2017-2018-高一上期中考-市北中学
黑龙江省哈尔滨市2017-2018学年高一第一学期期中数学试卷

2017—2018学年度上学期期中考试高一数学试题考试说明:本试卷分第I 卷(选择题)和第II 卷(非选择题)两部分,满分150分,考试时间120分钟.(1)答题前,考生先将自己的姓名、准考证号码填写清楚;(2)选择题必须使用2B 铅笔填涂, 非选择题必须使用0.5毫米黑色的签字笔书写, 字迹清楚;(3)请在各题目的答题区域内作答,超出答题区域书写的答案无效,在草稿纸上答题无效;(4)保持卡面清洁,不得折叠、不要弄破、弄皱,不准使用涂改液、刮纸刀.一、选择题:(本大题共12小题,每小题5分,共60分)1.集合2{|60}M x x x =--≥,集合{|31}N x x =-≤≤,则()R N C M ⋂等于( )(A )[2,1]- (B )(2,1]- (C )[3,3)- (D )(2,3)-2.下列函数中与函数x y =相等的函数是( )(A )2)(x y = (B )2x y = (C )x y 2log 2= (D )x y 2log 2=3.设20.3a =,0.32b =,2log 0.3c =,则,,a b c 的大小关系为( )(A )c a b << (B )c b a << (C ) a b c << (D)a c b << 4. 函数)1ln(432++--=x x x y 的定义域是( ) (A ) (1,1]- (B )(1,0)(0,1]-⋃ (C )[4,1]- (D )(1,0)(0,1)-⋃5.133)(1+=+x x x f 的值域是( ) (A )),3(+∞ (B ))3,0( (C )(0,2) (D )(2,)+∞6.函数41()2x xf x +=的图象( ) (A )关于原点对称 (B )关于直线y =x 对称 (C )关于x 轴对称 (D )关于y 轴对称7.已知,1()(4)2,12x a x f x a x x ⎧>⎪=⎨-+≤⎪⎩,对任意21x x ≠,都有1212()()0f x f x x x ->-成立,则实数a 的取值范围是( )(A ) 18a << (B )14a <≤ (C )48a ≤< (D )8a >8.定义运算⎩⎨⎧≥<=⊕ba b b a a b a ,, 若函数()x x x f -⊕=22,则)(x f 的值域是( ) (A ) ),1[+∞ (B )),0(+∞ (C )(0,1] (D )⎥⎦⎤⎢⎣⎡1,21 9.已知)(x f 是定义在R 上的偶函数,当[0,)x ∈+∞时,()22x f x =-,则不等式0)(log 2>x f 的解集为( )(A ))21,0( (B )),2()1,21(+∞(C )),2(+∞ (D )),2()21,0(+∞ 10.若函数)10()(≠>=-a a ax f x 且在),(+∞-∞上是减函数,则)1(log )(-=x x g a 的大致图象是( )11. 已知函数x x f ln )(=,若b a <<0,且)()(b f a f =,则b a 4+的取值范围是( )(A )),4(+∞ (B )),4[+∞ (C )(5,)+∞ (D ) ),5[+∞12.函数)3(log )(22++-=ax x x f 在(2,4)上是单调递减的,则a 的取值范围是( )(A )13(,4]4 (B )13[,4]4 (C )[8,)+∞ (D )]4,(-∞二、填空题:(本大题共4小题,每小题5分,共20分)13.计算:2439(log 9log 3)(log 2log 8)++= .14.已知函数)(x f 对任意实数b a ,,都有)()()(b f a f ab f +=成立,若2)2(=f ,3)3(=f ,(A ) (B )(C )(D )。
2017-2018学年上海市静安区市北高中高一上学期期末测试卷

2017学年度市北中学第一学期高一化学期终考试试卷相关元素的相对原子质量:Al-27 Mg-24 Ca-40 Cu-64 Na-23 Cl-35.5一、选择题(共40分,每题2分,只有一个正确答案)1、下列电子式错误的是()2、下列不属于离子化合物的是()A.Na2O2B.CaF2C.SO2D.Ba(OH)23、有反应KC1O3+HCl→ClO2+Cl2+KCl+H2O(未配平),若KClO3,用37Cl示踪,则在生成物中含有37Cl的是()A.ClO2B.Cl2C.KCl D.ClO2和Cl24、下列性质可以证明某化合物内一定存在离子键的是()A.可溶于水 B.具有较高的熔点C.水溶液能导电D.熔融状态能导电5、己知碳有三种常见的同位素:12C、13C、14C,氧也有三种同位素:16O、17O、18O,由这六种微粒构成的二氧化碳分子中,其相对分子质量最多有()A.18种B.6种C.7种D.12种6、铋(Bi)在医药方面有重要应用。
下列关于20983Bi和21083Bi的说法正确的是()A.20983Bi和21083Bi部含有83个中子B.20983Bi和21083Bi互为同位素C.20983Bi和21083Bi的核外电子数不同D.20983Bi和21083Bi分别含有126和127个质子7、N A表示阿伏伽德罗常数,1molNaOH固体含有()A.2N A个阳离子B.10N A个电子C.N A个氢氧根离子D.2N A个共价键8、向KOH溶液中通入11.2 L(标准状况)氯气恰好完全反应生成三种含氯盐:0.7molKCl、0.2moIKClO和X。
则X是()A.0.1molKClO4B.0.1molKClO3C.0.2molKClO2D.0.1molKClO29、下列变化只有吸热过程的是()A.碘的升华B.液态水结成冰C.硝酸铵溶于水D.浓硫酸溶于水10、下列物质的分子中,共用电子对数目最多的是()A.H2B.NH3C.H2O D.CH411、在3NO2+H2O→2HNO3+NO↑反应中,氧化剂与还原剂的分子数之比为()A.2:1 B.1:2 C.3:l D.1:312、下列物质变化时,需克服的作用力不是化学键的是()A.HCl溶于水B.I2升华C.H2O电解D.烧碱熔化13、下列有关晶体的叙述中错误的是()A.离子晶体中,一定存在离子键B.原子晶体中,只存在共价键C.金属晶体的熔沸点均很高D.稀有气体‘的原子能形成分子晶体14、从右图所示的某气体反应的能量变化分析,以下判断错误的是()A.这是一个放热反应B.该反应可能需要加热‘C.生成物的总能量低于参加反应的物质的总能量D.反应物比生成物更稳定15、下列过程中,共价键被破坏的是()A.碘升华B.氯化氢气体溶于水C.酒精溶于水 D. 溴蒸气被木炭吸附16、实验室制备氯气的装置如下图。
上海市市北高级中学2017-2018学年高一上学期12月月考数学试题

点睛:(1)已知函数的奇偶性求参数,一般采用待定系数法求解,根据 得到关于待求参数的恒等式,由系数的对等性得参数的值或方程(组),进而得出参数的值;(2)已知函数的奇偶性求函数值或解析式,首先抓住奇偶性讨论函数在各个区间上的解析式,或充分利用奇偶性得出关于 的方程,从而可得 的值或解析式.
1.设 ,则使 为奇函数且在 上单调递减的 的值的个数是()
A.1B.2C.3D.4
2.若函数 在区间 上为增函数,则实数 的取值范围是()
A. B. C. D.
3.已知函数 的定义域和值域都是 ,则“ ”成立的充要条件是( )
A.存在 ,使得 B.有无数多个实数 ,使得
C.对任意 ,使得 D.不存在实数 ,使得
4.已知函数 与 满足:对于任意的 ,总存在 ,使得 ,则实数 的取值范围是()
A. B. C. D.
第II卷(非选择题)
请点击修改第II卷的文字说明
评卷人
得分
二、填空题
5.函数 的定义域为_______________
6.已知函数 ,若 ,则 ____________;
7.已知 , ,则 =___________;
【分析】
(1)直接把 代入函数解析式,得到方程,求出 的值;
(2)求出函数 的解析式,用函数单调性的定义进行证明即可;
(3)分类讨论,把函数 的解析式,转化为二次函数解析式、分式类型函数解析式形式,利用它们的单调性求出 的取值范围.
