综合模拟1答案
山东专升本计算机科学与技术(综合一)模拟试卷1(题后含答案及解析)

山东专升本计算机科学与技术(综合一)模拟试卷1(题后含答案及解析)题型有:1. 操作系统 2. 微机原理与接口技术操作系统填空题1.操作系统目前有五大类型:_______、_______、_______、_______、_______。
正确答案:批处理操作系统分时操作系统实时操作系统网络操作系统分布式操作系统2.动态存储分配时,要靠硬件地址变换机构实现_______。
正确答案:重定位3.在存储管理中常用_______方式来摆脱主存容量的限制。
正确答案:虚拟存储器解析:虚拟存储器是具有请求调入功能和置换功能,能从逻辑上对内存容量加以扩充的一种存储系统,一般采用请求分页式,请求分段式,或段页式虚拟存储器系统。
虚拟存储器其逻辑容量有内存容量和外存容量之和决定。
4.在多道程序环境中,用户程序的相对地址与装入内存后的实际物理地址不同,把相对地址转换为物理地址,这是操作系统的_______功能。
正确答案:地址重定位5.操作系统提供给编程人员的唯一接口是_______。
正确答案:系统调用6.在页面置换算法中最有效的一种称为_______。
正确答案:LRU算法判断题7.程序在运行时需要很多系统资源,如内存、文件、设备等,因此操作系统以程序为单位分配系统。
( )A.正确B.错误正确答案:B解析:程序在运行时需要很多系统资源,如内存、文件、设备等,因此操作系统以程序为进程分配系统资源。
8.在采用树型目录结构的文件系统中,各用户的文件名必须互不相同。
( )A.正确B.错误正确答案:B解析:在采用树型目录结构的文件系统中,不同用户的文件名可以互不相同。
9.操作系统提供了大量的服务,在最高层是系统调用,它允许正在运行的程序直接得到操作系统的服务。
( )A.正确B.错误正确答案:B解析:操作系统提供了大量的服务,在最底层是系统调用,它允许正在运行的程序直接得到操作系统的服务。
10.虚拟存储器不是物理上扩大内存空间,而是逻辑上扩充了内存空间。
2020年度深圳九年级中考语文综合模拟测试卷1(含答案)

2020年度深圳九年级中考语文综合模拟测试卷1(含答案)一、积累与运用(本大题共5题,每小题2分,共10分)1.请选出下列加点词读音正确的一项()A. 看.(kàn)护秕.谷(bǐ)抚弄..(jìng tíng)..(fǔ nòng)大相径庭B. 发髻.(jì)匿.(nì)笑琢磨..不齐(cēn cī)..(zuó mo)参差C. 黄晕.(yūn)央.求(yāng)柠檬..(níng méng)恍.然大悟(huǎng)D. 应和.(hè)衣裳.(cháng)缥缈..(jǐn cù)..(piāomiǎo)花团锦簇2.请选出下列句子中加点成语运用不正确的一项()A. 许多人看到老人摔倒不扶,并非麻木不仁....,而是心存疑虑,担心引起误会。
B. 90后的求职者,要求工作时间相对自由,而且往往见异思迁....。
C. 大家认为他提出的这条建议很有价值,都随声附和....表示赞同。
D. 宋歌灵机一动....,想出了好方法,将这道数学题解答出来了。
3.下列句子中没有语病的一项是()A.受“厄尔尼诺”现象影响,黄河流域干旱严重,专家预测小麦将减产30%左右。
B.在科学家邓稼先的一生中,无处不以务实的作风和非凡的才学震惊于世。
C.大型文博探索节目《国家宝藏》播出后,在社会上引起了极大的赞誉。
D.国庆黄金周期间,小罗建议去云南丽江,小韦建议去海南三亚,我同意她的建议。
4.下列句子排序正确的一项是()①然而,我们信仰家,信仰我们的出处,又何以如此恒定?②在我看来,“叶落归根”说的不仅是过冬的事情,更是回家的事情。
③有风,有流水,有兽的足踪,有鸟的羽翎……它们都会将叶子带到很远的地方使之永不回归。
④其实,叶落何以就一定归根呢?⑤西山的木石不就被精卫衔去了东海么?⑥地球载着我们每个人,从这个区域漂到那个区域,每一天都面对陌生,永远不会返回初始的道路。
专升本(高等数学一)综合模拟试卷1(题后含答案及解析)

专升本(高等数学一)综合模拟试卷1(题后含答案及解析)题型有:1. 选择题 2. 填空题 3. 解答题选择题1.极限等于( )A.eB.ebC.eabD.eab+b正确答案:C解析:由于,故选C。
知识模块:极限和连续2.在空间直角坐标系中,方程x2-4(y-1)2=0表示( )A.两个平面B.双曲柱面C.椭圆柱面D.圆柱面正确答案:A解析:由于所给曲面方程x2-4(y-1)2=0中不含z,可知所给曲面为柱面,但是由于所给方程可化为x2=4(y-1)2,进而可以化为x=2(y-1)与-z=2(y-1),即x-2y+2=0,x+2y-2=0,为两个平面,故选A。
知识模块:空间解析几何3.级数是( )A.绝对收敛B.条件收敛C.发散D.收敛性不能判定正确答案:A解析:依前述判定级数绝对收敛与条件收敛的一般原则,常常先判定的收敛性,由于的p级数,知其为收敛级数,因此所给级数绝对收敛,故选A。
知识模块:无穷级数填空题4.若函数在x=0处连续,则a=________。
正确答案:-2解析:由于(无穷小量乘有界变量),而f(0)=a+2,由于f(x)在x=0处连续,应有a+2=0,即a=-2。
知识模块:极限和连续5.若f’(x0)=1,f(x0)=0,则=________。
正确答案:-1解析:由于f’(x0)存在,且f(x0)=0,由导数的定义有知识模块:一元函数微分学6.设y=xe+ex+lnx+ee,则y’=________。
正确答案:y’=ee-1+ex+解析:由导数的基本公式及四则运算规则,有y’=ee-1+ex+。
知识模块:一元函数微分学7.曲线y=ex+x上点(0,1)处的切线方程为________。
正确答案:由曲线y=f(x)在其上点(x0,f(x0))的切线公式y-f(x0)=f’(x0)(x-x0),可知y-1=2(x-0),即所求切线方程为y=2x+1。
解析:注意点(0,1)在曲线y=ex+x上,又y’=ex+1,因此y’|x=0=2。
导游实务(综合)模拟试卷1(题后含答案及解析)

