山东省泰安市2018届高三第二次模拟考试英语2018届淄博市高三二模数学试题及答案.pdf
山东省泰安市2018届高三第二次模拟考试数学试题(文)含答案
山东省泰安市2018届高三第二次模拟考试数学试题(文科)2018.5第I 卷一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.已知集合A=(){}lg 21x x -<,集合B={}2230x x x --<,则.A ∪B 等于A .(2,12)B .(-1,3)C .(-1,12)D .(2,3) 2.已知复数z 满足3iz i =-+,z 在复平面内对应的点位于 A .第一象限 B .第二象限 C .第三象限 D .第四象限3.计算0sin 35sin 65cos145sin 25-等于 A .32-B .12-C .12D .324.已知l ,m 是空间两条不重合的直线,α是一个平面,则“m α⊥,l 与m 无交点”是“l ∥m ,l α⊥”的A .充分而不必要条件B .必要而不充分条件C .充分必要条件D .既不充分也不必要条件5.某年级的全体学生参加数学测试,成绩的频率分布直方图如图,数据的分组依次为:[20,40),[40,60),[60,80),[80,100],若低于60分的人数是:150,则该年级的学生人数是 A .600 B .550 C .500D .4506.函数()()()2ln ln f x x e x e x =+-+的图象大致为7.根据如下程序框图,运行相应程序,则输出n 的值为 A .3 B .4 C .5 D .68.设抛物线()220y px p =>的焦点为F ,过F 点且倾斜角为4π的直线l 与抛物线相交于A ,B 两点,若以AB 为直径的圆过点(,22p-),则该抛物线的方程为A .22y x =B .24y x =C .28y x =D .216y x =9.某几何体的三视图如图所示,其中正视图由矩形和等腰直角三角形组成,侧视图由半圆和等腰直角三角形组成,俯视图的实线部分为正方形,则该几何体的表面积为 A .342π+B .()421π++C .()42π+D .()41π+10.设函数()()()sin 0,0f x x ωϕωϕ=+>>的最小正周期为π,且()8f x f π⎛⎫≤ ⎪⎝⎭,则下列说法不正确的是A .()f x 的一个零点为8π-B .()f x 的一条对称轴为8x π=C .()f x 在区间35,88ππ⎛⎫⎪⎝⎭上单调递增 D .()f x 是偶函数 11.已知函数()f x 是定义在R 上的偶函数,当0x ≤时,()f x 为减函数,则不等式()()132log 25log 8f x f ⎛⎫-> ⎪⎝⎭的解集为 A .541216xx ⎧⎫<<⎨⎬⎩⎭B .132x x ⎧⎫>⎨⎬⎩⎭C .541132162xx x ⎧⎫<<>⎨⎬⎩⎭或D .541132162x x x ⎧⎫<<<⎨⎬⎩⎭或 12.已知F 为双曲线C :()222210,0x y a b a b-=>>的右焦点,过点F 向C 的一条渐近线引垂线,垂足为A ,交另一条渐近线于点B .若OF FB =,则C 的离心率是A .233B .62C .2D .2第Ⅱ卷本卷包括必考题和选考题两部分,第(13)题—第(21)题为必考题,每个试题考生都必须作答.第(22)题、第(23)题为选考题,考生根据要求做答.二、填空题:本大题共4小题。
届淄博市高三英语模拟试卷题目及答案
届淄博市高三英语模拟试卷题目及答案2018届淄博市高三英语模拟试卷题目及答案要想在高考英语中取得好成绩,多做英语模拟试卷是必须的,以下是店铺为你整理的2018届淄博市高三英语模拟试卷,希望能帮到你。
2018届淄博市高三英语模拟试卷题目第一部分:听力(共两节,满分30分)第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What is the woman doing?A. Singing a songB. Listening to musicC. Reading a book2. What day is it tomorrow?A. WednesdayB. ThursdayC. Friday3. What will the weather be like this afternoon?A. SnowyB. RainyC. Cloudy4. What did Alice do this afternoon?A. She went boating with Ted.B. She saw a movie with Mike.C. She waited for Mike for a long time.5. What is the man’s plan for the day after tomorrow?A. To stay at home.B. To go to the airport.C. To go on a picnic.第二节(共15题;每小题1.5分,满分22.5分)听下面5段对话或独白。
每段对话或独白后有几个小题,从题中所给A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题给出5秒钟的作答时间。
山东省淄博市2018届高三英语第二次模拟考试(2018淄博
高三复习阶段性检测试题英语本试卷分第I卷和第II卷两部分,共14页。
满分150分。
考试用时120分钟。
考试结束后,将本试卷和答题卡一并交回。
注意事项:1.答题前,考生务必用0.5毫米黑色签字笔将自己的姓名、座号、准考证号、县区和科类填写在答题卡和试卷规定的位置上。
2.第I卷每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑;如需改动,用橡皮擦干净后,再选涂其他答案标号。
3.第II卷必须用0. 5毫米黑色签字笔作答,答案必须写在答题卡各题目指定区域内相应的位置,不能写在试卷上﹔如需改动,先划掉原来的答案,然后再写上新的答案:不能使用涂改液、胶带纸、修正带。
不按以上要求作答的答案无效。
第I卷(共118分)第一部分:听力(共两节,满分30分)该部分分为第一、第二两节。
注意:回答听力部分时,请先将答案标在试卷上。
听力部分结束前,你将有两分钟的时间将你的答案转涂到客观题答题卡上。
第一节(共5小题:每小题1.5分,满分7. 5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话后,你有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
例:How much is the shirt?A. £19.15.B. £9.15 .C. £9.18答案是B。
l .What's the probable relationship between the speakers?A .Mother and son.B. Teacher and student.C. Employer and employee.2.How much does Rose still owe the woman?A. $10.B. $20.C.$30.3. What does the man think of the woman's green dress?A. It’s ugly.B. It’s bright.C. It’s I unusual.4. What are the speakers mainly talking about?A. A club.B.An order.C.A calendar.5. How will the man contact the woman?A. By calling her.B. By sending a letter.C. By sending a postcard.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话。
2018年山东省泰安市高考英语二模试卷
2018年山东省泰安市高考英语二模试卷第二部分阅读理解(共两节)第一节(满分30分)阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项,并在答题卡上将该项涂黑.1. Several Jobs That Will Be Automated By Artificial Intelligence(AI) And RobotsTranslatorImage recognition software and voice recognition software are bringing some major advances to language translation.Applications like Google’s Word Lens can translate words from signs and documents in real time and there ale a lot of translation apps that allow you to type in a word or phrase and will translate it for you.Some will even speak the phrase for you and raw word﹣to﹣word translation will be fully automated soon.Fast food workersAutomated ordering booths have already made their w ay into a few McDonald’s restaurants around the world, and cooking positions could be removed next.The booths probably can’t handle customer service problems well, so televideo systems could bring in an office employee to deal with complaints.Field technicianNew advances in the Internet of Things could make this work ________.Low﹣cost sensors combined with high availability cellular/satellite communications and cloud technology are being started to automate and alarm these sites, and can be checked and maintained from a desktop or mobile device.Sales representativeBut, e﹣commerce is changing how we make purchasing decisions, especially those where there isn’t much differentiation among the major competitors.If you’re selling a h igh﹣differentiation product and/or a high﹣price, low﹣volume product you have some job security, but if you’re selling a high﹣volume, low﹣differentiation product, you better start polishing your resume, said Doug Camplejohn, CEO of Fliptop.“These kind of pr oduct sales are all moving online.”(1)What can Google’s Word Lens do?________A.Translate by image and voice recognition software.B.Speak the phrase or word for you.C.Make real﹣time translation.D.Allow you to type in a word or phrase.(2)What can we infer from the second part?________A.All the restaurants own automated ordering booths.B.Service problems can’t be handled automatically.C.Cooks will not be automated by AI and robots.D.Customers will have no complaints because of AI.(3)What does the underlined word“obsolete”mean in Part 3?________A.Abandoned.B.Welcome.C.Forbidden.D.Efficient.(4)What does the author mean by“you better start polishing your resume”in the last paragraph?________A.You must value your present work.B.You have some job security.C.Your resume needs correcting further.D.You should consider changing the job.【答案】CBAD【考点】完形综合阅读理解综合【解析】本文介绍了人工智能(AI)和机器人自动化的几种工作.翻译家,快餐工人,现场技术员和销售人员.【解答】(1) C.细节理解题.根据句子:Applications like Google’s Word Lens can tra nslate words from signs and documents in real time and there ale a lot of translation apps that allow you to type in a word or phrase and will translate it for you.应用程序可以实时地从符号和文档中翻译单词,并且有很多翻译应用程序可以让你输入单词或短语.会为你翻译的.所以答案选C.(2) B.细节理解题.根据句子:The booths proba bly can’t handle customer service problems well,可见服务问题不能自动处理,所以答案选B.(3) A.猜测词义题.根据下文句子Low﹣cost sensors combined with high availability cellular/satellite communications and cloud technology are being started to automate and alarm these sites,and can be checked and maintained from a desktop or mobile device.通信和云技术正在开始自动化和报警这些网站,并可以检查和维护从台式机或移动设备.可见物联网更加先进,可见Field technician“现场技术员”会被放弃,所以答案选A.(4) D.推理判断题.根据句子:These kind of product sales are all moving online.这些产品的销售都在网上进行.如果你是推销这些产品的人,那么前一句的劝告应该是改变工作的意思.