高一上学期期中考试
河南省天一大联考2023-2024学年高一上学期11月期中物理试题含答案
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2023—2024学年(上)高一年级期中考试物理(答案在最后)考生注意:1.答题前,考生务必将自己的姓名、考生号填写在试卷和答题卡上,并将考生号条形码粘贴在答题卡上的指定位置。
2.回答选择题时,选出每小题答案后,用铅笔把答题卡对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
回答非选择题时,将答案写在答题卡上,写在本试卷上无效。
3.考试结束后,将本试卷和答题卡一并交回。
一、单项选择题:本题共7小题,每小题4分,共28分。
每小题只有一个选项符合题目要求。
1.下列各组物理量中,全部是矢量的是()A.位移、弹力、加速度、平均速度B.路程、速度、摩擦力、时刻C.速度、质量、加速度、长度D.重力、速度、时间、位移【答案】A【解析】【详解】A.位移、弹力、加速度、平均速度都是既有大小又有方向的量,都是矢量,A正确;B.路程、时刻只有大小没有方向是标量,速度、摩擦力是矢量,B错误;C.速度、加速度是矢量,质量、长度是标量,C错误;D.重力、速度、位移是矢量,时间是标量,D错误。
故选A。
2.2023年9月23日晚20时杭州第19届亚运会开幕,这场以文化为底色、融科技之力与艺术之美的盛会,向世界展示了中华优秀传统文化的意韵。
入场式上中国体育代表团队伍的前端大约经过45s走完如图所示地屏上的运动员大道,步频约为1.6步/秒,步幅约为50cm,下列说法中正确的是()A.运动员走地屏大道向观众挥手致意时可以看成质点B.中国体育代表团在运动员大道上走路的速度大小约为0.8km/hC.地屏上的运动员大道的长度约为36mD.2023年9月23日晚20时是时间间隔【答案】C【解析】【详解】A .运动员走地屏大道挥手致意时有动作,看作质点则无法考查运动员的动作,选项A 错误;B .运动员走路的速度0.51.60.8m/s 1v ⨯==选项B 错误;C .地屏上的运动员大道长约为x =vt =0.8m/s×45s=36m选项C 正确;D .2023年9月23日晚20时是时刻,选项D 错误。
山东省泰安肥城市2024_2025学年高一语文上学期期中试题
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山东泰安肥城市2024-2025学年高一语文上学期期中试题本试卷共150分,考试时间150分钟。
留意事项:1.答卷前,考生务必将自己的姓名、考生号填写在答题卡和试卷指定位置上。
2.回答选择题时,选出每小题答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
回答非选择题时,将答案写在答题卡上。
写在本试卷上无效。
3.考试结束后,将本试卷和答题卡一并交回。
一、现代文阅读(36分)(一)论述类文本阅读(本题共3小题,9分)阅读下面的文字,完成1~3题。
大半个世纪以前,费孝通先生在《乡土中国》一书中提出了“差序格局”的概念,同样还是在这本书中,费老也告知我们,中国社会是一个熟人社会,人们生于斯长于斯,共同经营着家庭事业。
虽然还有天下与国家等关系的存在,但它们在客观上离自己太遥远。
大多数人都过着守望相助的生活。
差序格局概念的提出,实现了我们从理论上来相识乡土中国之可能,其说明力之强大已成为中国社会学的一个经典概念。
但特别缺憾的是,我们目前所运用的林林总总的理论和概念都是西方学术的舶来品。
他们给我们输入什么理论、概念和方法,我们就用什么理论、概念和方法;他们建立了什么新的学派,我们就抓紧学习并介绍什么学派。
正是在这层意义上,差序格局的提出显现了它的重要地位,为中国社会学探讨供应了一个重要的范例和理论方向。
缺憾的是,这个概念一花独放了60多年,没有呼应,没有发展。
当中国学术界还没有从根本上建立起中国社会的理论模式之时,代表着中国传统精华的乡土中国正在发生着深刻的社会变迁。
由于我们尚未有现成理论和概念可以套用,造成阅历描述性、总结性成果大量涌现,理论创簇新见。
仅就农夫城乡流淌问题而言,即有“农村剩余劳动力的转移”、“离土不离乡”、“城乡二元结构”、“新生代农夫工”等话语主题。
总之,有关中国农村社会问题探讨所显现的特点始终是阅历探讨不少,而理论概括不足,直至我们在2011年第1期《读书》上读到吴重庆先生写的《从熟人社会到“无主体熟人社会”》一文,才使得我们有机会看到理论苗头的出现。
2024-2025学年度第一学期高一英语期中考试卷(含解析)
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2024-2025学年度第一学期高一英语期中考试卷试卷满分:100分第一部分阅读理解(共20 小题;每小题2.5 分,满分50 分)第一节阅读下列短文,从每题所给的A、B、C 和D 四个选项中,选出最佳选项。
AHere are some pet-friendly universities in the UK and US.University of IllinoisStudents are allowed up to two pets in each apartment, as well as a fish tank of no more than 50 gallons.To keep a pet, you will need to get approval from the Family & Graduate housing department at the University of Illinois. You will have to provide proof that your pet is up to date with its vaccinations(疫苗), and pay a monthly US$30 pet fee, which is non-refundable(不可退款的).Your pet can’t be left for extended periods of time, and if there’s evidence that you’ve left it alone due to vacation or illness, the university may remove it.Harvard UniversityWith as many as 12 pet-friendly apartments, Harvard is a very pet-friendly university. It allows students to have fish in a tank of no more than 50 gallons, except for Harvard’s Cronkhite Graduate Center.In Harvard’s pet-friendly apartments, you’re allowed: one cat or one dog, which can’t be over 40 pounds when fully grown. At most, two pet birds.University of British Columbia Students can take advantage of the university’s B.A.R. K program, which uses the calming power of therapy dogs to help them.B.A.R. K started at the University of British Columbia, after an assistant professor called Dr. John-Tyler Binfet noticed that he couldn’t walk across campus without students running over to play with his dog, Frances. The students told him they were homesick and missed their pets, which encouraged Binfet to establish B.A.R. K as a way of fighting their loneliness.University of OxfordThe University of Oxford is famous for its resident pets, who happily wander around college grounds. Many Oxford colleges have their own tortoise and take part in the annual Corpus Christi tortoise race.Although you are not allowed to keep your own pet as a student, several Oxford colleges hold dog petting and walking therapy sessions.1.What is one of the rules for keeping pets at the University of Illinois?A.Pet keepers should pay a monthly US$ 30 pet fee which will be returned.B.Pets can’t be left alone in the apartments due to vacation or illness.C.Students have to keep fish in a fish tank of no more than 20 gallons.D.The cat or dog can’t be over 40 pounds when fully grown.2.Why did Dr. John-Tyler Binfet start B.A.R. K?A.To help students to fight against homesickness.B.To do research on dogs and train them to be pets.C.To help more professors to do exercise on campus.D.To give assistance to the pet dogs by offering them foods.3.Which university doesn’t allow students to keep pets?A.Harvard University. B.University of Oxford.C.University of Illinois. D.University of British Columbia.BA survey by the American Psychological Association shows that one in ten adults reads online news at least once an hour. A lot has been written about the mental health influence from news addiction, and in particular from reading negative reports. Just like junk food, “junk” news can be bad for our health.In recent years, things have been getting increasingly more negative. A study of the content of New Zealand’s largest newspaper showed that while in 1973 the average number of stories about death on the front page was 0.75, by 2013 it was 4.1(and no, there weren’t five times more people dying).What’s more, online news, and the stories we read on mobile phones in particular, tend to be even more negative than print. A 2019 study of 50 U.S. newspapers showed that mobile versions of newspapers report three times more stories about disasters and accidents than paper ones.Such negative reports lead people to believe that things are worse than they really are. They can lead to stress, worry and lower spirits.Experiments also suggest that loneliness and poor relationships have been connected with reading negative reports. After reading negative reports, people are less likely to help others. Even worse, when we check news on smart phones, we may “phub” our loved ones, which leads to lower relationship satisfaction.Negative reports attract our attention far more than positive ones. That’s a global happening. I hope, however, that if we realize that negative news is spoiling our moods, we might all be more willing to change. 4.Why is “junk food” mentioned in the first paragraph?A.To entertain readers.B.To introduce the topic.C.To make an advertisement.D.To keep readers away from it.5.What can we learn about the study in Paragraph 2?A.The death rate in New Zealand is very high.B.Print newspapers have become less popular.C.Stories about death have become less popular.D.Negative reporting has been increasing over years. 