Pathways to double ionization of atoms in strong fields
高级英语下翻译英汉对照
Isotopes with long half-lives have many uses in medicine and industry, but they must be handled and disposed of with great care, in case they cause radiation damage.
中子被放射出时以高速运动。正如所知,这种高速运动的中子几乎不可能被可裂变铀俘获。
However, if slowed down to thermal speeds, their probability of capture is greatly increased.
然而,如能使中子减速到热运动速度,热中子被俘获的可能性就会大大增加。
有一些裂变产物,例如铯-137,就是一种很有用的辐射源;目前已经能够从废弃的燃料中分离出我们所期望的同位素。
14.Chain Reaction连锁反应
Chain Reaction
连锁反应
When fission occurs, an average of 2-5 neutrons are emitted from the nucleus.
在使用石墨缓和剂的情况下,铀通常以铀棒形式插进石墨切槽内。
These channels areso arranged as toform a lattice structure, the object of which is to reduce neutron escape to a minimum.
如果原子核是重核,也就是说原子核如含有大量质子和中子,就可能更加趋于不稳定。
国际化学奥林匹克竞赛-国际化学奥林匹克竞赛-第38届ICHO理论试题(中文版)答案
1-1.The mass of a water droplet:m = V ρ = [(4/3) π r3] ρ = (4/3) π (0.5x10-6 m)3 (1.0 g/cm3)= 5.2x10-16 kg⇒10 marksAverage kinetic energy at 27o C:KE = mv2/2 = (5.2x10-16 kg) (0.51x10-2 m/s)2/2= 6.9x10-21 kg m2/s2= 6.9 x10-21 J ⇒15 marks*.The average kinetic energy of an argon atom is the same as that of a water droplet.KE becomes zero at –273 o C.From the linear relationship in the figure, KE = aT (absolute temperature)where a is the increase in kinetic energy of an argon atom per degree.a = KE/T = 6.9x10-21 J/(27+273K) = 2.3x10-23 J/K⇒25 marksS: specific heat of argon N: number of atoms in 1g of argonS = 0.31 J/g K = a x NN = S/a = (0.31 J/g K) / (2.3x10-23 J/K)= 1.4x1022 ⇒30 marksAvogadro’s number (N A) : Number of argon atoms in 40 g of argonN A = (40)(1.4x1022)= 5.6 x1023⇒20 marks2-1. ⇒ 30 marksmass of a typical star = (4/3)(3.1)(7x108 m)3(1.4 g/10-6 m 3) = 2×1033 g mass of protons of a typical star = (2×1033 g)(3/4 + 1/8) = 1.8×1033 g number of protons of a typical star = (1.8×1033 g)(6×1023/g) = 1×1057number of stellar protons in the universe = (1×1057)(1023) = 1×1080Partial credits on principles:Volume = (4/3)(3.14)radius 3×density; 4 marks 1 mole = 6×1023; 4 marksTotal number of protons in the universe = number of protons in a star ×1023; 2 marks Mass fraction of protons from hydrogen = (3/4)(1/1); 5 marks Mass fraction of protons from helium = (1/4)(2/4); 10 marks2-2. ⇒ 30 marks∆E(2→3) = C(1/4 - 1/9) = 0.1389 C λ(2→3) = 656.3 nm ∆E(1→2) = C(1/1 - 1/4) = 0.75 Cλ(1→2) = (656.3)(0.1389/0.75) = 121.5 nmNo penalty for using Rydberg constant from memory. 15 marks penalty if answered in a different unit (Hz, etc.)2-3.T = (2.9×10-3 m K)/1.215×10-7 m = 2.4×104 K ⇒ 10 marks2-4..⇒ 20 marksλ = 3 × 108 m/1.42 × 109 = 0.21 mT = (2.9 × 10-3 m K)/0.21 m = 0.014 K2-5. ⇒ 10 marks14N + 4He → (17O ) + 1HO-17, O acceptable1783-1.k des = A exp(-E des/R T)= (1x1012 s-1)(5x10-32) = 5x10-20 s-1 at T = 20 K ⇒10 markssurface residence time, τresidence = 1 / k des = 2x1019 s = 6x1011 yr ⇒20 marks(full credit for τhalf-life = ln2 / k des = 1x1019 s = 4x1011 yr)residence time = 2x1019s3-2.The distance to be traveled by a molecule: x = πr = 300 nm.k mig = A exp(-E mig/R T)= (1x1012 s-1)(2x10-16 ) = 2x10-4 s-1 at T = 20 K ⇒ 5 marksaverage time between migratory jumps,τ = 1 / k mig = 5x103 sthe time needed to move 300 nm= (300 nm/0.3 nm) jumps x (5x103 s/jump) = 5x106 s = 50 days ⇒15 marks(Full credit for the calculation using a random-walk model. In this case:t = τ (x/d) 2 = 5 x 109 s = 160 yr. The answer is still (b).)(a) (b)(c) (d) (e)10 marks3-3.k(20 K) / k(300 K) = exp[(E/R) (1/T1 - 1/T2)]= e-112 = ~ 10-49 for the given reaction ).) ⇒15 marks The rate of formaldehyde production at 20 K= ~ 10-49 molecule/site/s = ~ 10-42 molecule/site/ yr⇒10 marks(The reaction will not occur at all during the age of the universe (1x1010 yr).)rate = 10-42molecules/site/yr3-4. circle one(a) (b) (c) (a, b) (a, c) (b,c)(a, b, c)(15 marks, all or nothing)4-1.H PNumber of atoms ( 11.3 ) 1⇒ 10 marksTheoretical wt % ( 3.43 )⇒ 10 marks4-2.adenineN NN NN H H guanineNN N NO N HH HNN O N H H cytosineNN H O O thymine(10 marks on each)4-3. 7 marks each, 20 marks for threeadenineNNNNNHHguanine NN NNON HHH NNH OOthymineNNONHH cytosine NNH OOthymineguanine NN NNON HHHcytosineNNONHHcytosineNNON HHNNHOO thyminethymineNNHOONNH OOthyminethymine NNHOONNONHH cytosineadenineNNNNNHH adenineNNNNNHHadenine NNNNNHHguanineguanine NNNNON HHHNNNNONHHH4-4. 2.5 marks for each bracketadenineN NN N HNH 2guanine N NH N N HO NH 2Uracil N H NH O cytosineN H N NH 2OOHCN ( 5 ) ( 5 ) ( 4 )( 4 )H 2O ( 0 ) ( 1 ) ( 2 ) ( 1 )5-1.(20 marks)1st ionization is complete: H2SO4→ H+ + HSO4-[H2SO4] = 02nd ionization: [H+][SO42-]/[HSO4-] = K2 = 1.2 x 10-2 (1)Mass balance: [H2SO4] + [HSO4-] + [SO42-] = 1.0 x 10-7 (2)Charge balance: [H+] = [HSO4-] + 2[SO42-] + [OH-] (3)Degree of ionization is increased upon dilution.[H2SO4] = 0Assume [H+]H2SO4 = 2 x 10-7From (1), [SO42-]/[HSO4-] = 6 x 104 (2nd ionization is **plete)[HSO4-] = 0From (2), [SO42-] = 1.0 x 10-7 [5 marks]From (3), [H+] = (2 x 10-7) + 10-14/[H+][H+] = 2.4 x 10-7(pH = 6.6) [8 marks][OH-] = 10-14/(2.4 x 10-7) = 4.1 x 10-8[2 marks]From (1), [HSO4-] = [H+][SO42-]/K2= (2.4 x 10-7)(1.0 x 10-7)/(1.2 x 10-2) = 2.0 x 10-12[5 marks]Check charge balance:2.4 x 10-7≈ (2.0 x 10-12) + 2(1.0 x 10-7) + (4.1 x 10-8)Check mass balance:0 + 2.0 x 10-12 + 1.0 x 10-7≈ 1.0 x 10-7Species Concentration** x 10-12HSO4-** x 10-7SO42-** x 10-7H+** x 10-8 OH-5-2. (20 marks)mmol H3PO4 = 0.85 ⨯ 3.48 mL ⨯ 1.69g/mL ⨯ 1 mol/98.00 g ⨯ 1000 = 51.0 [5 marks]The desired pH is above p K2.A 1:1 mixture of H2PO4- and HPO42- would have pH = p K2 = 7.20.If the pH is to be 7.40, there must be more HPO42- than H2PO4-.We need to add NaOH to convert H3PO4to H2PO4-and to convert to the right amount of H2PO4-to HPO42-.H3PO4 + OH-→ H2PO4- + H2OH2PO4- + OH-→ HPO42- + H2OThe volume of 0.80 NaOH needed to react with to to convert H3PO4 to H2PO4- is:51.0 mmol / 0.80M = 63.75 mL [5 marks]To get pH of 7.40 we need:H2PO4- + OH-→ HPO42-Initial mmol 51.0 x 0Final mmol 51.0-x 0 xpH = p K2 + log [HPO42-] / [H2PO4-]7.40 = 7.20 + log {x / (51.0-x)}; x = 31.27 mmol [5 marks]The volume of NaOH needed to convert 31.27 mmol is :31.27 mmol / 0.80 M = 39.09 mLThe total volume of NaOH = 63.75 + 39.09 =102.84 mL , 103 mL [5 marks]Total volume of 0.80 M NaOH (mL) 103 mL5-3. (20 marks)p K = 3.52pH = pK a + log ([A-]/[HA])[A-]/[HA] = 10(pH-pKa) [5 marks]In blood, pH =7.40, [A-]/[HA] = 10(7.40-3.52) = 7586Total ASA = 7586 +1 = 7587 [5 marks]In stomach, pH = 2.00, [A-]/[HA] = 10(2.00-3.52) = 3.02x10-2Total ASA = 1+ 3.02x10-2 = 1.03 [5 marks]Ratio of total aspirin in blood to that in stomach = 7587/1.03 = 7400 [5 marks]** ( 103Ratio of total aspirin in blood to that in stomach6-1. (5 marks)4 H2O + 4 e-→ 2 H2(g) + 4 OH- (or 2 H2O + 2 e-→ H2(g) + 2 OH-)6-2. (5 marks)2 H2O → O2 + 4 H+ + 4 e-(or H2O → 1/2 O2 + 2 H+ + 2 e- )6-3. (5 marks)Cu → Cu2+ + 2e-6-4. (20 marks)Reduction of sodium ion seldom takes place.It has a highly negative reduction potential of –2.710 V.Reduction potential for water to hydrogen is negative (water is very stable).But, it is not as negative as that for sodium ion. It is –0.830 V.Reduction of both copper ion and oxygen takes place readily and the reduction potentials for both are positive.In the present system, the reverse reaction (oxidation) takes place at the positive terminal. Copper is oxidized before water.Reduction potential for hydrogen ion is defined as 0.000 V.6-5. (15 marks)pOH = 14.00 – 4.84 = 9.16[OH-] = 6.92 x 10-10K sp = [Cu2+][OH-]2 = 0.100 x (6.92 x 10-10) = 4.79 x 10-206-6.E = E o Cu2+/Cu + (0.0592/2) log [Cu2+]= +0.340 + (0.0592/2) log [Cu2+]= +0.340 + (0.0592/2) log (K sp / [OH-]2)= +0.340 + (0.0592/2) log (K sp) - (0.0592/2) log [OH-]2= +0.340 + (0.0592/2) log (K sp) - 0.0592 log [OH-],3 marksBy definition, the standard potential for Cu(OH)2(s) + 2e-→ Cu(s) + 2OH- is the potential where [OH-] = 1.00.E = E o Cu(OH)2/Cu = +0.340 + (0.0592/2) log (K sp)= +0.340 + (0.0592/2) log (4.79 x 10-20)= +0.340 - 0.5722 marks= -0.232 V10 marks-------------------------------------------------------------------------------------------------------------- One may solve this problem as following.Eqn 1: Cu(OH)2(s) + 2e -→ Cu + 2OH-E+o = E o Cu(OH)2/Cu = ?Eqn 2: Cu(OH)2(s) → Cu2+ + 2OH-E o = (0.05916/n) logK sp= (0.05916/2) log(4.79×10-20)= -0.5715 V3 marksEqn 1 – Eqn 2 : Cu2+ + 2e-→ CuE-o = E+o - E o = E o Cu2+/Cu = 0.34 VTherefore, E+o = E-o + E o = + 0.34 + (-0.5715)2 marks= -0.232 V10 marks-0.232 V6-7.Below pH = 4.84, there is no effect of Cu(OH)2 because of no precipitation.Therefore,E = E Cu2+/Cu = +0.340 + (0.0592/2) log [Cu2+]= +0.340 + (0.0592/2) log 0.1003 marks= +0.340 – 0.0296 = +0.310 V7 marks** V6-8.** g graphite = 0.0833 mol carbon6 mol carbon to 1 mol lithium; 1 g graphite can hold 0.0139 mol lithiumTo insert 1 mol lithium, 96487 coulombs are needed.Therefore, 1 g graphite can charge 96487 × 0.0139 = 1340 coulombs. 5 marks1340 coulombs / g = 1340 A sec / g = 1340 x 1000 mA × (1 / 3600) h = 372 mA h / g 5 marks372 mA h / g7-1. (10 marks)n/V = P/RT = (80 x 106 / 1.013 x 105 atm)/[(0.082 atm L/mol/K)(298K)] = 32 mol/L5 marksdensity = mass/volume = d = 32 x 2 g/L = 64 kg/m 3 5 marks64 kg/m 37-2.** or 0.23H 2(g) + 1/2 O 2(g) → H 2O(l); ∆H rexn-1 = ∆H f [H 2O(l)] = -286 kJ/mol = -143 kJ/g 7 marksC(s) + O 2(g) → CO 2(g); ∆H rexn-2 = ∆H f [CO 2(g)] = -394 kJ/mol = -33 kJ/g 7 marks(-∆H rexn-1) / (-∆H rexn-2) = 4.3 or (-∆H rexn-2) / (-∆H rexn-1)= 0.236 marks7-3. (a) (-)1.2 x 105 kJ, (b) (-)6.9 x 104 kJ** x 108 sec or 3.3 x 104 hr or 1.4 x 103 days or 46 month or 3.8 yrI = 0.81 AH 2(g) + 1/2 O 2(g) → H 2O(l)∆H c = -286 kJ/mol = -143 kJ/g = -143 x 103 kJ/kg 5 marksΔG = ΔH – T ΔSΔS c= 70 – 131 – 205/2 = -163.5 J/K/mol5 marksΔG c = -286 kJ/mol + 298K x 163.5 J/K/mol = -237 kJ/mol = -1.2 x 105 kJ/kg 5 marks(a) electric motor W max = ΔG c ⨯ 1 kg = - 1.2 x 105 kJ 5 marks (b) heat engine W max = efficiency x ∆H c 5 marks= (1 – 298/573) x (-143 x 103 kJ) = -6.9 x 104 kJ 5 marks119 x 103 kJ = 1 W x t(sec)t = 1.2 x 108 sec = 3.3 x 104 hr = 1.4 x 103 days = 46 month = 3.8 yr 5 marksΔG = -nFE n = # of electrons involved in the reaction F = 96.5 kC/molH 2(g) + 1/2 O 2(g) → H 2O(l) n = 2 5 marksE = - ΔG/nF = 237 kJ/mol / 2 / 96.5 kC/mol = 1.23 V5 marksI = W/E = 0.81 A5 marks8-1-1. (5 marks on each)①C②C③CO8-1-2.③ Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) 5marks① C(s) + O2(g) → CO2(g) ΔH①◦ = -393.51 kJ = ΔH f◦(CO2(g))② CO2(g) + C(s) → 2CO(g) ΔH②◦ = 172.46 kJFrom ① and ②,ΔH f◦(CO(g)) = (1/2){172.46 + (-393.51)} = -110.525 kJΔH f◦(Fe2O3) = -824.2 kJΔH③◦ = 3ⅹΔH f◦(CO2(g)) - ΔH f◦(Fe2O3) - 3ⅹΔH f◦(CO(g))= 3ⅹ(-393.51) – (-824.2) - 3ⅹ(-110.525) = -24.8 kJ 7 marks ΔS③°=2ⅹ27.28+3ⅹ213.74-87.4-3ⅹ197.674=15.36 J/K 3 marks ΔG③°=ΔH°-TΔS°=-24.8kJ-15.36J/Kⅹ1kJ/1000Jⅹ1473.15K=-47.43 kJ5 marksK = e(-ΔG°/RT)= e(47430J/(8.314J/Kⅹ1473.15K)) = 48 5 marksBalanced equation of ③:K = 48Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g)8-2-1. (20 marks)One AB2O4 unit has available 4 (= 1 + (1/4)ⅹ12) octahedral sites.48-2-2. (20 marks)Since one face-centered cube in AB2O4 represents one Fe3O4 unit in this case, it has 8 available tetrahedral sites. In one Fe3O4 unit, 1 tetrahedral site should be occupied by either one Fe2+ (normal-spinel) or one Fe3+ (inverse-spinel). Therefore, in both cases, the calculation gives (1/8) ⅹ100% = 12.5% occupancy in available tetrahedral sites.**%8-2-3. (10 marks for d-orbital splitting, 10 marks for elec. distribution)9-1-1. 1 answer for 8 marks, two for 15 marksH 3CN NNH 3CNNN :::+_+::_:9-1-2. ( 10 marks)H 3CN::9-1-3.H 3CNCH 2CH 2:H 3CN HH CCH 2:(10 marks) (10marks )9-2-1. 5 marks eachHONN +_::ONN:H+:HH_O NN:H+:H_::::::9-2-2.( 10 marks)CH 2CO ::9-3-1.(40 marks)CH 3H 3CH 3C+BC H 2CCH 3CH 3CO 2DEOOO_9-3-2.(10 marks)O OH O n+F10-1. 10 marks eachNMLCH 2OHCH 2OHMeOOMeH HH HOMeMeO CHOCHOCH 2OHCH 2OHHHH H OHOMeMeO OH10-2. 8 marks each for correct structuresNumber of possible structures24 marks12OH(OH)OH(H)HH HHOMeOMeOH COOMeOH(OH)OH(H)HH HHOMeOMeOHCOOMe34OH(OH)OH(H)OH(OH)OHe(H)10-3. 10 marks eachGICH 2OHCH 2OHHHHHMeOOMeOHOMeCH 2OHCH 2OHHHHOMeOMeOMe10-4. 10 marksNumber of the correct structure for C from 10-2110-5.BOH(OH)OH(H)HHHH OHCOOHOHOH10 marks eachDJOH(OH)OH(H)HHHHOMeOMeCOOMeOMeOH(OMe)OMe(H)HHHHOMeOMeOMeCOOMe10-6. 20 marksHOOCOHHH OOOHOOH COOHOOHOHOH COOH11-1. 10 marks311-2. 30 marksCOOHHOOCOOH11-3. 2.5 marks eacha, c, d11-4 30 marksOOCOCOOOHTransition State11-5.For the enzyme-catalyzed reaction, Arrehnius equation could be applied.k cat/k uncat = A exp (-E a, cat/ RT) / A exp (-E a, uncat / RT)= exp [-∆E a, cat-uncat/ RT]= exp [-∆E a, cat-uncat(J/mol) / (2,480 J/mol)] = 106Therefore, -∆E a, cat-uncat = 34,300 J/mol 15 marksk uncat, T/k uncat, 298 = exp (-∆H≠ uncat/ RT) / exp (-∆H≠uncat / 298R)= exp [(-∆H≠ uncat/R)(1/T-1/298)]ln(k uncat, T/k uncat, 298 )= 13.8 = [(-86900/8.32)(1/T-1/298)]Therefore, T = 491 K, or 218o C 15 marks-E a, cat-uncat = 34,300 J/molT = 491 K, or 218o C。
课文翻译