故选D.2. It was Groundhog Day.A winter storm had hit overnight too.I tried to open my backdoor only to find six inches of wet, heavy snow piled up against it.I knew I had quite a job of shoveling out ahead of me, so I reached over to grab my snow shovel.It looked a lot more ready to work than I did.I sighed and pulled on my boots, gloves, and heavy coat. The wind chill was below zero and cut into my face as I slowly shoveled off my deck.After that I stayed my way over to my daughter’s house shoveling the path as I walked.It took a while to get her driveway clear and I knew I still had a lot to do.Next came the paths down the hill to my own cars covered in snow.I had grabbed the broom to sweep them off as well.I winced when the breeze blew the swept snow back into my face.Then I started to shovel out my driveways.My back was aching as I worked.I wished I could be building a snowman instead of shoveling.Winter sure had seemed a lot more fun when I was a boy. When I was done I examined my work.It didn’t look half bad.I smiled and looked at thewoods covered in white.They were such a special sight.I leaned on my shovel and took it all in.Then I started up the hill with the snow shovel in one hand and the broom in the other.Suddenly, an urge came over me and I dropped them both.I spread my arms, fed back into the blanket of white and happily moved my arms and legs to make an angel in the snow.As you go through the seasons of this life take joy in your work.Take joy in your life.Remember that the course of your days rests in your own hands.(1)What’s the theme of the text?________A.Enjoy winter work.B.Take things seriously.C.Take joy in your life.D.Fight against cold.(2)Which is the correct order of what the author shoveled?________A.his deck﹣his daughter’s driveway﹣his cars﹣his driveway.B.his cars﹣his deck﹣his daughter’s driveway﹣his driveway.C.his daughter’s driveway﹣his deck﹣his driveway﹣his cars.D.his driveway﹣his daughter’s driveway﹣his cars﹣his deck.(3)What can we conclude about the author from Paragraph 3?________A.He was not satisfied with his work.B.He was absorbed in the snow sight.C.He was fond of making snowmen.D.He was in low spirits after work.【答案】CAB【考点】阅读理解综合【解析】本文是一篇历史文化类阅读,文章主要介绍了土拨鼠日.一场暴风雪也在一夜之间袭来.我试着打开我的后门,却发现有6英寸厚的湿雪堆积在上面.我伸手去拿雪铲,它看起来比我更愿意工作.我叹了口气,穿上靴子、手套和厚外套.【解答】(1)C.细节理解题.根据"As you go through the seasons of this life take joy in your work.Take joy in your life.Remember that the course of your days rests in your own hands.’可知课文的主题是在生活中享受快乐.故选C.(2)A.推理判断题.根据"The wind chill was below zero and cut into my face as I slowly shoveled off my deck.After that I stayed my way over to my daughter’s house shoveling the path as I walked.It took a while to get her driveway clear and I knew I still had a lot to do’可知作者铲的正确顺序是甲板、他女儿的路、他的车、他的车道.故选A.(3)B.推理判断题.根据"Suddenly,an urge came over me and I dropped them both.I spread my arms,fed back into the blanket of white and happily moved my arms and legs to make an angel in the snow.’可知作者被雪景吸引住了.故选B.3.If you’re a book lover, you may have a pile of books at your bedside, or a bookshelf in your room with a “to read” sign on it. Yet you can’t stop yourself from adding books to the pile. This can lead to feelings of guilt over your new purchases. But I’m he re to tell you to stop worrying.What you have is an antilibrary, and it’s a very good thing. The term comes from writer Umberto Eco. He is the owner of a large personal library. He separates visitors into two groups: those who react by saying “Wow! What a library you have! How many of these books have you read?” and the others who hold the point that a private library is not something to show off but a research tool. Read books are far less valuable than unread ones. Indeed, the more you know, the more unread books you will have. Let us call this collection an antilibrary.If you think you already know everything about a subject, you’re cutting yourself off from a stream of information. So a growing library of books you haven’t read means you’re consistently curious about the unknown. And that attitude provides the foundation for a lifelong love of learning.So don’t feel guilty about your unread books. Those books will be there for you when you do need them, and as you build your library of read and unread books, you can start using it as you are using a bigger library. Certain books may become references. Or you may find that a book you bought five years ago has special relevance today. Letting the role of books evolve in your life is a healthy sign of curi osity. That’s good for you and good for the world around you.(1)What does the underlined word “antilibrary” in Paragraph 2 refer to?A.Feelings of guilt over buying new books.B.A pile of books on the bookshelf.C.The collection of unread books.D.A large personal library.(2)According to the author, more unread books mean ______.A.your wrong lifelong learning attitudeB.you limit yourself off from the unknownC.your have no interest in the new worldD.your strong desire for new information(3)What’s the author’s attitude towards having an antilibrary?A.Favorable.B.Doubtful.C.Ambiguous.D.Contradictory.(4)What can we know from the last paragraph?A.Curiosity is a sign of high IQ.B.Books are the ladder in our life.C.Unread books are surely relevant to the bad attitude.D.We should read through every book.【答案】CDAB【考点】推理判断议论文阅读观点态度词义猜测细节理解日常生活类阅读【解析】本文是一篇议论文。
山东省淄博市 2018届 高三二模考试数学试题及答案(文理)PDF
相关视频讲解入群 B. 2 C. 3 D. 4 更多学而思下载 (文科)已知菱形 ABCD 的边长为 4 , ABC 30 ,若在菱形内任取一点,则 8. 相关视频观看 该点到菱形的四个顶点的距离都大于 1 的概率是 入群更新课程
解: (Ⅰ) 因为 BAC 所以 CAD 由余弦定理知
2π π 相关视频观看 ,BAD 3 2 入群更新课程 π , 在 DAC 中, 6
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相关视频讲解入群 2 2 2 B. 0, C. , D. , 0 , 更多学而思下载 e e e 相关视频观看 第Ⅱ卷(非选择题 共 90 分) 入群更新课程
淄博市 2017-2018 学年度高三二模考试 数学试题参考答案及评分说明 2018.05
第Ⅰ卷(选择题
只有一项是符合题目要求的. 1.已知 M x 1 x 2 , N x x 3 ,则 A. 2, 3 2.若复数 z B. (2, 3] C. , 1
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2018届淄博高三二模试题及答案(文理齐全)
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高三二模考试数学试题参考答案
第 5 页(共 21 页)
所以 cos ADB
21 7
……………………5 分
在直角三角形 DAB 中, DB
AD 7 cos ADB 2
………………………………6 分
所以所求 BD 的长为
7 . 2
(Ⅱ)设 ADB ,则 ACD 在直角三角形 DAB 中,
2 ,C
π ,则 AC 边上的高 6
为___
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高三二模考试数学试题参考答案 第 3 页(共 21 页)
15. (理科)甲、乙、丙、丁、戊五位同学相约去学校图书室借 A , B , C , D 四类 课外书(每类课外书均有若干本) ,已知每人均只借阅一本,每类课外书均有人借阅, 且甲只借阅 A 类课外书,则不同的借阅方案种类为___ 60 ___. (用数字作答) 16.椭圆
1 1 1 2n 1 1 2 2 1 1 2 2n 1 1 4
……………………………11 分
n 1 2 . 2 n 1 2n 1 3 2 3
…………………………………………………12 分
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【100所名校】2018年山东高三二模英语试题(解析版)
1.A.readingB.makingC.collectingD.telling
2.A.turn upB.turn offC.get offD.give up
3.A.guiltyB.boredC.tiredD.upset
4.A.caseBBiblioteka driverC.carD.tool
5.A.timeB.moneyC.chanceD.mood
I met a man sitting on a bench looking very_______, so I asked him what was wrong. He said his_______had been dragged away (拖走) from a public lot and that he had no_______to get to the airport to meet his wife. I told him that I could help him out and let him_______there.
