模拟试题(十)

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中考数学模拟试卷(十)(有答案)

中考数学模拟试卷(十)(有答案)

中考数学模拟试卷(十)一、选择题(每小题3分,共30分)1.3x2可以表示为()A.x2+x2+x2B.x2•x2•x2C.3x•3x D.9x2.200粒大米重约4克,如果每人每天浪费1粒米,那么约458万人口的漳州市每天浪费大米用科学记数法表示约为()A.9.16×103克B.9.16×104克C.9,16×105克 D.0.916×105克3.计算:()﹣1﹣(π﹣1)0,结果正确的是()A.2 B.1 C.﹣ D.﹣4.不能判定四边形ABCD为平行四边形的题设是()A.AB=CD,AB∥CD B.∠A=∠C,∠B=∠D C.AB=AD,BC=CD D.AB=CD,AD=BC5.如图,AB∥ED,CD=BF,若△ABC≌△EDF,则还需要补充的条件可以是()A.AC=EF B.BC=DF C.AB=DE D.∠B=∠E6.P1(x1,y1),P2(x2,y2)是函数y=x图象上的两点,则下列判断中正确的是()A.y1>y2B.y1<y2C.当x1<x2时,y1>y2D.当x1<x2时,y1<y27.我国古代数学家利用“牟合方盖”(如图甲)找到了球体体积的计算方法.“牟合方盖”是由两个圆柱分别从纵横两个方向嵌入一个正方体时两圆柱公共部分形成的几何体.图乙所示的几何体是可以形成“牟合方盖”的一种模型,它的主视图是()A.B.C.D.8.一个盒子内装有大小、形状相同的四个球,其中红球1个、绿球1个、白球2个,小明摸出一个球不放回,再摸出一个球,则两次都摸到白球的概率是()A.B.C.D.9.小美将某服饰店的促销活动内容告诉小明后,小明假设某一商品的定价为x元,并列出关系式为0.3(2x ﹣100)<1000,则下列何者可能是小美告诉小明的内容?()A.买两件等值的商品可减100元,再打3折,最后不到1000元B.买两件等值的商品可减100元,再打7折,最后不到1000元C.买两件等值的商品可打3折,再减100元,最后不到1000元D.买两件等值的商品可打7折,再减100元,最后不到1000元10.如图,矩形ABCD中,AB=3,BC=4,动点P从A点出发,按A→B→C的方向在AB和BC上移动,记PA=x,点D到直线PA的距离为y,则y关于x的函数图象大致是()A. B. C. D.二、填空题(每小题4分,共24分)11.若两个相似三角形的相似比是1:2,则它们的面积比是.12.已知直线l与⊙O相切,若圆心O到直线l的距离是5,则⊙O的半径是.13.一组数:2,1,3,x,7,﹣9,…,满足“从第三个数起,前两个数依次为a、b,紧随其后的数就是2a ﹣b”,例如这组数中的第三个数“3”是由“2×2﹣1”得到的,那么这组数中x表示的数为.14.如图,等腰直角三角形ABC的直角边长为1.如果将斜边BC绕着点B顺时针旋转45°后得BC′,则tan ∠BAC′=.15.计算下列各式的值:;;;.观察所得结果,总结存在的规律,应用得到的规律可得=.16.定义:直线l1与l2相交于点O,对于平面内任意一点M,点M到直线l1,l2的距离分别为p、q,则称有序实数对(p,q)是点M的“距离坐标”.根据上述定义,“距离坐标”是(1,2)的点的个数共有个.三、解答题(共46分)17.根据图中提供的信息,列方程或方程组求杯子和热水瓶的单价.18.某市对教师试卷讲评课中学生参与的深度和广度进行评价,其评价项目为主动质疑、独立思考、专注听讲、讲解题目四项.评价组随机抽取了若干名初中生的参与情况,绘制了如下两幅不完整的统计图.请根据图中所给的信息解答下列问题:(1)这次评价中,一共抽查了名学生;(2)请将条形统计图补充完整;(3)如果全市有16万初中学生,那么在试卷讲评课中,“独立思考”的学生约有多少万人?19.一个足球被从地面向上踢出,它距地面高度y(m)可以用二次函数y=﹣4.9x2+19.6x刻画,其中x(s)表示足球被踢出后经过的时间.(1)解方程﹣4.9x2+19.6x=0,并说明其根的实际意义;(2)求经过多长时间,足球到达它的最高点?最高点的高度是多少?20.在正方形ABCD外侧作直线AP,点B关于直线AP的对称点为E,连接BE,DE,其中DE交直线AP 于点F.(1)①依题意补全图1;②若∠PAB=20°,求∠ADF的度数;(2)若设∠PAB=a,且0°<a<90°,求∠ADF的度数(直接写出结果,结果可用含a的代数式表示)(3)如图2,若45°<∠PAB<90°,用等式表示线段AB、FE、FD之间的数量关系,并证明.中考数学模拟试卷(十)参考答案与试题解析一、选择题(每小题3分,共30分)1.3x2可以表示为()A.x2+x2+x2B.x2•x2•x2C.3x•3x D.9x【考点】单项式乘单项式;同底数幂的乘法.【分析】分别利用合并同类项法则以及同底数幂的乘法运算法则、单项式乘以单项式运算法则化简求出答案.【解答】解:A、x2+x2+x2=3x2,故此选项正确;B、x2•x2•x2=x6,故此选项错误;C、3x•3x=9x2,故此选项错误;D、9x≠3x2,故此选项错误;故选:A.2.200粒大米重约4克,如果每人每天浪费1粒米,那么约458万人口的漳州市每天浪费大米用科学记数法表示约为()A.9.16×103克B.9.16×104克C.9,16×105克 D.0.916×105克【考点】科学记数法—表示较大的数.【分析】科学记数法的表示形式为a×10n的形式,其中1≤|a|<10,n为整数.确定n的值时,要看把原数变成a时,小数点移动了多少位,n的绝对值与小数点移动的位数相同.当原数绝对值>1时,n是正数;当原数的绝对值<1时,n是负数.【解答】解:∵200粒大米重约4克,每人每天浪费1粒米,∴458万人口的漳州市每天浪费大米用科学记数法表示约为:4÷200×458万=9.16×104(克).故选:B.3.计算:()﹣1﹣(π﹣1)0,结果正确的是()A.2 B.1 C.﹣ D.﹣【考点】负整数指数幂;零指数幂.【分析】首先计算负整数指数幂和零次幂,然后再计算减法即可.【解答】解:原式=2﹣1=1,故选:B.4.不能判定四边形ABCD为平行四边形的题设是()A.AB=CD,AB∥CD B.∠A=∠C,∠B=∠D C.AB=AD,BC=CD D.AB=CD,AD=BC【考点】平行四边形的判定.【分析】根据平行四边形的判定定理(一组对边平行且相等的四边形是平行四边形;两组对角分别相等的四边形是平行四边形;两组对边分别相等的四边形是平行四边形)求解即可求得答案.【解答】解:A、∵AB=CD,AB∥CD,∴四边形ABCD为平行四边形(一组对边平行且相等的四边形是平行四边形);股本选项能判定四边形ABCD 为平行四边形;B、∵∠A=∠C,∠B=∠D,∴四边形ABCD为平行四边形(两组对角分别相等的四边形是平行四边形);股本选项能判定四边形ABCD 为平行四边形;C、由AB=AD,BC=CD,不能判定四边形ABCD为平行四边形;D、∵AB=CD,AD=BC,∴四边形ABCD为平行四边形(两组对边分别相等的四边形是平行四边形);股本选项能判定四边形ABCD 为平行四边形.故选C.5.如图,AB∥ED,CD=BF,若△ABC≌△EDF,则还需要补充的条件可以是()A.AC=EF B.BC=DF C.AB=DE D.∠B=∠E【考点】全等三角形的性质.【分析】因为AB∥ED,所以∠B=∠D,又因为CD=BF,则添加AB=DE后可根据SAS判定△ABC≌△DEF.【解答】解:∵AB∥ED,∵∠B=∠D,∵CD=BF,CF=FC,∴BC=DF.在△ABC和△DEF中BC=DF,∠B=∠D,AB=DE,∴△ABC≌△DEF.故选C.6.P1(x1,y1),P2(x2,y2)是函数y=x图象上的两点,则下列判断中正确的是()A.y1>y2B.y1<y2C.当x1<x2时,y1>y2D.当x1<x2时,y1<y2【考点】一次函数图象上点的坐标特征.【分析】根据正比例函数的性质进行判断正确选项即可.【解答】解:∵>0,∴对于函数y=x,y随x的增大而增大,∴当x1<x2时,y1<y2,故选D.7.我国古代数学家利用“牟合方盖”(如图甲)找到了球体体积的计算方法.“牟合方盖”是由两个圆柱分别从纵横两个方向嵌入一个正方体时两圆柱公共部分形成的几何体.图乙所示的几何体是可以形成“牟合方盖”的一种模型,它的主视图是()A.B.C.D.【考点】简单组合体的三视图.【分析】根据主视图的定义,得出圆柱以及立方体的摆放即可得出主视图为3个正方形组合体,进而得出答案即可.【解答】解:利用圆柱直径等于立方体边长,得出此时摆放,圆柱主视图是正方形,得出圆柱以及立方体的摆放的主视图为两列,左边一个正方形,右边两个正方形,故选:B.8.