radar_1

Sheet 1 of 11RADAR IntroductionRAdio Detection And Ranging Part 1 of 2Applications: Detection and Ranging of ground, sea and air targets Air Traffic Control (ATC) Guidance Tracking Meteorological applications Collision avoidance Speed measurement Remote sensing Why use microwave frequencies? 1. Low absorption by the atmosphere • • • • see Figure 1low attenuation below about 20 GHz, particularly below 10GHz resonant peaks due to oxygen and water molecular absorption at higher frequencies operate in 'windows' at about 35GHz, 94GHz etc much lower absorption by fog, rain, snow at microwave frequencies than at optical frequenciesFigure 1 Graph showing attemuation of a microwave signal through the atmosphere with varying conditions and frequencies 2. Antenna sizes • • • • angular resolution limited by beamwidth beamwidth determined by λ/D - D is antenna diameter - θ(radians) ≈ λ require D = 10λ for 6° beamwidth suggests using high microwave frequencies to reduce antenna size, but a balance must be struck with the atmospheric attenuationDSheet 2 of 11Types of radar 1. Bistatic Monostatic separate transmit and receive antennas same antenna for transmit and receiveTXRXTX RXBistatic (i)Bistatic (ii)MonostaticFigure 2 2. • 3. • 4. • CW radar • CW radarMonostatic and bistatic radar transmits continuous wave (CW)can detect objects, measures velocity from Doppler shift, but cannot measure range FM-CW radar frequency-modulated CW transmitted signaldetects, measures range and radial velocity Pulsed radar includes MTI (moving target indicator) and Pulsed Dopplerdetects, measures range and velocity, but has blind speeds and rangescan be bistatic or monostaticTXRXTX RXBistatic (i)Bistatic (ii)MonostaticFigure 3Monostatic and bistatic CW radarSheet 3 of 11•transmitter and receiver both operate continuously - hence no range measurement. Difficult to avoid Tx to Rx feed-through, even with separate antennas measure radial velocity of target from Doppler shift•foVrTX⎛ 2.vr ⎞ fo + ⎜ ⎟ fo ⎝ c ⎠Doppler shiftFig. 4. Doppler frequency shift for reflected signal Mix Tx and Rx signals to give difference frequency - the Doppler frequency⎛ 2v ⎞ ⎛ 2v ⎞ fD = f0 + ⎜ ⎟ f0 − f0 = ⎜ ⎟ f0 ⎝ c ⎠ ⎝ c ⎠• Ships ∴ radial velocity in range 0 to 30 knots typically at an operating frequency of 2GHz, i.e. 0 to 15ms-1f D is in the range 0 to 200HzUsing homodyne detection, where the Rx and Tx signals are mixed directly to give the Doppler frequency problems arise due to flicker noise in the detectors and amplifiers because the noise power is proportional to 1/f and flicker noise is large at low frequencies such as 200Hz.1/fFlicker noise Power densityNoise power density is Area for given bandwidth and is greater at lower Frequencies.B.WfFig. 5. Flicker noise versus frequencySheet 4 of 11A solution is to use heterodyne detection in which the Rx signal is mixed with a local oscillator (LO) with a frequency which differs from the Tx frequency by, for example, 30MHz. The received signal + LO generate an IF (intermediate frequency) output at 30 MHz which contains the same information - ie Doppler frequency shift - as the Rx signal. After amplification the Doppler frequency shift can be extracted by further mixing.(fo+fD) → RX (fo+fD)- fLO ≈ 30MHzamplify without flicker noiseLO fLOVelocity ambiguity with CW radar Velocity ambiguity is the inability to distinguish between approaching and receding targets. It arises because in a mixer with an LO frequency f 0 input signals with frequencies f 0 + f D and f 0 − f D give the same IF frequency ie the same IF output is obtained for targets that are approaching or receding from the radar at the same radial speed. Velocity ambiguity can be removed by splitting the received signal into two equal components. A 90° phase change is applied to one of the components. After further mixing the relative phases of the two components gives the sign of the Doppler frequency. Thus