2020年安徽省示范高中皖北协作区第22届高三联考数学(文科)试题精校版带答案

合集下载

2020届安徽高三联考试题

2020年“安徽省示范高中皖北协作区”第22届高三联考英语第二部分阅读理解(共两节,满分40分) AStart a summer company : studentsHow it worksThrough a program called Summer Company, you can get:* start-up money to kick-off a new summer business* advice and guide from local business leaders to help get the business up and runningLearning how to run your own student business is one of the best summer jobs you can have. You get to be your own boss while learning what it takes to manage a business. Sales ，marketing, bookkeeping, customer r elationship management and networking are just a few of the highly useful sills you’' I1 develop.Who is eligible( 具备条件的)You could be eligible, if you :* go to high school, college or university* live in Ontario* are a Canadian citizen or permanent resident* are between 15-29 years old( if under 18: a parent or guardian must sign the agreement for the applicant) * are not already running a business* are not working at another job or going to school for more than 12 hours a week during the program* are returning to school after the program endsYou cannot apply again if you have received a Summer Company grant in the past.Award amountMaximum award: $3 ,000.Successful Summer Company applicants get: .* up to $1,500 to help with start-up costs* up to $1,500 when you successfully complete the program requirements and hoursHow to applyThe program for 2020 is open through May 19. Here are the steps to apply:* Check to see if you’re eligible for the program* Complete the online application inquiry* Select your local program provider* Assign yourself a password* Submit your application inquiry21. The following skills can be developed through the program except_____A. salesB. marketingC. relationshipD. networking22. If you want to start a summer company, which of the following conditions is not suitable?A. You are between 18-29 years old.B. You are not already running a business.C. You are a Canadian citizen or permanent resident.D. You will attend school for over 12 hours a week during the program.23. When can you apply for the program?A. May 18, 2020.B. May 20, 2020.C. June 18, 2020. .D. June 20, 2020.BKeeping your teenager out of the social media world is impossible. Whether we like it or not, our kids are growing up in a digital era- -and although that creates major opportunities, it also comes with some pretty big risks. We saw this firsthand when we asked a group of tweens and teens to give up their phones and social media for a week; it was as though we' d asked them to part with a limb.A recent study of more than 10 ,000 six- to twelve-grade girls carried out by a nonprofit organization Ruling Our Experiences found that high school girls spend an average of six hours a day on social media. And the effect of too much logged-on time is clear. The study found kids who spend eight hours or more on technology per day are five times more likely to be sad or depressed. Adding to the pressure is that2 out of 3 high school girls report being asked to send a revealing photo to another person, and most of them report that they do send sexual texts and photos to each other.Another study, carried out by Common Sense Media, found that girls use social media more than boys and are also more likely to experience negative consequences. Most of the girls investigated admitted that content posted online often makes them worry about their appearance or social status, while just a quarter of the boys said the same. An earlier study from the Pew Research Center’s Internet came to a similar conclusion: A third of 12- to 13-year-old girls who used social media believed their peers were mostly unkind to each other online , while only 9 percent of the boys agreed.Of course, these di fferences don' t mean we shouldn’t have conce rns about boys and the impact of digital overload or online bulling. In fact, other studies have shown that boys and girls can be equally damaged by social media. The most important thing is for tens to feel safe, online and in the real world alike.24. What is the second paragraph mainly about?A. The pressure of the high school girls logging-on.B. The influence of too much logged-on time on high school girls.C. Too much time spent on social media for high school girls.D. The increasing population of the high school girls logging-on.25. Which of the following can replace the underlined word “revealing” in paragraph 2?A. Exposed.B. Interesting.C. Funny.D. Romantic.26. Why are the girls more likely to experience negative effect online than boys?A. Because the girls' social status is low.B. Because the girls are mostly unkind to each other.C. Because the girls use social media more than boys.D. Because the girls pay more attention to their appearance.27. What can be inferred from the passage?A. Parents should keep teens out of the social media.B. Parents keep teens feel safe online and in the real life.C. It is time to worry about your teens and social media.D. Boys and girls can be equally damaged by social media.CIt often seems that some people possess superhuman eating powers , allowing them to eat an entire pizza while remaining slim. Others only eat a slice but gain five pounds. Now one doctor says there' s evidence that genetics could be behind some of these differences. Regardless of how much you eat, your weight may be out of control.Vann Bennett, a biochemist at Duke University and his team led a new study and discovered why this happens. They engineered mice to have several common modifications of the gene found in humans. Theyobserved that mice who had mutations of ankyrin-B(锚蛋白B的变异) took more glucose(葡萄糖) into their fat ell, which in turn made more fat. Typically, the cell membrane( 膜) acts as a barrier to prevent glucose from entering these cells ; the change k ept the gate open. The change may serve a useful purpose.“ Pr obably this is not always a bad thing," Bennett told Newsweek. “It could help people survive hunger in the past. But today we have somuch food that it probably is a bad thing. ”Dieters have long been told to watch their calories and exercise more, but this new finding suggests that a common approach doesn't work for everyone. Our metabolism( 新陈代谢) naturally slows with age, making it harder to maintain the weight of our 30-year-old selves when we' re 50. Now add an uncontrollable ankyrin-B gene, and it may seem impossible to stay slim.The mice in the study gained more weight when on high-fat diets. Despite being studied in mice, the researchers believe further research on this gene could potentially create a field of customized diets and health plans based on genetics. Bennett imagines such assessments being performed at birth one day. For now, disappointed dieters can take comfort with one saying: It's not you, it's your genes.28. How did a mouse gain weight with mutations of ankyrin-B?A. The ankyrin-B could make the mouse eat more.B. The fat cells in the mouse would take more glucose to create more fat.C. The glucose could function as a barrier to prevent the fat from reducing.D. The cell membrane in the mouse could open the gate of fat into the mouse.29. What was the effect of the change in the past in paragraph 2?A. It could help people to avoid fat food.B. It could help people to absorb more nutrition.C. It could help people to get through the starvation.D. It could help people to enjoy more delicious snacks.30. Why is it more difficult to stay slim when we are older?A. Because we all lack exercise.B. Because we have ankyrin-B genes.C. Because we watch our calories less.D. Because our metabolism weakens.31. What can be expected from further research?A. It may help people to maintain the weight.B. It may provide more comfort for the depressed dieters.C. It may change many new-born babies’ gene arrangement.D. It may present human beings with a series of health plans.DBack in 1975，economists planned rising life expectancy( 预期寿命) against countries ’wealth，and concluded that wealth itself increases longevity. It seemed self- evident: everything people need to be healthy--from food to medical care- costs money.But it soon proved that the data didn't always fit that theory. Economic booms didn ' t always mean longer lives. In addition，for reasons that weren’t clear，a given gain in gross domestic product ( GDP ) caused increasingly higher gains in life expectancy over time, as though it was becoming cheaper to add years of life. Moreover, in the 1980s researchers found gains in learning were associated with greater increases in life expectancy than gains in wealth were. Finally, the more educated people in any country tend to live longer than their less educated fellow citizens. But such people also tend to be wealthier, so it has been difficult to make out which factor is increasing lifespan.Wolfgang Lutz and his colleagues have now done that by collecting average data on GDP per person，lifespan, and years of education from 174 countries，dating from 1970 to 2010. They found that, just as in 1975，wealth associated with longevity. But the association between longevity and years of schooling was closer, with a direct relationship that did not change over time, the way wealth does.Lutz argues that because schooling happens many years before a person has attained their life expectancy, this association reflects cause : better education drives longer life. It also leads to more wealth, which is why wealth and longevity are also associated. But what is important, says Lutz, is that wealth does not seem to be longevity, as experts thought- in fact, education is driving both of them.He thinks this is because education permanently improves a person’s cognitive abilities ,allowing better planning and self-control throughout the rest of their life. This idea is supported by the fact that people who are more intelligent appear to live longer.32. Which of the following best describes economists ’conclusion in 1975?A. Lifespan could be increased by wealth.B. Economic growth didn’t always mean longer life.C. Education influenced longevity more than wealth did.D. A given growth in GDP caused higher gains in longevity.33. What did Wolfgang Lutz and his colleagues find?A. Wealth and longevity did not have any association.B. Longevity and education were more closely associated.C. Differences in wealth predicted differences in longevity.D. Relationship between education and longevity changed over time.34. What part does education play permanently according to Lutz?A. It enables people to have better planning and self-control.B. It always leads to a longer but not necessarily richer life.C. It improves people’s imaginative and innovative abilities.D. It helps people acquire time-managing and learning habits.35. Which of the following is the best title for this passage?A. Wealth influences longevity.B. Education influences longevity.C. Wealth has nothing to do with longevity.D. The relationship between education and wealth.第二节(共5小题;每小题2分,满分10分)The first time I went to a playground in Berlin, I was surprised. All the German parents were huddled together, drinking coffee, not paying attention to their children who were hanging off a wooden dragon 20 feet above a sand pit. Contrary to stereotypes(模式化观念)，most German parents I’ve met are the opposite of strict. 36 . Those parents at the park weren’t ignoring their children; t hey were trusting them. Here are a few surprising things Berlin ’s parents do:Don't push reading. Berlin ’s kindergartens don’t emphasize academics. In fact, teachers and other parents discouraged me from teaching my children to read._ 37 . But even in first grade, academics aren’t pushed very hard. Our grade school provides a half-day of instruction interrupted by two outdoor breaks.38 . A note came home from school along with my excited second grader. They were doing a project on fire. Would I let her light candles and perform experiments with. matches? Together we lit candles and burned things, safely. It was brilliant.Let children go almost everywhere alone. Most grade school kids walk without their parents to school and around their neighborhoods. Some even take the subway alone._ 39 of course, but they usually focuson traffic.，not abductions(绑架).Take the kids outside every day. According to a German saying, “There is no such thing as bad weather, only unsuitable clothing.”The value of outside time is promoted in the schools._ 40 No matter how cold and grey it gets, and in Berlin it gets pretty cold, parents still bundle their kids up and take them to the park, or send them out on their own.A. Encourage kids to play with fireB. Inspire children to go out for leisureC. German parents are concerned about safetyD. It's also obvious on Berlin ' s numerous playgroundsE. Kindergarten was a time for play and social learningF. They place a high value on independence and responsibilityG.I was told it was something special that the kids learn together when they start grade school第三部分语言知识运用(共两节,满分45分)第一节(共20小题;每小题1.5分,满分30分)阅读下面短文,从短文后各题所给的A、B、C和D四个选项中,选出可以填人空白处的最佳选项,并在答题卡.上将该项涂黑。

