重庆八中中考试题
重庆八中考试题及答案
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重庆八中考试题及答案一、选择题(每题3分,共30分)1. 下列哪个选项不是重庆的著名景点?A. 长江索道B. 洪崖洞C. 磁器口古镇D. 故宫博物院答案:D2. 重庆火锅中常见的食材不包括以下哪一项?A. 毛肚B. 鸭肠C. 豆皮D. 鲍鱼答案:D3. 重庆话中“巴适”是什么意思?A. 合适B. 不好C. 舒服D. 糟糕答案:C4. 重庆的市花是什么?A. 牡丹B. 玫瑰C. 杜鹃D. 荷花5. 重庆的简称是什么?A. 渝B. 川C. 蜀D. 黔答案:A6. 重庆的直辖市地位是在哪一年开始的?A. 1996年B. 1997年C. 1998年D. 1999年答案:B7. 重庆的地形特点是什么?A. 平原B. 高原C. 山地D. 盆地答案:C8. 重庆的轨道交通系统中,哪一条线路是环线?A. 1号线B. 2号线C. 3号线D. 环线答案:D9. 重庆的著名小吃“小面”通常不包含以下哪种调料?B. 花椒C. 芝麻酱D. 醋答案:C10. 重庆的著名地标“解放碑”位于哪个区?A. 渝中区B. 江北区C. 南岸区D. 沙坪坝区答案:A二、填空题(每题2分,共20分)1. 重庆的市树是______。
答案:黄葛树2. 重庆的气候类型属于______。
答案:亚热带湿润气候3. 重庆的著名景点“武隆天生三桥”位于______区。
答案:武隆区4. 重庆的长江三峡包括______、______和______。
答案:瞿塘峡、巫峡、西陵峡5. 重庆的著名历史人物______是抗日战争时期的著名将领。
答案:张自忠6. 重庆的著名特产“涪陵榨菜”产自______区。
答案:涪陵区7. 重庆的著名桥梁“东水门大桥”是一座______桥。
答案:斜拉桥8. 重庆的著名文化活动“重庆国际火锅节”通常在每年的______月举行。
答案:11月9. 重庆的著名景点“白公馆”位于______区。
答案:沙坪坝区10. 重庆的著名小吃“陈麻花”产自______区。
2024年重庆八中中考物理一模试卷及答案解析.
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2024年重庆八中中考物理一模试卷一、选择题(本题共8个小题,每小题只有一个选项符合题意,每小题3分,共24分。
)1.(3分)下列估测值符合生活实际的是()A.人感觉舒适的环境温度约为37℃B.普通中学生的质量约为500kgC.中学生正常步行的速度约为1m/s D.空调正常工作时电压约为36V2.(3分)如图所示,关于生活中的光现象,下列说法错误的是()A.图甲中凿壁偷光是利用了光沿直线传播B.图乙中看见水中的鱼位置变浅是因为光的反射C.图丙中放大镜将字母放大是利用了光的折射D.图丁中洪崖洞夜景在水中的倒影是光的反射现象3.(3分)下列诗词中涉及到的物理知识说法正确的是()A.停车坐爱枫林晚,霜叶红于二月花——霜的形成是凝华现象,需要放热B.雪消门外千山绿,花发江边二月晴——雪的形成是凝固现象,需要放热C.斜月沉沉藏海雾,碣石潇湘无限路——雾的形成是液化现象,需要吸热D.瀚海阑干百丈冰,愁云惨淡万里凝——冰的形成是熔化现象,需要吸热4.(3分)如图所示,下列生活中和物理有关的现象解释正确的是()A.图甲中小朋友在下滑的过程中重力势能全部转化为动能B.图乙中拍打被子的过程中灰尘和被子分离是由于灰尘具有惯性C.图丙中所示轻轨站要设立安全线是因为靠近列车的空气流速大,压强大D.图丁中“小米su7生态汽车”对地面的压力和地面对它的支持力是一对平衡力5.(3分)如图所示的电和磁知识描述正确的是()A.图甲中验电器是利用异种电荷相互吸引的原理制成的B.图乙中“司南之杓,投之于地,其柢指南”,“柢”指向地理的南极附近C.图丙中低功率用电器使用两孔插座而大功率用电器使用三孔插座供电D.图丁中通电导体在磁场中受力而运动是发电机的工作原理6.(3分)如图所示为智能镜子,当人靠近镜子,开关S1自动闭合,摄像头工作。
图像识别系统被唤醒后S2自动闭合,智能模块启动,开始分析用户脸上的信息,并在镜面的显示屏上提供合适的护肤建议。
2024届重庆市八中中考数学最后一模试卷含解析
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2024届重庆市八中中考数学最后一模试卷注意事项:1.答卷前,考生务必将自己的姓名、准考证号、考场号和座位号填写在试题卷和答题卡上。
用2B 铅笔将试卷类型(B )填涂在答题卡相应位置上。
将条形码粘贴在答题卡右上角"条形码粘贴处"。
2.作答选择题时,选出每小题答案后,用2B 铅笔把答题卡上对应题目选项的答案信息点涂黑;如需改动,用橡皮擦干净后,再选涂其他答案。
答案不能答在试题卷上。
3.非选择题必须用黑色字迹的钢笔或签字笔作答,答案必须写在答题卡各题目指定区域内相应位置上;如需改动,先划掉原来的答案,然后再写上新答案;不准使用铅笔和涂改液。
不按以上要求作答无效。
4.考生必须保证答题卡的整洁。
考试结束后,请将本试卷和答题卡一并交回。
一、选择题(每小题只有一个正确答案,每小题3分,满分30分) 1.下列因式分解正确的是( ) A .()2211x x +=+B .()22211x x x +-=- C .()()22x 22x 1x 1=-+-D .()2212x x x x -+=-+2.已知反比例函数2y x-=,下列结论不正确的是( ) A .图象经过点(﹣2,1)B .图象在第二、四象限C .当x <0时,y 随着x 的增大而增大D .当x >﹣1时,y >23.12-的相反数是( ) A .2-B .2C .12-D .124.小宇妈妈上午在某水果超市买了 16.5 元钱的葡萄,晚上散步经过该水果超市时,发现同一批葡萄的价格降低了 25% ,小宇妈妈又买了 16.5 元钱的葡萄,结果恰好比早上多了 0.5 千克.若设早上葡萄的价格是 x 元/千克,则可列方程( ) A .()16.516.50.5x 125%x +=+B .()16.516.50.5x 1-25%x +=C .()16.516.5-0.5x 125%x =+ D .()16.516.5-0.5x 1-25%x =5.如图,一次函数y 1=x 与二次函数y 2=ax 2+bx +c 图象相交于P 、Q 两点,则函数y =ax 2+(b -1)x +c 的图象可能是( )A. B.C.D.6.超市店庆促销,某种书包原价每个x元,第一次降价打“八折”,第二次降价每个又减10元,经两次降价后售价为90元,则得到方程()A.0.8x﹣10=90 B.0.08x﹣10=90 C.90﹣0.8x=10 D.x﹣0.8x﹣10=907.如图,⊙O 是等边△ABC 的外接圆,其半径为3,图中阴影部分的面积是()A.πB.32C.2πD.3π8.如图,有一块含有30°角的直角三角板的两个顶点放在直尺的对边上.如果∠2=44°,那么∠1的度数是( )A.14°B.15°C.16°D.17°9.如图,已知在Rt△ABC中,∠ABC=90°,点D是BC边的中点,分别以B、C为圆心,大于线段BC长度一半的长为半径圆弧,两弧在直线BC上方的交点为P,直线PD交AC于点E,连接BE,则下列结论:①ED⊥BC;②∠A=∠EBA;③EB平分∠AED;④ED=12AB中,一定正确的是()A.①②③B.①②④C.①③④D.②③④10.如图,一束平行太阳光线FA、GB照射到正五边形ABCDE上,∠ABG=46°,则∠FAE的度数是()A .26°.B .44°.C .46°.D .72°二、填空题(共7小题,每小题3分,满分21分)11.科学家发现,距离地球2540000光年之遥的仙女星系正在向银河系靠近.其中2540000用科学记数法表示为_____.12.因式分解:223x 6xy 3y -+- =13.如图,在菱形ABCD 中,AB=3,∠B=120°,点E 是AD 边上的一个动点(不与A ,D 重合),EF ∥AB 交BC 于点F ,点G 在CD 上,DG=DE .若△EFG 是等腰三角形,则DE 的长为_____.14.已知a + =3,则的值是_____.15.写出一个比2大且比5小的有理数:______.16.如图,线段AB=10,点P 在线段AB 上,在AB 的同侧分别以AP 、BP 为边长作正方形APCD 和BPEF ,点M 、N 分别是EF 、CD 的中点,则MN 的最小值是_______.17.下表记录了甲、乙、丙、丁四名跳远运动员选拔赛成绩的平均数与方差s 2:甲 乙 丙 丁 平均数(cm ) 561 560 561 560 方差s 2(cm 2)3.53.515.516.5根据表中数据,要从中选择一名成绩好又发挥稳定的运动员参加比赛,应该选择_____. 三、解答题(共7小题,满分69分)18.(10分)解分式方程:12x=3x19.(5分)如图1,四边形ABCD,边AD、BC的垂直平分线相交于点O.连接OA、OB、OC、OD.OE是边CD的中线,且∠AOB+∠COD=180°(1)如图2,当△ABO是等边三角形时,求证:OE=12 AB;(2)如图3,当△ABO是直角三角形时,且∠AOB=90°,求证:OE=12 AB;(3)如图4,当△ABO是任意三角形时,设∠OAD=α,∠OBC=β,①试探究α、β之间存在的数量关系?②结论“OE=12AB”还成立吗?若成立,请你证明;若不成立,请说明理由.20.(8分)一艘货轮往返于上下游两个码头之间,逆流而上需要6小时,顺流而下需要4小时,若船在静水中的速度为20千米/时,则水流的速度是多少千米/时?21.(10分)为了了解市民“获取新闻的最主要途径”,某市记者开展了一次抽样调查,根据调査结果绘制了如下尚不完整的统计图:根据以上信息解答下列问题:这次接受调查的市民总人数是_______人;扇形统计图中,“电视”所对应的圆心角的度数是_________;请补全条形统计图;若该市约有80万人,请你估计其中将“电脑和手机上网”作为“获取新闻的最主要途径”的总人数.22.(10分)为响应国家的“一带一路”经济发展战略,树立品牌意识,我市质检部门对A、B、C、D四个厂家生产的同种型号的零件共2000件进行合格率检测,通过检测得出C厂家的合格率为95%,并根据检测数据绘制了如图1、图2两幅不完整的统计图.抽查D厂家的零件为件,扇形统计图中D厂家对应的圆心角为;抽查C厂家的合格零件为件,并将图1补充完整;通过计算说明合格率排在前两名的是哪两个厂家;若要从A、B、C、D四个厂家中,随机抽取两个厂家参加德国工业产品博览会,请用“列表法”或“画树形图”的方法求出(3)中两个厂家同时被选中的概率.23.(12分)列方程或方程组解应用题:为响应市政府“绿色出行”的号召,小张上班由自驾车改为骑公共自行车.已知小张家距上班地点10千米.他用骑公共自行车的方式平均每小时行驶的路程比他用自驾车的方式平均每小时行驶的路程少45千米,他从家出发到上班地点,骑公共自行车方式所用的时间是自驾车方式所用的时间的4倍.小张用骑公共自行车方式上班平均每小时行驶多少千米?24.(14分)抛物线y=ax2+bx+3(a≠0)经过点A(﹣1,0),B(32,0),且与y轴相交于点C.(1)求这条抛物线的表达式;(2)求∠ACB的度数;(3)设点D是所求抛物线第一象限上一点,且在对称轴的右侧,点E在线段AC上,且DE⊥AC,当△DCE与△AOC 相似时,求点D的坐标.参考答案一、选择题(每小题只有一个正确答案,每小题3分,满分30分) 1、C 【解题分析】依据因式分解的定义以及提公因式法和公式法,即可得到正确结论. 【题目详解】解:D 选项中,多项式x 2-x+2在实数范围内不能因式分解; 选项B ,A 中的等式不成立;选项C 中,2x 2-2=2(x 2-1)=2(x+1)(x-1),正确. 故选C . 【题目点拨】本题考查因式分解,解决问题的关键是掌握提公因式法和公式法的方法. 2、D 【解题分析】A 选项:把(-2,1)代入解析式得:左边=右边,故本选项正确;B 选项:因为-2<0,图象在第二、四象限,故本选项正确;C 选项:当x <0,且k <0,y 随x 的增大而增大,故本选项正确;D 选项:当x >0时,y <0,故本选项错误. 故选D . 3、D 【解题分析】 因为-12+12=0,所以-12的相反数是12. 故选D. 4、B 【解题分析】分析:根据数量=钱数单价,可知第一次买了16.5x 千克,第二次买了()16.501250x -,根据第二次恰好比第一次多买了 0.5千克列方程即可.详解:设早上葡萄的价格是 x 元/千克,由题意得,()16.516.50.501250x x +=-.故选B.点睛:本题考查了分式方程的实际应用,解题的关键是读懂题意,找出列方程所用到的等量关系. 5、A 【解题分析】由一次函数y 1=x 与二次函数y 2=ax 2+bx+c 图象相交于P 、Q 两点,得出方程ax 2+(b-1)x+c=0有两个不相等的根,进而得出函数y=ax 2+(b-1)x+c 与x 轴有两个交点,根据方程根与系数的关系得出函数y=ax 2+(b-1)x+c 的对称轴x=-12b a->0,即可进行判断. 【题目详解】点P 在抛物线上,设点P (x ,ax 2+bx+c ),又因点P 在直线y=x 上, ∴x=ax 2+bx+c , ∴ax 2+(b-1)x+c=0;由图象可知一次函数y=x 与二次函数y=ax 2+bx+c 交于第一象限的P 、Q 两点, ∴方程ax 2+(b-1)x+c=0有两个正实数根. ∴函数y=ax 2+(b-1)x+c 与x 轴有两个交点,又∵-2ba >0,a >0 ∴-12b a -=-2b a +12a>0∴函数y=ax 2+(b-1)x+c 的对称轴x=-12b a->0, ∴A 符合条件, 故选A . 6、A 【解题分析】试题分析:设某种书包原价每个x 元,根据题意列出方程解答即可. 设某种书包原价每个x 元, 可得:0.8x ﹣10=90考点:由实际问题抽象出一元一次方程. 7、D 【解题分析】根据等边三角形的性质得到∠A=60°,再利用圆周角定理得到∠BOC=120°,然后根据扇形的面积公式计算图中阴影部分的面积即可. 【题目详解】∵△ABC 为等边三角形, ∴∠A=60°,∴∠BOC=2∠A=120°,∴图中阴影部分的面积=2 1203360π⨯=3π.故选D.【题目点拨】本题考查了三角形的外接圆与外心、圆周角定理及扇形的面积公式,求得∠BOC=120°是解决问题的关键.8、C【解题分析】依据∠ABC=60°,∠2=44°,即可得到∠EBC=16°,再根据BE∥CD,即可得出∠1=∠EBC=16°.【题目详解】如图,∵∠ABC=60°,∠2=44°,∴∠EBC=16°,∵BE∥CD,∴∠1=∠EBC=16°,故选:C.【题目点拨】本题主要考查了平行线的性质,解题时注意:两直线平行,内错角相等.9、B【解题分析】解:根据作图过程,利用线段垂直平分线的性质对各选项进行判断:根据作图过程可知:PB=CP,∵D为BC的中点,∴PD垂直平分BC,∴①ED⊥BC正确.∵∠ABC=90°,∴PD∥AB.∴E为AC的中点,∴EC=EA,∵EB=EC.∴②∠A=∠EBA正确;③EB平分∠AED错误;④ED=12AB正确.∴正确的有①②④.故选B.考点:线段垂直平分线的性质.10、A【解题分析】先根据正五边形的性质求出∠EAB的度数,再由平行线的性质即可得出结论.【题目详解】解:∵图中是正五边形.∴∠EAB=108°.∵太阳光线互相平行,∠ABG=46°,∴∠FAE=180°﹣∠ABG﹣∠EAB=180°﹣46°﹣108°=26°.故选A.【题目点拨】此题考查平行线的性质,多边形内角与外角,解题关键在于求出∠EAB.二、填空题(共7小题,每小题3分,满分21分)11、2.54×1【解题分析】【分析】科学记数法的表示形式为a×10n的形式,其中1≤|a|<10,n为整数.确定n的值时,要看把原数变成a时,小数点移动了多少位,n的绝对值与小数点移动的位数相同.当原数绝对值>1时,n是正数;当原数的绝对值<1时,n 是负数.【题目详解】2540000的小数点向左移动6位得到2.54,所以,2540000用科学记数法可表示为:2.54×1,故答案为2.54×1.【题目点拨】本题考查科学记数法的表示方法.科学记数法的表示形式为a×10n的形式,其中1≤|a|<10,n为整数,表示时关键要正确确定a的值以及n的值.12、﹣3(x﹣y)1【解题分析】解:﹣3x1+6xy﹣3y1=﹣3(x1+y1﹣1xy)=﹣3(x﹣y)1.故答案为:﹣3(x﹣y)1.点睛:本题考查了提公因式法,公式法分解因式,提取公因式后利用完全平方公式进行二次分解,注意分解要彻底.13、1或3 3【解题分析】由四边形ABCD 是菱形,得到BC ∥AD ,由于EF ∥AB ,得到四边形ABFE 是平行四边形,根据平行四边形的性质得到EF ∥AB ,于是得到EF=AB=3,当△EFG 为等腰三角形时,①EF=GE=3时,于是得到DE=DG=12AD÷32=1,②GE=GF 时,根据勾股定理得到DE=33. 【题目详解】解:∵四边形ABCD 是菱形,∠B=120°,∴∠D=∠B=120°,∠A=180°-120°=60°,BC ∥AD , ∵EF ∥AB ,∴四边形ABFE 是平行四边形, ∴EF ∥AB ,∴EF=AB=3,∠DEF=∠A=60°,∠EFC=∠B=120°, ∵DE=DG ,∴∠DEG=∠DGE=30°, ∴∠FEG=30°,当△EFG 为等腰三角形时, 当EF=EG 时,EG=3, 如图1,过点D 作DH ⊥EG 于H , ∴EH=123在Rt △DEH 中,DE=0cos30HE=1,GE=GF 时,如图2,过点G作GQ⊥EF,∴EQ=12EF=32,在Rt△EQG中,∠QEG=30°,∴EG=1,过点D作DP⊥EG于P,∴PE=12EG=12,同①的方法得,DE=33,当EF=FG时,由∠EFG=180°-2×30°=120°=∠CFE,此时,点C和点G重合,点F和点B重合,不符合题意,故答案为1或33.【题目点拨】本题考查了菱形的性质,平行四边形的性质,等腰三角形的性质以及勾股定理,熟练掌握各性质是解题的关键.14、7【解题分析】根据完全平方公式可得:原式=.15、2【解题分析】25.【题目详解】252(答案不唯一),故答案为:2(答案不唯一).【题目点拨】此题考查无理数的估算,解题的关键在于利用题中所给有理数的大小求符合题意的答案.16、2【解题分析】设MN=y ,PC=x ,根据正方形的性质和勾股定理列出y 1关于x 的二次函数关系式,求二次函数的最值即可.【题目详解】作MG ⊥DC 于G ,如图所示:设MN=y ,PC=x ,根据题意得:GN=2,MG=|10-1x|,在Rt △MNG 中,由勾股定理得:MN 1=MG 1+GN 1,即y 1=21+(10-1x )1.∵0<x <10,∴当10-1x=0,即x=2时,y 1最小值=12,∴y 最小值=2.即MN 的最小值为2;故答案为:2.【题目点拨】本题考查了正方形的性质、勾股定理、二次函数的最值.熟练掌握勾股定理和二次函数的最值是解决问题的关键.17、甲【解题分析】首先比较平均数,平均数相同时选择方差较小的运动员参加.【题目详解】 ∵==x x x x 甲乙丁丙> ,∴从甲和丙中选择一人参加比赛,∵22S S 甲丙< ,∴选择甲参赛,故答案为甲.【题目点拨】此题考查了平均数和方差,关键是根据方差反映了一组数据的波动大小,方差越大,波动性越大,反之也成立.三、解答题(共7小题,满分69分)18、x=1【解题分析】分式方程去分母转化为整式方程,求出整式方程的解得到x的值,经检验即可得到分式方程的解.【题目详解】方程两边都乘以x(x﹣2),得:x=1(x﹣2),解得:x=1,检验:x=1时,x(x﹣2)=1×1=1≠0,则分式方程的解为x=1.【题目点拨】本题考查了解分式方程,利用了转化的思想,解分式方程注意要检验.19、(1)详见解析;(2)详见解析;(3)①α+β=90°;②成立,理由详见解析.【解题分析】(1)作OH⊥AB于H,根据线段垂直平分线的性质得到OD=OA,OB=OC,证明△OCE≌△OBH,根据全等三角形的性质证明;(2)证明△OCD≌△OBA,得到AB=CD,根据直角三角形的性质得到OE=12CD,证明即可;(3)①根据等腰三角形的性质、三角形内角和定理计算;②延长OE至F,是EF=OE,连接FD、FC,根据平行四边形的判定和性质、全等三角形的判定和性质证明.【题目详解】(1)作OH⊥AB于H,∵AD、BC的垂直平分线相交于点O,∴OD=OA,OB=OC,∵△ABO是等边三角形,∴OD=OC,∠AOB=60°,∵∠AOB+∠COD=180°∴∠COD=120°,∵OE 是边CD 的中线,∴OE ⊥CD ,∴∠OCE =30°,∵OA =OB ,OH ⊥AB ,∴∠BOH =30°,BH =12AB , 在△OCE 和△BOH 中,OCE BOH OEC BHO OB OC ∠=∠⎧⎪∠=∠⎨⎪=⎩,∴△OCE ≌△OBH ,∴OE =BH ,∴OE =12AB ; (2)∵∠AOB =90°,∠AOB +∠COD =180°,∴∠COD =90°,在△OCD 和△OBA 中,OD OA COD BOA OC OB =⎧⎪∠=∠⎨⎪=⎩,∴△OCD ≌△OBA ,∴AB =CD ,∵∠COD =90°,OE 是边CD 的中线,∴OE =12CD , ∴OE =12AB ; (3)①∵∠OAD =α,OA =OD ,∴∠AOD =180°﹣2α,同理,∠BOC =180°﹣2β,∵∠AOB +∠COD =180°,∴∠AOD +∠COB =180°,∴180°﹣2α+180°﹣2β=180°,整理得,α+β=90°;②延长OE 至F ,使EF =OE ,连接FD 、FC ,则四边形FDOC 是平行四边形,∴∠OCF +∠COD =180°,FC OA =,∴∠AOB =∠FCO ,在△FCO 和△AOB 中,FC OA FCO AOB OC OB =⎧⎪∠=∠⎨⎪=⎩,∴△FCO ≌△AOB ,∴FO =AB ,∴OE =12FO =12AB . 【题目点拨】本题是四边形的综合题,考查了线段垂直平分线的性质、全等三角形的判定和性质以及直角三角形斜边上的中线性质、平行四边形的判定与性质等知识;熟练掌握平行四边形的判定与性质,证明三角形全等是解题的关键.20、1千米/时【解题分析】设水流的速度是x 千米/时,则顺流的速度为(20+x )千米/时,逆流的速度为(20﹣x )千米/时,根据由货轮往返两个码头之间,可知顺水航行的距离与逆水航行的距离相等列出方程,解方程即可求解.【题目详解】设水流的速度是x 千米/时,则顺流的速度为(20+x )千米/时,逆流的速度为(20﹣x )千米/时,根据题意得:6(20﹣x )=1(20+x ),解得:x=1.答:水流的速度是1千米/时.【题目点拨】本题考查了一元一次方程的应用,读懂题意,找出等量关系,设出未知数后列出方程是解决此类题目的基本思路.21、 (1)1000;(2)54°;(3)见解析;(4)32万人【解题分析】根据“每项人数=总人数×该项所占百分比”,“所占角度=360度×该项所占百分比”来列出式子,即可解出答案. 【题目详解】解:(1)400÷40%=1000(人)(2)360°×1501000=54°,故答案为:1000人; 54°;(3)1-10%-9%-26%-40%=15% 15%×1000=150(人)(4)80×6601000=52.8(万人)答:总人数为52.8万人.【题目点拨】本题考查获取图表信息的能力,能够根据图表找到必要条件是解题关键.22、(1)500,90°;(2)380;(3)合格率排在前两名的是C、D两个厂家;(4)P(选中C、D)=16.【解题分析】试题分析:(1)计算出D厂的零件比例,则D厂的零件数=总数×所占比例,D厂家对应的圆心角为360°×所占比例;(2)C厂的零件数=总数×所占比例;(3)计算出各厂的合格率后,进一步比较得出答案即可;(4)利用树状图法列举出所有可能的结果,然后利用概率公式即可求解.试题解析:(1)D厂的零件比例=1-20%-20%-35%=25%,D厂的零件数=2000×25%=500件;D厂家对应的圆心角为360°×25%=90°;(2)C厂的零件数=2000×20%=400件,C厂的合格零件数=400×95%=380件,如图:(3)A厂家合格率=630÷(2000×35%)=90%,B厂家合格率=370÷(2000×20%)=92.5%,C厂家合格率=95%,D厂家合格率470÷500=94%,合格率排在前两名的是C、D两个厂家;(4)根据题意画树形图如下:共有12种情况,选中C、D的有2种,则P(选中C、D)=212=16.考点:1.条形统计图;2.扇形统计图;3. 树状图法.23、15千米.【解题分析】首先设小张用骑公共自行车方式上班平均每小时行驶x千米,根据题意可得等量关系:骑公共自行车方式所用的时间=自驾车方式所用的时间×4,根据等量关系,列出方程,再解即可.【题目详解】:解:设小张用骑公共自行车方式上班平均每小时行驶x千米,根据题意列方程得:10 x =4×1045x解得:x=15,经检验x=15是原方程的解且符合实际意义.答:小张用骑公共自行车方式上班平均每小时行驶15千米.24、(1)y=﹣2x2+x+3;(2)∠ACB=41°;(3)D(78,7532).【解题分析】试题分析:()1把点,A B 的坐标代入即可求得抛物线的解析式.()2作BH ⊥AC 于点H ,求出BH 的长度,即可求出∠ACB 的度数.()3延长CD 交x 轴于点G ,△DCE ∽△AOC ,只可能∠CAO =∠DCE .求出直线CD 的方程,和抛物线的方程联立即可求得点D 的坐标.试题解析:(1)由题意,得309330,42a b a b -+=⎧⎪⎨++=⎪⎩ 解得21a b =-⎧⎨=⎩. ∴这条抛物线的表达式为223y x x =-++.(2)作BH ⊥AC 于点H ,∵A 点坐标是(-1,0),C 点坐标是(0,3),B 点坐标是(32,0), ∴,AB=52,OC=3,∵BH AC OC AB ⋅=⋅,即∠BAD=532BH =⨯,∴BH =. Rt △ BCH中,BH =BHC =90º,∴sin 2ACB ∠=. 又∵∠ACB 是锐角,∴45ACB ∠=︒.(3)延长CD 交x 轴于点G ,∵Rt △ AOC 中,AO=1,,∴cos AO CAO AC ∠==. ∵△DCE ∽△AOC ,∴只可能∠CAO =∠DCE .∴AG = CG .∴122cos AC GAC AG AG ∠===. ∴AG=1.∴G 点坐标是(4,0). ∵点C 坐标是(0,3),∴3:34CD l y x =-+. ∴233423y x y x x ⎧=-+⎪⎨⎪=-++⎩ 解得787532x y ⎧=⎪⎪⎨⎪=⎪⎩,03x y =⎧⎨=⎩(舍). ∴点D 坐标是775,.832⎛⎫⎪⎝⎭。
2024届重庆八中学、九十五中学等校中考语文五模试卷含解析
