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Analysis of plastic and steel sleeve contact force on ANSYS

Abstract. Plastic and steel sleeve contact force distribution, widely used in oil drilling mechanics,

syringes, aerospace and so on. In this paper, plastic and steel ANSYS simulation compression sleeve contact deformation and contact force distribution state. Provide a valuable reference for the study of contact force fields Introduction.

Keywords: Plastic; Steel Sleeve; Contact Force Distribution; ANSYS

1.Introduction

Research achievements have been in contact mechanics of fracturing technology to further enhance the domestic level, control production costs, such as high-voltage swing has made a significant contribution. To further raise the contact force distribution, we use ANSYS simulation packer seated, considering nonlinear contact problems characteristics and plastic tube sealing seat when the rubber material of the packer seat seal process numerical simulation analysis, find contacts Neri distribution.

2.contact model analysis of the stress state

Plastic tube axial compressive stress state , radial expansion . Research by the expansion of the inner wall of the steel sleeve plastic tube extrusion role radial pressure , the use of isolation method , a separate study on steel sleeve , steel sleeve in the space of stress state , as shown by the force of the

inner wall of the steel sleeve case in Figure 1.

Figure 1 A steel sleeve inner wall by the force.

F is the axial pressure , pi is the radial pressure , a steel sleeve inner diameter , outer diameter is b,

2.Stress analysis of thin-walled cylinder

Shown in Figure 1 , We know that the stress distribution is axisymmetric . Thus, the expression is to take the stress components:

0,2)ln 23(,

2)ln 1(2

2==+++-=+++=ϕρρϕϕ

ρττρρσρρσC B A

C B A

( 2-1 ) Wherein the above formula, the radial stress , hoop stress and shear stress , A, B, C is a constant . Boundary conditions for the sleeve:

⎪⎭

⎪

⎬⎫-=-=======b b a a b a q q ρρρρρρϕρρϕσσττ)(,)(0)(,0)( ( 2-2 )

Steel sleeve are only subject to internal pressure problem , so the answer we get Lame

a q a

b b 11

22

2

2

---

=ρσρ ( 2-3 ) a q a

b b 112222

-+-=ρσϕ………………………………………… ( 2-4 )

Since the steel sleeve is axially symmetric problem, the calculation of circumferential strain was analyzed by the following formula

()[]ρϕϕσσμσε+-=z E

1

( 2-5 )

3.rubber deformation theory foundation

Stiffness is defined: refers to the displacement of the rubber in a certain range, the pressure on ( or tensile strength ) and its displacement ratio of the amount of variation is called static stiffness . Because rubber has such a static stiffness characteristics , variable compression deformation can restore the original state , radial axial pressure can occur after the expansion .

F 1

F

F 2

F 3X 2X 1X 3

X

Figure 2 Rubber compression load - displacement curve

The rubber is compressed to a range of the displacement amount after the pressure was slowly lifted uniform relationship between the rubber and the amount of displacement of the load suffered by the non-linear relationship shown in Figure 2 , the external force can be lifted back to the initial position of the rubber , there is no hysteresis with respect to the displacement of the load .

From the above tests can be drawn: the use of plastic tube axial compressive contact force to do the test trials to meet assumptions.

4.ANSYS simulation analysis

Using ANSYS mechanical model of the plastic tube in contact with the steel jacket for finite element analysis, the steel sleeve wall hoop stress strain distribution . According to the experimental method and the load characteristics , select three hollow plastic tube , the partition ring , fixed tube and pipe as the research object , create a structural model of the axis of symmetry shown in Figure 3 .