6.What may negative reports lead people to do?A.Live a hopeful life.B.Become more careful.C.Become less likely to help others.D.Pay more attention to their physical health.7.What does the underlined word “phub” in Paragraph 5 mean?A.Ignore B.Hate C.Laugh at D.Care about8.Which of the following can be the best title for the text?A.A Survey on News Reading Habits B.Negative Effects of Mobile PhonesC.Is Online News Better Than Print?D.Is Junk News a Danger to Health?CThere was once a boy called Mario who loved to have lots of friends at school. However, he wasn’t sure whether or not his classmates were his true friends, so he asked his grandpa. The old man answered, “I have just exactly what you need; it’s in the attic (阁楼). Wait here for a minute.”Grandpa left, soon returning as though carrying something in his hand, but Mario could see nothing there. “Take it. It’s a very special chair. Because it’s invisible (无形的) it’s rather difficult to sit on, but if you take it to school and you manage to sit on it, you’ll be able to tell who your true friends are.”Mario took the strange invisible chair and went to school. At break time he asked everyone to form a circle, and he put himself in the middle, with his chair. “Nobody move. You’re about to see something amazing,” Mario said.Then Mario tried sitting on the chair. He missed and fell straight onto his backside. Everyone had a pretty good laugh. Mario wouldn’t be beaten. He kept trying to sit on the magic chair, and kept falling to theground... until, suddenly, he tried again and didn’t fall. This time he sat, hovering (悬停) in mid-air.Looking around, Mario saw George, Lucas, and Diana — three of his best friends — holding him up, so he wouldn’t fall. At the same time, many others he had thought of as friends were doing nothing but make fun of him, enjoying each and every fall.Leaving with his three friends, Mario explained to them how his grandpa had so cleverly thought of such a good idea. Now he knows that those who take joy in our misfortunes (不幸) when we are in difficulty are not our true friends.9.What did Mario’s grandpa take from the attic?A.An invisible chair.B.An old chair.C.A real chair.D.Nothing.10.Why did Mario’s grandpa give him the invisible chair?A.To see whether Mario could sit on it. B.To test who were Mario’s true friends.C.To let Mario have fun with his classmates.D.To test whether Mario was popular at school. 11.How was Mario able to hover in mid-air?A.He saw the invisible chair suddenly. B.He managed to sit on the chair finally.C.His friends held him up with their hands. D.His classmates gave him a chair to sit on.12.What does the story tell us?A.Never laugh at our friends. B.True friends can help us do magic.C.True friends are those who care for us. D.Having too many good friends isn’t a good thing.DSure, it’s good to get along well with your teacher because it makes the time you spend in the classroom more pleasant.And yes, it’s good to get along well with your teacher because, in general, it’s smart to learn how to get along well with the different types of people you’ll meet throughout your life.In fact, kids who get along well with their teachers not only learn more, but they’re more comfortable with asking questions and getting extra help. This makes it easier for them to understand new materials and makes them do their best on tests. When you have this kind of relationship with a teacher, he or she can be someone to turn to with problems, such as problems with learning or school issues (问题).Here is a question:What if you don’t get along with your teachers? In fact, teachers want to get along well with you and enjoy seeing you learn. But teachers and students sometimes have personality clashes (个性冲突), which can happen between any two people. If you show your teacher that you want to make the situation better, he or she will probably do everything possible to make that happen. By dealing with a problem like this, you learn something about how to get along with people who are different from you.However if a certain teacher isn’t your favorite, you can still have a successful relationship with him or her especially if you fulfill (履行) your basic responsibilities as a student.Here are some of those responsibilities (责任):Attend class ready to learn.Be prepared for class with the right stationery, books, and completed assignments (作业).Listen when your teacher is talking.Do your best, whether it’s a classroom assignment, homework, or a test.13.According to the passage, what will happen to you when getting along well with your teachers ?A.We will have no problems with studyB.We will get a better seat in the classroomC.We will get the best scores in the examsD.We will have more pleasant time in the classroom14.What does the underlined word “that” refers to in the fourth paragraph?A.The happy time you have in the classroomB.Getting along very well with classmatesC.A better relationship between you and your teacherD.The disappearance of personality differences15.What does the passage mainly talk about?A.The importance of friendship in schools.B.The importance of a good relationship with your teachers.C.Studying skills for students.D.Useful skills to get along well with your teachers.16.As a student, what will you do if you don’t like a certain teacher ?A.You fulfill (履行) your basic responsibilities as a studentB.You are thought of as a good studentC.You know some basic social skillsD.You are easygoing and helpful第二节七选五(每小题1分,共5分,根据短文内容,选出能填入空白处的最佳选项。
浙江省嘉兴市2024-2025学年高一上学期期中联考数学试题含答案
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2024学年第一学期嘉兴八校联盟期中联考高一年级数学学科试题(答案在最后)考生须知:1.本卷满分150分,考试时间120分钟.2.答题前,在答题卷指定区域填写班级、姓名、考场号、座位号及准考证号并填涂相应数字3.所有答案必须写在答题纸上,写在试卷上无效.4.考试结束后,只需上交答题纸.选择题部分(共58分)一、单选题:本大题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一个合题目要求的.1.设集合{}{}21,2,1,0,1,2A x x B =-<<=--,则A B = ()A .{}1,0-B .{}0C .{}0,1D .{}1,0,1-2.已知1,12是方程20x bx a -+=的两个根,则a 的值为()A .12-B .2C .12D .2-3.“1x =”是“21x =”的()A .充分不必要条件B .必要不充分条件C .充要条件D .既不充分也不必要条件4.已知幂函数ay x =的图象过点(9,3),则a 等于()A .3B .2C .32D .125.已知0.20.50.23,3,log 5a b c ===,则,,a b c 的大小关系是()A .a b c <<B .c a b <<C .c b a <<D .a c b <<6.方程2ln 50x x +-=的解所在区间为()A .(4,5)B .(3,4)C .(2,3)D .(1,2)7.已知函数()22xf x =-,则函数()y f x =的图象可能是()A .B .C .D .8.已知函数()f x 为定义在R 上的奇函数,且在[0,1)为减函数,在[1,+)∞为增函数,且(2)0f =,则不等式(1)()0x f x +≥的解集为()A .(,2][0,1][2,)-∞-+∞B .(,1][0,1][2,+)-∞-∞C .(,2][1,0][1,)-∞--+∞ D .(,2][1,0][2,)-∞--+∞ 二、多选题:本大题共3小题,每小题6分,共18分.在每小题给出的选项中,有多项符合题目要求.全部选对的得6分,部分选对的得部分分,有选错的得0分.9.下列叙述正确的是()A .2,230x R x x ∃∈-->B .命题“,12x R y ∃∈<≤”的否定是“,1x R y ∀∈≤或2y >”C .设,x y R ∈,则“2x ≥且2y ≥”是“224x y +≥”的必要不充分条件D .命题“2,0x R x ∀∈>”的否定是真命题10.已知集合{}1,2,3A =,集合{},B x y x A y A =-∈∈,则()A .{}1,2,3AB = B .{}1,0,1,2,3A B =-C .0B∈D .1B-∈11.下列说法不正确的是()A .函数1()f x x=在定义域内是减函数B .若函数()g x 是奇函数,则一定有(0)0g =C .已知函数25,1(),1x ax x f x a x x⎧---≤⎪=⎨>⎪⎩在R 上是增函数,则实数a 的取值范围是[3,1]--D .若函数()f x 的定义域为[2,2]-,则(21)f x -的定义域为13[,22-非选择题部分(共92分)三、填空题:本大题共3小题,每小题5分,共15分.12.函数22,1()23,1x x f x x x ⎧-≤=⎨+>⎩,则((2))f f -的值是▲.13.计算:0ln 2lg 252lg 2eπ+-+=▲.14.x R ∀∈,用函数()m x 表示函数()f x 、()g x 中的最小者,记为{}()min (),()m x f x g x =.