【详解】
(1) ;
(2) ,当 时,解析式可化简为:
,设 是 上任意两个不相等的实数,则有 ,
,
因为 , ,所以 ,因此有
,所以函数 是 上的递增函数;
(3)当 时,而 ,所以 ,因为 ,所以有
2017-2018学年上海市重点中学高一上学期期中考试数学试题Word版含答案

2017-2018学年上海市重点中学高一上学期期中考试数学试题(考试时间:120分钟 满分:150分)一.填空题(1--6每小题4分,7--12每小题5分,共54分)1、方程组⎩⎨⎧=-=+0402x y x 的解组成的集合为 .2、写出命题“若0≥a 且0≥b ,则≥ab 0”的逆否命题: .3、 不等式21≥-x 的解集为 .4、设,0>x 当=x 时,xx 21+取到最小值. 5、已知集合},1|{2R x x y y M ∈-==,}3|{2xx y x N -==,则=⋂N M ___________. 6、()y f x =是定义在R 上的奇函数,当0<x 时,1)(2++=x x x f ,则0>x 时,=)(x f .7、已知命题42:<≤x α,命题β:m x m -≤≤+6,且β是α的必要非充分条件,则实数m 的取值范围是 .8、设函数⎪⎩⎪⎨⎧>-≤++=0,0,22)(22x x x x x x f ,若2))((=a f f ,则=a .9、关于x 的不等式01222>-++-k k kx x 的解集为{},x x a x R ≠∈,则实数a =______. 10、若不等式()0≤x f 的解集是[3,2]-,不等式()0≤x g 的解集是φ,且()x f ,()x g 中,R x ∈,则不等式()()0>x g x f 的解集为 . 11、设关于x 的不等式210ax x a-<-的解集为S ,且S S ∉∈3,2,则实数a 的取值范围为 .12、设函数()⎩⎨⎧∈-∈=M x x P x xx f ,其中P 、M 是实数集R 的两个非空子集,又规定()(){}P x x f y y P A ∈==,,()(){}M x x f y y M A ∈==,,下列所有错误的说法的序号是 .(1)若φ=⋂M P ,则()()φ=⋂M A P A ;(2)若R M P ≠⋃,则()()R M A P A ≠⋃; (3)若φ≠⋂M P ,则()()φ≠⋂M A P A ;(4)若R M P =⋃,则()()R M A P A =⋃。
大连市2017-2018学年高一数学上学期期中试题

2017—2018学年度第一学期期中高一数学试题考试时间:120分钟试题满分:150 分本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分.考查范围:必修1全册考生注意:1.答题前,考生务必将自己的考号、姓名填写在试题、答题纸和答题卡上,考生要认真核对涂准答题卡上的相关信息。
2.第I卷每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦干净后,再选涂其他答案标号。
第Ⅱ卷用黑色墨水签字笔在答题卡上书写作答。
在试题卷上作答,答案无效.3.考试结束,监考员将答题纸和答题卡按对应次序排好收回。
第Ⅰ卷(共60分)一.选择题:(本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的)1.若集合,,则()A. B. C. D。
2.已知(x,y)在映射下的象是(2x-y,x—2y),则原象(1,2)在下的象为( )A.(0,—3) B. (1,—3)C。
(0,3) D. (2,3)3.若,,,则的大小关系为()A。
B. C.D。
4。
函数的部分图象大致是()A B C D5.函数的值域是()A.B.C.D.6.函数的单调递减区间是()A.B.C.D.7.已知定义在上的奇函数和偶函数满足,则( )A.B。
C.D.8.设,则在下列区间中,使函数有零点的区间可能是( )A.B.C.D.9.已知函数在是减函数,且关于的函数为偶函数,则()A。
B.C。
D。
10.函数的函数值恒小于零,则实数的取值范围是()A.B.C.D.11.若函数是上的单调减函数,则实数的取值范围是()A.B.C. D.12.若存在正数使成立,则实数的取值范围是()A.B.C.D.第Ⅱ卷(非选择题满分90分)二。
填空题:(本大题共4小题,每小题5分,共20分) 13.函数f (x)=a x+1+3的图象恒过定点________。
14.若函数,则=__________15.已知,其中为常数,若,则_______16.函数为R上的奇函数,且当时,,则当时,= ________三.解答题:(本大题共6小题,共70分,解答应写出文字说明、证明过程或演算步骤)17.(本小题满分10分)已知集合,且,求实数的取值范围.18。
湖北省部分重点中学2017-2018学年高一上学期期中考试英语试题 Word版含答案

湖北省部分重点中学2017-2018学年度上学期高一期中考试英语试卷第Ⅰ卷第一部分听力(共两节,满分30分)第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. Where did the woman have lunch?A. At her house.B. At a café.C. On the riverbank.2. What will the man do?A. Book a restaurant.B. Have a rest.C. Send out invitations.3. What time is it now?A. 4:00.B. 3:30.C. 3:10.4. What are the speakers mainly talking about?A. Their university days.B. A football match.C. A person.5. What homework is the boy doing?A. English.B. Science.C. Maths.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。
每段对话后或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各个小题给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料,回答第6、7题。
6. What will the woman have to do tomorrow?A. Write a paper.B. Hand in her paper.C. Repair the man’s computer.7. What is the woman most likely to be?A. A computer programmer.B. A secretary.C. A student.听第7段材料,回答第8、9题。
上海市宝山区上海大学市北附属中学2017-2018学年高一下学期期中数学试题 精品

上海大学市北附属中学2017学年第二学期期中考试高一数学试卷(2018.4)答题时间90分钟,满分100分一、填空题(本大题共12题,每题4分,满分48分)1、已知扇形的圆心角为3π,半径为2,则该扇形的面积为______ 2、已知角α的终边经过点)4,3(-P ,则ααsec tan +=____3、化简:)20sin(70cos )20cos(20cos ︒-︒-︒-︒αα=_______4、已知等腰三角形的底角的正弦值等于32,则这个三角形顶角的余弦值为_____ 5、函数x y 2cos 42-=的值域为________ 6、函数⎪⎭⎫ ⎝⎛++=62cos 31πx y 取得最大值时的x 的值为______ 7、函数x x y 44sin cos -=的最小正周期是______8、某货轮在A 处看到灯塔S 在北偏东︒30方向,它以每小时36海里的速度向正北方向航行,经过40分钟航行到B 处,看灯塔S 在北偏东︒75方向,此时货轮到灯塔S 的距离为______海里9、已知2)tan 1)(tan 1(=++βα,且βα,都是锐角,则βα+=_____10、已知点⎪⎭⎫⎝⎛54,53A ,将OA 绕坐标原点逆时针旋转2π至A O ',则A '的坐标为_______ 11、已知x y sin =和x y cos =图像的连续的三个交点C B A 、、构成ABC ∆,则ABC ∆面积为______12、已知γβα、、是某三角形的三个内角,给出下列四组数据:①γβαsin ,sin ,sin ;②γβα222s i n ,s i n ,s i n ;③2c o s ,2c o s ,2c o s 222γβα;④2t a n ,2t a n ,2t a n γβα 分别以每组数据作为三条线段的长,其中一定能构成三角形的是________(将符合条件的数据序号都填上)三、解答题(本大题共5题,满分52分) 13、(本题10分)已知⎪⎭⎫ ⎝⎛∈-=ππθθ,2,32cos ,求θθθsin cos 2sin 2-的值14、(本题满分10分)已知βα,为锐角,且1411)cos(,71cos -=+=βαα,求βsin 的值15、(本题满分10分)已知函数]2,0[,sin 21)(π∈-=x x x f (1)用“五点法”作出)(x f 的图像(2)写出0)(>x f 的x 的取值范围16、(本题满分10分)已知函数),0(,21sin cos )(22π∈+-=x x x x f (1)求)(x f 的单调递增区间(2)设ABC ∆为锐角三角形,角A 所对边19=a ,角B 所对边5=b ,若0)(=A f ,求ABC ∆的面积17、(本题12分)如图是一个“蝴蝶形图案(阴影区域)”,其中BD AC 、是过抛物线2x y =的两条互相垂直的弦(点B A 、在第二象限),且BD AC 、交于点⎪⎭⎫ ⎝⎛41,0F ,点E 为y 轴上一点,α=∠EFA ,其中α为锐角(1)设线段AF 的长为m ,将m 表示为关于α的函数(2)求“蝴蝶形图案”面积的最小值,并指出取最小值时α的大小。
上海市市北中学2018-2019学年高一上学期期中考试物理试题 Word版缺答案

市北中学2018-2019学年第一学期期中考试高一物理试卷本卷:2g=10m/s一、单项选择题(每小题的四个选项中,只有一项是正确的)l.关于质点的描述,下列说法中正确的是()A.质量很小的物体必定可以看作质点B.体积很小的物体必定可以看作质点C.某些情况下,地球也可以看作质点D.乒乓球旋转时,可以看作质点2.下列各组物理量中,全部是矢量的有()A.位移、力、速度、平均速度B.速度、路程、时间、平均速度C.位移、速度、力、时间D.速度、质量、力、路程3.关于位移和路程,下列说法中正确的是()A.物体沿直线向某一方向运动,通过的路程就随移B.物体沿直线向某一方向运动,通过的路程等于位移的大小C.物体通过一段路程,其位移不可能为零D.物体通过的路程不等,则位移也不相同4.关于物体运动的速度和加速度的关系,以下说法中正确的是()A.加速度越大,速度变化越快B.速度改变量越大,加速度一定越大C.速度变化,加速度一定变化D.加速度为零,速度一定为零5.如图所示,一个质点沿两个半径为R的半圆弧由A运动到C,规定向右方向为正方向,在此过程中,它的位移和路程分别为()A.4R,2πRB.4R,2πR-C.4R--,2πR D.4R-,2πR6.下列说法中正确的是()A.甲用力把乙推倒,说明只是甲对乙有力的作用,乙对甲没有力的作用B.只有有生命的物体才会施力,无生命的物体只会受到力,不会施力C.任何一个物体,一定既是受力物体,也是施力物体D.拳击手一拳击出,没有声中对方,这时只有施力物体,没有受力物体7.用两根绳子吊起一重物,使重物保持静止,若逐渐增大两绳之间的夹角,则两绳对重物的拉力的合力变化情况是()A.不变B.减小C.增大D.无法确定8.关于物体的重心的说法,正确的是()A.物体的重心一定在物体上B.形状规则的物体的重心一定在其几何中心C.物体的重心位置跟物体的质量分布情况和物体的形状有关D.用线悬挂的静止物体,细线方向不一定通过物体的重心9.物体静止在水平桌上,物体对桌面的压力()A.就是物体的重力B.与桌面对物体的支持力是一对平衡力C.是由于物体的形变而产生的D.是由于桌面的形变而产生10.用于握住瓶子,使瓶子在竖直方向静止.如果握力加倍,则手对瓶子的摩擦力()A.加倍B.保持不变C.方向由向下变成向上D.方向由向上变成向下11.如图所示,一个物体质量为20kg,沿水平面向右运动,同时受到一水平向左的大小为10N 的力的作用.已知此物体与地面之间的动摩擦因数为0.1.则此物体与地面之间的滑动摩擦力,以下描述正确的是()A.10N,方向向右B.10N,方向向左C.20N,方向向右D.20N,方向向左12.如图所示,一个质量分布均匀的球放在互成120 的两块光滑平面上保持静止状态OA是水平面,OB是倾斜面,关于球的受力,下列说法正确的()A.球受重力、水平面和斜面的弹力B.球除了受重力外,只受到水平面的弹力C.球所受各个力的施力物体都是水平面D.球所受的弹力是由于球的形变而产生的13.一物体受到同一平面内1N、2N、3N、4N四个力作用而处于平衡,沿3N力的方向做匀速直线运动,现保持1N、3N、4N三个力的方向和大小不变,而将2N的力绕O点旋转60︒,此时作用在物体上的合力大小为()A.2NB.C.3ND.14.甲乙两物体从同一位置出发沿同一直线运动时的v t-图象如图所示,下列判断不正确的是()A.甲做匀速直线运动,乙做变速直线运动B.