导游实务(综合)模拟试卷1(题后含答案及解析) 题型有:1. 单选题 2. 多选题 3. 判断题 5. 简答题单选题1.旅行社的产品是在( )的同步进行中完成的。
A.生产与消费B.生产与销售C.服务与消费D.销售与消费正确答案:C 涉及知识点:综合2.通常被称为“旅游出口”的是经营( )。
A.国际出境旅游B.国际入境旅游C.国内旅游D.出入境旅游正确答案:B 涉及知识点:综合3.导游人员能够自觉抵制各种“旅游污染”,需要具备( )。
A.高尚的情操、健康的思想、正派的生活作风B.健康的思想、正派的生活作风、良好的职业道德C.较高的道德修养、坚定的意志、高度的思想觉悟D.情操修养、道德修养、学风修养、文化修养正确答案:C 涉及知识点:综合4.如果没有旅游者的消费,( )就不能实现,导游人员也就失去了存在的意义。
A.导游人员的价值B.旅游产品的价值C.旅行社的价值D.旅游者的价值正确答案:B 涉及知识点:综合5.国家旅游局发布的《旅行社管理条例实施细则》中,专门对( )作出了规定。
A.导游服务质量B.保护游客权益C.规范化服务D.个性化服务正确答案:B 涉及知识点:综合6.为了规范导游服务,国家发布了( )作为国家标准,规定了导游服务的质量要求。
A.《导游服务质量》B.《导游人员管理条例》C.《旅游权益法案》D.《旅行社管理条例实施细则》正确答案:A 涉及知识点:综合7.旅游团内的每位游客都交纳了相同的旅游费用,所以导游人员理应对他们( )。
A.完全满足他们所提出的要求B.按价论质,多酬多劳C.提供针对性服务D.保持同等距离,一视同仁正确答案:D 涉及知识点:综合8.下面哪一组导游人员的分类是按照导游职业性质来划分的?( )A.专职导游人员、业余导游人员、临时导游人员B.海外领队、全陪、地陪、讲解员C.普通话导游人员、外语导游员、方言或少数民族语言导游人员D.初级导游人员、中级导游人员、高级导游人员、特级导游人员正确答案:A 涉及知识点:综合9.旅游业的代表性业务就是( )。
2022年二建《水利管理与实务》综合模拟考试一(带答案解析)

二建水利管理与务实第 1题:单选题(本题1分)水库遇下游保护对象的设计洪水时在坝前达到的最高水位称为()。
A.校核洪水位B.设计洪水位C.防洪高水位D.防洪限制水位【正确答案】:C【答案解析】:教材P5 (3) 防洪高水位。
水库遇下游保护对象的设计洪水时在坝前达到的最高水位。
第 2题:单选题(本题1分)下列放样方法中,土坝坝轴线放样可采用的是()。
A.极坐标法B.套绘断面法C.经纬仪扫描法D.坡度尺法【正确答案】:A【答案解析】:教材P27 现场选定的坝轴线,可作为土坝施工控制网内的一条边;放样时可先在图 上根据施工坐标计算出坝轴线的放样数据,然后通过施工控制点,采用交会法或极坐标 法,将坝轴线放样到地面上。
第 3题:单选题(本题1分)某泵站用混凝土拌合物的坍落度为120mm,按坍落度大小分,此拌合物为()混凝土。
A.低塑性B.塑性C.流动性D.大流动性【正确答案】:C【答案解析】:教材P38 。
按坍落度大小,将混凝土拌合物分为:低塑性混凝土(坍落度为1〇?40mm)、塑 性混凝土(坍落度为50?90mm)、流动性混凝土(坍落度为100?150mm)、大流动性混 凝土(坍落度160mm)。
第 4题:单选题(本题1分)水利工程施工选择导流方案、确定导流建筑物的主要依据是导流()流量。
A.校核B.设计C.平均D.洪峰【正确答案】:B【答案解析】:教材P52 为了解决好施工导流问题,必须做好施工导流设计。
施工导流设计的任务是分析研究 当地的自然条件、工程特性和其他行业对水资源的需求来选择导流方案,划分导流时段, 选定导流标准和导流设计流量,确定导流建筑物的形式、布置、构造和尺寸,拟定导流建 筑物的修建、拆除、封堵的施工方法,拟定河道截流、拦洪度汛和基坑排水的技术措施, 通过技术经济比较,选择一个最经济合理的导流方案。
第 5题:单选题(本题1分)铲运机开挖渠道时,当渠道开挖宽度大于铲土长度,而填土或弃土宽度又大于卸土长度,宜采用()开行。
GRE(QUANTITATIVE)综合模拟试卷1(题后含答案及解析)