11.A.workedB.stoppedC.chattedD.planned
12.A.proudlyB.bravelyC.rudelyD.politely
13.A.butB.andC.soD.or
14.A.hadB.madeC.orderedD.sold
15.A.expectedB.wishedC.showedD.lent
As you may________I was so thankful for putting________on the wrong bus at the right time. This let me________two people who needed help and________. During each meeting, I never felt afraid; I only felt________to help them.
【高三数学试题精选】2018年高考理科数学二模试卷(淄博市附答案和解释)
2018年高考理科数学二模试卷(淄博市附答案和解释)
5 c 2018年东省淄博市高考数学二模试卷(理科)
一、选择题本大题共10个小题,每小题5分,共50分.在每小题给出的四个选项中,只有一项是符合题目要求的.
1.复数 =()
A.1﹣2iB.1+2ic.﹣1﹣2iD.﹣1+2i
2.已知集合A={x|=lg(x+1)},B={﹣2,﹣1,0,1},则( RA)∩B=()
A.{﹣2,﹣1}B.{﹣2}c.{﹣1,0,1}D.{0,1}
3.下列四个结论中正确的个数是()
①若a2<b2,则a<b
②己知变量x和满足关系=﹣01x+1,若变量与z正相关,则x与z负相关
③“己知直线,n和平面α、β,若⊥n,⊥α,n∥β,则α⊥β”为真命题
④=3是直线(+3)x+﹣2=0与直线x﹣6+5=0互相垂直的充要条.
A.1B.2c.3D.4
4.已知单位向量,,满足,则与夹角的余弦值为()
A. B. c. D.
5.函数f(x)=|x+2018|﹣|x﹣2018|的最大值为()
A.﹣1B.1c.4033D.﹣4033
6.二项式展开式的常数项为()
A.﹣80B.﹣16c.80D.16
7.若角θ终边上的点在抛物线的准线上,则cs2θ=()
A. B. c. D.
8.已知函数(e为自然对数的底数),当x∈时,=f(x)的图象大致是()。
2018年山东省淄博市高考数学二模试卷(理科)(解析版)
2018年山东省淄博市高考数学二模试卷(理科)一、选择题:本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.(5分)己知M={x|﹣1≤x≤2},N={x|x≤3},则(∁R M)∩N=()A.[2,3]B.(2,3]C.(﹣∞,﹣1]∪[2,3]D.(﹣∞,﹣1)∪(2,3]2.(5分)若复数z=(i是虚数单位),则|z|=()A.B.C.1D.3.(5分)公差为2的等差数列{a n},前5项和为25,则a10=()A.21B.19C.17D.154.(5分)公元263年左右,我国数学家刘徽发现当圆内接正多边形的边数无限增加时,多边形面积可无限逼近圆的面积,并创立了“割圆术”.如图是利用刘徽的“割圆术”思想设计的一个程序框图,则输出的n值为()(已知:sin15°≈0.2588,sin7.5°≈0.1305)A.12B.20C.24D.485.(5分)某几何体的主视图与俯视图如图所示,左视图与主视图相同,且图中的四边形都是边长为2的正方形,两条虚线互相垂直,则该几何体的体积是()A.B.C.6D.46.(5分)己知函数y=log a(x﹣1)+2(a>0,且a≠1)恒过定点A.若直线mx+ny=2过点A,其中m,n是正实数,则的最小值是()A.3B.3C.D.57.(5分)将函数的图象向左平移个单位,得到函数y =g(x)的图象,若上为增函数,则ω的最大值为()A.1B.2C.3D.48.(5分)己知等比数列{a n}的前n项和为S n,且满足a2,2a5,3a8成等差数列,则=()A.或B.或3C.D.或9.(5分)双曲线C:=1(a,b>0)的上焦点为F,存在直线x=t与双曲线C交于A,B两点,使得△ABF为等腰直角三角形,则该双曲线离心率e=()A.B.2C.D.+110.(5分)函数f(x)=x2•cos x在的图象大致是()A.B.C.D.11.(5分)棱长为1的正方体ABCD﹣A1B1C1D1,动点P在其表面上运动,且与点A的距离是,点P的集合是一条曲线,则这条曲线的长度是()A.B.C.πD.12.(5分)若存在两个正实数x,y使得等式2x+a(y﹣2ex)(lny﹣lnx)=0成立(其中e 为自然对数的底数),则实数a的取值范围是()A.(﹣∞,0)B.C.D.二、填空题:本大题共4小题,每小题5分,共20分.13.(5分)从标有1,2,3,4,5的五张卡片中,依次抽出2张,则在第一次抽到偶数的条件下,第二次抽到奇数的概率为.14.(5分)向量,满足=(1,),||=1,||=,则与的夹角为.15.(5分)甲、乙、丙、丁、戊五位同学相约去学校图书室借A,B,C,D四类课外书(每类课外书均有若干本),己知每人均只借阅一本,每类课外书均有人借阅,且甲只借阅A 类课外书,则不同的借阅方案种类为.(用数字作答)16.(5分)椭圆的左、右焦点分别为F1,F2,弦AB过F1,若△ABF2的内切圆周长为2π,A,B两点的坐标分别为(x1,y1)和(x2,y2),则|y2﹣y1|=.三、解答题:共70分.解答应写出文字说明、证明过程或演算步骤.第17~21题为必考题,每个试题考生都必须作答.第22、23题为选考题,考生根据要求作答.(一)必考题:60分.17.(12分)在△ABC中,,D为边BC上一点,DA⊥AB,且AD=.(I)若AC=2,求BD;(II)求的取值范围.18.(12分)如图,在三棱柱ABC﹣A1B1C1中,CA=CB=CC1=2,∠ACC1=∠CC1B1,直线AC与直线BB1所成的角为60°.(I)求证:AB1⊥CC1;(II)若AB1=,M是AB1上的点,当平面MCC1与平面AB1C所成二面角的余弦值为时,求的值.19.(12分)有一片产量很大的芒果种植园,在临近成熟时随机摘下100个芒果,其质量频数分布表如下(单位:克):(I)(i)由种植经验认为,种植园内的芒果质量Z服从正态分布N(μ,σ2),其中μ近似为样本平均数,σ2近似为样本方差S2≈65.72.请估算该种植园内芒果质量在(191.8,323.2)内的百分比;(ii)某顾客从该种植园随机购买100个芒果,记X表示这100个芒果质量在区间(191.8,323.2)内的个数,利用上述结果,求E(X).(II)以各组数据的中间值代表这组数据的平均值,将频率视为概率,某经销商收购芒果10000个,并提出如下两种收购方案:A:所有芒果以每千克10元的价格收购;B:对质量低于150克的芒果以每个0.5元的价格收购,质量不低于150克但低于300克的以每个2元的价格收购,高于或等于300克的以每个5元的价格收购.请你用学过的相关知识帮助种植园主选择哪种方案才能获利更多?附:Z服从N(μ,σ2),则P(μ﹣σ<Z<μ+σ)=0.6826,P(μ﹣2σ<Z<μ+2σ)=0.9544.20.(12分)已知抛物线C:y2=2px(p>0),其内接△ABC中∠A=90°当△ABC最短边所在直线方程为y=时,|BC|=5.(I)求抛物线C的方程;(II)当点A的纵坐标为常数t0(t0∈R)时,判断BC所在直线是否过定点?过定点求出定点坐标;不过定点,说明理由.21.(12分)己知函数f(x)=3x﹣e x+1,其中e=0.71828…,是自然对数的底数.(I)设曲线y=f(x)与x轴正半轴相交于点P(x0,0),曲线在点P处的切线为l,求证:曲线y=f(x)上的点都不在直线l的上方;(II)若关于x的方程f(x)=m(m为正实数)有两个不等实根x1,x2(x1<x2),求证:x2﹣x1.(二)选考题:共10分.请考生在第22、23题中任选一题作答,如果多做,则按所做的第一题计分.[选修4-4:坐标系与参数方程]22.(10分)在平面直角坐标系xOy中,曲线C1的普通方程为.以坐标原点为极点,x轴的正半轴为极轴建立极坐标系,曲线C2的极坐标方程为ρ2=2ρcosθ+1.(I)求曲线C1,C2的参数方程;(II)若点M,N分别在曲线C1,C2上,求|MN|的最小值.[选修4-5:不等式选讲]23.已知a,b,c为正数,函数f(x)=|x+1|+|x﹣3|.(I)求不等式f(x)≤6的解集:(II)若f(x)的最小值为m,且a+b+c=m,求证:.2018年山东省淄博市高考数学二模试卷(理科)参考答案与试题解析一、选择题:本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.(5分)己知M={x|﹣1≤x≤2},N={x|x≤3},则(∁R M)∩N=()A.[2,3]B.(2,3]C.(﹣∞,﹣1]∪[2,3]D.(﹣∞,﹣1)∪(2,3]【解答】解:M={x|﹣1≤x≤2},N={x|x≤3},∴∁R M={x|x<﹣1或x>2},∴(∁R M)∩N={x|x<﹣1或2<x≤3}=(﹣∞,﹣1)∪(2,3].故选:D.2.(5分)若复数z=(i是虚数单位),则|z|=()A.B.C.1D.【解答】解:z==.所以|z|=.故选:B.3.(5分)公差为2的等差数列{a n},前5项和为25,则a10=()A.21B.19C.17D.15【解答】解:由题意可得:5a1+=25,解得a1=1.∴a10=1+2×9=19.故选:B.4.(5分)公元263年左右,我国数学家刘徽发现当圆内接正多边形的边数无限增加时,多边形面积可无限逼近圆的面积,并创立了“割圆术”.如图是利用刘徽的“割圆术”思想设计的一个程序框图,则输出的n值为()(已知:sin15°≈0.2588,sin7.5°≈0.1305)A.12B.20C.24D.48【解答】解:模拟执行程序,可得:n=6,S=3sin60°=,不满足条件S≥3.10,n=12,S=6×sin30°=3,不满足条件S≥3.10,n=24,S=12×sin15°=12×0.2588=3.1056,满足条件S≥3.10,退出循环,输出n的值为24.故选:C.5.(5分)某几何体的主视图与俯视图如图所示,左视图与主视图相同,且图中的四边形都是边长为2的正方形,两条虚线互相垂直,则该几何体的体积是()A.B.C.6D.4【解答】解:由三视图知,原几何体为一个正方体挖掉一个正四棱锥其中正方体的棱为2,正四棱柱的底面边长为正方体的上底面,高为1∴原几何体的体积为故选:A.6.(5分)己知函数y=log a(x﹣1)+2(a>0,且a≠1)恒过定点A.若直线mx+ny=2过点A,其中m,n是正实数,则的最小值是()A.3B.3C.D.5【解答】解:令x﹣1=1可得x=2,故A(2,2),∴2m+2n=2,即m+n=1,∴=()(m+n)=1+++2≥3+2.当且仅当=即n=m时取等号.故选:B.7.(5分)将函数的图象向左平移个单位,得到函数y =g(x)的图象,若上为增函数,则ω的最大值为()A.1B.2C.3D.4【解答】解:函数的图象向左平移个单位,得到函数y=g(x)=2sin[ω(x+)﹣]=2sinωx的图象,由于:上为增函数,则:,则:ω≤2.故ω的最大值为2.故选:B.8.(5分)己知等比数列{a n}的前n项和为S n,且满足a2,2a5,3a8成等差数列,则=()A.或B.或3C.D.或【解答】解:等比数列{a n}的公比设为q,前n项和为S n,且满足a2,2a5,a8成等差数列,可得4a5=a2+3a8,即4a1q4=a1q+3a1q7,可得3q6﹣4q3+1=0,解得q=1或q3=,可得=或===.故选:A.9.(5分)双曲线C:=1(a,b>0)的上焦点为F,存在直线x=t与双曲线C交于A,B两点,使得△ABF为等腰直角三角形,则该双曲线离心率e=()A.B.2C.D.+1【解答】解:存在直线x=t与双曲线C交于A,B两点,使得△ABF为等腰直角三角形,则t=2c,∴A(2c,c),∴﹣=1,∵b2=c2﹣a2,e=,∴﹣=1,∴e2﹣=1,整理可得e4﹣6e2+1=0,解得e2=3+2=(+1)2,即e=+1,故选:C.10.