甘肃省武威市民勤县第四中学2020-2021学年高一上学期期末考试(普通班)化学试卷 Word版

合集下载

甘肃省武威市民勤县第四中学2020_2021学年高一语文上学期期末考试试题.doc

甘肃省武威市民勤县第四中学2020_2021学年高一语文上学期期末考试试题.doc

甘肃省武威市民勤县第四中学2020-2021学年高一语文上学期期末考试试题(考试时间:150分钟试卷满分:150分)一、现代文阅读(共23分)(一)论述类文本阅读(每小题3分,共9分,)阅读下面的文字,完成1——3题。

①“诗言志”,历来被我国诗人视为指导文学创作的一个基本原则,是中国古代诗歌理论领域的开山纲领。

作为一种文学观念,《诗经》在对作诗目的的叙述中就有“诗言志”的萌芽,明确提出“诗言志”的是《尚书·尧典》:“诗言志,歌咏言,声依永,律和声……”作为一种理论概念,“诗言志”最早大约是出自《左传》记载的襄公二十七年赵文子对叔向所说的“诗以言志”。

到了战国时代,“诗言志”的说法就比较普遍了,这个时期各家所说的“诗言志”含义并非完全相同,但占主流的还是指思想、抱负和志向,带有强烈的政治和伦理道德倾向。

②汉代,“诗言志”的内涵开始发生了变化,加入了情的内容。

先秦的“志”到了两汉,主要指志向抱负和情感相融合,情理结合。

孔颖达明确提出了“情志一也”:“在己为情,情动为志,情、志一也。

”汉代将情志作为一个统一体来看待,其意义在于,中国历史上向来有“言志”与“缘情”的分别,道学家往往割裂二者,导致对各种情感抒发的抹杀。

而汉人的情志统一,一来是合理的,并且出现了诗歌创作上汉魏风骨的伟大成就,成为后世的典范;二来对后来“缘情”说的兴起起到了示范作用,因此在文学批评史上有重大理论意义。

③汉魏之后,特别是六朝时期,诗歌创作则朝向重情的方向发展。

陆机《文赋》提出:“诗缘情而绮靡,赋体物而浏亮。

”刘勰在《文心雕龙·明诗》中指出:“诗者,持也,持人情性。

”这些观念的提出,反映了诗歌创作从“言志”到“缘情”的变化。

“言志”的“志”在汉代虽然也包含着“吟咏情性”的因素,但是,这种“情”只能是符合“礼义”之情,这种“志”也在儒家政教怀抱的范围。

而六朝的“缘情”说目的在于突破儒家“礼义”的束缚,自由地抒发自己的感情,不再囿于儒家政教怀抱的“志”,而自由地表现自己的愿望与要求,而且“情”甚至反过来包含了“志”。

2020-2020学年甘肃省武威高一(上)期末数学试卷(含答案解析)

2020-2020学年甘肃省武威高一(上)期末数学试卷(含答案解析)

