2015年成都外国语学校初升高直升考试
成都外国语学校初三2015下学期英语试题
成都外国语学校2014-2015年度下期期中考试初三英语试卷(满分120分,考试时间120分钟)Written Test Part A ( 50 marks)I. Multiple Choices.( 15 marks ) 1.My advice to you is that he is not the person you can count on, please choose another one tocomplete this project .A. depend onB. base onC. hold onD. insist on 2. I have just come across a beautiful poem in this book .A. read aloudB. written downC. discoveredD. went through 3. --- How was the party last night ? --- It couldn ’t be worst.A. It was so soB. It was awfulC. nothing badD. It was great 4. – Excuse me . --- ________?--- Could you tell me how I can get to Tian Fu square ?A. PardonB. WhyC. YesD. Please5. There is a restaurant near my house .It ’s famous for its ______ cooked dishes , _______ it ’s Gongbao Ji ding.A. specially ; especiallyB. especially ; speciallyC. especially ; especiallyD. specially ; specially6. He lay on his back at the corner of the street ,his eyes______ and his hands ______ . A. close; terrible B. closed; trembling C. closing ; trembling D. closed ; trembled7. It ’s nearly 7 o ‘clock .Jack________ be here at any moment. A. must B. can C. need D. should8. – What a pity ! My new camera doesn ’t work . _______ must be something wrong with it.--- Don ’t worry .Let me have a look.A. ItB. ThereC. ThatD. This 9. – The English test is not difficult ,is it ?-- _________. Even Tom _______ to the top students failed in it. A. Yes, belonged B. No, belonged C. No, belonging D. Yes, belonging10. The only person ________ he gives us sounded not satisfying. A. for B. which C. as D. that 11. Jim is not ______ foolish _______.A. such ;as he is lookedB. such; as he looksC. as ; as he is lookedD. as ; as he looks12. Thank you for all your hard work last night. I don ’t think we _______it without you. A. can manage B. could have managed C. could manage D. can have managed13. Everyone here will thank the firefighters for the things they have done to prevent fires_________ the environment safe.A. being madeB. to makingC. to makeD. from making 14. ______, We have to get down to the business right away. A. As there being no time left B. To be no time left C. There being no time left D. There is no time left15.--- Why are you all the pictures? -- I am going to paint the walls.A. hanging upB. putting downC. carrying outD. taking down II . Close test .( 15 marks )Languages are always changing. 1 English of today is very different from that of 500 years ago. In time, some languages become more 2 and 3 become less important. 4 even die out completely. About 1,000 years ago English was a little5 language.If a language has a large 6 of speakers, or 7 it is very old, there may be difference 8 the way it is spoken in different areas. 9 , the language may have 10 dialects. Chinese is a good example of dialect differences. Chinese 11 for thousands of years by many millions of 12 . The differences between the dialects of Chinese are 13 great that speakers of Chinese from some parts of China cannot understand each other.There are other kinds of dialects. In some languages we find words or expressions and even grammatical forms, which are, used 14 by men and others used by women. What’s more, each generation 15 its own expressions and grandparents and grandchildren may sometimes have difficulty in understanding each other.1. A.An B.The C./ D.A2. A.important B.simple C.easy D.impossible3. A.other B.some others C.the others D.others4. A.Anyone B.None C.Any D.Some5. A.known B.to know C.knowing D.knew6. A.amount B.deal C.number D.numbers7. A.if B.as C.as if D.even if8. A.on B.in C.at D.by9. A.However B.That is C.But D.So10. A.few B.several C.no D.little11.A.has been spoken B.has spoken C.is spoken D.have been spoken12. A.speakers B.talkers C.tellers D.writers13. A.very B.too C.such D.so14. A.till B.only C.neither D.either15. A.studies B.uses C.produces D.makesIII .Reading Comprehension (20 marks)AAmerican is a mobile society .Friendships between Americans can be close and real, yet disappear soon. They don’t f eel hurt. If the same two people meet again, even years later, they pick up the friendship. This can be quite difficult for us Chinese to understand. Friendships between us develop more slowly but may become lifelong feelings, extending(延伸)deeply into both families. There is another difficult point for us to understand .Although Americans treat friends warmly in their personal everyday lives, they don’t show their politeness to them if it requires a great deal of time. But in China, we are usually generous with our time. We, as hosts, will appear at an airport even in the middle of the night to meet a friend. We may take days off from our work to act as guides to our friends: It is opposite in America, Americans can not manage the time to do a great deal with a visitor outside their daily plans. They will probably expect the visitors to get themselves from the airport to the hotels. And they expect the visitors will phone them from there. Once the visitors arrive at their homes ,the welcome will be full, warm and real.For Americans, it is often considered more friendly to invite a friend to their homes than to restaurants, except for business matters. Americans are ready to receive us foreigners at their homes, share their holidays, and their home life. So accept their hospitality(好客)at home and enjoy your visit in America!( )42.The underlined phrase “pick up” in Paragraph 1 may mean “_______”.A. keep outB. give upC. pay no attention toD. continue( )43.Which of the following is the typical way of American hospitality?A. Treating friends at home.B. Taking days off to be with friends.C. Meeting friends at the airport at midnight.D. Sharing everything they have.( )44.Which of the following statements in True according to the passage?A. Americans are always generous with their time.B. Americans don’t feel hurt if their friendships disappear soon.C. Chinese friendships develop more slowly but will never disappear.D. Chinese friendships are more sincere than American friendships.( )45.This passage is most probably written for .A. American studentsB. Chinese studentsC. Chinese visitors to AmericaD. American visitors to ChinadabcBThere are many ways to find a job. It can be as easy as walking into a neighborhood store to look at its announcement board. Local stores often have areas where people can put small signs telling what kind of service they need or can provide. Such services include caring for children or cleaning houses.Besides, job searchers can look in the newspaper. Local newspapers have employment announcements placed by companies seeking workers.Another popular tool for finding jobs is the Internet. For example, people in four hundred and fifty cities around the world can use the Craigslist Web site to buy objects, meet people or find a job. Craigslist says that it receives two million new job listings each month.Another useful way to find a job is through a college or university. For example, students at the University of Texas in Austin can go to the Career Exploration Center to get help in finding a job. Of course, looking for a job requires knowing what kind of work you want to do. For example, there is a book called “What Color is Your Parachute ?” by Richard Bolles. This book has been helping people choose a career since it was first published in nineteen seventy.Some experts also help people find jobs. Susan W. Miller owns a company called California Career Services in Los Angeles. She says her company helps people find jobs by first helping them understand their strengths, goals and interests. Then she provides them with methods and resources to help them find the right job.26. What is the passage mainly about?A. College students’ part-time jobs.B. Finding a job.C. Craigslist Web site.D. The relation between study and work.27. By using the Craigslist Web site, you can ______.A. sell your old thingsB. create your own announcement boardC. do some shopping onlineD. get useful information about 450 cities28. “What Color is Your Parachute?” is a book which gives tips to those who want to _____.A. work on the airplaneB. find a suitable jobC. publish a bookD. buy a parachute29. It can be learned from the passage that ______.A. companies often put job information on announcement boards in local shopsB. the Internet is the most popular tool for job hunters in the USAC. California Career Services mainly serves university studentsD. Susan W. Miller’s company helps people find jobs accor ding to their abilities and goals.30. How many ways of finding a job are mentioned in the passage?A. Four.B. Five.C. Six.D. Seven.CScientists have tried to come up with biological explanations for the difference between boys and girls However, none were believable enough to explain the general picture. As one scientist points out, "There are slight genetic(遗传的) differences between the sexes at birth which may affect the subjects boys and girls choose. But the difficulty is that by the time children reach school age, there are so many other effects that it is almost impossible to tell whether girls are worse at science and maths, or whether they've been brought up to think of these subjects as boys'' territory". Statistics(统计数据) show that in mathematics, at least, girls are equal to boys. A recent reportsuggests that girls only stop studying mathematics because of social attitudes. One of the reports' authorssays, "While it is socially unacceptable for people not to be able to read and write, it is still acceptable for women to say that they are 'hope-less' at maths. Our research shows that, although girls get marks which are as good as the boys', they have not been encouraged to do so."The explanation for the difference, which is very clear during the teenage years, goes as far back as early childhood experiences. From their first days in nursery school, girls are not encouraged to work on their own or to complete tasks, although boys are. For example, boys but not girls, are often asked to 'help' with repair work. This encouragement leads to a way of learning how to solve problems later on in life. Evidence shows that exceptional mathematicians and scientists did not have teachers who supplied answers; they had to find out for themselves.A further report on maths teaching shows that teachers seem to give more attention to boys than to girls. Most teachers who took part in the study admitted that they