Metal are electropositive and have a tendency to loss electrons, if supplied with energy:M M++e. The stronger this tendency, the more electropositive and more metallic an element is. The tendency to loss electrons depends on the ionization energy. Since it is easier to remove an electron from a large atom than from a small one, metallic character increases as we descend the groups in the periodic table. Thus in GroupⅣ,carbon is nonmetal, germanium shows some metallic properties, and tin and lead are metals. Similarly metallic character decreases from left to right ecause atomic size decreases and ionization energy increases. Thus sodium and magnesium are more metallic than silicon,which in turn, is more metallic than chlorine. The most electropositive elements are found in the lower left of periodic table and the most nonmetallic in top right.
巴戟天中环烯醚萜苷和蒽醌在电喷雾离子源负离子模式下的质谱裂解行为
巴戟天中环烯醚萜苷和蒽醌在电喷雾离子源负离子模式下的质谱裂解行为赵祥升;杨美华;吴海峰;舒晓燕【摘要】Morinda officinalis,the dried root of Morinda officinalis How,is com-monly used as a traditional Chinese medicine for the treatment of impotence and osteo-porosis in clinical theraphy,and this effect is supposed to be attributed to iridoid glyco-side and anthraquinone compounds.Recent years,liquid chromatography coupled with high resolution mass spectrometry was widely used for the identification of components from traditional Chinese medicine based on the fragmentation pathways of main compo-nents.However,reports on the fragmentation pathway of main ingredients in M.offi-cinalis were limited.Therefore,in this paper,the fragmentation pathways of 4 iridoid glycosides (monotropein,deacetyla sperulosidic acid,asperulosidic acid and asperulo-side)and 2 anthraquinones (rubiadin-1-methyl ether and rubiadin)in M.officinalis were investigated using electrospray ionization quadrupole time-of-flight tandem mass spectrometry (ESI-Q-TOFMS/MS)in negative ion mode.The deprotonated [M-H]-were observed by ESI-MS,from which the molecular weights were deduced.The colli-sion induced dissociation (CID)data of [M-H]- ions provided fragmentation informa-tion of the compounds of interest.The main and typical fragmentation pathway of iri-doid glycosides were neutral losses ofH2O,CO2,CH3COOH and glucosidic units. Meanwhile,the cleavages ofdihydropyranoid and sugar ring were also observed.The common fragment ions of m/z 1 1 3,1 0 1 were the characteristic ions for the cleavages of dihydropyranoid.The fragmentation process of anthraquinones was continual loss of CO followed by dissociation ofCO2.The experimental results indicated that the fragmenta-tion behavior of iridoid glycosides and anthraquinones was reasonable and could provide the basis for their structures elucidation and identification.%利用电喷雾-四极杆-飞行时间串联质谱(ESI-Q-TOF MS/MS)技术,在负离子模式下,探讨巴戟天中4种环烯醚萜苷和2种蒽醌成分的质谱裂解途径.通过[M-H]-获得化合物的相对分子质量信息,进一步对[M-H]-进行碰撞诱导解离,获得相应化合物的裂解途径.结果表明,环烯醚萜苷主要的裂解途径是首先脱去母环上的功能基团,如中性丢失H2O、CO2、CH3COOH 和糖单元等部分;其次是二氢吡喃环和糖环的断裂,m/z 113、101为环烯醚萜苷母环断裂的特征碎片离子.蒽醌类化合物的裂解行为是连续失去CO,也可以失去CO2.这些质谱裂解行为的研究有助于环烯醚萜苷和蒽醌类化合物的结构解析,也可为其他同类化合物的鉴定提供依据.【期刊名称】《质谱学报》【年(卷),期】2018(039)003【总页数】9页(P342-350)【关键词】巴戟天;电喷雾-四极杆-飞行时间串联质谱(ESI-Q-TOFMS/MS);环烯醚萜苷;蒽醌;裂解行为【作者】赵祥升;杨美华;吴海峰;舒晓燕【作者单位】中国医学科学院药用植物研究所海南分所,海南海口 571100;中国医学科学院药用植物研究所,北京 100193;中国医学科学院药用植物研究所,北京100193;西南科技大学生命科学与工程学院,四川绵阳 621010【正文语种】中文【中图分类】O657.63巴戟天为茜草科多年生植物巴戟天(Morinda officinalis How)的干燥根,是我国著名的南药和保健药材,具有补肾阳、强筋骨、祛风湿之功效,在临床上主要用于治疗阳痿遗精、宫冷不孕、月经不调、少腹冷痛、风湿痹痛、筋骨萎软等症[1]。
核专业英语翻译
核专业英语段落翻译南华大学,核科学技术学院,崔爽OUR MA TERIAL world is composed of many substances distinguished by their chemical, mechanical, and electrical properties. They are found in nature in various physical states—the familiar solid, liquid, and gas, along with the ionic “plasma.” However, the apparent diversity of kinds and forms of material is reduced by the knowledge that there are only a little more than 100 distinct chemical elements and that the chemical and physical features of substances depend merely on the strength of force bonds between atoms.We recall that this energy may be released by heating of solids, as in the wire of a light bulb; by electrical oscillations, as in radio or television transmitters; or by atomic interactions, as in the sun. The radiation can be viewed in either of two ways—as a wave or as a particle—depending on the process under study. In the wave view it is a combination of electric and magnetic vibrations moving through space. In the particle view it is a compact moving uncharged object, the photon, which is a bundle of pure energy, having mass only by virtue of its motion.A COMPLETE understanding of the microscopic structure of matter and the exact nature of the forces acting is yet to be realized. However, excellent models have been developed to predict behavior to an adequate degree of accuracy for most practical purposes. These models are descriptive or mathematical, often based on analogy with large-scale processes, on experimental data, or on advanced theory.The emission and absorption of light from incandescent hydrogen gas was first explained by Bohr with a novel model of the hydrogen atom. He assumed that the atom consists of a single electron moving at constant speed in a circular orbit about a nucleus—the proton成。
2020高中化学路易斯共价键理论
Each Covalent Bond contains two electrons
Carbon has 4 valence electrons
H HCH
H methane
H HCH
H
HC
Ne Neon
Stable Octet required
Covalent Bonding – Atoms Share Electrons
NO2
Number of valence electrons = 17
ONO
ONO
ONO
Molecules and atoms which are neutral (contain no formal charge) and with an
unpaired electron are called Radicals
可以通过共用电子对形成分子,共价键,共价分子。 八隅体规则
Lewis Symbols
Represent the number of valence electrons as dots Valence number is the same as the Periodic Table Group Number
1. Odd Number of Electrons
NO
Number of valence electrons = 11
NO
NO
Resonace Arrows
Resonance occurs when more than one valid Lewis structure can be written for a particular molecule (i.e. rearrange electrons)
ct电离效应的原理
ct电离效应的原理The principle of the ionization effect of CT refers to the fact that as X-rays pass through the body, they can ionize atoms, leading to the production of free radicals and the subsequent creation of charged particles. 这种电离效应是由于X射线穿过人体时,会使原子电离,从而产生自由基,进而产生带电粒子。
This process occurs when the X-rays transfer energy to the atoms, causing the release of inner shell electrons from their orbits, leading to the formation of ions. 这个过程是X射线将能量传递给原子,导致内层电子脱离轨道,产生离子。
The ionization effect of CT is an important aspect of its functioning, as it allows for the creation of high resolution images that can be used for the diagnosis and treatment of various medical conditions. CT的电离效应是其功能的重要方面,因为它能够产生高分辨率的图像,用于诊断和治疗各种医学疾病。
Understanding the principles behind the ionization effect of CT is essential for medical professionals and researchers in order to ensure the safe and effective use of this imaging technology. 了解CT电离效应的原理对于医学专业人员和研究人员来说是至关重要的,以确保这种成像技术的安全有效使用。
Pathways for Biomass to Biofuels Conversion
Pathways for Biomass to BiofuelsConversionBiomass is one of the most promising sources of renewable energy, and biomass-to-biofuels conversion has the potential to play a significant role in reducing greenhouse gas emissions and addressing the world's energy needs. However, there are several challenges associated with converting biomass to biofuels, including the processing of complex feedstocks, the cost of production, and the need for sustainable and efficient conversion pathways. In this article, we will explore the different pathways for biomass-to-biofuels conversion and discuss their advantages and limitations.Thermochemical ConversionThermochemical conversion is one of the most widely used methods for converting biomass to biofuels. This process involves heating biomass in the absence of oxygen to produce synthesis gas (syngas), which is then converted into liquid biofuels such as ethanol or diesel.One of the primary advantages of thermochemical conversion is its ability to process a wide range of feedstocks, including wood, agricultural residues, municipal solid waste, and energy crops. Additionally, the process is highly efficient, with conversion efficiencies of up to 70%.However, the process can be costly, and the high temperatures required can result in the formation of toxic byproducts. Furthermore, the efficiency of the process depends on the quality of the feedstock, and the process may not be sustainable in the long term.Biochemical ConversionBiochemical conversion is another pathway for biomass-to-biofuels conversion and involves using microorganisms to break down complex carbohydrates in the biomass into simple sugars, which can then be fermented into biofuels such as ethanol.One of the primary advantages of biochemical conversion is its lower cost compared to thermochemical conversion, as the process can be carried out at lower temperatures and pressures. Additionally, the process produces fewer toxic byproducts and is more sustainable in the long term.However, the process is limited in terms of the feedstocks it can process, as it requires high-quality biomass with high sugar content. Additionally, the process can be slow, and the yield of biofuels may be low.Hybrid ConversionHybrid conversion combines both thermochemical and biochemical conversion pathways to overcome the limitations of each process. This method involves using thermochemical conversion to produce syngas, which is then partially fermented using microorganisms to produce biofuels such as ethanol or butanol.One major advantage of hybrid conversion is its ability to process a wide range of feedstocks, including low-quality biomass such as municipal solid waste. Additionally, the process is highly efficient, with yields of up to 80%.However, the process can be complex and costly, as both thermochemical and biochemical processes must be integrated and optimized. Additionally, the process may produce toxic byproducts, and the sustainability of the process is still under investigation.ConclusionBiomass-to-biofuels conversion has the potential to play a significant role in reducing greenhouse gas emissions and addressing the world's energy needs. However, the different pathways for converting biomass to biofuels each have their own advantages and limitations.Thermochemical conversion is highly versatile and efficient but may be costly and unsustainable in the long term. Biochemical conversion is lower cost and more sustainable but has limited feedstock options and may be slow. Hybrid conversion combines the best of both worlds but may be complex and costly to optimize.Overall, the choice of conversion pathway will depend on factors such as the quality and availability of the feedstock, the desired yield and purity of the biofuel, and the cost and sustainability of the process. As such, continued research and innovation are needed to develop more efficient and sustainable biomass-to-biofuels conversion pathways.。
Wave-particleduality
1. Wave Particle Dualitya. Write the relationship for the kinetic energy and momentum for particle moving at speeds much slower than the speed of light.b. Find the wavelength of an electron in an x -ray machine having a kinetic energy 10 keV.c. Write the relationship for the kinetic energy and momentum for a particle moving at speeds which are on the order of the speed of light.d. Write the relationship for the kinetic energy and momentum for a photon.e . The maximum energy of an x -ray photon produced by a 10 keV electron is 10 keV. Find the wavelength of such an x -ray photon.2. Schroedinger’s EquationA completely free beam of electrons is moving in the +x direction with a kinetic energy of 10 keV. a. Write the Schroedinger equation for a particle moving in the x direction. b. Show that the wave function in a. is a solution to the Schroedinger equation.3. Schroedinger’s EquationAn electron is confined to move freely in a one dimensional box of length L =1.0 nm having infinite potential walls.a. Write the space part wave function for the ground state, and draw it in the upper left provided axes.b. Write the space part probability density and draw it in the lower left provided axes.c. Draw the wave function and probability density for the same situation but for the case where the height of the potential walls is finite.d. Which state, a. or c., has the lower energy. Explain in one sentence.4. In momentum space (k -space) the separation of states is given by Δk x =Δk y =Δk z =π/L .a. Find the number of states in a volume V =L 3 with momentum less than k and kinetic energy less than E .b. Find the Fermi energy for neutrons in a neutron star having 5×1057neutrons with radius 10 km.c. Find the total zero-point kinetic energy of the neutrons at temperature T =0 K.