两物体两次相遇的时刻是1s末和4s末C.乙在前2s內做匀加速直线运动,2s后做匀减速直线D.0~6s内甲,乙两物体的运动方向始终相同15.一物体沿一直线从静止开始运动且同时开始计时,其加速度随时间变化关系如图所示.则关于它在前4s内的运动情况,下列说法中正确的是().A.前3s内先加速后减速,3s末回到出发点B.第3s末速度为零,第4s内反向加速C.第1s和第4s末,物体的速度均为8m/sD.前4s内位移为8m16.有一只小虫清晨6时起从地面沿树干向上爬,爬到树顶时是下午6时,第二天清晨6时起从树顶沿树干向下爬,爬回地面时是下午4时.若小虫爬行时快时慢,则两天中相同钟点(时、分、秒)爬过树干上相同高的机会是()A.一定有一次B.可能没有C.可能有两次D.一定没有二、多项选择题(每小题的四个选项中,有两个或两个以上是正确的,多选、错选均不得分)17.甲物体重力是乙物体重力的五倍,甲从H高处自由下落,乙从2H高处同时开始自由落下,在两物体下落过程中,下面几种说法正确的是( ) A.同一时刻甲的速度比乙的速度大 B.下落后1s 末,它们的速度相等 C.各自下落1m 时,它们的速度相等 D.下落过程中甲的加速度比乙的大18.一物体静止在斜面上,下面说法正确的是( )A.物体受到斜面的作用力,方向竖直向上B.物体所受重力可分解为平行于斜面的下滑力和对斜面的正压力C.只要物体不滑动,它受的摩擦力随斜面倾角的增大而减小D.一旦物体沿斜面下滑,它所受的摩擦力将随斜面倾角的增大而减小19.一物以6m/s 的初速度从斜面底端沿斜面向上做加速度大小为22m/s 的匀减速直线运动,又以同样大小的加速度沿斜面滑下,则经过多长时间物体位移的大小为5m .( )A.1sB.3sC.5sD.(s20.做初速度不为零的匀加速直线运动的物体在时间T 内通过位移1s 到达A 点,接着在时间T 内又通过位移2s 到达B 点,则以下判断正确的是( ) A.物体在A 点的速度大小为122s s T+ B.物体运动的加速度为122s TC.物体运动的加速度为212s s T - D.物体在B 点的速度大小为2132s s T- 三、填空题21.汽车以20m/s 的速度做匀速直线运动,刹车后以大小为52m/s 的加速度做匀减速直线运动,那么刹车后2s 内的位移是______m ,刹车后2s 内的位移与刹车后6s 内汽车通过的位移之比为___________.22.一物体做同向直线运动,前一半时间以9.0m/s 的速度做匀速运动;后一半时间以6.0m/s 的速度做匀速运动,则物体的平均速度是_______m/s .另一物体也做同向直线运动,前一半路程以3.0m/s 的速度做匀速运动:后一半路程以6.0m/s 的速度做匀速运动,则物体的平均速度是________m/s .23.一小球由静止开始沿光滑斜面滚下,依次经过A 、B 、C 三点.已知6cm AB =,10cm BC =,小球经过AB 和BC 两段所用的时间均为2s ,则小球经过A 点时的速度是________m/s ,加速度大小为_______2m/s .24.光滑水平面上一物体,受一水平恒力1F 作用从静止开始做匀加速直线运动,一段时间后末速度大小为1v ,同时撤去1F ,改为反方向恒力2F 作用,经过相同时间,恰好回到出发点,点,此时速度大小为2v ,求12:F F =_________,12:v v =__________. 四、作图题25.如下图所示,接触面均光滑,画出静止物体所受到重力和弹力的示意图26.如图所示,0点受到1F 和2F 两个力作用,已知13N F =,1F 与2F 的合力5N F =方向如图.试用作图法画出2F ,并把2F 的大小标在图上.(要求按给定的标度作图,2F 的大小要求两位有效数字)五、实验题27.下图是测定小车刹车时加速度的实验装置 (1)信号发射器和信号接收器组成_________传感器 (2)这组传感器所测量的物理量是________.(3)图是实验测得的图像,根据图像中数据求小车的加速度的大小a =_______2m/s .28.如图所示,是探究某根弹簧的伸长量x 与所受拉力F 之间的关系图:(1)写出图线代表的函数___________(x用m做单位):(2)弹簧的劲度系数是________N/m;(3)当弹簧受2800NF=的拉力作用时,弹簧伸长为2x=_________cm.六、计算题29.一物体做初速度为2m/s,加速度为12m/s的匀加速直线运动,试求:(1)物体在第3秒末的速度(2)在开始4秒内的位移和平均速度(3)在第4秒内的平均速度(4)通过第4米位移的平均速度30.如图所示,一根直棒长度为5m,用手提着其上端,在其下端的正下方10m处有一个长度为5m的、内径比直棒大得多的空心竖直管子,放开后让直棒做自由落体运动,求:(1)直棒下端刚到达空心管上端时所用的时间是多少?(2)直棒通过该空心管所用的时间是多少?(不计空气的阻力,210m/sg=)31.有一辆警车停在路边,此时一辆汽车以72km/h的速度匀速驶过,在汽车驶过警车的同时,警午以22m/s的加速度启动追击汽车,问:(1)警车启动多久后离汽车最远,最远距离是多少?(2)警车需多久能追上汽车,此时警车车速为多少?一共追了多远?。
湖北省部分重点中学2017-2018学年度上学期高一期中考试 数学 试 卷及答案

湖北省部分重点中学2016-2017学年度上学期高一期中考试数学试卷命题人:武汉中学余芳审题人:武汉中学杨银舟一、选择题(本大题共12个小题,每小题5分,共60分,每小题只有一个选项符合题意)1. 已知集合A=x−1≤x≤2,B=x x<1,求A∩C R B=().A. x x>1B. x x≥1C. x1<x≤2D. x1≤x≤22. 函数y=1x−2的定义域是(−∞,2)∪[3,5),其值域是().A. −∞,0∪(13,1] B. (−∞,1] C. (−∞,13)∪[1,+∞) D. (0,+∞)3. 下列与y=x相等的函数是().A. y=(x)2B. y=log22xC. y=2log2xD. y=x24. 设a=30.1,b=lg5−lg2,c=log3910,则a,b,c的大小关系是().A. b>c>aB. a>c>bC. b>a>cD. a>b>c5. 若函数f x=32x−m(m为常数)在[3,+∞)上是增函数,则m的范围是().A. [3,+∞)B. (3,+∞)C. (−∞,6]D. (−∞,6)6. 设f x=ax2+bx+2是定义在[a+1,2]上的偶函数,则f x的值域为().A. [−10,2]B. [−12,0)C. [−12,2]D. 与a、b有关不能确定7. 已知奇函数f x的定义域为R,当x>0时f x=lgx,则不等式xf x≤0的解集为().A. [−1,0)∪(0,1]B. [−1,1]C. −∞,−1∪[1,+∞)D. −∞,−1∪{0}∪[1,+∞)8. 已知函数f x=log a(x2−ax+5)(a>0且a≠1)满足对任意实数x1,x2,当x1<x2<a2时,f x2−f x1<0,则实数a的取值范围是().A. 1,25B. −25,25C. 1,+∞D. 0,19. 若函数f x=ae−x−e x为奇函数,则f x−1<e−1e的解集为().A. (−∞,0)B. (−∞,2)C. (2,+∞)D. (0,+∞)10. 已知f x=a x−2,g x=logα|x| (α>0,α≠1),若f4∙g−4<0,则y=f(x),y=g(x)在同一坐标系内的大致图象是().11. 设方程10x=lg(−x)的两根分别为x1,x2,则().A. x1∙x2<0B. x1∙x2=0C. x1∙x2>1D. 0<x1∙x2<112. 已知函数f x=x−[x],其中[x]表示不超过x的最大整数,若关于x的方程f x=kx+k有三个不同的实数根,则k的取值范围是().A. [−1,−12)∪(14,13] B. −1,−12∪[14,13) C. [−13,−14)∪(12,1] D. (−13,−14]∪[12,1)二、填空题(本大题共4个小题,每小题5分,共20分)13. 设集合A = x ∈N x <2 ,B = y y =x 2−1 x ∈A ,C = x x ∈A 或x ∈B ,则集合C 的真子集有 个.14. 若x log 23=1,则3x +9x = .15. 已知函数g x =log 3(2x +b)的图象过原点,函数f x =x 2−ax +b 的图象在区间(12,3)上与x 轴有交点,则实数a 的取值范围是 .16. 已知函数f x =ax 2+bx +c (a ≠0)且关于x 的方程f x =x 无实根,下列说法正确的是 . ① 关于x 的方程f f x =x 也一定无实根.② 若a >0,则不等式f f x >x 对一切实数x 都成立. ③ 若a <0,则一定存在x 0∈R 使f f x 0 >x 0.④ 若a +b +c =0,则不等式f f x <x 对一切实数都成立.三、解答题(本大题共6个小题,共70分,解答应写出文字说明,证明过程或演算步骤) 17.(本小题满分10分)① 已知0<x <1,且x +x −1=3,求x 2+x −2+1x 12−x −12的值.② 求值2723−2log 43×log 218+log 23×log 34.18.(本小题满分12分)已知集合A = x y =lg 5−xx+1 ,B = x x 2−2x −m <0,x ∈R .① m =3时,求A ∩(C R B).② 若A ∩B = x −1<x <4 ,求实数m 的值.19.(本小题满分12分)某企业生产A 、B 两种产品,根据市场调查预测,知A 产品的利润与投资成正比,关系如图(1);B 产品的利润与投资算术平方根成正比,关系如图(2). ① 分别将A 、B 两种产品的利润表示为投资的函数关系.② 该企业已筹集到10万元资金,并全部投入A 、B 两种产品的生产,问怎样分配这10万元资金才能使企业获得最大利润,最大利润为多少万元?20.(本小题满分12分)已知函数f x =2x −12+2. ① 判断f x 的奇偶性. ② 若不等式112−f(x)<4x +m 恒成立,求实数m 的取值范围.21.(本小题满分12分)设函数f x =2x 2x+1,g x =ax +5−2a (a >0).① 判断并证明f x 在[0,1]上的单调性.② 若对于任意的x 1∈[0,1],总存在x 0∈[0,1],使得g x 0 =f(x 1)成立,求a 的取值范围.22.(本小题满分12分)若在定义域内存在实数x 0使f(x 0+1)=f(x 0)+f(1)成立,则称函数有“漂移点”x 0.① 函数f x =1x 是否有漂移点?请说明理由.② 证明函数f x =x 2+2x 在(0,1)上有漂移点.③ 若函数f x =lg ax +1在(0,+∞)上有漂移点,求实数a 的取值范围.(2)湖北省部分重点中学2016-2017学年度上学期高一期中考试数 学 答 案一、选择题1. D2. A3. B4. D5. C6. A7. B8. A9. D 10. B 11. D 12. B 二、填空题13. 7 14. 6 15. [2,103) 16. ① ② ④ 三、解答题17. 解:① x 2+x −2=(x +x −1)2−2=9−2=7 (x 1−x −1)2=x +x −1−2=1 又∵ 0<x <1 ∴ x 12−x −12<0∴ x 12−x −12=−1 原式=7+1−1=−8②(略)原式=11+3 318. 解:① A = x −1<x <5 ,m =3时,B = x −1<x <3 ,A ∩(C R B)= x 3≤x <5 ② 若A ∩B = x −1<x <4 ,则x =4是方程x 2−2x −m =0的根. 42−2∙4−m =0 ∴m =819. 解:① f x =12x (x ≥0),g x =2 x (x ≥0)② 设投入x 万元生产B 产品,则10−x 万元生产A 产品,利润和为y ,则 y =12 10−x +2 x (0≤x ≤10)可求当x =4时,y max =7万元 20. 解:① 函数f x 的定义域为x ∈R f −x =2−x −12(2+1)=1−2x2(1+2)=−f(x) ∴ 函数f(x)为奇函数 ② 令g x =112−f(x)−4x =2x +1−4x函数g x 的最大值为54 ∴m >5421. 解:① 证明:任取0≤x 1<x 2≤1,f(x 1)−f x 2 =2x 12x 1+1−2x 22x 2+1=2 x 1−x 2 (x 1x 2+x 1+x 2)x 1+1 (x 2+1)∵ x 1<x 2 ∴ x 1−x 2<0x1x2+x1+x2>0,(x1+1)x2+1>0∴f(x1)−f(x2)<0∴f(x)在[0,1]上单调递增②当x1∈[0,1]时f(x1)∈[0,1],函数g x在[0,1]上单调递增所以g x在[0,1]上值域为[5−2a,5−a]由已知得:[0,1]⊆[5−2a,5−a]由5−2a≤05−a≥1,∴52≤a≤422. 解:①假设函数f x=1x 有“漂移点”x0,则1x0+1=1x0+1,即x02+x0+1=0.此方程无实根,与题设矛盾,∴函数f x=1x没有漂移点.②令h x=f x+1−f x−f1=2(2x−1+x−1)h0=−1,h1=2∴ h0∙h1<0∴ h x=0在(0,1)上至少有一实根,函数f x=x2+2x在(0,1)上有漂移点.③若f x=lg ax2+1在(0,+∞)上有漂移点x0,则lg a(x0+1)2+1=lg ax02+1+lg a2即:a(x0+1)+1=ax0+1∙a2即:即:即:2−a x02−2ax0+2−2a=0令g x=2−a x02−2ax0+2−2a则g x=0在(0,+∞)上有根,因为ax+1>0,所以a>0a=2时,g x=0的根为−12,舍当0<a<2时,对称轴x=a2−a>0只需∆=4a2−42−a(2−2a)≥0即3−≤a≤3+∴a∈[3−2)。
