人教版必修三第三章测试题(含答案)

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人教版新课标2019-2020(下)必修三 Unit 3 单元测试题 含答案

人教版新课标2019-2020(下)必修三 Unit 3 单元测试题 含答案

必修三unit 3 单元练习Dear Laura,I just heard you tell an old story of gift giving and un- selfish love in your program. You doubted that such unselfish love would happen in today’s world. Well, I’m here to give you1 .I wanted to do something very 2 for my fifteen – year - old son, who has always been the perfect child. He 3 all summer to earn enough money to buy a used motorcycle. Then, he spent hours and hours on it 4 it looked almost new. I was so 5 of him that I bought him the shiniest helmet and a riding outfit.I could 6 wait for him to open up his gift. In fact, I barely slept the night before. Upon a wakening, I went to the kitchen to 7 the coffee, tea, and morning goodies. In the living room was a beautiful keyboard with a 8 : “To my wonderful mother, all my love, your son.”I was so 9 . It had been a long - standing joke in our family that I wanted a piano so that I could 10 lessons. “Learn to play the piano,and I’ll get you one” was my hus- band’s 11.I stood there shocked, crying a river, asking myself how my son could 12 this expensive gift.Of course, the 13 awoke, and my son was thrilled(激动的)with my reaction. Many kisses were 14 ,and I immediately wanted him to 15 my gift.As he saw the helmet and outfit, the look on his face was not 16 what I was expecting. Then I 17 that he has sold the motorcycle to get me the keyboard.Of course I was the proudest mother 18 on that day, and my feet never hit the ground for a month.So I wanted you to know, that kind of love still 19 and lives even in the ever-changing world of me, me, me !I thought you’d love to 20 this story.Yours,HilaryP.S. The next day, my husband and I bought him a new “used” already shiny motorcycle.1. A. hope B. advice C. support D. courage2. A. polite B. similar C. special D. private3. A. played B. studied C. traveled D. worked4. A. after B. before C. unless D. until5. A. sure B. fond C. proud D. confident6. A. perhaps B. really C. almost D. hardly7. A. start B. cook C. set D. serve8. A. note B. notice C. word D. sign9. A. disturbed B. confused C. astonished D. inspired10. A. give B. take C. draw D. teach11. A. reason B. request C. comment D. response12. A. present B. afford C. find D. order13. A. neighbor B. building C. home D. house14. A. exchanged B. experienced C. expected D. exhibited15. A. tear B. open C. check D. receive16. A. purely B. basically C. obviously D. exactly17. A. realized B. remembered C. imagined D. supposed18. A. only B. still C. ever D. even19. A. works B. exists C. matters D. counts20. A. send B. publish C. share D. writeAMost men have somewhat tumultuous relationships with their fathers. We love them,admire them,hate them,rebel against them,and ideally end up with a great friend where a parent used to be. Making that transition can be challenging,though. Here are some tips to help you approach your father on a man-to-man level.First of all,you don't have to get too emotional.If you're uncomfortable with the idea of baring your emotions,chances are pretty good that your dad feels the same way. You simply need to take the right approach,one that allows you to talk with your father and learn about him,but without making everything feel like a TV drama.Hobbies are a good place to start. If your dad taught you any of the pastimes that you currently enjoy,dive right back into them and show him what you've learned. Your hobby will serve as a good start point to help you develop a healthy friendship. Don't immediately jump into time intensive activities such as camping or fishing trips. Try to set up a regular time to just hang out. Let's say you don't have any hobbies in common with your father. Many guys are in this position. This is where beer comes in. Just meet your dad at a bar to put one or two back,or if you don't drink,get a casual dinner somewhere.Don't act like a kid. Remember that if you want your dad to treat you like the adult you are,you've got to show him that you've grown up. Be willing to talk about things such as money,sex and other taboo subjects that you regularly discuss with your friends. Your dad can take it. He's been doing this whole “life” thing longer than you have. Just be frank and honest.To build a relationship with your father as an adult,you need to show him respect and invest some time. It's not the easiest thing in the world,but it's important. There are thousands of guys out there who'd love to be able to talk to their fathers; make them jealous. Take the first step. 21.What should you do,if both you and your farther are not good at baring emotions?A.Talk about your common hobbies. B.Make everything felt like a TV drama.C.Watch TV together with your father. D.Put up a TV drama for your father. 22.What does the author mea n by saying the underlined sentence?A.Many guys are sitting in the wrong position. B.Many guys don't share any common hobbies with their fathers.C.Many guys have the right thought D.Many guys have no hobby.23.What does this passage mainly talk about?A.The problems between father and son. B.How to approach your father freely as an adult man.C.How to act as an adult before your father. D.Tips for men about how to cheer their father up.24.For whom is this passage written?A.Fathers. B.Adult sons. C.Mothers. D.Physiologists.BI have been consistently opposed to feeding a baby regularly. As a doctor,mother and scientist in child development I believe there is nothing to recommend it,from the baby's point of view.Mothers,doctors and nurses alike have no idea of where a baby's blood sugar level lies. All we know is that a low level is harmful to brain development and makes a baby easily annoyed. In this state,the baby is difficult to calm down and sleep is impossible. The baby asks for attention by crying and searching for food with its mouth.It is not just unkind but also dangerous to say a four hourly feeding schedule will make a baby satisfied. The first of the experts to advocate a strict clock-watching schedule was Dr Frederic Truby King who was against feeding in the night. I've never heard anything so ridiculous. Baby feeding shouldn't follow a timetable set by the mum. What is important is feeding a baby in the best way,though it may cause some inconvenience in the first few weeks.Well,at last we have copper-bottomed research that supports demand feeding and points out the weaknesses of strictly timed feeding. The research finds out that babies who are fed on demand do better at school at age 5,7,11 and 14,than babies fed according to the clock. By the age of 8,their IQ (智商) scores are four to five percent higher than babies fed by a rigid timetable. This research comes from Oxford and Essex University using a sample (样本) of 10,419 children born in the early 1990s,taking account of parental education,family income,a child's sex and age,the mother's health and feeding style. These results don't surprise me. Feeding according to schedule runs the risk of harming the rapidly growing brain by taking no account of sinking blood sugar levels.I hope this research will put an end to advocating strictly timed baby feeding practices. 25.What does the author think about Dr King?A.He is strict. B.He is unkind. C.He has the wrong idea. D.He sets a timetable for mothers.26.The word copper-bottomed in Paragraph 4 is closest in meaning to ________.A.basic B.reliable C.surprising D.interesting27.What does the research tell us about feeding a baby on demand?A.The baby will sleep well. B.The baby will have its brain harmed.C.The baby will have a low blood sugar level. D.The baby will grow to be wiser by th e age of 8.28.The author supports feeding the baby ________.A.in the night B.every four hours C.whenever it wants food D.according to its blood sugar levelCDo you love the holidays,but hate the pounds that follow? You are not alone. Holidays are times for feasting and celebrating. Many people are worried about their weight. With proper planning,though,it is possible to keep normal weight during the holidays. Whether it is celebrating at the office party or sitting down for the traditional family dinner,regard eating as a time for tasting a variety of the foods. The idea is to enjoy the holidays but not to eat too much. You don't have to turn away from the foods that you enjoy.Here are some tips for preventing weight gain and maintaining physical fitness:Don't skip meals. Before you leave home,have a small,low-fat meal or snack. This may help to avoid getting too excited before delicious foods.Control portions. Use a small plate (about 10 inches) and put aside the large ones that may encourage you to “load up.” You should be most comfortable eating an amount of food about the size of your fist. Once you have your “tasting” serving,move away from the buffet. Doing so will make it less tempting to be eating constantly as your appetite is inspired by the sight of food.Begin with soup and fruit or vegetables. Fill up beforehand on water-based soup and raw fruit or vegetables. Or drink a large glass of water before you eat to help you feel full.Stick to physical activity. Don't let exercise take a break during the holidays. A 20-minute walk after a meal can help burn off excess calories.Avoid high-fat foods. Dishes that look oily or creamy may have a large amount of fat. Choose lean meats .Fill your plate with salad and green vegetables. Use lemon juice instead of dressing or butter.29.Which of the following is NOT true according to the passage?A.You had better turn your attention away from delicious foods.B.Drinking some water of soup before eating helps you eat less.C.Holidays are happy days with pleasure but they may bring weight problems.D.Physical exercise can reduce the chance of putting on weight.30.Which of the following CANNOT help lose weight according to the passage?A.Lean meats. B.Dressing or butter. C.Raw fruit or vegetables. D.Physical exercise. 31.Many people can't control their weight after the holidays mainly because they ________.A.can't help being tempted to ea t constantly B.take part in too many partiesC.enjoy delicious foods D.can't help turning away from the foods 32.If the passage appears in the newspaper,you think it should belong to ________ Column.A.Holidays and Festivals B.Health and Fitness C.Fashion and Frontier D.Student Times ClubDEarly in the autumn of 1674,Henry Oldenburg,secretary of the Royal Society in London,received an extraordinary letter. Sent by Antoni van Leeuwenhoek,a draper from Delft in the Netherlands,it contained an unlikely-sounding claim.Using a microscope of his own invention,van Leeuwenhoek had seen tiny creatures,invisible to the naked eye,living in lake water. Some of these “animalcules (微生物) ” were so small,he later estimated that 30 million of them would still be smaller than a grain of sand.Royal Society fellows couldn't believe it. Even with his most powerful instruments,the celebrated English microscopist Robert Hooke had never observed anything like the little creatures.In fact,the Dutchman had developed far superior lenses to Hooke's,and had discovered bacteria and protozoans (原生动物).By producing even smaller and more curved lenses—using a technique that he kept secret—van Leeuwenhoek was able to magnify objects up to 500 times. As well as discovering micro-organisms,he was the first to see red blood cells.In 1677,van Leeuwenhoek sent the Society further animalcule observations. Hooke eventually improved his own microscopes to the point where he,too,could see the tiny creatures. Three years later van Leeuwenhoek was made a fellow.It was not until 1890,more than 160 years after van Leeuwenhoek's death,that bacteria were linked with diseases. “Reading van Leeuwenhoek's letters,you very much get the impression of somebody dazzled by what he was finding,”says Lesley Robertson,leader of the archives at Delft University's school of microbiology. “He thought he'd found a whole new world—but he certainly never picked up on the connection with illness.”33.What did Antoni van Leeuwenhoek see with his own microscope?A.A letter. B.Bacteria and protozoans. C.Small animals in the water. D.The element of water.34.From the passage we can see ________.A.van Leeuwenhoek knew the tiny creatures in the water had something to do with nature B.van Leeuwenhoek was the first to discover bacteriaC.van Leeuwenhoek was the first to use the microscopeD.van Leeuwenhoek was the first one to know how to observe bacteria and protozoans 35.What does the underlined word “magnify” in the fourth paragraph mean?A.To clear away. B.To improve. C.To collect. D.To make large.36.From the last paragraph we can see,when Antoni van Leeuwenhoek saw the tiny creatures,invisible to the naked eye,living in lake water,________.A.he was overexcited B.he knew he followed someone else's discoveryC.he was a bit disappointed D.his discovery was to lead a connection between bacteria and illnesses短文改错My car just wouldn’t move any further. It was complete dead,and I was a few miles far away from anywhere on a c old wet night. I decided walk around a little before accepting I’d have to spend the night in the car. Maybe I can find a telephone. Actually,I didn’t have to walk far after I found a small house standing on a field with a light shone from the sitting room. I knocked at the door and was delighting when a pleasant old man opened the door but listened to my story carefully. He said he had no telephone,and it wasn’t one within walking distance,but offered to come and look at my car.答案1-20ACDDC DAACB DBDAB DACBC 21-36 ABBB CBDC ABAB BCDA 改错completely far去掉decide加to can-could after—before on—in shone—shining delighted but—and it--there。