(5分)函数f(x)=x2•cos x在的图象大致是()A.B.C.D.【解答】解:函数f(x)=x2•cos x在,满足f(﹣x)=f(x),所以函数是偶函数,排除选项A,C;当x∈(0,)时,f′(x)=2x cos x﹣x2sin x,令2x cos x﹣x2sin x=0,可得x tan x=2,方程的解x,即函数的极大值点x,排除D,故选:B.11.(5分)棱长为1的正方体ABCD﹣A1B1C1D1,动点P在其表面上运动,且与点A的距离是,点P的集合是一条曲线,则这条曲线的长度是()A.B.C.πD.【解答】解:由题意,此问题的实质是以A为球心、为半径的球在正方体ABCD﹣A1B1C1D1各个面上交线的长度计算,正方体的各个面根据与球心位置关系分成两类:ABCD、AA1DD1、AA1BB1为过球心的截面,截痕为大圆弧,各弧圆心角为、A1B1C1D1、B1BCC1、D1DCC1为与球心距离为1的截面,截痕为小圆弧,由于截面圆半径为r=,故各段弧圆心角为.∴这条曲线长度为3••+3••=.故选:B.12.(5分)若存在两个正实数x,y使得等式2x+a(y﹣2ex)(lny﹣lnx)=0成立(其中e 为自然对数的底数),则实数a的取值范围是()A.(﹣∞,0)B.C.D.【解答】解:解:由2x+a(y﹣2ex)(lny﹣lnx)=0得2x+a(y﹣2ex)ln=0,即2+a(﹣2e)ln=0,即设t=,则t>0,则2+a(t﹣2e)lnt=0,即(t﹣2e)lnt=﹣有解,设g(t)=(t﹣2e)lnt,则g′(t)=lnt+1﹣为增函数,∵g′(e)=lne+1﹣2=1+1﹣2=0,∴当t>e时,g′(t)>0,当0<t<e时,g′(t)<0,∴当t=e时,函数g(t)取得最小值g(e)=(e﹣2e)lne=﹣e,即g(t)≥g(e)=﹣e,若(t﹣2e)lnt=﹣有解,则﹣≥﹣e,即≤e,∴a<0或a≥,故选:D.二、填空题:本大题共4小题,每小题5分,共20分.13.(5分)从标有1,2,3,4,5的五张卡片中,依次抽出2张,则在第一次抽到偶数的条件下,第二次抽到奇数的概率为.【解答】解:在第一次抽到偶数时,还剩下1个偶数,3个奇数,∴在第一次抽到偶数的条件下,第二次抽到奇数的概率为.故答案为:.14.(5分)向量,满足=(1,),||=1,||=,则与的夹角为120°.【解答】解:,;∴;∴;∴.故答案为:120°.15.(5分)甲、乙、丙、丁、戊五位同学相约去学校图书室借A,B,C,D四类课外书(每类课外书均有若干本),己知每人均只借阅一本,每类课外书均有人借阅,且甲只借阅A 类课外书,则不同的借阅方案种类为60.(用数字作答)【解答】解:根据题意,分2种情况讨论:①,在乙、丙、丁、戊四人中,有1人与甲一起借阅A类课外书,需要先在4人中选出1人,再将剩下的3人全排列,对应剩下的三类课外书,此时有C41A33=24种借阅方案,②,在乙、丙、丁、戊四人中,没有人与甲一起借阅A类课外书,先将4人分成3组,再将分好的三组全排列,对应剩下的三类课外书,此时有C42A33=36种借阅方案,则一共有24+36=60种借阅方案,故答案为:6016.(5分)椭圆的左、右焦点分别为F1,F2,弦AB过F1,若△ABF2的内切圆周长为2π,A,B两点的坐标分别为(x1,y1)和(x2,y2),则|y2﹣y1|=3.【解答】解:由可得:a=6,c==4.如图所示,∵△ABF2的内切圆周长为2π,∴内切圆的半径r=1.由题意可得:r=|y2﹣y1|2c,∴2a×r=|y2﹣y1|c,∴|y2﹣y1|==3.故答案为:3.三、解答题:共70分.解答应写出文字说明、证明过程或演算步骤.第17~21题为必考题,每个试题考生都必须作答.第22、23题为选考题,考生根据要求作答.(一)必考题:60分.17.(12分)在△ABC中,,D为边BC上一点,DA⊥AB,且AD=.(I)若AC=2,求BD;(II)求的取值范围.【解答】解:(I)在△ACD中,∠CAD=﹣=,由余弦定理可得:CD==,由正弦定理可得,即,∴sin∠ACD=,cos∠ACD=.∴sin B=sin(﹣∠ACD)=cos C﹣sin C=.又sin B=,∴BD==.(II)在△ACD中,∠C=﹣B,∠CAD=,由正弦定理可得,∴==2sin(﹣B)=cos B﹣sin B,又=sin B,∴=cos B,∵0<B<,∴<cos B.即的取值范围是(,).18.(12分)如图,在三棱柱ABC﹣A1B1C1中,CA=CB=CC1=2,∠ACC1=∠CC1B1,直线AC与直线BB1所成的角为60°.(I)求证:AB1⊥CC1;(II)若AB1=,M是AB1上的点,当平面MCC1与平面AB1C所成二面角的余弦值为时,求的值.【解答】(Ⅰ)证明:CA=CB=CC1,∴四边形ACC1A1、BCC1B1皆为菱形,又直线AC与直线BB1所成的角为60°,∠ACC1=∠CC1B1,∴∠ACC1=∠B1BC=60°.取CC1中点O,连接AO,B1O,可得AO⊥CC1,B1O⊥CC1,又AO∩B1O=O,∴CC1⊥平面AOB1,则AB1⊥CC1;(Ⅱ)解:在Rt△AOC中,由AC=2,∠ACO=,可得AO=,在Rt△B1C1O中,由B1C1=2,∠,可得,又AB1=,得,∴OA⊥OB1.以O为坐标原点,分别以OB1,OC1,OA所在直线为x,y,z轴建立空间直角坐标系,B1(,0,0),C(0,﹣1,0),C1(0,1,0),A(0,0,).设=λ,则.,,,==.设平面MCC1的一个法向量为,由,取x=1,得z=﹣λ,则;平面AB1C的一个法向量为,由,取z=1,得.∵平面MCC1与平面AB1C所成二面角的余弦值为,∴|cos<>|=||=||=,解得或λ=2.∴的值为或2.19.(12分)有一片产量很大的芒果种植园,在临近成熟时随机摘下100个芒果,其质量频数分布表如下(单位:克):(I)(i)由种植经验认为,种植园内的芒果质量Z服从正态分布N(μ,σ2),其中μ近似为样本平均数,σ2近似为样本方差S2≈65.72.请估算该种植园内芒果质量在(191.8,323.2)内的百分比;(ii)某顾客从该种植园随机购买100个芒果,记X表示这100个芒果质量在区间(191.8,323.2)内的个数,利用上述结果,求E(X).(II)以各组数据的中间值代表这组数据的平均值,将频率视为概率,某经销商收购芒果10000个,并提出如下两种收购方案:A:所有芒果以每千克10元的价格收购;B:对质量低于150克的芒果以每个0.5元的价格收购,质量不低于150克但低于300克的以每个2元的价格收购,高于或等于300克的以每个5元的价格收购.请你用学过的相关知识帮助种植园主选择哪种方案才能获利更多?附:Z服从N(μ,σ2),则P(μ﹣σ<Z<μ+σ)=0.6826,P(μ﹣2σ<Z<μ+2σ)=0.9544.【解答】解:(I)(i)=125×0.1+175×0.1+225×0.15+275×0.4+325×0.2+375×0.05=257.5,∴x~N(257.5,65.72),∴P(191.8<x<323.2)=P(257.5﹣65.7<x<257.5+65.7)=0.6826.∴该种植园内芒果质量在(191.8,323.2)内的百分比约为68.26%.(ii)由题意可知X~B(100,0.6826),∴E(X)=100×0.6826=68.26.(II)若按方案A收购,则种植园主的收入为:10000××10=25750元,若按方案B收购,则种植园的收入为:10000×0.1×0.5+10000×(0.1+0.15+0.4)×2+10000×(0.2+0.05)×5=26000.∴选择方案B,种植园主获利更多.20.(12分)已知抛物线C:y2=2px(p>0),其内接△ABC中∠A=90°当△ABC最短边所在直线方程为y=时,|BC|=5.(I)求抛物线C的方程;(II)当点A的纵坐标为常数t0(t0∈R)时,判断BC所在直线是否过定点?过定点求出定点坐标;不过定点,说明理由.【解答】解:(I)联立方程组,解得或,∴A(8p,4p),不妨设B与原点重合,则直线AC的方程为:y=﹣2x+20p,联立方程组,消元可得2x2﹣41p+200p2=0,∴8p•x C=100p2,∴x c=,y C=﹣5p.即C(,﹣5p).∴|BC|==5,解得p=2.∴抛物线方程为:y2=4x.(II)A(,t0),设直线BC的方程为y=kx+b,B(,y1),C(,y2),∴k AB==,k AC=,∵AB⊥AC,∴=﹣1.即y1y2+t0(y1+y2)+t02+16=0.联立方程组,消去x可得y2﹣+=0,∴y1y2=,y1+y2=,∴++t02+16=0.即b=﹣t0﹣4k﹣,∴直线BC方程为:y=kx﹣t0﹣4k﹣=k(x﹣4﹣)﹣t0,∴直线BC经过定点(4+,﹣t0).21.(12分)己知函数f(x)=3x﹣e x+1,其中e=0.71828…,是自然对数的底数.(I)设曲线y=f(x)与x轴正半轴相交于点P(x0,0),曲线在点P处的切线为l,求证:曲线y=f(x)上的点都不在直线l的上方;(II)若关于x的方程f(x)=m(m为正实数)有两个不等实根x1,x2(x1<x2),求证:x2﹣x1.【解答】证明:(I)由题意可得:3x0﹣+1=0,=3x0+1,x0∈(1,).f′(x)=3﹣e x,f′(x0)=3﹣=3﹣3x0﹣1=2﹣3x0,可得:曲线在点P处的切线为l:y=(2﹣3x0)(x﹣x0),令g(x)=(2﹣3x0)(x﹣x0)﹣(3x﹣e x+1),g(x0)=0.g′(x)=2﹣3x0﹣3+e x=﹣1﹣3x0+e x,g′(x0)=﹣3x0+﹣1=0,可得函数g(x)在(﹣∞,x0)上单调递减,在(x0,+∞)上单调递增.∴g(x)≥g(x0)=0,因此:曲线y=f(x)上的点都不在直线l的上方.(II)由(I)可得:f′(x)=3﹣e x=0,解得x=ln3.f(ln3)=3ln3﹣3+1=3ln3﹣2.∴0<m<3ln3﹣2.曲线在点P处的切线为l:y=(2﹣3x0)(x﹣x0),x0∈(1,).同理可得:f(x)在点(0,0)处的切线为:y=2x.y=m与y=2x,y=(2﹣3x0)(x﹣x0)的交点的恒坐标分别为x3,x4.则x3=,x4=x0+.∴|x2﹣x1|<x4﹣x3=x0+﹣.下面证明:x0+﹣<2﹣.∵2﹣﹣x0﹣=2﹣x0﹣m=(2﹣x0)•.∵12x0﹣8+3m>4+3m>0.3x0﹣2>0.∴x0+﹣<2﹣.(二)选考题:共10分.请考生在第22、23题中任选一题作答,如果多做,则按所做的第一题计分.[选修4-4:坐标系与参数方程]22.(10分)在平面直角坐标系xOy中,曲线C1的普通方程为.以坐标原点为极点,x轴的正半轴为极轴建立极坐标系,曲线C2的极坐标方程为ρ2=2ρcosθ+1.(I)求曲线C1,C2的参数方程;(II)若点M,N分别在曲线C1,C2上,求|MN|的最小值.【解答】解:(Ⅰ)曲线C1的普通方程为.转换为参数方程为:(θ为参数).曲线C2的极坐标方程为ρ2=2ρcosθ+1.转换为直角坐标方程为:x2+y2=2x+1,转换为参数方程为:(α为参数),(Ⅱ)根据(Ⅰ)的方程,圆心(1,0)到曲线C1的距离为:d=,=,则:当cos,.所以:.[选修4-5:不等式选讲]23.已知a,b,c为正数,函数f(x)=|x+1|+|x﹣3|.(I)求不等式f(x)≤6的解集:(II)若f(x)的最小值为m,且a+b+c=m,求证:.【解答】解:(Ⅰ)f(x)=|x+1|+|x﹣3|≤6,等价于或或,解得﹣2≤x≤﹣1或﹣1<x<2或3≤x≤4,所以不等式f(x)≤6的解集为{x|﹣2≤x≤4}.(Ⅱ)证明:因为f(x)=|x+1|+|x﹣3|≥|(x+1)+(3﹣x)|=4,当且仅当(x+1)(x﹣3)≤0即﹣1≤x≤3时取等号.所以m=4,即a+b+c=4.∵a2+b2≥2ab,a2+c2≥2ac,c2+b2≥2bc,∴2(a2+b2+c2)≥2ab+2ac+2bc,∴3(a2+b2+c2)≥a2+b2+c2+2ab+2ac+2bc=(a+b+c)2=16.∴a2+b2+c2≥.当且仅当a=b=c =时等号成立.第21页(共21页)。
【最新推荐】2018届淄博市高考英语第二次模拟试卷及答案-范文模板 (20页)
