2019学年绍兴柯桥区高三上期末
绍兴市柯桥区高2020届2019学年第一学期高三数学期末试题及答案
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三、解答题：本大题共 5 小题，共 74 分。解答应写出文字说明、证明或演算步骤。
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2019 学年第一学期期末教学质量检测 高三数学试题
注意事项：
1．本科考试分为试题卷和答题卷，考生须在答题卷上答题。 2．答题前，请在答题卷的规定处用黑色字迹的签字笔或钢笔填写学校、班级、姓名和准考 证号。 3．选择题的答案须用 2B 铅笔将答题纸上对应题目的答案标号涂黑。 4．试卷分为选择题和非选择题两部分，共 4 页。全卷满分 150 分，考试时间 120 分钟。
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………………10 分
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………………12 分
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所以函数 f (x) 的递增区间是[k − 5 , k + ](k z) ．
一、选择题：本大题共 10 小题，每小题 4 分，共 40 分。在每小题给出的四个选项中，只有一 项是符合题目要求的。
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2019-2020学年绍兴市柯桥中学高三英语上学期期末试题及参考答案
2019-2020学年绍兴市柯桥中学高三英语上学期期末试题及参考答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AF the Art World competition.Prize -The winner of each type will get the chance to display their artworks in a week-long exhibition inChelsea,New York..Eligibility - Open to artists all over the world..Entry Fee(参赛费)-$24 for a maximum of 3 submitted(提交的)photos..Date of Exhibition - From 25thApril to 2ndMay.F the Art World is an international art competition organized by which is quite unusual, compared to other competitions. The artworks are not judged on the basis of creativity and skill. Instead, they're judged by the depth of the subject matter. The subject this year is “A Competition About Change”, where artists can try and show how they'd like to change humanity in a good way.Notes*For this competition, there are three types for submissions, namely: street art, fine art, and digital art.*Each type will have a winner as chosen by the organizers and all the winners will have the wonderful chance to exhibit their works at the Unarthodox Gallery inNew Yorkin a week-long exhibition.*All the winners will also receive 100% of the sale price when any of their artworks are sold!Winners will also be displayed on the website and the entrants' artworks will also be displayed in the opening ceremony(仪式)as well.1.What is special about F the Art World Competition?AIt is free to attend.B.It lasts for over a week.C.It is open to artists inNew York.D.It centers on the depth of the artworks.2.What will the winners get?A.Prize money.B.A chance to visit an exhibition.C.A written judgement of their artworks.D.Money from the sale of their artworks.3.Where will the entrants' artworks be shown?A.In the street.B.In the opening ceremony.C.On the website.D.At the market.BParents and math teachers regularly asked by their school-aged charges whether math matters inreal life now have an answer.In a study published by the National Bureau of Economic Research this week, Harvard Kennedy School Policy Professor Joshua Goodman took a look at what happened to students whose high schools were required in the 1980s to increase the minimum level of coursework required to graduate. What he found is that the students were more likely to increase the number of math courses they took as a result of the change in standards and that translated into higher earnings down the line.Put simply: About 15 years after they graduated, the high school graduates who went to school when these changes took effect saw their average earnings increase about 10% for every extra year of math coursework. The findings may add fuel to the steady drum of education experts, policy makers and others calling for an increased focus on science and math education.The increase in required math courses didn’t necessarily produce rocket scientists, Goodman notes, because the extra coursework wasn’t at a particularly high level. But becoming familiar with and practicing ly basic math skills allowed high school graduates to pursue and excel at jobs that required some level of computational knowledge, he said.Goodman acknowledged that the earnings boost for the students connected with the up tick （上升）in math education may be dependent on the state of the economy. When Goodman checked in the late 1990s and early 2000s on the earnings of the students who graduated in the late 1985，he found that their earnings increased significantly if they took more math.4. What does Joshua Goodman’s study find?A. High school graduates earn more.B. High school students prefer math.C. Math matters a lot in one’s income.D. Math is a compulsory course in school.5. Why is increase in required math courses useful?A. It produced rocket scientists.B. It makes high school students smarter.C. It meets the requirements of the government.D. It enables high school graduates to get better jobs.6. What might be the author’s purpose in writing the text?A. To give a warning to policy makers.B. To seek help for high school students’ problems.C. To show the great importance of learning math.D. To tell a struggling history of high school students.7. What could be the best title for the text?A. Efforts matter mostB. Math makes moneyC. Earnings of different graduatesD. Changes of high school coursesCSome of the oldest art in human history is being damaged, scientists say. And climate change may be speeding up its loss. Newresearch reports that ancient rock art in Indonesian caves is degrading over time, as bits of rock slowly break off from the walls. It's a huge loss