天津大学2006~2007学年第二学期期末考试试卷答案
2006-2007学年度第二学期高二期末考试物理试题(内容磁场电磁感应 交流电 电磁场与电磁波).doc 下学期

2006-2007学年度第二学期高二期末考试物理试题(内容:磁场 电磁感应 交流电 电磁场与电磁波)(时间:120分钟,满分:100分)一、选择题(下面每小题中有一个或几个答案是正确的,请选出正确答案填在括号内。
本题共10小题,每小题4分共40分)1.如图1所示,三根长直导线中的电流强度相同,导线b 和d 的电流方向垂直纸面向外,导线c 的电流方向垂直纸面向里,a 点为bd连线的中点,ac 垂直bd ,且ab=ad=ac ,则a 点处的磁感应强度的方向为A.垂直纸面向外 B .垂直纸面向里C.沿纸面由a 指向cD .沿纸面由a 指向d 2.如图2所示,两条长直导线AB 和CD 相互垂直,其中AB 固定,CD 可以以其中心为轴自由转动或平动,彼此相隔一很小距离,当分别通以图示方向的电流时,CD 的运动情况是A .顺时针方向转动,同时靠近导线ABB .顺时针方向转动,同时离开导线ABC .逆时针方向转动,同时靠近导线ABD .逆时针方向转动,同时离开导线AB3.如图3(a),在一水平放置的平板MN 的上方有匀强磁场,磁感应 强度的大小为B ,磁场方向垂直于纸面向里,许多质量为m ,带电量为q +的粒子,以相同的速率v 沿位于纸面内的各个方向,由小孔o 射入磁场区域.不计重力,不计粒子间的相互作用,下列图3(b)中阴影部分表示带电粒子可能经过的区域,其中qBm v R =.哪个图是正确的?4.图4中两平行虚线之间存在匀强磁场,虚线间的距离为l ,磁场方向垂直纸面向里,abcd 是位于纸面内的梯形线圈,ad 与bc 间的距离也为l .0=t 时刻,bc 边与磁场区域边界重合(如图).现令线圈以恒定的速度v 沿垂直于磁场区域边界的方向穿过磁场区域.取a d c b a →→→→的感应电流为正,则在线圈穿越磁场区域的过程中,感应电流I随着时间t 变化的可能是5.如图5左所示是某种型号的电热毯的电路图,电热毯接在交变电源上,通过装置 P 使加在电热丝上的电压的波形如图5右所示.此时接在电热丝两端的交流电压表的读数为A .110VB .156VC .220VD .311V 6.在变电站里,经常要用交流电表去监测电网上的强电流,所用的器材叫电流互感器.如图6所示的四个图中,能正确反应其工作原理的是7.如图7所示,长L 1宽L 2的矩形线圈电阻为R ,处于磁感应强度为B 的匀强磁场边缘,线圈与磁感线垂直.将线圈以向右的速度v 匀速拉出磁场,则第 3 页 共 13 页A.拉力F 大小为R VL B 212B.拉力做的功为RVL L B 2212C.线圈中产生的电热RV L L B 1222D.通过线圈某一截面的电荷量RL BL 21=8.质量为m ,带电量为q +的小球套在水平固定且足够长的绝缘杆上,如图8所示,整个装置处于磁感应强度为B,方向垂直向纸里的 匀强磁场中.现给球一个水平向右的瞬时冲量I 使其开始运动,则球运动克服摩擦力所做的功(不计空气阻力)不可能的是A.m I 22 B.0 C.)(2122232B q g m m I - D.m I 29. 关于电磁场和电磁波,下列叙述中正确的是A .均匀变化的电场在它周围空间产生均匀变化的磁场B .电磁波和机械波一样依赖于介质传播C .电磁波中每一处的电场强度和磁感强度总是互相垂直,且与波的传播方向垂直D .只要空间某个区域有振荡的电场或磁场,就能产生电磁波 10.如图9所示,半径为 r 且水平放置的光滑绝缘的环形管道内,有一个电荷量为 e ,质量为 m 的电子.此装置放在匀强磁场中,其磁感应强度随时间变化的关系式为kt B B +=0(0>k ).根据麦克斯韦电磁场理论,均匀变化的磁场将产生稳定的电场,该感应电场对电子将有沿圆环切线方向的作用力,使其得到加速.设t=0时刻电子的初速度大小为0v ,方向顺时针,从此开始后运动一周后的磁感应强度为1B ,则此时电子的速度大小为A.m re B 1B.mke r v 2202⋅+πC.m re B 0D.mke r v 2202⋅-π 二、填空题(共4小题,每小题4分共16分)11.电磁炮是利用电磁发射技术制成的一种先进的动能杀伤武器,具有速度快,命中率高,发射成本低,减少污b 0染等优点,是21世纪的一种理想兵器,它的主要原理如图10所示,1982年澳大利亚国立大学制成了能把2.2g 的弹体加速到s km /10的电磁炮(常规炮弹约为s km /2),若轨道宽m 2,长m 100,通过的电流恒为A 10,则轨道间所加的匀强磁场=B ________T ,磁场力的最大功率W P ______=(轨道摩擦力不计)12.一个电子在匀强磁场中,以一个固定的正电荷为圆心,在一个圆轨道上匀速转动,磁场方向垂直于它的轨道平面.电子受电场力大小恰是磁场力的3倍.已知电子质量为m ,电量为e ,磁感强度为B ,则电子运动的角速度可能为________.13.如图11有一只定值电阻接在一个交变电源上, 通过电阻的电流为 I .若将它通过一台理想变压器接在这个交变电源上,测得变压器的初级线圈中的电流为 I /4 ,那么这时通过该定值电阻的电流为 _________.14.电磁波遇到某些障碍物会发生反射,雷达就是根据这一原理制成的,某雷达站正在观察一飞机飞行,若飞机正向雷达站飞来,某一时刻雷达第一次发出电磁波到接收到反射波历时 200 微秒,第二次发出电磁波到接收到反射波历时 186 微秒,第一次发射到第二次发射的时间差为 4 秒钟,则飞机的飞行速度为__________ 米/秒.三、实验题(共2小题,共12分,写出必要的做题步骤,计算过程和单位.每小题5分.) 15.人们常常用充气泵为鱼缸内的水补充氧气,如图12是一种利用电磁原理制作的充气泵的结构示意图。
(完整版)天津大学07-08(2)复变函数期末考试试卷A

学院专业班 年级学号姓名共3页第2页
3、已知函数 在复平面上解析, 的虚部为 ,且满足 ,求 。
4、求函数 的所有孤立奇点,判别其类型,若为极点指出其级数。
5、求函数 在下列圆环内的Laurent展开式:
(1) ;(2)
三、计算下列积分(每小题院专业班 年级学号姓名共3页第3页
2、 ,其中C为不过0和1的任意简单闭曲线。
3、 .
四、求一保形映射 ,将 平面上的区域 映为 平面的上半平面。(6分)
4、若 满足柯西积分定理的条件,则其积分表达式 =。
5、积分 。
6、留数 。
7、把上半平面 映为单位圆 且满足 的分式线性映射为 。
8、 在 处的旋转角为, 在哪些点处的伸缩率为1。
二、解答题(每小题8分,共40分)
1、证明:函数 在复平面上除 外所有点都解析。
2、计算积分 ,其中 为:
(1)从原点到 的直线段;(2)半圆: ,起点为1。
天津大学试卷专用纸
学院专业班 年级学号姓名共3页第1页
2007~2008学年第二学期期末考试试卷
《复变函数》(A卷共3页)
(考试时间:2008年4月25日)
题号
一
二
三
四
成绩
核分人签字
得分
一、填空题(每空格3分,共30分)
1、 。
2、若 ,则 。
3、函数 在 处的Taylor展开式的平方项系数为,其收敛半径 =。
天津大学_数据库原理_本科生_期末试题+答案_试卷