一个盒子内装有大小、形状相同的四个球,其中红球1个、绿球1个、白球2个,小明摸出一个球不放回,再摸出一个球,则两次都摸到白球的概率是()A.B.C.D.【考点】列表法与树状图法.【分析】首先根据题意画出树状图,然后由树状图求得所有等可能的结果与两次都摸到白球的情况,再利用概率公式即可求得答案.【解答】解:画树状图得:∵共有12种等可能的结果,两次都摸到白球的有2种情况,∴两次都摸到白球的概率是:=.故答案为:C.9.小美将某服饰店的促销活动内容告诉小明后,小明假设某一商品的定价为x元,并列出关系式为0.3(2x ﹣100)<1000,则下列何者可能是小美告诉小明的内容?()A.买两件等值的商品可减100元,再打3折,最后不到1000元B.买两件等值的商品可减100元,再打7折,最后不到1000元C.买两件等值的商品可打3折,再减100元,最后不到1000元D.买两件等值的商品可打7折,再减100元,最后不到1000元【考点】一元一次不等式的应用.【分析】根据0.3(2x﹣100)<1000,可以理解为买两件减100元,再打3折得出总价小于1000元.【解答】解:由关系式可知:0.3(2x﹣100)<1000,由2x﹣100,得出两件商品减100元,以及由0.3(2x﹣100)得出买两件打3折,故可以理解为:买两件等值的商品可减100元,再打3折,最后不到1000元.故选:A.10.如图,矩形ABCD中,AB=3,BC=4,动点P从A点出发,按A→B→C的方向在AB和BC上移动,记PA=x,点D到直线PA的距离为y,则y关于x的函数图象大致是()A. B. C. D.【考点】动点问题的函数图象.【分析】①点P在AB上时,点D到AP的距离为AD的长度,②点P在BC上时,根据同角的余角相等求出∠APB=∠PAD,再利用相似三角形的列出比例式整理得到y与x的关系式,从而得解.【解答】解:①点P在AB上时,0≤x≤3,点D到AP的距离为AD的长度,是定值4;②点P在BC上时,3<x≤5,∵∠APB+∠BAP=90°,∠PAD+∠BAP=90°,∴∠APB=∠PAD,又∵∠B=∠DEA=90°,∴△ABP∽△DEA,∴=,即=,∴y=,纵观各选项,只有B选项图形符合.故选:B.二、填空题(每小题4分,共24分)11.若两个相似三角形的相似比是1:2,则它们的面积比是1:4.【考点】相似三角形的性质.【分析】利用似三角形的面积的比等于相似比的平方求解.【解答】解:因为两个相似三角形的相似比是1:2,所以它们的面积比是1:4.故答案为1:4.12.已知直线l与⊙O相切,若圆心O到直线l的距离是5,则⊙O的半径是5.【考点】切线的性质.【分析】根据圆切线的性质即可求出⊙O的半径.【解答】解:若直线l与⊙O相切,则圆心O到直线l的距离等于⊙O的半径长,即⊙O的半径为5.13.一组数:2,1,3,x,7,﹣9,…,满足“从第三个数起,前两个数依次为a、b,紧随其后的数就是2a﹣b”,例如这组数中的第三个数“3”是由“2×2﹣1”得到的,那么这组数中x表示的数为﹣1.【考点】规律型:数字的变化类.【分析】根据给定该组数列满足的规律,代入数据即可得出结论.【解答】解:∵该组数列满足“从第三个数起,前两个数依次为a、b,紧随其后的数就是2a﹣b”,∴x=2×1﹣3=﹣1.故答案为:﹣1.14.如图,等腰直角三角形ABC的直角边长为1.如果将斜边BC绕着点B顺时针旋转45°后得BC′,则tan ∠BAC′=.【考点】旋转的性质;等腰直角三角形;锐角三角函数的定义.【分析】首先利用勾股定理可求出BC的长,由旋转的性质可知:BC=BC',∠CBC'=45°,结合等腰直角三角形的性质可推出∠ABC'=90°,进而可求出tan∠BAC′的值.【解答】解:∵等腰直角三角形ABC的直角边长为1,∴BC==,∠ABC=45°∵将斜边BC绕着点B顺时针旋转45°后得BC′,∴BC=BC'=,∠CBC'=45°,∴∠ABC′=45°+45°=90°,∴tan∠BAC′==,故答案为:.15.计算下列各式的值:;;;.观察所得结果,总结存在的规律,应用得到的规律可得=102016.【考点】二次根式的性质与化简.【分析】直接利用已知数据计算得出结果的变化规律进而得出答案.【解答】解:=10;=100=102;=1000=103;=10000=104,可得=102016.故答案为:102016.16.定义:直线l1与l2相交于点O,对于平面内任意一点M,点M到直线l1,l2的距离分别为p、q,则称有序实数对(p,q)是点M的“距离坐标”.根据上述定义,“距离坐标”是(1,2)的点的个数共有4个.【考点】点的坐标.【分析】根据“距离坐标”分别写出各点即可得解.【解答】解:“距离坐标”是(1,2)的点有(1,2),(﹣1,2),(﹣1,﹣2),(1,﹣2)共4个.故答案为:4.三、解答题(共46分)17.根据图中提供的信息,列方程或方程组求杯子和热水瓶的单价.【考点】二元一次方程组的应用.【分析】根据图知道,一个保温瓶和一个杯子的价钱是43元,2个保温瓶和3个杯子的价钱是94元;先用43×2求出2个保温瓶和2个杯子的价钱,再用2个保温瓶和3个杯子的价钱减去2个保温瓶和2个杯子的价钱就是一个杯子的价钱,进而求出一个保温瓶的价钱.【解答】解:设杯子的单价为x元,则热水瓶单价为y元,则解得,答:杯子的单价为8元,则热水瓶单价为35元.18.某市对教师试卷讲评课中学生参与的深度和广度进行评价,其评价项目为主动质疑、独立思考、专注听讲、讲解题目四项.评价组随机抽取了若干名初中生的参与情况,绘制了如下两幅不完整的统计图.请根据图中所给的信息解答下列问题:(1)这次评价中,一共抽查了560名学生;(2)请将条形统计图补充完整;(3)如果全市有16万初中学生,那么在试卷讲评课中,“独立思考”的学生约有多少万人?【考点】条形统计图;用样本估计总体;扇形统计图.【分析】(1)用专注听讲的人数224除以专注听讲所占的百分比即可得到所抽查的学生总人数;(2)用16万乘以“独立思考”的学生所占的百分比即可.【解答】解:(1)抽查的学生总人数==560(名);(2)讲解题目的人数=560﹣84﹣168﹣224=84(名),画条形统计图为:(3)∵16×=4.8(万),∴全市在试卷讲评课中,“独立思考”的学生约有4.8万人.故答案为560.19.一个足球被从地面向上踢出,它距地面高度y(m)可以用二次函数y=﹣4.9x2+19.6x刻画,其中x(s)表示足球被踢出后经过的时间.(1)解方程﹣4.9x2+19.6x=0,并说明其根的实际意义;(2)求经过多长时间,足球到达它的最高点?最高点的高度是多少?【考点】二次函数的应用.【分析】(1)因式分解法求解可得,由此时y=0即足球的高度为0可知方程的根表示的实际意义;(2)配方成二次函数的顶点式可知其最值情况.【解答】解:(1)﹣4.9x2+19.6x=0,x(﹣4.9x+19.6)=0,∴x1=0,x2=4,其中x1=0表示足球离开地面的时间,x2=4表示足球落地的时间;(2)∵y=﹣4.9x2+19.6x=﹣4.9(x﹣2)2+19.6,∴当x=2时,y取得最大值,最大值为19.6m,答:经过2s,足球到达它的最高点,最高点的高度是19.6m.20.在正方形ABCD外侧作直线AP,点B关于直线AP的对称点为E,连接BE,DE,其中DE交直线AP 于点F.(1)①依题意补全图1;②若∠PAB=20°,求∠ADF的度数;(2)若设∠PAB=a,且0°<a<90°,求∠ADF的度数(直接写出结果,结果可用含a的代数式表示)(3)如图2,若45°<∠PAB<90°,用等式表示线段AB、FE、FD之间的数量关系,并证明.【考点】四边形综合题.【分析】(1)①根据题意直接画出图形得出即可;②利用对称的性质以及等角对等边的性质,进而得出答案;(2)利用对称的性质以及等角对等边进而得出答案;(3)由轴对称的性质可得:,进而利用勾股定理得出答案.【解答】解:(1)①如图1所示:②如图2,连接AE,由对称得,∠PAB=∠PAE=20°,AE=AB=AD,∵四边形ABCD是正方形,∴∠BAD=90°,∴∠EAP=∠BAP=20°,∴∠EAD=130°,∴∠ADF==25°;(2)如图2,连接AE,由对称得∠PAB=∠PAE=α,AE=AB=AD,∵四边形ABCD是正方形,∴∠BAD=90°,∴∠EAP=∠BAP=α,∴∠EAD=90°+2α,∴∠ADF==45°﹣α.(3)如图3,连接AE、BF、BD,由对称可知,EF=BF,AE=AB=AD,∠ABF=∠AEF=∠ADF,∴∠BFD=∠BAD=90°,在Rt△BDF中,BF2+FD2=BD2,在Rt△ABC中,BD=AB,∴EF2+FD2=2AB2.2016年8月11日。