ψx ψxP x P x1. R elativityA s tar i s e mitting l ight i n t he p ositive x d irection. T he w avelength o f t he l ight i s 400 n m.a. (5 p t) W hat i s t he p eriod Δt i n n s o f o ne o scillation o f l ight i n t he s tar’s f ixed reference f rame.Assuming t he w ave t urns o n a t t=0b. (5 p t) H ow f ar d oes i t g o i n t =100 n s i n t he s tar’s f ixed f rame?c. (5 p t) W rite t he 4-‐vector f or t he s pace-‐time p osition a fter a t ime 100 n s.d. (5 p t) O btain t he s pace-‐time i nvariant i nterval t hat t he l ight t ravels i n 100 n s. Suppose t he s tar m oves a way f rom t he e arth i n t he p ositive x d irection w ith a v elocity 0.8c.e. (5 p t) W hat i s t he p eriod Δ′t i n n s o f o ne o scillation o f l ight i n t he e arth’s m oving r eference f rame?f. (5 p t) H ow f ar d oes t he l ight t ravel a fter o ne o scillation a s s een b y t he e arth.f. (5 p t) W rite t he 4-‐vector f or t he s pace-‐time p osition a fter a t ime ′t corresponding t o one o scillation a s s een f rom t he e arth’s r eference f rame.g. (5 p t) O btain t he s pace-‐time i nvariant i nterval i n t he e arth’s f rame t hat t he l ight travels i n 100 n s2.) B ohr m odel.According t o t he B ohr m odel o f t he h ydrogen a tom, a n e lectron i n t he g round s tateorbits a t a r adius o f a bout 0.5 A o. S uppose t he e lectron i s r eplaced b y a m uon( mµc2=105 MeV) t o f orm a m uonic a tom.a. (10 p t) W hat i s t he r adius o f o rbit f or t he m uonic a tom i n i ts g round s tate?b. (10 p t) W hat a re t he e nergies o f t he g round a nd f irst a nd f irst e xcited s tates?c. (10 p t) W hat i s t he w avelength c orresponding t o t he t ransition b etween t he f irst exciteds tate a nd t he g round s tate?3.)Schroedinger e quation.A s imple h armonic o scillator (SHO) h as a m ass m a nd s pring c onstant K. T he p otential e nergy is 1/2Kx2.a. (10 p t) W rite t he S chroedinger e quation f or t he s pace p art o f t he S HO.b. (10 p t) T he w ave f unction f or t he g round s tate h as t he f orm Ae bx2. B y d irects ubstitution s how t his i s a s olution, a nd t hereby f inding t he c onstant b i n t erms o f m a nd Kc. (10 p t) W rite t he p robability d istribution f or t he g round s tate, a nd c arefullyg raph i t.d. (10 p t) W rite a n i ntegral w hichwould b e u sed t o o btain t he n ormalizing c onstantA.You d o n ot n eed t o s olve t his i ntegral)4.)Schroedinger E q. i n 3 d imensions.Consider a t hree d imensional c ubic p otential w ell w ith r igid (infinite) w alls, h avingsides o f d imension L x = L y = L z = L=0.1 n m.a. (5 p t) W rite t he S chroedinger e quation f or a p article w ithin t he w ell.b. (5 p t) W rite t he q uantum c onditions o n k x , k y a nd k z.c. (5 p t) O btain t he q uantum c ondition o n t he w ave n umber k2.d. (5 p t) O btain t he q uantum c ondition o n t he a llowed e nergies E.e. (5 p t) W rite t he g round s tate s olution Ψ(x,y,z)to t he S chroedingere quationf or a p article w ithin t he w ell.f. (5 p t) W rite t he p robability d ensity f or a p article w ithin t he w ell i n t he g roundstate.g. (5 p t) O btain t he n umerical r esult o n t he a llowed e nergies E i n u nits o f e V.h. (5 p t) O btain t he n umber o f e lectrons w hich c an b e a ccommodated a t e ach o ft he l owest 3 e nergy l evels. T ake i nto a ccount t hat d ifferent c ombinations o fq uantum n umbers c an h ave t he s ame e nergy, a nd t hat t wo e lectrons,c orresponding t o s pin u p a nd d own c an f it i ntoe ach c ombination of s patialq uantum n umbers.2006 Exam. 21. A b aby s eal i n t he p acific o cean h as a b ody t emperature o f 310 K. I f t he m ean temperature o f t he w ater i s 287 K a t w hat r ate w ill t he s eal l ose e nergy b y r adiating p hotons? (σ=5.7×10−8 W⋅m-2⋅K-4)2. W ave p article d uality.Compare t he w avelength a nd f requency o f a p hoton a nd e lectron, e ach w ith k ineticenergy 10 K eV.3. B ohr m odel.a. U se t he B ohr m odel o f t he a tom t o e stimate t he e nergy l evels o f p ositronium, i n w hich a n electron o rbits a p ositron.b. T he i onization e nergy (binding e nergy) o f a n e lectron i n h ydrogen i s 13.6 e V.What i s t he i onization e nergy o f p ositronium?4. P article i n a b ox.Approximate a n a tomic n ucleus a s a n i nfinite c ubical b ox o f s ide L=2 f m, w here1 f m = 10-‐15 m, i n w hich t he n ucleons m ove f reely.a. O btain a n e xpression f or t he w avelength o f t he g round, o r l owest l ying e nergy s tate.b. W hat i s t he k inetic e nergy o f a n eutron i n t he g round s tate o f t his a tom. T he r estenergy o f a n eutron i s m c2=939 M eV.5. S imple h armonic o scillator.A n a pproximate r epresentation o f t he i nteraction b etween t wo a toms i n a d iatomicm olecule i s a s pring l ike f orce F=-Kx w ith o scillator f requency ω=. T ake t he f orcec onstant t o b e 8×103 e V/nm2 = 1000 N/m, a nd t he m ass of e ach a tom a round t o b e5×10−27kg(mc2=4.69 G eV). T he w ave f unction f or t he g round s tate o f a s imple h armonic o scillatori s ψ0(x)=mωπ⎛⎝⎜⎞⎠⎟1/4e−mω2x2.a. W hat i s t he e nergy o f t he g round s tate?b. F ind t he w ave f unction i n m omentum s pace b y p erforming a F ourier t ransformation.6. D ensity o f s tates a nd F ermi e nergy.a. F ind t he a verage e nergy o f a n e lectron i n a w hite d warf s tar o f r adius 10,000 k mcontaining 2×1057 n ucleons, h alf o f w hich a re p rotons. T he d ensity o f s tates d istribution i sdNdE=E1/2.b. F rom t he r esults i n p art a, c omment o n w hether i t i s a pproporiate t o u se n on-‐relativistickinematics.Other p roblems f rom p revious e xams:1. A f ree e lectron h as k inetic e nergy 1000 e V. I t m oves i n t he x-y p lane i n a d irection w hichmakes a n a ngle 30 d eg. r elative t o t he x a xis.a. F ind i ts m omentum p, w avelength λ a nd w ave n umber k.b. W rite t he w ave f unction Ψ(x,y,z,t) i n s ymbols (not n umerical v alues) i n C artesiancoordinates.c. W rite t he p robability d ensity P(x,y,z).d. W hat c an y ou s ay a bout t he u ncertainty i n t he e lectron’s p osition.Approximate a n ucleus c onsisting o f f ree n ucleons i n a s pherical r igid w all p otential w ith radius R=4 f m. F or t he i sotope 17O:a. W hat a re t he q uantum n umbers o f e ach o f t he n eutrons a nd p rotons?b. W hat a re t he e nergies o f e ach o f t he n eutrons a nd p rotons i n t he i sotope 17O?2. a. W rite t he w ave f unction f or a f ree p article m oving i n 3-‐dimensional C artesiancoordinates.b. T he r elativistic v ersion o f t he S chroedinger e quation i s c alled t he K lein-‐Gordon e quation.Using E2=p2c2+m2c4, c onstruct t he K lein-‐Gordon e quation b y e xpressing t he e nergy a nd momentum i n t erms o f d ifferential o perators.c. S how t hat t he w ave f unction i n p art a. i s a s olution t o t he K lein-‐Gordon w ave f unction t hatwas c onstructed i n p art c.3.) C onsider a n e lectron w hich m oves f reely i n a 2 d imensional i nfinite s quare w ell o f s ide a . a. W rite t he S chroedinger e quation f or t his c ase. b. W hat a re t he a llowed v alues o fk x and k yc. W hat a re t he a llowed e nergy l evels?d. I f a =10Angstroms, w hat i s t he l owest e nergy.e. W rite t he w ave f unction f or t his s tate.4.) T he t hree p rimary t erms w hich d etermine t he b inding e nergy o f a n ucleusare v olume , s urface a nd C oulomb , E V , E S , E C e nergies.a. W hat i s t he R a nd Z d ependence o f e ach, w here R i s t he n uclear r adius a nd Z t he a tomic number.Also i ndicate t he s ign o f e ach. i E V ∝ii E S ∝iii E C ∝b. W hat i s t he A a nd Z d ependence o f e ach, w here A i s t he n umber o f n ucleons. A lso i ndicate the s ign o f e ach. i E V /A ∝ii E S /A ∝iii E C /A ∝c. D raw t he m agnitude o f e ach a s a f unction o f A , a s w ell a s t he s um o f e ach. B e s ure t o c learly fill i n t he e nergy s cale i n t he v ertical a xis a nd t he n umber o f n ucleons i n the h orizontal a xis a t t he p osition o f t he t ic m arks.5.) I n t he b lank s paces p rovided i n t he t able, f ill i n t he p roperties o f t he p article s hown, a s w ell a s t he energy s cales a nd q uark m akeup w here a ppropriate.6.Draw a g raph f or t he s hape o f t he n ucleon-‐nucleon a ttractive p otential e nergy, i ndicating the a pproximate r ange a nd d epth.particl e Charge Rest m ass energy Units o f energy QuarkFlavor c ontent p +1 .93 GeV uud nπ−.139 π+ e 0.511 ν γ W 89 g7. a . 92238U c aptures a n eutron, f ollowed b y a symmetric f ission i nto 2 u nbound n eutrons a nd3892Sr a nd 54140Xe . O btain t he d ifference i n t he b inding e nergy b etween t he i nitial 92238U and t he f inal 3892Sr a nd 54140Xe n uclides, a nd t herefore t he e nergy r eleased.b . C alculate t he k inetic e nergyd ue t o t he e lectrostatic r epulsion b etween t he 3892Sr a nd 54140Xe w hen t hey a re s till t ouching, a nd s how t hat i t i s t he s ame o rder a s y our a nswerin p art a . a bove. (note:r =r 0A 1/3with r 0≈1.2fm.)8.Fill i n t he t able b elow:9. a . T he m ajor s ource o f e nergy p roduction i n t he s un i s t he p roton-‐proton c ycle. Trace t he s teps o f t he p -p c ycle a s w e d iscussed i n c lass.b . I f t he f inal r esult i s t he f usion o f 4 p rotons i nto 4He ,c alculate t he t otal e nergy r eleased in t he c ycle.10. D raw a F eynman d iagram f or e ach o f t he f ollowing p rocesses, a nd i dentify t he e xchanged quantum:a. e - +µ+♑e - +µ+via t he e lectromagnetic i nteraction. b. e - +µ+♑e + +µ- v ia t he w eak i nteraction.c. u +u →s +s v ia t he s trong i nteraction.6. F rom t he i nformation o n s pin, b aryon n umber a nd s trangeness g iven i n t he t ablebelow, f ill i n t he q uark f lavor c ontent a nd d ecay i nteraction o f e ach o f t he f ollowing h adrons.Decay interact we。
空间转录组联合代谢
空间转录组联合代谢英文回答:Spatial transcriptomics has emerged as a powerful technique to study the spatial organization of cells and tissues. By combining spatial transcriptomics with metabolomics, researchers can gain a more comprehensive understanding of the relationship between cellular function and metabolism.One of the main advantages of combining spatial transcriptomics and metabolomics is that it allows researchers to identify cell types that are responsible for specific metabolic pathways. This information can be used to study how different cell types contribute to the overall metabolism of a tissue or organ. Additionally, spatial transcriptomics can be used to identify changes in metabolism that occur in response to disease or environmental stimuli.Several methods can be used to combine spatial transcriptomics and metabolomics. One common approach is to use a technique called multiplexed ion beam imaging (MIBI). MIBI allows researchers to measure the abundance ofmultiple metabolites in a tissue sample at the single-cell level. Another approach is to use a technique calledmatrix-assisted laser desorption/ionization (MALDI) mass spectrometry. MALDI-MS allows researchers to measure the abundance of metabolites in a tissue sample at the subcellular level.The combination of spatial transcriptomics and metabolomics is a powerful tool for studying the relationship between cellular function and metabolism. This technology has the potential to provide new insights into the development of diseases and the development of new therapies.中文回答:空间转录组学已经成为研究细胞和组织空间组织的一种强大技术。
大学有机化学双语教学辅助材料专业术语——英文解释