2020-2020学年甘肃省武威高一(上)期末数学试卷一、选择题(共12小题,每小题5分,满分60分)1.(5分)已知集合A={1,3,},B={1,m},A∪B=A,则m=()A.0或 B.0或3 C.1或 D.1或32.(5分)直线3x+y+1=0的倾斜角是()A.30°B.60°C.120° D.135°3.(5分)如图,在正方体ABCD﹣A1B1C1D1中,直线BD与A1C1的位置关系是()A.平行B.相交C.异面但不垂直D.异面且垂直4.(5分)点(5,﹣3)到直线x+2=0的距离等于()A.7 B.5 C.3 D.25.(5分)一个球的内接正方体的表面积为54,则球的表面积为()A.27πB.18πC.9πD.54π6.(5分)三个数70.3,0.37,ln 0.3的大小关系是()A.70.3>0.37>ln 0.3 B.70.3>ln 0.3>0.37C.0.37>70.3>ln 0.3 D.ln 0.3>70.3>0.377.(5分)若a,b是异面直线,且a∥平面α,则b与α的位置关系是()A.b∥αB.相交C.b⊂αD.b⊂α、相交或平行8.(5分)若幂函数f(x)=xα经过点,则f(x)是()A.偶函数,且在(0,+∞)上是增函数B.偶函数,且在(0,+∞)上是减函数C.奇函数,且在(0,+∞)是减函数D.非奇非偶函数,且在(0,+∞)上是增函数9.(5分)若ac<0,bc<0,则直线ax+by+c=0的图形只能是()A.B.C.D.10.(5分)直线l过点P(1,3),且与x、y轴正半轴围成的三角形的面积等于6的直线方程是()A.3x+y﹣6=0 B.x+3y﹣10=0 C.3x﹣y=0 D.x﹣3y+8=011.(5分)已知直线l的倾斜角为π,直线l1经过点A(3,2)、B(a,﹣1),且l1与l垂直,直线l2:2x+by+1=0与直线l1平行,则a+b等于()A.﹣4 B.﹣2 C.0 D.212.(5分)定义在R上的偶函数f(x)满足:对任意的x1,x2∈[0,+∞)(x1≠x2),有.则()A.f(3)<f(﹣2)<f(1)B.f(1)<f(﹣2)<f(3)C.f(﹣2)<f (1)<f(3)D.f(3)<f(1)<f(﹣2)二、填空题(共4小题,每小题5分,满分20分)13.(5分)已知点A(2,1),B(﹣2,3),C(0,1),则△ABC中,BC边上的中线长为.14.(5分)已知函数f(x)=的值为.15.(5分)到直线x﹣y﹣1=0的距离为2的直线方程为.16.(5分)设a,b,c是空间的三条直线,下面给出四个命题:①若a⊥b,b⊥c,则a∥c;②若a、b是异面直线,b、c是异面直线,则a、c也是异面直线;③若a和b相交,b和c相交,则a和c也相交;④若a和b共面,b和c共面,则a和c也共面.其中真命题的个数是.三、解答题(共4小题,满分40分)17.(10分)求过点P(2,3)并且在两轴上的截距相等的直线方程.18.(10分)直线l的倾斜角为135°,且经过点P(1,1).(1)求直线l的方程;(2)求点A(3,4)关于直线l的对称点A′的坐标.19.(10分)如图,在三棱锥V﹣ABC中,平面VAB⊥平面ABC,△VAB为等边三角形,AC⊥BC且AC=BC=,O,M分别为AB,VA的中点.(1)求证:VB∥平面MOC;(2)求证:平面MOC⊥平面VAB(3)求三棱锥V﹣ABC的体积.20.(10分)已知两条直线l1:x+(1+m)y=2﹣m,l1:2mx+4y=﹣16,m为何值时,l1与l2:(1)相交;(2)平行;(3)垂直.2020-2020学年甘肃省武威高一(上)期末数学试卷参考答案与试题解析一、选择题(共12小题,每小题5分,满分60分)1.(5分)已知集合A={1,3,},B={1,m},A∪B=A,则m=()A.0或 B.0或3 C.1或 D.1或3【解答】解:A∪B=A⇔B⊆A.∴{1,m}⊆{1,3,},∴m=3或m=,解得m=0或m=1(与集合中元素的互异性矛盾,舍去).综上所述,m=0或m=3.故选:B.2.(5分)直线3x+y+1=0的倾斜角是()A.30°B.60°C.120° D.135°【解答】解:根据题意,设直线3x+y+1=0的倾斜角为θ,直线3x+y+1=0即y=﹣x﹣,其斜率k=﹣,则有tanθ=﹣,又由0°≤θ<180°,则θ=120°,故选:C.3.(5分)如图,在正方体ABCD﹣A1B1C1D1中,直线BD与A1C1的位置关系是()A.平行B.相交C.异面但不垂直D.异面且垂直【解答】解:∵正方体的对面平行,∴直线BD与A1C1异面,连接AC,则AC∥A1C1,AC⊥BD,∴直线BD与A1C1垂直,∴直线BD与A1C1异面且垂直,故选:D.4.(5分)点(5,﹣3)到直线x+2=0的距离等于()A.7 B.5 C.3 D.2【解答】解:由已知代入点到直线的距离公式可得:d==7,故选:A.5.(5分)一个球的内接正方体的表面积为54,则球的表面积为()A.27πB.18πC.9πD.54π【解答】解:设正方体的边长为a,则正方体的表面积S=6a2=54,∴a=3,又正方体的体对角线长等于其外接球的直径,∴外接球的半径R=,∴其外接球的表面积为4π×=27π.故选A.6.(5分)三个数70.3,0.37,ln 0.3的大小关系是()A.70.3>0.37>ln 0.3 B.70.3>ln 0.3>0.37C.0.37>70.3>ln 0.3 D.ln 0.3>70.3>0.37【解答】解:∵70.3>70=1,0<0.37<0.30=1,ln 0.3<ln1=0,∴70.3>0.37>ln 0.3.故选A.7.(5分)若a,b是异面直线,且a∥平面α,则b与α的位置关系是()A.b∥αB.相交C.b⊂αD.b⊂α、相交或平行【解答】解:如图,在正方体ABCD﹣A1B1C1D1中,BB1的中点为E,CC1的中点为F,设D1C1=a,平面ABCD为α,则a∥α.观察图形,知:a与AD为异在直线,AD⊂α;a与AA1为异面直线,AA1与α相交;a与EF是异面直线,EF∥α.∴若a,b是异面直线,且a∥平面α,则b和α的位置关系是平行、相交或b 在α内.故选D.8.(5分)若幂函数f(x)=xα经过点,则f(x)是()A.偶函数,且在(0,+∞)上是增函数B.偶函数,且在(0,+∞)上是减函数C.奇函数,且在(0,+∞)是减函数D.非奇非偶函数,且在(0,+∞)上是增函数【解答】解:幂函数f(x)=xα的图象经过点(2,),所以=2α,解得:α=,函数的解析式为:f(x)=,故函数f(x)是非奇非偶函数,且在(0,+∞)上是增函数,故选:D.9.(5分)若ac<0,bc<0,则直线ax+by+c=0的图形只能是()A.B.C.D.【解答】解:由题意知,函数的解析式即y=﹣x﹣,∵ac<0,bc<0,∴a•b >0,∴﹣<0,﹣>0,故直线的斜率小于0,在y轴上的截距大于0,故选C.10.(5分)直线l过点P(1,3),且与x、y轴正半轴围成的三角形的面积等于6的直线方程是()A.3x+y﹣6=0 B.x+3y﹣10=0 C.3x﹣y=0 D.x﹣3y+8=0【解答】解:设所求的直线方程为:.∵过点P(1,3)且与两坐标轴的正半轴所围成的三角形面积等于6,∴,解得a=2,b=6.故所求的直线方程为:3x+y﹣6=0.故选:A.11.(5分)已知直线l的倾斜角为π,直线l1经过点A(3,2)、B(a,﹣1),且l1与l垂直,直线l2:2x+by+1=0与直线l1平行,则a+b等于()A.﹣4 B.﹣2 C.0 D.2【解答】解:∵l的斜率为﹣1,则l1的斜率为1,∴k AB==1,∴a=0.由l1∥l2 得,﹣=1,得b=﹣2,所以,a+b=﹣2.故选B.12.(5分)定义在R上的偶函数f(x)满足:对任意的x1,x2∈[0,+∞)(x1≠x2),有.则()A.f(3)<f(﹣2)<f(1)B.f(1)<f(﹣2)<f(3)C.f(﹣2)<f (1)<f(3)D.f(3)<f(1)<f(﹣2)【解答】解:∵f(x)是偶函数∴f(﹣2)=f(2)又∵任意的x1,x2∈[0,+∞)(x1≠x2),有,∴f(x)在[0,+∞)上是减函数,又∵1<2<3∴f(1)>f(2)=f(﹣2)>f(3)故选:A.二、填空题(共4小题,每小题5分,满分20分)13.(5分)已知点A(2,1),B(﹣2,3),C(0,1),则△ABC中,BC边上的中线长为..【解答】解:BC中点为(﹣1,2),所以BC边上中线长为=.故答案为:.14.(5分)已知函数f(x)=的值为.【解答】解:∵>0∴f()=log3=﹣2∵﹣2<0∴f(﹣2)=2﹣2=故答案为.15.(5分)到直线x﹣y﹣1=0的距离为2的直线方程为x﹣y+2﹣1=0,或x ﹣y﹣2﹣1=0.【解答】解:设要求的直线方程为:x﹣y+m=0,由题意可得:=2,解得m=±2﹣1.∴到直线x﹣y﹣1=0的距离为2的直线方程为:x﹣y+2﹣1=0,或x﹣y﹣2﹣1=0.故答案为:x﹣y+2﹣1=0,或x﹣y﹣2﹣1=0.16.(5分)设a,b,c是空间的三条直线,下面给出四个命题:①若a⊥b,b⊥c,则a∥c;②若a、b是异面直线,b、c是异面直线,则a、c也是异面直线;③若a和b相交,b和c相交,则a和c也相交;④若a和b共面,b和c共面,则a和c也共面.其中真命题的个数是0.【解答】解:若a⊥b,b⊥c,则a与c可能平行,可能相交,也可能异面,故①错误;若a、b是异面直线,b、c是异面直线,则a与c可能平行,可能相交,也可能异面,故②错误;若a和b相交,b和c相交,则a和c可能平行,可能相交,也可能异面,故③错误;若a和b共面,b和c共面,则a和c可能共面,也可能异面.故答案为:0三、解答题(共4小题,满分40分)17.(10分)求过点P(2,3)并且在两轴上的截距相等的直线方程.【解答】解:当直线经过原点时,直线的方程为y=x,化为3x﹣2y=0.当直线不经过原点时,设直线的截距式为x+y=a,把点p(2,3)代入可得:2+3=a,∴a=5.∴直线的方程为:x+y=5.故答案为:3x﹣2y=0或x+y﹣5=0.18.(10分)直线l的倾斜角为135°,且经过点P(1,1).(1)求直线l的方程;(2)求点A(3,4)关于直线l的对称点A′的坐标.【解答】解:(1)直线l的方程为:y﹣1=(x﹣1)tan135°,化为:x+y﹣2=0.(2)设对称点A′的坐标(a,b),则,解得a=﹣2,b=﹣1.∴A′(﹣2,﹣1).19.(10分)如图,在三棱锥V﹣ABC中,平面VAB⊥平面ABC,△VAB为等边三角形,AC⊥BC且AC=BC=,O,M分别为AB,VA的中点.(1)求证:VB∥平面MOC;(2)求证:平面MOC⊥平面VAB(3)求三棱锥V﹣ABC的体积.【解答】(1)证明:∵O,M分别为AB,VA的中点,∴OM∥VB,∵VB⊄平面MOC,OM⊂平面MOC,∴VB∥平面MOC;(2)∵AC=BC,O为AB的中点,∴OC⊥AB,∵平面VAB⊥平面ABC,OC⊂平面ABC,∴OC⊥平面VAB,∵OC⊂平面MOC,∴平面MOC⊥平面VAB(3)在等腰直角三角形ACB中,AC=BC=,∴AB=2,OC=1,=,∴S△VAB∵OC⊥平面VAB,=•S△VAB=,∴V C﹣VAB∴V V=V C﹣VAB=.﹣ABC20.(10分)已知两条直线l1:x+(1+m)y=2﹣m,l1:2mx+4y=﹣16,m为何值时,l1与l2:(1)相交;(2)平行;(3)垂直.【解答】解:(1)2m(1+m)﹣4≠0,可得:m2+m﹣2≠0,解得m≠﹣2且m ≠1.(2)由2m(1+m)﹣4=0,可得:m2+m﹣2≠0,解得m=﹣2或m=1.经过验证可得:m=﹣2时两条直线重合,可得:m=1.(3)m=﹣1时两条直线不垂直,m≠﹣1时,由两条直线垂直,可得:﹣×=﹣1,解得m=﹣.。

甘肃省武威市民勤县第四中学2020-2021学年高一英语上学期期末考试试题

甘肃省武威市民勤县第四中学2020-2021学年高一英语上学期期末考试试题

甘肃省武威市民勤县第四中学2020-2021学年高一英语上学期期末考试试题第I卷第一部分:阅读理解(共两节,满分40分)第一节:阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项,并在答题卡上将该项涂黑。