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2024届重庆八中学、九十五中学等校中考语文五模试卷注意事项:1.答卷前,考生务必将自己的姓名、准考证号、考场号和座位号填写在试题卷和答题卡上。
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一、积累与运用1.将下列句子组成一段话,排序恰当的一项是()①曾经万里飞沙的毛乌素沙漠,千余年后近80%穿上绿装。
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⑤这些“染绿”“复绿”的故事,折射出中国生态文明建设的力度与成就。
A.③①④⑤②B.②①④⑤③C.④⑤①②③D.⑤④③②①2.下列句子,排序最最恰当的一组是()①清明礼俗文化充分体现了中华民族礼敬祖先、慎终追远的人文精神。
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④每逢清明时节,人们无论身处何方,都会回乡参加祭祖活动,缅怀祖先。
⑤全国各地因地域不同而又存在着习俗内容上或细节上的差异。
⑥在祖先祭祀仪式中慎终追远,文化传承是清明礼俗的重要功能。
A.①⑥⑤②④③B.①⑤②④⑥③C.③⑤②④①⑥D.④⑤②③①⑥3.下列句子排列顺序最恰当的一项是( )①一方面,以娱乐为职能的大众文化得到蓬勃发展的机会。
②与此同时,文化领域却有全然不同的景观。
重庆八中中考试题
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中考测试(八中)II.单项选择(20分)21.English is ________useful language and it is widely used in the word.A. aB. anC. theD. /22 . — Do you know the funny man Yue Yunpeng?— Yes. He was born _______April 15th,1985 and he first put on a performance at 25.A. inB. onC. duringD.at23 . — You don’t look well. What’s wrong?— I think I have a fever. I want to go to the_____________.A.schoolB. bookstoreC. hospitalD. Cinema24.Be careful with the knife. You may cut ____________.A.youB. yourC. yoursD. yourself25.Tom is a good boy. He helps his mom ____________housework every day.A. doB. doingC. doesD. did26 — I haven’t seen you for a long time.— Oh, I___________ to Chongqing three days ago.A. have returnedB. returnC. will returnD. returned27 — Have you ________ the TV show The Descendants of the Sun?— Yes, I watch it with my daughter every evening.A. heard fromB. heard ofC. put onD. put off28 — Bob, would you mind taking out the rubbish?— ____________, I’ll do it right away.A. Not at allB. All rightC. Sorry, I can’tD. Yes, please29. Sam worked out the problem in only three minutes. It’s not as ______ as he thought.A. easyB. easierC. hardD. harder30 _____________ she didn’t say anything to me, I was sure she had seen me.A. BecauseB. ThoughC. UnlessD. Until31 — Chongqing has developed a lot in the last few years.— Yes. And a new amusement park ___________ here in 2017.A. is builtB. buildsC. will buildD. will be built32 — Can I speak to Mr. Brown?— ___________. He’s in the kitchen and I’ll call him right away.A. Hold on, pleaseB. I’m afraid notC. I hope soD. I’m sorry33 ______________lovely girl she is! We all love her.A. What aB. WhatC. How aD. How34 Driving was so difficult for me that I ________ knew where to put my feet the first time I gotinto the car.A. usuallyB. alwaysC. everD. hardly35 — Do you have any idea __________ ?— Yes, on the second floor.A. where is the movieB. where the movie theater isC. when is movie B. when the movie is36 ____________ her dream come true, Alice studies harder than any of her classmates.A. MakingB. To makeC. MakeD. Made37 — Must I look up each new word while reading?— No, you __________. You should try to guess its meaning.A. can’tB. mustn’tC. needn’tD. may not38 — Do you and your sister like comedies, Linda?— Yes. _________ of us think they are interesting.A. BothB. AllC. NeitherD. Either39 — ____________ do you have exams at your school?— Once a month.A. How oftenB. How longC. How soonD. How many40 — It’s raining hard outside. Could I use your umbrella, Linda?— Sorry. I ______ it at home this morning.A. forgetB. leftC. leaveD. forgotⅢ. 完形填空(每小题1.5分,共15分)In modern society we can see competitions(竞争) everywhere, both in our work and in our life. Team spirit(团队精神) is so important and helpful. It can lead us to 41 in the competitions.Team spirit means that people work together and help 42 as part of a team. With this spirit, people try hard to make their team the 43 of all.Everyone has experienced(经历) team spirit one way or another, whether they were part of a team or saw a group of people 44 for their favorite player.There are different kinds of team spirit. One kind is between a team of people whose efforts and teamwork are needed in reaching 45 goal. Another kind is when a group of people support a person, a team or even their country.Team spirit brings good effects. It helps to builds up 46 and trust(信任) between people who may not get on well when they don’t have such team spirit 47 , team spirit may also cause bad effects. For example, too great team spirit may cause fights or arguments with other team members.Some people don’t understand team spirit 48 . They think team spirit means having to become a member of a team or a fan club. In fact, team spirit can be built anywhere—between friends, workmates or even between, two people who have never 49 before. You don’t have to wear the same team spirit clothes. Anyone can show team spirit just 50 showing support for the same goal.( )41. A.dream B.surprise C.success D.end( )42. A.each other B.other C.another D.the other ( )43. A.fastest B.earliest C.biggest D.best( )44. A.call B.cheer C. to cheer D.to call ( )45. A.their B.his C.my D.our( )46. A.luck B.friendship C.health D.help( )47. A.But B.Although C.However D.So( )48. A.easily B.quickly C.simply D.properly ( )49. A.written B.heard C.met D.seen( )50. A.by B.through C.in D.withIV 阅读理解(每小题2分,共30分)AAre you a fan of traveling? Well, soon there will be a new place for you to take your vacation—the moon. Last month, the European Space Agency (ESA) said they would build an international moon base—the Moon Village. The purpose of building the village is to open the door for deeper space research. And it will also be a tourist center. According to the head of the ESA, Johann-Dietrich Woemer, it will only take about 20 years to finish it.However ,there are still some challenges, and the biggest one is how to get the building material into space without costing too much. Scientists suggest using the ice water and other things on the moon to print 3-D building materials, so people don’t have to carry everything from the earth.The ESA chose to build the base on the moon instead of the Mars because the moon is about 144 times closer than the Mars.The ESA has invited the US,Russia,China,India,Japan and some other countries to join in the moon plan.It hopes that in the future the moon will become a place where all the countries of the world can work together.51.The ESA will build an international base on__________.A.the moonB.the earthC.the MarsD.the sun52.The ESA plan to build the village__________.A.to open the door for deeper space researchB.to make all the countries work togetherC.to make money by building it as a tourist centerD.to get a new place to live in53.The biggest problem in building the base is ________.A.how to use 3-D printersB.where to build itC.how to get enough moneyD.how to get the building materials into space withoutcosting too muchBStudents from different schools are talking about strange rules in their schools.Zhao Jiacheng,13,from Xi’an: Students are not allowed to bring any balls to school. Our teachers think they will distract(使...分心) us from our studies. As a result, half of the students don’t have balls to play with during the PE class. Many people are disappointed about it. Another strange rule is that girls must have short hair.They think it will make them look unified (统一的).What a strange rule !Cui Anqi,15,from Guangdong: At my school,there is a strange rule for Class 5,Junior 2.Boys and girls must stay at least one meter away from one another.The teacher in their class says that this rule will help build pure friendships between boys and girls.Students don’t like it at all.I don’t think it’s reasonable. I’m sure that there are pure friendships between boys and girls.The rule is unnecessary.Wang Ying, 13, from Shanghai: At my school,we aren’t allowed to bring snacks and drinks into teaching buildings.I once bought a fried drumstick( 鸡腿) and a drink during break time.But I didn’t eat them by the time the break was over.So I put them alongside a garden. However,when I went to find them after class,there many ants on them.I don’t like the rule.Zhang Xueling,15,from Jiangsu: This term,we got vending machines(自动贩卖机) around our teaching buildings and dormitories. We were all excited and couldn’t wait to buy snacks from them.However,our school doesn’t let us use them.And they don’t give us a reason.We don’tunderstand why.Xiao Li,16,from Beijing: Many girls like to use colorful hair ties.But our school doesn’t allow it. Girls can only use black hair ties.At the beginning,our teachers checked it every day. My classmates and I followed it.But as time went by,no one followed it anymore.54. How many students talk about strange rules in their schools?A. 5B. 4C. 3D. 255. Why aren’t students allowed to take any balls to school?A. Because it will make them look unified.B. Because the teachers think balls are bad for the students.C. Because the teachers think balls will distract the students from their studies.D. Because balls are too expensive.56. The underlined word pure in Paragraph 3 may mean ___________.A. 可爱的B. 有价值的C. 短暂的D.纯洁的57. Students aren’t allowed to _________ at Wang Ying’s school.A.have short hairB.bring snacks and drinks into teaching buildingse colorful hair tiesD.buy snacks from the vending machineCWhat can help parents understand their kids better? More than 8,000 US kids answered this question in an online survey by Time for Kids and Kids Health Org.Many US kids—two out of three—said they get along with their parents.But that doesn’t mean they never disagree. In fact, most kids reported arguing with their parents, at least sometimes.And two out five kids said arguments sometimes even includes shouting at each other.It’s certainly normal to disagree and argue,” says Lyness,an American child psychologist(心里学家). “But it’s also important to learn how to do so respectfully. Be patient. Don’t use a raised, angry voice.”And not surprisingly, three out of four kids said they had lied to their parents some times.Many said they lie so they would not get in trouble or make their parents disappointed. According to Lyness, lying isn’t just wrong. It can actually have had results. Telling the truth builds trust. Telling the truth,says Lyness,shows maturity(成熟).But older kids actually lie more often than younger ones. Kids aged 12 to 14 not only said they lie more,but they also reported having less fun,feeling less close and not getting along as well with their parents.According to Lyness, those feelings are quite common. As kids become more independent,they have more areas of disagreement with their parents.But it doesn’t have to be that way. “Kids and parents get along differently at each stage of the journey,” she says. “As kids grow and change,it is important for everybody to change.”58.