Learning Supplementsin Organic Chemistry有机化学双语教学辅助材料(专业术语及英文解释)Glossary of Organic ChemistryAcetate(醋酸盐). (CH3COO-, C2H3O2-). acetate ion.1. an ion formed by removing the acidic hydrogen of acetic acid, HC2H3O2. 2. a compound derived byreplacing the acidic hydrogen in acetic acid. 3. A fiber made of cellulose acetate.Acetic acid(乙酸). (CH3COOH, C2H4O2). ethanoic acid; vinegar acid; methanecarboxylic acid.A simple organic acid that gives vinegar its characteristic odor and flavor. Glacial acetic acid is pureacetic acid.Acetone (丙酮).[CH3COCH3 or (CH3)2CO]. trivial name for propanone, formed by the oxidation of2-propanolwith KMnO4.Achiral(非手性的). A molecule that's superimposable on its mir ror image. Achiral molecules do not rotateplane-polarized light.Achiral molecule(非手性分子). a molecule that does not contain a stereogenic carbon; an achiral moleculehas a plane ofsymmetry and is superimposable on its mirror image.Acid anhydride(酸酐)[(RCO)2O]. Compare with acid .Nonmetallic oxides or organic compounds that react with water to form acids . For example, SO2, CO2,P2O5, and SO3 are the acid anhydrides of sulfurous, carbonic, phosphoric, and sulfuric acids, respectively. Acetic anhydride (CH3CO)2O) reacts with water to form acetic acid.Acid dissociation constant(酸电离常数).(Ka) acid ionization constant. Compare with base hydrolysis constant.The equilibrium constant for the dissociation of an acid into a hydrogen ion and an anion. For example, the acid dissociation constant for acetic acid is the equilibrium constant for HC2H3O2(aq)H+(aq) + C2H3O2-(aq), which is Ka = [H+][C2H3O2-]/[HC2H3O2].Acid halide(酰卤)(RCOX). acid chloride; acyl halide; acyl chloride.Compounds containing a carbonyl group bound to a halogen atom.Acid(酸). (Lat. acidus, sour) Compare with base.A proton donor or an electron pair acceptor. 1. a compound which releases hydrogen ions (H+) in solution (Arrhenius). 2. a compound containing detachable hydrogen ions (Bronsted-Lowry). 3. a compound that can accept a pair of electrons from a base (Lewis)..Acid-base indicator(酸碱指示剂).A weak acid that has acid and base forms with sharply different colors. Changes in pH around the acid's pKa are "indicated" by color changes.Acid/base reaction(酸/碱反应). a reaction in which an acidic H atom is transferred from one molecule toanother.Addition compound(加成化合物). complex compound. Compare with hydrate.An addition compound contains two or more simpler compounds that can be packed in a definite ratiointo a crystal. A dot is used to separate the compounds in the formula. For example, ZnSO4·7 H2Oan addition compound of zinc sulfate and water. This represents a compound, and not a mixture, because there is a definite 1:7 ratio of zinc sulfate to water in the compound. Hydrates are a commontype of addition compound.Addition reaction(加成反应). A reaction in which two molecules are combined to yield asingle product. Typical of the reactions of alkenes and alkynes.-al(醛,后缀). A suffix added to the systematic names of organic compounds that contain an aldehyde group-(C=O)-H. For example, the systematic name of acetaldehyde, CH3CHO, is ethanal.Alcohol(醇). (ROH) Compare with phenol and hydroxide.A molecule containing a hydroxyl (OH) group. Also a functional group. An alcohol is an organic compound with a carbon bound to a hydroxyl group. Examples are methanol, CH3OH; ethanol, CH3CH2OH; propanol, CH3CH2CH2OH. Compounds with -OH attached to an aromatic ring are calledphenols rather than alcohols.Aldehyde(醛). (RCHO)A molecule containing a terminal carbonyl (CHO) group. Also a functional group. An aldehyde is anorganic compound with a carbon bound to a -(C=O)-H group. Examples are formaldehyde (HCHO),acetaldehyde, CH3CHO, and benzaldehyde, C6H6CHO.Aliphatic(脂肪族的). Compare with aromatic .An organic compound that does not contain ring structures.Alkaline earth(碱土金属). An oxide of an alkaline earth metal, which produces an alkaline solution inreaction with water.Alkali metal(碱金属). (a metal in Group IA on the periodic table): active metals which may be used to reactwith analcohol to produce the corresponding metal alkoxide and hydrogen gas.Alkaline(碱的,碱性的). Having a pH greater than 7.Alkane(烷烃). (RH,CnH2n+2) paraffin. Compare with hydrocarbon and alkene. A molecule containing onlyC-H and C-C single bonds. A series of organic compounds with general formula CnH2n+2. Alkane names endwith -ane. Examples are propane (with n=3) and octane (with n=8).Alkene(烯烃). (CnH2n) A molecule containing one or more carbon-carbon double bonds. Also a functionalgroup. A compound that consists of only carbon and hydrogen, that contains at least one carbon-carbondouble bond. Alkene names end with -ene. Examples are ethylene (CH2=CH2); 1-propene (CH2=CH2CH3),and 2-octane (CH3CH=CH(CH2)4CH3).Alkoxide(醇盐, 烷氧根负离子). (RO- M+) alkoxide ion.An ionic compound formed by removal of hydrogen ions from the hydroxyl group in an alcohol usingreactive metals, e.g. sodium. For example, potassium metal reacts with methanol (CH3OH) to produce potassium methoxide (KOCH3).Alkoxy group(烷氧基)(RO-).a substituent containing an alkyl group linked to an oxygen.Alkyl benzene(烷基苯)(C6H5-R). a benzene ring that has one alkyl group attached; the alkyl group(exceptquaternary alkyl groups) is susceptible to oxidation with hot KMnO4 to yield benzoic acid (C6H5CO2H).Alkyl(烷基). (-CnH2n+1) alkyl group. A molecular fragment derived from an alkane by dropping a hydrogenatom from the formula. Examples are methyl (-CH3) and ethyl (-CH2CH3).Alkyne(炔烃). (CnH2n-2) A molecule containing one or more carbon-carbon triple bonds. Also a functionalgroup. A compound that consists of only carbon and hydrogen, that contains at least one carbon-carbontriple bond. Alkyne names end with -yne. Examples are acetylene (CHidentCH); 1-propyne (CHidentCCH3), and2-octyne (CH3CidentC(CH2)4CH3).Allenes(丙二烯). Propa-1,2-diene (CH2=C=CH2) and derivatives. In allenes the two πbonds are orthogonal(see below), as are the two terminal hydrogens at one end, with respect to those at the other.Allo-(同分异构的). prefix that designates the more stable of a pair of geometric isomers. allo- is sometimesused less precisely to designate isomers or close relatives of a compound.Allyl(烯丙基). allylic; allyl group; allyl radical.A molecular fragment derived by removing a methyl hydrogen from propene (-CH2-CH=CH2). Forexample, "allyl chloride" is 3-chloropropene, Cl-CH2-CH=CH2.Allylic carbon(烯丙基正离子). (CH2=CH-CH2+)An sp3 carbon adjacent to a double bond.Amide(酰胺)(RCONH2). A molecule containing a carbonyl group attached to a nitrogen (-CONR2). Also afunctional group. An amide is an organic compound that contains a carbonyl group bound to nitrogen: .The simplest amides are formamide (HCONH2) and acetamide (CH3CONH2).Amine(胺)(RNH2). Compare with ammine.A molecule containing an isolated nitrogen = (NR3). Also a functional group. An amine is an organiccompound that contains a nitrogen atom bound only to carbon and possibly hydrogen atoms. Examples are methylamine, CH3NH2; dimethylamine, CH3NHCH3; and trimethylamine, (CH3)3N.Amino acid(氨基酸). Amino acids are molecules that contain at least one amine group (-NH2) and at leastone carboxylic acid group (-COOH). When these groups are both attached to the same carbon, the acid is an alpha-amino acid. alpha-amino acids are the basic building blocks of proteins.Amino group(氨基). the -NH2 group.Ammine(氨络物). Compare with amine.A metal ion complex containing ammonia as a ligand. The ammonia nitrogen is bound directly to ametal ion in ammines; amines differ in that the ammonia nitrogen is directly bound to a carbon atom.Ammonia(氨,氨水). (NH3) Compare with ammonium.Pure NH3 is a colorless gas with a sharp, characteristic odor. It is easily liquified by pressure, and isvery soluble in water. Ammonia acts as a weak base. Aqueous solutions of ammonia are (incorrectly)referred to as "ammonium hydroxide".Ammonium ion(铵根离子). (NH4+) ammonium.NH4+ is a cation formed by neutralization of ammonia, which acts as a weak base.Amphiprotic solvent(两性溶剂). Compare with aprotic solvent.Solvents that exhibit both acidic and basic properties; amphiprotic solvents undergo autoprotolysis.Examples are water, ammonia, and ethanol.Amphoteric(两性的). ampholyte.A substance that can act as either an acid or a base in a reaction. For example, aluminum hydroxidecan neutralize mineral acids ( Al(OH)3 + 3 HCl = AlCl3 + 3 H2O ) or strong bases ( Al(OH)3 + 3 NaOH =Na3AlO3 + 3 H2O).Aniline(苯胺;苯胺的). (C6H5NH2).a primary (1) amine in which the NH 2 group is bonded directly to abenzene ring..ngstrom (.)(埃,1/10 纳米).Unit of length named after the Swedish physicist, now being superseded by nanometer (nm). 1 . = 10–10 m so that a bond length of 1.54 . is given by 0.154 nm.Anhydrous(无水的). anhydrous compound; anhydride. Compare with hydrate.A compound with all water removed, especially water of hydration. For example, strongly heating copper(II) sulfate pentahydrate (CuSO4·5H2O) produces anhydrous copper(II) sulfate (CuSO4).Anion(阴离子). Compare with cation.A negatively charged atom or molecule. An anion is a negatively charged ion. Nonmetals typically form anions.Anomers(异头物). Anomers are cyclic diastereoisomers that differ only at the hemiacetal carbon. Theanomeric carbon in a sugar is the only carbon that is bonded to two oxygen atoms.Anti(希腊字头,反;抗;对;阻) (see also Anti addition; Anti periplanar). Substituents are anti if they are onopposite sides of a defined reference plane in a molecule. Anti is used to assign stereochemistry toproducts of, for example, asymmetric aldol reactions. The main chain is drawn in the plane of the paper and substituents on opposite sides of the plane are termed anti.Anti addition(反式加成). A reaction in which the two groups of a reagent X-Y add on opposite faces of acarbon-carbon bond. Anti addition of X–Y occurs when X and Y are added to opposite faces of a double bond.Anti clinal(反错构象). When the C–C–C–C dihedral angle is between 90° and 150°, i.e. 120 .30°, theconformation is said to be anti clinal.Anti conformation(反式构象). A type of staggered conformation in which the two big groups are opposite ofeach other in a Newman projection.Anti periplanar (sometimes called Anti)(反式共平面). Term given to a molecular fragment, e.g.X–C(1)–C(2)–Y, or C(1)–C(2)–Y (in this second case, a lone pair of electrons in a p-orbital replacesthe X–C bond), in which the dihedral angle is 180°, or more generally 180 .30°.Anti-aromatic(反芳香性的). A highly unstable planar ring system with 4n pi electrons.Antibonding orbital(反键轨道). antibonding; antibonding molecular orbital.A molecular orbital that can be described as the result of destructive interference of atomic orbitals on bonded atoms. Antibonding orbitals have energies higher than the energies its constituent atomicorbitals would have if the atoms were separate.Anti-periplanar (a.k.a. anticoplanar)(反平面). The conformation in which a hydrogen and a leaving groupare in the same plane and on opposite sides of a carbon-carbon single bond. The conformation required for E2 elimination.Aprotic solvent(非质子溶剂;疏质子溶剂). Compare with amphiprotic solvent.Solvents that do not contain O-H or N-H bonds. A solvent that does not act as an acid or as a base; aprotic solvents don't undergo autoprotolysis. Examples are pentane, pet ether, and toluene.Aqua regia(王水).A mixture of nitric and hydrochloric acids, usually 1:3 or 1:4 parts HNO3 to HCl, used to dissolvegold.Arene(芳香烃). (ArH)A hydrocarbon that contains at least one aromatic ring.Aromatic(芳香族的). A planar ring system that contains uninterrupted p orbitals around the ring and a total of4n+2 pi electrons. Aromatic compounds are unusually stable compounds.Aromatic compound(芳族化合物).A compound containing an aromatic ring. Aromatic compounds have strong, characteristic odors. Aromatic ring(芳环). (Ar)An exceptionally stable planar ring of atoms with resonance structures that consist of alternating double and single bonds, e. g. benzene:Aryl(芳基). (Ar-) aryl group.An aromatic group as a substituent. A molecular fragment or group attached to a molecule by an atom that is on an aromatic ring.Aspirin(阿司匹林;乙酰水杨酸).trivial name for the compound acetylsalicylic acid; formed by treating salicylicacid with aceticanhydride.Asymmetric carbon atom(不对称碳原子;手性碳原子). a carbon atom with four different substituents; astereogenic carbon.Atactic(不规则的). This adjective describes a polymer whose stereogenic centres along the polymer chainare randomly oriented.Atropisomers(位阻异构体). Stereoisomers that arise from restricted rotation around a single bond in whichthe barrier to rotation is sufficiently high for the stereoisomers to be isolated. Certain ortho disubstituted biphenyls are atropisomers, and the stereoisomers referred to in this case are enantiomers.Average bond enthalpy(平均键焓). Compare with bond enthalpy.Average enthalpy change per mole when the same type of bond is broken in the gas phase for manysimilar substancesAxial bonds(直立键). A bond perpendicular to the equator of the ring (up or down), typically in a chaircyclohexane. In the chair conformation of cyclohexanes, axial bonds are described as being: (a) parallel to the C3 axis, or (b) perpendicular to a general plane that contains the majority of carbon atoms.Axial chirality(轴手性;轴不对称). Chirality that has its origins in the non-planar disposition of groups withrespect to an axis,and exemplified by 1,3-dichloroallene, certain alkylidenecyclohexanes and4-substituted cyclohexanone oximes.Axial(轴的).1. An atom, bond, or lone pair that is perpendicular to equatorial atoms, bonds, and lone pairs in a trigonal bipyramidal molecular geometry.Azo(偶氮). azo compound; azo group; azo dye.The azo group has the general structure Ar-N=N-Ar', where Ar and Ar' indicate substituted aromaticrings. Compounds containing the azo compounds are often intensely colored and are economically important as dyes. Methyl orange is an example of an azo dye.Base hydrolysis constant(碱水解常数). (Kb) base ionization constant; basic hydrolysis constant. Comparewith acid dissociation constant.The equilibrium constant for the hydrolysis reaction associated with a base. For example, Kb for ammonia is the equilibrium constant for NH3(aq) + H2O(ell) doublearrowNH4+(aq) + OH-(aq), or Kb =[NH4+][OH-]/[NH3].Base(碱). alkali; alkaline; basic. Compare with acid.A proton acceptor or an electron pair donor.1. a compound that reacts with an acid to form a salt.2. a compound that produces hydroxide ions inaqueous solution (Arrhenius). 3. a molecule or ion that captures hydrogen ions.(Bronsted-Lowry).4. amolecule or ion that donates an electron pair to form a chemical bond.(Lewis).Benzaldehyde(苯甲醛;安息香醛).