镇江市2020学年第一学期期中调研测试卷

合集下载

2020~2021镇江市八年级初二上学期数学期中调研及答案

2020~2021镇江市八年级初二上学期数学期中调研及答案

镇江市2020~2021学年第一学期期中调研八年级数学试卷本试卷共6页,共26题;全卷满分120分,考试时间100分钟.一、填空题(本大题共有12小题,每小题2分,共计24分.)1.如图,△ABC ≌△A'B'C',其中∠A =35°,∠C =25°,则∠B'= ▲ .2.如图,OC 是∠AOB 的平分线,P 是OC 上一点,PD ⊥OA 于点D ,PD =2,则点P 到3.直角三角形的两直角边长分别为6、8,则斜边上的中线长等于 ▲ .4.如图,在△ABC 和△DEF 中,B 、E 、C 、F 在一条直线上,AB ∥DE ,AB =DE ,添加一个条件: ▲ ,使得△ABC ≌△DEF .5.如图,以直角三角形三边向外作正方形,其中两个正方形的面积为100和64,则正方形A 的面积等于 ▲ .6.已知等腰三角形的一个内角为50°,则这个等腰三角形的顶角为 ▲ .7.如图,将一张长方形纸片按如图所示折叠,如果∠1=55°,那么∠2= ▲ °.8.如图,在△ABC 中,AC 的垂直平分线DE 分别交AC 、AB 于点D 、E ,若AB =7,BC =5,则△BCE 的周长等于 ▲ .9.如图,在△ABC 中,ED ∥BC ,∠ABC 和∠ACB 的平分线分别交ED 于点G 、F ,若BE =5,DC =7,DE =16,则FG = ▲ .10.如图,在△ABC 中,CP 平分∠ACB ,AP ⊥CP 于点P ,已知△ABC 的面积为2cm 2,则阴影部分的面积为 ▲ cm 2.A 'AB 'C 'B (第1题)(第7题)12A(第2题)DOPBCD(第8题)BCAE (第5题) A1006411. 如图,等腰△ABC 中,AB =AC ,AC 的垂直平分线分别交AB 、AC 于点D 、E ,BD 的垂直平分线交AB 于点F ,并且恰好经过点C ,则∠A= ▲ °.12.如图,在Rt △ABC 中,∠BAC =90°,AD 是BC 边上的高,点B 关于AD 的对称点为B',点A 关于BC 的对称点为A',连接A'B'并延长,交AC 于点E ,若AB =3,AC =4,则线段CE 的长为 ▲ .二、选择题(本大题共有6小题,每小题3分,共计18分.在每小题所给出的四个选项中,恰有一项符合题目要求.)13.下面四个手机的图标中,是轴对称图形的是( ▲ )14.小明玩自拍,自拍照中电子钟示数如图所示,拍照的时刻应是( ▲ ) A .21∶10 B .10∶21 C .10∶51 D .12∶01 15.下列四组线段中,不能作为直角三角形三边长度的是( ▲ )A .3,4,5B .8,15,17C .1.5,2,2.5D .514131,,16.到三角形三边距离相等的点是这个三角形的( ▲ ) A .三条高的交点 B .三条内角平分线的交点 C .三条中线的交点 D .三条边的垂直平分线的交点 17.如图是4×4的正方形网格,其中已有3个小方格涂成了黑色.现在要从其余13个白色小方格中选出一个也涂成黑色,与原来3个黑色方格组成的图形成为轴对称图形,则符合要求的白色小正方格有( ▲ ) A .1个 B .2个 C .3个 D .4个D A B CBCEAG(第9题)FDCA(第11题)BDE F (第10题) BAPC(第17题)CB(第12题)DEA 'B 'A(第14题)18.如图,在△ABC 中,∠ACB =90°,Rt △ABC ≌Rt △AB'C',且∠ABC =∠CAB',连接BC',并取BC'的中点D ,则下列四种说法: ①AC'∥BC ;②△ACC'是等腰直角三角形; ③AD 平分∠CAB'; ④AD ⊥CB'.其中正确的个数为( ▲ )A .1个B .2个C .3个D .4个三、解答题(本大题共有8小题,共计78分.解答时应写出必要的文字说明、证明过程或演算步骤.) 19.(本小题满分6分)如图,AB 、CD 相交于点O ,△AOC ≌△BOD ,点E 在AC 上,EO 的延长线交BD 于点F .求证:O 是EF 的中点.20.(本小题满分10分)如图所示,每个小正方形的边长为1,△ABC 的顶点都在小正方形的顶点处. (1)画出△ABC 关于直线l 对称的△A'B'C'; (2)直接写出△A'B'C'的面积等于 ▲ ;(3)在直线l 上求作一点P ,使P A +PC 的长度最小,并写出这个最小值为 ▲ .(第18题)BACB 'C 'DCF(第19题)AB DEO(第20题)如图,点B 、F 、C 、E 在同一直线上,AB ⊥BE ,垂足为B ,DE ⊥BE ,垂足为E ,AC 、DF 相交于点G ,且AC =DF ,BF =CE . (1)求证:△ABC ≌△DEF ;(2)若∠A =65°,则∠DGC = ▲ °.22.(本小题满分9分)如图,AB =AC ,BD =CD . (1)求证:△ABD ≌△ACD ; (2)连接BC ,求证:AD ⊥BC .23.(本小题满分10分)如图,△ABC 中,BC 的垂直平分线DE 分别交AB 、BC 于点D 、E ,且BD 2-DA 2=AC 2. (1)求证:∠A =90°;(2)若AB =8,AD ∶BD =3∶5,求AC 的长.CAD(第22题)ABDCE(第21题)F GBACE D(第23题)如图,在△ABC 中,∠ACB =90°,AC =BC =AD .(1)作△ACD 的高AE ,点E 为垂足(要求:尺规作图,不写作法,保留作图痕迹); (2)在射线CD 上找一点P ,使△PCB 与(1)中所作的△ACE 全等(要求:尺规作图,不写作法,保留作图痕迹).并证明你所作出的△PCB 与△ACE 全等.25.(本小题满分12分)如图,点E 在等边△ABC 的边AB 所在直线上,以EC 为一边作等边△ECF ,顶点E 、C、F 顺时针排序.(1)点E 在线段AB 上,连接BF .求证:BF ∥AC ; (2)已知AB =6,当△BCF 是直角三角形时,求BE 的长.(第24题)如图1,∠MCN=90°,点A在射线CM上滑动,点B在射线CN上滑动,且线段AB 的长始终保持10cm不变.(1)若AC=6cm,动点P从点A出发,从点A→点B→点C→点A,速度为2cm/s,设运动时间为t s.当t为何值时,△ACP为等腰三角形;(2)如图2,在滑动过程中,以AB为斜边在AB的右侧作Rt△ABE,在滑动的过程中EC的最大值为▲.(直接写出结果)(第26题)2020~2021学年第一学期期中调研八年级数学试卷参考答案及评分标准一、填空题(本大题共有12小题,每小题2分,共计24分.) 1.120° 2.2 3.5 4.∠A =∠D (答案不唯一) 5.36 6.50°或80° 7.110° 8.12 9.4 10.1 11.36° 12.2528二、选择题(本大题共有6小题,每小题3分,共计18分.)13. A 14. C 15. D 16. B 17. D 18. C 三、解答题(本大题共有8小题,共计78分.) 19.(本小题满分6分)证明:∵△AOC ≌△BOD , ∴∠C =∠D ,OC =OD . ……2分 在△COE 和△DOF 中,∠C =∠D ,OC =OD ,∠COE =∠DOF , ∴△COE ≌△DOF (ASA ). ………………4分 ∴OE =OF .即O 是EF 的中点. ………………6分 20.(本小题满分10分)(1)略,作图正确;………… 3分 (2)5;………… 6分(3)点P 位置正确,………… 8分, 最小值等于5. …………10分 21.(本小题满分9分)证明:(1)∵AB ⊥BE ,DE ⊥BE , ∴∠B =∠E =90°. …………2分 在Rt △ABC 和Rt △DEF 中,∠B =∠E =90°,AB =DE ,AC =DF , ∴Rt △ABC ≌Rt △DEF (HL );………6分 (2)50°. ………9分 22.(本小题满分9分)证明:(1)在△ABD 和△ACD 中,AB DC EFGCFABDEOAB=AC,BD=CD,AD=AD,∴△ABD≌△ACD;………4分(2)由(1)可得∠BAD=∠CAD. ………6分∵AB=AC,∠BAD=∠CAD,∴AD⊥BC. ………9分(用其他方法解答,相应给分)23.(本小题满分10分)(1)证明:连接CD.∵DE垂直平分BC,∴CD=BD. ………2分∵BD2-DA2=AC2,∴CD2-DA2=AC2.………………3分∴∠A=90°;……………5分(2)∵ AB=8,AD∶BD=3∶5,∴AD=3,BD=5,……………7分∴CD=5. ……………8分∵∠A=90°,∴由勾股定理得AC=4. …………10分24.(本小题满分10分)解:(1)作∠A的平分线,交CD于点E,点E即为所求;…………4分(2)以点C为圆心,AE长为半径画弧,与CD的延长线相交与点P,点P即为所求.…………8分证明(略).…………10分(用其他方法解答,相应给分)25.(本小题满分12分)(1)证明:∵△ABC是等边三角形,∴AC=BC,∠A=∠ACB=60°. (1)∵△EFC是等边三角形,∴EC=FC,∠ECF=60°. ……2分∴∠ACB-∠ECB =∠ECF-∠ECB.即∠ACE=∠BCF. ……3分在△BCF和△ACE中,BC = AC,∠BCF =∠ACE,FC = EC∴△BCF≌△ACE(SAS),……4分BACED∴∠CBF =∠A =60°,∴∠CBF =∠ACB =60°. ∴BF ∥AC ; ……6分 (2)①若∠BFC =90°,如图1.∵∠CBF =60°, ∴∠ECB =∠BCF =30°.由“等腰三角形的三线合一”可知,E 为AB 中点. ∴BE =32=AB; ……9分 ②若∠BCF =90°,如图2.∵∠CBF =60°, ∴∠CFB =∠BCE =∠BEC =30°. ∴BE =BC =6. ……12分26.(本小题满分12分)(1)由勾股定理,得BC =8. ………………1分 ①点P 在AB 上运动.当AC =AP 时,△ACP 为等腰三角形. ∴AP =6,∴t =326=s ; 当CA =CP 时,如图1,△ACP 为等腰三角形. 此时CP =CA =6.过点C 作CD ⊥AB 交AB 于点D . 由AC ·BC =AB ·CD ,得CD =4.8,由勾股定理得 AD =DP =3.6, ∴AP = AD +DP =7.2,∴t = 3.627.2=s ;…………6分 ABCEF图2当P A =PC 时,△ACP 为等腰三角形. 则P 为AB 中点. ∴AP =5. ∴t =25s ; ………8分 ②点P 在BC 上运动. CP =CA =6. 则BP =2. ∴t =62=+BPAB s . ………10分 综上所述,当t =2.5s ,3s ,3.6s ,6s 时,△ACP 为等腰三角形; (2)如图2,取AB 的中点G ,连接CG 、EG .当C 、G 、E 三点共线时,CE 的值最大,最大值为10. ……12分。