________of the US kids get along with their parents.A.One out of twoB.Two out of threeC.Two out of fiveD.Three out of five59.Which of the following sentences is true according to the passage?A.Two out of the three the US kids never disagree with their parents.B.Older kids lie to their parents less often than younger ones.C.Lying is wrong and it can cause bad results.D.Kids aged 12 to 14 have less fun but they feel closer to their parents60.As kids grow and change,________should change.A.only parentsB.only kidsC.both kids and parentsD.neither kids nor parents61.The child psychologist Lyness may agree that__________.A.it’s not normal to disagree and agrue between parents and kidsB.parents don’t need to be patient with their kidsC.kids can agrue with their parents in a raised angry voiceD.kids need to agrue with parents with respectDSome people can find the different color lump(色块)among 45,000 lumps.Others can remember 120 strangers and their fingerprints. There are also some people who can work out a seven-digit number(七位数)multiply(乘以) a 10-digit number in just a fehneseiw seconds.In a Chinese science TV show called Super Brain,you can be amazed by these people’s great brainpower. Brainpower actually means intelligence( 智力)which includes different abilities, such language, logic, memory and even imagination.Wang Yuheng is a painter from Beijing. He was born in 1981 and he has super observing( 观察)ability. In February, 2015 he took part in one of the competitions.There were 520 glasses of water on the stage. A judge chose one glass of water and give it to Wang to look at.Then the glass was put back where it was. He had to find this glass of water among 520 glasses of water. Unbelievably, he found it in just few minutes.You may ask how the competitors’ brains can be so strong and powerful. Are they born to be talents? Do you also want to have super brainpower? Here’s what we can do to improve our brainpower.ExerciseStudies have shown that exercise can improve the brain’s functions(功能), such as planning, organizing and multitasking. Exercise can also help you be in a good mood.Training your memoryHow often do you hear people say, “I wish I had a better memory ?” But no one does anything about this! If you train yourself to memorize phone numbers and other important numbers, you will see a change.Doing something newWhen you experience something new you actually stimulate( 刺激) your brain! This creates new neural pathways(神经通路) and increase your intelligence. You could take a new way to your school, try a new snack or even a new form of exercise!62. According to the passage, brainpower includes all the following abilities except__________.A.memorynguageB.imaginationmunication63. We can learn from the passages that _________.A.WangYuheng was 32 years old when he joined in the competitionB.Everyone believed that Wang Yuheng could easily find the classC.It was hard to find the glass because the judge put it in a new placeD. Wang Yuheng succeeded in finding the glass because of his super observing ability64.A.BC.study hard and remember more facts and informationD.watch the Chinese science TV show called Super Brain65.Which is the best title of this passage?A..Intelligence is important.B.Born talent.C.How to have super brainpower?D.How to be more talented?A: Tom,let’s go somewhere interesting to relax.B: 66 .A:Shall we go to the cinema? Some new films are on this week.B: 67 . Which film would you like to see?A: Let me search on the Internet. Er… How about Zootopia?B: Yeah, I have heard of it. It’s so interesting! 68_____A: UME Cinema is a little far. Let’s go to BONA Cinema.B: OK. Look! So many clouds in the sky! 69A: Yes. The weather report says it will be rainy tonight.B: 70A: I will. The film will begin in two hours. We can go there after dinner.B: Alright. Let’s meet at the gate of the cinema.A: OK. See you again.66.________ 67.________ 68.________ 69.________ 70.________VI 任务型阅读(每题2分,共8分)What do Australian teenagers do in their free time ? Many of them like to spend it with their friends.They play together outside or do some shopping. But a girl named Shanaya White spends her free time in a different way---she works hard to cheer upthose children with serious illness.Shanaya comes from Queenland. In September 2014, she spent four days in hospital because of an illness. She found it was really hard to stay in hospital. She felt upset when she thought many children had to stay in hospital for weeks and months because of illnesses. After learning more about childhood illness,she decided to help those children.She made a Facebook Page. On it, she posted stories of other children’s fights against illnesses, hoping more people would care about those children. “I name it Happy Little Smiles because I want to bring happiness and smiles to the kids in need,”saidShanaya. She also made “Happy Packs” and sent the packs to those children with illnesses. Inside the packs, there were toys , books and a mix of activities.It was a success and she made many sick children smile. And thanks to her,more and more people began to care about and help the children.71. What does Shanaya do in her free time?72. How did Shanaya feel when she thought many children had to stay in hospital because of illnesses?73. Did more children begin to care about the sick children?74. What do you think about the girl Shanaya?VII. 句型转换(每空1分,共10分)75. Lily often makes dinner for her family after school.(否定句)Lily _________often _________dinner for her family after school.76. I was washing the clothes at this time yesterday.________ ________ you doing at this time yesterday?77. Luckily, they got to the airport on time. 同义句Luckily, they _______ _______ the airport on time.78.他付款买下这些西红柿,然后匆匆回家了。
2024年重庆八中中考数学一模试卷及答案解析
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2024年重庆八中中考数学一模试卷一、选择题:(本大题10个小题,每小题4分,共40分)在每个小题的下面,都给出了代号为A、B、C、D的四个答案,其中只有一个是正确的,请将答题卡上题号右侧正确答案所对应的方框涂黑。
1.(4分)﹣6的倒数是()A.6B.﹣6C.D.﹣2.(4分)五个大小相同的正方体搭成的几何体如图所示,从上面得到的视图是()A.B.C.D.3.(4分)2024年某市计划重点工程建设项目投资总额为50450000万元,将数50450000用科学记数法表示为()A.50.45×106B.0.5045×108C.5.045×107D.5.045×1064.(4分)把一块直尺与一块三角板如图放置,若∠1=47°,则∠2的度数为()A.53°B.45°C.43°D.33°5.(4分)用边长相等的正方形和等边三角形按如图所示的规律拼图案,其中第①个图案用了4个正方形,第②个图案用了6个正方形,第③个图案用了8个正方形,…,按此规律排列下去,则第2024个图案中用的正方形的个数是()A.4045B.4046C.4048D.40506.(4分)设n为正整数且,则n的值为()A.5B.6C.7D.87.(4分)如图,AB是⊙O的直径,过AB的延长线上的点C作⊙O的切线,切点为P,点D是⊙O上一点,连接BD,DP,若∠BDP=α,则∠C等于()A.αB.2αC.90°﹣αD.90°﹣2α8.(4分)某种植物只有一个主干,该主干上长出若干数目的支干,每个支干又长出同样数目的小分支,主干、支干和小分支的总数是111,设一个主干长出x个支干,则下列方程中正确的是()A.1+x2=111B.(1+x)2=111C.1+x+x2=111D.1+(1+x)+(1+x)2=1119.(4分)如图,已知正方形ABCD的边长为1,点E为边BC上一点,连接AE,作∠DAE的平分线交CD于点F,若F为CD的中点,则BE的长为()A.B.C.D.10.(4分)按顺序排列的8个单项式a,b,c,d,﹣a,﹣b,﹣c,﹣d中,任选m(m≥2)个互不相邻的单项式(其中至少包含一个系数为1的单项式和一个系数为﹣1的单项式)相乘,计算得单项式M,然后在剩下的单项式中再任选若干个单项式相乘,计算得单项式N,最后计算M﹣N,称此为“积差操作”.例如:当m=3时,可选互不相邻的b,﹣a,﹣c相乘,得M=abc,在剩下的单项式a,c,d,﹣b,﹣d中可选c,d相乘,得N=cd,此时M﹣N=abc﹣cd,….下列说法中正确的个数是()①存在“积差操作”,使得M﹣N为五次二项式;②共有3种“积差操作”,使得M﹣N=ad﹣bc;③共有12种“积差操作”,使得M﹣N=0.A.0B.1C.2D.3二、填空题(本大题8个小题,每小题4分,共32分)请将每小题的答案直接填在答题卡中对应的横线上11.(4分)计算:﹣14+|﹣3|=.12.(4分)已知反比例函数与一次函数y=kx﹣2的图象交于点A(﹣1,3),则k的值为.13.(4分)正n边形的每一个外角都是它相邻的内角的2倍,则n的值为.14.(4分)有四张正面分别标有数字﹣2,,0,2的卡片,它们除数字不同外其余全部相同.现将四张卡片背面朝上,洗匀后从中随机抽取两张,则抽取的两张卡片上的数字之积为负数的概率是.15.(4分)如图,在Rt△ABC中,∠ACB=90°,∠A=60°,AC=2,点D是AB边上的中点,以点D 为圆心,BD的长为半径作弧BC.则图中阴影部分的面积为.16.(4分)如图,D,E是△ABC外两点,连接AD,AE,有AB=AD,AC=AE,∠BAD=∠CAE=40°.连接CD,BE交于点F,则∠DFE的度数为.17.(4分)若关于x的一元一次不等式组有解且最多有3个整数解,且使关于y的分式方程有整数解,则所有满足条件的整数a的值之和是.18.(4分)如果一个四位自然数的各数位上的数字不全相等,满足,那么称这个四位数为“跳跃数”.例如:四位数1323,∵12+33=5(1+2+3+3),∴1323是“跳跃数”;又如:四位数5324,∵52+34≠5(5+3+2+4),∴5324不是“跳跃数”.若一个“跳跃数”为,则这个数为;若一个“跳跃数”的前三个数字组成的三位数与后三个数字组成的三位数的差能被7整除,则满足条件的“跳跃数”的最大值是.三、解答题:(本大题8个小题,第19题8分,其余每题各10分,共78分)解答时每小题必须给出必要的演算过程或推理步骤,画出必要的图形(包括辅助线),请将解答过程书写在答题卡中对应的位置上。
2024年重庆八中重点达标名校中考语文模拟试题含解析
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2024年重庆八中重点达标名校中考语文模拟试题注意事项1.考试结束后,请将本试卷和答题卡一并交回.2.答题前,请务必将自己的姓名、准考证号用0.5毫米黑色墨水的签字笔填写在试卷及答题卡的规定位置.3.请认真核对监考员在答题卡上所粘贴的条形码上的姓名、准考证号与本人是否相符.4.作答选择题,必须用2B铅笔将答题卡上对应选项的方框涂满、涂黑;如需改动,请用橡皮擦干净后,再选涂其他答案.作答非选择题,必须用05毫米黑色墨水的签字笔在答题卡上的指定位置作答,在其他位置作答一律无效.5.如需作图,须用2B铅笔绘、写清楚,线条、符号等须加黑、加粗.一、积累与运用1.下列语句中,没有..语病的一项是()A.良好的语文素养是学生学好其他课程的基础,也是学生全面发展和终身发展的基础。
B.能不能战胜自己思想上的弱点,是一个人在事业上成功的关键。
C.在学习中,我们应注意培养自己观察问题、解决问题和分析问题的能力。
D.有关部门最近发出通知,要求各地在国庆期间严防安全不出现问题。
2.下列说法错误的一项是()A.维吾尔族姑娘插上金色的翅膀,在广阔的天地里自由地飞翔。
(这句话把人当做动物来写,运用了“拟物”的修辞手法。
)B.双腿瘫痪后,我的脾气变得暴怒无常。
(句中“双腿瘫痪后”在句中的成分是定语,“暴怒无常”在句中的成分是补语。
)C.我们家赶忙答应了他的请求,并且决定在举行婚礼之后全家到哲尔塞岛去游玩一次。
(句中“赶忙”一词的词性是副词,修饰限制“答应”。
)D.孔乙已是站着喝酒而穿长衫的唯一的人。
他身材高大;青白脸色,皱纹间时常夹些伤痕;一部乱蓬蓬的花白胡子。
(句中“身材高大”是一个主谓短语。
)3.下列各句中标点符号使用规范的一项是A.语言文字的学习。
就理解方面说,是得到一种知识;就运用方面说,是养成一种习惯。
B.通过注入历史、文化、艺术、科技等元素,绿道为城市打开了一个全新的交互界面,人们漫步绿道,便是在阅读这座城市,与它的过去、现在和未来进行对话。
2024年重庆八中学中考联考英语试卷含答案
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2024年重庆八中学中考联考英语试卷含答案考生须知:1.全卷分选择题和非选择题两部分,全部在答题纸上作答。
选择题必须用2B铅笔填涂;非选择题的答案必须用黑色字迹的钢笔或答字笔写在“答题纸”相应位置上。
2.请用黑色字迹的钢笔或答字笔在“答题纸”上先填写姓名和准考证号。
3.保持卡面清洁,不要折叠,不要弄破、弄皱,在草稿纸、试题卷上答题无效。
Ⅰ. 单项选择1、---Do you know ______ what your dream is?---Yes. I will work hard to make my dream come true.A.exactly B.hardly C.carefully D.nearly2、—Do you do any sports now?—Yes, all of us exercise at________least________hour a day in and outside school.A.the; a B.a; an C./; a D./; an3、―Excuse me, could you tell me ?―There is a bank on the second floor. Y ou can make it there.A.where the bank is B.how I can get to the bankC.if there's a bank near here D.where I can exchange money4、The boy promised ______ late for school again.A.not to be B.to not be C.not being D.being not5、—What do you think of the movie you saw last night?—I think it is worth ________.A.seeing B.sees C.to see6、-Could you please when you go out? It smells terrible in the room.-Sure. But where should I put it?A.take out the trash B.sweep the floorC.turn off the light D.fold the clothes7、It’s very important ______us _____ a second language.A.for, to learn B.for, learn C.to, to learn D.to, learn8、―Which magazine do you like better, Let's talk in English or English Salon?―I like of them. They are useful for English learning.A.all B.both C.either D.neither9、Time waits for no man.But some people won't realize the importance of time______it's gone.A.as B.since C.when D.until10、—I joined in 2019 Yangzhou International Half Marathon, ______ I couldn’t run as fast as a real athlete.—That’s really great! You’re my hero!A.though B.until C.unless D.ifⅡ. 完形填空11、I have never taken cooking classes. I learned cooking 1 my mother because she was really 2 in teaching me. Do you kno w why? When my mother got married, she didn’t know anything about cooking. My grandmother never allowed her 3 in the kitchen.My mother did not start to cook 4 she was twenty-five. At the beginning, it was very hard for her. So she had to take cooking classes to prepare our meals. After 5 that experience, she decided to teach me to do some cooking 6 she didn’t want me to have the same experience. I remember when I was seven 7 old, I often stayed in the kitchen and watched her cook. I always helped her. Sometimes we prepared meals that my mother already knew 8 to make them, and sometimes we prepared them from recipes. Nowadays, I am really thankful for that experience. Because I don’t need any help to cook a meal. I can cook for 9 or for a group of people. It doesn’t matter.I will teach my children and I don’t want them to have the same experience10 my mother. If one day I am not with them, I want to be sure that they can also eat well.1.A.by B.to C.from D.after2.A.interesting B.interested C.interest D.interests3.A.staying B.stayed C.to stay D.stay4.A.if B.after C.since D.until5.A.having B.have C.to have D.had6.A.so B.because C.although D.but7.A.years B.year’s C.year D.years’8.A.where B.what C.when D.how9.A.myself B.me C.mine D.I10.A.so B.as C.such D.ofⅢ. 语法填空12、阅读下面材料,在空白处填入适当的内容(1个单词) 或括号内单词的正确形式。
2024届重庆八中重点达标名校中考语文最后一模试卷含解析
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2024届重庆八中重点达标名校中考语文最后一模试卷请考生注意:1.请用2B铅笔将选择题答案涂填在答题纸相应位置上,请用0.5毫米及以上黑色字迹的钢笔或签字笔将主观题的答案写在答题纸相应的答题区内。
写在试题卷、草稿纸上均无效。
2.答题前,认真阅读答题纸上的《注意事项》,按规定答题。
一、积累与运用1.下列语句的顺序排列恰当的一项是()①从而使“痛苦指数”下降,“幸福指数”上升②这种条理性和有序性正是内心满足感的主要来源③守时让一切都变得有条理起来,使生活有序起来④而守时可以减缓甚至消除因时间不确定带来的焦虑⑤现代人普遍患有“时间焦虑症”A.②③⑤④①B.③②⑤④①C.③②①⑤④D.③⑤②④①2.下列句子没有语病的一项是()A.有关各方能否本着维护地区稳定,促进世界和平,是解决朝鲜半岛问题的关键。
B.2018年3月14日,圆周率日,也是爱因斯坦的诞辰日,与疾病顽强斗争的著名科学家斯蒂芬·霍金在这一天逝世。
C.主流媒体及时纠正并指出青少年沉迷“抖音”行为,录播不良视频的危害,让人感到欣慰。
D.通过南海海域举行的隆重海上阅兵仪式,使我们看到了人民海军崭新的面貌,激发了国人的爱国热情。
3.下列句子中划线成语使用正确的一项是()A.这两本成语词典各得其所,一本重视溯源,一本例句丰富,特色都很鲜明。
B.经过大家一番苦心孤诣的开导,他终于明白了团队精神的重要性。
C.由于厂家对产品的设计和生产吹毛求疵,因而产品销路越来越好。
D.魅力的画面与逼真的音响效果相得益彰,使这部影片达到很高的艺术水平。