approaching and receding targets are distinguished. A system that achieves the removal of velocity ambiguity is shown in Figure 6. The outputs are called the I (In phase) and Q (Quadrature phase) outputs. With Withf D +veQ output leads I by 90° Q output lags I by 90°approaching target receding targetf D -veFM-CW radar • • • • frequency modulate the CW signal to give range as well as velocity the frequency is swept repeatedly betweenf 1 and f 2the range is found from the frequency difference between the transmitted and the returned signal - see figure 7 for a stationary target if the target is moving there is an additional Doppler frequency shift. For an approaching target the frequency of the returned signal is increased. For m positive (m is the rate of change of frequency with time for the transmitted signal) the range frequency is decreased by the Doppler frequency, whereas for m negative the range frequency is increased by the Doppler frequency. Using both measurements both the range and radial velocity of the target can be obtained - see figure 8.Sheet 5 of 11System to remove Velocity Ambiguity with CW Radar TX fo CW TxfoLO at IFLO fIF (fd+fIF) <90 degreesfd < 90 degrees QRX fo+fdfo-fIFAmplifier90 degrees3dB (Approachin g target) (fo-fd)-(fo-fIF) = fd+fIF fd+fIF fIFfd < 0 degrees(fd+fIF) < 0 degreesIWith fd +ve (approaching target) Q output 90 degrees AHEAD of I outputWith fd -ve (receding target) Q output 90 degrees BEHIND of I outputFigure 6Sheet 6 of 11FM-CW Radar Frequency-modulate CW signal to give range information. (1) Stationary targetTxRxF2Frequency∆fm=∂f T ∂tF12R CtimetFigure 7 Tx frequency – increases with time⎛ ∂f ⎞ f T = f1 + ⎜ T ⎟t = f1 + m.t ⎝ ∂t ⎠Rx signal lags Tx signal by time to target and backTXRTR =2R CMixing Rx and Tx frequencies gives difference frequency ∆f∆f =m 2R C⎛ 2R ⎞ ∴ ∆f = f R = m⎜ ⎟ ⎝ C ⎠Range frequencySheet 7 of 11(2) Moving target with FM-CW due to Doppler - additional frequency shift due to Doppler effectTxRxF2fDFrequencyfD ∆frApproaching targetF1fr – fD = ∆frtimeFigure 8 Approaching target : Rx signal frequency increased by fdTherefore ∆f (measured) = fR-fd ( for m positive ) = f+ For m negative ∆f (measured) = fR+fd = fTherefore, fR = ½(f+ + f-) fd = ½(f- - f+) simultaneous equationsSheet 8 of 11•ambiguity can arise between very close fast moving targets and slow moving distant targets. It may not be possible to decide whether the difference frequency is f R − f D or f D − f R.Pulsed radar • short pulses (pulse length ∼ 1µs) of RF radiation are transmitted with relatively long intervals ( T(PRF)) ∼ ms) between them. PRF is the pulse repetition frequencyΤ ~ 1usEcho E1TXT R = (2R)/CT/RT (PRF) ~ 10-3sRXFigure 9 Pulsed radar and radar pulses • the time delay between the transmitted and reflected signal targetTR gives the range to theRTX RXTR =2R CR=1 CTR 2Figure 10 Transmitted and reflected signals • • each time delay of 1µs corresponds to an increase in range of 150m a T/R cell is connected between the transmitter and the receiver to protect the sensitive receiver from the high power pulses from the transmitter. This disables the receiver during pulse transmissionSheet 9 of 11•the maximum unambiguous range of the radar occurs when TR = ranges the echo returns after the transmission of the next pulse.T ( PRF ) . For longerR (unambiguou s ) = cT (PRF ) 2=c 2PRF• the blind range of the radar occurs when the echo signal arrives back when the next pulse is being transmitted and the receiver is disabled - ie TR = T ( PRF ) . This is the same as the maximum unambiguous range. to avoid the blind range and to distinguish targets that are beyond the maximum unambiguous range a variable PRF should be used. If we combine the reflections from several pulses, targets with R < R(unambiguous) will all have the same time delay with respect to the transmitted signal, but those will appear to have a variable delay, because they