expect their male students to do better at mathematics and science subjects than their female students. All of this tends to encourage boys to work harder in these subjects, gives them confidence and makes them believe that they can succeed.Interestingly, both boys and girls tend to regard such 'male' subjects like mathematics and science as difficult. Yet it has been suggested that girls avoid mathematics courses, not because they are difficult, but for social reasons.1. The underlined word "territory" in the second paragraph most probably means "________”.A. interestB. area of landC. special fieldD. district2. According to scientific studies,.A. maths is not fit for girls to learnB. boys have a special sense of mathsC. girls are poorer at maths because they are the weaker sexD. girls can learn maths as well as boys if given enough encouragement3. Those who made extraordinary contribution in mathematics and scienceA. usually had good teachers to help themB. had the abilities to solve problems by themselvesC. usually worked harder than othersD. were encouraged to repair things when young4. Which of the following is not true according to the text?A. It seems socially acceptable for a girl not to be able to read and write.B. It is a social problem rather than a problem of brains that girls are poor at mathsC. Mathematics and science are no easy subjects to either girls or boys.D. There is no connection between a girl's ability in maths and her appearance.5. What would be the best title for the text?A. Who's Afraind of Maths Anyway?B. Are Boys Cleverer than Girls?C. Boys Are Better at Maths than Girls by BirthD. Maths-A Difficult SubjectDLaptop computers are popular all over the world .People use them on trains and airplanes ,in airports and hotels .These laptops These laptops connect people to their workplace. In the United States today, laptops also connect students to their classrooms. Westlake College in Virginia will start a laptop computer program that allows students to do schoolwork anywhere they want. Within five years, each of the 1500 students at the college will receive a laptop. The laptops are part of a $10 million computer program at Westlake, a 110-year-old college. The students with laptops will also have access to the Internet. In addition, they will be able to use e-mail to "speak" with their teachers, their classmates, and their families. However, the most important part of the laptop program is that students will be able to use computers without going to computer labs. They can work with it at home, in a fast-food restaurant or under the trees-anywhere at all!Because of the many changes in computer technology, laptop use in higher education, such as colleges and universities, is workable. As laptops become more powerful, they become more similar to desktop computers. In addition, the portable computers can connect students to not only the Internet, but also libraries and other resources. State higher-education officials are studying how laptops can help students. State officials are also testing laptop programs at other universities, too.At Westlake College, more than 60 percent of the staff use computers. The laptops will allow all teachers to use computers in their lessons. As one Westlake teacher said, "Here we are in the middle of Virginia and we're giving students a window on the world. They can see everything and do everything."1. The main purpose of the laptop program is to give each student a laptop to _____.A. use for their schoolworkB. access the InternetC. work at homeD. connect them to libraries2. Why is the word "speak" in the second paragraph in quotation marks (引号)?A. They don't really talk.B. They use the computer language.C. Laptops have speakers.D. None of the above reasons is correct.3. Which of the following is true about Westlake College?A. All teachers use computers.B. 1500 students have laptops.C. It is an old college in America.D. Students there can do everything.4. A window on the world in the last paragraph means that students can _____.A. attend lectures on information technologyB. travel around the worldC. get information from around the worldD. have free laptops5. What can we infer from the passage ?A . The program is successfulB . The program is not workableC. The program is too expensiveD. We don’t know the result yet .Paper BI. Words. (15marks)1. Look at your dirty shoes, they really need___________ (wash) at once.2. After a three-year service in the Army, he came back to his hometown and found his beloved girl _____________(engage)to a rich business man.3. I ‘ll never forget the days I spent with my friend ____________ (travel)to every part of the world we could reach.4. One of the colorful presents which___________ (lay) under the Christmas tree belongs to me.5. Nowadays ,people are strongly_____________(criticism)of what the government do to the control of the house price.6. _________ (legal) speaking, it is wrong to do a U-turn on the motor way.7. We can do nothing but ___________(wait) for the ambulance _________(come).8. If you are a wise man, you should choose the __________ (beautiful) but _________(intelligent) woman of the two to marry.9. When___________ (ask) how to be successful ,the celebrity replied .“Never give up your dream”10. Especially in winter there aren’t so many ___________(season) fruits or vegetables, that’s the reason why the prices of them__________(raise) 10% by the end of last month.11. Don’t worry, all the jobs_____________(deal) perfectly so far although they are tough ones.12. The flowers are dead, you should_________(water) them in time.13. She does anticipate ___________(invite) to the Victoria Fashion Show as a VIP.II. Pattern shift. (10marks)1. The sculptors were careful to make the sculptures in Madam Tussaud’s.______ _____ _____ _____ the sculptors.to make the sculptures in Madam Tussaud’s.2. The movies were too attractive for me to resist.The movies were ______ _______ that_______ _______ _______ _______ .3. We didn’t know where to travel this holiday.We ________ _________ _______ where to travel this holiday.4. Having been told the news by his parents ,she didn’t say anything._________ ________ _________ by his parents ,she didn’t say anything.5. I think the policeman hit the thief on the head heavily with a bottle,___________?(tag question)6. They have spent nearly 3 years studying for the driving test. (rewrite the sentence by using “take”)_______________________________________________________________ 7.It seemed that the client agreed to sign the contract.( simple sentence )________________________________________________________________8 .The businessman asked Mary ,“Will you come to my party next weekend?”.The businessman asked Mary _______________________________________.9.He told us extremely terrible news when he came back from Africa. (exclamatory sentence)________________________________________________________________10. Have the visitors seen the plane fly over the building?(passive voice)________________________________________________________________11.If I was given another chance, I am sure I will succeed._______ ________ _________, I am sure I will succeed.III. Choose the wrong one from the sentences .1.Could you please speak loudly in order that I can hear it much clearly .2. You ‘ll find this map of great valuable in helping you to get round London .3.About 70 percent of students are from the south ,and the rest of them is from the northor foreign countries .4.Would you please to try your best to get a better method by which you can improveyour writing.5.The weather in summer in Beijing is hotter than it in Guangzhou.6.How could the students get the correct key of the question without being helped by theteachers .7.Catherina is the only one of the writers who write stories for children.8.The girl has fallen asleep for half a day because she worked very late last night .9.My mother bought me 3 novels yesterday ,but I found it quite boring .10.When I was at college I spoke three foreign languages ,but I had forgotten all exceptfew words of each .IV. Choose the word from the table and fill in the blanks with their proper forms.(10marks)environment necessarily allowed cheat internationaladmit hardly master joy excitement difficult communicateA friend of mine once asked me:“Why should a Chinese take time to learn alanguage that is not his own?” Obviously he has___1____ in learning a foreignlanguage .He is not the only one who is mentally against English learning. One reason ,asI suspect ,is the way English taught .The emphasis on memorization is such that no___2____ is left in the process of learning ,only endless annoyance . What students are presented in the classroom is not the language in real- world ___3____ . A Chinesestudent with extremely high scores for American standardized tests was___4____into one of the most famous universities .But his professors soon found out that he could___5____understand the lesson. Finding that he ___6____in the tests, the school asked him to repeat them. Again, he passed with high scores. Not till then they realized that the student ___7____ the techniques for dealing with the tests, not mastering the skills of using the language ..Many people take TOFEL, IELTS,GRE, annual Band 4 and Band 6 exams not because they work in areas where English is a ___8____tool ,but because they have to do it for job promotion or Enrolment in certain programs .Must English learning be such a pain in the neck? Create a(n)___9____where learning English is natural and painless .Don’t make it compulsory (强迫的)for people whose work or major does not require it . China will not become more ___10____by adding millions of people who can only say a simple “Hello”.1 2 3 4 56 7 8 9 10VV. Fill in the blanks according to the first letter to the words given and the context.Do you have bright ideas ? Ideas for inventions that c _________ society or, at least, make life easier for somebody? P_________ we all do sometimes, but we don't often make the idea a reality. Recently, there was a competition called British Designers for Tomorrow. The competition e_________ young people to carry out their bright ideas. There were t_________ groups in the contest: Group One was for schoolchildren under 16; Group Two was for schoolchildren o_________ 16, and there were eleven prize-winners altogether.Neil Hunt, one of the prize-winners, was c_________ "Sunshine Superman". It's important when people study the weather to be able to record sunshine accurately. We need to know how many h_________ of sunshine we have and how strong it is. Most sunshine recorders o_________ record direct sunlight. Neil's is more accurate and this is very i_________ for research into the way of using solar power. Neil plans to keep inventing.The ideas in the competition were so g_________ that we are surprised that British industry doesn't ask more schoolchildren for suggestions.change 2.Perhaps/Probably 3.encourage 4.two 5.over 6.called 7.hours 8.only 9.important 10.great/ goodVII. Reading. (10marks)We each have a memory .