苏州市2020┄2021届高三教学调研测试附答案

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江苏省苏州市2020_2021学年高三英语学业质量阳光指标调研试题含解析

江苏省苏州市2020_2021学年高三英语学业质量阳光指标调研试题含解析

某某省某某市2020-2021学年高三英语学业质量阳光指标调研试题(含解析)第一部分第一节:每小题1.5分1. What does the woman think of golf?A. It’s fun.B. It’s sillyC. It’s exciting2. How much will the man pay?A. 50B. 40C. 203. What does the man want to do?A. Walk to the next stop.B. Wait for the next bus.C. stay on the bus.4. Where does the conversation probably take place?A. At a restaurant.B. At a hotel.C. In a shop5. What is John doing?A. Meeting the managerB. Visiting his father.C. Asking for leave.第二节:每小题1.5分6. What did the man do in Atlanta?A. Attended two meetings.B. Made a presentation.C. Worked in the garden.7. Why did the woman move to Colorado?A. She got a job.B. She liked the weather.C. She went to college.8. What does the man say about the city?A. It’s cleaner.B. It’s healthier.C. It’s more dangerous.9. What do we know about the woman?A. She is married.B. She is living in the city.C. She is young.10. What has Peter been doing?A. Interviewing new employees.B. Shopping for a new suit.C. Looking for a job.11.What does the woman think of Peter’s quitting? A. Smart. B. Unwise. C. Surprising. 12. What does the man advise Peter to do? A. T o try a networking group. B. To send out more resumes. C. T o call for interviews. 13. Why does the man make the call? A. T o ask for his account number. B. To check his electricity bill. C. T o register in the database 14. What will the woman do to help the man? A. Open an account for the man. B. Contact the man’s manager.C. Mark the man’s enquiry.15. When can the man get a feedback?A. By the end of the weekB. At the weekend.C. After a week.16. What is the enquiry number?A. 2368.B. 3471.C. 3271.17. Which suits you when you study?A. sweets.B. Cola.C. apples.18. What are you supposed to do when you feel anxious?A. Find a fortable place.B. Go out for a walk.C. Drink a glass of water.19. What should the students avoid doing?A. Trying to learn everything.B. Taking regular breaks.C. Using past exam papers.20. What is probably the speaker?A. A student.B. A teacher.C. A parent.第二部分第一节:每小题2.5分AThere are two May bank holidays ing up! While we're sure you're excited to have a few extra days with your family and friends this month, we know you re probably wondering how to keep them occupied! A day trip or weekend getaway to London may be a good choice. We've picked the top four things to do!SEALIFE LondonLondon may not be top of mind when it es to checking all your favorite sea creatures but SEALIFE London offers a further understanding of the underwater world. Head over to the new Rainforest Adventure and e face to face with some of the strangest creatures you’ve ever seen.Adult admission: £ 26[ save £ 26 with 2 FOR 1]Clip’n ClimbHead to this colorful labyrinth (迷宫) in Chelsea where the little ones can swing, climb and explore to their hearts content. Let them take on the challenge of the “The scraper”, “Jungle Gym" and lots more. You can even register- to "climbercise", which includes a harness(马具) fitting, warm up and 60 minutes inside the climbing arena(场地).Child admission: £ 17.50ZSL London ZooEveryone loves a day out at the zoo. Explore the 750 species of animal and discover thousands of surprising and fascinating facts just waiting to be discovered. Hear the roar of the Asiatic lions, then catch a glimpse of the friendly giraffes. Wander through the ring-tailed lemurs(狐猴) before heading over to BUGS to quizthe insect experts. You just have to experience It yourselves.Adult admission: £ 27.04 [save £ 27.04 wit h 2 FOR 1]KidzaniaKidZania is a child-sized city in Shepherd’s Bush where the kids are in charge. Watch the excitement on their faces as they try out more than 60 real-life role-play activities. An empowering and entertaining experience, not to be missed!Admission: £ 35(online) [save £ 35 with 2 FOR 1]1. Where can people go if they like giraffes?A. Clip’n ClimbB. ZSL London ZooC. SEALIFE LondonD. Kidzania2. What do we know about SEALIFE London?A. It offers people’s favorite creatures.B. People like travelling there best.C. All the creatures there are strange.D. People can experience an adventure.3. How much will four friends pay if they go to KidZania?A. 35.B. 52C. 54.08D. 70【答案】1. B 2. D 3. D【解析】本文是一篇应用文。

江苏省苏州市2020-2021学年下学期期初学业质量阳光指标调研卷高三数学试题 含答案

江苏省苏州市2020-2021学年下学期期初学业质量阳光指标调研卷高三数学试题   含答案

苏州市2020~2021学年第二学期期初学业质量阳光指标调研卷高三数学注意事项:学生在答题前请认真阅读本注意事项及各题答题要求:1.本卷共6页,包含单项选择题(第1题~第8题)、多项选择题(第9题~第12题)、填空题(第13题~第16题)解答题(第17题~第22题).本卷满分150分,答题时间为120分钟.答题结束后,请将答题卡交回。

2.答题前,请您务必将自己的姓名、调研序列号用0.5毫米黑色墨水的签字笔填写在答题卡 的规定位置。

3.请在答题卡上按照顺序在对应的答题区域内作答,在其他位置作答一律无效.作答必须用 0.5毫米黑色墨水的签字笔.请注意字体工整,笔迹清楚.一、选择题.本题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的。

1.如图,阴影部分所表示的集合为A.A ∩(C U B)B.B ∩(C U A)C.A ∪(C U B)D.B ∪(C U A)2.已知复数z 满足iz=1-i(i 为虚数单位),则z 在复平面内对应的点在A.第一象限B.第二象限C.第三象限D.第四象限3.已知等差数列{a n }的前n 项和为S n ,2(a 1+a 3+a 5)+3(a 8+a 10)=60,则S 11的值为A.33B.44C.55D.664.古希腊哲学家毕达哥拉斯曾说过:“美的线型和其他一切美的形体都必须有对称形式”.在中华传统文化里,建筑、器物、书法、诗歌、对联、绘画几乎无不讲究对称之美。