江苏省镇江市2020届高三上学期期中联合调研测试语文试题(解析版)

江苏省镇江市2020届高三上学期期中联合调研测试语文试题(解析版)

江苏省镇江市2020届高三上学期期中联合调研测试语文试题一、语言文字运用(12分)1.在下面一段话的空缺处依次填入词语,最恰当的一组是()歌德的字斜得厉害,但整齐,像一片被大风吹伏了的柳枝。

席勒的字正常而略显自由,我想应该是多数西方有才华作家的习惯写法。

最怪异的莫过于尼采,那么的思想,手稿却板正、,像是一个木讷的抄写者的笔触。

A. 洒脱特立独行拘谨B. 潇洒狂放不羁拘谨C. 洒脱特立独行谨慎D. 潇洒狂放不羁谨慎2.在下面一段文字横线处填入语句,衔接最恰当的一项是()可是更妙的是三五月明之夜,,如果给田园诗人见了,必将赞叹为绝妙的题材。

①这时候忽然从山脊上长出两支牛角来②远看山顶的谷子丛密挺立,宛如人头上的怒发③他们姗姗而下,在蓝的天,黑的山,银色的月光的背景上,成就了一幅剪影④天是那样的蓝,几乎透明似的⑤随即牛的全身也出现,掮着犁的人形也出现,也许还跟着个小孩⑥月亮离山顶,似乎不过几尺A. ①⑤④⑥②③B. ③④⑥②①⑤C. ④⑥②①⑤③D. ⑥④②③①⑤3.下列四句诗中描写的传统节日,不同于...其它三项的是()A. 且欲近寻彭泽宰,陶然共醉菊花杯。

B. 茱萸插鬓花宜寿,翡翠横钗舞作愁。

C. 但将酩酊酬佳节,不用登临恨落晖。

D. 玉露金风报素秋,穿针楼上独含愁。

4. 对下列材料理解最恰当的一项是()清代著名戏曲理论家李渔对写作有形象的比喻:“基址初平,间架未定,先筹何处建厅,何处开户,栋需何木,梁用何材,必俟成局了然,始可挥斤运斧。

”A. 写文章先结构,选材料。

B. 写文章必须注意衔接,前后勾连。

C. 写文章打好基础,注重积累。

D. 写文章围绕中心,收放自如。

二、文言文阅读(20分)阅读下面的文言文,完成下面小题。

陈长生传张惠言余故居南郊德安里,邻有陈长生者,与兄奉母以居,无妻子,有室一楹,园地以稜计者十。

兄偻且病,常给爨.守舍。

而长生力治地种菜,卖之得钱,且为人赁佣以充食。

长生为人少言多笑,即有陵之,大恚,辄复笑,即已,未尝校.。

2019-2020镇江市九年级上册期中英语试卷

2019-2020镇江市九年级上册期中英语试卷

2019~2020学年第一学期期中质量调研测试九年级英语试卷满分:120分时间:100分钟一、听力(共20小题,每小题1分,满分20分)I.听对话,回答问题。

听两遍。

听第1至10段材料,回答第1至10小题。

1.What is Sandy’s animal sign?A. B. C.2.Which way does the girl like best to learn about the world?A. B. C.3.What does the boy think the girl can be?A. B. C.4.Who influenced Millie most?A. B. C.5.What colour may represent Amy’s feeling?A.Red.B.Blue.C.Green.6.Where did the man find his wallet?A.On the grass.B.In the library.C.On the playground.7.How does the boy feel about the Maths exam?A.Stressed.B.Confident.C.Worried.8.How many students ride to school in John’s class?A.18.B.12.C.15.9.Why is Tom’s English getting better?A.Because he took more English lessons.B.Because he visited New York.C.Because he made an American friend.10.Who are two speakers talking about?A.The old people.B.Babies.C.Children.II.听对话和短文回答问题。

