SOLVSAMP
新型的常年法律合规顾问服务方案
新型的常年法律合规顾问服务方案新型的常年法律合规顾问服务方案01 背景常法服务的内容与方式均需变革依法治企及合规经营是当今任何一家企业获得长久成功的基石。
现在的企业家都把对法律的运用当作发展的重要武器。
他们纷纷聘请法律与合规顾问对其经营与管理行为进行法律上的把关。
法律顾问，包括律师和法务，对企业快速发展与壮大的作用，日渐显现。
但是，很多律师在提供顾问服务时，效果往往不尽人意，甚至与企业的本来意愿背道而驰。
首先，传统的企业法律顾问存在服务内容单一，律师是顾而不问，问而不全等问题。
在这种服务模式下，企业的价值感不强，对专业价值的体验不够。
同时，随着企业对合规要求的加深，传统律师提供的仅是纯法律层面的服务，对于与法律密切相关的或进一步延伸的公司合规服务，却较少涉及。
其次，外部法律顾问（律师）与企业管理者、业务人员及企业的内部法律顾问（法务），在沟通与协作上也出现了一些不及时、不通畅的现象，导致企业支出了成本，却未产生相应的收益。
最后，律师作为法律方面的知识工作者，出于种种原因不了解企业，与企业的关注点经常不一致，导致法律工作与商业实践的脱钩。
法律强调风险预防，商业强调利润获取，两者亟需平衡。
如何解决以上痛点问题，平衡利益与风险，加强企业与法律顾问的沟通，实现法律顾问工作的流程化、标准化和模块化，提高企业法律运用的效率与效能，从而助推企业真正实现依法治企、合规经营，是所有创新型的执业律师必须思考的问题。
北京德和衡律师事务所律师团队推出本新常法.德服务法律与合规顾问产品。
02 内容复合式的服务菜单新常法.德服务法律合规顾问服务的内容实行菜单化、模块化。
核心模块：日常全领域法律顾问合同审查：合同起草，审查与修改；合同范本的制作；合同管理流程梳理等人力资源：员工招聘与解聘法律咨询；劳动制度与员工手册审查；劳动纠纷与仲裁咨询等规章制度：公司规章制度梳理与审查；公司管理行为合规咨询；公司治理方案设计与咨询等知识产权：商标专利版权注册检索咨询；品牌保护方案审查与咨询；知识产权侵权的咨询等合规顾问：企业合规情况诊断分析；合规流程与合规制度的法律建议；创新业务模式前期咨询等税务筹划：企业重大交易、并购、融资、重组等涉税事务的前期咨询投资并购：企业股权收购、资产收购、合并与分立等事项的前期法律咨询融资事项：企业股权融资、债权融资、融资合作等事项的前期法律咨询诉讼仲裁：企业涉及的诉讼或仲裁的前期咨询刑事风险：企业及企业高管涉嫌刑事犯罪的前期咨询法律公关：企业遭受危机或其他紧急情况下的前期法律咨询增值模块：五项特色增值服务法务管理架构：为企业搭建适宜业务与商业模式的法务部设置、法务管理流程法务人员培训：为企业提供法务人员的培训、交流等专项服务法务操作标准化：对企业基础的、例行的法务操作进行标准化、模块化的咨询与协助合规诊断报告：对企业的业务线、产品线、商业模式等的合规进行诊断、体检并出具报告年度法律风险评估报告：对企业的诉讼、纠纷及行业风险进行整理，出具年度风险评估报告资源模块：外部相关资源对接服务疑难要案论证资源：必要时，为企业提供疑难案件的第三方法律论证资源法务人才推荐资源：需要时，为企业推荐合适的法务人才投融项目信息资源：需要时，为企业提供特定事宜或项目或上下游企业的投融资信息资源法务管理软件资源：必要时，为企业提供合作的第三方合同或法律事务管理软件资源03 方式快、严、专、畅新常法.德服务法律合规顾问产品以客户为中心，第一时间内替客户分忧。
大连交通大学coa考试题1
1.In floating-point arithmetic,multiplication can divide to 4 steps:A. Check for zero, add exponets,multiply significands,normalize, and roundB. Fetch instrution,indirectly address operand,execute instrction and interruptC.process scheduling states:creats,get ready,is running and is blocked.D.load first operand,add second operand ,check overflow and store result2.Which the following is not the area that the source and result operands can be stored in_______?A.Main or virtual memoryB.CPU registerC.I/O deviceD.Instruction3.The advantage of Immediate Addressing is _______A.limited address rangeB.more memory accessC.limit value rangeD.no memory access4.The address is known as a type of date, because it is represented by ____.A.twos complementB.a signed integerC.an unsigned integerD.a number of hexadecimal5.In direct addressing mode, the operanad is in ____A.the main memoryB.the register RC.the instructionD.none6.In ____ sub-cycle,CPU fetch the operand’s address from memory.A.indirectB.fetchC.executeD.interrupt7.Which is not in the ALU? _____A,shifterB.adderplementerD.accumulator8.Instruction pipeline can improve______A.processing speed of programB.accessing speed of memoryC.accessing speed of I?OD.accessing speed of RAID9.The protocol “mesi” is alse called _______.A.write back policyB.write -update protocolC.write -invalidate protocolD.write through policy10.MESI protocol can solve the ______.A.problem of cache coherenceB.problem of memory write bottle-nekmunication problem of person-computerD.volatile problem of DRAM11.At the end of fetch cycle,IR holds______.A.instructionB.operandC.address of operandD.address of instruction12.There are three kinds of BUS,Which does not belong to themA.address busB.system busC.data busD.control bus13.Cache’s write-back policy means write operation to main memory_____.A.as well as to cacheB.only when the relative cache is replacedC.when the difference between cache and main mimory is foundD.only when using direct mapping14.A four-way set associative chache has 63k words,main memory has 256M words and divided 32M blocks.line size is _____words.A.4B.8C.16D.3215.In the following description,which is NOT right6?________.A.SRAM is faster than DRAMB.DRAM needs periodic charg refreshing circuitC.DRAM is slower than FlashD.ROM does not require power supplied continuously16.Which RAID level make use of parallel access technique?______.A.RAID0B.RAID2C.RAID4D.RAID617.RAID stored _____information that enable the recovery of data lost due to a disk failure.A.parityer dataC.OSD.interrupt18.The signals of interrupt request and acknowledgement exchange between CPU and requesting I?O module. The rason of CPU’s acknowledgement is ______.A.to let the I?O module remove request signalB.to let CPU get the vector from data busC.both A&BD.other aims19.In DMA,the DMA module takes over the operations of data transferring from CPU,it means_______.A.the DMA module can fetch and execute instructions like CPU doesB.the DMA module can control the bus to transfer data to or from meory using stealing cycle techniqueC.the DMA module and CPU work together(co-operate)to transfer data into or from memoryD.the DMA module get ready,it issues interrupt request signal to CPU for getting interrupt service20.In twos complement,two positive intergers add,when does overflow occur?A.There is a carryB.Sign bit of result is 1C.There is a carry,and sign bit of result is 0D.Can’t determine21.The 8-bits twos complement -128 is 10000000,its 16-bits twos complement is ___A.1000 0000 1000 0000B.0000 0000 1000 0000C.1111 1111 1000 0000D.1000 0000 0000 000022.The address of the top of stack is stored in ____ registerA.PCB. ACC.SPD.BP23.The REGISTER ADDRESSING is very fast,but it has_______.A.very less value rangeB.very less address spaceC.more memory accessD.very complex address’ calculating24.In instrucion,the number of addressed is 2,One address doubles as____A.a result and the address of next instructionB.an operand and a resultC.an operand and the address of next instructionD.two closed operands25.A branch instruction performed by CPU is to updatae ______.A.MBR to contain the instructionB.Program counter to contain the address of next instructionC.MAR to contain the address of current instructionD.IR to contain the instruction that just fetched from memory26.In register indirect addressing,the effective address of operand is stored in ____.A.registerB.main memoryC.instructionD.PC27.The Memory Address Register of CPU connects to ______BUSA.systemB.addressC.dataD.control28.The Accumulator is a(n)______register in 8086A.general purposeB. DataC.addressD.control29.Which is the worst instruction to limit instruction pipeline?A.ADD AX,XB.MOV AX,[X]C.RETURND.ISZ X30.In MESI protocol,the line in the cache is the same as that in main memory and is not present in other cache,which state is the line in______.A.ModifiedB.exclusiveC.sharedD.invalid31.Which of the following attributes associated with architectureA.Control signalsB.interfacesC.Instruction setD.memory technology32.Which of the following statement is not correct?A.N bits binary address coding can be 2N storage word to identify a wordB.N bits unsigned binary number can represent a value in the range between 0 to 2N-1C.The length of address is 32 bits ,so addressing range is 4GD.8086 has 20 bite address bus giving 220-1 address spaceputer memory is organized into a hierarchy .At the top level are the_____.A.registers B cache C.main memory D.external memory34.On address mapping of cache ,the data in any block of main memory can be mapped to ______of cache ,it is direct mapping.A.any lineB.fixed lineC.fixed set any lineD.A and B35.Which is the nonvolatile and permanent storge semiconductor memory?