双语题目
大学英语作文题目大全
大学英语作文题目大全1. The Impact of Social Media on College Students社交媒体对大学生的影响2. The Role of Technology in Modern Education技术在现代教育中的作用3. The Importance of Environmental Conservation环境保护的重要性4. Challenges and Opportunities of Online Learning在线学习的挑战与机遇5. The Influence of Pop Culture on Youth流行文化对青少年的影响6. The Ethics of Genetic Engineering基因工程的伦理问题7. The Benefits of Bilingualism双语的好处8. The Future of Renewable Energy Sources可再生能源的未来9. The Effects of Globalization on Local Cultures全球化对本土文化的影响10. The Role of Public Libraries in the Digital Age数字时代公共图书馆的作用11. The Importance of Physical Fitness in Daily Life日常健身的重要性12. The Impact of Artificial Intelligence on Employment人工智能对就业的影响13. The Role of Volunteering in Community Development志愿服务在社区发展中的作用14. The Challenges of Balancing Work and Personal Life平衡工作与个人生活的挑战15. The Significance of Cultural Exchange Programs文化交流项目的意义16. The Effects of Climate Change on Biodiversity气候变化对生物多样性的影响17. The Importance of Financial Literacy for College Students大学生金融素养的重要性18. The Impact of Urbanization on Rural Communities城市化对农村社区的影响19. The Role of Art in Society艺术在社会中的角色20. The Ethics of Animal Testing in Scientific Research科学研究中动物实验的伦理问题21. The Benefits of Studying Abroad出国留学的好处22. The Impact of E-commerce on Traditional Retail电子商务对传统零售业的影响23. The Role of Education in Achieving Gender Equality教育在实现性别平等方面的作用24. The Importance of Mental Health Awareness心理健康意识的重要性25. The Challenges of Immigration Policy移民政策的挑战这些题目覆盖了社会、文化、科技、环境、教育等多个领域,适合不同水平的大学生进行深入探讨和写作。
学生双语报高一29期B版答案
学生双语报高一29期B版答案第一篇:学生双语报高一29期B版答案第29期B1版Keys:(One possible version)词语保鲜一、1.get through2.get down to3.get away with4.get along with二、1.in great need of2.in favor of3.in celebration of4.in memory of词语狙击单词大练兵一、1.awarded2.permission3.forgivebine5.apologize6.admire7.celebration8.drowned9.customs 10.harvest11.religious12.belief 13.raw二、1.seasonal 2.worldwide3.independent4.energetic5.obvious6.balanced7.limited8.agricultural 9.slim10.fool词组训练场一、1.in memory of2.play tricks on3.as though4.earned her living5.day and night6.dress up7.look forward to8.tells lies 9.in debt 10.turned up二、1.is admired for2.must apologize to you for3.consult your lawyer4.benefit from5.remind me to call back第29期B2版Keys:阅读训练营 1-4 ACBA 5-8 ADCC 新题型聚焦 1-5 ECBAF第29期B3版Keys:(One possible version,客观题除外)语法小测一、1-5 ACBBD 6-8 DBC二、1.Shall 2.needn’t 3.must 4.may 5.should6.can7.would8.mustn’t9.mustn’t10.shall 句型巡航1.looks as though2.have you speaking to your mother3.It was obvious that4.I saw you reading a newspaper5.Does it mean 01第二篇:双语报高三版学生错题集锦双语报高三版学生错题集锦(原创)此题为天涯的好友提供,均为计算机阅卷显示正答率较低的题目,也是高三学生比较容易出错的题目。
双语物理题目
1. A particle moves along the x axis. Its position as a function of time is given by x=6.0t+8.5t2, where t is inseconds and x is in meters. What is the acceleration as a function of time?Solution:We find the velocity and acceleration by differentiating x = (6.0 m/s)t + (8.5 m/s2)t2:v = d x/d t = (6.0 m/s) + (17 m/s2)t; a = d v/d t = 17 m/s2.2.A car traveling at 95km/h strikes a tree.The front end of the car compresses and the driver comes to rest aftertraveling 0.80m.What was the average acceleration of the driver during the collision?Solution:We find the average acceleration fromunknown.(b) The average acceleration isa av = ∆v/∆t = [(27.5 m/s)i– (– 18.0 m/s)j]/(8.00 s) = (3.44 m/s2)i + (2.25 m/s2)k.The magnitude is∣ a av∣ = [(3.44 m/s2)2 + (2.25 m/s2)2]1/2 = 4.11 m/s2.We find the direction fromtan θ = (2.25 m/s2)/(3.44 m/s2) = 0.654, which gives θ = 33.2° north of east.4.A ball is thrown horizontally from the roof of a building 9.0m tall and lands 8.5m from the base.v2 = v02 + 2a(x2–x1);0 = [(95 km/h)/(3.6 km/h)]2 + 2a(0.80 m), which gives a = – 4.4 ⨯ 102 m/s2.3.A car is moving with speed 18.0m/s due south at one moment and 27.5m/s due east 8.00s later. Over this timeinterval, determine (a)its average velocity,(b)its average acceleration(magnitude and direction for both),Solution:(a) Because we do not know the displacement over the given time interval, the average velocity isWhat was the ball’s initial speed?Solution:We choose a coordinate system with the origin at the release point,with x horizontal and y vertical, with the positive direction down.y= y0+ v0y t+ 1/2a y t2; 9.0 m= 0 + 0+ 1/2(9.80 m/s2)t2, whichgives t = 1.35 s.The horizontal motion will have constant velocity.We find the initial speed fromx = x0 + v0x t; 8.5 m = 0 + v0(1.35 s), which gives v0 = 6.3 m/s.5.What is the centripetal acceleration of a child 3.6m from the center of amerry-go-round?The child’s speed is 0.85m/s.Solution:The centripetal acceleration i sa R = v2/r = (0.85 m/s)2/(3.6 m) = 0.20 m/s2 ,direction: toward the center.6.Calculate the centripetal acceleration of the Earth in its orbit around the Sun.Assume the Earth’s orbit is a circleof radius 1.5×1011m.Solution:The centripetal acceleration of the Earth isa R= v2/r= (2πr/T)2/r= 4π2r/T2= 4π2(1.5 ⨯ 1011m)/(3.16 ⨯ 107 s)2= 5.9 ⨯ 10–3m/s2direction:toward the Sun.7.Huck Finn walks at a speed of 1.0m/s across his raft(that is,he walks perpendicular to the raft’s motion relative tothe shore).The raft is traveling down the Mississipppi River at a speed of 2.5m/s relative to the river bank.What isthe velocity(speed and direction)of Hack relative to the river bank? Solution:If v HR is the velocity of Huck with respect to the raft, v HB the velocity of Huckwith respect to the bank, and v RB the velocity of the raft with respect to the bank, then HB = v HR + v RB , as shown in the diagram. From the diagram we get v HB = (v HR 2 + v RB 2)1/2 = [(1.0 m/s)2 + (2.5 m/s)2]1/2 = 2.7 m/s . We find the angle fromtan θ = v HR /v RB = (1.0 m/s)/(2.5 m/s) = 0.40, which gives θ = 22° from the river bank .8.A boat can travel 2.20m/s in still water.(a)If the boat point its prow directly across a stream whose current is 1.2m/s,what is the velocity(magnitude and direction) of the boat relative to the shore?