Cisco CCNA 认证考试最新真题

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思科认证CCNA认证试题与答案中文版

思科认证CCNA认证试题与答案中文版
(A) 224. 0. 0.5 (B) 127. 32. 5. 62 (0202. 112.5.0 (D) 162. 111. 111. Ill
答案:D 注释:这个题目不是太严谨,应该加上子网掩码. A:224. 0. 0. 5 是多播地址 B: 127. 0.0. 0 保留作为测试使用 C:网络地址 26、 设置主接口由 up 转 down 后延迟 30 秒切换到备份接口,主 接口 由 down 转 up 后 60 秒钟切换回主接口的配置为()
忍一句,息一怒,饶一着,退一步。——《增广贤文》
人之为学,不日进则日退,独学无友,则孤陋而难成;久处一方,则习染而不自觉。——《顾炎武》
答案:D 注释:255. 255. 255. 255 是全网广播,DHCP 客户端发送全网广播来 查 找 DHCP 服务器. 24、 下而有关 NAT 叙述正确的是() (A) NAT 是英文“地址转换”的缩写,又称地址翻译 (B) XAT 用来实现私有地址与公用网络地址之间的转换 (C) 当内部网络的主机访问外部网络的时候,一定不需要 NAT (D) 地址转换的提出为解决 IP 地址紧张的问题提供了一个有效途 径 答案:ABD 25、 以下属于正确的主机的 IP 地址的是()
(A) arp-a (B) traceroute (C) routeprint (D) displayiprouting-table
答案:D 23、 D0. 0. 0 (B) 10. 0. 0. 1 (0127. 0. 0. 1 (D)255. 255. 255. 255
192. 168. 1. 1
答案:D 注释:PC 的'默认网关要指向路由器的以太网口的 IP 地址. 28、 ISDNB 信道速率是()
(A) 16kbps (B) 64kbps

