必修一第二单元检测
必修一第二单元
必修一第二单元文言文基础知识及能力检测班级：姓名：得分：一、解释下列句子中的画线词（每小题1分，共20分）1、且贰于楚也（）2、焉用亡郑以陪邻？（）3、夜缒而出，见秦伯（）4、越国以鄙远（）5、夫晋，何厌之有？（）6、微夫人之力不及此（）7、失其所与，不知（）8、尽收其地（）9、今行而无信（）10、臣左手把其袖（）11、太子闻之，驰往（）12、荆轲遂就车而去（）13、比诸侯之列（）14、厚遗秦王宠臣中庶子蒙嘉（）15、君安与项伯有故？（）16、哙遂入，披帷西向立（）17、坐须臾，沛公起如厕（）18、会其怒，不敢献（）19、至陛下，秦武阳色变振恐（）20、秦王复击轲，被八创（）二、找出下列句中的通假字，并写出本字（每小题1分，共10分）1、距关，毋内诸侯（）2、旦日不可不蚤自来谢项王（）3、愿伯具言臣之不敢倍德也（）4、卒起不意，尽失其度（）5、燕王诚振怖大王之威（）6、令将军与臣有郤（）7、荆轲逐秦王，秦王还柱而走（）8、而燕国见陵之耻除矣（）9、秦伯说，与郑人盟（）10、今老矣，无能为也已（）三、解释下列多义字（每小题1分，共40分）1、去①欲呼张良与俱去（）②沛公军霸上，相去四十里（）2、故①故遣将守关者（）②君安与项伯有故（）3、收①尽收其地（）②乃遂收盛樊於期之首（）4、幸①妇女无所幸（）②幸来告良（）5、谢①旦日不可不蚤自来谢项王（）②乃令张良留谢（）6、辞①臣死且不避，卮酒安足辞（）②今者出，未辞也，为之奈何（）7、兵①进兵北略地（）②不得持尺兵（）③不得召下兵（）8、请①乃请荆卿（）②丹请先遣秦武阳（）9、穷①樊将军以穷困来归丹（）②图穷而匕首（）10、得①岂可得哉（）②诚能得樊将军首（）11、顾①顾计不知所出耳（）②终已不顾（）12、就①于是荆轲遂就车（）②轲自知事不就（）13、发①顷之，未发（）②轲既取图奉之，发图（）14、使①使使以闻大王（）②使毕使于前（）15、引①自引而起（）②乃引起匕首提秦王（）16、报①臣乃得有以报太子（）②可以解燕国之患，而报将军之仇者（）17、见①秦王必说见臣（）②乃遂私见樊於期（）③而燕国见陵之耻除矣（）④图穷而匕首见（）18、私①丹不忍以己之私（）②乃遂私见樊於期（）19、意①而伤长者之意（）②卒起不意（）四、解释下列句子中画线的古今异义词（每小题1分，共10分）1、若舍郑以为东道主（）2、行李之往来，共其乏困（）3、微夫人之力不及此（）4、沛公居山东时，使子婴为相（）5、备他盗之出入与非常也（）6、沛公奉卮酒为寿，约为婚姻（）7、将军战河南，臣战河北（）8、事所以不成者（）9、诸郎中持兵，皆陈殿下（）10、樊将军仰天太息流涕（）五、解释下列句子中画线的活用词，并指出类型（每小题1分，共15分）1、晋军函陵（）2、既东封郑，又欲肆其西封（）3、越国以鄙远（）4、沛公欲王关中（）5、吾得兄事之（）6、范增数目项王（）7、从郦山下，道芷阳间行（）8、素善留侯张良（）9、项伯杀人，臣活之（）10、交戟之卫士欲止不内（）11、常以身翼蔽沛公（）12、群臣怪之（）13、乃遂收盛樊於期之首，函封之（）14、今太子迟之，请辞决矣（）15、皆白衣冠以送之（）六、指出下列虚词的意义和用法（每小题1分，共30分）1、之①子犯请击之（）②项伯乃夜驰之沛公军（）③臣之壮也，犹不如人（）④今急而求子，是寡人之过也（）2、以①箕踞以骂（）②樊将军以穷困来归丹（）③而秦武阳奉地图匣，以次进（）④常以身翼蔽沛公（）⑤敢以烦执事（）3、因①项王即日因留沛公与饮（）②不如因善遇之（）③因人之力而敝之（）4、于①使毕使于前（）②嘉为先言于秦王曰（）③长于臣（）④吾每念，常痛于骨髓（）5、而①将军之仇报，而燕国见陵之耻除矣（）②今行而无信，则秦未可亲也（）③朝济而夕设版焉（）④倚柱而笑（）6、为①旦日飨士卒，为击破沛公军（）②不者，若属皆且为所虏（）③卒惶急不知所为（）7、若①若入前为寿（）②若使烛之武见秦君（）8、且①臣死且不避，卮酒安足辞（）②吾属今为之虏矣（）③以其无礼于晋，且贰于楚也（）七、翻译下列句子1、邻之厚，君之薄也2、吾令人望其气，皆为龙虎，成五采，此天子气也。
高一化学必修一第二单元习题含答案
第二单元测试题第Ⅰ卷(选择题，共54分)一、选择题(每小题3分，共54分)1．一化学兴趣小组在家中进行化学实验，按照图甲连接好线路发现灯泡不亮，按照图乙连接好线路发现灯泡亮，由此得出的结论正确的是( ).A．NaCl是非电解质B．NaCl溶液是电解质C．NaCl在水溶液中电离出可以自由移动的离子D．NaCl溶液中水电离出大量的离子2．下列离子方程式书写正确的是( ).A．在氨水中通入过量SO2：2NH3·H2O＋SO2===2NH＋SO＋H2OB．在次氯酸钠溶液中通入少量SO2：2ClO－＋H2O＋SO2===2HClO＋SOC．在氢氧化钠溶液中通入一定量的CO2：3OH－＋2CO2===CO＋HCO＋H2OD．在硫酸铝溶液中加入过量氨水：Al3＋＋4OH－===AlO＋2H2O3．已知在酸性溶液中，下列物质氧化KI时，自身发生如下变化：Fe3＋→Fe2＋；MnO→Mn2＋；Cl2→2Cl－；HNO2→NO，如果分别用等物质的量的这些物质氧化足量的KI，得到I2最多的是( ).A．Fe3 B．MnO C．Cl2 D．HNO24．三聚氰胺[C3N3(NH2)3]是一种重要的有机化工原料。
动物长期摄入三聚氰胺会造成生殖、泌尿系统的损害，膀胱、肾部结石，并可进一步诱发膀胱癌，它遇强酸或强碱水溶液会水解，胺基逐步被羟基取代，最后生成三聚氰酸[C3N3(OH)3]。
三聚氰酸可用于消除汽车尾气中的NO2，其反应原理为：C3N3(OH)33HNCO；8HNCO＋6NO27N2＋8CO2＋4H2O，下列说法正确的是( ).A．C3N3(OH)3与HNCO为同一种物质B．HNCO是一种很强的氧化剂C．1 mol NO2在反应中得到的电子为 4 molD．反应中CO2是氧化产物5．今有一混合物的水溶液，只可能含有以下离子中的若干种：K＋、NH、Cl－、Mg2＋、Ba2＋、CO、SO，现取三份100 mL溶液进行如下实验：(1)第一份加入AgNO3溶液有沉淀产生；(2)第二份加足量NaOH溶液加热后，收集到气体0.04 mol；(3)第三份加足量BaCl2溶液后，得干燥沉淀 6.27 g，经足量盐酸洗涤、干燥后，沉淀质量为2.33 g。
高一英语(必修1)第2单元综合检测题
一英语（必修1）第2单元综合检测题第一部分：听力测试（共两节；满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What does the man need to buy?A. Bread.B. Milk.C. Milk and eggs.2. What does Jack usually do after school?A. Read books.B. Play computer games.C. Do his homework.3. Why didn’t the man sleep well last night?A. Because he had a fever.B. Because his baby was ill.C. Because his dog was ill.4. What is the daughter doing?A. Perhaps she is playing.B. Perhaps she is sleeping.C. Perhaps she is reading books.5. How many minutes are left before the lecture starts?A. 10 minutes.B. 15 minutes.C. 5 minutes.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C 三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间来阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料，回答第6、7题。
高一化学必修一第二单元测试题及答案
高一化学必修一第二单元测试题及答案高一化学必修一第二单元测试题一、选择题( ) 1.熔点以上的物质不可能是A. 熔融状态B. 液体状态C. 固体状态D. 气体状态答案：D. 气体状态( ) 2.天然气的主要成分是A. 氧气B. 氮C. 氢D. 碳答案：C. 氢( ) 3.冰融解成液态水的过程中液体的体积A. 增加B. 减少C. 不变D. 一定答案：A. 增加二、填空题4.当物质从固态转变为气态时，物质的体积会____ 。
答案：增加5.液体也可以通过_____ 的方法转变成固态。
答案：冷却6.在室温下，固态水的性质是____ 。
答案：固体三、计算题7.42 g 氯化钠可以溶于100 g 水，溶液的摩尔浓度是_____答案：0.42 mol/L以上是高一化学必修一第二单元测试题，其中包括了选择题、填空题和计算题，这三种题型都是我们学习化学的基本知识，熟练掌握它们对正确理解和推导化学问题非常重要。
第一，选择题。
选择题是帮助我们领会重要概念的最快有效的方法。
通过这些题，我们不仅可以学习和熟悉物质态转化的知识，还可以了解各物质状态的性质变化，熟练掌握反应的过程和变化的规律，更好地应用化学知识去解决问题。
第二，填空题。
填空题有助于学生们检查、补充所学知识，能够熟练掌握与有关物质态转化的基本知识和基本概念，掌握不同状态物质之间的变化规律，学会化学反应的遵循，同时深入学习物质态转化的原理。
第三，计算题。
计算看似枯燥无味，但它是所有学科中最重要的考验之一，是衡量学生学习成果的关键。
计算题中所考查的内容，是比较大量知识，是由浅入深层层推进锻炼学生在化学情境中用脑去思考的过程，能够让学生们掌握一些量的计算方法，建立数 v x 对应的能力，从而更好的利用数值的方法去解决实际问题。
总之，通过这次高一化学必修一第二单元测试题，让我们学习了状态间物质态转化之间及其相互影响的定律，提高了我们理解和解决实际化学问题的能力，也增强了我们学习学习和应用化学的信心。
人教版高中英语必修一第二单元测试题及答案
高一年级英语学科必修一第二单元质量检测试题参赛试卷学校：斗鸡中学命题人：高一英语命题组第一卷（选择题，共100分）第一部分：英语知识运用（共4节，满分）第一节语音知识（共5小题，每题1分，满分5分）例ChinaA /’tʃa:nə/B /’chainə/C /’tʃainə/D /’cha:nə/答案是：C1. frequent A /’frikwənt / B /fri:’kwənt/ C /’fri:kwent / D /’fri:kwənt /2. accent A /’eksənt / B /’ æksənt/ C /æk’sənt / D /’ æksent /3. finally A/fai’nəli / B /’fainəli / C /’fenəuli / D /’faineuli /4. nation A/’neiʃən / B /’næʃən / C/’næʃn/ D /’neiʃn /5 concern A/’kʌnsə:n / B/kʌn’sə:n / C/kən’sə:n / D/’kənsən /第二节情景对话（共5小题，每小题1分，满分5分）根据对话情景和内容，从对话后所给的选项中选出能填入每一空白处的最佳选项，选项中有2个为多余选项。
A: Hi, Jim. 6 Did you enjoy your summer holidays ?B: Yes. How about you ? Did you stay at home ?A: No, I didn't . I went to Emei Moutains in Sichuan and had a wonderful time.B: 7 .A: And I climbed to the top of the mountain.B: So did I!A: And I stayed there for a night, and the next morning I saw the sunrise.8 .B: Oh, dear！So did I.A: 9 I went in late July .And you ?B: Early August . 10 .A. Really? So did I!B. I'd like to tell you the truth.C. It was great !D. Great to see you again.E. What great mountains!F. What a pity we didn't go there at the same time!G. Why didn't I see you there ? 第三节语法和词汇知识（共15小题，每小题1分，满分15分）11. Middle school students should learn from real heroes, ________ Yang Liwei and Hong Zhanhui, and try to makecontributions to our country in the future.A. for instanceB. for exampleC. as followsD. such as12. The number of peole invited _______ forty, but a number of them ______ absent for different reasons.A. were; wasB. was; wereC. was; wasD. were; were13. She was late not only __________ her illness but also _________ she missed the plane.A. for; because ofB. because; forC. because of; becauseD. because of; because of14. I like Emy, ________ she can be annoying（烦人的）at times.A. even thoughB. now thatC. as thoughD. as long as15. So far the problem we are worried about hasn’t ___________ yet.A. come upe onC. come onD. come down16. We thought about it for a long time, but still couldn’t _________ a solution.A. come outB. get along withC. come overD. come up with17. He commanded that all the gates __________.A. shutB. should shutC. would be shutD. be shut18. Yesterday she told me that she had met her aunt ___________.A. for two yearsB. two years beforeC. two years agoD. before two years19. The teacher told me that the light ______ faster than sound.A. travelsB. had traveledC. is travelingD. traveled20. The a pples are delicious. I’d like to have _____ third one because ____ second one is rather too small.A. the; aB. the; theC. a; aD. a; the21. It is so nice to hear from him. _____, we last met more than thirty years ago.A. In other wordsB. Wha t’s moreC. Believe it or notD. That is to say22. I have ____ him for fifteen years. But I didn’t _____ him just now because he has changed so much.A. known; recognizeB. recognized; knowC. known; knowD. recongnized; recongnize23. What do you think of the way _____ he worked out the problem?A. thatB. in whichC. /D. all the above24. She often gets up late，_____when she has no classes in the morning.A. generally B especially C usually D hardly25. On hearing the sound, the birds flew away in every _____.A. wayB. directionC. placeD. side第四节完形填空（共20小题，每小题1.5分，满分30分）Do you know 26 languages there are in the world? There are about 1500, but many of them aren’t very 27 . English is one of the most important languages because many people 28 it, not only in England and America, 29 in other countries of world. About 375000000 people speak it 30 their own language, and another 375000000 use it as 31 language. It is 32 to say how many people are learning it. 33 boys and girls in schools are trying to do so.Many English children study French. French is also a very important language. 34 children study German, Russian, Japanese and Chinese.What is the best 35 to learn a language? We know that we all learnt 36 language well when we were 37 . If we learn a second language in the 38 way, it won’t seem so difficult. What does a small child do? It 39 what people say, and it tries to guess what it hears. When it wants something, it has to 40 it. It is using the language, 41 in it and talking in it all the time. If people use a second language 42 , they will learn it 43 .In school, you learn to read, to write, to hear and to speak. It is best to learn all new words through the 44 .You can read them, spell them and 45 them later.