(b)What will be the position of the boat,relative to its point of origin,after 3.00s? Solution:(a ) If v BS is the velocity of the boat with respect to the shore,v BW the velocity of the boat with respect to the water, and v WS the velocity of the water with respect to the shore, then v BS = v BW + v WS , as shown in the diagram. From the diagram we get v BS = (v BW 2 + v WS 2)1/2 = [(2.20 m/s)2 + (1.20 m/s)2]1/2 = 2.51 m/s . We find the angle from tan θ = v BW /v WS = (2.20 m/s)/(1.20 m/s) = 1.83, which givesθ = 61.4° from the shore .(b ) Because the boat will move with constant velocity, the displacement will bed = v BS t = (2.51 m/s)(3.00 s) = 7.52 m at 61.4° to the shore .9.A 7.5kg bucket is lowered by a rope in which there is 63.0N of tension. What is the accelection of the bucket?Is it up or down? Solution:We write ∑F = m a from the force diagram for the bucket: y -component: F T – mg = ma ;63.0 N – (7.50 kg)(9.80 m/s 2) = (7.50 kg)a ,which gives a = – 1.40 m/s 2 (down).10.The two masses are each initially 1.8m above the ground,and the massless frictionless pulley is fixed 4.8m above the ground.What maximum height does the lighter object reach after the system is released?[Hint:First determine the acceleration of the lighter mass and then its velocity at the pulley.] Solution:Forces are drawn for each of the blocks. Because the string doesn’t stretch, the tension is the same at each end ofthe string, and the accelerations of the blocks have the same magnitude. Note that we take the positive direction in the direction of the acceleration for each block.We write ∑F = m a from the force diagram for each block: y -component (block 1): F T – m 1g = m 1a ;y -component (block 2): m 2g – F T = m 2a .By adding the equations, we find the acceleration:a = (m 2 – m 1)g /(m 1 + m 2)RBH RW Sv BWg+ y= (3.2 kg – 2.2 kg)(9.80 m/s 2)/(3.2 kg + 2.2 kg)= 1.81 m/s 2 for both blocks.For the motion of block 1 we take the origin at the ground and up positive. When block 2 hits the ground, we have v 12 = v 012 + 2a (y 1 – y 01) = 0 + 2(1.81 m/s 2) (3.60 m – 1.80 m), which givesv 1 = 2.56 m/s.Once block 2 hits the ground, F T → 0 and block 1 will have the downward acceleration of g .For this motion of block 1 up to the highest point reached, we have v 2 = v 12 + 2a (h – y 1)0 = (2.56 m/s)2 + 2(– 9.80 m/s 2) (h – 3.60 m), which gives h = 3.93m .11.The resistance of a packing material to a sharp object penetrating it is a force proportional to the fourth power of the penetration depth,x:F=kx 4i.Calculate the work done to force the sharp object a distance d. Solution:The resisting force opposes the penetration. If we assume no acceleration, the applied force must be equal to this inthe direction of the penetration. For a variable force, we find the work by integration:W =F ·ds =kx 4d x 0d =kx55d =kd 55. 12.The position of a 280-g object is given (in meters) by x=5.0t 3-8.0t 2-30t,where t is in seconds. Determine the net rate of work done on this object (a)at t=2.0s and (b) at t=4.0s.(c) What is the average net power input during the interval from t=0s to t=2.0s,and in the interval from t=2.0s to 4.0s? Solution:Because the rate of work is P = Fv and the applied force produces the acceleration, we find the velocity andacceleration as a function of time: x = (5.0 m/s 3)t 3 – (8.0 m/s 2)t 2 – (30 m/s)t ;v = d x /dt = (15.0 m/s 3)t 2 – (16.0 m/s 2)t – (30 m/s); a = d v /dt = (30.0 m/s 3)t – (16.0 m/s 2).Thus the rate of work is P = Fv = mav = m [(30.0 m/s 3)t – (16.0 m/s 2)][(15.0 m/s 3)t 2 – (16.0 m/s 2)t – (30 m/s)].(a ) At t = 2.0 s, we haveP = (0.280 kg )[(30.0 m/s 3)(2.0 s) – (16.0 m/s 2)][(15.0 m/s 3)(2.0 s)2 – (16.0 m/s 2)(2.0 s) – (30 m/s)]= – 25 W.Note that the negative sign means there are times when the applied force is opposite to the motion.(b ) At t = 4.0 s, we have P = (0.280 kg)[(30.0 m/s 3)(4.0 s) – (16.0 m/s 2)][(15.0 m/s 3)(4.0 s)2 – (16.0 m/s 2)(4.0 s) – (30 m/s)]= + 4.3 ⨯ 103 W .(c ) Over a time interval, the average net power produces the change in kinetic energy:P = W /∆t = ∆K /∆t = (1/2mv f 2 – 1/2mv i 2)/ ∆t = 1/2m (v f 2 – v i 2)/ ∆t . We find the velocities at the three times: v 0 = (15.0 m/s 3)(0)2 – (16.0 m/s 2)(0) – (30 m/s) = – 30 m/s; v 2 = (15.0 m/s 3)(2.0 s)2 – (16.0 m/s 2)(2.0 s) – (30 m/s) = – 2.0 m/s; v 4 = (15.0 m/s 3)(4.0 s)2 – (16.0 m/s 2)(4.0 s) – (30 m/s) = 146 m/s.From t = 0 to t = 2.0 s, we haveP = 1/2(0.280 kg)[(– 2.0 m/s)2 – (– 30 m/s)2]/(2.0 s – 0) = – 63 W .From t = 2.0 s to t = 4.0 s, we haveP = 1/2(0.280 kg)[(146 m/s)2 – (– 2.0 m/s)2]/(4.0 s – 2.0 s) = + 1.5 ⨯ 103 W .13.A ball of mass 0.540kg moving east (+x direction) with a speed of 3.9m/s collides head-on with a 0.320-kg ball at rest.If the collision is perfectly elastic,what be the speed and direction of each ball after the collision? Solution:For the elastic collision of the two balls, we use momentum conservation for this one-dimensional motion: m 1v 1 + m 2v 2 = m 1v 1' + m 2v 2';(0.540 kg)(3.90 m/s) + (0.320 kg)(0) = (0.540 kg)v 1' + (0.320 kg)v 2'. Because the collision is elastic, the relative speed does not change: v 1 – v 2 = – (v 1' – v 2'), or 3.90 m/s – 0 = v 2' – v 1'. Combining these two equations, we getv 1' = 0.998 m/s , and v 2' = 4.89 m/s .14.An 18-g rifle bullet traveling 180m/s buries itself in a 3.6-kg pendulum hanging on a 2.8-m-long string, which makes the pendulum swing upward in an arc. Determine the horizontal component of the pendulum ’s displacement. Solution:We let V be the speed of the block and bullet immediately after the collision and before the pendulum swings. For this perfectly inelastic collision, we use momentum conservation: mv + 0 = (M + m )V ;(0.018 kg)(180 m/s) = (0.018 kg + 3.6 kg)V ,which gives V = 0.896 m/s.Because the tension does no work, we can use energy conservation for the swing: 1/2(M + m )V 2 = (M + m )gh , or V 2 = 2gh ;(0.896 m/s)2 = 2(9.80 m/s 2)h , which gives h = 0.0409 m. We find the horizontal displacement from the triangle:L 2 = (L – h )2 + x 2;(2.8 m)2 = (2.8 m – 0.0409 m)2 + x 2, which gives x = 0.48 m .15.Calculate the moment of inertia of the array of point objects shown in the follows about(a) the vertical axis,and (b) the horizontal axis.Assume the objects are connected by very light rigid wires.About which axis would it be harder to accelerate this array?m=1.8kg and M=3.1kg.The array is rectangular and it is split through the middle by the horizontal axis. Solution:(a ) For the moment of inertia about the y -axis, we have I a = ∑m i R i 2 = md 12 + Md 12 + m (d 2 – d 1)2 + M (d 2 – d 1)2 = (1.8 kg)(0.50 m)2 + (3.1 kg)(0.50 m)2 +(1.8 kg)(1.00 m)2 + (3.1 kg)(1.00 m)2 = 6.1 kg · m 2.