最新CCNA认证考试真题

最新CCNA认证考试真题

⽆忧考为⼤家收集整理了《最新CCNA认证考试真题》供⼤家参考,希望对⼤家有所帮助(1)TCP/IP Addressing and Protocol1: Your junior network administrator wants to know what the default subnet mask is for a Class C IP address. What do you tell him?A. 255.0.0.0B. 255.255.0.0C. 255.245.255.0D. 255.255.255.0E. 255.255.255.255 2: An application needs to have reliable, end-to-end connect-ivity. Which of the following protocols will give you reliable connectivity?A. TCPB. UDPC. IPD. ICMP 3: You are designing a network, which needs to support 55 users. You don't plan to extend the segment beyond the current number of users. Which subnet mask would best meet your needs?A. 255.255.0.0B. 255.255.255.0C. 255.255.255.192D. 255.255.255.160 4: You have added a new switch to your network. You want to manage it remotely, so you need to assign it an IP address. Your router that connects to the switch has an IP address of 172.16.12.33/27. Which of the following addresses can you assign to this switch?A. 172.16.12.33/28B. 172.16.12.32/27C. 172.16.12.33/27D. 172.16.12.34/27E. 172.16.12.35/28F. 172.16.12.38/28G. 172.16.12.63/27 5: The address 172.16.208.16/20 is a host address in which of the following subnets? A. 172.16.176.0–255.255.240.0B. 172.16.192.0–255.255.240.0C. 172.16.208.0–255.255.240.0D. 172.16.224.0–255.255.240.0 6: You are designing an IP address scheme for your brand new remote office. The vice president of IT calls to tell you that you will be in charge of the 192.168.1.64/26 subnetwork. This supplies you with a single subnetwork with 62 hosts. You need to have at least two subnets with 14 hosts in each subnet. What custom subnet mask should you use?A. 255.255.255.128B. 255.255.255.192C. 255.255.255.224D. 255.255.255.240E. 255.255.255.248 7: You have subnetted the 210.106.14.0 network with a /24 mask. Your boss at Acme, Inc. wants to know how many usable subnetworks and usable host addresses per subnet this would provide. What should you tell her?A. One network with 254 hostsB. Two networks with 128 hostsC. Four networks with 64 hostsD. Six networks with 30 hosts 8: Identify three valid host addresses in any subnet of the 201.168.27.0 network, assuming a fixed subnet mask of 255.255.255.240. (Choose three.)A. 201.168.27.33B. 201.168.27.112C. 201.168.27.119D. 201.168.27.126E. 201.168.27.175F. 201.168.27.208 9: What is the subnetwork address for a host with the IP address 201.100.5.68/28?A. 201.100.5.0B. 201.100.5.32C. 201.100.5.64D. 201.100.5.65E. 201.100.5.31F. 201.100.5.1 10: Which of the following protocols uses a three-way handshake mechanism to establish sessions?A. TCPB. IPC. UDPD. IPXE. Frame relay 11: Which of the following protocols is connection-oriented? A. TCPB. IPC. IPXD. Frame relay 12: You are using an application on your Windows 2000 client machines that provides error correction. You need a protocol to provide fast transport. Which protocol should your application use?A. TCPB. IPC. UDPD. SPXE. AppleTalk 13: When using TCP, after a session is open, the applications can adjust the number of segments they receive before sending an acknowledgment. This behavior is known as ______________.A. MTU adjustmentB. WindowingC. Flexible Send PathD. FCS 14: If the destination did not receive a segment, how will the TCP host know to resend the information?A. The ACK received will not include the segment number that was not received.B. The ACK received will include the segment number that was not received.C. The sending host will send a PACK to verify segment receipt.D. The destination host will send a YACK message back to the sending host. 15: You are planning on using a single network that supports 208 users. Which IP address class would you choose to be the most efficient?A. Class AB. Class BC. Class CD. Class DE. Class E 16: RFC 1918 defines the private IP address ranges. Which of the following IP addresses are considered part of these ranges? (Choose three.)A. 10.23.45.67B. 126.21.34.56C. 172.16.32.1D. 172.31.234.55E. 192.169.4.5 17: A new network is being designed for your company, Acme, Inc. If you use a Class C IP network, which subnet mask will provide one usable subnet per department while allowing enough usable host addresses for each department specified in the table?Department Number of Users Corporate 7 Customer Support 15 Financial 13 HR 7 Engineering 16 A. 255.255.255.0B. 255.255.255.192C. 255.255.255.224D. 255.255.255.240E. 255.255.255.248 18: Which of these protocols provides data transport, relying on the error correction capabilities of the application itself?A. UDPB. TCPC. SNMPD. ICMP 19: Which of the following are used by TCP to ensure reliable delivery of data? (Choose two.)A. MAC address resolutionB. Sequence numbersC. AcknowledgmentsD. PingE. Routing updates 20: You discover that you are able to adjust the window size of the TCP segment. You increase the window size to test the results. What will you observe happening on your network?A. Increased throughputB. Decreased throughputC. Increased latencyD. Decreased reliability21: Your organization is using the 192.168.1.0/24 address space. You need 28 subnets. What subnet mask would you use to create these subnets?A. 255.255.255.0B. 255.255.255.128C. 255.255.255.192D. 255.255.255.224E. 255.255.255.240F. 255.255.255.248 22: Which of the following protocols maps IP addresses to MAC addresses for connectivity to occur between two hosts?A. ARPB. RARPC. SLARPD. DHCP 23: Your junior network administrator cannot seem to ping a host in another network and asks you why it isn't working. Which of the following is not an answer that you would give him?A. The host's default gateway is down.B. The destination host is not powered on.C. The IP address of the router interface is incorrect.D. The IP address of the switch to which the destination host connects is incorrect.E. The host is in a different subnet. 24: Which of the following classes of IP addresses is utilized for multicasting?A. Class AB. Class BC. Class CD. Class D 25: You give your IT department a spreadsheet of IP addresses and their subnets. You receive a call from one of the junior techs asking what the /26 means next to the IP addresses. You tell her: A. It represents the number of hosts possible on that subnetwork.B. It represents the number of subnetworks that are being used.C. It represents the class of IP address being used.D. It represents the number of bits in the subnet mask that are 1. 26: You are given an IP network of 192.168.5.0 and told that you need to separate this network into subnetworks that can support a maximum of 16 hosts per subnet. This will help alleviate congestion on the network. What subnet mask can you use to create the subnets necessary to meet the given criteria?A. 255.0.0.0B. 255.255.0.0C. 255.255.255.0D. 255.255.255.224E. 255.255.255.240 27: Which of the following would a Class A network be assigned to?A. Government agencyB. Small-to-medium sized corporationD. An individual 28: A client has the IP address 192.168.5.98/27. Which of the following addresses are on the same subnet as this host? (Choose two.)A. 192.168.5.95B. 192.168.5.100C. 192.168.5.128D. 192.168.5.110 29: Which of the following IP addresses is not a public IP address that can be routed over the Internet?A. 2.3.4.5B. 11.12.13.14C. 165.23.224.2D. 172.31.45.34E. 203.33.45.22 30: You are given a Class B network. What is the default subnet mask assigned to the Class B network?A. 255.255.255.255B. 255.255.0.0C. 255.224.0.0D. 0.0.0.0 31: You are troubleshooting your router's interfaces. For some reason, the Ethernet interface will not accept the IP address of 192.168.5.95/27 that you've assigned. Which of the following explains the router's refusal to take the IP address?A. Class C addresses cannot be assigned to Ethernet interfaces.B. The /27 is an invalid mask.C. It is a broadcast address.D. It is a public IP address.E. It is a private IP address. 32: You are a network technician at Acme, Inc. You are required to divide the 172.12.0.0 network into subnets. Each subnet must have the capacity of 458 IP addresses. Also, according to the requirements, you must provide the maximum number of subnets. Which subnet mask should you use?A. 255.255.255.254B. 255.255.254.0C. 255.255.240.254D. 255.255.0.0 33: What is the subnetwork and broadcast IP address of 192.168.2.37 with the subnet mask of255.255.255.248?A. 192.168.2.24/192.168.2.31B. 192.168.2.32/192.168.2.39C. 192.168.2.40/192.168.2.47D. 192.168.2.48/192.168.2.55E. 192.168.2.56/192.168.2.63 34: One of your co-workers at Acme, Inc., needs to convert the binary number 11011010 into a decimal. What is the decimal equivalent?A. 218B. 219C. 220E. 222 35: One of your co-workers at Acme, Inc., needs to convert the binary number 01011010 into a decimal. What is the decimal equivalent?A. 75B. 83C. 90D. 97 36: One of your co-workers at Acme, Inc. , n e e d s t o c o n v e r t t h e b i n a r y n u m b e r 1 1 0 1 0 1 1 0 i n t o a d e ci m a l . W h a t i s t h e d e c i m a l e q u i v a l e n t ? / p > p b d s f i d = " 2 1 0 " > A . 1 9 8 / p > p b d s f i d = " 2 1 1 " > B . 2 14 / p > p b d s f i d = " 2 1 2 " > C . 25 2 / p > p b d s f i d = " 2 1 3 " > D . 2 5 5 3 7 : O n e o f y o u r c o - w o r k e r s a t A c m e , I n c . , n e e d s t o c o n v e r t t h e b i n a r y n u m b e r 1 0 1 1 0 1 1 0 i n t o a d e c i m a l . W h a t i s t h e d e c i m a l e q u i v a l e n t ? / p > p b d s f i d = " 2 1 4 " > A . 1 8 2 / p > p b d s f i d = " 2 1 5 " > B . 1 9 2 / p > p b d s f i d = " 2 16 " > C . 2 0 2 / p > p b d s f i d = " 2 17 " > D . 2 1 2 38 : Y o u a r e c o n f i g u r i n g a s u b n e t f o r t h e A c m e , I n c . , b r a n c h o f f i c e i n B e i j i n g . Y o u n e e d t o a s s i g n I P a d d r e s s e s t o h o s t s i n t h i s s u b n e t . Y o u h a v e b e e n g i v e n t h e s u b n e t m a s k o f 2 5 5 . 2 5 5 . 2 5 5 . 2 2 4 . W h i c h o f t h e s e I P a d d r e s s e s w o u l d b e v a l i d ? ( C h o o s e t h r e e . ) / p > p b d s f i d = " 2 1 8 " > A . 1 5 . 2 3 4 . 1 1 8 . 6 3 / p > p b d s f i d = " 2 19 " > B . 9 2 . 1 1 . 1 7 8 . 9 3 / p > p b d s f i d = " 2 2 0 " > C . 1 3 4 . 1 7 8 . 1 8 . 5 6 / p > p b d s f i d = " 2 2 1 " > D . 1 9 2 . 1 6 8 . 1 6 . 8 7 / p > p b d s f i d = " 2 2 2 " > E . 2 0 1 . 4 5 . 1 1 6 . 1 5 9 / p > p b d s f i d = " 2 2 3 " > F . 2 1 7 . 6 3 . 1 2 . 1 9 2 3 9: Y o u a r e a n e t w o r k t e c h n i c i a n a t A c m e , I n c . Y o u h a v e s u b n e t t e d t h e 2 0 8 . 9 8 . 1 1 2 . 0 n e t w o r k w i t h a / 2 8 m a s k . Y o u r b o s s a s k s y o u h o w m a n y u s a b l e s u b n e t w o r k s a n d u s a b l e h o s t a d d r e s s e s p e r s u b n e t t h i s w i l l p r o v id e . W h a t s h o u l d y o u t e l l h e r , a s s u m i n g y o u r r o u t e r i s u s i n g i p s u b n e t - z e r o ? / p > p b d s f i d = " 22 4 " > A . 6 2 n e t w o r k s a n d 2 h o s t s / p > p b d s f i d = " 2 2 5 " > B . 6 n e t w o r k s a n d3 0 h o s t s / p > p b d s f i d = " 2 2 6 " > C . 8 n e t w o r k s a n d 3 2 h o s t s / p > p b d s f i d = " 2 2 7 " > D . 1 6 n e t w o r k s a n d 1 6 h o s t s / p > p b d s f i d = " 2 2 8 " > E . 1 6 n e t w o r k s a n d 14 h o s t s 4 0 : W h a t i s a d i s a d v a n t a g e o f u s i n g a c o n n e c t i o n -o r i e n t e d p r o t o c o l s u c h a s T C P ? / p > p b d s f i d = " 2 2 9 " > A . P a c k e t a c k n o w l e d g m e n t m i g h t a d d o v e r h e a d . / p > p b d s f i d = " 2 3 0 " > B . P a c k e t s a r e n o t t a g g e d w i t h s e q u e n c e n u m b e r s . / p > p b d s f i d = " 2 3 1 " > C . L o s s o r d u p l i c a t i o n o f d a t a p a c k e t s i s m o r e l i k e l y t o o c c u r . / p > p b d s f i d = " 2 32 " > D . T h e a p p l i c a t i o n l a y e r m u s t a s s u m e r e s p o n s i b i l i t y f o r t h e c o r r e c t s e q u e n c i n g o f t h ed a t a p a c ke t s . 4 1 : Y o u a r e a n e t w o r k t e c h n i c i a n a t A c m e , I n c . Y o u h a v e s u b n e t t e d t h e 1 9 2 . 16 8 .7 2 . 0 n e t w o r k w i t h a / 3 0 m a s k f o r c o n n e c t i o n s b e t w e e n y o u r r o u t e r s . Y o u r b o s s a s k s y o uh o w m a n y u s a b l e s u b n e t w o r k s a n d u s a b l e h o s t a d d r e s s e s p e r s u b n e t t h i s w i l l p r o v i d e . W h a t s h o u l d y o u t e l l h e r , a s s u m i n g y o u r r o u t e r c a n n o t u s e i p s u b n e t - z e r o ? / p > p b d s f i d = " 2 3 3 " > A . 6 2 n e t w o r k s a n d 2 h o s t s / p > p b d s f i d = " 2 3 4 " > B . 6 n e t w o r k s a n d 3 0 h o s t s / p > p b d s f i d = " 23 5 " > C . 8 n e t w o r k s a n d 3 2 h o s t s / p > p b d s f i d = " 2 3 6 " > D . 1 6 n e t w o r k s a n d 1 6 h o s t s / p > p b d s f id = " 2 3 7 " > E . 1 4 ne t w o r k s a n d 1 4 h o s t s 4 2 : W h i c h of t h e f o l l o w i ng I P a d d r e s s e s a r e c o n s i d e re d " n e t w o r k " a d d r e s s e s w i t h a / 2 6 p r ef i x ? ( C h o o s e t w o . ) / p > p b d s f i d = " 2 3 8 " > A . 1 6 5 . 2 0 3 . 2 . 0 / p > p b d s f i d = " 2 3 9 " > B . 1 6 5 . 2 0 3 . 5 . 1 9 2 / p > p b d s f i d = " 2 4 0 " > C . 1 6 5 . 2 0 3 . 6 . 6 3 / p > p b d s f i d = " 2 4 1 " > D . 1 6 5 . 2 0 3 . 6 . 1 9 1 / p > p b d s f i d = " 2 4 2 " > E . 1 6 5 . 2 0 3 . 8 . 2 5 5 4 3 : I d e n t i f y t h r e e v a l i d h o s t s i n a n y s u b n e t o f 1 9 2 . 1 6 8 . 3 2 . 0 , a s s u m i ng th e s u b n e t m a s k u s e di s 2 5 5 . 2 5 5 . 2 5 5 . 2 4 0 . (C h o o s e t h r e e . ) / p > p b d s f i d = " 2 4 3 " > A . 1 9 2 . 1 6 8 . 3 2 . 3 3 / p > p b d s f i d = " 2 4 4 " > B . 1 9 2 . 1 6 8 . 3 2 .1 12 / p > p b d s f i d = " 2 4 5 " > C . 1 9 2 . 1 6 8 .3 2 . 1 1 9 / p > p b d s f i d = " 24 6 " > D . 1 9 2 . 1 6 8 . 3 2 . 1 2 6 / p > p bd s f i d = " 2 4 7 " > E . 1 9 2 . 1 6 8 . 3 2 . 1 7 5 / p > p b d s f i d = " 2 4 8 " > F . 1 9 2 . 1 6 8 . 3 2 . 2 0 8 4 4 : A C l a s s C ne t w o r k a d d r e s s h a s b e e n s u b n e t t e d w i t h a / 2 7 m a s k . W h i c h of t h e f o l l o w i ng a d d r e s s e s i s a b r oa d c a s t a d d r e s s f o r o n e o f t h e r e s u l t i n g s ub n e t s ? / p > p b d s f i d = " 2 4 9 " > A . 1 9 8 . 5 7 . 7 8 . 3 3 / p > pb d s f i d = " 2 5 0 " > B . 1 9 8 . 5 7 . 7 8 . 6 4 / p > p b d s f i d = " 2 5 1 " > C . 1 9 8 . 5 7 . 7 8 . 9 7 / p > p b d s f i d = " 2 5 2 " >D . 1 9 8 . 5 7 . 7 8 . 9 7 / p > p b d s f i d = " 2 5 3 " >E . 1 9 8 . 5 7 . 7 8 . 1 5 9 / p > p b d s f i d = " 2 5 4 " >F . 1 9 8 . 5 7 . 7 8 .2 5 4 4 5 : W h a t i s t h e s u b n e t w o r k a d d r e s s f o r a h o s t w i t h I P a d d r e s s 1 6 5 . 1 0 0 . 5 . 6 8 / 2 8 ? / p > p bd s f i d = " 2 5 5 " > A . 1 6 5 . 1 0 0 . 5 . 0 / p > p b d s f i d = " 2 5 6 " > B . 1 6 5 . 1 0 0 . 5 . 3 2 / p > p b d s f i d = " 2 5 7 " > C .1 6 5 . 1 0 0 . 5 . 6 4 / p > p b d s f i d = "2 5 8 " > D . 1 6 5 . 1 0 0 . 5 . 6 5 / p > p b d s f i d = " 2 5 9 " > E . 1 6 5 . 1 0 0 . 5 .3 1 / p > p b d s f i d = " 2 6 0 " > F . 1 6 5 . 1 0 0 . 5 . 14 6 : Y o u r b o s s w a n t s t o k n o w w h a t T C P s t a n d s f o r . W h a t d o y o u t e l l h i m ? / p > p b d s f i d = " 2 6 1 " > A . T r a n s m i s s i o n C h e c k P r o t o c o l / p > p b d s f i d = " 2 6 2 " > B . T r a n s p o r t C h e c k P r o t o c o l / p > p b d s f i d = " 2 6 3 " > C . T r a n s m i s s i o n C o n t r o l P r o t o c o l / p > p b d s f i d = " 2 6 4 " > D . T r a n s p o r t C o n t r o l P r o t o c o l 4 7 : Y o u r b o s s w a n t s t o k n o w w h a t U D P s t a n d s f o r . W h a t d o y o u t e l l h i m ? / p > p b d s f i d = " 2 65 " > A . U n r e l i a b l e D a t a P r o t o c o l / p > p b d s f i d = " 26 6 " > B . U n r e l i a b l e D a t a P r o g r a m / p > p b d s f i d = " 2 67 " > C . U s e r - D e f i n e d P r o t o c o l / p > p b d s f i d = "2 6 8 " > D . U s e r D a t a g r a m P r o t o c o l 4 8 : W h i c h o f t h e f o l l o w i n g s t a t e m e n t s a c c u r a t e l y d e s c r ib e s U D P ? / p > p b d s f i d = " 2 6 9 " > A . U D Pc o p i e s f i l e s b e t w e e n a c o m p u t e r a nd a s y s te m r u n n i n g r s h d , t h e r e m o t e s h e l l s e r v i c e ( d a e m o n ) . / p > p b d sf i d = " 2 7 0 " > B . U D P i s a m e m b e r o f t h e T C P / I P s u i t e o f p r o t o c o l s t h a tg o v e r n s th e e x c h a n g e o f e l e c t r o ni c m a i l b e t w e e n m e s s a g e t ra n s f e r a g e n t s . / p > pb d s f i d = " 2 7 1 " > C . U D P i s a m e m b e r o f t h e T C P / I P s u i t e o f p r o t oc o l s a nd i s u se d t o c o p yf i l e s b e t w e e n t w o c o m p u t e r s o n t h e I n t e r n e t . B o t h c o m p u t e r s m u s t s u p p o r t t h e i r r e s p e c t i v e r o l e s : o n e m u s t b e a c l i e n t , a n d t h e o t h e r a s e r v e r . / p > p b d s f i d = " 2 7 2 " > D . U D P i s a T C P c o m p l e m e n t t h a t o f f e r s a c o n n e c t i o n l e s s d a t ag r a m s e r v i c e g u a r a n t e e i n g n e i th e r d e li v e r y n o r c o r r e c t s e q u e n c i n g o f d e l i v e r e d p a c k e t s ( m u c h l i k e I P ) . 4 9 : W h i c h o f t h e f o l l o w i n g h o s t a d d r e s s e s a r e m e m b e r s o f n e t w o r k s t h a t c a n b e r o u t e d a c r o s s t h e p u b l i c I n t e r n e t ? ( C h o o s e t h r e e . ) / p > p b d s f i d = " 2 7 3 " > A . 1 0 . 2 0 . 1 2 . 6 4 / p > p b d s f i d = " 2 7 4 " > B . 1 7 2 . 1 6 . 32 . 1 2 9 / p > p b d s f i d = " 2 7 5 " > C . 1 7 2 . 6 4 .3 2 . 34 / p > p b d s f i d = " 2 7 6 " > D . 1 9 2 . 1 6 8 . 2 3 . 25 2 / p > p bd s f i d = " 2 7 7 " > E . 1 9 6 . 1 0 4 . 1 2 . 9 5 / p > p b d s f i d = " 2 7 8 " > F . 2 1 4 . 1 9 2 . 4 8 . 2 5 4 5 0 : Y o u a re c o n n e c t i n g y o u r S e r i a l 0 / 1 i n t e rf a c e t o t h e I n t e r n e t . W h i c h o f t h e f o l l o w i ng n e e d t o b e d o n e f o r th e c o n n e c ti o n t o w o r k ? ( C h o o s e t w o . ) / p > p b d s f i d = " 2 7 9 " > A . A s s i g n a p u b l i c I P a d d r e s s . / p > pb d s f i d = " 2 8 0 " > B . U s e t h e s h u t d o w nc o m m a nd . / p > p b d s f i d = " 2 8 1 " > C . U se t h e n o s h u t d o w nc o m m a nd . / p > p b d s f i d = " 2 8 2 " > D . M a ke s u r e t h e i n t e rf a c e i s r u n n i ng i n f u l l - d u p l e x . / p >。

思科CCNA第三学期官方试题(完整版)[有答案解析]

思科CCNA第三学期官方试题(完整版)[有答案解析]

参加考试 - ESwitching Final Exam - CCNA Exploration: LAN 交换和无线 (版本 4.0)剩余时间正在显示第 1 页,共 4页下一页>页跳转<上一页1 以下哪项参数用于唯一标识一个无线网络,使其与其它网络区分开来?SSID OFDMWEPDSSS2 分层网络模型具有哪三项优点?(选择三项。

)带宽争用现象减少物理布局范围减小网络的容错能力提高无需配线间无需第三层功能管理和故障排除工作简化3在将 Catalyst 交换机迁移到其它 VTP 管理域之前,应该进行哪三项任务?(选择正确的 VTP 模式和版本。

使用新管理域的名称配置交换机。

从新域中的 VTP 服务器上下载 VTP 数据库。

配置新域内的 VTP 服务器,使其识别该交换机的 BID。

重置 VTP 计数器,使交换机可与新域内的其它交换机同步。

检验交换机的配置修订版号是否比新域内的其它交换机的低。

4下列哪两种说法正确地描述了生成树协议?(选择两项。

)它只在第 2 层使用。

它在交换机上配置。

它消除了网络拓扑中的第 2 层环路。

它限制了端口上所允许的有效 MAC 地址的数量。

它使 VLAN 信息得以传播到网络中的其它交换机。

5下列哪种方法可建立用于配置 Linksys WRT300N 无线接入点的管理连接?与接入点关联,然后与接入点建立超级终端会话。

以物理方式连接到接入点,然后重新启动计算机以启动配置软件。

在接入点所在的 IP 子网内的计算机上的 web 浏览器中输入接入点的默认修改与接入点连接的计算机的 TCP/IP 属性,使其与接入点处于同一个网机以建立连接。

6请参见图示。

源地址并非 0019.d2e4.d9f7 的帧进入接口 Fa0/24 时会发生什么情况?Fa0/24 会变为 error-disabled(错误-禁用)状态。

传入帧会被丢弃。

Fa0/24 端口 LED 会关闭。

安全违规计数会增加。

思科 CCNA 学习试题 答案!!!

