大学物理实验绪论答案

实验绪论课作业答案

1、(1) m (2) ± m (3) kg

(4) (5) m (6) ×104 m 2

3、V = 4πh •d 2 = ×10-4 m 3

方法一 ：∆V = |h V ∂∂|∆h +|d V ∂∂|∆d = 4π(d 2 •∆h + 2h •d •∆d) =×10-4 m 3

方法二 ：V V ∆ = h h ∆ + d

d ∆2 = ∆V = • V= ×10-4 m 3

V = ( ± )×10-4 m 3 B =

V

V ∆= % P=% 方法三 ：方和根传递法

∆V=()()2222d d V h h V ∆⎪⎭⎫ ⎝⎛∂∂+∆⎪⎭⎫ ⎝⎛∂∂ =4π()()()22242d hd h d ∆+∆=×10-4 m 3 V = ( ± ×10-4 m 3 B =V

V ∆= % P=% 4、 (1) ± mm (2) ±1℃ (3) ±

(4) ± mm (6) ± mA (或 ±2 mA) 5、 L =×10-2 m

L σ=())110(102--∑i i L L = ×10-2 m

L=± ×10-2 m B = % P =% L=± ×10-2 m B = % P =%

6、 R x =2

1R R •R O = Ω

①. 方法一 ：∆R x = |

1R R x ∂∂|∆R 1 +|2R R x ∂∂|∆R 2 +|0R R x ∂∂|∆R 0 = 2R R o ∆R 1 +22

1R R R o

∆R 2+21R R ∆R 0 =+ + = Ω

方法二 ：x x R R ∆ = 11R R ∆ + 22R R ∆+ 00R R ∆ = ∆R x = •R x = Ω

R x = ±Ω B = % P = %

②. ∆R x =()()()202022222121R R R R R R R R R x x x

∆⎪⎪⎭⎫ ⎝⎛∂∂+∆⎪⎪⎭⎫ ⎝⎛∂∂+∆⎪⎪⎭⎫ ⎝⎛∂∂=Ω ≈Ω

R x = ±Ω B = % P = %