(b ) For the moment of inertia about the x -axis, all the massesare the same distance from the axis, so we haveI b = ∑m i R i 2 = (2m + 2M )(1/2h )2= [2(1.8 kg) + 2(3.1 kg)](0.25 m)2 = 0.61 kg · m 2.It will be harder to accelerate the array around the y -axis, because the moment of inertia is greaterMm +Mxy16.Derive the formula for the moment of inertia of a uniform thin rod of length l about an axis through itscenter,perpendicular to the rod. Solution:We select a differential element of the rod of length d x a distance x from the center of the rod. The element is equivalent to a point mass with a mass of d m = (M /l) d x .We integrate from x = – l/2 to x = l/2 to find the moment of inertia of the rod:/22223/23/2/22|()33212l l l l M M M l Ml I x dm x dx x ll l --=====⎰⎰17.A person of mass 55kg stands at the center of a rotating merry-go-round platform of radius 2.5m and moment ofinertia 6702kg m ⋅.The platform rotates without friction with an angular velocity of 2.0 rad/s.The personwalks radially to the edge of the platform.(a)Calculate the angular velocity when the person reaches the edge.(b)Compare the rotational kinetic energies of the system of platform plus person before and after the person ’s work.Solution: (a ) By walking to the edge, the moment of inertia of the person changes. Because the system ofperson and platform is isolated, angular momentum will be conserved: L = (I platform + I person1)ω1 = (I platform + I person2)ω2 ;[670 kg · m 2 + (55 kg)(0)2](2.0 rad/s) = [670 kg · m 2 + (55 kg)(2.5 m)2]ω2 , which givesω2 = 1.3 rad/s .(b ) For the kinetic energies, we have K 1 = 1/2(I platform + I person1)ω12 = 1/2(670 kg · m 2 + 0)(2.0 rad/s)2 = 1.34 ⨯ 103 J ;K 2 = 1/2(I platform + I person2)ω22 = 1/2[670 kg · m 2 + (55 kg)(2.5 m)2](1.32 rad/s)2 =8.8 ⨯ 102 J .Thus there is a loss of 4.6 ⨯ 102 J, a decrease of 34%.18.A thin uniform stick of mass M and length l is positioned vertically,with its tip on a frictionless table.It isreleased and allowed to slip and fall.Determine the speed of its center of mass just before it hits the table. Solution:Because there is no friction, the center of mass must fall straight down. The vertical velocity of the right end of the stick must always be zero. If ω is the angular velocity of the stick just before it hits the table, the velocity of the right end with respect to the center of mass will beω(l/2) up. Thus we haveω(l/2) – v CM = 0, or ω = 2v CM /l.The kinetic energy will be the translational energy of the center of mass and the rotational energy about the center of mass. With the reference level for potential energy at the ground, we use energy conservation to find the speed of the center of mass just before the stick hits the ground: K i + U i = K f + U f ;0 +1/2 Mgl = 1/2Mv CM 2 + 1/2(M l 2/12)ω2 + 0;1/2Mg l= 1/2Mv CM 2 + 1/2(M l 2/12)(2v CM /l)2 = 1/2(4Mv CM 2/3), which gives v CM = (3g l/4)1/2 . 19.Anelectronhasaninitialvelocity6021.510/v m s=⨯i.It enters a region where4(2.08.0)10/E i j N C =+⨯.(a)Determine the vector acceleration of the elecron as a function oftime.(b)How much time will elapse before it returns to its starting point? Solution:(a ) We find the acceleration produced by the electric field: q E = m a ;(– 1.60 ⨯ 10–19 C)[(2.0 ⨯ 104 N/C) i + (8.0 ⨯ 104 N/C) j ] = (9.11 ⨯ 10–31 kg)a , which gives a = – (3.5 ⨯ 1015 m/s 2) i – (1.41 ⨯ 1016 m/s 2) j . Because the field is constant, the acceleration is constant. (b ) We find the velocity fromv = v 0 + a t = (8.0 ⨯ 104 m/s) i + [– (3.5 ⨯ 1015 m/s 2) i – (1.41 ⨯ 1016 m/s 2) j ](1.0 ⨯ 10–9 s)= (– 3.43 ⨯ 106 m/s) i – (1.41 ⨯ 107 m/s) j .The direction of the electron is the direction of its velocity:tan θ = v y /v x = (– 1.41 ⨯ 107 m/s) /(– 3.43 ⨯ 106 m/s) = 4.11, or θ = – 104°.20.Two point charges,1 6.7Q C μ=- and2 1.3Q C μ=,are located between two oppositely chargedparallel plates,as followns.The two point charges are separated by a distance of x=0.34m.Assume that the electric field produced by the charged plates is unifrom and equal to 73,000/E N C =.Calculate the net electrostaticforce on 1Q and give its direction.Solution:We find the electric field at the location of Q 1 due to the plates and Q 2. For the field of Q 2 we have E 2 = kQ 2/x 2 = (9.0 ⨯ 109 N · m 2/C 2)(1.3 ⨯ 10–6 C)/(0.34 m)2= 1.01 ⨯ 105 N/C (left).The field from the plates is to the right, so we haveE net= E plates – E 2= 73,000 N/C – 1.01 ⨯ 105 N/C = – 2.8 ⨯ 104 N/C (left). For the force on Q 1 , we haveF 1 = Q 1E net = (– 6.7 ⨯ 10–6 C)(– 2.8 ⨯ 104 N/C) = + 0.19 N (right).21.A very long solid nonconducting cylinder of radius 0R and length L(0R L ≤) possesses a uniform volumecharge density 3(/)E C m ρ.Determine the electric field at points(a)outside the cylinder (0r R >) and (b) insidethe cylinder(0r R <).Do only for points far from the ends and for which r L ≤.Solution:From the symmetry of the charge distribution, for points far from the ends and not too far from the shell, we know that the electric field must be radial, away from the axis of thecylinder, with a magnitude independent of the direction.For a Gaussian surface we choose a cylinder of length l and radius r , centered on the axis. On the ends of this surface, the electric field is not constant but E and d A are perpendicular, so we have E · d A = 0. On the curved side, the field has a constant magnitude and E and d A are parallel, so we have E · d A = E d A .