( )26. A. how many B. what number C. a lot of D. so many( )27. A. useful B. necessary C. important D. good( )28. A. like B. use C. learn D. speak( )29. A. but B. and C. also D. so( )30. A. like B. with C. for D. as( )31. foreign B. a second C. the second D. a special( )32. A. easy B. again C. difficult D. best( )33. A. Millions of B. Million of C. Millions D. Several million of( )34. A. Some B. Other C. All D. Few( )35. A. time B. way C. thing D. place( )36. A. a foreign B. our mothers’ C. other’s D. our own( )37. A. born B. children C. grown D. boys( )38. A. same B. different C. useful D. good( )39. A. does B. says C. listens to D. follows( )40. A. ask B. want C. get D. ask for( )41. speaking B. writing C. thinking D. doing( )42. A. some time B. sometimes C. all the same D. for the time( )43. A. quickly B. soon C. freely D. hardly( )44. A. mouth B. hands C. ears D. mind( )45. A. listen to B. use C. love D. write第二部分阅读理解（每小题3分，满分45分）AEnglish words don’t stay the same. People need new words for new invent ions. Different words come into use, or older words are used in a new way.English can change by borrowing words from other languages. The word “tomato” was borrowed from Mexico, and “tea” came from China, and so on. Now a great many of new space and scie nce words are being borrowed from other countries, too. New words can be formed in other ways. For example, some can be formed by adding two words together. “Weekend” and “cookbook” are made up of two parts. Sometimes new words are shorter forms of older w ords. The word “photo” was made from “photograph” by cutting off the end of the longer word. “Plane”was made by cutting off the front part of “airplane”. The names of people and products can become new words. Our “sandwich”was named aftera man named Sandwich and “sello（透明胶带）”was a name given by the company that first made the product.46. New English words are needed because ___________ .A. people use old words in a new wayB. people need a new way to explainC. the world is changing and developingD. new ideas and new inventions come about quickly47. We know from the passage that _______.A. new science words are shorter than the old onesB. the best way to make a new word is adding words togetherC. some new English words are borrowed from other languagesD. most new English words are borrowed from other languages48. How many ways of developing English words does the passage tell us?A. ThreeB. FourC. Five.D. SixBAs you research music, you will find music that is familiar to you. You will find music which tells of interesting places and exciting things to do. You will find music which expresses feelings that are often your own. Music is an expression of the people.As you research, you will find music of people at work and play. You will find music expressing love of the country, love of nature, and love of home. Music is also an expression of the composer(作曲家). The composer expresses his own musical ideas. He studies the materials of music and discovers ways of using them. He looks for new kinds of musical expression.Music can suggest actions and feelings which we all share. We can enjoy playing and singing music, dancing and listening to the music of the people and the composers of different times and places.49. In the first paragraph, the author tells us to_______.A. find entertainment(娱乐) in musicB. be friendly to musicC. express your feelings in musicD. discover the things and places in music50. From the second paragraph, we know that ________.A. if we love music, we will love the country, nature and homeB. music sings of the country, nature and homeC. you may listen to music at work or at playD. music can express how people live, work and think51. By means of music, the composer wishes that ________.A. you would study with themB. you would share his feelings and ideasC. you would express your own feelingsD. you help discover ways of using music and new kinds of musical expression52. The last paragraph shows that music makes it possible ________.A. that music can express actions and feelings at the same timeB. to bring understanding between people of different times and placesC. that people can enjoy playing and singing music, dancing and listening to the music at the same timeD. that people of different time and places can get togetherCJay Chou is a well-known name both in Taiwan and mainland. He is now one of Asia’s hottest pop stars. His catchy tunes have mainstreamed(主流) rap and R&B in the Mando-pop world. In the past his teacher thought he was dumb. Talent spotters(观察者) thought he was ugly. But his success proves that the music still matters more than looks and image. His musical talent（才能）is recognized by fans, fellow-singers and producers alike. Now, singing contest has been held in Taiwan.Chou appeared at the contest with band “Nan Quan Mama”, which was discovered by Chou. Their first album the Summer of Nan Quan Mama, composed and produced by Chou was a great success.Chou started his career at a singing contest, attracting the attention of record producers. But the successful singer does not believe in luck. He says it’s his passion for music and hard work that are keys to his success. He said,”I didn’t know how to sing at the beginning, so I lost the first time. But I was so determined that I never stopped trying. My advice to these young singers is to never give up, and alway s believe in yourself.”Chou’s confidence has strengthened his music. He is a great source of inspiration to youngsters who share his determination to become a superstar.53. The best title for this passage can be ________.A. From an ugly dumb to a superstarB. Jay Chou encourages youngstersC. Jay Chou and his bandD. Jay Chou’s career54. The underlined part “matters more” most probably means ______.A. betterB. more differentC. more difficultD. more important55. Which of the following is NOT TRUE about Jay Chou?A. Jay Chou is confident towards musicB. He is a determined man.C. He succeeded the first time he appeared on the stage.D. Though not good-looking, he has a gift for music.56. _______ makes Jay Chou a success according to the passage?A. His luckB. His passion of musicC. His hard workD. Both B and C57. Jay Chou’s musical talent is recognized by the follow ing except _________.A. fansB. fellow-singersC. producersD. his teachersDAm I expected to learn both American English and British English vocabulary? Yes，and add to that Australian English．And any other variety that is useful for your needs．If you intend to study in the United Kingdom，or work for a British company, then obviously you will need to spend more time on British English(BrE)．If you plan to work in the United States，then you will need to pay attention to American English (AmE)．However, let’s make the task a little easier for you．Some differences in BrE／AmE vocabulary are more difficult to deal with than others．(See the chart．)In addition to the categories(种类)on the chart，there is another category which could be described as unguessable，but the words are less important to learn．Such differences as aubergine/eggplant，spring onion/scallion，1ug／pitchermy wife bought me a few more pants”, we know that he is probably from A．Australia B．BritainC．America D．New Zealand59．When someone says “He’s engaged．Don’t bother him，or he’11 get angry．”，in AmE it means“He’s Don’t bother him，or he’11 get”．A．studying；mad B．married：angryC．mad；busy D．busy；mad60．What does the underlined Word“priority”in the passage mean?A．Earlier time．B．Special attention．C．Unimportance．D．Special right．第二卷（共50分）第一节单词拼写（每小题1分，共10分）61. The writer of that country has an __________(国际) fame.62. An _________(电梯) is a kind of machine for raising and lowering something.63. In America a flat is called an ________(公寓)64. He had lost his _______(身份) card and was being questioned by th police.65. He made __________(迅速)progress in his English country.66. ISBN stands for International __________(标准)Book Number.67. The German speak English with a strong German _________(口音)68. They have _____________(承认)him to be their leader.69. ___________(实际上)，you owe me more than this.70. All the people _________(出席) are table tennis lovers.第二节短文改错（每小题1.5分，共15分）请修改下列短文，短文中共有10处语言错误，每句中最多有两处。
高一历史必修一第二单元试题
高一历史必修一其次单元练习1．“从文明演进的角度看，中西民主制度的第一次分野几乎是必定的，无论是古希腊的城邦民主，还是中国的专制主义中心集权制度，他们都各自适应了当时当地的历史和地理条件，是制度演进的客观结果，而不是人们主观选择的结果。
”这表明()A．中西制度的差异完全不受主观因素影响B．中西制度的差异根源于地理环境的不同C．历史传统和地理环境影响政治制度演进D．政治制度的演进是人们自主选择的结果2．《历史大脉络》中谈到“中国人以为旺盛安定的景观是田畴相接，庄稼丰茂。
精耕细作的农业，为中国人的饮食开发出不少美味佳肴，其中最为丰富的成分是碳水化合物(淀粉)、纤维质与素食的蛋白质。
”《剑桥古代史》中描述到：雅典人“不仅可以享受阿提卡的橄榄油和葡萄酒，而且可以食用黑海的谷物和干鱼。
”以下关于古代中国和雅典饮食的比较错误的是()A．都特别注意美食的开发，美食品种多样B．中国美食以粮食等素食为主，古希腊副食种类丰富C．两者不同的饮食习惯源于政治体制的差异D．两者的不同与自然环境关系亲密3．古希腊哲学家有一句名言：“人是城邦的动物。
”有四位同学对此做了不同的说明，你认为其中有错误的是() A．城邦是指公民集团 B．公民把城邦的利益看得高于一切C．公民的公众形象代表他所在的城邦 D．这里的“人”指城邦中的男子4．先秦时期，中国产生了分封制，同时期古希腊却实行公民干脆管理国家的民主制度。
与中国相比，古希腊所具有的特殊条件不包括()A．山多地少，三面环海，岛屿众多的海洋地理环境B．形成了小国寡民的城邦政治C．工商业经济和海外贸易发达D．国家统一，疆域宽阔5．威尔·杜兰在《世界文明史·希腊的生活》中这样分析古希腊宗教：“每种手艺、职业和艺术都有它们的神性，或者更妥切地说，有它们的守护神……其数目之繁多，几可与地上人类相匹。
”“每一个城邦都有它的万神殿。
”古希腊宗教的这一特点()A．有利于古希腊民主政治同等精神的形成发展B．说明自然地理环境影响着古希腊文明C．必定会推动古希腊建立大一统专制政权D．有利于古希腊妇女参政议政6．任何人，只要他能够对国家有所贡献，肯定不会因为贫困而在政治上湮没无闻。
【高一】人教版高一英语必修1第二单元测试(带答案)
【高一】人教版高一英语必修1第二单元测试（带答案）Unit 2 单元综合检测（人教版必修1）第一部分听力(共两节，满分30分)第一节(共5小题；每小题1.5分，满分7.5分)听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间回答有关小题和阅读下一小题。
每段对话仅读一遍。
1．How uch is a ticket for the ovie?A．60 yuan. B．30 yuan. C．20 yuan.2．What is the woan?A．A policewoan.B．A waitress.C．A shop assistant.3．What did ary do last night?A．She did her hoework.B．She went to the party.C．She talked with the an.4．How does the an feel about the report?A．Not interesting at all.B．ore difficult than he thought.C．As difficult as he expected.5．What do we know about the woan?A．She was ill in hospital yesterday.B．She sent her brother to hospital yesterday.C．She asked for a day off today.第二节(共15小题；每小题1.5分，满分22.5分)听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