人教版高中英语必修三Unit3DiverseCultures考点精题训练(带答案)

人教版高中英语必修三Unit3DiverseCultures考点精题训练(带答案)

人教版高中英语必修三Unit3DiverseCultures考点精题训练单选题1、When _____ from the top of the hill, the whole city looks more beautiful.A.seeingB.seenC.is seenD.is seeing答案:B考查非谓语动词和省略。

句意:从山顶上看,整个城市看起来更美。

分析句子可知,本句为状语从句的省略句,还原后为:When the whole city is seen from the top of the hill,因从句的主语与主句的主语相同,且从句的动词为be动词,所以主语和谓语可以省略。

故B选项正确。

小提示:状语从句中的主谓省略①在以if、when、though、unless、as、as if等连词引导的从句中,如果从句的主语和主句的主语一致,而且从句中的谓语动词是be,可以将状语从句中的主谓省略。

②如果从句主谓语是it is或it was,可以省略主谓结构, if it is possible, when it is necessary 等都是这种结构。

分析句子可知,本句为状语从句的省略句,还原后为:When the whole city is seen from the top of the hill,因从句的主语与主句的主语相同,且从句的动词为be动词,所以主语和谓语可以省略。

故B选项正确。

2、—How did it ________ that you made such a silly mistake?—I myself haven’t figured it out yet.A.bring aboutB.come aboutC.come acrossD.come on答案:B考查动词短语辨析。

句意:——你怎么犯了如此愚蠢的错误?——我自己也还没有弄明白怎么会这样。

A. bring about导致,引起;B. come about发生,产生;C. come across偶遇;D. come on (表鼓励、催促等)加油,快。

高中化学(新人教版)选择性必修三同步习题:第三章达标检测(同步习题)【含答案及解析】

高中化学(新人教版)选择性必修三同步习题:第三章达标检测(同步习题)【含答案及解析】

本章达标检测(满分:100分;时间:90分钟)一、选择题(本题共10小题,每小题2分,共20分。

每小题只有一个选项符合题意)1.(2020河南省实验中学高二下期中)“绿色化学”提倡“原子经济性”。

理想的“原子经济性”反应中,原料分子中的所有原子全部转变成所需产物,不产生副产物,实现零排放。

以下反应中符合“原子经济性”的是( )A.乙烯与氢气在一定条件下制乙烷B.乙醇与浓硫酸共热制乙烯C.乙醇催化氧化制乙醛D.乙烷与氯气反应制一氯乙烷2.(原创)下列有关有机物的说法不正确的是( )A.甲醛分子中所有原子共平面B.乙酸乙酯能发生取代反应C.乙酸乙酯、甲酸丙酯的密度都小于水的密度D.丙酮与丙醛互为同分异构体,均能发生银镜反应3.(2020河北张家口一中高二下期中)相同条件下,下列物质在水中的溶解度最大的是( )A.C17H35COOHB.CH3COOCH3C.HOCH2CH(OH)CH2OHD.苯甲醇4.(2020天津五十七中高二下期中)下列有机物的命名正确的是( )A.CH3CH(C2H5)CH32-甲基丁烷B.2-甲基-1-丙醇C.CH2BrCH2Br 二溴乙烷D.2,2-二甲基丁酸5.(2020重庆十九中高二下期中)下列各组物质中,既不互为同系物又不互为同分异构体的是( )A.CH4和C4H10B.乙酸和甲酸甲酯C.和D.和6.(2020四川泸州高二下期中)下列说法不正确的是( )A.乙醇的酯化反应和酯的水解反应均属于取代反应B.乙烯能使酸性高锰酸钾溶液褪色,是因为乙烯分子中含有碳碳双键C.乙醛分子式为C2H4O,它可以被还原成乙醇D.苯与溴水混合,反复振荡后溴水层颜色变浅是因为苯与溴发生了加成反应7.(2020山东临沂高二下期中)下列关系正确的是( )A.沸点:丙三醇>乙醇>新戊烷>2-甲基丁烷>丙烷B.密度:CCl4>H2O>己烷>辛烷C.等质量的物质燃烧消耗O 2的质量:乙烷>乙烯>乙炔>甲烷D.酸性:甲酸>乙酸>碳酸>苯酚8.对于下列实验现象的解释,不合理的是( ) 实验现象解释A②中产生气体的速率比①慢 乙醇分子中,乙基对羟基产生影响,使O —H 键不容易断裂B③中振荡、静置后分层,上层为橙色;④中产生白色沉淀 苯酚分子中,苯环对羟基产生影响,使O —H 键更容易断裂C⑤中振荡、静置后分层,下层为紫色溶液;⑥中振荡后紫色溶液褪色甲苯分子中,苯环对甲基产生影响,使甲基更容易被氧化D水浴加热,⑦中未见明显现象;⑧中试管壁上出现光亮的银镜碱性条件下+1价的Ag 才能氧化乙醛9.(2020山东广饶一中高二下月考)下表为某有机物分别与各种试剂反应的现象,则这种有机物可能是( ) 试剂 钠 酸性高锰酸钾溶液NaHCO 3溶液 现象放出气体褪色不反应A. B.C.CH3COOCH2CH3D.10.(2020江西南昌第二中学高二下月考)某物质可能由甲酸、乙酸、甲醇和甲酸乙酯四种物质中的一种或几种组成,在进行鉴定实验时记录如下:①能发生银镜反应;②加入新制Cu(OH)2,无明显现象;③滴入几滴稀氢氧化钠溶液和酚酞溶液,溶液呈红色,加热后变为无色。

最新人教版高中数学必修3第三章同步训练1(附答案)

最新人教版高中数学必修3第三章同步训练1(附答案)

3.3 几何概型 3.3.1 几何概型1.一只蚂蚁在如图所示的地板砖上(除颜色不同外,其余全部相同)爬动,它最后随意停留在黑色地板砖上的概率是( )A.13B.23C.14D.18 2.(2009福建泉州高中毕业班质量检查,文5)拉练行军中,某人从甲地到乙地共走了500 m ,途中涉水横穿过一条宽为x m 的河流,该人不小心把一件物品遗落在途中,若物品遗落在河里找不到,否则可以找到,已知找到该物品的概率为45,则河宽为( )A .40 mB .50 mC .80 mD .100 m3.在区间(0,3)中随机地取1个数,则这个数大于2的概率是__________.4.如图,在圆心角为90°的扇形中,以圆心O 为起点作射线OC ,求使得∠AOC 和∠BOC 都不小于30°的概率.答案:1.A 记“小蚂蚁停留在黑色地板砖上”为事件A ,则P(A)=412=13.2.D 由题意可知,该人找不到物品的概率为15.由x 500=15,得x =100(m). 3.13 所求概率为大于2的区间长度与总区间长度之比,即P =3-23=13. 4.解:记F ={作射线OC ,使∠AOC 和∠BOC 都不小于30°},作射线OD 、OE ,使∠AOD=30°,∠AOE =60°.当OC 在∠DOE 内时,∠AOC 和∠BOC 都不小于30°,则P(F)=3090=13.1.已知直线y =x +b 的横截距在[-2,3]范围内,则直线在y 轴上截距b 大于1的概率是( )A.15B.25C.35D.452.如下图所示,在直角坐标系内,射线OT 落在60°角的终边上,任作一条射线OA ,则射线OA 落在∠xOT 内的概率是( )A.13B.14C.15D.163.如图所示,墙上挂有一块边长为a 的正方形木板,它的四个角的空白部分都是以正方形的顶点为圆心,以a2为半径的扇形,某人向此木板投镖,假设每次都能击中木板,且击中木板上每个点的可能性都一样,则击中阴影部分的概率是( )A .1-π4B .1+π4C .1-π3D .1-π64.设A 为圆周上一定点,在圆周上等可能地任取一点与A 连接,则弦长超过半径的概率为________.5.在平面直角坐标系xOy 中,设Ω是横坐标与纵坐标的绝对值均不大于2的点构成的区域,Φ是到原点的距离不大于1的点构成的区域.向Ω中随机投一点,则所投的点落在Φ中的概率是__________.6.一海豚在水池中自由游弋.水池为长30 m 、宽20 m 的长方形.求此刻海豚嘴尖离岸边不超过2 m 的概率.答案:1.A P =2-12-(-3)=15.2.D 记“射线OA 落在∠xOT 内”为事件A.事件A 的几何度量是60°,而所有区域的几何度量是360°,故P(A)=60°360°=16.3.A 由题意知,正方形木板的面积为a 2,则阴影部分的面积为a 2-4×14×π×(a2)2=a 2-14πa 2,根据几何概型的概率计算公式可知,击中阴影部分的概率是a 2-14πa 2a 2=1-π4.4.23 如图,AB =AC =OA =R ,则优弧BC 的长÷圆O 的周长=23,故弦长超过半径的概率为23.5.π16本小题考查几何概型.如图,区域Ω表示边长为4的正方形ABCD 的内部(含边界),区域Φ表示单位圆及其内部,因此P =π×124×4=π16.6.解:如图所示,区域Q 是长30 m 、宽20 m 的长方形.图中阴影部分表示事件A :“海豚嘴尖离岸边不超过2 m ”.问题可以理解为求海豚嘴尖出现在图中阴影部分的概率,于是S Q =30×20=600 m 2,S A =30×20-26×16=184 m 2.P(A)=S A S Q =184600=2375≈0.31.1.一个路口的红绿灯,红灯的时间为30秒,黄灯的时间为5秒,绿灯的时间为40秒,当某人到达路口时看见的是红灯的概率是( )A.15B.25C.35D.45 答案:B 记“看见的是红灯”为事件A ,则P(A)=3030+5+40=25.2.在半径为1的圆中随机地撒一大把豆子,则豆子落在圆内接正方形中的概率是( ) A.1π B.2π C.2π D.3π答案:B 豆子落在圆内的任意位置是等可能的,而落在圆内接正方形中只与面积有关,与位置无关,符合几何概型,圆内接正方形的对角线长等于2,则正方形的边长为 2.∴P =2×2πr 2=2π. 3.有四个游戏盘,如果撒一粒黄豆落在阴影部分,则可中奖.小明希望中奖,他应当选择的游戏盘为( )答案:C 设备选答案A 、B 、C 、D 所表示的事件分别为A 、B 、C 、D.则P(A)=38,P(B)=26=13,P(C)=πa 24a 2=π4,P(D)=12×2r ×r πr 2=1π.显然P(C)最大. 4.(2009福建高考,文14)点A 为周长等于3的圆周上的一个定点,若在该圆周上随机取一点B ,则劣弧的长度小于1的概率为__________.答案:23如图,点B可落在优弧上,其弧长为2,由几何概型知概率为23.5.向面积为20的△ABC 内任投一点P ,则使△PBC 的面积小于5的概率为__________.答案:716P 点所在区域为图中阴影部分,取高AD 的4等分点并作BC 的平行线,交AB 、AC 于G 、H ,得四边形BGHC 为P 点位置,故所求事件的概率为P =S 四边形BGHC S △ABC=716.6.在长为12 cm 的线段AB 上任取一点M ,并以线段AM 为边作正方形.试求该正方形的面积介于36 cm 2与81 cm 2之间的概率.答案:解:若正方形的面积介于36 cm 2与81 cm 2之间,则正方形的边长AM 介于6 cm与9 cm 之间.所以正方形的面积介于36 cm 2与81 cm 2之间的概率为312=14.7.在一个边长分别为a 、b(a>b>0)的矩形内画一个梯形,梯形上、下底长分别为13a 与12a ,高为b ,向该矩形内随机投一点,求所投的点落在所画的梯形内部的概率.答案:解:记“所投点落在所画的梯形内部”为事件A ,则事件A 所占的区域面积S A =12×(13a +12a)·b =512ab.整个基本事件的区域面积S Ω=ab ,由几何概型的概率公式得P(A)=S A S Ω=512ab ab =512,即所投点落在所画的梯形内部的概率是512.8.在等腰Rt △ABC 的斜边AB 上任取一点M ,求AM 小于AC 的概率.答案:解:在AB 上截取AC ′=AC ,于是,P(AM<AC)=P(AM<AC ′)=AC ′AB =ACAB =22. 9.已知棱长为2的正方体的内切球O.若在正方体内任取一点,则这一点不在球内的概率为多少?答案:解:球的直径就是正方体的棱长2.∴球O 的体积为V 球=4π3,正方体的体积为V =23=8.由于在正方体内任取一点时,点的位置是等可能的,在正方体内每个位置上,由几何概型公式,这点不在球O 内(事件A)的概率为P(A)=V -V 球V =8-4π38=1-π6.∴所求概率为1-π6.点评:一般地,在几何区域Q 中随机地抽取一点,记“该点落在其内部的一个区域A 内”为事件A ,则事件A 发生的概率为P(A)=A 的测度Q 的测度.这里要求Q 的测度不为0,其中“测度”的意义依Q 确定,当Q 分别是线段、平面图形和立体图形时,相应的“测度”分别是长度、面积和体积等.几何概型的试验中,事件A 的概率P(A)只与区域A 的几何度量(长度、面积或体积)成正比,而与A 的位置和形状无关.10.现向图中所示正方形内随机地投掷飞镖,求飞镖落在阴影部分的概率.答案:解:令x =1,得y =23;令y =-1,得x =16.所以阴影部分三角形的面积为12(1-16)(1+23)=2536.正方形的面积为4,所以飞镖落在阴影部分的概率为2536×4=25144. 点评:古典概型与几何概型中基本事件发生的可能性都是相等的,但古典概型要求基本事件有有限个,几何概型要求基本事件有无限多个.。