2020年江苏镇江中学高三英语上学期期中试卷及答案解析

2020年江苏镇江中学高三英语上学期期中试卷及答案解析

2020年江苏镇江中学高三英语上学期期中试卷及答案解析第一部分阅读(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的A、B、C、D四个选项中选出最佳选项AI started working with my hands at a young age. The youngest of five brothers, I took on the role as a “maintenance (维修) man” at an early age for our family’s small grocery store. Often my dad wouldn’t give me a clear idea of how something shouldbe done, so I just had to figure it out by researching or through trial and error.Fast forward to 2016 and those problem-solving skills would become the focus of Tippecanoe High School’s Homebuilding class. I knew I wanted to teach the students skills that went beyond just being able to hammer nails or cut pieces of two-by-fours. The problem was that we didn’t have the resources at the time to do much else. The idea of attracting some type of funding seemed very important. Designing, building and selling a tiny house on wheels seemed like the perfect project to accomplishthe task. I reached out to a number of local businesses and most of them responded with the greatest support for what x k w we were doing.This year we added a new element to the program. Through one of our partners, we were able to connect with the nonprofit Veteran’s Ananda Incorporated. Students in the Homebuilding class are leading the design and production of micro houses to be donated to this organization. The new partnership gives the students another focus to consider when designing and building the houses.There has been no shortage of students since our first year. Three years ago we had 41 students, the next 191, and this year it was limited to just over 160 students so we could have a safe and manageable classroom environment. The number of girls taking the class has risen steadily over the last few years as well. This class offers something for everyone and the skills are universal.1. How can we describe the young author?A. He opened a small grocery store.B. He did a lot of research in the lab.C. He enjoyed doing hands-on activities.D. He learnt about maintenance from his father.2. What do the underlined words “the task” in paragraph 2 refer to?A. Getting some financial support.B. Selling a tiny house on wheels.C. Reaching out to many local businesses.D. Offering the students some problem-solving skills.3. What can be inferred about the Homebuilding class from the last paragraph?A. Its size needs increasing.B. Itis popular with the students.C. It has caused some safety concerns.D. Its classroom environment is hard to manage.BPaper is an important part of modern life. People use it in school, at work, to make artwork and books, to wrap presents and much more. Trees are the most common material for paper these days.So how do people make paper out of trees today? People first cut trees, load them onto trucks and bring them to a factory. Machines cut open the outer coverings of the trees, and cut the trees into pieces. Those pieces are boiled into a soup. After that, it is hit flat, dried and cut up into sheets of paper.The entire process, from planting a small tree to buying your school notebook, takes a very long time. Just growing the trees takes 10 to 20 years.Making tons of paper from trees can harm the planet. Humans cut down 80, 000 to 160,000 trees around the world every day, and use many of them to make paper. Some of those trees come from tree farms. But people also cut down forests for paper, which means that animals and birds lose their homes.Cutting forests down also contributes to climate change, and paper factories pollute the air. After you throw paper, it often takes the paper six to nine years to break down. That's why recycling is important. It saves a lot of trees, slows climate change and helps protect endangered animals, birds and all creatures that rely on forests for their homes and food.So if paper isn't good for the environment, why don't people write on something else?The answer: They do. With computers, tablets and cellphones, people use much less paper than in the past. Maybe a day will come when we won't use paper at all — or will save it for very special books and artworks.4. What can we know about making paper out of trees?A. It costs much money.B. It takes a lot of time.C. It is very easy and fast.D. It is dangerous and difficult.5. What is the impact of paper production?A. It promotes the recycling.B. It does harm to the environment.C. It slows down the climate change.D. It protects the animals from losing homes.6. How will we use paper someday in the future according to the text?A. Use it for books only.B. Use the recycled paper.C. Treasure it occasionally.D. Use it for artworks.7. What idea does the author want to express from the text?A. The influence of making paper on environment.B. The wonderful experience of making paper.C. The necessary process of making paper.D. The good reasons for making paper.CSix Neanderthals who lived in what is now France were eaten by their fellow Neanderthals some 100,000 years ago, according to fearful evidence of the cannibalistic (食人的) event discovered by scientists in a cave in the 1990s. Now, researchersmay have figured out why the Neanderthals, including two children, became victims of cannibalism: Global warming.While previous studies have examined Neanderthal remains to find proof of cannibalistic behavior, this is the first study to offer clues as to what may have led Neanderthals to become cannibals. Scientists found that rapid changes in local ecosystems as the planet warmed may have wiped out the animal species that Neanderthals ate, forcing them to look elsewhere to fill their stomachs.The researchers examined a layer of sediment (沉积物) in a cave known as Baume Moula-Guercy, in southeastern France. In that layer, charcoal (碳) and animal bones were so well-preserved that scientists could reconstruct an environmental picture representing 120,000 to 130,000 years ago. They discovered that the climate in the area was likely even warmer than it is today, and that the change from a cold, dry climate to a warmer one happened quickly. “Maybe within a few generations”, study co-author Emmanuel said. As the animals that once populated the landscape disappeared, some Neanderthals ate what they could find — their neighbors.Cannibalism is by no means unique to Neanderthals, and has been practiced by humans and their s “from the early Palaeolithic to theBronze Age and beyond,” the study authors reported. The behavior adopted by the starving Neanderthals in the Baume Moula-Guercy should therefore not be viewed as “a mark of bestiality (兽性) or sub-humanity”, but as an emergency adaptation to a period of severe environmental stress, according to thestudy.8. What does the study mainly focus on?A. The social behavior of Neanderthals.B. The reason for cannibalism among Neanderthals.C. The climate change in southeasternFrance.D. The influence of global warming on ancient animals.9. What can possibly be used to describe the climate in southeasternFrance120,000 to 130,000 years ago?A. It was no warmer than it is today.B. It was first warm while later cold and dry.C. Its change was mild and went through quite a long process.D. Its change is a chief factor contributing to cannibalism.10. Which of the following might the study authors agree with?A. Neanderthals’ cannibalism showed their bestiality.B. Cannibalism was actually a measure the Neanderthals had to adopt to survive.C. Neanderthals’ cannibalism guaranteed their rule over other tribes.D. Only Neanderthals were found to have cannibalism in human history.11. Where can you most possibly find this passage?A. In a science journal.B. In a travel brochure.C. In a history book.D. In a geography book.DBertha von Suttner received the Nobel Peace Prize in 1905—she was the first woman to receive it, and also the inspiration for the creation of the Nobel Prize.She met Alfred Nobel, a rich millionaire, by answering hisnewspaper ad for a secretary. Although she only worked for him for a few weeks, she remained good friends with Alfred Nobel for the next 20 years. When she became involved in the peace movement inEurope, she promised to keep Nobel informed of its progress. When Alfred Nobel died in 1896, his will included the establishment of a peace prize, thanks to Bertha von Suttner’s influence.Bertha von Suttner was born in an aristocratic (贵族) military family, but she spent the second half of her life working for peace. She wrote books, attended peace conferences, gave lectures and helped organize peace societies inAustria,GermanyandHungary, as well as the International Peace Bureau inSwitzerland. Her novel LayDown your Arms, was one of the most influential anti-war books of all time, and helped to make her a leader of the peace movement in Europe. Its end to war theme was both the ambition (抱负) and the most important goal in the life of this great woman.Bertha von Suttner worked so hard for peace because she believed that a terrible war would break out inEuropeif nations didn’t work hard to establish lasting peace institutions. She made many major achievements for a more peaceful world, but two months after she died, World War I broke out. A hundred years after she won the Nobel Peace Prize, nations still seem to view war as a choice to work out their problems. But like Bertha von Suttner did, many today are working hard around the world to help strengthen peace institutions and spread the idea that it’s time to put an end to war.12. Which of the following is true about Bertha von Suttner?A. She worked for Alfred Nobel for 20 years.B. She helped Alfred Nobel draw up his will.C. She persuaded Alfred Nobel to join the peace movement.D. She inspired Alfred Nobel to establish the Nobel Peace Prize.13. Paragraph 3 is mainly about Bertha von Suttner’s _____________.A. efforts and contributions to the peace movement.B. family background and work experiences.C. writing career and life experiences.D. ambition and goals in life.14. What do we know aboutLay Doun Your Arms?A. It was based on a true story.B. It recorded Bertha von Suttner’s daily life.C. It was about an aristocratic military family.D. It showed Bertha von Suttner’s wish for peace.15. What can we infer about Bertha von Suttner from the last paragraph?A. Her fight for peace is still shared by many.B. She failed to found peace institutions.C. She successfully predicted awar.D. She lost her life in World War I.第二节(共5小题;每小题2分,满分10分)阅读下面短文,从短文后的选项中选出可以填入空白处的最佳选项。

江苏省镇江市2020届高三英语上学期期中试题(含解析)

江苏省镇江市2020届高三英语上学期期中试题(含解析)

江苏省镇江市2020届高三英语上学期期中试题(含解析)本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。

满分120分,考试时间120分钟。

第Ⅰ卷(选择题共85分)第一部分:听力(共两节,满分20分)第一节(共5小题;每小题1分,满分5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.音频What is Bob most probably doing?A. Watching a game.B. Playing basketball.C. Fishing.【答案】C【解析】【分析】此题为听力题,解析略。

【详解】此题为听力题,解析略。

2.音频When will the speakers meet?A. By 5:00.B. By 4:30.C. By 2:30.【答案】C【解析】【分析】此题为听力题,解析略。

【详解】此题为听力题,解析略。

3.音频What color is the T­shirt the man likes?A. Green and white.B. Gray and black.C. Gray and white. 【答案】A【解析】【分析】此题为听力题,解析略。

【详解】此题为听力题,解析略。

4.音频Why was the woman annoyed?A. Because the film was too long.B. Because the seats were uncomfortable.C. Because the people behind were too noisy.【答案】C【解析】【分析】此题为听力题,解析略。