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2018届淄博市高考英语第二次模拟试卷题目第二部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项,并在答题卡上将该项涂黑。
AMany schools across the US hold graduation ceremonies this timeof year. In some schools, even 5 and 6-year-olds observe their graduation from kindergarten. And so can older people, much older. Meet 70-year-old Jerry Reid, who just graduated from the Universityof Virginia in Charlottesville. He earned a bachelor’s degree.Mr. Reid might not look like the average college student; hishair is definitely grayer. But still Jerry Reid’s age is easy to forget, other UVA students know him as one of their own.Mr. Reid sat into the “Hoo Crew,” a group that cheers loudlyfor the school at sports events. He also joined a men's group on campus. He sang drinking songs along with many other students. Mr. Reid’s school friends say they can talk to him just about anything.About a half century ago, in his 20s, Mr. Reid was not in school. Instead, he was racing cars and chasing girls. But he says his friend Bill invited him to UVA parties.“Bill told me what a terrible life I had unless I came up here and went to school with him,” said Reid.That was in 1963. Jerry Reid says it took him 48 years to take that advice. In 201X, he entered college. UVA Professor Luke Wright says Mr. Reid influences students. He opened the minds of the young adults. The teacher says Mr. Reid showed them that life does not end at 40. Instead, the 70-year-old college graduate believes thatgetting older can be the beginning of a dream.“Remember that path that you left waits for you. It’s there. It’s yours. All you must do is to get out of your own way and get back to it. And, that's exactly what I did,” said Reid.Mr. Reid says that he and his wife Susan now would take some time off to enjoy his college degree. Then, he’ll return to UVA to begin studying for his graduate degree.21. Which of the following is true of Mr. Reid?A. He was laughed at by other students.B. He was interested in study in his youth.C. He enlarged the views of young people.D. He got his graduate degree at the age of 70.22. From the third paragraph, we can infer that Mr. Reid was_________.A. considerateB. independentC. intelligentD. energetic23. What does Paragraph 6 mainly discuss?A. How Mr. Reid realizes his dream.B. What teachers think of Mr. Reid.C. When Mr. Reid entered college.D. Why the students likes Mr. Reid.24. What lesson can we learn from the story of Jerry Reid?A. It is never too late to learn.B. Two heads are better than one.C. Actions speak louder than words.D. A friend in need is a friend indeed.BRaymond Wang, 17, of Canada was awarded first place for a device that improves air quality on airplanes while cutting down the spreading of diseases at this year’s Intel International Science and Engineering Fair (ISEF).According to Intel, Wang's system improves the quality of fresh air in a plane cabin by more than 190 per cent, while cutting diseases by up to 55 times, compared to conventional designs. Intel noted that Wang's invention could be easily and economically fixed into existing airplanes.Two other teen researchers earned awards of $50,000 each at the event. One developed a technique to more quickly diagnose diseases caused by HIV. It’s the virus responsible for AIDS. The other invented a device to more quickly shut down undersea oil spills.“Intel believes young people are the key to future innovation and that in order to confront the global challenges of tomorrow, we need students from all backgrounds to get involved in science, technology and engineering,” says Wendy Hawkins, executive director of the Intel Foundation. “We hope these winners will inspire other young people to pursue their interest in these fi elds,” she says, “and apply their curiosity and creativity to the common good.”This year's Intel International Science and Engineering Fair featured approximately 1,700 young scientists selected from more than 75 countries and regions. In addition to the top winners, 600finalists received awards and prizes for their innovative research.The Intel International Science and Engineering Fair honours the world’s most promising student scientists, inventors and engineers. Their projects are then evaluated online by nearly 1,000 judges from almost every scientific field.The 201X Intel ISEF is funded jointly by Intel and the Intel Foundation with additional awards and support from dozens of otheracademic, governmental and scientific organizations. This year, US$4 million was awarded.25. Compared to traditional designs, Raymond Wang’s system_________.A. prevents oceans from oil pollution quicklyB. improves air quality on airplanes effectivelyC. treats diseases happening on airplanes quicklyD. costs more but can be easily fixed into airplanes26. For what purpose is Intel ISEF carried out?A. To inspire teenagers to challenge the authorities.B. To persuade more teens to do good to the society.C. To get more teens involved in computer exploring.D. To encourage young people to get interested in science.27. What do we know about 201X Intel ISEF?A. More than 30% of finalists receive awards and prizes.B. Scientists all over the world compete for grand prizes.C. Nearly 1000 judges are present at the site of competition.D. US$4 million awards and prizes are offered by Intel alone.CWhere should an adventurous tourist go? After you’ve done sightseeing in London, shopping in New York, enjoyed the local food in Par is, and danced to your heart’s content at the Brazilian carnival, where else can you go? What attractive tourist destination awaits you?Well, Antarctica sounds like the holiday of a lifetime! It's considered the last great wilderness on Earth. Just a few scientists in research stations share the icy landscape with penguins and other animals which can struggle with the low temperatures.。