GRE(QUANTITATIVE)综合模拟试卷1(题后含答案及解析) 题型有:1. 2. 3.1.正确答案:A解析:In this question you are asked to compare the price at which Emma sold the bicycle with $140. From the information given, you can conclude that Emma spent a total of 75 + 27 = 102 dollars buying and repairing the bicycle and that she sold it for 40 percent more than the $102 she spent buying and repairing it. If you notice that 140 is 40 percent more than 100, you can conclude that 40 percent more than 102 is greater than 40 percent more than 100, and therefore, Quantity A is greater than Quantity B. The correct answer is Choice A.(If you solve the problem in this way, you do not have to calculate the value of Quantity A.)Another way to solve the problem is by explicitly calculating the value of Quantity A and comparing the result with $140 directly. Since 40 percent of 102 is(0.4)(102)= 40.8, it follows that Quantity A, the price at which Emma sold the bicycle, is 102.00 + 40.80 = 142.80 dollars. Thus Quantity A, $142.80, is greater than Quantity B, $140, and the correct answer is Choice A.2.正确答案:C解析:In this question you are asked to compare the area of the shaded region with 36. You are given that both PQRV and VRST are squares with sides of length 6. Therefore, you can conclude that the length of QS is 12, and the area of the shaded right triangle PQS is 1/2(12)(6), or 36. Thus Quantity A is equal to Quantity B, and the correct answer is Choice C.3.正确答案:A解析:Before making the comparison in this problem, you need to analyze the information given to see what it tells you about the value of Quantity A, the property tax in 2009 on a home in Town X that had an assessed value of $160,000. One way of doing this is to determine the value of the constant p and then use that value to calculate the tax on the home that had an assessed value of $160,000. Since it is given that a home that had an assessed value of $125,000 had a property tax of $2,500,you can conclude that p is equal to[*], or 2%. Once you know that the property tax is 2% of the assessed value, you can determine that tax on the home that had an assessed value of $160,000 was 2% of 160,000, or 3,200. The correct answer is Choice A. Another way to calculate the property tax on a home with an assessed value of $160,000 is by setting up a proportion. Because the tax rate is the same for each home in Town X, you can let the variable x represent the tax for the home assessed at $160,000 and solve for x as follows.[*]The correct answer is Choice A.4.正确答案:D解析:One way to approach this question is to plug in values for one of the variables and determine the corresponding value for the other variable. One way to plug in: Plug in easy values. For example, you can plug in x = 0 and find that the corresponding value of y is -1; then you can plug in y = 0 and find that the corresponding value of x is -1. Since in the first case x is greater than y and in the second case y is greater than x, the correct answer is Choice D, the relationship cannot be determined from the information given. A second way to plug in: If you prefer to always plug in values of x to determine corresponding values of y, you can begin by writing the equation x +y = -1 asy = -x - 1. Writing it in this form makes it easier to find the corresponding values of y. You can start by plugging in the value x = 0. For this value of x, the corresponding value of y is y = -1, and therefore, x is greater than y. If you continue plugging in a variety of values of x, some negative and some positive, you will see that sometimes x is greater than y and sometimes y is greater than x. If you inspect the equation y = —x - 1, you can conclude that since there is a negative sign in front of the x but not in front of the y, for each value of x that is greater than 0, the corresponding value of y is less than 0; therefore, for each x > 0, x is greater than y. What about negative values of x? A quick inspection of the equation y = —x - 1 allows you to conclude that if x < -1, then y > 0, so y is greater than x. So for some values of x and y that satisfy the equation, x is greater than y; and for other values, y is greater than x. Therefore, the relationship between the two quantities x and y cannot be determined from the information given, and the correct answer is Choice D.5.正确答案:B解析:You are given that three numbers, r, s, and t, are consecutive odd integers and that rIn the last step of the simplification, you can easily see that 3 In the last step of the simplification, you can easily see that 1 In the figure above, what is the value of?A.2B.3C.4D.5E.6正确答案:C解析:The sum of the measures, in degrees, of the three interior angles of any triangle is 180°. As shown in the figure, the three angles of the triangle have measures of x°, y°, and z°, so x + y + z = 180. Therefore,= 4, and the correct answer is Choice C.8.A certain store sells two types of pens: one type for $2 per pen and the other type for $3 per pen. If a customer can spend up to $25 to buy pens at the store and there is no sales tax, what is the greatest number of pens the customer can buy?A.9B.10C.11D.12E.20正确答案:D解析:It is fairly clear that the greatest number of pens that can be bought for $25 will consist mostly, if not entirely, of $2 pens. In fact, it is reasonable to begin by looking at how many of the $2 pens the customer can buy if the customer does not buy any $3 pens. It is easy to see that the customer could buy 12 of the $2 pens, with $1 left over. If the customer bought 11 of the $2 pens, there would be $3 left over with which to buy a $3 pen. In this case, the customer could still buy 12 pens. If the customer bought 10 of the $2 pens, there would be $5 left over. Only 1 of the $3 pens could be bought with the $5, so in this case, the customer could buy only 11 pens. As the number of $2 pens decreases, the total number of pens that the customer can buy with $25 decreases as well. Thus the greatest number of pens the customer can buy with $25 is 12. The correct answer is Choice D.9.If y = 3x and z = 2y, what is x + y + z in terms of x ?A.10xB.9xC.8xD.6xE.5x正确答案:A解析:It is not necessary to find the individual values of x, y, and z to answer the question. You are asked to rewrite the expression x + y + z as an equivalent expression in terms of x. This means that you need to use the information provided about y and z to express them in terms of the variable x. The variable y is already given in terms of x; that is, y = 3x; and because z = 2y, it follows that z =(2)(3x)= 6x. Using substitution, you can rewrite the expression as follows.x + y + z=x +(3x)+(6x)=(1 +3 + 6)x =10xThe correct answer is Choice A.10.A certain shipping service charges an insurance fee of $0.75 when shipping any package with contents worth $25.00 or less and an insurance fee of $1.00 when shipping any package with contents worth over $25.00. If Dan uses the shipping company to ship three packages with contents worth $18.25, $25.00, and $127.50, respectively, what is the total insurance fee that the company charges Dan to ship the three packages?A.1.75B.2.25C.2.5D.2.75E.3正确答案:C解析:Note that two of the packages being shipped have contents that are worth $25.00 or less. Therefore, each of them has an insurance fee of $0.75, for a total of $1.50. The third package has contents worth over $25.00, and it has an insurance fee of $1.00. Therefore, the total insurance fee for the three packages is $1.50 + $1.00 = $2.50, and the correct answer is Choice C.11.If 55 percent of the people who purchase a certain product are female, what is the ratio of the number of females who purchase the product to the number of males who purchase the product?A.11 to 9B.10 to 9C.9 to 10D.9 to 11E.5 to 9正确答案:A解析:Note that because 55 percent of the people who purchase the product are females, it follows that 45 percent of the people who purchase the product are males. Therefore, the ratio of the number of females who purchase the product to the number of males who purchase the product is 55 to 45, or 11 to 9, and the correct answer is Choice A.12.In the rectangular solid above, TU = 3, UV = 4, and VR = What is the area of the shaded rectangular region?______正确答案:10解析:To find the area of the shaded rectangular region, you need to multiply the length of the rectangular region by its width. In this question you are given the lengths of three edges: TU = 3, UV = 4, and VR = 2. Note that VR is the length of the shaded rectangle. To find the width of the shaded rectangle, you need to find either RS or VT. Note that VT lies on the front face of the rectangular solid. It is the hypotenuse of right triangle VUT. You know that UV = 4 and TU = 3, so by the Pythagorean theorem you can conclude that VT == 5. Therefore, the area of the shaded rectangularregion is(5)(2)= 10. The correct answer is 10.13.A list of numbers has a mean of 8 and a standard deviation of 2.If x is a number in the list that is 2 standard deviations above the mean, what is the value of x ? x=______正确答案:13解析:You are given that x is 2 standard deviations above the mean, 8. Because the standard deviation of the numbers in the list is 2.5, it follows that x is(2)(2.5), or 5 units above the mean 8. Therefore, x = 8 + 5 = 13, and the correct answer is 13.14.The circle graph above shows the distribution of 200,000 physicians by specialty. Which of the following sectors of the circle graph represent more than 40,000 physicians?Indicate all such sectors.A.PediatricsB.Internal MedicineC.SurgeryD.AnesthesiologyE.Psychiatry正确答案:A,B,C解析:One approach to solve this problem is to find out what percent of 200,000 is 40,000 and then compare this percent with the percents given in the circle graph. Because= 0.2, it follows that 40,000 is 20% of 200,000, and any specialty that has more than 20% of the distribution has more than 40,000 physicians. This is true for the specialties of pediatrics, internal medicine, and surgery. The correct answer consists of Choices A, B, and C.。
2023中考数学综合模拟习题一(含答案)