天津大学试卷专用纸学院计算机学院专业班年级学号姓名 A卷共 7 页第 1页题号一二三成绩核分人签字得分1C2D3D4A5B6D7B8D9B10B 11B12C13B14B15D 16C17C18B19B20C 21A22D23D24C25D 26B27B28D29B30B 31C32C33D34D35A 36D37C38C39B40C 41A42B43BC44BD45AB 46D47CD48CD49A50ABD天津大学试卷专用纸学院计算机学院专业班年级学号姓名 A卷共7 页第 2页7.某个企业的数据库包含以下信息.员工(由员工编号唯一确定,记为ssn),员工的子女(属性为name,age),在双亲给定的情况下,每个孩子能由他的姓名唯一确定(假设他们的双亲中只有一个是公司的员工).一旦员工离开公司,那么企业不再对其子女信息感兴趣.下面哪个ER图能够正确的反映以上需求B8.如果将下面的ER图转换成数据库中的关系,那么在数据库中需要定义. DA. 2个关系B. 3个关系C. 3个关系 ,1个断言D. 2个关系,1个断言9. 如果将下面的ER图转换成数据库中的关系(该ER图中要求员工的年龄在18到55岁之间),那么在数据库中至少需要定义. BA. 3个关系,1个断言个关系,1个约束个关系个关系10. 我们在一个关系中BA.必须定义一个主关键字B.只能创建一个聚集索引(cluster index)C.只能创建一个稠密索引D.只能定义一个约束.11. 在DBMS的关系中BA.关键字属性值可以为空B.外关键字属性值可以为空C.任何属性值都可以为空D.任何属性值都不可以为空.12. 下面关于外关键字描述不正确的是CA.外关键字必须是所参考表的主关键字.B.外关键字属性必须与参考的属性是相同的数据类型C.定义外关键字需要对所参考表拥有select权D.一个表中可以有多个外关键字.13.我们在DBMS中记录数据库员工和员工工作信息,要求当某个员工离职后,数据库需要自动删除该员工的工作信息,在定义工作表时我们对于外关键字的删除规则应定义为BA. ON DELETE ROLLBACKB. ON DELETE CASCADEDELETE SET NULL DELETE NO ACTION14.在DBMS中执行GRANT update(col1) ON TABLE TO user7,对于该语句下面哪个描述是正确的: B天津大学试卷专用纸学院计算机学院专业班年级学号姓名 A卷共 7页第3页15. 关系模式R,R的属性集是{ABCDEG}有函数依赖集F={AB C , C A, BE C, BC D , CG BD}计算(AB)的属性闭包.DA.. BDEGB. BDCC. ABCDEGD. ABCD16. staff的定义如下Cid INTEGERname CHAR(20)dept INTEGERjob CHAR(20)years INTEGERsalary DECIMAL(10,2)comm DECIMAL(10,2)下面哪个语句可以按照job和salary的升序排序来返回所有员工的信息.A. SELECT id,name,salary,dept,job,years,comm FROM staff ORDER BY 4,6B. SELECT id,name,salary,dept,job,years,comm FROM staff GROUP BY 4,6C. SELECT id,name,salary,dept,job,years,comm FROM staff ORDER BY 5,3D. SELECT id,name,salary,dept,job,years,comm FROM staff GROUP BY 5,317. 关系模式Sailors(sid,,age,ratring)其中lastname允许为空. 下面哪个语句能够查找出lastname属性值不为空的水手信息. CA. SELECT * FROM SAILORS WHERE LASTNAME<>’NULL’B. SELECT * FROM SAILORS WHERE LASTNAME<>NULLC. SELECT * FROM SAILORS WHERE LASTNAME IS not NULLD. SELECT * FROM SAILORS WHERE LASTNAME not LIKE ’NULL’18. 关系模式Sailors(sid,sname,age,ratring)下面哪个语句能够查找出sname属性值至少为四个字符长,并且开始和结束字符都是B的水手信息. B* FROM SAILORS WHERE sname like ’B%%_B’20.有关系模式R(A,B,C)和三个合法实例(6,4,6),(6,4,6),(7,4,8),下面哪个函数依赖在关系模式R 上不成立CA. A->BB. BC->AC. B->CD. C->A.21.设有关系模式R(B,I,S,Q,D),其上函数依赖集F={S D,I B,IS Q,B Q,B I}下面那些是R的关键字. A22.下面哪个改变可以通过alter table实现DA. 增加一个触发.B. 增加一个索引.C. 增加一调记录D. 定义一个候选关键字23.下面的语句按顺序成功执行后CREATE TABLE tab1 (c1 CHAR(1))INSERT INTO tab1 VALUES ('b')CREATE VIEW view1 AS SELECT c1 FROM tab1 WHERE c1 ='a'INSERT INTO view1 VALUES ('a')INSERT INTO tab1 VALUES ('b')执行SELECT c1 FROM tab1可以选择出多少条记录D24.有一个关系模式employee(name,department,phone_number),下面哪句话允许user1可以修改phone_number列的值CA. GRANT MODIFY (phone_number) ON TABLE employee TO user1B. GRANT ALTER (phone_number) ON TABLE employee TO user1C. GRANT UPDATE (phone_number) ON TABLE employee TO user1D. GRANT REFERENCES (phone_number) ON TABLE employee TO user125.数据库中SAILORS表是由joe创建的.在DBMS完成下面的语句后 D天津大学试卷专用纸学院计算机学院专业班年级学号姓名 A卷共7页第4页26.在使用数据库中使用索引的目的是: BA.提高数据文件的存储率.B.可以更加有效的控制事务处理中的幻影问题.C.增加DBMS的安全性.D.提高增加记录的效率.27.下面哪种文件格式对不等值搜索的效率最高BA.无序文件B.排序文件C.哈希文件D.队列文件28.下面关于主关键字描述不正确的是: DA.在表中可以通过主关键字唯一的确定一条记录.B.主关键字可以由多个属性组成.C.组成主关键字的属性值不能空.D.一个表中可以有多个主关键字29.关于第三范式描述正确的是BA.一个关系属于第第一范式,它就属于第三范式B. 一个关系模式属于BC范式,它就属于第三范式C. 一个关系实例有数据冗余,它就是属于第三范式D.一个关系实例没有数据冗余,它就是属于第三范式30.下面哪个调度是串行调度: BA. T1:R(A),T2:R(B),T2:W(B),T1:W(A)B. T1:R(B),T1:W(B),T2:R(A), T2:W(A)C. T1:R(A),T2:R(B),.T1:W(A),T2:W(B)D. T2:R(A),T1:R(B),.T1:W(A),T2:W(B)31.下面关于数据库事务处理描述错误的是: CA.原子性:表示的是事务的所有操作在数据库中要么全部正确反映出来要么全部不反映.B.一致性:事务在执行前如果数据库是一致性的那么执行后也是一致性的.C.隔离性:事务在执行过程中可以感觉到系统中其他事务的执行33.数据库系统的log中检查点的作用是: DA.系统事务取消时数据库关系系统需要重检查点开始取消.B.系统事务正确完成时数据库系统会在log中设置检查点.C.数据库重新启动时恢复系统中的重做阶段从检查点开始.D.数据库重新启动时恢复系统中的分析阶段从检查点开始34. 下面哪个说法符合数据库系统WAL(log先写协议): DA.数据库内存中被事务修改的页面在事务成功完成时被强制写到磁盘中B.数据库内存中被事务修改的页面在事务撤销时被写到标记为非脏页C.事务成功完成时不需要将与其相关的log页面强制写回磁盘D.事务中被修改的内存数据页面在写回磁盘前必须将与其相关的log写回磁盘35.一个企业提供了一个查询数据库,该数据库的数据可以很容易的重新构造.为了提供数据库中磁盘数据的访问速度,下面磁盘技术中采用哪种方法可以满足该要求: AA. RAID 0 1 C. RAID 0+1 536.一个企业有大量的数据需要存储在数据库中,企业要求数据的稳定性存储和数据开速访问,但不想使用太多的磁盘进行冗余存储,下面磁盘技术中采用哪种方法可以满足该要求: DA. RAID 0 1 C. RAID 0+1 537.在JDBC提供的数据库编程方法中提供了几种JDBC和数据库的连接方法: C38.下面哪些说法是正确的:CA.在死锁预防中,等待--死亡法是中止优先级高的事务B.在死锁预防中,受伤--等待法是优先级高的事务可能等待优先级低的事务释放锁C.使用死锁预防的系统中不会出现死锁。
天津大学2006~2007学年第一学期期末考试试卷答案

6.(×)由于BF3为非极性分子,所以BF3分子中无极性键。
7.(√)由于Hg2+与S2-之间的相互极化作用比Zn2+比S2-间的极化作用强,所以HgS比ZnS的溶解度小。
8.(√)中心原子的几个原子轨道杂化时,形成数目相同的杂化轨道。
(C)分子间力和氢键能同时存在于分子之间;
(D)大多数分子的分子间力以色散力为主;
三.填空题(本题共22分)
1.50号元素的电子排布式为[Kr]4d105s25p2,该元素属五周期,IVA族,P区元素.
2.在乙醇的水溶液中,分子间存在的分子间力的种类有色散力、诱导力、
取向力和氢键。
3.KCN, NH4F, NH4OAc, NH4NO3, Na2CO3,各溶液浓度均为0.1 mol·L-1,按pH值从小到大顺序排列NH4NO3, NH4F, NH4OAc, KCN, Na2CO3。(已知Kθ(NH3·H2O)=1.8×10-5,Kθ(HF)=6.6×10-4,Kθ(HCN)=6.2×10-10,Kθ(HOAc)=1.8×10-5, (H2CO3)=4.4×10-7, (H2CO3)=4.8×10-11)
15.( )既能衡量元素金属性强弱,又能衡量其非金属性强弱的物理量是________。
(A)电子亲合能(B)电离能(C)电负性(D)原子半径
16.( )下列各组离子化合物的晶格能变化顺序中,正确的是________。
(A) MgO>CaO>Al2O3(B) LiF>NaCl>KI
(C) RbBr<CsI<KCl (D) BaS>BaO>BaCl2
Kө(298.15K)=1.3×1048
(2) (500K)=-248.5kJ·mol-1
【期末复习】大学《无机化学与化学分析》第二学期期末考试试卷答案