(共15小题,每小题2分,满分30分)AWant to find a job? Now read the following advertisements.1. Which job of the four jobs will be paid best monthly from the passage?A. Computer SalesclerkB. AccountantC. SecretaryD. Not mentioned in the text2. If you don’t know how to use a computer, you can just apply for(申请) the position (职位) as ______.A. a secretaryB. a waiter or waitressC. an accountantD. a salesclerk3. If you want to get the position of accountant in Wilson Bookstore, you have to satisfy(满足) the following conditions(条件)except _______.A. being a womanB. knowing well how to use a computerC. having been an accountantD. having an accountant certificate4. If you want to try for a job in Fairemont Hotel, you _________.A. have to be a woman and know foreign languagesB. should be a university graduateC. have to be taller than 1.72 metersD. should be younger than 30 years of ageBEach morning a rich man found a poor man sitting on a bench(长凳) in the park. The poor man always sat there, looking at the big hotel in which the rich man lived. One day, the rich man got out of his car and said to the poor man, "Excuse me. I want to know why you sit here and look at my hotel every morning." " Sir," said the poor man, " I am a failure.I have no money , no family, no home. I sleep on this bench, and every night I dream that one day I'll sleep in that hotel." The rich man said , " Tonight your dream will come true. I'll pay for the best room in that hotel for you a whole month."A few days after, the rich man went into the poor man's room to ask him how he was enjoying himself. To his surprise, he found that the man had moved out of the hotel back to his bench. When the rich man asked why, he said, " You see, when I'm sleeping on my bench, I dreamed I am there, in the big hotel. It's a wonderful dream. But when I was there, I dreamed I was back to this cold bench. It was a terrible dream, and I couldn't get any sleep at all."5.The poor man lived in ______ before he met the rich man.A. the hotelB. his homeC. the parkD. the car6.Every morning, the poor man sat on the bench and ______ .A. waited for the rich manB. looked at the rich man's hotelC. looked at the rich man's carD. enjoyed the clean car7.Every night the poor man dreamed of ______ .A. sleeping in a hotelB. becoming richC. owning that hotelD. being the rich man's friend8.The poor man moved out of the hotel because ______ .A. he didn't want to live in such a fine roomB. he didn't like the rich manC. he couldn't pay for the roomD. he couldn't get any sleep at all thereCWhen my family moved to America in 2010 from a small village in Guangdong, China, we brought not only our luggage, but also our village rules, customs and culture. One of the rules is that young people should always respect elders. Unluckily, this rule led to my very first embarrassment in the United States.I had a part-time job as a waiter in a Chinese restaurant. One time, when I was serving food to a middle-aged couple, the wife asked me how the food could be served so quickly.I told her that I had made sure they got their food quickly because I always respect the elderly. As soon as I said that, her face showed great displeasure. My manager, who happened to hear what I said, told me that American people dislike “old”. I then walked back to the table and apologized to the wife. After the couple heard my reason, they understood that the problem was caused by cultural differences, so they laughed and were no longer angry.After that, I changed the way I had been with older people. It is not that I don’t respect them any more; I still respect them, but now I don’t show my feelings through words.9.Jack brought the couple their food very fast because _______.A. the manager asked him to do soB. he respected the elderlyC. the couple wanted him to do soD. he wanted more pay10.When Jack called the couple “elderly”, they became _______.A. nervousB. satisfiedC. unhappyD. excited11.After this experience, Jack _______.A. lost his job in the restaurantB. made friends with the coupleC. no longer respected the elderlyD. changed his way with older people12.Which of the following is TRUE?A. From this experience, Jack learned more about American culture.B. Jack was very angry with the old couple.C. The manager went back to the table and apologized to the couple.D. The more Jack explained, the angrier the couple got.DHow can we improve our life? Many people think that they have to accept(接受) whatever life throws at them. They'll say, "This is my destiny (命运). I cannot change it."Certainly not! You don't have to suffer too much. Your destiny depends on yourself, not on any other factors.I know someone who says she just accepts what life gives her because she has done everything she can to improve it. Guess what her lifestyle is? She wakes up in the morning, goes to work, comes back home, relaxes, chats with people, watches TV, then goes to sleep. Next day, the same routine cycle follows. Huh! Is this what she calls "doing her best"? She believes she has tried her best. But in fact she hasn't.Remember that you get what you pay. You just don't sit around and wait for a million dollars to fall from the sky. You have to get off the couch, get your eyes off the TV screen, get your hands off the phone. Don't expect your luck to change unless you do something about it. If something goes wrong, don't just regard it as a little failure, but use it as feedback (反馈). Learn your lesson, make the most of the situation, and do something to solve the problem. It's not enough to think positively, you also have to act positively.If someone's life is in the trouble, do you just hope that things will turn out fine? Of course not! You get to do anything you can to save the person. So it is with your own life. It is not enough to hope for the best, but you have to do your best. In other words, don't just stand (or sit) there, do something to improve your life.13.The writer's attitude towards destiny is that___.A. we can change itB. we can't depend on ourselvesC. we must accept itD. we have to suffer it14.According to the passage, what should you do if something goes wrong?A. Regard it as a little failure.B. Get your hands off your phone.C. Sit around and wait for luck.D. Do something to solve the problem.15.The underlined word "positively" in the passage means___.A.不礼貌地B.消极地C.积极地D.礼貌地第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。

甘肃省武威市2020-2021学年高一上学期政治期末考试试卷(II)卷

甘肃省武威市2020-2021学年高一上学期政治期末考试试卷(II)卷

甘肃省武威市2020-2021学年高一上学期政治期末考试试卷(II)卷姓名:________ 班级:________ 成绩:________一、单选题 (共24题;共52分)1. (2分) (2020高一上·南岔期末) 为庆祝第35个教师节,高一(1)班小明亲手制作了精美的贺卡,送给自己的老师以表敬意。

该贺卡()A . 不是商品,因为它不是劳动产品B . 不是商品,因为它没有用于交换C . 是商品,因为它具有使用价值和价值D . 是商品,因为它耗费人的体力和脑力2. (4分) (2018高三上·宜昌期中) 2018年“十一”长假期间,小李领取了存在银行里的2万元工资款,带领全家5口人到四川省甘孜藏族自治州稻城亚丁进行了三日自驾游。

在“蓝色星球上的最后一片净土”上,小李花2000元买了几件富有藏民族特色的纪念品,带回来赠送给自己的亲朋好友。

据此回答下列小题。

(1)小李送给亲朋好友的纪念品()A . 是商品,因为它是小李通过交换得来的B . 是商品,因为它耗费了无差别的人类劳动C . 不是商品,因为它没有用于交换D . 不是商品,因为它未满足小李的实际需要(2)材料中的“纸币”依次发挥的职能是()①价值尺度②支付手段③流通手段④贮藏手段A . ①②B . ②③C . ③④D . ②④3. (2分) 2017年4月13日,当天人民币对美元汇率中间价报6.8651,较前一交易日大幅上行289个基点。

前一交易日,人民币对美元汇率中间价报6.8940。

如果人民币对美元汇率保持上述趋势,不考虑其他因素,将对我国经济造成影响的传导路径可能有()①扩大出口商品价格优势——推动外向型经济发展——增加外汇收入②人民币升值——扩大我国对外投资规模——加快“走出去”步伐③海外采购成本降低——增加先进设备引进——推动企业技术升级④进口商品价格上涨——提升企业进口成本——促使企业转型升级A . ①③B . ②③C . ①④D . ③④4. (2分) (2015高一上·桂林期中) 2014年某企业生产的单位M商品的价值量用价格表示为30元,2015年该企业生产M商品的劳动产率提高1/3,而社会必要劳动时间减少1/3。

2024届甘肃省民勤县第四中学 高一上数学期末检测试题含解析

2024届甘肃省民勤县第四中学 高一上数学期末检测试题含解析

(1)求实数 k 的值;
(2)若函数 g x
log4 (a 2x
4 3
a)
,函数
Fx
f
x g x 只有一个零点,求实数 a
的取值范围.
参考答案
一、选择题(本大题共 12 小题,共 60 分)
1、D
【解析】∵ a 0 ,∴ 1 0 ,∴函数 y ax 需向下平
则当 x (1,3] 时, f (x) 2 (1)|x2| ,当 x (3,5) 时, f (x) 4 (1)|x4| ,
2
2
关于 x 的方程 f (x) a(x 3) 2 在 (0, 5) 上至少有两个实数解,
等价于函数 y f (x) 在 (0, 5) 上的图象与直线 y a(x 3) 2 至少有两个公共点,
A f (3) f (7) f (4.5)
B. f (7) f (3) f (4.5) C. f (7) f (4.5) f (3)
D. f (3) f (4.5) f (7)
8.已知函数 f (x) 2sin(x )( 0) 的部分图象如图所示,点 A( , 0) , B,C 是该图象与 x 轴的交点,过点 B 作
所以“ 1 x 5 ”是“ x 5 ”成立的充分不必要条件
故选:A
3、B
【解析】依据题意列出不等式即可解得 V 的最小值.
【详解】由 40
V
4V 5
(40 V )
40 60%
,解得10
V
40
40
则 V 的最小值为 10.
故选:B
4、B
【解析】由根的判别式列出不等关系,求出实数 a 的取值范围.
C.(–∞,0)
D.(1,+∞)