如清代诗人黄柏权的《茶壶回文诗》(如图)以连环诗的形式展现,20个字绕着茶壶成一圆环,不论顺着读还是逆着读,皆成佳作.数学与生活也有许多奇妙的联系,如2020年02月02日(20200202)电元被称为世界完全对称日(公历纪年日期中数字左右完全对称的日期)数学上把20200202这样的对称数叫回文数,两位数的回文数共有9个(11,22,...,99),则在三位数的回文数中,出现奇数的概率为A. 13 B. 49 C. 59 D. 235.如图,在斜坐标系xOy 中,x 轴、y 轴相交成60°角,e 1,e 2分别是与x 轴、y 轴正方向同向的单位向量,若向量OP =xe 1+ye 2,则称有序实数对(x,y)为向量OP 的坐标,记作OP =(x,y).在此斜坐标系xOy 中,已知向量a =(2,3),b =(-5,2),则a ,b 夹角的大小为A. 6πB. 3π C. 23π D. 56π6.已知函数y=f(x)和y=g(x)分别是定义在R 上的偶函数和奇函数,且f(0)=-4,f(x)=g(x+2),则g(x)的解析式可以是 A.y=-4sin4x π B.y=4sin 2x π C.y=-4cos 4x π D.y=4cos 2x π 7.已知函数f(x)=2sin(2x+6π),若α为锐角且f(2a )=65,则f(α+12π)的值为 A.- 4825 B.- 2425 C. 2425 D. 48258.我国南北朝时期的数学家祖暅在计算球的体积时,提出了一个原理(祖暅原理):“幂势既同,则积不容异”这里的“幂”指水平截面的面积,“势”指高。

江苏省苏州市2020~2021学年第一学期高三期初调研试卷数学(word版含答案)

江苏省苏州市2020~2021学年第一学期高三期初调研试卷数学(word版含答案)

江苏省苏州市2020~2021学年第一学期高三期初调研试卷数学试题2020.9一、单项选择题(本大题共8小题,每小题5分,共计40分.在每小题给出的四个选项中,只有一个是符合题目要求的,请把答案添涂在答题卡相应位置上)1.集合A ={}2230x x x --≤,B ={}1x x >,A B =A .(1,3)B .(1,3]C .[﹣1,+∞)D .(1,+∞)2.复数z 满足(1+i)z =2+3i ,则z 在复平面表示的点所在的象限为A .第一象限B .第二象限C .第三象限D .第四象限3.421(2)x x -的展开式中x 的系数为 A .﹣32 B .32 C .﹣8 D .84.已知随机变量ξ服从正态分布N(1,2σ),若P(ξ<4)=0.9,则P(﹣2<ξ<1)为A .0.2B .0.3C .0.4D .0.65.在△ABC 中,AB AC 2AD +=,AE 2DE 0+=,若EB AB AC x y =+,则A .y =2xB .y =﹣2xC .x =2yD .x =﹣2y6.大西洋鲑鱼每年都要逆流而上,游回到自己出生的淡水流域产卵,记鲑鱼的游速为v (单位:m /s ),鲑鱼的耗氧量的单位数为Q .科学研究发现v 与3Q log 100成正比,当v =1m /s 时,鲑的耗氧量的单位数为900.当v =2m /s 时,其耗氧量的单位数为A .1800B .2700C .7290D .81007.如图,正方体ABCD —A 1B 1C 1D 1的棱长为1,则下列四个命题不正确的是A .直线BC 与平面ABC 1D 1所成的角等于4πB .点C 到面ABC 1D 1的距离为2C .两条异面直线D 1C 和BC 1所成的角为4πD .三棱柱AA 1D 1—BB 1C 18.设a >0,b >0,且2a +b =1,则12a a a b ++ A .有最小值为4 B .有最小值为221+C .有最小值为143D .无最小值 二、 多项选择题(本大题共4小题,每小题5分, 共计20分.在每小题给出的四个选项中,至少有两个是符合题目要求的,请把答案添涂在答题卡相应位置上)9.A ,B 是不在平面α内的任意两点,则A .在α内存在直线与直线AB 异面 B .在α内存在直线与直线AB 相交C .存在过直线AB 的平面与α垂直D .在α内存在直线与直线AB 平行10.水车在古代是进行灌溉引水的工具,亦称“水转简车”,是一种以水流作动力,取水灌田的工具.据史料记载,水车发明于隋而盛于唐,距今已有1000多年的历史,是人类的一项古老的发明,也是人类利用自然和改造自然的象征,如图是一个半径为R 的水车,一个水斗从点A(3,33-)出发,沿圆周按逆时针方向匀速旋转,且旋转一周用时120秒.经过t 秒后,水斗旋转到P 点,设点P 的坐标为(x ,y ),其纵坐标满足()R y f t == sin()t ωϕ+(t ≥0,ω>0,2πϕ<),则下列叙述正确的是 A .3πϕ=-B .当t ∈(0,60]时,函数()y f t =单调递增C .当t ∈(0,60]时,()f t 的最大值为33D .当t =100时,PA 6=11.把方程1x x y y +=表示的曲线作为函数()y f x =的图象,则下列结论正确的有A .()y f x =的图象不经过第三象限B .()f x 在R 上单调递增C .()y f x =的图象上的点到坐标原点的距离的最小值为1D .函数()()g x f x x =+不存在零点12.数列{}n a 为等比数列A .{}1n n a a ++为等比数列B .{}1n n a a +为等比数列C .{}221n n a a ++为等比数列D .{}n S 不为等比数列(n S 为数列{}n a 的前n 项和三、填空题(本大题共4小题, 每小题5分,共计20分.请把答案填写在答题卡相应位置上)13.已知tan 2α=,则cos(2)2πα+= .14.已知正方体棱长为2,以正方体的一个顶点为球心,以为半径作球面,则该球面被正方体表面所截得的所有的弧长和为 .15.直线40kx y ++=将圆C :2220x y y +-=分割成两段圆弧之比为3:1,则k = .16.已知各项均为正数的等比数列{}n a ,若4321228a a a a +--=,则872a a +的最小值为 .四、解答题(本大题共6小题,共计70分.请在答题卡指定区域内作答.解答时应写出文字说明、证明过程或演算步骤)17.(本小题满分10分)在△ABC 中,角A ,B ,C 的对边分别为a ,b ,c ,△ABC 的面积为S .现在以下三个条件:①(2c +b)cosA +acosB =0;②sin 2B +sin 2C ﹣sin 2A +sinBsinC =0;③a 2﹣b 2﹣c 2S .请从以上三个条件中选择一个填到下面问题中的横线上,并求解.已知向量m =(4sin x ,,n =(cos x ,sin 2x ),函数()23f x m n =⋅-,在△ABC。