for human history.Salt crystals（结晶）building up on the walls are a key part of the problem, the study suggests. These salt crystals go into the cave walls, changing sizes as temperatures rise and fall. This process causes the rock to slowly break down.Salt crystals may become larger when exposed to repeated changes between wet conditions and periods of drought. These kinds of changes are expected to become more obvious as the climate continues to warm.In particular, the researchers say, climate change may cause more intense El Nino（厄尔尼诺）events in the future. These events can strengthen the kinds of conditions that help salt crystals form Scientists are still debating the exact influence of climate change on El Nino, a natural climate cycle that drives changing patterns of warming and cooling in thePacific Ocean.The new study, led by Jillian Huntley, examined 11 ancient cave art sites in South Sulawesi, Indonesia. The researchers found evidence of salt formation at all 11 sites. It's merely a small part There are more than 300known eave art sites around the region. The researchers note that salt crystals may indeed be part of the problem, adding that climate change is a growing threat, one that deserves more attention.8. What is the main cause of the rocks breaking off from the wall?A. Weather patterns.B. Salt crystals.C. Wet conditions.D. Drought Periods.9. Which of the following may researchers agree with?A. El Nino events prevent salt crystals forming.B. Climate change makes little difference to El Nino.C.Salt crystals may become much larger in wet conditions.D. Constant warm weather may cause salt crystals to change size.10. Which word best describes Huntley's attitude to climate change?A. Worried.B. Curious.C. Doubtful.D. Positive.11. What can we learn from thelast paragraph?A. The formation and patterns of salt crystals.B. The impact of climate change on ancient rock arts.C. The historical value of ancient rock art in cave sites.D. The threats of human activities to ancient eave art sites.DA cheap printed sensor could transmit wildfire warnings. Wildfires have recently destroyed regions across the world, and theirgravityis increasing. Hoping to reduce harm, researchersled by Yapei Wang, a Chinese chemist ofRenminUniversity, say they have developed an inexpensive sensor to detect such fires earlier with less effort.Current detection methods rely heavily on human watchfulness, which can delay an effective response. Most wildfires are reported by the general public, and other alerts come from routine foot patrols and watchtower observers. Passing planes and satellites also occasionally spot something, but “the fire first appears on the ground," Wang says. “ When you see the fire from the sky, it is too late. ”The team says its new sensor can be placed near tree trunks' bases and send a wireless signal to a nearby receiver if there is a dramatic temperature increase. That heat also powers the sensor itself, without replacing batteries. The team printed the substances onto ordinary paper to create a sensor for just $ 0.40.But improving coordination among the different agencies involved in firefighting is even more crucial to address, says Graham Kent, an earthquake expert at theUniversityofNevada,Reno, who was not part of thestudy.Kentis director of ALERTWildfire, a network that uses cameras and crowd sourcing to watch for fires inCalifornia,NevadaandOregon. “The whole way that you respond to a fire until it's put out is like a ballet," he says. “You'd have to choreograph (设计) it just so, with resources precisely used at the right time and place and in the right order from detection to confirmation to assignment to extinguishment (熄灭).Fire detection is just step one.Wang says his team's next steps are to extend the device'ssignal range beyond the current 100 meters, which can limit practical use, and to develop a protective shield for it. The transmitter's effectiveness, he notes, will also need to be examined in the field ahead.12. What does the underlined word “gravity” in paragraph 1 probably mean?A. Pull.B. Extinction.C. Popularity.D. Severity.13. What do we know about the sensor?A. Its price remains high.B. Its batteries are replaceable.C. It can detect fires earlier and easier.D. It can reduce firefighters' pain.14. What doesKentmean in paragraph 4?A. Firefighting is easy but crucial.B. Fire detection resources are rich.C. Putting out a fire is an orderly activity.D. Technology is the key to extinguishing a fire.15. What's the plan for the new sensor according to Wang?A. Improving and testing it.B. Limiting its use and transmission.C. Examing and reducing its signal range.D. Getting it on the market ahead of time.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
2019-2020学年绍兴市高级中学高三语文上学期期末考试试卷及参考答案
2019-2020学年绍兴市高级中学高三语文上学期期末考试试卷及参考答案一、现代文阅读（36分）(一)现代文阅读I(9分)阅读下面的文字，完成下面小题。
材料一：在漫长的历史进程中，我国的农耕文明催生了数以万计的乡村聚落。
在自然和文化的共同约束下，当地居民通过自己的生产、生活方式不断适应和改造着周边的自然环境，塑造了独特的景观形态和社会关系。
这些保留至今由人与自然持续互动的结果就是乡村遗产，也是研究乡村地区人地关系的重要的“活”文本。
因此，乡村遗产兼具“历史文化遗产地”和“乡村生产生活承载地”的双重特征，包含了山体、水体、建筑、植被等有形的物质层面，也蕴含了哲学观、生产技术、生活智慧等一切无形的精神层面。
在遗产保护领域，价值认定是保护的前提。
文化遗产的内在价值通常被理解为历史、审美和科学价值。
所以，对乡村遗产的认知与保护首先应以价值为导向。
作为乡村遗产的核心组成部分，乡土建筑是指散落于村镇中、富有地方特色的传统建筑，除了一般的居民住宅外，还包括与人生活息息相关的祠堂、商铺、作坊、桥梁等建筑。