高一政治人教版必修一第二单元检测题(有答案)
高一政治人教版必修一第二单元检测题（有答案）一、挑选题 1.[2013•福州质检]小明：我想买个智能手机。
爸爸：你已经有手机了，为何还要买?小明：现在商店卖的许多智能手机都有看电影、玩游戏等功能，我那款非智能手机只能接电话、发短信，老掉牙了。
这一对话体现了()A.生产决定消费B.消费反作用于生产C.收入是消费的基础和条件D.物价的变动影响人们的购买力解析：A 本题考核生产决定消费的知识。
题干反应了智能手机的新功能刺激了小明的消费愿望，体现了生产决定消费，生产为消费创造动力，A项正确。
B说法正确但不符合题意。
C、D与题意无关。
2.[2013•潮州质检]航天技术的发展，使新科技成果走入百姓生活：脱水蔬菜取自于航天食品储存技术，人造心脏取自于航天飞机的燃料泵技术，汽车导航取自于航天定位技术等。
这说明()A.消费增进产品结构升级B.生产为消费创造了动力C.生产决定消费质量和水平D.消费需求增进生产的发展解析：C 材料表明新科技的推广与运用为人民群众的生活提供了新的产品和服务，说明生产决定消费，C正确;A、D不符合题意;材料没有说明新科技刺激了消费需求，因此B不符合题意。
3.目前很多智能电视设计复杂，操作繁琐，让智能电视自产生起就戴上了功能多但“智商低”的帽子。
为此，海信在2013年推出了全新智能电视产品。
海信此次提出的是“极简”的概念，即通过后台系统“有组织的内容让设计更有整体感”、通过“洞悉人性化需求让使用变得简单”。
由此可以看出()A.消费是生产的目的和动力B.交换是连接生产与消费的桥梁C.生产与消费存在着相互影响的关系D.交换对生产和消费有侧重要影响解析：C 很多智能电视因设计复杂，操作繁琐，给消费者带来不便。
消费者把意见反馈给商品生产者，商品生产者改进产品后再投放市场，这是生产者与消费者互动的结果，故选C。
4.2013年一季度我国消费对经济增长的奉献率为55.5%，资本形成总额奉献率为30.3%，货物和服务净出口奉献率为14.2%;经济增长主要靠内需拉动，消费对经济增长的拉动作用提升。
人教版高中语文必修一【第二单元】综合检测及答案解析
综合检测(二)(时间：120分钟 满分：120分)一、基础积累(15分，每小题3分)1．下列各组句子中，没有通假字的一项是( )A ．旦日不可不蚤自来谢项王B ．卒起不意，尽失其度C ．失其所与，不知D ．樊於期偏袒扼腕而进【解析】 A 项，“蚤”通“早”；B 项，“卒”通“猝”；C 项，“知”通“智”。
【答案】 D2．下列句子中，加点词语的用法分类正确的一项是( )①常以身翼．蔽沛公 ②群臣怪．之 ③此其志不在小． ④越国以鄙远． ⑤顷之未发，太子迟．之 ⑥素善．留侯张良 ⑦吾得兄．事之 ⑧项伯杀人，臣活．之 ⑨沛公旦日从．百余骑来见项王 ⑩项伯乃夜．驰之沛公军 A ．①⑦/②③/④⑤⑧/⑥⑨⑩B ．①③⑩/②④⑤/⑥⑦/⑧⑨C ．①⑦⑩/②⑤/③④/⑥/⑧⑨D ．①/②③④/⑤/⑥⑨⑩/⑦⑧【解析】 ①⑦⑩为名词作状语，②⑤为形容词的意动用法，③④为形容词作名词，⑥为形容词作动词，⑧⑨为动词的使动用法。
【答案】 C3．下列句中加点词的意义和用法相同的一项是( )A.⎩⎨⎧ ①是寡人之．过也②行李之．往来 B.⎩⎨⎧①秦王还柱而．走②倚柱而．笑C.⎩⎨⎧ ①君为．我呼入②窃为．大王不取也 D.⎩⎨⎧①因．击沛公于坐②因．左手把秦王之袖 【解析】 B 项，均为连词，表修饰。
A 项，①结构助词，的；②助词，用于主谓之间，取消句子独立性，不译。
C 项，①介词，替，给；②动词，认为。
D 项，①介词，趁机；②副词，于是。
【答案】 B4．下列句式中与其他三项不同的一项是( )A ．是寡人之过也B ．太子及宾客知其事者C ．如今人方为刀俎，我为鱼肉D ．此亡秦之续耳【解析】 B 项为定语后臵句，其他三项为判断句。
【答案】 B5．补写下列名篇名句中的空缺部分。
(两题任选一题)(1)大行不顾细谨，________________。
________________，________________，何辞为？(《鸿门宴》)(2)又前而为歌曰：“________________，________________！”复为慷慨羽声，______________，发尽上指冠。
高中生物必修一第二单元检测题及答案解析
高中生物必修一第二单元检测题及答案解析(时间：75分钟满分：100分)一、选择题(本题共20小题，每小题2分，共40分。
每小题给出的四个选项中，只有一个选项是最符合题目要求的。
)1.(2021·华师一附中调研)下列有关组成细胞的化学元素的叙述，正确的是()A.人体细胞干重中含量最多的元素是NB.人体活细胞内含量最多的元素是OC.Mg、Zn、Ca等大量元素是生物体必不可少的D.微量元素对生物体来说可有可无2.(2021·珠海市期中)下列有关水和无机盐的叙述，不正确的有()①水能溶解、运输营养物质和代谢废物②细胞中无机盐含量很少且大多数是以化合物形式存在③哺乳动物的血液中钙离子含量过高，会出现抽搐等症状④无机盐可以为人体生命活动提供能量⑤休眠种子与萌发种子相比，结合水与自由水的比值更小⑥缺碘会引起儿童佝偻病A.六项B.五项C.四项D.三项3.(2021·合肥市期中)某牛奶饮品每100 mL中部分营养成分含量如下表：下列有关说法错误的是()A.维生素D可以增进补钙效果B.蛋白质摄入可以补充氨基酸C.脂肪的储能效率比糖类的高D.细胞中碳水化合物是结合水4.(2021·四川成都七中期中)下面是关于脂质的叙述，其中正确的是()A.细胞膜中含磷脂，细胞器膜中不含磷脂B.胆固醇能促进人体肠道对钙和磷的吸收C.脂肪只存在于动物细胞中，植物细胞中没有D.海豹的皮下脂肪有减少热量散失、保温的作用5.(2021·山东济南期中)医生常给脱水病人静脉注射质量分数为0.9%的氯化钠溶液(生理盐水)，而不是蒸馏水，因为红细胞在蒸馏水中会因吸水过多而涨破。
该现象主要说明()A.水分子容易进入细胞B.无机盐离子容易进出细胞C.红细胞容易破裂D.无机盐对维持细胞形态有重要作用6.(2021·黑龙江铁人中学)下列有关水的特性与水的生理功能相互对应关系的叙述不正确的是()A.水是极性分子决定其是细胞内良好溶剂，为生物化学反应所必需B.水分子间弱吸引力氢键决定其具有流动性，是物质运输所必需C.水具有较高的比热容，能够缓和温度的变化，为生命提供比较适宜的环境D.水可以和多糖、蛋白质物质结合，促进细胞的代谢7.(2021·襄阳市期中)几丁质又称壳多糖，关于壳多糖的叙述正确的是()A.几丁质可直接被细胞吸收B.被一些科学家称为“第七营养素”C.是各种动物骨骼的组成成分之一D.可用于制作食品的包装纸和人造皮肤8.(2020·安徽蚌埠二中期中)如图表示人体中一个由153个氨基酸构成的蛋白质分子。
高一数学必修一单元测试卷第二单元
高一数学必修1第二章测试题一、选择题：本题共12小题,每小题5分,共60分, 1、若:f A B →能构成映射,下列说法正确的有1A 中的任一元素在B 中必须有像且唯一；2B 中的多个元素可以在A 中有相同的原像；3B 中的元素可以在A 中无原像；4像的集合就是集合B ; A 、1个B 、2个C 、3个D 、4个2、对于函数()y f x =,以下说法正确的有①y 是x 的函数；②对于不同的,x y 的值也不同；③()f a 表示当x a =时函数()f x 的值,是一个常量；④()f x 一定可以用一个具体的式子表示出来;A 、1个B 、2个C 、3个D 、4个3、设函数()(21)f x a x b =-+是R 上的减函数,则有A 、12a >B 、12a <C 、12a ≥D 、12a ≤ 4、下列各组函数是同一函数的是①3()2f x x =-与()2g x x x =-；②()f x x =与2()g x x =；③0()f x x =与01()g x x =；④2()21f x x x =--与2()21g t t t =--;A 、①②B 、①③C 、②④D 、①④5、二次函数245y x mx =-+的对称轴为2x =-,则当1x =时,y 的值为A 、7-B 、1C 、17D 、25 6、函数265y x x =---的值域为A 、[]0,2B 、[]0,4C 、(],4-∞D 、[)0,+∞ 7、下列四个图像中,是函数图像的是A 、1B 、1、3、4C 、1、2、3D 、3、48、若()1f x x =+则(3)f =12 34A 、2B 、4C 、22D 、109)(x f 是定义在R 上的奇函数,下列结论中,不正确．．．的是A 、()()0f x f x -+=B 、()()2()f x f x f x --=-C ()()0f x f x -≤D 、()1()f x f x =-- 10果函数2()2(1)2f x x a x =+-+在区间(],4-∞上是减函数,那么实数a 的取值范围是A 、3a -≤B 、3a -≥C 、a ≤5D 、a ≥511、定义在R 上的函数()f x 对任意两个不相等实数,a b ,总有()()0f a f b a b->-成立,则必有A 、函数()f x 是先增加后减少B 、函数()f x 是先减少后增加C 、()f x 在R 上是增函数D 、()f x 在R 上是减函数12、下列所给4个图象中,与所给3件事吻合最好的顺序为1我离开家不久,发现自己把作业本忘在家里了,于是立刻返回家里取了作业本再上学； 2我骑着车一路以常速行驶,只是在途中遇到一次交通堵塞,耽搁了一些时间； 3我出发后,心情轻松,缓缓行进,后来为了赶时间开始加速;A 、124B 、423C 、413D 、412 二、填空题：共4小题,每小题4分,共16分,请把答案填写在答题纸上 13、已知(0)1,()(1)()f f n nf n n N +==-∈,则(4)f =;14．若函数ｆｘ＝2x －ａｘ－ｂ的两个零点是２和３,则函数ｇｘ＝ｂ2x －ａｘ－１的零点 ．15、定义在)1,1(-上的奇函数1)(2+++=nx x mx x f ,则常数=m ____,=n _____16、设2 2 (1)() (12)2 (2)x x f x x x x x +-⎧⎪=-<<⎨⎪⎩≤≥,若()3f x =,则x =;17.本题12分设全集U ＝{不超过5的正整数},A ＝{x |x 2－5x ＋q ＝0},B ＝{x |x 2＋px ＋12＝0},C U A ∪B ＝{1,3,4,5},求p 、q 和集合A 、B .18．本题12分定义在-1,1上的奇函数fx 是减函数,且f1-a+f 1-a 2＞0,求实数a 的取值范围; 19.本题12分已知fx 是定义在0,+∞上的增函数,且满足fxy ＝fx ＋fy ,f 2＝1. 1求证：f 8＝32求不等式fx －fx －2>3的解集.1234时时时时间离开家的距离离开家的距离离开家的距离离开家的距离20.本题12分某租赁公司拥有汽车100辆,当每辆车的月租金为3000元时,可全部租出,当每辆车的月租金每增加50元时,未租出的车将会增加一辆,租出的车每辆每月需维护费150元,未租出的车每辆每月需要维护费50元.1当每辆车的月租金定为3600元时,能租出多少辆车2当每辆车的月租金定为多少元时,租赁公司的月收益最大最大月收益是多少 22本题14分、已知函数2()(0,,)f x ax bx c a b R c R =++>∈∈ 若函数()f x 的最小值是(1)0f -=,(0)1f =且对称轴是1x =-,()(0),()()(0),f x xg x f x x >⎧=⎨-<⎩求(2)(2)g g +-的值：2在1条件下求()f x 在区间[](),2t t t R +∈的最小值 一、选择题： CBBCDABADACD 二、填空题：13、2414、31,21--15、15、0；016、317、解：P ＝－7,q ＝6,A ＝{2,3},B ＝{3,4} 18、解：f1-a+f1-a 2＞0,得：f1-a ＞fa 2-1211111111a a a a-≤-≤⎧⎪-≤-≤⎨⎪-<-⎩,1<a ≤2 19、1证明由题意得f 8＝f 4×2＝f 4＋f 2＝f 2×2＋f 2＝f 2＋f 2＋f 2＝3f 2 又∵f 2＝1∴f 8＝32解不等式化为fx >fx －2+3∵f 8＝3∴fx >fx －2＋f 8＝f 8x －16 ∵fx 是0,+∞上的增函数∴⎩⎨⎧->>-)2(80)2(8x x x 解得2<x <20、解1当每辆车月租金为3600元时,未租出的车辆数为＝12,所以这88辆.2设每辆车的月租金定为x 元,则公司月收益为fx ＝100－x －150－×50整理得:fx ＝－＋162x －2100＝－x －40502＋307050∴当x ＝4050时,fx 最大,最大值为f 4050＝307050元 22．15分1(1)0(0)112f f b x a ⎧⎪-=⎪=⎨⎪⎪=-=-⎩∴012a b c c b a -+=⎧⎪=⎨⎪=⎩∴112a c b =⎧⎪=⎨⎪=⎩∴2()(1)f x x =+ 2当21t +≤-时,即3t ≤-时2()(1)f x x =+在区间[],2t t +上单调递减当12t t <-<+时,即31t -<<-时2()(1)f x x =+在区间[],1t -上单调递减,2()(1)f x x =+在区间[]1,2t -+上单调递增min ()(1)0f x f =-=当1t ≥-时,2()(1)f x x =+在区间[],2t t +上单调递增,2min ()()(1)f x f t t ==+ 22．15分1(1)0(0)112f f b x a ⎧⎪-=⎪=⎨⎪⎪=-=-⎩∴012a b c c b a -+=⎧⎪=⎨⎪=⎩∴112a c b =⎧⎪=⎨⎪=⎩∴2()(1)f x x =+ 2当21t +≤-时,即3t ≤-时2()(1)f x x =+在区间[],2t t +上单调递减当12t t <-<+时,即31t -<<-时2()(1)f x x =+在区间[],1t -上单调递减,2()(1)f x x =+在区间[]1,2t -+上单调递增min ()(1)0f x f =-=当1t ≥-时,2()(1)f x x =+在区间[],2t t +上单调递增,2min ()()(1)f x f t t ==+。
人教版高中英语必修一第二单元测试卷
人教版版高中英语测试题必修一Unit 2《English around the world》单元测试1笔试部分：I. 单项选择21. — How was your weekend?—Great! We ______ a picnic by the lake.A. haveB. are havingC. hadD. will have22. He looked at the envelope and __________ Jenny's handwriting immediately.A. understoodB. knewC. recognizedD. recovered23. A large number of students in our school ____ from the countryside; the number _____ growing these years.A. is; has beenB. are; has beenC. is; have beenD. are; have been24. Washington D.C., the capital of the United States, is one of ______ cities in the world.A. the biggestB. biggerC. much biggerD. big25. One of her American friends asked her, “Would you please ______ to my apartment for a visit?”A. come upB. keep upC. put upD. catch up26. — Excuse me? ______—It is over there, near the bus stop.A. How do you like the cinema?B. May I ask you the way?C. Where is the Bank of China?D. How far is the market from here?27. The ______ from England to India used to take more than six months as there were storms and huge waves at times.A. travelB. journeyC. tripD. voyage28. — Mum, ______ I play computer games?—Yes, you can. But you have to finish your homework first.A. mustB. mayC. willD. need29. English has become the most wildly spoken language in the world ______ its special role as an international language.A. becauseB. FromC. withD. because of30. Chinese is also spoken in many other countries in Asia, ______ Singapore and Malaysia.A. for exampleB. such asC. instead ofD. according to31. American English has so many _________ because the American people have come from allover the world.A. grammarB. vocabularyC. pronunciationsD. dialects32. I don't know ______ tomorrow. Can you tell me?A. when we startedB. when did we startC. when we will startD. when will we start33. Kitty and Lucy are both from England, so they are ______ English speakers.A. nativeB. internationalC. foreignD. same34. — John has hurt his leg.—Really? ______?A. Who did thatB. How did that happenC. What's wrong with himD. Why was he so careless35. Americans and Canadians can understand each other ______ they don't speak the same kind of English.A. now thatB. even ifC. as ifD. only if第二节完形填空(共20小题; 每小题1.5分, 满分30分)“Dad, I'm sure I can do it well th is time. I promise,” I said to myself and went up to the stage and began my play ...Finally I 36 from my piano and took a bow to the people in the hall. There was a 37 and then loud applause (掌声) burst out. I knew I 38 it. Tears filled my eyes. Then I 39 three years ago right here when it was my turn to play. I 40 the hall and saw my dad. He sat at the end of a 41 with a serious face.Suddenly I became 42 . I had practiced my piece for months, 43 then it seemed there was something wrong with my fingers. I forced out some 44 tune and left the stage in tears. I 45 .On the way home my father didn't say even a word. He just 46 the car in silence. I didn't say anything either. What could I say, really, after what I'd done? I knew how 47 Dad worked to earn enough money 48 my piano. That time he was 49 to come to a competition(比赛), but I let him down.I didn't remember how we got home. Dad never said a word the entire way home, and he never 50 one of my competitions again. I never got over the hurt of having 51 the person I most wanted to make proud. I'd 52 more than my competition that afternoon. I felt as if I'd lost the key to my father's heart, and he died before I could 53 it again.