___A.SRAMB.CD-ROMC.FLASHD.DRAM36.In hamming code ,if syndrome contains one & only one 1,it means____.A.the old correct bit is errorB.the data is errorC.more than one errorD.nor error37.In _____,two copies of each stripe on separate disks,read from either and write to both.A.RAID 1B.RAID2C.RAID 3D.RAID438.When aprocessor access to the disk physical block ,it must know that the physical blocks on the disk location of three parameters:________.A.side,head and trackB.side ,sector and cylinderC.cylinder,sector and trackD.side,sector and platter39.There are three types of the Input Output Techniques,Which one is not belong them?______.A.Interrupt-driven I/OB.programmed I/O \C.direct I/O accessD.DMA40.In DMA,when does DMA module issue interrupt request signal to CPU?A.before DMA module transfers a block dataB.after DMA module finishes a block data transferC.before DMA module seizes to use busD.after DMA module ends to size bus1 2 3 4 5 6 7 8 9 10D D D C A A D A C A11 12 13 14 15 16 17 18 19 20A B B B C B A C B B21 22 23 24 25 26 27 28 29 30C C B B B B B AD B31 32 33 34 35 36 37 38 39 40C D A B C A A B C BII Answer the following questions1)Interrupt Processing,The CPU save information of current program to stack forresuming it.What is the important information?2) In MESI protocol , READ MISS, initiating in invalid and snooping in modified,fill in the following table.initiating snoopingState in beginning invalid ModifyactionState in end3)In Displacement Addressing,EA=A+(R),what is the R register holds? In RelativeAddressing,what is the R register?1）PC, PSW （4分）2）initiating SnoopingBegin invalid ModifiedAction Read data from ……Write to memoryEnd shared shared（4分）3）base or displacement, PC (4分)得分15III A four-way set associative main memory has 256M words,cache has 4M words and block size is 32-words. Please answer the following questions:1)Show the format of main memory addresses2)Which set of cache is memory location FCB5C6AH mapped to?What is the tag?3)Which words of main memory may be mapped to cache set 6E8A and tag value is B5H?1)-2分- Line size=Block size=32words=25words =>Word# =5bits(2)-3分- Number of sets=4M/32 lines/ 4lines/set =215sets =>Set# =15bits(3)-2分-Memory size=256Mwords=228words => Length of RA =28bits =>Tag=28-5-15=8 bitsTag 8 itb Set# 15 bit Word# 5 bit-1分-2) （3分）FCB5C6AH=1111 1100 1011 0101 1100 011 0 1010 is mapping to set# 5AE3, tag#FC3) （4分）B5 6E8A1011 0101 110 1 110 1 000 1 010 0 00001011 0101 110 1 110 1 000 1 010 1 1111words of main memory: B5 DD140~ B5 DD15IV According to the instruction of the following,Answer the questions. 1) Show all the micro-operations for the following instruction: BSA X -Branch and save addressAddress of instruction following BSA is saved in X Execution continues from X+12) Which addressing mode is included in this instruction? Please draw the figure of its addressing mode3) According to the initial value of the following figure ,at the end of Execute cycle,what is the value of PC,MBU,MAR and IR holdⅣAnswer:2) （4分） PC:2012MAR:2012（应该是2011） MBR:1124 IR:BSA 20113) （4分）Direct Addressing1) （10分）Fetch cycle t1: (PC) -> MAR t2: (MAR) ---> Memory read ---> Memory t3: Memory ---> MBR t4: (MBR) -> IR (PC) +1 -> PC Execute cycle t1: Ad(MBR) ->MAR t2: (PC) ->MBR t3: (MAR)-> Memory (MBR) ->Memory write ->Memory t4: (MAR)+1 ->PCFor the 8-bit data 0011 1001,Using the Hamming algorithm,the check bits stored with it.Suppose when the word is read from memory,the check bit are calculated to be 1101.1)What is the data word that was read from memory?2)Write the correct Hamming code(1) （2分）2k-1≥m+k =>k=4-bit(2) （4分）Set up a tableBit Position PositionnumberCheckbitDatabit12 1100 D8011 1011 D7010 1010 D6 19 1001 D5 18 1000 C87 0111 D4 16 0110 D305 0101 D204 0100 C43 0011 D1 12 0010 C21 0001 C1(3)（4分）Calculates old check bits:C1(1,2,4,5,7)=1⊕0⊕1⊕1⊕0=1C2(1,3,4,6,7)=1⊕0⊕1⊕1⊕0=1C4(2,3,4,8) =0⊕0⊕1⊕0 =1C8(5,6,7,8) =1⊕1⊕0⊕0 = 0old check bits：C8C4C2C1=0111 (4)（2分）Syndrome word: 0111⊕1101=1010 =>D6 is wrong, so the data from memory is 00011001.2) （3分）0011 0 100 1 1 11。
高考英语作文高级词汇词组句型大全(可直接打印)(完整资料).doc
【最新整理，下载后即可编辑】词汇篇 单词可以说一个人单词量的展现，如果总停留在使用very good 等小学词汇，那老师把你当成发育不完全也正常.所以要使用一些高级词汇（就象是给文章穿上了成人内衣），我不建议大家用考纲以外的词汇（当然你能用更好），这里可以教你用高级替换简单词汇~~ severe 替换掉serious （严重的） a severe water shortage 严重缺水 needy 替换掉 ppor （ 贫穷的） wealthy 替换掉 rich （ 富裕的） benificial 替换掉 good （有益的） undesirable 替换掉 bad （不好的，不受欢迎的） nevertheless 替换掉 however （然而，不过） fundamental / significant 替换掉 important （ 重要的） relevant 替换掉 related （有关的） ....is highly relevant to....... extraodinary 替换掉 surprising （惊人的，非凡的） provided/providing （that ）替换掉 if （如果.....） promote /strengthen 替换掉 improve （提高，加强） More should be done to strengthen industry's links with universities. 应该做更多的事情加强工业界和大学的联系. cope with 替换掉 solve （ 解决） motivate 替换掉 encourage （ 激励） We are looking for someone who will be able to motivate the staff to work hard.我们在寻找能激励职员们努力工作的人. jeopardize 替换掉 be bad to （损害，危及） Failing exams could jeopardize her future. 考试不及格危及她的前程. ease 替换掉 relieve （减轻，缓解） To ease the problem of ..... 为了缓解....的问题..... well-being 替换掉 happiness （幸福，安康） pros and cons 替换掉 advantages and disadvantages （好处和坏处） You must consider all the pros and cons of the matter before you make a decision.在你做决定之前，必须考虑这个问题的正反两个方面. approach / method 替换掉 way （方法，方案） adopt 替换掉 use （采用，采取） the aged 替换掉 old people （老人） adolescents 替换掉 the young （青少年） employment 替换掉 job （就业） affair 替换掉 thing （事情，东西） bent 替换掉 gift （天赋，爱好） catastrophe 替换掉（ disaster 灾难） subscribe to 替换掉 agree with （ 同意） tend 替换掉 want （趋向于..想要.....） I am tending to another customer at he moment. acquire 替换掉 gain （获得（尤指知识上的）） administration 替换掉 government （政府部门） contribute to 替换掉 cause （引起） extremely 替换掉 very （非常的） frown on sth 替换 disagree with sth （ 不同意） for instance 替换掉 for example （例如） advocate 倡导 compensate for 弥补..... Spare no efforts for 努力 In contemporary society 在当今社会 A vast amount of 大量的 be abundant in 富有... on ones own account 为了某人自己的利益 at ones own risk 自行负责 on account of 由于 On no account 绝不要 arise from 由....引起 Are these any matters arising from the last meeting ？ 这些事情都是由上次的会议引起的吗？ assess 评估，评价 Examinations are not the only means of assessing ones ability. 考试不是评价一个人能力的唯一方法. authentic 真实的，可信的 gradual 逐渐的 There has been a gradual improvment in ...over the last two years. 过去的两年中...逐渐改善. ....multiply rapidly ...迅速增加. ripe 时候成熟的 The country is ripe for change. 国家已是时候改变. trend 趋势，趋向，潮流 The trend at the moment is that .... 现在..是一个趋势..... emphrasize 强调，重视 I ’d like to emphrasize how important it is to .... sustainable development 可持续发展 句型篇 语里面常用的句型也就那么几个，尽量往里套。
文档：随机过程(雷斯尼克,英文)-Chapter1-2作业题提示