高中_上海市北高级中学2017-2018高一上月考数学卷

高一数学一、填空〔36分〕1、函数()f x =的定义域为 ;2、函数()20211x x f x x x ⎧<=⎨-≥⎩,假设()4f a =,那么a = ;3、()212f x x x =--,()12g x x =-,那么()()f x g x += ;4、)34f x =,那么()f x = ;5、函数()f x 的值域是 ;6、函数()3131x x f x +=-为 函数〔填奇偶性〕;7、函数()f x ()f x 的单调递增区间为 ;8、()f x 为定义在R 上的奇函数,当0x >,()21=41f x x x-+,那么x R ∈时,()f x = ; 9、()22f x kx x =-,在[]1,2上单调递减,那么k 的取值范围是 ;10、假设函数()22f x mx x =--只有一个零点,那么实数m 的取值范围是 ;11、电信部门有两种付费方式。
甲方案:入网,每月月租费50元,通话费0.38元/分钟;乙方案:买卡,不收月租费,通话费为0.6元/分钟。
假设某人每月的通话时间为300分钟以上,那么应选 方案〔填甲或乙〕;12、()||1x f x x s =-,假设函数()()g x f x kx =-有三个不同的零点,那么实数k 的取值范围 是 ;二、选择〔16分〕13、设11,,1,2,32n ⎧⎫∈-⎨⎬⎩⎭,那么使得()n f x x =为奇函数,且在()0,+∞上单调递减的n 的个数为〔 〕〔A 〕1 〔B 〕2 〔C 〕3 〔D 〕414、假设函数()4a f x x x=+在区间[)2,+∞上为增函数,那么实数a 的取值范围是〔 〕 〔A 〕16a ≤ 〔B 〕016a <≤ 〔C 〕04a <≤ 〔D 〕1a ≥15、函数()(),f x g x 的定义域和值域都是R ,那么“()()f x g x <,x R ∈〞成立的充要条件是〔 〕〔A 〕存在0x R ∈,使得()()00f x g x <; 〔B 〕有无数多个实数x ,使得()()f x g x <;〔C 〕对任意x R ∈,使得()()12f x g x +< 〔D 〕不存在实数x ,使得()()f x g x ≥16、函数()11f x x x =-+与()221g x x ax =-+满足;对于任意的[]10,1x ∈,总存在[]20,1x ∈,使得()()12f x g x ≥,那么实数a 的取值范围是〔 〕〔A 〕[)1,+∞ 〔C 〕[)2,+∞ 〔C 〕)+∞ 〔D 〕[)4,+∞ 三、解答〔48分〕17、函数()223px f x x p +=+是奇函数,且()523f =,求实数,p q 的值。
2017-2018学年市北中学第二学期高一年级英语期中考试试卷 word有答案

2017-2018学年度市北中学第二学期高一年级英语期中考试试卷第I 卷(共77分)I. Listening Comprehension (20%)Section ADirections:In Section A, you will hear ten short conversations between two speakers. At the end of each conversation, a question will be asked about what was said. The conversations and the questions will be spoken only once. After you hear a conversation and the question about it, read the four possible answers on your paper, and decide which one is the best answer to the question you have heard.1. A. A coach B. A doctor C. A professor. D. A conductor2. A. In a park B. In a bar C In a library D. In a club3. A. He will watch a movie tonight. B. He has no time to watch a movie tonight.C. He has time every night.D. He likes staying with the woman.4. A. Peter is a strange person. B. Peter likes communicating.C. Peter is much quieter than his brother.D. Peter hates his brother.5. A. The article was not written by him. B. He likes reading articles.C. He takes charge of the website.D. He is proud of himself.6. A. On Friday B. On Sunday C. On Thursday. D On Saturday7. A. The woman has a good taste in cartoons. B. The woman wants to watch the cartoon with the man.C. The man doesn't believe the woman's words.D. The man doesn't actually like the Japanese cartoon.8. A. He likes allocating resources. B. He wants to major in human resources very much.C. He doesn't know which major to choose yet.D. He doesn't like majoring in human resources.9. A. She had visited her dream city last month. B. She will make the place where she stays a dream city.C. She will fall in love with another city one day.D. She will go to her dream city quite often one day.10. A. The man is not attending the conference.B. The woman is not interested in the topic.C. Both the man and the woman support the manager.D. The man and the woman are colleagues.Section BDirections: In Section B, you will hear two short passages and one longer conversation, and you will be asked several questions on each of the passages and the conversation. The passages and the conversation will be read twice, but the questions will be spoken only once. When you hear a question, read the four possible answers on your paper and decide which one would be the best answer to the question you have heard.Questions 11 through 13 are based on the following passage.11. A. By holding back in conversations. B. By making quick decisions.C. By realizing the importance of our words. D By talking to others frequently12. A. To give others a chance to know more about us.B. To help feel self-conscious in a group.C. To learn more skills in conversations.D. To make others know our good qualities.13. A. Ways to start a conversation B. Reasons why shyness is commonC. Ways to be in a groupD. Ways to build self-confidenceQuestions 14 through 16 are based on the following passage14. A. Keep important relationships alive B. Offer great solutions to problemsC Listen to our problems and give advice D. Give anything we like to us15. A. When we are right. B When we are wrongC. When we are in a bad moodD. No matter we are right or wrong16. A. He knows he is wrong in some way. B. He doesn't want to lose us as best friendsC. He knows we are naughty and stubborn.D. He hopes we will forgive and understand him one day. Questions 17 through 20 are based on the following conversation.17. A. Whether the game is the hottest mobile game. B. Whether the game affects children's growth.C. Whether the game distorted historical figures.D. Whether the game is a nice game for the young.18. A. The game is very popular among us. B. The game was questioned by officials.C. The game makes people crazy.D. The game takes up much of our spare time.19. A. It helps people learn to set goals. B. It helps people learn to fight for success.C. It helps people learn to control time.D. It helps people learn to cooperate with others.20. A. The advantages of this game B. The importance of this game.C The way to play this game D. The dispute about this gameII. Grammar and VocabularySection A: Directions:After reading the passages below, fill in the blanks to make the passages coherent and grammatically correct. For the blanks with a given word, fill in each blank with the proper form of the given word; for the other blanks, use one word that best fits each blank. (6)Natalie Doan, 14, has always felt lucky to live in Rockaway, New York. Living just a few blocks from the beach, Natalie can see the ocean and hear the wave from her house. "It's the ocean __21__makes Rockaway so special," she says.On October 29, 