江苏省苏州市2021届高三上学期期初调研地理试题含答案

江苏省苏州市2021届高三上学期期初调研地理试题含答案

江苏省苏州市2021届⾼三上学期期初调研地理试题含答案江苏省苏州市2020 - 2021学年第⼀学期⾼三期初调研试卷地理2020.09 说明:1.本试卷满分100分,考试时间90分钟。

2.答题前,请务必将⾃⼰的姓名、准考证号填写在答题卡上。

3.请将所有答案按照题号填涂或填写在答题卡(纸)相应的答题处,否则不得分。

第I卷(选择题共50分)⼀、选择题(共50分)(⼀)单项选择题:本⼤题共16⼩题,每⼩题2分,共32分。

在每⼩题给出的四个选项中,只有⼀项是符合题⽬要求的。

右图为某⽇四地太阳⾼度变化图(时间为北京时间),图中丙地在回归线附近。

据此完成1 ~2题。

1.四地纬度由低到⾼的排序是A.甲⼄丙丁B.⼄丙丁甲C.丙丁甲⼄D.⼄丙甲丁2.该⽇⼀个⽉以后A.甲地正午太阳⾼度变⼤B.⼄地⽩昼时间逐渐变长C.丙地昼夜长短差值缩⼩D.丁地⽇出⽅位偏离正东下图为2019年2⽉某⽇某时刻欧洲西部部分地区海平⾯等压线分布图(单位:百帕)。

据此完成3~4题。

3.此时,受不同天⽓系统影响A.甲地风向为东南风B.⼄地狂风暴雪C.丙地有连续性降⽔D.丁地⾬过天晴4.与同纬度⼤陆东岸地区相⽐,丙地A.⽓温年较差⼩B.降⽔量年变化⼤C.四季变化明显D.年太阳辐射量⼤2018年8⽉4⽇,在“⼀带⼀路”倡议五周年之际,央视记者⾏⾛“冰上丝绸之路”,从江苏连云港出发,取道北极东北航道,从西太平洋,经⽩令海峡,跨越北冰洋,前往欧洲荷兰⿅特丹,历时30多天。

下图为“海上丝绸之路”与“冰上丝绸之路”⽰意图。

据此完成5~6题。

5.下列对各航段叙述正确的是A.甲→⼄:布满浮冰B.⼄→丙:途经⼤渔场C.丙→丁:逆风逆⽔D.甲→丁:全程昼渐长6.与“海上丝绸之路”相⽐,“冰上丝绸之路”最突出的A.航线⽐较安全B.沿途补给⽅便C.沿线贸易量⼤D.通航⾥程较短⽐特币是⼀种虚拟货币。

⽐特币挖矿机,就是⽤于获取⽐特币的计算机,耗电量较⼤。

若计算机运⾏特定程序得出的数据与远⽅服务器中数据相同,就可挖到相应的⽐特币。

2020-2021学年 苏州市高三期末教学情况调查(Word版 含答案)

2020-2021学年 苏州市高三期末教学情况调查(Word版 含答案)

2020年苏州市高三期末教学情况调查(模拟)化学2021.1注意事项:1.本试卷分选择题和非选择题两部分,共120分。

考试时间100分钟。

2.请将选择题的答案填涂在答题卡或对应表格内,非选择题的答案写在答题卷的指定栏目内。

可能用到的相对原子质量:H—1 C—12 O—16选择题(共42分)单项选择题本题包括6小题,每小题3分,共计18分。

每小题只有一个选项符合题意。

....1.化学与科学、技术、社会、环境密切相关。

下列有关说法中错误..的是A.北京奥运会燃放的焰火是某些金属元素焰色反应所呈现出来的色彩B.加热能杀死甲型H1N1流感病毒是因为病毒的蛋白质受热变性C.太阳能电池板中的硅在元素周期表中处于金属与非金属的交界位置D.废旧电池应集中回收,并填埋处理2.下列化学用语正确的是A.HCN分子的结构式:H-C≡N B.乙烯的结构简式:CH2CH2C.F-离子结构示意图:D.二氧化碳的电子式:3.下列实验操作正确的是A.用丁达尔现象区分淀粉溶胶和豆浆B.钠和水反应实验时,余下的金属钠放回原瓶C.浓硫酸与浓硝酸混合时,将浓硝酸加入浓硫酸中D.乙烯制备开始时未加碎瓷片,反应过程中打开橡皮塞重新加入4.用N A表示阿伏加德罗常数的值。

下列叙述正确的是A.常温常压下,4.6g乙醇中含有C-H键的个数为0.6N AB.一定温度下,15g甲醛和乙酸的混合物中O原子数为0.5N AC.1mol Cl2和1mol H2O充分反应,生成的H+离子数为N AD.标准状况下,11.2L庚烷完全燃烧后生成的CO2分子数为3.5N A5.下列各组离子能在指定溶液中,大量共存的是电解①无色溶液中:Al3+,Cl-,Na+,HCO3-,SO42-②使pH=11的溶液中:Na+,AlO2-,NO3-,S2-,SO32-③由水电离的H+浓度c(H+)=1×10-13mol/L的溶液中:Cl-,HCO3-,NO3-,NH4+,SO32-④加入Mg能放出H2的溶液中:Mg2+,NH4+,Cl-,K+,SO42-⑤使甲基橙变红的溶液中:Fe3+,MnO4-,NO3-,Na+,SO42-⑥酸性溶液中:Fe2+,Al3+,NO3-,I-,S2-A、①②⑤B、①③⑥C、②④⑤D、①②④6.短周期主族元素A、B、C、D原子序数依次增大。

江苏省2020—2021学年苏锡常镇四市高三教学情况调研(一)数学试题(word解析版)

江苏省2020—2021学年苏锡常镇四市高三教学情况调研(一)数学试题(word解析版)