____1______ Some people have very good memories and they can easily learn many things by heart ,but some people can only remember things when they say or do them again and again _____2_____.____3_____Everybody learns his mother language when he is a small child. He hears the sounds, remembers them and then he learns to speak. Some children are living with their parents in foreign countries. ____4______In school it is not so easy to learn a foreign language because the pupils have so little time for it, and they are busy with other subjects, too. ___5____A.T hey can learn two languages as easily as one because they hear, remember and speak two languages every day.B.A good memory is a great help in learning a language.C. But your memory will become better and better when you do more and more exercises.D. That’s why we can still remember things after a long time.E .Many of the great men of the world have got surprising memories.DEBACVIII. CompositionWhat do you think are the symbols of success in China ?The answers of what success means vary from person to person and change from time to time .Please write a composition with your activities .You have to write according to the following requirements .1.please write with the title of “The symbols of success in today’s China “2.You have to give at least two symbols of success in today’s China from your point of view .3. Give reasons for your opinions .4. Words from 80 -100.。
2015年成都市成都外国语学校自主招生考试数学试卷(含解析)
2015年成都市成都外国语学校自主招生考试数学试卷(考试时间:120分钟满分:150分)第Ⅰ卷(选择题,共45分)一、选择题:每小题3分,共45分.1.﹣|﹣|的负倒数是()A.B.C.D.2.计算:(a2b)3的结果是()A.a6b B.a6b3C.a5b3D.a2b33.在式子,,,中,x可以取1和2的是()A.B.C.D.4.如图,H7N9病毒直径为30纳米(1纳米=10﹣9米),用科学记数法表示这个病毒直径的大小,正确的是()A.30×10﹣9米B.3.0×10﹣8米C.3.0×10﹣10米D.0.3×10﹣9米5.的平方根是()A.4 B.﹣4 C.2 D.±26.如图,AB∥CD,点E在BC上,且CD=CE,∠D=74°,则∠B的度数为()A.68°B.32°C.22°D.16°7.已知a2﹣5a+1=0,则a+﹣3的值为()A.4 B.3 C.2 D.18.在平面直角坐标系中,点P(﹣2,a)与点Q(b,3)关于原点对称,则a+b的值为()A.5 B.﹣5 C.1 D.﹣19.下列命题中真命题是()A.有理数都能表示成两个整数之比B.各边相等的多边形是正多边形C.等式两边同时乘以(或除以)同一个实数,所得结果仍是等式D.相等的圆心角所对的弧相等,所对的弦相等10.已知|a|=2,|b|=3,则|a﹣b|=5的概率为()A.0 B.C.D.11.某几何体的主视图、左视图和俯视图分别如图所示,则该几何体的体积为()A.3πB.2πC.πD.1212.某校九年级共有1100名学生参加“二诊”考试,随机抽取50名学生进行总成绩统计,其中有20名学生总成绩达到优秀,估计这次“二诊”考试总成绩达到优秀的人数大约为()A.400 B.420 C.440 D.46013.若x1,x2是方程x2+2x﹣k=0的两个不相等的实数根,则x12+x22﹣2是()A.正数B.零C.负数D.不大于零的数14.已知△ABC的三边长分别为a、b、c,面积为s;△A′B′C′的三边长分别为a′,b′,c′,面积为s′,且a>a′,b>b′,c>c′,则s与s′的大小关系一定是()A.s>s′B.s<s′C.s=s′D.不确定15.b>a,将一次函数y=ax+b与y=bx+a的图象画在同一个直角坐标系内,则能有一组a、b的取值,使得如下四个图中为正确的是()A.B.C.D.第Ⅱ卷(非选择题,共105分)二、填空题:本大题共6小题,每小题6分,共36分.16.函数有意义,则x 的取值范围是 . 17.已知一组数据24、27、19、13、x 、12的中位数是21,那么x 的值等于 .18.已知x 2﹣x ﹣1=0,那么代数式x 3﹣2x+1的值是 .19.如图,E 、F 是平行四边形ABCD 的边AB 、CD 上的点,AF 与DE 相交于点P ,BF 与CE 相交于点Q .若S △APD =15cm 2,S △BQC =25cm 2,则阴影部分的面积为 cm 2.20.已知直线l 经过正方形ABCD 的顶点A ,过点B 和点D 分别作直线l 的垂线BM 和DN ,垂足分别为点M 、点N ,如果BM =5,DN =3,那么MN = .21.已知x 、y 、z 是三个非负实数,满足3x+2y+z =5,x+y ﹣z =2,若S =2x+y ﹣z ,则S 的最小值为 .三、解答题:本大题共7小题,计69分,写出必要的推算或演算步骤.22.(7分)根据题意回答下列问题:(1)如果(a ﹣2)+b+3=0,其中a 、b 为有理数,那么a = ,b = .(2)如果(2+)a ﹣(1﹣)b =5,其中a 、b 为有理数,求a+2b 的值.23.(8分)逸夫楼前石室水景广场园林及道路改造项目是我校2012年校园文化﹣﹣环境文化建设的重点项目之一,该项目2012年2月11日正式动工,经过四个多月的紧张施工,于2012年6月5日竣工,若该工程拆除旧设施每平方米需要80元,建造新设施每平方米需要800元,计划拆除旧设施与建造新设施共9000平方米,在实施中为扩大绿化面积,新建设施只完成了计划的90%而拆除旧设施则超过了计划的10%,结果恰好完成了原计划的拆、建总面积.(1)求原计划拆、建面积各是多少平方米?(2)若绿化1平方米需要200元,那么把在实际的拆、建工程中节余的资金全部用来绿化,可绿化多少平方米?24.(8分)已知y=m2+m+4,若m为整数,在使得y为完全平方数的所有m的值中,设m的最大值为a,最小值为b,次小值为c.(注:一个数如果是另一个整数的完全平方,那么我们就称这个数为完全平方数)(1)求a、b、c的值;(2)对a、b、c进行如下操作:任取两个求其和再除以,同时求其差再除以,剩下的另一个数不变,这样就仍得到三个数,再对所得三个数进行如上操作,问能否经过若干次上述操作,所得三个数的平方和等于2012?证明你的结论.25.(9分)已知:如图,AB是⊙O的直径,C是⊙O上一点,OD⊥BC于点D,过点C作⊙O的切线,交OD 的延长线于点E,连接BE.(1)求证:BE与⊙O相切;(2)连接AD并延长交BE于点F,若OB=9,sin∠ABC=,求BF的长.26.(12分)已知:在Rt△ABC中,∠C=90°,AC=4,∠A=60°,CD是边AB上的中线,直线BM∥AC,E 是边CA延长线上一点,ED交直线BM于点F,将△EDC沿CD翻折得△E′DC,射线DE′交直线BM于点G.(1)如图1,当CD⊥EF时,求BF的值;(2)如图2,当点G在点F的右侧时;①求证:△BDF∽△BGD;②设AE=x,△DFG的面积为y,求y关于x的函数解析式,并写出x的取值范围;(3)如果△DFG的面积为,求AE的长.27.(12分)如图,AB∥CD、AD∥CE,F、G分别是AC和FD的中点,过G的直线依次交AB、AD、CD、CE于点M、N、P、Q,求证:MN+PQ=2PN.28.(13分)如图,已知抛物线y=x2﹣(b+1)x+(b是实数且b>2)与x轴的正半轴分别交于点A、B(点A位于点B的左侧),与y轴的正半轴交于点C.(1)点B的坐标为,点C的坐标为(用含b的代数式表示);(2)请你探索在第一象限内是否存在点P,使得四边形PCOB的面积等于2b,且△PBC是以点P为直角顶点的等腰直角三角形?如果存在,求出点P的坐标;如果不存在,请说明理由;(3)请你进一步探索在第一象限内是否存在点Q,使得△QCO,△QOA和△QAB中的任意两个三角形均相似(全等可作相似的特殊情况)?如果存在,求出点Q的坐标;如果不存在,请说明理由.参考答案与试题解析1.【解答】解:﹣|﹣|=﹣,﹣的负倒数是.故选:B.2.【解答】解:(a2b)3=a6b3,故选:B.3.【解答】解:有意义的条件是x≠1,有意义的条件是x≠2,有意义的条件是x≥1,有意义的条件是x≥2,故选:C.4.【解答】解:30纳米=30×10﹣9米=3×10﹣8米.故选:B.5.【解答】解:∵=4,∴4的平方根为±2,故选:D.6.【解答】解:∵CD=CE,∴∠D=∠DEC,∵∠D=74°,∴∠C=180°﹣74°×2=32°,∵AB∥CD,∴∠B=∠C=32°.故选:B.7.【解答】解:∵a2﹣5a+1=0,∴a2+1=5a,∴a+=5,a+﹣3=5﹣3=2,故选:C.8.【解答】解:∵点P(﹣2,a)与Q(b,3)关于原点对称,∴b=2,a=﹣3,则a+b的值为:2﹣3=﹣1.故选:D.9.【解答】解:A、有理数包括整数和分数,整数可以表示为整数:1的形式,分数本身就是分子:分母的形式,故本选项正确;B、各边都相等,各角都相等的多边形是正多边形,故本选项错误;C、等式两边同时乘以(或除以)同一个实数(除数不为0),所得结果仍是等式,故本选项正确;D、在同圆或等圆中,相等的圆心角所对的弧相等,所对的弦相等,故本选项错误;故选:A.10.【解答】解:∵|a|=2,|b|=3,∴a=±2,b=±3,∴有|a﹣b|=1,|a﹣b|=5,|a﹣b|=1,|a﹣b|=5四种情况,∵|a﹣b|=5的概率为=.故选:B.11.【解答】解:根据三视图可以判断该几何体为圆柱,圆柱的底面半径为1,高为3,故体积为:πr2h=π×1×3=3π,故选:A.12.【解答】解:随机抽取了50名学生的成绩进行统计,共有20名学生成绩达到优秀,∴样本优秀率为:20÷50=40%,又∵某校九年级共1100名学生参加“二诊”考试,∴该校这次“二诊”考试总成绩达到优秀的人数大约为:1100×40%=440人.故选:C.13.【解答】解:∵x1,x2是方程x2+2x﹣k=0的两个不相等的实数根,∴△=b2﹣4ac>0,即4﹣4×1×(﹣k)>0,∴4+4k>0,∴2+2k>0,又∵x1+x2=﹣,x1•x2=,∴x1+x2=﹣2,x1•x2=﹣k,∴x12+x22﹣2=(x1+x2)2﹣2x1x2﹣2=2+2k,∵2+2k>0,∴x12+x22﹣2>0,故选:A.14.【解答】解:已知a>a′,b>b′,c>c′,分三种情况讨论:①△ABC∽△A′B′C′,此时=>1,∴s>s';②设a=b=,c=20,则=10,由勾股定理得:h c==1,∴s=×20×1=10,取a′=b′=c′=10,则h c'=10×sin60°=5,∴s'=×10×5=25>10,即s<s';③设a=b=,c=20,则同②h c=1,s=10,取a′=b′=,c′=10,则由勾股定理得h c'==2,∴s'=×10×2=10,即s=s'.∴s与s′的大小关系不确定.故选:D.15.【解答】解:A、假设y=ax+b正确,则a>0,b>0,则函数y=bx+a的图象应经过一、二、三象限,故本选项错误;B、假设y=ax+b正确,则a>0,b>0,因为b>a,所以函数y=bx+a与y轴的交点在y=ax+b与y轴交点的下方,故本选项正确;C、假设y=ax+b正确,则a<0,b>0,则函数y=bx+a的图象过一、三、四象限,因为函数y=ax+b与y =bx+a的交点坐标为(1,a+b),由图象可知a≠﹣b和b>a,两结论矛盾,故本选项错误;D、假设y=ax+b正确,则a<0,b>0,则函数y=bx+a的图象过一、三、四象限,故本选项错误.故选:B.16.【解答】解:由题意,得,解得x≥2且x≠3.故答案为x≥2且x≠3.17.【解答】解:根据题意,x的位置按从小到大排列只可能是:12,13,19,x,24,27.根据中位数是21得(19+x)÷2=21.解得x=23.故答案为:23.18.【解答】解:根据题意,x2﹣x=1,∴x3﹣x2=x,即x3﹣x=x2,∴x3﹣2x+1=x2﹣x+1=1+1=2,故答案为:2.19.【解答】解:如图,连接EF∵△ADF与△DEF同底等高,∴S△ADF=S△DEF,即S△ADF﹣S△DPF=S△DEF﹣S△DPF,即S△APD=S△EPF=15cm2,同理可得S△BQC=S△EFQ=25cm2,∴阴影部分的面积为S△EPF+S△EFQ=15+25=40cm2.故答案为40.20.【解答】解:如图1,在正方形ABCD中,∵∠NAD+∠BAM=90°,∠ABM+∠BAM=90°,∴∠NAD=∠MBA,在△ABM和△ADN中,∵,∴△ABM≌△ADN(AAS),∴AM=DN=3,AN=BM=5,∴MN=AM+AN=8,如图2,在正方形ABCD中,∵∠DAN+∠BAM=90°,∠ABM+∠BAM=90°,∴∠NAD=∠MBA,在△ABM和△ADN中,∵,∴△ABM≌△ADN(AAS),∴AM=DN=3,AN=BM=5,∴MN=AN﹣AM=2,综上所述:MN的值为2或8,故答案为:2或8.21.【解答】解:要使S取最小值,联立得到方程组,(1)+(2)得:4x+3y=7,y=,(1)﹣(2)×2得:x+3z=1,z=,把y=,z=代入S=2x+y﹣z,整理得:S=x+2,当x取最小值时,S有最小值,∵x、y、z是三个非负实数,∴x的最小值是0,∴S的最小值为2.故答案为:2.22.【解答】解:(1)由(a﹣2)+b+3=0,得到a=2,b=﹣3;故答案为:2;﹣3;(2)由(2+)a﹣(1﹣)b=5整理得:(a+b)+(2a﹣b﹣5)=0,∵a、b为有理数,∴,解得:a=,b=﹣,则a+2b=﹣.23.【解答】解:(1)由题意可设拆旧舍x平方米,建新舍y平方米,则答:原计划拆建各4500平方米.(2)计划资金y1=4500×80+4500×800=3960000元实用资金y2=1.1×4500×80+0.9×4500×800=4950×80+4050×800=396000+3240000=3636000∴节余资金:3960000﹣3636000=324000∴可建绿化面积=平方米答:可绿化面积1620平方米.24.【解答】解:(1)设m2+m+4=k2(k为非负整数),则有m2+m+4﹣k2=0,由m为整数知其△为完全平方数,即1﹣4(4﹣k2)=p2(p为非负整数),(2k+p)(2k﹣p)=15,显然2k+p >2k﹣p,∴或,解得:p=7或p=1,∴m=,∴m1=3,m2=﹣4,m3=0,m4=﹣1,∴a=3,b=﹣4,c=﹣1.(2)三个数,任意两个求其和,再除以,同求其差,再除以,剩下的一个数不变,经过两次这样的操作就又变成原来的三个数了,即()2+()2+p2=m2+n2+p2,∵32+(﹣4)2+(﹣1)2≠2012.∴对a、b、c进行若干次操作后,不能使所得三个数的平方和等于2012.25.【解答】证明:(1)连接OC,∵OD⊥BC,∴∠COE=∠BOE,在△OCE和△OBE中,∵,∴△OCE≌△OBE,∴∠OBE=∠OCE=90°,即OB⊥BE,∵OB是⊙O半径,∴BE与⊙O相切.(2)过点D作DH⊥AB,连接AD并延长交BE于点F,∵∠DOH=∠BOD,∠DHO=∠BDO=90°,∴△ODH∽△OBD,∴==又∵sin∠ABC=,OB=9,∴OD=6,易得∠ABC=∠ODH,∴sin∠ODH=,即=,∴OH=4,∴DH==2,又∵△ADH∽△AFB,∴=,=,∴FB=.26.【解答】解:(1)∵∠ACB=90°,AD=BD,∴CD=AD=BD,∵∠BAC=60°,∴∠ADC=∠ACD=60°,∠ABC=30°,AD=BD=AC,∵AC=4,∴AD=BD=AC=4,∵BM∥AC,∴∠MBC=∠ACB=90°,又∵CD⊥EF,∴∠CDF=90°,∴∠BDF=30°,∴∠BFD=30°,∴∠BDF=∠BFD,∴BF=BD=4;(2)①证明:由翻折,得∠E′CD=∠ACD=60°,∴∠ADC=∠E′CD,∴CE′∥AB,∴∠CE′D=∠BDG,∵BM∥AC,∴∠CED=∠BFD,又∵∠CE′D=∠CED,∴∠BDG=∠BFD,∵∠DBF=∠GBD,∴△BDF∽△BGD;②由△BDF∽△BGD,得=,∵D为AB的中点,∴BD=AD,又∵BM∥AC,∴∠DBF=∠DAE,∠BFD=∠DEA,在△BFD和△AED中,∵,∴△BFD≌△AED(AAS),∴BF=AE=x,∴=,∴BG=,在Rt△ABC中,AB=8,AC=4,根据勾股定理得:BC==4,∵点D到直线BM的距离d=BC=2,∴S△DFG=FG•d=(BG﹣BF)•d,即y=×(﹣x)×2=﹣x(0<x<4);(3)(i)当点G在点F的右侧时,由题意,得6=﹣x,整理,得x2+6x﹣16=0,解得x1=2,x2=﹣8(不合题意,舍去);(ii)当点G在点F的左侧时,如图3所示:同理得到S△DFG=FG•d=(BF﹣BG)•d,即y=x﹣(x>4),由题意,得6=x﹣,整理,得x2﹣6x﹣16=0,解得x3=8,x4=﹣2(不合题意,舍去),综上所述,AE的值为2或8.27.【解答】证明:延长BA、EC,设交点为O,则四边形OADC为平行四边形,∵F是AC的中点,∴DF的延长线必过O点,且.∵AB∥CD,∴.∵AD∥CE,∴.∴==.又∵=,∴OQ=3DN.∴CQ=OQ﹣OC=3DN﹣OC=3DN﹣AD,AN=AD﹣DN.∴AN+CQ=2DN.∴==2.即MN+PQ=2PN.28.【解答】解:(1)令y=0,即y=x2﹣(b+1)x+=0,解得:x=1或b,∵b是实数且b>2,点A位于点B的左侧,∴点B的坐标为(b,0),令x=0,解得:y=,∴点C的坐标为(0,),故答案为:(b,0),(0,);(2)存在,假设存在这样的点P,使得四边形PCOB的面积等于2b,且△PBC是以点P为直角顶点的等腰直角三角形.设点P的坐标为(x,y),连接OP.则S四边形PCOB=S△PCO+S△POB=••x+•b•y=2b,∴x+4y=16.过P作PD⊥x轴,PE⊥y轴,垂足分别为D、E,∴∠PEO=∠EOD=∠ODP=90°.∴四边形PEOD是矩形.∴∠EPD=90°.∴∠EPC=∠DPB.∴△PEC≌△PDB,∴PE=PD,即x=y.由解得由△PEC≌△PDB得EC=DB,即﹣=b﹣,解得b=>2符合题意.∴P的坐标为(,);(3)假设存在这样的点Q,使得△QCO,△QOA和△QAB中的任意两个三角形均相似.∵∠QAB=∠AOQ+∠AQO,∴∠QAB>∠AOQ,∠QAB>∠AQO.∴要使△QOA与△QAB相似,只能∠QAO=∠BAQ=90°,即QA⊥x轴.∵b>2,∴AB>OA,∴∠Q0A>∠ABQ.∴只能∠AOQ=∠AQB.此时∠OQB=90°,由QA⊥x轴知QA∥y轴.∴∠COQ=∠OQA.∴要使△QOA与△OQC相似,只能∠QCO=90°或∠OQC=90°.(I)当∠OCQ=90°时,△CQO≌△QOA.∴AQ=CO=.由AQ2=OA•AB得:()2=b﹣1.解得:b=8±4.∵b>2,∴b=8+4.∴点Q的坐标是(1,2+).(II)当∠OQC=90°时,△OCQ∽△QOA,∴=,即OQ2=OC•AQ.又OQ2=OA•OB,∴OC•AQ=OA•OB.即•AQ=1×b.解得:AQ=4,此时b=17>2符合题意,∴点Q的坐标是(1,4).∴综上可知,存在点Q(1,2+)或Q(1,4),使得△QCO,△QOA和△QAB中的任意两个三角形均相似.。
成都外国语学校2015年数学直升试卷
