计算机网络英文课件:2-1 Physical Layer

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– Where f = 1/T is the fundamental frequency, an and bn are the sine and cosine amplitude of the nth harmonics (terms), and c is a constant.---Fourier Series
a b 2 2
n
n
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Note: root mean squares (on the right) reflect the dispersed energy at the given frequency.
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– The quality of transmission is frequency dependent, not all parts of the digital signal get through the wire as you would expect.
– Digital signal transmission is subject to attenuation, distortion, etc. This is partly caused by disallowing high-frequency components to pass through. So the range of frequency or the number of bits of a transmission medium is called bandwidth.
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2.1 The Theoretical Basis for Data Communication
• We’re living in a digital world, meaning that we’d preferably want to send digital (i.e. two-valued) signals through wires.
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Bandwidth
• What does this all mean?
– Digital signal transmission can be thought of as being constructed as an infinite number of periodic analog signals.
• Wires are pretty much physical, meaning that Mother Nature will probably impose a few constraints here and there.
• Observation: Signals are not entirely transmitted through a wire as you would expect:
5
Example: (n is the number of harmonics we take into account)
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2.1.2 Bandwidth-Limited Signals
• Example: 01100010, 8 bit for ASCII “b”
T
0
sin(2k f t)
s in(2nf t)dt
0 T
fork n / 2 fork
n
an 2 T g(t)sin(2nft)dt
T0
c 2 T g(t)dt T0
bn 2 T g(t) cos(2nft)dt T0
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COMPUTER NETWORKS
Chapter 02 The Physical Layer
Part 1
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Chapter 2 The Physical Layer
• Essence: Physical layer defines the mechanical, electrical, and functional timing interfaces to the network, provides the means to transmit bits from sender to receiver, that is, involves a lot on how to use (analog) signals for digital information.
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• To understand what’s going on, we need Fourier Analysis.
• A periodic function with period T (and frequency f = 1/T ), g(t) can be written as:
• What will be talked about?
– Theoretical analysis of data transmission
– Transmission media (wires and no wires)
– Three communication system: telephone, mobile phone, and cable television system
an =1/πn[cos(πn/4) -cos(3πn/4) + cos(6πn/4) -cos(7πn/4)] bn = 1/πn[sin(3πn/4) -sin(πn/4) + sin(7πn/4) -sin(6πn/4)] cn = 3/4
The root mean square amplitudes is (an2 + bn2)1/2.
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