【详解】此题为听力题,解析略。

5.音频How does Mary feel today?A. Nervous.B. Sad.C. Happy.【答案】B【解析】【分析】此题为听力题,解析略。

江苏省镇江中学2020届高三上学期期中调研试题(强化班)数学试题 含答案解析

江苏省镇江中学2020届高三上学期期中调研试题(强化班)数学试题 含答案解析

江苏省镇江中学2020届高三年级第一学期期中调研试题数学试题一、填空题(本大题共14小题,每小题5分,共计70分.不需要写出解答过程,请将答案填写在答题卡相应的位置上..........) 1.已知集合A ={}(3)0x x x -<,B ={﹣1,0,1,2,3},则A I B = . 答案:{1,2} 考点:集合的运算解析:因为集合A ={}(3)0x x x -<, 所以A =(0,3),又B ={﹣1,0,1,2,3}, 所以A I B ={1,2}. 2.i 是虚数单位,复数15i1i--= . 答案:2i 3-+ 考点:复数解析:2215i (15i)(1i)5i 4i 164i2i 31i (1i)(1i)1i 2--+--+-====-+--+-. 3.函数y =的定义域为 .答案:(1,2]考点:函数的定义域解析:由题意得:12log (1)010x x -≥⎧⎪⎨⎪->⎩,则21x x ≤⎧⎨>⎩,故原函数的定义域为(1,2].4.已知α是第二象限角,其终边上一点P(x),且2cos 3α=-,则x 的值为 .答案:﹣2考点:三角函数的定义解析:由α终边上一点P(x,得2cos 3α==-,解得:24x =,α是第二象限角,所以x 的值为﹣2.5.右图是一个算法流程图,则输出的i 的值为 .答案:3考点:程序框图解析:第一次,S =400,不满足退出的循环条件,i =1; 第二次,S =800,不满足退出的循环条件,i =2; 第三次,S =1200,不满足退出的循环条件,i =3;第四次,S =1600,满足退出的循环条件.故输出的i 的值为3.6.若同时抛掷两枚骰子,则向上的点数之差的绝对值为3的慨率是 . 答案:16考点:古典概型解析:同时抛掷两枚骰子,基本事件总数为36,其中向上的点数之差的绝对值为3的事件数为6,故P =636=16. 7.若正四棱锥的底面边长为22,侧面积为422,则它的体积为 . 答案:8考点:棱锥体积解析:设四棱锥为P —ABCD ,底面ABCD 的中心为O 取CD 中点E ,连结PE ,OE ,则PE ⊥CD ,OE =2, ∵S 侧面=4S △PCD =4×12×CD ×PE =422, ∴PE =11,PO =3,∴正四棱锥体积V =12222383⨯⨯⨯=.8.设等差数列{}n a 的前n 项的和为n S ,若3a =5,且1S ,5S ,7S 成等差数列,则数列{}n a 的通项公式n a = . 答案:21n -考点:等差数列的通项公式解析:∵1S ,5S ,7S 成等差数列,∴25S =1S +7S ,即314107a a a =+故3331027()a a d a d =-++,又3a =5,求得d =2, ∴n a =5(3)2n +-=21n -. 9.在△ABC 中,B =4π,BC 边上的高等于13BC ,则cosA = .答案:10-考点:余弦定理解析:设BC 边上的高AD 为x ,则a =BC =3x ,BD =x ,CD =2x ,故c =ABx ,b =AC=,由余弦定理得:cosA =2222b c a bc +-22210-.10.已知x >0,y >0,且x +y =1,则21x y xy++的最小值为 .答案:5 考点:基本不等式解析:212323232()()55x y x y x y y xx y xy xy x y x y x y+++++==+=++=++≥当且仅当1x y =+=⎪⎩时取“=”.11.已知a ∈R ,设函数2, 1(), 1x x ax a x f x ae x x ⎧-+≥⎪=⎨-<⎪⎩(其中e 是自然对数的底数),若关于x的不等式()0f x ≥在R 上恒成立,则a 的取值范围为 . 答案:1e≤a ≤4 考点:函数与不等式(恒成立问题)解析:分两部分完成,第一部分20x ax a -+≥对1x ≥恒成立,第二部分0xae x -≥对1x <恒成立.(1)先20x ax a -+≥对1x ≥恒成立,当x =1时,符合题意;当x >1时,参变分离得:211211x a x x x ≤=-++--,因为1121x x -++-≥4,当x =2时取“=”,故上式恒成立时a ≤4; (2)再解0xae x -≥对1x <恒成立,参变分离得:x x a e ≥,令()x x p x e =,1()0xxp x e -'=>,故()p x 单调递增, ∴1()(1)x x p x p e e=<=要使0xae x -≥对1x <恒成立,则a ≥1e.综上所述,a 的取值范围为1e≤a ≤4.12.在△ABC 中,已知(4AB AC -u u u r u u u r )⊥CB u u u r,则sinA 最大值等于 .答案:35考点:余弦定理,平面向量数量积与向量垂直,基本不等式解析:∵(4AB AC -u u u r u u u r )⊥CB u u u r∴(4AB AC -u u u r u u u r )·CB u u u r=0∵CB u u u r =AB AC -u u u r u u u r,代入上式,并化简得:24AB 5AB AC AC 0-⋅+=u u u r u u u r u u u r u u u r ,故2245cos A 0c bc b -+=,得2244cos A 0555b c b cbc c b+==+>, 由同角三角函数关系式,可知sinA 最大时,cosA 最小,由44cos A 555b c c b =+≥,当且仅当b =2c 时取“=”, 此时sinA 最大值等于35.13.已知实数1a ,2a ,3a ,4a 满足1230a a a ++=,2142420a a a a a +-=,且1a >2a >3a ,则4a 的取值范围是 . 答案:(12+-,12) 考点:不等式与不等关系,一元二次方程与一元二次不等式 解析:∵1230a a a ++=,1a >2a >3a , ∴1a >0,1a >2a >﹣1a ﹣2a ,得21112a a -<<∵2142420a a a a a +-= ∴22441(1)a a a a =- 当4a =1时,显然不符题意;当4a ≠1时,224141a a a a =∈-(12-,1),解得12+-<4a<12, 故4a 的取值范围是(12+-,12). 14.已知2()(ln )(ln )f x ax x x x x =+--恰有三个不同零点,则a 的取值范围为 .答案:(1,221e e e e-+-)考点:函数与方程解析:令()0f x =,变形得:2ln ln ()(1)(1)0x xa a x x+---=, 令ln xt x=,得2(1)(1)0t a t a +---=, 发现ln x t x =,21ln xt x-'=, 当0<x <e ,0t '>,ln x t x =在(0,e )上单调递增;当x >e ,0t '<,ln xt x =在(e ,+∞)上单调递增,且ln x t x =>0.且ln x t x =在x =e 时有最大值1e.当2(1)(1)0t a t a +---=有唯一根或无解时,原方程最多两解,不符题意; 当2(1)(1)0t a t a +---=有两根时,1t t =或2t t =,规定12t t <,要使原方程有三个解,则直线1y t =,2y t =与ln xy x=的交点恰有三个, 即转化为2(1)(1)0t a t a +---=的两根10t ≤,210t e<<,则22(1)4(1)0(1)011(1)(1)0a a a a a ee ⎧⎪-+->⎪--≤⎨⎪⎪+--->⎩,解得1<a <221e e e e -+-. 二、解答题(本大题共6小题,共计90分.请在答题纸指定区域.......内作答,解答应写出文字说明,证明过程或演算步骤.)15.(本小题满分14分)如图,在四棱锥P -ABCD 中,PD ⊥底面ABCD ,底面ABCD 是直角梯形,DC ∥AB ,∠BAD =90°,且AB =2AD =2DC =2PD ,E 为PA 的中点.(1)证明:DE ∥平面PBC ; (2)证明:DE ⊥平面PAB .证明:(1)设PB 的中点为F ,连结EF 、CF ,EF ∥AB ,DC ∥AB ,所以EF ∥DC ,------2分 ,且EF =DC =12AB . 故四边形CDEF 为平行四边形,-----4分 可得ED ∥CF------5分又ED ⊄平面PBC ,CF ⊂平面PBC ,-------6分 故DE ∥平面PBC --------------7分注:(证面面平行也同样给分)(2)因为PD ⊥底面ABCD ,AB ⊂平面ABCD ,所以AB ⊥PD 又因为AB ⊥AD ,PD I AD =D ,AD ⊂平面PAD ,PD ⊂平面PAD , 所以AB ⊥平面PAD ----11分ED ⊂平面PAD ,故ED ⊥AB .-------12分又PD =AD ,E 为PA 的中点,故ED ⊥PA ;---------13分PA I AB =A ,PA ⊂平面PAB ,AB ⊂平面PAB ,所以ED ⊥平面PAB ----------14分 16.(本题满分14分)在△ABC 中,角A ,B ,C 的对边分别为a ,b ,c ,(a ﹣b )sinA =(b +c )(sinC ﹣sinB).(1)求角C 的值; (2)若cos(B +6π)=13,求sinA .17.(本题满分14分)已知a ,b 为实数,函数2()1f x x a x b =---. (1)已知a ≠0,讨论()y f x =的奇偶性;(2)若b =1,①若a =2,求()f x 在x ∈[0,3]上的值域;②若a >2,解关于x 的不等式()f x ≥0.18.(本题满分16分)在路边安装路灯,灯柱AB与地面垂直,灯杆BC与灯柱AB所在平面与道路垂直,且∠ABC=120°,路灯C采用锥形灯罩,射出的光线如图中阴影部分所示,已知∠ACD=60°,路宽AD=27米,设灯柱高AB=h(米),∠ACB=θ(30°≤θ≤45°).(1)求灯柱的高h(用θ表示);(2)若灯杆BC与灯柱AB所用材料相同,记此用料长度和为S,求S关于θ的函数表达式,并求出S的最小值.19.(本题满分16分)对于给定的正整数k ,若正项数列{}n a 满足1111n k n k n n n k n k a a a a a a --+-+--+++++L L 2()k n a =,对任意的正整数n (n >k )总成立,则称数列{}n a 是“G(k )数列”.(1)证明:正项等比数列{}n a 是“”;(2)已知正项数列{}n a 既是“G(2)数列”,又是“G(3)数列”,①证明:{}n a 是等比数列;②若21a qa =,N q *∈,且存在N t *∈,使得2134t t a a ++-为数列{}n a 中的项,求q的值.20.(本题满分16分)已知函数321()13f x x ax bx =+++(a ,b ∈R). (1)若b =0,且()f x 在(0,+∞)内有且只有一个零点,求a 的值;(2)若a 2+b =0,且()f x 有三个不同零点,问是否存在实数a 使得这三个零点成等差数列?若存在,求出a 的值,若不存在,请说明理由;(3)若a =1,b <0,试讨论是否存在0x ∈(0,12)U (12,1),使得01()()2f x f =.。

江苏省镇江市镇江中学2020-2021学年度第一学期高三年级期中教学质量检测英语试题及答案

江苏省镇江市镇江中学2020-2021学年度第一学期高三年级期中教学质量检测英语试题及答案

镇江市镇江中学2020-2021年度第一学期高三年级期中教学质量检测(英语)(本试卷共四部分;满分150 分;考试用时120 分钟)第一部分听力(共两节,满分30 分)做题时,先将答案标在试卷上。

录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5 小题;每小题1.5 分,满分7.5 分)听下面5 段对话。

每段对话后有一个小题,从题中所给的A、B、C 三个选项中选出最佳选项。

听完每段对话后,你都有10 秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What is the man most probably doing?A. Having a job interview.B. Applying for a college.C. Visiting sick kids.2.What are the speakers mainly talking about?A. A musical instrument.B. A volleyball player.C. A familiar person.3.How much is the mountain bike now?A $200. B. $160. C. $40.4.What does the man probably do?A. A visitor.B. A writer.C. A singer.5.What does the woman mean?A. She doesn’t agree with the man.B. Jason is likely to be the winner.C. Jason will fall on the ball.第二节(共15 小题;每小题 1.5 分,满分22.5 分)听下面5 段对话或独白。

每段对话或独白后有几个小题,从题中所给的A、B、C 三个选项中选出最佳选项。

听每段对话或独白前,你将有时间阅读各个小题,每小题5 秒钟;听完后,各小题将给出5 秒钟的作答时间。

江苏省镇江市市区统考2019-2020学年七年级第一学期期中质量调研考试英语试卷(无听力部分)

江苏省镇江市市区统考2019-2020学年七年级第一学期期中质量调研考试英语试卷(无听力部分)