(人教版)高中英语必修第三册Unit3单元测试试卷(含答案)03

(人教版)高中英语必修第三册Unit3单元测试试卷(含答案)03

加油!有志者事竟成答卷时应注意事项1、拿到试卷,要认真仔细的先填好自己的考生信息。

2、拿到试卷不要提笔就写,先大致的浏览一遍,有多少大题,每个大题里有几个小题,有什么题型,哪些容易,哪些难,做到心里有底;3、审题,每个题目都要多读几遍,不仅要读大题,还要读小题,不放过每一个字,遇到暂时弄不懂题意的题目,手指点读,多读几遍题目,就能理解题意了;容易混乱的地方也应该多读几遍,比如从小到大,从左到右这样的题;4、每个题目做完了以后,把自己的手从试卷上完全移开,好好的看看有没有被自己的手臂挡住而遗漏的题;试卷第1页和第2页上下衔接的地方一定要注意,仔细看看有没有遗漏的小题;5、中途遇到真的解决不了的难题,注意安排好时间,先把后面会做的做完,再来重新读题,结合平时课堂上所学的知识,解答难题;一定要镇定,不能因此慌了手脚,影响下面的答题;6、卷面要清洁,字迹要清工整,非常重要;7、做完的试卷要检查,这样可以发现刚才可能留下的错误或是可以检查是否有漏题,检查的时候,用手指点读题目,不要管自己的答案,重新分析题意,所有计算题重新计算,判断题重新判断,填空题重新填空,之后把检查的结果与先前做的结果进行对比分析。

亲爱的小朋友,你们好! 经过两个月的学习,你们一定有不小的收获吧,用你的自信和智慧,认真答题,相信你一定会闯关成功。

相信你是最棒的!Unit3Diverse Cultures单元测试一、单句语法填空1.Please say________(definite)whether you will be coming or not.2.She never participates________any of our discussions,does she?3.He speaks English as________(fluent)as a foreigner.4.The textbook________(contain)12units,including2revisions.m5.Whereas in the________(finance)world,you only get what you pay for.6.We deal with all________(variety)of information.7.I’ve had a few interviews,but no job________(offer)yet.8.Apart from________(be)the kingdom of flowers,it is home to many ethnic minority groups.9.The group had been carefully________(select)for the study because of their lifestyles.10.It suddenly occurred to her________Joe was afraid of being alone.二、短语填空1.The young birds________(依靠)their parents for food for several weeks.2.I never________(过去常常)enjoy science,but last year I changed schools,and the science teachers at my new school are excellent.3.________(各种各样的玩具)are on sale in shops.4.After thinking about it,I’ve decided to________(接受你的提议).5.I’m sure the child will soon________(安定下来)in his new school.6.____________(除了成本之外),we need to think about how much time the job will take.7.I finally________(查明)the reason of this strike.8.Things like parents’educational background________(对……有更大的影响)a child’s reading.9.Judgment should________(以事实为依据),not on hearsay.10.They are eternally happy and________(过着有意义的生活).三、根据提示完成句子1.Little Johnny felt the bag,curious to know__________________________.(what引导名词性从句)小约翰尼摸着袋子,非常好奇地想知道里面装着什么东西。

人教版高中地理必修三试题:第三章《第一节 能源资源的开发──以我国山西省为例》含解析

人教版高中地理必修三试题:第三章《第一节 能源资源的开发──以我国山西省为例》含解析

《第一节能源资源的开发──以我国山西省为例》测试题吉林省前郭县第五中学王彦峰一、单项选择题近年来,一轮煤炭开发的热潮正在新疆广阔的大地上如火如荼地进行.30多家大企业大集团的40多个重大投资项目相继奠基开工,投资总额超过1 000亿元。

据此回答1~2题。

1.山西和新疆在发展煤炭工业时所面临的共同问题是( )A.距市场距离远B.水资源短缺C.易造成严重的水土流失D.交通不便解析:山西和新疆发展煤炭工业所面临的共同问题是水资源短缺。

答案:B2.下列措施不利于新疆煤炭产业可持续发展的是( )A.大力增加原煤的开采数量,提高经济效益B.加大煤炭的加工转换,提高附加值C.促进煤炭清洁生产和利用D.解决煤炭生产和利用导致的环境问题解析:增加原煤的开采数量不利于可持续发展。

答案:A下列图表为我国四个省区2012年能源消费情况,据此完成3~4题。

3.下列叙述正确的是()A.①省区以水电、核电为主,其中核电消费量在四省区中最多B.②省区以煤炭为主,且煤炭消费量居四省区首位C.③省区水电、核电消费量在四省区中最少,能源结构不均衡D.④省区石油消费量在四省区中最少,能源结构较为均衡解析:四个省份的能源消费情况,读图做出正确判断,③省区以煤炭为主要能源,水电和核电比例低,能源结构不均衡.答案:C4.今后四省区能源消费构成变化的趋势是( )A.①②两省区发挥本省水能资源的优势,大力发展水电、核电B.②④两省区常规能源丰富,做好西电东送的能源保证C.②③两省区彻底转变以常规能源为主的局面,重点发展新能源D.①④两省区加强本省能源开发,提高能源利用率解析:从四个省份的能源消费构成及总能耗和单位GDP能耗,①为我国西部省区,大力发展核电没有必要,②应为我国东部地区,西电东送不正确;②③常规能源丰富,今后大力发展新能源不符合我国国情;①④两省能耗高,在加强本省能源开发的基础上,提高能源利用率。

答案:D下图是山西省煤炭产业链图。

读图回答5~8题。

人教版高中英语必修三课时训练:Unit 3测试题 (含答案)

人教版高中英语必修三课时训练:Unit 3测试题 (含答案)