成都外国语学校2015年初升高直升考试一、选择题(每小题3分,共45分) 1. 53--的负倒数是 ( B ) A. 35- B. 35 C. 53- D. 53 2. 计算:(a 2b )3的结果是 ( B )A. a 6bB. a 6b 3C. a 5b 3D. a 2b 33. 在式子11-x ,21-x ,1-x ,2-x 中,x 可以取1和2的是 ( C ) A. 11-x B. 21-x C. 1-x D. 2-x 4. H7N9病毒直径为30纳米(1纳米=10-9米),用科学计数法表示这个病毒直径的大小,正确的是( B )A. 30×10-9米B. 3.0×10-8米C. 3.0×10-10米D. 0.3×10-9米 5. 16的平方根是( D )A.4B.-4C.2D.2±6. 如图,AB//CD,点E 在BC 上,CD=CE,∠D=74°,则∠B 的度数为( B )A. 68°B. 32°C. 22°D. 16°7. 已知a 2-5a+1=0,则a+a1-3的值为( C ) A. 4 B. 3 C. 2 D. 18. 在平面直角坐标系中,点P (-2,a )与点Q (b,3)关于原点对称,则a+b 的值为( D )A.5B.-5C.1D.-19. 下列命题中真命题是( A )A. 有理数都能表示成两个整数之比B. 多边相等的多边形是正方形C. 等式两边同时乘以同一个实数,所得结果仍是实数D. 相等的圆心角所对的弧相等,所对的弦相等10. 已知2a =,3=b ,则5=-b a 的概率为( B ) A. 0 B.21 C. 31 D. 4111. 某几何体的主视图,左视图和俯视图分别如下,则该几何体的体积为( A )A. 3πB. 2πC. πD. 1212. 某校九年级共有1100名学生参加“二诊”考试,随机抽取50名学生进行总成绩统计,其中有20名学生成绩达到优秀,估计这次“二诊”考试总成绩达到优秀的人数约为( C )A. 400B. 420C. 440D. 46013. 若21x x 、是方程022=-+k x x 的两个不相等的实数根,则22221-+x x 是( A )A. 正数B. 零C. 负数D. 不大于零的数14. 已知△ABC 三边长分别为a,b,c ,面积s ;△A 'B 'C '的三边长分别为a '、b '、c ',面积为s ',且a>a ',b>b ',c>c,'则s 与s '的大小关系一定是( D )A. s>s 'B. s<s 'C. s=s 'D. 不确定15. b>a,将一次函数y=ax+b 与y=bx+a 的图像画在同一个直角坐标系内,则能有一组a,b 的取值,使得如下四个图为正确的是( B )二、填空题(本大题共6小题,每小题6分,共36分)16、函数 312-+-=x x y 有意义,则x 的取值范围是_______. 答案:x ≥2且x ≠3.17、已知一组数据24,27,19,13,x ,12的中位数是21,那么x 的值等于_______. 答案:2318、已知012=--x x ,那么代数式122+-x x 的值是_______.答案:219、如图,E 、F 分别是平行四边形ABCD 的边AB 、CD 上的点,AF 与DE 相交于点P ,BF 与CE 相交于点Q ,若,,222515cm S cm S BQ C APD ==∆∆则阴影部分面积为_______2cm . 答案:4020、已知直线l 经过正方形ABCD 的顶点A ,过点B 和点D 分别作直线l 的垂线BM 和DN ,交直线l 于点M ,点N ,如果BM=5,DN=3,那么MN=______.答案:2或821、已知x 、y 、z 是三个非负实数,满足3x+2y+z=5,x+y-z=2,若S=2x+y-z ,则S 的最小值为_______.答案:2三、解答题:(共80分)22.(7分)根据题意回答下列问题:(1)如果()03b 22=++-a ,其中a,b 为有理数,那么a=_____,b=______;(2)如果()()52122=--+b a ,其中a,b 为有理数,求a+2b 的值.23.(8分)逸夫楼前石室水景广场园林及道路改造项目是我校2012年校园文化——环境文化建设的重点项目之一,该项目2012年2月11日正式动工,经过四个多月的紧张施工,于2012年6月5日竣工.若该工程拆除旧设施每平方米需要80元,建设新设施每平方米需要800元.计划拆除旧设施与建筑新设施共9000平方米,在实施中为扩大绿化面积,新建设施只完成了计划的90%而拆除旧设施则超过了计划的10%,结果恰好完成了原计划的拆、建总面积.(1)求原计划拆、建面积各是多少平方米;(2)若绿化1平方米需要200元,那么把在实际的拆、建工程中节余的资金全部用来绿化,可绿化多少平方米?24. (8分)已知42++=m m y ,若m 为整数,在使得y 为完全平方数的所有m 的值中,设m 的最大值为a ,最小值为c.(注:一个数如果是另一个整数的完全平方,,那么我们就称这个数为完全平方数.)()1 求a 、b 、c 的值;()2 对a 、b 、c 进行如下操作:任取两个求其和再除以2,同时求其差再除以2,剩下的另一个数不变,这样就仍得到三个数,再对所得三个数进行如上操作,问能否经过若干次上述操作,所得三个数的平方和等于2012?证明你的结论。
【VIP专享】成都市2015年高中阶段教育学校统一招生考试(附答案)
成都市2015年高中阶段教育学校统一招生考试化学(满分90分,考试时间60分钟)可能用到的相对原子质量:C - 12 O - 16 Ca - 40第1卷(选择题,共42分)一、选择题(本题包括l4个小题,每小题3分,共42分。
每小题只有一个选项符合题意) ( )1.下列变化属于化学变化的是A.酒精挥发B.石蜡熔化C.粮食酿酒D.水凝成冰( )2.空气的组成成分中,体积分数最大的是A.O2B.N2C.CO2D.稀有气体( )3.不属于新能源开发和利用的是A.火力发电B.风力发电C.氢燃料客车D.太阳能电池路灯( )4.通常状况下,下列溶液的溶质为液体的是A.蔗糖溶液B.酒精溶液C.氯化钠溶液D.澄清石灰水( )5.实验室用氯酸钾和二氧化锰制取氧气,有关该实验的说法错误的是A.二氧化锰是反应物B.与高锰酸钾制取氧气的发生装置相同C.可用向上排空气法收集D.可用带火星的木条检验氧气( )6.对下列现象或事实的解释错误的是选项现象或事实解释A气体易被压缩分子间的间隔大B墙内开花墙外香分子在不停运动C物体热胀冷缩分子可变大可变小D1个水分子的质量约为3×10-26kg分子很小( )7.下列说法正确的是A.燃烧是人类最早利用的化学反应之一B.可燃物温度达到着火点即可燃烧C.图书档案起火宜用水基型灭火器扑灭D.不慎碰倒酒精灯,酒精在桌面燃烧,用水来灭火( )8.下列有关化肥和农药的说法错误的是A.氯化钾可用作钾肥B.化肥能有效提高农作物产量C.农药施用后,不会通过农作物转移到人体D.农药应根据农作物、虫害和农药的特点合理施用( )9.下图是某化学反应的微观示意图(“”与“”代表不同种元素的原子)。
甲乙有关说法不正确的是A.甲中的一个分子由三个原子构成B.化学反应的实质是原子的重新组合C.该反应可能是水的电解D.该反应前后元素的化合价不变( )10两种微粒的结构示意图是和,其中相同的是A.电子数B.质子数C.电子层数D.所带电荷数( )11.下列属于置换反应的是A.3CO + Fe2O3Error! 2Fe + 3CO2B.CH4 + 2O2Error! CO2 + 2H2OC.Zn + H2SO4 = ZnSO4 + H2↑D.Na2CO3 + CaCl2 = CaCO3↓+ 2NaCl( )12.将60℃的硝酸钾溶液降温至20℃,有晶体析出。
2015年成都某成外、成实外、成实外西区三校联合招生入学数学真卷和名师详解[28]
2015年成都某成外、成实外、成实外西区三校联考招生入学数学真卷(满分:120分时间:90分钟)A 卷(60分)一、判断(每小题2分,共12分)1.全明星投球比赛中,詹姆斯投出101个球,命中100个,命中率为100%。
( )2.一个长方形的长增加50%,宽减少了31,面积不变。
( ) 3.一个奇数和一个偶数,它们的最大公约数一定是奇数,最小公倍数一定是偶数。
( )4.(导学号 90672029)能把44颗糖分给10个小朋友,而且每人分到的糖的颗数都不一。
( )5.在右图中,圆柱和圆锥的体积相等。
( )6.(顺水速度一逆水速度)÷2=水速。
( )二、选择题。
(每小题2分,共12分)1.(导学号 90672030)如右图,一个棱长是4厘米的正方体,从它的一个顶点处挖去一个棱长是1厘米的正方体后,剩下物体的表面积和原来的表面积相比较( )。
A.大了B.小了C.不变D.无法确定2.下面的游戏( )是不公平的。
A.掷骰子,点数大于3甲赢,点数小于3乙赢。
B.抛硬币,正面朝上甲赢,反面朝上乙赢。
C.盒子里面有3个红球,5个黄球和2个白球,摸到黄球甲赢,摸到红球或白球乙赢。
3.小明班里的同学平均身高是1.4米,小强班里的同学平均身高是1.5米,小明和小强相比,( )。
A.小明高B.小明矮C.一样高D.无法确定4.半圆的周长是这个半圆直径的( )倍。
A.22+π B.2π C.π D.π2 5.在371、π、314%、∙∙41.3这四个数中,最大的数是( )。
A.371 B.π C.314% D.∙∙41.3 6.一列往返于成都和重庆之间的列车,全程停靠7个车站(包括起点站和终点站),共需准备( )种不同的车票。
A.14B.21C.42D.49三、填空(每小题3分,共36分)1.如果规定a*b=5×a-21×b ,其中a 、b 是自然数,那么10*6= 。
2.一桶油,第一天用去它的30%,第二天用去10千克,两天共用去这桶油的52,则用去两天后还剩 千克油。
四川省成都外国语学校初2015-2016学年初一下学期半期考试语文试题.doc
成都外国语学校2015-2016学年下期期中考试初一语文试卷命题人:晏光勇审题人:杜夕军注意事项:1.全卷分A卷和B卷,A卷满分100分,B卷满分50分;考试时间120分钟。
2.在作答前,考生务必将自己的姓名、准考证号涂写在试卷和答题卡规定的地方。
3.选择题部分必须使用2B铅笔填涂;非选择题部分必须使用0.5毫米黑色的签字笔书写,字体工整、笔迹清楚。
4.请按照题号在答题卡上各题目对应的答题区域内作答,超出答题区域书写的答案无效。
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A卷(共100分)第Ⅰ卷(选择题共24分)一、基础知识(每小题3分,共12分)1.下列加点字的注音全都正确的一项是()A.哺.育(bŭ)崎岖.(qū)骊.歌(lí)气冲斗.牛(dǒu)B.赫.然(hè)哽咽.(yè)蝉蜕.(tuì)锲.而不舍(qì)C.炽.痛(zhì)菜畦.(qí)花圃.(pŭ)义愤填膺.(yīn)D.污秽.(huì)亘.古(gèng)嫉.妒(jí)鲜.为人知(xiăn)2、下列词语中书写完全正确的一项是( )(2分)A、人声鼎沸万丈狂澜芳草萋萋锋芒必露B、迥乎不同亦复如是杂乱无章家喻户晓C、妇儒皆知鞠躬尽瘁寻欢作乐一反既往D、丛山叠岭一拍既合一泻万里博学多识3. 下列语句中加点的成语使用有误的一项是( )(2分)A、为了实现心中的梦想,在中考冲刺阶段,同学们刻苦学习,几乎达到了忘乎所以....的程度。
B、在乒乓球世锦赛中,李晓霞针对对手的特点,随机应变....,巧妙运用各种战术,赢得胜利。
C、人生路上有时山高难攀,海阔难越,只要我们锲而不舍....,定会登上理想之巅,到达梦想之岸。
D、四川爱乐交响乐团每月举办的免费音乐会,将音乐无与伦比....的美,带给了成都的广大市民。
4. 下面句子没有语病的一项是()A.能否杜绝“到此一游”这种不文明现象,关键是提升公民的文明素养。
2014-2015学年度下期成都外国语学校八年级水平监测语文试题(一)祥解
2014-2015学年度下期成都外国语学校八年级水平监测(一)语文试题本试卷分第I卷(选择题)和第Ⅱ卷(非选择题)两部分。
总分150分。
考试时间120分钟。
第Ⅰ卷(选择题,满分24分)注意事项:1.答题前,考生务必将自己的姓名、班级、考号用0.5毫米的黑色墨水签字笔填写在答题卡上。
并检查条形码粘贴是否正确。
2.选择题使用2B铅笔填涂在答题卡对应题目标号的位置上,非选择题用0.5毫米黑色墨水签字笔书写在答题卡对应框内,超出答题区域书写的答案无效;在草稿纸、试题卷上答题无效。
3.考试结束后,将答题卡收回。
一、选择题。
下面各题均有四个选项,其中只有一个符合题意,选出答案后在机读卡上用铅笔把对应题目的选项字母涂黑涂满。
(共24分,每小题3分)1.下列词语中加点的字读音正确..的一项是A.庇.护(pì) 哂.笑(xī) 解剖.(pōu) 即物起兴.(xìng)B.蜿.蜒(wǎn) 污秽.(huì) 执拗.(niù) 颔.首低眉(hán)C.模.样(mó) 迸.射(bèng) 挑衅.(xìn) 长吁.短叹(yū)D.吞噬.(shì) 真谛.(dì) 狩.猎(shòu) 雨后春笋.(sǔn)2.下列各组中没有错别字.....的一项是A.缄默不可思义引经踞典不值一提B.蓬蒿苍海桑田远见卓识全军覆没C.迁徙粗制滥造不容置疑心安理得D.憔悴一视同仁相形见拙孤漏寡闻3.依据对下列各组词语中加点字的解释,判断词语意思不正确...的一项是A.致.敬——致.意解释:“致”有“给予,向人表达”的意思。
判断:“致敬”指向人敬礼或表示敬意。
“致意”指向人表示问候之意。
B.熟.知——熟.视无睹解释:“熟”有“常见,清楚地知道”的意思。
判断:“熟知”指清楚地知道。
“熟视无睹”指虽然经常看到,却跟没有看初二语文试题第1页(共11页)见一样。
2015年成都外国语学校初升高直升考试
6题BA成都外国语学校2015年初升高直升考试考试时间:110分钟 满分:120分 姓名: 得分: . 一、选择题(共15小题,每小题3分,共45分) 1、53--的负倒数是 ( ) A .35- B .35 C .53- D .532、计算:32)(b a 的结果是 ( )A .b a 6B .36b aC .35b aD .32b a 3、在式子11-x ,21-x ,1-x ,2-x 中,可以取1和2的是 ( ) A .11-x B .21-x C .1-x D .2-x 4、97N H 病毒直径为30纳米(1纳米=910-米),用科学记数法表示这个病毒直径的大小,正确的是 ( )A .91030-⨯米B .8100.3-⨯米C .10100.3-⨯米D .9103.0-⨯米 5、16的平方根是 ( )A .4B .4-C .2D .2±6、如图,AB ∥CD ,点E 在BC 上,CE CD =,︒=∠74D ,则B ∠的度数为 ( )A .︒68B .︒32C .︒22D .︒167、已知0152=+-a a ,则31-+aa 的值为 ( )A .4B .3C .2D .18、在平面直角坐标系中,点P (2-,a )与点Q (b ,3)关于原点对称,则b a +的值为 ( )A .5B .5-C .1D .1- 9、下列命题中是真命题的是 ( )A .有理数都能表示成两个整数之比第(6)题图俯视图左视图主视图B .各边相等的多边形是正多边形C .等式两边同时乘以同一个实数,所得结果仍是等式D .相等的圆心角所对的弧相等,所对的弦相等 10、已知2=a ,3=b ,则5=-b a 的概率为 ( )A .0B .21C .31D .4111、某几何体的主视图.左视图和俯视图分别如下,则该几何体的体积为 ( )A .π3B .π2C .πD .1212、某校九年级共有1100名学生参加“二诊”考试,随机抽取50名学生进行总成绩统计,其中有20名学生总成绩达到优秀,估计这次“二诊”考试总成绩达到优秀的人数大约为 ( )A .400B .420C .440D .460 13、若1x .2x 是方程022=-+k x x 的两个不相等的实数根,则22221-+x x 是 ( )A .正数B .零C .负数D .不大于零的数 14、已知ABC ∆的三边长分别为a .b .c ,面积为s ;C B A '''∆的三边长分别为a '.b '.c ',面积为s ',且a a '>,b b '>,c c '>,则s 与s '的大小关系一定是 ( )A .s s '>B .s s '<C .s s '=D .不确定15.将一次函数b ax y +=与a bx y +=的图象画在同一个直角坐标系内,则能有一组a .b 的取值,使得如下四个图中为正确的是 ( )二、填空题(共5小题,每小题3分,共15分) 16、分解因式:=+-+a a a 8)3)(3( .A. B. C. D.17、如图,D 是ABC ∆的边BC 上一点,已知4=AB ,2=AD ,B DAC ∠=∠,若ABD ∆的面积为a ,ACD ∆的面积为 .18、若不等式⎩⎨⎧->+<121m x m x 无解,则m 的取值范围是 .19、在平面直角坐标系xOy 中,A (0,2),B (0,6),动点C 在直线x y -=上,若以A 、B 、C 三点为顶点的三角形是等腰三角形,则点C 的个数为 .20、设a x x x =++12(0≠a 且21≠a ),则1242++x x x 的值为 . 三、解答题(共8小题,共80分) 21、(每小题5分,共10分)(1)计算:02)14.3(45cos )21(30tan 360cos 2π-+︒---︒+︒⋅--(2)先化简,再求值)221(42122---÷-++x xx x x x ,其中x 为数据4,5,6,5,3,2的众数。
成都市2015年高中阶段教育学校统一招生考试
成都市二○一五年高中阶段教育学校统一招生考试(含成都市初三毕业会考)物理注意事项:1.全卷分A卷和B卷,A卷满分90分,B卷满分20分;全卷共110分;考试时间90分钟。
2.在作答前,考生务必将自己的姓名、准考证号涂写在试卷和答题卡规定的地方。
考试结束,监考人员将试卷和答题卡一并收回。
3.选择题部分必须使用2B铅笔填涂;非选择题部分必须使用0.5毫米黑色的签字笔书写,字体工整、笔迹清楚。
4.请按照题号在答题卡上各题目对应的答题区域内作答,超出答题区域书写的答案无效;在草稿纸、试卷上答题无效。
5.保持答题卡清洁,不得折叠、污染、破损等。
A卷(共90分)第I 卷(选择题,共28 分)一、单项选择题(每小题2分,共28分)1.下列现象与惯性有关的是A.小朋友喜欢看动画片B.投出的篮球在空中继续向前运动C.同种电荷相互排斥D.水银的温度升高时体积增大2.如图1所示,将正在发出声音的音叉放入水中,能观察到音叉周围溅起许多水花。
这说明A.发出声音的音叉在振动B.超声波具有能量C.声音从空气传入水中响度会变大D.声音从空气传入水中速度会变小3.关于电磁波与信息技术,下列叙述正确的是A.电磁波只能用于通信B.电磁波的应用对人类有利无害C.手机既能发射电磁波也能接收电磁波D.卫星通信不需要利用电磁波传递信息4.以下机械属于热机的是A.杠杆B.斜面C.洗衣机D.汽油机图15.如图2所示,直升飞机悬停在空中。
下列对直升飞机能量的分析,正确的是A .直升飞机具有重力势能B .直升飞机的动能不断转化为重力势能C .直升飞机的重力势能不断转化为动能D .直升飞机的机械能在不断增大6.下列做法中,符合安全用电要求的是A .将开关安装在灯具和中性线(零线)之间B .发生触电事故时,首先切断电源C .家中空气开关跳闸(断开)后马上将其闭合D .在高压线附近的空地放风筝7.对下列常见现象的分析,合理的是A .摩擦生热,是通过做功的方式改变内能B .围火取暖,是通过做功的方式改变内能C .雾霾弥漫,是因为分子在不停地运动D .雪花纷飞,是因为分子之间有排斥力作用8.下列现象中能说明存在大气压的是A. 火箭升空过程不断喷射高温燃气B. 坦克装有宽大的履带C. 医生推动活塞给病人注射药液D. 用吸管将杯中饮料吸入口中9.如图3所示,将一支铅笔放入水中,看起来铅笔发生了弯折。
成都外国语学校直升考试题_初三英语_英语_初中教育_教育专区
成都外国语学校直升考试题_初三英语_英语_初中教育_教育专区成都实验外国语学校直升考试题I. Multiple Choice.1. terrible weather we’ve been having these days.A. How aB. What aC. HowD. What 2. I keep medicines on the top shelf, out of the children’s .A. reachB. handC. holdD. place 3. He suddenly saw Sue the room. He pushed his way the crowd of people to get to her.A. across, acrossB. over; throughC. over, intoD. across, through4. Ideally for Broadway theatres and Fifth Avenue, the New York Park hotel is favourite with many guests.A. locatingB. being locatedC. having been locatedD. located. 5. Dogs have a very good of smell and are often used to search for survivors in an earthquake.A. senseB. viewC. meansD. idea 6. I am sure David will be able to find the library,he has a pretty good of direction.A. ideaB. feelingC. experienceD. sense 7. —Wow! I’ve burnt myself!—How did you do that?—I a hot pot.A. touchedB. keptC. feltD. held 8. Please remain until the plane has come to a complete stop.A. to seatB. to be seatedC. seatingD. seated 9. These oranges taste .A. goodB. wellC. to be goodD. to be well10. If by any chance someone comes to see me, ask him to leave a .A. messageB. letterC. sentenceD. notice 11. We the last bus and didn’t have any money for taxi, we had to walk home.A. reachedB. lostC. missedD. caught 12. The traffic lights green and I pulled away.A. cameB. grewC. gotD. went 13. —_____you ______him around the museum yet?— Yes. We had a great time there.A. Have showB. Do showC. Had showD. Did show 14. I can hardly hear the radio. Would you please ?A. turn it onB. turn I downC. turn it upD. turn it off 15. Mike didn’t play football yesterday because he had his leg.A. damagedB. hurtC. hitD. struck 16. —Why didn’t you b uy the camera you had longed for?—I had planned to, but I was ,50 .A. fewerB. lessC. cheapD. short 17. It is really to play computer games. But remember not to play too much. A. funs B. fun C. a fun D. funny1II. Fill in the blanks with the proper forms of the words given.1. The situation is very . All get about it. (worry)2. What us most is that nobody can find out the answer. (disappoint)3. To his , his son shouted at the guests. (embarrass)4. It is very to walk to the mountain carrying a heavy backpack. (tire)5. The movie us deeply. (move)6. Sorry, I forget (tell) you there would be a meeting.7.—Do remember _____ (tell) Tom to feed the bird.—Oh, I totally forgot _____ (buy) him a bird as a present.8.—Johnson, I’m in want of mon ey. Would you please return my money?—I remember ____ (not borrow) any from you.—But I do remember _____ (lend) you a 100-dollar note last Friday.