“God, why didn't you give me a 54 to make it up to him?” I'd often asked.I won first prize in the contest now. How I wish my father could share the 55 moment with me!36. A. dropped B. rose C. turned D. slid37. A. silence B. noise C. laughter D. shout38. A. got B. missed C. made D. caught39. A. thought B. realizedC. understoodD. remembered40. A. looked up B. looked aroundC. looked outD. looked over41. A. seat B. row C. group D. team42. A. nervous B. excited C. sick D. tired43. A. and B. though C. but D. so44. A. soft B. moving C. nice D. terrible45. A. succeeded B. wonC. failedD. disappeared46. A. drove B. started C. washed D. repaired47. A. quickly B. hard C. Warmly D. happily48. A. on B. in C. for D. with49. A. sad B. happy C. able D. unable50. A. attended B. noticed C. heard D. cared51. A. pleased B. surprisedC. disappointedD. satisfied52. A. felt B. lost C. made D. learned53. A. open B. close C. forget D. find54. A. piano B. duty C. chance D. contest55. A. exciting B. surprisingC. interestingD. relaxing第三部分阅读理解（共２０小题；每小题２分，满分４０分）ＡMany centuries ago, all people had to gather seeds and plants to eat. They did not know how to farm or raise animals for food. We call them the Stone Age people because they used stone tools and weapons.You may feel s urprised in the world today there are still people who live like the Stone Age people. They live in the places that are hard to reach. Because they have met few people from the outside world, they don't know about modern inventions. They have not learned ways of doing things from others.For 25,000 years, groups of people have lived alone in the middle of Australia. One of these groups is the Arunta tribe (部落). They do not know how to farm and how to raise sheep or cattle.The Aruntas spend most of their time searching for food and water. The men hunt animals with stone-tipped spears. The women and children look for roots, seeds and nuts. They use sticks to dig up the roots. Several Arunta families live together. They have no house. At night, they sleep around small fires.Now other people are moving into the center of Australia. Soon the Aruntas will no longer bea Stone Age people.56. The Stone Age people are called so because they ____.A. gathered seeds and plants to eatB. didn't know how to farmC. used stone tools and wea ponsD. didn't raise animals for food57. The Arunta tribe has lived ________.A. in the middle of AfricaB. in the center of AustraliaC. together with other peopleD. in poorly built houses58. Why do the Aruntas still live in the way as they lived before?A. Because they have not yet learned new ways from other people.B. Because they do not want to change their way of living.C. Because other people are moving in and living with the Aruntas.D. Because each family live alone without knowing others.59. It can be inf erred from the passage that ________.A. the Australians live much like the Stone Age peopleB. the Arunta tribe has a history of 25 centuriesC. the Stone Age people have at last disappeared in the worldD. the Aruntas will change their way of living sooner or laterＢThere are more than 250,000 rivers in the United States. Added up together, they flow for more than 5,500,000 kilometers.The largest and most famous river in the United States is the Mississippi. It starts near the northern border of the United States and flows through the center of the country for more than 3,700 kilometers. About 250 smaller rivers flow into the Mississippi. The mouth of the Mississippi empties into the Gulf of Mexico.However, the Missouri River is the longest river in the United States. It flows for about 4,000 kilometers. It begins in the Rocky Mountains of North America. It flows along the borders of seven states before it empties into the Mississippi River near the city of Saint Louis, Missouri.Three rivers that join together in the north central state of Montana form the Missouri River. The water is clear there. But, as it moves east and south, the Missouri River turns brown as it collects huge amounts of dirt from the land. That is why many people call the Missouri River the “Big Muddy”.Some people say the Columbia River in the northwest is the most beautiful river in America. It flows from the Canadian province of British Columbia into the United States through the state of Washington. The Columbia River is the largest river that empties into the Pacific Ocean.Another famous river is the Rio Grande. It is the longest river in the state of Texas. It forms the border between Texas and Mexico.The oldest river in the United States is the New River. It begins in the Appalachian Mountains of North Carolina and flows north through parts of Virginia and West Virginia. The New River may be also the second oldest in the world. It is funny how something so old can be called new.60. Near the city of Saint Louis is the place ________.A. where the Missouri River risesB. where the Missouri River joins the Mississippi RiverC. where other three rivers join the Missouri RiverD. where the Mississippi River flows into the ocean61. From Paragraph 4 we know that the water in the upper reaches of the Missouri River is ________.A. muddyB. dirtyC. clearD. brown62. In the state of Washington you can visit the beautiful ___.A. Missouri RiverB. Mississippi RiverC. New RiverD. Columbia River63. Which of the following rivers is the border between Texas and Mexico?A. The Rio Grande River.B. The New River.C. The Columbia River.D. The Mississippi River.ＣNowadays many students are interested in studying abroad.Attending schools abroad has many advantages. First, by looking at our own country from outside, we can best see the strong points and weak points of our nation and therefore widen our vision and broaden our minds. Second, while studying in a foreign country, we can travel widely, visiting famous scenic spots and making friends with the local people. Third, we can use the foreign language in our daily life so that our ability in that language may be improved quickly. But the most important is to learn advanced science and technology. For all these advantages, it is really worthwhile to go abroad for education.However, as everything has t wo sides, there are also some disadvantages in attending a foreign university. The most serious problem is the language barrier (障碍). Most of the students who are ready to go abroad do not prepare themselves well for the new language environment. As a result, on arriving there, they will find it difficult to understand what the instructors are saying in class. Besides, for not knowing about the customs and way of life of the local people, they may run into trouble in dea ling with various situations. Therefore, misunderstandings often arise. Furthermore, the cost of living is much higher than that in our country, so most students have to find part-time jobs in ord er to help support themselves. Faced with these difficulties, many students find themselves unable to pay full attention to their studies and some students may even fail in their courses and learn little.Therefore, given an opportunity to attend a school abroad, one must consider the factors carefully before making up his mind. On the one hand, it is a good thing to go and study abroad. But on the other hand, one must not neglect (忽视) the disadvantages.64. The following are all advantages of studying abroad EXCEPT ________.A. having more chances to get good jobsB. improving foreign language ability quicklyC. visiting well-known scenic spotsD. learning advanced science and technology65. The underlined word “instructors” in Paragraph 3 is closest in meaning to ________.A. neighborsB. teachersC. strangersD. classmates66. Why do some students find part-time jobs?A. Because they want to learn more skills in a different country.B. Because they want to make full use of their spare time.C. Because they are not interested in studying.D. Because they have to support themselves.67. The passage mainly tells us that ________.A. studying abroad is a good way to learn advanced science and technologyB. everything has two sidesC. people should think twice before going abroadD. going abroad has more advantages than disadvantagesＤThere is a lake near a forest in Sweden. The water in the lake is very clear and everything is quiet and still. On the far side of the water is some farmland and further away, across the field, is an old church built on a hill. It has just stopped raining. The brook flowing into the lake is full and there is still some half-melted (半融化的) snow from last winter on the ground.The reason why the water is so clear and everything is so quiet and still is that most of the animals and plants in and around the lake are dead. There are no birds because all the fish and insects, which the birds need for food, have disappeared. Many trees in the forest are losing their leaves and bark (树皮), and are sick and dying. Others were blown down by the strong winds of last winter. A farmer is working in a field planting something, but unless he plants a stronger kind of seed this year, the crop will be between 25 to 40 percent lower than a few years ago. The stones of the old church tower are turning to powder and unless the tower is repaired soon, it will fall down.All the death a nd destruction (破坏) in this place is caused by the smoke coming out of factories and poisonous gases from cars and trucks. And yet this silent lake is hundreds of kilometers away from the nearest factory and highway.68. Which season do you think it is?A. Spring.B. Summer.C. Autumn.D. Winter.69. Why are there no animals or birds in or around the lake?A. Because the weather is terribly cold.B. Because the lake is quiet.C. Because the area is seriously polluted.D. Because they have all been killed.70. Why does the farmer have to plant a stronger kind of seed?A. Because the soil is becoming less and less.B. Because few plant life can stand the weather there.C. Because the water in the lake can't be used to irrigate (灌溉) the field.D. Because the soil there is becoming unfit for farming.71. What do you think is the best title of the passage?A. A beautiful place of interest.B. A polluted place.C. A quiet place in Sweden.D. A faraway mountain area.