单元检测卷:Unit 3阅读理解ABefore you make friends, you have to decide who you want to be your friends. Most people like to have friends who like to do the same kinds of things they do.The quickest way to make a friend is to smile. When you smile, people think you are friendly and easy to talk to. It may not be easy at first to smile, but remember most people will stay away from a scared or angry looking face.One easy way to start a conversation with someone is to say something nice about him. Think about how great you feel when someone says something nice to you. Doesn’t it make you want to keep talking to that person?Ask your new friends questions about themselves. Who’s their favorite singer, where do they live, what do they do after school are all good questions to start a conversation. Make sure you have something to add to the conversation, too. When someone asks you a question, do have an answer for them. There is nothing that will stop a conversation quicker than a shrug for an answer.Kids who show an interest in other kids and who are kind and friendly make good friends. Remember, everyone wants to be around people who like to do similar things and people who are nice to them.1. This passage gives us some advice on_______.A.the importance of smile B.what kind of person you can make friends with C.how to start a conversation D.how to make friends2. Most people like to make friends with those________.A.who share the same interest B.who are sad every dayC.who are fond of talking D.who say bad things to them3. From the passage, if a kid wants to make good friends ,he should _______.A. smile to othersB. show an interest in othersC. be kind and friendly.D. All the aboveBI think people everywhere dream about having lots of money. I know I do. I would like to earn large amounts of money. You can win a large amount of money in the United States through lotteries(彩票). People pay money for tickets with numbers. If your combination of numbers is chosen, you will win a huge amount of money—often in the millions.A few years ago, my friend Al won the lottery. It changed his life. He was not “born with a silver spoon in his mouth”. Instead, my friend was always short of money. And the money he did earn was chicken feed.Sometimes Al even had to accept handouts(施舍物) from his friends. But do not get me wrong. My friend was always very careful with the money he spent. In fact, he was often a cheapskate. He did not like to spend money. The worst times were when he had no single penny left.One day, Al scraped together a few dollars for a lottery ticket. He thought he would never gain lots of money unexpectedly. But his combination of numbers was chosen and he won thelottery. Al was so excited. The first thing he did was buy a costly new car—one thing that he normally would not buy. Then he started spending money on unnecessary things. It was like he had “money to burn”.When we got together for a meal at a restaurant, Al paid every time. He would always tell me the money made him feel like a millionaire. But, Al spent too much money. Soon he was “down and out”again. He had spent his “bottom dollar”—his very last amount. He did not even save any of the money.I admit I do feel sorry for my friend. He had enough money to “live like a king”. Instead, he was back to “living on a shoestring”—a very low budget. Some might say he was wise about small things, but not about important things.4.What does the author desire to do like others?A.To combine the numbers perfectly. B.To make a huge fortune.C.To be chosen for selling lotteries. D.To get in touch with millionaires.5.Before Al won the lottery ________.A.he spent too much money buying chicken B.he didn't value the money he had earned C.he had trouble feeding his family D.he hated to give a hand to his friends 6.What does the fourth paragraph imply?A.Al always had good luck in life. B.Al valued his money above his life.C.Al had loved the expensive car probably. D.Al pretended to have more money. 7.When a person is “down and out”,________.A.he is as poor as a church mouse B.he lives a life like other peopleC.he has set aside all his money D.he is looking forward to big successCWhen you’re returning to Australia, be careful that you don’t bring in pests and diseases. Some items you might bring back from overseas can be pests and diseases that Australia doesn’t have. When you return, declare(申报)all food, meat, fruits, plants, seeds, wooden souvenirs, animal or plant materials.Australia has strict quarantine(检疫)laws and tough on-the-spot fines. Every piece of luggage is now screened or X-rayed. If you fail to declare any quarantine items, or if you make a false declaration, you will get caught. In addition to on-the-spot fines, you could be accused and fined more than $60, 000 and you may risk 10 years in prison. All international mail is also screened.Some products may require treatment to make them safe. Items that are restricted because of the risk of pests and diseases will be seized and destroyed by the Australian Quarantine and Inspection Service(AQIS).In many cases, the goods you declare will be returned to you after inspection. However, any item that presents a quarantine risk will be withheld(扣留). You will be given a range of options (选项)for each item depending on the quarantine risk: ··Treating the item to make it safe*;·Holding the item until an import permit is presented*; ··Re-exporting the item*;··Destroying the item.Those treatments with the sign “*”are subject to fees(付费).Further information:For more detailed information about bringing in food, animals, plants, animal or plant materials, call the AQIS at 1800-020-504.8. Which of the following don’t you need to declare when returning to Australia?A. Tea.B. Wooden combs.C. Some bread.D. A pair of glasses.9. If you make a false declaration, you would _______ .A. be fined a lot of moneyB. be forbidden to return to AustraliaC. have to declare your items againD. make yourself screened10. Where can we most probably find this passage?A. In an advertisement.B. In a traveling guidebook.C. At the police station.D. In a hospital.11. We can learn from the passage that _______ .A. you can keep the item before an import permit is presentedB. all products must be treated according to the AQISC. not all treatments for your declared items are freeD. travelers can sell their declared itemsDMark Twain,the famous American writer, liked to play jokes on others. Butonce a joke was played on him.One day Mark Twain was invited(被邀请)to give a talk in a small town. Atlunch he met a young man,one of his friends.The young man said that he has an uncle with him. He told Twain that hisuncle never laughed or smiled,and that nobody and nothing was able to make hisuncle smile or laugh."You bring your uncle to my talk tonight,"said Mark Twain."I'm sure I canmake him laugh"That evening the young man and his uncle sat in the front. Mark Twain beganto speak. He told several funny stories. This made everyone in the room laugh.But the man never even smiled. Mark Twain told more funny stories,but theold man still kept quiet. Mark Twain told his funny stories. Finally he stopped.He was tired and quite disappointed(失望的).Some days later, Mark Twain told another friend of his about what hadhappened."Oh,"said his friend."I know that old man. He's been deaf(聋)for years."1. Mark Twain liked to play jokes on_____.A. himselfB. othersC. old menD. Americans2. One day Mark Twain met_____at lunch.A. a friendB. a young man's uncleC. a young girlD. a deaf3. The young man told Mark Twain that his uncle never_____.A. spokeB. talkedC. laughedD. ate4. The young man and his uncle sat _____that evening.A. at homeB. near the doorC. at the backD. in the front5. Mark Twain stopped telling stories at last because he was_____.A. thirstyB. tiredC. angryD. sleepy七选五Does failure really exist?If you believe you have failed, then you have. If you believe you don’t have the ability to succeed, then you don’t. 16 The moment you decide to give up or stop working toward your goals, failure is born.17Most people give themselves an out without even realizing it. They are willing to work hard on reaching their goals, but only until the going gets too rough or their energy dies down. Don’t do that! 18 Never quit, never admit failure, and never lose heart.Don’t believe in a clear finish line for goals.It’s a good idea to set a general timeline (时间表), but remember that something will be beyond your control. 19 If you lock yourself into a given timeline, you might make yourself feel like a failure! Instead, get a general idea of when you’d like your goal to be completed. Then take it one day at a time and focus on making progress instead of reaching the finish line in as little time as possible.Be sure that you don’t see difficulties as failures.Difficulties mean only one thing: it’s not time for your goal to be completed yet. That’s it! It doesn’t mean you failed; it doesn’t mean you’re weak; it doesn’t mean you’ll never achieve your goals. 20 You’ve got to keep moving forward and find a way over, around, or through the difficulties.A. Never give up on yourself.B. Failure only exists in your own mind!C. That’s exactly how failure makes us feel.D. It simply means you have not done enough yet.E. You can never say exactly when your goal will be reached.F. Instead, make up your mind to make your goal happen, no matter what!G. Work hard towards your goal, and you will be likely to get good results.完形填空Let’s suppose you have a four-year-old daughter who has just started kindergarten. Whenever she 21 something new, she always thinks it is hard. For example, you start a dance class this year and even though she loves dancing, she 22 to do it because she thinks it’s just too hard. In such a situation, what would you do?This is a real 23 for a lot of parents. Your daughter is 24 four years old. Kids at this age are generally self-centered. That is why they are lying down on the ground and 25 when they can’t get the ball or when things don’t work out. They only 26 things from their own perspective(思考方法). Therefore, she thinks taking a dance class is hard though in your opinion it is the 27 .Here the problem is that your daughter 28 easily. You certainly don’t want to raise a child that always gives up if something is 29 . And this is the area where we need to be 30 so that her interest in things isn’t 31 . There are some things to do here: Expose (使体验)your daughter to different hobbies and activities and 32 her to choose what she likes to do the most. At the young age, one or two activities are enough, and they should only be for 33 . The idea is that our children get to 34 new things and make up their own minds. You should help her understand that her 35 doesn't matterr --- what matters most is that she is trying and she has fun. 36 , if your daughter struggles with activities that are new to her, as parents, you should be 37 . Tell her it’s normal for new things to be hard and that things are hard 38 they’re easy.In short, your daughter is just a baby, 39 let her have fun doing the things she likes to do and realize how 40 it is to try new things.21. A. tries B. remembers C. gets D. misses22. A. refuses B. pretends C. wants D. wishes23. A. reward B. result C. challenge D. reason24. A. already B. still C. almost D. just25. A. smiling B. sleeping C. crying D. leaving26. A. see B. teach C. solve D. buy27. A. favorite B. opposite C. exception D. choice28. A. works out B. gives up C. turns around D. brings in29. A. popular B. cheap C. difficult D. dirty30. A. ready B. angry C. brave D. careful31. A. developed B. protected C. damaged D. prevented32. A. allow B. forbid C. order D. promise33. A. life B. fun C. example D. luck34.A. produce B. design C. appreciate D.experience35. A. performance B. safety C. lesson D. health36. A. However B. Besides C. Instead D. Anyway37. A. serious B. anxious C. frightened D.supportive38. A. unless B. before C. while D. as39. A. for B. but C. so D. or40. A. foolish B. terrible C. successful D. important语法填空Online shopping is coming into fashion in most cities, where people are able to make full use of the rapidly-developed Internet technology. Nowadays, can we find a person___41___has not experienced online shopping? Definitely not.Online shopping___42___(welcome) by most people due to various reasons. From the perspective(观点)of consumers, it can save some time for people who don’t have much spare time. Just click the mouse, they can get___43___they want while staying at home. For the retailers(零售商), it can cut some costs for those who don’t have much circulating funds (流动资金). ___44___ (compare) with the traditional trade mode, it doesn’t need renting a house. ___45___, there are still some disadvantages in online shopping. First, a face-to-face deal makes online shopping less___46___(rely) and trustworthy(可靠的). Second, people will lose___47___fun of bargaining.___48___is undeniable that shopping on the Internet has become an irresistable(不可阻挡的)trend in modern society. It’s of great urgency that we need to make the relative laws in accordance with(根据)the rapid 49 ( grow) of online shopping. Only in this way can we enjoy the pleasure and ___50___(convenient) of online shopping without the concern of being cheated.短文改错假定英语课上英语老师要求同桌之间交换修改作文,请你修改你同桌写的以下作文。

人教版高一数学必修3第三章概率测试题附答案

人教版高一数学必修3第三章概率测试题附答案

人教版高一数学必修3第三章概率测试题(附答案)高中数学必修3第三章 概率单元检测一、选择题1.任取两个不同的1位正整数,它们的和是8的概率是( ).A . 241B .61C .83D .1212.在区间⎥⎦⎤⎢⎣⎡2π2π ,-上随机取一个数x ,cos x 的值介于0到21之间的概率为( ). A .31 B .π2C .21D .323.从集合{1,2,3,4,5}中,选出由3个数组成子集,使得这3个数中任何两个数的和不等于6,则取出这样的子集的概率为( ).A .103B .107C .53D .524.在一个袋子中装有分别标注数字1,2,3,4,5的五个小球,这些小球除标注的数字外完全相同.现从中随机取出2个小球,则取出的小球标注的数字之和为3或6的概率是( ).A .103B .51C .101D .1215.从数字1,2,3,4,5中,随机抽取3个数字(允许重复)组成一个三位数,其各位数字之和等于9的概率为( ).A .12513B .12516C .12518D .125196.若在圆(x -2)2+(y +1)2=16内任取一点P ,则点P 落在单位圆x 2+y 2=1内的概率为( ).A .21B .31C .41 D .161 7.已知直线y =x +b ,b ∈[-2,3],则该直线在y 轴上的截距大于1的概率是( ).A .51B .52C .53D .548.在正方体ABCD -A 1B 1C 1D 1中随机取点,则点落在四棱锥O -ABCD (O 为正方体体对角线的交点)内的概率是( ).A .61B .31C .21D .32 9.抛掷一骰子,观察出现的点数,设事件A 为“出现1点”,事件B 为“出现2点”.已知P (A )=P (B )=61,则“出现1点或2点”的概率为( ).A .21B .31C .61D .121 二、填空题10.某人午觉醒来,发觉表停了,他打开收音机想听电台报时,假定电台每小时报时一次,则他等待的时间短于10分钟的概率为___________.11.有A ,B ,C 三台机床,一个工人一分钟内可照看其中任意两台,在一分钟内A 未被照看的概率是 .12.抛掷一枚均匀的骰子(每面分别有1~6点),设事件A 为“出现1点”,事件B 为“出现2点”,则“出现的点数大于2”的概率为 .13.已知函数f (x )=log 2x , x ∈⎥⎦⎤⎢⎣⎡221 ,,在区间⎥⎦⎤⎢⎣⎡221 ,上任取一点x 0,使f (x 0)≥0的概率为 .14.从长度分别为2,3,4,5的四条线段中任意取出三条,则以这三条线段为边可以构成三角形的概率是.15.一颗骰子抛掷2次,观察出现的点数,并记第一次出现的点数为a,第二次出现的点数为b.则a+b能被3整除的概率为.三、解答题16.射手张强在一次射击中射中10环、9环、8环、7环、7环以下的概率分别是0.24、0.28、0.19、0.16、0.13.计算这个射手在一次射击中:(1)射中10环或9环的概率;(2)至少射中7环的概率;(3)射中环数小于8环的概率.17.甲、乙两船驶向一个不能同时停泊两艘船的码头,它们在一昼夜内到达该码头的时刻是等可能的.如果甲船停泊时间为1 h,乙船停泊时间为2 h,求它们中的任意一艘都不需要等待码头空出的概率.18.同时抛掷两枚相同的骰子(每个面上分别刻有1~6个点数,抛掷后,以向上一面的点数为准),试计算出现两个点数之和为6点、7点、8点的概率分别是多少?19.从含有两件正品a1,a2和一件次品b的三件产品中,每次任取一件,每次取出后不放回,连续取两次,求取出的两件产品中恰有一件次品的概率.参考答案一、选择题 1.D解析:1位正整数是从1到9共9个数,其中任意两个不同的正整数求和有8+7+6+5+4+3+2+1=36种情况,和是8的共有3种情况,即(1,7),(2,6),(3,5),所以和是8的概率是121.2.A解析: 在区间⎥⎦⎤⎢⎣⎡2π2π- ,上随机取一个数x ,即x ∈⎥⎦⎤⎢⎣⎡2π2π- ,时,要使cos x 的值介于0到21之间,需使-2π≤x ≤-3π或3π≤x ≤2π,两区间长度之和为3π,由几何概型知cos x 的值介于0到21之间的概率为π3π=31.故选A. 3.D解析:从5个数中选出3个数的选法种数有10种,列举出各种情形后可发现,和等于6的两个数有1和5,2和4两种情况,故选出的3个数中任何两个数的和不等于6的选法有(10-3×2)种,故所求概率为104=52.4.A解析:从五个球中任取两个共有10种情形,而取出的小球标注的数字之和为3或6的只有3种情况:即1+2=3,2+4=6,1+5=6,,故取出的小球标注的数字之和为3或6的概率为3.105.D解析:由于一个三位数,各位数字之和等于9,9是一个奇数,因此这三个数必然是“三个奇数”或“一个奇数两个偶数”.又由于每位数字从1,2,3,4,5中抽取,且允许重复,因此,三个奇数的情况有两种:(1)由1,3,5组成的三位数,共有6种;(2)由三个3组成的三位数,共有1种.一个奇数两个偶数有两种:(1)由1,4,4组成的三位数,共有3种;(2)由3,2,4组成的三位数,共有6种;(3)由5,2,2组成的三位数,共有3种.再将以上各种情况组成的三位数的个数加起来,得到各位数字之和等于9的三位数,共有19种.又知从数字1,2,3,4,5,中,随机抽取3个数字(允许重复)组成一个三位数共有53=125种.因此,所求概率为19.125 6.D解析:所求概率为224π1π⨯⨯ =161.7.B 解析:区域Ω为区间[-2,3],子区域A 为区间(1,3],而两个区间的长度分别为5,2.8.A解析:所求概率即为四棱锥O -ABCD 与正方体的体积之比.9.B解析:A ,B 为互斥事件,故采用概率的加法公式P (A +B )=P (A )+(B )=61+61=31. 二、填空题10.61. 解析:因为电台每小时报时一次,我们自然认为这个人打开收音机时处于两次报时之间,例如(13∶00,14∶00),而且取各点的可能性一样,要遇到等待时间短于10分钟,只有当他打开收音机的时间正好处于13∶50至14∶00之间才有可能,相应的概率是6010=61. 11.31. 解析:基本事件有A ,B ;A ,C ;B ,C 共3个,A 未被照看的事件是B ,C ,所以A 未被照看的概率为31.12.32. 解析:A ,B 为互斥事件,故采用概率的加法公式得P (A +B )=31,1-P (A +B )=32. 13.32. 解析:因为f (x )≥0,即log 2 x 0≥0,得x 0≥1,故使f (x )≥0的x 0的区域为[1,2].14.34. 解析:从长度为2,3,4,5的四条线段中任意取出3条共有4种不同的取法,其中可构成三角形的有(2,3,4),(2,4,5),(3,4,5)三种,故所求概率P =43. 15.13. 解析:把一颗骰子抛掷2次,共有36个基本事件.设“a +b 能被3整除”为事件A ,有(1,2),(2,1),(1,5),(2,4),(3,3),(4,2),(5,1),(3,6),(4,5),(5,4),(6,3),(6,6),共12个.P (A )=13. 三、解答题16.解:设“射中10环”、“射中9环”、“射中8环”、“射中7环”、“射中7环以下”的事件分别为A ,B ,C ,D ,E ,则(1)P (A ∪B )=P (A )+P (B )=0.24+0.28=0.52.所以,射中10环或9环的概率为0.52.(2)P (A ∪B ∪C ∪D )= P (A )+P (B )+P (C )+P (D )=0.24+0.28+0.19+0.16=0.87.所以,至少射中7环的概率为0.87.(3)P (D ∪E )=P (D )+P (E )=0.16+0.13=0.29.所以,射中环数小于8环的概率为0.29.17.解:这是一个几何概型问题.设甲、乙两艘船到达码头的时刻分别为x 与y ,A 为“两船都不需要等待码头空出”,则0≤x ≤24,0≤y ≤24,要使两船都不需要等待码头空出,当且仅当甲比乙早到达1h 以上或乙比甲早到达2h 以上,即y -x ≥1或x -y ≥2.故所求事件构成集合A ={(x ,y )| y -x ≥1或x -y ≥2,x ∈[0,24],2322y ∈[0,24]}.A 对应图中阴影部分,全部结果构成集合Ω为边长是24的正方形.由几何概型定义,所求概率为P (A )=的面积的面积ΩA =22224212-24211-24⨯⨯+)()(=5765.506=0.879 34.18.解:将两只骰子编号为1号、2号,同时抛掷,则可能出现的情况有6×6=36种,即n =36.出现6点的情况有(1,5),(5,1),(2,4),(4,2),(3,3).∴m 1=5,∴概率为P 1=n m 1=365. 出现7点的情况有(1,6),(6,1),(2,5),(5,2),(3,4),(4,3).∴m 2=6,∴概率为P 2=n m 2=366=61. 出现8点的情况有(2,6),(6,2),(3,5),(5,3),(4,4).∴m 3=5, ∴概率为P 3=n m 3=365. 19.解:每次取出一个,取后不放回地连续取两次,其一切可能的结果组成的基本事件有6个,即(a1,a2),(a1,b),(a2,a1),(a2,b),(b,a1),(b,a2)。