2020学年高考模拟试卷安徽省淮北市高考一模数学文科试卷(解析版)

2020学年高考一模数学文科试卷一、选择题1．已知集合A＝{1，2，3}，B＝{x|（x+1）（x﹣2）＜0，x∈Z}，则A∩B＝（）A．{1} B．{0，1} C．{0，1，2，3} D．{﹣1，0，1，2，3}2．在复平面内，复数（i为虚数单位）对应的点位于（）A．第一象限B．第二象限C．第三象限D．第四象限3．在区间[0，4]上随机地取一个数x，则事件“0≤log2（x﹣1）≤1”发生的概率为（）A．B．C．D．4．已知平面α，直线m，n，若n⊂α，则“m⊥n”是“m⊥α”的（）A．充分不必要条件B．充分必要条件C．必要不充分条件D．既不充分也不必要条件5．函数的部分图象是（）A．B．C．D．6．中国古代数学著作《孙子算经》中有这样一道算术题：“今有物不知其数，三三数之余二，五五数之余三，问物几何？”人们把此类题目称为“中国剩余定理”，若正整数量N除以正整数m后的余数为n，则记为N≡n（bmodm），例如11≡2（bmod3），现将该问题以程序框图的算法给出，我行该程序框图，则输出的结果等于（）A．35 B．36 C．37 D．387．已知双曲线C的中心在坐标原点且焦点在坐标轴上，C的一个焦点与抛物线的焦点F重合，且点F到双曲线C的渐近线的距离等于2，则双曲线C的方程为（）A．B．C．D．8．已知定义在R上的偶函数f（x）满足，当x∈[0，+∞）时，，，b＝f（20.3），c＝f（0.42），则下列不等式成立的是（）A．a＜b＜c B．c＜b＜a C．c＜a＜b D．b＜c＜a9．已知函数，当|f（x1）﹣f（x2）|＝4时，|x1﹣x2|最小值为，把函数f（x）的图象沿x轴向右平移个单位，得到函数g（x）的图象，关于函数g（x），下列说法正确的是（）A．在上是增函数B．其图象关于直线对称C．在区间上的值域为[﹣2，﹣1]D．函数g（x）是奇函数10．设等差数列{a n}的公差不为0，其前n项和为S n，若（a3﹣2）3+sin（a3﹣2）＝2020，（a2018﹣2）3+sin（a2018﹣2）＝﹣2020，则S2020＝（）A．0 B．﹣2020 C．2020 D．404011．已知正方形ABCD的边长为2，动点P满足，且，则2x+y的最大值为（）A．B．C．D．12．在三棱锥A﹣BCD中，平面ABC⊥平面ADC，AD⊥AC，AD＝AC，，若此三棱锥的外接球表面积为28π，则三棱锥A﹣BCD体积的最大值为（）A．7 B．12 C．6 D．二、填空题（本题共4小题，每小题5分，共20分）13．已知非零向量、满足，，且，则与的夹角为．14．已知，2sin（2α）＝cos（2α）+1，则＝．15．已知椭圆的左右焦点分别是F1，F2，以F2为圆心的圆过坐标原点，过点F1作直线l与圆F2相切，直线l与椭圆相交于点P、Q且PF2⊥x轴，则椭圆的离心率为．16．已知函数f（x）为奇函数，g（x）为偶函数，对于任意x∈R均有f（x）+2g（x）＝mx﹣4，若f（x）﹣3﹣lnx≥0对任意x∈（0，+∞）都成立，则实数m的取值范围是．三、解答题（本大题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤.）17．已知△ABC的内角A，B，C所对的边分别为a，b，c，且10b2cos B＝6ab cos C+3（b2+c2﹣a2）．（Ⅰ）求cos B；（Ⅱ）设，，求△ABC的周长．18．已知数列{a n}的前n项和S n＝n2+n，等比数列{b n}的公比q＞1，且b3+b4+b5＝28，b4+2是b3，b5的等差中项．（Ⅰ）求数列{a n}和{b n}的通项公式；（Ⅱ）求数列{b n}的前n项和T n．19．如图，在三棱柱ABC﹣A1B1C1中，AA1⊥平面ABC，∠ACB＝90°，AC＝CB＝CC1＝2，M，N 分别是AB，A1C的中点．（Ⅰ）求证：MN∥平面BCC1B1；（Ⅱ）求点M到平面B1NC的距离．20．纪念币是一个国家为纪念国际或本国的政治、历史，文化等方面的重大事件、杰出人物、名胜古迹、珍稀动植物、体育赛事等而发行的法定货币．我国在1984年首次发行纪念币，目前已发行了115套纪念币，这些纪念币深受邮币爱好者的喜爱与收藏.2019年发行的第115套纪念币“双遗产之泰山币”是目前为止发行的第一套异形币，因为这套纪念币的多种特质，更加受到爱好者追捧．某机构为调查我国公民对纪念币的喜爱态度，随机选了某城市某小区的50位居民调查，调查结果统计如下：（Ⅰ）根据已有数据，把表格数据填写完整，判断能否在犯错误的概率不超过1%的前提下认为不同年龄与纪念币的喜爱无关？（Ⅱ）已知在被调查的年龄不大于40岁的喜爱者中有5名男性，其中3位是学生，现从这5名男性中随机抽取2人，求至多有1位学生的概率．附：，n＝a+b+c+d．21．设A，B为抛物线C：x2＝2py（p＞0）上不同两点，抛物线C的焦点到其准线的距离为4，A与B的横坐标之和为8．（Ⅰ）求直线AB的斜率；（Ⅱ）若设M为抛物线C上一点，C在点M处的切线与直线AB平行，过M点作直线l与曲线C相交于点M，Q，与y轴交于点P，且满足，求△OPQ的面积．22．已知函数，f'（x）是f（x）的导函数，g（x）＝f'（x）+1．（Ⅰ）当m＝2时，判断函数g（x）在（0，π）上是否存在零点，并说明理由；（Ⅱ）若f（x）在（0，π）上存在最小值，求m的取值范围．参考答案一、选择题（本大题共12小题，每小题5分，在每小题所给的四个选项中只有一项符合题意）1．已知集合A＝{1，2，3}，B＝{x|（x+1）（x﹣2）＜0，x∈Z}，则A∩B＝（）A．{1} B．{0，1} C．{0，1，2，3} D．{﹣1，0，1，2，3}解：∵A＝{1，2，3}，B＝{x|﹣1＜x＜2，x∈Z}＝{0，1}，∴A∩B＝{1}．故选：A．2．在复平面内，复数（i为虚数单位）对应的点位于（）A．第一象限B．第二象限C．第三象限D．第四象限解：＝＝，其对应的点（）在第四象限故选：D．3．在区间[0，4]上随机地取一个数x，则事件“0≤log2（x﹣1）≤1”发生的概率为（）A．B．C．D．解：在区间[0，4]的长度为4；0≤log2（x﹣1）≤1，解之得[2，3]，长度为1；故在区间[0，4]上随机地取一个数x，则事件“0≤log2（x﹣1）≤1”发生的概率为．故选：B．4．已知平面α，直线m，n，若n⊂α，则“m⊥n”是“m⊥α”的（）A．充分不必要条件B．充分必要条件C．必要不充分条件D．既不充分也不必要条件解：由n⊂α，m⊥n，不一定得到m⊥α；反之，由n⊂α，m⊥α，可得m⊥n．∴若n⊂α，则“m⊥n”是“m⊥α”的必要不充分条件．故选：C．5．函数的部分图象是（）A．B．C．