Adventures in Stochastic ProcessesChapter 1 Preliminaries1.1. (a) Let X be the outcome of tossing a fair die. What is the gf of X? Use the gf to find EX.(b) Toss a die repeatedly. Let n μ be the number of ways to throw die until the sum of the faces is n. (So 11μ= (first throw equals 1), 22μ= (either the first throw equals 2 or the first 2 throws give 1 each), and so on. Find the generating function of{,1n 6}n μ≤≤ .解：(a) X 的概率分布为 1[],1,2,3,4,5,66P X k k ===,X 的生成函数为 66611111()[]66kk kk k k P s P X k s s s ======⋅=∑∑∑，X 的期望为 6611111117()||662k s s k k EX P s k s k -===='==⋅==∑∑.(b) n μ:点数之和为(1)n n ≥的投掷方法数，则 点数之和为1的投掷方法：第一次投掷点数为1，即0112μ==,点数之和为2的投掷方法： 情形1，第一次投掷点数为2， 情形2，前两次投掷点数均为1，即1222μ==,点数之和为3的投掷方法： 情形1，第一次投掷点数为3，情形2，前两次投掷点数为（1,2），（2,1）， 情形3，前三次投掷点数均为1，即012232222C C Cμ=++=,点数之和为6的投掷方法： 情形1，第一次投掷点数为6,情形2，前两次投掷点数为下列组合之一：1和5，2和4，3和3，情形3，前三次投掷点数为下列组合之一：1,1和4，1,2和3，2,2和2， 情形4，前四次投掷点数为下列组合之一：1,1,1和3，1,1,2和2， 情形5，前五次投掷点数为下列组合之一：1,1,1,1和2， 情形6，前六次投掷点数均为1，即015565552C C C μ=+++=,于是，n μ(6)n ≤的生成函数为66111()2nn n n n n P s s s μ-===⋅=⋅∑∑1.2. Let {},1n X n ≥ be iid Bernoulli random variables with 11[1]1[0]P X p P X ===-=and let 1nn i i S X ==∑ be the number of successes in n trials. Show n S has a binomial distribution by the following method: (1) Prove for 0,11n k n ≥≤≤+1[][][1 ] n n n P S k pP S k qP S k +===-+=.(2) Solve the recursion using generating functions. 解：(1) 由全概率公式，得1111111[][1][|1][0][|0]n n n n n n n P S k P X P S k X P X P S k X +++++++=====+===[1][]n n pP S k qP S k ==-+=(2) 1110()[]n k n n k P s P S k s +++===∑10([1][])n k n n k pP S k qP S k s +===-+=∑1110[1][]n nk kn n k k ps P S k sq P S k s +-====-+=∑∑11[][]n nlkn n l k ps P S l s q P S k s ====+=∑∑211()()()()()n n n ps q P s ps q P s ps q +-=+=+=+所以 1~(;1,)n S b k n p ++1.3 Let {,1}n X n ≥ be iid non-negative integer valued random variables independent of the non-negative integer valued random variable N and suppose()()11(), Var , , Var E X X EN N <∞<∞<∞<∞.Set 1nn i i S X ==∑. Use generating functions to check211Var()Var()()Var()N S EN X EX N =+ 证明：由1()(())N S N X P s P P s =所以 11111()()|(())()|()()N N S s N X X s E S P s P Ps P s E N E X =='''===，1111211()|[(())(())(())()]|N S s N X X N X X s P s P Ps P s P P s P s ==''''''''=+ 11112((1))((1))((1))(1)NX X N X X P P P P P P ''''''=+ （1(1)1X P =） 222111()()()()EN EN EX E N EX EX =-+- 22111Var()()EN X EN EX ENEX =+-又 2211()|()()N S s N N N P s E S ES E S ENEX =''=-=- 所以 22211()Var()()N E S EN X EN EX =+ 因此 22Var()()()N N N S E S ES =-2222111Var()()-()()EN X EN EX EN EX =+211Var()()Var()EN X EX N =+.1.4. What are the range and index set for the following stochastic processes ： (a) Let i X be the quantity of beer ordered by the th i customer at Happy Harry's and let ()N t be the number of customers to arrive by time t . The process is(){}()10,N t i i X t X t ==≥∑ where ()X t is the quantity ordered by time t .(b) Thirty-six points are chosen randomly in Alaska according to some probability distribution. A circle of random radius is drawn about each point yielding a random set S . Let ()X A be the value of the oil in the ground under region A S ⋂. The process is () {,}X B B Alaska ⊂.(c) Sleeping Beauty sleeps in one of three positions: (1) On her back looking radiant. (2) Curled up in the fetal position.(3) In the fetal position, sucking her thumb and looking radiant only to an orthodontist.Let ()X t be Sleeping Beauty's position at time t. The process is (){} ,0X t t ≥. (d) For 0,1,n =, let n X be the value in dollars of property damage to West PalmBeach, Florida and Charleston, South Carolina by the th n hurricane to hit the coast of the United States.解：(a) The range is {0,1,2,,}S =∞，the index is {|0}T t t =≥；(b) The range is [0,)S =∞，the index is {1,2,,36}T =；(c) The range is {1,2,3}S =，the index is {|0}T t t =≥； (d) The range is [0,)S =∞，the index is {0,1,2,}T =.1.5. If X is a non-negative integer valued random variable with~{},()X k X p P s Es =express the generating functions if possible, in terms of () P s , of (a) []P X n ≤, (b)[]P X n <, (c) []P X n ≥. 解：0()[]k k P s P X k s ∞===∑1000()[]k kki k k i P s P X k s p s ∞∞===⎛⎫=≤= ⎪⎝⎭∑∑∑001i k i i i k i i s s p p s ∞∞∞===⎛⎫== ⎪-⎝⎭∑∑∑ 011()11i i i s p P s s s ∞===--∑; 12000()[]k kki k k i P s P X k s p s ∞∞-===⎛⎫=<= ⎪⎝⎭∑∑∑10101i k i i i k i i s s p p s +∞∞∞==+=⎛⎫== ⎪-⎝⎭∑∑∑0()11i i i s ss p P s s s∞===--∑; 300()[]kki k k i k P s P X k s p s ∞∞∞===⎛⎫=≥= ⎪⎝⎭∑∑∑100011i i k i i i k i s s p p s +∞∞===-⎛⎫== ⎪-⎝⎭∑∑∑ 0011()111ii ii i s sP s p p s s s s ∞∞==-=-=---∑∑. 1.8 In a branching process 2()P s as bs c =++, where 0,0,0,(1)1a b c P >>>=. Compuct π. Give a condition for sure extinction. 解：由(1)1P a b c =++=，可得 1()b a c -=-+，2()s P s as bs c ==++ 2(1)0as b s c +-+=2(+)0as a c s c -+=,1cs s a== (1)21m P a b '==+≤.1.10. Harry lets his health habits slip during a depressed period and discovers spots growing between his toes according to a branching process with generating function23456()0.150 .050.030.070.40.250.05P s s s s s s s =++++++Will the spots survive? With what probability?解:由 2345()0 .050.060.21 1.6 1.250.3P s s s s s s '=+++++， 可得 (1)0 .050.060.21 1.6 1.250.3 3.471m P '==+++++=>， 又由 23456()0.150 .050.030.070.40.250.05s P s s s s s s s ==++++++， 依据1π<，可得=0.16π.1.23. For a branching process with offspring distribution,0,1,01,n n p pq n p q p =≥+=<<解: ()1pP s qs=- ()1ps P s qs==- 210qs s q -+-=1s = 或 p s q=1(1)1k k qm P p kq p∞='===≤∑， 112p p p -≤⇒≥.Chapter 2 Markov Chains2.1. Consider a Markov chain on states {0, 1, 2} with transition matrix0.30.30.4=0.20.70.10.20.30.5P ⎛⎫⎪⎪ ⎪⎝⎭.Compute 20[2|0]P X X == and 210[2,2|0]P X X X ===.解：由题意得 20.230.420.350.220.580.20.220.420.36P ⎛⎫⎪= ⎪ ⎪⎝⎭,(2)202[2|0]0.35P X X p ====, 120[2,2|0]P X X X === 2110[2|2][2|0]P X X P X X =====(1)(1)22020.50.40.2p p =⋅=⨯=2.8. Consider a Markov chain on {1, 2, 3} with transition matrix1001112631313515P ⎛⎫ ⎪ ⎪⎪= ⎪ ⎪ ⎪⎝⎭. Find ()3n i f for 1,2,3,n =.解：当1i =时，对任意1n ≥，()1313[(1)]0n f P n τ===；当2i =时，对于1n ≥，()112323222311[(1)]()63n n n f P n p p τ--====⋅； 当3i =时，对于1n =，(1)3333331[(1)1]15f P p τ====， 对于2n ≥，()222333332222331111[(1)]()()56356n n n n f P n p p p τ---===⋅⋅=⋅⋅=⋅. Exercise. Consider a Markov chain on states {1,2,3,4,5} with transition matrix1000001000120012000120120120120P ⎛⎫ ⎪ ⎪ ⎪= ⎪ ⎪ ⎪⎝⎭,(1) What are the equivalence classes ?(2) Which states are transient and which states are recurrent ?(3) What are the periods of each state? (详细过程自己完成！)解：(1) 分为三类：{1},{2}和{3,4,5}.(2) 1,2为正常返状态，3,4,5为瞬过状态.(3) 状态1,2的周期为1，状态3,4,5的周期为2.。
北京市英语小学六年级上学期试题及解答参考(2024-2025学年)
2024-2025学年北京市英语小学六年级上学期模拟试题及解答参考一、听力部分（本大题有12小题，每小题2分，共24分）1、Listen to the conversation between two students in the playground and choose the best answer to the question.A. What is the weather like today?B. What is the time now?C. What are they discussing about their school project?Answer: CExplanation: The students are discussing their school project, which is indicated by their conversation about the topic.2、Listen to the dialogue between a teacher and a student in the classroom and answer the question.What subject is the teacher asking the student about?A. MathematicsB. EnglishC. ScienceAnswer: BExplanation: The teacher asks the student if they have finished their Englishhomework, indicating that the subject being discussed is English.3、Listen to the following conversation and answer the question.A: Hi, Tom, how was your weekend?B: Oh, it was great! I went to the park with my family. We played basketball, flew kites, and had a picnic.Question: What activity did Tom’s family do at the park?A)They flew kites.B)They played basketball.C)They had a picnic.Answer: C) They had a picnic.Explanation: In the conversation, Tom mentions that they had a picnic at the park. Therefore, option C is the correct answer.4、Listen to the following dialogue and answer the question.M: Excuse me, can you help me with my math homework?F: Sure, what’s the problem?M: Well, I have to solve this equation: 3x + 4 = 19.F: Alright, let’s solve it together. First, subtract 4 from both sides of the equation.M: Okay, 3x + 4 - 4 = 19 - 4.F: Now, simplify the equation. What do you get?M: 3x = 15.F: Correct. Now, divide both sides by 3 to find the value of x.M: So, x = 15 ÷ 3.F: Exactly. What’s the answer?Question: What is the value of x in the equation 3x + 4 = 19?A)4B)5C)6Answer: B) 5Explanation: The conversation explains the process of solving the equation step by step. After simplifying the equation, they find that x = 5. Therefore, option B is the correct answer.5、Listen to the dialogue and choose the correct answer.A. How old is Tom?B. What’s Tom’s favorite color?C. How tall is Tom?D. What’s Tom’s favorite food?Answer: BExplanation: The question asks about Tom’s favorite color. The dialogue goes like this:•“Hi, Tom! What’s your favorite color?”