最新人教版高中数学必修3第三章同步训练6(附答案)2

最新人教版高中数学必修3第三章同步训练6(附答案)2

第三章 概率测评(A 卷)(总分:120分 时间:90分钟)一、选择题(本大题共10小题,每小题5分,共50分.在每小题给出的四个选项中,只有一项是符合题目要求的)1.下列事件中,不可能事件是 A .三角形内角和为180°B .三角形中大边对大角,小边对小角C .锐角三角形中两个内角和小于90°D .三角形中任意两边之和大于第三边答案:C A 、B 、D 是必然事件,C 是不可能事件.2.一种计算机芯片可以正常使用的概率为0.994,那么它不能正常使用的概率为 A .0.006 B .0.001 C .0.5 D .0.004答案:A 该种计算机芯片能否正常使用互为对立事件,故不能正常使用的概率为1-0.994=0.006.3.抛掷一枚质地均匀的硬币,如果连续抛掷1000次,那么第999次出现正面朝上的概率是A.1999B.11000C.9991000D.12答案:D 设事件A ={抛掷一枚硬币,出现正面},则P(A)=12.第999次出现正面朝上的概率与任何一次出现正面朝上的概率是相等的,都为12.4.在1万km 2的海域中有40 km 2的大陆架贮藏着石油,假如在海域中任取一点钻探,则钻到油层面的概率是A.1251B.1249C.1250D.1252答案:C 由几何概型的计算公式可知,钻到油层面的概率是P =4010000=1250.5.甲、乙两人随意入住两间空房,则每人各住一间的概率是 A.13 B.14 C.12D .无法确定 答案:C 问题属古典概型.总的基本事件数为4,甲、乙两人各住一间房包含的基本事件的个数为2,故概率为12.6.先后抛掷两枚均匀的正方体骰子(它们的六个面分别标有点数1、2、3、4、5、6),骰子朝上的面的点数分别为X 、Y ,则log 2X Y =1的概率为A.16B.536C.112D.12 答案:C 要log 2X Y =1,即Y =2X.于是,用有序实数对表示可能出现的结果为(1,2),(2,4),(3,6),共有3个基本事件;总的基本事件数为62=36(种),所以所求的概率为336=112.7.一袋中装有大小相同,编号分别为1,2,3,4,5,6,7,8的八个球,从中有放回...地每次取一个球,共取2次,则取得两个球的编号和不小于...15的概率为A.132B.164C.332D.364答案:D 从8个编号不同的小球中有放回地取2次,共包括8×8=64个基本事件,其中和不小于15的基本事件是(7,8),(8,7),(8,8)共3个.故P =364.8.在腰长为2的等腰直角三角形内任取一点,使得该点到此三角形的直角顶点的距离不大于1的概率为A.π16B.π8C.π4D.π2答案:B 该点应落在以直角顶点为圆心,半径为1的扇形内,记其面积为S 扇,则S 扇=14×π=π4,所求概率为S 扇S △=π412×2×2=π8. 9.在5件产品中,有3件一等品和2件二等品,从中任取2件,那么以710为概率的是A .都不是一等品B .恰好有一件一等品C .至少有一件一等品D .至多有一件一等品答案:D 三件一等品记为A 1,A 2,A 3;两件二等品记为B 1,B 2.从5件中任取2件的所有结果为A 1A 2,A 1A 3,A 1B 1,A 1B 2,A 2A 3,A 2B 1,A 2B 2,A 3B 1,A 3B 2,B 1B 2.共有10种结果,至多有一件一等品为A 1B 1,A 1B 2,A 2B 1,A 2B 2,A 3B 1,A 3B 2,B 1B 2七种结果,故概率为710.10.现有五个球分别记为A ,C ,J ,K ,S ,随机放进三个盒子,每个盒子只能放一个球,则K 或S 在盒中的概率为A.110B.35C.310D.910答案:D 从五个球中任取三个,包括ACJ ,ACK ,ACS ,AJK ,AJS ,AKS ,CJK ,CJS ,CKS ,JKS 共10个基本事件,其中不含K 或S 的只有ACJ 一个基本事件.故所求概率为1-110=910.二、填空题(本大题共4小题,每小题4分,共16分.答案需填在题中横线上)11.根据多年气象统计资料,某地6月1日下雨的概率为0.45,阴天的概率为0.20,则此地6月1日晴天的概率为__________.答案:0.35 阴天、下雨、晴天互为互斥事件,其并集是必然事件,故此地6月1日晴天的概率为1-0.45-0.20=0.35.12.单位正方形ABCD ,在正方形内(包括边界)任取一点M ,则△AMB 的面积大于或等于14的概率为__________. 答案:12如图,取BC 、AD 的中点E 、F ,连接EF ,当M 在矩形CEFD 内运动时,△ABM的面积大于或等于14,由几何概型的概率公式,得P =S 矩形CDFE S 正方形ABCD =12.13.从数学、英语、语文、科技、体育这5本书中任取2本,数学书一定被抽到的概率为__________.答案:25把数学、英语、语文、科技、体育5本书分别编码为A 、B 、C 、D 、E ,则任取两本的所有可能为“AB ”“AC ”“AD ”“AE ”“BC ”“BD ”“BE ”“CD ”“CE ”“DE ”,共10个基本事件(不考虑顺序),而其中有数学的基本事件有4个,故概率为410=25.14.从分别标有数字1,2,3,4的4个大小、形状完全相同的球中,有放回地随机抽取2个球,则抽到的2个球的标号之和不大于5的概率等于__________.答案:58基本事件共有4×4=16个,其中两标号之和不大于5的情况共有(1,1)、(1,2)、(1,3)、(1,4)、(2,1)、(2,2)、(2,3)、(3,1)、(3,2)、(4,1)10种,所以1016=58三、解答题(本大题共5小题,共54分.解答应写出必要的文字说明、证明过程或演算步骤)15.(本小题满分10分)在一个盒内放有10只手表,7只镀金表,2只镀银表,1只镀铜表,从中摸出一只,摸出镀铜表或镀银表的概率是多少?摸出镀金表或镀铜表的概率是多少?答案:解:记事件A ={摸出一只镀金表},B ={摸出一只镀银表},C ={摸出一只镀铜表},则A 、B 、C 两两互斥,且P(A)=710,P(B)=210,P(C)=110,“摸出镀银表或镀铜表”包含事件B ,C ,即为B ∪C ,“摸出一只镀金表或镀铜表”包含事件A ,C ,即为A ∪C ,由互斥事件的概率公式可得:P(B ∪C)=P(B)+P(C)=210+110=310,P(A ∪C)=P(A)+P(C)=710+110=45.所以摸出一只表为镀银表或镀铜表的概率为310,摸出一只表为镀金表或镀铜表的概率为45. 16.(本小题满分10分)如图所示,在半径为1的半圆内,放置一个边长为12的正方形ABCD ,向半圆内任投一点,求该点落在正方形内的概率.答案:解:记“该点落在正方形内”为事件A ,则A 所占区域的面积是μA =(12)2=14.整个基本事件的区域面积是μΩ=π2.由几何概型的概率公式,得P(A)=μA μΩ=14π2=12π,即该点落在正方形内的概率是12π.17.(本小题满分10分)一个袋子中有红、白、蓝三种颜色的球共24个,除颜色外完全相同,已知蓝色球3个.若从袋子中随机取出1个球,取到红色球的概率是16.(1)求红色球的个数;(2)若将这三种颜色的球分别进行编号,并将1号红色球,1号白色球,2号蓝色球和3号蓝色球这四个球装入另一个袋子中,甲乙两人先后从这个袋子中各取一个球(甲先取,取出的球不放回),求甲取出的球的编号比乙的大的概率.答案:解:(1)设红色球有x 个,依题意得x 24=16,解得x =4,∴红色球有4个.(2)记“甲取出的球的编号比乙的大”为事件A ,所有的基本事件有(红1,白1),(红1,蓝2),(红1,蓝3),(白1,红1),(白1,蓝2),(白1,蓝3),(蓝2,红1),(蓝2,白1),(蓝2,蓝3),(蓝3,红1),(蓝3,白1),(蓝3,蓝2),共12个.事件A 包含的基本事件有(蓝2,红1),(蓝2,白1),(蓝3,红1),(蓝3,白1),(蓝3,蓝2),共5个.所以,P(A)=512.18.(本小题满分12分)已知△ABC 的面积为S.(1)向△ABC 内任投一点P ,求△PBC 的面积大于S3的概率;(2)若在△ABC 的边AB 上任取一点P ,求△PBC 的面积大于S3的概率.答案:解:(1)过△ABC 的高的三等分且靠近垂足的分点作平行于BC 的平行线EF ,据题意知满足条件的点P 分布在△AEF 内,故事件A :“△PBC 的面积大于S3的概率”是两三角形的面积的比,即P(A)=S △AEF S △ABC =49.(2)过AB 边上的点P 作BC 边上的高AD 的平行线交BC 于点G ,使PG =13AD ,故事件B :“△PBC 的面积大于S 3”可用线段AP 的长度来度量,其中AP =23AB ,整个事件用AB的长度来度量,故事件B 的概率P(B)=AP AB =23.19.(本小题满分12分)(2009天津滨海五校高三毕业班联考,18)某商场举行抽奖活动,从装有编号0,1,2,3四个小球的抽奖箱中,每次取出后放回,连续取两次,取出的两个小球号码相加之和等于5中一等奖,等于4中二等奖,等于3中三等奖.(1)求中三等奖的概率;(2)求中奖的概率.答案:解:设“中三等奖”的事件为A ,“中奖”的事件为B ,“从四个小球中有放回地取两个”包括(0,0),(0,1),(0,2),(0,3),(1,0),(1,1),(1,2),(1,3),(2,0),(2,1),(2,2),(2,3),(3,0),(3,1),(3,2),(3,3),共16个基本事件.(1)“两个小球号码相加之和等于3”的基本事件有4个:(0,3)、(1,2)、(2,1)、(3,0).故P(A)=416=14.(2)“两个小球号码相加之和等于3”这一事件包括4个基本事件;“两个小球相加之和等于4”的取法有:(1,3),(2,2),(3,1),共3个基本事件;“两个小球号码相加之和等于5”的取法有:(2,3),(3,2),共2个基本事件.由互斥事件的加法公式得P(B)=416+316+216=916.。