2023中考数学综合模拟习题一一.选择题(共12小题)1.下列图形中,既是轴对称图形又是中心对称图形的是()A.扇形B.正五边形C.菱形D.平行四边形2.下列计算正确的是()A.﹣a4b÷a2b=﹣a2b B.(a﹣b)2=a2﹣b2C.a2•a3=a6D.﹣3a2+2a2=﹣a23.下列实数中,最小的数是()A.B.0C.1D.4.下列说法正确的是()A.“明天降雨的概率为50%”,意味着明天一定有半天都在降雨B.了解全国快递包裹产生的包装垃圾数量适合采用全面调查(普查)方式C.掷一枚质地均匀的骰子,骰子停止转动后,6点朝上是必然事件D.一组数据的方差越大,则这组数据的波动也越大5.如图,直线a∥b,c,d是截线且交于点A,若∠1=60°,∠2=100°,则∠A=()A.40°B.50°C.60°D.70°5题图6题图6.已知一次函数y1=kx+b(k≠0)与反比例函数y2=(m>0)的图象如图所示,则当y1>y2时,自变量x满足的条件是()A.1<x<3B.1≤x≤3C.x>1D.x<37.受央视《朗读者》节目的启发的影响,某校七年级2班近期准备组织一次朗诵活动,语文老师调查了全班学生平均每天的阅读时间,统计结果如下表所示,则在本次调查中,全班学生平均每天阅读时间的中位数和众数分别是()每天阅读时间(小时)0.51 1.52人数89103A.2,1B.1,1.5C.1,2D.1,18.已知=3,则代数式的值是()A.B.C.D.9.已知圆内接正三角形的面积为,则该圆的内接正六边形的边心距是()A.2B.1C.D.10.如果关于x的不等式组的整数解仅有x=2、x=3,那么适合这个不等式组的整数a、b组成的有序数对(a,b)共有()A.3个B.4个C.5个D.6个11.如图,四边形AOEF是平行四边形,点B为OE的中点,延长FO至点C,使FO=3OC,连接AB、AC、BC,则在△ABC中S△ABO:S△AOC:S△BOC=()A.6:2:1B.3:2:1C.6:3:2D.4:3:211题图12题图12.如图,正方形ABCD的边长为2,P为CD的中点,连结AP,过点B作BE⊥AP于点E,延长CE交AD于点F,过点C作CH⊥BE于点G,交AB于点H,连接HF.下列结论正确的是()A.CE=B.EF=C.cos∠CEP=D.HF2=EF•CF二.填空题(共6小题)13.若2n(n≠0)是关于x的方程x2﹣2mx+2n=0的根,则m﹣n的值为.14.一个多边形的每一个外角都是18°,这个多边形的边数为.15.已知一组数据10,15,10,x,18,20的平均数为15,则这组数据的方差为.16.如图,在△ABC中,AF平分∠BAC,AC的垂直平分线交BC于点E,∠B=70°,∠F AE=19°,则∠C=度.16题图17题图17.如图,已知抛物线y=ax2﹣4x+c(a≠0)与反比例函数y=的图象相交于点B,且B点的横坐标为3,抛物线与y轴交于点C(0,6),A是抛物线y=ax2﹣4x+c的顶点,P点是x轴上一动点,当P A+PB最小时,P点的坐标为.18.已知函数y=使y=a成立的x的值恰好只有3个时,a的值为.三.解答题(共7题)19.(1)计算:﹣(1﹣)0+sin45°+()﹣1(2)先化简,再求值:÷(﹣),其中a=+2.20.某网络约车公司近期推出了”520专享”服务计划,即要求公司员工做到“5星级服务、2分钟响应、0客户投诉”,为进一步提升服务品质,公司监管部门决定了解“单次营运里程”的分布情况.老王收集了本公司的5000个“单次营运里程”数据,这些里程数据均不超过25(公里),他从中随机抽取了200个数据作为一个样本,整理、统计结果如下表,并绘制了不完整的频数分布直方图(如图).频数组别单次营运里程“x”(公里)第一组0<x≤572第二组5<x≤10a第三组10<x≤1526第四组15<x≤2024第五组20<x≤2530根据统计表、图提供的信息,解答下面的问题:(1)①表中a=;②样本中“单次营运里程”不超过15公里的频率为;③请把频数分布直方图补充完整;(2)请估计该公司这5000个“单次营运里程”超过20公里的次数;(3)为缓解城市交通压力,维护交通秩序,来自某市区的4名网约车司机(3男1女)成立了“交通秩序维护”志愿小分队,若从该小分队中任意抽取两名司机在某一路口维护交通秩序,请用列举法(画树状图或列表)求出恰好抽到“一男一女”的概率.21.如图所示,在平面直角坐标系中,一次函数y=kx+b(k≠0)与反比例函数y=(m ≠0)的图象交于第二、四象限A、B两点,过点A作AD⊥x轴于D,AD=4,sin∠AOD =,且点B的坐标为(n,﹣2).(1)求一次函数与反比例函效的解析式;(2)E是y轴上一点,且△AOE是等腰三角形,请直接写出所有符合条件的E点坐标.22.某销售商准备在某市采购一批丝绸,经调查,用10000元采购A 型丝绸的件数与用8000元采购B型丝绸的件数相等,一件A型丝绸进价比一件B型丝绸进价多100元.(1)求一件A型、B型丝绸的进价分别为多少元?(2)若销售商购进A型、B型丝绸共50件,其中A型的件数不大于B型的件数,且不少于16件,设购进A型丝绸m件.①求m的取值范围.②已知A型的售价是800元/件,销售成本为2n元/件;B型的售价为600元/件,销售成本为n元/件.如果50≤n≤150,求销售这批丝绸的最大利润w(元)与n(元)的函数关系式(每件销售利润=售价﹣进价﹣销售成本).23.如图,在直角三角形ABC中,∠ACB=90°,点H是△ABC的内心,AH的延长线和三角形ABC的外接圆O相交于点D,连结DB.(1)求证:DH=DB;(2)过点D作BC的平行线交AC、AB的延长线分别于点E、F,已知CE=1,圆O的直径为5.①求证:EF为圆O的切线;②求DF的长.24.如图,矩形ABCD中,AC=2AB,将矩形ABCD绕点A旋转得到矩形AB′C′D′,使点B的对应点B'落在AC上,B'C'交AD于点E,在B'C′上取点F,使B'F=AB.(1)求证:AE=C′E.(2)求∠FBB'的度数.(3)已知AB=2,求BF的长.25.如图,在等腰直角三角形ABC中,∠BAC=90°,点A在x轴上,点B在y轴上,点C(3,1),二次函数y=x2+bx﹣的图象经过点C.(1)求二次函数的解析式,并把解析式化成y=a(x﹣h)2+k的形式;(2)把△ABC沿x轴正方向平移,当点B落在抛物线上时,求△ABC扫过区域的面积;(3)在抛物线上是否存在异于点C的点P,使△ABP是以AB为直角边的等腰直角三角形?如果存在,请求出所有符合条件的点P的坐标;如果不存在,请说明理由.参考答案二.填空题第13题:12第14题:20 第15题:443第16题:24 第17题:(125,0)第18题:2三.解答题第19题:(1)原式=3√2 2(2)化简,可得,原式=a+2a−2,当a=+2时,原式=1+2√2第20题:(1)①48 ②0.73 ③(画图略)(2)750(3)12第21题:(1) 一次函数的解析式为y =−23x +2反比例函效的解析式为y =−12x(2)E 点坐标为(0,258)或(0,5)或(0,−5)第22题:(1) 解:设一件B 型丝绸的进价为x 元,则一件A 型丝绸的进价为(x+100)元,根据题意,可得,10000x +100=8000x解得,x =400经检验:x =400是原方程的解,且符合题意。
金融硕士(MF)金融学综合模拟试卷1(题后含答案及解析)

金融硕士(MF)金融学综合模拟试卷1(题后含答案及解析)全部题型 2. 不定项选择题3. 判断题4. 名词解释5. 计算题不定项选择题1.国际金币本位制的特点有:( )A.黄金是国际货币体系的基础。
B.黄金可以在各国间自由输入、输出,并被自由铸造成货币。
C.各国货币均可以按法定含金量与黄金自由兑换。
D.在该制度下,各国的国际收支调节具有对称性。
正确答案:A,B,C,D2.汇率决定的资产组合分析法将一国持有的资产分为:( )A.本国货币B.本国债券C.外币资产D.实物资产正确答案:A,B,C3.次贷危机的发生、蔓延原因有:( )A.银行相对于自有资本而言发放了过多的住房贷款。
B.美国的高利率使银行发放贷款的利息收入增加,从而刺激了住房抵押贷款的发放。
C.住房抵押贷款证券化后,又在市场上出售,从而使银行能获得更多的贷款资源。
D.金融创新助长了抵押贷款债券的发放和国际流通。
正确答案:A,C,D4.在国际收支的货币分析法中:( )A.假定一国的货币需求是稳定的。
B.一国的货币供给来自国内信贷和国际储备。
C.居民对手中货币余额的调节体现为国际收支。
D.当本国国内信贷扩张时,本国将出现国际收支盈余。
正确答案:A,B,C5.一国执行货币兑换管制的可能后果包括:( )A.能够节约外汇,用于集中进口本国必需品。
B.会形成规模较大的外汇黑市。
C.为获得外汇,本国厂商会倾向于高报出口、低报进口。
D.会形成经济租金,进一步引发不公平的再分配和寻租成本。
正确答案:A,B,D判断题6.根据多恩布什的“汇率超调论”,汇率之所以在受到货币冲击后会有过度反应,是因为资产价格的调整速度快于商品价格的调整速度。
( ) A.正确B.错误正确答案:A7.外债清偿率是指年还债(还本利息)总额与年商品和劳务出口收入之比,这个比例一般不应超过10%。
( )A.正确B.错误正确答案:B8.按P-e模型,如果没有技术进步和劳动生产率的提高,产出的增长会伴有物价水平的上升。
综合素质模拟卷(一)参考答案及解析