江苏省2020—2021学年苏锡常镇四市高三教学情况调研(一)数学试卷一、单项选择题(本大题共8小题,每小题5分,共计40分.在每小题给出的四个选项中,只有一个是符合题目要求的,请把答案添涂在答题卡相应位置上) 1.设全集U =R ,集合A =[2,4],B ={}2log 1x x >,则集合A (UB)=A .∅B .{2}C .{}02x x ≤≤D .{}2x x ≤2.“2sin 2α=”是“sin cos αα=”的 A .充分不必要条件B .必要不充分条件 C .充要条件D .既不充分也不必要条件3.天干地支纪年法源于中国,中国自古便有十天干与十二地支,十天干即甲、乙、丙、丁、戊、己、庚、辛、王、癸;十二地支即子、丑、寅、卯、辰、已、午、未、申、酉、戌、亥.天干地支纪年法是按顺序以一个天干和一个地支相配,排列起来,天干在前,地支在后,天干由“甲”起,地支由“子”起,例如,第一年为“甲子”,第二年为“乙丑”,第三年为“丙寅”…,以此类推,排列到“癸酉”后,天干回到“甲”重新开始,即“甲戌”,“乙亥”,然后地支回到“子”重新开始,即“丙子”…,以此类推,今年是辛丑年,也是伟大、光荣、正确的中国共产党成立100周年,则中国共产党成立的那年是 A .辛酉年B .辛戊年C .壬酉年D .壬戊年4.5(32)(1)x x -+展开式中3x 的系数为 A .﹣15B .﹣10C .10D .155.函数2()sin ln(1)f x x x x =+-的图像大致是6.过抛物线22y x =上一点P 作圆C :22(6)1x y +-=的切线,切点为A ,B ,则当四边形PACB 的面积最小时,P 点的坐标是 A .(12.(323 C .(2,2)D .(525) 7.若随机变量X~B(3,p ),Y~N(2,2σ),若P(X ≥1)=0.657,P(0<Y <2)=p ,则P(Y >4)=A .0.2B .0.3C .0.7D .0.8 8.若316, 0()0, 0x x f x xx ⎧-≠⎪=⎨⎪=⎩,则满足(1)0xf x -≥的x 的取值范围是 A .[﹣1,1][3,+∞)B .(-∞,﹣1][0,1][3,+∞)C .[﹣1,0][1,+∞)D .(-∞,﹣3][﹣1,0][1,+∞)二、 多项选择题(本大题共4小题,每小题5分, 共计20分.在每小题给出的四个选项中,至少有两个是符合题目要求的,请把答案添涂在答题卡相应位置上) 9.函数()sin(2)4f x x π=+,则A .函数()y f x =的图象可由函数sin 2y x =的图象向右平移4π个单位得到 B .函数()y f x =的图象关于直线8x π=轴对称C .函数()y f x =的图象关于点(8π-,0)中心对称D .函数2()y x f x =+在(0,8π)上为增函数 10.已知O 为坐标系原点,F 1,F 2分别为双曲线22221x y a b-=(a >0,b >0)的左、右焦点,点P 在双曲线右支上,则下列结论正确的有 A .若PO =PF 2,则双曲线的离心率e ≥2B .若△POF 2是面积为3的正三角形,则223b =C .若A 2为双曲线的右顶点,PF 2⊥x 轴,则F 2A 2=F 2PD .若射线F 2P 与双曲线的一条渐近线交于点Q ,则12QF QF 2a ->11.1982年美国数学学会出了一道题:一个正四面体和一个正四棱锥的所有棱长都相等,将正四面体的一个面和正四棱锥的一个侧面紧贴重合在一起,得到一个新几何体.中学生丹尼尔做了一个如图所示的模型寄给美国数学学会,美国数学学会根据丹尼尔的模型修改了有关结论.对于该新几何体,则 A .AF ∥CD B .AF ⏊DEC .新几何体有7个面D .新几何体的六个顶点不能在同一个球面上 12.已知正数x ,y ,z 满足3412x y z ==,则A .634z x y <<B .121x y z+=C .4x y z +>D .24xy z <三、填空题(本大题共4小题, 每小题5分,共计20分.请把答案填写在答题卡相应位置上)13.已知向量a =(1,2),b =(0,﹣2),c =(﹣1,λ),若(2a b -)∥c ,则实数λ=. 14.已知复数z 对应的点在复平面第一象限内,甲、乙、丙、丁四人对复数z 的陈述如下(i为虚数单位):甲:2z z +=;乙:23i z z -=;丙:4z z ⋅=;丁:22z z z =.在甲、乙、丙、丁四人陈述中,有且只有两个人的陈述正确,则复数z =.15.若23sin 2cos 1x x +=,则5sin()cos(2)63x x ππ-⋅+=.16.四面体的棱长为1或2,但该四面体不是正四面体,请写出一个这样四面体的体积;这样的不同四面体的个数为.四、解答题(本大题共6小题,共计70分.请在答题卡指定区域内作答.解答时应写出文字说明、证明过程或演算步骤)17.(本小题满分10分)在△ABC中,∠BAC=90∘,点D在边BC上,满足AB=3BD.(1)若∠BAD=30°,求∠C;(2)若CD=2BD,AD=4,求△ABC的面积.18.(本小题满分12分)已知等比数列{}n a的各项均为整数,公比为q,且q>1,数列{}n a中有连续四项在集合M={﹣96,﹣24,36,48,192}中.(1)求q,并写出数列{}n a的一个通项公式;(2)设数列{}n a的前n项和为n S,证明:数列{}n S中的任意连续三项按适当顺序排列后,可以成等差数列.19.(本小题满分12分)如图,在四棱锥P—ABCD中,△PAD是以AD为斜边的等腰直角三角形,BC∥AD,AB⊥AD,AD=2AB=2BC=2,PC=2,E为PD的中点.(1)求直线PB与平面PAC所成角的正弦值;(2)设F是BE的中点,判断点F是否在平面PAC内,并请证明你的结论.20.(本小题满分12分)某地发现6名疑似病人中有1人感染病毒,需要通过血清检测确定该感染人员,血清检测结果呈阳性的即为感染人员,呈阴性表示没感染.拟采用两种方案检测:方案甲:将这6名疑似病人血清逐个检测,直到能确定感染人员为止;方案乙:将这6名疑似病人随机分成2组,每组3人.先将其中一组的血清混在一起检测,若结果为阳性,则表示感染人员在该组中,然后再对该组中每份血清逐个检测,直到能确定感染人员为止;若结果呈阴性,则对另一组中每份血清逐个检测,直到能确定感染人员为止.(1)求这两种方案检测次数相同的概率;(2)如果每次检测的费用相同,请预测哪种方案检测总费用较少?并说明理由.21.(本小题满分12分)已知O 为坐标系原点,椭圆C :2214x y +=的右焦点为点F ,右准线为直线n .