若()min m x ={}21,(1)x x -+--,则()m x 的最大值为▲.四、解答题:本大题共5小题,共77分,解答应写出文字说明、证明过程或演算步骤15.(本题满分13分)已知集合{}13A x x =<<,集合{}21B x m x m =<<-.(1)当1m =-时,求A B ;(2)若A B ⊆.求实数m 的取值范围.16.(本题满分15分)已知函数2()23()f x x ax a R =-+∈.(1)若函数()f x 在(,2]-∞上是减函数,求a 的取值范围;(2)当[1,1]x ∈-时,讨论函数()f x 的最小值.17.(本题满分15分)已知函数()af x x x=+,且(1)2f =.(1)求a ;(2)根据定义证明函数()f x 在区间(1,)+∞上单调递增;(3)在区间(1,)+∞上,若函数()f x 满足(2)(21)f a f a +>-,求实数a 的取值范围.18.(本题满分17分)已知函数()ln(1)ln(1)f x x x =--+,记集合A 为()f x 的定义域.(1)求集合A ;(2)判断函数()f x 的奇偶性;(3)当x A ∈时,求函数221()(2x xg x +=的值域.19.(本题满分17分)某校学生社团心理学研究小组在对学生上课注意力集中情况的调查研究中,发现注意力指数p 与听课时间t 之间的关系满足如图所示的曲线.当(0,14]t ∈时,曲线是二次函数图象的一部分,当[14,45]t ∈时,曲线是函数log (5)83a y t =-+,(0a >且1a ≠)图象的一部分.根据专家研究,当注意力指数p 大于80时听课效果最佳.(1)试求()p f t =的函数关系式;(2)老师在什么时段内讲解核心内容能使学生听课效果最佳?请说明理由.2024学年第一学期嘉兴八校联盟期中联考高一年级数学学科试题答案1234567891011A C A DBCBDABDCDABC12.713.114.015.解:(1)当{}1,22m B x x =-=-<<∵{}13A x x =<<∴{}23A B x x =-<< (2)∵A B⊆2113m m ≤⎧⎨-≥⎩,122m m ⎧≤⎪⎨⎪≤-⎩∴2m ≤-∴(,2]m ∈-∞-16.(1)对称轴:x a =∵为减函数∴2a ≥∴[2,)a ∈+∞(2)①当1a <-时,在[1,1]-,则min ()(1)24f x f a =-=+②当11a -≤≤,在[1,1]-有最低点,2min ()()3f x f a a ==-+③1a >时,在[1,1]-,min ()(1)24f x f a ==-+17.(1)∵(1)2f =∴21a=+∴1a =(2)1()f x x x=+12,(1,)x x ∀∈+∞,且12x x <,则12()()f x f x --121211x x x x =+--211212x x x x x x -=-+12121()(1)x x x x =--∵1212,(1,)x x x x <∈+∞∴121212110,01,10x x x x x x -<<<->∴12()()0f x f x -<,即12()()f x f x <故()f x 在(1,)+∞(3)∵在(1,)+∞,(2)(1)f a f a +>-∴211121a a a a +>⎧⎪->⎨⎪+>-⎩,12a a >-⎧⎪>⎨⎪⎩任意成立∴2a >18.(1)1010x x ->⎧⎨+>⎩,11x x <⎧⎨>-⎩,{}11A x x =-<<(2)1()ln()1xf x x-=+可知定义域关于原点对称111()ln(ln(ln ()111x x xf x f x x x x+---====-+++故()f x 为奇函数.(3)令22t x x =+,对称轴1x =-t 在(1,1)-上,故(1,3)t ∈-又1()2ty =在R 上递减故221()(2x xg x +=的值域是:1(,2)8.19.(1)当(0,14]t ∈,设2()f t at bt c =++代入顶点(12,82)1481(,,)可得:21()[12)824f t t =--+当[14,45]t ∈,由log (5)83(01)a y t a a =-+>≠且代入(14,81),13a =,故:1()log (5)833f t t =-+综上2131(12)82,((0,14])4()log (5)83,([14,45])t t p f t t t ⎧--+∈⎪==⎨-+∈⎪⎩(2)当014t <≤,21()(12)82804f t t =--+>∴1214t -<≤当[14,45]t ∈,13()log (5)8380f t t =-+>∴1432t ≤<∴在(1232)-这段时间安排核心内容效果最佳.。
黑龙江省尚志中学2024_2025学年高一语文上学期期中试题含解析
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黑龙江省尚志中学2024-2025学年高一上学期期中考试语文考题一、现代文阅读(一)论述类文本阅读阅读下面的文字,完成下列小题。
中华传统文化立足现实的社会和人生,始终关注社会和谐与人生华蜜。
这既是中华传统文化的特质,也体现了中华传统文化最根本的价值追求。
历史悠久的中华传统文化,在殷周之际出现了重要的人文转向,即由神本向人本转向以及人道主义思潮出现。
这为儒、墨、道、法等诸子百家供应了最干脆的思想来源,也规定了此后中华传统文化的基本精神和主要走向。
在博大精深的中华传统文化中,儒家思想长期居于主导地位,成为中华传统文化的主流和基础。
中华传统文化的价值追求在儒家文化中表现得最为显明和突出。
从孔子起先,儒家就致力于以仁为核心、仁礼相辅互动的理论构建。
由此动身,便有“仁者爱人”“克己复礼为仁”“仁爱万物”“仁者以天地万物为一体”的由人、社会至自然的层层理论绽开,有“为天地立心,为生民立命,为往圣继绝学,为万世开太平”的使命感和责任感。
这一切,无不体现着对志向社会和美妙人生的憧憬与追求。
在中华传统文化中,儒、道两家最具代表性。
与儒家讲仁爱形成比照的是,道家更强调道法自然,崇尚清静无为,主见返璞归真、与自然和谐相处。
道家身国同构、经国理身的理念,表现出其根本价值取向是憧憬真正符合人性的和谐社会与美妙人生。
由此,儒、道两家虽然对社会和人生的志向形成了不同的致思路向,但在拥有共同价值追求的基础上可以相融互补。
在魏晋玄学那里,通过名教与自然之辨,二者实现了辩证的统一,为容纳和汲取外来的佛教准备了思想文化条件。
两汉之际传入的佛教在魏晋时通过依附玄学而走进中国思想文化。
作为讲求“出世”的佛教,其根本宗旨是摆脱人生之“苦”而追求永恒之“乐”。
这种对华蜜欢乐人生的追求,成为佛教与儒、道文化融合发展的契机和基础。
经过不断的中国化,佛教最终融入了中华文化,成就了中华文化发展中文明沟通互鉴的历史佳话。
中国佛教关注现实人生,强调佛性与人性的统一,留意人格的自我培育与自我完善,形成了自身显明的思想特点与文化精神,对中华文化乃至世界文明发展都作出了重要贡献。
江苏省扬州市扬州中学2024-2025学年高一上学期11月期中数学试题(含答案)
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江苏省扬州中学2024-2025学年第一学期期中试题高一数学 2024.11试卷满分:150分,考试时间:120分钟注意事项:1.作答前,请考生务必将自己的姓名、考试证号等写在答题卡上并贴上条形码2.将选择题答案填写在答题卡的指定位置上(用2B 铅笔填涂),非选择题一律在答题卡上作答(用0.5mm 黑色签字笔作答),在试卷上答题无效。
3.考试结束后,请将答题卡交监考人员。
一、单项选择题:本大题共8小题,每小题5分,共40分。
在每题给出的四个选项中只有一项是最符合题意的。
1.已知集合,,则( )A. B. C. D. 或2. 已知为常数,集合,集合,且,则的所有取值构成的集合元素个数为( )A. 1B. 2C. 3D.43.设为奇函数,且当时,,则当时,( )A. B. C. D. 4.函数的值域为( )A. B. C. D. 5.已知函数的定义域为,则函数)A. B. C. D. 6. 若不等式的解集为,那么不等式的解集为( ){|02}A x x =<<{|14}B x x =<<A B = {|02}x x <<{|24}x x <<{|04}x x <<{2|x x <4}x >a {}260A x x x =+-=∣{20}B x ax =-=∣B A ⊆a ()f x 0x ≥()2f x x x =+0x <()f x =2x x +2x x -2x x --2x x -+x x y 211-++=(]2,∞-()2,∞-()20,[)∞+,2(2)f x +(3,4)-()g x =(1,6)(1,2)(1,6)-(1,4)20ax bx c ++>{}12x x -<<()()2112a x b x c ax ++-+>A. B. 或C. 或 D. 7.命题在单调增函数,命题在上为增函数,则命题是命题的( )条件.A.充分不必要B.必要不充分C.充要D.既不充分也不必要8. 已知,则的最大值为( )A. B. C. D.二、多项选择题:本大题共3小题,每小题6分,共18分。
福建省漳州市十校联盟2024-2025学年高一上学期期中质量检测联考数学试题含答案
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福建省漳州市十校联盟2024-2025学年高一上学期期中质量检测联考数学试题(答案在最后)满分150分,考试时间120分钟一、单选题:本题共8小题,每小题5分,共40分.在每小题给出的选项中,只有一项是符合题目要求的.1.设全集U 是实数集{}{}R,15,2M x x N x x =-≤≤=≥∣∣,则阴影部分所表示的集合是()A.{12}x x -≤<∣B.{25}xx ≤≤∣C.{12}xx -<≤∣ D.{12}xx -≤≤∣【答案】A 【解析】【分析】由阴影部分表示的集合U M N I ð求解.【详解】解:阴影部分表示的集合为:{12}U M xx N ≤⋂=-<∣ð,故选:A 2.函数22()1xf x x =+的图象大致是()A. B.C. D.【答案】D 【解析】【分析】首先判断函数的奇偶性,即可判断A 、B ,再根据0x >时函数值的特征排除C.【详解】函数22()1x f x x =+的定义域为R ,且()()2222()11x x f x f x x x --==-=-+-+,所以22()1xf x x =+为奇函数,函数图象关于原点对称,故排除A 、B ;又当0x >时()0f x >,故排除C.故选:D3.下列不等式中,可以作为“30x -<”的一个必要不充分条件是()A.14x <<B.4x <C.1x <D.02x <<【答案】B 【解析】【分析】由必要不充分条件的概念逐项判断即可.【详解】对于A:14x <<为30x -<既不充分也不必要条件;对于B :4x <为30x -<的必要不充分条件;对于C:1x <为30x -<的充分不必要条件;对于D :02x <<为30x -<的充分不必要条件;故选:B4.若336a b +=,则a b +的取值范围是()A.(1,2]-B.[]0,2C .(2,)+∞ D.(,2]-∞【答案】D 【解析】【分析】根据基本不等式的应用可得3≥2a b +≤.【详解】易知30,30a b >>,所以336a b +=≥=,即可得3≥2393a b +≤=,所以2a b +≤,当且仅当1a b ==时,等号成立.故选:D5.幂函数()223()1m m f x m m x +-=--在(0,)+∞上是增函数,则实数m 的值为()A.2或1-B.1-C.2D.2-或1-【答案】C 【解析】【分析】根据幂函数的定义及幂函数的单调性,可得221130m m m m ⎧--=⎨+->⎩,进而求解即可.【详解】由题意得,221130m m m m ⎧--=⎨+->⎩,解得2m =.故选:C.6.若命题“2R,20x ax ax ∃∈-+≤”是假命题,则实数a 的取值范围是()A.{04}aa <<∣ B.{}08aa ≤≤∣C.{08}aa ≤<∣ D.{04}aa ≤<∣【答案】C 【解析】【分析】转化为x ∀∈R ,220ax ax -+>为真命题,分类讨论,结合判别式符号列不等式求解即可.【详解】命题:p x ∃∈R ,220ax ax -+≤为假命题,即x ∀∈R ,220ax ax -+>为真命题.当0a =时:20>恒成立;当0a ≠时:满足2Δ80a a a >⎧⎨=-<⎩,解得08a <<.综上,实数a 的取值范围是[)0,8,故选:C7.已知函数()16,2,2x x a x f x ax -⎧-≤=⎨>⎩在定义域上是单调递减函数,求实数a 的取值范围为()A.2,15⎡⎫⎪⎢⎣⎭ B.1,13⎛⎫ ⎪⎝⎭C.1,13⎡⎫⎪⎢⎣⎭ D.2,15⎛⎫⎪⎝⎭【答案】A 【解析】【分析】分段函数是减函数,各个函数在对应区间上单调递减,且(],2-∞对应函数右端点函数值大于或等于()2,+∞对应函数的左端点函数值,建立不等式后解得a 的取值范围.【详解】由题意可知:()6g x x a =-在(],2-∞上单调递减,又∵()6g x x a =-关于直线6x a =对称,∴()g x 在(],6a -∞上单调递减,∴62a ≥,∴13a ≥;()1x h x a -=在()2,+∞上单调递减,∴01a <<;且()()22g h ≥即26a a -≥,∴27a ≥或25a ≤,∴215a ≤<.故选:A.8.已知函数()f x 为定义在R 上的偶函数,12,(,0)x x ∀∈-∞,且()()12211221,4x f x x f x x x x x -<>-,且(2)4,(0)0f f -=-=,求不等式()4f x <-的解集为()A.[2,2]-B.(2,0)(0,2)-C.(2,0)(2,)-+∞D.(2,2)-【答案】B 【解析】【分析】构造函数()4()+=f x g x x,由已知条件确定它的奇偶性与单调性,然后利用其性质分类讨论解不等式.【详解】12,(,0)x x ∀∈-∞,且()()12211221,4x f x x f x x x x x --,则()()12212140x f x x f x x x -->-,()()122121[4][4]0x f x x f x x x +-+>-,所以212121()4()4f x f x x x x x ++->-,设()4()+=f xg x x,则2121(0)()g x x x g x ->-,21()()g x g x >,因此(,0)x -∞时,()g x 是增函数,又因为()f x 是偶函数,所以()4()4()()f x f x g x g x x x-++-==-=--,所以()g x 是奇函数,因此()g x 在(0,)+∞上也是增函数,(2)4(2)02f g -+-==-,则(2)(2)0=--=g g ,()4f x <-,()40f x +<,0x <时,()40f x x +>,即()0g x >,所以20x -<<,0x >时,()40f x x+<,即()0g x <,所以0<<2,综上,不等式的解集为()()2,00,2-⋃,故选:B .【点睛】方法点睛:本题考查函数的奇偶性与单调性解不等式,解题时主要要构造新函数()4()+=f xg x x,利用它的性质求解.在题中出现1221()()x f x x f x -时,构造新函数需要通过提取(或分子分母同除以或不等式两边同除以)21x x 得出2121()()f x f x x x -,当然本题中不等式右边不为0,因此需先移项变形,再确定构造的函数.二、多选题:本题共3小题,共18分.在每小题给出的选项中,有多项符合题目要求.全部选对的得6分,选对但不全的得部分分,有选错或不选的得0分.9.中国古代重要的数学著作《孙子算经》下卷有题:“今有物,不知其数.三三数之,剩二;五五数之,剩三;七七数之,剩二.问:物几何?”