思科 CCNA 学习试题 答案!!!

思科 CCNA 学习试题答案思科ccna学习试题答案CCNA课程测试一、单项选择题:1.媒体100BaseT的最大传输距离为:()a:10MB:100mc:1000md:500M2、路由器下,由一般用户模式进入特权用户模式的命令是:()a:enableb:configc:interfaced:router3、哪个命令可以成功测试网络:()a:router>ping192.5.5.0b:router#ping192.5.5.30c:router>ping192.5.5.256d:router#ping192.5.5.2554、介质工作在osi的哪一层()a:物理层B:数据链路层C:网络层D:传输层5。

100BaseT的速率为()Mbit/SA:1b:10C:100D:10006、在启用igrp协议时,所需要的参数是:()a:网络掩码b:子网号c:自治系统号d:跳数7、基本ip访问权限表的表号范围是:()a:1―100b:1-99c:100-199d:800-8998、查看路由表的命令是:()a:ShowInterface B:showrunc:showiprouted:showtable9、工作在osi第三层的设备是:()a:网卡b:路由器c:交换机d:集线器10、osi第二层数据封装完成后的名称是:()a:比特b:包c:帧d:段11.为了禁止网络210.93.105.0 FTP到网络223.8.151.0并允许其他信息传输,可以实现此功能的选项有:()a:access-list1deny210 93.105.0.0.0.0.0.0b:access-list100denytcp210.93.105.00.0.0.255223.8.151.00.0.0.255eqftpc:access-List100Permitipanyd:access-list100denytcp210.93.105.00.0.0.255223.8.151.00.0.0.255eqftpaccess-list100permitipanyany12.路由器下“特权用户模式”的标识符为:()a:>b:!c:#d:#配置如果)#13。