乡土建筑是乡居文明的物质和精神载体，其建筑形态和建筑装饰等更为多样复杂，与其周边自然环境的关系更密切,很多乡村地区特别是少数民族的建筑中包含有非物质文化遗产。
因此，在乡村遗产视野下审视乡土建筑的价值时，不仅要关注建筑本体的价值（其蕴含的历史价值和艺术价值，包括建筑自身的历史久远度，与重要事件、人物或文化的关联度，某一地域或民族建筑类型的代表性，或者艺术审美上的价值），更要研究其背后所体现的人与自然、人与社会的关系。
（摘编自复旦大学国土与文化资源研究中心《乡村遗产视野下的乡土建筑》）材料二：在乡村遗产的保护实践工作中，应尝试在原生土壤中理解、尊重当地居民关于遗产的种种认知和实践行为，协助他们找到一条可持续的保护道路。
位于福建省永泰县的永泰庄寨与不同家族的迁徙繁衍有关。
诸多家族搬迁到永泰后，开始建造居所。
一些家族在营建过程中更注重安全性，逐渐形成了一个大家族共有的聚居防御空间。
2019年绍兴市高三数学上期末模拟试卷(及答案)
2019年绍兴市高三数学上期末模拟试卷(及答案)一、选择题1．已知点(),M a b 与点()0,1N -在直线3450x y -+=的两侧，给出以下结论：①3450a b -+>；②当0a >时，+a b 有最小值，无最大值；③221a b +>；④当0a >且1a ≠时，11b a +-的取值范围是93,,44⎛⎫⎛⎫-∞-⋃+∞ ⎪ ⎪⎝⎭⎝⎭，正确的个数是（ ） A ．1B ．2C ．3D ．42．若正实数x ，y 满足141x y +=，且234yx a a +>-恒成立，则实数a 的取值范围为（ ） A ．[]1,4-B ．()1,4-C ．[]4,1-D ．()4,1-3．数列{}n a 满足()11nn n a a n ++=-⋅，则数列{}n a 的前20项的和为( ) A ．100B ．-100C ．-110D ．1104．已知数列{}n a 中，()111,21,n n na a a n N S *+==+∈为其前n 项和，5S的值为（ ）A ．63B ．61C ．62D ．575．正项等比数列中，的等比中项为，令，则（ ） A ．6B ．16C ．32D ．646．设等比数列{}n a 的前n 项和为n S ，若633S S =， 则96S S =（ ） A ．2B ．73C ．83D ．37．已知实数x 、y 满足约束条件00134x y x ya a⎧⎪≥⎪≥⎨⎪⎪+≤⎩，若目标函数231x y z x ++=+的最小值为32，则正实数a 的值为（ ） A ．4B ．3C ．2D ．18．若变量x ，y 满足约束条件1358x y x x y ≥-⎧⎪≥⎨⎪+≤⎩，，，则2yz x =-的取值范围是（ ）A ．113⎡⎤-⎢⎥⎣⎦，B ．11115⎡⎤--⎢⎥⎣⎦，C ．111153⎡⎤-⎢⎥⎣⎦， D ．3153⎡⎤-⎢⎥⎣⎦，9．若a 、b 、c >0且a (a ＋b ＋c )＋bc ＝4－23，则2a ＋b ＋c 的最小值为( ) A ． 3－1 B ． 3＋1 C ．23＋2D ．23－210．“0x >”是“12x x+≥”的 A ．充分不必要条件 B ．必要不充分条件 C ．充要条件D ．既不充分也不必要条件11．设n S 为等差数列{}n a 的前n 项和，1(1)()n n n S nS n N *++∈＜.若871a a <-，则（ ） A ．n S 的最大值为8S B ．n S 的最小值为8S C ．n S 的最大值为7S D ．n S 的最小值为7S12．设2z x y =+，其中,x y 满足2000x y x y y k +≥⎧⎪-≤⎨⎪≤≤⎩，若z 的最小值是12-，则z 的最大值为（ ） A ．9-B ．12C ．12-D ．9二、填空题13．数列{}n a 满足14a =，12nn n a a +=+，*n N ∈，则数列{}n a 的通项公式n a =______.14．已知数列{}n a 的首项12a =，且满足()*12n n n a a n N +=∈，则20a =________．15．已知是数列的前项和，若，则_____．16．设,x y 满足约束条件0{2321x y x y x y -≥+≤-≤，则4z x y =+的最大值为 .17．若ABC ∆的三个内角45A =︒，75B =︒，60C =︒，且面积623S =+形的外接圆半径是______18．已知a b c R ∈、、，c 为实常数，则不等式的性质“a b a c b c >⇐+>+”可以用一个函数在R 上的单调性来解析，这个函数的解析式是()f x =_________19．等差数列{}n a 前9项的和等于前4项的和.若141,0k a a a =+=，则k = . 20．在数列{}n a 中，11a =，且{}n a 是公比为13的等比数列．设13521T n n a a a a L -=++++，则lim n n T →∞=__________．(*n ∈N ) 三、解答题21．在()f x 中，角,,A B C 的对边分别为,,a b c ，满足(2)cos cos b c A a C -=．(1)求角A 的大小(2)若3a =，求ABC △的周长最大值． 22．在△ABC 中，已知AC ＝4，BC ＝3，cosB ＝－14. (1)求sin A 的值； (2)求·BA BC u u u v u u u v的值.23．在ABC V 中内角,,A B C 所对的边分别为,,a b c .已知2,a b ==，面积S =. （1）求sin A 的值；（2）若点D 在BC 上（不含端点），求sin BDBAD∠的最小值.24．在ABC △中，内角A ，B ，C 所对的边分别为a ，b ，c.已知sin cos 6b A a B π⎛⎫=- ⎪⎝⎭. （1）求角B 的大小；（2）设a =2，c =3，求b 和()sin 2A B -的值. 25．已知函数221()cos sin ,(0,)2f x x x x p =-+?． （1）求()f x 的单调递增区间；（2）设ABC V 为锐角三角形，角A 所对边a =，角B 所对边5b =，若()0f A =，求ABC V 的面积．26．已知数列{}n a 的前n 项和为n S ，且4133n n S a =-. （1）求{}n a 的通项公式；（2）若1n b n =+，求数列{}n n a b 的前n 项和n T .【参考答案】***试卷处理标记，请不要删除一、选择题 1．B 解析：B 【解析】 【分析】 【详解】∵点M (a ,b )与点N (0,−1)在直线3x −4y +5=0的两侧,∴()()34530450a b -+⨯++<，即3450a b -+<，故①错误； 当0a >时,54a b +>，a +b 即无最小值，也无最大值，故②错误； 设原点到直线3x −4y +5=0的距离为d ,则22513(4)==+-d ,则22a b +>1，故③正确；当0a >且a ≠1时,11b a +-表示点M (a ,b )与P (1,−1)连线的斜率． ∵当0a =,b =54时,51194114b a ++==---,又直线3x −4y +5=0的斜率为34， 故11b a +-的取值范围为93,,44⎛⎫⎛⎫-∞-⋃+∞ ⎪ ⎪⎝⎭⎝⎭，故④正确.∴正确命题的个数是2个. 故选B.点睛：本题是常规的线性规划问题，线性规划问题常出现的形式有：①直线型，转化成斜截式比较截距，要注意z 前面的系数为负时，截距越大，z 值越小；②分式型，其几何意义是已知点与未知点的斜率；③平方型，其几何意义是距离，尤其要注意的是最终结果应该是距离的平方；④绝对值型，转化后其几何意义是点到直线的距离.2．B解析：B 【解析】 【分析】 根据1444y y x x x y ⎛⎫⎛⎫+=++ ⎪ ⎪⎝⎭⎝⎭，结合基本不等式可求得44yx +≥，从而得到关于a 的不等式，解不等式求得结果. 【详解】 由题意知：1442444y y x yx x x y y x⎛⎫⎛⎫+=++=++ ⎪ ⎪⎝⎭⎝⎭ 0x Q >，0y > 40x y ∴>，04yx>442244x y x yy x y x∴+≥⋅=（当且仅当44x y y x =，即4x y =时取等号） 44yx ∴+≥ 234a a ∴-<，解得：()1,4a ∈- 本题正确选项：B 【点睛】本题考查利用基本不等式求解和的最小值问题，关键是配凑出符合基本不等式的形式，从而求得最值.3．B解析：B 【解析】 【分析】数列{a n }满足1(1)nn n a a n ++=-⋅，可得a 2k ﹣1+a 2k ＝﹣（2k ﹣1）．即可得出．【详解】∵数列{a n }满足1(1)nn n a a n ++=-⋅，∴a 2k ﹣1+a 2k ＝﹣（2k ﹣1）．则数列{a n }的前20项的和＝﹣（1+3+……+19）()101192⨯+=-=-100．故选：B ． 【点睛】本题考查了数列递推关系、数列分组求和方法，考查了推理能力与计算能力，属于中档题．4．D解析：D 【解析】解：由数列的递推关系可得：()11121,12n n a a a ++=++= ， 据此可得：数列{}1n a + 是首项为2 ，公比为2 的等比数列，则：1122,21n n n n a a -+=⨯⇒=- ，分组求和有：()5521255712S ⨯-=-=- .本题选择D 选项.5．D解析：D 【解析】因为，即，又，所以.本题选择D选项.6．B解析：B【解析】【分析】首先由等比数列前n项和公式列方程，并解得3q，然后再次利用等比数列前n项和公式，则求得答案．【详解】设公比为q，则616363313(1)1113(1)11a qS qqqa qS qq---===+=---，∴32 q=，∴93962611271123 S qS q--===--．故选：B．【点睛】本题考查等比数列前n项和公式，考查函数与方程思想、转化与化归思想，考查逻辑推理能力、运算求解能力，求解时也可以利用连续等长片断的和序列仍然成等比数列，进行求解.7．D解析：D【解析】【分析】作出不等式组所表示的可行域，根据目标函数的几何意义，利用直线斜率的几何意义以及数形结合进行求解即可.【详解】目标函数()12123112111x yx y yzx x x++++++===+⨯+++，设11ykx+=+，则k的几何意义是区域内的点与定点(1,1)D--连线的斜率，若目标函数231x yzx++=+的最小值为32，即12z k=+的最小值是32，由3122k+=，得14k=，即k的最小值是14，作出不等式组对应的平面区域如图：由斜率的意义知过D 的直线经过()3,0B a 时，直线的斜率k 最小，此时011314k a +==+， 得314a +=，得1a =. 故选：D. 【点睛】本题考查利用线性规划中非线性目标函数的最值求参数，解题时要结合非线性目标函数的几何意义寻找最优解，考查数形结合思想的应用，属于中等题.8．A解析：A 【解析】 【分析】画出满足条件的平面区域，求出角点的坐标，结合2yz x =-的几何意义求出其范围，即可得到答案. 【详解】由题意，画出满足条件的平面区域，如图所示： 由358y x x y =⎧⎨+=⎩，解得11A (，)，由1x y x =-⎧⎨=⎩，解得(11)B --，， 而2yz x =-的几何意义表示过平面区域内的点与0(2)C ，的直线斜率， 结合图象，可得1AC k =-，13BC k =， 所以2y z x =-的取值范围为113⎡⎤-⎢⎥⎣⎦，， 故选：A.【点睛】本题主要考查了简单的线性规划问题，其中解答中作出约束条件所表示的平面区域，结合图象确定出目标函数的最优解是解答的关键，着重考查了数形结合思想，以及计算能力，属于基础题.9．D解析：D【解析】由a(a＋b＋c)＋bc＝4－3，得(a＋c)·(a＋b)＝4－3∵a、b、c>0.∴(a＋c)·(a＋b)≤22b c2a++⎛⎫⎪⎝⎭(当且仅当a＋c＝b＋a，即b＝c时取“＝”)，∴2a＋b＋c423－＝31)＝3－2.故选：D点睛：在利用基本不等式求最值时，要特别注意“拆、拼、凑”等技巧，使其满足基本不等式中“正”(即条件要求中字母为正数)、“定”(不等式的另一边必须为定值)、“等”(等号取得的条件)的条件才能应用，否则会出现错误10．C解析：C【解析】先考虑充分性,当x>0时，1122x xx x+≥⋅=，当且仅当x=1时取等.所以充分条件成立.再考虑必要性，当12xx+≥时，如果x>0时，22210(1)0x x x-+≥∴-≥成立，当x=1时取等.