—Yeah, I remember.II. Each of the following sentences has four underlined part labeled A, B, C and D. Identify the part is incorrect.1. Don’t worry. There is nothing much wrong to you .2. Eat the medicine twice a day and take it easy.3. In a few days you’ll be good.4. You need to have your blood checked.5. At present, there’s no effective cure of AIDS.6. The patient was diagnosed for heart trouble.7. The visitor has fallen ill since he came here.8. How long have you caught a cold?9. After operation, he was in the hospital for a fortnight. 10. My grandma keeps on taking exercise and is in a good health.11.The thief stole my pocket in the crowd.12.The robber was put into the prison.13.The foxy guy cheated me from my money.14.The prison is not the only effective way to prevent crimes.15.The eyewitness failed to give enough evidences in court.16. Bush was elected the president again.17. The kingdom had been under control of the king for forty years before his death. 18. The citizens considered the project profitable, so they voted against it.19. Women should be equal with men in all fields.20.The governments at all levels ought to lay stress on(重视) education. IV. Reading comprehensionAMany people go to school for an education. They learn languages, history, geography, physics, chemistry and mathematics. Others go to school to learn a skill so that they can make a living. School education is very important and useful. Yet no one can learn everything from school. A teacher, no matter how much he knows cannot teach his students everything they want to know. The teacher’s job is to show his students how to learn. Heteaches them how to read and how to think. So much more is to be learned outside school by the students themselves.It is always more important to study by oneself that to memorize some facts or a formula (公式). It is2actually quite easy to learn a certain fact in history or a formula in math. But it is very difficult to use a formula in working out a math problem. Great scientists, such as Einstein, Newton and Galileo didn’t get everything fromschool. But they were all so successful. They invented so manythings for mankind. The reason for their success is that they worked hard all their lives, wasting not a single moment. They would ask many questions as they read and they did thousands of experiments.Above all, they knew how to use their brains.1. The subject which is not spoken of in the article is _________.A. mathB. historyC. physiologyD. physics2. The teacher’s job is to reach __________.A. everything the students want to knowB. the students everything that they knowC. the students some facts of formulasD. the students how to learn3. Einstein, Newton and Galileo did so many things for mankind because __________.A. they learned a lot at schoolB. they knew how to learn new things outside class by themselvesC. they were so usefulD. they went to college and learned from professors4. From the passage we know that if we want to be successful, we should ___________.A. only learn more at schoolB. needn’t go to schoolC. only learn science subjectsD. learn to learn at school and learn more outside schoolBFrance has been one of the main pioneers of many forms of artistic expression throughout its history. France and art are strongly connected with each other, and it would not be possible to think of world art without thinking of France.The importance of art in France can be easily seen by the great number of museums and art exhibitions throughout the country. They include the Musee du Louvre, which is one of the greatest museums of the world. There is also the Musee du Moyen Age in this list, which exhibits medieval artworks, and the Centre Pompidou, exhibiting art from the twentieth century. Among other important museums and exhibitions are the Musee d’Orsay,where visitors can observe a collection of French art from the 20th century, and the Musee Picasso, which exhibits amazing artworks fromthis outstanding artist. The Musee Rodin is another great place to visit in order to enjoy French art and to observe some amazing sculptures from this artist.The relation between France and art can be traced back to as long ago as the Stone Age. Many artworks dating from this period have been found in France and provide unique information about the culture and art of the world. In France, each time was strongly connected with art andhad its own art expression forms and characteristics, and they were closely connected with French history and culture.36. We can learn from the first paragraph that _____________.A. France is famous for its artB. France has the greatest museum of the worldC. French art plays an important role in world artD. France has the largest number of famous artists37. How many museums are mentioned in the passage in total?A.4.B.5.C.6.D.7.38. If you want to observe some amazing sculptures, which of the following places should you visit?A. The Musee d'Orsay.B. The Musee du Moyen Age.C. The Centre Pompidou.D. The Mus6e Rodin.39. It is implied in the last paragraph that _____________.A. France has the longest history of art in the world3B. artworks from the Stone Age are the most valuableC. French people now don't think art is important in their livesD. in France different periods of time have different styles of art40. In which section of a newspaper would you most probably readthis passage?A. Business.B. Education.C. Art.D. GeographyCIf there is one thing I'm sure about, it is that in a hundred years from now we will still be reading newspapers. Now some people get mostof their news from television or radio. Many buy a newspaper only on Saturday or Sunday. But for most people reading a newspaper has become a habit passed down from generation to generation.The nature of what is news may change. What basically makes news is what affects our lives-the big political stories, the coverage of the wars, earthquakes and other disasters, will continue much the same. I think there will be more coverage of scientific researches, though. It's already happening in areas that may directly affect our lives, like genetic engineering. In the future, I think there will be more coverage of scientific explanations of why we feel as we do-as we develop abetter understanding of how the brain operates and what our feelings really are.It's quite possible that in the next century newspapers will be transmitted (传递) electronically from FleetStreet and printed out in our own homes. In fact, I'm pretty surehow it will happen in the future. You will probably be able to choose from a menu, making up your own newspaper by picking out the things you want to read----sports and international news, etc.I think people have got it wrong when they talk about thecompetition among the different media. They actually feed off each other. It was once predicted that television would kill off newspapers, butthat hasn't happened. What is read on the printed page lasts longer thanpictures on a screen or sound lost in the air. And as for the Internet,it's never really pleasant to read something just on a screen.41. What is the best title for the passage?A. The Best Way to Get NewsB. The Changes of MediaC. Make Your Own NewspapersD. The Future of Newspapers42. In the writer's opinion, in the future, ______________.A. more big political affairs, wars and disasters will make newsB. newspapers will not be printed in publishing houses any longerC. newspapers will cover more scientific researchesD. more and more people will watch TV43. What will probably be on in the newspaper made by yourself?A. Sports and international news.B. A menu of important news.C. The most important news.D. What you are interested in.44. From the passage, we can infer ______________.A. newspapers will win the competition among the different mediaB. newspapers will stay with us together with other mediaC. television will take the place of newspaperD. the writer believes some media will die out45. The phrase "feed off" in the last paragraph means ______________.A. supportB. divideC. separateD. break up4。
成都外国语学校初2015级中考直升模拟试题
成都外国语学校初2015级直升模拟试题一、选择题(每小题3分,共30分)1、若干小正方体堆成的立体图形主视图和左视图如图所示,则组成这个立体图形的小立方体的个数最少是()A 、3个B 、4个C 、5个D 、6个2、要使1321xx 有意义,则x 应满足()A 、132xB 、3x且12xC 、132x D 、132x 3、如图,四边形BDCE 内接于以BC 为直径的A ,已知:10BC,3cos 5BCD ,30BCE ,则线段DE 的长是()A 、89B 、73C 、433D 、3434、已知0a b ,xa bb ,ybb a ,则x ,y 的大小关系是()A 、x yB 、xyC 、xyD 、与a 、b 的取值有关5、方程2122xx x实数根的情况是()A 、仅有三个不同实根B 、仅有两个不同实根C 、仅有一个实根D 、无实根6、一次函数4ykx与反比例函数k yx的图像有两个不同的交点,点11,2y 、21,y 、31,2y 是双曲线229ky x上的三点,则1y 、2y 、3y 的大小关系是()A 、231y y y B 、123y y y C 、312y y y D 、321y y y 7、如图,已知O 的半径为R ,C 、D 是直径AB 同侧圆周上的两点,AC 的度数为96°,BD 的度数为36°,动点P 在AB 上,则PC PD 的最小值()A 、RB 、21RC 、2RD 、3R8、若多项式4316xmxnx 含有因式2x 和1x ,则mn 的值是()A 、100B 、0C 、-100D 、50 9、如图,在正方形纸片ABCD 中,对角线AC 、BD 交于点O ,折叠正方形纸片ABCD ,使AD 落在BD 上,点A 恰好与BD 上的点F 重合,展开后折痕DE 分别角AB 、AC 于点E 、G ,连接GF 。
下列结论①∠ADG=22.5°;AO DCPB主视图左视图②tan ∠AED=2;③S △AGD =S △OGD ;④四边形AEFG 是菱形;⑤BE=2OG。
成都市2015年高中阶段招生考试(暨初三毕业会考)
成都市2015年高中阶段招生考试(暨初三毕业会考)A 卷(共100分)第一部分听力(共30小题,计25分)一、听句子,根据所听到的内容选择正确答语。
每小题念两遍。
(共6小题,每小题1分;计6分)1.A.Yes, I am. B.Yes, this is Mike. C.Yes, are you Joe? 2.A.It’s sunny. B.I like the weather. C.It’s the weather report. 3.A.Sorry, it isn’t. B.Yes , it is. C.Yes, there’s one near the bank.4.A.Nice to meet you. B.Yes, she is. C.I don’t know her. 5.A.It doesn’t matter.B.I know it. C.OK, let’s go. 6.A.I’d like to.B.C offee, please. C.Here you are.二、听句子,选择与所听句子内容相符的图片,并将代表图片的字母填涂在答题卡的相应位置。
每小题念两遍。
(共4小题,每小题1分;计4分)A B C D7.___________ 8.___________ 9.___________ 10.___________三、听对话,根据对话内容及问题选择正确答案。
每小题念两遍。
(共10小题,每小题0.5分;计5分)11.A.Yellow. B.White. C.Red.12.A.On foot. B.By bus. C.B y bike. 13.A.Look for a new job. B.Welcome the customers.C.Stand for a long time.14.A.2 yuan. B.10 yuan C.20 yuan15.A.At7:30 B.A t 8:00 C.At 8:3016.A.In a shop B.A t the library C.I n a bookstore 17.A.Go to the cinema B.Go shopping C.G o swimming 18.A.Friday B.Saturday C.S unny 19.A.Helpful B.Friendly C.B eautiful 20.A.Looking for a backpack B.Packing the backpackC.Preparing the sweaters.四、听短文,根据短文内容选择正确答案。
成都外国语学校高中招生考试 成外直升3
A.1 个
B.2 个
C.3 个
D.4 个
9. 如图,王华晚上由路灯 A 下的 B 处走到 C 处时,测得影子 CD 的长为 1 米,
继续往前走 3 米到达 E 处时,测得影子 EF 的长为 2 米,已知王华的身高是 1.5
米,那么路灯 A 的高度 AB 等于( )
A.4.5 米
B.6 米
C.7.2 米
B 卷(共 50 分)
一、填空题(本大题共 5 个小题,每小题 4 分,共 20 分)
21. 关于 x 方程 (x2 x 1)x3 1的解是 x=____________
22.关于
x
的不等式组
1
3
1
2
(2x 5) x 1 (x 3) x a
的所有整数解的和为-5,则
A.