4.下列各句中,加点成语使用不正确的一项是()A.一些西方媒体别有用心地宣称“中印会陷入冷战”,这是西方有意渲染和扩大中印在地缘政治方面的矛盾,有挑.拨离间...的嫌疑。
B.讲好中国故事,不能一味地选择富丽堂皇....的镜头或夸张的语言来表现中国的繁荣富强,而是要用历史的眼光讲述中国人的时代变迁及其主题。
C.博鳌亚洲论坛2019年年会即将举行,而博鳌各主要路段被装扮一新,路面干干净净,路旁三角梅等花朵鲜艳绽放,彩旗花枝招展....,迎接博鳌亚洲论坛年会的到来。
重庆市八中2024届中考联考语文试卷含解析
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重庆市八中2024届中考联考语文试卷考生请注意:1.答题前请将考场、试室号、座位号、考生号、姓名写在试卷密封线内,不得在试卷上作任何标记。
2.第一部分选择题每小题选出答案后,需将答案写在试卷指定的括号内,第二部分非选择题答案写在试卷题目指定的位置上。
3.考生必须保证答题卡的整洁。
考试结束后,请将本试卷和答题卡一并交回。
一、积累与运用1.下列文学常识及对文章的理解表述正确..的一项是A.《范进中举》节选自《儒林外史》,它是我国一部长篇章回体讽刺小说,主要描写封建社会后期知识分子及官绅的活动和精神面貌。
B.《从百草园到三味书屋》是一篇描写作者童年生活的散文,其中成长读书阶段所遇的启蒙老师古板无趣,令作者心生厌恶。
C.《我的叔叔于勒》的作者是莫泊桑,是法国十九世纪后半期著名的批判现实主义作家。
代表作品有《项链》《变色龙》D.《爱莲说》的作者周敦颐,字茂叔,世称“濂溪先生”,南宋哲学家。
该文表达了作者不与世俗同流合污的高尚品格和对追名逐利世风的鄙弃。
2.下列各句中加点的成语,使用有误的一项是()A.有自知之明....的人,犯了错误也不可怕,他会从中吸取教训。
B.王伟同学参加全国中学生作文大赛获得一等奖,他高兴得涕泗横流....。
C.父亲郑重其事....地带着两个女儿和女婿。
向那个衣服褴褛的年老水手走去。
D.伏尔泰活过了八十四年,经历了登峰造极....的君主政体和曙光初现的革命年代。
3.选出下列关于课外名著的说法有误的一项A.中国第一部歌颂农民起义的长篇章回小说《水浒》通过写众多草莽英雄不同的人生经历和反抗道路,鲜明地表现了“官逼民反”的主题。
B.冰心的《骆驼祥子》讲述的是一个普通的人力车夫的故事。
它通过祥子这个人物的变化,无情地批判了祥子所处的那个社会——它不让好人有出路。
C.善于说故事,善于塑造人物,充满天马行空的想象和大胆奇特的夸张,是《西游记》这部小说的三大成功之处。
D.《钢铁是怎样炼成的》以主人公保尔·柯察金的生活经历为线索,展现了从1915到1930年前后苏俄广阔的历史画面和人民的艰苦卓绝的斗争生活。
重庆第八中学初市级名校2024届中考考前最后一卷化学试卷含解析
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重庆第八中学初市级名校2024年中考考前最后一卷化学试卷注意事项1.考生要认真填写考场号和座位序号。
2.试题所有答案必须填涂或书写在答题卡上,在试卷上作答无效。
第一部分必须用2B 铅笔作答;第二部分必须用黑色字迹的签字笔作答。
3.考试结束后,考生须将试卷和答题卡放在桌面上,待监考员收回。
一、单选题(本大题共10小题,共20分)1.如图1所示,连接好装置和压强传感器。
气密性良好的烧瓶内充满CO1.分别用注射器向烧瓶中迅速注入等量的水、饱和石灰水和40%的氢氧化钠溶液,关闭活塞,一段时间后再振荡烧瓶。
观察传感器所示气压变化如图1所示。
下列说法错误的是()A.曲线1代表加入的是水CO用NaOH溶液较合适B.吸收2C.AB段气压增大的原因之一是液体的添加使气体体积缩小D.曲线1中CD段气压“急速”减少的原因是振荡烧瓶使瓶内气体迅速反应2.结构相似,在分子组成上相差一个或若干个CH2原子团的物质互称为同系物,如甲烷(CH4)和乙烷(C2H6)互为同系物。
则下列物质中与乙醇C2H5OH互为同系物的是A.C3H8B.C4H9OH C.HCHO D.CH3COOH3.下列变化中属于化学变化的是A.苹果榨成汁B.大米酿成酒C.冰雪化成水D.木柴劈成片4.某种金属混合物样品由镁、铁、锌三种金属中的两种金属组成,取5.6 g样品与足量的稀盐酸反应,得到0.28 g氢气。
则此样品的组成是A.镁和铁B.镁和锌C.铁和锌D.无法确定5.下列说法正确的是( )A.物质的量表示约6.02×1023个微粒的集合体B.1mol氧气的质量为32g/molC.等质量的N2和CO的原子个数比为1:1 D.1molCO2中含有2mol氧6.推理是化学学习中常用的方法。
下列推理正确的是A.含碳元素的物质充分燃烧生成CO2,燃烧生成CO2的物质一定含碳元素B.单质中只含一种元素,只含一种元素的物质一定是单质C.有机物是指含碳元素的化合物,含碳元素的化合物一定是有机物D.中和反应生成盐和水,生成盐和水的反应一定是中和反应7.下列图像能正确反映对应变化关系的是( )A.两份等质量、等质量分数双氧水在有、无MnO2的情况下产生氧气B.加水稀释浓盐酸C.向稀盐酸和氯化钙的混合溶液中加入碳酸钠溶液D.将足量粉末状的铁和镁分别与等质量、等质量分数的稀盐酸反应8.生物体中含有多种氨基酸.下列有关甘氨酸的叙述正确的是()A.甘氨酸是有机高分子化合物B.一个甘氨酸分子中含有10个原子C.甘氨酸是由碳、氢、氧、氮四种原子构成的D.甘氨酸中碳原子与氢原子的个数比为24:59.下列日常生活中发生的变化,属于化学变化的是A.苹果榨汁B.玻璃破碎C.冰雪融化D.牛奶变酸10.下列实验现象描述正确的是A.在加热的条件下,一氧化碳还原氧化铜时黑色粉末逐渐变为红色B.电解水一段时间后,正负极产生气体的质量比约为1:2C.打开盛有浓盐酸的瓶盖,在瓶口出现大量白烟D.二氧化碳能使干燥的紫色石蕊纸花变红二、填空题(本大题共1小题,共4分)11.小盘同学配制质量分数为5%的氯化钠溶液100g,以备实验。
重庆市第八中学校2023-2024学年九年级下学期第4次数学试卷(含解析)
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重庆市第八中学校2023-2024学年九年级下学期第4次数学试卷学校:___________姓名:___________班级:___________考号:___________一、单选题1.( )A. B.2024 C.2.在数轴上表示不等式的解集,正确的是( ).A. B. C. D.3.不一定相等的一组是( )A.与B.与C.与D.与4.如图,该几何体的主视图是( )A. B. C. D.5.对于反比例函数函数图象上的为( )A. B. C. D.6.把黑色圆点按如图所示的规律拼图案,其中第①个图案中有4个黑色圆点,第②个图案中有6个黑色圆点,第③个图案中有8个黑色圆点,…,按此规律排列下去,则第⑦个图案中黑色圆点的个数为( )(2024)--=2024-1x>a b+b a+3a a a a++3a a a a⋅⋅()3a b+3a b+y=(1,3)-(3,2)(2,1)--(0,3)-A.12B.14C.16D.187.将进货价格为38元的商品按单价45元售出时,能卖出300个.已知该商品单价每上涨1元,其销售量就减少5个.设这种商品的售价上涨元时,获得的利润为2300元,则下列关系式正确的是( )A. B.C. D.8.如图,是的直径,点C 、D 是上的两点,连接,且,若,,则的长为( )A.9.如图,在正方形内有一点F ,连接,有,若的角平分线交于点E ,若E 为中点,,则的长为( )A. D.510.已知两个实数x 、y ,可按如下规则进行运算:计算的结果,得到的数记为,称为第一次操作.再从x 、y 、中任选两个数,操作一次得到的数记为;再从x 、y 、、中任选两个数,操作一次得到的数记为,依次进行下去.以下结论正确的个数为( )①若x 、y 为方程的两根,则;②对于整数x 、y ,若为偶数,在操作过程中,得到的一定为偶数;x ()()3830052300x x --=()()730052300x x ++=()()730052300x x --=()()730052300x x +-=AB O O AC OD CD 、、AC OD ∥6AB =15ACD =︒∠AC ABCD AF CF ,AF AB =BAF ∠BC BC 3CF =AD (1)(1)1x y ---1z 1z 2z 1z 2z 3z 240m m +-=12z =-x y +n z③若成立,则n 至少为4.A.0B.1C.2D.3二、填空题11.单项式的次数是______.12.若五边形的内角中有一个角为,则其余四个内角之和为______.13.已知反比例函数时,x 的取值范围是______.14.不透明的袋子里装有除标号外完全一样的四个小球,小球上分别标有,0,1,2这四个数字,从袋子中随机抽取一个小球,记标号为a ,不放回,将袋子摇匀,再随机抽取一个小球,记标号为b ,则在第四象限的概率为______.15.如图,AB 是半圆O 的直径,,将半圆O 绕点A 逆时针旋转,点B 的对应点为,连接,则图中阴影部分的面积是______.16.在中,于点D ,以为斜边作,与交于点E ,使得,连接,,若,则的长为______.17.如果关于x 的不等式组至少有两个整数解,且关于y 的分式方程18.若一个四位正整数m 的各个数位数字之和是百位上的数字与十位数字之和的3倍,则称这个四位正整数m 为“和谐数”.将一个“和谐数”m 百位数字和十位数字交换位置后,4,2x y =-=2024232πx y -80︒y =1y ≤1-(,)a b 4AB =30︒B 'AB 'ABC ,AB AC AD BC =⊥BC Rt BCF CF AD AE BD =AF 2FAE BCF ∠=∠4BC =AB 312231x x x x m-⎧<+⎪⎨⎪+≥+⎩311y y =-得到一个新的四位数,记,则______;当“和谐数”m 的百位上的数字是个位上的数字的2倍,千位上的数字与十位上的数字之和能被9整除时,记的最大值为______.三、解答题19.计算:(1)(2)20.在中,是的角平分线,作线段的垂直平分线,分别交、,于点E 、O 、F ,连接、,证明四边形是菱形.(1)尺规作图:作线段的垂直平分线,分别交、,于点E 、O 、F ,连接、(用基本作图,保留作图痕迹,不写作法、结论)(2)证明:四边形是菱形.证明:平分,____________________是线段的垂直平分线,,,在与中,,,__________________m '()F m m m '=-(8526)F =()G m =()()m F m -(2)(2)3(2)a b a b a a b +---2241244x x x x x -⎛⎫-÷ ⎪--+⎝⎭ABC AD BAC ∠AD AB AD AC DE DF AEDF AD AB AD AC DE DF AEDF AD BAC ∠∴EF AD 90AOE AOF ∴∠=∠=︒,AE DE AF DF ==AOE △AOF _________EAO FAO AO AO∠=∠⎧⎪=⎨⎪⎩EAO FAO ∴△≌△AE AF ∴=∴四边形是菱形.(____________________)21.2023年,我国航天事业收获丰硕成果.为激发学生的兴趣,我校举行了航天知识问答活动,从八、九年级学生的知识问答成绩中,各随机抽取了20名学生的成绒进行统计分析.数据整理如下:(成绩得分用x 表示,共分成四组:A .,B .,C .,D .)八年级20名学生的成绩是:76,77,95,84,50,85,85,97,99,92,97,85,65,82,68,85,78,84,98,84九年级20名学生的成绩在C 组中的数据是:81,89,83,88,80,89.八、九年级抽取的学生成绩统计表根据以上信息,解答下列问题:(1)上述图表中__________,__________,__________;(2)通过以上数据分析,你认为这次比赛中哪个年级的成绩更好?请说明理由(写出一条即可);(3)我校八、九年级共有3000人参加此次知识问答活动,请你估计参加此次问答活动成绩优秀的学生有多少人.22.上周末,小马约上小唐一起出发去离学校的地游玩,小唐从学校出发,,结果小马比小唐提前分钟到达地.(1)求小马和小唐的车速分别为多少?(单位:千米小时)∴AEDF 70x <7080x ≤<8090x ≤<90100x ≤≤a =b =c =()90x ≥240km A 18A /(2)地游玩之后,小马和小唐两车以原速度同时出发前往地,小马的车行驶了小时后发生故障,小马原地检修用了分钟后以原速度的行驶.此时,小唐提高速度,为了保证小唐再用不超过1小时与小马相遇,那么小唐的行驶速度至少提高多少千米小时?23.如图,在中,,点D 为斜边的中点,连接,动点E 从点A 出发,沿着折线达B 点停止运动,过点E 作,垂足为点F ,点G 、H 分别是射线,上的两个动点,的长度等于点E 运动的路程,,的长度为,BH 的长度为.(1)直接写出关于x的函数关系式,并注明自变量x 的取值范围;(2)在给定的直角坐标系中画出的图象,并写出函数的一条性质:(3)结合函数图象,直接写出当时,x 的取值范围:__________.(结果保留1位小数,误差不超过0.2)24.如图,,,,为同一平面内的四个点,已知景点位于景点的正东方向,景点位于景点的正东方向,景点位于点的西北方向米处,景点位于景点的北偏西方向,景点位于景点的南偏东方向.(参考数据:)A B 22080%Rt ABC △90,12,16ABC AB BC ∠=︒==AC BD A D →→EF AB ⊥BA BC BG BGH S =△(0)x >EF 1y 2y 12,y y 12,y y 1y 12y y ≤A B C D B A C D B C 1500A C 53︒D A 30︒sin 53︒≈︒≈53︒≈≈≈ 2.45≈(1)求景点与景点之间的距离.(结果保留根号)(2)小豪选择路线前往景点处,小兰选择路线前往景点与小豪汇合,两人在各景点处停留的时间忽略不计.己知两人同时出发且速度相同,请通过计算说明谁先到达景点.25.如图1,在平面直角坐标系中,抛物线与x 轴交于两点,与y 轴交于点C .(1)求抛物线的解析式;(2)如图1,点P 为第二象限抛物线上的一点,过点P 作轴交直线于点D ,过点P 作轴交直线于点E ,F 为y 轴上一点,且满足,求的最大值及此时点P 的坐标;(3)如图2,将原抛物线进行平移,平移后的抛物线与x 轴交于点M ,N ,顶点为,轴于H ,在平移后的抛物线上是否存在点R ,使得,若存在,请直接写出R 的坐标,若不存在,请说明理由.26.在等腰中,,点是射线上的一点.A C A D C →→CB AC →→C C 22y ax bx =++(3,0),(2,0)A B -PD y ∥AC PE x AC DC DF =38PE CF +(4,3)G GH x ⊥GNR BAC MGH ∠+∠=∠ABC AB AC =D BC(1)如图1,若,,求的长;(2)如图2,若,过点作交于点,点为边上的一点,且,过点作交直线于点,求证:;(3)如图3,若,,点是边上的一点,且,点是平面内任意一点,将沿翻折得到,点为直线上的一点,将线段绕着点逆时针旋转得到线段,若,当线段最短时求的面积.30BAC ∠=︒6AC =45D ∠=︒CD 90BAC ∠=︒C CQ AB ∥AD Q M AC MBC D ∠=∠B BH BM ⊥CQ H 2CQ CM CH +=60BAC ∠=︒6AC =F AB 2BF =K AKF AK AKF '△M AC BM M 90︒EM 90AF E '∠=︒F E 'ABE参考答案1.答案:B 解析:,故选B.2.答案:A 解析:在数轴上表示不等式的解集,故选:A.3.答案:D解析:A .=,故选项A 不符合题意;B .,故选项B 不符合题意;C . ,故选项C 不符合题意;D . ,故选项D 符合题意,故选:D .4.答案:B解析:从正面看易得,该几何体的视图为B ,故选:B5.答案:A解析:∵每个象限内y 都随x 的增大而增大,∴反比例函数A.∵,∴符合题意;B.∵,∴不符合题意;C.∵,∴不符合题意;D.∵在坐标轴上,不在二四象限,∴不符合题意;故选A.6.答案:C(2024)2024--=1x >a b +b a +=3a a a a ++3=a a a a ⋅⋅()3333a b a b a b +=+≠+y =0<1330k =-⨯=-<(1,3)-3260k =⨯=>(3,2)()2120k =-⨯-=>(2,1)--(0,3)-(0,3)-解析:由已知图形可知:第①个图案中有4个黑色圆点,第②个图案中有6个黑色圆点,,第③个图案中有8个黑色圆点,,……以此类推,第n 个图形黑色圆点个数为:,因此第⑦个图案中黑色圆点的个数为:,故选C.7.答案:D 解析:根据题意可得:,即:故选:D.8.答案:D 解析:如图,连接,∵,∴,∵,∴,∴,∴故选:D9.答案:C解析:设的长为,连接,过点E 作于点H ,过点F 作于点()64221=+⨯-()84231=+⨯-()42122n n +-=+27216⨯+=()()453830052300x x +--=()()730052300x x +-=BC 15ACD =︒∠230AOD ACD ∠=∠=︒AC OD ∥30CAB AOD ∠=∠=︒132BC AB ==AC ==AD 2x EF EH FC ⊥FG AE ⊥G .如图所示,∵四边形是正方形,∴.∵为的中点,∴.∵平分,∴,∵,∴.∴,,.∴.∴.∵,.∴.∴.∵,.∴,在中,,∵∴∴在中,,ABCD 2AB BC AD x ===E BC BE EC x ==AE BAF ∠BAE FAE ∠=∠2,AF AB x AE AE ===()SAS BAE FAE ≌EF EB x ==90AFE B ∠=∠=︒AEB AEF ∠=∠EF EC =ECF EFC ∠=∠180ECF EFC CEF ∠+∠+∠=︒180AEB AEF CEF ∠+∠+∠=︒ECF AEB ∠=∠FC AE ∥EH FC ⊥FG AE ⊥EH FG =Rt AEF AE ===1122AEF S AF EF AE FG =⋅=⋅ AF EF FG AE ⋅==EH =Rt EHC △13,22HC FC EC x ===∵,∴,解得:∴故选C.10.答案:B解析:①x 、y 为方程的两根,∴,,∴故说法错误;②对于整数x 、y ,若为偶数,则x 、y 同为偶数或同为奇数,∴为偶数或奇数,∴的结果可能为奇数或偶数,∴得到的一定为偶数说法错误;③若,则 ,然后从中选取绝对值较大的两个数,进行计算,则,,成立,则n 至少为4,说法正确,故选:B.11.答案:5解析:单项式的次数是,故答案为:512.答案:解析:.222EC HC EH =+22232x ⎛⎫=+ ⎪⎝⎭x =2AD x ==240m m +-=1x y +=-4xy =-()()(1)(1)111413x y xy x y xy x y ---=--+-=-+=---=-x y +xy (1)(1)1x y ---n z 4,2x y =-=1826z =-+=-()()()2464634z =-⨯----=()()3346346232z =⨯---=-()4232342323467690z =-⨯--+=-20242024232πx y -235+=460︒()5218080460-⨯︒-︒=︒故答案为:.13.答案:或解析:当时,则有,∵,即y 随x 的增大而增大,反比例函数的图象在第二、四象限,∴当时,的取值范围是或;故答案为:或.解析:画树状图如图:共有个等可能的结果,则在第四象限的结果有个,∴解析:连接, 过作于,由旋转的性质得到:,,,,,460︒1x ≤-0x >1y =1=1=-10k =-<1y ≤x 1x ≤-0x >1x ≤-0x >12(),a b 2(,a b =2π3OK K KH AB ⊥H 30BAK ∠=︒OA OK = 30OKA OAK ∴∠=∠=︒30260BOK ∴∠=︒⨯=︒4AB =,的面积扇形的面积∴阴影的面积的面积扇形的面积16.答案:解析:连接,∵于点D,∴,即点D为的中点,∵以为斜边作,∴,∴∴,设,则,∴,∴,∵,2OB OK OA∴===sin sin60KHKOHOK∴∠=︒==KH∴=OAK∴11222OA KH=⋅=⨯=OBK260π2360⨯==OAK= +OBK=DF,AB AC AD BC=⊥122BD CD BC===BCBC Rt BCF90BFC∠=︒122DF BD CD BC====CFD BCF∠=∠BCF x∠=22,FAE BCF x∠=∠=CFD x∠=2BDF CFD BCF x∠=∠+∠=BDF FAE∠=∠90BCF CED BCF CBF∠+∠=∠+∠=︒∴,∵∴,又∵,∴∴,,∴,∴∴在中,故答案为:17.答案:12解析:解不等式组,得:不等式组至少有两个整数解,,解得:,解关于得:,且∴分式方程解为正整数,且,符合条件的所有整数的值为5,7,符合条件的所有整数的和为.故答案为:12.18.答案:270;解析:,CED CBF ∠=∠CED AEF∠=∠CBF AEF ∠=∠AE BD =()ASA AEF DBF ≌2AF DF ==BFD AFE ∠=∠90AFE CFD BFD CFD BFC ∠+∠=∠+∠=∠=︒90AFD ∠=︒AD ===Rt ABD △AB ===312231x x x x m -⎧<+⎪⎨⎪+≥+⎩x x <⎧⎪⎨≥⎪⎩ ∴132m -≤7m ≤y 1=12m y -=10y -≠3m ≠ 3m ≠∴m ∴m 5712+=2661(8526)852********F =-=设“和谐数”m 千位、百位、十位和个位的数字分别为a 、b 、c 、d ,∴,由“和谐数”定义可得,∴,∵百位上的数字是个位上的数字的2倍,∴,∴,即∵千位上的数字与十位上的数字之和能被9整除,∴设,∴,即,∴∴、取最大值时有最大值∵,,,,∴,,∴∵∴最大值为,此时,满足∴当、时,,故答案为:270,.19.答案:(1)()1()10001001033m G m a b c d ==+++()()()1000100101000100109090F m m m a b c d a c b d b c'=-=+++-+++=-()3b c a b c d +=+++()2b c a d +=+2b d =42d c a d +=+32d c a+=9a c n +=329d c c n ++=3d c n +=()()1()()10001001090903G m F m a b c d b c -=+++--()110001702803a b c d =-++()110003217022803d c d c d =+-⨯++⎡⎤⎣⎦()1266122803d c =+d c ()()G m F m -19a ≤≤09b ≤≤09c ≤≤09d ≤≤1329d c ≤+≤029d ≤≤0d ≤≤1329d c ≤+≤d 30c =3d c n+=3d =0c =()()G m F m -()26613228002661⨯+⨯=26612242b a --(2)解析:(1);(2)20.答案:(1)见解析(2),,,四条边相等的四边形是菱形解析:(1)作图如下:(2)证明:平分,,是线段的垂直平分线,,,在与中,22x -+(2)(2)3(2)a b a b a a b +---22224263a ab ab b a ab=-+--+2242a b =--2241244x x x x x -⎛⎫-÷ ⎪--+⎝⎭()()()222222x x x x x x ---=⨯-+-()()()222222x x x x --=⨯-+-=EAO FAO ∠=∠AOE AOF ∠=∠AE AF DE DF ===AD BAC ∠∴EAO FAO ∠=∠EF AD 90AOE AOF ∴∠=∠=︒,AE DE AF DF ==AOE △AOF EAO FAOAO AOAOE AOF ∠=∠⎧⎪=⎨⎪∠=∠⎩,,,四边形是菱形.(四条边相等的四边形是菱形)21.答案:(1);;(2)九年级的成绩更好,理由见解析(3)1050人解析:(1)由题意得,,∴;把九年级学生成绩从低到高排列,处在第10名和第11名的成绩分别为88,89,∴九年级的中位数,∵八年级成绩中,成绩为85的出现了四次,出现的次数最多,∴八年级的众数,故答案为:;;;(2)九年级的成绩更好,理由如下:从平均成绩看,两个年级的平均成绩相同,但是九年级的中位数和众数都比八年级的大,∴九年级的成绩更好;(3)人,∴估计参加此次问答活动成绩优秀的学生有1050人.22.答案:(1)小马和小唐的车速分别为千米小时和千米小时;(2)小唐的行驶速度至少提高千米小时.解析:(1)设小马的车速为千米千米/小时,,经检验是原方程的解,EAO FAO∴△≌△AE AF∴=AE AF DE DF∴===∴AEDF4088.5856%110%20%100%40%20a=---⨯=40a=888988.52b+==85c=4088.58562040%300010502020+⨯⨯=+()90x≥100/75/30/x/x2401860x-=+100=100x=,答:小马和小唐的车速分别为千米小时和千米小时;(2)设小唐的行驶速度提高千米小时,由题意得:,解得:,答:小唐的行驶速度至少提高千米小时.23.答案:(1),(2)作图见解析,当时,有最大值为8(答案不唯一);(3)或解析:(1)∵,∴,∵点D 是的中点,∴,,当时,∵,,∴,∴,∴,当时,过D 作于点G ,3100754=⨯=100/75/y /()20752751100210080%160y ⎛⎫⨯+++⨯≥⨯+⨯⨯ ⎪⎝⎭30y ≥30/()()120421648t t y t t <≤⎧⎪=⎨-+<≤⎪⎩()2608y t t =<≤4t =1y 0 1.7t <≤7.68t ≤≤90,12,16ABC AB BC ∠=︒==20AC =AC 1102BD AD AC ===51042t =÷=04t ≤<EF AB ⊥90BAC ∠=︒EF AC ∥FAE BAC ∽△△==12y t =48t ≤≤DM AB ⊥∵点D 是的中点,∴,,∴,∵,,∴,∴,∴,∴,根据题意,得,∵,,∴(2)画图如下:AC 12ABD ABC S S =1122AB DM AB BC ⋅=⨯⋅1112121622DM ⨯=⨯⨯⨯8DM =DM AB ⊥EF AB ⊥EF DM ∥BFE BMD ∽==14165y t =-+()()120421648t t y t t <≤⎧⎪=⎨-+<≤⎪⎩BG t =BGH S =△2BH y =90GBH ∠=︒252t y ⋅=()2608y t t=<≤根据图象,知:当时,有最大值为8(答案不唯一);(3)令,可得:(舍去负值),或根据图象知:当或时,.24.