(a ) For the region where r > R 0 , the charge inside the Gaussian surface is Q = ρE πR 02l.For Gauss’s law we have0/enclosedendssideE dA E dA E dA QA Φ⋅=⋅+⋅=⎰⎰0 + E 2πr l= ρE πR 02l/Å0 , or E = ρE R 02/2Å0r ; r > R 0 .(b ) For the region where r < R 0 , the charge inside the Gaussian surface is Q = ρE πr 2l, so we have0/enclosedendssideE dA E dA E dA QA Φ⋅=⋅+⋅=⎰⎰0 + E 2πr l= ρE πr 2l/Å0 , or E = ρE r /2Å0; r < R 0 .22.Dry air will break down and generate a spark if the electric field exceeds about6310/N C ⨯.How muchcharge could be packed onto a green pea(diameter 0.75cm)before the pea spontaneously discharges? Solution:For a charged spherical surface, the radial electric field just outside the surface is E = σ/Å0 = Q /4πÅ0r 2;3 ⨯ 106 N/C = Q /4π(8.85 ⨯ 10–12 C 2/N · m 2)(0.375 ⨯ 10–2 m)2, which gives Q = 5 ⨯ 10–9 C = 5 nC . 23.A charge Q creates an electric potential of +125V at a distance of 15cm.What is Q? Solution:We find the charge from V = Q /4πÅ0r ;125 V = (9.0 ⨯ 109 N · m 2/C 2)Q /(15 ⨯ 10–2 m), which gives Q = 2.1 ⨯ 10–9 C = 2.1 nC .24.Two different dielectrics each fill half the space between the plates of a parallel-plate capacitor.Determine a formula for the capacitance in terms of 1K ,2K ,the area A of the plates,and the separation d.Solution:The potential difference must be the same on each half of the capacitor, so we can treat the system as two capacitors in parallel: C = C 1 + C 2 = [K 1Å0(1/2A )/d ] + [K 2Å0(1/2A )/d ] = (Å01/2A /d )(K 1 + K 2) = 1/2(K 1 + K 2)(Å0A /d )= Å0A (K 1 + K 2)/2d .25.Two different dielectrics fill the space between the plates of a parallel-plate capacitor .Determine a formula forthe capacitance in terms of 1K ,2K ,the area A,of the plates,and the separation 12/2d d d ==.Solution:If we think of a layer of equal and opposite charges on the interface between the two dielectrics, we see that they are in series. For the equivalent capacitance, we have 1/C = (1/C 1) + (1/C 2) = (1/2d /K 1Å0A ) + (1/2d /K 2Å0A ) = (d /2Å0A )[(1/K 1) + (1/K 2)]= (d /2Å0A )[(K 1 + K 2)/K 1K 2],which gives C = 2Å0AK 1K 2/d (K 1 + K 2).26.A proton moving with speed52.010/v m s =⨯ in a field-free fegion abruptly enters an essentiallyuniform magnetic field B=0.850T.If the proton enters the magnetic field region at a 45 angle.(a) at whatangle does it leave and (b)at what distance x does it exit from the field? Solution:(a ) Because the velocity is perpendicular to the magnetic field, the proton will travel in a circular arc. From the symmetry of the motion we see that the upper half is a mirror image of the lower half, so the exit angle is the same as the incident angle: 45°. (b ) The magnetic force provides the radial acceleration,so we have F = evB = mv 2/r , sor = mv /eB = (1.67 ⨯ 10–27 kg)(2.0 ⨯ 105 m/s)/(1.60 ⨯ 10–19 C)(0.850 T)= 2.46 ⨯ 10–3 m.Thus the distance x isx==3.5 ⨯ 10–3 m .27.Let two long parallel wires,a distance d apart,carry equal currents I in the same direction.One wire is at x=0,theother at x=d.Determine B between the wires as a function of x. Solution:Because the currents are in the same direction, between the wires the fields will be in opposite directions. For the net field we have B = B 1 – B 2 = [(μ0/4π)2I 1/x ]j – [(μ0/4π)2I 2/(d – x )]j = (μ0/4π)2I {[(d – x ) – x ]/x (d – x )}j= [(μ0/4π)2I (d – 2x )/x (d – x )]j .28. Let two long parallel wires,a distance d apart,carry equal currents I in the different direction.One wire is at x=0,the other at x=d.Determine B between the wires as a function of x. Solution:Because the currents are in opposite directions, between the wires the fields will be in the same direction. With I 1 = 2I 2 , for the net field we have B = B 1 + B 2 = – [(μ0/4π)2I 1/x ]j – [(μ0/4π)2I 2/(d – x )]j = – (μ0/4π)2I {[2(d – x ) + x ]/x (d – x )}j= – [(μ0/4π)2I (2d – x )/x (d – x )]j.dxxy29.The magnetic field perpendicular to a single 15.6-cm-diameter circular loop of copper wire decreases uniformly from 0.550T to zero.If the wire is 2.05mm in diameter,how much charge moves through the coil during this operation?Solution:For the resistance of the loop, we haveR = ρL/A = ρπD/(πd2 = 4ρD/d2.The induced emf iså = –∆ΦB/∆t = –(πD2∆B/∆t;so the induced current isI = å/R = – (πDd2/16ρ) ∆B/∆t.In the time ∆t the amount of charge that will pass a point isQ = I∆t= – (πDd2/16ρ) ∆B = – [π(0.156 m)(2.05 ⨯ 10–3 m)2/16(1.68 ⨯ 10–8Ω · m)](0 – 0.550 T) =4.21 C.30.How much energy is stored in a 400-mH inductor at an instant when the current is 9.0A?Solution:For the energy stored in the inductor we haveU = 1/2LI 2 = 1/2(0.400 H)(9.0 A)2 = 16 J.。
双语学习报21至22x版45期答案
双语学习报21至22x版45期答案Social practice has been more and more popular in sc hools. Senior school students are asked to get involved in the community and get some ideas of it.Surely, social practice does good to senior school s tudents in many ways. Firstly, social practice can offer students a chance to get in touch with society and deal with different kinds of people. In this way students ca n gain some precious social experience, which will be of great use to their future career. Secondly, students ca n apply what they have learned in class to practical wor k. Thus, it enables students to get to know themselves m ore clearly. Thirdly, social practice can bring them som e financial reward and make them more independent of the ir family.However, some problems may arise if no correct guida nce is made. For example, some students get overly inter ested in social practice and want to work full-time and earn more money. Consequently, they will neglect their s tudies. At the same time, through social practice, somestudents are likely to get in touch with the dark side o f society, which will affect their future values.【写作内容】1. 以约30个词概括上文的主要内容。
初中英语互译真题答案解析
初中英语互译真题答案解析互译是学习外语的重要环节之一,它帮助学生更好地理解和运用英语语言。
在初中阶段,学生们经常会接触到一些互译练习题。
在这篇文章中,我们将会对一些初中英语互译真题进行答案解析,帮助学生们更好地掌握这一技巧。
第一题:翻译句子“我在写一份日记。
”正确答案解析:The correct translation of the sentence is "I am writing a diary." 这句话中,关键词"write"需要变为现在进行时形式"writing",同时"diary"翻译为"日记"。