D
D
A
C
C
1.既溶于过量氨水,又溶于过量NaOH溶液的是。
(A) Ni(OH)3(B) Fe(OH)3(C) Zn(OH)2(D) Al(OH)3
2.下列各组离子中的所有离子都能将I-氧化的是。
(A) Hg2+, Ni2+, Fe2+(B) Ag+, Sn2+, Pb2+
(C) Co2+, Cr2O72-, Sb3+(D) MnO4-, Cu2+, Fe3+
5. (×)平行实验的精密度越高,其分析结果的准确度也越高。
6.(×) CrCl3在金属焊接时用于清除金属表面氧化物。
7.(×)铁(Ⅲ)、钴(Ⅲ)、镍(Ⅲ)氧化物的氧化性从强到弱的次序为:Fe2O3>Co2O3> Ni2O3。
8. (√)锰的氧化物的酸性随氧化数的增大而逐渐增强。
9.(×)同一金属组成不同氧化数的卤化物,高氧化数卤化物多为离子型化合物。
16.读取滴定管数时,下列错误的是。
(A)在常量分析中,滴定管读数必须读到小数点后第四位
(B)读数时,应使滴定管保持垂直
(C)读取弯月面下缘最低点,并使视线与该点在同一水平面上
(D)读数前检查管壁是否挂水珠,管尖是否有气泡
17.间接碘量法中加入淀粉指示剂的适宜时间是。
(A)滴定开始时
(B)用标准滴定溶液滴定近50%时
天津大学试卷专用纸
学院专业班年级学号姓名共5页第2页
8.下列各族元素中,金属的化学活泼性随原子序数增加而减弱的是。
(A) IA (B) IIA (C) IIIA (D) IB
9.下列硫化物中,不溶于Na2S溶液的是。
天津外国语学院 06-07(2)高等数学

u
发散
4.方程 3 x 3 y z 0 表示旋转曲面,它的旋转轴是( (A) x 轴 (B) y 轴
2
)(C) z 轴2 Nhomakorabea(D) x 轴或 y 轴 )
5.微分方程 ( x 2 y y )dy y dx 0 是(
(A)变量可分离方程; (B)线性方程; (C)齐次方程; (D)全微分方程. 三、 计算下列各题: (本题 42 分,每小题 7 分)
)
(C ) I 1 0, I 2 0
( D ) I 1 0, I 2 0
2、函数 f ( x , y ) 在点 ( x0 , y0 ) 处偏导数 f x ( x 0 , y0 ) , f y ( x 0 , y0 ) 存在是
f ( x , y ) 在点 ( x0 , y0 ) 处可微的(
_______________ 。
二、单项选择题: (本题 15 分,每小题 3 分) 1.若 I
(1 x )d , 其中 D 是 x 1, y 1; I
1 D1
2
xyd , 其中 D 是
2 D2
x 2 y 2 1, 则 I1 , I 2 的值为( ( A) I 1 0, I 2 0 ( B ) I 1 0, I 2 0
期末考试试卷 (B 卷)
一、 1. 填空: (本题 15 分,每题 3 分)
两直线 L1 :
x y2 z x 1 y z3 和 L2 : 的夹角为 2 2 1 1 4 1
2、 3.
2 2
( x 3 1)sin 2 xdx __________ .
设 D :1
2006年天津大学非英语专业研究生英语期末考试(真题+答案)