现有如下表示:已知{}*32,N A xx n n ==+∈∣,{}*53,N B x x n n ==+∈∣,{}*72,N C x x n n ==+∈∣,若()a A B C ∈⋂⋂,则下列选项中符合题意的整数a 为()A.23B.68C.128D.233【答案】ACD 【解析】【分析】依题意可知整数a 除以3余数为2,除以5余数为3,除以7余数为2;对选项逐一验证即可得出结论.【详解】根据题意可知,A B C ⋂⋂代表的是除以3余数为2,除以5余数为3,除以7余数为2的整数;对于A ,可知23372,23543,23732÷=⋅⋅⋅⋅⋅⋅÷=⋅⋅⋅⋅⋅⋅÷=⋅⋅⋅⋅⋅⋅,即A 正确;对于B ,可得683222,685133,68795÷=⋅⋅⋅⋅⋅⋅÷=⋅⋅⋅⋅⋅⋅÷=⋅⋅⋅⋅⋅⋅,不合题意,即B 错误;对于C ,可得1283422,1285253,1287182÷=⋅⋅⋅⋅⋅⋅÷=⋅⋅⋅⋅⋅⋅÷=⋅⋅⋅⋅⋅⋅,即C 正确;对于D ,易知2333742,2335463,2337332÷=⋅⋅⋅⋅⋅⋅÷=⋅⋅⋅⋅⋅⋅÷=⋅⋅⋅⋅⋅⋅.可知D 正确.故选:ACD10.若0,0,2a b a b >>+=,则下列不等式对一切满足条件的a ,b 恒成立的是()A.222a b ab +≤B.222a b +≥C.+≤ D.112a b+≥【答案】ABD 【解析】【分析】A 选项,222b a a a b b +=,利用基本不等式求出最大值;B 选项,由基本不等式得()()22224a b a b +≥+=,求出222a b +≥;C 选项,()224a b ≤+=2≤,C 错误;D 选项,利用基本不等式“1”的妙用求出最小值.【详解】A 选项,()()222222ab a b b a a b a b ab ++≤+===,当且仅当1a b ==时,等号成立,故A 正确;B 选项,()()22222224a bab ab a b +≥++=+=,故222a b +≥,当且仅当1a b ==时,等号成立,B 正确;C 选项,()224=+++=a b a b 2≤,当且仅当1a b ==时,等号成立,C 错误;D 选项,()11111111122222b a a b a b a b a b ⎛⎛⎫⎛⎫+=++=+++≥+= ⎪ ⎪ ⎝⎭⎝⎭⎝,当且仅当b aa b=,即1a b ==时,等号成立,D 正确.故选:ABD11.已知函数()f x 的定义域为R ,且满足2()()e e x x f x f x ---=+,则下列命题正确的是()A.函数()f x 的图像关于(0,0)对称B.函数()f x 的图像关于y 轴对称C.函数()f x 的最小值2D.()()0.10.123f f >-【答案】BC 【解析】【分析】依题意求出函数()f x 的解析式,可得其为偶函数,判断出A 错误,B 正确;再由基本不等式可得C 正确,利用奇偶性和单调性可得D 错误.【详解】由2()()e e x x f x f x ---=+可得2()()e e x x f x f x ---=+;两式联立可得()e e x x f x -=+,易知函数()f x 满足()()e e xxf x f x -=+=-,可知()f x 为偶函数,即可得A 错误,B 正确;易知e 0x >,所以()1e 2e x x f x =+≥=,当且仅当0x =时,等号成立,可得C 正确;当[)0,x ∈+∞时,根据对勾函数以及偶函数性质可得,()f x 为单调递增;易知()()0.10.133f f -=,且0.10.123<,所以()()()0.10.10.1233f f f <=-,即D 错误.故选:BC三、填空题:本题共3小题,每小题5分,共15分.12.计算:314316(0.125)(1181-⎛⎫-+-= ⎪⎝⎭___________.【答案】1927-【解析】【分析】根据分数指数幂运算法则计算可得结果.【详解】易知原式()()()314343132278190.510.512172323--⎛⎫⎛⎫⎛⎫=-+=-+=-+=-⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭;故答案为:1927-13.定义运算,,a a ba b b a b≤⎧⊗=⎨>⎩,已知函数()(132)3x f x x =-⊗,则()f x 的最大值为___________.【答案】9【解析】【分析】根据a b ⊗的含义及函数132y x =-与函数3x y =的单调性可得分段函数()f x 的解析式及单调性,可得最大值.【详解】由题意得,a b ⊗表示a 与b 的最小值,∵132y x =-在R 上单调递减,3x y =在R 上单调递增,且2x =时,1323x x -=,∴当2x ≤时,3132x x ≤-,当2x >时,3132x x >-,∴op =3,≤213−2s >2,∴()f x 在(,2)-∞上单调递增,在(2,)+∞上单调递减,∴max ()(2)9f x f ==.故答案为:9.14.若函数2231()3ax x f x ++⎛⎫= ⎪⎝⎭的值域是10,9⎛⎤ ⎥⎝⎦,则f (x )的单调递增区间是________.【答案】(,1]-∞-【解析】【分析】令g (x )=ax 2+2x +3,由f (x )的值域确定g (x )的值域,从而求出a 值,利用复合函数单调性的性质可得答案.【详解】令g (x )=ax 2+2x +3,由于f (x )的值域是10,9⎛⎤ ⎥⎝⎦,所以g (x )的值域是[2,+∞).因此有0,12424a a a>⎧⎪-⎨=⎪⎩解得a =1,这时g (x )=x 2+2x +3,2231()3x x f x ++⎛⎫= ⎪⎝⎭,由于g (x )的单调递减区间是(-∞,-1],所以f (x )的单调递增区间是(-∞,-1].故答案为:(,1]-∞-【点睛】本题考查复合函数的单调性,考查指数函数性质的应用,属于基础题.四、解答题:本大题共5小题,共77分.解答应写出文字说明,证明过程或演算步骤.15.已知集合|A x y ⎧==⎨⎩,103|2B x x x ⎧⎫=⎨⎬⎩⎭+>-.(1)求()R A B ⋃ð;(2)若{6}C xa x a =-≤≤∣,且A C A = ,求实数a 的取值范围.【答案】(1)()1A ,(0,)2R B ⎛⎤⋃=-∞-⋃+∞ ⎥⎝⎦ð(2)[4,6]【解析】【分析】(1)先化简集合A ,B ,再利用集合的并集和补集运算求解;(2)由A C A = ,得到A C ⊆求解.【小问1详解】解:由040x x >⎧⎨-≥⎩,得04x <≤.所以A (0,4]=,由2103x x +>-,得:2110,332x x x +<∴-<<-.所以1,32B ⎛⎫=-⎪⎝⎭,1,[3,)2R B ⎛⎤=-∞-⋃+∞ ⎥⎝⎦ð.所以,()1A ,(0,)2R B ⎛⎤⋃=-∞-⋃+∞ ⎥⎝⎦ð;【小问2详解】由A C A = ,得A C ⊆,所以604a a -≤⎧⎨≥⎩,解得64a a ≤⎧⎨≥⎩即46a ≤≤.所以实数a 的取值范围[4,6].16.已知2()(2)(,)f x ax a x b a b R =-++∈(1)若不等式()0f x <的解集为(1,3)-,求a ,b 的值;(2)若b =2,且0a >求关于x 的不等式()0f x >的解集.【答案】(1)2,6a b ==-(2)答案见解析【解析】【分析】(1)由不等式的解集得相应一元二次方程的解,结合韦达定理求解;(2)不等式变形为2(1)0x x a ⎛⎫--> ⎪⎝⎭,再根据2a与1的大小分类讨论得出不等式的解集.【小问1详解】因为()0f x <的解集为(1,3)-,所以0a >,且1-和3是方程2(2)0ax a x b -++=的两个实数根.2(1)3,(1)3a ba a+∴-+=-⨯=,解得:2,6a b ==-.【小问2详解】当2b =时,2()(2)2(2)(1)f x ax a x ax x =-++=--()0f x >等价于(2)(1)0ax x -->因为0a >,得2(1)0x x a ⎛⎫--> ⎪⎝⎭当21a =,即2a =时,不等式为2(1)0x ->,得1x ≠,当21a <,即2a >时,解不等式得2x a <或1x >,当21>a,即02a <<时,解不等式得1x <或2x a >,综上,当2a =时,不等式的解集为(,1)(1,)-∞⋃+∞.当2a >时,不等式的解集为2,(1,)a ⎛⎫-∞+∞ ⎪⎝⎭.当02a <<时,不等式的解集为2(,1),a ⎛⎫-∞+∞ ⎪⎝⎭.17.漳州市是中国重要的食用菌生产基地之一,食用菌产业得益于得天独厚的气候环境和土壤条件.某乡镇企业于2025年准备投资种植一批目前市场上较受欢迎的鸡枞菌.根据研究发现:种植鸡枞菌,一年需投入固定成本55万元,第一年最大产量50万斤,每生产x 万斤,需投入其他成本()c x 万元,211010,0366()160021285,3650x x x c x x x x ⎧++≤≤⎪⎪=⎨⎪+-<≤⎪⎩,根据市场调查,鸡枞菌的市场售价每万斤20万元,且全年所有产量都能全部售出.(利润=收入-固定成本-其它成本)(1)写出2025年利润f x ()(万元)与产量x (万斤)的函数解析式;(2)求2025年鸡枞菌产量x 为多少万斤时,该企业所获利润最大,求出利润最大值.【答案】(1)211065,0366()1600230,3650x x x f x x x x ⎧-+-≤≤⎪⎪=⎨⎪--+<≤⎪⎩(2)2025年产量为40万斤时,该企业所获利润最大,利润最大值为150万元【解析】【分析】(1)由利润=收入-固定成本-其它成本,根据题意求解;(2)由(1)的结论,利用二次函数的性质和基本不等式求解.【小问1详解】解:由题意可知:当036x ≤≤时,2211()20101055106566f x x x x x x ⎛⎫=-++-=-+- ⎪⎝⎭,当3650x <≤时,16001600()202128555230,f x x x x x x ⎛⎫=-+--=--+ ⎪⎝⎭211065,0366()1600230,3650x x x f x x x x ⎧-+-≤≤⎪⎪∴=⎨⎪--+<≤⎪⎩.【小问2详解】由211065,0366()1600230,3650x x x f x x x x ⎧-+-≤≤⎪⎪=⎨⎪--+<≤⎪⎩,①当036x ≤≤时,2211()1065(30)8566f x x x x =-+-=--+当30x =时,()f x 取得大值,最大值为85,②当3650x <≤时,1600()230230150f x x x ⎛⎫=-++≤-= ⎪⎝⎭,当且仅当1600x x=即40x =时,()f x 取得最大值50,由①②可得:当40x =时,()f x 取得最大值150,综上所述,2025年产量为40万斤时,该企业所获利润最大,利润最大值为150万元.18.设函数2x x f a ka x -=-()(0a >且1,R)a k ≠∈,若()f x 是定义在R 上的奇函数且8(1)3f =.(1)求k 和a 的值;(2)判断()f x 的单调性(无需证明),并求关于m 的不等式()2(1)50f m f m ++-+<成立时实数m 的取值范围;(3)已知函数22()2(),[0,1]x x g x a a f x x -=+-∈,求()g x 的值域.【答案】(1)1,32k a ==(2)在R 上单调递增,()(),23,-∞-⋃+∞(3)341,9⎡⎤⎢⎥⎣⎦【解析】【分析】(1)利用函数奇偶性以及函数值即可解得k 和a 的值;(2)由复合函数单调性可判断()f x 在R 上单调递增,利用单调性以及奇偶性解不等式可得实数m 的取值范围;(3)利用换元法将函数整理成二次函数形式,判断出其单调性,再由二次函数性质可得结果.【小问1详解】因为()f x 是R 上奇函数,所以()()f x f x -=-,即22x x x x a ka a ka ---=-+,整理得:()(12)0x x k a a --+=所以1120,2k k -==.所以()x x f x a a -=-,检验可知符合题意;又18(1)3f a a =-=,即28103a a --=,解得3a =或13a =-(舍)所以1,32k a ==.【小问2详解】由(1)可知()33x x f x -=-,易知指数函数3x y =为单调递增,函数3x y -=为单调递减,利用复合函数单调性可得()f x 在R 上单调递增,又因为()f x 为R 上的奇函数,所以()()22(1)55f m f m f m +<--+=-所以215m m +<-,即260m m -->,解得2m <-或3m >.所以()f x 在R 上单调递增,m 的取值范围是−∞,−2∪3,+∞【小问3详解】()2222()2()2,[0,1]x x x x x x g x a a f x a a a a x ---=+-=+--∈所以()22()33233x x x x g x --=+--()()2332332,[0,1]x x x x x --=---+∈令33x x t -=-,由(2)易知33x x t -=-在0,1上单调递增,所以8t 0,3⎡⎤∈⎢⎥⎣⎦记22822(1)1,0,3y t t t t ⎡⎤=-+=-+∈⎢⎥⎣⎦当时min 1,1t y ==;当83t =时,max 349y =.所以()g x 的值域是341,9⎡⎤⎢⎥⎣⎦.19.我们知道,函数()y f x =的图象关于坐标原点成中心对称图形的充要条件是函数()y f x =为奇函数,有同学发现可以将其推广为:函数()y f x =的图象关于点(,)P a b 成中心对称图形的充要条件是函数()y f x a b =+-为奇函数.给定函数4()1f x x x c=-++.(1)写出函数()f x 图象的对称中心(只写出结论即可,不需证明);(2)当2c =时,①判断函数()f x 在区间(2,)-+∞上的单调性,并用定义证明;②已知函数g(1)1x +-是奇函数,且当[0,1]x ∈时,2()22g x x mx m =-+,若对任意1[0,2]x ∈,总存在2[0,2]x ∈,使得()()12g x f x =,求实数m 的取值范围.【答案】(1)(,1)c c --(2)①函数()f x 在区间(2,)-+∞上单调递增,证明见解析;②[0,1].【解析】【分析】(1)由函数成中心对称的充要条件可得()4()1f x c c x x---=-为奇函数,可得对称中心;(2)①根据单调性定义按照步骤即可证明函数()f x 在区间(2,)-+∞上单调递增;②依题意并根据二次函数性质得出两函数的值域之间的包含关系,限定出最值之间的不等关系,解不等式即可求得结果.【小问1详解】根据题意可知,函数4()1f x x x c =-++是由函数4y x x =-向左平移c 个单位,向上平移1个单位得到的;所以()4()1f x c c x x---=-为奇函数,可得函数()f x 图象的对称中心是(,1)c c --.【小问2详解】当2c =时,4()12f x x x =-++.①函数()f x 在区间(2,)-+∞上单调递增;证明如下:12,(2,)x x ∀∈-+∞,且12x x <,()()()()()12121212124441112222f x f x x x x x x x x x ⎛⎫-=-+-+-=-+ ⎪ ⎪++++⎝⎭,因为122x x -<<,所以12120,20,20x x x x -<+>+>,所以()()1241022x x +>++,所以()()120f x f x -<,即()()12f x f x <.所以()f x 在(2,)-+∞单调递增,②因为(1)1g x +-是奇函数,所以()g x 关于点(1,1)对称,设()g x 在[0,2]上的值域为,()A f x 在[0,2]上的值域为B .因为对任意1[0,2]x ∈,总存在2[0,2]x ∈,使得()()12g x f x =,所以A B ⊆,由①可知()f x 在[0,2]上单调递增,又(0)1,(2)2f f =-=,所以[1,2]B =-,又222()22()2,[0,2]g x x mx m x m m m x =-+=--+∈,当0m <时,()g x 在[0,1]上单调递增,又g(1)1,()g x =关于点(1,1)对称,所以函数()g x 在(1,2]也单调递增,故()g x 在[0,2]上单调递增,又因为g(0)2,(2)2(0)22m g g m ==-=-,故[2,22]A m m =-,因为A B ⊆,所以21222m m ≥-⎧⎨-≤⎩,得0m ≥,又0m <,所以此时m 不存在.当01m ≤≤时,g()x 在(0,)m 单调递减,在(,1)m 单调递增,又g()x 的对称中心为(1,1),所以g()x 在(1,2)m -单调递增,在(2,2]m -单调递减,所以[min{(2),()},max{(0),(2)}]A g g m g g m =-,要使A B ⊆,只需()()()222022121g g m g m m m ⎧=-=-≥-⎪⎨=-+≥-⎪⎩,且()()()202222222g m g m g m m m ⎧=≤⎪⎨-=-=-+≤⎪⎩,解得01m ≤≤,又01,m ≤≤所以01m ≤≤,当1m >时,()g x 在[0,1]单调递减,所以()g x 在(1,2]单调递减,所以()g x 在[0,2]单调递减,所以[22,2]A m m =-,所以22122m m -≥-⎧⎨≤⎩,所以1m ≤,又1m >,所以此时m 不存在,综上:01m ≤≤,即m 的范围是[0,1].【点睛】关键点点睛:本题关键在于根据二次函数性质得出两函数的值域之间的包含关系,限定出最值之间的不等关系,解不等式即可求得结果.。