actually originated from an earlier transmitted pulse.T1 T2 T3 TWill move if R > R (unambiguous)•E1E2E1E2Fixed for all transmission pulses if R < R (unambiguous)combineFigure 11 Use of variable PRF to distinguish targets beyond the unambiguous range • the radar range resolution is the ability of the radar to distinguish two targets with similar ranges. The resolution is determined by the pulse duration τ . The smallest time interval that the radar can resolve is τ which gives a range resolution of cτ 2 . If τ = 1µs the range resolution is 150m.T1 T2τR = ½.CTR AR = ½.C(A.TR)τFigure 12 Radar resolutionSheet 10 of 11•the angular resolution of the radar is determined by the beamwidth of the antenna, which is in turn set by the frequency of operation and the antenna diameter θ (radians)≈ λ/D.Blind speeds with pulsed radars If the frequency of the echo signal is measured the target radial velocity can be determined as well as its range. The sketches below show the time domain and the frequency domain forms of the transmitted pulses.τ⎛ sin(x) ⎞ sin x 2 = ⎜ ⎟ ⎝ x ⎠2Time DomainP(f)Line spectrum∆f1 =1 = PRF T(PRF )PRF fofTransmitted Waveformsfo −1 τfofo +1 τFrequency domainFigure 13 Time and frequency domain forms of a radar pulse train In the frequency domain the pulse contains frequency components with spacing ∆f 1 = ( PRF ) from the transmitted frequency f 0 . If the Doppler-shifted echo signal falls on one of these frequency components it cannot be distinguished, and so the radar is 'blind' to the corresponding radial velocities - ie to velocities that give f D = n∆f1 =n( PRF ) where n = 1, 2, 3, etc.Blind speeds c.n(PRF) ⎛ 2.v r ⎞ f D = n(PRF) = ⎜ ⎟ fo ; v r (blind) = c ⎠ 2 fo ⎝ eg fo = 10GHz; PRF= 1KHz vr = 3x108 x n x 103 = 15n....15ms −1 ; 30ms −1 ; 45ms −1 10 2x10Sheet11 of 11 For a pulsed radar with a frequency of 10GHz which transmits pulses at millisecond intervals-1-1-1-1(PRF = 1kHz) the blind speeds are 15ms, 30ms, 45ms etc. 15ms is about 30mph, so in some applications there would be many blind speeds within the speed range of interest eg aircraft.To avoid problems due to blind speeds the radar must be operated so that they do not fall into the range of interest. This can be achieved by increasing the PRF. However, this reduces the unambiguous range and so a compromise must be reached.ms-1Example: Blind speeds less than 1500mph (670) are to be avoided. For a radar operating at 10GHz this corresponds to a Doppler shift, and hencea PRF of 45kHz. This PRF gives an unambiguous range of only 3.3km.The value of the Doppler frequency, and hence the PRF, could be reduced by operating the radar at a lower frequency -eg 2GHz -but this might mean using a larger antenna to give the same angular resolution.Two broad categories of pulsed radar are1. MTI (Moving Target Indicator) radar•distinguishes moving targets from the stationary background by Doppler shift. Only those echoes with a frequency shift are displayed. The reflections from thebackground are known as clutter.•MTI uses a low PRF to avoid range ambiguity, and gives a large range•the blind range is small because the receiver is only disabled for a small % of the time•'blind' to many speeds, starting from quite low speeds•the low PRF reduces the number of hits per target as the radar beam is scanned.This reduces the radar sensitivity.2. Pulse Doppler radar• uses high PRF to avoid blind speeds•short unambiguous range, more extended blind range•more hits per target increases sensitivityNote: Hits per target gives the number of pulses that hit the target as the radar beam is scanned. The signal at the receiver is averaged over several pulses to average out the effects of noise. The radar sensitivity increases with the number of hits per target. If a beam with width 2° is scanned at 36° per second a target will be in the beam for 1/18 seconds. With a PRF of 300Hz the number of hits per target will be 300/18 = 15.。