答案:(1)(2)小豪先到景点解析:(1)如图,过点作交延长线于点,在中,,,在中,,答:景点与的距离为米;(2)如图,过点作交延长线于点,4t =1y 12y y = 1.7t ≈7.6t ≈0 1.7t <≤7.68t ≤≤12y y ≤C CE AB ⊥AB E t R BEC △1500BC =45BCE ∠=︒cos 451500CE BC ∴⋅︒==t R AEC 53ACE ∠=︒cos CE AC ACE ∴∠=A C A AF CD ⊥CD F在中,又在中,,,故小豪总路程,米,又故小兰总路程米,,答:小豪先到景点.25.答案:(1)(2)取得最大值2,此时(3)存在,或解析:(1)∵抛物线与x 轴交于两点,∴,∴t R AFD AF CE ==cos30AF AD ∴︒==2AD FD ==Rt AEC AC =ACE ︒=534sin 535AE AC ∴⋅︒===CD CF FD ∴--==AD DC ++-==2022.5+≈=AB AE BE AE AF =-=-==2115AB AC ++≈==2022.52115< C 211233y x x =--+38PE CF +42,3P ⎛⎫- ⎪⎝⎭83,3⎛⎫ ⎪⎝⎭119,24⎛⎫ ⎪⎝⎭22y ax bx =++(3,0),(2,0)A B -93204220a b a b -+=⎧⎨++=⎩a b ⎧=⎪⎪⎨⎪=⎪⎩∴;(2)如图,故点D 作轴于点Q ,当时,,∴,设直线的解析式为,∴,∴∴,∵,∴,∴.∵,∴.设,则,,∴,,∴211233y x x =--+DQ y ⊥0x =11002233y =-⨯-⨯+=()0,2C AC 12y k x =+1032k =-+1k =223y x =+PE OA 2tan tan 3OC PED OAC OA ∠=∠==32PE PD =DC DF =2CF CQ =()211,23033P m m m m ⎛⎫--+-<< ⎪⎝⎭2,23D m m ⎛⎫+ ⎪⎝⎭20,23Q m ⎛⎫+ ⎪⎝⎭221121223333PD m m m m m =--+--=--222233CQ m m =--=-38PE CF +,∵,∴当时,取得最大值2,此时;(3)∵平移后的抛物线顶点为,∴平移后解析式为当时,,∴,∴.∵,,∴,∴是等腰直角三角形,∴.连接,并延长交直线于点K ,①当在的左侧时,∵,,∴,∴,∴,∴∴,设直线的解析式为,2313222383m m m ⎛⎫⎛⎫=--+⨯⨯- ⎪ ⎪⎝⎭⎝⎭2122m m =--()21222m =-++102-<2m =-38PE CF +42,3P ⎛⎫- ⎪⎝⎭(4,3)G ()2211843333y x x x =--+=-+0y =21870333x x -+-=121,7x x ==()()1,0,7,0M N 2218MG NG ==236MN =222MG NG MN +=GMN 45GMN GNM HGM ∠=∠=∠=︒NR NR AC NK NG 45GNR BAC MGH ∠+∠=∠=︒45GNR ANR MNG ∠+∠=∠=︒BAC ANR ∠=∠AK NK =3722K x -+==2223K y =⨯+=102,3K ⎛⎫ ⎪⎝⎭NK 22y k x b =+把点,点代入,得∴∴直线的解析式为:解(舍去),∴.②当在的右侧时∵,,∴∴.∵,∴,∴∴∴()3,0A-()7,0N222272k bk b+=⎧⎪⎨+=⎪⎩22kb⎧=⎪⎪⎨⎪=⎪⎩NK2y x3=-+2183321433y x xy x⎧=-+⎪⎪⎨⎪=-+⎪⎩11xy==227xy==83,3R⎛⎫⎪⎝⎭NK NG45GNR BAC MGH∠+∠=∠=︒45MNG∠=︒''90NAK ANK∠+∠=︒90AK N'∠=︒,90CAO NAK AOC AK N''∠=∠∠=∠=︒CAO NAK'∽OC ACNK AN==='AK NK''==KAK NKyAN'''⋅==Kx'=∴,用待定系数法可求出解(舍去),∴.综上可知,R 的坐标为或.26.答案:(1)(2)见解析解析:(1)过点作,交于点,∵,∴是等腰直角三角形,∴,,∵,,∴,∴,∵,∴,∴,5160,1313K '⎛⎫ ⎪⎝⎭32NK y x '=-+2183332122y x x y x ⎧=-+⎪⎪⎨⎪=-+⎪⎩11x y =2270x y ==119,24R '⎛⎫ ⎪⎝⎭83,3⎛⎫ ⎪⎝⎭119,24⎛⎫ ⎪⎝⎭C CE AD ⊥ADE 45D ∠=︒ECD 45ECD ∠=︒CD =AB AC =30BAC ∠=︒()()11180180307522ACB ABC BAC ∠=∠=︒-∠=︒-︒=︒180180754560ACE ACB ECD ∠=︒-∠-∠=︒-︒-︒=︒6AC =116322CE AC ==⨯=3CD ===故答案为:(2)过点作,交于点,∵,,,∴是正方形,∴,,∵,∴,∴,∴,∴,∵,,,∴,∴,∴,∴,∴,即:,(3)过点,作,交于点,在射线上截取,连接、、,过点作,交直线于点,B BE CQ ⊥CQ E AB AC =90BAC ∠=︒CQ AB ∥ABEC BE AB AC EC ===90ABE ∠=︒BH BM ⊥90ABM MBE MBE EBH ∠+∠=∠+∠=︒ABM EBH ∠=∠()ASA ABM EBH ≌AM EH =45MBC ABM ABC ∠+∠=∠=︒45CAQD ACB ∠+∠=∠=︒MBC D ∠=∠ABM CAQ ∠=∠()ASA ABM CAQ ≌AM EH CQ ==AM MC EC +=AM MC EH EC EH ++=+2CQ CM CH +=B BD AC ⊥AC D DC DG DB =AE BE BG A AH GE ⊥GE H∵,,,,∴、是等腰直角三角形,,,∴,∴,∴,∴,∴,∴是等腰直角三角形,∴,∵,∴,由翻折的性质可得,,∴当取最小值时,取得最小值,∵当点与点重合时,取得最小值,∵,,,∴,,∴∵,,∴,BM BE =90BME ∠=︒DG DB =BD AC ⊥BME BDG BD BG ==45MBE DBG =∠=︒45DGB ∠=︒45MBD DBE DBE EBG ∠+∠=∠+∠=︒MBD EBG ∠=∠MBD EBG ∽90BDM BGE ∠=∠=︒904545AGH BGH BGD ∠=∠-∠=︒-︒=︒AGH AH GH AG ==90AF E '∠=︒222F E AE F A ''=-624F A FA AB BF '==-=-=AE F E 'E H AE 60BAC ∠=︒6AC =BD AC ⊥BD =3AD =BD DG =3AG AD DG =+=+3AH GH ==+=90BGE ∠=︒AH GE ⊥AH BG ∥∴21122ABE AGHS S AH GH==⋅==。
重庆八中重点达标名校2024届中考联考生物试题含解析
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重庆八中重点达标名校2024年中考联考生物试题注意事项1.考生要认真填写考场号和座位序号。
2.试题所有答案必须填涂或书写在答题卡上,在试卷上作答无效。
第一部分必须用2B 铅笔作答;第二部分必须用黑色字迹的签字笔作答。
3.考试结束后,考生须将试卷和答题卡放在桌面上,待监考员收回。
1、下列食品的保存方法与所利用的生物学原理,不相符的是()A.A B.B C.C D.D2、关节在运动中所起的作用是A.动力B.支点 C.控制D.杠杆3、植被覆盖率高的地方,气候条件往往较好,如降雨量较多,夏天也较凉爽。
这主要是利用植物的何种生理作用()A.光合作用B.呼吸作用C.蒸腾作用D.吸收作用4、下列有关人体食物的消化和吸收说法错误的是()A.淀粉的初始消化场所是口腔,口腔中的唾液含有唾液淀粉酶B.胃腺分泌的胃液,含有胃蛋白酶和盐酸,胃蛋白酶能初步消化蛋白质C.脂肪的初步消化场所是肝脏,肝脏分泌的胆汁中含有脂肪酶D.消化的主要器官是小肠,吸收营养的主要器官也是小肠5、人体吸收营养物质的主要场所是()A.胃B.小肠C.大肠D.食道6、血液的成分中具有止血和凝血作用的是( )。
A.红细胞B.白细胞C.血浆D.血小板7、蝗虫的呼吸器官是()A.体壁B.气管C.气门D.肺8、如图是某些生物结构或部分结构示意图,下列说法中不正确的是()A.除③外,其他都有细胞结构,都属于真核细胞B.①进行的是分裂生殖,③必须寄生在活细胞内C.②可以用于制面包、酿酒,④对污水净化有一定作用D.①②④是由细胞直接构成生物体,而⑤是构成植物体的最基本单位9、自然界中的生物具有多样性,如图为四种生物示意图,有关叙述错误的是()A.①与②相比,在细胞结构上的主要区别是没有成形的细胞核B.③由蛋白质外壳和内部核酸构成,只有在寄主活细胞内才能表现生命活性C.四种生物都不能进行光合作用D.②和④在条件适宜时都可以进行出芽生殖10、如图分別表示人体免疫的两种免疫过程。
重庆八中学2024届中考五模数学试题含解析
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重庆八中学2024届中考五模数学试题注意事项1.考生要认真填写考场号和座位序号。
2.试题所有答案必须填涂或书写在答题卡上,在试卷上作答无效。
第一部分必须用2B 铅笔作答;第二部分必须用黑色字迹的签字笔作答。
3.考试结束后,考生须将试卷和答题卡放在桌面上,待监考员收回。
一、选择题(共10小题,每小题3分,共30分)1.如图是由6个完全相同的小长方体组成的立体图形,这个立体图形的左视图是()A.B.C.D.2.计算(-18)÷9的值是( )A.-9 B.-27 C.-2 D.23.方程=的解为( )A.x=3 B.x=4 C.x=5 D.x=﹣54.式子2x1x1+-有意义的x的取值范围是()A.1x2≥-且x≠1B.x≠1C.1x2≥-D.1x>2-且x≠15.小军旅行箱的密码是一个六位数,由于他忘记了密码的末位数字,则小军能一次打开该旅行箱的概率是()A.110B.19C.16D.156.如图,是由7个大小相同的小正方体堆砌而成的几何体,若从标有①、②、③、④的四个小正方体中取走一个后,余下几何体与原几何体的主视图相同,则取走的正方体是()A.①B.②C.③D.④7.下列运算正确的是()A.﹣(a﹣1)=﹣a﹣1 B.(2a3)2=4a6C.(a﹣b)2=a2﹣b2D.a3+a2=2a58.如图,在△ABC 中,EF ∥BC ,AB=3AE ,若S 四边形BCFE =16,则S △ABC =( )A .16B .18C .20D .249.如图,AB 是半圆圆O 的直径,ABC ∆的两边,AC BC 分别交半圆于,D E ,则E 为BC 的中点,已知50BAC ∠=,则C ∠=( )A .55B .60C .65D .7010.把直线l :y=kx+b 绕着原点旋转180°,再向左平移1个单位长度后,经过点A (-2,0)和点B (0,4),则直线l 的表达式是( )A .y=2x+2B .y=2x-2C .y=-2x+2D .y=-2x-2二、填空题(本大题共6个小题,每小题3分,共18分)11.已知平面直角坐标系中的点A (2,﹣4)与点B 关于原点中心对称,则点B 的坐标为_____12.数据﹣2,0,﹣1,2,5的平均数是_____,中位数是_____.13.四张背面完全相同的卡片上分别写有0、·392、227四个实数,如果将卡片字面朝下随意放在桌子上,任意取一张,那么抽到有理数的概率为___________.14.在反比例函数2y x=图象的每一支上,y 随x 的增大而______(用“增大”或“减小”填空). 15.有下列等式:①由a=b ,得5﹣2a=5﹣2b ;②由a=b ,得ac=bc ;③由a=b ,得a b c c =;④由23a b c c=,得3a=2b ; ⑤由a 2=b 2,得a=b .其中正确的是_____.16.小青在八年级上学期的数学成绩如下表所示.平时测验 期中考试 期末考试 成绩 86 90 81 如果学期总评成绩根据如图所示的权重计算,小青该学期的总评成绩是_____分.三、解答题(共8题,共72分)17.(8分)如图,已知⊙O的直径AB=10,弦AC=6,∠BAC的平分线交⊙O于点D,过点D作DE⊥AC交AC的延长线于点E.求证:DE是⊙O的切线.求DE的长.18.(8分)已知关于x 的一元二次方程x2﹣2(k﹣1)x+k(k+2)=0 有两个不相等的实数根.求k 的取值范围;写出一个满足条件的k 的值,并求此时方程的根.19.(8分)如图,在大楼AB的正前方有一斜坡CD,CD=13米,坡比DE:EC=1:125,高为DE,在斜坡下的点C处测得楼顶B的仰角为64°,在斜坡上的点D处测得楼顶B的仰角为45°,其中A、C、E在同一直线上.求斜坡CD 的高度DE;求大楼AB的高度;(参考数据:sin64°≈0.9,tan64°≈2).20.(8分)我们定义:如果一个三角形一条边上的高等于这条边,那么这个三角形叫做“等高底”三角形,这条边叫做这个三角形的“等底”.(1)概念理解:如图1,在△ABC中,AC=6,BC=3,∠ACB=30°,试判断△ABC是否是”等高底”三角形,请说明理由.(1)问题探究:如图1,△ABC是“等高底”三角形,BC是”等底”,作△ABC关于BC所在直线的对称图形得到△A'BC,连结AA′交直线BC于点D.若点B是△AA′C的重心,求ACBC的值.(3)应用拓展:如图3,已知l1∥l1,l1与l1之间的距离为1.“等高底”△ABC的“等底”BC在直线l1上,点A在直线l1上,有一边的长是BC的2倍.将△ABC绕点C按顺时针方向旋转45°得到△A'B'C,A′C所在直线交l1于点D.求CD的值.21.(8分)如图,AB、CD是⊙O的直径,DF、BE是弦,且DF=BE,求证:∠D=∠B.22.(10分)为进一步打造“宜居重庆”,某区拟在新竣工的矩形广场的内部修建一个音乐喷泉,要求音乐喷泉M到广场的两个入口A、B的距离相等,且到广场管理处C的距离等于A和B之间距离的一半,A、B、C的位置如图所示.请在答题卷的原图上利用尺规作图作出音乐喷泉M的位置.(要求:不写已知、求作、作法和结论,保留作图痕迹,必须用铅笔作图)23.(12分)如图,平行四边形ABCD的对角线AC,BD相交于点O,延长CD到E,使DE=CD,连接AE.(1)求证:四边形ABDE是平行四边形;(2)连接OE,若∠ABC=60°,且AD=DE=4,求OE的长.24.综合与探究:如图1,抛物线y=﹣33x2+233x+3与x轴分别交于A、B两点(点A在点B的左侧),与y轴交于C点.经过点A的直线l与y轴交于点D(0,﹣3).(1)求A、B两点的坐标及直线l的表达式;(2)如图2,直线l从图中的位置出发,以每秒1个单位的速度沿x轴的正方向运动,运动中直线l与x轴交于点E,与y轴交于点F,点A 关于直线l的对称点为A′,连接FA′、BA′,设直线l的运动时间为t(t>0)秒.探究下列问题:①请直接写出A′的坐标(用含字母t的式子表示);②当点A′落在抛物线上时,求直线l的运动时间t的值,判断此时四边形A′BEF的形状,并说明理由;(3)在(2)的条件下,探究:在直线l的运动过程中,坐标平面内是否存在点P,使得以P,A′,B,E为顶点的四边形为矩形?若存在,请直接写出点P的坐标;若不存在,请说明理由.参考答案一、选择题(共10小题,每小题3分,共30分)1、B【解题分析】根据题意找到从左面看得到的平面图形即可.【题目详解】这个立体图形的左视图是,故选:B.【题目点拨】本题考查了简单组合体的三视图,解题的关键是掌握左视图所看的位置.2、C【解题分析】直接利用有理数的除法运算法则计算得出答案.【题目详解】解:(-18)÷9=-1. 故选:C .【题目点拨】此题主要考查了有理数的除法运算,正确掌握运算法则是解题关键.3、C【解题分析】方程两边同乘(x-1)(x+3),得x+3-2(x-1)=0,解得:x=5,检验:当x=5时,(x-1)(x+3)≠0,所以x=5是原方程的解,故选C.4、A【解题分析】根据二次根式被开方数必须是非负数和分式分母不为0在实数范围内有意义,必须12x 10x 1{{x 2x 102x 1+≥≥-⇒⇒≥--≠≠且x 1≠.故选A . 5、A【解题分析】∵密码的末位数字共有10种可能(0、1、 2、 3、4、 5、 6、 7、 8、 9、 0都有可能), ∴当他忘记了末位数字时,要一次能打开的概率是110. 故选A.6、A【解题分析】根据题意得到原几何体的主视图,结合主视图选择.【题目详解】解:原几何体的主视图是:.视图中每一个闭合的线框都表示物体上的一个平面,左侧的图形只需要两个正方体叠加即可.故取走的正方体是①.故选A.【题目点拨】本题考查了简单组合体的三视图,中等难度,作出几何体的主视图是解题关键.7、B【解题分析】根据去括号法则,积的乘方的性质,完全平方公式,合并同类项法则,对各选项分析判断后利用排除法求解.【题目详解】解:A、因为﹣(a﹣1)=﹣a+1,故本选项错误;B、(﹣2a3)2=4a6,正确;C、因为(a﹣b)2=a2﹣2ab+b2,故本选项错误;D、因为a3与a2不是同类项,而且是加法,不能运算,故本选项错误.故选B.【题目点拨】本题考查了合并同类项,积的乘方,完全平方公式,理清指数的变化是解题的关键.8、B【解题分析】【分析】由EF∥BC,可证明△AEF∽△ABC,利用相似三角形的性质即可求出S△ABC的值.【题目详解】∵EF∥BC,∴△AEF∽△ABC,∵AB=3AE,∴AE:AB=1:3,∴S△AEF:S△ABC=1:9,设S△AEF=x,∵S四边形BCFE=16,∴1 169xx=+,解得:x=2,∴S△ABC=18,故选B.【题目点拨】本题考查了相似三角形的判定与性质,熟练掌握相似三角形的面积比等于相似比的平方是解本题的关键.9、C【解题分析】连接AE,只要证明△ABC是等腰三角形,AC=AB即可解决问题.【题目详解】解:如图,连接AE,∵AB是直径,∴∠AEB=90°,即AE⊥BC,∵EB=EC,∴AB=AC,∴∠C=∠B,∵∠BAC=50°,∴∠C=12(180°-50°)=65°,故选:C.【题目点拨】本题考查了圆周角定理、等腰三角形的判定和性质、线段的垂直平分线的性质定理等知识,解题的关键是学会添加常用辅助线,灵活运用所学知识解决问题.10、B【解题分析】先利用待定系数法求出直线AB的解析式,再求出将直线AB向右平移1个单位长度后得到的解析式,然后将所得解析式绕着原点旋转180°即可得到直线l.【题目详解】解:设直线AB的解析式为y=mx+n.∵A(−2,0),B(0,1),∴,解得,∴直线AB的解析式为y=2x+1.将直线AB向右平移1个单位长度后得到的解析式为y=2(x−1)+1,即y=2x+2,再将y=2x+2绕着原点旋转180°后得到的解析式为−y=−2x+2,即y=2x−2,所以直线l的表达式是y=2x−2.故选:B.【题目点拨】本题考查了一次函数图象平移问题,掌握解析式“左加右减”的规律以及关于原点对称的规律是解题的关键.二、填空题(本大题共6个小题,每小题3分,共18分)11、(﹣2,4)【解题分析】根据点P(x,y)关于原点对称的点为(-x,-y)即可得解.【题目详解】解:∵点A (2,-4)与点B关于原点中心对称,∴点B的坐标为:(-2,4).故答案为:(-2,4).【题目点拨】此题主要考查了关于原点对称点的性质,正确掌握横纵坐标的关系是解题关键.12、0.8 0【解题分析】根据中位数的定义和平均数的求法计算即可,中位数是将一组数据按照从小到大(或从大到小)的顺序排列,如果数据的个数是奇数,则处于中间位置的数就是这组数据的中位数.如果这组数据的个数是偶数,则中间两个数据的平均数就是这组数据的中位数.【题目详解】平均数=(−2+0−1+2+5)÷5=0.8;把这组数据按从大到小的顺序排列是:5,2,0,-1,-2,故这组数据的中位数是:0.故答案为0.8;0.【题目点拨】本题考查了平均数与中位数的定义,解题的关键是熟练的掌握平均数与中位数的定义.13、34【解题分析】根据概率的求法,找准两点:①全部情况的总数;②符合条件的情况数目;二者的比值就是其发生的概率.【题目详解】∵在0.·3、227这四个实数种,有理数有0.·3227这3个, ∴抽到有理数的概率为34, 故答案为34. 【题目点拨】此题考查概率的求法:如果一个事件有n 种可能,而且这些事件的可能性相同,其中事件A 出现m 种结果,那么事件A 的概率P (A )=m n . 14、减小【解题分析】根据反比例函数的性质,依据比例系数k 的符号即可确定.【题目详解】∵k=2>0,∴y 随x 的增大而减小.故答案是:减小.【题目点拨】本题考查了反比例函数的性质,反比例函数y=k x(k≠0)的图象是双曲线,当k >0,双曲线的两支分别位于第一、第三象限,在每一象限内y 随x 的增大而减小;(3)当k <0,双曲线的两支分别位于第二、第四象限,在每一象限内y 随x 的增大而增大.15、①②④【解题分析】①由a =b ,得5﹣2a =5﹣2b ,根据等式的性质先将式子两边同时乘以-2,再将等式两边同时加上5,等式仍成立,所以本选项正确,②由a =b ,得ac =bc ,根据等式的性质,等式两边同时乘以相同的式子,等式仍成立,所以本选项正确,③由a =b ,得a b c c =,根据等式的性质,等式两边同时除以一个不为0的数或式子,等式仍成立,因为c 可能为0,所以本选项不正确,④由23a b c c=,得3a =2b , 根据等式的性质,等式两边同时乘以相同的式子6c,等式仍成立,所以本选项正确, ⑤因为互为相反数的平方也相等,由a 2=b 2,得a =b,或a =-b ,所以本选项错误,故答案为: ①②④.16、84.2【解题分析】小青该学期的总评成绩为:86×10%+90×30%+81×60%=84.2(分),故答案为: 84.2.三、解答题(共8题,共72分)17、 (1)详见解析;(2)4.【解题分析】试题分析:(1)连结OD ,由AD 平分∠BAC,OA=OD ,可证得∠ODA=∠DAE,由平行线的性质可得OD ∥AE,再由DE ⊥AC 即可得OE ⊥DE ,即DE 是⊙O 的切线;(2)过点O 作OF ⊥AC 于点F ,由垂径定理可得AF=CF=3,再由勾股定理求得OF=4,再判定四边形OFED 是矩形,即可得DE=OF=4.试题解析:(1)连结OD ,∵AD 平分∠BAC,∴∠DAE=∠DAB ,∵OA=OD ,∴∠ODA=∠DAO,∴∠ODA=∠DAE,∴OD ∥AE,∵DE ⊥AC∴OE ⊥DE∴DE 是⊙O 的切线;(2)过点O 作OF ⊥AC 于点F ,∴AF=CF=3,∴OF=, ∵∠OFE=∠DEF=∠ODE=90°,∴四边形OFED 是矩形,∴DE=OF=4.考点:切线的判定;垂径定理;勾股定理;矩形的判定及性质.18、方程的根120=2x x =-或【解题分析】(1)根据方程的系数结合根的判别式,即可得出关于k 的一元一次不等式,解之即可得出k 的取值范围; (1)取k=0,再利用分解因式法解一元二次方程,即可求出方程的根.【题目详解】(1)∵关于x 的一元二次方程x 1﹣1(k ﹣a )x+k (k+1)=0有两个不相等的实数根,∴△=[﹣1(k ﹣1)]1﹣4k (k ﹣1)=﹣16k+4>0,解得:k <14. (1)当k=0时,原方程为x 1+1x=x (x+1)=0,解得:x 1=0,x 1=﹣1.∴当k=0时,方程的根为0和﹣1.【题目点拨】本题考查了根的判别式以及因式分解法解一元二次方程,解题的关键是:(1)牢记“当△>0时,方程有两个不相等的实数根”;(1)取k=0,再利用分解因式法解方程.19、(1)斜坡CD 的高度DE 是5米;(2)大楼AB 的高度是34米.【解题分析】试题分析:(1)根据在大楼AB 的正前方有一斜坡CD ,CD=13米,坡度为1:125,高为DE ,可以求得DE 的高度; (2)根据锐角三角函数和题目中的数据可以求得大楼AB 的高度.试题解析:(1)∵在大楼AB 的正前方有一斜坡CD ,CD=13米,坡度为1:125, ∴1512125DE EC ==,设DE=5x 米,则EC=12x 米,∴(5x )2+(12x )2=132,解得:x=1,∴5x=5,12x=12,即DE=5米,EC=12米,故斜坡CD 的高度DE 是5米;(2)过点D 作AB 的垂线,垂足为H ,设DH 的长为x ,由题意可知∠BDH=45°,∴BH=DH=x ,DE=5,在直角三角形CDE 中,根据勾股定理可求CE=12,AB=x+5,AC=x-12,∵tan64°=AB AC , ∴2=AB AC, 解得,x=29,AB=x+5=34,即大楼AB 的高度是34米.20、(1)△ABC 是“等高底”三角形;(1)132;(3)CD 的值为2103,12,1. 【解题分析】(1)过A 作AD ⊥BC 于D ,则△ADC 是直角三角形,∠ADC =90°,根据30°所对的直角边等于斜边的一半可得:132AD AC ==,根据“等高底”三角形的概念即可判断. (1)点B 是'AA C 的重心,得到2BC BD =,设BD x =,则23AD BC x CD x ===,, 根据勾股定理可得13AC x =,即可求出它们的比值.(3)分两种情况进行讨论:①当2AB BC =时和②当2AC BC =时.【题目详解】(1)△ABC 是“等高底”三角形;理由:如图1,过A 作AD ⊥BC 于D ,则△ADC 是直角三角形,∠ADC =90°,∵∠ACB =30°,AC=6,∴132AD AC ==, ∴AD =BC =3,即△ABC 是“等高底”三角形;(1)如图1,∵△ABC 是“等高底”三角形,BC 是“等底”,∴AD BC =,∵△ABC 关于BC 所在直线的对称图形是'A BC ,∴∠ADC =90°,∵点B 是'AA C 的重心,∴2BC BD =,设BD x =,则23AD BC x CD x ===,, 由勾股定理得13AC x =,∴1313.22AC x BC x == (3)①当2AB BC =时,Ⅰ.如图3,作AE ⊥BC 于E ,DF ⊥AC 于F ,∵“等高底”△ABC 的“等底”为BC ,l 1∥l 1,l 1与l 1之间的距离为1,2AB BC =.∴222BC AE AB ,,===∴BE =1,即EC =4,∴25AC ,=∵△ABC 绕点C 按顺时针方向旋转45°得到△A'B'C ,∴∠DCF =45°,设DF CF x ==,∵l 1∥l 1,∴ACE DAF ∠=∠, ∴1,2DF AE AF CE == 即2AF x =, ∴325AC x ==,∴225,210,33x CD x === Ⅱ.如图4,此时△ABC 等腰直角三角形,∵△ABC 绕点C 按顺时针方向旋转45°得到''A B C ,∴ACD 是等腰直角三角形,∴222CD AC ==. ②当2AC BC =时,Ⅰ.如图5,此时△ABC 是等腰直角三角形,∵△ABC 绕点C 按顺时针方向旋转45°得到△A'B'C ,∴1'A C l ⊥,∴2CD AB BC ===;Ⅱ.