当x<0时，不等式不成立. 所以x>0.故选C.11．C解析：C 【解析】 【分析】由已知条件推导出（n 2﹣n ）d ＜2n 2d ，从而得到d ＞0，所以a 7＜0，a 8＞0，由此求出数列{S n }中最小值是S 7． 【详解】∵（n +1）S n ＜nS n +1， ∴S n ＜nS n +1﹣nS n ＝na n +1 即na 1()12n n d-+＜na 1+n 2d ，整理得（n 2﹣n ）d ＜2n 2d ∵n 2﹣n ﹣2n 2＝﹣n 2﹣n ＜0 ∴d ＞0 ∵87a a -＜1＜0 ∴a 7＜0，a 8＞0 数列的前7项为负， 故数列{S n }中最小值是S 7 故选C ． 【点睛】本题考查等差数列中前n 项和最小值的求法，是中档题，解题时要认真审题，注意等差数列的性质的灵活运用．12．B解析：B 【解析】 【分析】作出不等式对应的可行域，当目标函数过点A 时，z 取最小值，即min 12z =-，可求得k 的值，当目标函数过点B 时，z 取最大值，即可求出答案. 【详解】作出不等式对应的可行域，如下图阴影部分，目标函数可化为2y x z =-+，联立20x y y k +=⎧⎨=⎩，可得()2,A k k -，当目标函数过点A 时，z 取最小值，则()2212k k ⨯-+=-，解得4k =，联立0x y y k-=⎧⎨=⎩，可得(),B k k ，即()4,4B ，当目标函数过点B 时，z 取最大值，max 24412z =⨯+=.故选：B.【点睛】本题考查线性规划，考查学生的计算求解能力，利用数形结合方法是解决本题的关键，属于基础题.二、填空题13．【解析】【分析】由题意得出利用累加法可求出【详解】数列满足因此故答案为：【点睛】本题考查利用累加法求数列的通项解题时要注意累加法对数列递推公式的要求考查计算能力属于中等题 解析：22n +【解析】 【分析】由题意得出12nn n a a +-=，利用累加法可求出n a .【详解】数列{}n a 满足14a =，12n n n a a +=+，*n N ∈，12nn n a a +∴-=，因此，()()()211213214222n n n n a a a a a a a a --=+-+-++-=++++L L ()121242212n n --=+=+-.故答案为：22n +. 【点睛】本题考查利用累加法求数列的通项，解题时要注意累加法对数列递推公式的要求，考查计算能力，属于中等题.14．512【解析】【分析】利用已知将n 换为n+1再写一个式子与已知作比得到数列的各个偶数项成等比公比为2再求得最后利用等比数列的通项公式即可得出【详解】∵anan+1=2n （）∴an+1an+2=2n+解析：512 【解析】 【分析】利用已知将n 换为n +1，再写一个式子，与已知作比，得到数列{}n a 的各个偶数项成等比，公比为2，再求得2=1a ，最后利用等比数列的通项公式即可得出． 【详解】∵a n a n +1=2n ，（*n N ∈） ∴a n +1a n +2=2n +2．（*n N ∈）∴22n na a +=,（*n N ∈），∴数列{}n a 的各个奇数项513...a a a ，，成等比，公比为2， 数列{}n a 的各个偶数项246...a a a ，，成等比，公比为2， 又∵a n a n +1=2n ，（*n N ∈），∴a 1a 2=2,又12a =，∴2=1a ， 可得：当n 为偶数时，1222n n a a -=⋅∴a 20＝1•29＝512． 故答案为：512． 【点睛】本题考查了等比数列的通项公式、数列递推关系，考查了推理能力与计算能力，属于中档题．15．4950【解析】【分析】由an+Sn ＝2nan+1+Sn+1＝2n+1两式相减可得2an+1﹣an ＝2n 即可计算【详解】解：∵an+Sn＝2nan+1+Sn+1＝2n+1两式相减可得2an+1﹣an 解析：【解析】 【分析】由a n +S n ＝2n ，a n +1+S n +1＝2n +1，两式相减可得2a n +1﹣a n ＝2n ．即可计算． 【详解】解：∵a n +S n ＝2n ，a n +1+S n +1＝2n +1， 两式相减可得2a n +1﹣a n ＝2n ．则（2a 2﹣a 1）（2a 3﹣a 2）…（2a 100﹣a 99）＝21•22•23…299＝24950．【点睛】本题考查了数列的递推式，属于中档题．16．【解析】试题分析：约束条件的可行域如图△ABC 所示当目标函数过点A(11)时z 取最大值最大值为1+4×1=5【考点】线性规划及其最优解解析：【解析】 .试题分析：约束条件的可行域如图△ABC 所示.当目标函数过点A(1，1)时，z 取最大值，最大值为1+4×1=5.【考点】线性规划及其最优解.17．【解析】【分析】设三角形外接圆半径R 由三角形面积公式解方程即可得解【详解】由题：设三角形外接圆半径为R （）根据正弦定理和三角形面积公式：即解得：故答案为：【点睛】此题考查三角形面积公式和正弦定理的应 解析：2【解析】 【分析】设三角形外接圆半径R ，由三角形面积公式21sin 2sin sin sin 2S ab C R A B C ==解方程即可得解. 【详解】由题：232162sin sin 75sin(4530)222B +=︒=︒+︒=+=设三角形外接圆半径为R （0R >），根据正弦定理和三角形面积公式：211sin 2sin 2sin sin 2sin sin sin 22S ab C R A R B C R A B C ==⋅⋅= 即223623226R ++=， 解得：22R = 故答案为：2【点睛】此题考查三角形面积公式和正弦定理的应用，利用正弦定理对面积公式进行转化求出相关量，需要对相关公式十分熟练.18．【解析】【分析】构造函数通过讨论其单调性即解析不等式的性质【详解】函数是定义在上的单调增函数若则即即故答案为：【点睛】此题考查利用函数单调性解析不等式的性质利用常见函数的单调性结合不等式的特征即可求 解析：x c -【解析】 【分析】构造函数()f x x c =-，通过讨论其单调性即解析不等式的性质． 【详解】函数()f x x c =-，是定义在R 上的单调增函数， 若a c b c +>+，则()()f a c f b c +>+，即a c c b c c +->+-， 即a b >． 故答案为：x c - 【点睛】此题考查利用函数单调性解析不等式的性质，利用常见函数的单调性结合不等式的特征即可求解．19．10【解析】【分析】根据等差数列的前n 项和公式可得结合等差数列的性质即可求得k 的值【详解】因为且所以由等差数列性质可知因为所以则根据等差数列性质可知可得【点睛】本题考查了等差数列的前n 项和公式等差数解析：10 【解析】 【分析】根据等差数列的前n 项和公式可得70a =，结合等差数列的性质即可求得k 的值． 【详解】因为91239S a a a a =+++⋅⋅⋅ 41234S a a a a =+++，且94S S =所以567890a a a a a ++++= 由等差数列性质可知70a = 因为40k a a += 所以4770k a a a a +=+=则根据等差数列性质可知477k +=+ 可得10k = 【点睛】本题考查了等差数列的前n 项和公式，等差数列性质的应用，属于基础题．20．【解析】【分析】构造新数列计算前n 项和计算极限即可【详解】构造新数列该数列首项为1公比为则而故【点睛】本道题考查了极限计算方法和等比数列前n 项和属于中等难度的题目解析：9lim 8n n T →∞=【解析】 【分析】构造新数列{}21n a -，计算前n 项和，计算极限，即可。
绍兴市柯桥区2019学年第一学期高三数学期末试题_PDF压缩
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浙江省绍兴市柯桥区2019届高三上学期1月教学质量检测(期末考试)语文试题
【题文】阅读下面的文字，根据要求作文。
有人说：“好看的皮囊千篇一律，有趣的灵魂万里挑一。
”对此你有什么感想？请写一篇文章。
注意：①角度自选，立意自定，题目自拟。
②明确文体，不得写成诗歌。
③不少于800字。
④不得抄袭、套作。
【答案】有趣的灵魂，永久的魅力有人说，初识一个人，第一印象完全取决于外貌。
两个互不相识的人初次见面，漂亮的外在，是吸引别人关注的第一要素。
但随着时间的流逝，两个人是否能从陌生人发展成熟人，再变成朋友或者恋人，外在就不是先决条件了。
而有趣的灵魂，才是持续的吸引力。
有趣的灵魂，最是难能可贵。
与一个有趣的人聊天，总是充满乐趣，笑容满面。
不用担心彼此没话可说，更不用担心在一起时无聊至极。
有趣的灵魂，总是自由而又让人向往。
机械枯燥的生活，总是会让人失去初心，变得暗淡无光，变得失去自己。
而有趣的灵魂，总是如莲花一般，出淤泥而不染，保持真我，散发出沁人心脾的清香。
在浑浑噩噩的现实世界中，拥有一个有趣的灵魂，可以称之为混沌浑浊中的一股清流。
面对不那么顺心如意的现实生活，有人因此失去了自己的棱角，丧失了最后一丁点脾气，没有了自己的爱好。
于是，我们周边开始充斥着越来越多没趣的人，当人现实到可怕的程度，生活也就只剩下了苟且。
我们所说的诗和远方，大抵只有有趣的灵魂才会去追寻。
因为人们一旦向现实生活的残酷低头，就失去了憧憬美好和不放弃追求的初心。
能够笑看人生，在没趣的世界中保持有趣的灵魂的人，总是寥寥无几，难能可贵。
人和人最大的区别，不是外表而是内在。
长得好看的人总是漂亮得很相似，而有趣的灵魂，却总是独一无二、万里挑一。
人与人之间最大的区别，永远都不是外表，而是内在。
一个心灵丑恶的人，长得再漂亮，嘴脸也是招人烦；而一个外表不怎么符合主流审美的人，如若心灵足够慈善，也会散发出由内而外的真正的美感。
这个世界上，其实没有特别丑的人，只要稍微拾掇一下，长相上并无太大差异。
所以，真正能让一个人脱颖而出、与众不同的，不是千篇一律的外在，而是万里挑一的内在。
浙江省柯桥区2019届高三历史上学期期末教学质量调测试题(扫描版)
高三历史试卷参考答案与评分标准一、单选题 1-5：DABAB 6-10：CBDAA 11-15：DBDCB 16-20：CAABC 21.BBACB 26-30：CCACD二、非选择题31．（1）中美两国正式建立外交关系，从此实现两国关系正常化；（2 分）为中国社会主义现代化建设争取一个较长时期的和平的国际环境；（2 分）促进中国利用西方的资金、技术、机制，深化改革、扩大开放。
（2 分）（2）三次机遇：建省、设经济特区——建国际旅游岛——建全岛自由贸易试验区（2 分）。
意义：成为我国扩大开放的窗口和改革的“试验田”；顺应了经济全球化，贸易自由化的趋势，有力地推动了改革开放和社会主义现代化建设。
（2 分） 32.（1）主张：认为财产私有权是“天赋权利”；伏尔泰不反对财产不平等；卢梭认为私有制是人类不平等的起源，主张财产平等。
（3 分）作用：高扬“理性”与“天赋人权”两面旗帜，以“财产私有权”为基础，用“自由平等”把人们从封建专制和等级特权的藩篱中解放出来。
（2 分，其他言之成理可酌情给分）（2）理由：制定中国第一部资产阶级宪法《临时约法》；效仿美国三权分立制度，总统执掌行政大权；模仿英法，实行责任内阁制，以限制总统权力。
（3 分）成果：五四运动爆发，标志着中国新民主主义革命的开端；新文化运动宣扬民主与科学，促进马克思主义的传播。
（2 分，其他言之成立可酌情给分）33．（1）《九十五条论纲》。
（1 分）影响：使人们获得灵魂自救的自主权和精神自由，从广泛的社会层面和更内在的心灵角度传播了人文主义，将西欧人从长期的基督教神权统治中解放出来，为启蒙运动的到来做了思想上的准备，促进了德意志民族国家的形成（或增强了德意志民族意识）。
（5 分）（2）侧重解读①：气候变冷影响了经济基础和社会结构的变化（可以展开）（2 分）使当时人们心理受到影响，开始着力追求现世生活。
（2 分）侧重解读②：朱熹区分了教育的“小学”和“大学”两个阶段，强调日积月累和循序渐进（或格物致知），陆九渊反对埋首书册，主张于人生日常处直接体悟理，“发明本心”。
2020年1月学考选考浙江省绍兴市柯桥区2019学年第一学期高三期末教学质量检测数学试题参考答案
2
2
4
4
由余弦定理可得： cos FAH = AH 2 + AF 2 − HF 2 = 4
70
.