山东省淄博市部分学校2018届高三第二次模拟考试英语试卷
部分学校高三阶段性诊断考试试题英语注意事项:1.答题前填写好自己的姓名、班级、考号等信息2.请将答案正确填写在答题卡上3..考试结束后保留试卷方便讲解,只交答卷第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1.Why did the woman come back late?A.She had a meeting.B.She went to see the dentist.C.She stopped to buy cookies.2.What does the man think of lots of Japanese people? A.Quiet.B.Shy.C.Outgoing.3.How did the woman learn about the fire?A.From TV B.From radio.C.From Bob.4.Where are the speakers probably?A.In a cinema.B.In a library.C.In a dining hall.5.What does the woman advise the man to do?A.Be more careful.B.Buy a new car.C.Get his car checked.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。
每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项。
听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料,回答第6、7题。
6.Who bought a set of knives and forks for Tanya?A.Her mother.B.Her grandmother.C.Her grandfather.7.What does the woman decide to buy for Tanya?A.A sofa.B.Cushions.C.A set of glasses.请听第7段材料,回答第8、9题。
届淄博市高三英语二模拟试卷及答案
届淄博市高三英语二模拟试卷及答案2018届淄博市高三英语二模拟试卷及答案是国际交流语言,也是我国高考的重点科目,所以我们要加以重视多做一些模拟试卷备战高考,以下是店铺为你整理的2018届淄博市高三英语二模拟试卷,希望能帮到你。
2018届淄博市高三英语二模拟试卷题目第二部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项,并在答题卡上将该项涂黑。
AMany schools across the US hold graduation ceremonies this time of year. In some schools, even 5 and 6-year-olds observe their graduation from kindergarten. And so can older people, much older. Meet 70-year-old Jerry Reid, who just graduated from the University of Virginia in Charlottesville. He earned a bachelor’s degree.Mr. Reid might not look like the average college student; his hair is definitely grayer. But still Jerry Reid’s age is easy to forget, other UVA students know him as one of their own.Mr. Reid sat into the “Hoo Crew,” a group that cheers loudly for the school at sports events. He also joined a men's group on campus. He sang drinking songs along with many other students. Mr. Reid’s school fr iends say they can talk to him just about anything.About a half century ago, in his 20s, Mr. Reid was not in school. Instead, he was racing cars and chasing girls. But he says his friend Bill invited him to UVA parties.“Bill told me what a terrible life I had unless I came up hereand went to school with him,” said Reid.That was in 1963. Jerry Reid says it took him 48 years to take that advice. In 2011, he entered college. UVA Professor Luke Wright says Mr. Reid influences students. He opened the minds of the young adults. The teacher says Mr. Reid showed them that life does not end at 40. Instead, the 70-year-old college graduate believes that getting older can be the beginning of a dream.“Remember that path that you left waits for you. It’s there. It’s yours. All you must do is to get out of your own way and get back to it. And, that's exactly what I did,” said Reid.Mr. Reid says that he and his wife Susan now would take some time off to enjoy his college degree. Then, he’ll return to UVA to begin studying for his graduate degree.21. Which of the following is true of Mr. Reid?A. He was laughed at by other students.B. He was interested in study in his youth.C. He enlarged the views of young people.D. He got his graduate degree at the age of 70.22. From the third paragraph, we can infer that Mr. Reid was _________.A. considerateB. independentC. intelligentD. energetic23. What does Paragraph 6 mainly discuss?A. How Mr. Reid realizes his dream.B. What teachers think of Mr. Reid.C. When Mr. Reid entered college.D. Why the students likes Mr. Reid.24. What lesson can we learn from the story of Jerry Reid?A. It is never too late to learn.B. Two heads are better than one.C. Actions speak louder than words.D. A friend in need is a friend indeed.BRaymond Wang, 17, of Canada was awarded first place for a device that improves air quality on airplanes while cutting down the spreading of diseases at this year’s Intel International Science and Engineering Fair (ISEF).According to Intel, Wang's system improves the quality of fresh air in a plane cabin by more than 190 per cent, while cutting diseases by up to 55 times, compared to conventional designs. Intel noted that Wang's invention could be easily and economically fixed into existing airplanes.Two other teen researchers earned awards of $50,000 each at the event. One developed a technique to more quickly diagnose diseases caused by HIV. It’s the virus responsible for AIDS. The other invented a device to more quickly shut down undersea oil spills.