思科CCNA题目及答案

思科CCNA题目及答案

CCNA-Cisco-Chapter11C11 An electrician has investigated your recent power problems and has suggested that they are caused by oscillation. What is the BEST solution to your problem?Move the network server to another roomReplace UTP with fiber optic cable* Rewire the electrical systemFit commercial surge suppressors2 What is another term that can be used to describe an Intermediate Distribution Frame (IDF)? work area (WA)telecommunications outlet (TO)main cross-connect (MCC)* horizontal cross-connect (HCC)3 Why is fiber optic cable commonly used as a network backbone between campus buildings?It provides a less resistive path for electrical current to flow from one building to anotherIt enhances the signals at the physical layer* It reduces the hazardous effects of electrical potential difference and lightning strikesIt is cheaper and easier to install than copper wire4 Which of the following environmental specifications are recommended for a wiring closet ? Carpeted floor; tiled walls and an inward opening doorWooden floor; brick walls and fluorescent lightingTiled floor; internal power outlets and a dropped ceiling* Raised floor; wood covered walls and an internal light switch5 What is one of the most significant causes of oscillatory noise problems on a power circuit? ??? Long wiring runsSchool photocopiersLocating power cables in elevator shaftsAir conditioners cycling on and off6 What device is best used to minimize the effects of power line sags and brownouts?A primary protection deviceA surge suppressorAn optical isolator* An uninterruptible power supply7 What causes Electrostatic Discharge (ESD)?Long power linesFaulty electrical equipment* An accumulation of static electricityAn increase in atmospheric humidity8 Which of the following problems is caused by too high a humidity level in a wiring closet? Signal degradation* Copper wire corrosionInsulation failurePower surges9 What is the ideal room temperature and relative humidity at which a wiring closet should bemaintained?* 21 degrees Celsius / 45 % relative humidity21 degrees Fahrenheit / 45 % relative humidity45 degrees Celsius / 21 % relative humidity45 degrees Fahrenheit / 21 % relative humidity10 What is the maximum length specified for 62.5/125µm multimode optical fiber run between the MDF and IDF?90 m800 m2000 m* 3000 m11 What are the three components that make up an uninterruptible power supply?* A battery, inverter and battery chargerA MOV, capacitor and diodeA generator, changeover circuit and server softwareA circuit breaker, fuse and battery12 Where does the horizontal cable extend?From the main distribution frame in the wiring closet to the vertical cross connect in the intermediate distribution frameFrom the telecommunications outlet in the work area to the horizontal cross-connect in the telecommunications closet* From the patch panel in the point of presence to the backbone connection in the customer premises equipmentFrom the telecommunications outlet in the wiring closet to the conduit in the intermediate distribution frame13 Which statement BEST describes the current flow in an electrical circuit with a DC source?* It is constant over timeIt varies over timeIt increases with timeIt decreases with time14 Why are exposed metal components normally connected to the ground, or earth, pin of a power outlet?The connection is needed to increase the resistance of the circuit to ground* If an electrical fault occurs in the equipment, the connection will reduce the chance of shock Connecting the metal to ground makes it act like an insulatorThe ground connection can act as an alternative path for controlled current flow if the neutral wire is disconnected15 What is the term used to describe a problem in an electrical system between the hot, or live, wire and the neutral wire?An isolated mode problemA ground fault problem* A common mode problemA normal mode problem16 What function does an electrical insulator perform?It completes the circuit, allowing current to flowIt reduces the resistance in an electrical circuitIt allows a short circuit to be present* It prevents uncontrolled current flow17 What is an alternative name for backbone cabling?Horizontal cabling* Vertical cablingMain cablingTrunk cabling18 Why can digital electronic equipment, such as a computer, malfunction if subjected to excessive power line noise?Logic gates are unable to correctly distinguish the noise polarityThe noise enhances the digital signal edgesThe noise replaces the digital signal* Logic gates are unable to correctly distinguish between a one and a zero19 A potential wiring closet has been identified in a building with a floor area of 930 sq. m. The distance from this closet to the furthest workstation is 127 m. How many ADDITIONAL wiring closets would need to be installed?* 012820 Why is copper considered a good conductor of electricity?* It offers a path of least resistance to current flowIt is easily formed into wiresIt is cheaper than other metalsIt reduces power line noise21 In a controlled electrical circuit, which path do electrons normally follow?From the positively charged source to ground* From the negatively charged source to a positively charged sourceFrom the more positively charged source to the less positively charged sourceFrom the negatively charged source to ground22 What is the purpose of providing a ground, or earth, connection on a wall power outlet?To reduce the resistance in the electrical circuitTo link the neutral wire to ground* To allow fault currents to flow to groundTo complete the circuit for normal current to flow23 What is a possible problem associated with multiple building grounds?They are often at the same potential with respect to each otherThey do not allow electrical current to flow between the buildingsSeparate protective devices are needed at each building* They may present a shock hazard due to different potentials24 What features should be considered when assessing a potential wiring closet?It should be secure and situated on the first (ground) floor???? It should be secure and close to the POPIt should be within 150 m of the MDF and close to an entranceIt should be an internal room and close to the electrical supply distributionC21. Which statements correctly identify the role of intermediary devices in the network? (Choose three.)determine pathways for datainitiate data communicationsretime and retransmit data signalsoriginate the flow of datamanage data flowsfinal termination point for data flow2. Select the statements that are correct concerning network protocols. (Choose three.) define the structure of layer specific PDU'sdictate how to accomplish layer functionsoutline the functions necessary for communications between layerslimit the need for hardware compatibilityrequire layer dependent encapsulationseliminate standardization among vendors3. What are two functions of encapsulation? (Choose two.)tracks delay between end devicesenables consistent network paths for communicationallows modification of the original data before transmissionidentifies pieces of data as part of the same communicationensures that data pieces can be directed to the correct receiving end device4. What is a primary function of the trailer information added by the data link layer encapsulation?supports error detectionensures ordered arrival of dataprovides delivery to correct destinationidentifies the devices on the local networkassists intermediary devices with processing and path selection5. Which statements correctly identify the role of intermediary devices in the network? (Choose three.)determine pathways for datainitiate data communicationsretime and retransmit data signalsoriginate the flow of datamanage data flowsfinal termination point for data flow6. What is a PDU?corruption of a frame during transmissiondata reassembled at the destinationretransmitted packets due to lost communicationa layer specific encapsulation7. Which characteristic correctly refers to end devices in a network?manage data flowsoriginate data flowretime and retransmit data signalsdetermine pathways for data10. Which three statements best describe a Local Area Network (LAN)? (Choose three.)A LAN is usually in a single geographical area.The network is administered by a single organization.The connection between segments in the LAN is usually through a leased connection. The security and access control of the network are controlled by a service provider.A LAN provides network services and access to applications for users within a common organization.Each end of the network is generally connected to a Telecommunication Service Provider (TSP).12. What is the primary purpose of Layer 4 port assignment?to identify devices on the local mediato identify the hops between source and destinationto identify to the intermediary devices the best path through the networkto identify the source and destination end devices that are communicatingto identify the processes or services that are communicating within the end devices13. What device is considered an intermediary device?file serverIP phonelaptopprinterswitch16. Which layer encapsulates the segment into packets?physicaldata linknetworktransport17. What can be identified by examining the network layer header?the destination device on the local mediathe destination host addressthe bits that will be transferred over the mediathe source application or process creating the data18. What is the purpose of the TCP/IP Network Access layer?path determination and packet switchingdata presentationreliability, flow control, and error detectionnetwork media controlthe division of segments into packets19. During the encapsulation process, what occurs at the data link layer?No address is added.The logical address is added.The physical address is added.The process port number is added.21. What is the proper order of the layers of the OSI model from the highest layer to the lowest layer?4physical, network, application, data link, presentation, session, transport application, physical, session, transport, network, data link, presentation application, presentation, physical, session, data link, transport, network application, presentation, session, transport, network, data link, physical presentation, data link, session, transport, network, physical, application22. Which two layers of the OSI model have the same functions as the TCP/IP model Network Access Layer? (Choose two.)34NetworkTransportPhysicalData LinkSessionC31 How does the application layer on a server usually process multiple client request for services?ceases all connections to the servicedenies multiple connections to a single daemonsuspends the current connection to allow the new connectionuses support from lower layer functions to distinguish between connections to the service2 A small home network has been installed to interconnect three computers together for gaming and file sharing. What two properties represent this network type? (Choose two.)User accounts are centralized.Security is difficult to enforce.Specialized operating system software is required.File permissions are controlled by a single computer.A computer that responds to a file sharing request is functioning as a server.3 What is the purpose of resource records in DNS?temporarily holds resolved entriesused by the server to resolve namessent by the client to during a querypasses authentication information between the server and client4 A network administrator is designing a network for a new branch office of twenty-five users. What are the advantages of using a client-server model? (Choose two.)centralized administrationdoes not require specialized softwaresecurity is easier to enforcelower cost implementationprovides a single point of failure5 What are three properties of peer-to-peer applications? (Choose three.)acts as both a client and server within the same communicationrequires centralized account administrationhybrid mode includes a centralized directory of filescan be used in client-server networksrequires a direct physical connection between devicescentralized authentication is required6 As compared to SSH, what is the primary disadvantage of telnet?not widely availabledoes not support encryptionconsumes more network bandwidthdoes not support authentication7 What is the automated service that matches resource names with the required IP address?HTTPSSHFQDNDNSTelnetSMTP8 What application layer protocol describes the services that are used for file sharing in Microsoft networks?DHCPDNSSMBSMTPTelnet9 Which two protocols are used to control the transfer of web resources from a web server to a client browser? (Choose two.)ASPFTPHTMLHTTPHTTPSIP10 What three protocols operate at the Application layer of the OSI model? (Choose three.)ARPDNSPPPSMTPPOPICMP11 Which layer of the OSI model supplies services that allow user to interface with the network?physicalsessionnetworkpresentationapplicationtransport12 Which email components are used to forward mail between servers? (Choose two.) MDAIMAPMTAPOPSMTPMUA13 What are two forms of application layer software? (Choose two.)applicationsdialogsrequestsservicessyntax14 Which statements are correct concerning the role of the MTA in handling email? (Choose three.)routes email to the MDA on other serversreceives email from the client's MUAreceives email via the POP3 protocolpasses email to the MDA for final deliveryuses SMTP to route email between serversdelivers email to clients via the POP3 protocol15 What are two characteristics of clients in data networks? (Choose two.)use daemonsinitiate data exchangesare repositories of datamay upload data to serverslisten for requests from servers16 What is the role of the OSI application layer?provides segmentation of dataprovides encryption and conversion of dataprovides the interface between the applications on either end of the network provides control of all the data flowing between the source and destination devices 17 Which application layer protocols correctly match a corresponding function? (Choose two.)DNS dynamically allocates IP addresses to hostsHTTP transfers data from a web server to a clientPOP delivers email from the client to the server email serverSMTP supports file sharingTelnet provides a virtual connection for remote access19 What are two characteristics of peer-to-peer networks? (Choose two.) scalableone way data flowdecentralized resourcescentralized user accountsresource sharing without a dedicated server20 What application layer protocol is commonly used to support for file transfers between a client and a server?HTMLHTTPFTPTelnetC42. With TCP/IP data encapsulation, which range of port numbers identifies all well-known applications?0 to 255256 to 10220 to 10231024 to 204749153 to 655353. Why are port numbers included in the TCP header of a segment?to indicate the correct router interface that should be used to forward a segmentto identify which switch ports should receive or forward the segmentto determine which Layer 3 protocol should be used to encapsulate the datato enable a receiving host to forward the data to the appropriate applicationto allow the receiving host to assemble the packet in the proper order4. Which OSI model layer is responsible for regulating the flow of information from source to destination, reliably and accurately?applicationpresentationsessiontransportnetwork6. Why is flow control used for TCP data transfer?to synchronize equipment speed for sent datato synchronize and order sequence numbers so data is sent in complete numerical orderto prevent the receiver from being overwhelmed by incoming datato synchronize window size on the serverto simplify data transfer to multiple hosts7. Which two options represent Layer 4 addressing? (Choose two.)identifies the destination networkidentifies source and destination hostsidentifies the communicating applicationsidentifies multiple conversations between the hostsidentifies the devices communicating over the local media10. What is dynamically selected by the source host when forwarding data? destination logical addresssource physical addressdefault gateway addresssource port11. What are two features of the User Datagram Protocol (UDP)? (Choose two.) flow controllow overheadconnectionlessconnection-orientedsequence and acknowledgements12. What mechanism is used by TCP to provide flow control as segments travel from source to destination?sequence numberssession establishmentwindow sizeacknowledgments13. Which transport layer protocol provides low overhead and would be used for applications which do not require reliable data delivery?TCPIPUDPHTTPDNS14. Which information is found in both the TCP and UDP header information? sequencingflow controlacknowledgmentssource and destination port15. Which three features allow TCP to reliably and accurately track the transmission of data from source to destination? (Choose three.)flow controlurgent pointerbest effort deliverysession establishmentconnectionless servicesnumbering and sequencing16. During a TCP communication session, if the packets arrive to the destination out of order, what will happen to the original message?The packets will not be delivered.The packets will be retransmitted from the source.The packets will be delivered and reassembled at the destination.The packets will be delivered and not reassembled at the destination.17. Which is an important characteristic of UDP?acknowledgement of data deliveryminimal delays in data deliveryhigh reliability of data deliverysame order data delivery18. After a web browser makes a request to a web server that is listening to the standard port, what will be the source port number in the TCP header of the response from the server?1353801024172819. Which event occurs during the transport layer three-way handshake?The two applications exchange data.TCP initializes the sequence numbers for the sessions.UDP establishes the maximum number of bytes to be sent.The server acknowledges the bytes of data received from the client.C51 What is the purpose of a default gateway?physically connects a computer to a networkprovides a permanent address to a computeridentifies the network to which a computer is connectedidentifies the logical address of a networked computer and uniquely identifies it to the rest of the networkidentifies the device that allows local network computers to communicate with devices on other networks2 What type of routing uses information that is manually entered into the routing table?dynamicinteriorstaticstandard4 Which IP packet field will prevent endless loops?type-of-serviceidentificationflagstime-to-liveheader checksum6 What is a component of a routing table entry?the MAC address of the interface of the routerthe destination Layer 4 port numberthe destination host addressthe next-hop address7 In an IPv4 environment, what information is used by the router to forward data packets from one interface of a router to another?destination network addresssource network addresssource MAC addresswell known port destination address8 What information is added during encapsulation at OSI Layer 3?source and destination MACsource and destination application protocolsource and destination port numbersource and destination IP address9 If the default gateway is configured incorrectly on the host, what is the impact on communications?The host is unable to communicate on the local network.The host can communicate with other hosts on the local network, but is unable to communicate with hosts on remote networks.The host can communicate with other hosts on remote networks, but is unable to communicate with hosts on the local network.There is no impact on communications.10 In a connectionless system, which of the following is correct?The destination is contacted before a packet is sent.The destination is not contacted before a packet is sent.The destination sends an acknowledgement to the source that indicates the packet was received.The destination sends an acknowledgement to the source that requests the next packet to be sent.11 Which portion of the network layer address does a router use to forward packets? host portionbroadcast addressnetwork portiongateway address13 When the destination network is not listed in the routing table of a Cisco router, what are two possible actions that the router might take? (Choose two.)The router sends an ARP request to determine the required next hop address.The router discards the packet.The router forwards the packet toward the next hop indicated in the ARP table.The router forwards the packet to the interface indicated by the source address.The router forwards the packet out the interface indicated by the default route entry.14 What are three common problems with a large network? (Choose three.)too few broadcastsperformance degradationsecurity issueslimited management responsibilityhost identificationprotocol compatibility15 Which three statements are true about routes and their use? (Choose three.)If no route to the destination network is found, the packet is returned to the previous router.If the destination network is directly connected, the router forwards the packet to the destination host.If multiple network entries exist for the destination network, the most general route is used to forward the packet.If no route exists for the destination network and a default route is present, the packet is forwarded to the next-hop router.If the originating host has a default gateway configured, the packet for a remote network can be forwarded using that route.If a host does not have a route manually configured for the destination network, the host will drop the packet.16 Which intermediary devices could be used to implement security between networks? (Choose two.)routerhubswitchfirewallaccess pointbridge19 What are the key factors to consider when grouping hosts into a common network? (Choose three.)gatewayspurposephysical addressingsoftware versiongeographic locationownership20 What two characteristics are commonly associated with dynamic routing protocols? (Choose two.)require no device configurationprovide routers with up-to-date routing tablesrequire less processing power than static routes requireconsume bandwidth to exchange route informationprevent manual configuration and maintenance of the routing table21. What statement describes the purpose of a default route?A host uses a default route to transfer data to another host on the same network segment.A host uses a default route to forward data to the local switch as the next hop to all destinations.A host uses a default route to identify the Layer 2 address of an end device on the local network.A host uses a default route to transfer data to a host outside the local network when no other route to the destination exists.C62 Which IPv4 subnetted addresses represent valid host addresses? (Choose three.) 172.16.4.127 /26172.16.4.155 /26172.16.4.193 /26172.16.4.95 /27172.16.4.159 /27172.16.4.207 /273 Which statements are true regarding IP addressing? (Choose two.)NAT translates public addresses to private addresses destined for the Internet.Only one company is allowed to use a specific private network address space.Private addresses are blocked from public Internet by router.Network 172.32.0.0 is part of the private address space.IP address 127.0.0.1 can be used for a host to direct traffic to itself.4 Which process do routers use to determine the subnet network address based upon a given IP address and subnet mask?binary addinghexadecimal andingbinary divisionbinary multiplicationbinary ANDing5 What is the network address of the host 172.25.67.99 /23 in binary?10101100. 00011001.01000011.0000000010101100. 00011001.01000011.1111111110101100. 00011001.01000010.0000000010101100. 00011001.01000010.0110001110101100. 00010001.01000011. 0110001010101100. 00011001.00000000.000000006 What subnet mask would a network administrator assign to a network address of 172.30.1.0 if it were possible to have up to 254 hosts?255.255.0.0255.255.255.0255.255.254.0255.255.248.07 Which three IP addresses are private? (Choose three.)172.168.33.110.35.66.70192.168.99.5172.18.88.90192.33.55.89172.35.16.58 Given the IP address and subnet mask of 172.16.134.64 255.255.255.224, which of the following would describe this address?This is a useable host address.This is a broadcast address.This is a network address.This is not a valid address.11 Which of the following network devices are recommended to be assigned static IP addresses? (Choose three.)LAN workstationsserversnetwork printersroutersremote workstationslaptops12 Which of the following are features of IPv6? (Choose three.)larger address spacefaster routing protocolsdata types and classes of serviceauthentication and encryptionimproved host naming conventionssame addressing scheme as IPv413 A router interface has been assigned an IP address of 172.16.192.166 with a mask of 255.255.255.248. To which subnet does the IP address belong?172.16.0.0172.16.192.0172.16.192.128172.16.192.160172.16.192.168172.16.192.17614 What two things will happen if a router receives an ICMP packet which has a TTL value of 1 and the destination host is several hops away? (Choose two.)The router will discard the packet.The router will decrement the TTL value and forward the packet to the next router on the path to the destination host.The router will send a time exceeded message to the source host.The router will increment the TTL value and forward the packet to the next router on the path to the destination host.The router will send an ICMP Redirect Message to the source host.16 How many bits make up an IPv4 address?12864483217 What is the primary reason for development of IPv6?securityheader format simplificationexpanded addressing capabilitiesaddressing simplification18 What three facts are true about the network portion of an IPv4 address? (Choose three.)identifies an individual deviceis identical for all hosts in a broadcast domainis altered as packet is forwardedvaries in lengthis used to forward packetsuses flat addressing19 What is a group of hosts called that have identical bit patterns in the high order bits of their addresses?an interneta networkan octeta radixC71 What is a function of the data link layer?。

ccna考试题库最新版

ccna考试题库最新版

ccna考试题库最新版CCNA(Cisco Certified Network Associate)认证是全球范围内最受欢迎的网络工程师认证之一,具备CCNA认证可以证明一个人在建立、规划、运行、安装和配置中等规模的局域网和广域网方面的专业知识。

为了帮助广大考生顺利通过CCNA考试,不断更新的CCNA考试题库至关重要。

以下是最新版本的CCNA考试题库,希望对考生们有所帮助。

第一部分:网络基础知识1. 什么是OSI七层模型?简要介绍每一层的功能。

2. TCP和UDP之间有哪些区别?请分别举例说明。

3. 什么是IP地址?IP地址的类型有哪些?请列举并简要介绍各自的特点。

4. 什么是子网掩码?为什么在网络中使用子网掩码?5. 简述常见的网络设备有哪些,以及各自的功能与作用。

第二部分:路由和交换技术1. 路由器和交换机之间有何区别?请进行比较并指出各自的优势和劣势。

2. 什么是VLAN?VLAN的作用及在网络中的应用场景是什么?3. OSPF和EIGRP是两种常见的路由协议,请比较它们的特点并举例说明。

4. 请解释静态路由和动态路由的概念以及在网络中的应用。

5. 交换机在网络中扮演什么角色?交换机的MAC地址表是如何工作的?第三部分:网络安全和管理1. 网络安全的重要性是什么?请列举几种常见的网络安全威胁并介绍应对策略。