2023-2024学年第一学期期中考试高一语文试题卷
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巴楚县2023-2024学年第一学期期中测试卷高一年级语文考生须知:1.本试卷满分150分,考试时间150分钟。
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一、现代文阅读(35分)(一)现代文阅读Ⅰ(本题共5小题,19分)阅读下面的文字,完成下面小题。
材料一:旷世奇才苏轼不仅是杰出的文学家,而且是出色的文学批评家。
在对诗歌的社会功能和审美特性的认识上,苏轼有自己的见解和思想渊源。
苏轼具有仁政爱民的思想和积极入世的精神,重视文学积极的社会作用,强调有为而作,针砭时弊。
他在《题柳子厚诗》中写道:“诗须要有为而作……好奇务新,乃诗之病。
”所谓“有为而作”,目的在于揭发当世政治的过失和社会中的种种不平,从而达到“疗饥”“伐病”的功效。
苏轼认为写诗就要充分发挥诗歌的社会功能,有所劝诫,有补于世,不能一味地粉饰现实,阿谀奉承。
苏轼《答乔舍入启》中写道:“某闻人才以智术为后,而以识度为先;文章以华采为末,而以体用为本。
国之将兴也,贵其本而贱其末;道之将废也,取其后而弃其先。
用舍之间,安危攸寄。
”作者把文章重“体用”还是重“华采”与国家的兴亡联系起来,强调“以体用为本”。
“以体用为本”与“有为而作”的精神完全一致,都是儒家兼济天下的思想的苏轼文艺的反映。
苏轼认为诗画要传神,他的“诗画一律”精辟地阐述了诗画创作中形似与神似的关系。
绘画过分追求形似,则不能传神;作诗仅仅满足于摹写物象,意尽句中,也不是成功的艺术作品。
诗画都要遗貌取神,抓住客观物象的本质特征,才能达到传神的目的,这就是诗与画共同的本质特点。
诗与画是两种不同的文艺形式,但苏轼认为它们之间有着共同的美学标准,即“天工与清新”。
广东省深圳市深圳盟校期中联盟考试2024-2025学年高一上学期11月期中英语试题含答案
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2024~2025学年度高一上学期期中考试英语(答案在最后)考生注意:1.本试卷满分150分,考试时间120分钟。
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第一部分单项填空(共20小题;每小题1.5分,满分30分)从A、B、C、D四个选项中,选出可以填入空白处的最佳选项。
1.At______sight of his classmate,Bill,who was in______lead in the long-distance running,Bruce tried to run faster.A.a;a B.the;a C.a;the D.the;the2.Which of the following prefixes(前缀)means“No”?A.un-B.en-C.co-D.over-3.—Jack,are you familiar with Boston?—Yes,I______in Boston for four years.A.remain B.am remaining C.have remained D.remained4.The store______sells children’s clothes is at the end of the street.A.whom B.不填C.whose D.which 5.Yesterday the policemen______the traffic accident that happened in front of the supermarket and relevant people are waiting for the result.A.investigated B.stuck C.sculpted D.disqualified6.I found him ashamed when I asked him the question.What is the sentence element underlined in the sentence? ______A.Subject(主语).B.Object(宾语).C.Predictive(表语).D.Object complement(宾语补足语).7.An______is an important subject that people are arguing about or discussing.A.impact B.issue C.alarm D.exploration8.Tom tends______very well in a match and that may allow us______the match to be held tomorrow.A.to perform;to win B.to perform;winning C.performing;to win D.performing;winning 9.Which of the following suffixes is the opposite(反义词)of“-ful”?A.-able B.-ness C.-less D.-ous10.The man______job is a lawyer lives in the apartment above ours.A.that B.which C.who D.whose11.A fact,situation,or experience that is______is unpleasant,depressing,or harmful.A.significant B.powerful C.negative D.specific 12.Though Tom stayed______touch with his friend Sam for a long time,they lost track______each ther during the war.A.in;of B.at;over C.by;with D.for;on13.______technology has changed the way we make friends,the meaning of friendship and our longing for friends remain the same.A.Until B.Though C.Since D.Unless14.Which word is formed in the same way as“homesick”?A.unfold B.rainbow C.disqualify D.professional 15.The water in the river was very dirty and smelly in the past but______it is very clear and clean. A.currently B.individually C.creatively D.bitterly16.—I wonder where some of our classmates are?—They______a drama on the stage at the moment.A.practise B.will practise C.are practising D.were practising 17.Living without an aim is like sailing without a compass.What is the basic structure of the sentence?______ A.S+V(主语+谓语动词)B.S+V+P(主语+系表结构)C.S+V+IO+DO(主语+谓语动词+间接宾语+直接宾语)D.S+V+O+OC(主语+谓语动词+宾语+宾语补足语)18.What is the structure of the sentence“The company offered me a job the day before yesterday”?A.S+V+P(主语+系表结构)B.S+V+O(主语+谓语动词+宾语)C.S+V+O+OC(主语+谓语动词+宾语+宾语补足语)D.S+V+IO+DO(主语+谓语动词+间接宾语+直接宾语)19.Helen spent a lot of time______to solve the math problem but she still had trouble______it out. A.trying;to work B.trying;working C.to try;to work D.to try;working 20.We waited for Franklin to come to the party but he did not______until well after midnight.A.work out B.go all out C.calm down D.turn up第二部分阅读(共两节,满分50分)第一节(共15小题;每小题2.5分,满分37.5分)阅读下列短文,从每题所给的A、B、C和D四个选项中,选出最佳选项。
山西省山西大学附中2024_2025学年高一语文上学期期中试题
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山大附中2024~2024学年第一学期期中考试高一年级语文试题考试时间:120分钟考查内容:综合题一、文学类文本阅读(15分)阅读下面的散文,完成1~3题。
秋风桐槐说项羽梁衡①这里属于江苏省宿迁市。
我原以为故里者只是一座古朴的草房,或农家小院,不想这项羽故里竟是一座新修的旅游城,而城中真正与项羽有关的旧物也只有两棵树:一棵青桐,一棵古槐。
斯人远去,就只有来凭吊这两棵树了。
②那棵青桐,树上特地挂了牌,名“项里桐”。
据说,项羽诞生后,家人将他的胞衣(胎盘)埋于此树下,这桐树就特殊茂密,青枝绿叶,直冲云天。
在中国神话中梧桐是凤凰的栖身之地,有桐有凤的人家贵不行言,项羽在此树下诞生盖有天意。
梧桐之东不远处,有一棵巨大的中国槐,说是项羽手植。
两千年的风雨,手植槐修成了黄河槐;黄河槐又炼成了雷公槐。
这摄取了天地之精、大河之灵的古槐,日修月炼,水淹不没,沙淤不死,雷劈不倒,壮哉项羽!③项羽的家乡在苏北平原,两千年来战火多数,文物留存极少,而其故里始终未被遗忘,直到现在这个旅游城。
城内遍置各种与项羽有关的游乐设施,其中有一种可在架子上翻转的木牌,正面是项羽、虞姬等各种画像,翻过来就是一条条因项羽而生的成语。
如:破釜沉舟、取而代之、一决雌雄、所向无敌、拔山扛鼎、分我杯羹……现在我们常用到的成语总共也就一千多条,项羽一人就占百条。
要知道他才活了三十一岁,政治、军事生涯也只有五年。
后人多观赏他的武功,倒忽视了他的文化贡献。
④项羽是个失败的英雄,失败缘于他人性的弱点。
刚烈坚毅又优柔寡断,欲雄霸天下又留恋家乡;他少不读书,临终之时却作“力拔山兮气盖世”,感天动地、流传千古;他杀人如麻,却爱得缠绵,在身陷重围、生死攸关之际还与虞姬弹剑而歌。
他身上有巨大的悲剧之美,因此他是艺术境界中的人物,是艺术创作的好原型。
⑤项羽是民间筛选出来的体现了平民价值观和生活旨趣的人物,人们宠爱他的英勇刚烈、纯朴真实,就如宠爱关羽的忠义一样。
历史上的“两羽”一勇一忠,成了中国人的偶像,是与岳飞的精忠报国、文天祥的青史丹心并存的两个价值体系。
2024-2025学年江苏省苏州市常熟市高一第一学期期中考试数学试题 (含答案)
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2024-2025学年江苏省常熟市高一第一学期期中考试数学试题一、单选题:本题共8小题,每小题5分,共40分。
在每小题给出的选项中,只有一项是符合题目要求的。
1.已知命题p:“∃x∈R,x+2≤0”,则命题p的否定为( )A. ∃x∈R,x+2>0B. ∀x∈R,x+2>0C. ∃x∉R,x+2>0D. ∀x∈R,x+2≤02.已知x>0,则x−1+4x的最小值为( )A. 4B. 5C. 3D. 23.已知函数y=f(x)的定义域为[−2,1],则函数y=f(2x+1)的定义域为( )A. RB. [−2,1]C. [−3,3]D. [−32,0]4.若函数f(x)=(m2−2m−2)x2−m是幂函数,且y=f(x)在(0,+∞)上单调递减,则实数m的值为( )A. 3B. −1C. 1+3D. 1−35.常熟“叫花鸡”,又称“富贵鸡”,既是常熟的特产,也是闻名四海的佳肴,以其鲜美、香喷、酥嫩著称。
双十一购物节来临,某店铺制作了300只“叫花鸡”,若每只“叫花鸡”的定价是40元,则均可被卖出;若每只“叫花鸡”在定价40元的基础上提高x(x∈N∗)元,则被卖出的“叫花鸡”会减少5x只.要使该店铺的“叫花鸡”销售收入超过12495元,则该店铺的“叫花鸡”每只定价应为( )A. 48元B. 49元C. 51元D. 50元6.已知f(x)是奇函数,对于任意x1,x2∈(−∞,0)(x1≠x2),均有(x2−x1)(f(x2)−f(x1))>0成立,且f(2)=0,则不等式xf(x−2)<0的解集为( )A. (−2,0)∪(2,4)B. (−∞,−2)∪(2,4)C. (2,4)D. (−2,0)∪(0,2)7.通过研究发现:函数y=f(x)的图象关于点P(a,b)成中心对称图形的充要条件是函数y=f(x+a)−b为奇函数,则函数f(x)=x3−3x2图象的对称中心为( ) 参考公式:(a+b)3=a3+3a2b+3ab2+b3A. (0,0)B. (1,2)C. (1,−2)D. (2,−4)8.已知正实数a,b满足a+b=4,则代数式1b +b+1a的最小值为( )A. 5+12B. 5+14C. 54D. 25+2二、多选题:本题共3小题,共18分。
2023-2024学年度上学期高一数学期中考试[含答案]
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又 f (x) 是奇函数,所以 0 x 2 时, f (x) 0 , x 2 时, f (x) 0 ,且 f (0) f (2) 0 ,
不等式
xf
x
0
x
f
0
x
0
或
x
f
0 (x)
0
或
x
0
,所以 0
x
2 或 2
x
0
,
综上 2 x 2 .
