单相交流电抗器设计单

Fu Δτ=(0.55*(((Ws+0.05246)/(5.13*10^-12))^0.25-318)+0.45*(Ws/(2.7*10^-4))^0.8333)/2
Total gap 21.5413648 mm
H~Intensity 0.1325 A/cm Permeabilityμ 90566.03774
Calculation
Results
Coefficient
Remark
1 Power Pva = Ux × I
27.632 ×
1100
30395.2 VA REF 2.87 353.702 Power
Winding Current I
1100
A
Set height 8 8
8 8 mm
Turns
N
12
TURNS Toltal Air-duct * 8
3 2 EA
Current density j
1.6 j = 0.75 × Pm / Z × Gm
A/mm2
Conductor sectio q Connection C
Wire length Ln
7084.1472
Single coil mm
DC Resistance DCR
0.375674473
Single coil mΩ
Conductor weight Gm
20.80614033
Single coil KG
Insulating paper P L
8855.184
Design：Renquan.xiao
Check：
Date：2014/1/2
Single-phase AC power reactor
Specification
0.8mH/1100A
Revision
A
Page PAGE 2 OF 3
Ciol Calculate
Power
S
Turns/Voltage T/V
a2 = ( L - P ) ÷ Kl （
*
÷ 6.00
* - 0 ） ÷ 5.00
* mm kh 6.00 4.0~ 7.0 * mm Kl 5.00 3.0~5.0
Heiht Length
a = ( a1 ＋ a2 ) ÷ 2 （ * ＋ * ） ÷ 2
* mm K2 1.00 0.8~1.5
Width
W
240
mm
Paper weight W'T
0.347743
Single coil KG
146.08
Inductance&gap check
Step Item
Formula
Process
Result
Evolution MFL width
1
Line
x%=Lg/Lc*100%
0.20175 /
89.12
0 HZ 0 Arms
Loss W 37.34480421 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
37.3448
100% 75% 50% 30% 20% 10% 5%
CEC
294.9738 404.7910048 186.1312473 71.48862553 34.26237607 10.43283423 3.541828663 CEC&EURO
core 4 10.8
gap 115
尺寸比
X = 0.94 Y = 1.44 Z = 3.06
2.81%
Item ①
②
Unit
Remark
Width 80
80
mm
Length
Length 235.0 46.8 mm paramagnetic
Stack 223.1 1115.5 mm
Core type
30395.2
VA
0.420635786
Bm 1.2 T
t/v
T/V=10000 / (4.44 * f * B0 * Sc )
Air-duct space calculation
Item
F/B Actual L/R Actual Unit
Winding voltage U
27.632
V Available space * 68 28.9 20 mm
Core loss(Fundamental & harmonic)
Load
LossW Effη
Frequency 0
Current 0
Frequency
HZ
50
3200
0
0
0
Loss&
Biblioteka Baidu
0
Efficiency
0
0
0
0
0
00
00 Current
Ar 1100
0 0 0 0 0 0 0 0 0 0
Core loss
0.23%
2 nlx-Gap nlx=1.78*I*W/Bc*10^-4 23496 / 1.2 * 10^-4 1.958 cm
3 H-Discus H = 1/2nlx / δ
9.79 / 2.50
5 EA
hm
4 Diffraction ε=δ/π*ln((H+δ)/δ) 2.50 / 3.14 * LN ( 16.7 ) 2.241 mm
EURO
99.03% 98.22% 98.78% 99.22% 99.44% 99.66% 99.77%
Coil Loss
Coil loss
257.6289926 W
Restance Rdc
0.000212917 Ω
Kw
1.001779785
Winding Ie
1100
A
Eddy coefficient
hm= 245.0 － 20 ＝ 225 hm = c - k ( k = 25 ~ 80 )
b Left mm
b Right
Manual adjustment
Bobbin
0 0 0
0
Core 10 1 10 1 10 1
10 1
Winding
24 3
24 3
0
0
0
0
Winding layout D
V
Load loss Pz 400 340
W
Temperature Δτ 100 47
K
Dimensions
Item
Spec Design Actual
Unit
Length L
*
301
mm
Depth D
*
239.08
mm
Height H
*
485
mm
Cost
Material Price Weight Wire 57.7 41.6 Core 21.2 64.1
4 Stack b = Sc ÷ a
92 ÷ 80 × 100
115 mm P 0 10~200 Clamps
h1 = a × z 5 Windows H
h2 = H - BASE - el
80.0 × 3.063 * - 80 - 80.0 × 2
245 mm z 3.06 2 ~ 4 Z coefficient * mm BASE 80 20 ~ 200 Base height
Ls=0.4*π*ρs*N^2*Ss/(2*hm)*10^-5
8 Inductance L=0.4*π*N^2*Sc/(lg+lc/μ) 1.257 * 14138 / 2.155
9 Total L
L=L"+Ls
0.08246 ＋ 0.003189716
10 Check gap
lg"=L/ Le* lg
P P.wide may turn 12 × 1 = 12
1 220 1 T 0 × 0 = 0
/
TURNS
S Stack Layers L 0 × 0 = 0
2 1.5 12
12 Layer Total 12
47.04
Winding insulation I
Materials Nomex － 0.18
Leakage areaSs
95.7 cm
Design：Renquan.xiao
Check：
Date：2014/1/2
Single-phase AC power reactor
Specification
0.8mH/1100A
Revision
A
Page PAGE 3 OF 3
Performance calculations
Conductor Material M
Winding width hm
343.75
Single coil mm2
PARALLEL
Copper foil
A/mm2 Item
Side a 0.75 Sectio No.