(1)过点(4,0)的直线交椭圆C 于D ,E 两个不同点,且以线段DE 为直径的圆经过原点O ,求该直线的方程;(2)已知直线l 上有且只有一个点到F 的距离与到直线n,直线l 与直线n 交于点N ,过F 作x 轴的垂线,交直线l 于点M .求证:FMFN为定值. 22.(本小题满分12分)已知函数()1ln f x m x =+(m ∈R).(1)当m =2时,一次函数()g x 对任意x ∈(0,+∞),()f x ≤()g x ≤2x 恒成立,求()g x 的表达式;(2)讨论关于x 的方程2()1()f x x f x=解的个数.江苏省2020—2021学年苏锡常镇四市高三教学情况调研(一)数学试卷一、单项选择题(本大题共8小题,每小题5分,共计40分.在每小题给出的四个选项中,只有一个是符合题目要求的,请把答案添涂在答题卡相应位置上) 1.设全集U =R ,集合A =[2,4],B ={}2log 1x x >,则集合A (UB)=A .∅B .{2}C .{}02x x ≤≤D .{}2x x ≤ 答案:B解析:∵B ={}2log 1x x >=(2,+∞),∴UB =(-∞,2],∴A(UB)={2},选B .2.“2sin α=”是“sin cos αα=”的 A .充分不必要条件B .必要不充分条件 C .充要条件D .既不充分也不必要条件 答案:D解析:当“2sin α=”时,可得“sin cos αα=±”;而当“sin cos αα=”时,可得“sin α=2±”,故“2sin α=”是“sin cos αα=”的既不充分也不必要条件,选D . 3.天干地支纪年法源于中国,中国自古便有十天干与十二地支,十天干即甲、乙、丙、丁、戊、己、庚、辛、王、癸;十二地支即子、丑、寅、卯、辰、已、午、未、申、酉、戌、亥.天干地支纪年法是按顺序以一个天干和一个地支相配,排列起来,天干在前,地支在后,天干由“甲”起,地支由“子”起,例如,第一年为“甲子”,第二年为“乙丑”,第三年为“丙寅”…,以此类推,排列到“癸酉”后,天干回到“甲”重新开始,即“甲戌”,“乙亥”,然后地支回到“子”重新开始,即“丙子”…,以此类推,今年是辛丑年,也是伟大、光荣、正确的中国共产党成立100周年,则中国共产党成立的那年是 A .辛酉年B .辛戊年C .壬酉年D .壬戊年 答案:A解析:由题意可知,天干是以10为公差的等差数列,地支是以12为公差的等差数列,从共产党成立到2021经历100年,则共产党成立那年为辛酉年,选A .4.5(32)(1)x x -+展开式中3x 的系数为 A .﹣15B .﹣10 C .10D .15 答案:C解析:23553(2)10C C ⋅+-⋅=,选C . 5.函数2()sin ln(1)f x x x x =+-的图像大致是答案:A解析:首先判断出该函数为偶函数,排除B 、D ,其次函数过点(0,0),排除C ,选A . 6.过抛物线22y x =上一点P 作圆C :22(6)1x y +-=的切线,切点为A ,B ,则当四边形PACB 的面积最小时,P 点的坐标是 A .(1,2)B .(32,3) C .(2,2)D .(52,5) 答案:C解析:设点P(x ,y ),2222221()(6)()(6)2g y PC x y y y ==+-=+-,令,2()(2)(26)0g x y y y '=-++=,则当y =2时,min ()20g y =, ∴,此时点P 的坐标为(2,2),选C .7.若随机变量X~B(3,p ),Y~N(2,2σ),若P(X ≥1)=0.657,P(0<Y <2)=p ,则P(Y >4)=A .0.2B .0.3C .0.7D .0.8 答案:A 解析:则选A8.若316, 0()0, 0x x f x xx ⎧-≠⎪=⎨⎪=⎩,则满足(1)0xf x -≥的x 的取值范围是 A .[﹣1,1][3,+∞)B .(-∞,﹣1][0,1][3,+∞) C .[﹣1,0][1,+∞)D .(-∞,﹣3][﹣1,0][1,+∞)答案:B解析:不妨求(1)()0x f x +≥, ①当x =﹣1或0时显然成立;故则原不等式的解为(-∞,﹣1][0,1][3,+∞),选B .二、 多项选择题(本大题共4小题,每小题5分, 共计20分.在每小题给出的四个选项中,至少有两个是符合题目要求的,请把答案添涂在答题卡相应位置上)9.函数()sin(2)4f x x π=+,则A .函数()y f x =的图象可由函数sin 2y x =的图象向右平移4π个单位得到 B .函数()y f x =的图象关于直线8x π=轴对称C .函数()y f x =的图象关于点(8π-,0)中心对称D .函数2()y x f x =+在(0,8π)上为增函数 答案:BCD解析:作出()y f x =的图象,如图所示:显然A 错误,BC 正确, 显然()f x 在(0,8π)上递增,又2()g x x =在(0,8π)上递增,故D 正确; 因此,选ABD.10.已知O 为坐标系原点,F 1,F 2分别为双曲线22221x y a b-=(a >0,b >0)的左、右焦点,点P 在双曲线右支上,则下列结论正确的有 A .若PO =PF 2,则双曲线的离心率e ≥2B .若△POF 2是面积为3的正三角形,则223b =C .若A 2为双曲线的右顶点,PF 2⊥x 轴,则F 2A 2=F 2PD .若射线F 2P 与双曲线的一条渐近线交于点Q ,则12QF QF 2a -> 答案:ABD解析:选项A ,PO =PF 2中垂线与双曲线有交点,正确;选项B ,,则,正确;选项C ,,显然不等,错误; 选项D ,不妨设P ,Q 均在第一象限,则:,正确;因此,选ABD .11.1982年美国数学学会出了一道题:一个正四面体和一个正四棱锥的所有棱长都相等,将正四面体的一个面和正四棱锥的一个侧面紧贴重合在一起,得到一个新几何体.中学生丹尼尔做了一个如图所示的模型寄给美国数学学会,美国数学学会根据丹尼尔的模型修改了有关结论.对于该新几何体,则 A .AF ∥CD B .AF ⏊DEC .新几何体有7个面D .新几何体的六个顶点不能在同一个球面上 答案:ABD解析:新几何体有五个面,而不是七个面,故C 错误,其他选项均正确,选ABD . 12.已知正数x ,y ,z 满足3412x y z ==,则A .634z x y <<B .121x y z += C .4x y z +>D .24xy z <答案:AC 解析:令,则则显然有111x y z+=,故B 错误, 选项A ,又,故A 正确;故,故C 正确,D 错误;因此,选AC .