“Intel believes young people are the key to future innovation and that in order to confront the global challenges of tomorrow, we need students from all backgrounds to get involved in science, technology and engineering,” says Wendy Hawkins, executive dire ctor of the Intel Foundation. “We hope these winners will inspire other young people to pursue their interest in these fields,” she says, “and apply their curiosity and creativity to the common good.”This year's Intel International Science and Engineering Fair featured approximately 1,700 young scientists selected from more than 75 countries and regions. In addition to the top winners, 600 finalists received awards and prizes for their innovative research.The Intel International Science and Engineering Fair honoursthe world’s most promising student scientists, inventors and engineers. Their projects are then evaluated online by nearly 1,000 judges from almost every scientific field.The 2015 Intel ISEF is funded jointly by Intel and the Intel Foundation with additional awards and support from dozens of other academic, governmental and scientific organizations. This year, US$4 million was awarded.25. Compared to traditional designs, Raymond Wang’s system _________.A. prevents oceans from oil pollution quicklyB. improves air quality on airplanes effectivelyC. treats diseases happening on airplanes quicklyD. costs more but can be easily fixed into airplanes26. For what purpose is Intel ISEF carried out?A. To inspire teenagers to challenge the authorities.B. To persuade more teens to do good to the society.C. To get more teens involved in computer exploring.D. To encourage young people to get interested in science.27. What do we know about 2015 Intel ISEF?A. More than 30% of finalists receive awards and prizes.B. Scientists all over the world compete for grand prizes.C. Nearly 1000 judges are present at the site of competition.D. US$4 million awards and prizes are offered by Intel alone.CWhere should an adventurous tourist go? After you’ve done sightseeing in London, shopping in New York, enjoyed the local food in Paris, and danced to your heart’s content at the Brazilian carnival, where else can you go? What attractive tourist destination awaits you?Well, Antarctica sounds like the holiday of a lifetime! It'sconsidered the last great wilderness on Earth. Just a few scientists in research stations share the icy landscape with penguins and other animals which can struggle with the low temperatures.Tourism began in Antarctica in the 1950s and it's still small part. About 37,000 tourists are expected there this season, but many won't even leave the boat.The BBC’s Juliet Rix visited the frozen continent and asked herself if she should be there at all, causing potential problems to such a sensitive environment. Her tour guide admitted that all visitors leave a footprint and they all go to the same places, the accessible coastline, which is also where the penguins and seals go to raise.But some people believe that if carefully controlled, tourism can be good for Antarctica. It has no native population and it needs advocates. Visitors to the icy continent might be ready to support and even to fund its preservation. And they're likely to engage in the discussion about global warming, which has led to the melting of glaciers.According to Rix, guidelines are followed when you’re about to set foot in Antarctica and tourists have to disinfect(消毒)their boots to make sure no alien species are introduced.And once on land, there's no eating or smoking. Rocks, bone fragments—nothing should be taken as a souvenir and nothing should be left behind.Tourists fortunate enough to visit the Antarctic must be aware that this is not their home and keep their fingers crossed that future generations will also be able to enjoy such breathtaking views.28. Who lives in Antarctica?A. 37,000 tourists.B. The BBC's Juliet Rix.C. A few scientists and animals.D. People in London and Paris.29. Why can tourism be good for Antarctica?A. People can bring some animals into it.B. People may take interest in the protection of it.C. People can give advice to the native population.D. People will go to the coastline to play with the seals.30. What are the guidelines when you go on the shore?A. You can leave rubbish on the shore.B. You can smoke and eat on the shore.C. You can take something as souvenirs.D. You can help to protect the environment.31. What is the author’s attitude towards the tourists going to Antarctica?A. Positive.B. Ambiguous.C. Subjective.D. Negative.DUntil recently, scientists had mapped only about 20 percent of the sea floor. But our knowledge of the deep seas is changing because of information from satellites. Scientists have produced a new map that provides a detailed picture of the oceans. The map is expected to help oceanographers (海洋学家), industry and governments.The new map is twice as detailed as the map made 20 years ago. David Sandwell is a geophysics professor at the University of California. He and other scientists worked on the mapping project. He says they turned to space to look deeper into the ocean.The scientists collected and studied information from two satellites. Some of the data came from the European SpaceAgency’s Cryo-2 satellite. It was placed in Earth's orbit to watch sea ice. The other satellite is the American space agency's Jason-1. It is studying the surface of the oceans. Scientists combined the satellite data with images gathered by sonar (声波定位仪) equipment on ships. Sonar works by sending sound waves through the water. When the sound waves hit an object, its presence is confirmed.The new map shows the sea floor as it has never been seen before. It shows thousands of underwater mountains and places where continents pulled apart. It shows where earthquakes were active many years ago. They all are buried deep underneath the ocean floor.David Sandwell says the map is a powerful tool for fisheries, those interested in protecting the environment and for oil exploration.