如图6,作AE BC ⊥于E ,则AE BC =,∴22AC BC AE ==,∴45ACE ∠=︒,∴△ABC 绕点C 按顺时针方向旋转45°,得到''A B C 时,点A '在直线l 1上,∴'A C ∥l 1,即直线'A C 与l 1无交点,综上所述,CD 210,22,2.3【题目点拨】属于新定义问题,考查对与等底高三角形概念的理解,勾股定理,等腰直角三角形的性质等,掌握等底高三角形的性质是解题的关键.21、证明见解析.【解题分析】根据在同圆中等弦对的弧相等,AB 、CD 是⊙O 的直径,则CFD AEB =,由FD=EB ,得,FD EB =,由等量减去等量仍是等量得:CFD FD AEB EB -=-,即FC AE =,由等弧对的圆周角相等,得∠D=∠B .【题目详解】解:方法(一)证明:∵AB 、CD 是⊙O 的直径,∴CFD AEB =.∵FD=EB ,∴FD EB =.∴CFD FD AEB EB -=-.即FC AE =.∴∠D=∠B .方法(二)证明:如图,连接CF ,AE .∵AB 、CD 是⊙O 的直径,∴∠F=∠E=90°(直径所对的圆周角是直角).∵AB=CD,DF=BE,∴Rt△DFC≌Rt△BEA(HL).∴∠D=∠B.【题目点拨】本题利用了在同圆中等弦对的弧相等,等弧对的弦,圆周角相等,等量减去等量仍是等量求解.22、解:作AB的垂直平分线,以点C为圆心,以AB的一半为半径画弧交AB的垂直平分线于点M即可.【解题分析】易得M在AB的垂直平分线上,且到C的距离等于AB的一半.23、(1)见解析13【解题分析】(1)四边形ABCD是平行四边形,由平行四边形的性质,可得AB=DE,AB//DE ,则四边形ABDE是平行四边形;(2)因为AD=DE=1,则AD=AB=1,四边形ABCD是菱形,由菱形的性质及解直角三角形可得AO=AB⋅sin∠ABO=2,BO=AB⋅cos∠3,3,则AE=BD,利用勾股定理可得OE.【题目详解】(1)证明:∵四边形ABCD是平行四边形,∴AB∥CD,AB=CD.∵DE=CD,∴AB=DE.∴四边形ABDE是平行四边形;(2)∵AD =DE =1,∴AD =AB =1.∴▱ABCD 是菱形,∴AB =BC ,AC ⊥BD ,12BO BD =,12ABO ABC ∠=∠. 又∵∠ABC =60°,∴∠ABO =30°.在Rt △ABO 中,sin 2AO AB ABO =⋅∠=,cos BO AB ABO =⋅∠=∴BD =∵四边形ABDE 是平行四边形,∴AE ∥BD ,AE BD ==.又∵AC ⊥BD ,∴AC ⊥AE .在Rt △AOE 中,OE == 【题目点拨】此题考查平行四边形的性质及判断,考查菱形的判断及性质,及解直角三角形,解题关键在于掌握判定定理和利用三角函数进行计算.24、(1)A (﹣1,0),B (3,0),y=x ;(2)①A′(32t ﹣1t );②A′BEF 为菱形,见解析;(3)存在,P 点坐标为(53)或(73. 【解题分析】(1)通过解方程﹣3x 20得A (−1,0),B (3,0),然后利用待定系数法确定直线l 的解析式;(2)①作A′H ⊥x 轴于H ,如图2,利用OA =1,OD 得到∠OAD =60°,再利用平移和对称的性质得到EA =EA′=t ,∠A′EF =∠AEF =60°,然后根据含30度的直角三角形三边的关系表示出A′H ,EH 即可得到A′的坐标;②把A′(32t−1,2t )代入y =−3x 2+3x 得−3(32t−1)2+3(32t−12t ,解方程得到t =2,此时A′点的坐标为(2,3),E (1,0),然后通过计算得到AF =BE =2,A′F ∥BE ,从而判断四边形A′BEF为平行四边形,然后加上EF =BE 可判定四边形A′BEF 为菱形;(3)讨论:当A′B ⊥BE 时,四边形A′BEP 为矩形,利用点A′和点B 的横坐标相同得到32t−1=3,解方程求出t 得到A′(3,433),再利用矩形的性质可写出对应的P 点坐标;当A′B ⊥EA′,如图4,四边形A′BPE 为矩形,作A′Q ⊥x 轴于Q ,先确定此时A′点的坐标,然后利用点的平移确定对应P 点坐标.【题目详解】 (1)当y=0时,﹣33x 2+233x+3=0,解得x 1=﹣1,x 2=3,则A (﹣1,0),B (3,0), 设直线l 的解析式为y=kx+b ,把A (﹣1,0),D (0,﹣3)代入得0{3k b b -+==-,解得3{3k b =-=-, ∴直线l 的解析式为y=﹣3x ﹣3;(2)①作A′H ⊥x 轴于H ,如图,∵OA=1,3,∴∠OAD=60°,∵EF ∥AD ,∴∠AEF=60°,∵点A 关于直线l 的对称点为A′,∴EA=EA′=t ,∠A′EF=∠AEF=60°,在Rt △A′EH 中,EH=12EA′=12t ,33, ∴OH=OE+EH=t ﹣1+12t=32t ﹣1,∴A′(32t﹣1,32t);②把A′(32t﹣1,32t)代入y=﹣33x2+233x+3得﹣33(32t﹣1)2+233(32t﹣1)+3=32t,解得t1=0(舍去),t2=2,∴当点A′落在抛物线上时,直线l的运动时间t的值为2;此时四边形A′BEF为菱形,理由如下:当t=2时,A′点的坐标为(2,3),E(1,0),∵∠OEF=60°∴OF=3OE=3,EF=2OE=2,∴F(0,3),∴A′F∥x轴,∵A′F=BE=2,A′F∥BE,∴四边形A′BEF为平行四边形,而EF=BE=2,∴四边形A′BEF为菱形;(3)存在,如图:当A′B⊥BE时,四边形A′BEP为矩形,则32t﹣1=3,解得t=83,则A′(343),∵OE=t﹣1=53,∴此时P点坐标为(5343;当A′B⊥EA′,如图,四边形A′BPE为矩形,作A′Q⊥x轴于Q,∵∠AEA′=120°,∴∠A′EB=60°,∴∠EBA′=30°∴33332t,∴32t﹣1+32t=3,解得t=43,此时A′(123,E(13,0),点A′向左平移23个单位,向下平移33个单位得到点E,则点B(3,0)向左平移23个单位,向下平移33个单位得到点P,则P(73,﹣33),综上所述,满足条件的P点坐标为(5343)或(7323.【题目点拨】本题考查了二次函数的综合题:熟练掌握二次函数图象上点的坐标特征、二次函数的性质、菱形的判定和矩形的性质;会利用待定系数法求函数解析式;理解坐标与图形性质.。
重庆八中学、九十五中学等校2024学年中考英语模拟精编试卷含答案
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重庆八中学、九十五中学等校2024学年中考英语模拟精编试卷含答案注意事项:1.答卷前,考生务必将自己的姓名、准考证号填写在答题卡上。
2.回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦干净后,再选涂其它答案标号。
回答非选择题时,将答案写在答题卡上,写在本试卷上无效。
3.考试结束后,将本试卷和答题卡一并交回。
Ⅰ. 单项选择1、—I had a really nice weekend on the beach. — _______.A.Oh, tha t’s very nice of you B.CongratulationsC.It’s a pleasure D.I’m glad to hear that2、As President Xi Jinping tells us, happiness through hard work.A.achieve B.is achieved C.has achieved3、—I think this skirt is very nice.—I agree. But it’s 500 yuan. I don’t think I can it.A.afford B.find C.put D.see4、---What’s your hobby ? ---______collecting balls, I also like different kinds of CDs.A.Besides B.Except C.Beside D.About5、More and more people ______ the importance of the eco-friendly lifestyle.A.miss B.promise C.realize D.suggest6、You should study hard. No one can _______ you ________a good future.A.provide, for B.provide, withC.keep, / D.protect, to have7、-- Could you please tell me _ _ ? -- Certainly.A.what should I do to improve my English B.how can I get to the reading roomC.what she is looking for D.when shall we have a parents' meeting8、—Hi, Bob! I can’t find my story book. Have you seen it?—Sorry, I haven’t. Why not ask Jim? Perhaps he’s seen it _____.A.anywhere B.everywhere C.nowhere D.somewhere9、My uncle regretted his house in Shanghai last year, because the house price keeps rising.A.sell B.to sell C.selling D.sold10、—Hi, Cathy! I saw Miss Zhang in the meeting room just now.―No, it ______ be her. She went to Nanjing two days ago.A.must B.may C.can’t D.needn’tⅡ. 完形填空11、My friend Alan did not have a rich family. He did not have much money. Sometimes Alan 1 had to accept money and gifts from his family and friends. But do not get me 2 . He was not thekind of person who never3 the money he should. He was always very4 with the money he spent.However ,a few years ago, he won the lottery and got a huge 5 of money. He was veryexcited. It changed his life. The 6 thing he did was to buy a very expensive new car. Then he 7 spending money on unnecessary things or the things that he normally would not buy. It seemedthat he had money to 8 . He had more money than he needed and it was burning a hole in his pocket. He wasted his money 9When we got together for a 10 at a restaurant, he would always pay the bill. He 11 me the money made him feel very happy.But, Alan soon 12 out all of his money. He was as poor as a church mouse again. His last dollarwas spent and he had no money 13 .I admit I do feel 14 for my friend. He had enough money to live like a king. 15 , heis back to living a hard life. He was wise about small things, but not about important things.1.A.only B.just C.even D.either2.A.guilty B.wrong C.confident D.surprised3.A.took B.had C.brought D.paid4.A.nervous B.careful C.anxious D.excited5.A.pocket B.envelope C.amount D.purse6.A.final B.perfect C.recent D.first7.A.pretended B.suggested C.started D.practiced8.A.risk B.show C.burn D.play9.A.quietly B.secretly C.quickly D.possibly10.A.journey B.meal C.rest D.meeting11.A.interviewed B.taught C.treated D.told12.A.ran B.came C.went D.walked13.A.remained B.stayed C.left D.reached14.A.educational B.sorry C.embarrassed D.realistic15.A.Exactly B.Easily C.Instead D.ReallyⅢ. 语法填空12、动词应用1.(grow)up is not always easy.When we face difficulties,a spirit of depending on yourself is more useful than 2.(cry)for help.That’s what Hong Zhanhui’s story of growing from boy to man with family hardship 3.(tell) us.Hong 4.(bear) in 1982 in a poor family in Xihua County(县),Henan Province.When he was only 11,his father5.(become) badly ill and one day he came back with an unwanted baby girl.A year later,Hong’s mother left home.She no longer wanted 6.(live) such a poor life and face her sick husband.So everything hard fell onto the young boy’s shoulders:to take care of his father and the sister Chenchen,and to go on to study.Although his life was hard,Hong 7.(never go) away from his father and sister.He worked in part—time jobs to feed his family.He climbed tall trees to get birds’ eggs for his sister.He walked two hours at weekends to the market to buy different things to sell around his school.He said that he 8.(make) a good life in the future. A few years later,he studied at a college.To take care of Chenchen,he had worked hard to rent(租)a room near his college for several years.After Hong’s story went public,he became a hero in people’s eyes.But Hong refused offers from others.He said he 9.(feel) encouraged by kind offers,but he could depend on his own work.Through his hard life,he 10.(grow) up from boy to man.Ⅳ. 阅读理解A13、Students have to take tests. Sometimes, robots do too. Torobo from Japan is one of these robots. Torobo is a robot brain with two arms. It is part of a project called “Can a Robot Get into the University of Tokyo?” A group of Japanese scientists started it in 2011.To go to the University of Tokyo, Torobo has to take Japan’s national college entrance exam. So in 2013, the robot started to take the test with Japanese students.Sadly, Torobo has failed the test every year. It couldn’t get a good enough score for the University of Tokyo. This year it was the same.Torobo has a big database (数据库). So it is good at knowledge and calculations (计算). That’s why it got high scores in physics, history and math.But Torobo is not good at thinking by itself. So it got poor scores in language and writing.Scientists started the Torobo project to learn about the intellectual abilities (智能) of machines.Now after Torobo’s four years of hard work, they may have learned a lot.1.According to the passage, Torobo is __________.A.a student B.a robot C.a scientist D.a project2.Why did Torobo get poor scores in language and writing?A.It only has a robot brain.B.It failed the test many times.C.It is good at knowledge and calculations.D.It is not good at thinking by itself.3.Which of the following is not TRUE?A.Torobo is a robot brain with two arms.B.Torobo is better at writing than at physics.C.Torobo is better at math than at writing.D.Scientists may be studying the intellectual abilities.4.The passage comes from_______.A.a newspaper B.a film C.an advertisement D.a novelB14、Think of life as a game in which you are playing with five balls in the air. You name them work, family, health, friends and spirit (精神) and you keep all of them in the air. Y ou will soon understand that work is a rubber ball. If you drop it, it will bounce (弹跳) back.But the other four balls, family, health, friends and spirit, are made of glass. If you drop one of these, they will be broken. They will never be the same. You must understand that and try to have balance in your life. How?Don’t loo k down on your worth by comparing yourself with others. It is because we are different and each of us is special.Don’t let other people set goals for you. Only you know what is best for yourself.Don’t give up when you still have something to give.____________________________.Don’t be afraid of difficulties. It is by taking chances that we learn how to be brave.Don’t shut love out of your life by saying it’s impossible. The quickest way to receive love is to give it; the fastest way t o lose love is to hold it too tightly (紧紧地); the best way to keep love is to give it wings.Don’t run through life so fast that you forget not only where you’ve been, but also where you are going.Don’t be afraid to learn. Knowledge is a treasure (珍宝) you can always carry easily.Don’t use time or words carelessly. You can’t get them back. Yesterday is history, tomorrow is a mystery (秘密), and today is a gift; that’s why we call it “the present”. Life is not a competition, but a trip, step by step.1.The passage tells us not to _________ because everyone is special.A.be afraid of difficulties B.be afraid to learnC.run through life so fast D.compare yourself with others to look down on your worth2.The sentence “Nothing is really over until the moment you stop trying.” me ans that .A.Nothing is possible B.If we don’t give up, there is always hopeC.Y ou should learn to give up D.Although you try, nothing will change.3.Why can’t we use time carelessly? ___________A.Because time is too expensive. B.Because time never returns.C.Because we are too poor. D.Because times will get back. 4.If you run through life so fast, you will ____________.A.lose your own treasure that you can always carry easily B.lose love by holding it too tightlyC.forget not only where you’v e been, but also where you are going. D.not afraid of the difficulties5.According to the passage, which is the best title? ___________ A.Nothing is impossible. B.Glass balls are easy to be broken. C.Things you can’t do. D.Treat your life in a right way.C15、据材料内容选择最佳答案,将其标号填入题前括号内。
重庆八中2024届中考物理模拟精编试卷含解析