B.
C.
D.
4.已知一组数据从小到大依次为-1,0,4,x,6,15,其中位数为 5,则其众数为( )
A.4
B.5
C.5.5
D.6
5.函数 y 2x 3 2(x 3)0 的取值范围是( x 1
A. x 1且 x 3
B. x 3 且 x 1,x 3 2
) C. x 3 且 x 1
(3)已知互相平行的直线 y=x-2 与 y=x+b 之间的距离是 3 2 ,试求 b 的值。
18. (8 分)如图,隧道的截面由抛物线和长方形构成,长方形的长为 12m,宽为 5m,抛物线的最高点 C 离路面 AA1 的距离为 8m,建立如图所示的直角坐标系。 (1)求该抛物线的函数表达式,并求出自变量 x 的取值范围; (2)一大型货运汽车装载大型设备后高为 6m,宽为 4m. 如果该 隧道内设双向行车道,那么这辆货车能否安全通过?
2015年成都市成都实验外国语学校直升考试数学试卷(含解析)
2015年成都市成都实验外国语学校直升考试数学试卷(考试时间:110分钟满分:120分)第Ⅰ卷(选择题,共30分)一、选择题(每小题3分,共30分)1.在函数中,自变量x的取值范围是()A.x≥﹣1 B.x>﹣1且x≠C.x≥﹣1且x≠D.x>﹣12.下列各式计算正确的是()A.m2•m3=m6B.C.D.(a<1)3.对于实数x,我们规定[x]表示不大于x的最大整数,例如[1.2]=1,[3]=3,[﹣2.5]=﹣3,若[]=5,则x的取值可以是()A.40 B.45 C.51 D.564.设a>b>0,a2+b2=3ab,则的值为()A.B.C.2 D.5.设x1、x2是关于x的一元二次方程x2+x+n﹣2=mx的两个实数根,且x1<0,x2﹣x1<0,则()A.B.C.D.6.如图所示,已知A(,y1),B(2,y2)为反比例函数y=图象上的两点,动点P(x,0)在x轴正半轴上运动,当线段AP与线段BP之差达到最大时,点P的坐标是()A.(,0)B.(1,0)C.(,0)D.(,0)7.已知:D是半圆O的直径AB上的一点,OD=OA,CD⊥AB,弧AC=弧CF,AF交CD于E,连OE,则tan ∠DOE=()A.B.2C.D.18.如图,正方形ABCD的边长为a,动点P从点A出发,沿折线A→B→D→C→A的路径运动,回到点A时运动停止.设点P运动的路程长为x,AP长为y,则y关于x的函数图象大致是()A.B.C.D.9.如图,等腰梯形纸片ABCD,AD∥BC,AD=3,BC=7,折叠纸片,使点B与点D重合,折痕为EF,若DF ⊥BC,则下列结论:①EF∥AC;②DE⊥AC;③△AED~△DAC;④EF=3;⑤梯形ABCD的面积为25,其中正确的是()A.①③④B.①②⑤C.③④D.①⑤10.已知函数y=|8﹣2x﹣x2|和y=kx+k(k为常数),则不论k为何值,这两个函数的图象()A.有且只有一个交点B.有且只有二个交点C.有且只有三个交点D.有且只有四个交点第Ⅱ卷(非选择题,共90分)二、填空题(每小题3分,共30分)11.若x2+2x﹣=5,则x2+2x=.12.计算:﹣3tan230°+2×|﹣|+(﹣2)0﹣(﹣1)2009=.13.已知关于x的分式方程的解为正数,则a的范围为14.关于x的不等式组只有4个整数解,则a的取值范围是.15.如果m是从0,1,2,3四个数中任取的一个数,n是从0,1,2三个数中任取的一个数,那么关于x 的一元二次方程x2﹣2mx+n2=0有实数根的概率为.16.如图,平行四边形ABCD的对角线交于O点,过O任作一直线与CD、BC的延长线分别交于F、E点,设BC=a,CD=b,CE=c,则CF=.17.已知二次函数y=ax2+bx+c的图象与x轴交于点(﹣2,0),(x1,0)且1<x1<2,与y轴正半轴的交点在(0,2)的下方,下列结论:①a<b<c;②b2﹣4ac>﹣8a;③4a+c<0;④2a﹣b+1<0.其中正确结论是(填写序号).18.已知二次函数的图象开口向上且不过原点O,顶点(1,﹣2),与x轴交于A,B,与y轴交于点C,且满足关系式OC2=OA•OB,则第二次函数的解析式为.19.如图,在正方形ABCD中,△AEF的顶点E,F分别在BC,CD边上,高AG与正方形的边长相等,连接BD分别交AE,AF于点M,N.若EG=4,GF=6,BM=3,则AG=,MN=.20.如图,A、P、B、C是⊙O上的四点,∠APC=∠BPC=60°,AB与PC交于Q点.若∠ABP=15°,△ABC 的面积为4,则PC的长是.三、解答题(共60分)21.(10分)先化简,再求值:(﹣)÷(1+),其中a2﹣4ab+5b2+b+=0.22.(10分)已知:对于x的所有实数值,二次函数y=x2﹣4ax+2a+12(a为实数)的值都是非负的,求关于x的方程=|a﹣1|+2的根的取值范围.23.(10分)设m是不小于﹣1的实数,关于x的方程x2+2(m﹣2)x+m2﹣3m+3=0有两个不相等的实数根x1、x2,(1)若x12+x22=6,求m值;(2)求的最大值.24.(10分)由于国家重点扶持节能环保产业,某种节能产品的销售市场逐渐回暖,某经销商销售这种产品,年初与生产厂家签订了一份进货合同,约定一年内进价为0.1万元/台,并预付了5万元押金.他计划一年内要达到一定的销售量,且完成此销售量所用的进货总金额加上押金控制在不低于34万元,但不高于40万元.若一年内该产品的售价y(万元/台)与月次x(1≤x≤12且为整数)满足关系式:y=,一年后发现实际每月的销售量p(台)与月次x之间存在如图所示的变化趋势.(1)直接写出实际每月的销售量p(台)与月次x之间的函数关系式;(2)求前三个月中每月的实际销售利润w(万元)与月次x之间的函数关系式;(3)试判断全年哪一个月的售价最高,并指出最高售价;(4)请通过计算说明他这一年是否完成了年初计划的销售量.25.(10分)如图甲,⊙O中AB是直径,C是⊙O上一点,∠ABC=45°,等腰直角△DCE中,∠DCE是直角,点D在线段AC上.(1)问B、C、E三点在一条直线上吗?为什么?(2)若M是线段BE的中点,N是线段AD的中点,直接写出的值;(3)将△DCE绕点C逆时针旋转α(0°<α<90°)后,记为△D1CE1(图乙),若M1是线段BE1的中点,N1是线段AD1的中点,则的值是否变化?若变化求其值;若不变,证明你的结论.26.(10分)如图,二次函数y=ax2+bx+c(a≠0)的图象与x轴交于A、B两点,与y轴相交于点C.连接AC、BC,A、C两点的坐标分别为A(﹣3,0)、C(0,),且当x=﹣4和x=2时二次函数的函数值y相等.(1)求实数a,b,c的值;(2)若点M、N同时从B点出发,均以每秒1个单位长度的速度分别沿BA、BC边运动,其中一个点到达终点时,另一点也随之停止运动.当运动时间为t秒时,连接MN,将△BMN沿MN翻折,B点恰好落在AC边上的P处,求t的值及点P的坐标;(3)在(2)的条件下,二次函数图象的对称轴上是否存在点Q,使得以B,N,Q为顶点的三角形与△ABC 相似?如果存在,请求出点Q的坐标;如果不存在,请说明理由.参考答案与试题解析1.【解答】解:由题意得,x+1≥0且2x﹣1≠0,解得x≥﹣1且x≠.故选:C.2.【解答】解:A、m2•m3=m5,故选项错误;B、==,故选项错误;C、=,故选项错误;D、正确.故选:D.3.【解答】解:根据题意得:5≤<5+1,解得:46≤x<56,故选:C.4.【解答】解:∵a2+b2=3ab,∴a2+b2﹣2ab=ab,a2+b2+2ab=5ab,∴(a﹣b)2=ab,(a+b)2=5ab,∵a>b>0,∴a﹣b>0,a+b>0,∴a﹣b=,a+b=,∴故选:D.5.【解答】解:∵x2﹣x1<0,∴x2<x1,∵x1<0,∴x2<0.∵x1,x2是关于x的一元二次方程x2+x+n﹣2=mx,即x2+(1﹣m)x+n﹣2=0的两个实数根,∴x1+x2=m﹣1,x1x2=n﹣2,∴m﹣1<0,n﹣2>0,解得:.故选:C.6.【解答】解:∵把A(,y1),B(2,y2)代入反比例函数y=得:y1=2,y2=,∴A(,2),B(2,),∵在△ABP中,由三角形的三边关系定理得:|AP﹣BP|<AB,∴延长AB交x轴于P′,当P在P′点时,PA﹣PB=AB,即此时线段AP与线段BP之差达到最大,设直线AB的解析式是y=kx+b,把A、B的坐标代入得:,解得:k=﹣1,b=,∴直线AB的解析式是y=﹣x+,当y=0时,x=,即P(,0),故选:D.7.【解答】解:连接AC,BC∵∠CAE=∠ABC∵∠ACE=∠ABC∴∠CAE=∠ACE∴AE=CE设圆的半径是3,则OD=1,AD=2,DB=4,∴CD===2在直角三角形ADE中,设DE=x,则AE=CE=2﹣x,由勾股定理,得AD2+DE2=AE2,即22+x2=(2﹣x)2,解得x=DE=∴tan∠DOE=.故选:A.8.【解答】解:设动点P按沿折线A→B→D→C→A的路径运动,∵正方形ABCD的边长为a,∴BD=a,①当P点在AB上,即0≤x<a时,y=x,②当P点在BD上,即a≤x<(1+)a时,过P点作PF⊥AB,垂足为F,∵AB+BP=x,AB=a,∴BP=x﹣a,∵AE2+PE2=AP2,∴()2+[a﹣(x﹣a)]2=y2,∴y=,③当P点在DC上,即a(1+)≤x<a(2+)时,同理根据勾股定理可得AP2=AD2+DP2,y=,④当P点在CA上,即当a(2+)≤x≤a(2+2)时,y=a(2+2)﹣x,结合函数解析式可以得出第2,3段函数解析式不同,得出A选项一定错误,根据当a≤x<(1+)a时,P在BE上和ED上时的函数图象对称,故B选项错误,再利用第4段函数为一次函数得出,故C选项一定错误,故只有D符合要求,故选:D.9.【解答】解:如图,过点A作AH⊥BC于H,∵四边形ABCD是等腰梯形,∴AB=CD,∠B=∠DCB,且∠AHB=∠DFC=90°,∴△ABH≌△DCF(AAS)∴BH=CF,∵AH⊥BC,DF⊥BC,∴AH∥DF,且AD∥BC,∴四边形AHFD是平行四边形,∴AH=DF,AD=HF=3,∴BH=CF=(BC﹣HF)=2,∴BF=5=CH,∵折叠纸片,使点B与点D重合,∴DF=BF=5,∠BFE=∠DFE=45°,∴AH=5,∴AH=CH=5,∴∠ACB=45°,∴∠EFB=∠ACB=45°,∴AC∥EF,故①正确;∵梯形ABCD的面积===25,∴⑤正确,∵折叠纸片,使点B与点D重合,∴∠BEF=∠DEF≠90°,∴DE不垂直EF,∴DE与AC也不垂直,故②错误;若△AED~△DAC,则∠DAC=∠AED=45°,∴∠DEF=∠BEF=67.5°,∴∠ABC=∠BAC=67.5°,∴BC=AC=7,∵AH=CH=5,∴AC=5≠7,∴△AED与△DAC不相似,故③错误;如图,过点E作EN⊥BC于N,∵EN⊥BC,AH⊥BC,∴AH∥EN,∴△BEN∽△BAH,∴∴∴设BN=2x,BN=5x,∵∠EFB=45°,EN⊥BC,∴△ENF是等腰直角三角形,∴EN=NF=5x,EF=EN=5x,∴BF=BN+NF=7x=5,∴x=,∴EF=,故④错误,故选:D.10.【解答】解:函数y=8﹣2x﹣x2中,令y=0,解得:x=﹣4或2.则二次函数与x轴的交点坐标是(﹣4,0)和(2,0).则函数的图象如图.一次函数y=kx+k(k为常数)中,令y=0,解得:x=﹣1,故这个函数一定经过点(﹣1,0).经过(﹣1,0)的直线无论k多大,都是2个交点.故选:B.11.【解答】解:设t=x2+2x,则t+=5,整理,得(t﹣8)(t+3)=0,解得t1=8,t2=﹣3,经检验t1=8,t2=﹣3都是原方程的解.即x2+2x=8或x2+2x=﹣3.由于x2+2x=﹣3无解,所以x2+2x=8.故答案是:8.12.【解答】解:原式=+1﹣3×()2+2(1﹣)×+1﹣(﹣1)=+1﹣1+﹣+1+1=+﹣+2.故答案为+﹣+2.13.【解答】解:方程去分母得:(x+1)(x﹣1)﹣x(x+2)=a,去括号、移项、合并同类项得:2x=﹣(1+a),解得:x=﹣,∵x>0,∴﹣>0解得:a<﹣1,又∵分母x﹣1≠0,∴x≠1,即﹣≠1,解得a≠﹣3,则a的范围为a<﹣1且a≠﹣3.14.