第二题:翻译句子“你家离学校有多远?”正确答案解析:The correct translation of the sentence is "How far is your house from school?" 这句话中,关键词"离"需要翻译为"from",而"有多远"则应翻译为"How far"。
第三题:翻译句子“他在做作业。
”正确答案解析:The correct translation of the sentence is "He is doing his homework." 在这个句子中,"作业"翻译为"homework",而"做"则需要翻译为"doing"。
第四题:翻译句子“My father likes playing basketball.”正确答案解析:The correct translation of the sentence is "我爸爸喜欢打篮球。
" 在这个句子中,"playing basketball"翻译为"打篮球",而"likes"需要改为"喜欢"来符合中文的表达习惯。
男孩和钉子的英语的题目
男孩和钉子的英语的题目题目:男孩和钉子(The Boy and the Nail)用法:这个题目可以用于提问或者描述一个男孩与钉子之间的关系或故事情节。
通常在故事中,男孩会与钉子发生互动,例如:拿起、敲打、拔出或者绕开等。
双语例句:1. The boy picked up the nail from the ground.男孩从地上捡起了钉子。
2. He held the nail tightly in his hand.他紧紧地握住了钉子。
3. The boy accidentally stepped on the nail and got hurt.男孩不小心踩到了钉子,受伤了。
4. He carefully inspected the nail before using it.他仔细检查了一下钉子,然后开始使用。
5. The boy used the nail to hang up a picture on the wall.男孩用钉子把一幅画挂在了墙上。
6. He tapped the nail lightly with a hammer.他轻轻地用锤子敲打了钉子。
7. The boy's father showed him how to pull out a nail.男孩的父亲给他示范如何拔出钉子。
8. He skillfully removed the nail from the wooden board.他熟练地从木板上拔下了钉子。
9. The boy accidentally hit his thumb with the hammer instead of the nail.男孩不小心用锤子砸到了大拇指,而不是钉子。
10. He carefully placed the nail in a box to keep it organized.他小心地把钉子放进盒子里,保持整齐。
精选雅思阅读考试题及答案解析
精选雅思阅读考试题及答案解析1. 题目:The Benefits of Bilingualism阅读理解:双语的好处解析:本文主要介绍了双语对个人和社会的好处。
首先,双语人士更容易找到工作,因为他们可以胜任双语工作岗位。
其次,双语人士在跨文化交流中更加得心应手,能够更好地理解不同文化之间的差异。
此外,双语人士在认知能力方面也具有优势,他们更善于处理信息和解决问题。
因此,研究第二语言对个人和社会发展都是有益的。
2. 题目:The Importance of Sleep阅读理解:睡眠的重要性解析:本文主要介绍了睡眠对身体和大脑的重要性。
睡眠对身体恢复和健康至关重要。
不良的睡眠惯可能导致多种健康问题,如肥胖、心脏疾病和免疫系统功能下降。
此外,睡眠对大脑功能也有重要影响。
充足的睡眠可以提高记忆力、注意力和创造力。
因此,为了保持身体和大脑的健康,我们应该重视睡眠。
3. 题目:The Impact of Social Media阅读理解:社交媒体的影响解析:本文主要探讨了社交媒体对个人和社会的影响。
社交媒体的普及改变了人们的沟通方式,使得信息传播更加迅速和广泛。
然而,社交媒体也带来了一些负面影响。
首先,过度使用社交媒体可能导致沉迷和时间浪费,影响个人的研究和工作。
其次,社交媒体也可能导致隐私泄露和网络欺凌等问题。
因此,人们需要理性使用社交媒体,注意维护个人信息安全和网络礼仪。
4. 题目:The Benefits of Exercise阅读理解:锻炼的好处解析:本文介绍了锻炼对身体和心理健康的好处。
锻炼可以帮助人们保持健康的体重、增强心肺功能和提高肌肉力量。
此外,锻炼还能改善心理健康,减少焦虑和抑郁症状,增强自信心和幸福感。
因此,每个人都应该定期进行适量的锻炼,以提高身体素质和生活质量。
5. 题目:The Impact of Climate Change阅读理解:气候变化的影响解析:本文主要讨论了气候变化对地球的影响。
双语TED阅读笔记S01第2集 贫穷的本质
TED题⽬:Poverty isn't a lack of character; it's a lack of cash作者: Rutger Bregman贫穷的本质I'd like to start with a simple question: Why do the poor make so many poor decisions? I know it's a harsh question, but take a look at the data. The poor borrow more, save less, smoke more, exercise less, drink more and eat less healthfully. Why?Well, the standard explanation was once summed up by the British Prime Minister, Margaret Thatcher. And she called poverty "a personality defect."A lack of character, basically.让我们从⼀个简单的问题开始: 为什么穷⼈总是做出不好的决策? 我知道这是⼀个残酷的问题, 但是让我们看看数据。
穷⼈借钱越多,积蓄越少, 抽烟越多,锻炼越少,喝酒越多, 饮⾷越不健康。
为什么呢?标准的解释 是由英国⾸相Margaret Thatcher总结的。
她将贫穷称为“⼀种⼈格缺陷”简⽽⾔之,就是缺少⼀种品格。
Now, I'm sure not many of you would be so blunt. But the idea that there's something wrong with the poor themselves is not restricted to Mrs. Thatcher. Some of you may believe that the poor should be held responsible for their own mistakes. And others may argue that we should help them to make better decisions. But the underlying assumption is the same: there's something wrong with them. If we could just change them, if we could just teach them how to live their lives, if they would only listen. And to be honest, this was what I thought for a long time. It was only a few years ago that I discovered that everything I thought I knew about poverty was wrong.我知道你们⼤部分⼈不会这么直接。
WCDMA海外工作面试题目_中英双语
WCDMA项目面试问题1. 项目经验介绍(注重时间段)Tell me something about your WCDMA projects (pay attention to the period)2. XXX项目主要都是做些什么,你负责哪些工作?What are you responsible for in XXX project?3. 是否做过数据分析?数据分析都分析哪些指标?关注哪些参数?Have you ever done data analyszing? And what KPI we should pay attention to?4. 有没有做过天线调整?都做些什么?Have you ever done antenna tuning? And what to do?机械下倾角、电子下倾角、方位角调整E-Tilt tuning/M-Tilt tuning/Azimuth tuning天线接反调整Tuning of Antenna wrongly connected5. 勘站时需注意什么事项?勘站需要勘察什么数据?What would you pay attention to when doing site survey? And why do site survey?安全第一Safty must come first工具列表1) Longitude、Latitude——GPS2) Tilt(倾斜角)——倾角仪3) Antenna Height(天线高度)——GPS4) Azimuth(方位角)——指南针5) Picture(每30度角一个照片)反映基站周边情况——数码相机6) Antenna type6. 都用过哪些测试软件、优化软件?What testing and optimization tools have you used?TI 9.1RASony Ericsson Z750(MS)ScannerTVTCPU7. WCDMA如何定义为导频污染?How to define pilot pollution in WCDMA netwrok?WCDMA是个自干扰系统,但是过度的干扰也会带来诸多负面效应,导频污染就是其中最明显的一个。
好的英语作文题目
好的英语作文题目1. "The Impact of Social Media on Modern Communication"社交媒体对现代交流的影响2. "The Role of Technology in Education: Boon or Bane?"技术在教育中的角色:福音还是祸根?3. "Exploring the Benefits of Bilingualism"探索双语的好处4. "The Challenges of Environmental Conservation"环境保护的挑战5. "The Power of Positive Thinking"积极思考的力量6. "The Influence of Cultural Diversity in the Workplace"文化多样性在工作场所的影响7. "The Importance of Time Management"时间管理的重要性8. "The Evolution of E-Commerce and Its Impact on Traditional Retail"电子商务的演变及其对传统零售业的影响9. "The Role of Art in Society"艺术在社会中的角色10. "The Impact of Globalization on Local Cultures"全球化对本土文化的影响11. "The Ethics of Artificial Intelligence"人工智能的伦理问题12. "The Significance of Physical Fitness in Daily Life"日常健身的重要性13. "The Effects of Fast Fashion on the Environment"快时尚对环境的影响14. "The Role of Public Transport in Urban Planning"公共交通在城市规划中的角色15. "The Importance of Mental Health Awareness"心理健康意识的重要性16. "The Challenges of Achieving Work-Life Balance"实现工作与生活平衡的挑战17. "The Impact of Climate Change on Agriculture"气候变化对农业的影响18. "The Role of Volunteering in Community Development"志愿工作在社区发展中的作用19. "The Influence of Advertising on Consumer Behavior"广告对消费者行为的影响20. "The Importance of Lifelong Learning"终身学习的重要性这些作文题目覆盖了社会、文化、科技、环境等多个领域,旨在激发学生的思考和讨论,同时也能够提高他们的英语写作能力。
平和双语考试题目
平和双语考试题目
以下是一些可能出现在平和双语考试中的题目:
1. 你的家乡有什么特色?
2. 描述一下你的假期计划。
3. 你的朋友是怎样的一个人?
4. 你认为生活在城市还是农村更好?为什么?
5. 你最喜欢的电影是什么?为什么?
6. 你最喜欢的运动是什么?为什么?
7. 如果你成为一位明星,你想成为什么样的明星?为什么?
8. 你最喜欢的科目是什么?为什么?
9. 你有没有参加过志愿者活动?描述一下你的经历。
10. 你希望未来能做什么工作?为什么?