ENGLISH PROFICIENCY EXAMFOR NON-ENGLISH MAJOR POSTGRADUATE STUDENTSTIANJIN UNIVERSITY JAN 13th, 2006PART 2 CLOZE (10%)Directions:In this part of the test, you’ll read an incomplete passage with10 blanks. Read the passage carefully, and choose the best answer from choices marked A, B, C and D. Then on your ANSWER SHEET, find the number of the question and mark your answer with a single line through the center.Americans have been awarded more than one-half of all Nobel Prizes in physics, chemistry and medicine since 1945. _15_ impressive success is no accident, but the result of a firm and consistent commitment by the federal government _16_ basic science research at our universities. Out nation’s policymakers and public have been prudent investors _17_ their support has paid off in tremendous ways.America’s investment in research over the last fifty years has been a vital _18_ of our economic and political strength around the world, as well as the quality of life Americans enjoy at home. The polio vaccine, computers, jet propulsion and disease resistant grains and vegetables are _19_ the thousands of advances pioneered at our universities that have had dramatic benefits for our health, economy, _20_ and quality of life. New and equally breathtaking advances may be just _21_ the corner. Genetic research, for example, gives _22_ of better treatments for Alzheimer’s, cancer and other diseases. Lighter and stronger composite materials may be developed with important applications in transportation, medicine and the military. Continuing support for university-based research will not only pave the way for these important breakthroughs, but will also train the next _23_ of pioneers and Nobelists.The engine of scientific innovation and discovery cannot fuel itself. Our own achievements and the benefits they have brought would not have been possible without the government’s patient capital. Discoveries are rarely made instantaneously, but result from years of painstaking work by scientists in a variety of fields. With competition forcing industry to focus research investments on returns over the _24_, the government is left with the crucial role of making the longer term investment in discovery.15. A. This B. ThatC. AndD. So16. A. of B. inC. toD. for17. A. for B. butC. soD. as18. A. reason B. originC. statusD. source19. A. some B. amongC. ofD. just20. A. secure B. insecureC. securityD. insecurity21. A. around B. inC. atD. on22. A. future B. cautionC. intentionD. promise23. A. generation B. groupC. herdsD. school24. A. immediate B. urgentC. long runD. shorter termPART 3. Vocabulary (10%)Directions: This section consists of 20 incomplete sentences. In each question there are four words or phrases marked A, B, C and D beneath each sentence. You are to choose the ONE word or phrase that best completes the sentence. Then, on your ANSWER SHEET, find the number of the question and blacken the corresponding letter of the answer you have chosen.25. You should also have a treasurer or accountant to __________ the spending of themoney and a finance chairman to raise it.A. circulateB. reinforceC. superviseD. enlarge26. In Japan, by contrast, no single car-producer dominates, and the impetus for evergreater innovation and lower prices springs less from international competition than from the intense __________ within Japan itself.A. incentiveB. rivalryC. recessionD. dilemma27. He enjoys his food and wine, but does not allow its enjoyment to __________ theimage which is important chiefly to himself, and then to his public.A. distortB. manifestC. glorifyD. squint28. No reason was given for the departure of Rourke at the time, and this only servedto __________ speculation.A. intimateB. acquaintC. intensifyD. inspect29. However, he was a writer with a number of plays to his credit, none of them greatsuccesses but all __________ note.A. short ofB. clear ofC. ashamed ofD. worthy of30. Failure to _________ with the regulations can result in a $10,000 fine or asix-month prison sentence.A. consultB. complyC. coincideD. compete31. The new policy will drop a presumption in favor of house building __________other conservation considerations.A. at the expense of C. in the process ofC. in the name ofD. in the midst of32. The object of this letter is to __________ policy holders of any changes affectingtheir policies.A. ridB. freeC. clearD. notify33. Hinges and latches on garden gates are very _________ to rust –the action ofopening and closing them will wear away any protective coating you may apply.A. tolerantB. hostileC. proneD. contrary34. Although he found that television is far less violent than in the United States, DrTadecki intends to campaign with Mary Whitehouse to __________ violence on the screen.A. inspectB. curbC. shieldD. tighten35. But if the valuer is __________ and you buy the property relying on his report,you may still be able to sue him for damages.A. patheticB. negligentC. depressiveD. authentic36. A child under 10 incurs no criminal __________ for its acts.A. dilemmaB. remorseC. liabilityD. sensation37. Women work the same hours, only to rush off afterwards to do childcare,shopping, cooking and cleaning tasks from which men are __________.A. conservativeB. vacantC. giddyD. exempt38. He was unshaven, and his stomach was beginning to __________ over his belt,but there were still traces of the fine, athletic figure and well-cut features that she had married seven years ago.A. protrudeB. distortC. overlookD. unfold39. We believe that results can only be properly evaluated if the problems connectedwith the study are made ___________ rather than concealed.A. accessibleB. compatibleC. implicitD. manifest40. Other countries’currencies are either fixed in value or __________ against thedollar in the world’s foreign exchange marke ts.A. regulateB. fluctuateC. devastateD. emulate41. A failure to __________ the legal requirements in contracting a marriage willrender that marriage void.A. cling toB. hold toC. conform toD. subscribe to42. As she walked onto the floor her heart was beating fast with excitement but herface was a smiling ____________ mask.A. sereneB. contentedC. feebleD. circular43. After work the same evening, my husband and I walked all over the golf courseand were eventually rewarded by spotting the dog in the distance, although we failed to __________her towards us.A. commenceB. sootheC. coaxD. commend44. The Government’s __________ for more competition less regulation andconsumer choice is expected to result in three new national commercial radio networks as well as an excess of local and community stations.A. moduleB. seminarC. thirstD. guidancePART 4 READING COMPREHENSION (15%)Directions: There are 3 passages in this part. Each passage is followed by some questions or unfinished statements. For each of them there are four choices marked A, B, C and D. You should decide on the best choice and blacken the corresponding letter on the ANSWER SHEET. (15%)Passage 1Something is wrong, if not rotten, in the state of New York, the state of California and every state in between. While searching endlessly for just the right diet, we are consuming ever more calories, growing ever more obese(肥胖)and suffering shocking rates of diabetes, hypertension and heart disease as a result. No one outside the weigh-loss industry is happy about the situation, but as the crisis worsens we seem to grow ever more confused about how we got here – and ever more polarized about how to set things right. Stubborn vegetarians continue to rail against dietary fat and emulate Chinese peasants. Born-again carnivores blame white bread and force themselves onto all-meat diets in hopes of burning up their belly fat. Ordinary civilians throw up their hands and consume whatever is convenient – which is to say potato chips and Coke.Is this the cost of modernity? Have we escaped scurvy, pellag r a and rickets only to suffer higher-tech forms of inadequate nutrition? Somewhere in the fog of conflicting prescriptions, is there a diet that’s both safe and tasty –a diet that can control weight and promote health without denying us the pleasure of food?The federal government has long tried to get the best science on diet and health. But commercial pressures and bureaucratic obstacles have often clouded the results. The United States Department of Agriculture’s famous Food Guide Pyramid, first published in 1992, is now widely viewed as faulty. “The pyramid is a disaster,” says K. Din Gifford of Oldways, a non-profit think tank based in Boston. “The American epidemic of obesity is the proof that it hasn’t worked. Period.”That doesn’t mean all such efforts are doomed. Researchers have gained critical insights into diet and health in recent years. And while they wait for the USDA to remodel its pyramid, some of those experts are concocting whole new alternatives. By far the most ambitious of these efforts is the so-called Healthy Eating Pyramid devised by Dr. Walter and his colleagues at the Harvard School of Public Health. Instead of simply pooling diet preferences, the Willett team claims to have gathered the best evidence from all possible data sources. The Healthy Eating Pyramid has some controversial features, including a strong recommendation of calorie-rich vegetable oils and a virtual prohibition of potatoes and white rice. But its effects have been cleverly evaluated. The diet is designed not for short-term weight loss but for lifelong health. It doesn’t require that you weigh your food or eat according to your blood type. As Willett likes to say, its ultimate message is simple: “Eat, drink and be healthy.”45.We learn from the first paragraph that the average American __________ .A.eats more meat than vegetablesB.eats more vegetables than meatC.consumes a lot of fast foodD.pay more attention to diet than ever before46.According to the passage, Food Guide Pyramid __________ .A.is misleading people on what to eatB.has done a good job on advising food to eatC.is a necessary evil in highly industrialized countriesD.is a non-profit think tank47.It can be inferred from the passage that scurvy, pellagra and rickets __________ .A.are diseases caused by lack of nutritionB.were epidemics once widespread in AmericaC.are diseases resulting from overeatingD.were once incurable diseases48.According to the author, the policy of the federal government concerning food__________ .A.is based on solid scienceB.has undergone great changesC.is swayed by interest groupsD.often results in disaster49.The Healthy Eating Pyramid devised by Dr. Walter Willett and his colleagues atthe Harvard School of Public Health __________ .A.is likely to win universal acceptanceB.has brought about a lot of confusionC.is designed for long-term health benefitsD.aims to eliminate obesity throughout AmericaPassage 2People often talk about how a business should treat its customers. But how often do they talk or even think about how customers should treat a business?Almost everyone has had the experience of standing at the cash register in front of a long line while a salesclerk struggles to find a bar code or price tag. Instead of taking the time to call for a price check, the clerk may turn to the customer and ask, “Do you know what the price is?”For every customer who shakes his head “no,” forcing the salesclerk to call for assistance, there is a customer like Irene, a gray-haired widow, who loves to get into these situations. Though Irene knows the exact price of everything she purchases, she won’t tell it to the salesclerk. She’ll say “It’s $1.98” even when she knows it costs several dollars more. The fact that the salesclerk believes Irene isn’t her problem, Irene says, though she’ll admit it is one of the few benefits of looking like a nice old lady.Nancy, a math teacher, will never forget the time she was buying clothes for her four children. All of the items were reduced 20 percent from the clearance price. The salesgirl punched in the first item’s price, and then took 20 percent off. So far, so good. Then she entered the price of the second item, subtotaled, and took 20 percent off again. Each time the clerk added another item, she subtotaled first before taking 20 percent off. When the final bill was a little over $10, Nancy could hardly believe her eyes. But she paid the bill without saying anything. She told her husband later that many people wou ldn’t have even noticed what the clerk was doing wrong. “Why should I be penalized for knowing math?” Nancy argued.A recent college graduate, Jeffrey, can’t afford everything he wants. When he got an offer to receive free issues of a very expensive magazine, he immediately signed up for a subscription. From the very beginning he planned to cancel the subscription as soon as the free issues ran out. And he did. The problem was that the magazine kept coming anyway and, eventually, Jeffrey was billed for a y ear’s subscription. It took more than a few months of correspondence to get the whole mess settled. And, in the end, Jeffrey did get quite a few issues of the magazine without paying anything.We probably would all agree that Irene, Nancy and Jeffrey are not very good customers. But what does it take to be a good customer? In short, good will. Good will means a customer treats the business honestly and fairly even when he doesn’t have to. Good business policies and good consumer protection against fraud are necessary, but not enough to cover all the possible situations arising between abusiness and its customers. It takes good will to fill in the cracks. It takes good will to make both good businesses and good customers.50.Why did the salesclerk believe Irene?A.There was a long queue of customers standing at the cash register.B.Irene knew the exact price of everything she purchased.C.There was no time to call for a price check.D.Irene looked like a respectable old lady.51.What does the author mean by “So far, so good”?A.It was right for the salesgirl to take 20% off every item.B.Up to now, everything went smoothly.C.The salesgirl had punched in the right price.D.Up to this point, the calculation was correct.52.The correct procedure for the salesgirl to perform should have been __________ .A.to add up each item and then take 20% off the totalB.to take 20% off the subtotal each time she added a new itemC.to take 20% off each item and then take another 20% off the totalD.to add up the clearance price of each item53.What did Nancy mean by saying, “Why should I be penalized for knowing math”?A.It’s unfair for me to pay the correct sum for knowing her mistakes.B.Why should I be punished because I knew where she made a mistake?C.It’s only fair for me to pay less because I am good a t math.D.People who know math should be rewarded rather than punished.54.What, in the author’s view, should Jeffrey have done to be a good customer?A.He should not have accepted the magazine after the free issues ran out.B.He should have canceled the subscription as soon as the free issues ran out.C.He should have paid in advance when he signed up for the subscription.D.He should not have signed up for the free issues in the first place.Passage 3Certainly, the concept of a “death with dignity” has become an increasing focus of debate, not the least because of medical progress that has brought about a major increase in the number of retired and aged persons. The issue has generated lots of legislation, much of which confuses rather than clarifies an important question in euthanasia: Who will pull the plug?In general, the laymen’s view of euthanasia is one of “mercy killing,” or active intervention to end life, with little or no concept of the possibility of a passive form.I make no excuses and ask no forgiveness for admitting that I have practiced passive euthanasia for many years. In fact, I gave instructions to the doctor attendingmy own mother in her last illness that she should receive no antibiotics nor be tube-fed. At that stage, she was in her 98th year, suffering from her third stroke and unconscious with pneumonia.I have never practiced active euthanasia, a deed that in my country is regarded as murder and could merit the death penalty. But I do believe that in the clinical practice of medicine, active euthanasia has a definite place. I also believe that we should not be afraid to discuss its place in the scheme of things and to explore the possibilities in this approach to the terminally ill.I cannot accept the simple statement that a doctor does not have the right to take life; furthermore, I believe the greatest difficulty is to define life. I myself have defined it as joy in living. Given the absence of this quality, the request of the suffering person and the satisfaction of other criteria such as good faith on the part of those caring for the person and the completion of legal requirements, there is no ethical reason why active medical euthanasia may not be administered.Indeed, I have always wondered at the kind of person who would mercifully end the life of a suffering animal, yet would hesitate to extend the same privilege to a fellow human being.As a scientist and a humanitarian, I find society’s attitude toward the different ways of causing the death of an individual both hypocritical and illogical. Consider that, for as long as man has inhabited the earth, he has accepted with few reservations the right to kill and be killed on the battlefield, even when this leads to not only his own but multiple deaths.I have talked to legal, ethical and medical authorities in many parts of the world on the need for active euthanasia. Again and again the same questions came up: Who will decide when a life is to be terminated and how can mistakes be avoided?Would doctors perhaps misuse the right to take life by getting rid of the people they do not like?Does a doctor have the right to play God?If it is feared that a doctor is playing God when he terminates a life, it can just as readily be argued that he is playing the same role when he prolongs the life of a terminally-ill patient. And surely, when the terminally-ill person develops an inter-current infection that will cause death if not treated, are we not also interfering with God’s will by instituting treatment and preventing the patient fr om dying of the infection?55.What is the layman’s understanding of euthanasia?A.Killing somebody out of pity because he is in severe pain.B.Ceasing feeding of the patient.C.Stopping treatment.D.Death with dignity.56.What does the author think of active euthanasia?A.It is a form of human cruelty.B.It should be allowed for the terminally ill.C.It is interference in God’s will.D.It is ethically wrong even if legally permissible.57.Why does the author say society’s attitude toward the different ways of causingthe death of an individual is both hypocritical and illogical?A. A single death is much dwelled on while multiple deaths go unnoticed.B.Passive euthanasia is overlooked while active euthanasia is penalized.C.Ending the life of a suffering animal is called mercy while doing the same toa human is called murder.D.Euthanasia is condemned while killing on the battlefield is accepted withoutreservation.58.What is the chief problem that may arise in administering euthanasia?A.Abuse of this practice.B.Religious opposition.pletion of legal procedures.D.The defining of life.59.According to the author, in giving treatment to a terminally-ill patient, the doctoris ________ .A.doing a disservice to societyB.performing humanitarian obligationsC.increasing his sufferingD.interfering with God’s will, too.PART 4 TRANSLATION (15%)Section ADirections: Read the following passage in English carefully and translate it into Chinese in the space provided on the ANSWER SHEET.Neuroscientists(神经科学家)have conducted the first detailed examination of Albert Einstein’s brain and found evidence that part of the renowned physicist’s genius may have come from a section involved in abstract thought that was unusually large and uniquely shaped.Researchers have found that Einstein’s brain was no different than the others in most respects, clearly indicating that a large brain is not a necessary condition for exceptional intellect.However, Einstein’s brain did clearly differ when the researchers examined the parietal lobes (大脑顶叶), which are located in the top back of the brain, and believed to be involved in spatial visualization, mathematical thought, and three-dimensional thinking. Portions of Einstein’s parietal lobes were large on both sides, making his brain 15 percent wider than the other brains.Although the discovery does not conclusively explain the source of Einstein’s towering intellect, and probably was just one factor in the development of his intelligence, it does provide a clue to how subtle differences in the human brain can profoundly affect how the mind works. Section BDirections: Read the following passage in Chinese carefully and translate it into English in the space provided on the ANSWER SHEET.今天我们生活在一个包装了的世界。
06-07(2)高等数学试题(A)解答