2019-2020学年第一学期七年级期中考试英语试卷一、听力部分(共20小题,每小题1分,计20分)略二、单项选择(共15小题,每小题1分,计15分)( )21.He likes playing football, so he wants to buy football.A. a; aB./;/C. /; aD. the; a( )22.Daniel and I in Class 2. are friends.A. am; TheyB. am; WeC. are; WeD. are; They( )23.---What do you want to buy? ---Nothing. Thanks.A. elseB. else thingsC. othersD. other( )24.---How does he look? --- .A. He is 12 years old.B. He is a worker.C. He looks strong.D. He is my brother. ( )25.---What about to He Family Garden(何园)for a trip?---Good idea. Let's have great fun!A. go ; aB. going ; 不填C. going ; aD. to go ; 不填( )26.The city library from 8:00 a.m. to 5:30 p.m. Let’s right now.A. is open ; walk thereB. opens ; walk to thereC. is opened ; walk to thereD. open ; walk there( )27.His home is about 20 kilometers(公里) Nantong.A. far fromB. away fromC. far awayD. away( )28.---I like reading. It makes me .What about you? ---Me, too.A.to feel happilyB. to feel happyC. feel happilyD. feel happy( )29.Which is different(不同)from others?A. HeadB. breadC. readD. ready( )30.Miss Jones teaches English. is a good teacher.A. our ; HerB. us ; SheC. our ; SheD. us ; He( )31. The man a blue coat is standing my father.A.wears ; in front ofB. in ; in the front ofC.wears ; in the front ofD. in ; in front of ( )32.We do eye 10 o'clock at school.A.exercises ; atB. exercise ; atC. exercises ; inD. exercise ; in( )33.My cousin goes to bed early because she can't get ready for a new day without enough sleep.A. sometimesB. seldomC. alwaysD. never( )34.They middle school students and they hard.A.are all ; work allB. are all ; all workC.all are ; work allD. all are ; all work( )35.---I’ll go for a picnic tomorrow with my parents. --- .A. That's all rightB. Good luckC. That’s rightD. Have a good time二、完形填空(共10小题,每小题1分,计10分)a waiter says. “I'd like some” says the man. “Anything else?” asks the waiter, “No,” the man answers. “That's 38 .”“For here or to go?” asks the waiter. “To go, please,” says the man. The waiter puts the food into a bag. Then the man goes away 39 the bag. “have a nice day,” the waiter says.The man walked to the park. He sits down and opens the bag. There is a hamburger, some French fries and a Coke. There is also some 40 in the bag. “That’s the money for my lunch,” says the man. He wants to go back to the 41 because he doesn’t want to get his lunch for free. He is really a good man.When he gets back to the restaurant, he finds it’s 42 . So he has to wait for half an hour there. After 43 the man’s words, the waiter smiles and 44 the manager(经理). The manager thinks the man is good, so he says to the man, “Sorry. We make a mistakes(). You are so 45 , we decide(决定) to give the food to you as a reward(作为回报).”( )36. A. breakfast B. lunch C. dinner D.supper( )37. A.hamburger B. dumpling C. tomato D. potato( )38.A.all B. her C. his D. none( )39.A.of B. with C. from D. to( )40.A.money B. beef C.cabbage D. food( )41.A.park B.house C. restaurant D. home( )zy B. free C. busy D. happy( )43.A.seeing B. watching C. hearing D. listening( )44.A.tells B. asks C. speaks D. talks( )45.A.special B. delicious C.good D. nice四、阅读理解(共10小题,每小题2分,计20分)A( )46.Mike at 6:00 in the morning.A. gets upB. does morning exercisesC. is in bedD. has a quick breakfast( )47.Mike right after lunch.A. chats with friendsB. watches TVC. Plays basketballD. talks to his parents( )48. Which of the following is John's bad habit(习惯)?A. Getting up late and hurrying to school.B. Doing homework in a hurry.C. Going to bed at 9:00 p.m.D. Having dinner while reading.BWe know the 2020 Olympic Games will be in Tokyo. Which city will be the one after that? On Sept 13, 2017, the International Olympic Committee(IOC, 国际奥委会) gave us the answer.Paris will host the Olympic Games in2024 and Los Angeles will be the next in 2028. This is the first time that IOC has chosen(选择) two host cities at the same time, reported Xinhua. Both countries are happy to bring home the Games.Paris hosted two Olympics before. It will host the Games 100 years after its last Games in 1924. For the United States, the event goes back to the country since the 1996 Atlanta Olympics.The two cities already have more than 90 percent of the facilities(设施) for the Games. This will help them to cut the costs(降低成本).( )49. The 2028 Olympic Games will be in .A. TokyoB. AtlantaC. Los AngelesD. Paris( )50. How many times did Paris host the Olympics before?A. Once.B. Twice.C. Three times.D. Four times.( )51. What special thing did the IOC do this time?A. It chose two host cities at the same time.B. It gave the news to Xinhua.C. It chose the 2024 host city earlier.D. It gave Paris a special chance.CLaura is at the airport(机场). She waits for her plane. Her plane is to Berlin, and it is 4 hours away. Laura walks around the shops.After an hour she wants to go to the bathroom. But she doesn't find it. "Where is the bathroom?”she says. She starts asking other people. Laura says to a man, "Excuse me, sir. Could you please tell me where the bathroom is?" The man says, "You mean the restroom, right?" Laura says, "No, I mean the bathroom." "Well, the restroom is over there." He says and walks away.Laura doesn't understand(明白). She asks a woman, “Excuse me, madam. Could you please tell me where the bathroom is?”“The restroom is over there,”the lady answers and walks away. Laura is confused. “What's wrong? I need to use the bathroom and they tell me to rest!” Then Laura gives up(放弃). She feels tired and thinks she needs to rest. She walks to the restroom. Now she is surprised. She realizes(意识到) the restroom is the name for a public(公共的) bathroom!( )52. Laura will go to .A. the airportB. the shopC. a restaurantD. Berlin( )53. Laura asks where the bathroom is.A. a boyB. a man and a womanC. two menD. nobody( )54 What's the meaning of the underlined(加下划线的) word “confused” ?A.兴奋的B.明白的C.迷惑的D.发怒的( )55.The passage tells us .A. the culture(文化) about languageB. the rules(规则) at the airportC. the people are not kindD. the restroom is for rest五、词汇运用(共5小题,每小题1分,满分15分)(A) 根据发音句意和汉语注释,写出正确的单词。

江苏省镇江市润州区2019~2020学年第一学期期中质量调研测试九年级英语试卷及答案

江苏省镇江市润州区2019~2020学年第一学期期中质量调研测试九年级英语试卷及答案

镇江市润州区2019~2020学年第一学期期中质量调研测试九年级英语试卷满分:120 分时间:100 分钟一、听力(共20 小题,每小题 1 分,满分20 分)I. 听对话,回答问题。

听两遍。

听第1 至10 段材料,回答第1 至10 小题。

1. What is Sandy’s animal sign?A. B. C.2. Which way does the girl like best to learn about the world?A. B. C.3. What does the boy think the girl can be?A. B. C.4. Who influenced Millie most?A. B. C.5. What colour may represent Amy’s feeling?A. Red.B. Blue.C. Green.6. Where did the man find his wallet?A. On the grass.B. In the library.C. On the playground.7. How does the boy feel about the Maths exam?A. Stressed.B. Confident.C. Worried.8. How many students ride to school in John’s class?A. 18.B. 12.C. 15.9. Why is Tom’s English getting better?A. Because he took more English lessons.B. Because he visited New York.C. Because he made an American friend.10. Who are two speakers talking about?A. The old people.B. Babies.C. Children.II. 听对话和短文回答问题。

2020┄2021学年第一学期镇江市高三期中质量调研测试

2020┄2021学年第一学期镇江市高三期中质量调研测试

2020┄2021学年第一学期镇江市高三期中质量调研测试化学本卷满分:120分考试用时:100分钟可能用到的相对原子质量:H-1 O-16 C-12 Si-28 P-31 S-32 Cl-35.5 Al-27 K-39Mg-24 Mn-55 Cu-64 Ba-137第Ⅰ卷(选择题共40分)单项选择题:本题包括10小题,每小题2分,共计20分。

每小题只有一个选项符合题意。

1.化学与能源、环境、生产、生活密切相关。

下列说法不正确的是A.CO2和氟氯烃等物质的大量排放会造成温室效应的加剧B.可利用工业生产产生的二氧化碳制造全降解塑料C.世博会很多场馆的外壳使用非晶硅薄膜,以充分利用太阳能,体现低碳经济D.用K2FeO4代替Cl2处理饮用水,有杀菌消毒作用,且不会形成致癌物,但无净水作用2.下列叙述正确的是A.用乙醇或CCl4均可提取碘水中的碘单质B.NaCl和SiC晶体熔化时,克服粒子间作用力的类型相同C.PCl3和Na2O2中各原子或离子最外层都满足8电子稳定结构D.24Mg34S晶体中电子总数与中子总数之比为1∶13.下列有关物质的性质和该性质的应用均正确的是A.常温下浓硫酸能使铝发生钝化,可在常温下用铝制罐贮运浓硫酸B.二氧化硅不与任何酸反应,可用石英制造耐酸容器C.二氧化氯具有还原性,可用于自来水的杀菌消毒D.常温下,K spAgI>K spAgCl,可在AgI、AgCl混合悬浊液中加入浓KI溶液等操作除去AgCl4.常温下,下列各组离子在指定溶液中一定能大量共存的是A.1.0 mol·L—1的KNO3溶液:H+、Fe2+、Cl—、SO42—B.甲基橙呈红色的溶液:NH4+、Ba2+、AlO2—、Cl—C.c(H+)=10-12 mol·L-1的溶液:K+、Ba2+、Cl-、Br-D.加入苯酚显紫色的溶液:K+、NH4+、Cl—、I—操作现象结论A滴加BaCl2溶液生成白色沉淀原溶液中有SO42—B滴加氯水和CCl4,振荡、静置下层溶液显紫色原溶液中有I―C用洁净铂丝蘸取溶液进行焰色反应火焰呈黄色原溶液中有Na+、无K+ D滴加稀NaOH溶液,将湿润红色石蕊试纸不变蓝原溶液中无NH4+试纸置于试管口6.下列表示对应化学反应的离子方程式正确的是A .漂白粉露置在空气中失效:ClO —+CO 2+H 2O =HClO +HCO 3—B .向NaAlO 2溶液中通入过量CO 2:AlO 2—+CO 2+2H 2O =Al (OH )3↓+HCO 3—C .向Na 2S 2O 3溶液中通入足量氯气:S 2O 32—+2Cl 2+3H 2O =2SO 32—+4Cl —+6H +D .在强碱溶液中次氯酸钠与Fe (OH )3反应生成Na 2FeO 4:3ClO —+Fe (OH )3= FeO 42—+3Cl —+H 2O+4H +7.如下图所示,利用海水可提取很多重要的化工原料。

2020届江苏省镇江中学高三上学期期中调研试题(强化班)数学试题(含答案)