Side b 220 165
2
Total J
a Front
330 1.667 A/mm2 a Back
0.08565 / 0.8000 * 2.15
0.00319 0.08246 0.08565
mH δ0
Dm UNIT
mH mH
1.273
4.782
ρs=1-2*(Dm+δo)/(π*hm
cm Rockwellρs
0.82866203
0.23063 cm
Ss=1/3*Dm*lm+ (a+δ0)*(b+δ0)
00
0
00 0
Flux
B(G)
12000.00
0.00
0.00
0.00
0.00
0.00
0.00
0.00
0.00
0.00
0.00
0
0
00
Unit/loss
W/kg
0.5829
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.5829
6 Windows W c = a × x
80.0 × 0.9375
75 mm x 0.94 0.6 ~ 1.28 X coefficient
7
Gap Lg'=0.4*π*N^2*Sc*10^-8 / L 1.26 × 144 × 89.24 ÷ 0 0.20175 cm Kg 1 0.8~1.2 Core gap
Insulator 130 0.695
Total weight 117.0 kg
Tltal cost 5005 RMB
Results OK
Core calculation
46.8 75
UNIT:mm Core calculation
Step Item
235 Formula
Additional loss GAP1 48.1 W GAP2 44.6 W 5 GAP
Weight 32.0862 31.981 kg
23ZH90
Core operating parameters
Section 89.24 cm Magnetic path L 89.12 cm δSingle gap 2.50 mm
Flux 1.20 T Unit loss 0.6 W Saturation flux 1.543 T
405 245 80
Single-phase AC power reactor
Specification
0.8mH/1100A
Revision
A
Page PAGE 1 OF 3
Technical requirementsn
Frequency fz 50 HZ Inductance Lm 0.8 mH Rated Irms 1100 A Saturation Ipm 1556 A
Frequency
50 HZ Switch frequency 3200 HZ
Remark
Current
1100
Turns
12
B= 1.78*I*W/Lg;
A Switch frequency 0
A
TS Effective Gap 2.15 cm W=0.677*10^-3*f^1.656*B*^1.857 Pg=Ki*E*lg*f*B^2(E為EI鐵心尺寸）Ki=0.155
22.5
5 Gap section Se=Sc+2ε(a+b+2ε) 89.2 + 4.4813 * 199.4813 98.1793 cm^2
6 lg'Gap lg"=1.78*I*W*Se/(Bc*Sc) 1.78 * 1295967.234 / 107.088 2.15 cm
7 Leakage
Turns 15
TURNS
239.08
135
Winding thickness δn
23.04
mm
100
Around the mold
A B
A Side B Side
20 + 80 = 100 20 + 115 = 135
mm 23.04
Average turn length Lm
590.3456
Single coil mm
Saturation Lpm ≧ 0.792 mH
Switch frequency
3200
HZ
Switch current Ifrms
0
A
Test condition
AC
V
Characteristics of contrast
Performance Spec Design Actual Unit
Voltage Ux 27.632 29.5977
2 Core section Sc = Kb × Pva ÷ 2
0.746 × 15197.6
92.00 cm2 Kb 0.75 1~ 1.5
Section
a' = sc ÷ y
92.00 ÷ 1.44 × 10
80 mm y 1.44 1 ~ 2
stack
a1 =
H ÷ Kh
3 Core wide