计算机网络英文课件:2-1 Physical Layer

合集下载

计算机网络基础知识ppt课件 英文版

计算机网络基础知识ppt课件  英文版

sketch map
Main function: to achieve the communication and resource sharing1. Basic function: data communication Main features: resource sharing
data
Classification: wide area network (WAN):Tens to thousands of kilometers local area network (ALN) A few meters to a few kilometers metropolitan area network(MAN) (Between WAN and LAN)
1.2
The basis of computertion -- in the form of an electrical signal to the data transmitted from one end to the other end. 2、 The m ai n technol ogy -- "t he maxi m um transmission rate index of data communication" 3、Modulation, demodulation (Modem): converting the data signals and analog signals.
批注本地保存成功开通会员云端永久保存去开通
What is a computer network
? ?
The computer network is the computer system in different geographical location and function of independent by communication lines are interconnected, the system realizes the sharing and communication of cyber source in the network management software

计算机网络英文教材ppt第二章

计算机网络英文教材ppt第二章

Chapter 2 The Physical Layer
30
2.5.3 The Local Loop: Modems, ADSL, and Wireless
Figure 2-23. The use of both analog and digital transmission for a computer to computer call. Conversion is done by the modems and codecs.
3
Chapter 2 The Physical Layer
DTE
DCE
传输介质 DCE
DTE
用户环境
通信系统
Chapter 2 The Physical Layer
用户环境
4
Chapter 2 The Physical Layer
DTE: Equipment that hopes to connect the network. Such as computer, terminal, etc.
2
Chapter 2 The Physical Layer
The definition of physical layer:
the interface between DTE(Data
Terminal Equipment) and
DCE(Data Communications
Equipment)
Chapter 2 The Physical Layer
Chapter 2 The Physical Layer
27
2.5.1 Structure of the Telephone System
(a) Fully-interconnected network. (b) Centralized switch. (c) Two-level hierarchy.

网络工程课件PPT课件

网络工程课件PPT课件

解答:数据报在进入第二个局域网之前, 必须经过路由器分片。第二个局域网所能 传送的最长数据帧中的数据部分只有 1200bit,该长度即数据报片的长度(包含 160bit的首部)。因此,该数据报片的数 据部分=1200-160=1040。 所以所分的片数=(3200/1040)=4, 第二个局域网向其上层要传送的数据长度 为:4*160+ 3200=3840bit
11、源地址 4个字节
12、目的地址 4个字节
协议字段指出应将数据部分交给哪个过程处理
常用的一些协议和相应的协议字段值
协议名 ICMP IGMP TCP UDP OSPF EGP
89 8
10、首部检验和 16 位 只检验数据报的首部,不包括数据部分。 因为数据报每经过一个结点,结点处理机都要
重新计算机一下首部检验和(一些字段:如生存 时间、标志、片偏移等都可能发生变化)。如将 数据部分一起检验,计算的工作量太大。
首部
字节0
首部1
1400
首部2
2800
3799
首部3
字节0 1399
1400 2799
2800 3799
IP数据报首部中与分片有关的字段中的数值
总长度 标识
DF MF 片偏移
原始数据报 3820 12345 0 0
0
数据报片1
01
0
数据报片2
0
数据报片3
0
IP数据报首部中与分片有关的字段中的数值
总长度 标识
DF MF 片偏移
原始数据报 3820 12345 0 0
0
数据报片1 1420 12345 0 1
0
数据报片2 1420 12345 0 1

2physical浙大计算机网络课件

2physical浙大计算机网络课件

Bandwidth-Limited Signals Successive approximations to the original signal.
The Theoretical Basis For Data Communication

Bandwidth-Limited Signals Successive approximations to the original signal.
Guided Transmission Media: Twisted pair
(a) Category 3 UTP. (b) Category 5 UTP.
Guided Transmission Media: Twisted pair

Twisted pairs can be used for transmitting either analog or digital signals. Full-Duplex, Half-Duplex, Simplex Types Category 5 (100Mbps, 1Gbps) Category 6 (10Gbps) Category 7 (Shielded Twisted Pair)
Guided Transmission Media: Magnetic media

One of the most common ways to transport data form one computer to another is



To write them onto magnetic tape or removable media, To transport the tape or disks to the destination machine, and To read them back in again.