•“Oh, it’s blue.”6、Listen to the conversation and fill in the blanks.Alice: Hey, Bob, what did you do last weekend?Bob: I went to the_______park. We had a great time playing basketball and _______. Alice: That sounds fun! Did you meet anyone interesting?Bob: Yes, I met a new friend named _______. We talked about music and _______.Answer: 1. local 2. swimming 3. Mary 4. moviesExplanation: The conversation is about Bob’s weekend activities. The blanks should be filled with the appropriate words based on the context of the dialogue.7、Listen to the dialogue and choose the best answer to the question you hear.A. What is the boy’s favorite sport?B. How often does the boy play football?C. Who invited the boy to play football?Answer: BExplanation: The boy says, “I play football about once a week,” which indicates how often he plays football.8、Listen to the conversation and fill in the blanks with the missing words.W: Hi, John. How was your school trip last week?M: It was amazing, but we had to walk a lot.W: Really? Why?M: Because the school bus was broken down. We had to walk to the next town and catch another bus.W: That sounds exhausting. How long did it take?M: It took us about (______).W: Wow, that’s quite a walk.Answer: 2 hoursExplanation: The boy mentions that it took them about two hours to walk to the next town, which is the missing word to complete the sentence.9.Listen to the conversation and choose the best answer to complete the sentence.W: Hi, John. How was your science project fair yesterday?M: It was amazing! I showed my classmates my model of the solar system.W: Tha t’s impressive. What did you find the most interesting about it?M: I was fascinated by the fact that Mercury is the closest planet to the sun.Question: What did John find the most interesting about his science project?A) The model was big.B) Mercury’s position near the sun.C) The number of planets in the solar system.D) The color of the model.Answer: B) Mercury’s position near the sun.Explanation: The key phrase in the conversation is “I was fascinated by the fact that Mercury is the closest planet to the sun,” which directly answers the question.10.Listen to the dialogue and fill in the blanks with the correct words.M: Hey, Lisa, did you watch the new movie that just came out?W: Yes, I did. It was quite a thrilling adventure story.M: I heard it had a lot of action scenes. Did you like them?W: Oh, definitely! The climax of the movie was when the hero fought the villain at the top of the tallest building in the city.M: That must have been intense. The movie also had somereally___________music, d idn’t it?W: Yes, it did. The music really___________the tension in the scene.Question: Fill in the blanks with the correct words.M: The movie also had some really___________music, didn’t it?W: Yes, it did. The music really___________the tension in the scene.A)dramatic, addedB)funny, decreasedC)sad, removedD)loud, increasedAnswer: A) dramatic, addedExplanation: The context of the conversation suggests that the music added to the tension of the scene, which is best described by “dramatic” and “added.”11.Listen to the following dialogue and answer the question.A: What’s the weather like today, Tom?B: It’s a sunny day, but it’s a bit windy.Question: Is it a sunny day or a cloudy day?Answer: A sunny day.Explanation: The speaker Tom said, “It’s a sunny day, but it’s a bit windy.”This means that the weather is sunny.12.Listen to the following passage and complete the sentence with the missing word.The cat is very clever. It can open the door with its paws. It can also climb the tree easily. One day, the cat found a mouse in the garden. It caught the mouse and brought it back to the house. Then, it played with the mouse for a while. Finally, it ate the mouse.Question: How did the cat catch the mouse?Answer: The cat caught the mouse.Explanation: The passage mentions that “the cat found a mouse in the garden. It caught the mouse and brought it back to the house.” This indicates that the cat caught the mouse.二、选择题（本大题有12小题，每小题2分，共24分）1、What is the capital city of France?A. LondonB. ParisC. RomeD. Berlin答案：B解析：The capital city of France is Paris. London is the capital of the United Kingdom, Rome is the capital of Italy, and Berlin is the capital of Germany.2、Which of the following is not a planet in our solar system?A. MercuryB. VenusC. EarthD. Pluto答案：D解析：Pluto is no longer considered a planet in the solar system. It is now classified as a dwarf planet. Mercury, Venus, and Earth are all full planets.3、What is the correct plural form of the word “child”?A. childsB. childsC. childrenD. childenAnswer: C. childrenExplanation: The word “child” is irregular in its plural form. It changes to “children” when used in the plural. The other options are incorrect spellings.4、Choose the word that best completes the sentence.She___________her homework before she went to bed.A. finishedB. finishesC. finishingD. finishAnswer: A. finishedExplanation: The sentence is in the past tense, indicating that the action of doing homework has already been completed. Therefore, the correct choice is the past tense form “finished.” The other options do not match the tense of the sentence.5、Which sentence uses the correct form of the verb in the past tense?A)She eated an apple yesterday.B)He drinked a lot of water after running.C)They went to the park last Sunday.D)We seen a movie last night.Answer: C) They went to the park last Sunday.Explanation: The correct past tense form of the verb “to go” is “went.” Option A should be “She ate an apple yesterday,” option B should be “He drank a lot of water after running,” and option D should be “We saw a movie last night.”6、Choose the sentence that correctly uses the comparative form of the adjective:A)This book is more interesting than the one we read it last week.B)That test was easier than this one.C)She is the smartest in her class, but he is faster.D)My sister sings more beautiful than I do.Answer: B) That test was easier than this one.Explanation: The correct comparative form is used in option B. In option A, “it” is unnecessary; it should be “T his book is more interesting than the one we read last week.” Option C compares two different qualities (smart and fast), which isn’t what the comparative form is used for here. Option D should be “My sister sings more beautifully than I do.”7、What is the capital city of France?A. LondonB. ParisC. RomeD. BerlinAnswer: BExplanation: Paris is the capital city of France. London is the capital of the United Kingdom, Rome is the capital of Italy, and Berlin is the capital of Germany.8、Which of the following is the smallest planet in our solar system?A. JupiterB. VenusC. EarthD. MercuryAnswer: DExplanation: Mercury is the smallest planet in our solar system. Jupiter is the largest planet, Venus is the second hottest planet, and Earth is the third planetfrom the Sun.9、Which of the following words is an adjective?A. QuicklyB. BeautifulC. RunningD. JumpedAnswer: B. BeautifulExplanation: An adjective is a word that describes or modifies a noun or pronoun, giving more informati on about it. “Beautiful” is an adjective as it can describe something or someone (e.g., a beautiful flower, a beautiful person). “Quickly” is an adverb, often describing how an action is performed. “Running” and “Jumped” are forms of verbs; “Running” can a lso act as a verb in the present continuous tense or as a gerund (a verb form functioning as a noun), while “Jumped” is the past tense of the verb “to jump.”10、Choose the correct preposition to complete the sentence: “I will meet you___the end of the stre et.”A. atB. inC. onD. byAnswer: A. atExplanation:The preposition “at” is used here because it is typicallypaired with points or specific locations, such as “the end of the street.” We use “in” for enclosed spaces or areas, “on” for surfaces, and “by” to indicate being close to or next to something. In this context, “at the end of the street” means exactly at the point where the street ends.11.Choose the correct word to complete the sentence:The cat is sitting on the_and looking out the window.A. bedB. chairC. tableD. floorAnswer: B. chairExplanation: The correct answer is “chair” because a cat is more likely to sit on a chair than on a bed, table, or floor. The sentence is describinga specific location where the cat is sitting, which is on a chair.12.Select the word that best completes the sentence:The sun rises in the_and sets in the west.A. northB. southC. eastD. westAnswer: C. eastExplanation: The correct answer is “east” because the sun rises in theeast and sets in the west. This is a well-known fact about the Earth’s rotation and is a common piece of information taught in geography. The other options, north, south, and west, are incorrect because they do not follow the pattern of the sun’s movement.三、完型填空（10分）Read the following passage carefully and choose the best answer to fill in each blank. Write your answers on the line provided.It was a bright, sunny day. Sarah and her brother Tim decided to go to the (1) ______. They packed some sandwiches, fruits, and drinks into a picnic basket. When they arrived, the park was already (2)______with children playing and families enjoying the good weather. They found a nice spot under a big tree and set up their picnic there. As they were eating, a friendly dog came over and sat next to them. It looked (3)______and thirsty. Sarah gave it some water and a piece of bread. The dog wagged its tail happily. After lunch, they played frisbee and (4)______games. It was so much fun that th ey didn’t even notice when it started to get (5) ______. They had such a wonderful time that they promised to come back again soon.1.__________2.__________3.__________4.__________5.__________Answers:1.park2.full3.hungry4.otherteFeel free to adjust the difficulty or the context as per the specific requirements of the class.四、阅读理解（26分）Four, Reading ComprehensionRead the following passage and answer the questions that follow.Passage:In the small town of Greenfield, there was a little girl named Emily. Emily was known for her love of animals. She spent every spare moment she had with her beloved pets. Her favorite animal was her dog, Max. Max was a golden retriever with a heart of gold. He was always there for Emily, whether she needed a friend or someone to comfort her.One sunny afternoon, Emily noticed that Max was acting strangely. He was pacing back and forth, and his tail was tucked between his legs. Concerned, Emily checked on Max and found a cut on his paw. It seemed that Max had stepped ona sharp object while chasing a squirrel.Emily knew she had to help Max. She carefully cleaned the wound with antiseptic solution and wrapped it in a bandage. She also made a makeshift splint using a wooden spoon and some gauze. She was determined to take care of Max until he healed.As the days went by, Emily visited Max several times a day. She checked his paw, changed the bandage, and made sure he was comfortable. Max seemed to appreciate her efforts, as he wagged his tail and licked her hand.One evening, as Emily was sitting on the porch with Max, a storm began to brew. The sky turned dark, and the wind howled. Emily knew she had to take Max inside before the storm hit. She gently picked him up and carried him to the house. As they entered the shelter, Emily felt a sense of relief.The next morning, the storm had passed, and the sun was shining brightly again. Emily checked on Max and found that his paw had healed significantly. She was overjoyed to see him back to his playful self.Questions:1.What was Emily’s favorite animal?A. A catB. A golden retrieverC. A hamsterD. A parrot2.What did Emily do when she noticed that Max was acting strangely?A. She ignored him and continued her activities.B. She cleaned the wound and wrapped it in a bandage.C. She scolded Max for chasing the squirrel.D. She called the veterinarian to come over immediately.3.What did Emily make for Max to help his paw heal?A. A homemade bedB. A makeshift splint using a wooden spoon and gauzeC. A special treatD. A toy to keep him occupiedAnswers:1.B. A golden retriever2.B. She cleaned the wound and wrapped it in a bandage.3.B. A makeshift splint using a wooden spoon and gauze五、写作题（16分）Writing Prompt (Question 5):Imagine you’re planning a perfect da y during summer break. Describe what you would do from morning until night. Include details about who you would spend the day with, where you would go, what activities you would do, and why this day would be special to you. Write at least five sentences using correct grammar, punctuation, and spelling.Sample Response:My perfect summer day would start early in the morning with a delicious breakfast picnic at the beach with my best friends, Lily and Tom. We would eat fresh fruits and homemade sandwiches while watching the sun come up over the ocean. After breakfast, we’d play volleyball on the sand and splash around in the water until it’s time for lunch. In the afternoon, we would visit the nearby amusement park and ride all the roller coasters. As the sun sets, we would return to the beach for a bonfire, roast marshmallows, and share stories. This day would be special because I love spending time with my friends doing fun activities outdoors, creating memories that will last forever.Analysis:This response meets the requirements of the writing prompt by providing a clear narrative structure that covers the entire day from morning until night. The writer has included specific details about companions (Lily and Tom), locations (the beach and amusement park), activities (picnic, volleyball, amusement rides, bonfire), and personal significance (creating lasting memories). The use of descriptive language helps paint a vivid picture of the ideal day. The writer has also adhered to the instruction regarding sentence count and demonstrated proper use of grammar, punctuation, and spelling.。
Maple的常用内部数学函数要点
5、3D图象
Maple可以生成由显函数、参数型、微分 方程的解给出的3D曲线和曲面。图像的外观如：字体、光照、着色等也可随便更改。
下例将生成二元函数： 的图 象。
>plot3d(x*exp(-x^2-y^2),x=-2..2,y=-2..2,axes=BOXED,
>eval(eqn,x=1/2*a);
4、解方程组
求解如下5元的方程组：
>eqn1:=a+2*b+3*c+4*d+5*e=41;
>eqn2:=5*a+5*b+4*c+3*d+2*e=20;
>eqn3:=3*b+4*c-8*d+2*e=125;
>eqn4:=a+b+c+d+e=9;
我们可以用变量e来 表示其他未知数a，b，c，d得 到一组解。如果5个未知数一起求，Maple将任选其一作为自由变量 。
>expand(expr);
类似的你可以用factor命令对 上面结果进行因式分解来验证。
>factor(%);
化简表达式
Maple可以使用包括三角恒等式在内的恒 等关系对复杂的表达式进行化简。
考察 .