三、填空题(本大题共4小题, 每小题5分,共计20分.请把答案填写在答题卡相应位置上)13.已知向量a =(1,2),b =(0,﹣2),c =(﹣1,λ),若(2a b -)∥c ,则实数λ=. 答案:﹣3解析:2a b -=(2,6),则2603λλ+=⇒=-.14.已知复数z 对应的点在复平面第一象限内,甲、乙、丙、丁四人对复数z 的陈述如下(i为虚数单位): 甲:2z z +=;乙:23i z z -=;丙:4z z ⋅=;丁:22z z z =.在甲、乙、丙、丁四人陈述中,有且只有两个人的陈述正确,则复数z =. 答案:z =1+i解析:设,则,显然丙丁,乙丁不同时成立,且甲乙丙可以知二推一,故甲丁正确.15.若23sin 2cos 1x x +=,则5sin()cos(2)63x x ππ-⋅+=. 答案:732解析:23sin 2cos 14sin()16x x x π+=⇒+=,∴51sin()sin[()]sin()6664x x x ππππ-=-+=+=, 27cos(2)cos[2()]12sin ()3668x x x πππ+=+=-+=,故5177sin()cos(2)634832x x ππ-⋅+=⨯=.16.四面体的棱长为1或2,但该四面体不是正四面体,请写出一个这样四面体的体积;这样的不同四面体的个数为.答案:11,3 解析:显然可以构成一个底面为边长为1正三角形,侧棱长均为2的正三棱锥,该三棱锥的高223112()33h =-=,则体积1311113123V =⨯⨯=, 1和2可以构成的三角形有:边长为1的正三角形,边长为2的正三角形,边长为1,2,2的三角形,除了已求体积的正三棱锥外,还可以是:四个1,2,2的三角形拼成的三棱锥;两个边长为2的正三角形和两个1,2,2的三角形拼成的三棱锥.所以,共3个.四、解答题(本大题共6小题,共计70分.请在答题卡指定区域内作答.解答时应写出文字说明、证明过程或演算步骤) 17.(本小题满分10分)在△ABC 中,∠BAC =90∘,点D 在边BC 上,满足AB =3BD . (1)若∠BAD =30°,求∠C ;(2)若CD =2BD ,AD =4,求△ABC 的面积.解:(1)在△ABD 中,,所以, 因为,所以,或,当时,,所以,当时,(舍)所以;(2)因为,所以,所以,所以,所以.18.(本小题满分12分)已知等比数列{}n a的各项均为整数,公比为q,且q>1,数列{}n a中有连续四项在集合M={﹣96,﹣24,36,48,192}中.(1)求q,并写出数列{}n a的一个通项公式;(2)设数列{}n a的前n项和为n S,证明:数列{}n S中的任意连续三项按适当顺序排列后,可以成等差数列.解:(1)因为,且各项均为整数,所以连续四项为,所以公比,取,则;(2),当n为奇数时,,,所以,当n为偶数时,,,所以对数列{}n S中的任意连续三项按适当顺序排列后,可以成等差数列.19.(本小题满分12分)如图,在四棱锥P—ABCD中,△PAD是以AD为斜边的等腰直角三角形,BC∥AD,AB⊥AD,AD=2AB=2BC=2,PC2E为PD的中点.(1)求直线PB与平面PAC所成角的正弦值;(2)设F是BE的中点,判断点F是否在平面PAC内,并请证明你的结论.解:取AD的中点G,连接PG,CG,因为△APD是等腰直角三角形,所以PG⊥AD,因为AD=2,所以PG=1,因为AG=1,AD∥BC,所以AG∥BC且AG=BC=1,所以AGCB是平行四边形,所以AB//CG,又因为AB⊥AD,所以CG⊥AD,又CG=1,PC=2,PG=1,所以PG⊥CG,建立如图空间直角坐标系,则A(0,﹣1,1),P(0,0,1),C(1,0,0),B(1,﹣1,0),(1),设平面PAC法向量为则,取,则,则,所以直线PB与平面PAC所成角的正弦值为;(2),所以,所以,则,所以AF在平面PAC中,所以点F在平面PAC内.20.(本小题满分12分)某地发现6名疑似病人中有1人感染病毒,需要通过血清检测确定该感染人员,血清检测结果呈阳性的即为感染人员,呈阴性表示没感染.拟采用两种方案检测:方案甲:将这6名疑似病人血清逐个检测,直到能确定感染人员为止;方案乙:将这6名疑似病人随机分成2组,每组3人.先将其中一组的血清混在一起检测,若结果为阳性,则表示感染人员在该组中,然后再对该组中每份血清逐个检测,直到能确定感染人员为止;若结果呈阴性,则对另一组中每份血清逐个检测,直到能确定感染人员为止.(1)求这两种方案检测次数相同的概率;(2)如果每次检测的费用相同,请预测哪种方案检测总费用较少?并说明理由.解:记甲方案检测的次数是X,则X∈{1,2,3,4,5},记乙方案检测的次数是Y,则Y ∈{2,3},(1)记两种方案检测的次数相同为事件A,则,所以两种方案检测的次数相同的概率为;(2)所以,,所以采用乙方案.21.(本小题满分12分)已知O为坐标系原点,椭圆C:2214xy+=的右焦点为点F,右准线为直线n.(1)过点(4,0)的直线交椭圆C于D,E两个不同点,且以线段DE为直径的圆经过原点O,求该直线的方程;(2)已知直线l上有且只有一个点到F的距离与到直线n的距离之比为32,直线l与直线n交于点N,过F作x轴的垂线,交直线l于点M.求证:FMFN为定值.解:(1)设过点(4,0)的直线为交于椭圆,联立消去y得又因为以线段DE为直径的圆经过原点,则则所求直线方程为;(2)已知椭圆2214xy+=的离心率为32,右准线直线n的方程为,已知直线l上有且只有一个点到F的距离与到直线n的距离之比为3,可以得出直线l与椭圆相切,设直线l的方程为:,联立消去y得:,联立点N坐标为得到.22.(本小题满分12分)已知函数()1lnf x m x=+(m∈R).(1)当m =2时,一次函数()g x 对任意x ∈(0,+∞),()f x ≤()g x ≤2x 恒成立,求()g x 的表达式;(2)讨论关于x 的方程2()1()f x x f x=解的个数. 解:(1)设求导略,又 设,又∵∴在(0,+∞)上恒成立,∴在(0,+∞)上恒成立,∴又综上;(2),则,即设,则,设①当m ≥1时,在(0,+∞)上递增,又∴在(0,+∞)恒有一解,即只有一解 ②m <0时,在上递减又在(0,+∞)恒有一解,③0<m <1时,设∴在(0,+∞)上有二解,且又∵当时,∴在上恰有一根 当时,当时,∴且,解得∴在上恰有一根,在(0,+∞)上恰有三根,综上,当m ≥1或m ≤0时,2()1()f x x f x =恰有一根;当0<m <1时,2()1()f x x f x=恰有三根.。