计算机网络与互联网(英语)chap16(共45张PPT)

计算机网络与互联网(英语)chap16(共45张PPT)
Packets delivered out of order Infer congestion from packet loss
Protocol suite designers Layering principle
For lost packets Now somewhat dated
Analyze Illustration of the 7-Layer Model communication problem
computer
第3页,共45页。
Set of Protocols
Complexity requires multiple protocols, each Sliding window of which manages a part of the problem Related to buffering
第14页,共45页。
Layers and Packet Headers
On the sender, each layer:
Accepts an outgoing message from the layer above
Adds a header and other processing Passes resulting message to next lower layer
chap16计算机网络与互联网计算机网络专业英语计算机网络技术英语互联网英语互联网的利弊英语作文关于互联网的英语作文互联网金融英语互联网英语作文互联网利弊英语作文
Chapter 16
Protocols and Protocol Layering
第1页,共45页。
Protocol
Agreement about communication A network protocol or computer

国防科大计算机网络ppt课件

国防科大计算机网络ppt课件

电气特性:“0”和“1”表示,决定数据速率和传输距 离
功能特性:对信号线的功能进行定义
过程特性:接口如何收发数据的过程
实例
EIA RS-232, RS-422,USB接口 10兆位以太网RT-45第接一章口绪/光论接口
35
35/51
Networking techno;ogy
局域网的两种拓扑结构
第一章 绪 论
11
11/51
Networking techno;ogy
1.4.2 MAN
第一章 绪 论
12
12/51
Networking techno;ogy
1.4.3 WAN
第一章 绪 论
13
13/51
Networking techno;ogy
广域网组成
主机(hosts)
协议实现
同一个协议规范可以由不同人员在不同的软硬件平台 上采用不同的方法来实现,即同样的协议规范可能有 不同的实现 。
互操作
不同协议实现之间要能够通信
协议栈
第一章 绪 论
29
29/51
Networking techno;ogy
网络体系结构
网络中层次和协议的集合——网络体系结构 网络体系结构包括:
802.11a
5GHz,54Mbps
802.11n
2.4 GHz 和5 GHz 108Mbps、320Mbps、500Mbps或600Mbps
安全
WEP、WPA以及802.1x
WAPI
Wi-Fi联盟
第一章 绪 论
20
20/51
Networking techno;ogy

计算机网络课件 chapter2-2 Physical Layer

计算机网络课件 chapter2-2 Physical Layer
• Scrambler tx/rx data with XORs pseudorandom bits
2020/12/9
Computer ssband Transmission
• Modulating the amplitude, frequency/phase of a carrier signal sends bits in a (non-zero) frequency range
2020/12/9
Computer Network -02-2
2
2.5.1 Baseband Transmission
• Line codes send symbols that represent one or more bits
• NRZ is the simplest, literal line code (+1V=“1”, -1V=“0”)
Amplitude Shift Keying, ASK
2. Use two frequencies to encode your bits (these frequencies can be put “on top” of your base frequency). FSK
3. Change the phase of the sine wave to do signal encoding. PSK
• Other codes tradeoff bandwidth and signal transitions
2020/12/9
Computer Network -02-2
3
Clock Recovery
• To decode the symbols, signals need sufficient transitions