2AH AF
35
………………14 分
所以 AF 与平面 ACF 所成角的余弦值为 4 70 ． 35
………………15 分
20．解：（1）设首项为 a1
，公差为
d
，则
a1 + d = −3 4a1 + 6d = 2(a1
A
所以 BC ⊥ AD ，
………………3 分
又由于 EA = EB = ED ，所以 AD ⊥ BC ，
BG
E
HF
C
所以 AD ⊥ 平面 ABC ，所以 AD ⊥ AC .………………7 分 D （2）取 BE 中点 G ，连接 GF 与 CE 相交于 H ，由于平面
ABD ⊥ 平面 BCD ，且 AG ⊥ BD ，所以 AG ⊥ 平面 BCD ，
………………15 分
22．解：（1）当 a = 2 时， f (x) = −2e−2x + 2 ，
………………2 分
由于 f (0) = 0 ，且函数 f (x) 单调递增，
案 答 考 选 考 学 省 江 浙
所以当 x 0 时， f (x) 0 ，当 x 0 时， f (x) 0 ， 故函数的单调递减区间是 (−, 0) ，递增区间是 (0, +) ．
………………4 分 ………………5 分
（2）令 x = 0 ，得 a 2 ，所以 11 a 2 ． 2
因为 f (x) a (x2 +1) eax ( a x2 − 2x + a ) 1，
2
2019-2020学年绍兴市柯桥中学高三英语期末考试试卷及答案解析
2019-2020学年绍兴市柯桥中学高三英语期末考试试卷及答案解析第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AAmid the coronavirus outbreak, the U. S. Department of Homeland Security recommends having at least a two - week supply of water and food.PotatoesShelf life：2 to 5 weeks if stored in a cool, dry, dark placeYukon Gold, red, and fingerling potatoes will last from two to three weeks. Larger white potatoes can last for three to five weeks. Sweet potatoes have about the same shelf life. Don't store them next to onions, however. The two might go together well in cooking, but raw, each gives off gases and moisture that might cause the other to spoil faster.Tea※Shelf life：6 to 12 months past "sell - by" dateDried tea leaves, whether loose (in a sealed container) or in teabags (in an unopened box) can easily last a year or more if they' re not subjected to damp or humidity. However, the tea does tend to lose flavor over time.Peanuts● Shelf life：1 to 2 monthsPeanuts in their shell, especially when kept cool and dry, are perfectly happy in the cupboard for as long as two months.Canned fruits and vegetables● Shelf life：1 to 2 years past "sell - by” dateCanningis an extremely efficient means of preserving food. Generally speaking, if canned foods aren't subjected to extreme heat, their contents should stay good for two years or more. Be aware, however, of dented cans or those with swollen tops, which may indicate the presence of bacteria inside.1. Which can go bad faster if stored with onions?A. Potatoes.B. Tea.C. Peanuts.D. Canned fruits and vegetables.2. What is special about tea?A. The flavor of tea can always remain the same.B. Tea leaves are better to be preserved in an open jar.C. Tea leaves should be kept away from the state of being wet.D. The maximum length of time that tea can be stored is 6 months.3. What may shorten the "sell - by” date of canned foods ?A. Shapes of cans.B. Categories of foods.C. Decline of the temperature.D. Exposure to high temperature.BWe all use different ways to remember ideas, facts and things we need to store. Remembering is an extremely important part of our learning experience. Information process, storage and recall encourage purposeful learning.But the brain doesn’t store everything we want or need for future use. It makes choices and tends to remember information that forms a memorable pattern. Things you learned recently can be particularly difficult to remember because they haven’t taken root in your mind.“Forgetting allows us to remember what is really important to our survival. We forget much of what we read, watch, and think directly every day.” writes John Medina in his book, Brain Rules.How do you avoid losing 90%of what you’ve learned? An inspiring writer and speaker Zig Ziglar once said: “Repetition is the mother of learning, the father of action, which makes it the architect of accomplishment.”Repetition has been a remembering skill for ages. When you hear or read something once，you don’t really learn it-at least not well enough to store the new information for long. The right kind of repetition can do wonders for your memory. People learn or remember better by repeating things or getting exposed to information many times. Othersrepeat particular steps or processes deliberately a number of times or even years to become better at certain skills.Daniel Coyle explains in his book, The Little Book of Talent:“...closing the book and writing a summary, even short ones, forces you to figure out the key points, process and organize those ideas so they make sense, and write them on the page. When you pick it back up weeks later, reread all of your notes or highlights to strengthen the ideas even further.”People learn by repeating things. Better learning is a repetition process. Every time we repetitively access something we already know, we increase the memory’s stored value.4. Which of the following can be inferred from the passage?A. The brain tends to store 90% of the things we learn.B. The fresher the information isthe easier to remember.C. Thinking is more important than remembering in study.D. The brain tends to choose and keep what it thinks important.5. How does the writer prove his opinion?A.By giving examples.B. By listing numbers.C. By borrowing words of experts.D. By providing scientific finding.6. What does Daniel Coyle want to say in his book?A. You can’t pay too much attention to repetition.B. Summarizing is a very effective learning tool.C. Forgetting forces human brain to make choices.D. Regular repetition helps to form good habits.7. Which do you think is the best title of the passage?A. How the Brain WorksB. Reading for MoreC. Fighting Against ForgettingD. Repeat to RememberCHave you ever noticed that some people can eat what they want and stay in shape, while others carefully watch what they eat and still put on weight? How annoying! However, scientists are beginning to believe that some people get the ability to stay thin from their parents.Scientists say that when some people eat, their bodies will naturally store the excess energy from food as fat. These people gain weight if they eat more than they need each day. Meanwhile, other people eat more than they need but their bodies are able to “burn off” the extra food without making fat, so they rarely have weight problems.To show that this is true, scientists have experimented on laboratory mice. They gave the mice a special diet with a lot of fat. Some mice gained weight while the other mice stayed thin, even though both groups of mice ate the same amount of food and got the same amount of exercise. Scientists concluded that weight gain seemed to be influenced by genetic (基因的) factors. They also believe they have now identified the genes that may cause this tendency. These genes, according to the scientists, get passed down the generations. Armed with this knowledge, they believe it may be possible to develop medicines thatcan