模拟卷一参考答案及解析一、单项选择题1.【答案】D。
【解析】“深山树木长不齐,荷花出水有高低”的意思是说,不可能所有学生都是一样的,表明学生与学生之间存在个体差异性。
2.【答案】B。
【解析】此题考察的是教师的教育理念,面对学生的学习疑问应该循循善诱,不应该讽刺学生,借此会打击学生的积极性,伤害学生的自尊心,故B为正确答案。
教育机智指的是教师面对突发情况采取的快速合理的措施,不符合此题情境,故A错;小雨对知识有疑惑不属于课堂无关行为,故C错;教师讽刺学生与教学任务的完成无关,故D错。
3.【答案】D。
【解析】此题考察对学生观的理解。
“以人为本”的学生观指出,学生是发展的人,作为教师应该用发展的眼光去看待学生,避免只关注学生的成绩,坚信每个学生都可以积极成长。
郭老师格外关照成绩好的学生,忽视了学生的发展性。
ABC题意未体现,故选D。
4.【答案】B。
【解析】此题考察个体具有差异性的知识。
素质教育强调促进学生的个性发展,个性是基于个人的特点和差异。
学生之间本身存在巨大的差异,而老师组织朗诵兴趣小组规定每个同学都必须参加,忽视了学生的意愿,也忽视了学生的个性差异。
故选B。
5.【答案】B。
【解析】《中华人民共和国教育法》第十五条规定,国务院教育行政部门主管全国教育工作,统筹规划、协调管理全国的教育事业。
6.【答案】C【解析】本题考查《中华人民共和国预防未成年人犯罪法》的相关规定。
依据《中华人民共和国预防未成年人犯罪法》第七章第五十条规定:“未成年人的父母或者其他监护人违反本法第十九条的规定,让不满十六周岁的未成年人脱离监护单独居住的,由公安机关对未成年人的父母或者其他监护人予以训诫,责令其立即改正。
”C项正确。
7.【答案】B【解析】本题考查的是学生的隐私权。
人身权是公民权利中最基本、最重要、内涵最为丰富的一项权利。
与学生密切相关的人身权包括生命健康权、隐私权、人身自由权和人格尊严权。
其中隐私权一般是指自然人享有的对自己的个人秘密和个人私生活进行支配并排除他人干涉的权利。
2023年化学中考综合模拟题及答案(1)

2023年中考化学综合训练(一)说 明:1.全卷满分70分,考试时间50分钟。
2.本试卷分为第I 卷(选择题)和第II 卷(非选择题)两部分,共四个大题,17个小题。
可能用到的相对原子质量:H —1 C —12 N —14 O —16 Fe —56 Cu —64 Ag —108 S —32第Ⅰ部分 (选择题 共 30 分)一、选择题(本题共 10 个小题,每小题 3 分,共 30 分。
每小题只有一个选项符合题意) 1.下列变化属于物理变化的是( )A .剩饭、剩菜变馊B .用稻草制作稻草人C .葡萄酿成酒D .鸡蛋壳上滴加食醋会冒气泡 2.保护环境,建设美丽广元。
下列说法正确的是( ) A .工业废水处理达标后再循环使用 B .田地秸秆就地焚烧后作农家肥使用 C .将化工厂烟囱加高以减少空气污染 D .将废弃塑料袋用土填埋以减少白色污染3.化学概念之间存在有并列、交叉、包含等不同关系。
下列选项符合M 、N 如图所示关系的是( )4.实验是学习化学的一条重要途径。
下列实验基本操作你认为正确的是( )A.氯化钠溶解 B .滴加液体 C .检验H 2纯度 D .收集CO 2 5.下列各组物质按单质、氧化物、混合物的顺序排列的是( ) A .锌粒、二氧化锰、矿泉水 B .石灰石、冰水混合物、液氧 C .水银、生铁、过氧化氢溶液 D .干冰、金刚石、白糖水A.化学与安全B.化学与健康(1)进入干涸的深井,一定要进行灯火实验(2)天然气泄漏,立即打开排风扇排气(1)喝牛奶有利于补钙(2)缺乏维生素C 会引起怀血病 C.化学与环境D.化学与材料(1)雨水呈酸性,所以叫酸雨(2)禁止使用农药和化肥,以减少水体污染(1)铝制易拉罐和废铁都属于金属材料 (2)合金、合成橡胶都属于有机合成材料482酸乙酯说法正确的是( )A .乙酸乙酯由4个碳原子、8个氢原子和2个氧原子构成B .乙酸乙酯中C 、H 、O 三种元素的质量比为4:8:2 C .乙酸乙酯的相对分子质量为88gD .乙酸乙酯中碳元素质量分数最大8.物质的鉴别、分离、提纯是化学重要的实验技能。
雅思写作(综合)模拟试卷1(题后含答案及解析)

雅思写作(综合)模拟试卷1(题后含答案及解析) 题型有: 2. WRITING TASK 2WRITING TASK 2You should spend about 40 minutes on this task.1.In some countries young people are encouraged to work or travel for a year between finishing high school and starting university studies. Discuss the advantages and disadvantages for young people who decide to do this.正确答案:It is quite common these days for young people in many countries to have a break from studying after graduating from high school. The trend is not restricted to rich students who have the money to travel, but is also evident among poorer students who choose to work and become economically independent for a period of time. The reasons for this trend may involve the recognition that a young adult who passes directly from school to university is rather restricted in terms of general knowledge and experience of the world. By contrast, those who have spent some time earning a living or travelling to other places, have a broader view of life and better personal resources to draw on. They tend to be more independent, which is a very important factor in academic study and research, as well as giving them an advantage in terms of coping with the challenges of student life. However, there are certainly dangers in taking time off at that important age. Young adults may end up never returning to their studies or finding it difficult to readapt to an academic environment. They may think that it is better to continue in a particular job, or to do something completely different from a university course. But overall, I think this is less likely today, when academic qualifications are essential for getting a reasonable career. My view is that young people should be encouraged to broaden their horizons. That is the best way for them to get a clear perspective of what they are hoping to do with their lives and why. Students with such a perspective are usually the most effective and motivated ones and taking a year off may be the best way to gain this. 涉及知识点:写作2.Some people argue that teaching children of different abilities together benefits all of them. Others believe that intelligent children should be taught separately and given special treatment. Discuss both views and give your own opinion.正确答案:Today, it is quite common for many schools to practice an “elite students”policy, where the intelligent students are selected and given special treatment. Personally, I think this practice generally has more benefits on several different levels. The most obvious advantage lies in the fact that it allows teachers to employ different pedagogic strategies suited to the particular group of pupils. For example, for the more intelligent students who are more likely to have a quicker mindand stronger thirst for knowledge, teachers or tutors can include something more difficult or complex in their syllabus, catering for the special needs. On the other hand, for some other students who are not that intelligent and may be slow at learning or acquiring new knowledge or skills, a correspondingly suitable teaching strategy then is highly desirable. In this case, the separate teaching scheme is generally good for both groups of students, since teachers can thereafter design different courses and teaching methods catering for their special needs. Of course, those who are in support of integration teaching may argue that separating one from another is a violation of individual rights and that everyone should be treated equally regardless of their intelligence. I think the notion of equality is not the issue. The less intelligent students can be allowed to choose some advanced courses originally designed for those fast learners, and vice versa. Overall, I think it is not bad to separate students and nurture them individually. The authorities should take into consideration their pupils’ own preference as to being in or out of one particular group so that the benefits of this system can be maximised. 涉及知识点:写作3.Since science and technology are becoming more and more important in modern society, schools should spend more time on teaching these subjects rather than on arts and humanities. To what extent do you agree or disagree?正确答案:Some people claim that scientific and technological subjects should receive more emphasis in schools, given the importance of these subjects in the modern world. However, others think that this is not a sufficient reason to neglect education in arts and humanities. Obviously, there is little doubt that science and technology have had a great influence on modern society. The commonly cited examples of the Internet boom and the need to keep pace with a fast-changing global economy show us the importance of familiarising the next generation with science and technology. But does it mean that arts and humanities should take up a smaller proportion of a students’curriculum? Arts and humanities, it is argued, help students to gain a better vision of the past and how the world has, and continues to change over time. In other words, arts and humanities help them to think; to understand the mistakes made in the past, but also to reflect upon the great things humanity has accomplished. However, with the never-ending demand for new technologies and inventions, society is starting to pay less attention to the importance of arts and humanities. Therefore some people are wondering whether subjects in arts and humanities should give way to courses focusing on science and technology. It is imaginable that if this really happened, the younger generations today would lack the skills of critical thinking, knowledge of how the world turns around us, and suffer in their ability to read, reason and communicate. At a time when so much is happening to change the way we work and live, the way we relate to one another and the way we relate to the rest of the world, we actually need more knowledge and a better understanding of our shared history, philosophy and literature so that the lessons of the past are not lost. Therefore, I believe arts and humanities should not be given less attention in schools today, and the planning of a reasonable curriculumshould consider the overall benefits to the students. 涉及知识点:写作4.In many countries schools have severe problems with student behavior. What do you think are the causes of this? What solutions can you suggest?正确答案:Poor student behavior seems to be an increasingly widespread problem and I think that modern lifestyles are probably responsible for this. In many countries, the birth rate is decreasing sb that families are smaller with fewer children. These children are-often spoilt, not in terms of love and attention because working parents do not have the time for this, but in more material ways. They are allowed to have whatever they want, regardless of price, and to behave as they please. This means that the children grow up without consideration for others and without any understanding of where their standard of living comes from. When they get to school age they have not learnt any self control or discipline. They have less respect for their teachers and refuse to obey rules in the way that their parents did. Teachers continually complain about this problem and measures should be taken to combat the situation. But I think the solution to the problem lies with the families, who need to be more aware of the future consequences of spoiling their children. If they could raise them to be considerate of others and to be social, responsible individuals, the whole community would benefit. Perhaps parenting classes are needed to help them to do this, and high quality nursery schools could be established that would support families more in terms of raising the next generation. The government should fund this kind of parental support, because this is no longer a problem for individual families, but for society as a whole. 涉及知识点:写作。
牛津版中考英语综合模拟习题一及答案Word版