甘肃省武威市民勤县第四中学2020-2021学年高一上学期期末考试地理试题

甘肃省武威市民勤县第四中学2020-2021学年高一上学期期末考试地理试题

2020-2021学年度第一学期期末考试试卷高一地理命题人:第Ⅰ卷(每题2分,共计60分)太阳系是以太阳为中心,和所有受太阳引力约束天体的集合。

下图为太阳系简图。

读图,完成下面小题。

1.图中甲区域的天体主要是()A.卫星B.彗星C.小行星D.流星2.由M到N,天体()A.公转周期变短 B.表面温度降低C.公转方向不同D.均有卫星读右图,完成下面小题。

3.图中A、B、C、D四点中,地球自转线速度最大的是()A.A B.B C.C D.D4.图中A、C、D、E、F各点中,地球自转角速度与B点相同的个数是()A.2个B.5个C.3个D.1个5.我校将期末考试的时间定于1月7、8日两天,请判断此时民勤昼夜长短的状况()A.昼长夜短B.昼短夜长C.昼夜等长D.以上都不对6. 据图回答下题。

B处此时的时刻是( )A. 12:00 B. 6:00C. 18:00 D. 0:00“渔光互补”式光伏电站是在水面上架设太阳能电池板发电,水域用于水产养殖,实现“一地两用”提高单位面积土地的经济价值。

读图完成下列各题。

7.我国下列地区中,最适合大范围建“渔光互补”式光伏电站的是()A.柴达木盆地B.黄土高原C.内蒙古高原D.长江中下游地区北京(北纬40°)某中学地理兴趣小组在开展地理课外活动中,连续三天记录天安门广场升降旗时间(注:与日出日落时间相同)。

结合下表,完成下列问题。

第一天第二天第三天8.此时有关北京昼夜情况说法正确的是()A.昼长夜短B.昼夜平分C.昼短夜长D.极昼9.表中所给的三天时间,太阳直射点的位置和移动方向是()A.北半球,向南移B.北半球,向北移C.南半球,向南移D.南半球,向北移10.从地转偏向力考虑,理想状态下,下列示意中(空心箭头表示水流初始运动方向,虚线箭头表示水流实际运动方向),能正确表示北半球水流流向的是()A.① B.② C.③D.④11.下列现象的产生,主要与太阳活动有关的是()①鸽子飞行失踪②无线电短波通讯出现短暂的中断③狮子座流星雨④手表上的指南针指向异常⑤两极地区美丽"极光"的产生⑥两极地区极昼极夜现象的产生A.①②③B.②④⑤C.③④⑥D.④⑤⑥12.在下图所示四幅图中,所注日期和图形相符合的是(虚线表示的是极圈,阴影表示黑夜)()A. B.C.D.13.读下图,A、B、D、E在晨昏线上,完成下题。

【政治】甘肃省武威市民勤县第四中学2020-2021学年高一上学期期末考试试题

【政治】甘肃省武威市民勤县第四中学2020-2021学年高一上学期期末考试试题

甘肃省武威市民勤县第四中学2020-2021学年高一上学期期末考试试题一、单项选择题(30小题,每小题2分,共计60分)1、一般说来,声音不是商品,但一美国青年带上录音机周游各地,录下自然景区的鸟语虫鸣、松林喧哗,瀑布奔腾和小溪的潺潺水声。

然后他把这些磁带精心剪辑,开办一家“自然之声”的豪华商店。

由于这些磁带能极大地满足人们渴望“回归自然”的心理,并成为众多失眠者地绝妙催眠曲,遂使商店门庭若市,生意兴隆。

这些录有“自然之声”的磁带之所以能成为商品,其根本原因是A.能为众多失眠者催眠B.极大地满足了人们渴望“回归自然”的心理需求C.“自然之声”磁带有使用价值D.录有“自然之声”的磁带耗费了人们的劳动并以交换为目的2、截止2019年10月11日凌晨,电影《我和我的祖国》票房收入已突破24亿,影片接连刷新国庆档票房纪录、献礼片票房纪录,跻身华语影史票房前十。

有观众评价这是一部“值得花钱去影院欣赏的爱国题材的影视剧”,这体现出A.有使用价值的物品就是商品B.使用价值决定商品价格C.耗费人类劳动的产品是商品D.商品是使用价值与价值的统一体3、在“商品—货币—商品”的流通过程中,“商品—货币”阶段的变化“是商品的惊险的跳跃”。

这个跳跃如果不成功,摔坏的不是商品,而是商品所有者。

这说明A.商品生产者需要生产适销对路、质量上乘的商品B.商品生产者生产的商品失去了使用价值和价值C.货币的职能发生了根本的改变D.货币作为一般等价物在物物交换中起决定作用4、2019年春节期间,小林和父母选择标价为498元的西安两日游,并支付600元采购了当地特产,材料中体现的货币职能依次是A.价值尺度支付手段B.支付手段流通手段C.价值尺度流通手段D.流通手段支付手段5、国庆节期间,李先生带全家人去北京旅游。

对其而言,最适合携带的信用工具认识正确的是。

甘肃省武威市民勤县第四中学2020-2021学年高一历史上学期期末考试历史试题

甘肃省武威市民勤县第四中学2020-2021学年高一历史上学期期末考试历史试题

甘肃省武威市民勤县第四中学2020-2021学年高一历史上学期期末考试试题第Ⅰ卷一、单项选择题(本大题共25小题,每小题2分,共50分)1.商代对神的崇拜到了无以复加的地步,商王对神的意志绝对信仰,事事都要征得神的旨意,以至于每事必卜。

这表明商代()A.王权具有神秘色彩B.国王权力受到限制C.宗教势力比较强大D.文化教育极端落后2.柳宗元说:周之失,在于制;秦之失,在于政,不在制。

关于第一个“制”的说法正确的是( )A.其核心是嫡长子继承制B.指的是中央集权制度C.其内涵是封邦建国,以藩屏周D.指的是郡县制3.秦王嬴政统一六国后,把古代传说中神和人最尊贵的三皇五帝的称号合二为一,以“皇帝”作为自己的尊号。

嬴政这一做法( )A.重在限制丞相权力B.在寻求统治依据C.企图保证皇位世袭D.具有宣扬功业色彩4.秦朝三公之下有九卿:奉常,掌管宗庙祭祀礼仪;郎中令,掌管宫殿警卫;少府,掌管皇室财政;卫尉,掌管宫门警卫;太仆,掌管宫廷用马;宗正,掌管皇族、宗族事务……这反映了九卿( ) A.职权细化,各负其责 B.政务繁杂,中央集权 C.官员众多,权力分化 D.服务皇室,君权至上5.秦始皇建立的封建专制主义中央集权制与分封制相比,主要特点是( )①确立皇权的至高无上②爵位世袭制③确立中央和地方的行政构④三公、九卿和郡县长官直接由皇帝任免A.①②③B.①③④C.②③④D.①②④6.“财政事务由三司掌管,这是政府的一个独立部门……。

另外一个独立的实权部门是枢密院,其地位与中书省相当。

”(摘自《哈佛中国史》)材料介绍的制度所在的朝代是( )A.宋朝B.汉朝C.唐朝D.元朝7.公元前127年,汉武帝规定:诸侯王死后,嫡长子继承王位,其他诸子都在王国范围内分得封地为列侯。

这一规定( )A.强化了汉初的郡国并行体制B.巩固了刘姓宗室的血缘亲情C.进一步加强了中央集权 D.增强了地方封国的实力8.“只许州官放火,不许百姓点灯”这一典故源自宋代政府的告示。

