c语言程序设计15题

1.基础题#include<stdio.h>main(){int a,b;for(a=1,b=1;a<=100;a++){if(a%3==1){b+=3;continue;if(b>=20)break;}b-=5;}printf("%d\n",a);}2改错题：输入asdfg时，输出asdfggfdsa。

#include <stdio.h>#include <string.h>main(){ char s[80],t[80];int i, sl;printf("\nPlease enter string s:");scanf("%s", s);sl = strlen(s);/************found************/for( i=0; i<=sl; i++)t[i] = s[i];for (i=0; i<sl; i++)t[sl+i] = s[sl-i-1];/************found************/t[sl+i]=t[sl-i-1]=s[sl];printf("The result is: %s\n", t);}3．填空题：输入m，求1-m中哪些数可以分为两个相等的素数之和。

如m=15，输出4=2+2 6=3+3 10=5+5 14=7+7.#include <stdio.h>main( ){int M,t,i,M1,n=0;printf("Please enter a number:") ;/************found************/for(t=2;t<=M;t+=2){M1=t/2;for(i=2;i<M1;i++)if(M1%i==0)break;/************found************/if(i=M1-M1%i){printf("%d=%d+%d ",t,M1,M1);n++;} if(n%5==0) printf("\n");}}4．s=m!/(n!*(m-n)!),已知m=10,n=4。

#include <stdio.h>void NONO (void);int fact(int i){int p=1,j;/***********begin***********/for(j=1;j<=i;j++)p*=j;/***********end************/return p;}main(){int m=10,n=4,s,p1,p2,p3;/***********begin***********/p1=fact(m);p2=fact(n);p3=fact(m-n);s=p1/(p2*p3);/***********end************/printf("s=%d\n",s);NONO();}void NONO (void ){FILE *wf ;int s;wf = fopen("out1.dat","w");s = fact(10)/(fact(4)*fact(6));fprintf(wf, "s=%d\n",s);fclose(wf);5．基础题（好像没错）#include<stdio.h>main(){int i,j,k,n;printf("请输入一个3位数:\n");scanf("%d",&n);i=n/100;j=n/10-i*10;k=n%10;if(n==i*i*i+j*j*j+k*k*k)printf("该书是水仙花数!\n");elseprintf("该书不是水仙花数!\n");}6．一元以下硬币有一、二、五角，列举出将一元兑换成硬币的所有兑换方法。

#include <stdio.h>#include <stdlib.h>#include <math.h>main(){ int i,j,k;/************found************/for(i=0;i<=2;i++)for(j=0;j<=5;j++)for(k=0;k<=10;k++)/************found************/{ if(i*5+j*2+k*1==10)printf("%d,%d,%d\n",i,j,k);}}7填空题:将a[i]={1 2 3 4 5 6 7 8 9 10}倒序输出。

#include <stdio.h>main( ){ int i,a[10],t;for(i=0;i<10;i++)a[i]=i+1;/**************found************/for(i=0;i<=5;i++){t=a[i];/**************found************/a[i]=a[9-i];}for(i=0;i<10;i++)printf("%5d",a[i]);printf("\n");}8.程序题求矩阵最大值并输出。

#include <conio.h>#include <stdio.h>void nono(int max);int fun(int a[3][3]){int i,j,max=0;/***********begin***********/for(i=0;i<3;i++){for(j=0;j<3;j++)if(max<a[i][j])max=a[i][j];}return max;/************end************/}main(){ int a[3][3]={1,2,3,4,9,5,7,8,6};int i,j,max;printf("array is:\n");for(i=0;i<3;i++){for(j=0;j<3;j++)printf("%5d",a[i][j]);printf("\n");}max=fun(a);printf("Result is: %d\n",max);nono(max);}void nono(int max){FILE *f;f=fopen("out1.dat","w");fprintf(f,"Result is :%d\n",max);fclose(f);}9将【m，n】之间的数放到数组a中，并输出素数。

（改错题）main(){ int a[100],i,j,k,m,n,c=0;printf("Please enter m,n(m<n):");scanf("%d,%d",&m,&n);/************found************/for ( i=m; i<=n; i++){k=sqrt(i);for ( j=2; j<=k; j++)/************found************/if (i % j == 0)break;if(j >= k+1)a[c++] = i;}for (i=0; i<c; i++){ printf("%4d",a[i]);if ((i+1) % 4 == 0) printf("\n");}}10求x，y的最大公约数。

（填空题）#include <math.h>#include <conio.h>#include <stdio.h>main(){ int x,y,t,i;printf("Please enter two numbers:");scanf("%d,%d",&x,&y);if(x < y){t = x; x = y; y = t;}t = x % y;while( t ){ x = y;/************found************/y=t ;t = x % y;}/************found************/printf("max is : %d",y);}11输入整数x（x=45），调用函数fun后，统计该书中偶数的个数n#include "conio.h"#include "stdlib.h"void NONO( int y);int fun(int x) ;main(){ int x,n;printf("请输入一个任意整数：");scanf("%d",&x);n=fun(x);printf("该数中偶数的个数是：%d",n);NONO(n);}int fun(int x)/************begin************/ {int m,n=0;while(x!=0){m=x%10 ;If(m%2==0)n++;x=x/10;}return n;}/************end************/void NONO( int y){ FILE *f;f=fopen("out1.dat","w");fprintf(f,"s=%d\n",y);fclose(f);}12基础题#include<stdio.h>main(){char str[80];int a,i,num;printf("输入一个字符串：");gets(str);num=0;for(i=0;str[i]!='\0';i++)if(str[i]==’a’)printf("字符串中有%d个字母a\n",num);}13求1！+2！+3!+·······+15！（改错题）#include <stdio.h>#include <stdlib.h>#include <math.h>main()/*************found**************/{ double s,t;int n,i;s=1;t=1;/*************found**************/for(n=1;n<=15;n++){for(i=1;i<=n;i++)t=t*i;s=s+t;}printf("1!+3!+5!+ … +15!=%e\n",s);}14输出数列：1，1，2，3，5，8，·······的前20项的项值，每行5个数，列宽为8.（填空题）#include "stdio.h"main(){ long int f[20]={1,1};int i;/**************found************/printf("%8ld %8ld",f[0],f[1]);for(i=2;i<20;i++){f[i]=f[i-1]+f[i-2];/**************found************/if(i%8==0) printf("\n");printf("%8ld",f[i]);}printf("\n");}15将4位的整数m拆开，然后按相反顺序输出，没输出一位数后留两个空格。