(C6H5CHO).simplest aromatic aldehyde, formed by the controlledoxidation of benzyl alcohol; vigorous oxidation yields benzoic acid.Benzene(苯). an aromatic cyclic hydrocarbon of formula C6H6.Benzoic acid(苯甲酸)(C6H5CO2H): simplest aromatic carboxylic acid, formed by the vigorous oxidation ofalkyl benzene, benzyl alcohol, and benzaldehyde.Benzyl group(苄基;苯甲基) (C6H5CH2-). A benzene ring plus a methylene (CH2) unit (C6H5-CH2-).Benzylic position( ). The position of a carbon attached to a benzene ring.Benzyne(苯炔; 脱氢苯). A highly reactive intermediate. A benzene ring with a triple bond.Bicyclic(二环的). A molecule with two rings that share at least two carbons.Binary compound(二元化合物). Compare with compound.A compound that contains two different elements. NaCl is a binary compound; NaClO is not.Bond energy(键能). bond enthalpy(键焓).Compare with bond enthalpy.Energy change per mole when a bond is broken in the gas phase for a particular substance.Bond length(键长).The average distance between the nuclei of two bonded atoms in a stable molecule.Bond order(键级).1. In Lewis structures, the number of electron pairs shared by two atoms.2. In molecular orbital theory,the net number of electron pairs in bonding orbitals (calculated as half the difference between the number of electrons in bonding orbitals and the number of electrons in antibonding orbitals.Bridgehead carbon(桥头碳原子). In an unsubstituted hydrocarbon that consists of two or more fused orbridged rings, with two or more carbons in common, the bridgehead carbons are tertiary carbons common to two or more rings. Bridgehead carbons can be substituted by, for example, Cl,OH, etc. Inbicyclo[2.2.1]heptane the bridgehead carbons are C(1) and C(4); in bicyclo[4.4.0]decane they are C(1) and C(6).Br.sted acid(布朗斯特酸). Compare with acid.A material that gives up hydrogen ions in a chemical reaction.Br.sted base(布朗斯特碱). Compare with base.A material that accepts hydrogen ions in a chemical reaction.Brosylate (4-bromobenzenesulfonate, 4-BrC6H4SO3)(对甲基苯磺酸盐). Slightly mbetter leaving groupgroup than tosylate in substitution and elimination reactions. Usually abbreviated to OBs.Buffer(缓冲液). pH buffer; buffer solution.A solution that can maintain its pH value with little change when acids or bases are added to it. Buffer solutions are usually prepared as mixtures of a weak acid with its own salt or mixtures of saltsof weak acids. For example, a 50:50 mixture of 1 M acetic acid and 1 M sodium acetate buffers pHaround 4.7.Cahn–Ingold–Prelog (CIP) R/S convention(R/S构型命名法). The most widely used method for assignmentof configuration to stereogenic centres (and chiral axes). Substituents at stereogenic centres are given ranking numbers 1, 2, 3 and 4, associated with decreasing atomic number; configuration is then assigned as in Chapter 2.Canonical forms (also called resonance structures)(共振结构式). These are different mLewis structures thatare alternative ways of representing the actual structure of a molecule that contains delocalized bonds. One draws several possible structures that all have the same number of unpaired electrons, and in which the relative positions of the nuclei are the same. Each canonical structure contributes inproportion to its stability, so that the structure is a weighted average of all canonical structures. These delocalized canonical structures have no individual existence. As an example, aromatic compounds and amides are weighted averages of two or more canonical forms (or Lewis structures);in the case of an amide, these are, for example, R12N–C(=O)R2 and R12N+=C(O–)R2.Carbanion(负碳离子). A negatively charged carbon atom.Carbene(碳烯). A reactive intermediate, characterized by a neutral, electron-deficient carbon center with twosubstituents (R2C:).Carbocation(碳正离子). A positively charged carbon.Carbonyl(羰基). carbonyl group.A carbon double bonded to oxygen (C=O). A divalent group consisting of a carbon atom with a double-bond to oxygen. For example, acetone (CH3-(C=O)-CH3) is a carbonyl group linking twomethyl groups. Also refers to a compound of a metal with carbon monoxide, such as iron carbonyl,Fe(CO)5.Carboxylic acid(羧酸)(RCOOH). carboxyl; carboxyl group.A molecule containing a carboxyl (COOH) group.Also a functional group. A carboxylic acid is an organic molecule with a -(C=O)-OH group. The group is also written as -COOH and is called a carboxyl group. The hydrogen on the -COOH group ionizes in water; carboxylic acids are weak acids.The simplest carboxylic acids are formic acid (H-COOH) and acetic acid (CH3-COOH).Carotene(胡萝卜素).Carotene is an unsaturated hydrocarbon pigment found in many plants. Carotene is the basic buildingblock of vitamin A.Catalyst(催化剂)a substance which changes the rate of a chemical reaction but is unchanged at the end ofthe reaction; an example would be the Pt used in the hydrogenation of alkenes.Cation(阳离子). Compare with anion.A positively charged molecule or atom. A cation is a positively charged ion. Metals typically form cations.Chair conformation(椅式构象). Typically, the most stable cyclohexane conformation. Looks like a chair. Thelowest energy conformation of cyclohexane. All the vicinal C–H bonds are staggered; this conformation has very little angle strain or torsion strain.Chelate(螯合的).A stable complex of a metal with one or more polydentate ligands. For example, calcium complexeswith EDTA to form a chelate.Chemical bond(化学键). bond; bonding; chemical bonding.A chemical bond is a strong attraction between two or more atoms. Bonds hold atoms in moleculesand crystals together. There are many types of chemical bonds, but all involve electrons which areeither shared or transferred between the bonded atoms.Chemical shift(化学位移). The location of an NMR peak relative to the standard tetramethylsilane (TMS),given in units of parts per million (ppm).Chiral center(手性中心). asymmetric center.A carbon or other atom with four nonidentical substituents. An atom in a molecule that causes chirality,usually an atom that is bound to four different groups. A molecule can have chirality without having achiral center, and a molecule may also have more than one chiral centers.Chiral molecule(手性分子). A molecule that's not superimposable on its mirror image. Chiral molecules rotateplane-polarized light.Chiral(手性的). chirality(手性).Having nonsuperimposable mirror images. For example, a shoe or a glove is chiral.A chiral (or handed) molecule is one that is not superimposable on its mirror image. The adjective isideally restricted to single molecules. An object such as a helix can also be described as chiral.The property of non-identity of an object with its mirror image. An object, e.g. a molecule in a givenconfiguration or conformation, is said to be chiral when it is not identical with its mirror image.Cis(顺式). Groups or atoms are cis when they lie on the same side of an identifiable reference plane in amolecule.Two identical substituents on the same side of a double bond or ring.Concerted(一致的;协同的). In a concerted reaction the bonding changes occur in a single step andsimultaneously.Condensation reaction(缩合反应). A reaction in which a small molecule (usually HO or HX) is produced inthe combination of two other molecules.2Configuration(构型). The three-dimensional arrangement (or sequence) in space of atoms, or functionalgroups, that characterizes a stereoisomer. In order to change a configuration, bond breaking and bond re-forming in a different sequence must occur. Enantiomers have opposite configurations.Configurations are denoted by R/S; D/L; E/Z. Configuration should be contrasted withconformation, in which changes are brought about only by bond rotation.Conformation (boat)( 船式构象). A conformation of cyclohexane that, by virtue of two eclipsed C–C bondsand a 1,4 non-bonded H...H interaction, is of higher energy than the chair conformation. So called because it resembles a boat when viewed sideways on.Conformation (chair)( 椅式构象). The lowest energy conformation of cyclohexane, in which all C–C bondsare staggered, and which has very little angle or torsional strain. This conformation resembles a chair when viewed sideways on.Conformation (eclipsed)(重叠式构象). When, for example, in ethane the dihedral angle .between a pair ofhydrogens on adjacent carbons is 0°; this is the least stable conformation. In butane, both C–C–C–Cdihedral angles of 0.(synperiplanar) and 120.(anticlinal) are eclipsed; the C–H bonds are eclipsedhere also. Some rigid molecules, e.g. bicyclo[2.2.1]heptane, have the C–H bonds at C(2), C(3), C(5)and C(6) locked in an eclipsed conformation.Conformation (skewed)(扭曲式构象). As above, but with the value of between 0° and 60°; there are aninfinite number of skewed conformations.Conformation (staggered)(交叉式构象). As above but with ..= 60°; in the case of ethane, the most stableconformation. Butane has a gauche staggered conformation in which the C–C–C–C dihedral angle is60°and an antiperiplanar staggered conformation in which the corresponding dihedral angle is 180°.Conformation(构象). The instantaneous spatial arrangements of atoms. Conformations can change byrotation around single bonds. The instantaneous spatial arrangements of atoms. Conformations can change by rotation around single bonds.Conformers(构象异构体). conformation(构象).Molecular arrangements that differ only by rotations around single bonds. For example, the "boat" and"chair" forms of cyclohexane are conformers.Conjugate acid(共轭酸). The acid that results from protonation of a base.Conjugate base(共轭碱). The base that results from the deprotonation of an acid.Conjugated double bonds(共轭双键). Double bonds separated by one carbon-carbon single bond. Alternating double bonds.Conjugation(共轭).A general feature of molecules which haveadjacent p-orbitals as in molecules withalternating multiple bonds. Electrons are said to be delocalized through extended π bonding.Conrotatory(顺旋). This adjective indicates that both p-orbitals at the terminal carbons (and the substituentsat these carbons) of a conjugated acyclic hydrocarbon rotate in the same sense, both clockwise or both anti-clockwise, during ring closure. Also applied to the reverse step, namely ring opening.Constitutional isomers(构造异构体). Molecules with the same molecular formula but with atoms attached indifferent ways.Coordination number(配位数).The number of bonds formed by the central atom in a metal-ligand complex.Coupling constant( 耦合常数). The distance between two neighboring lines in an NMR peak (given in unitsof Hz).Coupling protons(耦合质子). Protons that interact with each other and split the NMR peak into a certainnumber of lines following the n+1 rule.Covalent bond(共价键). covalent; covalently bound. Compare with covalent compound and ionic bond.Bond in which the two electrons are shared between the two atoms.A covalent bond is a very strong attraction between two or more atoms that are sharing their electrons.In structural formulas, covalent bonds are represented by a line drawn between the symbols of the bonded atoms.A compound made of molecules- not ions. The atoms in the compound are bound together by sharedelectrons. Also called a molecular compound.Cyclic compound(环状化合物)a molecule which has the two ends of the carbon chain connected togetherto form a ring.Crystal field splitting energy(晶体场分裂能). (Delta)Ligands*complexed to a metal ion will raise the energy of some of its d orbitals and lower the energyof others. The difference in energy is called the crystal field splitting energy.Crystal field theory( 晶体场理论). crystal field.The color, spectra, and magnetic properties of metal-ligand complexes can be explained by modelingthe effect of ligands on metal's d orbital energies.Cupric. (Cu2+) cupric ion(二价铜的).Deprecated. 1. the copper(II) ion, Cu2+. 2. A compound that contains copper in the +2 oxidation state.Cuprous. (Cu+) cuprous ion(亚铜的).Deprecated. 1. the copper(I) ion, Cu+. 2. A compound that contains copper in the +1 oxidationstate.Cycloaddition reaction( 环化加成反应). In the context of pericyclic reactions, this term refers to twomolecules, the same or different, with one or more .bonds, that combine to form a cyclic compound withcreation of two new .bonds in a concerted, bimolecular reaction. Of course, cycloaddition reactions mayproceed stepwise, but these are not pericyclic reactions.D-. D-isomer(D-异构体). Compare with L- .Prefix used to designate a dextrorotatory enantiomer .D-. D-isomer(D-异构体). Compare with L-.Prefix used to designate a dextrorotatory enantiomer.Dehydration(脱水)an elimination reaction in which an alcohol reacts with concentrated acid to yield analkene plus water.Dehydrogenases(脱氢酶). Enzymes that operate in conjunction with a cofactor,usually NADH. Despite thename, dehydrogenases catalyse both dehydrogenation (oxidation) and reduction reactions, under appropriate conditions.dehydrohalogenation(脱去卤化氢). Loss of a hydrohalic acid (like HBr, HCl, and so on) to form adouble bond.Delta value (a.k.a. d value)(δ:化学位移值). The chemical shift. The location of an NMR peak relative to thestandard tetramethylsilane (TMS), given in units of parts per million (ppm).Dextrorotatory (d)( 右旋的). Having the property of rotating plane-polarized light clockwise.Description given to a chiral compound that rotates the plane of polarized light (usually of wavelength589.6 nm, the sodium D line) in a clockwise sense as the observer looks into the propagating beam.Diastereoisomers(非对映异构体). Stereoisomers that are not mirror images of each other. Stereoisomers。