故选:D.a 23 , b 45 , c 253 ,则
【解析】
【分析】根据交集含义即可得到答案.
A B 1, 0,1
【详解】根据交集含义即可得到
,
故选:B.
2. 命题: x R, x | x | 0 的否定为( )
A. x R, x | x | 0
B. x R, x | x | 0
C. x R, x | x | 0
D. x R, x | x | 0
【详解】因为
f
2x
1
x2
1 t
,令
2x
1,
x
t
1 2
,
f
(t)
t
1 2 2
1
,即
f
(x)
x 12 2
1
,
所以 f (3) 2 .
故选:B
6.
若定义在 R 的奇函数
f
x
,若
x
0
时
f
x
x 2
xf
,则满足
x 0 的 x 的取值范围是(
)
, 20, 2
A. 【答案】D 【解析】
, 2 2, , 20, 2
对于 C,
y∣y∣ x2 1, x R
2024-2025学年淄博市实验高一数学上学期期中模拟考试卷及答案解析
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,解得 m 5 或 m 1 ,
所以实数 m 的取值范围为 ,1 5, .
故选:C.
8. 已知定义在 R 上的函数 f x 满足 f x f x 0 , x1 , x2 0, ,当 x1 x2 时,都有
f x1 f x2
5 2x 0
【详解】由题意可得 ln(5 2 x) 0 ,解得 0 x 2 ,
ex 1 0
故选:D.
1
1
2
3
5. 已知 a log 3 2 , b 1 , c 1 ,则实数 a, b, c 的大小关系正确的是(
5
【详解】 A { y | y lg( x 2 x 2)} 为函数 y lg( x 2 x 2) 的值域,
令 t x 2 x 2 0 x 2 或 x 1 , t (0, ) y lg t y R ,
B {x | y x 2 x 2} 为函数 y x 2 x 2 的定义域,
D. 1,5
【答案】C
【解析】
【分析】根据题意,问题可转化为
得到 ( x 1) y 4 ,进而得到
到
m
y2 x 1
y
1
对任意的 x 0, y 0 恒成立,由题设条件
m 1 x 1 y x 1 y
y
1
y
x 1 1
y
1
,接着结合基本不等式求得
)
, 2
故选:D
7. 已知 x 0, y 0 ,且 x y 3 ,若
贵州贵州省部分学校联考2024-2025学年高一上学期11月期中英语试题(含解析,含听力原文无音频)
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高一联考英语注意事项:1.答题前,考生务必将自己的姓名、考生号、考场号、座位号填写在答题卡上。
2.回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
回答非选择题时,将答案写在答题卡上。
写在本试卷上无效。
3.考试结束后,将本试卷和答题卡一并交回。
第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。
录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
例:How much is the shirt?A. £19.15.B. £9.18.C. £9.15.答案是C。
1. Which place was dry yesterday?A. The beach.B. The eastern area.C. The downtown area.2. What does the man want to buy?A. Clothes.B. Shoes.C. Socks.3. What will the woman do next?A. Go to sleep.B. Turn on the TV.C. Talk to the man.4. What is the probable relationship between the speakers?A. Mother and son.B. Doctor and patient.C. Boss and secretary.5. How does the man feel about living on his own?A. Excited.B. Bored.C. Worried.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。
2024—2025学年度第一学期期中考试高一学年 语文试卷
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2024—2025学年度第一学期期中考试高一学年语文试卷分值:150分时间:150分钟一、课内知识考查(每题2分,12小题共计24分)1.下列各项对划线的词解释完全正确的一项是()A.①食野之苹苹:青草②渚清沙白鸟飞回渚:水中的小洲B.①一尊还酹江月酹:将酒洒在地上,表示凭吊。
②如今有谁堪摘?堪:可以,能够。
D.①弦弦掩抑声声思思:悲伤②赢得仓皇北顾顾:回头望2.下列各项对划线的词解释完全正确的一项是()A.①契阔谈讌契阔:久别重逢②落木:落叶B.①户庭无尘杂尘杂:灰尘杂物②最难将息将息:养息,休息②江州司马青衫湿青衫:蓝色单衣,唐代地方官员的服色D.①虚室有余闲虚室:静室。
潦倒:漂泊沦落3.下列各项中对划线的词语解释完全正确的一项是()A.①青青子衿,悠悠我心悠悠:从容自然的样子②水澹澹兮生烟澹澹:水波平静的样子B.①又闻此语重唧唧唧唧:内心悲伤的样子②呦呦鹿鸣,食野之苹呦呦:鹿叫的声音C.①云青青兮欲雨青青:黑沉沉的样子②凄凄惨惨戚戚戚戚:悲愁、哀伤的样子。
D.②无边落木萧萧下萧萧:形容风声4.下列各项划线的词意义用法不相同的一项是()A.B.①低眉信手续续弹,C.①势拔五岳掩赤城②出类拔萃5.下列各项划线的词意义和用法相同的一项是()A.①满座重闻皆掩泣②座中泣下谁最多B.①我从去年辞帝京②莫辞更坐弹一曲C.①采采芣苢,薄言掇之②明明如月,何时可掇D.①秧根未牢莳未匝②绕树三匝,何枝可依?6.下列各项划线的词意义和用法相同的一项是()A.①云霞明灭或可睹②马之千里者,一食或尽粟一石B.①我欲因之梦吴越②未若柳絮因风起C.①忽魂悸以魄动②何以解忧?唯有杜康D.①为君翻作《琵琶行》②初为《霓裳》后《六幺》7.下列选项中全为通假字一项是()①契阔谈讌②樯橹灰飞烟灭③曲终收拨当心画④误落尘网中,一去三十年⑤列缺霹雳,丘峦崩摧⑥一尊还酹江月A.①②⑤B.③④⑥C.③⑤⑥D.①⑤⑥8.下列各项两句中划线的词活用方式不相同的一项是()A.B.C.①安能摧眉折腰事权贵②廉颇老矣,尚能饭否?D.①乌鹊南飞②浔阳江头夜送客9.下列各项中全是古今异义词的一项是()A.②渌水荡漾清猿啼B.①失向来之烟霞②憔悴损,如今有谁堪摘C.①整顿衣裳起敛容②梦啼妆泪红阑干D.①赢得仓皇北顾②对酒当歌,人生几何10.下列各项修辞手法相同的一项()A.①唯有杜康②安能摧眉折腰事权贵B.①身登青云梯②主人下马客在船C.①一夜飞度镜湖月。
北京2023-2024学年高一上学期期中生物试题含答案
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【详解】A、该午餐包含脂肪、磷脂和固醇等脂质,A 正确;
B、该午餐含有的多糖有糖原、淀粉、纤维素,B 错误;
C、高温会破坏蛋白质的空间结构,因此熟鸡蛋比生鸡蛋的蛋白质更易消化,C 错误;
D、午餐中的 DNA 不会改变人体的 DNA,D 错误。
故选 A。 【点睛】“吃得营养,吃出健康”是人类普遍的饮食追求,本题考查了人体所需的六大营养素,同时告诫我们 在生活中一定要注意营养物质的均衡搭配,要合理膳食。 9. 人胰岛素是由 A、B 两条多肽链构成的蛋白质,其中 A 链含有 21 个氨基酸,B 链含有 30 个氨基酸(如 图)。下列表述正确的是( )
是由 C、H、O 构成。
【详解】A、核糖核酸的元素组成是 C、H、O、N、P,氨基酸的元素组成为 C、H、O、N,都含有 N 元素,
均能用 15N 标记,A 正确;
B、脂肪和纤维素都是由 C、H、O 构成,不含有氮元素,B 错误;
C、乳糖属于糖类,由 C、H、O 构成,不含有氮元素,C 错误;
D、淀粉属于糖类,由 C、H、O 构成,不含有氮元素,D 错误。 故选 A。 5. 水和无机盐是细胞的重要组成成分,下列说法正确的是( ) A. 自由水和结合水都能参与物质运输和化学反应 B. 同一植株,老叶细胞比幼叶细胞自由水含量高 C. 哺乳动物血液中 K+含量太低,会出现抽搐等症状 D. 点燃一粒小麦,燃尽后的灰烬是种子中的无机盐 【答案】D 【解析】 【分析】1、细胞内水的存在形式是自由水与结合水。结合水与细胞内的其他物质相结合,是细胞结构的重 要组成成分,约占细胞内全部水分的 4.5%;细胞中绝大部分的水以游离的形式存在,可以自由流动,叫做 自由水。 2、自由水的作用是:①细胞内良好的溶剂;②参与生化反应;③为细胞提供液体环境;④运送营养物质和 代谢废物。自由水与结合水的比值越大,细胞代谢越旺盛,抗逆性越差,反之亦然。 3、无机盐的功能:(1)细胞中某些复杂化合物的重要组成成分。如:Fe2+是血红蛋白的主要成分;Mg2+是 叶绿素的必要成分。(2)维持细胞的生命活动。如血液钙含量低会抽搐。(3)维持细胞的形态、酸碱度、 渗透压。 【详解】A、结合水与细胞内的其他物质相结合,是细胞结构的重要组成成分,结合水不能参与物质运输和 化学反应,A 错误; B、同一植株,幼叶细胞比老叶细胞自由水含量高,代谢旺盛,B 错误; C、哺乳动物血液中钙离子含量太低,会出现抽搐等症状,C 错误; D、点燃一粒小麦,有机物在燃烧过程中分解为 CO2 和水,燃尽后的灰烬是种子中的无机盐,D 正确。 故选 D。 6. 关于玉米细胞和人体细胞中的糖类,下列说法不正确的是( ) A. 玉米细胞中有蔗糖 B. 都以葡萄糖作为主要的能源物质 C. 人体肝细胞中有糖原 D. 都以淀粉作为主要的储能物质 【答案】D 【解析】 【分析】糖类分为多单糖、二糖和多糖,单糖包括葡萄糖、核糖、脱氧核糖等,二糖包括蔗糖、麦芽糖、
河北省保定市六校联盟2024-2025学年高一上学期11月期中联考语文试题附答案
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六校联盟2024年11月期中联考高一语文试题考生注意:1.本试卷满分150分,考试时间150分钟。
2.答题前,考生务必用直径0.5毫米黑色墨水签字笔将密封线内项目填写清楚。
3.考生作答时,请将答案答在答题卡上。
选择题每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑;非选择题请用直径0.5毫米黑色墨水签字笔在答题卡上各题的答题区域内作答,超出答题区.....域书写的答案无效,在试题卷、草稿纸上作答无效。
.......................4.本卷命题范围:人教版必修上册第一、二、三单元。
一、现代文阅读(37分)(一)现代文阅读Ⅰ(本题共5小题,19分)阅读下面的文字,完成1~5题。
①人物通讯是以报道新闻人物事迹或活动,展示人物精神面貌为主要内容的通讯类型。
它在通讯体裁中占有相当重要的位置。
人物通讯在写作上文笔细腻,描述事实详尽,常常和议论、抒情结合起来,人物形象较为丰满,精神境界得到充分揭示,因而篇幅较长,在时效性上不如人物消息。
也正因为如此,它比人物消息具有更高的审美要求。
②人物通讯要选择适当的新闻事实塑造新闻人物的形象美。
人物通讯的形象美与作者能否正确把握人物与事件的关系密切相关。
季水河先生在《新闻美学》中曾明确指出,新闻事实本身也含有形象之意,因为事与人有着紧密的联系。
在社会生活中,既没有离开事实的人物,也没有离开人物的事实。
新闻作品报道事实也好,描写人物也好,都是不能将人和事截然分开的。
写人必叙事,叙事必写人。
新闻事实是新闻形象的基础,成功的新闻作品所描写的人物形象都不是抽象的,都是以大量事实为基础去塑造形象的。
③要选择最典型的事件来塑造新闻人物形象。
无论是普通百姓还是高层人物,都会在不同方面体现出特殊的社会影响,他们身上也有着不同的新闻价值,因此根据人物所具有的新闻价值来选取的新闻事件,必须是最能体现人物个性的事件,必须是最具代表性的事件。
例如描写医学界名人的一篇人物通讯《多重角色王宁生》,这是《人民日报》上的一篇人物专访,全文主要介绍了王宁生作为医学界重要人物对于其工作领域的贡献。
安徽省2024-2025学年高一上学期11月期中教学质量检测数学试题(含答案)
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安徽省2024-2025学年高一上学期11月期中教学质量检测数学试题考试时间:120分钟满分150分一、单选题:本题共8小题,每小题5分,共40分.1.下列集合中表示同一集合的是()A. B.C. D.2.若,则下列不等式不能成立的是()A. B.C. D.3.不等式的解集为A.或B.或C.或D.4.函数的图象可能是()A. B. C. D.5.已知,则()A.27B.18C.15D.256.函数的单调递减区间是()A. B. C. D.7.已知是偶函数,且其定义域为,则()A. B.-1 C.1 D.78.已知函数,若存在,且两两不相等,则的取值范围为A. B. C.[0,1] D.{(3,2)},{(2,3)}M N=={4,5},{5,4}M N=={(,)1},{1}M x y x y N y x y=+==+=∣∣{1,2},{(1,2)}M N==a b<<||||a b>2a ab>11a b>11a b a>-23540x x-+->{3x x≤-∣2}x≥{3x x≤-∣1}x≥{31x x-≤≤∣2}x≥∅1(0,1)xy a a aa=->≠13a a-+=33a a-+=()f x=(,3]-∞-[1,1]-(,1]-∞-[1,)-+∞2()35f x ax bx a b=+-+[61,]a a-a b+=1725,0()22,0x xf xx x x->⎧=⎨+-≤⎩()()()123f x f x f x==123x x x、、123x x x++()(1,1)-(1,1]-(0,1]二、多选题:本题共3小题,共18分.9.(多选)下列说法正确的有( )A.命题,则B.“”是“”成立的充分条件C.命题,则D.“”是“”的必要条件10.若正实数a ,b 满足,则下列说法正确的是( )A.ab 有最大值C.有最小值4 D.11.对于函数的定义域中任意的,当时,如下结论正确的是( )A. B.C.D.三、填空题:本题共3小题,每小题5分,共15分.12.命题“对任意,都有”的否定是_______________.13.已知,求函数的最小值是_______________.14.已知是上的增函数,则实数的取值范围是_______________.四、解答题:本题共5小题,共77分.15.(本小题13分)已知集合,集合.(1)求;(2)设集合,且,求实数的取值范围.16.(本小题15分)已知二次函数.(1)若的解集为,求a ,b 的值;(2)若f (x )在区间上单调递增,求的取值范围.:,(0,1),2p x y x y ∀∈+<0000:,(0,1),2p x y x y ⌝∃∈+≥1,1a b >>1ab >2:,0p x R x ∀∈>2:,0p x R x ⌝∃∈<5a <3a <1a b +=14+11a b+22a b +()f x ()1212,x x x x ≠()2xf x =()()()1212f x x f x f x +=⋅()()()1212f x x f x f x ⋅=+()()12120f x f x x x ->-()()121222f x f x x x f ++⎛⎫<⎪⎝⎭x R ∈20x ≥54x >14245y x x =-+-2,1()4,12x a x f x a x x ⎧->⎪=⎨⎛⎫-≤ ⎪⎪⎝⎭⎩R a {22}A xx =-∣……{1}B x x =>∣()R B A ⋂ð{6}M xa x a =<<+∣A M M ⋃=a 2()3()f x x ax a R =--∈()0f x <{3}xx b -<<∣[2,)-+∞a17.(本小题15分)如图,某人计划用篱笆围成一个一边靠墙(墙的长度没有限制)的矩形菜园.设菜园的长为x m ,宽为y m.(1)若菜园面积为18m 2,则当x ,y 为何值时,可使所用篱笆总长最小?并求出最小值.