计算机网络英文版课件-第2章 The Physical Layer

计算机网络英文版课件-第2章 The Physical Layer
• To computer scientists, (digital) bandwidth is the maximum data rate of a channel, a quantity measured in bits/sec.
Amplitude Amplitude
••• Time
f
3f
9f
Frequency
b. Frequency-domain decomposition of the composite signal
Computer Networks, Chapter 2 The Physical Layer
18
Time and frequency domain of a nonperiodic composite signal
Computer Networks, Chapter 2 The Physical Layer
6
Units of period and frequency
Computer Networks, Chapter 2 The Physical Layer
7
Simplex, half-duplex, or full-duTransmission
• The timing of a signal is unimportant. • Information is received and translated by agreed upon patterns.
Computer Networks, Chapter 2 The Physical Layer
Computer Networks, Chapter 2 The Physical Layer
3
Type of Data

计算机网络英文课件:1-2 Introduction

计算机网络英文课件:1-2 Introduction

Computer Networks -1-Part 2
4
The Data Link Layer
• Data link layer is to transform a raw transmission facility into a line that appears free of undetected transmission errors to the network layer
Add a checksum (cyclic redundancy check) that should match the bits before it
Also: Provide the mechanisms so that fast senders don’t overwhelm slow receivers (flow control)
2020/12/7
Computer Networks -1-Part 2
5
Data Link Layer
• Observation: We also need to specify how a number of computers can share a common channel (e.g. wire), that is medium access control sublayer (MAC):
– How many nanoseconds a bit lasts
– whether transmission may proceed simultaneously in both directions
– how the initial connection is established
– how it is torn down when both sides are finished

计算机网络英文课件

计算机网络英文课件
Chapter 1: Computer Networks and the Internet
Resource sharing, high reliability, saving money Powerful communication medium(electronic mail, videoconference) e-commerce (electronic commerce)
Introduction and Overview
Uses of Computer Networks Mobile Users


Mobile computers, such as notebook computers and personal digital assistants (PDAs), are one of the fastest-growing segments of the computer industry. merger of cell phones and PDAs into tiny wireless computers, WAP (Wireless Application Protocol) portable office wireless networks on campus wireless networks on military Privacy Freedom of speech Copyright ……



Two computers are said to be interconnected if they are able to exchange information. The connection need not be via a copper wire; fiber optics, microwaves, infrared, and communication satellites can also be used. Networks come in many sizes, shapes and forms.

计算机网络英文教材ppt第三章

计算机网络英文教材ppt第三章

1. Character count
● Technology:use a field in the header to specify the number of
characters in the frame.
● Problem:the count can be garbled by a transmission error.
思考题
当帧里的下列比特序列在链路上发送时,真实 的比特序列是什么 110101111101011111101011111110
3.1.3 Error Control
●错误产生原因:噪声 ●错误类型:数据帧出错、数据帧丢失 ●噪声
○白噪声: 随机错误,某一码元与前后码元无关的错误,单 个出现 ○冲击噪声:突发错误,某一码元与前后码元有关的错误, 成串密集出现Βιβλιοθήκη 数据虚通路数据实通路
数据实通路
数据链路/逻辑链路 数据链路层提供的 数字信道
=
(物理)链路
+
通信规程
物理层提供的无源 点到点物理线路段
数据链路层协议
3.1.1 Services Provided to the Network Layer
Three services: 1. Unacknowledged connectionless service 2. Acknowledged connectionless service 3. Acknowledged connection-oriented service
3.1.2 Framing
●帧同步:以帧为单位进行传送,指出哪里是帧的开 始和结束。 ●为什么成帧?
○提高传输效率
○差错控制
● Framing methods:

计算机网络Computer Network

计算机网络Computer Network

计算机网络Computer NetworkTopics include internetworking philosophies, unicast and multicast routing, congestion control, network quality of service, mobile networking, router architectures, network-aware applications, content dissemination systems, network security, and performance issues.Coverage:…Switching technology:marked free●Means for applications to access OSI TCP/IP Protocol SuiteFive layers:OSI vs TCP/IPMultiplexing: Channel sharingMultiplexer (Mux):Combine multiple streamsDe-Multiplexer (DeMux):Pick out one/more streams out of the aggregationMUXEDMUXbufferData Link LayerThe PDU at the Data Link Layer (DL PDU) is typically called a Frame. A Frame has a header, a data field, and a trailer.Error ControlTwo basic approaches to handle bit errors:●Error correcting codesUsed if retransmission of the data is not possibleData are encoded with sufficient redundancy to correct bit errorsExamples: Hamming Codes Reed Solomon Codes etc …●Error-detecting codes plus retransmissionUsed if retransmission of corrupted data is feasibleReceiver detects error and requests retransmission of a frameFlow ControlFlow Control is a technique for speed-matching of transmitter and receiver. Flow control ensures that a transmitting station does not overflow a receiving station with data.We will discuss two protocols for flow control:●Stop-and-Wait Protocol●Sliding Window ProtocolARQ Error Control。

  1. 1、下载文档前请自行甄别文档内容的完整性,平台不提供额外的编辑、内容补充、找答案等附加服务。
  2. 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
  3. 3、如文档侵犯您的权益,请联系客服反馈,我们会尽快为您处理(人工客服工作时间:9:00-18:30)。

a b 2 2
n
n
2020/12/7
Computer Networks - 02 -1
7
Note: root mean squares (on the right) reflect the dispersed energy at the given frequency.
2020/12/7
Computer Networks - 02 -1
2020/12/7
Computer Networks - 02 -1
2
2.1 The Theoretical Basis for Data Communication
• We’re living in a digital world, meaning that we’d preferably want to send digital (i.e. two-valued) signals through wires.
• What will be talked about?
– Theoretical analysis of data transmission
– Transmission media (wires and no wires)
– Three communication system: telephone, mobile phone, and cable television system
– Where f = 1/T is the fundamental frequency, an and bn are the sine and cosine amplitude of the nth harmonics (terms), and c is a constant.---Fourier Series
5
Example: (n is the number of harmonics we take into account)
2020/12/7
Computer Networks - 02 -1
6
2.1.2 Bandwidth-Limited Signals
• Example: 01100010, 8 bit for ASCII “b”
T
0
sin(2k f t)
s in(2nf t)dt
0 T
fork n / 2 fork
n
an 2 T g(t)sin(2nft)dt
T0
c 2 T g(t)dt T0
bn 2 T g(t) cos(2nft)dt T0
2020/12/7
Computer Networks - 02 -1
COMPUTER NETWORKS
Chapter 02 The Physical Layer
Part 1
2020/12/7
Computer Networks - 02 -1
1
Chapter 2 The Physical Layer
• Essence: Physical layer defines the mechanical, electrical, and functional timing interfaces to the network, provides the means to transmit bits from sender to receiver, that is, involves a lot on how to use (analog) signals for digital information.
2020/12/7
Computer Networks - 02puter Networks - 02 -1
4
• To understand what’s going on, we need Fourier Analysis.
• A periodic function with period T (and frequency f = 1/T ), g(t) can be written as:
an =1/πn[cos(πn/4) -cos(3πn/4) + cos(6πn/4) -cos(7πn/4)] bn = 1/πn[sin(3πn/4) -sin(πn/4) + sin(7πn/4) -sin(6πn/4)] cn = 3/4
The root mean square amplitudes is (an2 + bn2)1/2.
• Wires are pretty much physical, meaning that Mother Nature will probably impose a few constraints here and there.
• Observation: Signals are not entirely transmitted through a wire as you would expect:
– The quality of transmission is frequency dependent, not all parts of the digital signal get through the wire as you would expect.
– Digital signal transmission is subject to attenuation, distortion, etc. This is partly caused by disallowing high-frequency components to pass through. So the range of frequency or the number of bits of a transmission medium is called bandwidth.
8
Bandwidth
• What does this all mean?
– Digital signal transmission can be thought of as being constructed as an infinite number of periodic analog signals.
相关文档
最新文档