这些题目旨在考察学生的表达能力和思维逻辑,并且要求学生用双语进行回答。
考试的难度会根据年级和学生水平的不同而有所调整。
管理信息系统 作业题目及答案(双语)
1. Which four reasons do make IT a difference to the success of a business? Explain them simply. IT对于企业的成功有哪4个方面的原因,简单说说。
There are four reasons why IT makes a difference to the success of a business:1) Capital management 资产管理a) IT is the largest single component of capital investment in the United States.b) About $1.8 trillion is spent each year by American businesses.c) Managers and business students need to know how to invest this capital wisely.d) The success of your business in the future may well depend on how you makeIT investment decisions.2) Foundation of doing business 业务流程建设a) Most businesses today could not operate without extensive use of informationsystems and technologies.b) IT can increase market share.c) IT can help a business become a high-quality, low-cost producer.d) IT is vital to the development of new products.3) Productivity 生产力a) IT is one of the most important tools managers have to increase productivityand efficiency of businesses.b) According to the Federal Reserve Bank, IT has reduced the rate of inflation by0.5 to 1% in the last decade. For firms this means IT is a major factor inreducing costs.c) It is estimated that IT has increased productivity in the economy by about 1% inthe last decade. For firms this means IT is a major source of labor and capitalefficiency.4) Strategic opportunity and advantage 战略机会和优势a) Create competitive advantage: IT makes it possible to develop competitiveadvantages.b) New Business Models: Dell Computer has built its competitive advantage on anIT enabled build-to-order business model that other firms have not been able toimitate.c) Create new services: eBay has developed the largest auction trading platformfor millions of individuals and businesses. Competitors have not been able toimitate its success.d) Differentiate yourself from your competitors: Amazon has become the largestbook retailer in the United States on the strength of its huge online inventoryand recommender system. It has no rivals in size and scope.2. What are three dimensions of the IS? Explain them simply. 信息管理的3个维度是什么,请简单说说。
英语议论作文题目
英语议论作文题目1. "The Impact of Social Media on Modern Communication"- 探讨社交媒体对现代交流方式的影响,包括它如何改变人们的社交习惯和沟通技巧。
2. "The Role of Technology in Education: Boon or Bane?"- 分析技术在教育中的作用,讨论它带来的积极和消极影响。
3. "Globalization and Its Effects on Local Cultures"- 讨论全球化如何影响各地文化,包括文化同质化的问题。
4. "The Importance of Environmental Conservation"- 阐述环境保护的重要性,探讨个人和政府可以采取的措施。
5. "The Influence of Celebrity Culture on Society"- 分析名人文化对社会价值观和年轻人的影响。
6. "The Ethics of Genetic Engineering"- 探讨基因工程的伦理问题,包括对人类社会和自然环境的潜在影响。
7. "The Challenges of Achieving Gender Equality"- 讨论实现性别平等面临的挑战,以及如何克服这些障碍。
8. "The Future of Work in the Age of Automation"- 预测自动化时代工作的未来,讨论它对就业市场和个人职业发展的影响。
9. "The Significance of Bilingual Education"- 论述双语教育的重要性,以及它如何促进认知发展和跨文化交流。
10. "The Impact of Fast Fashion on the Environment and Society"- 探讨快时尚对环境和社会的影响,包括消费主义和可持续发展的问题。
贵州民汉双语考试题目
贵州民汉双语考试题目样卷一一、请用本民族语言依次朗读下列词汇(20分)1、爸爸2、奶奶3、姐姐4、伯父5、星星6、月亮7、晴天8、下雨9、云 10、椅子二、请用本民族语言依次朗读下列句子(40分)1、不怕山高,只怕脚软。
2、你从哪里来?要到哪里去?3、这位是我的母亲,她今年有六十九岁了。
4、到时间了,我们回去吧!5、我吃饱了,你们慢慢吃。
三、请用本民族语言朗读下列短文(40分)老师的话老师经常给我们说,你们要认真读书,认真写字,不懂就问,这样才能学到书本上的知识。
至今,我没有忘记老师说的这些话。
一、请用本民族语言依次朗读下列词汇(20分)1、叔叔2、阿姨3、上4、下5、水6、斧头7、镰刀8、筷子9、碗 10、床二、请用本民族语言依次朗读下列句子(40分)1、鸟三顾而后飞,人三思而后行。
2、喝酒两边醉,打架两边伤。
3、明天是赶场天,你要去赶场吗?4、哥,等会吃完饭,我们去河边散步吧!5、今年我高考考得好,大家都为我高兴。
三、请用本民族语言朗读下列短文(40分)我的朋友我的朋友是一个可爱的女生,她的天真是我们快乐的起源,她的快乐带给了我们笑容。
她的名字叫李明,她的眼睛大大的,嘴巴像樱桃,可爱极了,头发长长的,她擅长跳绳,跑步,跳远,等等……一、请用本民族语言依次朗读下列词汇(20分)1.发烧2.胡子3.喉咙4.聋子5. 推6.坟墓7.小孩8. 老人9. 膝盖 10.骂二、请用本民族语言依次朗读下列句子(40分)1、我舅舅家的房子很宽敞。
2、大家都喜欢从这边走。
3、天色突然暗下来了。
4、他每天都是这时候才回家。
5、你知道他什么时候走的吗?三、请用本民族语言朗读下列短文(40分)石井我们村有一口石井。
水井不大,四四方方,全村的人都吃这口井的水。
听老人们说,这口井已经有几百年了。
不知道是谁心好,把水井边的杂草清除得干干净净,天刚亮的时候,人们去井边打水,你来我往,有说有笑,天天如此。
往年考题词汇、句子、短文一、词汇1.脚趾2.牛3.拉4.女人5.写字6.说话7.舌头8.火9.喝 10.拍手 11.裤子 12.七十 13.下去 14.桥 15.天亮 16. 青菜17.瓜 18.拿 19.四十 20.舅妈 21.天黑22.绿色 23.婆婆 24.妻子 25.牙齿 26.一百 27.天亮 28.中午 29.半夜 30.老师 31.肉 32.石头 33.云 34.伯母 35. 洗衣服36.跑 37.睡觉 38.杀鸡 39.吃药 40.找 41. 厨师 42.夫妻 43.放学 44.簸箕45.舅舅 46.名字 47.干活 48.扁担49.哭 50.种菜 51.腐烂 52.绳子 53.女孩54.姑姑 55.拉56.叔父 57.踩 58.哥哥 59.犁田 60.赶场二、句子1.奶奶坐在门前和他聊天。
amc8 中英文双语 试题
amc8 中英文双语试题AMC8 中英文双语试题中文部分:1. 题目:一个正方形的面积是40平方厘米,它的边长是多少厘米?答案:5厘米2. 题目:一个圆的半径是6厘米,它的面积是多少平方厘米?答案:平方厘米3. 题目:一个长方形的长是8厘米,宽是6厘米,它的周长是多少厘米?答案:28厘米4. 题目:一个三角形的底是10厘米,高是6厘米,它的面积是多少平方厘米?答案:30平方厘米5. 题目:一个平行四边形的底是12厘米,高是8厘米,它的面积是多少平方厘米?答案:96平方厘米英文部分:1. Q: If a square has an area of 40 square centimeters, what is the length of its sides?A: The side length is 5 centimeters.2. Q: If a circle has a radius of 6 centimeters, what is its area?A: The area is square centimeters.3. Q: If a rectangle has a length of 8 centimeters and a width of 6 centimeters, what is its perimeter?A: The perimeter is 28 centimeters.4. Q: If a triangle has a base of 10 centimeters and a height of 6 centimeters, what is its area?A: The area is 30 square centimeters.5. Q: If a parallelogram has a base of 12 centimeters and a height of 8 centimeters, what is its area?A: The area is 96 square centimeters.。
给我换个英文作文题目
给我换个英文作文题目英文,The Importance of Learning a Second Language。