“The petrol exploration industry is interested i n how to reconnect the continents, bring them back together tectonically so you can map the basins on one continental edge—say, Africa—and use that to establish where the similar basin would be on the other continental edge in South America.”If scientists know that information, they may be able to find oil fields. The new data also will help scientists improve their estimates of ocean depths. This information can help ships travel safely and improve military operations and scientific projects worldwide.Mr. Sandwell thinks scientists will make many more discoveries as they examine the new map and the information it provides.32. Which one is not mentioned about the benefits brought by the new map?A. Fisheries.B. Scientific projects.C. Ship manufacture.D. Oil exploration.33. What can we know about the new map?A. It shows where earthquakes will happen.B. It will be helpful to industry and governments.C. It is three times as detailed as the old one years ago.D. It shows the sea floor as it has ever been seen before.34. The text is likely to appear in _________.A. a newspaperB. an advertisementC. a science magazineD. a finance report35. Which of the following can be the best title for the text?A. The detailed picture of the oceansB. Underwater mountains and placesC. More discoveries about the oceansD. Scientists create new maps of ocean floor第二节(共5小题;每小题2分,满分10 分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
届淄博市高考英语二模拟试卷及答案
届淄博市高考英语二模拟试卷及答案2018届淄博市高考英语二模拟试卷及答案高考前不如多做一些高考模拟试卷,可以增加自己的语感和对高考英语题型的熟悉,下面是店铺为大家精心推荐的2018届淄博市高考英语二模拟试卷,希望能够对您有所帮助。
2018届淄博市高考英语二模拟试卷题目第一部分听力(共两节,满分30分)第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. Where was the woman’s phone yesterday?A. At her home.B. In a restaurant.C. In her office.2. Why didn’t the woman buy the coat?A. She disliked the colour.B. It didn’t fit her.C. The price was high.3. Why does the woman thank the man?A. He attended her party.B. He got her known to his friends.C. He found a new school for her.4. What’s the relationship between Lia and the woman?A. Neighbors.B. Classmates.C. Sisters.5. Which necklace will the woman buy?A. The red one.B. The blue one.C. The clear one.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。
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山东省泰安市2018届高三第二次模拟考试
英语试题2018.5
本试卷由四个部分组成。
其中,第一、二部分和第三部分的第一节为选择题。
第三部分的第二
节和第四部分为非选择题,共12页。
试卷满分150分,考试时间120分钟。
考试结束后,将本试卷和答题卡一并交回。
注意事项:
1.答题前,考生务必将自己的姓名、准考证号、考试科目涂写在答题卡上。
2.答选择题时,每小题选出答案后,用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,
用橡皮擦干净后,再选涂其他答案标号。
不能答在试卷上。
3.答非选择题时,将答案写在答题卡上。
写在本试卷上无效。
第一部分听力(共两节,满分30分)
做题时,先将答案标在试卷上。
录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到
答题卡上。
第一节(共5小题;每小题 1.5分,满分7.5分)
听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1.How much were the cards all together?
A.10 cents.B.14 cents.C.40 cents.
2.Why did the customer return the dress?
A.Because she didn’t like its color.
B.Because it was too small.
C.Because it was too expensive.
3.What kind of bike does Tom want to buy?
A.A heavier one.B.An expensive one.C.A racing one.
4.What does the woman mean?
A.They can’t be gotten now.
B.It’s the right season to grow it.
C.They have been sold out.
5.When would the man like to see the Great Wall?
A.In spring.B.In winter.C.In autumn.
第二节(共15小题;每小题 1.5分,满分22.5分)
听下面5段对话或独白。
每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选
出最佳选项,并标在试卷的相应位置。
听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听下面一段对话,回答第6和第7两个小题。
6.How long will Uncle’s family stay at Tom’s?
A.For about a week.
B.For at least four days.
C.For three days.
7.What can we infer about their ages?
A.Tom is older than Fay but younger than Rosemary.
B.Fay is two years younger than Rosemary.
C.Rosemary is younger than Fay but older than Tom.
听下面一段对话,回答第8至第10三个小题。
8.Where is the woman going?
A.To the library.B.To the cinema.C.To the classroom.
9.What does the man invite the woman to do?
A.Write papers.B.See a film.C.Do some reading.
10.Why does the woman refuse the man’s invitation?
A.She has three classes.
B.She has to take exams.
C.She has to do her schoolwork
听下面一段对话,回答第11至第13三个小题。
11.Where are the two speakers?
A.In a dining room.B.In a classroom.C.In a poo1.
12.When does the conversation take place?
A.In the morning.B.In the afternoon.C.In the evening.
13.What will the speakers do at the end of the talk?
A.Go to class.B.Eat breakfast.C.Go swimming.
听下面一段对话,回答第14至第16三个小题。
14.Why will the woman put on a show?
A.To make money.B.To have fun.C.To select singers.
15.What can we learn from the conversation?
A.Many people will watch the show.
B.Three songs will be sung in the show.
C.Three people will appear on the stage.。