【解答】解:,由①得:x<21,由②得:x>2﹣3a,∴不等式组的解集为:2﹣3a<x<21,∵不等式组只有四个整数解,即:20,19,18,17,∴16≤2﹣3a<17,∴﹣5<a≤﹣.故答案为:﹣5<a≤﹣.15.【解答】解:从0,1,2,3四个数中任取的一个数,从0,1,2三个数中任取的一个数则共有:4×3=12种结果,∵满足关于x的一元二次方程x2﹣2mx+n2=0有实数根,则△=(﹣2m)2﹣4n2=4(m2﹣n2)≥0,符合的有9个,∴关于x的一元二次方程x2﹣2mx+n2=0有实数根的概率为.16.【解答】解:过O作OG∥CD,则△CEF∽△GEO,∴=,∵GO=AB=b,EG=c+a,∴CF=,故答案为:.17.【解答】解:①因为图象与x轴两交点为(﹣2,0),(x1,0),且1<x1<2,对称轴x==﹣,则对称轴﹣<﹣<0,且a<0,∴a<b<0,由抛物线与y轴的正半轴的交点在(0,2)的下方,得c>0,即a<b<c,①正确;②假设b2﹣4ac>﹣8a成立,由于a<0,所以4ac﹣b2<8a,∴>2,∴抛物线的顶点纵坐标应该大于2,由题可知:抛物线与y轴的正半轴的交点在(0,2)的下方,抛物线的对称轴大于﹣1∴顶点一定在这个交点的上方,但不代表顶点纵坐标应该大于2.∴假设不成立,即②错误;③设x2=﹣2,则x1x2=,而1<x1<2,∴﹣4<x1x2<﹣2,∴﹣4<<﹣2,∴2a+c>0,4a+c<0.∴③正确;④抛物线过(﹣2,0),则4a﹣2b+c=0,而c<2,则4a﹣2b+2>0,即2a﹣b+1>0.④错误.故答案为:①③.18.【解答】解:∵抛物线顶点坐标为(1,﹣2),设顶点式为y=a(x﹣1)2﹣2=ax2﹣2ax+a﹣2,A(x1,0),B(x2,0),则x1x2=,C(0,a﹣2),由OC2=OA•OB,得(a﹣2)2=|x1x2|=||,即a3﹣4a2+4a=|a﹣2|,当0<a<2时,有a3﹣4a2+5a﹣2=0即(a﹣1)2(a﹣2)=0,解得a1=1或a2=2(舍去)由a=1得y=x2﹣2x﹣1;当a>2时,有a3﹣4a2+3a+2=0即(a﹣2)(a2﹣2a﹣1)=0解得a1=2(舍去),a2=1+,a3=1﹣(舍去),故a=1+,y=(1+)x2﹣(2+2)x+﹣1,故所求二次函数解析式为:y=x2﹣2x﹣1或y=(1+)x2﹣(2+2)x+﹣1;故答案为:y=x2﹣2x﹣1或y=(1+)x2﹣(2+2)x+﹣1.19.【解答】解:(1)在Rt△ABE和Rt△AGE中,,∴Rt△ABE≌Rt△AGE(HL).∴∠BAE=∠GAE,BE=EG=4,同理,∠GAF=∠DAF,GF=DF=6,∴∠EAF=∠BAD=45°.设AG=x,则CE=x﹣4,CF=x﹣6.在Rt△CEF中,∵CE2+CF2=EF2,∴(x﹣4)2+(x﹣6)2=102.解得x1=12,x2=﹣2(舍去负根).即AG=12.在Rt△ABD中,∴BD===12.将△ADN绕点A顺时针旋转90°至△ABH位置,连接MH,由旋转知:∠BAH=∠DAN,AH=AN,∵四边形ABCD是正方形,∴∠BAD=90°,∵∠EAF=45°,∴∠BAM+∠DAN=45°,∴∠HAM=∠BAM+∠BAH=45°,∴∠HAM=∠NAM,又AM=AM,∴△AHM≌△ANM,∴MN=MH∵四边形ABCD是正方形,∴∠ADB=∠ABD=45°由旋转知:∠ABH=∠ADB=45°,HB=ND,∴∠HBM=∠ABH+∠ABD=90°,∴MH2=HB2+ND2,∴MN2=MB2+ND2;设MN=a,则a2=(12﹣3﹣a)2+(3)2.即a2=(9﹣a)2+(3)2,∴a=5,即MN=5.故答案为12,5.20.【解答】解:∵∠ABC=∠APC=60°,∠BAC=∠BPC=60°,∴∠ACB=180°﹣∠ABC﹣∠BAC=60°,∴△ABC是等边三角形;设正△ABC的高为h,则h=BC•sin60°.∵BC•h=4,即BC•BC•sin60°=4,解得BC=4,连接OB,OC,OP,作OE⊥BC于E,由△ABC是正三角形知∠BOC=120°,从而得∠OCE=30°,∴OC==,由∠ABP=15°得∠PBC=∠ABC+∠ABP=75°,于是∠POC=2∠PBC=150°,∴∠PCO=(180°﹣150°)÷2=15°,如图,作等腰直角△RMN,在直角边RM上取点G,使∠GNM=15°,则∠RNG=30°,作GH⊥RN,垂足为H.设GH=1,则cos∠GNM=cos15°=,NH=GN•cos30°=,在Rt△RGH中,RH=GH=1,MN=RN•sin45°=(1+)×=,∴cos15°=.在图中,作OF⊥PC于F,∴PC=2CF=2OC•cos15°=2+.故答案为2+.21.【解答】解:原式=•=,已知等式a2﹣4ab+5b2+b+=0,整理得:(a﹣2b)2+(b+)2=0,可得a=2b,b=﹣,解得:a=﹣1,b=﹣,则原式=﹣.22.【解答】解:∵对于x的所有实数值,二次函数y=x2﹣4ax+2a+12(a为实数)的值都是非负的,∴△=16a2﹣8a﹣48≤0,∴,当a=2时,a﹣2=0,则关于x的方程=|a﹣1|+2无意义,舍去;当1≤a<2时,由=|a﹣1|+2得,x=(a﹣2)(a﹣1)+2(a﹣2),即x=a2﹣a﹣2=(a﹣)2﹣,由二次函数的性质知,﹣2≤x<0;当﹣时,由由=|a﹣1|+2得,x=(a﹣2)(1﹣a)+2(a﹣2),即x=﹣a2+5a﹣6=﹣(a﹣)2+,由二次函数的性质知,﹣≤x<﹣2;综上,﹣≤x<0.23.【解答】解:∵方程有两个不相等的实数根,∴△=b2﹣4ac=4(m﹣2)2﹣4(m2﹣3m+3)=﹣4m+4>0,∴m<1,结合题意知:﹣1≤m<1.(1)∵x12+x22=(x1+x2)2﹣2x1x2=4(m﹣2)2﹣2(m2﹣3m+3)=2m2﹣10m+10=6∴,∵﹣1≤m<1,∴;(2)==(﹣1≤m<1).∵对称轴m=,2>0,∴当m=﹣1时,式子取最大值为10.24.【解答】解:(1)由题意得:;(2)w=(﹣0.05x+0.25﹣0.1)(﹣5x+40)=(x﹣3)(x﹣8)=即w与x间的函数关系式w=;(3)①当1≤x<4时,y=﹣0.05x+0.25中y随x的增大而减小∴x=1时,y最大=0.2②当4≤x≤6时,y=0.1万元,保持不变③当6<x≤12时,y=0.015x+0.01中y随x的增大而增大∴x=12时,y最大=0.015×12+0.01=0.19综合得:全年1月份售价最高,最高为0.2万元/台;(4)设全年计划销售量为a台,则:34≤0.1a+5≤40解得:290≤a≤350∵全年的实际销售量为:35+30+25+20+22+24+26+28+30+32+34+36=342(台)>290台∴这一年他完成了年初计划的销售量.25.【解答】解:(1)B、C、E三点在一条直线上.理由如下:∵AB为⊙O直径,∴∠ACB=90°,∵△DCE为等腰直角三角形,∴∠ACE=90°,∴∠BCE=90°+90°=180°,∴B、C、E三点共线.(2)连接BD,AE,ON,并延长BD交AE于F,∵∠ACB=90°,∠ABC=45°,∴BC=AC,在△BCD和△ACE中,∵,∴△BCD≌△ACE(SAS),∴AE=BD,∠DBE=∠EAC,∴∠AEB+∠EBD=90°,∴BD⊥AE,∵O,N为中点,∴ON∥BD,ON=BD,同理:OM∥AE,OM=AE,∴OM⊥ON,OM=ON,∴MN=OM,∴=,(3)的值不变化.理由如下:连接BD1,AE1,ON1,延长BD1交AE于点F,和(2)一样,易证得△BCD1≌△ACE1,∴∠E1AC=∠FBC,∠BD1C=∠AE1C,∴∠E1FB+∠AE1C+∠D1BC+90°+∠D1CB=360°(四边形内角和定理),又∵∠AE1C+∠D1BC+∠D1CB=180°,∴∠E1FB+90°+180°=360°,∴∠E1FB=90°,∴BD1⊥AE1,可得△ON1M1为等腰直角三角形,从而有M1N1=OM1.∴=.26.【解答】解:(1)∵C(0,)在抛物线上∴代入得c=,∵x=﹣4和x=2时二次函数的函数值y相等,∴顶点横坐标x==﹣1,∴,又∵A(﹣3,0)在抛物线上,∴=0由以上二式得a=,b=,c=;(2)由(1)y==∴B(1,0),连接BP交MN于点O1,根据折叠的性质可得:O1也为PB中点.设t秒后有M(1﹣t,0),N(1﹣,),O1)设P(x,y),B(1,0)∵O1为P、B的中点可得,,即P()∵A,C点坐标知AC:y=,P点也在直线AC上代入得t=,即P();(3)假设成立;①若有△ACB∽△QNB,则有∠ABC=∠QBN,∴Q点在x轴上,AC∥QN但由题中A,C,Q,N坐标知直线的一次项系数为:则△ACB不与△QNB相似.②若有△ACB∽△QBN,则有 (1)设Q(﹣1,y),C(0,),A(﹣3,0),B(1,0),N()则CB=2,AB=4,AC=2代入(1)得y=2或.当y=2时有Q(﹣1,2)则QB=4⇒不满足相似舍去;当y=时有Q(﹣1,)则QB=⇒.∴存在点Q(﹣1,)使△ACB∽△QBN.综上可得:(﹣1,).。
成都外国语学校初三年级直升考试物理模拟训练试题2 力学综合 电学综合 中考模拟 自主招生(答案在文末)
成都外国语学校初升高招生考试物理试卷考前模拟综合训练物理培优2一、单选题1.用如图所示滑轮组提起重300N的货物,人所用的拉力为200N,当物体上升1m高度时(不计绳重和摩擦),在此过程中下面说法正确的是()A.拉力所做的总功为200 J B.提升货物所做的有用功为300J C.额外功为50J D.滑轮组的机械效率为80%2.如图所示,圆柱体甲和装有适量某液体的圆柱形容器乙的底面积之比为3:4,把它们平放在同一水平桌面上。
在甲物体上,沿水平方向截取一段长为x的物体A,并平稳放入容器乙中,用力使物体A刚好浸没在液体中(A不与容器乙接触,液体无溢出)。
截取后,甲、乙对桌面的压强截取长度x的变化关系如图所示。
已知甲的密度为0.6×103kg/m3,容器乙壁厚和质量均忽略不计,g取10N/kg。
下列说法正确的是A.圆柱体甲截取前和容器乙中的液体质量之比为3:2B.圆柱体甲截取前对桌面的压强为1000PaC.容器乙中液体的密度为0.4×103kg/m3D.容器乙中未放入物体A时,液体的深度为8cm3.下列说法中正确的是()A.接触的物体间才会产生力的作用,不接触的物体间不会有力的作用B.重力的方向一定竖直向下的C.弹簧测力计只能沿竖直或水平方向使用,不能倾斜使用D.PM2.5属于分子的热运动4.你认为下列数据中最接近事实的是()A.某同学正常的体温是47℃B.人的大拇指指甲宽约为1cmC.人的正常步行速度是4m/sD.健康人的脉搏,1s跳动75次左右5.如图所示,两灯泡均能正常工作,下列说法正确的是A.1、2是电流表,3是电压表B.1是电压表,2、3是电流表C.1、2、3是电流表D.1是电流表,2、3是电压表6.如下图所示的滑动变阻器连入电路的四种接法中。
当滑片P向左滑动时,滑动变阻器接入电路部分的电阻减小的是7.如图所示,以下说法正确的是()A.开关S断开时,L1和L2串联B.开关S断开时,L1和L2并联C.开关S闭合时,L2被短路D.开关S闭合时,电源被短路8.在室温下,用绷紧的橡皮膜把一空锥形瓶的瓶口封上,然后把瓶子放入热水中,橡皮膜会向外凸,下列关于瓶内气体的描述错误的是()A.分子的无规则运动会加剧B.内能会增大C.质量会不变D.压强会减小9.密度是物质的属性之一,至今人们知道具有最大密度和最小密度的物质分别是A.黑洞、星际物质B.中子星、慧星C.巨星、氢气D.白矮星、氢气二、多选题10.小明是兴化市的一名初二学生,下列估测不合理的是A.小明游泳时受到的浮力约500NB.小明将两个鸡蛋从地上举过头顶,对鸡蛋做功约1JC.小明正常爬楼的功率约20WD.小明食指指甲受到的大气压力约为10N11.关于磁现象,下列说法中正确的是A.磁体上磁性最强的部分叫磁极B.奥斯特实验说明导体周围存在着磁场C.地磁场的北极在地理的南极附近D.发电机是利用电磁感应现象制成的12.关于力的概念,下列说法正确的是()A.力是物体对物体的作用,离开物体就没有力B.一个受力物体同时也一定是施力物体C.马向前拉车,同时车用同样大小的力向后拉马D.从空中降落的雨滴不受力的作用13.如图所示,利用图象可以描述物理量之间的关系,以下图象大致描述正确的是A.物体所受重力与质量的关系B.定值电阻消耗的电功率与电流的关系C.燃料完全燃烧放出的热量与燃料质量的关系D.降落伞匀速下落的路程与时间的关系14.由锰铜合金制成的长度相等的甲、乙两段电阻丝,甲电阻丝比乙电阻丝粗些。