人教版高中语文必修3第三单元试卷(附答案)

人教版高中语文必修3第三单元试卷(附答案)

人教版高中语文必修3第三单元试卷(附答案)人教版高中语文必修3第三单元试卷(附答案)【人教版高中语文必修3第三单元试卷(附答案)】一、积累运用(28分)1、下列加横线的字注音正确的一项是( )A、饿殍(piǎo) 逡巡(qūn) 弃甲曳兵(yè) 丢三落四(luò)B、中绳(zhòng)句读(dòu) 瓮牖绳枢(yǒu)心广体胖(pàng)C、庠序(yáng) 氓隶(méng) 度长薭大(duó) 抛头露面(lù)D、供养(gōng) 经传(zhuàn) 贻笑大方(yí)间不容发(jiān)2、下列各组词语中,有错别字的一项是( )A、殊俗叩关不测之渊兵刃既接B、迁徙须臾约从离衡防微杜渐C、崛起堕落追亡逐北要言不烦D、谪戍孝悌锲而不舍人才汇萃3、下列各句中“胜”字的含义与“予观夫巴陵胜状,在洞庭一湖”中“胜”字相同的一项是( )A、此所谓战胜于朝廷B、不违农时,谷不可胜食也C、日出江花江胜火D、引人入胜4、下列各句中加横线的词,解释有误的一项是( )D、《师说》选自《昌黎先生集》,作者韩愈,字退之,世称“ 韩昌黎”。

欧阳修称他“文起八代之衰”,明人列之为“唐宋八大家”之首。

8、课文填空(7分)(1)或百步而后止,或五十步而后止,________________________。

(2)故_______________,金就砺则利。

(3)一夫作难而七庙隳,身死人手,为天下笑者,何也?__________________________。

(4)是故_______________,师不必贤于弟子。

(5)_______________,_________________,天下云集响应,赢粮而景从。

(6)谨庠序之教,___________________,颁白者不负戴于道路矣。

二、阅读与鉴赏(一)阅读下面文言文,完成9—12题。

高中英语(新人教版)必修第三册课后习题:第三单元测评(课后习题)【含答案及解析】

高中英语(新人教版)必修第三册课后习题:第三单元测评(课后习题)【含答案及解析】

第三单元测评(时间:120分钟满分:150分)第一部分听力(共两节,满分30分)第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What did the woman buy for her son?A.A doll.B.A book.C.A kite.2.What are the speakers mainly talking about?A.Writings.B.Photographs.puter programs.3.How many cakes does the woman advise the man to buy?A.1.B.6.C.12.4.What’s the probable relationship between the speakers?A.Workmates.B.Classmates.C.Strangers.5.Where does the conversation probably take place?A.In a restaurant.B.In a meeting room.C.In a theatre.第二节(共15 小题;每小题1.5分,满分22.5分)听下面5段对话或独白。

每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项。

听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料,回答第6、7题。

6.What sports does the man like to play after work?A.Tennis,swimming and golf.B.Tennis,jogging and golf.C.Tennis,running and golf.7.How often does the man play golf?A.Once a week.B.Once a month.C.Twice a month.听第7段材料,回答第8至10题。

高中物理(新人教版)选择性必修三同步习题:第三章达标检测(同步习题)【含答案及解析】

高中物理(新人教版)选择性必修三同步习题:第三章达标检测(同步习题)【含答案及解析】

第三章热力学定律本章达标检测(满分:100分;时间:45分钟)一、选择题(本题共8个小题,每小题6分,共48分。

其中1~6小题只有一个选项正确,7~8小题有多个选项正确,全选对得6分,选对但不全得3分,选错或不选得0分)1.根据热力学定律,下列判断正确的是( )A.我们可以把火炉散失到周围环境中的能量全部收集到火炉中再次用来取暖B.冰可以熔化成水,水也可以结成冰,这个现象违背了热力学第二定律C.制冷系统能将冰箱内的热量传给外界较高温度的空气,而不引起其他变化D.利用其他手段,使低温物体温度更低,高温物体的温度更高2.(2020江苏南京中华中学高二下段考)下列说法正确的是( )A.电能不可能全部转变成内能B.热力学第二定律可表述为所有自发的热现象的宏观过程都具有方向性C.因为能量守恒,所以能源危机是不可能的D.摩擦力做功的过程,必定有机械能转化为内能3.(2020江苏徐州一中高二下月考)某同学用导热性能良好的汽缸和活塞将一定质量的空气(视为理想气体)封闭在汽缸内(活塞与汽缸壁间的摩擦不计),待活塞静止后,将小石子缓慢地加在活塞上,如图所示。

在此过程中,若大气压强与室内的温度均保持不变,下列说法正确的是( )A.由于汽缸导热,故缸内气体的压强保持不变B.缸内气体温度不变,缸内气体对活塞的压力保持不变C.外界对缸内气体做的功大小等于缸内气体向外界释放的热量D.外界对缸内气体做功,缸内气体内能增加4.(2020山东临沂平邑一中高二下测试)“温泉水滑洗凝脂,冬浴温泉正当时”,在寒冷的冬天里泡一泡温泉,不仅可以消除疲劳,还可扩张血管,促进血液循环,加速人体新陈代谢。

设水温恒定,则温泉中正在缓慢上升的气泡( )A.压强增大,体积减小,吸收热量B.压强增大,体积减小,放出热量C.压强减小,体积增大,吸收热量D.压强减小,体积增大,放出热量5.某学生利用自行车内胎、打气筒、温度传感器以及计算机等装置研究自行车内胎打气、打气结束、突然拔掉气门芯放气与放气后静置一段时间的整个过程中内能的变化情况,车胎内气体温度随时间变化的情况如图所示。

人教版必修三第三章测试题(含答案)

人教版必修三第三章测试题(含答案)

人教版必修三第三章测试题(含答案) 第三章测试题一、选择题(本大题共12小题,每小题3分,共36分。

在每小题给出的四个选项中,只有一项是符合题目要求的)1.从一批产品中取出三件产品,设A=“三件产品全不是次品”,B=“三件产品全是次品”,C=“三件产品不全是次品”,则下列结论不正确的是()。

A。

A与B互斥且为对立事件B。

B与C互斥且为对立事件C。

A与C存在有包含关系D。

A与C不是对立事件2.抛掷一枚质地均匀的硬币,如果连续抛掷1000次,那么第999次出现正面朝上的概率是()。

A。

1/1991B。

1/1000C。

1/2D。

1/10013.同时抛掷两枚质地均匀的硬币,则出现两个正面朝上的概率是()。

A。

1/4B。

1/8C。

1/2D。

3/44.甲、乙两人随意入住两间空房,则甲乙两人各住一间房的概率是()。

A。

1/3B。

11/42C。

1/2D。

2/35.口袋内装有一些大小相同的红球、白球和黑球,从中摸出1个球,摸出红球的概率是0.42,摸出白球的概率是0.28,那么摸出黑球的概率是()。

A。

0.42B。

0.28C。

0.3D。

0.76.已知地铁列车每10 XXX一班,在车站停1 XXX则乘客到达站台立即乘上车的概率是()。

A。

109/118B。

1/10C。

1/11D。

1/97.有五条线段长度分别为1,3,5,7,9,从这5条线段中任取3条,则所取3条线段能构成一个三角形的概率为()。

A。

1/10B。

3/10C。

17/50D。

102/1258.从五件正品,一件次品中随机取出两件,则取出的两件产品中恰好是一件正品,一件次品的概率是()。

A。

1B。

1/12C。

3/23D。

3/109.一个袋中装有2个红球和2个白球,现从袋中取出1球,然后放回袋中再取出一球,则取出的两个球同色的概率是()。

A。

1/12B。

1/6C。

1/3D。

5/1210.现有五个球分别记为A,C,J,K,S,随机放进三个盒子,每个盒子只能放一个球,则K或S在盒中的概率是()。

最新人教版高中数学必修3第三章数学三模块综合测评(附答案)

最新人教版高中数学必修3第三章数学三模块综合测评(附答案)