广州大学2006-2007学年第二学期考试卷高等数学(A 卷)(90学时)参考解答一.填空题(每小题3分,本大题满分30分)1.(,)(1,2)lim x y →=14. 2.设2sin z x y =,则2z x y∂=∂∂2cos x y .3.函数3x z y e =的全微分dz =323x x y e dx y e dy +.4.若243(,)2f x x x x x =++,221(,)221f x x x x '=-+,则22(,)f x x '=2221x x ++.5.改换积分次序:ln 1(,)ex dx f x y dy =⎰⎰10(,)y eedy f x y dx ⎰⎰.6.平面1x y z ++=在第一卦限部分的面积等于. 7.设L 为圆周222x y a +=,则⎰=+Lds y x )(2232a π.8.若级数1n n u ∞=∑条件收敛,则级数1||n n u ∞=∑的敛散性为: 发散 .9.函数11()xn f x n∞==∑的定义域为x ∈(1,)+∞. 10.若2()2ln 0y f x dx y xdy +=为全微分方程,则()f x =1x.二.解答下列各题(每小题7分,本大题满分14分)1.已知),(y x f z =是由方程0ze xyz -=确定的隐函数, 求x z ∂∂和22xz∂∂.解: 0zz ze yz xy x x∂∂--=∂∂ zz yzx e xy∂=∂-………………………………………………………4分 222()()()z z x x z yz e xy yz e z y z x e xy ---∂=∂- ………………………………6分 2322322()z zz y ze xy z y z e e xy --=-……………………………………7分2.求曲面222236x y z ++=在点(1,1,1)-处的切平面及法线方程.解: (2,4,6)n x y z =(1,1,1)(2,4,6)n -=-……………………………………………3分所求切平面方程 2(1)4(1)6(1)0x y z --++-= ……………………5分 即 2360x y z -+-= 所求法线方程 111246x y z -+-==- ……………………………7分三.解答下列各题(每小题7分,本大题满分14分)1.计算cos()Dx x y d σ+⎰⎰,其中D 是顶点分别为(0,0),(,0)π和(,)ππ的三角形闭区域.解: 积分区域如图(从略) ……………………………………………2分cos()Dx x y d σ+⎰⎰cos()xdx x x y dy π=+⎰⎰…………………………………………4分(sin 2sin )x x x dx π=-⎰ …………………………………………5分01(cos cos 2)2xd x x π=-⎰ 011[(cos cos 2)(sin sin 2)]24x x x x x π=---32π=- …………………………………………………………7分2.设L 为正向圆周221x y +=,计算⎰+-Ldy xy dx yx x 222)(sin .解: 记22:1D x y +≤,由格林公式有 ⎰+-Ldy xy dx yx x 222)(sin22()Dy x dxdy =+⎰⎰………………………………………………3分2130d d πθρρ=⎰⎰ ………………………………………………5分2π= ……………………………………………………………7分四.(本题满分8分)求幂级数2ln nn x n ∞=∑的收敛域.解: 收敛半径 1ln(1)lim ||lim 1ln n n n n a n R a n→∞→∞++===………………………3分 当1x =时,得级数21ln n n ∞=∑, 因11ln n n >,而21n n ∞=∑发散,所以21ln n n∞=∑发散……………………………5分 当1x =-时,得交错级数2(1)ln n n n∞=-∑,因1lim 0ln n n →∞=,且11(2,,)ln ln(1)n n n >=+ ,所以2(1)ln nn n ∞=-∑收敛 ……7分所求收敛域为[1,1)-……………………………………………………8分五.(本题满分6分) 求微分方程dy y xdx x y=+的通解. 解: 令y ux =,则dy duu x dx dx =+………………………………………2分 原方程化为 1du u x u dx u +=+………………………………………3分 分离变量得 1udu dx x =……………………………………………4分两边积分得 21ln ||2u x C =+………………………………………5分yu x=回代得 222(ln ||)y x x C =+ …………………………………6分六.(本题满分8分)某厂家生产两种产品I 和II ,出售单价分别为10元与9元,生产x 单位的产品I 与生产y 单位的产品II 的总费用是:22400230.01(33)x y x xy y +++++(元)假定销售量等于生产量.求取得最大利润时,两种产品的产量各多少? 解: 利润函数为(,)(109)L x y x y =+-22[400230.01(33)]x y x xy y +++++ 22860.01(33)400x y x xy y =+-++-………………3分由80.01(6)060.01(6)0x y L x y L x y =-+=⎧⎨=-+=⎩……………………………………………5分得驻点(120,80)…………………………………………………………7分 因驻点唯一,所以取得最大利润时,两种产品的产量分别为120x =,80y =…………………………………………………………8分七.(本题满分8分)设Ω是由曲面226z x y =--及z =所围成的有界闭区域,求Ω的体积.解: Ω在xOy 面上的投影区域为22:4D x y +≤……………………2分Ω的体积为 22260V dv d d dz πρρθρρ-Ω==⎰⎰⎰⎰⎰⎰…………………5分22200(6)d d πθρρρρ=--⎰⎰………………………6分43222[3]43ρρπρ=--323π=……………………8分八.(本题满分12分) (1)验证函数3693()13!6!9!(3)!nx x x x y x n =++++++ ,(x-∞<<+∞)满足微分方程 x y y y e '''++=;(2)利用(1)的结果求幂级数30(3)!nn x n ∞=∑的和函数.解: (1) 258312!5!8!(31)!n x x x x y n -'=+++++-47324!7!(32)!n x x x y x n -''=+++++-0!nx n x y y y e n ∞='''++==∑……………………………………4分(2) 0y y y '''++=的通解为212(cossin )22x Y e C x C x -=+………………………7分 设x y y y e '''++=的待定特解*x y Ae =,代入x y y y e '''++=,求得13A =,1*3x y e =……………………………………………9分x y y y e '''++=的通解为2121()3xx y e C x C x e -=++……………………10分 由(0)1y =,(0)0y '=,求得123C =,20C =幂级数30(3)!nn x n ∞=∑的和函数为22133x x y e x e -=+ ……………………………12分。
天津大学期末试题合集及答案

学平衡常数 KC =(
)。
13 光化学中的量子效率φ 的定义(
)。
14 胶体分散系统的主要特点是(
)。
15 丁达尔现象产生的原因是入射光的波长(
)分散相粒子尺寸时发生光
的( )现象。
二 (29 分)
1
(20 分)气相反应 2A(g) + B(g) → C(g) 的速率方程为 − dpB dt
= kpA pB ,
物理化学期末考题(A) 2001-01-12
题号
1
2
3
4
5
6
7
总分
分数
一 概念题(30 分)
1
离子的极限摩尔电导率
Λ∞ 1 Ca2+
及
Λ∞ Br −
分别为
59.4×10-4与
78.4×10-4S·m2·mol-1,
2
则
Λ∞ CaBr2
=(
)S·m2·mol-1。
2 某电导池中充以 0.10mol·dm3的醋酸水溶液,25℃时测得其电阻为 703 Ω ,已 知该电导池的电导常数为 36.90m-1,则该醋酸溶液的电导率k=( )S·m-1,
摩尔电导率 Λm =( )S·m2·mol-1。
3 已知 25℃下,浓度b=0.20mol·kg-1 Al2(SO4)3的 r± =0.70,则 b± =( ),电解
质Al2(SO4)3的活度a =(
)。
4
电 池 反 应 Pb2+(
aPb2+
)+
SO42−
(
a2− SO42−
)
=
PbSO4
(g)所对应的原电池为
(
)(表示出所设计的电池)。
天津大学2006~2007学年第一学期期末考试试卷

KKKKK K K K K K K K K K K K K K六.计算题:(本题共32分)1.已知mfH∆(NO) = 90 kJ·mol-1, mfH∆(NOF) = -66.5 kJ·mol-1, m S(NO) = 211J·mol-1·K-1,mS(NOF) = 248 J·mol-1·K-1, m S(F2) = 203 J·mol-1·K-1。
试求:(1)下列反应2NO(g) + F2(g) 2NOF(g) 在298K时的平衡常数Kө;(2)上反应在500K时的mrG∆和Kө。
2.在514K时,PCl5分解反应:PCl5(g) PCl3(g)+Cl2(g)的K=1.78; 若将一定量的PCl5放入一密闭的真空容器中,反应达到平衡时,总压为200.0kPa,计算PCl5分解得百分数为多少?3.含有FeCl 2和CuCl 2的溶液,两者的浓度均为0.10 mol·L -1,通H 2S 至饱和(饱和H 2S 溶液的浓度为0.1 mol·L -1),通过计算说明是否会生成FeS 沉淀?( sp K (FeS) = 3.7⨯10-19, sp K (CuS) = 6.0⨯10-36,H 2S : a1K = 5.7⨯10-8,a2K = 1.2⨯10-15)4.已知下列原电池:(-) Zn ⎪ Zn 2+ ( 1.00 mol·L -1 ) ⎪⎢ Cu 2+ ( 1.00 mol·L -1 ) ⎪ Cu (+) 在Cu 电极中通入氨气至c (NH 3·H 2O) = 1.00 mol·L -1,在Zn 电极中加入Na 2S ,使c (S 2-) = 1.00 mol·L -1。
此时测得原电池的电动势为1.4127 V ,试计算[Cu(NH 3)4]2+的标准稳定常数 f K ([Cu(NH 3)4]2+)。
2006+2007+2008+2009+2010高数第二学期期末考试卷(综合)