2. 什么是ACL(访问控制列表)?ACL的作用是什么?请给出一个ACL的配置示例。

3. VPN是什么?VPN的工作原理及在企业网络中的应用。

4. SNMP是网络管理中常用的协议,它的作用是什么?请解释SNMP中的几个重要概念。

5. 如何保护无线网络的安全?请列举几种方法。

第四部分:WAN技术1. 什么是WAN?WAN的主要特点是什么?2. PPP协议和HDLC协议分别是什么?请比较它们的异同。

3. 什么是Frame Relay?Frame Relay的工作原理及在WAN中的应用。

4. 请解释T1和E1的概念,以及它们在传输速率和应用方面的差异。

2023年CCNA考试真题

2023年CCNA考试真题

2023年CCNA考试真题2023年CCNA考试正式开考啦!本次考试涉及网络技术的基础知识,将对考生的技术水平进行全面考察。

下面是本次考试的真题,希望能够帮助考生更好地复习。

【第一部分:选择题】(共10题,每题2分,共计20分)1. OSI模型中,位于网络层的协议是:A. TCPB. IPC. HTTPD. UDP2. 下面哪个命令可以查看路由表信息:A. pingB. tracertC. ipconfigD. route print3. 在IP地址192.168.0.1/24中,/24表示什么意思:A. 子网掩码B. 路由器IP地址C. 网络IDD. 主机ID4. 下面哪个协议可以实现主机与交换机之间的通信:A. BGPB. ARPC. MPLSD. SNMP5. 下面哪个命令可以查看IP地址的连通性:A. telnetB. netstatC. pingD. tracert6. VLAN是指:A. 虚拟本地区域网络B. 可视化局域网C. 个人局域网D. 无线局域网7. 下面哪个设备可以实现不同局域网之间的互联:A. 集线器B. 路由器C. 交换机D. 网桥8. 下面哪个协议负责在网络中寻找设备的物理地址:A. ARPB. ICMPC. OSPFD. BGP9. 下面哪个命令可以查看交换机的端口信息:A. show ip interface briefB. show mac-address-tableC. show running-configD. show version10. 下面哪个协议可以实现安全的远程登录:A. FTPB. HTTPC. SSHD. Telnet【第二部分:填空题】(共5题,每题4分,共计20分)1. 在OSI模型中,位于物理层的设备是_________。

2. 在TCP/IP协议族中,位于传输层的协议是_________。

3. IP地址由_________位二进制数组成。

思科第一学期期末考试最新考题CCNA1

思科第一学期期末考试最新考题CCNA1

1Refer to the exhibit。

Which Layer 2 protocol could be used inside nework A and network C?IPTCPUDPEthernet2Refer to the exhibit。

Which set of devices contains only intermediary devices?A, B,D,GA,B,E, FC, D,G,IG,H, I, J3Refer to the exhibit. The headers added at each layer are shown。

Which layer adds the destination and source process n ensure that data is delivered to the correct application?physical layerdata link layernetwork layertransport layer4The Layer 4 header contains which type of information to aid in the delivery of data?service port numberhost logical addressdevice physical addressvirtual connection identifier5Which fiber connector supports full-duplex Ethernet?6Which device should be used for routing a packet to a remote network?access switchDHCP serverhubrouter7Refer to the exhibit。

Host A sends a frame to host C with a destination MAC address CC. The MAC address for host C is n table of switch SW1. How will SW1 handle the frame?Switch SW1 will drop the frame。

CCNA考试题

CCNA考试题

C C N A考试题(总9页) -CAL-FENGHAI.-(YICAI)-Company One1-CAL-本页仅作为文档封面,使用请直接删除第一部分:选择题1:提供可靠数据传输、流控的是OSI的第几层()A、表示层B、网络层C、传输层D、会话层E、链路层2:子网掩码产生在那一层()A、表示层B、网络层C、传输层D、会话层3:当路由器接收的IP报文的目的地址不是本路由器的接口IP地址,并且在路由表中未找到匹配的路由项,采取的策略是()A、丢掉该分组B、将该分组分片C、转发该分组D、以上答案均不对4:当一台主机从一个网络移到另一个网络时,以下说法正确的是()A、必须改变它的IP地址和MAC地址B、必须改变它的IP地址,但不需改动MAC地址C、必须改变它的MAC地址,但不需改动IP地址D、MAC地址、IP地址都不需改动5:ISO提出OSI的关键是()A、系统互联B、提高网络速度C、为计算机制定标准D、经济利益6:OSI参考模型按顺序有哪些层()A、应用层、传输层、网络层、物理层B、应用层、表示层、会话层、网络层、传输层、数据链路层、物理层C、应用层、表示层、会话层、传输层、网络层、数据链路层、物理层D、应用层、会话层、传输层、物理层7:LAN的拓扑形式一般以()为主。

A、总线型B、环型C、令牌环D、载波侦听与冲突检测CSMA/CD8:网段地址154.27.0.0的网络,若不做子网划分,能支持()台主机A、254B、1024C、65,534D、16,777,2069:路由器网络层的基本功能是()。

A、配置IP地址B、寻找路由和转发报文C、将MAC地址解释成IP地址10:选出基于TCP协议的应用程序()。

A、PINGB、TFTPC、TELNETD、OSPF11:某公司申请到一个C类IP地址,但要连接6个的子公司,最大的一个子公司有26台计算机,每个子公司在一个网段中,则子网掩码应设为()。

A、255.255.255.0B、255.255.255.128C、255.255.255.192D、255.255.255.22412:B类地址的缺省掩码是()。