2020届江苏省镇江中学高三上学期期中调研试题(强化班)数学试题(含答案)

江苏省镇江中学2020届高三年级第一学期期中调研试题数学(强化班)一、填空题(本大题共14小题,每小题5分,共计70分.不需要写出解答过程,请将答案填写在答题卡...相应的位置上.......) 1.已知集合A ={}(3)0x x x -<,B ={﹣1,0,1,2,3},则A I B = . 答案:{1,2} 2.i 是虚数单位,复数15i1i--= . 答案:2i 3-+ 3.函数12log (1)y x =-的定义域为 .答案:(1,2]4.已知α是第二象限角,其终边上一点P(x ,5),且2cos 3α=-,则x 的值为 . 答案:﹣25.右图是一个算法流程图,则输出的i 的值为 .答案:36.若同时抛掷两枚骰子,则向上的点数之差的绝对值为3的慨率是 . 答案:167.若正四棱锥的底面边长为22422,则它的体积为 . 答案:88.设等差数列{}n a 的前n 项的和为n S ,若3a =5,且1S ,5S ,7S 成等差数列,则数列{}n a 的通项公式n a = . 答案:21n - 9.在△ABC 中,B =4π,BC 边上的高等于13BC ,则cosA = .答案:10-10.已知x >0,y >0,且x+y =1,则21x y xy++的最小值为 . 答案:265+11.已知a ∈R ,设函数2, 1(), 1x x ax a x f x ae x x ⎧-+≥⎪=⎨-<⎪⎩(其中e 是自然对数的底数),若关于x 的不等式()0f x ≥在R 上恒成立,则a 的取值范围为 . 答案:1e≤a ≤4 12.在△ABC 中,已知(4AB AC -u u u r u u u r )⊥CB u u u r,则sinA 最大值等于 .答案:3513.已知实数1a ,2a ,3a ,4a 满足1230a a a ++=,2142420a a a a a +-=,且1a >2a >3a ,则4a 的取值范围是 . 答案:(152+-,512-) 14.已知2()(ln )(ln )f x ax x x x x =+--恰有三个不同零点,则a 的取值范围为 .答案:(1,221e e e e-+-)二、解答题(本大题共6小题,共计90分.请在答题纸指定区域.......内作答,解答应写出文字说明,证明过程或演算步骤.)15.(本小题满分14分)如图,在四棱锥P -ABCD 中,PD ⊥底面ABCD ,底面ABCD 是直角梯形,DC ∥AB ,∠BAD =90°,且AB =2AD =2DC =2PD ,E 为PA 的中点.(1)证明:DE ∥平面PBC ; (2)证明:DE ⊥平面PAB .证明:(1)设PB 的中点为F ,连结EF 、CF ,EF ∥AB ,DC ∥AB ,所以EF ∥DC ,------2分 ,且EF =DC =12AB . 故四边形CDEF 为平行四边形,-----4分 可得ED ∥CF------5分又ED ⊄平面PBC ,CF ⊂平面PBC ,-------6分 故DE ∥平面PBC --------------7分注:(证面面平行也同样给分)(2)因为PD ⊥底面ABCD ,AB ⊂平面ABCD ,所以AB ⊥PD 又因为AB ⊥AD ,PD I AD =D ,AD ⊂平面PAD ,PD ⊂平面PAD ,所以AB ⊥平面PAD ----11分ED ⊂平面PAD ,故ED ⊥AB .-------12分又PD =AD ,E 为PA 的中点,故ED ⊥PA ;---------13分PA I AB =A ,PA ⊂平面PAB ,AB ⊂平面PAB ,所以ED ⊥平面PAB ----------14分 16.(本题满分14分)在△ABC 中,角A ,B ,C 的对边分别为a ,b ,c ,(a ﹣b )sinA =(b +c )(sinC ﹣sinB).(1)求角C 的值; (2)若cos(B +6π)=13,求sinA .17.(本题满分14分)已知a ,b 为实数,函数2()1f x x a x b =---. (1)已知a ≠0,讨论()y f x =的奇偶性;(2)若b =1,①若a =2,求()f x 在x ∈[0,3]上的值域;②若a >2,解关于x 的不等式()f x ≥0.18.(本题满分16分)在路边安装路灯,灯柱AB 与地面垂直,灯杆BC 与灯柱AB 所在平面与道路垂直,且∠ABC =120°,路灯C 采用锥形灯罩,射出的光线如图中阴影部分所示,已知∠ACD =60°,路宽AD =27米,设灯柱高AB =h (米),∠ACB =θ(30°≤θ≤45°).(1)求灯柱的高h (用θ表示);(2)若灯杆BC 与灯柱AB 所用材料相同,记此用料长度和为S ,求S 关于θ的函数表达式,并求出S 的最小值.19.(本题满分16分)对于给定的正整数k ,若正项数列{}n a 满足1111n k n k n n n k n k a a a a a a --+-+--+++++L L 2()kn a =,对任意的正整数n (n >k )总成立,则称数列{}n a 是“G(k )数列”.(1)证明:正项等比数列{}n a 是“”;(2)已知正项数列{}n a 既是“G(2)数列”,又是“G(3)数列”,①证明:{}n a 是等比数列;②若21a qa =,N q *∈,且存在N t *∈,使得2134t t a a ++-为数列{}n a 中的项,求q 的值.20.(本题满分16分)已知函数321()13f x x ax bx =+++(a ,b ∈R). (1)若b =0,且()f x 在(0,+∞)内有且只有一个零点,求a 的值;(2)若a 2+b =0,且()f x 有三个不同零点,问是否存在实数a 使得这三个零点成等差数列?若存在,求出a 的值,若不存在,请说明理由;(3)若a =1,b <0,试讨论是否存在0x ∈(0,12)U (12,1),使得01()()2f x f =.。

江苏省镇江市2020届九年级英语上学期期中试题

江苏省镇江市2020届九年级英语上学期期中试题

2020~2020学年第一学期市属九年级英语期中考试本试卷共10页,满分120分。

考试用时100分钟。

注意事项:1. 答卷前,考生务必用0.5毫米黑色水笔将自己的姓名、准考证号填写在试卷、答题卷上相应位置。

2. 选择题每小题选出答案后,用2B铅笔把答题卷上对应题目选项的答案信息点涂黑;如需改动,用橡皮擦干净,再选涂其他答案。

答案答在试卷上无效。

3. 非选择题必须用0.5毫米黑色水笔作答,答案必须写在答题卷各题目指定区域内相应位置上;如需改动,先划掉原来的答案,然后再写上新答案;不得使用铅笔和涂改液。

不按以上要求作答的答案无效。

祝同学们考出优异成绩!一、听力部分(共20小题;每小题1分,满分20分)(一)听对话回答问题。

本部分共有10道小题,每道小题你将听到一段对话,从题中所给的A、B、C三个选项中选择最佳选项,每段对话听两遍。

1. What’s Jack’s animal sign?A. B. C.2. What kind of sport does the boy prefer?A. B. C.3. What does the boy want to be?A. B. C.4. What’s the problem according to the speaker?A. B. C.5. What colour is Jack’s pen?A. Blue.B. Black.C. Black and blue.6. What does the boy think of growing up?A. He enjoys growing up .B. It helps to learn more about the world.C. It brings him many worries.7. How does John feel these days?A. Sad.B. Angry.C. Happy.8.What does the man think of John?A. He has caught up with others.B. He works hard with his lessons.C. He hasn’t made any progress.9. When did the film begin?A. At 8:10.B. At 7:15.C. At 7:30.10. What is NOT true about the new mobile phone?A.The man bought it himself.B.It was a present.C. The man got it from a friend.(二)听对话和短文回答问题。