2022版义务教育语文课程标准模拟试题及答案(十)精选全文

2022版义务教育语文课程标准模拟试题及答案(十)精选全文

可编辑修改精选全文完整版
2.阅读与鉴赏;
3.表达与交流;
4.梳理与探究。

〔二〕过程性评价主要包含哪几个局部?
1.过程性评价原则;
2.课堂教学评价建议;
3.作业评价建议;
4.阶段性评价建议。

三、综述题
综述整本书阅读中反映革命文化的内容与代表作有哪些?
1.第二学段中,阅读表现英雄榜样事迹的图书,如(小英雄雨来)(雷锋的故事)等,讲述英雄榜样的动人故事。

2.第三学段中,阅读反映革命传统的作品,如(可爱的中国)(小兵张嘎)(闪闪的红星)等,讲述自己感受到的家国情怀和爱国精神。

3.第四学段中,阅读革命文学作品,如(革命烈士诗抄)(红岩)(红星照耀中国)等,体会、评析革命领袖、革命英雄的爱国精神和人格魅力。

填空题答案见(义务教育语文课程标准)2022版“文学阅读与创意表达〞局部。

单片机原理及应用技能比赛模拟试题及答案(十).教学内容

单片机原理及应用技能比赛模拟试题及答案(十).教学内容

单片机原理及应用技能比赛模拟试题(十一、填空题:1、单片机与普通计算机的不同之处在于其将( CPU (存储器和(I/O 口三部分集成于一块芯片上。

2、单片机存储器的主要功能是存储(程序和(数据。

3、在MCS-51单片机中,如果采用6MHz晶振,1个机器周期为(2us。

4、若A中的内容为63H,那么,P标志位的值为(0。

析:P为偶校验位,因为A中1的个数为偶数所以P=0。

5、使用8031芯片时,需将/EA引脚接(低电平,因为其片内无(程序存储器。

6、片内RAM 低128个单元划分为(工作寄存器区、(位寻址区、(数据缓冲区 3 个主要部分.7、通过堆栈操作实现子程序调用,首先就要把(PC 的内容入栈,以进行断点保护。

调用返回时,再进行出栈保护,把保护的断点送回到(PC 。

8、MCS-51单片机程序存储器的寻址范围是由程序计数器PC的位数所决定的因为MCS-51 的PC是16位的,因此其寻址的范围为(64 KB。

9、当MCS-51 单片机运行出错或程序陷入死循环时可以(复位来摆脱困境。

10、在基址加变址寻址方式中,以(累加器A作变址寄存器,以(DPTR或(PC 作基址寄存器。

11、指令格式是由(操作码和(操作数所组成,也可能仅由(操作码组成。

12、在MCS-51中,PC和DPTR都用于提供地址,但PC是为访问(程序存储器提供地址,而DPTR 是为访问(数据存储器提供地址。

13、在寄存器间接寻址方式中,其“间接”体现在指令中寄存器的内容不是操作数,而是操作数的(地址。

14、外部中断1 所对应的中断入口地址为( 0013HH。

15、8031 单片机响应中断后,产生长调用指令LCALL, 执行该指令的过程包括: 首先把(PC的内容压入堆栈,以进行断点保护,然后把长调用指令的16位地址送(PC ,使程序执行转向(程序存储器中的中断地址区。

二、单项选择题。

1. MCS—5l 单片机的最大程序寻址空间是( C(A16KB (B32 KB (C64 KB (D128 KB 2.在CPU内部,反映程序运行状态或反映运算结果的特征寄存器是( A 。

初中数学夏令营赛前模拟试题(10)

初中数学夏令营赛前模拟试题(10)