>simplify(cos(x)^5+sin(x)^4+2*cos(x)^2-2*sin(x)^2 -cos(2*x));
·Maple中乘号为星号“*”，两项相乘时乘号不能省略。
· 对变量赋值时用赋值运算符“：＝”，而不是通常的等号“；”。
长期口服华法林患者行骨科大手术围术期抗凝治疗策略
海峡药学2691年第33卷第(期化水平低的患者吸入用药的依从性得到显著改善，生活质量提高。
影响患者用药依从性的因素多种多样,可能主要包括吸入设备、药物、患者的文化程度和心理及医护人员等因素教育等。
临床药师采用各种通讯工具对出院后的患者进行随访及接受相关用药咨询，有针对性地对不同个体进行教育指导，对其用药过程实施监护，可以达到更有针对性地有效提高DPI使用患者的用药依从性的目的，增强其防护意识,弥补不足，从而保障DPI治疗的效果，更好地控制患者病情,降低复发率。
综上所述，本研究通过比较临床药师监护前后患者的吸入步骤评分表和吸入剂用药依从性调查问卷表发现,临床药师对患者实施全程药学监护的社会效益和经济效益显著，应在临床大力推广。
参考文献〔4史东明，徐浩锋,杨华俊,等.干粉吸入剂药学干预流程的建立及疗效评价分析中国医院统计,254,(02)：437W46.〔2〕杨婷婷，沈晓莉，金菊，等.三步宣教法对患者干粉吸入剂使用正确率的影响〔〕.医药高职教育与现代护理,264,1(64):219-2244〕罗云.临床药师干预对慢阻肺患者吸入剂使用技术和自我管理的影响研究〔J〕.当代医学,224,24(2)：42-125.〔〕冯于洛，王雅葳,褚燕琦,等.临床药师床旁教育实践及患者依从性评价〔〕.药学实践杂志,264,36(06)：554956,566.4〕S.MaPmouUi,K.ElseUf,5.Cheua,e)al.Fluibisatioa ChascWSs/cs cf Lactose Powdeu is Simply Turbulent Channei Flows〔J〕.Experimeutal Thesnal anS Fluib Science,262,Accepted：201-42.〔〕马凌悦，阙呈立，田硕涵，等•临床药师干预对慢性阻塞性肺疾病患者吸入剂使用技术和自我管理的影响〔J〕.中国临床药理学杂志9512,32(2)：469W571.〔7〕严莉琳•强化教育对支气管哮喘患者使用干粉吸入剂的效果研究4〕中国卫生标准管理9620(2)：46W58.长期口服华法林患者行骨科大手术围术期抗凝治疗策略商晶晶、*，龚金红、，徐航2(1.南京医科大学附属常州市第二人民医院药剂科，江苏常州24023；.南京大学医学院附属鼓楼医院药学部，江苏南京910065)摘要：目的探讨临床药师在长期口服华法林患者行骨科大手术围术期抗凝治疗实践中的药学服务内容及作用。
新视野大学英语第三版读写教程B3U4SectionA课后练习答案PPT学习教案
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2. I am most interested in visiting the Terracotta Army in Xi'an. First, I believe it is the most famous tourist attraction that will jump into anyone's mind when one is visiting Xi'an. It is regarded as an admirable miracle of the world.
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3. What kind of travel is truly compulsory? Only corporate travel, about 30% of trips over 50 miles, is truly
compulsory 4. How do you understand the phrase "Paris is Paris" in Paragraph 4? We go to Paris for the sake of its being Paris. We just want to
python 解复杂方程组复数域solve 函数
文章标题：探讨Python中解复杂方程组复数域的solve函数一、引言复杂方程组在数学和科学领域中有着广泛的应用，而Python作为一种强大的编程语言，提供了solve函数来解决复杂方程组，在复数域中尤为重要。
本文将从简单到复杂，由浅入深地探讨Python中解复杂方程组复数域的solve函数。
二、复数域的概念和应用复数是由实部和虚部组成的，通常表示为a+bi的形式，其中a和b分别为实数部分和虚数部分。
在实际问题中，很多方程组涉及到复数，比如电路分析、量子力学等。
解决复数域中的方程组对于实际问题具有重要意义。
三、Python中的solve函数Python中的solve函数是用来求解代数方程组的，它可以处理实数域和复数域中的方程组。
当方程组涉及到复数时，使用solve函数可以方便地得到方程组的解，从而进行进一步的分析和计算。
四、使用solve函数解复数域方程组的示例为了更好地理解solve函数在复数域中的应用，我们通过一个简单的示例来展示其用法。
考虑方程组：1. z + 2i = 02. 2z - 3i = 5其中z为复数，i为虚数单位。
我们可以使用solve函数来求解这个方程组，在Python中的代码如下：```pythonfrom sympy import Symbol, Eq, solvez = Symbol('z')equation1 = Eq(z + 2j, 0)equation2 = Eq(2*z - 3j, 5)solution = solve((equation1, equation2), z)print(solution)```在这段代码中，我们首先引入了Symbol、Eq和solve函数，然后定义了方程组的两个方程，最后使用solve函数求解得到了方程组的解。
在这个示例中，solve函数成功地求解了复数域中的方程组，并输出了解z的值。
五、深入理解solve函数的实现原理solve函数的实现原理涉及到复数域中方程组的求解算法，这超出了普通用户的使用范围。
《大学英语精读1》(上海外语教育出版社)
+at other times
\ 在别的时候；平时
\
+round/around the corner
\ 在附近；即将来临
\
+after all
\ 毕竟，终究
\
+be sure of
\ 对……有把握，确信
\
+pick up
\ 拿起，捡起
\
+worthwhile
\ n.娱乐
\
+entertain
&7entE5tein
\ vt.娱乐，招待
\
+solve
&sClv
\ vt.解决(问题)
\
+aware
&E5wZE
\ a.知道的；意识到的
\
+furthermore
&f\:TE5mC:(r)
\ ad.而且；此外
\
+average
&5AvEridV
\ a.普通的；中等的
\
+intelligence
&in5telidVEns
\ n.智力
\
+necessarily
&5nesisErili; nesi5serili
\ ad.必定
\
+case
&keis
\ n.实情
\
+additional
\ vt. & n.损坏 n.损坏
\
+gale
中英句子翻译-定语从句的翻译
中英句子翻译-定语从句的翻译中英句子翻译-定语从句的翻译定语从句的翻译1.将下列含有限制性定语从句的复合句译成汉语：1).Everythingthatisaroundusismatter.我们周围的一切都是物质人。
rgy.力存在的空间。
8).Thehousewhoseroofwasdamagedhasnowbeenrepaired.屋顶坏了的房子现在已经修好。
9).Shanghaiistheplacewherehewasborn.上海是他出生的地方。
10).Thepeoplewhoworkedforhimlivedinmortalfearofhim.在他手下工作的人对他怕的要死。
11).Theforcethatcauseseverythingtofalltowardthegroundiscalledgr avity.使所有物体落向地面的力称为重力。
12).Substanceswhichallowelectricitytoflowthroughfreelyarecalled他们17).Heunselfishlycontributedhisuncommontalentsandindefatigables pirittothestrugglewhichtodaybringsthoseaimswithinthereachofamaj orityofthehumanrace.他把自己非凡的才智和不倦的精力无私地献给了这种斗争，这种斗争今天以使人类中大多数人可以达到这些目标。
18).Hesaidtherewasneveranythinghappeninginhisfamilyhewasashamed of.他说他们家可从来没有出现过见不得人的事儿。
19).Thereisamandownstairswhowantstoseeyou.楼下有人要见你。
20).Therearesomecountriesintheworldwherethereislittlerainatanyt ime.世界上有些国家终年少雨。
solve_ivp解的定义范围 -回复
solve_ivp解的定义范围-回复solve_ivp函数是Python中用于求解初值问题的函数，通过数值方法来近似求解常微分方程的解。
在本文中，我们将探讨solve_ivp函数的定义范围，并详细介绍其用法和参数设置。
solve_ivp函数的完整定义如下：solve_ivp(fun, t_span, y0, method='RK45', t_eval=None, dense_output=False, events=None, vectorized=False, args=None, options)其中，参数的含义如下：- `fun`：一个函数，用于计算关于时间和状态的微分方程的导数。
函数的第一个参数是时间t和状态y，返回值是一个包含微分方程导数的一维数组。
- `t_span`：一个包含起始和结束时间的tuple，用于定义时间的范围。
- `y0`：一个包含初始状态值的数组。
- `method`：求解微分方程的数值方法，默认为`'RK45'`，也可以选择其他方法，如'Euler'、'RK23'等。
- `t_eval`：包含所需评估解的时间点的一维数组。
- `dense_output`：如果为True，则返回密集解。
如果为False，则只返回其中一些时间点的解。
- `events`：触发事件的函数，用于检测特定条件是否满足，从而停止或改变积分过程。
- `vectorized`：如果为True，则函数fun可以接受多维数组作为输入。
如果为False，则fun只能接受一维数组作为输入。
- `args`：fun函数中除t和y之外的其他参数。
- `options`：其他可选参数。
solve_ivp函数返回一个包含解的对象，可以使用该对象的属性和方法来访问求解的结果。
下面我们将详细介绍solve_ivp函数的各个参数和用法。
首先是`fun`参数，它是一个函数，用于计算微分方程的导数。
FLOTHERM.6.1版本中文教程6
添加散热器和风扇本练习指导用户完成以下步骤进一步细化置顶盒的模型：1.创建一个风扇。
2.使用库操作。
3.创建一个散热器。
4.在FLOMOTION中显示粒子流。
5.诊断有关收敛的问题。
.练习题6：添加散热器和风扇Load (读取)项目“Tutorial 5”，并将其另保存为新项目，取名"Tutorial 6"。
设置其’Title’(标题)为"Addition of heat sink andfan to set top box"。
在项目管理窗口(PM)中点击图标，激活调色板(Palette)。
选中根组件‘Root Assembly’ 并点击调色板中的‘Assembly’(组件)图标，将新创建的组件更名为"Ventilation"(通风)。
练习题6：添加散热器和风扇点击项目管理窗口(PM)中的图标打开‘LibraryManager’(库管理窗口)。
在‘Libraries’(库)下找到‘Sanyo DenkiAxial Fan’(Sanyo Denki 轴流风扇)，选择编号为‘109P0612H702’的风扇。
按住鼠标左键，将这一风扇拖拽到”Ventilation”组件中。
通过在项目管理窗口(PM)或绘图板(DB)中用鼠标右键点击风扇可进入’Location’(安置)对话框。
将风扇置于PSU旁，风从机箱中吹出。
风扇的位置设为(7.5,75, 270) mm。
注意：单位要正确。
练习题6：添加散热器和风扇在画图板中，确定风扇方向箭头显示在图中。
如果没有显示，选择“Modify Picture”图标进行修改。
选中“Flow/Source Direction”单选按钮.返回Drawing board 并观察风扇，你将可以看到带方向箭头的风扇。
练习题6：添加散热器和风扇在绘图板(DB)中，查看+Z视图。
如果现在绘图板显示的是四视图，请将其转换为单视图，即全屏显示+Z 方向视图。
MATLAB实例：散点密度图