SAT化学考试常用的词汇
SAT化学考试常用的词汇SAT化学考试常用的词汇汇总Matter 物质Definition of Water(物质的定义)States of Matter(物质的状态)Composition of Matter (物质的构成)Chemical and Physical Properties(化学性质和物理性质)Chemical and Physical Changes (化学变化和物理变化)Conservation of Mass (质量守恒)Energy 能量Definition of Energy(能量的定义)Forms of Energy(能量的形式)Types of Reactions(Exothermic Versus Endothermic) 反应类型(放热对吸热)Conservation of Energy (能量守恒)Conservation of Mass and Energy(质能守恒)Scientific Method(科学方法)Measurements and Calculations(测量和计算)Metric System(指标系统)Temperature Measurements(温度测量)Heat Measurements(热量测量)Scientific Notation (科学记数法)Factor-Label Method of Conversion(Dimensional Analysis)转换方法(量纲分析)Precision, Accuracy, and Uncertainty(精密度,准确度,不确定度)Significant Figures(有效数字)Calculations with Significant Figures (有效数字的计算)Atomic Structure and the Periodic Table of the Elements 原子结构&元素周期表Electric Nature of Atoms 原子的电本质History (历史)Basic Electric Charges(基本电荷)Bohr Model of the Atom(原子的波尔模型)Components of Atomic Structure(原子结构构成)Calculating Average Atomic Mass(计算平均原子量)Oxidation Number and Valence(氧化数和化合价)Metallic,Nonmetallic,and Noble Gas Structures(易失电子.易得电子.惰性气体结构)Reactivity(反应)Atomic Spectra 原子光谱Spectroscopy(光谱学)Mass Spectroscopy (质谱学)The Wave-Mechanical Model 波动力学模型Quantum Numbers(量子数)Hund’s Rule of Maximum Multiplicity 最大多重性洪特法则Sublevels and Electron Configuration 原子内电子排布Order of Filing and Notation(电子填充次序和命名)Electron Dot Notation(Lewis Dot Structures)(Lewis 点结构) Noble Gas Notation(稀有气体元素)Transition Elements and Variable Oxidation Numbers(过渡元素和可变的氧化数)Period Table of the Elements元素周期表History(历史)Periodic Law(周期律)The Table(周期表)Properties Related to the Periodic Table(元素周期表的性质) Radii of Atoms(原子半径)Atomic Radii in Periods(同周期的原子半径)Atomic Radii in Groups(同族的'原子半径)Ionic Radius Compared to Atomic Radius(相对原子半径的离子半径)Electro negativity(电负性)Electron Affinity(电子亲和能)Ionization Energy(电离能)Bonding 化学键Types of Bonds 化学键类型Ionic Bonds(离子键)Covalent Bonds(共价键)Metallic Bonds(金属键)Intermolecular Forces of Attraction 分子间的吸引力Dipole-Dipole Attraction (极性分子间的吸引力)London Forces(伦敦力)Hydrogen Bonds(氢键)Double and Triple Bonds(双键和三键)Resonance Structures(共振结构)Molecular Geometry—VSEPR—and Hybridization分子几何学—价层电子对互斥理论和杂化轨道理论VSEPR—Electrostatic Repulsion(VSEPR—价层电子对互斥理论) VSEPR and Unshared Electron (VSEPR和非共享电子对)VSEPR and Molecular Geometry(VSEPR和分子几何学)Hybridization(杂化轨道理论)Sigma and Pi Bonds (Sigma键和Pi键)Properties of Ionic Substances(离子化合物的性质)Properties of Molecular Crystals and Liquids (分子晶体与液晶的性质)Chemical Formulas 化学分子式Writing Formulas (写分子式)General Observations About Oxidation States and FormulaWriting(氧化状态和分子式写作的一般性结论)More About Oxidation Numbers (关于氧化数)Naming Compounds (化合物命名)Chemical Formulas (化学分子式)Laws of Definite Composition and Multiple Proportions (定比定律和倍比定律)Writing and Balancing Simple Equations (写作和平衡简单方程式)Showing Phases in Chemical Equations (化学平衡式)Writing Ionic Equations (书写离子方程式)Gases and the Gas Laws 气体和气体定律Introduction—Gases in the Environment(入门—环境中的气体) Some Representative Gases(一些有代表性的气体)Oxygen(氧气)Hydrogen(氢气)General Characteristics of Gases(气体的基本特征)Measuring the Pressure of a Gas(测量气压)Kinetic Molecular Theory(气体动力论)Some Particular Properties of Gases(气体的特殊性质)Gas Laws and Related Problems(气体定律和相关的难题)Graham’s Law(格锐目定律)Charles’s Law(查理定律)Boyle’s Law(波义耳定律)Combined Gas Law(混合气体定律)Pressure Versus Temperature(气压和温度)Dalton’s Law of Partial Pressures (道尔顿分压定律)Corrections of Pressure(压力校正)Ideal Gas Law(理想气体定律)Ideal Gas Deviations(理想气体偏差)Chemical Calculations(Stoichiometry)and the Mole Concept 化学计算&摩尔内容Solving Problems in Chemistry(解答化学难题)The Mole Concept(摩尔内容)Molar Mass and Moles(摩尔质量和摩尔)Mole Relationships(摩尔关系)Gas Volumes and Molar Mass(气体体积和摩尔质量)Density and molar Mass(密度和摩尔质量)Mass-Volume Relationships(摩尔与体积的关系)Mass-Mass Problems(质量—质量难题)Problems with an Excess of One Reactant(涉及某一反应物多余的难题)Liquids, Solids, and Phase Changes 液体,固体和状态变化Liquids(液体)Importance of Intermolecular Interaction(分子间相互作用的重要性)Kinetics of Liquids(液体动力学)Viscosity(粘性)Surface Tension(表面张力)Capillary Action(毛细作用)Phase Equilibrium(平衡状态)Boiling Point(沸点)Critical Temperature and Pressure(临界温度和临界压力)Solids(固体)Phase Diagrams(状态图表)Water(水)History of Water(水的历史)Purification of Water(水净化)Composition of Water(水的构成)Properties and Uses of Water(水的性质和使用)Water’s Reactions with Anhydrides(水和碱性氧化物的反应) Polarity and Hydrogen Bonding(极性和氢键)Solubility(可溶性)General Rules of Solubility(可溶性的基本原则)Factors That Affect Rate of Solubility(影响溶解率的因素)Summary of Types of Solutes and Relationships of Type to Solubility(溶液类型和类型之间关系的总结)Water Solutions(水处理)Continuum of Water Mixtures(水混合溶剂)Expressions of Concentration(浓度的表达)Dilution(稀释)Colligative Properties of Solutions(溶液的依数性)Crystallization(结晶化)Chemical Reactions and Thermochemistry 化学反应和热化学Types of Reactions(反应类型)Predicting Reactions(预知化学反应)Combination(Known Also as Synthesis(化合反应)Decomposition(Known Also as Analysis(分解反应)Single Replacement(置换反应)Double Replacement(复分解反应)Hydrolysis Reactions(水解反应)Entropy(熵)Thermochemistry(热化学)Changes in Enthalpy(焓变化)Additivity of Reaction Heats and Hess’s Law(反应热加成性定律—赫士定律)Bond Dissociation Energy(键裂解能)Enthalpy from Bond Energies(键能中的键焓)Rates of Chemical Reactions 化学反应速率Measurements of Reaction Rates(反应速率的测量)Factors Affecting Reaction Rates(影响反应速率的因素)Collision Theory of Reaction Rates(化学反应速率的碰撞理论) Activation Energy(激活能)Reaction Rate Law(化学反应速率定律)Reaction Mechanism and Rates of Reaction(化学反应机制和化学反应速率)Chemical Equilibrium化学平衡Reversible Reactions and Equilibrium(可逆反应和平衡)Le Chatelier’s Principle(化学平衡移动原理—勒复特列原理)Effects of Changing Conditions(条件变化的影响)Effect of Changing the Concentrations(浓度改变的影响)Effect of Temperature on Equilibrium(平衡中温度改变的影响) Effect of Pressure on Equilibrium(平衡中压力改变的影响)Equilibrium in Heterogeneous Systems(异构系统中的平衡)Equilibrium Constant for Systems Involving Solids(涉及固体的系统平衡常数)Acid Ionization Constants(酸电离常数)Ionization Constant of Water(水电离常数)Solubility Products(溶解度产物)Common Ion Effect(同离子效应)Driving Forces of Reactions(反应推动力)Relation of Minimum Energy(Enthalpy) to Maximum Disorder(Entropy)(焓—熵关系)Change in Free Energy of a System-the Gibbs Equation(系统中自由能的变化—吉布斯公式)Acids, Bases, and Salts 酸,碱,盐Definitions and Properties(定义和性质)Acids(酸)Bases(碱)Broader Acid-Base Theories(酸—碱理论)Conjugate Acids and Bases(共轭酸碱)Strengh of Conjugate Acids and Bases(共轭酸碱强度)Acid Concentration Expressed as pH(pH表示为酸浓度)Indicators(指示剂)Titration—Volumetric Analysis(滴定—容量分析法)Buffer Solutions(缓冲溶液)Salts(盐)Amphoteric Substances(两性物质)Acid Rain—An Environmental Concern(酸雨—共同关心的环境问题)Oxidation-Reduction and Electrochemistry 氧化—还原反应和电化学Ionization(电离)Oxidation-Reduction and Electrochemistry(氧化---还原反应和电化学)Voltaic Cells(伏打电池)Electrode Potentials(电极电位)Electrolytic Cells(电解池)Applications of Electrochemical Cells(Commercial Voltaic Cells)(电化电池的应用)Quantitative Aspects of Electrolysis(电解现象)Relationship Between Quantity of Electricity and Amount of Products(电量和数量的关系)Balancing Redox Equations Using Oxidation Numbers(用氧化数配平氧化还原方程式)The Ion-Electron Method(离子—电子法)Some Representative Groups and Families 一些有代表性的元素族Sulfur Family(S族)Sulfuric Acid(硫酸)Other Important Compounds of Sulfur(S元素的其他重要化合物)Halogen Family(卤素)Some important Halides and Their Uses(一些重要的卤化物及其应用)Nitrogen Family(氮族) Nitric Acid(硝酸)Other Important Compounds of Nitrogen(N元素的其他重要化合物)Other Members of the Nitrogen Family(N族的其他区成员)Metals(金属)Properties of Metals(金属性质)Some Important Reduction Methods(一些重要的还原方法)Alloys(铝)Metalloids(非金属)Carbon and Organic Chemistry 碳和有机化学Carbon(碳) Forms of Carbon(碳的构成)Carbon Dioxide(二氧化碳)Organic Chemistry(有机化学)Hydrocarbons(碳氢化合物)Alkane Series(Saturated)(烷烃)Alkene Series(Unsaturated) AlkyneSeries(Unsaturated)(炔属烃)Aromatics(芳烃)Isomers(异构体)Changing Hydrocarbons(碳氢化合物的改变)Hydrocarbon Derivatives(碳氢化合物的衍生物)Alcohols—Methanol an Ethanol(酒精—甲醇和乙醇)Other Alcohols(其他酒精)Aldehydes(乙醛)Organic Acids orCarboxylic Acids(有机酸和羧酸)Ketones(酮)Ethers(醚)Amines and Amino Acids(胺和氨基酸)Esters(酯)Carbohydrates(碳水化合物)Monosaccharides and Disaccharides(单糖和二糖)Polysaccharides(多糖) Polymers(聚合体)Nucleonics 原子核物理学Radioactivity(放射热)The Nature of Radioactive Emissions(放射的本质)Methods of Detection of Alpha, Beta, and Gamma Rays(α,β和γ射线)Decay Series, Transmutations, and Half-life(衰变,嬗变和半衰期)Radioactive Dating(放射年代测定法)Nuclear Energy(核能) Conditions for Fission(核裂变条件)Methods of Obtaining Fissionable Material(得到裂变材料的方法Fusion(核聚变) Radiation Exposure(辐射暴露)The Laboratory 实验Technology in the Laboratory(实验室里的技术)Some Basic Setups(一些基本步骤)Summary of Qualitative Tests(定性测试总结) Ⅰ. Identificati on of Some Common Gases(常见气体认证) Ⅱ. Identification of Some Negative Ions(负离子认证) Ⅲ . Identification of Some Positive Ions(正离子认证) Ⅳ .Qualitative Tests of Some Metals(金属的定性测试)。
生物与制药工程专业英语第二单元翻译
Biologists and chemists divide compounds into two principal classes, inorganic and organic. Inorganic compounds are defined as molecules, usually small, that typically lack carbon and in which ionic bonds may play an important role. Inorganic compounds include water, oxygen, carbon dioxide, and many salts, acids, and bases.生物学家和化学家分裂成两个主要种类化合物、无机和有机。
无机化合物被定义为分子,通常小,通常缺乏的碳离子束缚,那么它就能起到重要的作用。
无机化合物包括水、氧气、二氧化碳和许多盐、酸、和根据地。
化碳和许多盐、酸、和根据地。
All living organisms require a wide variety of inorganic compounds for growth, repair, maintenance, and reproduction. Water is one of the most important, as well as one of the rmost abundant, of these compounds, and it is particularly vital to microorganisms. Outside the cell, nutrients are dissolved in water, which facilitates their passage through cell membranes. And inside the cell , water is the medium for most chemical reactions. In fact, water is by far the most abundant component of almost all living cells. Water makes up 5% to 95% or more of each cell, the average being between 65% and 75%. Simply stated, no organism can survive without water 所有生物体需要多种无机化合物的增长、维修、维护、和繁衍。
核能专业英语
第一课词汇:•Concept概念, conception概念, conceive构想、理解•Isotope同位素, isomer同质异能素•element, atom, nucleus, nucleon–element, elements,–molecule, molecules, molecular–atom, atoms, atomic,–nucleus['nju:kliəs,'nu:kliəs]原子核 , nuclei, nuclear,–nucleon['nju:kliɔn]核子, nucleons, nucleonic核子的–particle, particles,•fissile易裂变的, fissionable可以发生裂变的•fertile可裂变的,fertile materials增殖材料•fission, fusion, decay•inner, innermost / outer, outermost•chain reaction•fragment碎片Expression:•times– A is ten times B.•varies inversely as•E equals m times c squared. E = mc2•the n-th power of a: an•result in / result from•is accompanied by / correspond to•The discovery of fission was made in Germany in 1938 by Hahn......•Be composed of 由…组成•Binding energy 结合能•Discrete excited states 不连续的激发态•Electromagnetic radiation 电磁辐射•Ev:electron-volt•Conservation of mass/energy 质量/能量守恒练习:•电子带负电,质子带正电。
药学英语Unit two-text A
15
biological macromolecules.
• The identity of each organism is preserved by its
possession of distinctive sets of nucleic acids and of proteins. • 所有的生命有机体都具有相同种类的单聚体;在 生物大分子的构成上采用基本的模式;每一种生
• enzyme 酶
6
• The molecules of which living organisms are composed conform to all the familiar laws of chemistry. • 组成生命有机体的分子都遵循着熟知的化学规律 • ,but they also interact with each other in accordance with another set of principles, which we shall refer to collectively as the molecular logic of life. • 但是这些分子却按照另一套规律相互作用,就是 我们将提到的生命的分子逻辑学的全部原理
?人类精子和卵子携带着数百万年进化累积的遗传信息以dna分子的形式传递着这些指令在dna分子中共价连接的核苷酸亚单位的线性序列编码着这些遗传信息
Unit Two
Text A Foundation of Biochemistry
1
biochemistry 生物化学
• carbon 碳
• hydrogen 氢
电离辐射效应 英语
电离辐射效应英语The ionizing radiation effect refers to the ability of certain types of radiation to remove tightly bound electrons from atoms, creating ions. This process can lead to a variety of biological and health effects, as well as impact materials and electronics.In terms of health effects, ionizing radiation can cause damage to living tissue, leading to an increased risk of cancer, radiation sickness, and other health issues. The ionization of atoms within the body can disrupt normal cellular function and lead to mutations in DNA, which can contribute to the development of cancer.In addition to health effects, ionizing radiation can also impact materials and electronics. For example, exposure to ionizing radiation can cause degradation of materials, such as plastics and metals, and can lead to the malfunction of electronic components.In summary, the ionizing radiation effect refers to the ability of radiation to create ions by removing tightly bound electrons from atoms. This process can have significant impacts on human health, as well as on materials and electronics. Understanding the effects of ionizing radiation is crucial in fields such as medicine, nuclear energy, and space exploration, where exposure to radiation is a concern.。
化学基础英文31阳离子重排_cationic_rearrangement
However, subsequent discoveries showed that nature was not always so obliging, leaving chemists and chemistry students to grapple with the possibility of deep seated structural change occurring during certain reactions.