D．解：f（﹣x）＝＝﹣f（x），则函数f（x）是奇函数，图象关于原点对称，排除A．当x＝π时，f（π）＝＝＜0，排除C，且﹣＜f（π）＜0，排除D，故选：B．6．中国古代数学著作《孙子算经》中有这样一道算术题：“今有物不知其数，三三数之余二，五五数之余三，问物几何？”人们把此类题目称为“中国剩余定理”，若正整数量N除以正整数m后的余数为n，则记为N≡n（bmodm），例如11≡2（bmod3），现将该问题以程序框图的算法给出，我行该程序框图，则输出的结果等于（）A．35 B．36 C．37 D．38解：该程序框图的作用是求被3除后的余数为2，被5除后的余数为3的数；在所给的选项中，满足被3除后的余数为2，被5除后的余数为3的数是38．故选：D．7．已知双曲线C的中心在坐标原点且焦点在坐标轴上，C的一个焦点与抛物线的焦点F重合，且点F到双曲线C的渐近线的距离等于2，则双曲线C的方程为（）A．B．C．D．解：抛物线即x2＝16y的焦点F（0，4），可设双曲线的方程为﹣＝1（a，b＞0），可得c＝4，即a2+b2＝16，由点F（0，c）到双曲线C的渐近线by±ax＝0的距离等于2，可得d＝＝b＝2，解得a＝2，则双曲线的方程为﹣＝1，故选：A．8．已知定义在R上的偶函数f（x）满足，当x∈[0，+∞）时，，，b＝f（20.3），c＝f（0.42），则下列不等式成立的是（）A．a＜b＜c B．c＜b＜a C．c＜a＜b D．b＜c＜a解：∵∀x1，x2≥0，且x1≠x2，，∴f（x）在[0，+∞）上单调递增，根据偶函数的对称性可知，f（x）在（﹣∞，0）上单调递减，距离对称轴越远，函数值越大，∵＝f（﹣2）＝f（2），b＝f（20.3），c＝f（0.42）＝f（0.16），∵1＜20.3＜2，∴a＞b＞c．故选：B．9．已知函数，当|f（x1）﹣f（x2）|＝4时，|x1﹣x2|最小值为，把函数f（x）的图象沿x轴向右平移个单位，得到函数g（x）的图象，关于函数g（x），下列说法正确的是（）A．在上是增函数B．其图象关于直线对称C．在区间上的值域为[﹣2，﹣1]D．函数g（x）是奇函数解：已知函数＝2sin（ωx+），当|f（x1）﹣f（x2）|＝4时，|x1﹣x2|最小值为＝•，∴ω＝4，f（x）＝2sin （4x+）．把函数f（x）的图象沿x轴向右平移个单位，得到函数g（x）＝2sin（4x﹣+）＝﹣2cos4x的图象．在上，4x∈[π，2π]，g（x）是减函数，故排除A；当x＝时，g（x）＝1，不是最值，故g（x）的图象不关于直线对称；故排除B；在区间上，4x∈[﹣，]，cos4x∈[，1]g（x）∈[﹣2，﹣1]，故C正确；由于g（x）＝﹣2cos4x为偶函数，故排除D，故选：C．10．设等差数列{a n}的公差不为0，其前n项和为S n，若（a3﹣2）3+sin（a3﹣2）＝2020，（a2018﹣2）3+sin（a2018﹣2）＝﹣2020，则S2020＝（）A．0 B．﹣2020 C．2020 D．4040解：等差数列{a n}的公差不为0，且（a3﹣2）3+sin（a3﹣2）＝2020，（a2018﹣2）3+sin （a2018﹣2）＝﹣2020，令f（x）＝x3+sin x，则f（﹣x）＝﹣f（x）即f（﹣x）+f（x）＝0，∵（a3﹣2）3+sin（a3﹣2）＝2020，（a2018﹣2）3+sin（a2018﹣2）＝﹣2020，两式相加可得，（a3﹣2）3+sin（a3﹣2）+（a2018﹣2）3+sin（a2018﹣2）＝0，∴（a3﹣2）+（a2018﹣2）＝0，∴a3+a2018＝4，则S2020＝＝1010（a3+a2018）＝4040．故选：D．11．已知正方形ABCD的边长为2，动点P满足，且，则2x+y的最大值为（）A．B．C．D．解：如图建立平面直角坐标系，A（0，0），B（2，0），D（0，2），设P（m，n），因为，所以（m，n）＝（2x，0）+（0，2y），即（m，n）＝（2x，2y），m＝2x，n＝2y，因为又因为动点P满足，所以，，即（x﹣1）2+y2，设z＝2x+y，当该直线与圆（x﹣1）2+y2＝相切时会取得z最大值，，z＝2±，所以z max＝2+，即2x+y的最大值为2+，故选：B．12．在三棱锥A﹣BCD中，平面ABC⊥平面ADC，AD⊥AC，AD＝AC，，若此三棱锥的外接球表面积为28π，则三棱锥A﹣BCD体积的最大值为（）A．7 B．12 C．6 D．解：根据题意，设三棱锥A﹣BCD外接球的半径为R，三棱锥的外接球球心为O，△ABC的外心为O1，△ABC的外接圆半径为r，取DC的中点为O2，过O2作O2E⊥AC，则OO1⊥平面ABC，OO2⊥平面ADC，如图，连结OA，O1A，则O1A＝r，设AD＝AC＝b，则OO1＝O2E＝b，由S＝4πR2＝28π，解得R＝，在△ABC中，由正弦正理得2r＝，∴2r＝，解得b＝，在Rt△OAO1中，7＝r2+（）2，解得r＝2，b＝2，∴AC＝2，若三棱锥A﹣BCD的体积最大，则只需△ABC的面积最大，在△ABC中，AC2＝AB2+BC2﹣2•AB•BC•cos∠ABC，∴12＝AB2+BC2﹣AB•BC≥2AB•BC﹣AB•BC，解得AB•BC≤12，∴≤＝3，∴三棱锥A﹣BCD的体积的最大值：＝＝6．故选：C．二、填空题（本题共4小题，每小题5分，共20分）13．已知非零向量、满足，，且，则与的夹角为．解：，，且，所以（+）•＝0，所以•＝﹣＝﹣1，所以cosθ＝＝＝﹣；又θ∈[0，π]，所以θ＝；即与的夹角为．故答案为：．14．已知，2sin（2α）＝cos（2α）+1，则＝ 3 ．解：由半角公式，则＝＝，由2sin（2α）＝cos（2α）+1＝2，化简得5cos22α+2cos2α﹣3＝0，故或者cos2α＝﹣1（舍弃），由2sin2α＝cos2α+1＝，sin2α＝，所以＝，故答案为：315．已知椭圆的左右焦点分别是F1，F2，以F2为圆心的圆过坐标原点，过点F1作直线l与圆F2相切，直线l与椭圆相交于点P、Q且PF2⊥x轴，则椭圆的离心率为．解：以F2为圆心的圆过坐标原点，可得圆F2的圆心为（c，0），半径为c，PF2⊥x轴，可设P（c，m），m＞0，由+＝1，解得m＝|PF2|＝，在直角三角形PF1F2中，|PF1|+|PF2|＝2a，可得|PF1|＝2a﹣＝，由三角形的面积公式可得••2c＝c•，化为2a2＝3b2，则e＝＝＝＝．故答案为：．16．已知函数f（x）为奇函数，g（x）为偶函数，对于任意x∈R均有f（x）+2g（x）＝mx﹣4，若f（x）﹣3﹣lnx≥0对任意x∈（0，+∞）都成立，则实数m的取值范围是[e2，+∞）．