根据图幅左下角经纬度计算其所在图幅号

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答5：
int k=99;
string s = k.ToString();
s = Right("0000" + s , 4);
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答3：
or
int i,e;//i=1--99
string e=i.Tostring().PadLeft(4, '0');
long f=lat_deg*3600+lat_min*60+lat_sec; // 纬度单位秒
for(ScaleID=0;ScaleID<8;ScaleID++){
if(Scale[ScaleID]==lscale){
break;
}
}
if(ScaleID==8){
return false;
ScaleMark ScaleMark_1s1000000 = new ScaleMark();
IPoint scaleDelta_1s1000000 = new PointClass();
ScaleMark_1s1000000 = 0;
this.initialScaleMark(ScaleMark_1s1000000, scaleDelta_1s1000000);
Response.Write(j);
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答2：
int k=99;
string s = k.ToString("d4"); s-->0099
private int m_1s1000000_row;//1:100万图幅行
private int m_1s1000000_list;//1：100万图幅列
private int m_assign_row;//指定比例尺图幅行
private int m_assign_list;//指定比例尺图幅列
//lat_sec：纬度-秒
//long lscale：比例尺
bool Trans(char *MapNo,int lon_deg,lon_min,lon_sec,lat_deg,lat_min,lat_sec,long lscale)
{
int ScaleID;
char buf[10];
private int m_scale;//指定比例尺;
private esriUnits m_CurMapUnits;
private IMap curMap = new MapClass();
/// <summary>
/// 构造函数，初始化类中的私有变量
/// </summary>
问：
想把一些数字格式化为字符串，并在不足的位置补0
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答1：
int i = 1;
string j = string.Format("{0:D4}",i);
pScaleMark = (ScaleMark)this.m_scale;
this.initialScaleMark(pScaleMark, scaleDelta);//获取不同比例尺及对应的经纬差
double delta_xp = scaleDelta.X;//其余比例尺的经差(度)
double delta_yp = scaleDelta.Y;//其余比例尺的纬差(度)
MapNo[0] = S[a];
strcpy(MapNo+1,itoa(b,buf,10));
if(ScaleID==0){
return true;
}
MapNo[3] = S[ScaleID];
itoa(c,buf,10);
if(c<10){
MapNo[4]=MapNo[5]='0';
}
}
#region 图幅号计算函数
private IEnvelope FromGeocodingDawn()
{
//计算要素的值
int h = this.m_1s1000000_row;//1:100万行号
int l = this.m_1s1000000_list;//1:100万列号
double df[] = {14400,7200,3600,1200,600,300,150,75}; // 图幅纬差,单位秒
double dr[] = {21600,10800,5400,1800,900,450,225,112.5}; // 图幅经差单位秒
long r=lon_deg*3600+lon_min*60+lon_sec; // 经度, 单位秒
m_assign_row = rowAssigned;
m_assign_list = columAssigned;
m_scale = scale;
if (m_map != null)
{
m_CurMapUnits = m_map.MapUnits;
}
else
{
MessageBox.Show("a oh!", "提示", MessageBoxButtons.YesNo, MessageBoxIcon.Question);
public MapFenfu(int rowIn100,int columIn100, int rowAssigned,int columAssigned,int scale,IMap m_map)
{
m_1s1000000_row = rowIn100;
m_1s1000000_list = columIn100;
strcpy(MapNo+6,buf);
}else if(c<100) {
MapNo[4]='0';
strcpy(MapNo+5,buf);}
else if(c<1000){
strcpy(MapNo+4,buf);
}else{
return false;
}
char S[] = "ABCDEFGHIJKLMNOPQRSTUV"; // 1:1000000地形图图幅所在纬度带字符码
long Scale[] = {1000000,500000,250000,100000,50000,25000,10000,5000}; // 图幅比例尺
谢谢
本文来自: 站长() 详细出处参考：/web/719/248721.htm
#region 好像没用的分幅
/*class MapFenfu
{
public enum ScaleMark { A, B, C, D, E, F, G, H };//不同比例尺的号码
strcpy(MapNo+7,buf);
}else{
return false;
}
MapNo[10] = '"0';
return true;
}
本篇文章来源于GIS动力站| 原文链接：/article/dev/2009/720/0972093211BBBBG0BB3063IEDH8F8I.html
}
int a = f/(4*3600);
int b = r/(6*3600)+31;
int c = (int)(4*3600/df[ScaleID])-(int)((f%(4*3600))/df[ScaleID]);
int d = (int)((r%(6*3600))/dr[ScaleID])+1;
itoa(d,buf,10);
if(d<10){
MapNo[7]=MapNo[8]='0';
strcpy(MapNo+9,buf);
}else if(d<100) {
MapNo[7]='0';
strcpy(MapNo+8,buf);
}else if(d<1000){
{
//进行指定图幅号左上角点经纬度计算：
double ymax = h * delta_y - (hp - 1) * delta_yp; //纬度
double xmin = (l - 31) * delta_x + (lp - 1) * delta_xp;//经度