九年级英语模拟考试试卷〔考试时间:120分钟总分值120分〕请注意:1.本卷分选择题和非选择题两个局部。
2.所有试题的答案均填写在答题卡上,答案写在试卷上无效。
第一局部选择题〔60分〕一、单项选从以下每题所给的选项中,选出一个最正确答案。
〔15分〕择题〔〕HannahLucashadadisease,sheandherbrotherCharilemadeappcalledNOTOKtolethergethelpfrom otherswhenshewasn'tfeelingwell.A.the;theB.a;theC.an;不填D.the;不填〔〕2.—Whydidhemakeno_______tobeunderstoodorliked?—Hedidn’tcarewhatothersthinkofhim.A.riskB.balanceC.suggestionD.effort〔〕3.Juliaisveryclever.Infact,Idoubtwhetheranyoneintheclasshas_____IQ.A.ahighB.ahigherC.thehigherD.thehighest〔〕4.Ineed________money.Wouldyoupleaselendme________?A.agreatdealof,anyB.agreatdealof,someC.agreatdeal,anyD.agreatdeal,some〔〕5.―Itseemsthatyourdaughtershowsaninterest playingtheguitar.―Exactly.Herteachersaysshehasagift musicA.for;ofB.of;forC.in;ofD.in;for〔〕6.Jackfeltnervouswhenhefoundthephysicsproblems_______toworkout.A.sodifficultB.difficultenoughC.toodifficultD.difficultas〔〕7.―Ifyoualways________yourselfwithothers,youmayhavemuchstress.Iagree.Weshouldbelieveinourselves.A pareB municate C.connect D.consider〔〕8.—_______willthediscussionlast?—____wereachanagreement.A.When,UntilB.When,NotuntilC.Howlong,Until long,Notuntil〔〕9.They_______standatthegateandwelcometheguestsbecausetherobotscandothat.A.mustn’tB.needn’tC.shouldn’tD.can’t〔〕10.—Wholivestogetherwithyourgrandmother?—livesalone.MyparentsandIcometseehereverySaturday.B.Nobody〔〕oldTVissobigthatittoomuchspace.---Well,Iwillbuyanewonesoon.off B.takesaway C.takesplace D.takesup〔〕12.Theysay_______andmineisonSaturday,whenIwaschosentobethehostoftheartshow.A.everydoghasitsdayB.manyhandsmakeslightworkC.itneverrainsbutitpoursD.theearlybirdcatchestheworm〔〕13.—ManypeoplesaythetemperatureinTaizhouthisspringisjustlikearollercoaster.—Ican’tagreemore.__________________________!A.WhatastrangeweatherB.HowastrangeweatherC.WhatchangeableweatherD.Howchangeableweather〔〕14.—Whatareyougoingtodothisweekend?—.Ifthereisenoughtime,ImaygotoShanghaiwithmyfriends.A.Don'tmentionitB.Itdoesn'tmatterC.ForgetitD.Itdepends〔〕15.—WhyisthegamecalledTravelFrog〔旅行青蛙〕sopopular?—Iguessithassomethingtodowith.A.howdidpeoplefeellikeinthegameB.howlonelypeopleareintheirreallifeC.howmuchdopeopleenjoytravellingD.whetherpeople’slovefortravellingwithfrogs二、完形填空阅读短文,从每题所给选项中选出可以填入空白处的最正确选项。
综合英语(1)模拟一答案

I.Vocabulary and Structure:Directions: Beneath each of the following sentences, there are four choices marked A, B, C and D. Choose the one that best completes the sentence. Mark your answer on the ANSWER SHEET. (20 points)Example: The old couple at last in finding a flat to rent.A.managedB.didC.finishedD.succeededThe sentence should read, "The old couple succeeded at last in finding a flat to rent." Therefore, you should choose D.1.The plane at 10:45. There is still an hour to go.A.takes overB.takes offC.takes downD.takes up2.I have been waiting for him for the last twenty minutes, but he hasn't yet.A.shown offB.shown upC.shown throughD.shown around3.I don't know the number– I'll look in the telephone book.A. make sureB.as sureC.of sureD.for sure4.They are going to turn that land in the neighborhood into a large parking lot.A.vacantB.variousC.violentD.vital5.The restaurant also has an excellent wine to complement your meal.A.selectionB.electionC.correctionD.reflection6.Could you tell me the tissues are, please?A.whatB.whereC.whichD.when7.How long?A. have you got marriedB.you got marriedC.have you been marriedD.did you marry8.You will find rice at every meal in the South of China.A.servedB.servingC.be servedD.serves9.She opened the door the fresh air to come in.A.ofB.forC.intoD.let10.All is a continuous supply of the basic necessities of life.A.that is neededB.what is neededC.the thing neededD.our needs1 B从本句句子来看,飞机应该是十点四十五分起飞,所以选项B 是正确答案。
中小学教师资格考试综合素质(小学)模拟卷(一)参考答案