2012, that ocean turned fierce. That night, Hurricane Sandy attacked the East Coast, and Rockaway _22__(hit) especially hard. Fortunately, Natalie's family escaped to Brooklyn shortly _23__ the city's bridge closed.When they returned to Rockaway the next day, they found their neighborhood in ruins. Many of Natalie's friends___24__(lose) their homes and were living far away. All around her, people were suffering, especially the elderly. Natalie's school was so damaged that she had to temporarily attend a school in Brooklyn.In the following few days, the men and women helping Rockaway recover inspired Natalie. Volunteers came with carloads of___25__(donate) clothing and toys. Neighbors devoted their spare time to helping others rebuild. Teenagers climbed dozens of flights of stairs__26__(deliver) water and food to elderly people trapped in powerless high-rise buildings."My mom tells me that I can't control__27___ happens to me," Natalie says. "but I can always choose __28__I deal with it. "Natalie's choice was to help. She created a website page __29__(match) survivors in need with donors who wanted to help. Natalie posted introduction about a boy named Patrick, who lost his baseball card collecting when his house burned down. Within days, Patrick's collection was replaced.In the coming months, her website page helped lots of kids: Christopher, _30__ received a new basketball; Charlie, who got a new keyboard. Natalie also worked with other organizations to bring much-need supplies to Rockaway. Her efforts made her a famous person. Last April, she was invited to the White House and honored___31__ a Hurricane Sandy Champion of Change.Today, the scars (创痕) of destruction are still seen in Rockaway, but hope is in the air. The streets are clear, and many homes have been rebuilt. "I _32__not imagine living anywhere but Rockaway," Natalie declares. "My neighborhood will be back, even stronger than before. "Section B: Directions: Complete the following passage by using the words in the box. Each word can begone 33 . More are likely to follow. In March the 34 of a large-scale, 24-year survey gave one of the clearest pictures yet of the decline of Australian and Asian shorebirds, including the long-distance migrants (候鸟) that are most difficult to 35 . The results of the survey are awful.Every October for more than two decades, teams from the University of New South Wales in Australia counted birds from an airplane flown low over 130,000 square miles of wetlands in the eastern third of the continent. Their 36 showed a steady decline, beginning in the mid-1980s. By 2006 the number of migratory shorebirds had dropped by 73 percent and the number of Australia’s resident of shorebirds had fallen by 81 percent. “The37 of the decline took us by surprise,” says evolutionary ecologist Silke Nebel of the University of Western Ontario in London, the lead author of the report.The survey 38 that inland wetlands were more important to both resident and migratory birds than had been 39 , and that wetland loss from damming (筑坝) and the diversion (分散) of river water for irrigation was at least in part 40 for the shorebird decline in Australia. But wetlands are becoming smaller in countries all along the major flyway that 41 from eastern Siberia to New Zealand, the study’s authors note, so protecting the 8 million birds that use the corridor 42 will require an international solution.III. Reading ComprehensionSection A: Directions: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context. (15)Traditionally uniforms were manufactured to protect the worker. When they were first designed, it is also likely that all uniforms made symbolic sense — those for the military, for example, were originally __43__ to impress and even terrify the enemy; other uniforms indicated a distinction in __44__ — chefs wore white because they worked with flour, but the main chef wore a black hat to show he inspected and supervised.The last 30 years, however, have seen an increasing __45__ on their role in mirroring the image of an organization and in uniting the workforce, particularly in “customer facing” industries. From uniforms and workwear has emerged “__46__ clothing”. “The people you employ are your ambassadors (大使),” says Peter Griffin, managing director of a major retailer in the UK. “What they say, how they look, and how they behave is of vital importance.” From being a simple means of __47__ who is a member of staff, the uniform is emerging as a new channel of marketing communication.Truly effective marketing through __48__ images such as uniforms is a subtle art, however. How we look sends all sorts of powerful messages to other people. Dark colours give a sense of __49__ while lighter colour shades suggest approachability. Certain dress style creates a sense of conservatism (守旧), while others a sense of __50__ to new ideas. If the company is selling quality, then it must have quality uniforms. If it is selling style, its uniforms must be stylish. If it wants to appear __51__, everybody can’t look exactly the same.But turning corporate philosophies into the right combination of colour, style, degree of branding and uniformity is not always __52__. According to Company Clothing magazine, there are 1000 companies supplying the workwear and corporate clothing market. Of these, 22 __53__ for 85% of total sales — £380 million in 1994.A successful uniform needs to __54__ two key sets of needs. On the one hand, no uniform will work if staff feel uncomfortable or ugly. On the other hand, it is __55__ if the look doesn’t express the business’s marketing strategy. The greatest challenge in this respect is time. When it comes to human awareness, first impressions count. Customers will assess the way staff look in just a few seconds, and that few seconds will __56__ their