CCNA认证考试真题

CCNA认证考试真题

为⼤家收集整理了《CCNA认证考试真题》供⼤家参考,希望对⼤家有所帮助(1)TCP/IP Addressing and Protocol1: Your junior network administrator wants to know what the default subnet mask is for a Class C IP address. What do you tell him?A. 255.0.0.0B. 255.255.0.0C. 255.245.255.0D. 255.255.255.0E. 255.255.255.255 2: An application needs to have reliable, end-to-end connect-ivity. Which of the following protocols will give you reliable connectivity?A. TCPB. UDPC. IPD. ICMP 3: You are designing a network, which needs to support 55 users. You don't plan to extend the segment beyond the current number of users. Which subnet mask would best meet your needs?A. 255.255.0.0B. 255.255.255.0C. 255.255.255.192D. 255.255.255.160 4: You have added a new switch to your network. You want to manage it remotely, so you need to assign it an IP address. Your router that connects to the switch has an IP address of 172.16.12.33/27. Which of the following addresses can you assign to this switch?A. 172.16.12.33/28B. 172.16.12.32/27C. 172.16.12.33/27D. 172.16.12.34/27E. 172.16.12.35/28F. 172.16.12.38/28G. 172.16.12.63/27 5: The address 172.16.208.16/20 is a host address in which of the following subnets? A. 172.16.176.0–255.255.240.0B. 172.16.192.0–255.255.240.0C. 172.16.208.0–255.255.240.0D. 172.16.224.0–255.255.240.0 6: You are designing an IP address scheme for your brand new remote office. The vice president of IT calls to tell you that you will be in charge of the 192.168.1.64/26 subnetwork. This supplies you with a single subnetwork with 62 hosts. You need to have at least two subnets with 14 hosts in each subnet. What custom subnet mask should you use?A. 255.255.255.128B. 255.255.255.192C. 255.255.255.224D. 255.255.255.240E. 255.255.255.248 7: You have subnetted the 210.106.14.0 network with a /24 mask. Your boss at Acme, Inc. wants to know how many usable subnetworks and usable host addresses per subnet this would provide. What should you tell her?A. One network with 254 hostsB. Two networks with 128 hostsC. Four networks with 64 hostsD. Six networks with 30 hosts 8: Identify three valid host addresses in any subnet of the 201.168.27.0 network, assuming a fixed subnet mask of 255.255.255.240. (Choose three.)A. 201.168.27.33B. 201.168.27.112C. 201.168.27.119D. 201.168.27.126E. 201.168.27.175F. 201.168.27.208 9: What is the subnetwork address for a host with the IP address 201.100.5.68/28?A. 201.100.5.0B. 201.100.5.32C. 201.100.5.64D. 201.100.5.65E. 201.100.5.31F. 201.100.5.1 10: Which of the following protocols uses a three-way handshake mechanism to establish sessions?A. TCPB. IPC. UDPD. IPXE. Frame relay 11: Which of the following protocols is connection-oriented? A. TCPB. IPC. IPXD. Frame relay 12: You are using an application on your Windows 2000 client machines that provides error correction. You need a protocol to provide fast transport. Which protocol should your application use?A. TCPB. IPC. UDPD. SPXE. AppleTalk 13: When using TCP, after a session is open, the applications can adjust the number of segments they receive before sending an acknowledgment. This behavior is known as ______________.A. MTU adjustmentB. WindowingC. Flexible Send PathD. FCS 14: If the destination did not receive a segment, how will the TCP host know to resend the information?A. The ACK received will not include the segment number that was not received.B. The ACK received will include the segment number that was not received.C. The sending host will send a PACK to verify segment receipt.D. The destination host will send a YACK message back to the sending host. 15: You are planning on using a single network that supports 208 users. Which IP address class would you choose to be the most efficient?A. Class AB. Class BC. Class CD. Class DE. Class E 16: RFC 1918 defines the private IP address ranges. Which of the following IP addresses are considered part of these ranges? (Choose three.)A. 10.23.45.67B. 126.21.34.56C. 172.16.32.1D. 172.31.234.55E. 192.169.4.5 17: A new network is being designed for your company, Acme, Inc. If you use a Class C IP network, which subnet mask will provide one usable subnet per department while allowing enough usable host addresses for each department specified in the table?Department Number of Users Corporate 7 Customer Support 15 Financial 13 HR 7 Engineering 16 A. 255.255.255.0B. 255.255.255.192C. 255.255.255.224D. 255.255.255.240E. 255.255.255.248 18: Which of these protocols provides data transport, relying on the error correction capabilities of the application itself?A. UDPB. TCPC. SNMPD. ICMP 19: Which of the following are used by TCP to ensure reliable delivery of data? (Choose two.)A. MAC address resolutionB. Sequence numbersC. AcknowledgmentsD. PingE. Routing updates 20: You discover that you are able to adjust the window size of the TCP segment. You increase the window size to test the results. What will you observe happening on your network?A. Increased throughputB. Decreased throughputC. Increased latencyD. Decreased reliability21: Your organization is using the 192.168.1.0/24 address space. You need 28 subnets. What subnet mask would you use to create these subnets?A. 255.255.255.0B. 255.255.255.128C. 255.255.255.192D. 255.255.255.224E. 255.255.255.240F. 255.255.255.248 22: Which of the following protocols maps IP addresses to MAC addresses for connectivity to occur between two hosts?A. ARPB. RARPC. SLARPD. DHCP 23: Your junior network administrator cannot seem to ping a host in another network and asks you why it isn't working. Which of the following is not an answer that you would give him?A. The host's default gateway is down.B. The destination host is not powered on.C. The IP address of the router interface is incorrect.D. The IP address of the switch to which the destination host connects is incorrect.E. The host is in a different subnet. 24: Which of the following classes of IP addresses is utilized for multicasting?A. Class AB. Class BC. Class CD. Class D 25: You give your IT department a spreadsheet of IP addresses and their subnets. You receive a call from one of the junior techs asking what the /26 means next to the IP addresses. You tell her: A. It represents the number of hosts possible on that subnetwork.B. It represents the number of subnetworks that are being used.C. It represents the class of IP address being used.D. It represents the number of bits in the subnet mask that are 1. 26: You are given an IP network of 192.168.5.0 and told that you need to separate this network into subnetworks that can support a maximum of 16 hosts per subnet. This will help alleviate congestion on the network. What subnet mask can you use to create the subnets necessary to meet the given criteria?A. 255.0.0.0B. 255.255.0.0C. 255.255.255.0D. 255.255.255.224E. 255.255.255.240 27: Which of the following would a Class A network be assigned to?A. Government agencyB. Small-to-medium sized corporationD. An individual 28: A client has the IP address 192.168.5.98/27. Which of the following addresses are on the same subnet as this host? (Choose two.)A. 192.168.5.95B. 192.168.5.100C. 192.168.5.128D. 192.168.5.110 29: Which of the following IP addresses is not a public IP address that can be routed over the Internet?A. 2.3.4.5B. 11.12.13.14C. 165.23.224.2D. 172.31.45.34E. 203.33.45.22 30: You are given a Class B network. What is the default subnet mask assigned to the Class B network?A. 255.255.255.255B. 255.255.0.0C. 255.224.0.0D. 0.0.0.0 31: You are troubleshooting your router's interfaces. For some reason, the Ethernet interface will not accept the IP address of 192.168.5.95/27 that you've assigned. Which of the following explains the router's refusal to take the IP address?A. Class C addresses cannot be assigned to Ethernet interfaces.B. The /27 is an invalid mask.C. It is a broadcast address.D. It is a public IP address.E. It is a private IP address. 32: You are a network technician at Acme, Inc. You are required to divide the 172.12.0.0 network into subnets. Each subnet must have the capacity of 458 IP addresses. Also, according to the requirements, you must provide the maximum number of subnets. Which subnet mask should you use?A. 255.255.255.254B. 255.255.254.0C. 255.255.240.254D. 255.255.0.0 33: What is the subnetwork and broadcast IP address of 192.168.2.37 with the subnet mask of255.255.255.248?A. 192.168.2.24/192.168.2.31B. 192.168.2.32/192.168.2.39C. 192.168.2.40/192.168.2.47D. 192.168.2.48/192.168.2.55E. 192.168.2.56/192.168.2.63 34: One of your co-workers at Acme, Inc., needs to convert the binary number 11011010 into a decimal. What is the decimal equivalent?A. 218B. 219C. 220E. 222 35: One of your co-workers at Acme, Inc., needs to convert the binary number 01011010 into a decimal. What is the decimal equivalent?A. 75B. 83C. 90D. 97 36: One of your co-workers at Acme, Inc., needs to convert the binary num b e r 1 1 0 1 0 1 1 0 i n t o a d e c i m a l . W h a t i s t h e d e c i m a l e q u i v a l e n t ? / p > p b d s f i d = " 2 1 0 " > A . 1 9 8 / p > p b d s f i d = " 2 1 1 " > B . 2 1 4 / p > p b d s f i d = " 2 1 2 " > C . 2 5 2 / p > p b d s f i d = " 2 1 3 " > D . 2 5 5 3 7 : O n e o f y o u r c o - w o r k e r s a t A c m e , I n c . , n e e d s t o c o n v e r t t h e b i n a r y n u m b e r 1 0 1 1 0 1 1 0 i n t o a d e c i m a l . W h a t i s t h e d e c i m a l e q u i v a l e n t / p > p b d s f i d = " 2 1 4 " > A . 1 8 2 / p > p b d s f i d = " 2 1 5 " > B . 1 9 2 / p > p b d s f i d = " 2 1 6 " > C . 2 0 2 / p > p b d s f i d = " 2 1 7 " > D . 2 1 2 3 8 : Y o u a r e c o n f i g u r i n g a s u b n e t f o r t h e A c m e , I n c . , b r a n c h o f f i c e i n B e i j i n g . Y o u n e e d t o a s s i g n I P a d d r e s s e s t o h o s t s i n t h i s s u b n e t . Y o u h a v e b e e n g i v e n t h e s u b n e t m a s k o f 2 5 5 . 2 5 5 . 2 5 5 . 2 2 4 . W h i c h o f t h e s e I P a d d r e s s e s w o u l d b e v a l i d ? ( C h o o s e t h r e e . ) / p > p b d s f i d = " 2 1 8 " > A . 1 5 . 2 3 4 . 1 1 8 . 6 3 / p > p b d s f i d = " 2 1 9 " > B . 9 2 . 1 1 . 1 7 8 . 9 3 / p > p b d s f i d = " 2 2 0 " > C . 1 3 4 . 1 7 8 . 1 8 . 5 6 / p > p b d s f i d = " 2 2 1 " > D . 1 9 2 . 1 6 8 . 1 6 . 8 7 / p > p b d s f i d = " 2 2 2 " > E . 2 0 1 . 4 5 . 1 1 6 . 1 5 9 / p > p b d s f i d = " 2 2 3 " > F . 2 1 7 . 6 3 . 1 2 . 1 9 2 3 9 : Y o u a r e a n e t w o r k t e c h n i c i a n a t A c m e , I n c . Y o u h a v e s u b n e t t e d t h e 2 0 8 . 9 8 . 1 1 2 . 0 n e t w o r k w i t h a / 2 8 m a s k . Y o u r b o s s a s k s y o u h o w m a n y u s a b l e s u b n e t w o r k s a n d u s a b l e h o s t a d d r e s s e s p e r s u b n e t t h i s w i l l p r o v i d e . W h a t s h o u l d y o u t e l l h e r , a s s u m i n g y o u r r o u t e r i s u s i n g i p s u b n e t - z e r o ? / p > p b d s f i d = " 2 2 4 " > A . 62 n e t w o r k s a n d 2 h o s t s / p > p b d s f i d = " 2 2 5 " > B . 6 n e t w o r k s a n d3 0 h o s t s / p > p b d s f i d = " 2 2 6 " >C . 8 n e t w o r k s a n d 3 2 h o s t s / p > p b d s f i d = " 2 2 7 " >D . 1 6 n e t w o r k s a n d 1 6 h o s t s / p > p b d s f i d = " 22 8 " > E . 1 6 n e t w o r k s a n d 1 4 h o s t s 4 0 : W h a t i s a d i s a d v a n t a g e o f u s i n g a c o n n e c t i o n - o r i e n t ed p r o t o c o l s u c h a s T C P ? / p > p b d s f i d = " 2 2 9 " > A . P a c ke t a c k n o w l e d g m e n t m i g h t a d d o v e r h ea d . / p > pb d s f i d = " 2 3 0 " > B . P ac k e t s a r e n o t t a g g ed w i t h se q u e n c e n u m b e r s . / p > p b d sf i d = " 23 1 " > C . L o s s o r d u p l i c a t i o n o f d a t a p a c k e t s i s m o r e l i k e l y t o o c c u r . / p > p b d s f i d = " 2 3 2 " > D . Th e a p p l i c a t i o n l a y e r m u s t a s s u m e r e s p o n s i b i l i t y f o r t h e c o r r e c t s e q u e n c i n g o f t h e d a t a p ac k e t s . 4 1 : Y o u a r e a n e t w o r k t e c h n i c i a n a t A c m e , I n c . Y o u h a v e s u b n e t t ed t he 1 9 2 . 1 6 8 . 7 2 .0 n e t w o r k w i t h a / 3 0 m a s k f o r c o n n e c t i o n s b e t w e e n y o u r r o u t e r s . Y o u r b o s s a s k s y o u h o w m a n y u s a b l e s u b n e t w o r k s a n d u s a b l e h o s t a d d r e s s e s p e r s u b n e t t h i s w i l l p r o v i d e . W h a t s h o u l d y o u t e l l h e r , a s s u m i n g y o u r r o u t e r c a n n o t u s e i p s u b n e t - z e r o ? / p > p b d s f i d = " 2 3 3 " > A . 6 2 n e t w o r k s a n d 2 h o s t s / p > p b d s f i d = " 2 3 4 " > B . 6 n e t w o r k s a n d 3 0 h o s t s / p > p b d s f i d = " 2 3 5 " > C .8 n e t w o r k s a n d 3 2 h o s t s / p > p b d s f i d = " 2 3 6 " > D . 1 6 n e t w o r k s a n d 1 6 h o s t s / p > p b d s f i d = " 2 3 7 " > E . 1 4 n e t w o r k s a n d 1 4 h o s t s 4 2 : W h i c h o f t h e f o l l o w i n g I P a d d r e s s e s a r e c o n s i d e r e d " n e t w o r k " a d d r e s s e s w i t h a / 2 6 p r e f i x ? ( C h o o s e t w o . ) / p > p b d s f i d = " 2 3 8 " > A . 1 6 5 . 2 0 3 . 2 . 0 / p > p b d s f i d = " 2 3 9 " > B . 1 6 5 . 2 0 3 . 5 . 1 9 2 / p > p b d s f i d = " 2 4 0 " > C . 1 6 5 . 2 0 3 . 6 . 6 3 / p > p b d s f i d = " 2 4 1 " > D . 1 6 5 . 2 0 3 . 6 . 1 9 1 / p > p b d s f i d = " 2 4 2 " > E . 1 6 5 . 2 0 3 . 8 . 2 5 5 4 3 : I d e n t i f y t h r e e v a l i d h o s t s i n a n y s u b n e t o f 1 9 2 . 1 6 8 . 3 2 . 0 , a s s u m i n g t h e s u b n e t m a s k u s e d i s 2 5 5 . 2 5 5 . 2 5 5 . 2 4 0 . ( C h o o s e t h r e e . ) / p > p b d s f i d = " 2 4 3 " > A . 1 9 2 . 1 6 8 . 3 2 . 3 3 / p > p b d s f i d = " 2 4 4 " > B . 1 9 2 . 1 6 8 . 3 2 . 1 1 2 / p > p b d s f i d = " 2 4 5 " > C . 1 9 2 . 1 6 8 . 3 2 . 1 1 9 / p > p b d s f i d = " 2 4 6 " > D . 1 9 2 . 1 6 8 . 3 2 . 1 2 6 / p > p b d s f i d = " 2 4 7 " > E . 1 9 2 . 1 6 8 . 3 2 . 1 7 5 / p > p b d s f i d = " 2 4 8 " > F . 1 9 2 . 1 6 8 . 3 2 . 2 0 8 4 4 : A C l a s s C n e t w o r k a d d r e s s h a s b e e n s u b n e t t e d w i t h a / 2 7 m a s k . W h i c h o f t h e f o l l o w i n g a d d r e s s e s i s a b r o a d c a s t a d d r e s s f o r o n e o f t h e r e s u l t i n g s u b n e t s ? / p > p b d s f i d = " 2 4 9 " > A . 1 9 8 . 5 7 . 7 8 . 3 3 / p > p b d s fi d = " 2 5 0 " > B . 1 9 8 . 5 7 . 7 8 . 6 4 / p > p b d s f i d = " 2 5 1 " > C . 1 9 8 . 5 7 . 7 8 . 9 7 / p > p b d s f i d = " 2 5 2 " > D . 1 98 . 5 7 . 7 8 . 9 7 / p > p b d s f i d = " 2 5 3 " > E . 1 9 8 . 5 7 . 7 8 . 1 5 9 / p > p b d s f i d = " 2 5 4 " > F . 1 9 8 . 5 7 . 7 8 . 2 5 4 4 5 : W h a t i s t h e s u b n e t w o r k a d d r e s s f o r a h o s t w i t h I P a d d r e s s 1 6 5 . 1 0 0 . 5 . 6 8 / 2 8 ? / p > p b d s f i d = " 2 5 5 " > A . 1 6 5 . 1 0 0 . 5 . 0 / p > p b d s f i d = " 2 5 6 " > B . 1 6 5 . 1 0 0 . 5 . 3 2 / p > p b d s f i d = " 2 5 7 " > C . 1 6 5 . 1 0 0 . 5 . 6 4 / p > p b d s f i d = " 2 5 8 " > D . 1 6 5 . 1 0 0 . 5 . 6 5 / p > p b d s f i d = " 2 5 9 " > E . 1 6 5 . 1 0 0 . 5 . 3 1 / p > p b d s f i d = " 2 6 0 " > F . 1 6 5 . 1 0 0 . 5 . 1 4 6 : Y o u r b o s s w a n t s t o k n o w w h a t T C P s t a n d s f o r . W h a t d o y o u t e l l h i m ? / p > p b d s f i d = " 2 6 1 " > A . T r a n s m i s s i o n C h e c k P r o t o c o l / p > p b d s f i d = " 2 6 2 " > B . T r a n s p o r t C h e c k P r o t o c o l / p > p b d s f i d = " 2 6 3 " > C . T r a n s m i s s i o n C o n t r o l P r o t o c o l / p > p b d s f i d = " 2 6 4 " > D . T r a n s p o r t C o n t r o l P r o t o c o l 4 7 : Y o u r b o s s w a n t s t o k n o w w h a t U D P s t a n d s f o r . W h a t d o y o u t e l l h i m ? / p > p b d s f i d = " 2 6 5 " > A . U n r e l i a b l e D a t a P r o t o c o l / p > p b d s f i d = " 2 6 6 " > B . U n r e l i a b l e D a t a P r o g r a m / p > p b d s f i d = " 2 6 7 " > C . U s e r - D e f i n e d P r o t o c o l / p > p b d s f i d = " 2 6 8 " > D . U s e r D a t a g r a m P r o t o c o l 4 8 : W h i c h o f t h e f o l l o w i n g s t a t e m e n t s a c c u r a t e l y d e s c r i b e s U D P ? / p > p b d s f i d = " 2 6 9 " > A . U D P c o p i e s f i l e s b e t w e e n a c o m p u t e r a n d a s y s t e m r u n n i n g r s h d , t h e r e m o t e s h e l l s e r v i c e ( d a e m o n ) . / p > p b d s f i d = " 2 7 0 " > B . U D P i s a m e m b e r o f t h e T C P / I P s u i t e o f p r o t o c o l s t h a t g o v e r n s t h e e x c h a n g e o f e l e c t r o n i c m a i l b e t w e e n m e s s a g e t r a n sf e r ag e n t s . / p > p b d s f i d = " 2 7 1 " > C . U D P i s a m e m b e r o f th e T C P / I P s ui t e o f p r o t o c o l s a n d i s u s e d t o c o p y f i l e s b e t w e e n t w o c o m p u t e r s o n t h e I n t e r n e t . B o t h c o m p u t e r s m u s t s u p p o r t t h e i r r e s p e c t i v e r o l e s : o n e m u s t b e a c l i e n t , a n d t h e o t h e r a s e r v e r . / p > p b d s f i d = " 2 7 2 " > D . U D P i s a T C P c o m p l e m e n t t h a t o f f e r s a c o n n e c t i o n l e s s d a t a g r a m s e r v i c e g u a r a n t e e i n g n e i t h e r d e l i v e r y n o r c o r r e c t s e q u e n c i n g o f d e l i v e r e d p a c k e t s ( m u c h l i k e I P ) . 4 9 : W h i c h o f t h e f o l l o w i n g h o s t a d d r e s s e s a r e m e m b e r s o f n e t w o r k s t h a t c a n b e r o u t e d a c r o s s t h e p u b l i c I n t e r n e t ( C h o o s e t h r e e . ) / p > p b d s f i d = " 2 7 3 " > A . 1 0 . 2 0 . 1 2 . 6 4 / p > p b d s f i d = " 2 7 4 " > B . 1 7 2 . 1 6 . 3 2 . 12 9 / p > p b d s f i d = " 2 7 5 " > C . 1 7 2 . 6 4 .3 2 . 34 / p > p b d s f i d = " 2 7 6 " > D . 1 9 2 . 1 6 8 . 2 3 . 25 2 / p > p b d s f id = " 2 7 7 " > E . 1 9 6 . 1 0 4 . 1 2 . 9 5 / p > p b d s f i d = " 2 7 8 " > F . 2 1 4 . 1 9 2 . 4 8 . 2 5 4 5 0 : Y o u a re c o n n e c t i n g y o u r S e r i a l 0 / 1 i n t e rf a c e t o t h e I n t e r n e t . W h i c h o f t h e f o l l o w i ng n e e d t o b e d o n e f o r th e c o n n e c ti o n t o w o r k ? ( C h o o s e t w o . ) / p > p b d s f i d = " 2 7 9 " > A . A s s i g n a p u b l i c I P a d d r e s s . / p > p b d s f i d = " 2 8 0 " > B . U s e t h e s h u t d o w n c o m m a n d . / p > p b d s f i d = " 2 8 1 " > C . U s e t h e n o s h u t d o w n c o m m a n d . / p > p b d s f i d = " 2 8 2 " > D . M a k e s u r e t h e i n t e r f a c e i s r u n n i n g i n f u l l - d u p l e x . / p >。

