，“dBr”表示相对功率电平。
（×）
3、交流配电屏接入两路以上交流电源时，可以并路使用。
（×）
4、高频缆线应与电源线、音频配线一起布放绑扎。
（×）
5、全呼是指总机能叫出该回线上的全部分机。
（√）
6、传真机的原理，就是一个对图像进行分解和合成的过程。
（√）
7、区间电话柱电话盒的安装在复线区段应面向来车方向，在单线区段应背向铁路。
（×）
8、数字通信中，为了延长通信距离，在沿线每隔一定的距离加入一个再生中继器。
（√）
9、误码产生的主要原因是在传输信道中的噪声和干扰以迭加的形式随信号一起进入判决电路，使判决再生电路产生误码。
（√）
10、常规单模光纤在1.55um的微湾曲特性要求衰减增加值小于0.1dB。
（√）
四、简答题
1、铁路运输通信工程质量的检验和评定应按什么来划分？
答：应按分项、分部和单位工程划分。
2、铁路运输通信工程质量验收单位工程是按什么原则确定的？
答：单位工程应按一个完整工程、系统或一个相当规模的施工范围划分，并按以下原则确定：
光电缆线路：一个调度区段为一个单位工程。
光纤用户接入网及中间站电源：一个接入网区段为一个单位工程。
铁路运输调度通信：一个调度区段为一个单位工程。
列车无线调度通信：：一个调度区段为一个单位工程。
区段通信：：一个调度区段为一个单位工程。
站场通信：一个站场为一个单位工程。
车站客运信息系统：一个车站为一个单位工程。
数据接入终端业务：一个数据段为一个单位工程。
中间站环境及电源监控系统：一个监控段为一个单位工程。
3、电气化铁道区段电缆引入室内及通信站时有何规定？
答：电气化铁道区段电缆引入室内时其金属护套与相连接的室内金属构件间应进行绝缘。
引入通信站时，应将其金属护套的室内与室外部分绝缘。
绝缘阻值不应小于1000MΩ。
4、光缆接续后光纤收容有何规定？
答：光缆接续后的光纤收容余长单端引入引出不应小于0.8米，两端引入引出不应小于1.2米，水底光缆不应小于1.5米。
光纤收容时的弯曲半径不应小于40㎜。
5、中间站电源绝缘测试及接地电阻有何规定？
答：电源测试须符合①电源设备带电部分与金属外壳间的绝缘电阻应大于5MΩ。
②电源配线的芯线间和芯线对地的绝缘电阻应大于1MΩ。
接地电阻应符合①联合接地电阻值不应大于5Ω。
②保护接地电阻值不应大于10Ω。
③防雷接地电阻值不应大于10Ω。
五、综合题
1、叙述隧道中继器正、反向传输工作工程。
当来自机车台的信号强度大于-85dB时,458MHz放大通道输出指示灯亮,功放输出继电器与开关控制器1继电器接通,信号经放大后从中继器的另一端口(A)输出，此时正向传输（468MHz）放大通道指示灯不亮。
当来自机车台的信号关闭或小于中继器实际开启电平时，458MHz放大通道输出指示灯熄灭，功放输出继电器与开关控制器1继电器关闭。
通信正常时，输出指示灯随着信号的有无而点亮和熄灭，器静噪开启和关断的时延均应小于30ms，指示灯点亮和熄灭的时延无明显感觉。
当来自车站台的信号强度大于-85dB时,468MHz放大通道输出指示灯亮,功放输出继电器与开关控制器2继电器接通,信号经放大后从中继器的 B端口输出。
反向传输（458MHz）放大通道输出制式灯不亮。
当来自车站台的信号关闭或小于中继器实际开启电平时，468 MHz放大通道输出指示熄灭，功放输出继电器与开关控制器2继电器关闭。
2.叙述数字通信的优缺点主要有哪些？
答：优点：抗干扰能力强、传输中出现的差错（误码）可以设法控制，提高了传输质量、便于进行信号加工与处理、数字信息易于加密且保密性强、能够传输话音、电视、数据等多种信息，增加了通信系统的灵活性和通用性。
缺点：频带利用率低。