初中数学夏令营赛前模拟试题(十)第一试1. 设A 、B 在直线l 的同侧, 已知AB=13, 点A 、B 到直线l 的距离分别为10.5和5.5点C 是l 上使AC +BC 最小的点, 则AC +BC = ___________.2. 如图, EF 是正方形ABCD 的对折线, 将∠A沿DK 折叠, 使它的顶点A 落在EF 上的G 点, 则∠DKG=____________度.3. 设P 为□ABCD 内一点, ∠BAP =∠BCP, 且∠PBC = 40°, 则∠PDC = __________度.4. 一次函数y = kx +b, 当-3≤x ≤1时, 对应的y 的值为1≤y ≤9, 则kb 的值为________.5. 设f (x) = ax +a1(1-x) (a >0), 则当0≤x ≤1时, f (x)的最小值g (a)为______. 6. 已知三条直线: y =3x , y =21x +1, y = -x +4, 那么这三条直线所围成的封闭图形的面积等于__________.7. 如果函数y = |x +2|+|1-x|+|x|的值随x 的值的增大而增大, 那么x 取值的范围是____________.8. 某环形跑道上顺时针排列有4所中学: A 1、A 2、A 3、A 4, 它们顺次有彩电15台, 8台, 5台, 12台, 为使各校的彩电数相同, 允许一些中学向相邻中学调出彩电, 则满足要求的调配方案中调出彩电台数最少时的台数为___________台.9. 设动直线通过第一象限与x 轴的交点为 (x, 0),与y 轴的交点为 (0, y), 如果x +y = m (m 为大于零的常数), 以坐标原点为圆心的圆O 外切于直线AB,则⊙O 半径R 的最大值为__________.10. 已知一次函数f (x) = ax+b经过点(10, 13), 它在x轴上的截距是一个质数, 在y轴上的截距是一个正整数, 则函数的个数有_________个.第二试一、某家电生产企业根据市场调查报告, 决定调整产品生产方案, 准备每周(按120个工时计算) 生产空调器、彩电、冰箱共360台, 且冰箱至少生产60台, 已知生产这些家电产品每台所需工时和每台产值如下表:问每周应生产空调器、彩电、冰箱各多少台, 才能使产值最高? 最高产值是多少(以千克为单位)?二、已知△ABC中, BC = a, AB = c, ∠B = 30°, P是△ABC内一点, 求PA+PB +PC的最小值.三、已知直线L1: y = 4x和点P(6, 4), 在直线L1上求一点Q, 使过P, Q的直线与直线L1以及x轴在第一象限内所围成的三角形面积最小.。

初一年级12月数学模拟试题10

初一年级12月数学模拟试题10

2014~2015学年度第一学期顾庄学校12月考试初一年级数学模拟试题(十)一、细心填一填。

(每题2分,计20分)1. -3的相反数是 .2、若(x -1)2+||y +2=0,则(x +y )2010=______. 3、36°18′=___________°.4、在数轴上点P 到原点的距离为5,点P 表示的数是_______________. 5.比较大小:32-- ______ 43- (填“<”、“=”或“>”)6. 观察下列单项式:2x , 5x 2, 10x 3, 17x 4, 26x 5, ……,按此规律,第10个单项式是 .7.如图是一个数值转换机,若输入的a 值为3-,则输出的结果应为 .8. 如图,A 、B 、C 、D 四名同学的家在同一条直线上,已知C 同学家处在A 与B 两家的中点处,而D同学的家又处于A 与C 两家的中点处,又知C 与B 两家相距3千米,则A 与D 两同学家相距 9.如图所示,要使图中平面展开图按虚线折叠成正方体后,相对面上 两个数之积为12,则x y += .10.已知x ,y 为有理数,现规定一种新的运算*,满足x*y=xy+1,则 (1*4)*(-2)= .二、精心选一选。

(每题2分,计20分)11.已知代数式x +2y+1的值是3,则代数式132x y --的值是 A .1 B .2 C .3 D .412、如果知道a 与b 互为相反数,且x 与y 互为倒数,那么代数式|a + b| - 2xy 的值为 A. 0 B.-2 C.-1 D.无法确定13.如图,从A 到B 有多条道路,人们会走中间的直路,而不会走其他的曲折的路,这是因为 A .两点之间线段最短 B .两条直线相交只有一个交点 C .两点确定一条直线 D .其他的路行不通14.几个同学在日历竖列上圈出了三个数,算出它们的和,其中错误的是 A. 28 B. 33 C. 45 D. 57 15.物理教科书中给出了几种物质的密度,符合科学记数法的是 A .水银13.6×103kg/m 3B .铁7.8×103kg/m 3C .金19.3×103kg/m 3D .煤油0.8×103kg/m(第9题)yx432 (第8题)输入(第7题)(第13题)A B222363()3x x x x +-+16. 下列关于单项式-352xy 的说法中,正确的是A .系数是-52,次数是4 B .系数是-52,次数是3C .系数是-5,次数是4D .系数是-5,次数是317.下列方程中,解为x=-2的方程是A .2x +5=1-xB .3-2(x -1)=7-xC .x -5=5-xD .1-14x =34x 18. 某超市出售的三种品牌月饼袋上,分别标有质量为(500±5)g ,(500±10)g , (500±20)g 的字样,从中任意拿出两袋,它们的质量最多..相差 A .10g B .20g C .30g D .40g 19. 下列变形中, 不正确的是A.a +(b +c -d)=a +b +c -dB.a -(b -c +d)=a -b +c -dC.a -b -(c -d)=a -b -c -dD.a +b -(-c -d)=a +b +c +d20.将如图(*)所示的图形绕虚线旋转一周,所成的几何体是三.计算小能手。

信息政策与法规模拟题十

信息政策与法规模拟题十

02133《信息政策与法规》全真模拟试题(十)一、单项选择题(本大题共15小题,每小题1分,共15分)1.下列主体中,不能申请集体商标的是( C )A.团体B.协会C.自然人D.企业2.信息法中的“信息”指的是( D )A.一切信息B.一切社会信息C.一切自然信息D.有特定意义和范围的信息3.信息法律关系亦由三个要素构成,三个要素密切相关,缺一不可,分别是主体、客体还有( B )A.关系B.内容C.联系D.权利4.布图设计自创作完成之日起多少年后,不再受保护?( B )A.10年B.15年C.20年D.25年5.世界上最早提出对软件给予专利保护的国家是( C )A.德国B.英国C.美国D.中国6.食品广告不包括( C )A.饮料广告B.按照传统既是食品又是药品的物品的广告C.以治疗为目的的物品广告D.食品原料广告7.我国《商标法》第8条规定,能够作为商标的是任何能够将自然人、法人或者其他组织的商品与他人的商品区别开的可视性标志,下列不可以作为商标的是( C )A.文字B.图形C.声音D.字母8.商业方法专利中,申请量和授权量第一的是( B )A.金融类B.网络交易类C.市场营销类D.管理类9.甲厂以招标方法向社会公开征集企业形象标识设计。

最后,甲厂职工乙的设计稿被选用作为企业形象标识。

乙设计的标识属于( A )A.受工厂委托而创作的作品B.为完成工厂的工作任务而创作的职务作品C.由工厂主持并代表工厂意志创作的法人作品D.不受著作权保护的作品在其装置中使用有关专利产品10.音乐家甲不幸英年早逝,留下创作完成而未公开的乐曲《江山万里红》,甲的继承人可以继承该作品的权利是( D )A.修改权B.发表权C.署名权D.获得报酬权11.统计机构和统计人员享有的统计信息权不包括( B )A.统计调查权B.统计公布权C.统计报告权D.统计监督权12.根据我国的著作权取得制度,下列选项的内容符合我国公民著作权产生的情况的是( B )A.随作品的发表而自动产生B.随作品的创作完成而自动产生C.在作品上加注版权标记后自动产生D.在作品以一定的物质形态固定后产生13.“秘密级”国家秘密的保密期限一般不超过( A )A.10年B.20年C.30年D.40年14.不属于我国信息技术标准等级的是( B )A.国家标准B.内部标准C.企业标准D.地方标准15.信息系统安全保护等级分为( C )A.二级B.三级C.四级D.五级二、填空题(本大题共5小题,每小题2分,共10分)16.我国现阶段信息立法应遵循(效益)原则、(实事求是)原则、吸收借鉴原则和协调原则。