ＥOne of the most difficult things for children to deal with when moving to a new town is leaving their friends and making new ones.We once moved and one of our new neighbors told us about a summer camp at the Recreation Center all the kids went to. My husband and I looked into it and we found it was unbelievably cheap. I had the kids sign up (报名) the next day so that they could know more kids there.Another thing we did was to have them sign up for sports when school started. They were happy to be on teams with new friends they made. This also gave me a chance to meet new people and from them I s ometimes got some useful ideas for my new books.If you're just moving to a new house in the same city you live in now, it won't really be a problem unless your kids are changing schools. If they are, it is a great idea to have them take the address book to school. Thus, your children won't feel “lost” without their old friends.If you're able to, over the summer vacation, try inviting the friend your child misses most to come and visit your new home for a week, or even a few weeks. I know this can be difficult if that child has to fly, but maybe you can work out a plan with the child's parents. Think how happy the kids will be when they meet!72. The author had her kids sign up for the summer camp mainly because _____.A. she could afford the costB. she was asked to do so by her kidsC. it could give her kids a chance to meet more kidsD. it could make the summer holiday not so boring73. What is probably the author?A. A housewife.B. A business woman.C. A teacher.D. A writer.74. What we can't learn from the passage is that ____.A. a summer camp at the Recreation Center was very cheapB. having the kids take part in sports is good for both the author and her kidsC. parents should ask their children not to think of their old friendsD. parents should create more chances for children to make new friends75. The purpose of the passage is to teach parents how to ______ when they move to a new place.A. get used to the new life in a short timeB. help their children make new friends and keep the old onesC. get along with their new neighborsD. help their children get used to the new school life第二节书面表达假如你在暑假期间参加了一个英语夏令营，在该夏令营结束时举行的晚会上，你要对这次夏令营进行简单总结，并表达感谢。
(好题)高中数学必修一第二单元《函数》检测题(包含答案解析)
一、选择题1．我们把定义域为[)0,+∞且同时满足以下两个条件的函数()f x 称为“Ω函数”：①对任意的[)0,x ∈+∞，总有()0f x ≥；②若0x ≥，0y ≥，则有()()()f x y f x f y +≥+成立，给出下列四个结论：（1）若()f x 为“Ω函数”，则()00f =；（2）若()f x 为“Ω函数”，则()f x 在[)0,+∞上为增函数；（3）函数()0,1,x Qg x x Q∈⎧=⎨∉⎩在[)0,+∞上是“Ω函数”（Q 为有理数集）；（4）函数()2g x x x =+在[)0,+∞上是“Ω函数”；其中正确结论的个数是（ ） A ．1B ．2C ．3D ．42．已知函数()f x =的定义域为R ，则实数m 的取值范围是（ ）A ．04m ≤≤B ．04m <≤C ．04m ≤<D ．04m <<3．以下说法正确的有（ ）（1）若(){},4A x y x y =+=，(){},21B x y x y =-=，则{}3,1AB =；（2）若()f x 是定义在R 上的奇函数，则()00f =； （3）函数1y x=的单调区间是()(),00,-∞⋃+∞； （4）在映射:f A B →的作用下，A 中元素(),x y 与B 中元素()1,3x y --对应，则与B 中元素()0,1对应的A 中元素是()1,2 A ．1个B ．2个C ．3个D ．4个4．若函数()f x =在[]1,3-上具有单调性，则实数a 的可能取值是（ ）A ．4-B ．5C ．14D ．235．设函数()y f x =的定义域D ，若对任意的1x D ∈，总存在2x D ∈，使得()()121f x f x ⋅=，则称函数()y f x =具有性质M .下列结论：①函数3x y =具有性质M ； ②函数3y x x =-具有性质M ；③若函数8log (2)y x =+，[]0,x t ∈具有性质M ，则510t =. 其中正确的个数是（ ） A ．0个B ．1个C ．2个D ．3个6．下列函数中，在其定义域内既是奇函数又是减函数的是（ ）A ．1y x=B ．y =C ．2x y =D ．||y x x =-7．已知定义在R 上的函数()f x 满足：对任意的[)()1212,2,x x x x ∈+∞≠，有()()21210f x f x x x ->-，且()2f x +是偶函数，不等式()()121f m f x +≥-对任意的[]1,0x ∈-恒成立，则实数m 的取值范围是（ ）A ．[]4,6-B ．[]4,3-C ．(][),46,-∞-+∞ D ．(][),43,-∞-⋃+∞8．已知()f x 在[],x a b ∈的最大值为M ，最小值为m ，给出下列五个命题：（ ） ①若对任何[],x a b ∈都有()p f x ≤，则p 的取值范围是(],m -∞. ②若对任何[],x a b ∈都有()p f x ≤，则p 的取值范围是(],M -∞. ③若关于x 的方程()p f x =在区间[],a b 有解，则p 的取值范围是[],m M . ④若关于x 的不等式()p f x ≤在区间[],a b 有解，则p 的取值范围是(],m -∞. ⑤若关于x 的不等式()p f x ≤在区间[],a b 有解，则p 的取值范围是(],M -∞. A ．4B ．3C ．2D ．19．已知函数()f x 的定义域为R ，()0f x >且满足()()()f x y f x f y +=⋅，且()112f =，如果对任意的x 、y ，都有()()()0x y f x f y ⎡⎤--<⎣⎦，那么不等式()()234f x f x -⋅≥的解集为（ ）A ．(][),12,-∞+∞ B ．[]1,2 C ．()1,2 D ．(],1-∞10．定义在(0,)+∞上的函数()f x 满足：()()1122120x f x x f x x x -<-且()24f =，则不等式()80f x x->的解集为（ ） A ．(2,)+∞ B ．()0,2C ．(0,4)D ．(,2)-∞11．已知函数f x （）满足当4x ≥时，f x （）=12x⎛⎫ ⎪⎝⎭；当4x <时，1f x f x =+（）（），则22log 3f +（）=A ．124 B ．112C ．18D ．3812．若函数()()12311ax f x x a x x ⎧>⎪=⎨⎪-+≤⎩是R 上的减函数，则实数a 的取值范围是（ ）A ．2,13⎛⎫⎪⎝⎭B ．3,14⎡⎫⎪⎢⎣⎭C ．23,34⎛⎤⎥⎝⎦D ．2,3⎛⎫+∞⎪⎝⎭二、填空题13．关于函数()f x =的性质描述，正确的是_________.①()f x 的定义域为[-1，0)∪(0，1]； ②()f x 的值域为R ； ③在定义域上是减函数； ④()f x 的图象关于原点对称.14．已知()13=f x x ，则不等式(21)f x -() 230f x ++>的解集为_________. 15．已知函数()225f x x ax =-+在(],2-∞上是减函数，且对任意的1x 、[]21,1x a ∈+，总有()()124f x f x -≤，则实数a 的取值范围是________. 16．设函数2222,0(),0x x x f x x x ⎧++=⎨->⎩，若(())2f f a =，则a =___________.17．已知函数()(12)3,1ln ,1a x a x f x x x -+<⎧⎨⎩＝的值域为R ，则实数a 的取值范围是________．18．已知函数()1f x x x =+，()12xg x m ⎛⎫=- ⎪⎝⎭.若[]11,2x ∀∈，[]21,1x ∃∈-，使()()12f x g x ≥，则实数m 的取值范围是______. 19．已知函数2()2f x x x a =-++，21()7log g x x=+，若对任意1[0,3]x ∈，总存在24x ⎤∈⎦，使得12()()f x g x ≤成立，则实数a 的取值范围是___________.20．已知函数()2()10f x x ax a =++>，若“()f x 的值域为[)0,+∞”为真命题，则()3f =________. 三、解答题21．设函数()f x 的定义域是(0,)+∞，且对任意的正实数,x y 都有()()()f xy f x f y =+恒成立，已知(2)1f =，且1x >时，()0f x >． （1）求12f ⎛⎫⎪⎝⎭的值； （2）判断()y f x =在(0,)+∞上的单调性，并给出你的证明；（3）解不等式2()(86)1f x f x >--．22．（1）已知()()43f x x a =-+时，当实数a 为何值时，()f x 是偶函数？（2）已知()g x 是偶函数，且()g x 在[)0,+∞是增函数，如果当[]1,2x ∈时()()6g x a g x +≤-恒成立，求实数a 的取值范围.23．对于函数()f x ，若在定义域内存在实数0x ，满足()()00f x f x -=-，则称()f x 为“M 类函数”（1）已知函数()23f x cos x π⎛⎫=- ⎪⎝⎭，试判断()f x 是否为“M 类函数”，并说明理由； （2）设()1423xx f x m +=-⋅-是定义域R 上的“M 类函数”，求实数m 的取值范围24．已知函数()21ax bf x x +=+（其中a >0）为奇函数． （1）求实数b 的值；（2）证明：()f x 在()01，上是增函数，在()1+∞，上是减函数； （3）若存在实数m ，n （0<m <n ），使得m ≤()f x ≤n 的解集为[]m n ，，求a 的取值范围．25．已知函数12()12x xa f x -⋅=+是R 上的奇函数(a 为常数)，()22.g x x x m m R =-∈+， （1）求实数a 的值；（2）若对任意12[]1x -∈，，总存在2]3[0x ∈，，使得12()()f x g x =成立，求实数m 的取值范围.26．已知函数()()222f x x ax a a =-+∈R .（1）若1a =，[]2,2x ∀∈-，()f x m 成立，求实数m 的取值范围;（2）若0a <，()()1212,0,x x x x ∀∈+∞≠，()()1212||2||f x f x x x ->-成立，求实数a 的最大值;（3）函数()()1g x f x x=+在区间()1,2上单调递减，求实数a 的取值范围.【参考答案】***试卷处理标记，请不要删除一、选择题 1．B 解析：B 【分析】利用“Ω函数”的定义依次判断即可，必须同时满足“Ω函数”的两个条件，才是“Ω函数”.【详解】解：对（1），由①得()00f ≥， 在②中令0x y ==， 即()()020f f =， 解得：()00f ≤，()00f ∴=，故（1）正确；对（2），当()0f x =时，满足①②，但在[)0,+∞不是增函数，故（2）错误； 对（3），当x ，y 都为正无理数时，不满足②，故（3）错误； 对（4），()2g x x x =+，当[)0,x ∈+∞时，min ()(0)00g x g ==≥， 即满足条件①，222()()()()20g x y g x g y x y x y x x y y xy +--=+++----=≥，即满足条件②，∴函数2()g x x x =+在[0,)+∞上是“Ω函数”，故（4）正确.故选：B. 【点睛】关键点点睛：本题解题的关键是理解“Ω函数”的定义，必须同时满足“Ω函数”的两个条件，才是“Ω函数”.2．C解析：C 【分析】由题意可知，对任意的x ∈R ，210mx mx ++>恒成立，然后分0m =和0m ≠，结合题意可得出关于实数m 的不等式组，由此可解得实数m 的取值范围. 【详解】由题意可知，对任意的x ∈R ，210mx mx ++>恒成立. 当0m =时，则有10>，合乎题意； 当0m ≠时，则有240m m m >⎧⎨∆=-<⎩，解得04m <<. 综上所述，04m ≤<. 故选：C. 【点睛】结论点睛：利用二次不等式在实数集上恒成立，可以利用以下结论来求解： 设()()20f x ax bx c a =++≠①()0f x >在R 上恒成立，则0a >⎧⎨∆<⎩；②()0f x <在R 上恒成立，则00a <⎧⎨∆<⎩；③()0f x ≥在R 上恒成立，则00a >⎧⎨∆≤⎩； ④()0f x ≤在R 上恒成立，则00a <⎧⎨∆≤⎩.3．B解析：B 【分析】 根据AB 为点集，可判断（1）的正误；根据奇函数的性质，可判断（2）的正误；分解反比例函数的单调性，可判断（3）的正误；根据映射的概念，可判断（4）的正误. 【详解】 （1）若(){},4A x y x y =+=，(){},21B x y x y =-=，则{}(3,1)AB =，所以（1）错误；（2）若()f x 是定义在R 上的奇函数，则()00f =，所以（2）正确； （3）函数1y x=的单调区间是(),0-∞和()0,∞+，所以（3）错误； （4）设A 中元素为(,)x y ，由题意可知1031x y -=⎧⎨-=⎩，解得12x y =⎧⎨=⎩，所以A 中元素是()1,2，所以（4）正确；所以正确命题的个数是2个， 故选：B. 【点睛】关键点点睛：该题考查的是有关命题的真假判断，在解题的过程中，关键点是要熟练掌握基础知识，此类题目综合性较强，属于中档题目.4．C解析：C 【分析】令函数()218g x x ax =-++，则只需使当[]1,3x ∈-时，()0g x ≥且单调，然后针对()3210a g ⎧≥⎪⎨⎪-≥⎩或()1230ag ⎧≤-⎪⎨⎪≥⎩两种情况讨论求解. 【详解】由题意可设()218g x x ax =-++，则当[]1,3x ∈-时，()218g x x ax =-++单调，且()0g x ≥恒成立，因为()218g x x ax =-++的对称轴方程为2a x =，则()3210a g ⎧≥⎪⎨⎪-≥⎩或()1230ag ⎧≤-⎪⎨⎪≥⎩，解得617a ≤≤或32a --≤≤，即[][]6,173,2a ∈--，则只有14满足题意． 故选：C ． 【点睛】本题考查根据复合函数的单调性求参数的取值范围，解答时注意不仅要使原函数在所给区间上单调，且必须使原函数在所给区间上有意义.5．C解析：C 【分析】根据函数性质M 的定义和指数对数函数的性质，结合每个选项中具体函数的定义，即可判断. 【详解】解：对于①：3xy =的定义域是R ，所以1212()()13x x f x f x +⋅==，则120x x +=.对于任意的1x D ∈，总存在2x D ∈，使得()()121f x f x ⋅=， 所以函数3xy =具有性质M ，①正确；对于②：函数3y x x =-的定义域为R ，所以若取10x =，则1()0f x =，此时不存在2x R ∈，使得12()()1f x f x ⋅=，所以函数3y x x =-不具有性质M ，②错误；对于③：函数8log (2)y x =+在[]0,t 上是单调增函数，其值域为[]88log 2,log (2)t +，要使得其具有M 性质，则88881log 2log (2)1log (2)log 2t t ⎧≤⎪+⎪⎨⎪+≤⎪⎩，即88log 2log (2)1t ⨯+=，解得3(2)8t +=，510t =， 故③正确； 故选：C. 【点睛】本题考查函数新定义问题，对数和指数的运算，主要考查运算求解能力和转换能力，属于中档题型.6．D解析：D 【分析】利用奇函数的定义和常见基本初等函数的性质，对选项逐一判断即可. 