锚固法兰强度计算书
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SR=(1.33*t*e+1)*M0/(L*t^2*B)=
0.13 MPa
40 Tangential flange stress
ST=Y*M0/(t^2*B)-Z*SR=
0.51 MPa
41
CALCULATION ANCHOR FLANGE
(IN ACCORDANCE WITH ASME BPVC SEC. VIII DIV.1 APP.2)
21 Ratio
g1/g0=
2.5
22 Factor
h0=(B*g0)^0.5
145.44 mm
23 Ratio
h/h0=
0.76
24 Hub stress correction factor (as per Fig.2-7.6)
f=
1
25 Factor for integral type flanges (as per Fig.2-7.2)
1450 Lbs
8 Corrosion allowance
0 mm
9 Type of flange
10
Allowable design stress for material of flange at max. design temperature (operating condition)
Sf=
11
F=
0.76
26 Factor
e=(F/h0, for integral type flange)=
0.0052
27 Ratio of outside flange diameter to inside flange diameter
K=A/B=
1.37
28 Factor involving K (as per Fig.2-7.1)
3462656
32 Factor
L=(t*e+1)/T+t^3/d=
2.42
33 Factor involving K (as per Fig.2-7.1)
Y=
6.6
34 Factor involving K (as per Fig.2-7.1)
Z=
3.5
35 Design load (operating condition)
42 inch
3 Inside diameter of pipe
40.376 inch
4 Material grade of pipe
API 5L X70
5 Design temperature
Td=
ห้องสมุดไป่ตู้-5 ~ 204 ℃
6 Material grade of flange
A694 F70
7 Maximum axial load
Integral type 188.00 MPa
12 PART II - FLANGE DIMENSIONS SUPPOSED
13 Thickness of hub at small end
g0=
20.6248 mm
14 Thickness of hub at large end
g1=
50.7248 mm
T=
1.8
29 Factor involving K (as per Fig.2-7.1)
U=
7.5
30 Factor for integral type flanges (as per Fig.2-7.3)
V=
0.134
31 Factor
d=(U/V)*h0*g0^2, for integral flange)=
CALCULATION ANCHOR FLANGE
(IN ACCORDANCE WITH ASME BPVC SEC. VIII DIV.1 APP.2)
RFQ NO.:
SHEET NO.:
1 PART I - DESIGN CONDITIONS
2 Outside diameter of pipe
D=
47 Anchor flange design
YES YES YES YES PASSED
15 Outside diameter of flange
A=
1405.00 mm
16 Inside diameter of flange
B=
1025.55 mm
17 Flange thickness
t=
168.3 mm
18 Hub length
h=
110.7 mm
19
20 PART III - CALCULATION OUTPUT
W=
1500 Lbs
36 Load circle diameter
C=
1282.7 mm
37 Total flange moment
M0=
4279 N*m
38 Longitudinal hub stress
SH=f*M0/(L*g1^2*B)=
0.67 MPa
39 Radial flange stress
RFQ NO.:
SHEET NO.:
42 PART IV - CALCULATION RESULT
43 Condition 1
SH≤1.5*Sf?
44 Condition 2
SR≤Sf?
45 Condition 3
ST≤Sf?
46 Condition 4
(SH+SR)/2≤Sf &(SH+ST)/2≤Sf)?