《土力学与基础工程》第三版(赵明华)课后习题答案

mw = wm wms = wd s
w
m = ms + mw = d s ( (1 1 + w) 1
d d
=
ms v
=
ds w 1+ e sr = vw vv
2
100% 0%
sr =
wd s ⇒ wd s = sr e e
w
r= g=
m d (1 + w) g= s v 1+ e n=
g=
d s (1 + w)rw d s wrw + d s rw sr erw + d s rw = = 1+ e 1+ e 1+ e sr = vw vv
∴
Q 0.67> Dr >0.33
2.7 40%
d
=1.66g/ cm3 ,
d s =2.69 w e= ds
d w
? −1 = 2.69 ∗ 1 − 1 = 0.620 1.66
= 1.66 g / cm3 d s = 2.69 sr = 40%
w= 2.8
sr e 0.40 ∗ 0.62 *100%=9.2% = ds 2.69 w=28.5%, r=19kN/ m3 , d s = 2.68 ,
w
vv = d s vs w
Qe =
vv d s vs w =2.68 2 68*0.32=0.86 = = d s w =2 vs vs
d s (1 + w) 1+ e
w
∴ r=
g=
2.68 × 1+0.32 *10=19kN/ m3 1 + 0.86
2.6 0.461
1.77g/ cm3 , 0.943
mm % 1 2 3 4 1 50% 2
>2 9.4
2
0.5
0 0.5 .5 21
0.25 0 .25 0
0.2 0.2
0.075 0 .075 37.5
<0.075 13.5
18.6 8.6
3m 0.075mm 75mm d s (1 1 + w)
N=14 9.4%+18.6%+21.0%+37.5%=86.9%
9.8% e
2.67 Dr
= 1.77 g / cm3 e= d s (1 + w)
w
w=9.8%
d s = 2.67
emin = 0.461
来自百度文库
emax = 0.943
−1 =
2.67 ∗ (1 + 0.098) − 1 =0.656 1.77
4
Dr =
0.943 − 0.656 emax − e = = 0.595 emax − emin 0.943 − 0.461
'
0. 0.87 .87 vw * 100% * 100% = 100% 0% = vv 0 0.87 ds − 1 1+ e
w
g=
g=
2.7 − 1 * 10 = 9.1kN / m 3 1 + 0.87
72 cm 3 2.7 w rd , ms = 121.5 g
129.5g e sr
121.5g r
vv = v − vs = 72 − 45 = 27
2
e=
m vv 27 129.5 − 121.5 = 0.60 vw = w = = =8 vs 45 1 w
3 4 5 6
sr =
vw 8 * 100% =29.6 = vv 27
r = g = 1.799 *10=18.0kN/ m3 rsat = ms + vv v
' w
g =
121.5 + 27 *10=20.6kN/ m3 72
r'= rd =
g= g=
r
ms − vs v
w
g=
121.5 − 45 *10 72
10.6Kn/ m3
d
ms 121.5 *10=16.9kN/ m3 g= v 72 rd r
r'
rsat 2.5 e
2.68 2 68 sr = 100% d s = 2.68
e=
sr =
w
−1 =
2.68 ∗ (1 + 0.285) ∗ 1 2 − 1 = 0.81 1.9
wd s 0.285 28 ∗ 2.68 = ∗100% = 94.3% e 0.81
3 4 2.9 (1) (2)
N=14
10<N 15
w =36.4%
IP
wL =48% IL
wP =35.4%.
3 2.3
n=
vv v
100%
e n ⇒e= 1+ e 1− n
100% =
wd s vd s (1 − n) = e n
vs = 1 =32.2% 2.50 vs = 1 , d s = 2.70 , w=32.2%, =1.91 g / cm3 6
w w
d s =2.70
= 1.0 g / cm3
2
2.2 1
d
=
ds w (2) 1+ e
=
sr erw + d s rw wd S (1 − n) (3) sr = 1+ e n
vs = 1
e=
vv vs w=
vv = e mw ms
w
v = vs + vv = 1 + e
ds =
ms vs
1 pw
ms = d s vs
w
= ds
w
100% 1 00%
sr
= 1.0 g / cm3
r'
=1.91g/ cm 3 ,
2
e= 1 2 3 4 5 6 7 8 2.4
d s (1 + w)
w
−1 =
2.70(1 + 0.322)1.0 − 1 = 0.87 1.91
v v = e = 0.87 cm 3
vw = wd s = 0.322 *2.70=0.87 cm3
v = 1 + e = 1 + 0.87 = 1.87 cm 3
ms = d s
w
= 2.70 *1.0=2.70g 70g 70 g
w
mw = wd s
= 0.322 22 * 2 2.70 .70 * 1.0 = 0. 0.87 .87 g
m = ms + mw = 3.57 g sr = r' = wd s e
rsat
r' v = 72cm3 m=129.5g
d s = 2.7
=
m 129.5 = = 1.799 g / cm3 72 v
(1) w =
mw 129.5 − 121.5 m − ms * 100% = * 100% = * 100% =6.6% ms ms 121.5
3
ds =
ms m 121.5 ⇒ vs = s = = 45 vs w ds 2.7
32.0%
w = 32.0% 32.0% 0%
w= v mw v v *100%= 100%= w w = v w ⇒ ms = v w ms ms ms w
sr =
vw *100%=100% ⇒ vw = vv vv ms ⇒ ms = d s vs vs w ∴
ds =
w
vv w = d s vs w