一。
偏导数的几何应用1、[07]曲线cos :sin x a ty a t z ct=⎧⎪Γ=⎨⎪=⎩在点(),0,0a 的切线方程为0x a y z a c -==. 2.[07](化工类做)在曲面22122z x y =+上求出切平面,使所得的切平面与平面42210x y z ---=平行。
解:曲面的法向量{}4,,1n x y =-应与平面平面42210x y z ---=的法向量平行,从而有411,1,4222x y y x -==⇒=-=--,由于切点在曲面上()221121122z ⎛⎫=+-= ⎪⎝⎭ 因此切平面为()()1421210,2102x y z x y z ⎛⎫--+--=---= ⎪⎝⎭3.[2006]已知直线34:273x y zL ++==--和平面:4223x y z ∏--=则( B ) A 、L 在∏内 B 、L 与∏平行,但L 不在∏内 C 、L 与∏垂直 D 、L 不与∏垂直,L 不与∏平行4.[2006]曲面23z z e xy -+=在点()1,2,0处的法线方程是12420x y z--== 5. [2006](化工类做) 已知直线1210:320x y L x z +-=⎧⎨+-=⎩和2112:123x y z L -+-==,证明:12//L L ,并求由12,L L 所确定的平面方程。
证明:直线1L 上任取两点()()0,1,2,1,1,1--,则{}11,2,3S =--是1L 的方向向量;2L 的一个方向向量为{}21,2,3S =-,因为12//S S ,所以12//L L设12,L L 所确定的平面方程为0Ax By Cz D +++=,它经过点()1,1,2-和点()()0,1,2,1,1,1--,所以2022000A B C D A DB C D B D A B C D C -++==-⎧⎧⎪⎪++=⇒=-⎨⎨⎪⎪--+==⎩⎩所求方程为210x y --+=二。
《建筑力学》2006--2007学年度第二学期试题及答案

试卷代号:2348中央广播电视大学2006--_'2007学年度第二学期“开放专科"期末考试建筑施工专业建筑力学试题2007年7月一、判断题(每小题2分,共计30分。
将判断结果填入括弧,以\/表示正确.以×表示错误)1.对于作用在物体上的力,力的三要素是大小、方向和作用点。
( )2.力对矩心的矩,是力使物体绕矩心转动效应的度量。
( )3.如果有n个物体组成的系统,每个物体都受平面一般力系的作用,则共可以建立2n 个独立的平衡方程。
( )4.未知量均可用平衡方程解出的平衡问题,称为超静定问题。
( )5.平面弯曲是指作用于梁上的所有荷载都在梁的纵向对称平面内,则弯曲变形时梁的舳线仍在此平面内。
( )6.轴向拉伸(压缩)的正应力大小和轴力的大小成反比,规定拉为正,压为负。
( ) 7.平面图形的对称轴一定通过图形的形心。
( )8.在材料相同的前提下,压杆的柔度越小,压杆就越容易失稳。
( )9.从提高梁弯曲刚度的角度出发,较为合理的梁横截面应该是:以较小的横截面面积获得较大的惯性矩。
( )10.位移法的基本未知量为结点位移。
( )11.杆件的特征是其长度等于横截面上其他两个尺寸。
( )12.力偶对物体的转动效应,用力偶矩度量而与矩心的位置无关。
( )13.多余约束是指维持体系几何不变性所多余的约束。
( )14.任何一种构件材料都存在着一个承受应力的固有极限,称为极限应力,如构件内应力超过此值时,构件即告破蟒。
( )15.压杆上的压力等于临界荷载,是压杆稳定平衡的前提。
( )二、单项选择题(每小题3分。
共计30分)1.链杆(二力杆)对其所约束的物体的约束反力( )作用在物体上。
A.为两互相垂直的分力 B.为沿链杆的几何中心线C.为沿链杆的两铰链中心的连线 D.沿接触面的法线2.如图1所示结构为()A.几何可变体系 B.几何瞬变体系C.几何不变体系,无多余约束 D.几何不变体系,有一个多余约束3.截面法求杆件截面内力的三个主要步骤顺序为( )。
天津大学高数期末考试试卷

,求 函 数 项 级
五、计算下列各题(每小题7分,共21分) 1.计算三重积分I =
Ω
n=1
fn (x)之和.
(x + z )dV,其中Ω是曲面z =
x2 + y 2 与z =
1 − x2 − y 2 所
围成的区域. 2.求
(y −1)dx−xdy ,其中L为含有点(0, 1)的区域D的边界闭曲线,方向取逆时针. x2 +(y −1)2
二、单项选择题(每小题3分,共15分) 1.设有级数
(−1)n np ,则(
) (B)当p > 1时,该级数收敛;
(A)当p > 1时,该级数条件收敛;
(C)当0 < p ≤ 1时,该级数绝对收敛; (D)当0 < p ≤ 1时,该级数发散. 2.已知,则下面答案正确的是( ) 2
(A)点(3, 2)是函数的极大点; (B)点(3, 2)是函数的极小点; (C)点(3, −2)是函数的极大点; (D)点(3, −2)是函数的极小点. 3.若L是平面曲线x2 + y 2 = a2 (a > 0),L依顺时针方向转动一周,则
(B) 3 4;
(C)− 1 2;
(D)1.
二、填空题(每小题3分,共15分) 1.曲线积分
x L (e sin y
+ my )dx + ex cos ydy 的值为
,其中L为上半
圆x2 + y 2 ≤ 2ax(a > 0, y ≥ 0). 2.设u = z + 3.幂级数
∞ n=1
x2 + y 2 ,则div(gradu) =
1 4
3.(7分)求二重积分 4.(7分)计算I =
2006-2007高数下(8学分)期末试题A及解答

华东理工大学2006-2007学年高等数学下(8学分)期末考试试卷A 2007.7一. 填空题(每小题4分, 共36分) 1.微分方程22x x e xy y -=+'满足初始条件0)0(=y 的特解为y =____________. 2.微分方程09)4(=''+y y 的通解为y =________________.3.1||||==b a , a 与b 夹角等于3π, 则|32|b a -=_____________.4.过直线⎩⎨⎧=-=+21:z y y x L 且平行于}4,1,2{--=l 的平面方程是____________5.设),4()(2)4(t e t f t F -+=, 其中1),(C y x f ∈且有a f =-)1,2(及b f =-')1,2(1, c f =-')1,2(2, 则)0(F '=______________6.设函数),(y x z z =由方程xz xy e z y x -=-+32确定, 则)0,0(dz =_____________.7.σd y x y x y x ⎰⎰≤++++12222222)(1)(=______________.8.广义积分dx x x ⎰+∞+1)1(1=_______________. 9.极坐标系下心脏线)cos 1(2ϑρ+=所围成区域D 的面积为A =_______________.二. 选择题(每小题4分, 共32分)1.椭圆122≤+y x 绕x 轴和y 轴旋转所得的体积分别是上x V 和y V , 则 ( ) (A)y x V V 49=; (B)y x V V 32=; (C)y x V V 94=; (D)y x V V 23=.2.函数Cx y =是微分方程032=+'-''y y x y x 的 ( ) (A)通解; (B)特解; (C)是解, 但既不是通解, 也不是特解; (D)以上都不对.3.若a 与b不平行, 且μλ≠, 则b a λ+与b a μ+ ( ) (A)必不平行; (B)模不相等; (C)必不垂直(正交); (D)不排除有平行的可能性; 4.“函数),(y x f 在),(00y x 点两个一阶偏导数都存在”是“函数),(y x f 在),(00y x 点 可微”的 ( ) (A)充分条件, 但不是必要条件; (B)必要条件, 但不是充分条件;(C)必要条件; (D)既不是充分条件, 也不是必要条件.5.设2C f ∈, ),,2(xz z y y x f u -+=, 则yx u∂∂∂2= ( )(A)131122f z f ''+''; (B)23131122f z f z f ''+''+''; (C)2313121122f z f z f f ''+''+''+''; (D)23131211222f z f z f f ''+''+''+'' 6.C f ∈, 则⎰⎰ϑϑπρρρρϑρϑcos 2sec 40)sin ,cos (d f d = ( )(A)⎰⎰--111102),(y dx y x f dy ; (B)⎰⎰-22121),(x x dy y x f dx ; (C)⎰⎰-22020),(x x dy y x f dx ; (D)⎰⎰-+211110),(y dx y x f dy .7.下列极限中等于0的是 ( ) (A)dx e n nn xn ⎰+∞→12lim ; (B)dx e n nn xn ⎰+∞→12lim ; (C)dx e n nn xn ⎰+∞→12lim ; (D)dx e n nn xn ⎰+∞→1222lim .8.边际成本等于边际收益是利润最大的 ( )(A)充要条件; (B)充分条件, 非必要条件;(C)必要条件, 非充分条件; (D)既不是必要条件, 也不是充分条件.三. (本题8分) 微分方程y y y y ''='+''2)(2满足初始条件2)0(=y , 3)0(='y 的特解.四. (本题8分)求曲线⎩⎨⎧-=++=++3zx yz xy z y x L :上的点P , 使L 在点P 处的切线平行与平面0=-+z y x .五. (本题8分) 利用夹逼性准则求极限)332211(lim 2222nn nn n n n n n n n ++++++++++++∞→ . 六. (本题8分)求有二阶连续导数的函数)0)((>t t f , 使)(22y x f u +=满足12222=∂∂+∂∂y ux u .华东理工大学2006-2007学年第二学期《高等数学(下)》课程期终考试试卷参考答案与评分标准一.填空题(每小题4分,共36分)1.)1e (e2--x x 2.x C x C x C C 3sin 3cos 4321+++ 3.7 4. 123=++z y x5. )8(3c b a - 6. y xd 20d 1+ 7. )122(3-π8. 2ln 9. π6二.选择题(每小题4分,共32分):8.C. 7.C; 6.D; 5.B; B; 4.A; 3.; C 2.; 1.D三.以y p '=为新未知函数,暂以y 为新自变量,原方程可化为 p ypy 2d d )1(=----(2分)解得 21)1(-=y C p ------------------------------------------------(2分)由32==y p可得31=C ---------------------------------------------------------------------------(1分)由2)1(3-='y y 解得x C y 3112-=----------------------------------------------------------(2分) 根据条件2)0(=y 可得12=C ,即x y 3111-=-或xxy 3132--=------------------------(1分) 四.因为{}1,1,11=→n ,{}y x x z z y n +++=→,,2,所以切向量为 {}y x x z z y n n t ---=⨯=→→→,,21 --------------------------( 3分){}{}y x y x x z z y l t lt =⇒=-⋅---⇒=⋅⇒⊥→→→→1,1,1.,0 ------------(3分)代入原曲线方程(组)得⎩⎨⎧-=+=+32,022zx x z x 解得)2,1,1(1-=P 和)2,1,1(2--=P -------(2分)五.(本题8分)记kn kn b k ++=2,n k ,,3,2,1 =,并记n n b b b a +++= 21, 适当放大缩小可得11122++≤≤++=n n n b n n n n k ,n k ,,3,2,1 =, 所以 n k n Q n n n n a n n P =⎪⎪⎭⎫⎝⎛++≤≤⎪⎭⎫ ⎝⎛=112----------------------------------------------------(5分) 而1lim lim ==∞→∞→n n n n Q P ,根据夹逼准则可得1lim =∞→k n a -------------------------------------(3分)六.(本题8分)记22y x t +=,则有)(t f u =,所以tx t f x u ⋅'=∂∂)(,t y t f y u⋅'=∂∂)(-------------------------------(1分) 322222)()(ty t f t x t f x u ⋅'+⋅''=∂∂,322222)()(t x t f t y t f y u ⋅'+⋅''=∂∂---------(2分) 原方程可化为 1)(1)(='+''t f tt f ---------------------------------------------------------(1分) 以)(t f p '=为新的未知函数,仍然以x 为自变量,得到新方程为11=+'p tp ------------------------------------------------(2分)解得t C t p t f 121)(+==',从而有212ln 21)(C t C t t f ++=--------------------------(2分)。
2006-2007学年第二学期高等数学期末试题(B)答案