江苏省镇江市2019-2020学年第一学期八年级物理期中调研试卷 PDF无答案

江苏省镇江市2019-2020学年第一学期八年级物理期中调研试卷  PDF无答案

2019-2020学年第一学期八年级物理期中调研试卷本试卷共8页,28小题,总分100分。

考试用时90分钟。

一、选择题(本题共12小题,每小题2分,共24分.每小题只有一个选项是正确的)....1.小明发现自己的杯子经常被碰倒,如图甲所示,而同桌的杯子却不容易碰倒,如图乙所示,这是为什么呢?于是他向自己的学习小组寻求帮助,同学们提出了以下四个问题,其中最有探究价值且易于探究的科学问题是()A.为什么有的杯子容易倒,有的不容易倒B.杯子的稳定程度与形状有什么关系C.物体的稳定程度与支撑面有什么关系D.物体的稳定程度与哪些因素有关234.在北京召开的科博会上,有一款幼教机器人可以和小朋友比赛背唐诗,人们能区分机器人和小朋友的声音,主要是依据声音的(A.声速B.音色)C.音调D.响度.下列数据中,符合实际情况的是(A.适合人们洗澡的热水温度约60℃)B.沸水的温度一定是100℃C.人的心跳频率大约为1.2Hz D.声音在真空中的传播速度为340m/s.下列声现象中,主要不是利用声音传递信息的是()..A.蝙蝠靠超声波发现昆虫B.超声波清洗机C.倒车雷达D.B超检查身体5.在拨动吉他弦后,同学们发现,即使停止了对吉他弦的拨动,吉他也会“余音不断”,其根本原因是(A.吉他声的回声仍在回荡C.吉他弦停止振动,空气还在振动D.人的听觉发生了”延长”)B.吉他弦还在振动6.关于体温计,下列说法中正确的是(A.图中体温计的读数是38.2℃)B.可以用沸水给体温计消毒C.读数时,体温计的玻璃泡不能离开人体D.不能用体温计直接测量冰水混合物的温度7.某兴趣小组以相同的烧杯盛等量的水,以相同的热源同时加热.如图所示,甲杯为隔水加热,乙杯为隔油加热,丙杯为隔砂加热,加热一段时间后,测得烧杯外物质的温度分别为水温100℃、油温300℃、砂温600℃,且观察到乙、丙两烧杯中的水呈沸腾状态,则三杯水的温度高低顺序为(A.甲=乙=丙B.甲<乙<丙C.甲<乙=丙D.甲>乙>丙)8 .在北方寒冷的冬季,某地的地下水管破裂,水喷射出来形成了如图所示的“冰花”.虽然气温没有 回升,过一段时间,发现“冰花”还是变小了.则“冰花”从形成到变小的过程中发生的物态变化是 ( )A .先凝固后升华 C .先凝华后升华B .先凝固后汽化D .先凝华后汽化9 .关于物态变化,下列说法中正确的是: () A .凝固、液化、凝华过程均放热 C .固体熔化过程中吸热但温度不变 B .液体凝固过程吸热,温度可能不变D .各种液体只有达到沸点才会汽化) 1 0.下列关于光现象的说法正确的是(A .彩色电视机的色彩是用红、黄、蓝三种色光按不同的比例混合得到B .验钞机是利用了红外线能使荧光物质发光来检验钞票真伪C .我们能看到鲜艳的黄色的花是因为花能发出黄色的光D .电视遥控器是利用红外线来调节电视的11.“蜡炬成灰泪始干”, 歌颂蜡烛默默地燃烧着自己,用自己的光去照亮别人,直至将自己燃尽.图1 中蜡烛油在顺着蜡烛向下流淌时,它的温度随时间的变化图线是图2 中的( )AB C D图 2 图 1 1 2.如图是小阳在室外游泳池游泳时的几幅画面,下面是文文同学提出的一些问题,其中最贴合画 面情景的是( )A .液体的种类是否影响蒸发的速度B .蒸发快慢和液体表面积的大小是否有关?C .体表温度降低与皮肤表面上水的蒸发快慢有关吗?D .哪些因素影响蒸发的快慢二、填空题(本题共 11 小题,每空 1 分,共 35 分)1 3.教室里,小明正认真听老师上物理课,老师的声音是由于声带并通过 传入小明耳中.小明的妈妈到学校给小明送东西,怕打扰上课,故脱掉高跟鞋,赤脚跑了四层楼(如图),这样做是在 减弱噪声.4.舞蹈演员小芳身穿白上衣、绿裙子去参加演出,她先用手机扫描共享单车上的二维码,获取验证后,骑车前往剧场,则共享单车上的二维码 (选填“是”或“不是”)光源;她在表演时,在没有其它任何光照的情况下,当舞台追光灯发出的蓝光照在她的身上时,观众看到她的上衣呈 色, 裙子呈 色.5.城区步行街上安装了如图 1 所示的噪声监测装置,某一时刻该装置的显示屏显示 35 的数字,这产生, 1 第 13 题图1 个数字的单位是 ,它 (选填“能”或“不能”)控制噪声;其中图2 和图3 是两(选填“2”或“3”)是噪声的波形.种声音的波形图,则图第 15 题图 1 第 15 题图 2 第 16 题图第 15 题图 3 1 6.如图所示,交警正利用某种速度测定器来探测公路上汽车是否违章超速,该仪器是利用(选填“超声波”、“次声波”或“可听声”下同)的相关原理工作的;现代科学家已成功研 . .制一种叫做“水母耳”的海上警报器,用来接收 选填 “高于”或“低于”)人耳的听觉频率范围. 7.超声测位仪可用来定位被搜救舰船和测量海深,当在海面用超声测位仪向水深 1531 m 的海底垂直发射超声波,经过 2s 后收到回波,则声音在海水中的传播速度为 m/s ;马里亚纳海沟最 大水深为 11034 米,是地球的最深点,假设声音在海水中的速度相同,当在海面向此处海底垂 直发射超声波,则超声波到达海底需要时间 s (结果精确到整数).8.现已研发出一种“激光橡皮”.在激光照射下,纸张上的黑色碳粉直接为高温碳蒸气,字迹消失;在这个过程中,碳粉需要 (选填“吸热”或“放热”).再经过 特殊冷却装置,高温碳蒸气又直接 (填物态变化名称)成碳粉.这样,废纸和碳粉重 ,从而预报海上风暴,这种声音的频率(1 1 1 (填物态变化名称) 新得到了利用,可有效地节约资源并保护环境.9.常用温度计是利用液体的热胀冷缩原理工作的.此时,图中温度计的示数是℃. 享有“中国冷极”之称的根河市是我国最冷的地方,在一月平均气温接近-30℃,极端最低气温 可达-58℃,依据表格提供的在一标准大气压下的数据,若要监测根河市在一月份的平均气温, 温度计中的测温液体不可以是下列表格中的 .... 物质 酒精水银甲苯 熔点 沸点℃ 10 20 ﹣117℃ ﹣39℃ ﹣95℃ 78℃ 357℃ 111℃2 0.一些枪械上的瞄准器装有夜视仪,这利用的是;适当的 照射可促进人体骨骼 生长和有助人体合成维生素 D (上述两空均选填“红外线”或“紫外线”);绿色植物在光合作用时....... 可将光能转化为 1..如图所示,让一束太阳光通过三棱镜射到白屏上,屏上标出了三个区域,其中能让温度计示数明显升高的是 区域。

江苏省镇江市2020-2021学年第一学期高一数学期中考试卷(word版含答案)

江苏省镇江市2020-2021学年第一学期高一数学期中考试卷(word版含答案)

镇江市2020年高一(上)数学期中考试卷一、单选题(共8题,每题5分,总计40分,在每小题给出的选项中,只有1项符合题意)1.如果集合U={1,2,3,4,5,6,7,8},A={2,4,8},B={1,3,4,7},那么()U A B ⋂等于() A.{4} B.{1,3,7} C.{2,8} D.{1,3,4,5,6,7,8}2.命题“2,220x R x x ∃∈++≤”的否定是()2.,220A x R x x ∀∈++>2.,220B x R x x ∀∈++≤ C.2,220x R x x ∃∈++> 2.,220D x R x x ∃∈++≥3.函数y =的定义域是() A.[-3,+∞) B.(0,+∞)C.(-3,+∞)D.[-3,0)∪(0,+∞) 4.设x ∈R,则"|x-2|<|"是“220x x +->”的()A.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件5.函数y=f(x)与函数y=f(-x)的图像关于()对称Ax 轴 B.y 轴 C.坐标原点 D.不能确定6.若偶函数f(x)在区间(-∞,-1]上是增函数,则()3.()(1)(2)2A f f f -<-< 3.(1)()(2)2B f f f -<-< 3(2)(1)()2C f f f ⋅<-<- 3.(2)()(1)2D f f f <-<- 11.已知x,y 为正数,且xy=1,a=x+y,14,b x y=+下列选项中正确的有() A.a 的最小值为2B.b 的最小值为4C.a+b 的最小值为5D.ab 的最小值为9 12.集合A,B 是实数集R 的子集,定义{|}A B x x A x B -=∈∉且,*()()A B A B B x =-⋃-A)叫做集合的对称差,若集合2{|(1)1,03}A y y x x ==≤≤-+,2{|1,13}B y y x x ==+≤≤,则以下说法正确的是()A.[2,5]B.A-B=[1,2)C.B-A=(5,10]D.A*B=(1,2]U(5,10]三、填空题(共4题,每题5分,总计20分,只要求直接写出结果,不必写出计算和推理过程).13.已知集合A={x|ax ≤1},B =若B ⊆A,则实数a 的取值范围是___.14.若()(22)x x f x x a -=+⋅是奇函数,则实数a=_______.15.高斯是德国著名的数学家,近代数学奠基者之一,享有“数学王子”的称号,他和阿基米德、牛顿并列为世界三大数学家,用其名字命名的“高斯函数”为:设x ∈R,用[x]表示不超过x 的最大整数,则y=[x]称为高斯函数.例如:[-3.5]=-4,[2.1]=2,己知函数31(),132x x f x =-+则函数y=[f(x)]的值域是___. 16.已知函数22,1(),1,1x x f x x x x -≥⎧=⎨+-<⎩那么f(f(4))=_____,若存在实数a,使得f(a)=f(f(a)),则a 的个数是_______. 17.(本小题满分10分)设全集U=R,函数()f x =的定义域为集合A,集合1{|232}4x B x =≤≤命题P:若__________,则A ∩B ≠∅.请从①a=2,②a=-3,③a=-5中选择-一个作为条件,补充到上面命题P 中,使得命题P 为真命题,并求()U A B ⋂18.(本小题满分12分)(1)求值:130263290.125()[(2)]8-+-+。

  1. 1、下载文档前请自行甄别文档内容的完整性,平台不提供额外的编辑、内容补充、找答案等附加服务。
  2. 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
  3. 3、如文档侵犯您的权益,请联系客服反馈,我们会尽快为您处理(人工客服工作时间:9:00-18:30)。

镇江市2020学年第一学期期中调研测试卷九 年 级 化 学命题人 顾大荣 蒋明 审核人:姚建军 冷国平相对原子质量: H-1 C-12 N-14 O-16 Cl-35.5 I-127 Na-23 K-39 Ca-401.下列属于物理变化的是 ( )A .铁器生锈B .燃放烟花C .干冰升华D .食品变质2.下列性质中属于化学性质的是 ( )A .空气可以液化B .汽油能够挥发C .碳酸氢铵受热会分解D .氧气是无色气体3.下列各组物质中,前者属于单质,后者属于混合物的是 ( )A .酒精 天然气B .水银 澄清石灰水C .空气 甲烷D .石油 生铁4、下列产品的开发利用与环境保护无关的是 ( )A .加碘食盐B .无磷洗衣粉C .无铅汽油D .无氟冰箱5、下列说法错误..的是 ( ) A .氮气的化学性质不活泼,所以可用作粮食的保护气B .氦气密度小且化学性质稳定,通常用于填充气球C .废弃塑料的乱扔乱丢产生了“白色污染”,所以要禁止塑料制品的研发D .使用含氟牙膏可预防龋齿6.化学反应中,反应前后一定发生变化的是 ( )A .原子的种类B .原子的数目C .分子的种类D .各物质的总质量7.6月5日是世界环境日,环境保护是我国的一项基本国策,空气的净化越来越受到人们的关注。