【详解】选项A 中，函数1y x =，由幂函数性质知1y x=是奇函数，且其在()(),0,0,-∞+∞两个区间上递减，不能说在定义域内是减函数，故错误；选项B 中，函数y =[)0,+∞，不对称，故不具有奇偶性，，且在定义域内是增函数，故错误；选项C 中，指数函数2xy =，22x x -≠，且22x x -≠-，故不是奇函数，故错误；选项D 中，函数22,0,0x x y x x x x ⎧-≥=-=⎨<⎩，记()y f x =，当0x >时，0x -<，故22(),()f x x f x x =--=，故()()f x f x -=-，当0x =时，(0)0f =，故()()f x f x -=-，当0x <时，0x ->，故22(),()f x x f x x =-=-，故()()f x f x -=-，综上，()y f x =是奇函数，又0x ≥时，2()f x x =-是开口向下的抛物线的一部分，是减函数，由奇函数性质知()y f x =在定义域R 上是减函数，故正确. 故选：D. 【点睛】本题解题关键是熟练掌握常见的基本初等函数的性质，易错点是分段函数奇偶性的判断，分段函数必须判断定义域内的每一段均满足()()f x f x -=-（或()()f x f x -=）才能判定其是奇函数（或偶函数）.7．C解析：C 【分析】根据已知条件可知()f x 在(,2]-∞上单调递减，在[2,)x ∈+∞上单调递增，由不等式在[]1,0x ∈-恒成立，结合()f x 的单调性、对称性即可求m 的取值范围.【详解】对任意的[)()1212,2,x x x x ∈+∞≠，有()()21210f x f x x x ->-，知：()f x 在[2,)x ∈+∞上单调递增，()2f x +是偶函数，知：()f x 关于2x =对称，∴()f x 在(,2]-∞上单调递减，在[2,)x ∈+∞上单调递增；∵不等式()()121f m f x +≥-对任意的[]1,0x ∈-恒成立，且3211x -≤-≤-， ∴max (1)(21)(3)f m f x f +≥-=-即可，而根据对称性有(1)(7)f m f +≥， ∴综上知：13m +≤-或17m +≥，解得(][),46,x ∈-∞-+∞，故选：C 【点睛】结论点睛：注意抽象函数单调性、对称性判断对任意的()1212,x x x x ≠：()()21210f x f x x x ->-有()f x 单调递增；()()21210f x f x x x -<-有()f x 单调递减；当()f x n +是偶函数，则()f x 关于x n =对称；思路点睛：对称型函数不等式在一个闭区间上恒成立：在对称轴两边取大于或小于该闭区间最值即可，结合函数区间单调性求解.8．B解析：B 【分析】这是一个对不等式恒成立，方程或不等式解集非空的理解，概念题．对各个选项分别加以判断，在①②中，得出①正确②错误，④⑤中得出⑤正确④错误，而不难发现③是一个真命题，由此可得正确答案. 【详解】对任何x ∈[a ，b]都有()p f x ≤，说明p 小于等于()f x 的最小值，①是正确的; 由于①正确，所以②是一个错误的理解，故不正确;关于x 的方程p =f (x ）在区间[a ，b ]上有解，说明p 应属于函数f (x ）在[a ，b ]上的值域[m ，M ]内，故③是正确的;关于x 的不等式p ≤f (x ）在区间[a ，b ]上有解，说明p 小于或等于的最大值，所以④是错误的，而⑤是正确的 正确的选项应该为①③⑤ 故选： B. 【点睛】关键点点睛：本题考查了命题的真假判断与应用，属于基础题．不等式或方程解集非空，只要考虑有解;而不等式恒成立说明解集是一切实数，往往要考虑函数的最值了．9．B解析：B 【分析】计算出()24f -=，并由()()()0x y f x f y ⎡⎤--<⎣⎦可得出函数()y f x =在R 上为减函数，再由()()234f x f x-⋅≥，可得出()()232f xx f -≥-，再由函数()y f x =在R 上的单调性可得出232x x -≤-，解出该不等式即可. 【详解】由于对任意的实数x 、y ，()()()f x y f x f y +=⋅且()0f x >. 令0x y ==，可得()()()000f f f =⋅，且()00f >，解得()01f =. 令y x =-，则()()()01f x f x f ⋅-==，()()1f x f x -=，()()1121f f -==. ()()()211224f f f ∴-=-⋅-=⨯=.设x y <，则0x y -<，由()()()0x y f x f y ⎡⎤--<⎣⎦，得()()f x f y >. 所以，函数()y f x =在R 上为减函数，由()()234f x f x-⋅≥，可得()()232f x x f -≥-.所以232x x -≤-，即2320x x -+≤，解得12x ≤≤. 因此，不等式()()234f x f x -⋅≥的解集为[]1,2.故选B. 【点睛】本题考查抽象函数的单调性解不等式，解题的关键就是将不等式左右两边转化为函数的两个函数值，并利用函数的单调性进行求解，考查分析问题和解决问题的能力，属于中等题.10．B解析：B 【分析】构造新函数()()g x xf x =，得出函数()g x 在(0,)+∞为单调递减函数，把()80f x x->，转化为()()220f xf x -<，得到()()2g x g >，结合单调性和定义域，即可求解. 【详解】 由题意，定义在(0,)+∞上的函数()f x 满足()()1122120x f x x f x x x -<-，设()()g x xf x =，可得()()12120g x g x x x -<-，所以函数()g x 在(0,)+∞为单调递减函数，因为()24f =，则()228f =， 不等式()80f x x ->，可化为()80xf x x-<，即()80xf x -<，即()()220f xf x -<，即()()2g x g >，可得20x x <⎧⎨>⎩，解得02x <<，所以不等式()80f x x->的解集为()0,2. 故选：B. 【点睛】本题主要考查了利用函数的单调性求解不等式，其中解答中根据已知条件，构造新函数，利用新函数的单调性和特殊点的函数值，得出不等式关系式是解答的关键，着重考查构造思想，以及推理与运算能力.11．A解析：A 【分析】根据232log 34<+<，()()222log 33log 3f f +=+可得，又有23log 34+> 知，符合4?x >时的解析式，代入即得结果. 【详解】因为函数f x （）满足当4x ≥时，f x （）=12x⎛⎫ ⎪⎝⎭； 当4x <时，1f x f x =+（）（），所()()()()22222log 3log 121log 12log 24f f f f +==+=以=21log 242=124，故选A ． 【点睛】本题主要考查分段函数的解析式、对数的运算法则，意在考查灵活应用所学知识解答问题的能力，属于中档题.12．C解析：C 【分析】由函数是R 上的减函数，列出不等式，解出实数a 的取值范围． 【详解】因为()f x 是R 上的减函数，故023033a a a a>⎧⎪-<⎨⎪-≥⎩，故2334a <≤，故选：C 【点睛】本题考查函数的单调性的应用，考查分段函数，属于中档题．二、填空题13．①②④【分析】求出函数的定义域值域判断①②根据单调性的定义判断③根据奇偶性的定义与性质判断④【详解】函数满足解得或故函数的定义域为故①正确当时当时所以函数值域为故②正确③虽然时函数单调递减当时函数单解析：①②④ 【分析】求出函数的定义域，值域判断①②，根据单调性的定义判断③，根据奇偶性的定义与性质判断④． 【详解】函数()f x =21011x x ⎧-⎪⎨+≠⎪⎩，解得10x -<或01x <，故函数的定义域为[1-，0)(0⋃，1]．故①正确．当[1x ∈-，0)时(][)(]2211,(),00,1x f x x ∈+∞⇒===-∞∈⇒，当(0x ∈，1]时，(][)220,,111x x ∈∈⇒+∞⇒()[0f x ===，)+∞，所以函数值域为R ，故②正确．③虽然[1x ∈-，0)时，函数单调递减，当(0x ∈，1]时，函数单调递减，但在定义域上不是减函数，故③错误．④由于定义域为[1-，0)(0⋃，1]，()11f x x x==+-，则()()f x f x -=-，()f x 是奇函数，其图象关于原点对称，故④正确．故答案为：①②④． 【点睛】本题通过对多个命题真假的判断，综合考查函数的单调性、值域、函数的定义域与对称性，属于难题.这种题型综合性较强，也是高考的命题热点，同学们往往因为某一处知识点掌握不好而导致“全盘皆输”，因此做这类题目更要细心、多读题，尽量挖掘出题目中的隐含条件，另外，要注意从简单的自己已经掌握的知识点入手，然后集中精力突破较难的命题.14．【分析】先利用幂函数性质和奇函数定义判断是R 上单调递增的奇函数再结合奇偶性和单调性解不等式即可【详解】由幂函数性质知时在是增函数故函数在是增函数又定义域是R 而故是R 上的奇函数根据奇函数对称性知在R 上解析：1,2⎛⎫-+∞ ⎪⎝⎭【分析】先利用幂函数性质和奇函数定义判断()f x 是R 上单调递增的奇函数，再结合奇偶性和单调性解不等式即可. 【详解】由幂函数性质知，01α<<时y x α=在[)0,+∞是增函数，故函数()13=f x x 在[)0,+∞是增函数，又()f x 定义域是R ，而()()()1133=f x x x f x =-=---，故()f x 是R 上的奇函数，根据奇函数对称性知，()f x 在R 上单调递增.故不等式(21)f x -() 230f x ++>即(21)f x -()() 2323f x f x >-+=--，故2123x x ->--，即12x >-，故解集为1,2⎛⎫-+∞ ⎪⎝⎭.故答案为：1,2⎛⎫-+∞ ⎪⎝⎭. 【点睛】 思路点睛：利用函数奇偶性和单调性解不等式问题：（1）()f x 是奇函数，图像关于原点中心对称，利用奇函数性质将不等式()()12f g x f g x ⎡⎤⎡⎤<⎣⎦⎣⎦形式，再利用单调性得到()1g x 和()2g x 的大小关系，再解不等式即可；（2）()f x 是偶函数，图像关于y 轴对称，利用偶函数性质将不等式()()12f g x f g x ⎡⎤⎡⎤<⎣⎦⎣⎦形式，再利用单调性得到()1g x 和()2g x 的大小关系，再解不等式即可.15．【分析】根据二次函数的单调性求得求得函数在区间上的最大值和最小值由题意可得出可得出关于实数的不等式进而可求得实数的取值范围【详解】二次函数的图象开口向上对称轴为直线由于函数在上是减函数则则所以函数在 解析：[]2,3【分析】根据二次函数()y f x =的单调性求得2a ≥，求得函数()y f x =在区间[]1,1a +上的最大值和最小值，由题意可得出()()max min 4f x f x -≤，可得出关于实数a 的不等式，进而可求得实数a 的取值范围. 【详解】二次函数()225f x x ax =-+的图象开口向上，对称轴为直线x a =，由于函数()225f x x ax =-+在(],2-∞上是减函数，则2a ≥，则()1,1a a ∈+，所以，函数()y f x =在区间[)1,a 上单调递减，在区间(],1a a +上单调递增， 所以，()()2min 5f x f a a ==-，又()162f a =-，()216f a a +=-，则()()()211220f f a a a a a -+=-=-≥，()()max 162f x f a ∴==-，对任意的1x 、[]21,1x a ∈+，总有()()124f x f x -≤，则()()()()22max min 625214f x f x a a a a -=---=-+≤，即2230a a --≤，解得13a -≤≤， 又2a ≥，则23a ≤≤，因此，实数a 的取值范围是[]2,3.故答案为：[]2,3. 【点睛】本题考查利用不等式恒成立求参数值，同时也考查了利用二次函数在区间上的单调性求参数，考查计算能力，属于中等题.16．【分析】先令则求解的值然后再分类讨论求解的值【详解】令则当时有无解当时有解得或所以或当时故无解；当时若则得若则即无解综上所述：故答案为：【点睛】本题考查分段函数的应用考查根据函数值求参难度一般解答时【分析】先令()f a t =，则()2f t =，求解t 的值，然后再分类讨论，求解a 的值. 【详解】令()f a t =，则()2f t =，当0t >时，有22t -=，无解， 当0t ≤时，有2222t t ++=，解得0t =，或2t =-， 所以()0f a =或()2f a =-，当()0f a =时，()2222110a a a ++=++>，20a -<，故 ()0f a =无解；当()2f a =-时，若0a >，则22a -=-，得a =若0a ≤，则2222a a ++=-，即2240a a ++=，无解，综上所述：a =【点睛】本题考查分段函数的应用，考查根据函数值求参，难度一般，解答时注意分类讨论思想的运用.17．【分析】先求出当时函数的值域根据函数的值域为R 可以确定函数在时的单调性以及左侧函数的值域的区间的右端点的值与右侧函数的值域的区间的左端点的值的大小关系这样可求出实数a 的取值范围是【详解】由题意知的值解析：11,2⎡⎫-⎪⎢⎣⎭【分析】先求出当1x 时，函数的值域，根据函数的值域为R ，可以确定函数在1x <时的单调性，以及左侧函数的值域的区间的右端点的值与右侧函数的值域的区间的左端点的值的大小关系，这样可求出实数a 的取值范围是 【详解】由题意知() 1y ln x x ≥＝的值域为[0，＋∞)，故要使()f x 的值域为R ，则必有23(1)y a x a ＝-+为增函数，且1230a a ≥-+，所以120a -＞且1a ≥-，解得112a ≤－＜，实数a 的取值范围是11,2⎡⎫-⎪⎢⎣⎭.【点睛】本题考查了已知分段函数的值域求参问题，考查了逻辑推理能力、数形结合能力.18．【分析】转化为可求得结果【详解】因为在上单调递增所以当时因为在上单调递减所以当时若使只要使即可即解得所以实数的取值范围为故答案为：【点睛】结论点睛：本题考查不等式的恒成立与有解问题可按如下规则转化：解析：3,2⎡⎫-+∞⎪⎢⎣⎭【分析】转化为()()12min min f x g x ≥可求得结果. 【详解】因为()f x 在[1,2]上单调递增， 所以当[]11,2x ∈时，()1522f x ≤≤， 因为()12xg x m ⎛⎫=- ⎪⎝⎭在[1,1]-上单调递减， 所以当[]21,1x ∈-时，()2122m g x m -≤≤-. 若[]11,2x ∀∈，[]21,1x ∃∈-，使()()12f x g x ≥， 只要使()()12min min f x g x ≥即可. 即122m -≤，解得32m ≥-，所以实数m 的取值范围为3,2⎡⎫-+∞⎪⎢⎣⎭. 故答案为：3,2⎡⎫-+∞⎪⎢⎣⎭. 【点睛】结论点睛：本题考查不等式的恒成立与有解问题，可按如下规则转化：一般地，已知函数()[],,y f x x a b =∈，()[],,y g x x c d =∈ （1）若[]1,x a b ∀∈，[]2,x c d ∀∈，总有()()12f x g x <成立，故()()2max min f x g x <； （2）若[]1,x a b ∀∈，[]2,x c d ∃∈，有()()12f x g x <成立，故()()2max max f x g x <； （3）若[]1,x a b ∃∈，[]2,x c d ∃∈，有()()12f x g x <成立，故()()2min min f x g x <； （4）若[]1,x a b ∀∈，[]2,x c d ∃∈，有()()12f x g x =，则()f x 的值域是()g x 值域的子集 ．19．【分析】由和的单调性求得它们的最大值由题意可得解不等式可得所求范围【详解】在递增递减可得在递减可得由对任意总存在使得成立可得则解得所以的取值范围是故答案为：【点睛】结论点睛：本题考查不等式的恒成立与解析：13,15⎛⎤-∞- ⎥⎝⎦【分析】由()f x 和()g x 的单调性求得它们的最大值，由题意可得()()max max f x g x ≤，解不等式可得所求范围. 【详解】2()2f x x x a =-++在[0]1，递增，[1]3，递减，可得()()11max f x f a ==+， 21()7log g x x =+在⎤⎦递减，可得()max 215g x g ===， 由对任意1[0,3]x ∈，总存在24x ⎤∈⎦，使得12()()f x g x ≤成立，可得()()max max f x g x ≤， 则2115a +≤，解得1315a ≤-， 所以a 的取值范围是13,15⎛⎤-∞- ⎥⎝⎦， 故答案为：13,15⎛⎤-∞- ⎥⎝⎦. 【点睛】结论点睛：本题考查不等式的恒成立与有解问题，可按如下规则转化：一般地，已知函数()[],,y f x x a b =∈，()[],,y g x x c d =∈ （1）若[]1,x a b ∀∈，[]2,x c d ∀∈，总有()()12f x g x <成立，故()()2max min f x g x <； （2）若[]1,x a b ∀∈，[]2,x c d ∃∈，有()()12f x g x <成立，故()()2max max f x g x <； （3）若[]1,x a b ∃∈，[]2,x c d ∃∈，有()()12f x g x <成立，故()()2min min f x g x <； （4）若[]1,x a b ∀∈，[]2,x c d ∃∈，有()()12f x g x =，则()f x 的值域是()g x 值域的子集.20．16【分析】二次函数的值域为得到求得值得解【详解】因为的值域为所以则又所以故答案为：16【点睛】二次函数的值域为得到是解题关键解析：16 【分析】二次函数()f x 的值域为[)0,+∞得到240a ∆=-=求得a 值得解 【详解】因为()2()10f x x ax a =++>的值域为[0,)+∞，所以240a ∆=-=，则2a =±.又0a >，所以2,a =.22()21,(3)323116f x x x f ∴=++∴=+⨯+=故答案为：16 【点睛】二次函数()f x 的值域为[)0,+∞得到0∆=是解题关键.三、解答题21．（1）1-； （2）函数单调递增，证明见解析； （3）3{|14x x <<或3}x >. 【分析】（1）利用赋值法，即可求得所求的函数值，得到答案；（2）首先判定函数为增函数，然后利用函数的单调性的定义和所给条件进行证明即可； （3）利用函数的单调性和所得函数值对应的自变量得到函数不等式，得出不等式组，即可求解. 【详解】（1）由题意，函数()f x 对任意的正实数x ，y 都有()()()f xy f x f y =+恒成立， 令1x y ==，可得(1)(1)(1)f f f =+，所以()10f =， 令12,2x y ==，可得1(1)(2)()2f f f =+，即11()02f +=，解得1()12f =-. （2）函数()f x 为增函数，证明如下： 设12,(0,)x x ∈+∞且12x x <， 令211,x x x y x ==，根据题意，可得2121()()()x f x f f x x +=，即2211()()()x f x f x f x -=，又由1x >时，()0f x >， 因为211x x >，可得21()0x f x >，即21()()0f x f x ->，即21()()f x f x >， 所以函数()y f x =在(0,)+∞上的单调性.（3）由题意和（1）可得11(86)1(86)()[(86)](43)22f x f x f f x f x --=-+=-=-， 又由不等式2()(86)1f x f x >--，即2()(43)f x f x >-，可得243430x x x ⎧>-⎨->⎩，解得314x <<或3x >，即不等式2()(86)1f x f x >--的解集为3{|14x x <<或3}x >. 【点睛】求解函数有关的不等式的方法及策略： 解函数不等式的依据是函数的单调性的定义，具体步骤：①将函数不等式转化为12()()f x f x >的形式；②根据函数()f x 的单调性去掉对应法则“f ”转化为形如：“12x x >”或“12x x <”的常规不等式，从而得解.利用函数的图象研究不等式，当不等式问题不能用代数法求解但其与函数有关时，常将不等式问题转化为两函数的图象上、下关系问题，从而利用数形结合求解. 22．（1）0a =；（2）62a -≤≤. 【分析】（1）当0a =时，由()43f x x =+判断，当0a ≠时，由()(),f a f a -的关系判断；（2）根据()g x 是偶函数，将()()6g x a g x +≤-，转化为 ()()6g x a g x +≤-，再根据()g x 在[)0,+∞是增函数，转化为[]1,2x ∈时，6x a x +≤-恒成立求解. 【详解】（1）当0a =时，()43f x x =+是偶函数，当0a ≠时，a a ≠-，而()()()420f a f a a --=≠，()f x 不可能是偶函数，所以当0a =时，()f x 是偶函数；（2）由()g x 是偶函数知()()g x a g x a +=+，()()66g x g x -=-，且x a +，60x -≥，因为()g x 在[)0,+∞是增函数，及()()6g x a g x +≤-，所以当[]1,2x ∈时，6x a x +≤-恒成立， 即当[]1,2x ∈时，6x a x +≤-恒成立，即当[]1,2x ∈时，66x x a x -≤+≤-恒成立， 即当[]1,2x ∈时，662a x -≤≤-恒成立，所以62a -≤≤. 