江苏省苏州市2020-2021学年高三下学期期初学业质量阳光指标调研地理试题 含答案

江苏省苏州市2020-2021学年高三下学期期初学业质量阳光指标调研地理试题 含答案

江苏省苏州市2020-2021学年第二学期期初学业质量阳光指标调研卷高三地理2021.02一、单项选择题:共22题,每题2分,共44分。

中华老字号是指历史悠久,具有深厚文化底蕴,形成良好信誉的品牌,企业类型主要包括餐饮服务、食品加工、商贸百货和医疗保健等。

图1为中华老字号企业空间分布图,据此完成1-2题。

1.中华老字号企业总体分布格局是A.集中在地势的第一阶梯B. 粤港澳大湾区密度最高C.集中于胡焕庸线东南侧D. 西部地区分布较为均衡2.影响中华老字号企业空间分布的因素有①资源禀赋②地域文化③消费需求④生态环境A.①②③B.①②④C.②③④D.①③④今年春节期间,小苏同学和家人在城郊自驾游,他们打算一天中游览3个景点,计划大约在日出时从家里出发,日落时回来。

图2为当日行程线路示意图。

据此完成3—4题。

A.上海(310N,1210E)B.郑州(34.80N,1130E)C.成都(30.50N,1030E)D.乌鲁木齐(430N,870E)4.该日出游时,途中为免受阳光长时间照射且能欣赏窗外的风景,小苏应选择的座位是A.酒店至观光点1,右侧靠窗B.观光点1至观光点2,右侧靠窗C 观光点2至观光点3,左侧靠窗D.观光点3至酒店,左侧靠窗“锋前增温”主要是暖气团在受挤压集聚的情况下温度升高所致。

图3为2020年3月3日2时我国局部海平面气压分布图,完成5—6题。

5.该日最可能出现“锋前增温”的地区是1A 甲B.乙C.丙D.丁6 符合甲—丙沿线剖面天气系统分布的是注:水平与垂直方向比例尺不同。

A.①B.②C.③D.④陕西省神木市地处毛乌素沙漠和黄土高原过渡地带,多年平均降水量435.8mm。

图4为神木市水系及降水入渗系数(反映降水时地表下渗强弱的指标,系数越大,下渗能力越强)分布图。

读图4回答7.神木市西部地表为A.风沙荒漠区B.黄土源地区C.沟壑纵横区D.丘陵起伏区8.影响神木市降水入渗系数东西差异的主要因素有①土壤结构②地形坡度③降水强度④植被覆盖率A.①②B ②③C.②④D ③④海坨山地区是2022年北京冬奥会的三大赛区之一(图5),这里建有国家高山滑雪中心、国家雪车雪橇中心等比赛场地。

苏州四市五区2021届高三期初调研考试英语试题及答案

苏州四市五区2021届高三期初调研考试英语试题及答案

苏州四市五区20204021学年第一学期高三期初调研试卷英语 2020.09第二部分阅读(共两节,满分50分)第一节(共15小题;每小题2.5分,满分37.5分)阅读下列短文,从每题所给的A 、B 、C x D 四个选项中选出最佳选项。