解：∵f（x）为奇函数，g（x）为偶函数，对于任意x∈R均有f（x）+2g（x）＝mx﹣4，①∴f（﹣x）+2g（﹣x）＝﹣mx﹣4，即﹣f（x）+2g（x）＝﹣mx﹣4，②由①②得2f（x）＝2mx，得f（x）＝mx，若f（x）﹣3﹣lnx≥0对任意x∈（0，+∞）都成立即若mx﹣3﹣lnx≥0对任意x∈（0，+∞）都成立则mx≥3+lnx，m≥，设h（x）＝，则h′（x）＝，由h′（x）＞0得﹣2﹣lnx＞0，得lnx＜﹣2，得0＜x＜，此时函数为增函数，由h′（x）＜0得﹣2﹣lnx＜0，得lnx＞﹣2，得x＞，此时函数为减函数，即当x＝，时，函数h（x）取得极大值，同时也是最大值，最大值为h（）＝＝＝e2，即m≥e2，则实数m的取值范围是[e2，+∞），故答案为：[e2，+∞）三、解答题（本大题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤.）17．已知△ABC的内角A，B，C所对的边分别为a，b，c，且10b2cos B＝6ab cos C+3（b2+c2﹣a2）．（Ⅰ）求cos B；（Ⅱ）设，，求△ABC的周长．解：（Ⅰ）∵10b2cos B＝6ab cos C+3（b2+c2﹣a2）＝，∴．（Ⅱ）∵，∴ac cos B＝3，∴ac＝5，∵b2＝a2+c2﹣2ac cos B，，∴，∴a+c＝6，∴△ABC的周长．18．已知数列{a n}的前n项和S n＝n2+n，等比数列{b n}的公比q＞1，且b3+b4+b5＝28，b4+2是b3，b5的等差中项．（Ⅰ）求数列{a n}和{b n}的通项公式；（Ⅱ）求数列{b n}的前n项和T n．解：（Ⅰ）∵，∴n≥2时，a n＝S n﹣S n﹣1＝2n，又n＝1时，a1＝S1＝2满足上式，∴a n＝2n；∵b4+2是b3，b5的等差中项，可得b3+b5＝2（b4+2），又等比数列{b n}的公比q＞1，且b3+b4+b5＝28，∴b4＝8，b3+b5＝20，又∵＝64，q＞1，解得b3＝4，b5＝16，∴q＝2，；（Ⅱ）∵＝，∴＝．19．如图，在三棱柱ABC﹣A1B1C1中，AA1⊥平面ABC，∠ACB＝90°，AC＝CB＝CC1＝2，M，N 分别是AB，A1C的中点．（Ⅰ）求证：MN∥平面BCC1B1；（Ⅱ）求点M到平面B1NC的距离．解：（Ⅰ）连接AC1，BC1交B1C于点O，∵AA1⊥平面ABC且AC＝CC1＝2，∴四边形ACC1A1为正方形，∴AC1过点N，且点N为AC1中点，又∵M为AB的中点，∴MN∥BC1，且，又∵MN不在平面BCC1B1内，BC1在平面BCC1B1内，∴MN∥面BCC1B1．（Ⅱ）由（1）可得四边形MBON为平行四边形，∴可证BM∥平面B1NC，∴点M到平面B1NC的距离等于点B到平面B1NC的距离，设为d，∵，N为A1C中点，∴，由，得，又∵，∴．20．纪念币是一个国家为纪念国际或本国的政治、历史，文化等方面的重大事件、杰出人物、名胜古迹、珍稀动植物、体育赛事等而发行的法定货币．我国在1984年首次发行纪念币，目前已发行了115套纪念币，这些纪念币深受邮币爱好者的喜爱与收藏.2019年发行的第115套纪念币“双遗产之泰山币”是目前为止发行的第一套异形币，因为这套纪念币的多种特质，更加受到爱好者追捧．某机构为调查我国公民对纪念币的喜爱态度，随机选了某城市某小区的50位居民调查，调查结果统计如下：（Ⅰ）根据已有数据，把表格数据填写完整，判断能否在犯错误的概率不超过1%的前提下认为不同年龄与纪念币的喜爱无关？（Ⅱ）已知在被调查的年龄不大于40岁的喜爱者中有5名男性，其中3位是学生，现从这5名男性中随机抽取2人，求至多有1位学生的概率．附：，n＝a+b+c+d．解：（1）根据题意，设表中数据为则有e+22＝50，则e＝28；24+d＝50，则d＝26，a+20＝e＝28，则a＝8，a+b＝24，则b＝16，b+c＝22，则c＝6；故列联表为：则有≈9.623＞6.635．故能在犯错误的概率不超过1%的条件下认为不同年龄与纪念币的喜爱无关．（2）根据题意，记不大于40岁的5位喜爱者中的3位学生记为a，b，c，非学生记为A，B，则从5人中任取2人，共有（a，b），（a，c），（a，A），（a，B），（b，c），（b，A），（b，B），（c，A），（c，B），（A，B）10种结果．其中至多有1位学生的有7种，∴至多有1位学生的概率．21．设A，B为抛物线C：x2＝2py（p＞0）上不同两点，抛物线C的焦点到其准线的距离为4，A与B的横坐标之和为8．（Ⅰ）求直线AB的斜率；（Ⅱ）若设M为抛物线C上一点，C在点M处的切线与直线AB平行，过M点作直线l与曲线C相交于点M，Q，与y轴交于点P，且满足，求△OPQ的面积．解：（Ⅰ）由条件可知：p＝4，∴x2＝8y．设点A（x1，y1），B（x2，y2），∴，∴．（Ⅱ）设M（x0，y0），，∴，∴x0＝4，∴y0＝2．设点P（0，y3），Q（x4，y4），直线l为：y＝k（x﹣4）+2，∴，∴x2﹣8kx+32k﹣16＝0，∴x0+x4＝8k，x0x4＝32k﹣16．∵，∴﹣x0＝2x4，∴x4＝﹣2，，∴，∴．22．已知函数，f'（x）是f（x）的导函数，g（x）＝f'（x）+1．（Ⅰ）当m＝2时，判断函数g（x）在（0，π）上是否存在零点，并说明理由；（Ⅱ）若f（x）在（0，π）上存在最小值，求m的取值范围．解：（Ⅰ）m＝2时，g（x）＝x﹣2sin x+1．令g'（x）＝0，即，x∈（0，π），得，当x变化时，g'（x），g（x）变化如下：∴函数g（x）的单调递减区间为，单调递增区间为．∴g（x）的极小值为．∴函数g（x）在（0，π）上不存在零点．（Ⅱ）因为，所以f'（x）＝x﹣m sin x，令h（x）＝f'（x）＝x﹣m sin x，则h'（x）＝1﹣m cos x．①当m＜1时，1﹣m cos x＞0，即h'（x）＞0，∴h（x）＝f'（x）＝x﹣m sin x在（0，π）单调递增，∴x∈（0，π）时，h（x）＞h（0）＝0，∴f（x）在（0，π）单调递增，∴f（x）在（0，π）不存在最小值，②当m＞1时，，所以h'（x）＝1﹣m cos x＝0，即在（0，π）内有唯一解x0，当x∈（0，x0）时，h'（x）＜0，当x∈（x0，π）时，h'（x）＞0，所以h（x）在（0，x0）上单调递减，在（x0，π）上单调递增．所以h（x0）＜h（0）＝0，又因为h（π）＝π＞0，所以h（x）＝x﹣m sin x在（x0，π）⊆（0，π）内有唯一零点x1，当x∈（0，x1）时，h（x）＜0即g'（x）＜0，当x∈（x1，π）时，h（x）＞0即g'（x）＞0，所以g（x）在（0，x1）上单调递减，在（x1，π）上单调递增．所以函数g（x）在x＝x1处取得最小值，即m＞1时，函数g（x）在（0，π）上存在最小值．。