中小学教师资格考试综合素质(小学)模拟卷(一)参考答案一、单项选择题1.【答案】B。
解析∶个体身心发展具有顺序性、阶段性、不平衡性、互补性、个别差异性等规律。
其中,个别差异性要求教育必须因材施教,关注学生差异,有的放矢地选择适宜、有效的教育途径和教育方法,使每个学生都能得到最大的发展。
题干中,邹老师根据学生的学习水平布置适宜每个学生的家庭作业。
这表明邹老师关注到了学生的个别差异,能更好地促进全体学生发挥潜能。
故本题选B。
2.【答案】B。
解析∶《中华人民共和国宪法》(2018年修正)第二条规定,“中华人民共和国的一切权力属于人民。
人民行使国家权力的机关是全国人民代表大会和地方各级人民代表大会。
人民依照法律规定,通过各种途径和形式,管理国家事务,管理经济和文化事业,管理社会事务”。
故本题选B。
3.【答案】A。
解析∶《中华人民共和国义务教育法》(2018年修正)第五十六条第三款规定,"国家机关工作人员和教科书审查人员参与或者变相参与教科书编写的,由县级以上人民政府或者其教育行政部门根据职责权限责令限期改正,依法给予行政处分;有违法所得的,没收违法所得"。
B、C、D三项均属于恰当的处理方式,不符合题意。
陈某的行为尚未构成犯罪,不能追究其刑事责任。
A项处理方式不正确,符合题意,故当选。
4.【答案】B。
解析∶循循善诱是指善于有步骤地引导、教育。
题干中,李老师没有简单粗暴地批评小刚,而是让小刚站在小明的角度思考问题,引导小刚换位思考。
这种循循善诱的沟通方式既体现了对学生的尊重,又能达到较好的沟通效果。
B项正确,C、D两项错误。
教师权威是指教师在角色要求下控制或约束学生的权力和威望。
题干未体现A项。
5.【答案】D。
解析∶班主任在处理班级突发事件时,要用“育人”的态度去看事件,用发展的眼光去看学生。
无论什么事都应持一分为二的观点,既看到消极、不利的一面,又看到积极、有利的一面。
题干中,小成拒绝承认自身的错误,班主任应当寻找恰当的时机,通过适当的方式引导学生敢于担当,勇于承担自己的错误,积极改正自己的不足。
山东专升本工程管理(综合一)模拟试卷1(题后含答案及解析)

山东专升本工程管理(综合一)模拟试卷1(题后含答案及解析) 题型有:1. 管理学 2. 会计学管理学判断题1.美国的坦南鲍姆和施米特创立了“管理方格图”理论。
( )A.正确B.错误正确答案:B解析:美国得克萨斯大学的布莱克和穆顿提出了管理方格理论。
2.控制工作的灵活性主要适应于在正确计划指导下人们工作不当的情况。
( )A.正确B.错误正确答案:B3.计划工作的第一步是估量机会。
( )A.正确B.错误正确答案:A4.组织目标是通过一定的计划工作来实现的。
( )A.正确B.错误正确答案:A5.组织工作是根据组织的目标,考虑组织内外环境来建立和协调组织结构的过程。
( )A.正确B.错误正确答案:B6.组织在正常的情况下,一个管理人员能够直接指挥多少人员,这叫管理层次。
( )A.正确B.错误正确答案:B解析:组织在正常的情况下,一个管理人员能够直接指挥多少人员,这叫管理幅度。
名词解释7.企业文化正确答案:企业文化是在一定的社会历史条件下,企业及企业职工在生产经营和企业管理中逐步形成的观念形态、文化形式和价值体系的总合。
主要构成因素是:价值观念、企业精神、制度规范、习俗仪式、英雄人物、企业环境等。
8.管理幅度正确答案:管理幅度是一个上级管理人员直接指挥的下级人员的人数。
9.计划工作正确答案:根据组织内外部的实际情况,权衡客观需要和主观可能,通过科学的预测,提出在未来一定时期内组织所要达到的目标以及实现目标的方法。
广义的计划包括制订计划、执行计划和检查计划,狭义的计划只包括制订计划。
简答题10.简述管理的特征。
正确答案:管理的载体是组织;管理具有目的性;管理的对象是组织资源;管理是各种职能活动应用的过程;管理的核心是协调各种人际关系;管理活动是在特定的组织内外部环境约束下进行的。
11.组织设计应该遵循哪些原则?正确答案:统一指挥原则;分工协作原则;权责一致原则;集权与分权相结合原则;有效管理幅度原则;弹性结构原则;经济原则。
《民航乘务服务》综合模拟试卷一及答案

一、单项选择题(每题2分,共30分)1.飞机舱门上的滑梯释放后,正常的充气时间是()。
A.5秒钟B. 10秒钟C. 15秒钟D.30秒钟2.飞机在夜航中无服务项目、旅客休息阶段,应将顶灯调至()档位。
A.DimB. BrightC.MediumD.Night3. 当客舱中出现几个部位同时使用内话系统时,客舱广播系统优先播放()。
A. 登机音乐B.乘务员呼叫C. 预录广播D.驾驶舱呼叫4.飞行服务工作中,负责核实签收各种文件,负责有关物品交接是()。
A.前舱乘务员B. 后舱乘务员C.安全员D.乘务长5.飞机落地前8分钟,乘务员需将客舱顶灯调至()档。
A.OFFB.DIMC.MEDIUMD.NIGHT6. 乘务员在客舱内供餐时,将餐盘从餐车中抽取出来时按照()的顺序逐格抽取。
A.随机抽取B.从中间向上C. 从下至上D. 从上至下7.犹太餐的代码是()。
A.VGMLB.MOMLC.CHMLD.KSML8.出于安全考虑,为避开颠簸高峰期,民航局规定乘务员在落地前()分钟应停止一切服务工作。
A.8B.15C.20D.30 9.旅客在航班中要求冷藏药品,乘务员可将之放入盛有冰块的容器内(如塑料袋内),放置于()处。
A.厨房冷藏柜B.服务车内C.厨房储藏柜D.旅客自行博爱管10.危险性最小的出血是()。
A.动脉出血B.静脉出血C.毛细血管出血D.内出血11.波音、空客飞机配备的氧气瓶的高流量出口(HI)每分钟流出4立升氧气,1瓶氧气可使用()分钟。
A.55B. 77C.87D.9512.使用机上灭火器实施灭火时,需将灭火器距离火源约()米左右进行喷射。
A.1米B. 2米C.5米D.6米13.紧急情况下,机上全体人员必须听从机长的指挥;如果机长失去指挥能力,()接替下达命令。
A.副驾驶B.主任乘务长C.安全员D.3号乘务员14.儿童旅客乘飞机,飞机在起飞、降落时要注意防止小旅客()。
A.睡觉B.大声吵闹C.四处跑动D.玩弄服务设施15.在为糖尿病人推荐机上果汁类饮料时,应重点推荐适宜其饮用的()。
在职教育硕士教育学(综合)模拟试卷1(题后含答案及解析)