attitudes from then on. Those few seconds can be so important that big companies are prepared to __57__ years, andmillions of pounds, getting them right.43. A. intended B. tended C. extended D. attended44. A. statue B. stability C. status D. statistics45. A. preference B. argument C. compliment D. emphasis46. A. cooperate B. political C. corporate D. academic47. A. exposing B. identifying C. qualifying D. requesting48. A. studio B. audio C. visual D. casual49. A. clarity B. authority C. availability D. accessibility50. A. exposure B. rejection C. reluctance D. openness51. A. stable B. uniform C. innovative D. similar52. A. smooth B. disagreeable C. objective D. complex53. A. exchange B. call C. stand D. account54. A. establish B. balance C. neglect D. desert55. A. pointless B. significant C. useful D. careless56. A. maintain B. shape C. draw D. value57. A. commit B. command C. dedicate D. investSection B: Directions:Read the following four passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage you have read. (20)AAmong all the fast growing science and technology, the research of human genes, or biological engineering as people call it, is drawing more and more attention now. Sometimes it is a hot topic discussed by people.The greatest thing that gene technology can do is to cure serious diseases that doctors at present can almost do nothing with, such as cancer and heart disease. Every year, millions of people are murdered by these two killers. And to date, doctors have not found an effective way to cure them. But if the gene technology is applied, not only these two diseases can be cured completely, bringing happiness and more living days to the patients, but also the great amount of money people spend on curing their diseases can be saved, therefore it benefits the economy as well. In addition, human life span(寿命) can be prolonged.Gene technology can help people to give birth to healthy and clever children. Some families, with the English imperial family being a good example, have hereditary(遗传的) diseases. This means their children will for sure have the family disease, which is a great trouble for these families. In the past, doctors could do nothing about hereditary diseases. But gene technology can solve this problem perfectly. The scientist just need to find the wrong gene and correct it, and a healthy child will be born.Some people are worrying that the gene research can be used to manufacture human beings in large quantities. In the past few years, scientists have succeeded in cloning a sheep, therefore these people predict that human babies would soon be cloned. But I believe cloned babies will not come out in large quantities, for most couples in the world can have babies in very normal way. Of course, the government must take care to control gene technology.58. What does “these two killers” in the second paragraph refer to?A. Gene technology and another treatment of the two diseases.B. The two murderers who killed the cloned baby.C. Hereditary diseases and cancer.D. The two diseases of cancer and heart disease.59. What’s the main idea of the third paragraph?A. Gene technology can be used to clone human babies.B. How gene technology can be applied in the field of treating hereditary diseases.C. Gene technology can help people to give birth to a baby.D. Gene technology can help the English imperial family out.60. In what way gene technology can help to treat hereditary diseases?A. Using gene technology, people with hereditary diseases can have more living days.B. Using gene technology, human babies can be cloned.C. Using gene technology, the scientist finds the wrong gene and corrects it.D. Doctors can cure cancer and heart disease with the help of gene technology.(B)Where to DrinkCafe San BernardoJoin table-tennis and pool-playing port. Cafe San Bernardo has been running since 1912.The Villa Crespo dive bar also offers up table football for£4 an hour. Service is efficient; with last orders at 5 am. The daily happy hour between 6 pm and 9 pm includes 60 minutes playing your game of choice, plus a half-bottle of red wine and a corn pie, for£9.●Avenue Corrientes 5436, Villa Crespo, 5411 4855 3956, cafesanbernardo. comM Salumeria & EnotecaTrading only in wine with a story, sommelier (侍酒师)Mariana Torta chooses new ways on a daily basis, and keeps a list of around 250 labels. There's no wine menu—simply take your bottle from the shelf.●Open 11:00am-11:30pm, El Salvador 5777, Palermo Hollywood, 5411 4778 9016, on FacebookNegro Cueva de CafeCoffee has found its place in Buenos Aires. While LAB: Tostadores, The Shelter and Coffee Town are famous new places, Negro Cueva de Cafe is one of the best downtown. It serves Ecuadorian, Colombian and Brazilian beans and its attracting cakes include croissant.●Open 9:30 a m—7:00 pm, Suipacha 637, Microcentro, 5411 4322 3000, negrocuevade-cafe. comLa CalleHead to the Niceto Vega address and you'II be faced with a pizza. Don't worry, it’s the right place. La Guitarrita is the front to “hidden” bar La Calle. Order the house cocktail, special candy, and prepare to sing until dawn with a high-energy young crowd.