target the genes and stop people from gaining weight.The study of weight gain is becoming more important as the numbers of people who are overweight continues to grow. In theUnited States, over seventy percent of the population have weight problems. This means they are at risk of illness such as high blood pressure and heart disease.Current medicines for weight control do not work very well because they can have serious side effects, such as heart problems. However, it takes a long time to develop and thoroughly test new drugs. Therefore, despite this breakthrough in the study of weight-loss drugs, scientists and health professionals all agree that currently the best way to control weight gain is to have a healthy, balanced diet and an active lifestyle with daily exercise. This will not only help people avoid becoming overweight, but also help them stay healthy and energetic.8. According to the scientists, some people ________.A. are able to stay thin because of genetic factorsB. can eat what they want and stay healthy foreverC. usually keep doing exercise to lose their weightD. don’t eat anything every day but still put on weight9. Some people don’t need to worry about weight problems because ________.A. they eat many vegetablesB. they eat less than othersC. they don’t store any energy from food as fatD. they can burn off the extra food without making fat10. What can we learn from the passage?A. Fewer people will have weight problems in the future.B. People with weight problems may suffer from heart trouble.C. We now have good medicine for people with weight problems.D. The result of the experiments on mice and humans are different.11. What does the last paragraph imply?A. Current medicine solve weight problems well.B. We should exercise regularly and eat properly.C. Taking exercise every day may cause heart problems.D. Testing new drugs is hard because of the side effects.DOne day when I was 5, my mother criticized me for not finishing my rice and I got angry. I wanted to playoutside and not to be made to finish eating my old rice. In my angry motion to open the screen door (纱门) with my foot, I kicked back about a 12-inch part of the lower left hand corner of the new screen door. But I had no regret, for I was happy to be playing in the backyard with my toys.Today, I know if my child had done what I did, I would have criticized my child, and told him about how expensive this new screen door was, and I would have delivered a spanking (打屁股) for it. But my parents never said a word. They left the corner of the screen door pushed out, creating an opening, a crack in the defense against unwanted insects.For years, every time I saw that corner of the screen, it would remind me of my mistake from time to time. For years, I knew that everyone in my family would see that hole and remember who did it. For years, every time I saw a fly buzzing in the kitchen, I would wonder if it came in through the hole that I had created with my angry foot. I would wonder if my family members were thinking the same thing, silently blaming me every time a flying insectentered our home, making life more terrible for us all. My parents taught me a valuable lesson, one that a spanking or stern (严厉的) words perhaps could not deliver. Their silent punishment for what I had done delivered a hundred stern messages to me. Aboveall, it has helped me become a more patient person and not burst out so easily.12. When the author damaged the door, his parents _______.A. scolded him for what he had doneB. left the door unrepairedC. told him how expensive it wasD. gave him a spanking13. How did the author feel every time he saw the damaged door?A. He felt ashamed of his uncontrolled anger at that time.B. He found that his family members no longer liked him.C. He found it destroyed the happy atmosphere at his home.D. He felt he had to work hard to make up for (弥补) the damage.14. The experience may cause the author _______.A. to hide his anger away from othersB. not to go against his parents’ willC. to have a better control of himselfD. not to make mistakes in the future15. What of the following is the main idea of this passage?A. Adults should ignore their children’s bad behavior.B. Parents shouldn’t educate their children.C. What is the best way to become a more patient person?D. Silent punishment may have a better effect on educating people.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
绍兴市柯桥区2019学年第一学期高三数学期末试题参考答案
………………4 分
（2）①设点 A(x1, x12 ) ， B(x2, x22 ) ， Q(m, n) .切线 QA : y = 2x1x − x12 ， QB : y = 2x2x − x22 ，
由题设知 n = 2x1m − x12 ， n = 2x2m − x22 ，
………………5 分
即 x1 ， x2 是方程 x2 − 2mx + n = 0 的两根，于是 x1 + x2 = 2m ， x1x2 = n . ………………7 分
设 BC = 1，则 AF = 1 CD = 5 ， HF = GH = 2 ， AH = AG2 + GH 2 = 14 ，
2
2
4
4
由余弦定理可得： cos FAH = AH 2 + AF 2 − HF 2 = 4
70
.
2AH AF
35
………………14 分
所以 AF 与平面 ACF 所成角的余弦值为 4 70 ． 35
ABD ⊥ 平面 BCD ，且 AG ⊥ BD ，所以 AG ⊥ 平面 BCD ，
所以 AG ⊥ CE ，又 GF ⊥ CE ，所以 CE ⊥ 平面 AFG ，所以平面 ACE ⊥ 平面 AFG ，所以 AF 在平面 ACE 上的射影在直线 AH 上，则 FAH 即为 AF 与平面 ACE 所成角.………10 分
= −n ，即Tn
=−1 n
，
−1, n = 1
所以 bn
=
Tn
− Tn−1
=
1 n(n −1)
(n
2)
，故 bn
=
1
n(n −1)
,n
2,
浙江省绍兴市柯桥区2018-2019学年第一学期期末高中教学质量监测高三数学试题
2018学年第一学期期末高中教学质量检测高三数学试题注意事项:1.本科考试分考试卷和答题卷，考生须在答题卷上答题;2.本试卷分为第I卷(选择题部分)和第I卷(非选择题部分),共4页。
全卷满分150分，考试时间120分钟。
第I卷(选择题部分)一、选择题（本大题共10小题，每小题分，共40分．在每小题给出的四个选项中，只有一项是符合题目要求的）1．已知集合A＝{1，2，3，4，5}，B＝{2，4，6}，则A∩B＝（）A．∅B．{2，4} C．{2，4} D．{2，4，6}2．双曲线的渐近线方程是（）A．2x±y＝0 B．x±2y＝0 C．4x±y＝0 D．x±4y＝03．某几何体的三视图如图所示（单位：cm），则该几何体的体积（单位：cm2）是（）A．3 B．6 C．9 D．184．复数（i为虚数单位）在复平面内对应的点在（）A．第一象限B．第二象限C．第三象限D．第四象限5．函数y＝ln（x2+1）•sin2x的图象可能是（）6．已知平面α，β，直线l满足l⊂α，则“l⊥β”是“α⊥β”的（）A．充分不必要条件B．必要不充分条件C．充要条件D．既不充分也不必要条件7．设0＜p＜1，随机变量ξ的分布列是则当p在（0，1）内增大时（）A．E（ξ）减小，D（ξ）减小B．E（ξ）减小，D（ξ）增大C．E（ξ）增大，D（ξ）减小D．E（ξ）增大，D（ξ）增大8．已知△ABC中，AC≥BC，D、E分别是AC、BC的中点，沿直线DE将△CDE反折成△C′DE，设∠C′DA＝θ1，∠C′EB＝θ2，二面角C′﹣DE﹣A的平面角为θ3，则（）A．θ1≥θ2≥θ3B．θ1≥θ3≥θ2C．θ2≥θ1≥θ3D．θ3≥θ1≥θ29．已知向量，满足||＝1，||＝2，若对于长度为2的任意向量都有|•|+|•|，则||的最小值为（）A．1 B．C．D．310．已知不等式xe x﹣a（x+1）≥lnx对任意正数x恒成立，则实数a的最大值是（）A．B．1 C．D．第I卷(非选择题部分)二、填空题（本大题共7小题，多空题每题6分，单空题每题4分，共36分）11．我国古代数学名著《九章算术》中有如下问题：“今有女善织，日自倍，五日织五尺，问日织几何？”意思是：一名纺织女工，在五天时间内共织了五尺布，后一天的织布量是前一天的2倍，问每天的织布量分别是多少？若设第一天的织布量为a1，第五天的织布量为a5，则a1＝，a5＝．12．若x，y满足约束条件，则z＝2x+y的最小值为，最大值为13．在△ABC中，角A，B，C所对的边分别为a，b，c，若a＝4，c＝2，B＝60°，则b＝，C＝．14．二项式（）9展开式中x3项的系数是15．已知函数f（x），，＞，则不等式f（x）≤1的解集为，若实数a，b，c满足f（a）＝f（b）＝f（c），且a＜b＜c，则a+2b+c的取值范围是．16．有2个不同的红球和3个不同的黄球，将这5个球放入4个不同的盒子中，要求每个盒子至少放一个球，且同色球不能放在同一个盒子中，则不同的放置方法有种．（用数字作答）17．已知椭圆1（a＞b＞0）的左、右焦点分别为F1，F2，P是椭圆上一点，直线F2M垂直于OP 且交线段F1P于点M，若|F1M|＝2|MP|，则该椭圆的离心率的取值范围是．三、解答题（本大题共5小题，共74分，解答应写出文字说明、证明过程或演算过程）18．（本小题满分14分）已知sin cos（0＜α＜）．（Ⅰ）求tanα的值；（Ⅱ）若角β满足sin（2α+β），求cos（α+β）的值．19．（本小题满分15分）已知四面体ABCD中，AB＝BC＝AC＝CD＝2，AD，∠BCD＝120°，E为BC中点．（Ⅰ）求证：AE⊥平面BCD；（Ⅱ）求AD与平面ABC所成的角的正切值．20．（本小题满分15分）已知等差数列{a n}的公差d为整数，且a2+a3+a4＝18，a3是a2和a5﹣1的等比中项．（Ⅰ）求a1和d的值；（Ⅱ）若数列{b n}满足b1＝1，b n+1求证：21．21．（本小题满分15分）已知抛物线C：x2＝2py（p＞0），F是其焦点，A是C上异于原点的点，过A作C 的切线与C的准线l相交于点P，点B满足BP⊥l，AB∥l．（Ⅰ）求证：FB∥AP；（Ⅱ）设直线FB与抛物线C相交于M，N两点，求△AMN面积的取值范围．22．（本小题满分15分）已知函数f（x）＝ln（x+1）在（﹣1，）内有极值（e为自然对数的底数）．（Ⅰ）求a的取值范围；（Ⅱ）若x1∈（﹣1，0），x2∈（0，+∞），求证：f（x2）﹣f（x1）＞2（ln）．。