甘肃省武威市民勤县第四中学2021届高三上学期期末考试(实验班)物理试题+Word版含答案

甘肃省武威市民勤县第四中学2021届高三上学期期末考试(实验班)物理试题+Word版含答案

为 h,到达斜面顶端的速度为 v,则在此过程中( )
A.物体所受的合力做功为 mgh+1mv2 B.物体所受的合力做功为 1mv2
2
2
C.人对物体做的功为 mgh
D.人对物体做的功大于 mgh
第Ⅱ卷
二、非选择题(本题共 2 小题,共 18 分)
13.如图甲所示,用铁架台、弹簧和多个已知质量且质量相等的钩码,探究在弹性
为避免两船相撞,乙船上的人将一质量为 m 的货物沿水平方向抛向甲船,甲船上 的人将货物接住,求抛出货物的最小速度。(不计水的阻力)
16.一个物块置于粗糙的水平地面上,受到的水平拉力 F 随时间 t 变化的关 系如图甲所示,速度 v 随时间 t 变化的关系 如图乙所示。取 g=10 m/s2,求:
(1)1 s 末物块所受摩擦力的大小 Ff1; (2)物块在前 6 s 内的位移大小 x; (3)物块与水平地面间的动摩擦因数μ。

C.实验中,只在极板间插入有机玻璃板,静电计指针的张角变大
D.实验中,只增加极板带电荷量,静电计指针的张角变大,表明电容增大
6.如图所示,a、b、c 为电场中同一条电场线上的三点,其中 c 为 ab 的中点.已
知 a、b 两点的电势分别为φa=3 V,φb=9 V,则下列叙述正确的是( )
A.该电场在 C 点处的电势一定为 6 V
C.由于气体阻力做负功,地球引力做正功,机械能保持不变
D.卫星克服气体阻力做的功小于引力势能的减小
11.如图所示,一个质量为 m=2.0 kg 的物体放在倾角为α=37°的固定斜面
上,现用 F=30 N、平行于斜面的力拉物体使其由静止开始
沿斜面向上运动。已知物体与斜面之间的动摩擦因数μ=
0.50,斜面足够长,g 取 10 m/s2,sin 37°=0.60,cos 37°

甘肃省武威市2020-2021学年高一英语上学期期末考试试题

甘肃省武威市2020-2021学年高一英语上学期期末考试试题

甘肃省武威市20212021学年高一英语上学期期末考试试题第一部分阅读明白得(共两节,满分40分)第一部分:阅读明白得共两节(满分40分)第一节(15小题;每小题2分,共30分)阅读下列短文,从每题所给的A、B、C、D四个选项中,选出最佳选项,并在答题卡上将该项涂黑。

AWild animals are our friends, but many of them are getting fewer and fewer. We should try to protect them. The four animals below are now in danger.Tibe AntetanlopseTibetan antelopes (藏羚羊) are medium-sized animals. They mainly feed on grass. They are usually found in groups of about 20. They are killed for their wool, which is warm, soft and fine and can be made into expensive clothes. Although people can get the wool without killing the animals, people simply kill them before taking the wool. The number of them is dropping year by year. There are less than 75,000 Tibetan antelopes left in the world, down from a million 50 years ago.Golden MonkeysGolden monkeys are mainly found in Sichuan, Gansu, Shanxi provinces and Shengnongj ia mountainous area of Hubei Province. Golden monkeys have golden-orange fur. They move around in the daytime, usually in groups of as many as 100 to 200 heads, or 20 to 30 heads. They feed on fruits and young leaves of bamboos. But people are destroying the environment where they live. Trees and bamboos are disappearing, so golden monkeys have less and less to eat.ElephantsElephants are very big and st rong . They are bigger than any other animals on land. They are grey and have long trunks and tusks. They have poor eyesight, but very good hea ring and smell. They can lift heavy things and break down branches with their trunks. Elephants are very friendly towards each other and towards theirneighb ors. Normally, they live in a group for many years. Young male elephants do not leave the group until they are about 12 years old. Now, there are very few elephants in the world. The number of them is becoming smaller and smaller because their living areas are used for farming. Also, people hunt them for their tusks.WolvesWolves are not very big. They have grey fur. Wolves have very good eyesight, hearing and smell. Wolves' food is various. They eat animals, insects and snails. They are friendly to each other and never attack people. They do not kill for fun. Wolves are in danger, too. They are losing their living areas because people cut down forests. Soon they will have no home or food.1. Tibetan antelopes usually live in groups of about _______.A. 20B. 30C. 100D. 2002. Which of the following animal s are the biggest on land?A. Tibetan antelopes.B. Golden monkeys.C. Elephants.D. Wolves3. Which of the following sentences is right?A. There are less than 7,500 Tibetan antelopes left in the world now.B. Golden monkeys usually move around during the night.C. Elephants have good eyesight, but very poor hearing and smell.D. Wolves are friendly to each other and they never attack people.4. What can be the best title of the passage?A. Wild animals in dangerB. How to hunt wild animalsC. Animals in the zooD. How to train the animalsBAs traditional Chinese art, paper cutting has a long history. The first and earliest paper cutting was found in China 1,500 years ago. B ut this traditional art is at risk of disappearing now. Luckily, Voyo Woo, a Chinese immigrant(移民)in Ame rica, is trying to bring this art back to life.One Saturday in 2020, Ms Woo held a paper cutting show at a shopping center near Washington. She got much fun and peace doing it. She hoped more people would enjoy it. Ms Woo began to study the art of paper cutting as a 14-year-old girl inher hometown in China. She said all the students at school had to learn paper cutting. But she had a deep love for it. So her teacher spent more time teaching her after class. Later, she won the second prize in a nat ional painting and art competition. Ms Woo went to America after she finished collage in 2008. Soon after that, she took part in an activity to promote(宣传)Chinese paper cutting. And then she was invited to show the a rt in many important activities.“It is im portant to promote this art to Americans or anyone who is interested in it. Maybe it will make this art more popular.” Woo said.From the art of paper cutting, people can know about Chinese cultural values, history and stories of people’s life. Ms Woo uses the art as a t ool to show Chinese culture to people who know little about it. Chinese art is not only for Chinese, but also for people all over the world.5. What did Ms Woo do in 2020?A. She won the second prize in a national painting and art competition.B. She was invited to many activities to show paper cutting.C. She held a paper cutting show at a shopping center near Washington.D. She took part in an activity to promote Chinese paper cutting.6. When did Ms Woo began to study the art of paper cutting?A. when she was fourteenB. after she got to AmericaC. when she was in collegeD. after she finished college7. In the passage, the writer thinks the art of paper cutting is now.A. very po pular in AmericaB. very popular in ChinaC. for people who know about itD. in danger of disappearingCSports are all about change. A team gets better. A kid practices more and swims a personal best or learns a new move on the basketball court. In 2006, two things happened that got me thinking about change—in sports and in life.One of them is tennis champion Andre Agassi, who retired in 2006. Agassi was a terrific player who won 60 titles, including eight major championships(冠军称号). But his greatest accomplishment(成就)might have been how much he changed duringhis career.When he was young, Agassi was a show off who seemed to care only about himself. He didn't train very hard, but he won matches because of his tremendous(极大的)talent. Eventually, though, injuries and his bad attitude caught up with him. He fell from No.1 in the world ranking to No.141. So Agassi changed. He trained harder and became a world-class player again. More importantly, he changed as a person. He was nicer to fans and opponents(对手). He stopped thinking just about himself and started thinking about others. Through his Andre Agassi Charitable Foundation, he raised more than $60 million to help disadvantaged kids around his hometown of Las Vegas, Nevada. He even started a school, the Andre Agassi College Preparatory Academy, for at-risk kids.At the start of a new year, lots of people promise themselves they will change. They might vow to get in good physical shape, do better in school or be nicer to others. Changes such as those can be difficult. But they do happen. Just remember Andre Agassi: It wasn't easy, but he changed, and changed for the better.8. According to the writer, which of the following may be the greatest achievement for Agassi?A. He once ranked No.1 in the world rankings.B. He won 60 titles.C. He changed much during his career.D. He won 8 major championships.9. What does the underlined work “vow” in the 4th paragraph probably mean?A. promise.B. agree.C. become.D. prove.10. What do you know about Andre Agassi Charitable Foundation?A. It is intended to help at-risk kids.B. It is a charity school set up by Agassi.C. Some disadvantaged kids can get help from it.D. Agassi runs it with his prize money.11. What might be talked about in the paragraphs following this passage?A. What achievements Agassi has made after he changed for the better.B. How we can change for the better.C. Another thing happened in l ife that got the writer thinking about change.D. Some assessments(评判) about Agassi from different people.DLaptop computers are popular all over the world. People use them on trains and airplanes, in airports and hotels. These laptops connect people to their workplace. In the United States today, laptops also connect students to their classrooms.Westlake College in Virginia will start a laptop computer program that allows students to do schoolwork anywhere they want. Within five years, each of the 1500 students at the college will receive a laptop. The laptops are part of a $10 million computer program at Westlake, a 110-year-old college. The students with laptops will also have access to the Internet. In addition, they will be able to use e-mail to "speak" with their teachers, their classmates, and their families. However, the most important part of the laptop program is that students will be able to use computers without going to computer labs. They can work wi th it at home, in a fast-food restaurant or under the trees----anywhere at all!Because of the many changes in computer technology, laptop use in higher education, such as colleges and universities, is workable. As laptops become more powerful, they become more similar to desktop computers. In addition, the portable computers can connect students to not only the Internet, but also libraries and other resources. State higher-education officials are studying how laptops can help students. State officials are also testing laptop programs at other universities, too.At Westlake College, more than 60 percent of the staff use computers. The laptops will allow all teachers to use computers in their lessons. As one Westlake teacher said, "Here we are in the middle of Virginia and we're giving students a window on the world. They can see everything and do everything."12. The main purpose of the laptop program is to give each student a laptop to _____.A. use for their schoolworkB. access the InternetC. work at homeD. connect them to libraries13. Which of the following is TRUE about Westlake College?A. All teachers use computers.B. 1500 students have laptops.C. It is an old college in America.D. Students there can do everything.14. “A window on the world” in the last paragraph means that students can _____.A. attend lectures on information technologyB. travel around the worldC. get information from around the worldD. have free laptops15. What can we infer (推断)from the passage?A. The program is successfulB. The program is not workable.C. The program is too expensive.D. We don't know the result yet第二节(共5小题;每小题2分,共10分)依照短文内容,从短文后的七个选项中选出能填入空白处的最佳选项。