●Open 8:00 pm—2:00 am, Niceto Vega 4942, Palermo Soho, 5411 3914 1972, on Facebook61. Which number should you call if you are an addict of Columbian coffee flavour?A. 5411 4322 3000.B. 5411 4778 9016.C. 5411 4855 3956.D. 5411 3914 1972.62. What makes La Calle different?A. Its allowing you to play games.B. Its having no wine menu.C. Its opening for the longest time.D. Its having special candy.63. The author's purpose in writing the passage is .A. to show wine cultureB. to show how to enjoy yourselfC. to help people choose drinksD. to introduce some wine bars(C)What does it say about the futu re of meat when the country’s largest processor of chicken, pork, and beef buys a stake(股份) in a start-up that aims to “perfectly replace animal protein with plant protein”?Tyson Foods announced this week that it purchased a 5 percent stake in Beyond Meat, the Southern California-based food-tech start-up that made headlines earlier this year with its veggie burger that reportedly cooks and tastes like real beef.To be sure, Beyond Meat’s meatless creations have yet to take the country by storm. Although th e 100 percent plant-based burgers have achieved plenty of positive press since they appeared for the first time in May, so far they’re only available at Whole Foods stores in seven states. Even though the company’s “chicken” strips, “beef” pies, and meatle ss frozen dinners are available nationwide, Beyond Meat is hardly a household name.That may be what makes the news of Tyson’s investment all the more noteworthy. While the two companies declined to give details about the deal, it’s doubtful that Tyson’s 5 percent stake made much of dent(凹陷) in the meat giant’s coffers(金库). The company posted $41.4 billion in sales last year; prior to the deal with Tyson, Beyond Meat had reportedly raised $64 million in project capital funding—about what Tyson earns before lunch on any given day.Tyson is doing pretty great. The company reported record third-quarter earnings per share in August and says that it expects overall meat production to increase 2 to 3 percent during the next financial year. But like a big oil compa ny shelling out cash to invest in wind power, Tyson’s toe-in-the-water move to team up with a start-up devoted to bringing more plant-based protein to American dinner tables seems to suggest the meat industry is starting to see which way the winds are blowing.Sales of plant-based protein, which totaled an estimated $5 billion last year, continue to pale compared with the market for meat in America—but vegetarian alternatives to meat are booming, with sales growing at more than double the rate for food products overall. The steady drumbeat of news about the negative health impacts, environmental problems, and animal welfare concerns associated with meat consumption appears to be sinking in. According to a survey released in April, more than half of Americans surveyed said they plan to eat more plant-based foods in the coming year.64. Beyond Meat’s veggie burger made headlines probably because __________.A. it makes perfect use of animal proteinB. it tastes as good as a genuine beef burgerC. it uses high tech in the making processD. it represents the diet trend in South California65. Which of the following statements is TRUE regarding the state of Beyond Meat?A. It is the creator of the country’s first 100 percent plant-based burgers.B. It has been well received as its products are available nationwide.C. It is far from being a match to real food processing giants like Tyson.D. It provides high-quality dining experience in selected Whole Foods stores.66. What can we infer from paragraph 4?A. The 5 percent stake in Beyond Meat means a lot to Tyson.B. The purchase of the stake barely costs a thing for Tyson.C. Tyson’s investment hasn’t caught the attention of the media as expected.D. Tyson is relying on this investment to raise more project capital funding.67. What does the passage mainly talk about?A. A major American meat company is betting on plant-based protein.B. Meat will still take over the market in spite of other alternatives.C. Tyson and Beyond Meat work together to build a global meat giant.D. Plants have been found to contain protein that does more good to human beings.Section C:Directions:Read the following passage. Fill in each blank with a proper sentence given in the box.Depression is a common illness that affects many people throughout the world. About 10%-15% of the population will suffer from the illness. ___68___ . One’s personal relationship s, performance at work and enjoyment of leisure activities will be greatly affected. Depression occurs more frequently in women and elderly.___69__. This can make it difficult to diagnose. However, a number of symptoms are commonly seen in our daily life. For example, feelings of anxiety or guilt, inability to concentrate or make decisions, loss of interest in personal appearance, reduced appetite, and so on.There are many myths and misconception about depression. Many people think depression will go away if the sufferer just makes an effort to think positively. Unfortunately, they do not understand that depression is an illness that requires specific treatment, just as other illness does. __70__. It also means that people with depression are often reluctant to tell their friends about their condition.Fortunately, a number of effective drugs and psychological interventions are available to treat depression, and the illness can be successfully treated in the majority of people. By visiting your doctor and having your depression diagnosed, you have already taken the first step on the road to recovery. ___71_.Depression can be a difficult illness for your family and friends to understand. However, once they understand the nature of your illness, your family can help by reminding you to take your medicine and encouraging you to go to your counseling session.第II 卷(共23分)I. Translation:Directions: Translate the following sentence into English, using the words given in the brackets. (13)72.园丁们打算在早春把花园修缮得和先前一样美。
上海市上海大学市北附中2018年高一第一学期数学期中考试卷(简答)