2019-2020学年绍兴市柯桥中学高三英语期末考试试题及答案
2019-2020学年绍兴市柯桥中学高三英语期末考试试题及答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AGet up to 19% off the cover pricePlus, get digital access with your paid print subscription●Up-to-date news that touches your lifeFrom money-saving tips and quick reports on the latest healthcare, to inspiring articles on world events, you'll discover hundreds of ideas for living a richer, more satisfying life.●Read it anytime, anywhereGet a l-year-print subscription ofReader's Digestmagazine today and you'll also get free digital instantly. With digital access, you can read the latest issue ofReader's Digestanytime, anywhere! Plus, you can quickly access your past issues online, too.●Continuous renewal serviceYour subscription will automatically renew at the end of each term until you cancel. You authorize us to charge you credit/debit cardat the discounted rate on the renewal service unless you cancel. You may cancel at anytime by visiting Customer Care and receive a refund on all unmailed issues.●Other informationThe cover price ofReader's Digestis $3.99 per issue and it is currently published 10 times annually. Please check the confirmation page and your mailbox to download detailed instructions.1. What is the annual fee for subscription?A. $32. 3.B. $39. 9.C. $40.D. $47. 9.2. Which of the following words best describes the content inReader's Digest?A. Touching and amusing.B. Inspiring and practical.C. Amazing and entertaining.D. Educational and theoretical.3. If you subscribe toReader’s Digest, you can ________.A. have as many issues as possible every yearB. renew your subscription at the original rateC. get back your money for the issues not mailedD. obtain all the past issues online anytime, anywhereBTwenty years ago, I became involved in pet therapy(疗法) work with our Angel. As she matured and went through professional training, we realized that she would be good at this new job.Angel is ten now and works every week. She visits two hospitals providing day care for the elderly, and our library’s PAWS forReadingprogram. At the library, six to ten dogs lie on the floor, and the kids pick a book to read to a dog. After they finish, they get a card with the dog’s picture and history. Angel also helps out at a special-needs camp. She is so popular that everywhere we go people recognize her, especially the kids she has worked with.We have seen some very special things through our pet therapy work. I brought Angel to our local hospital to visit a woman who was completely unable to move the right side of her body from a stroke(中风). One day, my husband, Jack, got Angel up into a chair next to the woman’s bed, asking her if she wanted to give Angel a treat. She nodded. Angel gently took the treat. Then the woman raised her right hand and started petting Angel. Her friend couldn’t believe her eyes.After that, every time we saw the woman, she lifted her left hand. We’d tell her she had to use her right hand, and she would. Next, you’ll fall in love with this woman’s story of rearing her own Angel later in her family and why she calls it the best decision she ever made.4. Who is Angel?A. A pet trainer.B. A hospitalC. A therapy dog.D. The author’s kid.5. What does Angel usually do?A. Save seriously ill people.B. Pay visits to kids in hospital.C. Protect the elderly in their homes.D. Help children at a special camp.6. Why was the woman’s friend astonished?A The woman moved her right hand.B. The woman treated Angel.C. Angel helped the woman recover.D. Angel got along with the woman.7. What does the underlined word “rearing” in the last paragraph mean?A. Accompanying.B. Raising.C. Assisting.D. Training.CPaper is an important part of modern life. People use it in school, at work, to make artwork and books, to wrap presents and much more. Trees are the most common material for paper these days.So how do people make paper out of trees today? People first cut trees, load them onto trucks and bring them to a factory. Machines cut open the outer coverings of the trees, and cut the trees into pieces. Those pieces are boiled into a soup. After that, it is hit flat, dried and cut up into sheets of paper.The entire process, from planting a small tree to buying your school notebook, takes a very long time. Just growing the trees takes 10 to 20 years.Making tons of paper from trees can harm the planet. Humans cut down 80, 000 to 160,000 trees around the world every day, and use many of them to make paper. Some of those trees come from tree farms. But people also cut down forests for paper, which means that animals and birds lose their homes.Cutting forests down also contributes to climate change, and paper factories pollute the air. After you throw paper, it often takes the paper six to nine years to break down. That's why recycling is important. It saves a lot of trees, slows climate change and helps protect endangered animals, birds and all creatures that rely on forests for their homes and food.So if paper isn't good for the environment, why don't people write on something else?The answer: They do. With computers, tablets and cellphones, people use much less paper than in the past. Maybe a day will come when we won't use paper at all — or will save it for very special books and artworks.8. What can we know about making paper out of trees?A. It costs much money.B. It takes a lot of time.C. It is very easy and fast.D. It is dangerous and difficult.9. What is the impact of paper production?A. It promotes the recycling.B. It does harm to the environment.C. It slows down the climate change.D. It protects the animals from losing homes.10. How will we use paper someday in the future according to the text?A. Use it for books only.B. Use the recycled paper.C. Treasure it occasionally.D. Use it for artworks.11. What idea does the author want to express from the text?A. The influence of making paper on environment.B. The wonderful experience of making paper.C. The necessary process of making paper.D. The good reasons for making paper.DLast