ccna考试题及答案

ccna考试题及答案

ccna考试题及答案1. 以下哪项是网络层的功能?A. 路由选择B. 错误检测C. 流量控制D. 封装数据包答案:A2. 在OSI模型中,哪一层负责在网络中传输数据?A. 应用层B. 传输层C. 会话层D. 网络层答案:D3. 以下哪个协议是用于在IP网络中发现网络设备的?A. ARPB. RARPC. ICMPD. OSPF答案:A4. 在TCP/IP模型中,哪一层与OSI模型的传输层相对应?A. 应用层B. 互联网层C. 网络接口层D. 传输层答案:D5. 以下哪个地址是一个有效的IPv4地址?A. 192.168.1.256B. 192.168.1.1C. 10.0.0.0D. 172.16.300.1答案:B6. 在配置路由器时,以下哪个命令用于进入全局配置模式?A. enableB. configure terminalC. privileged execD. user exec答案:B7. 以下哪个命令用于在Cisco设备上显示当前配置?A. show running-configB. show startup-configC. show configD. show current-config答案:A8. 在Cisco设备上,以下哪个命令用于保存当前的配置到启动配置文件?A. copy running-config startup-configB. copy startup-config running-configC. save running-configD. save startup-config答案:A9. 以下哪个命令用于在Cisco设备上查看所有接口的状态?A. show interfacesB. show ip interface briefC. show interface statusD. show running-config interface答案:B10. 在Cisco设备上,以下哪个命令用于关闭接口?A. shutdownB. no shutdownC. disableD. no enable答案:A11. 以下哪个命令用于在Cisco设备上启用接口?A. shutdownB. no shutdownC. disableD. no enable答案:B12. 在配置静态路由时,以下哪个命令用于指定下一跳地址?B. ip static-routeC. route ipD. static-route ip答案:A13. 以下哪个命令用于在Cisco设备上清除ARP表?A. clear arp-cacheB. clear arpC. clear arp tableD. clear ip arp答案:D14. 在配置动态路由协议时,以下哪个命令用于在接口上启用RIP?A. ip rip enableB. ip rip receiveD. network rip答案:C15. 以下哪个命令用于在Cisco设备上查看RIP路由表?A. show ip ripB. show ip route ripC. show ripD. show ip protocols答案:B16. 在配置EIGRP时,以下哪个命令用于指定自动汇总?A. metric weightsB. auto-summaryC. network auto-summaryD. no auto-summary答案:B17. 以下哪个命令用于在Cisco设备上查看EIGRP邻居?A. show ip eigrp neighborsB. show eigrp neighborsC. show ip eigrpD. show eigrp interfaces答案:A18. 在配置OSPF时,以下哪个命令用于指定路由器ID?A. router-idB. router ospfC. networkD. area答案:A19. 以下哪个命令用于在Cisco设备上查看OSPF路由表?A. show ip ospfB. show ip ospf databaseC. show ospfD. show ip route ospf答案:D20. 在配置VLAN时,以下哪个命令用于创建一个新的VLAN?A. vlan databaseB. configure terminalC. vlan [vlan-id]D. new-vlan答案:C21. 以下哪个命令用于将接口分配给VLAN?A. switchport mode accessB. switchport mode trunkC. switchport access vlan [vlan-id]D. switchport trunk vlan [vlan-id]答案:C22. 在配置交换机时,以下哪个命令用于将接口设置为Trunk 模式?A. switchport mode accessB. switchport mode trunkC. switchport access vlan [vlan-id]D. switchport trunk vlan [vlan-id]答案:B23. 以下哪个命令用于在Cisco设备上查看VLAN配置?A. show vlanB. show vlan briefC. show vlan detailD. show vlan all答案:B24. 在配置VTP时,以下哪个命令用于将交换机设置为VTP服务器模式?A. vtp mode serverB. vtp mode clientC. vtp mode transparentD. vtp mode off答案:A25. 以下哪个命令用于在Cisco设备上查看VTP状态?A. show vtp statusB. show vtp statisticsC. show vtp passwordD. show vtp configuration答案:A26. 在配置STP时,以下哪个命令用于设置根桥?A. spanning-tree root primaryB. spanning-tree root secondaryC. spanning-tree root primary [priority]D. spanning-tree root secondary [priority]答案:C27. 以下哪个命令用于在Cisco设备上查看STP状态?A. show spanning-treeB. show spanning-tree detailC. show spanning-tree summaryD. show spanning-tree interface答案:A28. 在配置VLAN Trunking Protocol (VTP) 时,以下哪个命令用于设置VTP域名?A. vtp domain [domain-name]B. vtp password [password]C. vtp mode [mode]D. vtp version [version]答案:A29. 以下哪个命令用于在Cisco设备上查看当前的VTP版本?A. show vtp statusB. show vtp statisticsC. show vtp passwordD. show vtp configuration答案:A30. 在配置端口安全时,以下哪个命令用于限制接口上可以学习到的最大MAC地址数量?A. switchport port-security maximum [mac-count]B. port-security maximum [mac-count]C. switchport port-security violation restrictD. port-security violation shutdown答案:A这些题目和答案仅供学习和参考之用,实际的CCNA考试内容和形式可能会有所不同。

CCNA认证试题(中文+答案)

CCNA认证试题(中文+答案)

CCNA认证试题一(附答案和解析)中文版(一)1、目前,我国应用最为广泛的LAN标准是基于()的以太网标准.(A) IEEE 802。

1(B) IEEE 802。

2(C) IEEE 802.3(D)IEEE 802.5答案:C参考知识点:现有标准:IEEE 802.1 局域网协议高层IEEE 802.2 逻辑链路控制IEEE 802。

3 以太网IEEE 802.4 令牌总线IEEE 802。

5 令牌环IEEE 802.8 FDDIIEEE 802。

11 无线局域网记住IEEE802.1-——-—--IEEE802。

5的定义以太网是一种计算机局域网组网技术.IEEE制定的IEEE 802。

3标准给出了以太网的技术标准.它规定了包括物理层的连线、电信号和介质访问层协议的内容。

以太网是当前应用最普遍的局域网技术.它很大程度上取代了其他局域网标准,如令牌环、FDDI和ARCNET。

以太网的标准拓扑结构为总线型拓扑,但目前的快速以太网(100BASE—T、1000BASE-T标准)为了最大程度的减少冲突,最大程度的提高网络速度和使用效率,使用交换机(Switch)来进行网络连接和组织,这样,以太网的拓扑结构就成了星型,但在逻辑上,以太网仍然使用总线型拓扑的C***A/CD介质访问控制方法.电气电子工程师协会或IEEE(Institute of Electrical and Electronics Engineers)是一个国际性的电子技术与信息科学工程师的协会.建会于1963年1月1日。

总部在美国纽约市。

在150多个国家中它拥有300多个地方分会。

目前会员数是36万.专业上它有35个专业学会和两个联合会。

IEEE发表多种杂志,学报,书籍和每年组织300多次专业会议。

IEEE定义的标准在工业界有极大的影响.下面列出:IEEE802.3以太网标准802。

3--——---—— 10Base以太网标准802.3u-—------ 100Base-T(快速以太网)802.3z—-—————— 1000Base-X(光纤吉比特以太网)802.3ab———-——-— 1000Base—T(双绞线吉比特以太网)2、对于这样一个地址,192。

ccnp测试题及答案

ccnp测试题及答案

ccnp测试题及答案1. 在CCNP认证中,关于VLAN的以下哪个说法是正确的?A. VLAN是将交换机端口划分为多个广播域B. VLAN是将路由器端口划分为多个广播域C. VLAN是将无线接入点划分为多个广播域D. VLAN是将服务器划分为多个广播域答案:A2. 在Cisco网络设备中,哪个命令用于创建一个新的VLAN?A. `switchport mode access`B. `switchport mode trunk`C. `vlan database`D. `configure terminal`答案:C3. 以下哪个协议用于在不同VLAN之间路由?A. EIGRPB. OSPFC. RIPD. VTP答案:A4. 在Cisco设备上,如何将接口配置为Trunk模式?A. `switchport mode access`B. `switchport mode trunk`C. `interface vlan 1`D. `interface fastethernet 0/1`答案:B5. 以下哪个命令用于在Cisco设备上查看VLAN信息?A. `show vlan`B. `show interfaces`C. `show ip interface brief`D. `show running-config`答案:A6. 在CCNP考试中,关于EIGRP协议的以下哪个说法是错误的?A. EIGRP是一个距离矢量路由协议B. EIGRP使用DUAL算法计算最短路径C. EIGRP支持VLSM和CIDRD. EIGRP仅在Cisco设备上可用答案:D7. 在Cisco设备上,如何配置EIGRP的自动汇总?A. `router eigrp 100`B. `no auto-summary`C. `ip summary-address eigrp 100 0.0.0.0 0.0.0.0`D. `metric weights 0 1 1 1 0 0 0 1`答案:C8. 以下哪个命令用于在Cisco设备上查看EIGRP邻居?A. `show ip eigrp neighbors`B. `show ip ospf neighbors`C. `show ip rip neighbors`D. `show ip eigrp interface`答案:A9. 在CCNP考试中,关于OSPF协议的以下哪个说法是正确的?A. OSPF仅在Cisco设备上可用B. OSPF使用RIP算法计算最短路径C. OSPF支持VLSM和CIDRD. OSPF使用广播来发现邻居答案:C10. 在Cisco设备上,如何配置OSPF的Hello和Dead间隔?A. `ip ospf hello-interval 10`B. `ip ospf dead-interval 40`C. `timers 10 40`D. `ospf hello-interval 10 dead-interval 40`答案:C结束语:以上是CCNP测试题及答案,希望对您的学习和准备有所帮助。

思科CCNA第三学期期末考试完整版

思科CCNA第三学期期末考试完整版

参加考试-ESwitchingFinalExam-CCNAExploration:LAN交换和无线(版本4.0)以下哪项参数用于唯一标识一个无线网络,使其与其它网络区分开来?SSIDOFDMWEPDSSS分层网络模型具有哪三项优点?(选择三项。

)带宽争用现象减少物理布局范围减小网络的容错能力提高无需配线间无需第三层功能管理和故障排除工作简化在将Catalyst交换机迁移到其它VTP管理域之前,应该进行哪三项任务?(项。