大学有机化学期末模拟题(附答案)

大学有机化学期末模拟题(附答案)

模拟试题(十)一、 答下列问题:1. 试比较下面三种化合物与CH 3ONa 发生S N 反应的相对活性。

A.NO 2CH 2ClB.NO 2CH 3BrC.NO 2CH 3F2. 比较下面三种化合物发生碱性水解反应的相对活性。

A.B.C.CH 3CH =CHCH 2BrCH 3CH 2CH 2BrCH 3CCH 2Br =O3. 下面三种化合物一硝化时,所得间位产物的多少次序如何?A.B.C.C 6H 5CH 3C 6H 5CHCl 2C 6H 5CCl 34. 下面三种化合物分子的偶极矩大小的次序如何?A.B.CH 3C.CH 3235. 下面三种化合物与一分子HBr 加成的反应活泼性大小次序如何?A. B. C.PhCH =CH 2p - O 2NC 6H 4CH =CH 2p - CH 3C 6H 4CH=CH 26. 甲基环戊烷的一氯代产物中哪个有对映异构体?7. 下面三种化合物发生消除HBr 的反应活化能大小次序如何?A.3B.C.Br8. 下列各化合物发生亲核取代反应是按S N 1机理还是S N 2机理进行的?A.C 6H 5CH 2BrB.(C 6H 5)2CHBrC.C 6H 5COCH 2BrD.二、 写出下面反应的反应机理:CH =CH 2+=CH CH 33H+33333三、 用化学方法鉴别下列化合物:A. B.ClC. D. E. F.四、合成下列化合物:1.由苯合成Ph2C=CH2(其它试剂任选)。

2.由甲苯合成2-硝基-6-溴苯甲酸。

五、完成下列反应:1.25。

O2[ A ]PhCH3AlCl3H3O+[ B ][ C ]2.HCHO , HCl2[ D ][ E ]H2O2+ +[ F ]3.PhC+CH3CH2MgBr[ G ]PhCH2Cl[ H ]Na , NH3[ I ]HBr[ J ][ K ](1) CO23+[ M ]六、化合物A、B、C、D的分子式都是C10H14,它们都有芳香性。

2020年电工特种作业人员上岗操作证考试全真模拟试题及答案(十)

2020年电工特种作业人员上岗操作证考试全真模拟试题及答案(十)

2020年电工特种作业人员上岗操作证考试全真模拟试题及答案(十)判断题1、带负荷误合刀闸,发现后立即将刀闸拉开。

标准答案:错2、TT系统是电源系统有一点直接接地,设备外露导电部分的接地用保护接地线(PE线)接到独立的接地体上。

标准答案:对3、电焊机外壳应当接零(或接地)。

标准答案:对4、当验明设备确无电压后,应立即将检修设备三相短路。

标准答案:错5、电伤是电流对人体内部组织的伤害,是最危险的一种伤害。

标准答案:错6、已执行的操作票注明“ 已执行”。

作废的操作应注明“ 作废”字样。

这两种操作票至少要保存三个月。

标准答案:对7、一般对低压设备和线路,绝缘电阻应不低于0.5MΩ,照明线路应不低于0.22MΩ。

标准答案:对8、在RLC 串联电路中,总电压的有效值总会大于各元件的电压有效值。

标准答案:错9、栅栏用于室外配电装置时,其高度不应低于1.5米,栅条间距和到地面的距离不应小于0.2米。

标准答案:对10、高压熔断器具有定时限特性。

标准答案:错11、电动机的绝缘等级,表示电动机绕组的绝缘材料和导线所能耐受温度极限的等级。

如 E 级绝缘其允许最高温度为120 摄氏度。

标准答案:对12、变配电所操作中,接挂或拆卸地线、验电及装拆电压互感器回路的熔断器等项目可不填写操作票。

标准答案:错13、导线的选择要满足机械强度、导线的安全载流量和允许电压损失三方面的要求。

标准答案:对14、电源从厂内总降压变配电所引入的厂内二次变配电所,变压器容量在500kVA 以下的,可以不设专人值班,只安排巡视检查。

标准答案:对15、填写操作票,要包括操作任务操作顺序、发令人、操作人、监护人及操作时间等。

16、严禁工作人员在工作中移动或拆除围栏、接地线和标示牌。

标准答案:对17、使用RL螺旋式熔断器时,其底座的中心触点接负荷,螺旋部分接电源。

标准答案:错18、检修刀开关时只要将刀开关拉开,就能确保安全。

标准答案:错19、阀型避雷器的阀型电阻盘是非线性电阻。

《教育原理》模拟试题及参考答案10

《教育原理》模拟试题及参考答案10

《教育原理》模拟试题(十)一、填空题(本大题共10个小题,共20分)1.教育学是研究_____教育现象及其规律____的一门科学。

2.教育现象包括_____教育社会现象____和____认识现象_____。

3.教育的方针政策是____人们主观意志_____的体现。

4.教师的根本任务是____教书育人_____。

具体任务包括____搞好教学_____、____做好思想品德教育工作_____、____关心学生的身体和生活_____。

5.教师的劳动特点是_____复杂性、创造性____、____连续性、广延性_____、___长期性、间接性______、______主体性、示范性___。

6.教师是教育工作的组织者_____领导者____,在教育过程中起___主导作用______作用。

7.课的类型分为_____单一课____和____综合课_____。

8.课的结构是指一节课的组成部分以及各部分进行先后顺序和时间分配,它包括_____组织教学____、____检查复习_____、___讲授新教材______、___巩固新教材______、____布置课外作业_____几部分。

9.教学的辅助形式有____个别教学_____、___分组教学______、___现场教学______。

10.教师的素养包括____思想品德修养_____、____知识结构_____、____能力结构_____。

二、名词解释(每小题4分,共20分)1.终身教育1.终身教育:是人们在一生中所受到的各种培养的总和。

对于社会来说,终身教育的理想在于建立一个学习化的社会;对于个人来说,终身教育是要造就能够在现代社会中应付各种变化并发挥个人独特才能的成功者。

2.教育方针2.教育方针是指一个国家在一定时期内的确定的教育发展的总方向、总目标、总的指导思想和指导原则。

3.特许学校3.特许学校:特许学校就是具有共同教育主张的一群人(比如对当地公立学校不满的一群教师或几个家长)共同拟定一份章程(charter),根据州及地方法令获得批准后,便可按照该章程建立一所他们自己的学校,自己招收学生,自己管理学校。

行政执法资格考试全真模拟试10

行政执法资格考试全真模拟试10

行政执法资格考试全真模拟试题(十)一、单项选择题(共20题)1、县级以上人民政府工作部门制定的规范性文件,是(A.政府规范性文件)。

2、县级以上人民政府及其办公厅(室)的规范性文件,由(D.本级人民政府法制机构)在完成合法性审查后登记、编制登记号。

3、某工商局在办理完毕某企业变更法定代表人登记一年之后,发现办理登记的工作人员由于工作疏忽未认真核实有关材料,导致作出了错误的变更登记。

在这种情况下,工商局应当(A.撤销变更登记,恢复到原来的登记状态)。

4、某县技术监督局委托该县农业技术推广站对贩卖假种子的单位和个人行使处罚权,技术推广站应当以(县技术监督局)的名义行使处罚权。

5、冻结存款、汇款应当由(法律)规定的行政机关实施,不得委托给其他行政机关或组织。

6、依照法律规定冻结存款、汇款的,作出决定的行政机关应当在(三日)内向当事人交付冻结决定书。

7、关于行政机关实施行政强制措施应当遵守的程序规定,以下哪种说法是正确的。

(对于一情况紧急的,行政机关可以当场实施行政强制措施,并且在二十四小时之内向行政机关负责人报告,并补办批准手续)8、冻结存款、汇款的行政强制措施可以由(法律规定的行政机关)实施。