Protonation of the double bond gives a 3º-carbocation. An adjacent hydrogen atom (colored blue) shifts as a hydride moiety to create a new 3º-carbocation, which in turn induces the shift of a methyl group (colored green) with formation of yet another 3º-carbocation. This electrophilic center then bonds to the nucleophilic oxygen of the carboxylic acid function, releasing a catalytic proton to continue the process.
初一地球科学探索单选题50题
初一地球科学探索单选题50题1. The outermost layer of the Earth is called the ____.A. mantleB. coreC. crust答案:C。
解析:地球最外层是地壳,地幔在中间,地核在地球的中心,所以这里选地壳。
2. Which part of the Earth is the thickest among the following?A. The oceanic crustB. The continental crustC. The upper mantle答案:B。
解析:大陆地壳比海洋地壳厚,而上地幔的厚度小于大陆地壳的厚度,所以在这几个选项里大陆地壳是最厚的。
3. The Earth's core is mainly made up of ____.A. silicon and oxygenB. iron and nickelC. magnesium and iron答案:B。
解析:地球的地核主要由铁和镍组成。
硅和氧是地壳中含量较多的元素,镁和铁不是地核主要的组成成分。
4. The layer between the crust and the core is the ____.A. lithosphereB. mantleC. asthenosphere答案:B。
解析:位于地壳和地核之间的是地幔。
岩石圈包含地壳和上地幔顶部,软流层是地幔中的一部分。
5. The thickness of the Earth's crust varies from about ____ kilometers.A. 5 - 10B. 5 - 70C. 2900 - 6371答案:B。
解析:地球地壳的厚度大约在5到70千米之间。
5 - 10千米范围过小,2900 - 6371千米这个范围是地幔和地核相关的厚度范围。
6. Which of the following statements about the mantle is correct?A. It is the coldest part of the Earth.B. It is mainly solid but can flow slowly.C. It is as thin as the crust.答案:B。
化学元素英文演讲稿范文
Ladies and gentlemen,Good morning/afternoon/evening. It is my great pleasure to stand before you today to talk about one of the most fascinating and fundamental aspects of our universe: chemical elements. These are the buildingblocks of everything around us, from the air we breathe to the food we eat, and from the planets we orbit to the stars that illuminate ournight sky. In this speech, I will explore the history, significance, and properties of some of the most intriguing elements known to humankind.IntroductionThe concept of chemical elements dates back to ancient times when alchemists and philosophers tried to understand the nature of matter. However, it was not until the 19th century that scientists began to systematically categorize and study these elements. Today, we know of118 chemical elements, each with its own unique properties and characteristics.The Discovery of Chemical ElementsThe journey of discovering chemical elements began with the alchemists, who sought to turn base metals into gold. Over time, they discovered various substances that could not be broken down further, which we now call elements. The first true discovery of an element is often credited to Henry Cavendish, who isolated hydrogen in 1766.The 19th century was a period of great discovery in the field of chemistry. Scientists like John Dalton proposed the atomic theory, which explained that elements are composed of indivisible particles called atoms. The periodic table, created by Dmitri Mendeleev in 1869,organized elements based on their atomic weights and chemical properties, making it easier to study and predict the behavior of elements.The Periodic TableThe periodic table is a masterpiece of organization that has been continuously refined over the years. It is divided into periods (rows) and groups (columns), and each element is represented by a unique symboland atomic number. The table allows us to see patterns and trends in the properties of elements, such as their electronegativity, ionization energy, and atomic radius.Some of the most well-known elements include:- Hydrogen (H): The most abundant element in the universe, hydrogen is the lightest and simplest element, consisting of a single proton and electron.- Oxygen (O): Essential for life, oxygen is a highly reactive element that forms compounds with nearly all other elements.- Carbon (C): The backbone of organic chemistry, carbon can form four bonds, making it versatile and capable of creating a vast array of molecules.- Iron (Fe): A fundamental element in the Earth's crust, iron is used in construction, manufacturing, and as a component of hemoglobin in blood.- Gold (Au): Known for its luster and resistance to corrosion, gold has been valued throughout history and is used in jewelry, electronics, and medicine.Properties of Chemical ElementsChemical elements exhibit a wide range of properties, which can be categorized into physical and chemical properties.- Physical properties include color, density, melting point, boiling point, and conductivity. For example, mercury is a liquid at room temperature, while gold is a solid with a high melting point.- Chemical properties describe how elements interact with other substances. Some elements are highly reactive, like fluorine, which can react with almost any other element, while others are relatively inert, such as noble gases.Significance of Chemical ElementsChemical elements play a crucial role in our lives and the functioning of our planet. Here are some of their key significance:- Life and Medicine: Elements like carbon, hydrogen, oxygen, nitrogen, and phosphorus are the building blocks of organic molecules, which are essential for life. Many medicines and drugs are based on chemical elements.- Technology: Elements like silicon, aluminum, and copper are used in the manufacturing of computers, smartphones, and other electronic devices.- Industry: Iron, steel, and other metals are vital for the construction and manufacturing industries.- Energy: Elements like uranium and plutonium are used in nuclear power generation, while solar panels are made from elements like silicon and gallium.ConclusionIn conclusion, chemical elements are the fundamental units that make up our world. They have shaped the history of science, driven technological advancements, and are essential for life as we know it. As we continue to explore and discover new elements, we gain a deeper understanding of the universe and our place within it. Let us appreciate the marvels of chemical elements and the endless possibilities they hold for the future.Thank you for your attention.。
关于原子物理认识的英语作文
关于原子物理认识的英语作文## Atomic Physics ##。
English Answer:Atomic physics is the study of the atom, which is the basic unit of matter and contains a nucleus of protons and neutrons surrounded by a cloud of electrons. Atomic physics is a branch of physics that studies the structure and properties of atoms, as well as the interactions between atoms and other particles. Atomic physics is the bridge between nuclear physics and molecular physics.Atomic physics is responsible for the development of many important technologies, including the laser, the transistor, and the nuclear reactor. It has also led to the development of new materials, such as semiconductors and superconductors, which have revolutionized the electronics industry.The atom is the basic unit of matter and contains a nucleus of protons and neutrons surrounded by a cloud of electrons. The nucleus is made up of positively charged protons and uncharged neutrons. The electrons are negatively charged and orbit the nucleus in clouds. The number of protons in an atom determines its chemical properties.Atomic physics is the study of the structure and properties of atoms, as well as the interactions between atoms and other particles. Atomic physics is a branch of physics that studies the atom, which is the basic unit of matter and contains a nucleus of protons and neutrons surrounded by a cloud of electrons. Atomic physics is responsible for the development of many important technologies, including the laser, the transistor, and the nuclear reactor. It has also led to the development of new materials, such as semiconductors and superconductors, which have revolutionized the electronics industry.Atomic physicists study the interactions between atoms and other particles, such as photons, electrons, and ions.They also study the properties of atoms, such as their energy levels, ionization energies, and atomic radii.Atomic physics is a fundamental science that has led to the development of many important technologies.Chinese Answer:原子物理学。
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a r X i v :p h y s i c s /0010031v 2 [p h y s i c s .a t o m -p h ] 31 J a n 2001Pathways to double ionization of atoms in strong fieldsKrzysztof Sacha 1,2and Bruno Eckhardt 11Fachbereich Physik,Philipps Universit¨a t Marburg,D-35032Marburg,Germany2Instytut Fizyki im.Mariana Smoluchowskiego,Uniwersytet Jagiello´n ski,ul.Reymonta 4,PL-30-059Krak´o w,Poland(February 2,2008)We discuss the final stages of double ionization of atoms in a strong linearly polarized laser field within a classical model.We propose that all trajectories leading to non-sequential double ionization pass close to a saddle in phase space which we identify and characterize.The saddle lies in a two degree of freedom subspace of symmetrically escaping electrons.The distribution of longitudinal momenta of ions as calculated within the subspace shows the double hump structure observed in experiments.Including a symmetric bending mode of the electrons allows us to reproduce the transverse ion momenta.We discuss also a path to sequential ionization and show that it does not lead to the observed momentum distributions.32.80.Fb,32.80.Rm,05.45.MtI.INTRODUCTIONPresent day lasers are powerful enough to ionize several electrons from an atom.The electrons can be removed one by one in a sequential process or all at once in a non-sequential process.Independent electron models give ion-ization rates that are much smaller than experimentally observed [1],indicating that interactions between elec-trons are important.A series of most recent experiments has added the observation that also the final state of the electrons is dominated by the interactions:the to-tal momentum of the electrons is aligned along the field axis [2–5]and the joint distribution of parallel momenta for the two electrons,in the double ionization experi-ment [5],has pronounced maxima along the diagonal,showing that the electrons typically come with the same momenta.These observations have been reproduced in numerical simulations with varying approximations and simplifying assumptions [6,7].But given the complexity of the analysis that is required the essential elements are difficult to identify.As a step towards a better under-standing we discuss here the pathways to double ioniza-tion within a classical model for electrons in a combined Coulomb and external field.Our aim is not to describe the full ionization process all the way from the ground state to the final,multiply ionized state.According to the currently accepted mod-els [8–13,6,7],the whole process of multiphoton multiple ionization can naturally be divided into two steps:in the first step a compound state of highly excited electrons close to the nucleus is formed and in the second step sev-eral electrons can escape from this compound state to produce the multiply ionized final state.We focus on the last step,the escape of two or more electrons from the highly excited compound state close to the nucleus.The formation of the intermediate compound state is suggested by the rescattering model [8,9]for strong field multiple ionization.According to this model the en-hanced cross section for multiple ionization is due to a rescattering of one electron that is temporarily ionizedand accelerated by the field before it returns to the nu-cleus when the field reverses.During the collision energy is transfered to other electrons,but all of this happens close to the core,where the dynamics of the electrons is fast and the interactions are strong and non-integrable.As a consequence,details of the initial preparation pro-cess are lost.Moreover,the decay of this state is also quick.The compound state is thus a short lived,highly unstable complex that separates the first half of the ex-citation process,whose main contribution is the build up of energy in the complex,from the second half,where the decay mode is determined.The compound state has several decay paths:single ionization when only one electron escapes to infinity,dou-ble or multiple ionization with two or more electrons es-caping to infinity,and the case of a single electron that es-capes from the neighborhood of the nucleus but is rescat-tered to the next field reversal:in the latter case the whole process repeats itself,another compound state is formed and the decay path has to be selected anew.We discuss here the further evolution after the forma-tion of the compound state.To be specific,we will focus on the escape of two electrons in the following,but the arguments can easily be extended to the removal of more than two electrons.The main aim is to identify the chan-nels that lead to double escape and to study their signa-tures in the distribution of electron and ion momenta.Our analysis is purely classical.Given the highly excited complex from which we start and the multiphoton nature of the process this seems a reasonable point of entry to the final stage of the ionization process.Our analysis is very similar to Wanniers approach [14–17]to double ion-ization by electron impact.There main difference is that in the present case one has to take into account also the external field.Brief summaries of some aspects of this model have been presented in [18,19].The pathways to double ionization are discussed in sec-tion 2.The dynamics in the C 2v and C v subspaces in-cluding the effective potential and sample trajectories is discussed in section 3.A key element of our argument is1the identification of a saddle in phase space near which trajectories leading to non-sequential double ionization have to pass;its properties and stability are discussed in section4.The distributions of electron momenta within the C2v and C v subspaces are analyzed in section5.The dynamics outside these symmetry spaces and sequential ionization processes are discussed in section6.We con-clude with a summary of the model in section7.II.PATHW AYS TO DOUBLE IONIZATIONAs described in the introduction we assume an ini-tial state of two highly excited electrons near the nucleus which then decays to either single ionization or double ionization.During this process the linearly polarized laserfield is always on.Therefore,the Hamiltonian con-sists of three parts,H=T+V i+V12(1) the kinetic energy of the electrons,T=p212(2)the potential energies associated with the interaction with the nucleus and thefield(polarized along z-axis),V i=−2|r2|+F(t)z1+F(t)z2(3)and the repulsion between the electrons,V12=12/|F|and has a potential energy(singleelectron)V F=−2atom and,in the adiabatic picture,the other constants of motions allow to do so.In such sequential ionization cor-relations between escaping electrons are strongly weak-ened,that is the final momenta of the electrons along the polarization axis can be either parallel or anti-parallel.III.DYNAMICS IN THE C 2V AND C VSUBSPACESA two electron atom illuminated by a linearly polar-ized electromagnetic wave possesses some symmetry sub-spaces.The simplest C 2v symmetric configuration corre-sponds to both electrons moving in a plane which con-tains the field polarization axis and with positions andmomenta symmetric with respect to this axis.The elec-trons put in such a configuration never leave it because there is no force which can pull them out of the subspace.The symmetry subspace can be enlarged.That is,with additional bending motion of the electrons with respect to the field axis the symmetry subspace is C v .The symmetric configurations become more apparent in suitably chosen coordinates.We apply the canonical transformationR =(ρ1+ρ2)/2,p R =p ρ1+p ρ2r =(ρ1−ρ2)/2,p r =p ρ1−p ρ2Z =(z 1+z 2)/2,p Z =p z 1+p z 2z =(z 1−z 2)/2,p z =p z 1−p z 2,ϕ=ϕ1+ϕ2,L =(p ϕ1+p ϕ2)/2φ=ϕ1−ϕ2,p φ=(p ϕ1−p ϕ2)/2(5)where (ρi ,z i ,ϕi )are cylindrical coordinates of the elec-trons,labeled i =1and 2.For double ionization in lin-early polarized laser field the total angular momentum projection on the polarization axis is conserved.The ex-periments begin with atoms in the ground state,thus,for the field directed along the z -axis we may choose L =0.Then the Hamiltonian of the system readsH =p 2R +p 2r +p 2Z +p 2z2(R +r )2+p 2φ4+p 2φ√RThe further constraintφ=πand pφ=0leads to the C2v symmetry subspacep2R+p2ZH=√2R+2ZF(t).(12)Let us begin with an analysis of the motion in the C2v subspace.The electrons move in a plane and their posi-tions(ρi=R,z i=Z)in that plane and their momenta (pρi=p R/2,p z i=p Z/2)are the same.The adiabatic potential(12)forfixed time correspond-ing to the maximalfield amplitude F=0.137a.u.,i.e. an intensity of6.6·1014W/cm2,is shown in Fig.1a. The saddle is located along the line Z S=r S cosθS and R S=r S sinθS withθS=π/6or5π/6and at a distance√r2S=|F(t)|/√variations.In the full space we expect at least one ad-ditional unstable one,corresponding to the amplification of energy differences mentioned before in section(IIB). The analysis in this section is forfixedfield strength,for electron dynamics in a constant externalfield,justified by the adiabatic reasoning.The second order variations of the potential(7)around the saddle point results inH≈p2R+p2Z2r3S(R−R S)2−3√r3S(R−R S)(Z−Z S)−54+132r3Sz2+p2φ4R S(φ−π)2+V S.