2006~2007学年第二学期《高等数学A 》期终试题(B )卷参考答案一、选择题(本题共5小题, 每小题5分,满分25分)1.D; 2.B ; 3.A; 4.B; 5.C .二、填空题(本题共5小题, 每小题5分,满分25分)1.xdy x dx yx yy ln 1+-; 2. 21; 3.5512a π; 4.x e C x y sin )(-+=; 5.),(,)!12(121+∞-∞-∑=-∞=n x shx n n . 三(本题满分6分)解:.6,33222y yx z y x x z -=∂∂∂-=∂∂(每个3分) 四(本题满分6分)解:方程两边对x 求导,0=∂∂--∂∂x z xy yz x z ez ………(3分) 解得xye yz x z z -=∂∂………(6分) 五(本题满分7分)对应的齐次方程的特征方程为0452=++r r ,………(2分)特征根为4,1-=-=r r (3分)对应的齐次方程的通解为x x e c e c y 421--+=………(4分),特解为x y 21811-=*………(5分),原方程的通解为 =y x e c e c x x 21811421-++--………(7分) 六(本题满分8分)解:xQ y P ∂∂=∂∂…………(1分),即,2)(2)(2)(x x f x x f x f -'+=…………(2分)整理得1)(21)(=+'x f xx f ,解得)()(2121C dx e e x f dx x dx x +⎰⎰=⎰-…………(4分) ),32(1)(123C x x C dx x x +=+=⎰……(6分) 由1)1(=f 得C ,31=……(7分)故x x x f 3132)(+=……(8分) 七(本题满分8分)解:用柱面坐标得:⎰⎰⎰⎰⎰⎰=Ωπρρρθ202042zdz d d zdv …………(4分) π364= …………(4分) 八(本题满分8分)、解:,||12)1(:1)1(2)1(lim 2121)1(21x x n x n n n n n n =+-++-++++∞→ 1||2<∴x , 即当1||<x 时级数绝对收敛,从而收敛;当1||>x 时,级数发散………………………(2分)当1=x 时,原级数为收敛的交错级数∑∞=+-012)1(n n n ; ……(3分)当1-=x ,级数也为收敛的交错级数∑∞=++-0112)1(n n n .…(4分)故级数12012)1(+∞=∑+-n n nx n 的收敛区间为]1,1[-……………(5分), 令=)(x f 12012)1(+∞=∑+-n n n x n ,,1||≤x 则224211)1(1)('x x x x x f n n +=+-+-+-= ,…………(6分) 得,11)('002⎰⎰+=xxdx x dx x f 由于0)0(=f ,故x x f arctan )(=,.1||≤x ………(8分) 九(本题满分7分)解:对)(x f 进行偶延拓,…………(1分) 则有⎪⎩⎪⎨⎧=-==-=++=+=⎰.,5,3,1,4,,6,4,2,0)1(cos 2]cos sin )1([2cos )1(222002 n n n n n n nx n nx x nxdx x a n πππππππ……(4分) ,2)1(20+=+=⎰πππdx x a …………(5分)故)0(1)(π≤≤+=x x x f 展开成余弦级数为 ),5cos 513cos 31(cos 412122 +++-+=+x x x x ππ).0(π≤≤x ……(7分)。
天津大学2006~2007学年第二学期期末考试试卷答案