9、某市卫生行政部门因某饭馆的卫生质量存在问题,遂以违反《公共场所卫生条例》为由,对其作出吊销卫生许可证的决定。

这一行为属于(行政处罚)。

10、下列行政处罚措施中,只能由法律设定的是(行政拘留)。

11、违法行为在法定时效内未被发现的,不再给予行政处罚。

法律另有规定的除外。

前款规定的期限,从违法行为(发生之日)起计算;违法行为有连续或者继续状态的,从行为终了之日起计算。

12、行政机关对当事人进行处罚时不使用罚款、没收财物单据或者使用非法定部门制发的罚款、没收财物单据的,当事人(有权拒绝处罚)13、公安机关对在公共场所酗酒滋事的人进行人身拘束,该行政行为性质是(行政强制)。

14、某乙为一待业青年,某日与朋友在饭店喝酒,因心情不顺喝得大醉,结账的时候,对结账服务员丙污言秽语,丙忍无可忍,驳斥了几句,乙便动手打了丙几个耳光,在众人的强行阻止下,事态才未进一步发展。

学前心理学 模拟试题及参考答案(十)

学前心理学 模拟试题及参考答案(十)
2、①无意记忆,②形象记忆
3、①前概念阶段(2---4岁),②直觉思维阶段(4----7岁)
4、①成熟,②物理环境,③社会环境,④平衡
5、①前言语阶段,②基本掌握口语
6、①怒,②爱。
7、①安全性依恋,②焦虑抗拒型依恋。
8、①外表,②社交技能
9、①霍尔
10、①倒“u“字形
8、影响学前儿童同伴关系发展的因素有①、能力、②、 性格等。
9、一两的遗传胜过一顿的教育,是①的著名论断。
10、愉快强度与操作效果之间呈现①关系。
11、幼儿期言语发展的主要任务是发展①。
三、单项选择题(每题1分,共12分)
1、双生子爬梯研究说明了( )在发展中的重要性。
7、顺应:指主体内部图式改变以适应现实。如婴儿从吃奶改为吃饭,幼儿从幼儿园到上小学等都需要内部图式的改变。
8、定向性注意:指外来的强烈的刺激会引起新生儿暂时停止哭喊或把视线转向刺激物,这就视最初的定向性注意。它主要是由外界事物的特点引起的。
二、填空(每空0.5分,共10分)
1、①具体形象性
(3)出现明显的个体差异。(1分)
影响因素:
(1)社会生活环境;亲社会行为受社会文化的影响:比如当今社会强调社会和谐,无论是成人还是儿童表现出的亲社会行为就多;亲社会行为受电视媒介的影响:电视是儿童学习亲社会行为的重要途径,当然,如不加以干预,儿童也易从电视媒介上学习攻击性行为。(2分)
(2)儿童日常的生活环境:家庭的影响;同伴的相互作用;移情:无论是社会生活环境的影响,还是儿童具体生活环境的影响,最终都要通过儿童的移情而起作用。移情是导致亲社会行为的根本的、内在的因素。(2分)注:对各要点适当的拓展或举例各加2分