)选择正确的VTP模式和版本。

使用新管理域的名称配置交换机。

从新域中的VTP服务器上下载VTP数据库。

配置新域内的VTP服务器,使其识别该交换机的BID。

重置VTP计数器,使交换机可与新域内的其它交换机同步。

检验交换机的配置修订版号是否比新域内的其它交换机的低。

下列哪两种说法正确地描述了生成树协议?(选择两项。

)它只在第2层使用。

它在交换机上配置。

它消除了网络拓扑中的第2层环路。

它限制了端口上所允许的有效MAC地址的数量。

它使VLAN信息得以传播到网络中的其它交换机。

下列哪种方法可建立用于配置LinksysWRT300N无线接入点的管理连接?与接入点关联,然后与接入点建立超级终端会话。

以物理方式连接到接入点,然后重新启动计算机以启动配置软件。

在接入点所在的IP子网内的计算机上的web浏览器中输入接入点的默认址。

修改与接入点连接的计算机的TCP/IP属性,使其与接入点处于同一个然后重新启动计算机以建立连接。

请参见图示。

源地址并非0019.d2e4.d9f7的帧进入接口Fa0/24时会发生什么Fa0/24会变为error-disabled(错误-禁用)状态。

传入帧会被丢弃。

Fa0/24端口LED会关闭。

安全违规计数会增加。

可采用哪两种方法删除交换机的MAC地址表中的条目?(选择两项。

)关闭交换机电源并再次打开以清除所有动态获知的地址。

可采用clearswitching-tables命令删除静态配置的条目。

2022年CCNA认证试题及答案

2022年CCNA认证试题及答案

2022年CCNA认证试题及答案1、目前,我国应用最为广泛的LAN标准是基于()的以太网标准.(A) IEEE 802.1(B) IEEE 802.2(C) IEEE 802.3(D) IEEE 802.5答案:C参考知识点:现有标准:IEEE 802.1 局域网协议高层IEEE 802.2 逻辑链路控制IEEE 802.3 以太网IEEE 802.4 令牌总线IEEE 802.5 令牌环IEEE 802.8 FDDIIEEE 802.11 无线局域网记住.1-------.5的定义以太网是一种计算机局域网组网技术。

IEEE制定的IEEE 802.3标准给出了以太网的技术标准。

它规定了包括物理层的连线、电信号和介质访问层协议的内容。

以太网是当前应用最普遍的局域网技术。

它很大程度上取代了其他局域网标准,如令牌环、FDDI和ARCNET。

以太网的标准拓扑结构为总线型拓扑,但目前的快速以太网(100BASE-T、1000BASE-T标准)为了最大程度的减少冲突,最大程度的提高网络速度和使用效率,使用交换机(Switch)来进行网络连接和组织,这样,以太网的拓扑结构就成了星型,但在逻辑上,以太网仍然使用总线型拓扑的C某某某A/CD介质访问控制方法。

电气电子工程师协会或IEEE(Institute of Electrical and Electronics Engineers)是一个国际性的电子技术与信息科学工程师的协会。

建会于1963年1月1日。

总部在美国纽约市。

在150多个国家中它拥有300多个地方分会。

目前会员数是36万。

专业上它有35个专业学会和两个联合会。

IEEE发表多种杂志,学报,书籍和每年组织300多次专业会议。

IEEE定义的标准在工业界有极大的影响。

下面列出:.3以太网标准802.3--------- 10Base以太网标准802.3u-------- 100Base-T(快速以太网)802.3z-------- 1000Base-某(光纤吉比特以太网)802.3ab-------- 1000Base-T(双绞线吉比特以太网)2、对于这样一个地址,192.168.19.255/20,下列说法正确的是: ( )(A) 这是一个广播地址(B) 这是一个网络地址(C) 这是一个私有地址(D) 地址在192.168.19.0网段上(E) 地址在192.168.16.0网段上(F) 这是一个公有地址答案:CE注:IP地址中关键是看她的主机位,将子网掩码划为二进制,1对应上面的地址是网络位,0对应的地址是主机位192.168.19.255/20划为二进制为:..00010011. (00000000)主机位变成全0表示这个IP的.网络地址主机槐涑扇?表示这个IP的广播地址文件规定了保留作为局域网使用的私有地址:10.0.0.0 - 10.255.255.255 (10/8 prefi某)172.16.0.0 - 172.31.255.255 (172.16/12 prefi某)192.168.0.0 - 192.168.255.255 (192.168/16 prefi某)3、Quidway系列路由器在执行数据包转发时,下列哪些项没有发生变化(假定没有使用地址转换技术)?( )(A) 源端口号(B) 目的端口号(C) 源网络地址(D) 目的网络地址(E) 源MAC地址(F) 目的MAC地址答案:ABCD参考知识点:路由功能就是指选择一条从源网络到目的网络的路径,并进行数据包的转发。

思科 ccna第三册final试题及答案

思科 ccna第三册final试题及答案

思科第三册final 试题及答案1请参见图示。

下列哪三种说法描述了 Host1 和 Host2 无法通信的原因?(选择三项。

)交换机端口处于不同的 VLAN 中。

交换机的 IP 地址在错误的子网中。

主机被配置在不同的逻辑网络中。

需要路由器在 Host1 与 Host2 之间转发流量。

每个 VLAN 中的 VLAN 端口必须连续分配。

主机的默认网关地址必须处于同一个逻辑网络中。

2请参见图示。

主机 PC_A 和主机 PC_B 同时发送流量,来自这两台发送站的帧发生了冲突。

最突信号的是哪台设备?集线器 HB1交换机 SW1路由器 R1交换机 SW2路由器 R2交换机 SW43请参见图示。

在生成树协议中,“学习”表示什么意思?交换机正在发送并接收数据帧。

交换机并未接收 BPDU,但正在发送并接收数据。

交换机正在通过转发收到的 BPDU 参与选举过程。

交换机正在接收 BPDU 并填充 MAC 地址表,但并未发送数据。

4请参见图示。

RTB 被配置为进行传统的 VLAN 间路由。

RTB 可以 ping 通计算机 A 但无法 pin 机 B。

此故障的原因可能是什么?Fa0/11 端口处于错误的 VLAN 中。

RTB 上没有有效的路由协议。

计算机 B 的 IP 地址在错误的逻辑网络中。

路由器的 Fa0/1 接口上配置了错误的中继封装类型。

5请参见图示。

网络管理员已将网络划分为两个 VLAN,R1 和 S1 的配置如图所示。

但是,PC1 无法问题很可能出在哪里?R1 上未配置路由协议。

S1 的 Fa0/1 端口不是中继端口。

S1 上未设置默认网关地址。

S1 和 R1 之间只配置了一条物理链路用于 VLAN 间路由。

6单臂路由器 VLAN 间路由有哪三项特征?(选择三项。

)需要使用 VTP需要使用子接口减少广播域的数量使用过多 VLAN 时会影响性能需要在路由器和至少一台交换机之间采用接入链路比用于 VLAN 间路由的其它方法更加经济规定至少要在路由器和交换机之间使用两个交换机端口7请参见图示。

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Cisco CCNA 认证考试最新真题体验1. The command frame-relay map ip 10.121.16.8 102 broadcast was entered on the router. Which of the following statements is true concerning this command?A.This command should be executed from the global configuration mode.B.The IP address 10.121.16.8 is the local router port used to forward data.C.102 is the remote DLCI that will receive the information.D.The broadcast option allows packets, such as RIP updates, to be forwarded across the PVC2. While troubleshooting a network connectivity problem, a technician observes steady link lights on both the workstation NIC and the switch port to which the workstation is connected. However, when the ping command is issued from the workstation, the output message "Request timed out." is displayed. At which layer of the OSI model does the problem most likely exist?A.the session layerB.the network layerC.the data link layerD.the access layer3. In order to allow the establishment of a Telnet session with a router, which set of commands must be configured?A.router(config)# line console 0router(config-line)# enable password ciscoB.router(config)# line console 0router(config-line)# enable secret ciscorouter(config-line)# loginC.router(config)# line console 0router(config-line)# password ciscorouter(config-line)# loginD.router(config)# line vty 0router(config-line)# password cisco router(config-line)# login4. On point-to-point networks, OSPF hello packets are addressed to which address?A.127.0.0.1B.192.168.0.5C.224.0.0.5D.254.255.255.2555. What should be part of a comprehensive network security plan?A.Allow users to develop their own approach to network security.B.Physically secure network equipment from potential access by unauthorized individualsC.Encourage users to use personal information in their passwords to minimize the likelihood of passwords being forgottenD.Delay deployment of software patches and updates until their effect on end-user equipment is well known and widely reported6. During startup, the router displays the following error message:boot: cannot open "flash:" What will the router do next?A.Because of damaged flash memory, the router will fail the POST.B.It will attempt to locate the IOS from a TFTP server. If this fails, it will initiate the setup dialogC.It will attempt to locate the IOS from a TFTP server. If this fails, it will load a limited IOS from ROM.D.It will attempt to locate the configuration file from a TFTP server. If this fails, it will initiate the setup dialog7. At which OSI layer is a logical path created between two host systems?A.sessionB.transportworkD.physical8. A routing protocol is required that supports:1) routing update authentication2) an addressing scheme that conserves IP addresses3) multiple vendors4) a network with over 50 routersWhich routing protocol fulfills these requirements?A.RIPv1B.RIPv2C.EIGRPD.OSPF9. When a new trunk is configured on a 2950 switch, which VLANs by default are allowed over the trunk link?A.no VLANsB.all VLANsC.only VLANs 1 - 6D.only the VLANs that are specified when creating the trunk10. Which protocol provides a method of sharing VLAN configuration information between switches?A.VTPB.STPC.ISLD.802.1QDBDCB CCDBA博主的更多文章>>CCNA第一学期《Final Examination》2009-02-27 08:58:47 标签:CCNA[推送到技术圈]1请参见图示。

下列哪组设备仅包含中间设备?A、B、D、GA、B、E、FC、D、G、IG、H、I、J2您所在的网际网络发生了路由问题。

要鉴别此错误,应该检查以下哪种类型的设备?接入点主机路由器交换机3请参见图示。

技术人员正在处理网络问题,需要验证路由器的LAN 接口。

要确认路由器接口工作正常,应该从此主机ping 哪个地址?127.0.0.1192.168.64.196192.168.254.1192.168.254.9192.168.254.2544下列哪三项陈述说明了传输层协议的特征?(选择三项)应用层协议使用TCP 端口号和UDP 端口号。

TCP 使用端口号提供可靠的IP 数据包传输。

UDP 使用窗口和确认获得可靠的数据传输。

TCP 使用窗口和定序提供可靠的数据传输。

TCP 是面向连接的协议。

UDP 是无连接协议。

5OSI 模型的哪两项功能在第2 层实现?(选择两项)物理编址编码路由介质访问控制6由于发生安全规规事件,必须更改路由器口令。

从以下配置项可获知什么信息?(选择两项。

)Router(config)#line vty 0 3Router(config-line)# password c13c0Router(config-line)#login这些配置项对远程访问指定了三条Telnet 线路。

这些配置项对远程访问指定了四条Telnet 线路。

这些配置项将控制台口令和Telnet 口令设置为"c13c0"。

因为Telnet 配置不完整,所以Telnet 访问将遭到拒绝。

允许使用"c13c0" 作为口令访问Telnet。

7请参见图示。

电缆1 和电缆 2 的两端分别按照特定的物理层要求接线。

表中按编号列出了每个网段以及网络技术人员在该网段不同网络组件之间已经安装的电缆。

根据给定的数据回答,哪些网段的电缆安装正确?(选择三项)网段1网段2网段3网段58下列哪种提示符代表适合copy running-config startup-config命令使用的模式?Switch-6J>Switch-6J#Switch-6J(config)#Switch-6J(config-if)#Switch-6J(config-line)#9请参见图示。

下列关于图中所示IP 配置的陈述,哪三项是正确的?(选择三项)分配给该计算机的地址代表私有地址。

该计算机无法在本地网络外通信。

此计算机的网络可支持126 台主机。

该计算机地址的前缀是/27。

分配给该计算机的IP 地址可在Internet 上路由。

分配给该计算机的IP 地址是广播地址。

1 0第4 层报头包含帮助数据传输的哪一类信息?服务端口号主机逻辑地址设备物理地址虚拟连接标识符1 1何时必须使用clock rate命令配置路由器串行接口?当该接口充当DTE 设备时当该接口计时器已经清除时当连接的DTE 设备关闭时当该接口充当DCE 设备时1在封装过程中,传输层添加什么标识符?2路由数据包的两个网络进行数据通信的两个应用程序分别位于通信两端的两台主机本地网络中交换帧的两个节点13请参见图示。

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