2020-2021学年度第一学期甘肃省武威市民勤县第四中学高一物理期末试题

2020-2021学年度第一学期甘肃省武威市民勤县第四中学高一物理期末试题

2020-2021学年度第一学期甘肃省武威市民勤县第四中学高一物理期末试题学校:___________姓名:___________班级:___________考号:___________一、单选题1.关于惯性,下列说法中正确的是()A.同一汽车,速度越快,越难刹车,说明物体速度越大,惯性越大B.物体只有静止或做匀速直线运动时才有惯性C.乒乓球可以快速抽杀,是因为乒乓球的惯性小的缘故D.已知月球上的重力加速度是地球上的16,故一个物体从地球移到月球惯性减小为162.下列关于质点的说法,正确的是( )A.因为原子核很小,所以原子核一定可以当作质点B.研究和观察日食时,可把太阳当作质点C.研究地球的自转时,可把地球当作质点D.研究地球的公转时,可把地球当作质点3.下面哪一组单位属于国际单位制中的基本单位A.米、牛顿、千克B.千克、焦耳、秒C.米、千克、秒D.米/秒2、千克、牛顿4.用如图所示的方法可以测量人的反应时间.实验时,上方的手捏住直尺的顶端,下方的手做捏住直尺的准备.当上方的手放开直尺时,下方的手“立即”捏住直尺.下列说法正确的是A.图中上方的手是受测者的B.图中下方的手是受测者的C.图中的两只手应是同一位同学的D.两手间的距离越大,说明受测者的反应时间越长5.伽利略在研究运动的过程中,创造了一套科学研究方法,如图所示:其中方框4中是()A.提出猜想B.数学推理C.实验检验D.合理外推6.如图所示是P、Q两质点运动的v-t图象,由图线可以判定( )A.P质点的速度越来越小B.零时刻P质点的加速度为零C.在t1时刻之前,P质点的加速度均大于Q质点的加速度D.在0-t1时间内,P质点的位移大于Q质点的位移7.一种测定风作用力的仪器原理如图所示,它的细长金属丝一端固定于悬点O ,另一端悬挂着一个质量为m 金属球.无风时,金属丝自然下垂,当受到沿水平方向吹来的风时,金属丝将偏离竖直方向一定角度θ,风力越大,偏角越大.下列关于风力F 与偏角θ小球质量m 之间的关系式正确的是()A.F = mg sinθB.F = mg cosθC.F = mg tanθD.F = mg cotθ8.2009年9月28日,甬台温高速铁路正式开通,浙江铁路进入了高铁时代.假设列车在某段距离中做匀加速直线运动,速度由5m/s增加到10m/s时位移为x,则当速度由10m/s增加到15m/s时,它的位移是()A.5 2 xB.5 3 xC.2xD.3x9.用水平外力F将木块压在竖直墙面上面保持静止状态,如图所示,下列说法中正确的是()A.木块重力与墙对木块的静摩擦力平衡B.木块重力与墙对木块的静摩擦力是一对作用力和反作用力C.外力F与墙对木块的正压力是一对作用力和反作用力D.木块对墙的压力的反作用力与外力F大小相等10.如图所示,一根轻质弹簧固定在天花板上,下端系着质量为m的物体A,A的下面再用细绳挂另一质量也为m的物体B。

武威市民勤县第四中学2020_2021学年高一物理上学期期末考试试题普通班

武威市民勤县第四中学2020_2021学年高一物理上学期期末考试试题普通班

甘肃省武威市民勤县第四中学2020—2021学年高一物理上学期期末考试试题(普通班)第I卷(选择题)一、单选题(每小题4分,共36分)1.在物理学发展的过程中,许多物理学家的科学研究推动了人类文明的进程.在对以下几位物理学家所作科学贡献的叙述中,正确的说法是()A.在对自由落体运动的研究中,伽利略猜想运动速度与下落时间成正比,并直接用实验进行了验证B.牛顿应用“理想斜面实验”推翻了亚里士多德的“力是维持物体运动的原因”观点C.胡克认为只有在一定的条件下,弹簧的弹力才与弹簧的形变量成正比D.亚里士多德认为两个从同一高度自由落下的物体,重物体与轻物体下落一样快2.某学校刚刚结束运动会,跳高比赛项目引人注目.如图,跳高运动员起跳后向上运动,越过横杆后开始向下运动,则运动员越过横杆前、后在空中所处的状态分别为()A.失重、失重B.超重、超重C.失重、超重D.超重、失重3.t=0时甲、乙两物体同时从同一地点出发沿同一直线运动,以出发点为参考点,它们的位移—时间(x—t)图像如图所示,则在t1时刻()A.它们的速度相同,甲在乙的前方B.它们的速度相同,乙在甲的前方C.它们的位置相同,甲的速度大于乙D.它们的位置相同,乙的速度大于甲4.如图一只小鸟落在了树枝上,树枝发生了弯曲,小鸟处于静止状态,下列说法正确的是()A.树枝发生了弯曲,是因为小鸟对树枝的压力大于树枝对小鸟的支持力B.树枝对小鸟的支持力是由树枝发生形变产生的C.树枝对小鸟弹力的方向斜向上偏右D.小鸟起飞瞬间,翅膀对空气的作用力大于空气对翅膀的作用力5.如图所示,有一辆汽车满载西瓜在水平路面上匀速前进.突然发现意外情况,紧急刹车做匀减速运动,加速度大小为a,则中间一质量为m的西瓜A受到其他西瓜对它的作用力的大小是()A.m22-B.mag aC.m22g a+D.m(g+a)6.汽车刹车后做匀减速直线运动,经过3s停止运动,那么汽车在先后连续相等的三个1s内通过的位移之比x1:x2:x3为()A.1:2:3 B.5:3:1 C.1:4:9 D.3:2:17.如图所示,在0.1μ=的水平桌面上向右运动的物体,质量为20 kg,在运动过程中,还受到一个方向向左的大小为10 N的拉力作用,则物体受到的滑动摩擦力为(10N/kgg=)() A.10 N,向右B.10 N,向左C.20 N,向右D.20 N,向左8.如图所示,一个小木块在斜面上匀速下滑,则小木块受到的力是()A.重力、弹力和摩擦力B .重力、弹力和下滑力C .重力、弹力、下滑力和摩擦力D .重力、下滑力和摩擦力9.如图所示,甲、乙两辆小车放在光滑的水平面上.在相同的拉力F 作用下,甲车产生的加速度为22m/s ,乙车产生的加速度为24m/s ,则甲、乙两车的质量之比12:m m 为( )A .1∶2B .2∶1C .1∶4D .4∶1二、多选题(每小题4分,少选得2分,错选不得分,共16分) 10.下列属于国际单位制中基本单位的是( )A .牛顿(N )B .千克(kg )C .焦耳(J )D .米(m)11.如图所示,用轻绳悬挂于运动小车里的小球向左偏离竖直方向θ角,则小车可能的运动情况是( ) A .向右加速运动 B .向右减速运动 C .向左加速运动D .向左减速运动12.如图所示,人站在自动扶梯的水平踏板上,随扶梯斜向上匀速运动,不计空气阻力,以下说法正确的是()A.人受到重力和支持力的作用B.人受到重力、支持力和摩擦力的作用C.人的重力和人对踏板的压力是一对平衡力D.人对踏板的压力和踏板对人的支持力是一对作用力和反作用力13.如图所示,质量为m的木块在推力F的作用下,在水平地面上做匀速直线运动.已知木块与地面间的动摩擦因数为μ,F的方向与地面成θ角斜向下.则地面对木块的滑动摩擦力大小为()A.μmg B.Fco sθC.F sinθD.μ(mg+F sinθ)第II卷(非选择题)三、实验题(每空2分,共14分)14.小欧同学用如图所示的实验装置来“探索求合力的方法”。