安徽省示范高中皖北协作区第22届高三联考

安徽省示范高中皖北协作区第22届高三联考语文考生注意：1.答题前，考生务必将自己的姓名、考生号填写在试卷和答题卡上，并将考生号条形码粘贴在答题卡上的指定位置。

2.回答选择题时，选出每小题答案后，用铅笔把答题卡对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其他答案标号。

回答非选择题时，将答案写在答题卡上。

写在本试卷上无效。

3.考试结束后，将本试卷和答题卡一并交回。

一、现代文阅读（36分）（一）论述类文本阅读（本题共3小题,9分）阅读下面的文字，完成1 ~3题。

截至目前,我国共公布了五批传统村落6819个。

中国传统村落已成为世界上规模最大、仍然鲜活的文化遗产。

在我国，传统村落分布相对集中，形成了“一心、三片、多组团、多特色”分布特点。

这些种类繁多、生动多彩的传统村落，形成了人类文化多样性的重要支撑，它们既是世界农耕文明的源头和我国农耕文明最集中的反映，也是中华民族复兴的源泉所在。

在城乡关系重构的今天，传统村落已成为传统文化传承与重塑的重要载体和诗意栖居的家园。

当前，传统村落面临的紧迫任务依然是严格保护。

经过很长一段时期的努力，我们遏制了传统村落的自然消亡，但是空心化、建设性破坏、资金不足等依然是传统村落保护面临的主要挑战。

对传统村落进行严格保护，一方面需要开展传统村落谱系研究，充分利用现代信息技术实施精细化记录和管理，把传统村落中有价值的内容进行进一步明确。

另一方面则要健全传统村落保护体系，分级分类，精准保护利用。

对于有一定价值的传统村落，要保护好传统风貌，充分挖掘特色，适度恢复和还原，促进传统建筑的改善利用。

让传统村落走向现代，离不开完善基础设施，提升人居环境。

当前历史村镇最突出的矛盾之一就是居住者对现代生活的要求与历史文化的冲突。

对此，我们要重点研究和突破，进一步改善传统村落的基础设施和人居环境，包括加强公共服务，完善公共服务设施、配设小型综合体等。

通过优化调整适宜的产业，促进传统村落实现农业与二、三产业融合发展,进一步发展生态农业、特色农业。

2020届安徽省示范高中皖北协作区高三联考数学(文)试题

绝密★启用前2020年“安徽省示范高中皖北协作区”第22届高三联考数学（文科）考生注意：1.答题前，考生务必将自已的姓名、考生号填写在试卷和答题卡上，并将考生号条形码粘贴在答题卡上的指定位置.2.回答选择题时，选出每小题答案后，用铅笔把答题卡对应题目的答案标号涂黑.如需改动，用橡皮擦干净后，再选涂其他答案标号.回答非选择题时，将答案写在答题卡上，写在本试卷上无效.3.考试结束后，将本试卷和答题卡一并交回。