year, 138,000San Franciscoresidents used Airbnb, a popular app designed to connect home renters and travelers. It’s a striking number for a city with a population of about 850,000, and it was enough for Airbnb to win a major victory in local elections, asSan Franciscovoters struck down a debatable rule that would have placed time restrictions and other regulations on short-term rental services.The company fiercely opposed the measure, Proposition F, with a nearly $10 million advertising campaign. It also contacted its San Franciscan users with messages urging them to vote against Proposition F.Most people think of Airbnb as a kind of couch-surfing app. The service works for one-night stays on road trips and longer stays in cities, and it often has more competitive pricing than hotels. It’s a textbook example of the “sharing economy”, but not everyone is a fan.The app has had unintended consequences inSan Francisco. As the San Francisco Chronicle reported last year, a significant amount of renting on Airbnb is not in line with the company’s image: middle-class families putting up a spare room to help make ends meet. Some users have taken advantage of the service, using it to turn their multiple properties into vacation rentals or even full-time rentals. Backers of Proposition F argued that this trend takes spaces off the conventional, better-regulated housing market and contributes to rising costs.“The fact is, widespread abuse of short-term rentals is taking much needed housing off the market and harming our neighborhoods,” said ShareBetter SF, a group that supported Proposition F. Hotel unions have protested the company’s practices inSan Franciscoand other cities, saying that it creates an illegal hotel system.San Franciscois in the middle of a long-term, deeply rooted housing crisis that has seen the cost of living explode. Actually, explode is a generous term. The average monthly rent for an apartment is around $4, 000. Located on a narrow outcropping of land overlooking the bay,San Franciscosimply doesn’t have enough space to accommodate the massive inflow of young, high-salaried tech employees flocking toSilicon Valley.As the Los Angeles Times reported, someSan Franciscoresidents supported the measure simply because itseemed like a way to check a big corporation. Opponents of Proposition F countered that the housing crisis runs much deeper, and that passing the rule would have discouraged a popular service while doing little to solve the city’s existing problems.12. The intention of Proposition F is to ________.A. place time limits in local election.B. set limits on short-term rental.C. strike down a controversial rule.D. urge users to vote against Airbnb.13. What is the negative consequence of Airbnb onSan Francisco?A. It shrinks the living space of middle-class families.B. Users are taken advantage of by the service financially.C. It makes the house market more competitive.D. It indirectly leads to high house rental price.14. The housing crisis inSan Franciscoresults from ________.A. explosion of the living costB. its geographic characteristicsC. generosity of local enterprisesD. inflow of migrant population15. Theauthor’s attitude toward Proposition F is ________.A. objectiveB. supportiveC. negativeD. indifferent第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
浙江省绍兴市柯桥区2020届高三上学期期末考试语文试题及参考答案
柯桥区2019学年第一学期高三期末测试注意事项1.本试题卷分四部分，全卷共 8 页。
满分 150 分，考试时间 150 分钟。
2.请考生按规定用笔将所有试题的答案填写在答题纸上。
一、语言文字运用（共20分）1.下列各句中，没有错别字且加点字的注音全都正确的一项是（）（3分）A. 大自然崇高而又优雅，雄浑而又柔和，人们感怀并摹写它亘（gèng）古如斯的美丽，将身心沉浸其中，在聆听万籁的时候体味人世的纷烦复杂，感慨历史的沧桑变化。
B. 如果确认战争乃是流血的政治，那么，“三国”的智慧就是政治智慧。
政治智慧之外的哲学智慧等则几乎阙．（què）如，至少可说是相当薄．（bó）弱，远逊于《红楼梦》。
C. 持反讽叙写姿态的作家们间或从自然景物中汲取抨击丑恶的力量，使戏谑．(xuè)场景富有深意；部分晚生代作家则戏拟景物以消解美丑界限，显露出稀薄的自然美意识。
D.首长这番话使他幡．（fān）然醒悟:我之所以要对着虚无的话筒谍谍不休，正是在荆棘载（zài）途中拼命撑着延缓虚无的到来。
阅读下面的文字，完成下面小题。
当我们撇开有关“语言”“言语”的种种迷魂阵，用看待普遍．．小说的眼光来看《马桥词典》，我们应当承认，作者有很多写得精彩的地方。
在这里，我主要关注的是作者在小说中所表现的某种“世纪末”情绪。
这种情绪特别体现在作者对马桥人内心世界中根深蒂固．．．．的道家精神的不由自主的欣赏、赞叹之上。
这一方面是因为，中国文化的根底在道家，一个对中国文化寻根的作者必然会达到道家情怀和道家境界；【甲】另一方面是因为，道家本身就是一种最典型．．的“世纪末”情绪，因为道家在人类文明的起点上就已经把这个文明的归宿和终点都看透了，想透了。
【乙】两千多年来他们一直在向人类一切文明的标志：仁义道德、礼法规范、国家体制、科学艺术等一一发出警告，在抵制一切由名言规范形成的任何形式的“本文”。
【丙】老子、庄子及其追随者们以猫头鹰的智慧所体悟到的、以身体力行的固执所昭示出来的生命真理，在20世纪下半叶已由西方的哲人们重新发现了。
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2019学年绍兴柯桥区高三上期末
一、选择题：每小题4分，共40分
1. 已知全集{}1U x x =≥-，集合{}0A x x =>，{}11B x x =-≤≤，则()U A B =I ð（ ） A ．{}10x x -≤≤
B ．{}01x x ≤≤
C ．{}01x x <≤
D ．{}10x x -≤< 2. 若实数x ，y 满足约束条件0230y y x x y ≥⎧⎪
≤⎨⎪+-≤⎩，则2z x y =-的最大值是（ ）
A ．1-
B ．0
C ．2
D ．3
3. 双曲线22
124x y -=的焦点到其渐近线的距离是（ ）
A ．1
B
C ．2
D
4. 某几何体的三视图如图所示（单位：cm ），则该几何体的体积是（单位：3cm ）（ ）
A ．2
B ．6
C ．10
D ．12
5. 设a ，b 是实数，则“221a b +≤”是“1a b +≤”的（ ） A ．充分不必要条件 B ．必要不充分条件
C ．充要条件
D ．既不充分也不必要条件
6. 在同一坐标系中，函数()()0a f x x x =>与()1x g x a +=的图象可能是（ ）
7. 已知多项式()()()2
6
60126111x a a x a x a x =+-+-++-L ，则4a =（ ） A ．15-
B ．20-
C ．15
D ．20
俯视图
正视图
D.
C.
B.
A.
1
8. 斜三棱柱111ABC A B C -中，底面ABC 是正三角形，侧面11ABB A
是矩形，且12AA =，M 是AB 的
中点，记直线1A M 与直线BC 所成的角为α，直线1A M 与平面ABC 所成的角为β，二面角1A AC B --的平面角为γ，则（ ）
A ．βγ<，αγ<
B ．βα<，βγ<
C ．βα<，γα<
D ．αβ<，γβ<
9. 已知函数()()()322
22121,1
31,1x t t x tx x f x t x t x x ⎧--+++<⎪=⎨⎪++≥⎩，则满足“对于任意给定的不等于1的实数1x ，都有
唯一的实数()221x x x ≠，使得()()12f x f x ''=”的实数t 的值（ ）
A ．不存在
B ．有且只有一个
C ．有且只有两个
D ．无数个
10. 已知数列{}n a 满足101a <<，()142
R n n n a t
a t a ++=∈+，若对于任意*N n ∈，都有103n n a a +<<<，则t 的
取值范围是（ ）
A ．(]1,3-
B ．[]0,3
C ．()3,8
D ．()8,+∞
二、填空题：单空题每题4分，多空题每题6分
11. 已知复数11i z =-，122i z z ⋅=-，则复数2z = ．
12. 设直线y kx =与圆C ：()2
221x y -+=相交于A ，B
两点，若AB =k = ，当k 变
化时，弦AB 中点轨迹的长度是 ． 13. 设随机变量ξ
若1
3
E ξ=
，则b = ，D ξ= ． 14. 在ABC △中，4BC =，135B ∠=︒，
点D 在线段AC 上，满足BD BC ⊥，且2BD =，则cos A = ，AD = ．
15. 已知双曲线()2222:1,0x y C a b a b -=>的右焦点(),0F c 关于直线b
y x a
=的对称点在直线2a x c =-上，则该
双曲线的离心率为
．
16. 已知正三角形ABC 的边长为4，P 是平面ABC 内一点，且满足3
APB π
=∠，则PB AC ⋅u u u r u u u r 的最大值
是 ，最小值是 ．
17. 设实数a ，b 满足1b a ≤≤，则221
a b ab
+-的最大值为 ．
三、解答题：5小题，共74分
18. 已知函数()2sin 23f x x x π⎛
⎫=-- ⎪⎝
⎭．
（1）求34f π⎛⎫
⎪⎝⎭
的值；
（2）求()f x 的最小正周期和单调递增区间．
19. 如图，三棱锥A BCD -中，平面ABD ⊥平面BCD ，90CBD =︒∠，E ，F 分别是BD ，CD 的中点，且
AB BE AE BC ===．
（1）证明：AC AD ⊥；
（2）求AF 与平面ACE 所成角的余弦值．
20. 设等差数列{}n a 的前n 项和为n S ，23a =-，()4521S a =+，数列{}n b 的前n 项和为n T ，满足11b =-，
()11n n n b T T n *++=∈Ν．
（1）求数列{}n a 、{}n b 的通项公式； （2
）记n c =n *∈Ν
，证明：()1221n c c c n +++<+L ；
F
E
D
C
B
A
21. 已知抛物线()2:20C x py p =>，直线y x =截抛物线C
（1）求p 的值；
（2）若直角三角形APB 的三个顶点在抛物线C 上，且直角顶点P 的横坐标为1，过点A 、B 分别作抛物线C 的切线，两切线相交于点Q ． ①若直线AB 经过点()0,3，求点Q 的纵坐标；
②求PAB QAB
S
S △△的最大值及此时点Q 的坐标．
22. 设函数()()e 20ax f x x a -=+≠．
（1）当2a =，求函数()f x 的单调区间； （2
）当a >(],0x ∈-∞，均有()()212
a
f x x >+，求a 的取值范围．。