专升本英语模拟试题模拟试题 10

专升本英语模拟试题模拟试题 10

模拟试题(十)Part I Vocabulary and Structure ( 30% )Directions: Each of the following sentences is incomplete and followed by four choices markedA), B), C) and D), choose the ONE that best completes the sentence .1. All is a continuous supply of oil.A. that is neededB. the thing neededC. what is neededD. for their needs2. The master was very angry and had all the slaves before him.A. to be broughtB. broughtC. bringingD. being brought3. Mary was not in that car so she in the accident.A. can not have injuredB. should be in. lured.C. may have been injuredD. cannot have been injured4. He suggested to tomorrow's exhibition together.A. us to goB. we shall goC. we wentD. we go5. I have two boys but of them likes sweets.A. bothB. eitherC. neitherD. none6. John regretted to the meeting last week.A. not goingB. not to goC. not have been goingD. not to be going7. I hope my teacher will take my recent illness into when judging my examination.A. viewB. countingC. accountD. point8. No sooner had we reached the top of the hill we all sat down to rest.A. whenB. thenC. thanD. until9. If this building project by the end of next season is delayed, the construction company should be fined.A. to be completedB. being completedC. has been completedD. will be completed10. Y ou'd better the examination paper once more before you hand it in.A. go forB. go overC. go roundD. go about11. The novel was said into several languages.A. to translateB. to be translatedC. to have translatedD. to have been translated12. I don't enjoy the situation, but I can it.A. live outB. live withC. live onD. live off13. Mary is not good at sports, but when it to English, she is the best student in her class.A. refersB. goesC. comesD. concerns14. On this you had to do what you were asked to do.A. caseB. circumstanceC. situationD. occasion15. Silver is the best conductor of electricity, copper it closely.A. followedB. followingC. to followD. is following16. Age is not important. It's brain and knowledge that really .A. judgeB. countC. impressD. survive17. It's well known that traffic regulations everyone.A. apply forB. fit forC. suit toD. apply to18. Last year, Mike earned his brother, who has a better position.A. twice as many asB. twice timesC. twice as much asD. twice as time as19. It's high time we something to stop air pollution.A. doB. didC. would doD. are doing20. It was not until 1972 I began learning English?A. thatB. whenC. beforeD. then21. what you say is not to blame this time.A. In view ofB. In sight ofC. With a view toD. In seeing.22. If it tomorrow, we will not go out.A. will rainB. is to rainC. rainsD. is going to rain23. I know her, so I can't tell you anything about her.A. occasionallyB. actuallyC. regularlyD. scarcely24. Some of the questions have four choices that sound .A. alikeB. unlikeC. likelyD. like25. Hurry up, you'll miss the train.A. andB. butC. soD. or26. If you make another effort you will certainly how to solve the problem.A. memorizeB. acquireC. figure outD. break out27. from his appearance, he must be from the south .A. JudgingB. JudgeC. JudgedD. To judge28. I never heard such stories he tells.A. whichB. asC. thatD. whom29. Is this the man to you talked last week?A. whichB. whomC. thatD. who30. Mary must have felt a bit yesterday because she was not invited to the party.A. injuredB. woundedC. harmedD. hurtPart II Cloze ( 20 % )Directions: There are 20 blanks in the following passage. For each blank there are four choices marked A), B), C) and D). Y ou should choose the one that best fits into the passage.Cheques have largely replaced money as a means of exchange, for they are widely accepted everywhere. Though this is very 31 for both buyer and seller, it should not be forgotten that cheques are not real money: they are quite 32 in themselves. A shopkeeper always runs a certain 33 when he accepts a cheque and he is quite 34 his rights if, 35 , he refuses to do so.People do not always know this and are shocked if their good faith is called 36 . An old and very wealthy friend of mine told me he had an extremely unpleasant 37 . He went to a famous jewel shop which keeps a large 38 of precious stones and asked to be shown some pearl necklaces. After examining several trays, he 3 9 to buy a particularly fine string of pearls and asked if he could pay 40 cheque. The assistant said that this was quite 41 , but the moment my friend signed his name, he was invited into the manager's office.The manager was very polite, but he explained that someone with 42 the same name had presented them with a 43 cheque not long ago. He told my friend that the police would arrive 44 any moment and he had better stay 45 he wanted to get into serious trouble.46 , the police arrived soon afterwards. They apologized to my friend for the 47 and asked him to 48 a note which had been used by the thief in a number of shops. The note 49 : "I have a gun in my pocket. Ask no questions and give me all the money in the safe." 50 my friend's handwriting was quite unlike the thief's.31. A. complicated B. trivial C. bearable D. convenient32. A. valueless B. invaluable C. valuable D. indefinite33. A. danger B. change C. risk D. opportunity34. A. within B. beyond C. without D. out of35. A. in general B. at the least C. on occasion D. in short36. A. in difficulty B. in doubt C. in earnest D. in question37. A. accident B. experience C. event D. incident38. A. mount B. stock C. number D. store39. A. considered B. thought C. conceived D. decided40. A. by B. in C. with D. through41. A. in order B. in need C. in use D. in common42. A. largely B. mostly C. exactly D. extremely43. A. worth B. worthy C. worthwhile D. worthless44. A. for B. at C. until D. during45. A. whether B. if C. otherwise D. unless46. A. Really B. Sure enough C. Certainly D. However47. A. treatment B. manner C. inconvenience D. behavior48. A. write off B. write out C. copy out D. make out49. A. read B. told C. wrote D. informed50. A. Especially B. Fortunately C. Naturally D. BasicallyPart III Reading Comprehension ( 30 % )Directions: There are three passages in this part. Each passage is followed by some questions or unfinished statements. For each of them there are four choices marked A), B), C) and D). Y ou should decide on the best choice.Passage One:The basic flag of the United is one of the world's oldest national States flags.Only the basic flags of Austria, Denmark, Great Britain, the Netherlands, Sweden, and Switzerland are older.During the discovery and settlement of what is now the United States, the flags of various European nations were flown over the land, as symbols of possession. Later, in the Colonial and Revolutionary War periods, flags representing famous persons, places, and events were flown in the American Colonies.The first official flag of the United States was created by Congress on June 14, 1777. It consisted of 13 alternate red and white stripes and 13 white stars in a field of blue, representing the 13 colonies that had declared their independence in 1776. Congress adopted a new flag of 15 stars and 15 stripes in 1795, to give representation to the two new states admitted into the Union, V ermont and Kentucky.By 1817, there were 20 states in the Union, and it became apparent that adding one stripe for each new state would destroy the shape of the flag. As a result, Congress in 1818 restored the original- design of 13 stripes and provided that each state was to be represented by one star. In 1912 President William H. Taft made the first official provision for the arrangement of the stars. He ordered that there be six even rows of eight stars each. Previously the arrangement of the stars had been left to the flag-maker's fancy.The evolution of the Stars and Stripes reflects the growth of the United States. After the admission of Hawaii into the Union in 1959, the flag was officially changed for the 26th timesince its creation.There are many government flags flown in the United States in addition to the national flag. Among them are the president's and vice-president's flags and those of the federal departments and some federal agencies. Each state in the Union has an official flag. The United States Navy uses special flags for signaling.51. The basic flag of the United States is .A. the oldest national flag in the worldB. one of the world's oldest flagsC. the most beautiful flag in the WestD. as old as the basic flags of some European nations52. Before the War of Independence the flags of various European nations flown over the landwere symbols of .A. self-ruleB. occupationC. peace and friendshipD. independence53. The first official flag of the United States was adopted .A. before the independence WarB. right after the Independence WarC. when independence was declared in 1776D. during the War of Independence. which ended in 178354. The 1.3 red and white stripes and 13 white stars represent .A. 13 independent statesB. the colonies that declared independence in 1776C. the U.S. CongressD. 13 famous figures in the American colonies55. Why was the original design of 13 stripes restored in 1818 ?A. Too many stripes would destroy the shape of the flag.B. Congress resisted 13 is the best number.C. That was a decision President Taft had made.D. The American people suggested it.Passage T wo:Boxing matches were very popular in England two hundred years ago. In those days, boxers fought with bare fists for prize money. Because of this, they were known as "prize-fighters". However, boxing was very crude, for there were no rules and a prize-fighter could be seriously injured or even killed during a match.One of the most colorful figures in boxing history was Daniel Mendoza, who was born in 1764. The use of gloves was not introduced until 1860 when the Marquis Queensberry drew up the first set of rules. Though he was technically a prize-fighter, Mendoza did much to change crude prize-fighting into a sport, for he brought science to the game. In his day, Mendoza enjoyed tremendous popularity. He was adored by rich and poor alike.Mendoza rose to fame swiftly after a boxing-match when he was only fourteen the years old. This attracted the attention of Richard. Humphries,who was then most eminent boxer in England. He offered to tram Mendoza and his young pupil was quick to learn. In fact, Mendoza soon became so successful that Humphries turned against him. The two men quarreled bitterly and was clear that the argument could only be settled by a fight. A match was held at Stilton where bothmen fought for an hour. The public bet a great deal of money on Mendoza, but he was defeated. Mendoza met Humphries in the ring on a later occasion and he lost for a second time. It was not until his third match in 1790 that he finally beat Humphries and became Champion of England. Meanwhile he founded a highly successful Academy and even Lord Byron became one of his pupils. He earned enormous sums of money and was paid as much as 100 for a single appearance. Despite this, he was so extravagant that he was always in debt. After he was defeated by a boxer called Gentleman Jackson, he was quickly forgotten. He was sent to prison for failing to pay his debts and died in poverty in 1836.56. Boxing in the 18th century was crude because .A. boxers fought with bare fistsB. there were no regulations.C. boxers could be seriously injured or even killed during a matchD. all of the above57 What do you think led to the change of crude prize-fighting into a sport?A. Prize money.B. The introduction of science to the game.C. The use of glovesD. The first set of rules of boxing.58. Why did Mendoza enjoy tremendous popularity in his day?A. He had defeated his own coach.B. He was the first to introduce the use of gloves.C. He did much to change prize-fighting into a sport.D. He had drawn up the first set of rules of boxing.59. Mendoza when he was only a teenager.A. was seriously injuredB. enjoyed more popt0arity than HurnphriesC. made a great deal of moneyD. gained fame quickly60. Richard Humphries was in England at that time.A. an experienced boxing coachB. adored by old and young alikeC. admired by rich and poor alikeD. not much of a boxerPassage Three:In the earliest stages of man's development he had no more need of money than animals have. He was content with very simple forms of shelter, made his own rough tools and weapons and could provide food and clothing for himself and his family from natural materials around him. As he became more civilized, however, he began to want better shelter, more efficient tools and weapons, and more comfortable and more lasting clothing than could be provided by his own neighborhood or by the work of his own unskilled hands. For these things he had to turn to the skilled people such as smiths, leather workers or carpenters who were springing up everywhere. It was then that the question of payment arose.At first he got what he wanted by a simple process of exchange. The smith who had not the time to look after land or cattle was glad to take meat or grain from the farmer in exchange for anaxe or a plough. But as more and more goods which had no fixed exchange value came on the market, exchange became too complicated to be satisfactory. Another problem arose when those who made things wanted to get stocks of wood or leather, or iron, but had nothing to offer in exchange until their finished goods were ready.Thus the difficulties of exchange led by degrees to the invention of money.In some countries, easily handled things like seeds or shells were given a certain value and the farmer, instead of paying the smith for a new axe by giving him some meat or grain, gave him so many shells. If the smith had any shells left when he had bought his food, he could get stocks of the raw materials of his trade. In some countries quite large things such as cows or camels or even big flat stones were used for trade. Later, pieces of metal, bearing values according to the rarity of the metal and the size of the pieces, or coins were used. Money as we know it had arrived.61. Why were early men content with their simple life?A. They did not have to use money.B. They were able to make their own tools.C. They could provide food and clothing and. simple shelter for themselves.D. They had enough natural materials around them.62. As men became more civilized they .A. all learnt to make by themselves the things they neededB. had to travel a lot to look for what they wantedC. wanted better things than those they themselves could provideD. no longer provided food and clothing for themselves63. Exchange of goods became difficult because .A. there was not a marketplace for farmers and smiths to exchange their goodsB. farmers were unwilling to provide smiths with grain and meatC. more and more goods which had no fixed exchange value came to the marketD. skilled workers did not work hard enough to produce good tools and weapons64. Before people used metal coins they used .A. shells or seeds because they could be easily handledB. camels even though they were largeC. flat stones even though they were largeD. all of the above65. Money was not used until .A. paper was inventedB. people practiced a simple' process of exchangeC. nothing could be offered in exchangeD. the exchange of one thing for another became too complicatedPart IV Mistake spotting ( 10% )Directions: Each of the following sentences has four underlined parts and marked A,B,C and D. Identify the one that needs correction.66. That old lady can't stop me listening the tennis match on my radio.A B C D67. His parents died when he was young, so he was brought out by his aunt.A B C D68. We have told him several times but he yet doesn't understand.A B C D69. Y ou said the books were on the desk but there was none.A B C D70. Seeing from the top of the hill, the park is very beautiful.A B C D71. It is not known for certain whether he comes to the party tonight.A B C D72. Tom and I are looking forward to be seeing you, so don't disappoint us!A B C D73. I really appreciate you to offer to help me, but I am sure that I will be able to manage byA B C D myself .74. The professor considers it no good to read without understanding.A B C D75. The culture and customs of America are more like that of England than of any other country.A B C DPart V Translation ( 10% )Section ADirections: Translate the following sentences into English.76.这位教师可能不是一个了不起的学者, 但他的确怎样把一门课教得活泼而有趣。