2025届甘肃省武威市民勤县第四中学生物高一第一学期期末联考模拟试题含解析

2025届甘肃省武威市民勤县第四中学生物高一第一学期期末联考模拟试题含解析

2025届甘肃省武威市民勤县第四中学生物高一第一学期期末联考模拟试题请考生注意:1.请用2B铅笔将选择题答案涂填在答题纸相应位置上,请用0.5毫米及以上黑色字迹的钢笔或签字笔将主观题的答案写在答题纸相应的答题区内。

写在试题卷、草稿纸上均无效。

2.答题前,认真阅读答题纸上的《注意事项》,按规定答题。

一、选择题:(共6小题,每小题6分,共36分。

每小题只有一个选项符合题目要求)1.下图所示,1、2为物镜长度;3、4为目镜长度;5、6为观察时物镜与标本之间的距离大小。

欲获得最大放大倍数的观察效果,其正确的组合是A.1、3、5B.2、4、6C.2、3、6D.2、4、52.细胞相对表面积、细胞对外物质交换速率和细胞新陈代谢强度之间的关系正确的是()A.细胞的相对表面积越大,物质交换速率越快,细胞新陈代谢越旺盛B.细胞的相对表面积越大,物质交换速率越慢,细胞新陈代谢越缓慢C.细胞的相对表面积越小,物质交换速率越快,细胞新陈代谢越缓慢D.细胞的相对表面积越小,物质交换速率越慢,细胞新陈代谢越旺盛3.在“比较过氧化氢在不同条件下的分解”实验中,对1~4号试管的过氧化氢溶液分别进行4种不同处理(常温、90℃水浴加热、滴入2滴FeCl3溶液、滴入2滴新鲜肝脏研磨液)后,观察实验现象,以下有关该实验的叙述正确的是A.试管2和3的基本反应原理相同B.比较试管1和2,说明不可用来研究温度对过氧化氢酶活性的影响C.若将试管4中的新鲜肝脏研磨液换成久置肝脏研磨液,则反应速率将不变D.比较试管1和4,说明酶具有高效性4.研究人员将R型肺炎链球菌荚膜中的各种糖类都提取出来,然后再通过动物实验筛选出能引发机体免疫反应的糖类制成“多糖”疫苗,这里的多糖相当于免疫反应中的A.抗原 B.抗体 C.淋巴因子 D.抗原受体5.下图表示夏季晴朗的白天某种绿色植物叶片光合作用强度变化曲线。

下列对此图描述错误..的是A.AB之间光合作用强度上升是因为光照强度增强所致B.DE之间光合作用强度下降是因为光照强度减弱所致C.BC和DE光合作用强度下降原因不同D.AB和CD光合作用强度上升原因相同6.生物体内主要能源物质、主要的储能物质和直接能源物质分别是A.脂肪、糖类、ATP B.ATP、脂肪、糖类C.糖类、脂肪、ATP D.糖类、ATP、糖类二、综合题:本大题共4小题7.(9分)为探究植物A能否移植到某地生长,某生物学研究性学习小组通过质壁分离实验,用不同浓度的蔗糖溶液测定植物A根细胞液的浓度,实验结果如下表:第1组第2组第3组第4组蔗糖浓度(mol/L)0.15 0.2 0.25 0.3质壁分离状态不分离刚分离显著分离显著分离请回答:植物细胞的____________相当于一层半透膜,细胞液与外界溶液之间存在________,因此,植物细胞可以通过__________吸水和失水。

甘肃省武威市民勤县第四中学2023年高一生物第一学期期末联考模拟试题含解析

甘肃省武威市民勤县第四中学2023年高一生物第一学期期末联考模拟试题含解析

甘肃省武威市民勤县第四中学2023年高一生物第一学期期末联考模拟试题注意事项1.考生要认真填写考场号和座位序号。

2.试题所有答案必须填涂或书写在答题卡上,在试卷上作答无效。

第一部分必须用2B 铅笔作答;第二部分必须用黑色字迹的签字笔作答。

3.考试结束后,考生须将试卷和答题卡放在桌面上,待监考员收回。

一、选择题(本大题共7小题,每小题6分,共42分。

)1.下列有关ATP的叙述,错误..的是A.细胞内ATP的含量很少,但消耗量很大B.ATP与ADP相互转化过程中所需酶的种类相同C.ATP和ADP迅速相互转化保证了机体对能量的需求D.人体细胞内形成ATP的主要场所是线粒体2.下列属于构成细胞的大量元素的一组是A.Ca、C、O、Mn B.H、O、K、MgC.P、N、C、Mo D.N、S、O、Fe3.在有氧呼吸的全过程中,氧的作用发生在A.葡萄糖酵解为丙酮酸的阶段B.柠檬酸(三羧酸)循环阶段C.产生大量ATP的阶段D.参与有氧呼吸的全过程4.有氧呼吸过程中葡萄糖分解释放的能量将()A.全部用于生物合成等生理过程B.一部分以热能形式散失,一部分转移到ATP中C.全部转移到ATP中D.一部分供给生命活动需要,一部分转移到ATP中5.关于生物学原理在农业生产上的应用,下列叙述错误的是A.“一次施肥不能太多”,避免土壤溶液浓度过高,引起烧苗现象B.“正其行,通其风”,能为植物提供更多的CO2,提高光合作用C.“低温、干燥、无O2储存种子”,更能降低细胞呼吸,减少有机物的消耗D.“露田,晒田”,能为根系提供更多O2,促进细胞呼吸,有利于根吸收无机盐6.下图装置可用来测定豌豆种子萌发时进行的呼吸作用类型。

同时关闭活塞,在25℃下经过20 min 再观察红色液滴移动情况,下列对实验结果分析不符合实际的是A.装置1的红色液滴向左移动的体积是呼吸作用消耗O2的体积,装置2的红色液滴向右移动的体积是呼吸作用释放CO2和消耗O2的体积之差B.若装置1的红色液滴左移,装置2的红色液滴不移动,则说明萌发的种子既进行有氧呼吸也进行无氧呼吸C.若装置1的红色液滴左移,装置2的红色液滴不移动,则说明萌发的种子只进行有氧呼吸D.若装置1的红色液滴不移动,装置2的红色液滴右移,则说明萌发的种子只进行无氧呼吸7.在鉴定可溶性还原糖的实验中,加入斐林试剂时必须()A.先加入斐林试剂甲液,后加入乙液B.先加入斐林试剂乙液,后加入甲液C.将斐林试剂的甲液和乙液混合均匀后再使用D.以上A、B、C三项操作方法都正确8.(10分)鉴定一个正在分裂的细胞是高等植物细胞还是高等动物细胞,最可靠的方法是( )A.观察是否有中心体发出星状射线B.观察是否有细胞核的消失和重建C.观察是否有纺锤体的出现D.观察是否有染色体形态的变化二、非选择题9.(10分)选取生理状态良好的甜槠植株,保持温度(30℃)、CO2浓度等恒定,测定不同光照强度条件下O2和CO2的释放量(如图1)。