(15)Theφ-degree of freedom corresponds to a bending mo-tion of the electrons against each other and is stable on account of the repulsive nature of the Coulomb force. This degree of freedom is also the one that comes in by going from the C2v subspace to the C v subspace. Diagonalization in the(R−R S,Z−Z S)space reveals one stable and one unstable mode.The latter corre-sponds to the reaction coordinate and its Lyapunov expo-nent isµ≈1.21F3/4.Similar analysis in the(r,z)space yields another stable and unstable mode with Lyapunov exponentν≈1.57F3/4.The direction of the unstable mode is(w r,w z)≈(0.43w,w)and it corresponds to the situation when one electron escapes and the other one is turned back to the nucleus.That is,with positive and in-creasing w thefirst electron moves away from the nucleus, i.e.ρ1=R S+w r and z1=Z S+w z grow[see(5)],while the other one returns to the nucleus,i.e.ρ1=R S−w r and z1=Z S−w z decrease.All in all there are three stable modes and two un-stable ones.Any energy contained in the stable modes is preserved and cannot be transferred to kinetic energy along the reaction coordinates.Whether single or dou-ble ionization occurs is thus determined solely by the energy and initial conditions in the two hyperbolic sub-spaces.For energy equal to the saddle energy only a trajectory within the C2v symmetry subspace leads to non-sequential escape–any deviation from the subspace are growing faster than the escape along the reaction coordinate sinceν>µ.For energy higher than the sad-dle some deviations from the symmetry subspace are al-lowed.In particular,following Wanniers lead and Rosts generalization[14–17]it is possible to estimate the crit-ical behavior for the double ionization cross section at threshold.It is algebraic with the exponent given by the ratio of the positive Lyapunov exponents of the unstable modes.A detailed discussion of this is outside the main line of our arguments here and will be given elsewhere. It is instructive to actually calculate numbers for the Lyapunov exponents in the two directions.For laserswith the maximalfield strength of F=0.137a.u.we find1/µ=3.7a.u.and1/ν=pared to the period of the laser,2π/ω=110.2a.u.this is rather fast, indicating that the crossing of the saddle and the separa-tion away from the double ionization manifold take place rather quickly.This justifies also our adiabatic analysis in this section.V.FINAL STATE MOMENTA DISTRIBUTION WITHIN THE SYMMETRIC SUBSPACESSo far we have discussed the phase space features in an adiabatic approximation forfixedfield strengths.Now we will use this to draw conclusions about the experi-mentally observed signatures,specifically about the dis-tributions of ion momenta in thefinal state.They can be calculated within the C v subspace by averaging over all initial conditions and all phases of thefield.That this is possible is connected with the instability of the saddle: all trajectories leading to the non-sequential ionization have to pass sufficiently close to the saddle and the sym-metric subspace.It therefore is possible to estimate the behaviour near the subspace from the dynamics within the subspace.A.Parameters of the modelThe rescattering of an electron leads to a highly excited complex of total energy E which is one of the parame-ters of our model.The maximal energy a rescattering electron can bring in has been estimated to be about3.17U p[8,9],where U p is the ponderomotive energy of anelectron.For the weakestfield used in the experiment on double ionization of He atoms[2]this maximal en-ergy barely corresponds to the ionization energy of the He1+ions.We therefore assume in the following that the highly excited complex has a negative initial energy, E<0.The absence of detailed knowledge of the structure of the initial compound nucleus suggests to average over the initial configurations.However,even for a negative en-ergy andfixed time it is difficult to define a microcanon-ical distribution of initial conditions for the Hamiltonian(9)since,for non-zero externalfield,the system is open.Therefore,we choose for the calculations initial condi-tions from the energy shell that also lie in the hypersur-face Z=0.The results are not sensitive to a particular choice of the hypersurface but the one for Z=0has the advantage that the dipole moment along thefiled is zero and the choice of the initial conditions does not depend on the initialfield phase.The second parameter,in addition to the energy,is the time t0during the pulse Eq.(8)when the highly excited complex is formed.The rescattering event is not possible 5at the beginning of the pulse,so one has to start simula-tions somewhere in the middle of the pulse.In Fig.3and 4final distributions of ion momenta for the initial energy E =−0.1a.u.,field strength F =0.137a.u.and dif-ferent initial time t 0are shown.The distributions of the transverse momenta are almost the same but the ones for the parallel momenta differ.The latter reveal a double hump structure with widths sensitive to the initial time.p par (a.u.)0.00.10.2p r o b a b i l i t y d e n s i t y0.00.10.20.3p trans (a.u.)0.00.50.00.51.0FIG.3.Final distributions of ion momenta parallel,p par and transverse,p trans to the field polarization axis for the ini-tial energy E =−0.1a.u.,peak field amplitude F =0.137a.u.and pulse duration T d =20×2π/ω.Panels (a)-(b)cor-respond to the initial time t 0=0.25T d in the pulse dura-tion with the envelop f (t )=sin 2(πt/T d )while panels (c)-(d)to t 0=0.75T d .Dashed lines are related to the estimates ±2F f (t 0)/ω=±2.4a.u..Note that the distributions are es-sentially the same independently if one chooses t 0before or after the peak field value provided f (t 0)is the same.The results are based on integrations of about 8·104trajectories.p par (a.u.)0.00.1p r o b a b i l i t y d e n s i t y0.00.10.2p trans (a.u.)0.00.50.00.51.0FIG.4.The same as in Fig.3but for t 0=0.4T d [panels (a)-(b)]and t 0=0.6T d [panels (c)-(d)].The width of the parallel momentum distribution can be estimated as ±2F f (t 0)/ω=±4.3a.u..The maximum energy that can be acquired by a free electron in the field is 2U p .So,for parallel emission of two electrons,the maximal parallel ion momentum can be estimated asp par =2electrons cross the saddle the interaction with the elec-tric field is stronger than the attraction to the nucleus and the distribution is mostly shaped by the laser field.The initial energy of the complex is the higher the higher intensity of the laser is andthe larger the energy a rescattered electron can bring in [8,9].From the depen-dence of the distributions on the initial energy we may conclude that in the experiment the shape of the distri-bution of the parallel ion momenta should change char-acter when the laser intensity increases.For the intensity at the threshold for non-sequential double ionization the distribution with single maximum around zero momen-tum is expected;for higher intensities the double hump structure should turn up.All numerical results have been obtained for initial con-ditions taken from the C v symmetry subspace.Our re-sults for the C 2v subspace for parallel momentum dis-tributions are essentially the same.The transverse mo-menta of ions for the C 2v subspace are,however,zero because of the symmetry assumption.After this discussion of the two parameters (initial en-ergy and starting time of the integration)we can turn to comparisons with experimental observations.parison with experimental resultsWeber et al.[2]carried out double ionization exper-iments with He atoms and measured the distributions of ion momenta.They applied infrared (800nm)laser pulses of the duration 220fs (measured on the half peak value)and with the peak intensities in the range (2.9−6.6)×1014W/cm 2.In Fig.6and 7we show the experimental distributions and compare with those cal-culated in the C v subspace.The agreement is very good except for the parallel momentum distribution in Fig.7where the calculated distribution possesses a much more pronounced minimum than in the experiment and the positions of the peaks do not exactly coincide with the experimental values.There are a few possible sources for these discrepan-cies.First,the pulse duration in the experiment was quite long,i.e.about 80field cycles.The slow ramp-ing of the field in the experiment implies that the initial time t 0of the ionization is less well defined,i.e.there are contributions from some range of t 0.There are also con-tributions from different initial energies.Secondly,real ionizing trajectories do not live exactly in the symmetry subspace but close to it,leading to asymmetries and ad-ditional differences in the final momenta.And there are also possible contributions from sequential double ioniza-tion events (see below).Moshammer et al.[4]performed experiments with Ne atoms for much shorter pulses,i.e.30fs and for radiation with similar wave length (795nm)as the previous group.The comparison of our calculations with this experiment are presented in Fig.8.Interactions of the two excitedelectrons with the other electrons are neglected in our model and the energy values used in the calculations are measured with respect to the threshold for the two elec-tron continuum (i.e.about 2.3a.u.).The agreement is even better than for the case of He atoms.This is pre-sumably due to the much shorter pulse duration and the fasted ramping of the field,so that the time t 0when the majority of the ionization events happen is much better defined.p par (a.u.)0.00.10.20.3p r o b a b i l i t y d e n s i t y0.00.10.20.3p trans (a.u.)0.00.50.00.51.0FIG.6.Panels (a)-(b):final ion momentum distributions measured in the experiment of double ionization of He atoms in the focus of 800nm,220fs (i.e.about 80×2π/ω)laser pulses at peak intensity of 2.9×1014W/cm 2(i.e.for the field strength F =0.091a.u.)from [2].Panels (c)-(d):the cor-responding distributions calculated in the C v symmetry sub-space for the initial energy E =−0.6a.u.and t 0=0.33T d where T d /2=80×2π/ω,see Eq.8.p par (a.u.)0.00.1p r o b a b i l i t y d e n s i t y0.00.10.2p trans (a.u.)0.00.40.00.40.8FIG.7.Panels (a)-(b):the same as in the corresponding panels in Fig.6but for the peak intensity of 6.6×1014W/cm 2(i.e.for the field strength F =0.137a.u.).Panels (c)-(d):the same as in the corresponding panels in Fig.6but for the initial energy E =−0.4a.u..7p par (a.u.)0.000.09p r o b a b i l i t y d e n s i t y0.000.070.14p trans (a.u.)0.00.40.00.20.4FIG.8.Panels (a)-(b):final ion momentum distributions measured in the experiment of double ionization of Ne atoms in the focus of 795nm,30fs (i.e.about 11×2π/ω)laser pulses at peak intensity of 13×1014W/cm 2(i.e.for the field strength F =0.192a.u.)from [4].Panels (c)-(d):the corresponding distributions calculated in the C v symmetry subspace for the initial energy E =−0.3a.u.and t 0=0.4T d where T d /2=11×2π/ω,see Eq.8.VI.SEQUENTIAL DOUBLE IONIZATIONAlready from the experiment it is clear that double ionization is a rare process,e.g.outnumbered by single ionization by about 104:1for He atoms and field inten-sity 2.9·1014W/cm 2[2].Hence arbitrarily chosen ini-tial conditions in the full space will typically not lead to double ionization and numerical simulations of the whole process are rather unattainable.We have discussed the non-sequential double escape of the electrons considering trajectories within the sym-metry subspace.Motion in the symmetry subspace is unstable,that is deviations from the subspace will be amplified leading to single rather than double ionization.We can illustrate this with trajectories started slightly outside the symmetry plane (Fig.9).Fig 9a shows ini-tial conditions on the saddle and symmetrically escaping electrons.For some deviation from symmetry,one elec-tron escapes,the other remains trapped to the nucleus (Fig.9b).It is possible,however,that the second electron returns to the nucleus but picks up enough energy to ionize itself (Fig.9c).In the adiabatic picture,if the energy of the remaining electron is higher than the saddle for a sin-gle electron atom,V F =−2estimate the distribution of thefinal ion momenta if the sequential process were dominant.To simulate sequen-tial escape one may return to a non-interacting electron model,essentially since the electrons cross the barrier at different times.In the model the initial conditions for each electron are chosen independently,constrained only by the requirement that the total initial energy isfixed E=E1+E2and that E1<0and E2<0.Simulta-neous double ionization are not explicitly excluded,but events with delayed ionization are more probable,so that the distributions can still reflect the contributions from sequential ionization.In Fig.10the distributions of parallel ion momenta for E=−0.8a.u.and E=−0.1a.u.,calculated in the non-interacting electrons model for F=0.137a.u,are plotted.Thefigure should be compared with thefigures from the previous section.The conclusion is straightfor-ward:the non-interacting electrons model is not able to reproduce correlations between the electrons observed in the experiments.Moreover,sequential escape can not be a dominant mechanism for double ionization in the range of thefield intensities considered here.VII.CONCLUSIONSWe have considered the process of double ionization of atoms in a strong,linearly polarizedfield for inten-sities below the saturation of single electron ionization. We have developed a model for non-sequential double ionization within classical mechanics.The process has been divided into two stages:in thefirst one a rescat-tering process leads to a highly excited complex of two electrons.In the second stage,an ionization of such com-pound state takes place.We have focused on the latter stage considering different pathways to double escape of the electrons.The excited complex can doubly ionize even when its energy is negative because the externalfield opens up saddles for electron escape.The pathway favored by the Coulomb interactions and thefield is simultaneous symmetric escape of both electrons.Deviations form the symmetric configurations are amplified by the repulsion between the electrons which pulls one electron to infinity but the other one is pushed back to the nucleus.There-fore we propose that non-sequential double ionization is dominated by motions of electrons in or near the sym-metric subspace with the saddle.The requirement of the symmetric motion greatly sim-plifies the analysis which then can be carried out for the three-or even two-dimensional effective potential.The trajectory simulations within the symmetric configura-tions turns out to reproduce the experimentally observed ion momenta distributions very well.We have also con-sidered an alternative mechanism of the ionization,i.e. sequential escape of the electrons.By means of the non-interacting electrons model we show that the sequential ionization is not able to explain the experimentally ob-served electrons correlations.The modeling of the experimental distributions re-quires information on two parameters,the initial energy and the time of formation,which reflect a lack of knowl-edge on the compound state and the ramping of thefield. The dependence of the momentum distributions on the parameters and comparison with the experimental results give insights into the dynamics of double ionization. The analysis in the present paper has been restricted to double ionization but its extension to multiple escape is straightforward[19].In its current form the model is applicable for linearly polarizedfields only.For other polarizations the number of rescattering events is greatly reduced.However,for some elliptically polarizedfield, if an electron is driven back to the core and a highly excited complex is formed,in the adiabatic approxima-tion the symmetric configuration of the electrons can be defined with respect to the temporary electricfield axis. Then one can proceed with the analysis as for the linearly polarized case.Our whole discussion has a more than superficial sim-ilarity with Wanniers analysis of double ionization by electron impact[14–16].The main differences are the presence of afield and its time dependence,which en-larges phase space and complicates the identification of the transition state.In the adiabatic approximation at fixedfield strength we could identify this saddle in the C2v subspace.The comparison with experiments is com-plicated furthermore by the necessity to average over initial energy and time of preparation of the compound state.Thus,signatures one might attribute to Wanniers analysis,such as threshold exponents(they follow imme-diately from the stability analysis of the saddle,but are not easy to verify),will be even more difficult to study. 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