【点睛】方法点睛：函数奇偶性与单调性求参数问题，当涉及到偶函数时，要利用()()()f x f x f x -==转化为求解.23．（1）是；答案见解析；（2）1m -. 【分析】（1）特殊值验证使得()()f x f x -=-即可；（2）因为函数满足新定义，则问题由存在问题转化为求函数值域问题，进而可以求解． 【详解】解：（1）因为()2cos()2cos()2(22323f πππππ-=--=+=⨯=()2cos()2223f πππ=-==()()22f f ππ-=-，所以存在02=x π使得函数()f x 为“M 类函数”；（2）由已知函数1()423x x f x m +=--满足：()()f x f x -=-， 则化简可得：442(22)60x x x x m --+-+-=⋯① 令222x x t -=+，则2442x x t -+=-，所以①可化为：2280t mt --=在区间[2，)+∞上有解可使得函数()f x 为“M 类函数”， 即18()2m t t=-在[2，)+∞有解，而函数18()2t t -在[2，)+∞上单调递增，所以当2t =时，有最小值为18(2)122-=-，所以1m -，故实数m 的取值范围为：[1-，)+∞． 【点睛】本题考查了新定义的函数问题以及函数的有解问题，涉及到求函数的值域问题. 求函数最值和值域的常用方法：(1)单调性法：先确定函数的单调性，再由单调性求最值；(2)图象法：先作出函数的图象，再观察其最高点、最低点，求出最值；(3)基本不等式法：先对解析式变形，使之具备“一正二定三相等”的条件后用基本不等式求出最值；(4)导数法：先求导，然后求出在给定区间上的极值，最后结合端点值，求出最值； (5)换元法：对比较复杂的函数可通过换元转化为熟悉的函数，再用相应的方法求最值． 24．（1）0；（2）证明见解析；（3）（1，2）． 【分析】（1）依题意可得()00f =，即可求出参数b 的值，（2）利用定义法证明函数的单调性，按照设元、作差、变形、判断符号、下结论的步骤完成即可；（3）依题意结合（2）中函数的单调性，即可得到方程组，即可求出参数的取值范围； 【详解】解：（1）由题意可知函数()21ax bf x x +=+的定义域为R ，且为奇函数，所以()00f b ==，经检验满足题意，所以b =0； （2）证明：由（1）知b =0，所以()211ax af x x x x==++，则任取12x x <，则12110x x ->，因为12x x <，所以当()01x ∈，时，210x x ->，12110x x -<，所以()()120f x f x -<，即()()12f x f x <，则()f x 在()01，上是增函数；当()1x ∈+∞，时，210x x ->，()()1f x +∞，，所以()()120f x f x ->，即()()12f x f x >，[]m n ，上是减函数，综上：()f x 在()01，上是增函数，在()1+∞，上是减函数； （3）由（2）知()f x 在()01，上是增函数，在()1+∞，上是减函数，又存在实数m ，n （0<m <n ），使得m ≤()f x ≤n 的解集为()221112amm m an m n a f n ⎧=⎪+⎪⎪=⎨+⎪⎪=≤⎪⎩，则221112a m a n a n ⎧=+⎪⎪=+⎨⎪≤⎪⎩，化简得221112a m a n a n⎧=+⎪⎪=+⎨⎪≤⎪⎩，因为0<m <n ，所以1<a <2，所以a 的取值范围为（1，2）．【点睛】函数的单调性是函数的重要性质之一，它的应用贯穿于整个高中数学的教学之中.某些数学问题从表面上看似乎与函数的单调性无关，但如果我们能挖掘其内在联系，抓住其本质，那么运用函数的单调性解题，能起到化难为易、化繁为简的作用.因此对函数的单调性进行全面、准确的认识，并掌握好使用的技巧和方法，这是非常必要的.根据题目的特点，构造一个适当的函数，利用它的单调性进行解题，是一种常用技巧.许多问题，如果运用这种思想去解决，往往能获得简洁明快的思路，有着非凡的功效. 25．（1）1；（2）82[,]35-. 【分析】（1）()f x 为R 上的奇函数，由()00f =得解；（2）由“任意[]11,2x ∈-，总存在[]20,3x ∈，使得()()12f x g x =成立”得到等价命题是 “()f x 在[]1,2-上的取值集合是()g x 在[]0,3上的取值集合的子集”，分别求出两个函数的值域得解. 【详解】（1）因为()f x 为R 上的奇函数， 所以()00f =，即102a-=，解得1a = （2）因为[]20,3x ∈，且()g x 在[]0,1上是减函数，在[]1,3上为增函数 所以()g x 在[]0,3上的取值集合为[]1,3m m -+.由122()11221x x xf x -==-+++得()f x 是减函数，所以()f x 在[]1,2-上是减函数所以()f x 在[]1,2-上的取值集合为31[,]53-.由“任意[]11,2x ∈-，总存在[]20,3x ∈，使得()()12f x g x =成立” ()f x 在[]1,2-上的取值集合是()g x 在[]0,3上的取值集合的子集， 即[]31[,]1,353m m -⊆-+. 则有315m -≤-，且133m +≥，解得：8235m -≤≤. 即实数m 的取值范围是82[,]35-.【点睛】探讨方程()()0f x g m -=解的存在性，通常可将方程转化为()()f x g m =，通过确认函数()f x 或()g m 的值域，从而确定参数或变量的范围；类似的，对于不等式()()0(0)f x g m -≥≤，也可仿效此法．26．（1）10m ≥（2）1-（3）158a ≥【分析】（1）转化为max ()m f x ≥，利用二次函数单调性求出最大值即可得解；（2）将不等式化为1222a x x +<+恒成立，利用12(0,)x x +∈+∞可解得结果； （3）因为211()()22g x f x x ax a x x=+=-++在区间()1,2上单调递减，设1212x x <<<，则12()()0g x g x ->，即121212a x x x x >+-对任意的1212x x <<<恒成立，根据1212111522224x x x x +-<+-=⨯可得1524a ≥，得158a ≥即为所求. 【详解】 （1）若1a =，22()22(1)1f x x x x =-+=-+在[2,1)-上递减，在(1,2]上递增，所以max ()(2)10f x f =-=，因为对[]2,2x ∀∈-，()f x m 即222x x m -+≤成立，所以max ()10m f x ≥=. （2）若0a <，()()1212,0,x x x x ∀∈+∞≠，()()1212||2||f x f x x x ->-成立，则22112212|2222|2||x ax a x ax a x x -+-+->-，即121212|||2|2||x x x x a x x -⋅+->-，因为0a <，12120,0,x x x x >>≠，所以1222x x a +->，即1222a x x +<+恒成立， 因为120x x +>，所以220a +≤，得1a ≤-，所以实数a 的最大值为1-.（3）211()()22g x f x x ax a x x=+=-++在区间()1,2上单调递减， 设1212x x <<<，则12()()g x g x -=22112212112222x ax a x ax a x x -++-+-- 1212121()(2)x x x x a x x =-+--0>对任意的1212x x <<<恒成立， 因为120x x -<，所以1212120x x a x x +--<，即121212a x x x x >+-对任意的1212x x <<<恒成立， 因为1212111522224x x x x +-<+-=⨯，所以1524a ≥，即158a ≥. 【点睛】 结论点睛：本题考查不等式的恒成立与有解问题，可按如下规则转化： ①若()k f x ≥在[,]ab 上恒成立，则max ()k f x ≥；②若()k f x ≤在[,]a b 上恒成立，则min ()k f x ≤；③若()k f x ≥在[,]a b 上有解，则min ()k f x ≥；④若()k f x ≤在[,]a b 上有解，则max ()k f x ≤；。
高中语文 人教版 必修一 第二单元测试卷 Word版含解析
第二单元测试卷时间：90分钟分值：100分．依次填入下列各句画线处的成语，最恰当的一组是(3分)()①父母是孩子的启蒙老师，也是孩子成长的终身老师。
如何维持老师身份的新鲜感，大家________，互不相让，这使得年轻的父母们无所适从。
②对于什么是企业人才，与会者________，但有一点得到公认：引领未来企业发展的人才必须具备领导才能、谈判能力和全球思维三大条件。
③蒙娜丽莎的神秘微笑为什么是最美的？500多年来，人们一直对此________。
即便是同一个观者，在不同的时间去看，感受似乎都有所不同。
A．莫衷一是各抒己见各执一词B．各执一词各抒己见莫衷一是C．莫衷一是各执一词各抒己见D．各抒己见莫衷一是各执一词解析：“各执一词”指各人坚持各人的说法，意见不一致，但都有明确的观点或态度。
“莫衷一是”强调很多人意见各不相同，众说纷纭。
“各抒己见”指各人充分表达自己的意见。
①句中有“互不相让”，说明大家都坚持自己的观点。
“各执一词”最合适。
②说有一点是公认的，“各执一词”“莫衷一是”强调的是不同，可见只有“各抒己见”才符合。
③句中“莫衷一是”最合适。
答案：B2．下列各句中，没有语病的一句是(3分)()A．目前中国经济流动性过剩的主要原因一是外汇储备增长过快，二是美元的过量发行导致了美元的泛滥和全球流动性过剩所致。
B．散文创作空前繁荣，文化环境的多样化，正为散文作者的成熟提供了丰沃的土壤，这是好事，它能提高人们的文化品位。
C．波音公司方面信心满满地把波音787称为“梦想客机”，是代表该公司最高科技的机种，自启用以来却出现了一系列故障。
D．教育部通过“一号文件”明确表示，今年的教育改革将采取联合调研、部门会商的方式，共同研究解决改革中出现的重大问题。
解析：A“原因是……所致”句式杂糅，可删除“所致”。
B“正”表正在发生，“了”表已经完成，二者联用不合逻辑。
C偷换主语，可将第一个分句改为“波音787被波音公司方面信心满满地称为‘梦想客机’”。
高一数学必修一第二单元测试题及答案
高一数学必修一第二单元测试题及答案一、选择题1.(20 13年高考四川卷)设集合a={1,2,3},集合b={ -2,2},则a∩b等于( b )(a) (b){2}(c){-2,2} (d){-2,1,2,3}解析:a∩b={2},故挑选b.(a){2} (b){0,2}(c){-1,2} (d){-1,0,2}解析:依题意得集合p={-1,0,1},(a)1个 (b)2个 (c)4个 (d)8个4.(年高考全国新课标卷ⅰ)已知集合a={x|x2-2x>0},b={x|-(a)a∩b= (b)a∪b=r解析:a={x|x>2或x<0},∴a∪b=r,故挑选b.5.已知集合m={x ≥0,x∈r},n={y|y=3x2+1,x∈r},则m∩n等于( c )(a) (b){x|x≥1}(c){x|x>1} (d){x|x≥1或x<0}解析:m={x|x≤0或x>1},n={y|y≥1}={x|x≥1}.∴m∩n={x|x>1},故选c.6.设子集a={x + =1},子集b={y - =1},则a∩b等同于( c )(a)[-2,- ] (b)[ ,2](c)[-2,- ]∪[ ,2] (d)[-2,2]解析:集合a表示椭圆上的点的横坐标的取值范围a=[-2,2],集合b表示双曲线上的点的纵坐标的取值范围b=(-∞,- ]∪[ ,+∞),所以a∩b=[-2,- ]∪[ ,2].故选c.二、填空题7.( 年高考上海卷)若集合a={x|2x+1>0},b={x||x-1|<2},则a∩b=.解析:a={x x>- },b={x|-1所以a∩b={x -答案:{x -解析:因为2∈a,所以 <0,即(2a-1)(a- 2)>0,Champsaura>2或a< .①若3∈a,则 <0,即为( 3a-1)(a-3)>0,解得a>3或a< ,①②挑关连得实数a的值域范围就是∪(2,3].答案: ∪(2,3]若a≠0,b=(- ),∴- =-1或- =1,∴a=1或a=-1.所以a=0或a=1或a=-1组成的集合为{-1,0,1}.答案:{-1,0,1}10.已知集合a={x|x2+ x+1=0},若a∩r= ,则实数m的取值范围是.解析:∵a∩r= ,∴a= ,∴δ=( )2-4<0,∴0≤m<4.答案:[0,4)11.已知集合a={x|x2-2x-3>0},b={x|x2+ax+b≤0},若a∪b=r,a∩b={x| 3解析:a={x|x<-1或x>3},∵a∪b=r,a∩b={x|3∴b={x|-1≤x≤4},即方程x2+ax+b=0的两根为x1=-1,x2=4.∴a=-3,b=-4,∴a+b=-7.答案:-7三、解答题12.未知子集a={-4,2a-1,a2},b={a-5,1-a,9},分别谋适宜以下条件的a的值.(1)9∈(a∩b);(2){9}=a∩b.解:(1) ∵9∈(a∩b),∴2a-1= 9或a2=9,∴a=5或a=3或a=-3.当a=5时,a={-4,9,25},b={0,-4,9};当a=3时,a-5=1-a=-2,不满足集合元素的互异性;当a=-3时,a={-4,-7,9},b={-8,4,9},所以a=5或a=-3.(2)由(1)所述,当a=5时,a∩b={-4,9},相左题意,当a=-3时,a∩b={9}.所以a=- 3.13.已知集合a={x|x2-2x-3≤0};b={x|x2-2mx+m2-4≤0,x∈r,m∈r}.(1)若a∩b=[0,3],谋实数m的值;解:由已知得a={x|-1≤x≤3},b={x|m-2≤x≤m+2}.(1)∵a∩b=[0,3],∴∴m=2.∴m-2>3或m+2<-1,即m>5或m<-3.14.设u=r,子集a={x |x2+3x+2=0},b={x|x2+(m+1)x+m=0},若解:a={x|x=-1或x=-2},方程x2+(m+1)x+m=0的根是x1=-1,x2=-m,当-m=-1,即m=1时,b={-1},当-m≠-1,即m≠1时,b={-1,-m},∴-m=-2,即m=2.所以m=1或m=2.集合的三个特性(1)无序性指集合中的元素排列没有顺序，如集合a={1,2}，集合b={2,1}，则集合a=b。
人教版高中英语选择性必修一第二单元检测卷
UNIT 2 LOOKING INTO THE FUTUR单元检测卷第一部分阅读（共两节，满分50分）第一节（共15小题；每小题2.5分，满分37.5分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项。
ASTEM is short for Seience, Technology, Engineering and Math education. These camps provide the skills needed to succeed in our technological society.Steve & Kate's CampSteve& Kate's Camp was founded on the belief that when you trust kids, they learn to trust themselves, and develop creative confidence that will help them unleash（释放）their true potential. It offers a safe，judgment free environment where kids can be themselves, explore their passions, and make a few mistakes along the way. Phone:415-389-5437App CampAsheville School is offering a unique app camp experience to teenagers across the U.S. and abroad who are interested in learning how to make exciting new apps for the iPhone and iPad. Students will learn about Apple'sSwift programming language and learn about Apple's new AR technology. Phone: 828-254-6345Game Camp NationHarness（利用）your child＇s energy for video games to fuel their future, strengthen self-confidence and make new friends. Creativity, Critical thinking &Communication: we emphasize the 3Cs needed for success in today's media-driven world. Hands-on projects spark curiosity. Our groups are intentionally kept small, and our staff encourage the kinds of peer interaction that easily make friends. Phone:619-446-6495Camp MotorsportFor the camper who loves to hear those famous words“Start your engines!”, Camp Motorsport offers the exciting motor sport focusing on summer camp programs for girls and boys aged 9 to 17. In addition to gaining valuable seat time, campers get hands-on experience with the STEM aspects of automotive design. In addition to driving,Camp Motor sport still has all the fun summer camp activities campers expect including a private lake with swimming, boats, and gaga ball just to name a few.Phone: 888-836-12121.Which camp will you choose if you want to take program courses?A.Steve & Kate's Camp.B.Game Camp Nation.C.Camp Motorsport.D.App Camp.2.What number will you call if you want to have much funafter joining the camp?A.619-446-6495.B.828-254-6345.C.888-836-1212.D.415-389-5437.3.What do Steve & Kate's Camp and Game Camp Nation have in common?A.They both appeal to learners full of curiosity.B.They both make learners become confident.C.They are both free of charge for teenagers across the U.S.D.They are both popular with programming language learners.BAt school, I was in the top set for maths. My teachers recommended that I study economics and statistics as my A-level subjects, but I had my mind set on a life fulfilled by the arts.In fact, I was a victim of a gender stereotype made stronger since birth, that men do science and maths and women do arts or languages. Computer science,technology and physics just did not figure in my teenage world view.Nobody in my school chose to study those subjects.Reality struck hard when