在职教育硕士教育学(综合)模拟试卷1(题后含答案及解析)题型有:1. 选择题 3. 名词解释7. 简答题选择题每小题1分。
以下每道小题的备选答案中,只有一个是正确的。
1.教育是人类社会特有的现象,任何社会进步与个人发展都离不开教育,这表明教育具有( )。
A.永恒性B.依附性C.时代性D.独立性正确答案:A解析:教育是人类特有的现象,只要人类存在教育就存在,这体现了教育的永恒性。
知识模块:教育的概念2.教育活动与其他社会活动最根本的区别在于( )。
A.是否有目的的培养人B.是否促进人的发展C.是否促进社会发展D.是否具有组织性和系统性正确答案:A 涉及知识点:教育的概念3.教育的本质特点是( )。
A.影响人的身心发展B.促进社会发展C.有目的地培养人D.完善人的自身生产正确答案:C解析:教育是一种有目的地培养人的社会活动,这是教育区别于其他事物现象的根本特征,是教育的本质属性。
知识模块:教育的概念4.古希腊斯巴达教育目的是培养( )。
A.演说家B.智者C.军人和武士D.全面和谐发展的人正确答案:C 涉及知识点:教育的概念5.我国封建社会学校教育的主要内容( )。
A.六艺B.七艺C.论语D.四书、五经正确答案:D 涉及知识点:教育的概念6.学校教育与生产劳动相脱离始于( )。
A.原始社会B.奴隶社会C.封建社会D.资本主义社会正确答案:B 涉及知识点:教育的概念7.1904年,清政府颁布了由张之洞、张百熙、荣庆等人制定的《奏定学堂章程》,史称( ),这个学制体现的是张之洞“中学为体,西学为用”的思想,吸收了日本明治维新时期的学制形式,也保留了一定的封建科举制度的残余。
该学制的最大特点是修业年限长,从小学堂至大学堂需要21年,至通儒院需要26年。
这是我国正式实施的第一个学制。
A.六三三制B.五四学制C.壬寅学制D.癸卯学制正确答案:D 涉及知识点:教育制度8.通常把一个国家各级各类学校的总体系称为( )。
计算机学科专业基础综合模拟1

[模拟] 计算机学科专业基础综合模拟1单项选择题第1题:利用栈求表达式的值时,设立运算数栈OPND。
假设OPND只有两个存储单元,在下列表达式中,不发生溢出的是( )。
A.A—B*(C—D)B.(A—B)*C—DC.(A—B*C)—DD.(A—B)*(C—D)参考答案:B第2题:已知输入序列为abcd,经过输出受限的双端队列后,能得到的输出序列是( )。
A.dacbB.cadbC.dbcaD.以上答案都不对参考答案:B输出受限的双端队列是指删除限制在一端进行,而插入允许在两端进行的队列。
分析选项A,输入序列为abcd,输出序列为dacb,由输出受限性质可知以da开头的结果只有dabc,选项A为错误答案。
分析选项B,输入序列为abcd,输出序列为cadb,其输入输出顺序为:先在输出端输入a,然后在非输出端输入b,这时队列中的序列为ba,再在输出端输入c,这时队列中的序列为bac:;输出c,再输出a;再在输出端输入d,这时队列中的序列为bd;输出d,再输出b。
最后得到输出序列为cadb。
分析选项C,输入序列为abcd,输出序列为dbca,由输出受限性质可知以db开头的结果只有dbad,选项C为错误答案。
第3题:一个具有1025个结点的二叉树的高度为( )。
A.11B.10C.11至1025之间D.10至1024之间参考答案:C一棵二叉树每层只有1个结点,则具有1025个结点的二叉树的最大高度为1025。
一个具有1025个结点的完全二叉树的高度为11。
这一个具有1025个结点的二叉树的高h为11至1025之间。
第4题:以下关于二叉排序树的说法正确的是( )。
Ⅰ在二叉排序树中,每个结点的关键字都比左孩子关键字大,比右孩子关键字小Ⅱ每个结点的关键字都比左孩子关键字大,比右孩子关键字小,这样的二叉树都是二又排序树Ⅲ在二叉排序树中,新插入的关键字总是处于最底层Ⅳ在二叉排序树中,新结点总是作为叶子结点来插入的Ⅴ二叉排序树的查找效率和二叉排序树的高度有关A.Ⅰ、Ⅱ、Ⅳ、ⅤB.Ⅱ、Ⅲ、ⅣC.Ⅰ、Ⅲ、ⅤD.Ⅰ、Ⅳ、Ⅴ参考答案:D对于二叉排序树,左子树上所有记录的关键字均小于根记录的关键字;右子树上所有记录的关键字均大于根记录的关键字。
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一、简答题(每题6分,共30分)
1.原子的结合键有哪几种?各有什么特点?
离子键:正负离子相互吸引;键合很强,无方向性;熔点、硬度高,固态不导电,导热性差。
共价键:相邻原子通过共用电子对结合;键合强,有方向性;熔点、硬度高,不导电,导热性有好有差。
金属键:金属正离子于自由电子相互吸引;键合较强,无方向性;熔点、硬度有高有低,导热导电性好。
分子键:分子或分子团显弱电性,相互吸引;键合很弱,无方向性;熔点、硬度低,不导电,导热性差。
氢键:类似分子键,但氢原子起关键作用XH-Y;键合弱,有方向性;
熔点、硬度低,不导电,导热性好。
2.面心立方晶体和体心立方晶体的晶胞原子数、配位数和致密度各是多少?
晶胞原子数配位数致密度
面心立方 4 12 74%
体心立方 2 8 68%
3.立方晶系中,若位错线方向为[001],,试说明该位错属于什么类型。
因位错线方向垂直于柏氏矢量,所以是刃位错。
4.请说明间隙化合物和间隙固溶体的异同。
相同点:小原子溶入
不同点:若小原子溶入后,大小原子数量成比例,在选取点阵时,大小原子点阵可以合并,这实际上改变了大原子的点阵结构,因此认为形成
新相,称为间隙相(间隙化合物)。
若小原子溶入后,分布随机,大小原子点阵不能合并,仍然保留大
原子点阵,称为间隙固溶体。
5.试从扩散系数公式说明影响扩散的因素。
从公式表达形式可以看出扩散系数和扩散激活能Q和温度T有关。
扩散激活能越低扩散系数越大,因此激活能低的扩散方式的扩散系数较大,如晶界和位错处的扩散系数较大。
温度越高,原子活性越大,扩散系数越大。
6.何为过冷度?它对形核率有什么影响?
过冷度:实际结晶温度和理论结晶温度的差值。
随过冷度增大,形核率先增后减。
二、作图计算题(每题10分,共40分)
1.在面心立方晶体中,分别画出(101)、[110]和、[,指出哪
些是滑移面、滑移方向,并就图中情况分析它们能否构成滑移系?
对面心立方晶体,(101)非密排面,因此它不是滑移面;[110]是密排方向,因此是滑移方向。
但这二者不能构成滑移系。
和[是密排面和密排方向,因此可以构成滑移系。
2.已知Al为面心立方晶体,原子半径为r A。
若在Al晶体的八面体间隙中
能溶入最大的小原子半径为r B,请计算r B和r A的比值是多少。
3.A-B二元合金中具有共晶反应如下:若共晶
反应刚结束时,α和β相的相对含量各占50%,试求该合金的成分。
设合金成分为c%,由题知:
得:c %=0.55%
4.已知铜的临界切分应力为1Mpa,问要使面上产生[101]方向的滑
移,应在[001]方向上施加多大的力?
对立方晶系,两晶向[h1k1l1]和[h2k2l2]夹角公式为:
故滑移面的法线和拉力轴方向[001]的夹角为:
同理,滑移方向[101]和拉力轴方向[001]的夹角为:
由分切应力公式得:
三、综合分析题(每题15分,共30分)
1.按下列条件绘出A-B二元相图:
1)A组元(熔点600℃)和B组元(熔点500℃)在液态时无限互溶;
2)固态时,A在B中的最大固溶度为w A=0.30,室温时为w A=0.10;而B
在固态下不溶于A;
3)300℃时发生共晶反应。
在A-B二元相图中,分析w B=0.6的合金平衡凝固后,在室温下的相组成物及组织组成物,并计算各相组成物的相对含量。
相组成:A+β
组织组成:A+β+A II
2.请绘出下列Fe-C合金极缓慢冷却到室温后的金相组织示意图,并标注各组织。
(腐蚀剂均为3%硝酸酒精)
工业纯铁: F
20钢: F+P
45钢: F+P
T8钢: P
T12钢: P+Fe
C网状
3
亚共晶白口铸铁:P+Ld’。