完整版广联达培训楼工程量计算1
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广联达培训楼工程量计算
1、 建筑面积:m 2
首层:11.6 X 6.5=75.4m 2
二层:11.6 X 6.5=75.4m 2
阳台:4.56X 1.2X 1 十 2=2.736 m 2
建筑总面积:75.4+75.4+2.736=153.536 吊
2、 平整场地面积:m 2
11.6X 6.5=75.4 m 2
3、 土方量:m 3
H=(-0.45)-(-1.6)=1.15m
垫层长:11.6+0.35X 2=12.3m
垫层宽:6.5+0.35X 2=7.2 m
V= (a+2c ) (b+2c)h
=(12.3+0.3X 2)X( 7.2+0.3X 2)X 1.15=115.7m 3
4、 C 10砼垫层:m 3
V=垫层长X 垫层宽 X 垫层厚 =(11.6+0.35X 2) X (6.5+0.35X 2) 0.1=8.856 m 3 垫层模板m 2
S= (11.6+0.35X 2+6.5+0.35X 2)X 2X 0.1=3.9 m 2
5、 C 25满堂基础(有梁式):m 3
W = (11.6+0.25X 2) (6.5+X 2) 0.3=25.41
V=1/2 X 0.15X 0.1X [11.6+(0.1+0.075) X 2+6.5+ (0.1+0.075) X 2] X 2=0.282 V=25.41-0.282=25.128 m 3
基础梁砼体积:m 3
①④2JL2 (1): (6-0.25X 2)X 0.5X 0.12X 2=1.1 m 3
②③2JL3 (2): [ (3.3-0.25-0.2) + (2.1-0.25-0.2) ] X 0.4X 0.2 X 2=0.816 m 3 AC2JL1 (3): [ (3.3-0.25-0.2)X 2 (4.5-0.2-0.2) ] X 0.5X 0.2X 2=1.96 m 3 BJL4 (4.5-0.2-0.2)X 0.4X 0.2=0.328 m 3
V 梁=1.1+0.816+1.936+0.328=4.204 *
V 总25.128+4.204=29.332 n?
基础模板:m 2
V= (11.6+0.25X 2+6.5+0.25X 2)X 2X 0.2=7.64 m 2 梁的模板:m 2
①④2JL2 (1): (6-0.25X 2)X 0.2X 2X 2=4.4m 2
②③ 2JL3 (2) : [ (3.3-0.25-0.2) + (2.1-0.25-0.2)]
AC2JL1 (3): [ (3.3-0.25-0.2)X 2 (4.5-0.2-0.2)] BJL4 (4.5-0.2-0.2)X 0.2X 2=1.64 m 2
梁的模板:S=4.4+4.08+7.84+1.64=17.96 &
C30 砼框架柱(-1.2 〜土 0.00 ): m 3
4Z 1=0.5X 0.5X 1.2X 4=1.2 m 3
4Z 2=0.5 X 0.4X 1.2X 4=0.96 m 3 2Z 3=0.4 X 0.4X 1.2 X 2=0.384 m 3
C30 砼框架柱的总体积=1.2+0.96+0.384=2.544 m?
C25 砼框架柱(土 0.00 〜7.17): m 3 X 0.2X 2X 2=4.08 m 2
2
4Z i=0.5X 0.5X 7.17X 4=7.17 m3
4Z2=0.5X 0.4X 7.17X 4=5.736 m3
2Z3=0.4X 0.4X 7.17X 2=2.2944 m3
C25 砼框架柱的总体积=7.17+5.736+2.2944=15.2004 n? 框架柱的模板(-1.2〜7.17): m2
4Z1=0.5X 4X( 1.2+7.17)X 4=66.96 m2
4Z2= (0.5+0.4)X 2X( 1.2+7.17)X 4=60.264 m2
2Z3=0.4X 4X( 1.2+7.17)X 2=26.784 m2 小计:66.96+60.264+26.784=154.008 首层梁与柱交叉部分模板的面积:m2 4Z1=0.37X 0.5X 2X 4=1.48 m2
4Z2= (0.37X 0.5X 2+0.24X 0.5)X 4=1.96 m2
2Z3=0.24X 0.5X 3 X 2=0.72 m2 小计:1.48+1.96+0.72=4.16 mf 二层梁与柱交叉部分模板的面积:m2
4Z1=0.37X 0.65X 2X 4=1.924 m2
4Z2= (0.37X 0.65X 2+0.24X 0.5)X 4=2.404 m2 2Z3=0.24X 0.5X 3 X 4=0.72 m2
小计:1.924+2.404+0.72=5.048 *
框架柱的模板=154.008-4.16-5.048=144.8 吊
C25砼女儿墙构造柱:m3
4Z-= (0.24X 0.24X 0.54+0.24X 0.03X 0.54X 2)X 4=0.156 m3 4Z L= (0.24 X 0.24X 0.54+0.24X 0.03X 0.54X 2)X 4=0.156 m3 V 总=0.156+0.156=0.312 m
模板的面积:m2
4Z-= (0.24+0.006X 2)X 0.54X2X4=1.555 m2
4Z L= (0.24+0.006)X 0.54X 2X 4+0.006X 0.54X 2X 4=1.555 m2 S 总
=1.555+1.555=3.11 m?
3.57mC25砼框架梁m3
①④2KL2 (1) : (6-0.25X 2)X 0.37X 0.4X 2=1.628 m3
②③2KL4 (2): (6-0.25X 2-0.4)X 0.24X 0.4X 2=0.979m3 A2KL3 (3) : (11.1-
0.25X 2-0.4X 2)X 0.37 X 0.4=1.4504 m3 C2KL1 (3): (11.1-0.25X 2-0.4X 2)X 0.37 X 0.4=1.4504 m3 BKL5 (1): (4.5-0.2X 2)X 0.24X 0.4=0.394 m3 小计:
1.628+0.979+1.4504+1.4504+0.394=5.901 m 模板:m2
①④2KL2 (1) : (0.5+0.4+0.37)X( 6-0.25X 2)X 2=13.97 m2
②③2KL4 (2) (0.4+0.4+0.24)X( 6-0.25X 2-0.4)X 2=10.608 m2 A2KL3 (3):
(0.5+0.4+0.37)X( 11.1-0.25X 2-0.4 X 2) =12.446 m2 C2KL1 (3):
(0.5+0.4+0.37)X( 11.1-0.25X2-0.4X2) =12.446 m2 BKL5 (1) (0.4+0.4+0.24)X( 4.5-0.2X 2) =4.264 m2 小计:13.97+10.608+12.446+12.446+4.264=53.734 rf l 7.17mC25砼框架梁:m3
①④2KL2 (1): (6-0.25X 2)x 0.37X 0.55X 2=2.2385 m3
②③2KL4 (2): (6-0.25X 2-0.4)X 0.24X 0.4X 2=0.979m3
A2KL3 (3): (11.1-0.25X 2-0.4X 2)X 0.37 X 0.55=1.9943 m3
C2KL1 (3): (11.1-0.25X 2-0.4X 2)X 0.37 X 0.55=1.9943 m3
BKL5 (1): (4.5-0.2X 2)X 0.24X 0.4=0.3936 m F
小计:2.2385+0.979+1.9943+1.9943+0.3936=7.599 m
模板:m2
①④2KL2 (1): (0.65+0.55+0.37)X( 6-0.25X 2)X 2=17.27 m2