(2)若使用的篱笆总长度为16m ,则当x ,y 为何值时,可使菜园面积最大?并求出最大值.18.(本小题17分)已知函数在上是偶函数,当时,,(1)求函数在上的解析式;(2)求单调递增区间和单调递减区间;(3)求在的值域.19.(本小题17分)已知函数对任意实数x ,y 恒有,且当时,,又.(1)判断的奇偶性;(2)求证:是上的减函数并求函数在区间上的最大值;(3)若对任意,不等式恒成立,求的取值范围.()f x R 0x (2)()23f x x x =+-()f x R ()f x ()f x [4,4]-()f x ()()()f x y f x f y +=+0x >()0f x <(1)2f =-()f x ()f x R ()f x [3,3]-x R ∈()23()4f axf x <+a高一期中考试数学参考答案1.B2.D3.D4.D5.B6.B7.A8.D 7.A 8.D9.ABD 10.AC 11.ACD12.存在,使得13.514.[4,8)14.解:(1)由已知,又,所以;(2)因为,所以,又,所以,解得.所以的取值集合为.16.解:(1)的解集为,和是方程的两根,由根与系数关系得:;.(2)的对称轴为且在区间上单调递增,;.17.解:(1)由已知可得,而篱笆总长为;又因为,当且仅当时,即时等号成立所以菜园的长为6m ,宽为3m 时,可使所用篱笆总长最小,最小值为12;0x R ∈200x ≤{1}R B x x =≤∣ð{22}A x x =-∣……(){21}R B A xx ⋂=-∣......ðA M M ⋃=A M ⊆{22},{6}A x x M x a x a =-=<<+∣∣ (62)2a a +>⎧⎨<-⎩42a -<<-a {42}a a -<<-∣()0f x < {3}x x b -<<∣3∴-b 230x ax --=∴3,33b a b -+=-⨯=-2,1a b ∴=-=()f x 2ax =()f x [2,)-+∞22a∴≤-4a ∴≤-18xy =2L x y =+212x y +≥=2x y =6,3x y ==x y(2)由已知得,而菜园面积为,则,当且仅当即时取等号,菜园的长为8m ,宽为4m 时,可使菜园面积最大,最大值为32.18.解:(1)当时,,函数是偶函数,当时,,.(2)由(1)可画出函数在上的图像,如图所示,则的单调递增区间为和,单调递减区间为和.(3)由函数的定义域为,由(2)中所作函数图象可知,当或时,取得最小值,当或时,取得最大值,故函数的值域.19.(1)解:取,则,,取,则,216x y +=S xy =2112232222x y S xy x y +⎛⎫==⋅⋅≤⋅= ⎪⎝⎭2x y =8,4x y ==∴x y 0x (2)()23f x x x =+- ()y f x =0x >20,()()23x f x f x x x -<∴=-=--22230()230x x x f x x x x ⎧+-∴=⎨-->⎩…()y f x =R ()f x (1,0)-(1,)+∞(,1)-∞-(0,1)()y f x =[4,4]-1x =1x =-(1)(1)4f f =-=-4x =4x =-(4)(4)5f f =-=()f x [4,5]-0x y ==(00)2(0)f f +=(0)0f ∴=y x =-()()()f x x f x f x -=+-对任意恒成立,为奇函数.(2)证明:任取且,则,,又为奇函数,.故为上的减函数;为上的减函数,在区间上的最大值为,,故在上的最大值为6.(3)解:为奇函数,且,整理原式得,即可得,而在上是减函数,所以即恒成立,①当时不成立,②当时,有且,即,解得.故的取值范围为.()()f x f x ∴-=-x R ∈()f x ∴12,(,)x x ∈-∞+∞12x x <()()()2121210,0x x f x f x f x x ->+-=-<()()21f x f x ∴<--()f x ()()12f x f x ∴>()f x R ()f x R ()f x ∴[3,3]-(3)f -(3)3(1)236,(3)(3)6f f f f ==-⨯=-∴-=-=()f x [3,3]-()f x (2)(2)2(1)4f f f -=-=-=()22()()(2)f ax f x f x f +-<+-()2(2)()(2)f axf x f x f +-<+-()22(2)f ax x f x -<-()f x R 222ax x x ->-2320ax x -+>0a =0a ≠0a >0< 0980a a >⎧⎨-<⎩98a >a 9,8⎛⎫+∞ ⎪⎝⎭。
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高一上学期期中考试英语试卷第I卷(三部分共80分)第一部分:听力(共三节,满分20分)第一节(共5小题;每小题1分,满分5分)听下面5段对话,选出最佳选项。
每段对话仅读一遍。
1. What will Green do?A. Ask Bill to play tennis.B. Go skating.C. Go skiing.2. What does the man want the woman to do?A. Telephone him.B. Buy him a ring.C. Come to see him.3. What color does the man prefer?A. White.B. Yellow.C. Light blue.4. What is the woman doing?A. Looking for a new house.B. Studying at a college.C. Finding a job.5. Where does the conversation most probably take place?A. In a restaurant.B. At a bus stop.C. At a store.第二节(共10小题每小题1分,满分10分)听下面4段对话或独白,选出最佳选项。
每段对话或独白读两遍。
请听下面一段材料,回答第6和第7题。
6. How long does the man’s vacation last?A. Sixteen days.B. Ten days.C. Six days.7. Where is the man going?A. Nanjing and Lanzhou.B. Beijing and Hangzhou.C. Nanjing and Hangzhou.请听下面一段材料,回答第8至10题。
8. What is being repaired?A. A TV set.B. A radio.C. A bike.9. When can the man have it repaired?A. The next day.B. That evening.C. That afternoon.10. What does the man advise the woman to do?A. Wait until he finishes the repair work.B. Call before she comes for the set.C. Better come the next day.请听下面一段对话,回答第11和第13题。
11. What class does the woman want to take?A. Singing classes.B. Dance classes.C. Language classes.12. How many classes are there in the afternoon?A. One.B. Two.C. Three.13. Which class will the woman take?A. The morning class.B. The afternoon class.C. The evening class.请听下面一段材料,回答第14至第15题。
14. When does the man usually spend his winter holiday?A. During the first and second week of January.B. During the second or third week of January.C. During the second or third week of February.15. What can we learn from the conversation?A. The man likes skiing.B. The man often goes skiing alone.C. The woman likes cold weather.第三节(共5小题,每小题1分,满分5分。
)Bill likes football very much, and he often goes to 16 in our town on Saturdays. Hedoes not go to the best seats, because they are very 17 . There was a big football match in our town last Saturday. At first it was very cold and 18 , but then the sun shone, and it was very hot.There was a 19 man on a bench behind Bill. At first the fat man was cold, but then he was very hot. He took his coat off and put it in front of him, but it fell on Bill’s head. Bill was not 20 . He took the coat off his head, looked at it and then smiled and s aid, “Thank you —but where are the trousers.16. 17. 18. 19. 20.第二部分:英语知识运用(共两节,满分45分)第一节:单项填空(共15小题;每小题1分,满分15分)21. I can’t spend ____ money on the car which is ____ expensive for me.A. too much, much tooB. far too, too muchC. much too, too muchD. too many, much too22. When ____ to each other, they shook hands.A. introducingB. to introduceC. introducedD. introduce23. His father bought him a watch last month, but now it is ____.A. missingB. missedC. being missedD. being missing24. He plays football ____, if not better than John.A. as well asB. as wellC. as good asD. as good25. I will go with you as soon as I ____ my work.A. will finishB. finishedC. finishD. would finish26. He had never spent a ____ day.A. more worryB. most worryingC. more worryingD. more worried27. ____ of the workers in this factory ____ women.A. one thirds; areB. one thirds; isC. one third; isD. one third; are28. In some cities, missing a bus means ____ for another hour.A. waitingB. to waitC. waitD. to be waiting29. ____ the days went on, the weather got worse.A. WithB. SinceC. WhileD. As30. ____ do you think may have done this?A. WhoB. WhomC. WhatD. That31. His classmates made him ____ captain of the football team.A. /B. aC. theD. their32. It is believed that if a book is ____, it will surely ____ the reader.A. interested; interestB. interesting; be interestedC. interested; be interestingD. interesting; interest33. My English is poor, I am afraid I can’t make myself ____.A. understandB. understoodC. to understandD. understanding34. The news she looked forward to ____.A. come at lastB. coming at lastC. come recentlyD. came at last35. Which is ____ country, America ____ Canada?A. larger, orB. a larger; andC. larger, andD. the larger, or第二节:完形填空(共20小题;每小题l分,满分20分)My father often works very hard. And he 36 goes to the movies. Here I will tell you a 37 story about him.One afternoon, when he finished his work, and 38 go home, he found a film ticket under the glass on his desk. He thought he 39 to have not much work to do that day and 40 was quite wonderful to pass the evening at the cinema.So he came back home and 41 finished his supper. Then he said good-bye to us and left..But to our 42 , he came back about half an hour later. I asked him what was the 43 . He smiled and told us about the funny thing that had happened at the 44 .Whey my father was sitting in his seat, a 45 came to father’s seat and said that the seat was hers. My father was 46 . he took out the ticket 47 looked at it carefully. It was Row17, 48 . And then he looked at the seat. It was 49 . So he asked her to 50 her ticket. She took out the ticket at once and the seat 51 in it was Row 17, Seat 3.Why? What’s the matter with all this? While they were wondering, suddenly the woman said, “The 52 of the tickets are different.” 