杭电题目acm答案

1001 Sum Problem (2)1089 A+B for Input-Output Practice (I) (4)1090 A+B for Input-Output Practice (II) (6)1091 A+B for Input-Output Practice (III) (8)1092 A+B for Input-Output Practice (IV) (9)1093 A+B for Input-Output Practice (V) (11)1094 A+B for Input-Output Practice (VI) (12)1095 A+B for Input-Output Practice (VII) (13)1096 A+B for Input-Output Practice (VIII) (14)2000 ASCII码排序 (16)2001计算两点间的距离 (17)2002计算球体积 (19)2003求绝对值 (20)2004成绩转换 (21)2005第几天 (22)2006求奇数的乘积 (24)2007平方和与立方和 (26)2008数值统计 (27)2009求数列的和 (28)2010水仙花数 (29)2011多项式求和 (31)2012素数判定 (33)2014青年歌手大奖赛_评委会打分 (34)2015偶数求和 (36)2016数据的交换输出 (38)2017字符串统计 (40)2019数列有序! (41)2020绝对值排序 (43)2021发工资咯：） (45)2033人见人爱A+B (46)2039三角形 (48)2040亲和数 (49)姓名：郑春杰班级：电商1001学号：341001 Sum ProblemProblem DescriptionHey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.?InputThe input will consist of a series of integers n, one integer per line.?OutputFor each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.?Sample Input1100?Sample Output15050?AuthorDOOM III解答：#include<>main(){int n,i,sum;sum=0;while((scanf("%d",&n)!=-1)) {sum=0;for(i=0;i<=n;i++)sum+=i;printf("%d\n\n",sum);}}1089 A+B for Input-Output Practice(I)Problem DescriptionYour task is to Calculate a + b.Too easy! Of course! I specially designed the problem for acm beginners.You must have found that some problems have the same titles with this one, yes, all these problems were designed for the same aim.?InputThe input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line.?OutputFor each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.?Sample Input1 510 20?Sample Output630?Authorlcy?RecommendJGShining解答：#include<>main(){int a,b;while(scanf("%d%d",&a,&b)!=EOF) printf("%d\n",a+b);}1090 A+B for Input-Output Practice(II)Problem DescriptionYour task is to Calculate a + b.?InputInput contains an integer N in the first line, and then N lines follow. Each line consists of a pair of integers a and b, separated by a space, one pair of integers per line.?OutputFor each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.?Sample Input21 510 20?Sample Output630?Authorlcy?RecommendJGShining解答：#include<>#define M 1000void main(){int a ,b,n,j[M],i;1091A?InputInput contains multiple test cases. Each test case contains a pair of integers a and b, one pair of integers per line. A test case containing 0 0 terminates the input and this test case is not to be processed.?OutputFor each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.?Sample Input1 510 200 0?Sample Output630?Authorlcy?RecommendJGShining解答：#include<>main(){int a,b;scanf("%d %d",&a,&b);while(!(a==0&&b==0)){printf("%d\n",a+b);scanf("%d %d",&a,&b);}}1092A+B for Input-Output Practice(IV)Problem DescriptionYour task is to Calculate the sum of some integers.?InputInput contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed.?OutputFor each group of input integers you should output their sum in one line, and with one line of output for each line in input.?Sample Input4 1 2 3 45 1 2 3 4 5?Sample Output1015?Authorlcy?RecommendJGShining?解答：#include <>int main(){int n,sum,i,t;while(scanf("%d",&n)!=EOF&&n!=0){sum=0;for(i=0;i<n;i++){scanf("%d",&t);sum=sum+t;}printf("%d\n",sum);}}1093 A+B for Input-Output Practice(V)Problem DescriptionYour task is to calculate the sum of some integers.?InputInput contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.?OutputFor each group of input integers you should output their sum in one line, and with one line of output for each line in input.?Sample Input24 1 2 3 45 1 2 3 4 5?Sample Output1015?Authorlcy解答：#include<>main(){int n,a,b,i,j,sum;sum=0;while(scanf("%d\n",&n)!=-1) {for(i=0;i<n;i++){scanf("%d",&b);for(j=0;j<b;j++){scanf("%d",&a); sum+=a;}printf("%d\n",sum); sum=0;}}}1094 A+B for Input-Output Practice(VI)Problem DescriptionYour task is to calculate the sum of some integers.?InputInput contains multiple test cases, and one case one line. Each case starts with an integer N, and then N integers follow in the same line.?OutputFor each test case you should output the sum of N integers in one line, and with one line of output for each line in input.?Sample Input4 1 2 3 45 1 2 3 4 5?Sample Output1015?Authorlcy?RecommendJGShining解答：#include<>main(){int n,a,b,i,j,sum;sum=0;while(scanf("%d\n",&n)!=-1){for(j=0;j<n;j++){scanf("%d",&a);sum+=a;}printf("%d\n",sum);sum=0;}}[ Copy to Clipboard ]????[ Save to File]1095A+B for Input-Output Practice(VII)Problem DescriptionYour task is to Calculate a + b.?InputThe input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line.?OutputFor each pair of input integers a and b you should output the sum of a and b, and followed by a blank line.?Sample Input1 510 20?Sample Output630?Authorlcy?RecommendJGShining解答：#include<>main(){int a,b;while(scanf("%d%d",&a,&b)!=EOF)printf("%d\n\n",a+b);}1096 A+B for Input-Output Practice(VIII)Problem DescriptionYour task is to calculate the sum of some integers.?InputInput contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.?OutputFor each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs.?Sample Input34 1 2 3 45 1 2 3 4 53 1 2 3?Sample Output10156?Authorlcy?RecommendJGShining解答：int main(){int a,b,i,j,l[1000],k;scanf("%d",&i);getchar();for(j=1;j<=i;j++)l[j]=0;for(j=1;j<=i;j++){scanf("%d",&a);getchar();for(k=1;k<=a;k++){scanf("%d",&b);getchar();l[j]+=b;}}for(j=1;j<=i-1;j++)printf("%d\n\n",l[j]);printf("%d\n",l[i]);}2000 ASCII码排序Problem Description输入三个字符后，按各字符的ASCII码从小到大的顺序输出这三个字符。