一、选择题：本题共12小题，每小题5分，共60分在每小题给出的四个选项中，只有一项是符合题目要求的.1，已知复数z 满足i i z +=2，则在复平面内z 对应的点位于（） A.第一象限 B.第二象限 C.第三象限 D.第四象限2.已知集合{}⎭⎬⎫⎩⎨⎧<=<+-=110342x x B x x x A ，，则A ∩B=（） A. {}3<x x B.{}1>x x C.{}31<<x x D.{}31><x x x 或 3．设函数⎩⎨⎧>≤+-=,0,2,0,1)(x x x x f x 则))2((-f f =（）， A ．8- B ．6- C ．6 D ．84．函数x e e x f x x cos 11)(+-=在[ -π，π]上的图像大致为（）5．双曲线C ：)0,0(12222>>=-b a b y a x 的一条渐近线的倾斜角为60°，则C 的离心率为（） A ．23 B ．2 C ．3 D ．32 6巳知角a 的顶点与原点O 重合，始边与x 物的非负半轴重合，它的终边过点)4,3(-P ，则)4tan(απ+=（） A ．71- B ．71 C ．7- D ．7 7．如图是汉代数学家赵爽在注解《周髀算经》时绘制的“赵爽弦图”，该图是由四个全等的直角三角形和中间的一个小正方形拼成的一个大正方形，这是我国对勾股定理的最早证明.记直角三角形中较小的锐角为θ，且2572cos =θ.若在大正方形内随机取一点，则此点取自小正方形的概率是（）A.251B.254C.51D.53 8．已知非零向量b a ,满足b a 3=，且)3()(b a b a +⊥+，则a 与b 的夹角为（）A.65πB.32π c.3π D.6π 9．已知F 是抛物线C ：x y 42=的焦点，A ，B 为抛物线C 上两点，且6=+BF AF ．则线段AB 的中点到y 轴的距离为（）A ．3B ．2C ．25 D ．23 10．已知212ln 21sin π===c b a ，，，则（） A ．a>b>c B ．b>c>a C ．c>a>b D ．c>b>a11．已知某三棱锥的三视图如图所示，则该三棱锥的体积为（）A.322B.938 C.38 D.412．关于曲线12121=+y x C ：，有下述四个结论：①曲线C 是轴对称图形；成曲线C 关于点)41,41(P 中心对称： ③曲线C 上的点到坐标原点的距离最小值是22： ④曲线C 与坐标轴围成的图形的面积不大于21，其中所有正确结论的编号是 A ．①③ B ．①④ C ．①③④ D ．②③④二、填空题：本题共4小題，每小题5分，共20分13．已知数据5,4,2,a 的平均数是3，则该组数据的方差为 .14．△ABC 的内角A ，B ，C 的对边分别a ，b ，c ．已知b c B a -=2cos 2，则A= .15．已知正三棱柱111C B A ABC -的六个顶点都在球O 的球面上，4,21==AA AB ，则求O 的表面积为．16．函数])2,0[(cos sin 23sin )(2π∈-=x x x x x f 的最大值为 .三、解答题：共70分.解答应写出文字说明，证明过程或演算步骤.第17~21题为必考题，每个试题考生都必须作答，第22，23题为选考题，考生根据要求作答.(一)必考题：共60分17．（12分）记n S 为等差数列{}n a 的前n 项和．巳知351253==S S ，．（Ⅰ）求{}n a 的通项公式；（Ⅱ）设n an b 2=．求数列{}n b 的前n 项和n T .18．（12分）为了贯彻落实党中央对新冠肺炎疫情防控工作的部署和要求，坚决防范疫情向校园蔓延，切实保障广大师生身体健康和生命的安全，教育主管部门决定通过电视频道、网络平台等多种方式实施线上教育教学工作．某教育机构为了了解人们对其数学网课授课方式的满意度，从经济不发达的A 城市和经济发达的B 城市分别随机调查了20个用户，得到了一个用户满意度评分的样本，并绘制出茎叶图如下：若评分不低于80分，则认为该用户对此教育机构授课方式“认可”，否则认为该用户对此教育机构授课方式“不认可”.（Ⅰ）请根据此样本完成下列2x2列联表，并据此列联表分析，能否有95%的把握认为城市经济状况与该市的用户认可该教育机构授课方式有关？（Ⅱ）在样本A ，B 两个城市对此教育机构授课方式“认可”的用户中按分层抽样的方法抽取6人，若在此6人中任选2人参加数学竞赛，求A 城市中至少有1人参加的概率. 参考公式：))()()(()(22d b c a d c b a bc ad n K ++++-=，其中d c b a n +++=. 参考数据：I9．（12分）图1是矩形ABCD ，AB =2， BC =1，M 为CD 的中点，将△AMD 沿AM 翻折，得到四梭锥D 一ABCM ，如图2．（Ⅰ）若点N 为BD 的中点，求证：CN//平面DAM ；（Ⅱ）若AD ⊥BM ．求点A 到平面BCD 的距离．图1 图220．（12分）已知椭圆)0,0(12222>>=+b a b y a x C ：经过点)23,1(A ，且离心率为21，过其右焦点F 的直线l 交椭圆C 于M ．N 两点，交y 轴于E 点．若1EM MF λ=u u u u r u u u r 2,EN NF λ=u u u r u u u r（Ⅰ）求椭圆C 的标准方程；（Ⅱ）试判断21λλ+是否是定值．若是定值，求出该定值；若不是定值，请说明理由．21．（12分）已知函数)(ln )(2R a x a x x f ∈-=．（Ⅰ）讨论函数f （x ）的单调性：（Ⅱ）若a>0，直线y=g （x ）为函数f （x ）图像的一条切线，求证：g （1）≤1．（二）选考题：共10分请考生在第22，23题中任选一题作答，如果多做，则按所做的第一题计分，22.[选修4-4；坐标系与参数方程]（10分）平面直角坐标系xOy 中，曲线1C 的参数方程为⎪⎪⎩⎪⎪⎨⎧+-=++-=λλλλ121131y x (λ为参数，且1-≠λ).以坐标原点O 为极点，x 轴的正半轴为极轴建立极坐标系，曲线2C 的极坐标方程为032cos 122=++θρρ.（Ⅰ）求曲线1C 的普通方程和曲线2C 的直角坐标方程；（Ⅱ）已知点P 的极坐标为)4,22(π，Q 为曲线2C 上的动点，求PQ 的中点M 到曲线1C 的距离的最大值.23.[选修4-5：不等式选讲]（10分）) 已知函数)0(5)(>+--=m m x x x f 的最大值为8.（Ⅰ）求m 的值；（Ⅱ）若实数a 满足0)()1(>+-a f a f ，求a 的取值范围.。