Learning a second language is a valuable skill that can open up a world of opportunities. As a bilingual individual, I have experienced firsthand the many benefits of beingable to communicate in more than one language. Not onlydoes it enhance my personal and professional life, but it also allows me to connect with people from differentcultures and backgrounds.One of the main advantages of being bilingual is the ability to communicate with a wider range of people. For example, when I travel to a foreign country, I can easily converse with locals and immerse myself in the local culture. This not only enriches my travel experience, but also helps me gain a deeper understanding of the customsand traditions of the place I am visiting.In addition, being bilingual has also opened up manycareer opportunities for me. For instance, I once had the opportunity to work as a translator for a multinational company. My language skills allowed me to bridge the gap between the company and its international clients, and Iwas able to facilitate smooth communication and buildstrong relationships with them. This experience not only boosted my professional reputation, but also gave me asense of fulfillment in knowing that I was able to make a meaningful contribution to the company.Furthermore, learning a second language has also improved my cognitive abilities. Studies have shown that bilingual individuals have better problem-solving skillsand are more adept at multitasking. For example, I findthat I am able to switch between languages effortlessly,and this has trained my brain to be more flexible and adaptable in various situations.中文,学习第二语言的重要性。
请帮忙取个作文题目英文
请帮忙取个作文题目英文英文,A Tale of Two Languages。
Growing up in a bilingual household, I have always been fascinated by the differences and similarities between English and Chinese. Both languages have their own unique features and complexities, and I have had the privilege of experiencing both firsthand.One of the most noticeable differences between the two languages is the writing system. While English uses the Latin alphabet, Chinese characters are a completely different ballgame. Memorizing thousands of characters can be daunting, but it also allows for a deeper understanding of the language and culture.Another difference is the grammar structure. English follows a subject-verb-object pattern, while Chinese follows a subject-object-verb pattern. This can lead to confusion when translating between the two languages, butit also allows for more flexibility in expression.Despite these differences, there are also many similarities between the two languages. For example, both English and Chinese have idioms and expressions that are unique to their respective cultures. Learning these can provide insight into the values and beliefs of the people who speak the language.In my experience, being bilingual has been a great advantage. It has allowed me to communicate with a wider range of people and has given me a deeper understanding of both cultures. It has also given me the ability to switch between languages seamlessly, depending on the situation.中文,两种语言的故事。
the benefits of being bilingual 题目
the benefits of being bilingual 题目1. The Cognitive Advantages of Bilingualism双语的认知优势2. How Bilingualism Enhances Professional Opportunities双语如何增加职业机会3. The Role of Bilingualism in Promoting Cultural Understanding双语在促进文化理解中的作用4. Bilingualism and Delayed Onset of Dementia双语和延迟痴呆症的发病5. The Impact of Bilingualism on Memory and Recall双语对记忆和回忆的影响6. Bilingualism as a Pathway to Improved Problem-Solving Abilities双语作为提高解决问题能力的途径7. The Benefits of Bilingualism for Personal Development双语对个人发展的好处8. Bilingualism and Increased Global Connectivity双语和增强的全球连通性9. The Influence of Bilingualism on Academic Performance双语对学术表现的影响10. Bilingualism: A Bridge to Diverse Social Interactions双语:通往多元社交互动的桥梁These topics can be developed into essays, research papers, or discussion points exploring the various ways in which being bilingual can benefit individuals in multiple aspects of their lives.。
大学生作文题目英文版
大学生作文题目英文版英文:As a college student, I often find myself facing various writing prompts in my classes. One of the most challenging tasks for me is to write an essay in both English and Chinese. It requires me to switch between two different languages and express my thoughts and ideas in a coherent and logical manner. Despite the difficulties, I have come to realize the benefits of being bilingual and the importance of being able to communicate effectively in both languages.One of the advantages of being able to write in both English and Chinese is the ability to reach a wider audience. For example, if I write an essay in English, I can easily connect with people who speak English as their first language. On the other hand, if I write in Chinese, I can communicate with a different group of people who are more comfortable reading and understanding Chinese. Thisnot only allows me to share my ideas with a diverse range of readers but also helps me to improve my language skills in both English and Chinese.Another benefit of writing in two languages is the opportunity to explore different cultural perspectives. For instance, when I write about a certain topic in English, I may approach it from a Western point of view. However, when I translate the same essay into Chinese, I may need to consider the cultural nuances and values of the Chinese-speaking audience. This process not only broadens my understanding of different cultures but also enhances my ability to empathize with people from diverse backgrounds.中文:作为一名大学生,我常常在课堂上面对各种写作题目。