下列气体组中,三种气体都属于空气污染物的是 ( )A .SO 2、N 2、NO 2B .CO 2、CO 、N 2C .CO 、CH 4、H 2D .SO 2、CO 、NO 28.下列实验现象描述正确的是 ( )A .磷在氧气中燃烧,有大量白雾产生B .木炭在氧气中燃烧,发出白光,产生大量的白烟C .铁丝在氧气中燃烧,火焰呈蓝色并有黑色固体生成D .硫在氧气中燃烧,发出蓝紫色火焰,并生成有刺激性气味的气体9.下列实验操作中正确的是 ( )A .用酒精灯的内焰给物质加热B .给试管内液体加热时,试管垂直放置,以免液体洒出C .用漏斗过滤时,液面低于滤纸的边缘第一部分 单项选择题(共40分)D.用胶头滴管吸取液体后,将滴管平放或倒置,以免试液污染10.一种元素与另一种元素的本质..区别是()A.原子核外电子数不同B.原子核内质子数不同C.相对原子质量不同D.单质的化学性质不同11.在N2、NO、NO2、NH4NO3四种物质中,N元素表现出的化合价共有()A.3种B.4种C.5种D.6种12.一位同学要用已调平的托盘天平称量2.5g药品,在称量中他发现天平指针向左偏移,这时,他应该()A.减少药品B.向右盘中加砝码C.移动游码D.调节平衡螺母13.下列关于分子和原子的说法中,不.正确的是()A.分子、原子都在不停地运动B.分子、原子都是构成物质的微粒C.原子是不能再分的最小微粒D.分子是保持物质化学性质的一种微粒14.NO是汽车尾气中的一种大气污染物,它是一种无色气体,难溶于水,密度比空气略大,在空气中能与氧气迅速反应而生成红棕色的NO2气体。

在实验室中,收集NO时可选用的集气方法是()A.排水集气法B.向上排空气集气法C.向下排空气集气法D.排水集气法或向上排空气集气法15.亚铁离子Fe2+共有24个电子,则Fe3+离子核外的电子数为()A.3B.23C.24D.2516.过滤操作中不必使用的玻璃仪器是()A.烧杯B.漏斗C.量筒D.玻璃棒17.如图是水分子分解的示意图,该图说明了()A.水是由氢气和氧气组成的B.水分子在化学反应中可以再分C.水分子中含有氢分子和氧原子D.水分子中氢原子和氧原子可以再分18.下列说法中正确的是()A.氧化物都属于含氧化合物B.氧化物只能由物质跟氧气反应生成C.海水中含量最多的元素是钠元素D.蔬菜中不可能含有铁元素19.H2、O2和N2的混合气体20g,点燃完全反应后生成18g水。

则剩余的气体不.可能是()A.H2、O2和N2的混合气体B.O2和N2的混合气体C.H2和N2的混合气体D.2g N220.某物质R是人类生命活动中不可缺少的物质。

已知R的相对分子质量为150,其中含碳元素40%,含氢元素6.7%,其余为氧元素。

则R的化学式为()A.C5H10O2 B.C5H10O5C.C6H6O D.C6H12O6得分评卷人第二部分非选择题(共60分)+2 21.(6分)现有下列物质:①金刚石 ②大理石 ③蒸馏水 ④液态空气 ⑤干冰 ⑥液氧 ⑦高锰酸钾 ⑧氧化铝 ⑨氯化钠 (用序号填写)其中: (1)属于混合物的是 , (2)属于单质的是 ,(3)属于化合物的是 , (4)属于氧化物的是 ,(5)属于含氧化合物的是 , (6)含有氧分子的是 。

22.(6分)用化学符号填空:(1)1个氮分子 (2)2个钠离子 (3)地壳中含量最多的金属元素与最多 的非金属元素组成化合物的化学式 (4)1个铵根离子 (5)2个五 氧化二磷分子 (6)氧化铁中铁元素的化合价为+3价 。

23.(3分)盛放石灰水的瓶中常形成一种不溶于水的白色固体,它是__________,产生这 种物质的原因是(用化学式表示反应过程) 。

24.(2分)若某气体只能..用排水法收集,请你推测该气体可能具有的性质: ① ② 。

25.(2分)氢化钠是一种白色固体,化学式是NaH ,它与水反应生成氢氧化钠和氢气。

该 反应用化学式可表示为 。

26.(3分)依据下列化学符号中数字“2”所表示的意义,把符合题意的序号填在横线上: ①Mg 2+ ②CO 2 ③2CO ④CaO ⑤2NO 3—(1)表示一个离子所带电荷的是_______;(2)表示分子个数的是___________;(3)表示一个分子中所含原子数目的是_______。

27.(2分)涂改液有毒,常使用会影响健康。

某些涂改液背面的文字说明中常有一个标志(如右图所示)。

说明这些涂改液还是一种_______物质。

其中,有 一种涂改液的主要成分是二氯甲烷(CH 2Cl 2),则它是由 组成的。

28.(4分)新型胃动力药物吗丁啉的化学式为C 22H 24ClN 5O 2,其中氮、氧两种元素的质量 比为____ _ ____。

苯丙醇胺(英文缩写为PPA )是禁止使用的感冒药和减肥 药,其结构简式为C 6H 5CH(OH)CH(NH 2)CH 3,则PPA 的化学式为_______ ________, 其相对分子质量为______ ___。

29.(2分)已知某原子中的质子、中子、电子的微粒数之和为40,其中14个微粒不带电,则该原子的核电荷数是 ,该原子的相对原子质量是 。

得分评卷人 得分评卷人 第27题图第32题图 第30题图 30.(3分)如图是电解水的实验装置图。

请回答下列问题: ① 在A 、B 两点标明“+”、“-”极。

② 理论上乙试管中气体体积应是甲试管气体体积的1/2,而实验 结果表明乙试管中气体体积小于甲试管中气体体积的1/2。

你认为产生这种现象的可能 原因 。

31.(6分)将下列实验操作选用的一种仪器名称填在横线上:(1)吸取或滴加少量液体时用____________;(2)实验室收集氧气时用___________盛装气体;(3)移走正在加热的蒸发皿时用____________;(4)做硫粉在氧气中燃烧实验时使用____________;(5)取用块状药品一般使用____________;(6)多量液体反应需要使用 。

32.(9分)如图是加热碱式碳酸铜的实验装置图。

回答下列问题:(1)写出标有序号的仪器名称:①________ _____,②_____ ________,③_______ ______。

(2)加热后,可以观察到试管中___ ____色粉末变成____ __色,试管壁上出 现____ ____,同时可以看到澄清石灰水_____ _____。

(3)用化学式表示碱式碳酸铜加热反应的过程 , 此反应的类型是_______ _____。

(4)实验室运用此反应发生装置可以制取的气体是 , 该反应过程用化学式 可表示: 。

33.(6分)小明参观某养鱼池时,好奇地发现农民向养鱼池撒一种叫做过氧化钙的淡黄色 固体,用来增加鱼池中的含氧量。

小明刚学完氧气的实验室制法,于是他想可否用过氧化 钙制取氧气。

【提出问题】过氧化钙可否用于制取氧气?得分评卷人【查阅材料】部分内容如下:过氧化钙(CaO2)室温下稳定,在300℃时分解生成氧气,可做增氧剂、杀菌剂等。

【猜想与验证】(1)小明依据上述材料,提出猜想Ⅰ:,然后进行以下实验实验装置实验主要过程①检验装置气密性。

操作如下:先将导管伸入液面下,用手紧握试管,观察到________________,松开手后,有液体进入导管。

②加入过氧化钙于试管中,加热,导管口有大量气泡冒出。

③收集满一瓶气体。

④停止加热。

熄灭酒精灯前,应_________________________。

⑤检验气体。

方法是____________________________________。

(2)小明联想到农民用过氧化钙增加鱼池中的含氧量,提出猜想Ⅱ。

猜想Ⅱ:过氧化钙与水反应可制取氧气。

实验装置实验主要过程①检验装置气密性。

②加入过氧化钙和水后,有少量细小气泡缓慢放出,在导管口几乎收集不到气体。

该装置放置到第二天,集气瓶只收集到极少量气体,振荡试管后仍有少量细小气泡缓慢放出。

【实验结论】不能用过氧化钙与水反应制取氧气。

【分析与反思】①虽然没有快速收集到大量氧气,但由此实验现象,小明认为农民用过氧化钙做增氧剂的主要原因是_________________________________________________。

②小明希望对此实验进行改进,使该反应加快,你能帮他提出建议吗?你的合理建议:______________________________________________________________________。

以上建议是否可行,还需进一步通过实验验证。

得分评卷人34.(6分)碘盐就是在食盐中加入一定量的碘酸盐如碘酸钾(KIO3),食用碘盐可以有效地预防碘缺乏病。

试计算:(计算结果保留一位小数)(1)多少质量的碘酸钾含碘20mg?(2)成人每天大约需0.15mg碘,假设这些碘主要是从碘盐中摄取的,若1000g碘盐中含碘20mg,则成人每天需食用碘盐的质量是多少?。

相关文档
最新文档