模块综合测评(时间:120分钟,总分:150分)一、选择题(本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的)1.下列赋值语句正确的是( )A.m+n=3B.l=mC.m=1,n=1D.m=m-1 解析:判断是否为赋值语句,主要看它是否满足赋值语句的特点.注意,赋值语句中的等号与数学中等号意义的区别. 答案:D2.抛掷一枚骰子,观察骰子出现的点数,若“出现2点”这个事件发生,则下列事件一定发生的是( )A.“出现奇数点”B.“出现偶数点”C.“点数大于3”D.“点数是3的倍数”解析:若事件A 发生,则事件B 发生,则事件A 和事件B 的关系是A B ,令事件A={出现2点},则事件B={出现偶数点}一定发生. 答案:B 3.高三(1)、(2)班在一次数学考试中,成绩平均分相同,但(1)班的成绩比(2)班整齐,若(1)、(2)班的成绩方差分别为s 12和s 22,则( )A.s 12>s 22B.s 12<s 22C.s 12=s 22D.s 1>s 2解析:方差的大小描述了数据的分散程度,因为(1)班成绩比(2)班成绩整齐,这说明(1)班的成绩分布比较集中,所以s 21<s 22. 答案:B4.某地招生办为了了解2007年高考文科数学主观题的阅卷质量,将2 050本试卷中封面保密号的尾数是11的全部抽出来,再次复查,这种抽样方法采用的是( )A.抽签法B.简单随机抽样C.系统抽样D.分层抽样 解析:由各抽样方法的使用条件可知,这种抽样为系统抽样. 答案:C5.若以连续抛掷两次骰子分别得到的点数m 、n 作为点P 的坐标,则点P 落在圆x 2+y 2=25内的概率是( ) A.21 B.3613 C.94 D.125 解析:设P 点坐标为(m,n),则P 点落在圆内,即满足m 2+n 2<25通过列举法可得满足条件的点(m,n)有(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(4,1),(4,2)共13个,而(m,n)所有可能的点有36种,所以P 点落在圆内的概率为3613,本题也可从对立事件角度去考虑. 答案:B6.①学校为了解高一学情,从每班抽2人进行座谈;②一次数学竞赛中,某班有10人在110分以上,40人在90—110分,12人低于90分,现从中抽取12人了解有关情况;③运动会服务人员为参加400 m 决赛的6名同学安排跑道.就这三件事,合适的抽样方法为( ) A.分层抽样、分层抽样、简单随机抽样 B.系统抽样、系统抽样、简单随机抽样 C.分层抽样、简单随机抽样、简单随机抽样 D.系统抽样、分层抽样、简单随机抽样 解析:明确各种抽样方法的适用范围,进而选择合适的抽样方法. 答案:D7.在如下图所示的Rt △ABC 中,∠A=30°,过直角顶点C 在∠ACB 内任作一条射线交线段AB 于M ,则使AM >AC 的概率是( )A.61 B.65 C.232- D.21 解析:它属于几何概型,令事件A={过直角顶点C 在∠ACB 内任作一条射线交线段AB 于M ,使AM >AC },事件A 发生的区域为∠BCM=15°(如图),构成事件总的区域为∠ACB=90°,由几何概型的概率公式得P(A)=61. 答案:A8.已知框图,则表示的算法是( )A.求和S=2+22+…+264B.求和S=1+2+22+…+263C.求和S=1+2+22+…+264D.以上均不对解析:关键是要读懂框图的含义.循环结构中是完成数据的累加,要实现所求算法,框图中第一次执行循环体时i 的值应为0,框图中最后一次执行循环体时i 的值应为64,结合条件不满足时执行循环体,当i >64时就会终止循环. 答案:C9.一人在打靶中,连续射击2次,事件“至少有一次中靶”的互斥事件是( ) A.至少有一次中靶 B.两次中靶 C.两次都不中靶 D.只有一次中靶 解析:若A 、B 为互斥事件则A∩B=∅. 答案:C10.现有语文、数学、英语、历史、政治和物理共六本书,从中任取一本,取出的是文科书的概率是( ) A.21 B.65 C.61 D.32 解析:取到的书是文科书,即取到的书为语文、英语、历史、政治书,根据互斥事件的概率公式可求得P=3261616161=+++.答案:D11.甲口袋内装有大小相等的8个红球和4个白球,乙口袋内装有大小相等的9个红球和3个白球,从两个口袋内各摸出1个球,那么125等于( ) A.2个球都是白球的概率 B.2个球中恰好有1个是白球的概率 C.2个球都不是白球的概率 D.2个球都不是红球的概率 解析:依次求出A 、B 、C 、D 四项中所求事件的概率,四个选项的概率依次是A :121121234=⨯⨯;B :12512129438=⨯⨯+⨯;C :21121298=⨯⨯;D :21121234=⨯⨯答案:B12.用辗转相除法求204与85的最大公约数时,需要做除法的次数是( )A.1次B.2次C.3次D.4次 解析:用辗转相除法可得:204÷85=2…34,85÷34=2…17,34÷17=2,到此时可以判断它们的最大公约数是17,使用了3次除法得出结果. 答案:C二、填空题(本大题共4小题,每小题4分,共16分.把正确答案填在题中的横线上)13.设集合P={x,1},Q={y,1,2},P ⊆Q,x,y ∈{1,2,3,…,9},且在直角坐标平面内,从所有满足这些条件的有序实数对(x,y )所表示的点中任取一个,其落在圆x 2+y 2=r 2内的概率恰为72,则r 2的一个可能的整数值是____________.(只需写出一个即可) 解析:由于P ⊆Q,所以x=2或x=y.当x=2时,点(x,y )有(2,3)、(2,4)、(2,5)、(2,6)、(2,7)、(2,8)、(2,9)共7个;当x=y 时,点(x,y )有(3,3)、(4,4)、(5,5)、(6,6)、(7,7)、(8,8)、(9,9)共7个;所以满足条件的点(x,y )总共有7+7=14个.由于落在圆x 2+y 2=r 2内的概率恰为72,则共有72×14=4点落在圆x 2+y 2=r 2内. 将满足条件的14个点(x,y )按横纵坐标的平方和从小到大的顺序排列:(2,3)、(3,3)、(2,4)、(2,5)、(4,4)、(2,6)、(5,5)、(2,7)、(2,8)、(6,6)、(2,9)、(7,7)、(8,8)、(9,9).则第4个点是A (2,5),第5个点是B (4,4),显然r 2只需满足|OA|2<r 2<|OB|,即22+52<r 2<42+42,所以有29<r 2<32,则r 2的一个可能的整数值是30或31,故填30(或31也行). 答案:30(或31).14.x=input(“请输入一个正的两位数x=”); if 9<x and x <100 then a=x/10;b=x mod 10; x=10*b+a ; print x elsedisp(“输入有误!”) end以上程序运行的含义是______________.解析:读懂程序的流程和程序的意图(或程序目的),可以代入数据试运行,这样一般可以得到准确的答案.答案:将一个数的十位数与个位对换 15.一个样本方差是S 2=151[(x 1-12)2+(x 2-12)2+…+(x 15-12)2],则这个样本的平均数是___________,样本容量是___________. 解析:在样本方差的公式S 2=n1[(x 1-x )2+(x 2-x )2+…+(x n -x )2]中我们可以知道样本的容量为n 及样本的平均数为x ,因此同学们应记清公式中各个量的含义.答案:12 1516.将一批数据分成4组,列出频率分布表,其中第1组的频率是0.27,第2组与第4组的频率之和为0.54,则第3组的频率是______________.解析:在直方图中频率之和为1,所以第3组的频率为1-0.27-0.54=0.19. 答案:0.19三、解答题(本大题共6小题,共74分.解答应写出必要的文字说明、证明过程或演算步骤) 17.(12分)根据下面程序,画出程序框图,并说出表示了什么样的算法. a=input(“a=”); b=input(“b=”); c=input(“c=”); if a >b and a >c then print(% io (2),a ); elseif b >c thenprint (% io (2),b ); elseprint (% io (2),c ); end end end分析:我们根据程序按顺序从上到下分析. 第一步:是输入a ,b ,c 三个数;第二步:是判断a 与b ,a 与c 的大小,如果a 同时大于b ,c ,则输出a ,否则执行第三步; 第三步:判断b 与c 的大小,因为a 已小于b 与c ,则只需比较b 与c 的大小就能看出a ,b ,c 中谁是最大的了,如果b >c ,则输出b ,否则输出c.通过上面的分析,程序表示一个什么样的算法已经非常清楚了. 解:框图如图所示:以上程序表示了输出a ,b ,c 中三个数的最大数的一个算法.18.(12分)在一个边长为a ,b(a >b >0)的矩形内画一个梯形,梯形上、下底分别为a 31与a 21,高为b ,向该矩形内随机投一点,求所投的点落在梯形内部的概率. 分析:投中矩形内每一点都是一个基本事件,基本事件有无限多个,并且每个基本事件发生的可能性相等,所以投中某一部分的概率只与这部分的几何度量(面积)有关,符合几何概型的条件.解:记A={所投的点落在梯形内部},S 矩形=ab ,S 梯形=125)2131(21=+b a a ab ,P(A)=125125=ab ab, 即所投的点落在梯形内部的概率是125.19.(12分)一个小球从100 m 高处自由落下,每次着地后又跳回到原高度一半再落下,编写程序,求当它第10次着地时, (1)向下运动共经过多少米? (2)第10次着地后反弹多高? (3)全程共经过多少米?分析:搞清楚小球的运动的特点,通过循环来设计程序. 解:程序: i=100; sum=0; k=1;while k <=10 sum=sum+i i=i/2 k=k+1 endprint(% io (2),sum) print(% io (2),i)print(“全程共经过(单位:(m))”;2*sum -100) end20.(12分)某地区100位居民的人均月用水量(单位:t)的分组的频数如下:[0,0.5),4;[0.5,1),8;[1,1.5),15;[1.5,2),22;[2,2.5),25;[2.5,3),14;[3,3.5),6;[3.5,4),4;[4,4.5),2.(1)列出样本的频率分布表.(2)画出频率分布直方图,并根据直方图估计这组数据的众数.(3)当地政府制订了人均月用水量为3t的标准,若超出标准加倍收费,当地政府解释说,85%以上的居民不超出这个标准,这个解释对吗?为什么?分析:众数即直方图中所有矩形中最高矩形的中点的横坐标.解:(1)(2)众数约为2.25.(3)对,上面的图和表显示了样本数据落在各个小组的比例大小.从中我们可以看到,月用水量在区间[2,2.5]内的居民最多,在[1.5,2]的次之,大部分居民的月用水量都在[1,3]之间,其中月用水量在3t以上的居民所占的比例为6%+4%+2%=12%,即大约占12%的居民月用水量在3t以上,88%的居民月用水量在3t以下.因此居民月用水量标准定为3t是一个可以考虑的标准.即不超出这个标准的概率约为88%,在85%以上.21.(13分)A、B两个箱子中分别装有标号为0、1、2的三种卡片,每种卡片的张数如下表所示:(1)从A、B箱中各取1张卡片,用x表示取出的2张卡片的数字之积,求x=2的概率.(2)从A、B箱中各取1张卡片,用y表示取出的2张卡片的数字之和,求x=0且y=2的概率.分析:本题属于古典概型,关键是列举出基本事件的个数. 解:(1)记事件A={从A 、B 箱中各取1张卡片,两卡片的数字之积等于2},由上图知总基本事件个数为6×5=30(个),事件A 包含基本事件个数为5个. 由古典概型的概率公式得:P(A)=61305=. 即x=2的概率为61. (2)记事件B={从A 、B 箱中各取1张卡片,其数字和为2且积为0},由图知事件B 包含基本事件个数为10个.所以由古典概型的概率公式得P(B)=313010=. 即x=0且y=2的概率为31. 22.(13分)(2007广东高考,理17)下表提供了某厂节能降耗技术改造后生产甲产品过程中(2)请根据上表提供的数据,用最小二乘法求出y 关于x 的线性回归方程=bx+a.(3)已知该厂技改前100吨甲产品的生产能耗为90吨标准煤.试根据(2)求出的线性回归方程预测生产100吨甲产品的生产能耗比技改前降低多少吨标准煤? (参考数值:3×2.5+4×3+5×4+6×4.5=66.5)分析:根据表中的数据在直角坐标系中把所给的数据点(x,y )描出,然后根据最小二乘法思想求出b 与a 的,代入回归直线方程,把所得到的回归直线方程用来估计总体. 解:(1)如下图.(2)∑=ni ii yx 1=3×2.5+4×3+5×4+6×4.5=66.5,46543+++=x =4.5,45.4435.2+++=y =3.5,∑=ni ix12=32+42+52+62=86,b=8186635.665.44865.35.445.662--=⨯-⨯⨯-=0.7,a=y -b x =3.5-0.7×4.5=0.35. 故线性回归方程为yˆ=0.7x+0.35. (3)根据回归方程的预测,现在生产100吨产品消耗的标准煤的数量为0.7×100+0.35=70.35,故耗能减少了90-70.35=19.65(吨标准煤).。