  1. 1、下载文档前请自行甄别文档内容的完整性,平台不提供额外的编辑、内容补充、找答案等附加服务。
  2. 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
  3. 3、如文档侵犯您的权益,请联系客服反馈,我们会尽快为您处理(人工客服工作时间:9:00-18:30)。

2020-2021学年第一学期期末考试试卷
高一化学(普)
命题人:
第I卷
可能用到的相对原子质量:H-1 C-12 N-14 O-16 Na-23 Mg-24 Al-27 S-32
Cl-35.5 K-39 Ca-40 Fe-56 Cu-64 Mn-55 Pb-207
一、选择题(每小题只有一个正确选项,每小题3分,共60分)
1. 下列化学药品与其危险化学品图形标志不一致的一组是()
A.甲烷—2 B.烧碱—1 C.酒精—3 D.白磷—4
2.“摩尔”是()的单位
A. 质量
B. 体积
C. 物质的量
D.摩尔质量
3. 下列物质分离方法错误的是()
A.用过滤的方法除去食盐水中的泥沙
B.用四氯化碳萃取碘水中的碘
C.用蒸馏的方法将自来水制成蒸馏水
D.用分液的方法分离硫酸和水
4.下列有关分散系的叙述中不正确的是( )
A.胶体分散质微粒直径较大,不能透过滤纸
B.液态分散系根据分散质粒子大小分为溶液、胶体和浊液三类
C.利用丁达尔效应可以区分溶液和胶体
D.纳米材料分散到液体分散剂中得到的分散系属于胶体
5.物质的量相同的H
2O和NH
3
一定具有相同的()
A.原子个数
B.质量
C.体积
D.分子个数
6.下列反应中,水作还原剂的反应是( )
A.CaO+H
2O=Ca(OH)
2
B.Na+H
2
O=2NaOH+H
2

C.2F
2+2H
2
O=4HF+O
2
↑D.Na
2
O
2
+2H
2
O=2NaOH+O
2

7.下列物质不属于电解质的是()
A. Ba (OH)
2 B. CaCl
2
C.H
2
SO
4
D.Cu
8.下列仪器用于过滤和蒸发分离物质的是( )
①漏斗②试管③蒸发皿④天平⑤烧杯⑥研钵
A.①③④ B.①②⑥ C.①③⑤ D.①③⑥9.用聚光手电筒照射下列分散系,能观察到丁达尔效应的是( )
A.溶液 B.胶体 C.乳浊液 D.悬浊液
10.地壳中含量最多的金属元素和非金属元素组成的化合物的化学式是( )
A.CuO B.Al
2O
3
C.Fe
2
O
3
D.SiO
2
11.在反应CuO + H
2=Cu +H
2
O中,氧化剂和还原剂的物质的量之比是()
A. 40:1
B. 1:1
C. 1:40
D. 2:1
12.下列叙述正确的是()
A.1molH
2
O的质量为18g
B.二氧化碳的摩尔质量为44g
C.铁原子的摩尔质量等于它的相对原子质量D.标准状况下,1mol 任何物质的体积均为22.4L
13.下列各组离子能在溶液中大量共存的是( )
A.Ag+、K+、NO
3-、Cl-B.Mg2+、Na+、SO
4
2-、Cl-
C.NH
4+、Mg2+、OH−、Cl− D Ba2+、Na+、CO
3
2−、SO
4
2−
14.下列电离方程式中,不正确的是( )
A. NaHCO
3 = Na++H++CO
3
2- B. Ba(OH)
2
=Ba2++2OH—
C. Al
2(SO
4
)
3
=2Al3++3SO
4
2- D. NaCl=Na++Cl—
15.下列溶液中Cl—浓度与1mol·L—1 AlCl
3
溶液中浓度相等的是()
A. 3mol/L 的KCl溶液 B. 2.5mol/L的CaCl
2
溶液
C. 2.5mol/L的NaCl溶液 D. 2mol/L FeCl
3
溶液
16.下列离子方程式中正确的是( )
A.稀硫酸滴加在铜片上: Cu+2H+ = Cu2+ +H
2

B.氧化铁粉末溶于稀盐酸: Fe
2O
3
+ 6H+ = 2Fe3+ + 3H
2
O
C.硫酸滴加到氢氧化钡溶液中: H+ + OH- = H
2
O
D.碳酸氢钠和盐酸反应: CO
32-+ 2H+ = CO
2

17.用洁净的铂丝蘸取以下溶液进行焰色反应,其火焰焰色为黄色的是()
A.KCl溶液
B.NaCl溶液
C.CuCl
2溶液 D. FeCl
3
溶液
18.氧化钠和过氧化钠的相同点是( )
A.都是淡黄色的固体 B.氧元素的化合价均为-2价C.都能与水反应生成碱 D.都能与二氧化碳反应放出氧气19.下列混合物中,可选用过滤实验分离的是( )
A.固体和固体 B.固体和液体 C.液体和液体 D.液体和气体20.下列反应进行分类时,不属于四种基本反应类型的是( )
A. Zn+H
2SO
4
===ZnSO
4
+H
2
↑ B. 2KClO
3
2KCl+3O
2

C. S+O
2SO
2
D. CH
4
+2O
2
CO
2
+2H
2
O
第II卷
二、填空题(每空2分,共40分)
21.I.如图是有关钠与水反应及产物检验的实验装置。

实验开始时先向管内加入滴有酚酞试液的水,使水位达到B端管口,然后迅速塞紧橡胶塞并拔掉大头针,此时Na掉入水中。

回答下列问题:
(1)钠与水反应的化学方程式为____________________________________。

(2)钠与水反应的现象有很多,不同的现象证明不同的性质。

①能证明钠的密度比水小的现象是_______________________________。

②能证明钠的熔点低的现象是_______________________________________。

③能证明有氢氧化钠生成的现象是______________________________。

④能证明有气体产生的现象是A端液面___(填“上升”、“下降”或“不变”,下同),B端液面_________。

II某化学实验小组需要2mol/L的NaCl溶液98mL,现在NaCl固体来配制。

请回答下问题:
(1)需称取NaCl固体的质量为 g
(2)配制过程中,不需要的仪器(填序号).
A.药匙 B.胶头滴管 C.漏斗 D.烧杯 E.玻璃棒 F.托盘天平
完成实验还缺少的仪器是.
(3)在配制过程中,下列操作能引起所配溶液浓度偏低的有(填序号).
①定容时,俯视刻度线
②转移时有少量液体溅出
③转移前,容量瓶中含有少量蒸馏水
22.运用化学知识完成下列问题:
(1)潜艇中常用Na
2O
2
作供氧剂,请写出Na
2
O
2
和CO
2
反应的化学方程式:
(2)除去Na
2CO
3
和NaHCO
3
固体混合物中的NaHCO
3
可选用的方法是:
(3)在CuSO
4
溶液中加入少量的金属Na,将有红色的固体生成(填“正确”或“错误”)
(4)配平以下反应方程式前系数:C + H
2SO
4(浓)
== CO
2
↑ + SO
2
↑ + H
2
O
23.在标准状况下,1.5molCO
2的体积为L;2.5molO
2
质量为g;
将20gNaOH的物质的量为 mol,将其溶于水配成100ml溶液,该溶液中NaOH物质的量浓度为mol/L,其中Na+物质的量浓度为mol/L
加热
2020-2021学年第一学期期末考试试卷答案
高一化学(普)
一、选择题(每小题只有一个正确选项,每题3分,共60分)
1. B
2.C
3. D
4.A
5.D
6.C
7.D
8.C
9.B 10.B 11.B 12.A 13.B 14.A 15.A 16.B 17.B 18.C 19.B 20.D
二、填空题(每空2分,共40分)
21、I(1)2Na+2H2O=2NaOH+H2↑
(2)①钠浮在水面上
②钠熔化为光亮的小球
③溶液变为红色
④上升,下降
II(1)11.7 (2)C 100mL容量瓶(3)②
22、(1)2Na2O2 + 2CO2==2 Na2CO3 + O2(2)加热(3)错误(4) 2;2
23、 33.6,80,0.5, 5, 5。

相关文档
最新文档