2020届安徽高三联考试题

2020年“安徽省示范高中皖北协作区”第22届高三联考英语第二部分阅读理解(共两节,满分40分) AStart a summer company : studentsHow it worksThrough a program called Summer Company, you can get:* start-up money to kick-off a new summer business* advice and guide from local business leaders to help get the business up and runningLearning how to run your own student business is one of the best summer jobs you can have. You get to beyour own boss while learning what it takes to manage a business. Sales ，marketing, bookkeeping, customer relationship management and networking are just a few of the highly useful sills you’' Who is eligible( 具备条件的)You could be eligible, if you :* go to high school, college or university* live in Ontario* are a Canadian citizen or permanent resident* are between 15-29 years old( if under 18: a parent or guardian must sign the agreement for the applicant)* are not already running a business* are not working at another job or going to school for more than 12 hours a week during the program* are returning to school after the program endsYou cannot apply again if you have received a Summer Company grant in the past.Award amountMaximum award: $3 ,000.Successful Summer Company applicants get: .* up to $1,500 to help with start-up costs* up to $1,500 when you successfully complete the program requirements and hoursHow to applyThe program for 2020 is open through May 19. Here are the steps to apply:* Check to see if you’re eligible for the program* Complete the online application inquiry* Select your local program provider* Assign yourself a password* Submit your application inquiry21. The following skills can be developed through the program except_____A. salesB. marketingC. relationshipD. networking22. If you want to start a summer company, which of the following conditions is not suitable?A. You are between 18-29 years old.B. You are not already running a business.C. You are a Canadian citizen or permanent resident.D. You will attend school for over 12 hours a week during the program.23. When can you apply for the program?A. May 18, 2020.B. May 20, 2020.C. June 18, 2020. .D. June 20, 2020.BKeeping your teenager out of the social media world is impossible. Whether we like it or not, our kidsare growing up in a digital era- -and although that creates major opportunities, it also comes with some pretty big risks. We saw this firsthand when we asked a group of tweens and teens to give up their phonesand social media for a week; it was as though we' d asked them to part with a limb.A recent study of more than 10 ,000 six- to twelve-grade girls carried out by a nonprofit organizationRuling Our Experiences found that high school girls spend an average of six hours a day on social media.And the effect of too much logged-on time is clear. The study found kids who spend eight hours or more on technology per day are five times more likely to be sad or depressed. Adding to the pressure is that2 out of 3 high school girls report being asked to send a revealing photo to another person, and most of them report that they do send sexual texts and photos to each other.Another study, carried out by Common Sense Media, found that girls use social media more than boys and are also more likely to experience negative consequences. Most of the girls investigated admitted that content posted online often makes them worry about their appearance or social status, while just a quarter ofInternet came to a similar the boys said the same. An earlier study from the Pew Research Center’sconclusion: A third of 12- to 13-year-old girls who used social media believed their peers were mostly unkind to each other online , while only 9 percent of the boys agreed.rns about boys and the impact of digital Of course, these di fferences don' t mean we shouldn’t have conceoverload or online bulling. In fact, other studies have shown that boys and girls can be equally damaged by social media. The most important thing is for tens to feel safe, online and in the real world alike.24. What is the second paragraph mainly about?A. The pressure of the high school girls logging-on.B. The influence of too much logged-on time on high school girls.C. Too much time spent on social media for high school girls.D. The increasing population of the high school girls logging-on.in paragraph 2?25. Which of the following can replace the underlined word “revealing”A. Exposed.B. Interesting.C. Funny.D. Romantic.26. Why are the girls more likely to experience negative effect online than boys?A. Because the girls' social status is low.B. Because the girls are mostly unkind to each other.C. Because the girls use social media more than boys.D. Because the girls pay more attention to their appearance.27. What can be inferred from the passage?A. Parents should keep teens out of the social media.B. Parents keep teens feel safe online and in the real life.C. It is time to worry about your teens and social media.D. Boys and girls can be equally damaged by social media.CIt often seems that some people possess superhuman eating powers , allowing them to eat an entire pizza while remaining slim. Others only eat a slice but gain five pounds. Now one doctor says there' s evidencethat genetics could be behind some of these differences. Regardless of how much you eat, your weight maybe out of control.Vann Bennett, a biochemist at Duke University and his team led a new study and discovered why this happens. They engineered mice to have several common modifications of the gene found in humans. Theyobserved that mice who had mutations of ankyrin-B(锚蛋白B的变异) took more glucose(葡萄糖) into their fat ell, which in turn made more fat. Typically, the cell membrane( 膜) acts as a barrier to prevent glucose from entering these cells ; the change k ept the gate open. The change may serve a useful purpose.obably this is not always a bad thing," Bennett told Newsweek. “It could help people survive hunger in the past. But today we have somuch food that it probably is a bad thing. ”Dieters have long been told to watch their calories and exercise more, but this new finding suggests thata common approach doesn't work for everyone. Our metabolism( 新陈代谢) naturally slows with age, making it harder to maintain the weight of our 30-year-old selves when we' re 50. Now add an uncontrollable ankyrin-B gene, and it may seem impossible to stay slim.The mice in the study gained more weight when on high-fat diets. Despite being studied in mice, the researchers believe further research on this gene could potentially create a field of customized diets and health plans based on genetics. Bennett imagines such assessments being performed at birth one day. For now, disappointed dieters can take comfort with one saying: It's not you, it's your genes.28. How did a mouse gain weight with mutations of ankyrin-B?A. The ankyrin-B could make the mouse eat more.B. The fat cells in the mouse would take more glucose to create more fat.C. The glucose could function as a barrier to prevent the fat from reducing.D. The cell membrane in the mouse could open the gate of fat into the mouse.29. What was the effect of the change in the past in paragraph 2?A. It could help people to avoid fat food.B. It could help people to absorb more nutrition.C. It could help people to get through the starvation.D. It could help people to enjoy more delicious snacks.30. Why is it more difficult to stay slim when we are older?A. Because we all lack exercise.B. Because we have ankyrin-B genes.C. Because we watch our calories less.D. Because our metabolism weakens.31. What can be expected from further research?A. It may help people to maintain the weight.B. It may provide more comfort for the depressed dieters.gene arrangement.C. It may change many new-born babies’D. It may present human beings with a series of health plans.DBack in 1975，economists planned rising life expectancy( 预期寿命) against countries ’wealth，and concluded that wealth itself increases longevity. It seemed self- evident: everything people need to be healthy--from food to medical care- costs money.But it soon proved that the data didn't always fit that theory. Economic booms didn ' t always mean longer lives. In addition，for reasons that weren’t clear， a given gain in gross domestic product ( GDP ) caused increasingly higher gains in life expectancy over time, as though it was becoming cheaper to add years oflife. Moreover, in the 1980s researchers found gains in learning were associated with greater increases in life expectancy than gains in wealth were. Finally, the more educated people in any country tend to live longerthan their less educated fellow citizens. But such people also tend to be wealthier, so it has been difficult to make out which factor is increasing lifespan.Wolfgang Lutz and his colleagues have now done that by collecting average data on GDP per person，lifespan, and years of education from 174 countries，dating from 1970 to 2010. They found that, just as in1975，wealth associated with longevity. But the association between longevity and years of schooling was closer, with a direct relationship that did not change over time, the way wealth does.Lutz argues that because schooling happens many years before a person has attained their life expectancy,this association reflects cause : better education drives longer life. It also leads to more wealth, which is whywealth and longevity are also associated. But what is important, says Lutz, is that wealth does not seem to be longevity, as experts thought- in fact, education is driving both of them.He thinks this is because education permanently improves a person’s cognitive abilities ,allowing better planning and self-control throughout the rest of their life. This idea is supported by the fact that people whoare more intelligent appear to live longer.32. Which of the following best describes economists ’conclusion in 1975?A. Lifespan could be increased by wealth.B. Economic growth didn’t always mean longer life.C. Education influenced longevity more than wealth did.D. A given growth in GDP caused higher gains in longevity.33. What did Wolfgang Lutz and his colleagues find?A. Wealth and longevity did not have any association.B. Longevity and education were more closely associated.C. Differences in wealth predicted differences in longevity.D. Relationship between education and longevity changed over time.34. What part does education play permanently according to Lutz?A. It enables people to have better planning and self-control.B. It always leads to a longer but not necessarily richer life.C. It improves people’s imaginative and innovative abilities.D. It helps people acquire time-managing and learning habits.35. Which of the following is the best title for this passage?A. Wealth influences longevity.B. Education influences longevity.C. Wealth has nothing to do with longevity.D. The relationship between education and wealth.第二节(共5小题;每小题2分,满分10分)The first time I went to a playground in Berlin, I was surprised. All the German parents were huddledtogether, drinking coffee, not paying attention to their children who were hanging off a wooden dragon 20feet above a sand pit. Contrary to stereotypes(模式化观念)，most German parents I’ve met are the oppositehey were trusting them. Here areof strict. 36 . Those parents at the park weren’t ignoring their children; ta few surprising things Berlin ’s parents do:Don't push reading. Berlin ’s kindergartens don’t emphasize academics. In fact, teachers and o discouraged me from teaching my children to read._ 37 . But even in first grade, academics aren’t pushedvery hard. Our grade school provides a half-day of instruction interrupted by two outdoor breaks.38 . A note came home from school along with my excited second grader. They were doing a projecton fire. Would I let her light candles and perform experiments with. matches? Together we lit candles andburned things, safely. It was brilliant.Let children go almost everywhere alone. Most grade school kids walk without their parents to schooland around their neighborhoods. Some even take the subway alone._ 39 of course, but they usually focuson traffic.，not abductions(绑架).Take the kids outside every day. According to a German saying, “There is no such thing as bad weather,time is promoted in the schools._ 40 No matter how coldonly unsuitable clothing.”The value of outsideand grey it gets, and in Berlin it gets pretty cold, parents still bundle their kids up and take them to the park,or send them out on their own.A. Encourage kids to play with fireB. Inspire children to go out for leisureC. German parents are concerned about safetyD. It's also obvious on Berlin ' s numerous playgroundsE. Kindergarten was a time for play and social learningF. They place a high value on independence and responsibilityG.I was told it was something special that the kids learn together when they start grade school第三部分语言知识运用(共两节,满分45分)第一节(共20小题;每小题 1.5分,满分30分)阅读下面短文,从短文后各题所给的A、B、C和D四个选项中,选出可以填人空白处的最佳选项,并在答题卡.上将该项涂黑。