人教版语文必修三第三单元综合测试题(带解析)

人教版语文必修三第三单元综合测试题(带解析)

人教版语文必修三第三单元综合测试题(带解析)语文必修三第三单元综合测试题是人教版第四单元的重点内容,也是考试常出现的内容,语文必修三第三单元综合测试题拿来练练手,一起来看看吧!二、阅读鉴赏(40分)(一)阅读下面的文字,完成6~8题。

(15分)柯瓦连科在他后面一把抓住他的衣领,使劲一推,别里科夫就连同他的雨鞋一齐乒乒乓乓地滚下楼去。

楼梯又高又陡,不过他滚到楼下却安稳无恙,站起来,摸了摸鼻子,看了看他的眼镜碎了没有。

可是,他滚下楼的时候,偏巧华连卡回来了,带着两位女士。

她们站在楼下,怔住了。

这在别里科夫却比任何事情都可怕。

我信任他情愿摔断脖子和两条腿,也不愿意成为别人取笑的对象。

是啊,这样一来,全城的人都会知道这件事,还会传到校长耳朵里去,还会传到督学耳朵里去。

哎呀,不定会闹出什么乱子!说不定又会有一张漫画,到头来弄得他奉命退休吧。

……等到他站起来,华连卡才认出是他。

她瞧着他那滑稽的脸相,他那揉皱的大衣,他那雨鞋,不明白是怎么回事,以为他是一不小心摔下来的,就忍不住纵声大笑,笑声在整个房子里响着:“哈哈哈!”这响亮而清脆的“哈哈哈”就此结束了一切事情:结束了预想中的婚事,结束了别里科夫的人间生活。

他没听见华连卡说什么话,他什么也没有看见。

一到家,他第一件事就是从桌子上撤去华连卡的照片;然后他上了床,从此再也没起过床。

过了一个月,别里科夫死了。

我们都去送葬。

我们要老实说:埋葬别里科夫那样的人,是一件大快人心的事。

我们从墓园回去的时候,露出忧郁和谦虚的脸相;谁也不肯露出快活的感情。

——像那样的感情,我们很久很久以前做小孩子的时候,遇到大人不在家,我们到花园里去跑一两个钟头,享受完全自由的时候,才经历过。

我们高兴奋兴地从墓园回家。

可是一个礼拜还没有过完,生活又恢复旧样子,跟先前一样郁闷、无聊、乱糟糟了。

局面并没有好一点。

实在,虽然我们埋葬了别里科夫,可是这种装在套子里的人,却还有许多,将来也还不知道有多少呢!6.“埋葬别里科夫那样的人,是一件大快人心的事”,但为什么“我们从墓园回去的时候”却“谁也不肯露出快活的感情”?(4分) 这正表明了环境的恶劣、人们的恐惧,不敢流露真情实感,正是专制统治的结果。

人教版高二英语必修三Unit 3 单元测试卷(含答案)

人教版高二英语必修三Unit 3 单元测试卷(含答案)

人教版高二英语必修三Unit 3 单元测试卷(含答案)(考试时间:100分钟分值:100分)班级:_________ 姓名:__________ 得分:__________一、单词拼写(共10小题;每小题0.5分,满分5分)1.I don’t know how you __________ (忍受) that noise!2.__________ (核能的) plants are expensive to build, though cheap to operate.3.She burst into tears, __________ (释放) all her pent-up emotions.4.The house should be __________ (适合居住的) by the new year.5.It was a live __________ (广播节目), not a recording.6.The wrestlers try to __________ (抓住) hold of each other.7.On the floor of the __________ (盆地) lie deserts, lakes and swamps.8.He was an effective supporter of __________ (改革).9.How do you measure the __________ (体积) of the gas?10.Such kindness __________ (恢复) your faith in human nature.二、单句语法填空(共10小题;每小题0.5分,满分5分)1. To our shock, many children in underdeveloped regions die of __________ (starve).2. We should take an active part in sports and outdoor activities _________ (frequent).3. We risk upsetting the __________ (ecology) balance of the area.4. But is throwing things away a ____________ (sustain) approach?5. They were __________ (comprehensive) beaten in the final.6. I enjoyed being able to go out and buy __________ (trend) clothes.7. The government has agreed to lift __________ (restrict) on press freedom.8. When is the final date for the __________ (submit) of proposals?9. The exhibition is held __________ (annual).10. He seems completely __________ (sensitive) to criticism. I think he doesn’t know what shame is.三、完成句子(共5小题;每小题1分,满分5分)1. 二氧化碳太多是导致温室效应的最主要原因。

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第三章测试题
一、选择题(本大题共12小题,每小题3分,共36分.在每小题给出的四个选项中,只有一项是符合题目要求的)
1. 从一批产品中取出三件产品,设A =“三件产品全不是次品”,B =“三件产品全是次品”,C =“三件产品不全是次品”,则下列结论不正确...
的是( ). A . A 与B 互斥且为对立事件 B . B 与C 互斥且为对立事件
C . A 与C 存在有包含关系
D . A 与C 不是对立事件
2. 抛掷一枚质地均匀的硬币,如果连续抛掷1000次,那么第999次出现正面朝上的概率是( ).
A .
B .
C .
D . 3.同时抛掷两枚质地均匀的硬币,则出现两个正面朝上的概率是( ).
A .
B .
C .
D . 4.甲、乙两人随意入住两间空房,则甲乙两人各住一间房的概率是( ).
A .
B .
C .
D .无法确定 5. 口袋内装有一些大小相同的红球、白球和黑球,从中摸出个球,摸出红球的概率是,摸出白球的概率是,那么摸出黒球的概率是( ).
A .
B .
C .
D .
6. 已知地铁列车每10 min 一班,在车站停1 min .则乘客到达站台立即乘上车的概率是( ).
A .
B .
C .
D . 7. 有五条线段长度分别为1,3,5,7,9,从这5条线段中任取3条,则所取3条线段能构成一个三角形的概率为( ).
A .
B .
C .
D . 8. 从五件正品,一件次品中随机取出两件,则取出的两件产品中恰好是一件正品,一件次品的概率是( ).
A . 1
B .
C .
D . 9991100011000999212141318131412110.420.280.420.280.30.71019111181212131103
10732101
2 9.一个袋中装有2个红球和2个白球,现从袋中取出1球,然后放回袋中再取出一球,则取出的两个球同色的概率是( ).
A .
B .
C .
D . 10.现有五个球分别记为A ,C ,J ,K ,S ,随机放进三个盒子,每个盒子只能放一个球,则K 或S 在盒中的概率是( ).
A .
B .
C .
D . 二、填空题(本大题共4小题,每小题4分,共16分.把答案填在题中横线上).
11.某小组有三名女生,两名男生,现从这个小组中任意选出一名组长,则其中一名女生小丽当选为组长的概率是___________.
12.掷两枚骰子,出现点数之和为3的概率是______________________________.
13.某班委会由4名男生与3名女生组成,现从中选出2人担任正副班长,其中至少有1名女生当选的概率是_____________.
14.我国西部一个地区的年降水量在下列区间内的概率如下表所示:
则年降水量在 [ 200,300 ]范围内的概率是___________.
15.如右图,在一个边长为a 、b (a >b >0)的矩形内画一个梯形,梯形上、下底
分别为a 与a ,高为b ,向该矩形内随机投一点,则所投的点落在梯形内部的概率为________.
三、解答题(本大题共5小题,共48分.解答时应
写出必要的文字说明、证明过程或演算步骤)
16.(8分)(1) 如图,在边长为25cm 的正方形中
挖去边长为23cm 的两个等腰直角三角形,现有均匀的粒子散落在
正方形中,问粒子落在中间带形区域的概率是多少?
(2) 10本不同的语文书,2本不同的数学书,从中任意取出2本,能取出数学书的概率有多大?
2131415
21015310310
93
121年降水量/mm
[ 100, 150 ) [ 150, 200 ) [ 200, 250 ) [ 250, 300 ] 概率 0.21 0.16 0.13 0.12
3
(3)一年按365天计算,两名学生的生日相同的概率是多少?
(4) 抽签口试,共有10张不同的考签.每个考生抽1张考签,抽过的考签不再放回.考生王某会答其中3张,他是第5个抽签者,求王某抽到会答考签的概率.
17. (10分)甲盒中有红,黑,白三种颜色的球各3个,乙盒子中有黄,黑,白三种颜色的球各2个,从两个盒子中各取1个球;(1)求取出的两个球是不同颜色的概率.
(2)请设计一种随机模拟的方法,来近似计算(1)中取出两个球是不同颜色的概率(写出模拟的步骤).
18.(10分)同时投掷两个骰子,计算下列事件的概率:
(1)事件A :两个骰子点数相同;
(2)事件B :两个骰子点数之和为8;
(3)事件C :两个骰子点数之和为奇数.
19.(10分) 由经验得知,在某商场付款处排队等候付款的人数及概率如下表:
(1)至多有2人排队的概率是多少?
(2)至少有2人排队的概率是多少?
20.(10分)袋中有除颜色外完全相同的红、黄、白三种颜色的球各一个,从中每次任取1个,有放回地抽取3次.求:
(1)3个全是红球的概率;
(2)3个颜色全相同的概率;
(3)3个颜色不全相同的概率;
(4)3个颜色全不相同的概率.
参考答案
16.(1)解:因为均匀的粒子落在正方形内任何一点是等可能的,所以符合几何概型的条件
设A =“粒子落在中间带形区域”,则依题意得正方形面积为:25×25
=625;两个等腰直角三角形的面积为:2××23×23=529,带形区域的面积为:625-529=96.所以 P (A )=.
2
162596
4
(2)解:基本事件的总数为:12×11÷2=66;“能取出数学书”这个事件所包含的基本事件个数分两种情况:①“恰好取出1本数学书”所包含的基本事件个数为:10×2=20.②“取出2本都是数学书”所包含的基本事件个数为:1;所以“能取出数学书”这个事件所包含的基本事件个数为:20+1=21;因此, P (“能取出数学书”)=.
(3); (4)(等可能事件,与抽签顺序无关). 17.解:(1)设A =“取出的两球是相同颜色”,B =“取出的两球是不同颜色” 则事件A 的概率为: P (A )==; 由于事件A 与事件B 是对立事件,所以事件B 的概率为: P (B )=1-P (A )=1-
=. (2)随机模拟的步骤:第1步:利用抓阄法或计算机(计算器)产生1~3和2~4两组取整数值的随机数,每组各有N 个随机数.用“1”表示取到红球,用“2”表示取到黑球,用“3”表示取到白球,用“4”表示取到黄球;第2步:统计两组对应的N 对随机数中,每对中的两个数字不同的对数n ;第3步:计算n N 的值.则n N
就是取出的两个球是不同颜色的概率的近似值.
18.解:(1)将两个骰子标上记号A 、B ,将A 、B 骰子的点数依次记为(x ,y ),则共有6×6=36种等可能的结果.出现点数相同的结果有(1,1)(2,2)(3,3)(4,
4)(5,5)(6,6)共6种.所以 . (2)出现点数之和为8的结果有(2,6)(3,5)(4,4)(5,3)(6,2)共5种,故.(3)出现点数之和为奇数包括“x 是奇数、y 是偶数”和“x 是偶数、y 是奇数”,共有3×3+3×3=18种;故. 19. 解:(1)0.56; (2)0.74.
20. 解:(1)
; (2); (3); (4). 22736511036
92323⨯⨯⨯+9292976
1366)(==A P 36
5)(=B P 213618)(==
C P 27191989
2。

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