MATLAB实例：散点密度图MATLAB实例：散点密度图MATLAB绘制⽤颜⾊表⽰数据密度的散点图数据来源：，将数据保存为gauss.txt1. demo.m% ⽤颜⾊表⽰数据密度的散点图data_load=dlmread('E:\scanplot\gauss.txt');X=data_load(:,1:2);scatplot(X(:,1),X(:,2),'circles', sqrt((range(X(:, 1))/30)^2 + (range(X(:,2))/30)^2), 100, 5, 1, 8);% colormap jetprint(gcf,'-dpng','散点密度图.png');2. scatplot.mfunction out = scatplot(x,y,method,radius,N,n,po,ms)% Scatter plot with color indicating data density% https:///matlabcentral/fileexchange/8577-scatplot% USAGE:% out = scatplot(x,y,method,radius,N,n,po,ms)% out = scatplot(x,y,dd)%% DESCRIPTION:% Draws a scatter plot with a colorscale% representing the data density computed% using three methods%% INPUT VARIABLES:% x,y - are the data points% method - is the method used to calculate data densities:% 'circles' - uses circles with a determined area% centered at each data point% 'squares' - uses squares with a determined area% centered at each data point% 'voronoi' - uses voronoi cells to determin data densities% default method is 'voronoi'% radius - is the radius used for the circles or squares% used to calculate the data densities if% (Note: only used in methods 'circles' and 'squares'% default radius is sqrt((range(x)/30)^2 + (range(y)/30)^2)% N - is the size of the square mesh (N x N) used to% filter and calculate contours% default is 100% n - is the number of coeficients used in the 2-D% running mean filter% default is 5% (Note: if n is length(2), n(2) is tjhe number of% of times the filter is applied)% po - plot options:% 0 - No plot% 1 - plots only colored data points (filtered)% 2 - plots colored data points and contours (filtered)% 3 - plots only colored data points (unfiltered)% 4 - plots colored data points and contours (unfiltered)% default is 1% ms - uses this marker size for filled circles% default is 4%% OUTPUT VARIABLE:% out - structure array that contains the following fields:% dd - unfiltered data densities at (x,y)% ddf - filtered data densities at (x,y)% radius - area used in 'circles' and 'squares'% methods to calculate densities% xi - x coordenates for zi matrix% yi - y coordenates for zi matrix% zi - unfiltered data densities at (xi,yi)% zif - filtered data densities at (xi,yi)% [c,h] = contour matrix C as described in% CONTOURC and a handle H to a contourgroup object% hs = scatter points handles%%Copy-Left, Alejandro Sanchez-Barba, 2005endif nargin<3 | isempty(method)method = 'vo';endif isnumeric(method)gsp(x,y,method,2)returnelsemethod = method(1:2);endif nargin<4 | isempty(n)n = 5; %number of filter coefficientsendif nargin<5 | isempty(radius)radius = sqrt((range(x)/30)^2 + (range(y)/30)^2); endif nargin<6 | isempty(po)po = 1; %plot optionendif nargin<7 | isempty(ms)ms = 7; %markersizeendif nargin<8 | isempty(N)N = 100; %length of gridend%Correct data if necessaryx = x(:);y = y(:);%Asuming x and y matchidat = isfinite(x);x = x(idat);y = y(idat);holdstate = ishold;if holdstate==0claendhold on%--------- Caclulate data density ---------dd = datadensity(x,y,method,radius);%------------- Gridding -------------------xi = repmat(linspace(min(x),max(x),N),N,1);yi = repmat(linspace(min(y),max(y),N)',1,N);zi = griddata(x,y,dd,xi,yi);%----- Bidimensional running mean filter -----zi(isnan(zi)) = 0;coef = ones(n(1),1)/n(1);zif = conv2(coef,coef,zi,'same');if length(n)>1for k=1:n(2)zif = conv2(coef,coef,zif,'same');endend%-------- New Filtered data densities --------ddf = griddata(xi,yi,zif,x,y);%----------- Plotting --------------------switch pocase {1,2}if po==2[c,h] = contour(xi,yi,zif);out.c = c;out.h = h;end %ifhs = gsp(x,y,ddf,ms);out.hs = hs;colorbarcase {3,4}if po>3[c,h] = contour(xi,yi,zi);out.c = c;end %ifhs = gsp(x,y,dd,ms);out.hs = hs;colorbarend %switch%------Relocate variables and place NaN's ----------dd(idat) = dd;dd(~idat) = NaN;ddf(idat) = ddf;ddf(~idat) = NaN;%--------- Collect variables ----------------out.dd = dd;out.yi = yi;out.zi = zi;out.zif = zif;if ~holdstatehold offendreturn%~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~function scatplotdemopo = 2;method = 'squares';radius = [];N = [];n = [];ms = 5;x = randn(1000,1);y = randn(1000,1);out = scatplot(x,y,method,radius,N,n,po,ms)return%~~~~~~~~~~ Data Density ~~~~~~~~~~~~~~function dd = datadensity(x,y,method,r)%Computes the data density (points/area) of scattered points%Striped Down version%% USAGE:% dd = datadensity(x,y,method,radius)%% INPUT:% (x,y) - coordinates of points% method - either 'squares','circles', or 'voronoi'% default = 'voronoi'% radius - Equal to the circle radius or half the square widthLd = length(x);dd = zeros(Ld,1);switch method %Calculate Data Densitycase 'sq' %---- Using squares ----for k=1:Lddd(k) = sum( x>(x(k)-r) & x<(x(k)+r) & y>(y(k)-r) & y<(y(k)+r) ); end %forarea = (2*r)^2;dd = dd/area;case 'ci'for k=1:Lddd(k) = sum( sqrt((x-x(k)).^2 + (y-y(k)).^2) < r );endarea = pi*r^2;dd = dd/area;case 'vo' %----- Using voronoi cells ------[v,c] = voronoin([x,y]);for k=1:length(c)%If at least one of the indices is 1,%then it is an open region, its area%is infinity and the data density is 0if all(c{k}>1)a = polyarea(v(c{k},1),v(c{k},2));dd(k) = 1/a;end %ifend %forend %switchreturn%~~~~~~~~~~ Graf Scatter Plot ~~~~~~~~~~~function varargout = gsp(x,y,c,ms)%Graphs scattered poitsmap = colormap;ind = fix((c-min(c))/(max(c)-min(c))*(size(map,1)-1))+1;h = [];%much more efficient than matlab's scatter plotfor k=1:size(map,1)if any(ind==k)h(end+1) = line('Xdata',x(ind==k),'Ydata',y(ind==k), ...'LineStyle','none','Color',map(k,:), ...'Marker','.','MarkerSize',ms);endendif nargout==1varargout{1} = h;endreturn3. 结果。
solve的用法
solve的用法solve的用法1. 解决问题•“Solve”作为动词，指解决问题或者找到答案。
例如：–I need to solve this math problem before thedeadline. （在截止日期前，我需要解决这个数学问题。
）–The detective solved the mystery and caught the criminal. （侦探揭开了谜团并逮捕了罪犯。
）2. 消除疑虑•“Solve”可以用来表示消除疑虑或解除担忧。
例如：–Regular communication can solve misunderstandings between team members. （定期沟通可以消除团队成员之间的误解。
）–The doctor’s explanation solved my worries about the potential risks of the surgery. （医生的解释消除了我对手术潜在风险的担忧。
）3. 完成任务•在某些情况下，“Solve”也可以表示成功地完成一个任务。
例如：–The engineer solved the technical challenges and completed the project on time. （工程师解决了技术挑战并按时完成了项目。