2020 皖北协作区联考

2020年“安徽省示范高中皖北协作区”第22届高三联考文科综合·地理卷一、选择题（每小题4分，共44分）皖北某县是我国著名的水果之乡。

众多大型水果加工企业利用该县出产的优质黄桃，配以白砂糖,生产出的糖水黄桃罐头酸甜适中，深受国内外市场欢迎。

近年来，随着电商的兴起,该县农户纯手工制作的糖水黄桃罐头更是在网上热销。

据此完成1 ~3题。

1.该县吸引众多大型水果加工企业集聚的主要原因是A.劳动力丰富、廉价B.土地充足、价格低C.水果产量大、品质优D.招商政策优惠2.从配料添加角度考虑，下列省区中农业生产对该县的黄桃罐头加工业影响最大的是A.广西B.江西C.山西D.陕西3.该县农户纯手工制作的黄桃罐头若要长期保持在网上热销，应当主要依靠A.产量大B.价格低C.质量优D.包装美图1示意城市化发展过程。

X轴为时间轴，表示社会发展的不同时期。

Y轴为城市人口迁移差额率(城市迁入人口与迁出人口的差额占城市总人口的比重)。

图中a、b、c、d分别表示城市化的四个不同阶段,其中a、b、c为城市化的一个周期。

据此完成4~6题。

4.图中e表示A.集中城市化B.郊区城市化C.逆城市化D.再城市化5.据图分析下列说法正确的是A.合肥市处于图中城市化d阶段B.目前发达国家处于图中城市化b阶段C.C阶段城市发展速度较a阶段快D.城乡差距变化对图像振幅不断变化起主要作用6.下列与图中人口迁移强度总体变化呈正相关的是A.个人意愿B.交通C.文化D.经济冰雪圈(冰雪覆盖)是气候系统的组成部分之一，它包括季节性雪被、高山冰川、大陆冰盖、永冻土和海冰等。

图2示意北半球、南半球、全球的月平均气温与冰雪覆盖面积对应值的分布。

据此完成7~9题。

7.北半球南半球、全球1月冰雪覆盖面积(106km2)分别A.17 53 70B.53 17 70C.70 17 53D.17 70 538.关于冰雪覆盖面积与月平均气温，叙述正确的是A.南半球7月份冰雪覆盖面积达一年中最大值B.北半球7月份海冰面积未达到一年中最小值C.北半球夏季冰雪覆盖面积比南半球夏季冰雪覆盖面积大D.影响全球1月均温与7月均温差异的主要因素是太阳辐射9.导致冰雪覆盖地区高空等压面向下凹的主要原因是A.冷锋附近，气流上升B.冰雪广阔,气流上升C.空气聚集,气流下沉D.冰雪致冷，气流下沉图3示意岩层产状要素。

1、下载文档前请自行甄别文档内容的完整性，平台不提供额外的编辑、内容补充、找答案等附加服务。
2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
3、如文档侵犯您的权益，请联系客服反馈,我们会尽快为您处理(人工客服工作时间：9:00-18:30)。

绝密★启用前
2020年“安徽省示范高中皖北协作区”第22届高三联考
数学（文科）
考生注意：
1.答题前，考生务必将自已的姓名、考生号填写在试卷和答题卡上，并将考生号条形码粘贴在答题卡上的指定位置.
2.回答选择题时，选出每小题答案后，用铅笔把答题卡对应题目的答案标号涂黑.如需改动，用橡皮擦干净后，再选涂其他答案标号.回答非选择题时，将答案写在答题卡上，写在本试卷上无效.
3.考试结束后，将本试卷和答题卡一并交回。

2020年安徽省示范高中皖北协作区第22届高三联考数学(文科)试题精校版带答案

2020届 安徽高三联考试题

2020学年高考模拟试卷安徽省淮北市高考一模数学文科试卷(解析版)

安徽省示范高中皖北协作区第22届高三联考

2020届安徽省示范高中皖北协作区高三联考数学(文)试题

2020届安徽高三联考试题

2020 皖北协作区联考

2020届安徽高三联考试题