I began attending job interviews and interviewers would say:“It's great that you speak foreign languages, but what else do you do?”Nobody asked my friends who had studied science or technology those questions.A survey recently showed that three of the best-paid jobs for women are in the technology sector. It's a sector that really can change the world. We must show girls that technology has an effect on every industry out there, from fashion to architecture to journalism. Anybody can learn code and these days it's as important as reading and writing.I've realized that at university I'd achieved the wrong kind of literacy. Not being able to learn code limits your impact on the world far more than ignorance of great literature.Now I have a five-year-old daughter. I don't want her to blindly follow gender roles the way I did.I want her to know the fact that a science or technical degree will not limit her creativity but expand it and broaden her horizons far more than my arts background could. I'm exposing her to Minecraft and apps, which help improve analytical thinking and problem solving skills. I'm hoping that my daughter will discover and accept her potential in science and want to change the world.4.What does the underlined phrase "gender stereotype" in Paragraph 2 refer to?A.Personal learning style.B.Sex characteristic.C.Conventional sex concept.D.Profession difference.5.According to the author, which may be the benefit of learning science?A.Increasing job possibility.B.Winning popularity.C.Improving language competence.D.Enriching imagination.6.How did the author feel for her major choice?A.Satisfied.B.Active.C.Discouraged.D.Regretful.7.What may be the best title for the text?A.Art or Science, Either is OKB.Good Subjects,Good FutureC.Girls, Choose More WiselyD.Catch Chances,Change the WorldCFor riders of the Lopifit, getting from A to B is as easy as putting one foot in front of the other,with its unusual design helping users to ride around by walking.Designed by Dutchman Bruin Bergmeester, the electric walking bike called Lopif it is a mixture between a scooter（踏板车），an electric bike and a treadmill（跑步机）.According to Lopifit's website, bike lover Bergmeester came up with the idea while training in the gym, wondering:“How can I use the treadmill outdoors?What about a treadmill on wheels?”Four years ago the first Lopifit was created in the Netherlands, now the Lopifit firm is selling the bikes to several countries, including the United States, Mexico and the Caribbean.The bikes use a motor to support the treadmill, sousing the bikes takes “no more effort...than a walk in the park”. As the rider walks，sensors（传感器）record the turning treadmill and kick the motor into gears（齿轮）to support the movement and set the wheels in action.Lopifit＇s bikes come with a heavy price tag（价格标签），at ＄2,495（£ 1,980）per bike．But bikers can choose their walking bike with a series of colours.At present, the company is struggling to keep up with the orders from all over the world. Bruin Bergmeester,CEO of the company says,“Our goal is to make the electric walking bike available for as many people as possible. We want to change the way people move. We wish that everyone can benefit from a greener and cleaner way of transportation that naturally improves your health.”8.When did Bruin Bergmeester come up with the idea of the Lopifit bike?A.While he was training on a treadmill in the gym.B.While he was putting one foot in front of the other.C.While he was mixing a scooter and an electric bike.D.While he was using unusual design to help users.9.What does the fifth paragraph mainly talk about?A.How to use a motor to support the treadmill.B.How to use the electric walking bike in the park.C.How the electric walking bike really works.D. How sensors kick the motor into gears on the treadmill.10.What can we learn from the last paragraph?A.The Lopifit bikes are getting more and more popular.B.The Lopifit bikes can be available to many people naturally.C.The Lopifit company hopes to help many more people walk.D.The Lopifit company is struggling with Bruin Bergmeester.11.Where does this text most probably come from?A.A TV interview.B.A newspaper.C.A science textbook.D.A novel.DIf you could change your child's DNA in the future to protect them against diseases, would you? It could be possible because of technology known as CRISPR-Cas, or just CRISPR.CRISPR involves a piece of RNA, a chemical messenger, designed to work on one part of DNA; it also uses an enzyme（酶）that can take unwanted genes out and put new ones in, according to The Economist. There are other ways of editing DNA, but CRISPR will do it very simply, quickly, and exactly.The uses of CRISPR could mean that cures are developed for everything from Alzheimer's disease to cancer to HIV. By allowing doctors to put just the right cancer-killing genes into a patient's immune system, the technology could help greatly.The US' National Academy of Sciences plans to discuss questions about CRISPR＇s ethics（伦理问题）.For example, CRISPR doesn't work properly yet. As well as cutting the DNA it is looking for, it often cuts other DNA,too. In addition, we currently seem to have too little understanding of what DNA gives people what qualities.There are also moral questions around “playing God". Of course, medicine already stops natural things from happening-for example, it saves people from infections. The opportunities to treat diseases make it hard to say we shouldn't keep going.Also,according to The Economist, gene editing may mean that parents make choices that are not obviously in the best interests of their children: “Deaf parents may prefer their children to be deaf too; parents might want to make their children more intelligent at all costs.”In the end, more research is still needed to see what we can and can't do with CRISPR. “It's still a huge mystery how we work," Craig Mello, a UMass Medical School biologist and Nobel Prize winner, told The BostonGlobe,"We're just trying to figure out this amazingly complicated thing we call life."12.What is the passage mainly about?A.What we can and can't do with CRISPR.B.The advantages of CRISPR and arguments about its ethics.C.How CRISPR was developed by scientists.D. Scientists' experiments of using CRISPR to edit human embryos.13.What does the writer mean by saying “playing God" in Paragraph 5?A.Playing jokes on religious people.B.Asking God to help deal with moral questions.C.Following the instructions of God.D.Doing things that go against nature.14.According to the passage, the technology of CRISPRA.is very safe because it only cuts the DNA it is looking forB.is very helpful to cure people of any diseaseC. could cause parents to make unwise choices for their childrenD.could help us understand how complicated life is15.What is the author's attitude towards CRISPR?A.Objective.B.Worried.C.Negative.D.Supportive.第二节（共5小题；每小题2.5分，满分12.5分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
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高一语文必修一文言文知识点梳理检测
满分150分，及格140分，40分钟做完
一．找出句中的通假字并解释。
（15分）
1.共其乏困（通____，________）
2.秦伯说（通____，________）
3.失其所与，不知（通____，________）
4. 今日往而不反者（通____，_______ _）
5.燕王诚振怖大王之威（通____，________）
6.秦王还柱而走（通____，________）
7.卒起不意，尽失其度（通____，________）
8.距关，毋内诸侯（通___，_________）（通， ____ ）
9.要项伯（通____，________）
10.不敢倍德（通____，_____ ___）
11.不可不蚤来（通____，________）
12.令将军与臣有郤（通___，________）
13. 因击沛公于坐（通____，________）
14.燕王拜送于庭（通____，________）
15. 图穷而匕首见（通____，________）
二．找出古今异义词并解释古义。
（10分）
1.行李之往来（古义：________________ ）
2.樊将军仰天太息流涕（古义：__________）
3.持千金之资币物（古义：________________）
4.樊将军以穷困来归丹（古义：__________）
5.樊於期偏袒扼腕而进（古义：________________）
6.沛公居山东时（古义：________________）
7.约为婚姻（古义：________________）
8.备他盗之出入与非常也（古义：________________）
9.将军战河北（古义：______________）
10. 而伤长者之意（古义：_________ ）
三.找出活用词并解释。
（6分）
1.函封之（）
2.项伯杀人，臣活之（）
3.群臣怪之（）
4.范增数目项王（）
5.素善留侯张良（）
6.其人居远（）
四．一词多义（解释词义与用法）（24分）
1、兵：①不得持尺兵（）②不及召下兵（）③秦兵旦暮渡易水（）
2、顾：①顾计不知所出耳（）②荆轲顾笑武阳（）③三顾臣与草庐之中（）
④大行不顾细谨（）
3、见：①秦王必喜而见臣（）②而燕见陵之耻除矣（）③私见张良，具告以事（）
④图穷而匕首见（）
4、举：①愿举国为内臣（）②举所佩玉块以示之者三（）③是以众议举宠为督促（）
④今亡亦死，举大计亦死（）
5、若：①若使烛之武见秦君（）②徐公不若君之美也（）③仿佛若有光（）④若入前为寿（）
6、胜：①沛公不胜杯杓（）②刑人如恐不胜（）③何可胜道也哉（）
④此时无声胜有声（）⑤余观夫巴陵胜状在洞庭一湖（）
五．重点实词、虚词（解释加点词）（20分）
1. 臣之．壮也，犹不如人（） 2．郑既．知亡矣（） 3．且君尝为晋君赐．矣（）4．朝济．而夕设版焉（） 5．唯．（）君图之 6．进兵北略．地（）7．愿足下更．虑之（） 8．以．试人，血濡缕（） 9．厚遗．秦王宠臣中庶子蒙嘉（）
10．比．诸侯之列（） 11．愿大王少．（）假借
．．（）之 12．乃引．（）
其匕首提．（）秦王 13．旦日飨．（）士卒 14．料．（）大王士卒足以当．（）项王乎15．君安．（）与项伯有故．（） 16．然不自意．（）能先入关破秦 17．披．（）帷西向立18．卮酒安足．（）辞 19．窃．（）为大王不取也 20．会．（）其怒，不敢献
六．解释下列文言虚词意义和用法。
（24分）
1. 以①以其无礼于晋( ) ②敢以烦执事( ) ③越国以鄙远
( )④焉用亡郑以陪邻？ ( ) ⑤具告以事（）
2. 焉①子亦有不利焉。
( ) ②焉用亡郑以陪邻？ ( ) ③若不阙秦，将焉取之( ) ④朝济而夕设版焉（）
3．乃①乃遂私见樊於期。
( ) ②度我至军中，公乃( )
③乃为装遣荆轲。
( ) ④乃今
．．得闻教。
( )
4．为①旦日飨士卒，为击破沛公军( ) ②皆为龙虎，成五采。
( )③谁为大王为此计。
( ) ④窃为大王不取也 ( ) ⑤如今人方为刀俎，我为鱼肉
( )⑥何辞为？( ) ⑦不者，若属皆且为所虏！( )
5．之①项伯乃夜驰之沛公军( ) ②公从之( )③臣之壮也，犹不如人。
( ) ④夫晋，何厌之有？ ( ) ⑤顷之未发( )
七．特殊句式判断（翻译下列句式，写出句式的类型，思考并归纳各类句式的特点，省略句的调整补足到位）（18分）
（一）1、是寡人之过也。
2、以乱易整，不武。
3、楚左尹项伯者，项羽季父也。
4、今人有大功而击之，不义也。
5、沛公之参乘樊哙者也。
6、此亡秦之续耳。
7、人方为刀俎，我为鱼肉。
（二）1、夫晋，何厌之有？
2、以其无礼于晋。
3、太子及宾客知其事者。
4、大王来何操？
5、沛公安在？
（三）1、晋军函陵。
2、敢以烦执事。
3、夫今樊将军，秦王购之金千斤，邑万家。
（四）1、父母宗族，皆为戮没。
2、而燕见陵之耻除矣。
3、若属皆且为所虏。
八．文言翻译：（33分）
1、越国以鄙远，君知其难也，焉用亡郑以陪邻？
2、既东封郑，又欲肆其西封，若不阙秦，将焉取之？
3、微太子言，臣愿得谒之，今行而无信，则秦未可亲也。
4、然则将军之仇报，见陵之耻除矣。
5、沛公奉卮酒为寿，约为婚姻，曰：“吾入关，秋毫不敢有所近，籍吏民封府库，而待将军。
所以遣将守关者，备他盗之出入与非常也。