53 they looked at the tickets more carefully. After a while my father said, “Oh, I am 54 , I made a mistake. My ticket is for the 55 a month ago. Take this seat, please.” With these words, he left.36. A. always B. seldom C. often D. sometimes.37. A. funny B. sad C. bad D. strange38. A. was to B. was about to C. had to D. ought to39. A. happened B. liked C. pretended D. wanted40. A. it B. this C. that D. which41. A. early B. quietly C. quickly D. suddenly42. A. surprise B. joy C. sorrow D. delight43. A. matter B. date C. time D. price44. A. hall B. theatre C. office D. cinema45. A. man B. woman C. boy D. stranger46. A. interested B. surprised C. frightened D. disappointed47. A. and B. but C. or D. so48. A. Seat 1 B. Seat 2 C. Seat 3 D. Seat 449. A. different B. unusual C. the same D. strange50. A. bring B. get C. see D. show51. A. said B. named C. told D. shown52. A. designs B. colors C. prices D. owners53. A. .But B. However C. So D. Yet54. A. sad B. sorry C. wrong D. worried55. A. exhibition B. play C. concert D. film第三部分:阅读理解(共15小题,满分30分)AHow long can a person live without breathing? Probably for only four to six minutes. The airwe breathe in supplies the oxygen that is necessary for keeping every part of the body alive. And the brain, which itself controls breathing, is the first to suffer if oxygen is lacking(缺乏). If no air enters the lungs, the heart will continue to beat for a little longer, supplying the blood to the brain and other parts of the body. But soon, the supply of oxygen already in the blood is used up.First, the patient loses consciousness(知觉), because the brain is no longer getting enough oxygen to work. Then lack of oxygen in the heart causes it to stop beating. Without oxygen, the brain can survive undamaged(不受损的)for about only 4 minutes. The heart may survive for as long as 12 minutes. But within six minutes the person will almost certainly be dead.56. The oxygen that our body needs comes from ____.A. the air we breathe inB. the moving bloodC. the beating heartD. the working brain57. If there is no enough oxygen, ____.C.the heart will stop beating immediatelyB. the brain is the first to sufferC. the blood can continue to move a long timeD. a person will stop breathing58. According to the passage, we can learn that ____.C.the heart is more important than the brain.B. the brain can continue to work in a little longer than the heart without oxygenC. the brain stops working before the heart does without oxygenD. if a person stops breathing it means he is dead59. In which order will the following happen without oxygen?a. The heart stops beatingb. The brain stops workingc. A person is deadd. A person loses consciousness.A. b, a, d, cB. a, b, d, cC. d, a ,b, cD. d, b, c, a60. Oxygen is carried to every part of the body by ____.A. the lungsB. the heartC. the bloodD. the brainBNow I would like to talk to you about your final exam. The exam will be held next Thursday,the last day of the exam week. Remember to bring two or three pens in case they run out of ink. Unlike the midterm exam, this test will not include multiple-choice (多项选择)questions, it will consist entirely of essays(文章). You will have to answer three of the five essay questions. The exam will be comprehensive(综合理解性的), which means you will have to go over all of the subject matters we covered in class this term. I would suggest you review your midterm exam al well as textbooks and your class notes. The research project will count as 20% and the midterm exam 30%. I will be in my office almost all day next Tuesday. If you run into any problems, please drop in. Good luck to you and I will see you on Tuesday.61. When will the final exam be held?A. Next Tuesday.B. Next Wednesday.C. Next ThursdayD. Next Friday62. What will be included in the exam?A. Only multiple-choice questions.B. Both multiple-choice and essay question.C. Both an oral and written part.D. only essay questions.63. Why does the teacher call the exam comprehensive?A. It will be easy to understand.B. It will cover topics from a variety of subjects.C. Students must finish it by themselves.D. Students must complete all parts of it.64. The underlined phrase “run into any problems” in the last paragraph probably means “____”A. go into some placeB. meet someone by chanceC. have difficultiesD. have the ability to resolve problems.65. When was this talk most likely given?A. During the first week of class.B. During the midterm week.C. On the last day of class.D. On the last day of the exam week.COne night, after attending a birthday party, Agatha Christie walked home along a quiet road. Suddenly from the shade of a dark building a tall man with a sharp knife in his right hand ran out at her and then said in a cool voice, “Give me your earrings, or you will die.”Hearing this, Agatha seemed less worried. She tried to cover her necklace with the collar of her overcoat while she used the other hand to take off both of her earrings which she quickly threw on the ground. “Take them and let me go.” She said.The robber looked at her, feeling uncertain. He saw the girl didn’t care for the earrings at all, only trying to protect the necklace. He realized the necklace would cost much more, so he said, “Give me your necklace.” “Oh, sir, it is not worth much. Please let me keep it.”“Stop talking rubbish, quickly!” With shaky hands, Agatha took off her necklace unwillingly. As soon as the robber disappeared, with a half smile on her face, she picked up her earrings and ran as quickly as she could to one of her friends.66. From this story, we can see that the robbery happened on ____.A. a warm nightB. a hot nightC. a cool nightD. a cold night67. Facing with the robber, Agatha was ____.A. calmB. angryC. surprisedD. frightened68. Why did Agatha try to cover her necklace with the collar of her overcoat?A. Because she wanted to protect her necklace.B. Because she liked the necklace much more than the earrings.C. Because she wanted to make the robber think she cared more for the necklace than for the earrings.D. Because she didn’t want to have herself robbed of her necklace.69. The author mainly wants to tell us ____.A. robbery often happened at night.B. how frightened Agatha wasC. an interesting storyD. the value of the necklace and the earrings.70. From the passage, we know that the robber is ____.A. successfulB. very intelligentC. very satisfiedD. stupid第II卷(三部分共40分)第一节:单词拼写(共10个小题,每小题0.5分,总计5分)71. The book c______ a lot of valuable knowledge 71.72. I can’t ____(集中)on my studies with all that noise going on. 72.73. Metal c____ as it cools. 73.74. He lives in one of the low and stone ____(建筑物)of the southwest.74.75. He had been u____ for two months before he got a new job again.75.76. After passing the exam, most students feel really r____. 76.77. Our manager is always busy traveling. He seems to be very e____.77.78. What c______ can you draw from the scientific experiment? 78.79. The ____(关系)between the army and the people is as close as that between fish and water.79.80. I don’t like attending marriage ____(仪式)80.第二节:短文改错(共10小题;每小题1分,满分10分)此题要求改正所给短文中的错误。