成外直升2
成都外国语学校高中招生考试数学试卷(满分:150分 考试时间:120分钟)一、选择题(每题3分,共30分)1、下列运算中,正确的是( )A 、()2211x x +=+ B 、()325x x =C 、()2130x x x x −÷=≠D 、428236x x x ⨯=2、已知23,23,a b b c −=+−=−则222a b c ab bc ac ++−−−的值为( )A 、15B 、123C 、10D 、1033、已知数据1210,,,x x x 的平均数是m ,111230,,,x x x 的平均数是n ,则1230,,,x x x 的平均数为( )A 、m n +B 、23m n +C 、34m n +D 、2m n+4、某商品由每件a 元,提价10%后,又要恢复到原价,则应降价( )A 、9%B 、10%C 、11%D 、19%115、已知:AB 是半圆O 的直径,且1AB =,弦,AD BC 交于点P ,若DPB α∠=, 则CD =( )A 、sin αB 、cos αC 、tan αD 、1tan α5题图 7题图 8题图 10题图6、若关于x 的方程121m x −=−的解为正数,则m 的取值范围是( ) A 、1m >− B 、1m ≠ C 、1m >且1m ≠− D 、1m >−且1m ≠7、二次函数()2,0y ax bx c a =++<图象如图,下列5个结论:①20a b +<;②b a c <+;③420a b c ++>; ④23c b <;⑤()()1a b m am b m +>+≠, 正确结论有( )个。
A 、2B 、3C 、4D 、58、如图MN 是圆O 的直径,2MN =,点A 在圆O 上,030,AMN B ∠=为AN 的中点,P 为直径MN 上一动点,则PA PB +的最小值为( )A 、2B 2C 、1D 、29、设c a bk a b b c a c ===+++,则直线y kx k =+必经过的象限是( )象限。
2015年成都某七中嘉祥外国语学校招生入学数学真卷(内部直升)及答案解析
○312015年成都某七中嘉祥外国语学校招生入学数学真卷(内部直升) (满分:100分时间:90分钟) 一、选择题(每小题1分,共5分)1.一件上衣,如果卖84元,可赚12%,如果要赚40%,那么卖价应该是( )元。
A.98B.100C.105D.1142.一根钢材长4米,用去全长的41后,又用去41米,还剩()米。
A.213B.2C.412D.4323.甲乙两数(两数均不为0)之积是甲数的32,是乙数的40%,甲乙两数的积是( )。
A.1511B.154C.321 D.无法计算4.从甲堆煤中取出73给乙堆后,又从乙堆中取出41给甲堆。
这时两堆煤的质量相等,原来甲、乙两堆煤的质量之比是()。
A.4:3B.16:21C.7:5D.21:16 5.(导学号90672127)下面说法错误的有( )。
①甲数比乙数多25%,乙数比甲数少20%。
②圆柱的底面半径和高都扩大到原来的2倍,则体积扩大到原来的8倍。
③甲乙两人各走一段路,他们所用时间的比是4:5,速度的比是5:6,那么他们所走路程的比是2:3。
④一个正方体和一个圆锥底面积相等,高也相等,那么正方体的体积是圆锥体积的3倍。
⑤在打靶练习中,发射50发子弹,有2发没有命中,命中率为96%。
A.0个 B.1个 C.2个 D.3个 二、填空题(1-6题,每空1分,其余每空2分,共34分) 1.3时48分=__________小时;640平方米=()()公顷()。
(填最简分数) 2.植树小组去年植树成活了60棵,死了15棵,成活率是__________%。
3.要配制一种浓度为30%的盐水,210克水需要加入__________克盐,如果有42克盐,刚需要加水__________克。
4.一个圆的半径减少10%,它的周长减少__________%,面积减少__________%。
5.一个圆的周长是18.84厘米,这个圆的半径是__________厘米,这个圆的面积是__________平方厘米。
2015成都中考试卷
成都市2015年高中阶段教育学校统一招生考试(含成都市初三毕业会考)语文(教)注意事项:1.全卷分为第A卷和第B卷,A卷满分100分,B卷满分50分,考试时间120分钟。
2.在作答前,考生务必将自己的姓名、考号涂写在试卷和答题卡规定的地方。
考试结束,监考人员将试卷和答题卡一并收回。
3.选择题部分必须用2B铅笔填涂;非选择题部分必须使用0.5毫米黑色墨水签字笔书写,字体工整,笔迹清楚。
4.请按照题号在答题卡上各题目对应的答题区域内作答,超出答题区域书写的答案无效;在草稿纸、试卷上答题均无效。
5.保持答题卡清洁,不得折叠、污染、破损等。
A卷(共100分)第Ⅰ卷(选择题,共21分)一、基础知识(每小题3分,共12分)1.下面加点字注音有误的一项是()A.拂晓(fú)禀告(bǐng)气冲斗牛(dǒu)B.涟漪(yī)呐喊(nà)随声附和(huó)C.胆怯(qiè)逞能(chěng)恪尽职守(kè)D.嶙峋(lín)发窘(jiǒng)吹毛求疵(cī)2.下列语句中书写正确的一项是()A.敏感的人受了一言半语的呵责也会过分懊恼,因而我尽量刻制自己的敏感。
B.开始于盛气临人的物质的铁蹄之下,终结在不动声色的死神的怀抱。
C.袅袅烟云在我身边漂浮,而你那充满生机的树梢,却刚够得着我的脚尖。
D.鸭们十分乖巧,它们把嘴插在翅膀里,一幅睡觉绝不让主人操心的样子。
3.下列语句中加点的成语使用正确的一项是()A.别的学生都在抓紧时间汲取知识,他却苦心孤诣地沉迷游戏,父母为此心急如焚。
B.周末参加社区志愿服务的华西医院的医生们表示,他们所做的事情是微不足道的。
C.不法分子利用微博、微信等平台实施诈骗,手段不断翻新,令人叹为观止,防不胜防。
D.此刻,老师与孩子们在舞台上开心地拥抱,共享天伦之乐,庆祝本校合唱团荣获冠军。
4.下列语句中没有语病的一项是()A.汪国真的诗作曾点燃了一代人的青春梦想,他猝然长逝,怎不让人扼腕叹息?B.通过我市举办的“名师好课”系列送教活动,促进了全市城乡教育的均衡发展。
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6题
B
A
成都外国语学校2015年初升高直升考试
考试时间:110分钟 满分:120分 姓名: 得分: . 一、选择题(共15小题,每小题3分,共45分) 1、5
3
-
-的负倒数是 ( ) A .35- B .35 C .53
- D .53
2、计算:32)(b a 的结果是 ( )
A .b a 6
B .36b a
C .35b a
D .32b a 3、在式子
11-x ,21
-x ,1-x ,2-x 中,可以取1和2的是 ( ) A .
11-x B .2
1-x C .1-x D .2-x 4、97N H 病毒直径为30纳米(1纳米=910-米),用科学记数法表示这个病毒直径的大小,
正确的是 ( )
A .91030-⨯米
B .8100.3-⨯米
C .10100.3-⨯米
D .9103.0-⨯米 5、16的平方根是 ( )
A .4
B .4-
C .2
D .2±
6、如图,AB ∥CD ,点E 在BC 上,CE CD =,︒=∠74D ,则B ∠的度数为 ( )
A .︒68
B .︒32
C .︒22
D .︒16
7、已知0152
=+-a a ,则31
-+a
a 的值为 ( )
A .4
B .3
C .2
D .1
8、在平面直角坐标系中,点P (2-,a )与点Q (b ,3)关于原点对称,则b a +的值为 ( )
A .5
B .5-
C .1
D .1- 9、下列命题中是真命题的是 ( )
A .有理数都能表示成两个整数之比
B .各边相等的多边形是正多边形
第(6)题图
俯视图
左视图
主视图
C .等式两边同时乘以同一个实数,所得结果仍是等式
D .相等的圆心角所对的弧相等,所对的弦相等 10、已知2=a ,3=b ,则5=-b a 的概率为 ( )
A .0
B .21
C .31
D .4
1
11、某几何体的主视图.左视图和俯视图分别如下,则该几何体的体积为 ( )
A .π3
B .π2
C .π
D .12
12、某校九年级共有1100名学生参加“二诊”考试,随机抽取50名学生进行总成绩统计,
其中有20名学生总成绩达到优秀,估计这次“二诊”考试总成绩达到优秀的人数大约为 ( )
A .400
B .420
C .440
D .460 13、若1x .2x 是方程022=-+k x x 的两个不相等的实数根,则22
22
1-+x x 是 ( )
A .正数
B .零
C .负数
D .不大于零的数 14、已知ABC ∆的三边长分别为a .b .c ,面积为s ;C B A '''∆的三边长分别为a '.b '.c ',面
积为s ',且a a '>,b b '>,c c '>,则s 与s '的大小关系一定是 ( )
A .s s '>
B .s s '<
C .s s '=
D .不确定
15.将一次函数b ax y +=与a bx y +=的图象画在同一个直角坐标系内,则能有一组a .b 的取值,使得如下四个图中为正确的是 ( )
二、填空题(共5小题,每小题3分,共15分) 16、分解因式:=+-+a a a 8)3)(3( .
17、如图,D 是ABC ∆的边BC 上一点,已知4=AB ,2=AD ,B DAC ∠=∠,若ABD ∆的面
积为a ,ACD ∆的面积为 .
A. B. C. D.
18、若不等式⎩⎨⎧->+<1
21
m x m x 无解,则m 的取值范围是 .
19、在平面直角坐标系xOy 中,A (0,2),B (0,6),动点C 在直线x y -=上,若以
A 、
B 、
C 三点为顶点的三角形是等腰三角形,则点C 的个数为 .
20、设a x x x =++1
2(0≠a 且21
≠a ),则12
4
2++x x x 的值为 . 三、解答题(共8小题,共80分) 21、(每小题5分,共10分)
(1)计算:02)14.3(45cos )21
(30tan 360cos 2π-+︒---︒+︒⋅--
(2)先化简,再求值
)2
21(42122---÷-++x x
x x x x ,其中x 为数据4,5,6,5,3,2的众数。
22、(8分)用配方法解方程02=++c bx ax (0≠a ),并由此推出根与系数的关系
B
23、(10分)用三种方法证明:直角三角形斜边上的中线等于斜边的一半.
已知,如图,︒=∠90BCA ,DB AD =
求证: AB CD 21
=
证法1: 证法2: 证法3:
24、(10分)
解方程:x
x x x x x -+
-+-+-+-=53
413424113
B
F
E
25、(10分)一艘巡逻船在海面C 处望见一灯塔A 在它的正北方向,另一个灯塔B 在它的北
偏西︒60,此船向正西航行1海里后到D ,这时灯塔A ,B 分别在它的东北、西北方向,求两灯塔之间的距离(精确到0.1海里)
26、(10分)如图,正方形ABCD 中,DC 的中点为E ,F 为CE 的中点,求证:BAF DAE ∠=∠2
1
27、(10分)如图,直线AB 经过A (1,0),B (0,1)
两点,动点P 在双曲线x
y 21
=(0>x )
上运动,x
PN⊥轴,垂足分别为M、N,PM,PN与直线AB分别交于PM⊥轴,y
点E,F
(1)求证:矩形OMPN的面积为定值;
(2)求:BE
AF⋅的值;
(3)求动点P到直线AB的最短距离。
28、(12分)已知,在ABC
∆中,AD为BAC
∠的平分线,以C为圆心,CD为半径的半圆交
∠=,FE:4
B∠
BC的延长线于点E,交AD于点F,交AE于点M,且CAE
FD:3。
=
(1)求证:DF
AF=;
∠的余弦值;
(3)如果10
∆的面积。
BD,求ABC
=。