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重庆八中2024届中考物理模拟精编试卷注意事项:1.答卷前,考生务必将自己的姓名、准考证号填写在答题卡上。
2.回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦干净后,再选涂其它答案标号。
回答非选择题时,将答案写在答题卡上,写在本试卷上无效。
3.考试结束后,将本试卷和答题卡一并交回。
一、单选题(本大题共10小题,共30分)1.国外科研人员设计了一种“能量采集船”,如图所示.在船的两侧附着可触及水面的旋转“工作臂”,每只“工作臂”的底端装有一只手掌状的、紧贴水面的浮标.当波浪引起浮标上下浮动时,工作臂就前后移动,获得电能储存起来.下列电器设备与“能量采集船”获得能量原理相同的是A.B.C.D.2.如图1所示,为医用氧气瓶.若以○表示氧气分子,用图2的方式代表容器内氧气的分布情况.病人吸完氧气并将其静置一段时间后(瓶内仍有剩余氧气),瓶内氧气分子分布为A.B.C.D.3.下列数值最接近实际情况的是A.物理课本中一张纸的厚度约为8mmB.一个鸡蛋的质量约为600mgC.一瓶500ml的饮料的质量约为0.5kgD.一座6层教学楼的高度约为18dm4.汽车匀速直线上坡的过程中,各物理量随时间变化关系正确的是()A.B.C.D.5.下列有关压强知识说法正确的是()A.在流体中,流速越大的位置,压强越小B.随着大气压的减小,水的沸点会升高C.利用马德堡半球实验可以精确测出大气压的值D.载重货车的车轮越多,对地面的压强越大6.如图所示的四种现象中,能用光的直线传播解释的是A.手影游戏B.天空彩虹C.“断笔”现象D.光纤传输信号7.对物理量的估测,是一种良好的学习习惯,也是学好物理的基本功之一.下列估测的数据中最接近事实的是A.洗澡水的适宜温度约为80℃B.教室中日光灯的功率约为400WC.人体平均密度约为1g/cm3D.中学生正常步行的速度约为1.4km/h8.如图,水平地面ABOCD,以O点为界,AO段是一种材质,OD段是另一种材质.细线一端系在物体上,绕过轻质滑轮,另一端系在墙上,拉滑轮的水平力F恒为4N,物体经A点开始计时,此后各段路程及耗时见下表.以下说法正确的是()区间AB BO OC CD距离1m 1m 1.5m 2.5m耗时1s 1s 1s 1sA.物体在CD区间运动的平均速度为2m/sB.物体在BO区间运动时物体受到水平向左4N縻擦力C.物体在OC区间运动过程中,拉力F做的功为3JD.物体在BO区间运动过程中,拉力F做功的功率为1W9.关于电与磁的材料,下列说法中正确的是()A.地磁场的磁感线是从地球南极附近发出回到北极附近B.导体在磁场中运动就一定会产生感应电流C.在真空中,无线电波的传播速度小于光的传播速度D.集成电路中的三极管是利用超导体材料制成的10.热敏电阻的阻值是随环境温度的增大而减小的.要想设计一个通过电表示数反映热敏电阻随环境温度变化的电路,要求温度升高时电表示数减小,以下电路符合要求的是()A.B.C.D.二、多选题(本大题共3小题,共12分)11.水平桌面上放有质量和底面积相同的两个容器甲和乙,用它们分别装有体积不相同的a、b两种不同的液体,把两个质量相同的物体M、N分别放入甲、乙容器中静止时的情况液体深度相同,两容器对水平桌面压强相等.下列说法正确的是:A.物体M的密度大于物体N的密度B.物体M下表面受到的压力大于物体N下表面受到的压力C.物体M浸入液体中的体积大于物体N浸入液体中的体积D.甲容器底受到的压强大于乙容器底受到的压强12.如图所示,工人用150N的拉力通过滑轮组吊起质量为20kg的箱子.若箱子被匀速竖直提升了2m,不计绳重和摩擦,取g=10N/kg,则A.箱子的重力势能增大B.动滑轮的重力为100NC.工人施加的拉力做的功为300JD.滑轮组的机械效率为86.7%13.临近中考小兰妈妈用家里的压力锅煲鸡汤来为她加强营养,当她看到色香味俱佳的鸡汤时,联想到了许多物理知识,下列说法正确的是A.鸡汤香气四溢是扩散现象,说明分子在不停地做无规则运动B.鸡汤沸腾过程中吸收热量,温度不变,內能不变C.煲汤过程中,压力锅内的气压大于标准大气压D.煲汤过程中,限压阀转动,此过程中的能量转化与内燃机的做功冲程相似三、填空题(本大题共5小题,共10分)14.小明用一个空矿泉水瓶将鸡蛋的清和黄分开,他拧开瓶盖轻捏瓶子,瓶子变瘪,说明力可以改变物体的_____。
重庆八中重点达标名校2024届中考数学猜题卷含解析
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重庆八中重点达标名校2024届中考数学猜题卷考生须知:1.全卷分选择题和非选择题两部分,全部在答题纸上作答。
选择题必须用2B铅笔填涂;非选择题的答案必须用黑色字迹的钢笔或答字笔写在“答题纸”相应位置上。
2.请用黑色字迹的钢笔或答字笔在“答题纸”上先填写姓名和准考证号。
3.保持卡面清洁,不要折叠,不要弄破、弄皱,在草稿纸、试题卷上答题无效。
一、选择题(本大题共12个小题,每小题4分,共48分.在每小题给出的四个选项中,只有一项是符合题目要求的.)1.正五边形绕着它的中心旋转后与它本身重合,最小的旋转角度数是()A.36°B.54°C.72°D.108°2.民族图案是数学文化中的一块瑰宝.下列图案中,既不是中心对称图形也不是轴对称图形的是()A.B.C.D.3.计算(﹣5)﹣(﹣3)的结果等于()A.﹣8 B.8 C.﹣2 D.24.如图显示了用计算机模拟随机投掷一枚图钉的某次实验的结果.下面有三个推断:①当投掷次数是500时,计算机记录“钉尖向上”的次数是308,所以“钉尖向上”的概率是0.616;②随着试验次数的增加,“钉尖向上”的频率总在0.618附近摆动,显示出一定的稳定性,可以估计“钉尖向上”的概率是0.618;③若再次用计算机模拟此实验,则当投掷次数为1000时,“钉尖向上”的频率一定是0.1.其中合理的是()A.①B.②C.①②D.①③5.如图,在Rt△ABC中,∠B=90º,AB=6,BC=8,点D在BC上,以AC为对角线的所有□ADCE中,DE的最小值是()A .4B .6C .8D .106.点P (﹣2,5)关于y 轴对称的点的坐标为( )A .(2,﹣5)B .(5,﹣2)C .(﹣2,﹣5)D .(2,5)7.如图,二次函数y=ax 2+bx+c (a≠0)的图象的顶点在第一象限,且过点(0,1)和(﹣1,0).下列结论:①ab <0,②b 2>4a ,③0<a+b+c <2,④0<b <1,⑤当x >﹣1时,y >0,其中正确结论的个数是A .5个B .4个C .3个D .2个8.如图是二次函数2y=ax +bx+c 的部分图象,由图象可知不等式2ax +bx+c<0的解集是( )A .1<x<5-B .x>5C .x<1-且x>5D .x <-1或x >59.关于x 的一元二次方程230x x m -+=有两个不相等的实数根,则实数m 的取值范围是( )A .94m <B .94mC .94m >D .94m 10.将抛物线向右平移1个单位长度,再向上平移1个单位长度所得的抛物线解析式为( ) A .B .C .D . 11.如图所示是由几个完全相同的小正方体组成的几何体的三视图.若小正方体的体积是1,则这个几何体的体积为( )A.2 B.3 C.4 D.512.已知点A为某封闭图形边界上一定点,动点P从点A出发,沿其边界顺时针匀速运动一周.设点P运动的时间为x,线段AP的长为y.表示y与x的函数关系的图象大致如右图所示,则该封闭图形可能是( )A.B.C.D.二、填空题:(本大题共6个小题,每小题4分,共24分.)13.分解因式:mx2﹣4m=_____.14.自2008年9月南水北调中线京石段应急供水工程通水以来,截至2018年5月8日5时52分,北京市累计接收河北四库来水和丹江口水库来水达50亿立方米.已知丹江口水库来水量比河北四库来水量的2倍多1.82亿立方米,求河北四库来水量.设河北四库来水量为x亿立方米,依题意,可列一元一次方程为_____.15.如图,“人字梯”放在水平的地面上,当梯子的一边与地面所夹的锐角α为60时,两梯角之间的距离BC的长为3m.周日亮亮帮助妈妈整理换季衣服,先使α为60,后又调整α为45,则梯子顶端离地面的高度AD下降了______m(结果保留根号).16.若函数y=mx2+2x+1的图象与x轴只有一个公共点,则常数m的值是.17.某种商品两次降价后,每件售价从原来元降到元,平均每次降价的百分率是__________.18.已知一组数据3,4,6,x,9的平均数是6,那么这组数据的方差等于________.三、解答题:(本大题共9个小题,共78分,解答应写出文字说明、证明过程或演算步骤.19.(6分)已知:如图,在△ABC中,AB=BC,∠ABC=90°,点D、E分别是边AB、BC的中点,点F、G是边AC的三等分点,DF 、EG 的延长线相交于点H ,连接HA 、HC .(1)求证:四边形FBGH 是菱形;(2)求证:四边形ABCH 是正方形.20.(6分)如图,在四边形ABCD 中,∠BAC=∠ACD=90°,∠B=∠D .(1)求证:四边形ABCD 是平行四边形;(2)若AB=3cm ,BC=5cm ,AE=13AB ,点P 从B 点出发,以1cm/s 的速度沿BC→CD→DA 运动至A 点停止,则从运动开始经过多少时间,△BEP 为等腰三角形.21.(6分)如图,一次函数y=kx+b 的图象与二次函数y=﹣x 2+c 的图象相交于A (﹣1,2),B (2,n )两点. (1)求一次函数和二次函数的解析式;(2)根据图象直接写出使二次函数的值大于一次函数的值的x 的取值范围;(3)设二次函数y=﹣x 2+c 的图象与y 轴相交于点C ,连接AC ,BC ,求△ABC 的面积.22.(8分)解方程组220y x x y =⎧⎨+-=⎩. 23.(8分)数学课上,李老师和同学们做一个游戏:他在三张硬纸片上分别写出一个代数式,背面分别标上序号①、②、③,摆成如图所示的一个等式,然后翻开纸片②是4x 1+5x +6,翻开纸片③是3x 1﹣x ﹣1.解答下列问题求纸片①上的代数式;若x是方程1x=﹣x﹣9的解,求纸片①上代数式的值.24.(10分)如图,在△ABC中,AB=AC,以AB为直径作⊙O交BC于点D,过点D作⊙O的切线DE交AC于点E,交AB延长线于点F.(1)求证:BD=CD;(2)求证:DC2=CE•AC;(3)当AC=5,BC=6时,求DF的长.25.(10分)在“植树节”期间,小王、小李两人想通过摸球的方式来决定谁去参加学校植树活动,规则如下:在两个盒子内分别装入标有数字1,2,3,4的四个和标有数字1,2,3的三个完全相同的小球,分别从两个盒子中各摸出一个球,如果所摸出的球上的数字之和小于5,那么小王去,否则就是小李去.用树状图或列表法求出小王去的概率;小李说:“这种规则不公平”,你认同他的说法吗?请说明理由.26.(12分)已知a2+2a=9,求22212321121a a aa a a a+++-÷+--+的值.27.(12分)如图所示,AB是⊙O的一条弦,OD⊥AB,垂足为C,交⊙O于点D,点E在⊙O上.若∠AOD=52°,求∠DEB的度数;若OC=3,OA=5,求AB的长.参考答案一、选择题(本大题共12个小题,每小题4分,共48分.在每小题给出的四个选项中,只有一项是符合题目要求的.)1、C【解题分析】正五边形绕着它的中心旋转后与它本身重合,最小的旋转角度数是3605=72度,故选C.2、C【解题分析】分析:根据轴对称图形与中心对称图形的概念,轴对称图形两部分沿对称轴折叠后可重合;中心对称图形是图形沿对称中心旋转180度后与原图重合.因此,A、不是轴对称图形,是中心对称图形,故本选项错误;B、是轴对称图形,也是中心对称图形,故本选项错误;C、不是轴对称图形,也不是中心对称图形,故本选项正确;D、是轴对称图形,也是中心对称图形,故本选项错误.故选C.3、C【解题分析】分析:减去一个数,等于加上这个数的相反数.依此计算即可求解.详解:(-5)-(-3)=-1.故选:C.点睛:考查了有理数的减法,方法指引:①在进行减法运算时,首先弄清减数的符号;②将有理数转化为加法时,要同时改变两个符号:一是运算符号(减号变加号);二是减数的性质符号(减数变相反数).4、B【解题分析】①当频数增大时,频率逐渐稳定的值即为概率,500次的实验次数偏低,而频率稳定在了0.618,错误;②由图可知频数稳定在了0.618,所以估计频率为0.618,正确;③.这个实验是一个随机试验,当投掷次数为1000时,钉尖向上”的概率不一定是0.1.错误,故选B.【题目点拨】本题考查了利用频率估计概率,能正确理解相关概念是解题的关键.5、B【解题分析】平行四边形ADCE的对角线的交点是AC的中点O,当OD⊥BC时,OD最小,即DE最小,根据三角形中位线定理即可求解.【题目详解】平行四边形ADCE 的对角线的交点是AC 的中点O ,当OD ⊥BC 时,OD 最小,即DE 最小。
重庆市渝北八中学2024学年中考语文考前最后一卷含解析
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重庆市渝北八中学2024学年中考语文考前最后一卷注意事项1.考试结束后,请将本试卷和答题卡一并交回.2.答题前,请务必将自己的姓名、准考证号用0.5毫米黑色墨水的签字笔填写在试卷及答题卡的规定位置.3.请认真核对监考员在答题卡上所粘贴的条形码上的姓名、准考证号与本人是否相符.4.作答选择题,必须用2B铅笔将答题卡上对应选项的方框涂满、涂黑;如需改动,请用橡皮擦干净后,再选涂其他答案.作答非选择题,必须用05毫米黑色墨水的签字笔在答题卡上的指定位置作答,在其他位置作答一律无效.5.如需作图,须用2B铅笔绘、写清楚,线条、符号等须加黑、加粗.一、积累1.下列句子没有语病的一项是()A.创新是互联网发展的基因,我们要坚持把创新摆在首要位置,牢牢掌握网信事业发展。
B.理论再好,只有被我们掌握、接受和理解,才能成为自觉遵守和奉行的准则。
C.初中生可能对传统文化如“四书五经”比较陌生,但语文老师对这些却是熟悉的。
D.在践行“尊老爱幼”传统美德活动中,我们所缺乏的,一是执行力不足,二是方法不当。
2.下列诗句与“三军可夺帅也,匹夫不可夺志也”倡导的理想人格不相符的一项是()A.刑天舞干戚,猛志固常在。
B.零落成泥碾作尘,只有香如故。
C.不畏浮云遮望眼,自缘身在最高层。
D.人生自古谁无死,留取丹心照汗青。
3.下列说法不完全正确的一项是A.《登飞来峰》《登勃朗峰》的作者分别是北宋政治家、文学家、思想家王安石,美国作家马克·吐温。
B.电视剧《露从今夜白》的取名与《月夜忆舍弟》有关,关雎宫的取名与《诗经》有关,古曲《后庭花》的取名与《泊秦淮》有关。
C.现代诗《天上的街市》、历史剧《屈原》都是郭沫若的作品,小说《社戏》、驳论文《中国人失掉自信力了吗》都是鲁迅的作品。
D.《行路难(其一)》借用姜尚闲来垂钓碧溪后被周文王启用的典故,表达诗人希望得到朝廷任用的思想。
《变色龙》运用对比、夸张,塑造了一个专横跋扈、欺下媚上、看风使舵的沙皇专制制度走狗的典型形象。
2023年重庆市沙坪坝区重庆八中中考强化训练化学试题二(含答案解析)
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2023年重庆市沙坪坝区重庆八中中考强化训练化学试题二学校:___________姓名:___________班级:___________考号:___________一、单选题1.重庆拥有众多非物质文化遗产项目,下列制作过程涉及化学变化的是A.三峡皮影B.渝中木偶C.荣昌烧陶D.江北蜀绣2.重庆解放碑的“八一好吃街”吸引着各地的吃货们,下列美食中富含糖类的是A.涪陵榨菜B.黔江鸡杂C.邮亭鲫鱼D.重庆小面3.生态兴则文明兴,人与自然共命运,下列做法与该理念不符合的是A.生活垃圾分类处理B.废旧电池就地掩埋C.使用可降解塑料袋D.工业废水达标排放4.二十四节气中的谷雨是秧苗初插的时节。
若发现秧苗发黄,可施用的化肥是A.磷矿粉B.草木灰C.尿素D.氯化钾5.分类是化学学习和研究的重要方法,下列分类正确的是A.冰、干冰、过氧化氢属于氧化物B.电木、合金、玻璃钢属于合成材料C.熟石灰、浓硫酸、烧碱属于干燥剂D.苛性钠、消石灰、纯碱属于碱6.我国科学家开发了一种基于二氧化钒的“冷热双吸”材料,有望助力实现“双碳”目标,钒元素在周期表中的信息如图所示,下列说法错误的是A.钒为金属元素B.钒离子核外电子数为23C.钒的相对原子质量为50.94D.钒原子的中子数为287.“依山傍水”、“显山露水”是重庆的独有魅力,下列关于水的说法正确的是A.长江水一定是软水B.可用煮沸的方法淡化海水C.用pH试纸测得雨水pH=4.9,则该雨水为酸雨D.电解水实验中用燃着的木条检验负极产物8.中华文化源远流长、博大精深。
从化学的视角看,下列理解不正确的是A .“千淘万漉虽辛苦,吹尽狂沙始到金”,金不活泼,在自然界以单质形式存在B .“高奴县有洧水(即石油)可燃”,“洧水”属于可再生能源C .“锤锻成钢”,意为生铁经不断高温锻打成钢,降低了含碳量D .“釜底抽薪”,蕴含的灭火的原理是清除可燃物9.化学也可以萌萌哒,“小狗烯”(C 26H 26)、“企鹅酮”(C 10H 14O)分别因分子结构类似狗和企鹅而得名(如图)。
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中考测试(八中)II.单项选择(20分)21.English is ________useful language and it is widely used in the word.A. aB. anC. theD. /22 . — Do you know the funny man Yue Yunpeng?— Yes. He was born _______April 15th,1985 and he first put on a performance at 25.A. inB. onC. duringD.at23 . — You don’t look well. What’s wrong?— I think I have a fever. I want to go to the_____________.A.schoolB. bookstoreC. hospitalD. Cinema24.Be careful with the knife. You may cut ____________.A.youB. yourC. yoursD. yourself25.Tom is a good boy. He helps his mom ____________housework every day.A. doB. doingC. doesD. did26 — I haven’t seen you for a long time.— Oh, I___________ to Chongqing three days ago.A. have returnedB. returnC. will returnD. returned27 — Have you ________ the TV show The Descendants of the Sun?— Yes, I watch it with my daughter every evening.A. heard fromB. heard ofC. put onD. put off28 — Bob, would you mind taking out the rubbish?— ____________, I’ll do it right away.A. Not at allB. All rightC. Sorry, I can’tD. Yes, please29. Sam worked out the problem in only three minutes. It’s not as ______ as he thought.A. easyB. easierC. hardD. harder30 _____________ she didn’t say anything to me, I was sure she had seen me.A. BecauseB. ThoughC. UnlessD. Until31 — Chongqing has developed a lot in the last few years.— Yes. And a new amusement park ___________ here in 2017.A. is builtB. buildsC. will buildD. will be built32 — Can I speak to Mr. Brown?— ___________. He’s in the kitchen and I’ll call him right away.A. Hold on, pleaseB. I’m afraid notC. I hope soD. I’m sorry33 ______________lovely girl she is! We all love her.A. What aB. WhatC. How aD. How34 Driving was so difficult for me that I ________ knew where to put my feet the first time I gotinto the car.A. usuallyB. alwaysC. everD. hardly35 — Do you have any idea __________ ?— Yes, on the second floor.A. where is the movieB. where the movie theater isC. when is movie B. when the movie is36 ____________ her dream come true, Alice studies harder than any of her classmates.A. MakingB. To makeC. MakeD. Made37 — Must I look up each new word while reading?— No, you __________. You should try to guess its meaning.A. can’tB. mustn’tC. needn’tD. may not38 — Do you and your sister like comedies, Linda?— Yes. _________ of us think they are interesting.A. BothB. AllC. NeitherD. Either39 — ____________ do you have exams at your school?— Once a month.A. How oftenB. How longC. How soonD. How many40 — It’s raining hard outside. Could I use your umbrella, Linda?— Sorry. I ______ it at home this morning.A. forgetB. leftC. leaveD. forgotⅢ. 完形填空(每小题1.5分,共15分)In modern society we can see competitions(竞争) everywhere, both in our work and in our life. Team spirit(团队精神) is so important and helpful. It can lead us to 41 in the competitions.Team spirit means that people work together and help 42 as part of a team. With this spirit, people try hard to make their team the 43 of all.Everyone has experienced(经历) team spirit one way or another, whether they were part of a team or saw a group of people 44 for their favorite player.There are different kinds of team spirit. One kind is between a team of people whose efforts and teamwork are needed in reaching 45 goal. Another kind is when a group of people support a person, a team or even their country.Team spirit brings good effects. It helps to builds up 46 and trust(信任) between people who may not get on well when they don’t have such team spirit 47 , team spirit may also cause bad effects. For example, too great team spirit may cause fights or arguments with other team members.Some people don’t understand team spirit 48 . They think team spirit means having to become a member of a team or a fan club. In fact, team spirit can be built anywhere—between friends, workmates or even between, two people who have never 49 before. You don’t have to wear the same team spirit clothes. Anyone can show team spirit just 50 showing support for the same goal.