）–Our team successfully solved the complex puzzle and won the competition. （我们的团队成功解决了这个复杂的谜题并赢得了比赛。
）4. 找到解决方法•“Solve”也可以用来表示找到解决问题的方法或途径。
例如：–We need to solve the issue of lack of funding for our project. （我们需要找到解决项目资金不足的方法。
）–The consultant helped us solve the problem of low customer satisfaction by implementing a newcustomer service strategy. （顾问通过实施新的客户服务策略帮助我们解决了客户满意度低的问题。
全英文数学试卷七年级
Section 1: Multiple Choice (40 points, 1 point each)1. What is the value of \(5^3 - 3^2\)?A) 16B) 28C) 49D) 702. Simplify: \(8 \times 2 + 6 \div 3\).A) 16B) 20C) 18D) 213. If \(x = 4\), what is the value of \(3x - 2\)?A) 10B) 12C) 14D) 164. Solve for \(y\) in the equation \(2y + 5 = 19\).A) 7B) 8C) 9D) 105. What is the sum of the first 10 even numbers?A) 100B) 110C) 120D) 1306. The perimeter of a rectangle is 24 cm. If the length is 6 cm, what is the width?A) 4 cmB) 5 cmC) 6 cmD) 7 cm7. Solve the following system of equations:\[\begin{cases}2x + 3y = 8 \\x - y = 1\end{cases}\]A) \(x = 3, y = 2\)B) \(x = 2, y = 3\)C) \(x = 1, y = 4\)D) \(x = 4, y = 1\)8. The product of two consecutive integers is 56. Find the integers.A) 7 and 8B) 8 and 9C) 9 and 10D) 10 and 119. What is the area of a square with a side length of 8 cm?A) 32 cm²B) 64 cm²C) 128 cm²D) 256 cm²10. Simplify: \(\frac{5}{8} + \frac{3}{4} - \frac{1}{2}\).A) \(\frac{3}{4}\)B) \(\frac{5}{8}\)C) \(\frac{1}{8}\)D) \(\frac{7}{8}\)Section 2: Short Answer (30 points, 3 points each)11. Factorize \(18x^2 - 27x\).12. Solve the inequality \(2(x - 3) > 6\).13. Write the following mixed number as an improper fraction:\(4\frac{3}{5}\).14. Find the mean of the following set of numbers: 10, 15, 20, 25, 30.15. Simplify the expression: \(\sqrt{64} - \sqrt{49}\).Section 3: Extended Response (30 points)16. A triangle has sides measuring 5 cm, 10 cm, and 13 cm. Determine if the triangle is a right triangle. Explain your reasoning.17. Solve the following quadratic equation: \(x^2 - 6x + 9 = 0\).18. A farmer has a rectangular field that measures 30 meters by 50 meters. If he wants to fence the entire perimeter of the field, how much fencing will he need? Show your work.19. Solve the following system of equations using the substitution method:\[\begin{cases}3x + 4y = 14 \\2x - y = 3\end{cases}\]20. A company produces two types of pens, type A and type B. Type A pens cost $2 each, and type B pens cost $3 each. The company sold a total of 50 pens, making a profit of $60. How many pens of each type were sold? Set up a system of equations and solve it.Good luck!。
POWER AMPLIFIER AND AMPLIFYING METHOD
专利名称：POWER AMPLIFIER AND AMPLIFYINGMETHOD发明人：KIJIMA TORU,来島 徹申请号：JP2005326435申请日：20051110公开号：JP2007134994A公开日：20070531专利内容由知识产权出版社提供专利附图：摘要：PROBLEM TO BE SOLVED: To provide a high-frequency power amplifier with high efficiency which has simple circuit configuration.SOLUTION: Input signals generated by dividing an input signal input from an input terminal 1 into two by a hybrid 3a are input to phase shifters 4a and 4b which makesphase shifts of opposite polarities with an input signal level detected by a level detector1. Output signals from the phase shifters 4a and 4b are amplified by amplifiers 6a and 6b,whose outputs are input to a hybrid 3b having a reflection terminal R. Then the amplifiers 6a and 6b operate so that the output voltages hold saturation voltages with a reflectionsignal from the reflection terminal R, thereby operating to maintain high efficiency.COPYRIGHT: (C)2007,JPO&INPIT申请人：TOSHIBA CORP,株式会社東芝地址：東京都港区芝浦一丁目１番１号国籍：JP代理人：堀口 浩更多信息请下载全文后查看。
正方四角锥静力分析
(25)设置分析选项，模态提取方法Mode extraction method选择Block Lanzcos，
模态提取数No. of mode to extract取6：Main Menu>Solution>Analysis
Type>Analysis Options。
由于杆件较多，建立分析模型时利用APDL提供的循环操作命令，通过循
环语句简化GUI界面操作，其它均使用GUI操作。
统一单位制，长度m，重量kg，力N，则应输入数值为：截面面积
AREA=4.56E-4，弹性模量EX=2.06E11，泊松比PRXY=0.3，密度DENS=7850
上弦节点竖向作用力FORCE/MOMENT=-8000，重力加速度ACELZ=9.8。
(14)存储模型：单击ANSYS Toolbar中的SAVE_DB。
第3步：ANSYS求解器：执行静力求解
(15)选择分析类型为静力分析Static：Main Menu>Solution>Analysis Type>New
Analysis。
(16)执行求解：Main Menu>Solution>Analysis Type>New
(5)定义单元实常数,横截面面积AREA=4.56E-4：Main Menu>Preprocessor>Real
Constants>Add/Edit/Delete。
(6)定义材料属性，弹性模量EX=2.06E11，泊松比PRXY=0.3，材料密度
Density=7850：Main Menu>Preprocessor>Material Props> Material Models。
ANSYS地震分析实例
ANSYS地震分析实例土木工程中除了常见的静力分析以外，动力分析，特别是结构在地震荷载作用下的受力分析，也是土木工程中经常碰到的题目。
结构的地震分析根据现行抗震规范要求，一般分为以下两类：基于结构自振特性的地震反应谱分析和基于特定地震波的地震时程分析。
本算例将以一个4质点的弹簧－质点体系来说明如何使用有限元软件进行地震分析。
更复杂结构的分析其基本过程也与之类似。
关键知识点：(a) 模态分析(b) 谱分析(c) 地震反应谱输进(d) 地震时程输进(e) 时程动力分析(1) 在ANSYS窗口顶部静态菜单，进进Parameters菜单，选择Scalar Parameters选项，在输进窗口中填进DAMPRATIO=0.02，即所有振型的阻尼比为2%(2) ANSYS主菜单Preprocessor->Element type->Add/Edit/Delete，添加Beam 188单元(3) 在Element Types窗口中，选择Beam 188单元，选择Options，进进Beam 188的选项窗口，将第7个和第8个选项，Stress/Strain (Sect Points) K7, Stress/Strain (Sect Nods) K8，从None 改为Max and Min Only。
即要求Beam 188单元输出积分点和节点上的最大、最小应力和应变(4) 在Element Types 窗口中，继续添加Mass 21集中质量单元(5) 下面输进材料参数，进进ANSYS主菜单Preprocessor->Material Props-> Material Models菜单，在Material Model Number 1中添加Structural-> Linear-> Elastic->Isotropic 属性，输进材料的弹性模量EX和泊松比PRXY分别为210E9和0.3。
solve是什么意思_solve的意思
solve是什么意思_solve的意思solve是我们在英语中常用的动词，那么你solve做动词都表达哪些意思吗?下面是小编为大家整理的关于solve是什么意思_solve的意思，希望对您有所帮助。
欢迎大家阅读参考学习!solve作动词的意思解决;解答;解释;清偿solve的英语音标英 [s?lv] 美 [sɑlv, s?lv]solve的时态现在分词： solving过去式： solved过去分词： solvedsolve的英语例句1. I dreamed up a plan to solve both problems at once.我想出了一个方案，可以同时解决两个问题。
2. Human societies have the power to solve the problems confronting them.人类社会有能力解决面临的问题。
3. Egypt wants to solve the problem in an atmosphere of cordiality.埃及想要友好地解决该问题。
4. Their domestic reforms did nothing to solve the problem of unemployment.他们的国内改革未能解决失业问题。
5. She leaned on him to help her to solve her problems.她靠他帮忙解决自身问题。
6. You know, it occurs to me you could solve all your problems by obtaining more money.依我看，你的所有问题都可以通过多挣点钱来解决。
7. It isn't going to solve a single thing.这什么问题也解决不了。
8. Attempts are being made to solve the problem of waste disposal.正在想办法解决废物处理的问题。