天津大学试卷专用纸学院专业班年级学号姓名共 5 页第1 页天津大学试卷专用纸学院专业班年级学号姓名共 5 页第2 页11.下列金属硫化物中,可溶于稀盐酸的是______。
(A) ZnS (B) PbS (C) CuS (D) Ag2S12. 下面三种物质热稳定性顺序正确的是______。
(A) NH4HCO3<Na2CO3<Ag2CO3 (B) NH4HCO3<Ag2CO3<Na2CO3(C) Na2CO3<NH4HCO3<Ag2CO3 (D)Ag2CO3<NH4HCO3<Na2CO313.下列关于硼酸结构的叙述错误的是_______.(A) 硼酸为白色片状晶体,其结构单元为平面三角形的B(OH)3(B) 硼原子通过sp3杂化轨道与三个OH基团成键(C) 分子间通过氢键形成接近于六角形的对称层状结构(D) 层与层间以范德华力联系14.仅用一种试剂就可以将Ag+, Hg2+, Zn2+, Fe3+, Ni2+ 5种离子区分开,这种试剂可选用_________。
(A) NaCl(B) NaOH (C) K2SO4 (D)H2SO415. 下列有关碱金属过氧化物性质的描述不正确的是_________。
(A)过氧离子中的O-O键不如氧分子中的O-O键牢固(B)碱金属过氧化物具有氧化性(C)碱金属过氧化物具有还原性(D)碱金属过氧化物与冷水反应可生成H2O2, 所以H2O2可看作过氧离子的共轭酸16. 向下列溶液中加入AgNO3溶液,析出黑色沉淀的是_________。
(A)H3PO4(B) NaH2PO4(C) H3PO2(D) Na2H2P2O717. 下列说法不正确的是_________。
(A)还原性HClO4 > HClO3 > HClO(B)热稳定性NaClO > NaClO3 > NaClO4(C)氧化性NaClO >> NaClO3 > NaClO4(D)酸性HClO4 > HClO3 > HClO18. 有关HgCl2和Hg2Cl2的描述不正确的是_________。
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天津大学试卷专用纸____ 班年级______________ 学号__________________ 姓名_____________共5页第1页学院专业2006〜2007学年第二学期期末考试试卷参考答案《无机化学与化学分析》(A卷共5页)(考试时间:2007年7月4日)2 .可用于减小测定过程中偶然误差的方法是__________ 。
(A)对照实验(B)空白实验(C)校正仪器(D)增加平行测定次数3. ___________________________________________________ 在酸性介质中,用KMnO4溶液滴定草酸盐,滴定应___________________ 。
(A)快速进行(B)在开始时缓慢进行,以后逐渐加快(C)始终缓慢地进行(D)快慢都可以(A) BF 3 (B) AlCl 3 (C) H3BO3 (D) H[BF 4]9. ___________________________ 金属锡与浓硝酸反应所得到的产物有______________________________ 。
(A) SnO2 和NO2 (B) H2SnO3(M和NO2(C) H2SnO3(3和NO2 (D) Sn(NO3)2 和NO210. _____________________________ 下列各组物质能共存于同一溶液中的是_____________________________ 。
分)1. (X )卤素单质自F2至12熔、沸点逐渐升高,是由于取向力逐渐增大。
2. (X )一般情况下浓HNO3被还原剂还原为NO2,稀HNO3被还原为NO,因此稀HNO3的氧化性大于浓HNO3的氧化性。
3. (X )金属Zn、Cu能溶解于氨水和NaOH溶液中,都可以与CN-形成配合物。
4. (V )[Ti(H 20)6]3+呈紫色是因为发生d-d跃迁的缘故;MnO4-呈紫色是因为发生了p-d跃迁的缘故。
5. (V )氯的含氧酸盐热稳定性次序为MCIO v MCIO 3v MCIO4。
6. (X )碳酸盐的溶解度均比酸式碳酸盐的溶解度小。
7. (V )金属铁可置换溶液中的Cu2+离子为金属铜,而金属铜也可与FeT离子反应生成Fe2+离子和Cu2+离子。
8. (X )O3(g)不是直线型分子,它是顺磁性物质。
9. (X )分析结果的置信度要求越高,置信区间越小。
10. (X )有效数字是指所用仪器可以显示的数字。
4.钠的液氨溶液呈深蓝色且能导电,一般认为溶液中含有_______________________________________________________________ <(A)NH 4+和NH2-(C)Na+和e-5.元素周期表中第五、六周期的于_________ 。
(A) s区元素的影响(C) ds区元素的影响•选择题(每题只有一个正确的答案,将所选答案的号码填入下表中题号对应的表格内。
本题20分)(B)Na+和NH2-(D)Na+和e(NH3)x-IVB、VB、VIB族中的各元素性质非常相似,这是由6.现有ds区某元素的硫酸盐A和另(B) p区元素的影响(D)镧系收缩的影响元素氯化物B水溶液,各加入适量KI溶液,则A生成某元素的碘化物沉淀和12。
B则生成碘化物沉淀,这碘化物沉淀进一步与KI 溶液作用,生成配合物溶解,则硫酸盐和氯化物分别是____________ C(A) ZnSO4,Hg2Cl2 (B) CuSO4,HgCl2(C) CdSO4,HgCl2 (D) Ag2SO4,Hg2Cl27.在Cr2(SO4)3溶液中,加入Na2S溶液,其主要产物是(A) Cr+S (B) Cr2S3+Na2SO4- 2-(C) Cr(OH) 3+H2S (D) CrO 2+S8.下列化合物中不属于缺电子化合物的是___________1.下列各组物质中,可用Na2S —种试剂逐一鉴别出来的是 ___________ 。
(A) NH4CI、(NH4)2SO4、(NH4)2CO3 (B) Ba(NO3)2、Pb(NO3)2、Al(NO 3)3(C) PbCl2、Bi(NO3)3、AgNO3 (D) Na2S2O3、Na2SO4、Na3PO4(A) Fe2、NO2、NH4、Cl (B) Al3、NH3、Cl、SO42(C) Sn2+、H2S、Cl-、Na+(D) Cr3+、Mn2+、Fe3+、Co2+、SO42天津大学试卷专用纸____ 班年级______________ 学号__________________ 姓名_____________共5页第2页学院专业11. 下列金属硫化物中,可溶于稀盐酸的是。
(A) ZnS (B) PbS (C) CuS (D) Ag z S12. 下面三种物质热稳定性顺序正确的是。
(A) NH4HCO3V Na2CO3V Ag2CO3 (B) NH4HCO3V Ag2CO3V N&C03(C) Na?CO3< NH4HCO3V Ag2CO3 (D)Ag 2CO3V NH4HCO3V N&CO313. 下列关于硼酸结构的叙述错误的是(A) 硼酸为白色片状晶体,其结构单元为平面三角形的B(OH)3(B) 硼原子通过sp3杂化轨道与三个OH基团成键(C) 分子间通过氢键形成接近于六角形的对称层状结构(D) 层与层间以范德华力联系14. 仅用一种试剂就可以将Ag , Hg2 , Zn2 , Fe3 , Ni2 5种离子区分开,这种试剂可选用。
(A) NaCl (B) NaOH (C) K2SO4 (D)H2SO415. 下列有关碱金属过氧化物性质的描述不正确的是。
(A) 过氧离子中的O-O键不如氧分子中的O-O键牢固(B) 碱金属过氧化物具有氧化性(C) 碱金属过氧化物具有还原性(D) 碱金属过氧化物与冷水反应可生成H2O2,所以H2O2可看作过氧离子的共轭酸16. 向下列溶液中加入AgNO3溶液,析出黑色沉淀的是。
(A)H 3PO4 (B) NaH2PO4 (C) H3PO2 (D) Na2H2P2O717. 下列说法不正确的是。
(A) 还原性HCIO4 > HCIO3 > HClO(B) 热稳定性NaClO > NaClO3 > NaClO4(C) 氧化性NaClO >> NaClO3 > NaClO4(D) 酸性HCIO4 > HCIO3 > HClO18. 有关HgCl2和Hg2Cl2的描述不正确的是。
(A) H gCl 2和Hg z Cb都是剧毒的化合物(B) 二者都可以和NH3H2O反应牛成Hg(NH2)CI(C) 这两种化合物都可以被SnCI2还原19. CrO5中Cr的真实氧化数为。
(A) 4 (B) 6 (C) 8 (D) 1020. 下列物质的水溶液易变为棕红色的是。
(A) AgNO 3 (B) (NH 4)2S (C) HBr (D) NH 4SCN三.填空题(本题17分)1. CuCI、AgCI、Hg2Cl2均为难溶于水的白色粉末,加入过量的氨水,溶解的是CuCI ,AgCI ,产物分别为[Cu(NH3)2]+,[Ag(NH 3)2]+ ;不溶解的是Hg2Cl2 ,产物为HgNH2CI Hg 。
2. 物质SnS、SnQ、Bi z S s、PbS、AS2S3、S6S3、ZnS、MnS 和K?S 中,能溶于硫化铵的有:SnS? , AS2S3 , SbS3 , K2S 。
3. 在d区第一过渡系、s区、p区和ds区金属的氢氧化物中,能溶于酸又能溶于碱的两性氢氧化物有:Cu(OH)2 , Zn (OH)2 , Be(OH)2 , AI(OH)3 , As(OH)3 , Sb(OH)3 , Pb(OHb , Cr(OH)3 。
4. 用同一KMnO4标准溶液分别滴定等体积的FeSQ和H2C2O4溶液,消耗KMnO4的体积相等,则H2C2O4与FeSd浓度的关系为c(H2C2O4) : c(FeSO) = 1:2 。
5. 以HCI为滴定剂测定试样中K2CO3含量,若其中含有少量Na2CO3,测定结果将偏咼。
(填偏咼、偏低或无影响)6. 金属离子指示剂与金属离子生成的络合物过于稳定称为指示剂封闭。
7. 某银白色金属A在空气中容易生成化合物B而使其钝化,经过灼烧的B难溶于酸也难溶于碱,但和KHSO4熔融可形成可溶性的硫酸盐C和D,C的水溶液呈淡紫色或紫色,在C 的溶液中加入适量的碱,可形成灰绿色沉淀E,沉淀E与碱反应形成F而溶解,F与H2O2作用生成黄色溶液G,溶液G酸化后变成橙色溶液H,在H中加入Pb(NO3)2生成黄色沉淀1。
与出下列编号所代表的物质的化学式:A Cr ,B C12O3 ,C C12一(SO4f , E Cr(OH)3 ,F [Cr(OH)4] ,G _CrO42 ,H aa2,I PbCrO4 。
8. 亚磷酸(H3PO3)二元酸,次磷酸(H3PO2)是一元酸,这两种酸及其盐的水溶液都具有较强的还原性。
次磷酸不稳定,在无氧化剂存在时,它在碱性溶液中很容易歧化生成—PH ____ 和HPO32-。
天津大学试卷专用纸____ 班年级______________ 学号__________________ 姓名_____________共5页第3页学院专业1. 酸性介质中H3ASO4与I「反应H3ASO4 + 2 I - +2H+—H3ASO3 + I2 +H2O2. 氯气与黄血盐反应4- 3- -2[Fe(CN)6] + CI2 —2 [Fe(CN)6] +2CI3. 在碱性条件下,Ni(OH)2与次氯酸钠溶液反应2Ni(OH)2 + CIO-—2NiO(OH)J +Cl- + H2O4. 氧化亚铜溶于稀硫酸+ 2+CU2O + 2H —Cu J + Cu + H2O5. 用硝酸酸化过的NaBiO3中,逐滴加入MnCI2溶液,先出现紫红色,然后紫红色又逐渐变为棕色5NaBiO3 + 2Mn2+ + 14H+—5Bi3+ +2MnO『+5Na+ +7H2O2MnO4 + 3Mn2 + 2出0 —5Mn O2J + 4H6. 酸性KMnO4溶液与NaNO2溶液反应- - + 2+ -2MnO4 + 5NO2 +6H —2Mn + 5NO3 + 3H2O天津大学试卷专用纸____ 班年级______________ 学号__________________ 姓名_____________共5页第4页学院专业7. 重铬酸铵的加热分解(NH4)2CtO7 爸503 + N2 T + 4 HOT8. Na2B4O7 和MnO 熔融Na2B4O7 + MnO —L Mn(BO 2)2 2NaBO29. 向FeCb溶液中通入H2S气体2Fe3+ + H2S —2Fe+ + S J + 2 H10. H2O滴加在红磷和碘的混合物上312 + 2P + 6 H2O —2H3PO3 +6HI T11. Bi(OH)3在强碱性(NaOH)中被Cb氧化Bi(OH) 3 + Cl2 +3 NaOH —NaBiO3 +2NaCl + 3 出0 12. 金属锌溶于氨水Zn + 4NH 3 + 2 H2O —[Zn(NH3)4]2+ + H2 T + 20H13. PbO2 + Mn SO4 + HNO3 —2+ 2- + -2Mn +5 SO4 +5 PbO2 + 4 H —2MnO4 + 2 H2O + 5PbSC4 六•计算题:(本题共12分)1 •银量法中常以K2CrO4溶液为指示剂,以AgNO3为滴定剂,测定溶液中Cl-含量。