( )41. A.dream B.surprise C.success D.end( )42. A.each other B.other C.another D.the other ( )43. A.fastest B.earliest C.biggest D.best( )44. A.call B.cheer C. to cheer D.to call ( )45. A.their B.his C.my D.our( )46. A.luck B.friendship C.health D.help( )47. A.But B.Although C.However D.So( )48. A.easily B.quickly C.simply D.properly ( )49. A.written B.heard C.met D.seen( )50. A.by B.through C.in D.withIV 阅读理解(每小题2分,共30分)AAre you a fan of traveling? Well, soon there will be a new place for you to take your vacation—the moon. Last month, the European Space Agency (ESA) said they would build an international moon base—the Moon Village. The purpose of building the village is to open the door for deeper space research. And it will also be a tourist center. According to the head of the ESA, Johann-Dietrich Woemer, it will only take about 20 years to finish it.However ,there are still some challenges, and the biggest one is how to get the building material into space without costing too much. Scientists suggest using the ice water and other things on the moon to print 3-D building materials, so people don’t have to carry everything from the earth.The ESA chose to build the base on the moon instead of the Mars because the moon is about 144 times closer than the Mars.The ESA has invited the US,Russia,China,India,Japan and some other countries to join in the moon plan.It hopes that in the future the moon will become a place where all the countries of the world can work together.51.The ESA will build an international base on__________.A.the moonB.the earthC.the MarsD.the sun52.The ESA plan to build the village__________.A.to open the door for deeper space researchB.to make all the countries work togetherC.to make money by building it as a tourist centerD.to get a new place to live in53.The biggest problem in building the base is ________.A.how to use 3-D printersB.where to build itC.how to get enough moneyD.how to get the building materials into space withoutcosting too muchBStudents from different schools are talking about strange rules in their schools.Zhao Jiacheng,13,from Xi’an: Students are not allowed to bring any balls to school. Our teachers think they will distract(使...分心) us from our studies. As a result, half of the students don’t have balls to play with during the PE class. Many people are disappointed about it. Another strange rule is that girls must have short hair.They think it will make them look unified (统一的).What a strange rule !Cui Anqi,15,from Guangdong: At my school,there is a strange rule for Class 5,Junior 2.Boys and girls must stay at least one meter away from one another.The teacher in their class says that this rule will help build pure friendships between boys and girls.Students don’t like it at all.I don’t think it’s reasonable. I’m sure that there are pure friendships between boys and girls.The rule is unnecessary.Wang Ying, 13, from Shanghai: At my school,we aren’t allowed to bring snacks and drinks into teaching buildings.I once bought a fried drumstick( 鸡腿) and a drink during break time.But I didn’t eat them by the time the break was over.So I put them alongside a garden. However,when I went to find them after class,there many ants on them.I don’t like the rule.Zhang Xueling,15,from Jiangsu: This term,we got vending machines(自动贩卖机) around our teaching buildings and dormitories. We were all excited and couldn’t wait to buy snacks from them.However,our school doesn’t let us use them.And they don’t give us a reason.We don’tunderstand why.Xiao Li,16,from Beijing: Many girls like to use colorful hair ties.But our school doesn’t allow it. Girls can only use black hair ties.At the beginning,our teachers checked it every day. My classmates and I followed it.But as time went by,no one followed it anymore.54. How many students talk about strange rules in their schools?A. 5B. 4C. 3D. 255. Why aren’t students allowed to take any balls to school?A. Because it will make them look unified.B. Because the teachers think balls are bad for the students.C. Because the teachers think balls will distract the students from their studies.D. Because balls are too expensive.56. The underlined word pure in Paragraph 3 may mean ___________.A. 可爱的B. 有价值的C. 短暂的D.纯洁的57. Students aren’t allowed to _________ at Wang Ying’s school.A.have short hairB.bring snacks and drinks into teaching buildingse colorful hair tiesD.buy snacks from the vending machineCWhat can help parents understand their kids better? More than 8,000 US kids answered this question in an online survey by Time for Kids and Kids Health Org.Many US kids—two out of three—said they get along with their parents.But that doesn’t mean they never disagree. In fact, most kids reported arguing with their parents, at least sometimes.And two out five kids said arguments sometimes even includes shouting at each other.It’s certainly normal to disagree and argue,” says Lyness,an American child psychologist(心里学家). “But it’s also important to learn how to do so respectfully. Be patient. Don’t use a raised, angry voice.”And not surprisingly, three out of four kids said they had lied to their parents some times.Many said they lie so they would not get in trouble or make their parents disappointed. According to Lyness, lying isn’t just wrong. It can actually have had results. Telling the truth builds trust. Telling the truth,says Lyness,shows maturity(成熟).But older kids actually lie more often than younger ones. Kids aged 12 to 14 not only said they lie more,but they also reported having less fun,feeling less close and not getting along as well with their parents.According to Lyness, those feelings are quite common. As kids become more independent,they have more areas of disagreement with their parents.But it doesn’t have to be that way. “Kids and parents get along differently at each stage of the journey,” she says. “As kids grow and change,it is important for everybody to change.”58.________of the US kids get along with their parents.A.One out of twoB.Two out of threeC.Two out of fiveD.Three out of five59.Which of the following sentences is true according to the passage?A.Two out of the three the US kids never disagree with their parents.B.Older kids lie to their parents less often than younger ones.C.Lying is wrong and it can cause bad results.D.Kids aged 12 to 14 have less fun but they feel closer to their parents60.As kids grow and change,________should change.A.only parentsB.only kidsC.both kids and parentsD.neither kids nor parents61.The child psychologist Lyness may agree that__________.A.it’s not normal to disagree and agrue between parents and kidsB.parents don’t need to be patient with their kidsC.kids can agrue with their parents in a raised angry voiceD.kids need to agrue with parents with respectDSome people can find the different color lump(色块)among 45,000 lumps.Others can remember 120 strangers and their fingerprints. There are also some people who can work out a seven-digit number(七位数)multiply(乘以) a 10-digit number in just a fehneseiw seconds.In a Chinese science TV show called Super Brain,you can be amazed by these people’s great brainpower. Brainpower actually means intelligence( 智力)which includes different abilities, such language, logic, memory and even imagination.Wang Yuheng is a painter from Beijing. He was born in 1981 and he has super observing( 观察)ability. In February, 2015 he took part in one of the competitions.There were 520 glasses of water on the stage. A judge chose one glass of water and give it to Wang to look at.Then the glass was put back where it was. He had to find this glass of water among 520 glasses of water. Unbelievably, he found it in just few minutes.You may ask how the competitors’ brains can be so strong and powerful. Are they born to be talents? Do you also want to have super brainpower? Here’s what we can do to improve our brainpower.ExerciseStudies have shown that exercise can improve the brain’s functions(功能), such as planning, organizing and multitasking. Exercise can also help you be in a good mood.Training your memoryHow often do you hear people say, “I wish I had a better memory ?” But no one does anything about this! If you train yourself to memorize phone numbers and other important numbers, you will see a change.Doing something newWhen you experience something new you actually stimulate( 刺激) your brain! This creates new neural pathways(神经通路) and increase your intelligence. You could take a new way to your school, try a new snack or even a new form of exercise!62. According to the passage, brainpower includes all the following abilities except__________.A.memorynguageB.imaginationmunication63. We can learn from the passages that _________.A.WangYuheng was 32 years old when he joined in the competitionB.Everyone believed that Wang Yuheng could easily find the classC.It was hard to find the glass because the judge put it in a new placeD. Wang Yuheng succeeded in finding the glass because of his super observing ability64.A.BC.study hard and remember more facts and informationD.watch the Chinese science TV show called Super Brain65.Which is the best title of this passage?A..Intelligence is important.B.Born talent.C.How to have super brainpower?D.How to be more talented?A: Tom,let’s go somewhere interesting to relax.B: 66 .A:Shall we go to the cinema? Some new films are on this week.B: 67 . Which film would you like to see?A: Let me search on the Internet. Er… How about Zootopia?B: Yeah, I have heard of it. It’s so interesting! 68_____A: UME Cinema is a little far. Let’s go to BONA Cinema.B: OK. Look! So many clouds in the sky! 69A: Yes. The weather report says it will be rainy tonight.B: 70A: I will. The film will begin in two hours. We can go there after dinner.B: Alright. Let’s meet at the gate of the cinema.A: OK. See you again.66.________ 67.________ 68.________ 69.________ 70.________VI 任务型阅读(每题2分,共8分)What do Australian teenagers do in their free time ? Many of them like to spend it with their friends.They play together outside or do some shopping. But a girl named Shanaya White spends her free time in a different way---she works hard to cheer upthose children with serious illness.Shanaya comes from Queenland. In September 2014, she spent four days in hospital because of an illness. She found it was really hard to stay in hospital. She felt upset when she thought many children had to stay in hospital for weeks and months because of illnesses. After learning more about childhood illness,she decided to help those children.She made a Facebook Page. On it, she posted stories of other children’s fights against illnesses, hoping more people would care about those children. “I name it Happy Little Smiles because I want to bring happiness and smiles to the kids in need,”saidShanaya. She also made “Happy Packs” and sent the packs to those children with illnesses. Inside the packs, there were toys , books and a mix of activities.It was a success and she made many sick children smile. And thanks to her,more and more people began to care about and help the children.71. What does Shanaya do in her free time?72. How did Shanaya feel when she thought many children had to stay in hospital because of illnesses?73. Did more children begin to care about the sick children?74. What do you think about the girl Shanaya?VII. 句型转换(每空1分,共10分)75. Lily often makes dinner for her family after school.(否定句)Lily _________often _________dinner for her family after school.76. I was washing the clothes at this time yesterday.________ ________ you doing at this time yesterday?77. Luckily, they got to the airport on time. 同义句Luckily, they _______ _______ the airport on time.78.他付款买下这些西红柿,然后匆匆回家了。