高一第一学期数学期中考试卷答题时间 90 分钟满分 100 分一.填空题(本大题每题 4 分,共 40 分)1. 已知会合 Ax x 1, Bx xa ,且 A B R ,则实数 a 的取值范围是 _________.2.给出以下 8 个命题:○1 b aab 0 ;○2 a b0 a 2 ab ;○3 a b0 1 1 ;a b4bac 22 5a b,c dac6cac 7ba b c 0 ;○ abc;○bd ;○ ab;○ ac 2c 2b8b, c da cb d ,○ a此中真命题的序号是 ____.(将你以为的全部真命题的序号都填上)3.不等式 x x x 的解集是 ___________.4. 某种衬衫进货价为每件 30 元,若以 40 元一件销售,则每日能卖出40 件;若每件抬价 1 元, 则每日卖出件数将减少一件,为使每日销售衬衫的净收入不低于 525 元,则每件衬衫的售价的取值范围是 ______________.(结果用区间表示)5. 设函数 f x2x 1 , x,则不等式 f x 0 的解集为 ____________.3 x , x 0 x6. 函数 y2 , x,1 U 2,5 的值域为 ____________.x 17. 若函数 f x 是定义在 R 上的偶函数,在 0,上是减函数,且 f2 0 ,则不等式 f x1 0的解集为 ________________.8. 若函数 f xm 2 m1 x m2 2 m3 是幂函数,且在 0,上是减函数,则不等式 x m x 的解为 ______________.9.在 4×□+ 9×○= 60 的□和○中,分别填入两个自然数,使它们的倒数之和最小,则应分别填入 ___________ 和 ____________.10. 已知会合Ax 1x4 , f xx 2pxq , g xx4 x是定义在 A 上的函数,且在x 0 处同时取到最小值,并知足f x 0g x 0,则 f x 在 A 上的最大值为____________.二.解答题(本大题共60 分)11.(此题满分 10 分)已知 f x是定义在5,5 上的奇函数,g x是定义在, 22,上的偶函数,记h x f x ·g x ,判断 h x 在其定义12.(此题满分 10 分)已知函数 f x x22ax 1,x 0,1 ,( 1)求f x 的最小值;( 2)若f x 的最小值是 3 ,务实数 a 的值 .13.(此题满分 12 分)已知正常数a,b 和正实数 x, y 知足 a b 10 ,ab 1 ,若 x y 的最小值为18,求 a, b x y的值 .14.(此题满分14 分)已知函数 f x 3 x a , g x x 2 x 2a ,若不等式 f x 6 的解集为3,1 ,( 1)务实数 a 的值;( 2)设 F x f x g x ,写出 F x 的分析式,并作出 F x 的图像;(3)依据图像,写出 F x的单一区间:递加区间为 _________;递减区间为 ______;15.(此题满分 14 分)已知函数 f x x2 10 x a 3 ,( 1)当 a 1 时,判断并用定义证明f x在 x 2, 上的单一性 .g xx( 2)若 f x 0 对全部 x 2, 恒建立,务实数 a 的取值范围;( 3)若 f x ax 对全部 x 2,3 恒建立,务实数 a 的取值范围 .参照答案:1. 已知会合 A x x 1 , B x x a ,且 A B R ,则实数 a 的取值范围是 _________. a 12. 给出以下 8 个命题:○1b aa b 0 ;○2 a b0 a2ab ;○3 a b0 1 1 ;a b○4a bac 2bc 25a b,c dac bd6c 7a b ;;○ ;○ abc a b ;○ a bc 2 c 2 c 08b, c d a c b d ,○ a此中真命题的序号是 _____________.(将你以为的全部真命题的序号都填上)○1 ○2 ○3 ○73. 不等式 x xx 的解集是 ___________., 10,14. 某种衬衫进货价为每件30 元,若以 40 元一件销售,则每日能卖出40 件;若每件抬价 1 元, 则每日卖出件数将减少一件,为使每日销售衬衫的净收入不低于525 元,则每件衬衫的售价的取值范围是 ______________.(结果用区间表示) 45,655. 设函数 f x2x 1 , x,则不等式 f x 0 的解集为 ____________. 1 ,3 x , x 0 x2 6. 函数 y2 , x,1 U 2,5 的值域为 ____________.- ,01,2x 127. 若函数 f x 是定义在 R 上的偶函数,在 0,上是减函数,且 f2 0 ,则不等式 f x 1的解集为 ________________.1,38. 若函数 f xm 2m22 m 3是幂函数,且在 0,x mx 的解1 x m上是减函数,则不等式为 ______________. 0,19.在 4×□+ 9×○= 60 的□和○中,分别填入两个自然数,使它们的倒数之和最小,则应分别填入 ___________ 和 ____________. 6、 410. 已知会合Ax 1x4 , f xx 2pxq , g xx4 x是定义在A 上的函数,且在x 0 处同时取到最小值,并知足f x 0g x 0,则f x 在A 上的最大值为____________. 811. 已知f x 是定义在5,5上的奇函数,g x 是定义在, 22,上的偶函数,记h xf x·gx,判断 h x在其定义域上的奇偶性,并用定义证明.D 5, 2 2,5 ,奇函数12. 已知函数 f x x2 2ax 1,x 0,1 ,( 1)求 f x 的最小值;( 2)若 f x 的最小值是 3 ,务实数 a 的值 .( 1)当 a 0 时,y min f 0 1 ;当0 a 1 时,y min f a 1 a2;当a 1 时,y min f 1 2 2a . (2)a5213. 已知正常数 a, b 和正实数 x,y 知足 a b 10 ,ab 1,若 x y 的最小值为18,求 a, b x y的值 . a 2,b 8 or a 8,b 214. 已知函数 f x 3 x a , g x x 2 x 2a ,若不等式 f x 6 的解集为3,1 ,( 1)务实数 a 的值; a 1( 2)设 F x f x g x ,写出 F x 的分析式,并作出F x 的图像; F x x2 2x 1, x 1 x2 4x 5, x 1(3)依据图像,写出 F x的单一区间:递增区间为 _________ ;递减区间为 ______ ;, 2 , 1,1 增;2, 1 , 1, 减15. 已知函数 f x x2 10 x a 3 ,( 1)当 a 1 时,判断并用定义证明g x f x 在 x 2, 上的单一性 . 单一递加x( 2)若 f x 0 对全部 x 2, 恒建立,务实数 a 的取值范围; a 22( 3)若 f x ax 对全部 x 2,3 恒建立,务实数 a 的取值范围 . a 9。
上海市上海大学市北附属中学2017-2018学年高一上期中数学试题(无答案)word

上海大学市北附属中学2017学年第一学期期中考试高一数学试卷2017.11一、填空题(本大题每题4分,共48分)1、已知集合}4,3,2,1{=A ,}5,4,3{=B ,则B A =___________2、不等式1|1|<-x 的解集是_________3、设集合}30|{≤<=x x M ,}20|{≤<=x x N ,那么“M a ∈”是“N a ∈”的_________条件4、命题“若0>ab ,则0>a 且0>b ”的一个等价命题是___________5、不等式11>-xx 的解集是__________ 6、若关于x 的不等式0<-b ax 的解集为),1(+∞-,则关于x 的不等式02<+bx ax 的解集为__________7、设⎪⎩⎪⎨⎧<≥-=0,10,121)(x xx x x f ,则))1((f f =_________ 8、若函数b x x f +=3)(是]1,[a x ∈上的奇函数,则b a +的值为__________9、函数)(x f y =的定义域]4,2[-,则函数)()()(x f x f x g -+=的定义域为__________10、已知函数)(x f 为R 上的奇函数,当0≥x 时,)1()(+=x x x f ,若2)(-=a f ,则实数a =_______11、已知)(),(x g x f 分别是定义在R 上的偶函数和奇函数,且1)()(23++=-x x x g x f ,则)1()1(g f +=_________12、若实数0≠a ,函数⎩⎨⎧≥--<+=1,21,2)(x a x x a x x f ,)1()1(a f a f +=-,则a =_______ 二、解答题(本大题共52分)13、(本题满分8分)集合}0|{2=++=q px x x A ,}0|{2=+-=r x x x B ,}1{-=B A ,}2,1{-=B A ,求r q p 、、14、(本题满分10分)已知函数)1()3()1(2-+-+-=m x m x m y ,m 取什么实数时,函数图像与x 轴(1)没有公共点?(2)只有一个公共点?(3)有两个不同的公共点?15、(本题满分10分)某新建居民小区欲建一面积为700平方米的矩形绿地,在绿地四周铺设人行道,设计要求绿地长边外人行道宽3米,短边外人行道宽4米。
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2017学年度市北中学第一学期高一年级数学期中考试试卷
一、填空题(每小题3分)
1. 已知集合2{2,3,1}B a a =-+,且{1,2}A a =+,A B ⊆,则实数a =___________
2. 命题“若21a ≠,则1a ≠”的逆否命题是___________
3. 若函数()1),()
f x
g x ==()()f x g x ⋅=___________ 4. 已知集合{|},{|1A x x a B x x =<=≤或2}x ≥,且R A
B =∅ð,则实数a 的取值范围是
___________ 5. 已知,a b R ∈,且2221a b +=,则ab 的最大值是___________
6. 已知(,1)(5,),(,4)A B a a =-∞-+∞=+,若A B A =,则实数a 的取值范围是___________
7. 设条件:22x α-<<,条件:2213m x m β-≤<-,且α是β的充分条件,则实数m 的取值范围是___________
8. 已知a R ∈,不等式31x x a
-≥+的解集为P ,且2P -∉,则a 的取值范围是___________ 9. 某服装公司生产得到衬衫,每件定价80元,在某城市年销售8万件,现在该公司在该市设立代理商来销售衬衫代理商要收取代销费,代销费为销售金额的r %(即每销售100元收取r 元),为此,该衬衫每件价格要提高到801%
r -元才能保证公司利润。
由于提价每年将少销售0.62r 万件,如果代理商每年收取的代销费不小于16万元,则r 的取值范围是___________
10. 定义:关于x 的不等式||(,0)x A B A R B -<∈>的解集称为A 的B 领域,若3a b +-的a b +领域是区间(3,3)-,则22a b +的最小值是___________
二、选择题(每小题4分)
11. 已知,a b 为非零实数,且a b <,则下列命题成立的是( )
A. 22a b <
B. 22a b ab <
C. 2211ab a b <
D. b a a b
< 12. 下列四组函数中,函数()f x 与()g x 表示同一个函数的是( )
A. 2()||,()f x x g x ==
B. (),()f x x g x ==
C. 3(),{1,0,1},(),{1,0,1}f x x x g x x x =∈-=∈-
D. 以上三组都不是同一个函数
13. 若{(,)|0,,},{(,)||||||,,}P x y xy x y R Q x y x y x y x y R =≤∈=+≠+∈,则( )
A. P Q =∅
B. P Q =
C. P Q ⊃
D. P Q ⊂
14. 设,x y R +∈,当21x y +=时,14a x y
+≥恒成立,则a 的最小值是( ) A. 12 B. 1 C. 23 D. 2
三、解答题
15. (本题10分)解关于x 的不等式:2(21)20()mx m x m R --->∈
(1)求一次购买x (单位:千克),此商品的花费()f x (单位:元)的函数解析式;
(2)某人一次购买此商品400元,问他能购得此商品多少千克?
(1)若()f x 的定义域为R ,求a 的取值范围;
(2)当1a =时,求()f x 的最小值
18. (本题11分)求出一个数学问题的正确结论后,将其作为条件之一提出与原来问题有关
的新问题,我们把它称为原来问题的一个“逆向”问题。
例如,原来问题是“若直角三角形的两条直角边长分别为3和4,求该直角三角形的面积”,求出面积6 后,它的一个“逆向”问题可以是“若直角三角形的面积为6,一条直角边长为3,求另一条直角边的长”。
试给出问题“已知c a b =+,若12,13a b ≤≤-≤≤,求c 的取值范围”的一个“逆向”问题,并解答你所给出的“逆向”问题。
19. (本题12分)若实数,,x y m 满足||||x m y m -<-,则称x 比y 接近m
(1)若4比2
3x x -接近0,求x 的取值范围;
参考答案
1、0
2、如果1a =,则21a = 3
[)())0,11,x ∈⋃+∞ 4、1a ≤ 5
6、(][),55,-∞-⋃+∞
7、13m ≤-
8、()[),32,-∞-⋃+∞
9、100,1031⎡⎤⎢⎥⎣⎦ 10、92
11-14、CCCA
15、当0m >或12m ≤-时,解集为()1,2,m ⎛⎫-∞-⋃+∞ ⎪⎝⎭
; 当0m =时,解集为()2+∞,;当102m -<<时,解集为()1,2,m ⎛⎫-∞⋃-+∞ ⎪⎝⎭
16、(1)()[](](]10,0,2092020,4086040,x x f x x x x x ⎧∈⎪=+∈⎨⎪+∈+∞⎩;
(2)42.5千克
17、(1)04a <<;(2)1
18、“逆向”问题:已知c a b =+,若05,12c a ≤≤≤≤,求b 的取值范围。
解答:24b -≤≤
19、(1)()(),14,-∞-⋃+∞;(2)证明略;(3)()4,2-。