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2011-2012学年第一学期高三年级双语班期中模拟考试题卷(备注:选择题答案和作文内容均写在答题卷上)(考试时间;120分钟)第一部分阅读理解(13题,13分)1~4题一个猎人与朋友到草原上打野兔。
1 ,猎人突然发现远处的地平线在冒烟,很快地和朋友就听到噼啪噼啪的声音,他意识到自己2了草原野火。
火势在3,火迅速地向他们身边推近,速度非常快,根本来不及逃脱。
猎人马上从口袋里掏出火柴,把两人周围的干草和灌木点着。
于是,他们就站在一块光秃秃的被烧焦的地上了。
大伙迫近了,他们用毛巾捂住嘴,紧紧抱在一起。
随后,火从四周一掠而过,他们却毫发无损——3烈火燃烧过的地方不必再惧怕火。
[1]文中1 处应该填写的词语是:A.之间B.期间C.其间D.瞬间[2]文中2 处应该填写的词语是:A.遭遇B.遇困C.碰见D.遭受[3]文中3 处应该填写的词语是:A.蜿蜒B.延长C.蔓延D.延伸[4]文中4处应该填写的词语是:A.竟然B.因为C.因而D.并且5~7题是金子总会发光。
5被一时的阴云遮挡了光芒,但只要抱定一种6刻苦、勇于创新的精神和献身人类的高度责任感、使命感,那么,7有一天会被放射出璀璨的光芒。
[5]文中5 处应该填写的词语是:A.既然B.只要C.哪怕D.只有[6]文中5 处应该填写的词语是:A.勤奋B.勤劳C.勤快D.勤恳[7]文中7 处应该填写的词语是:A.究竟B.竟然C.到底D.终究8~10题朋友,你到过天山吗?天山是我国西北边疆的一条大山脉,8几千里,横亘塔里木盆地和准格尔盆地之间,把9的新疆分为南北两半。
远望天山,10多姿,那常年积雪、高插云霄的群峰,像集体起舞是的维吾尔族少女的珠冠,银光闪闪;那富有色彩的连绵不断的山峦,像孔雀开屏,艳丽迷人。
[8]文中8处应该填写的词语是:A.连续B.延续C.连绵D.绵绵[9]文中9处应该填写的词语是:A.广阔B.宽阔C.广大D.宽大[10]文中10处应该填写的词语是:A.漂亮B.美丽C.好看D.美观11~13题近日,教育部组织百名一流(11)专家学者进行了“中国教育与人力12问题研究”重大课题研究,课题报告首次前瞻性地提出我国未来50年,特别是近20年中国教育与人力资源开发的13构想和重大政策举措。
[11]文中11处应该填写的词语是:A.同一类B.第一等C.一群D.一派[12]文中12处应该填写的词语是:A.资料B.资产C.资源D.资金[13]文中13处应该填写的词语是:A.战略B.战术C.战争D.政策第二部分阅读理解(20题,40分)14题去年,在沈阳召开的一次全国医药产品订货会上,一些制药厂为了吸引客户,竟展出用压力锅等包装的产品样品,有的干脆把毛毯等“陪嫁”物摆在样品旁边。
还有一家制药厂在推销产品时提出,凡订购本厂一箱药的,厂方就当场给他100元钱。
这种做法果然“有效”仅三天时间,这个长积压的100多万元药品被代表抢购一空。
沈阳第一制药厂有20多种主要产品均获省、市优质产品奖,产品质好价优。
由于推销产品没有“嫁妆”或“嫁妆”少,在订货会上经常收到冷遇。
[14]这段话主要介绍了哪方面的情况?A.为什么要举办订货会B.订货会上的怪现象C.订货会上的名牌产品D.订货会举办的时间和地点15题一年一度的北美国际汽车展1月16日在被誉为世界汽车之都的美国底特律拉开了帷幕。
近50加汽车厂商参加了这次展览,共为观众展出了700多俩款式各异的汽车。
北美国际汽车展是世界上历史最长、规模最大的汽车展之一,创始于1907年,为世界各国车迷所关注,今年的车展更是吸引了近70万参观者。
通用、奔驰和丰田等世界著名的汽车公司在内的汽车厂商纷纷推出了设计新颖、技术先进、兼具豪华和休闲特点的生产型汽车以及代表了高科技发展方向的概念车。
这些概念车不仅集科技与智慧于一身,而且为车车发烧友们预示了汽车未来的发展趋势,因此成为了本届车展的最大亮点。
[15]从这段话中我们可以知道:A.北美国际汽车展在世界上历史最长、规模最大B.今年的车展吸引了70多万参观者C.北美国际汽车展被誉为世界汽车之都D.北美国际汽车展每年举行一次16~17题昨晚在首都剧场的舞台上再次上演了“这里的黎明静悄悄”这部前苏联著名现实主义剧作。
这次的重排对剧本做了几处变动,前半段中敌机空袭的场面被删掉,大段落的台词被精简压缩,最大的改动在后半部分,五个女兵相继牺牲后闪回的处理手法被尽量区分,这样就避免了雷同,这次改动和变化是一次比较大胆的尝试,将近三个小时的戏压缩到2个小时15分钟左右。
改动后的戏保留了原有的现实主义风格而不失美感,这部戏的美是从一开始就存在着的,美在薄雾笼罩下的白桦林,没在白桦林中那群活泼可爱的姑娘......上半场的悠闲、从容和其中爆发的阵阵枪炮声蕴藏着下半场的杀机,真正的戏剧开始在姑娘们开始死去的时候,她们的美丽消失在白桦林中,白桦林因为她们而更美丽。
[16]关于该剧的改动,从本文可知:A.后半部分更有美感B.五个女兵在空袭中牺牲C.改动前为3个多小时D.台词比原剧缩短了[17]这部剧作短文中没有告诉我们的是:A.故事发生在白桦林中B.有战斗的剧情C.是第二次在首都剧场上演D.具有现实主义风格18~19题余光中面海低语:“在台北时办公室也靠海,不过是靠着台湾东海岸,我看着太平洋有什么意思,看美国有什么意思。
现在我凭窗而立,便可直视18西面,尽管身在台湾,我可以眺望对面的香港,可以一生守望着我的大陆。
”[18]余光中说话是脸朝着:A.南边B.西边C.东边D.北边[19]余光中先生要表达的心情是:A.满意现在的工作B.怀念大陆的故乡C.观看大海没意思D.讨厌台北的住宅20题一个人从中学到大学,在一定程度上可以说是真正迈入了复杂的社会,开始学习如何面对竞争,如何在社会上找准自己的位置,如何去实现自我全面发展。
这时关键要对大学环境完全不同于过去有清醒的认识,同时做好适应新的环境、迎接新挑战、解决新问题的准备。
[20]替代画线部分的最好一项是:A.这时关键要对完全不同的、过去的大学环境有清醒的认识B.这时关键要对过去的、完全不同的中学环境有清醒的认识C.这时关键要对大学环境的新特点有清醒的认识D.这时关键要对完全不同于大学的、过去的环境有清醒的认识21~22题有人在数学考试时夹进了这么一道题:航行在大海上的船里运了75头牛、32只羊、问该船船长的年龄是多少岁?这道题首先考了法国学生,有4%的孩子回答75-32=43,船长43岁。
中国的教育工作者又把它拿来考中国的中小学生,结果,回答43岁的学生比例超过了4%。
这些孩子只知道单纯的数字运算,为什么不想想这道题的正确程度呢?[21] 这4%的学生:A.太粗心了B.犯了计算错误C.犯了逻辑错误D.没有错[22]这是一道:A.很简单的问题B.难度很大的问题C.错误的问题D.缺少解题条件的问题23~25题谁说宇宙是没有生命的?宇宙是一个硕大无比的、永恒的生命体,那永恒的运动、那演化的过程,不正是她生命力的体现吗?如果宇宙没有生命,怎么会从中开出灿烂的生命之花?这个宇宙到处都隐藏着生命,到处都有生命的萌芽,到处都有沉默的声音。
你难道没有听到石头里也有生命的呐喊吗?你难道没有用心灵听到从哪遥远的星系里传来的友好问候吗?即使那些看起来死气沉沉的物质,也是宇宙生命的构成部分,也是生命的一种存在形式。
那些高级的生命形态正是从这“死”的物质中产生的,换言之,包括我们人类在内的高级生命,只是物质的另一种存在方式。
在物质中,有无数的生命在沉睡着,一旦出场的时间到了,他们就会从睡梦中醒来。
因此,人类并不孤独,在宇宙中处处是我们的兄弟。
因此,我们再也不应该把宇宙的其他部分看作只是我们征服的对象,再也不应该把其他生物仅仅看作我们的美味佳肴,而首先应该把他们看作是与我们平等的生命,看作是宇宙智慧的创造物,看做是宇宙之美德展示者,首先应该敬畏它们,就像敬畏我们自己一样。
敬畏他们,就是敬畏宇宙,敬畏自然,就是敬畏我们自己。
[23]从这几段文字中,作者得出的结论是:A.人类应该敬畏我们自己B.人类应该敬畏其他生物C.人类并不孤独D.人类应该敬畏自然[24]“人类并不孤独,在宇宙中处处是我们的兄弟”的含义是:A.人类是脱离宇宙的存在B.人类是宇宙生命的构成部分,人类之外的一切也是生命的存在形式C.人类是高级生命的存在,其他物质都是低级生命的存在D.宇宙是一个硕大无比的,永恒的生命,那永恒的运动,那演化的过程是宇宙生命力的体现[25]不属于“敬畏自然”就是“敬畏我们自己”的原因是:A.因为人类与自然都是宇宙的创造物B.人类与自然都是平等的生命,都是兄弟C.敬畏自然就是爱护自然,爱护人类生存的家园D.自然是比人类更高级的一种生命宁形式26~29题21世纪前半期,人类将以天然气为主要能源。
一方面,天然气的资源暂时还比较丰富;另一方面,天然气也比石油和煤更环保一些。
到目前为止,世界上占主流的能源还是煤和室友,然而它们的燃烧带给世界的是酸雨和全球气候变暖等恶果。
为了一只全球气候变暖的趋势,稳定能源供给,世界各国已开始开发天然气,希望以此代替煤河石油。
天然气是最干净的化石燃料,其燃烧产生的二氧化碳的量仅为石油的70%。
天然气的储藏量也相当大。
然而比起氢气来,天然气的环保效果就差远了。
纯净的氢气不仅发热量高,而且燃烧后一点也不污染环境,不仅不会产生有毒气,而且不会产生导致问世效应的二氧化碳,它的唯一产物是不对环境产生污染的水。
氢气可是再生的燃气资源,它可以通过分解水来获得,它的产物是又是水,所以氢气简直就是取之不尽、用之不竭的心能源,既然这样,我们以前怎么就没有想到使用它呢?说到底这是个成本问题,由于现在分解水货的氢气的技术还不是很完善,故燃烧氢气的成本比石化燃料要高得多。
随着科学技术的发展,制造氢气的成本会越来越低。
德国目前已经开始进行液体和气体氢供给给基本建设项目的准备,计划到2010年将建成月3000个氢气气站。
研制环保汽车已成为全球汽车业的主攻方向。
一些规模较大的国际汽车团为了在产品的核心技术方面保持领先,在环保汽车产品的开发方面下了大力。
利用氢气制造的氢动力燃料电池可作为汽车的动力来源,氢燃料电池是利用氢和氢(或空气)直接经电化学反应产生电能的装置。
在底特律举办的2002年国际车展上,通用汽车公司“自主魔力”氢动力概念车首次亮相。
由于汽车须解决环保问题的迫切性,将很可能使得氢燃料时代提前到来。
科学家家预测,从2020年开始,将在天然气中加入15%的氢,到21世纪后期,人类将慢慢过渡到使用纯净氢气的时代。
[26]就环保效果而言,三大能源排序正确的是:A.石油和煤> 天然气> 氢气B.天然气> 氢气> 石油和煤C.氢气> 石油和煤> 天然气D.氢气> 天然气> 石油和煤[27]关于氢气的优点,说法不正确的是:A.分解水货的氢的技术很完善B.氢气是可再生的燃气资源C.氢气的环保效果非常好D.到21世纪后期,人类将慢慢过渡到使用纯净氢气的时代[28]属于本文采取的说明方法的是:A.列数字B.打比方C.作比较D.举例子[29]根据本文,说法错误的一项是:A.煤和石油的燃烧带来酸雨和全球变暖等恶果B.2010年德国将建成3000个氢气气站C.研制环保汽车已成为全球汽车业的主攻方向D.随着科学技术的发展,制造氢气的成本会越来越低30~33题教育部新闻发言人王旭明带领一个小组到宁夏做宣传、调研。