2019小学语文毕业模拟试卷(十)

2019小学语文毕业模拟试卷(十)

密学校 班级 姓名 学号密 封 线 内 不 得 答 题人教版小学语文毕业考试模拟试题(十)(总分120分,时间120分)(91分)一、基础知识(33分)1.看拼音写词语(12分)y ōu y ǎ f ěi t ú d ǎ ji ǎo m éi gui ku í w ú bào yuàn ( ) ( ) ( ) ( ) ( )( )nuó yí fù yōnɡ dūn hòu chōnɡ jǐnɡ jiàn wēi zhī zhù( ) ( ) ( ) ( ) ( ) 2.写同音字(3分)ji ǎo ( )子 ( )刑 ( )猾 l ì 经( ) 鼓( ) 严( ) 3.比一比,组词语 (4分)析( ) 躁( ) 竣( ) 协 ( ) 折( ) 燥( ) 峻( ) 胁( ) 4.把下面的词语补充完整(4分)可见一( ) ( )然大悟 ( )不经心 精兵( )政座无( )席 舍本( )末 发( )图强 革故( )新5.同一个字读音全相同的是( )组,全不同的是( )组。

(2分) A 、 含糊 糊弄 糊涂 B 、 勉强 顽强 强词夺理 C 、 摩托 摩平 按摩 D 、 吆喝 喝住 齐声喝彩 6.下列说法错误的一项是( )。

(1分)A “卓有成效”的“卓”起笔是部首,音序是Z ,声母是zh 。

B “心领神会、无独有偶 、铺天盖地 ”构词方式各不相同。

C “不闻不问” 中的“不”读音不同,“一心一意”中的“一”读音也不同。

D “插秧、鞭炮、吭声 、语无伦次”中带点字都是形声字。

7.找错别字,错误最多的一组是( )。

(1分)A 专心志致 勃勃生机 座无虚席B 不知所错 月以继日 司空见贯C 见微知著 锲而不舍 落慌而逃D 满不在呼 肃然起敬 零七八粹 8.用“心”组词后填空(2分)姑娘看着经过 挑选的鹅卵石那么五彩缤纷,她 地笑了。

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3、 (5 分)证明设 A 是集合,R A×A,则 R 是对称的 R=R 。
-1
4、 (5 分)证明:若群<G,*>的子群<H,*>满足|G|=2|H|,则<H,*>一定是群 <G,*>的正规子群。
5、 (5 分)证明:在同构意义下,4 阶格只有 2 个。
6、 (5 分)若 G 有 n 个结点,m 条边,f 个面,且每个面至少由 k(k 3)条边围成,则 m k(n-2)/(k-2)。
10、设 G 为连通的无向图,若 G 仅有 2 个结点的度数是奇数,则 G 一定具有( (A)欧拉路径; (B)欧拉回路; (C)哈密尔顿路径; (D)哈密尔顿回路。 二、填充题(每小题 4 分,共 40 分)

1、设 P:努力学习,Q:取得好成绩,则命题“只有努力学习,才能取得好成绩”可符
号化为 。 2、若一个平面图 G 是面 4 可着色的,则其对偶图 G*一定满足
模拟试题(十)
一、选择题(每小题 3 分,共 30 分) 1、下列集合关于数的加法和乘法运算不能构成环的是( (A)自然数集合; (B)整数集合; (C)有理数集合; ) (D)实数集合。 )
2、设 I 为整数集合,则下列集合关于数的加法运算不能构成独异点的是( (A) I ; (B) {2k | k I } ; (C) {2k 1| k I } ;
7、 设 R 为实数集合,S {x | x R 0 x 1} , 则在代数 S , max > 中,S 关于 max 运 算的么元是 。 。 ,当且仅当
8、有限集合 A 上的等价关系中,等价类最多的关系是 9 、 在 格 L, , 中 , a, b L , a b 当 且 仅 当 a b
(D) {3m 5n | m, n I } 。
3、 设 N6 {0,1, (A)2;
则下列元素是 N6 , 6 的生成元的是 ( ,5} , 6 为模 6 加法, (B)3; (C)4; (D)5。 ) (D)域。

4、设 F ,, 是整环,则 F ,, 不一定是( (A)可交换环; 5、格不一定具有( (A)交换律; (B)无零因子环; ) (B)结合律; (C)分配律; (C)含么环;
(D)吸收律。
6、设 S {1, 2, 4,8} , 和 分别表示求最小公倍数和最大公约数运算,则 S , , 是 ( ) (B)分配格; (C)有补分配格; (D)布尔代数。
(A)有补格;
7、一个含 4 个结点的无向图中有 3 个结点的度数分别为 1, 2,3 ,则第 4 个结点的度数不 可能是( (A)0; ) (B)1; (C)2; (D)4。 )
a b
。 ,至多为 。
10、 一个具有 n 个结点的简单连通无向图的边数至少为 三、计算证明题(共 30 分)
1、 (5 分)求(P (Q R)) ( P ( Q R))的主析取范式与主合取范式
2、 (5 分)证明:A→(C B),B→ A,D→ C => A→ D

3、设R 是A 中的一个关系,I A ⊆R,若有< a,b >∈R∧ < a,c >∈R ⇒< b,c >∈R , 则R是 。 -1 4、在一个群〈G,*〉中,若 G 中的元素 a 的阶是 k,则 a 的阶是 。 5、权序列为(30,25,20,15,10)的最优二叉树的带权路径总长为_ 6、有 n 个结点的树,其结点度数之和是 。 。
8、 设连通的简单平面图 G 中有 10 条边和 5 个面,则 G 的结点数为( (A)6; (B)7; (C)8; (D)9。
9、 设无向树 T 中有 1 个结点度数为 2 ,2 个结点度数为 3 ,3 个结点度数为 4 ,则 T 中 的树叶数为( (A)10; ) (B)11; (C)12; (D)13。 )
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