The Best Silk Road TourSilk Road.a business and trade route.originates from the ancient China and connects with thcAsian.African andEuropean countries.Our well-designed Silk Road tour package will never let youdown ・Departure City:ShanghaiGuidc&Driver:English-speaking guidexxpericnced driver with an air-conditioned vehicleMeals: 12 western buffet breakfasts,6 lunches with some being a la carte (点菜)styleTour Highlights:•Must -scc sights in China-Terracotta Warriors,Famen Temple^Dunhuang Mogao Caves,MaijiCavcsJiayuguan Pass and Mutianyu Great Wall•Trace back to the Silk Road of 2.000 years ago& learn about the culture and history•Marvel at the art trcasure -Mogao Caves&enjoy an exciting camel riding in the GobiDcscrtWe Guarantee 100%No Shopping Stops!Tour Prices•Prices are per person in US Dollars.•Any parts of the tour length.activities or hotels can be tailored to your individual interestsAre you ready to follow the footsteps of the ancients to explore this mysterious land now?21 .What will people do on the tour?$3749Tour Prices with Standard Hotels I 2-3 travelers4-5 travelers $3479$3029 6-9 travelers ~$2669~A.Appreciate the ancient heritage・B.Ride on camels all the way.C.Stay a few nights in caves・D.Do a lot of shopping.22.Which of the following is most likely to join the tour?A. A Beijing businessman good at golf.B. A Japanese model loving fashion・C. A Yunnan biologist interested in birds.D.AnAmerican student learning history.23.How much should a traveler pay for her family(with two sons)who want to live comfortably?A・$3479・B・$3749・C・$7498・D・$ 11247.BThe universe likes to be shy about its age,but astronomers believe they have a pretty goodidea ofthe range.Currentlyjhe most widely accepted age for the universe is around 13.8 billion years,butdetermining the age of...well,everything's no easy feat(功绩).Now.ncw studies have investigatedthe question using different methods・ and they've come up with two different answers,separated bymore than a billion years・Because the universe is expanding at an accelerating pacejhe further away anobject isahc fasterit appears to be moving away from us.This is expressed as the Hubble constant (哈勃常数),and it's akey factor in figuring out the age of the universe.After all.if we can determine how fastmoving away from us,we can rewind that process to its beginning-the Big Bang.Researchers from the University of Oregon set out to map the distance to dozens of galaxies The team calculated that the universe is only 12.6 billion years old-that,you might notice is much younger than the 13.8 years usually stated.In the second study.the method of figuring out the age of the universe is by mapping the oldest light we can detect.We are restoring lhe'baby photo'of the universe to its original condition・ removing the wear and tear of time and space that distorted(扭曲)the image,says Neelima SehgaLco-author on the study.Only by seeing this sharper baby photoor image of the universe can we more fully understand how our universe was born."In doing so, the researcherdeterminedthat the universeis 13.8 billion years old-in agreement with the accepted age・The real problem though js that the studies disagreeso wildly with each other, to the tune of a billion years.But they are not the only ones-the battle lines are commonly drawn by the methods used. Obviously.more research is heeded to determine where the tnith lies・24.What do we know about the universe from the first two paragraphs?A.It doesn't exist long.B.It becomes larger.C.It runs away.D.It causes the Big Bang・25.What makes the researchers in the first study think the universe is much younger?A.Tlic speed of moving objects.B.Thc number of galaxies・C.Thc process of the universe evolution.D.Thc distance to other objects・26.How does Neelima Sehgal explain their method in the second study?A.By referring to a similar thing.B.By using hard scientific data・C.By introducing a new concept.D.By quoting an expert's words.27.Which can be a suitable title for the text?A.Whose method is better?B.Which result can you believe?C.How old is the universe?D.Why is the universe so old?CDid you know that die average child has heard the word u no' o\-er 20.000 times before they tiirnthe age ofthree?Ironically4t is also around this time that children begin to develop enough pcrsonalcharacter to refuse to obeyThe^terrible twos”are categorized by a lack of understanding.Somewherebetween three and four,childrcn begin to acquire the skills to reason.lt is during this time they watchhow other children and adults reason.If weYe not carefuljhe children will watch us model a world of 11 NOs \By the time a person turns eighteen.how many times have they been told no?I haven't found anystudies that even attempted to track this statistic,but I'm sure if the number is 20,000 by three.then ateighteen that number has multiplied.You can do the math.AnywayJ think I know why we say no.We say no to protect.We say no to direct.We say no tostop potential confusion.Howevendo we sometimes say no just for the sake of saying no?Do we sayno because we have internalized(内在化)all of the M NOs H we,ve heard over the years and we feel it isfinally our time to say no to someone else?The internalized no can damage the growth process of dreams in infancy as quickly as it canweaken a three-year- old.And we wonder why we mn into people with big,un-accomplishcd dreamswho have a bit of a chip on their shoulder.Tliey have to take on the 20.000 NOs.HoweverJhe thingthat keeps them going is the possibility of the power of ONE YES!Just as it only takes one book toniake a writer a Pulitzer Prize Winnerjt only takes one word to change the course of your day.Thatword is YES!2&What do we know about two-year-olds?A.Tliey understand well.B.They often say no to others・C.Thcy think logically・D.They don't do all theyYe told.29.What effect does saying no have on children?A.Tliey lose all their dreams・B.They aren*t easy to succeed・C.Thcy don't make mistakes・D.They never say yes to others・30.Which word best describes the author's attitude to a world oPNOs'1?A.Tolcrant .B.Disapproving ・C.Favourable.D.Carefree.31.What is the text?A.A how-to guide・B.A survey report・C.An opinion essay.D.A short story.DI'm Jeff Logan,president of Logan Luxury Theaters Corporation.Fm very sorry to tell you many cinemas are at risk of closing pcmiancnlly(永久)o Thafs something we would hate to see happenWatching the newest box office movie and eating a big bucket of popcorn is an experience that many of us have enjoyed for a very long time.We all have fond memories of going to a theaterof our first dates or the first movie we saw with our children.A movie theater is so important to the fabric of the local community.Ifs a place where we all gather.no matter what our interests,and no matter whatages,young and old.rich and poor.But how much longer will classic theaters remain open?Just like other industriesjnovie theatershave been hit hard by the pandemic(流行病)and are going dark.The entire industry is being controllcdby the pandemic.bccause the studios don*t want to release their new movies until all the theaters can bcopen.As we all knowjhe theaters can*t do well and can*t get back to full 7-day a week at full speedoperation without new movies to play.Recently,the Logan Luxury 5 Cinema in Mitchell reopened for the weekends.HoweverJike manytheatersjt is only operating at about 10 percent capacity.Since opening,several new safety nieasureshave been put in place.Block off every other row.People are asked to leave three seats between themand the next group.Staff spray the theater with disinfcclantC肖毒剂)after every show.And sanitizerstations can be found throughout the theater.Even so,some people still aren't comfortable going to a movie theater yet.I fully understand that.AnyhowJ just hope we must do something else to help out our local theatersjike taking part in a newnational proposal called H Save Your Cinema/132.What does the underlined word u fabric u in paragraph 4 refer to?A.Typical feature.B.Basic structure.C.Public support.mon vision.33.Why are the film studios unwilling to release the new movies?A.Cinemas don't operate normally・B.New movies aren*t welcomed・C.People don't like going to cinema・D.Many cinemas go out of business・34.What can we infer about the Logan Luxury 5 Cinema after its reopening?A.It makes a lot of money.B.It does well in disease prevention.C.It receives a large audience every day.D.It offers more enjoyable experience・35.What is the purpose of this text?A.To share the good old days・B.To explain a social problem・D.To recommend a theater.C.To ask for people's help.第二节(共5小题;每小题2.5分,满分12.5分)阅读下面短文,从短文后的选项中选出可以填入空白处的最佳选项。

江苏省苏州四市五区2021届高三上学期期初调研试题 物理 Word版含答案

江苏省苏州四市五区2021届高三上学期期初调研试题 物理 Word版含答案

2020~2021学年第一学期高三期初调研试卷物理2020.9 (本试卷共18小题,满分100分,考试时间90分钟。

)注意事项:1.答题前,考生务必用黑色签字笔将自己的姓名和考试号填写在答题卷上,并用2B铅笔填涂考试号下方的涂点。

2.选择题每小题选出答案后,用2B铅笔把答题卷上对应的答案信息点涂黑。

如需改动,用橡皮擦干净后,再选涂其他答案。

答案写在试题卷上无效。

3.非选择题必须用0.5mm黑色签字笔作答,必须在答题卷上各题目的答题区域作答。

超出答题区域书写的答案无效。

在试题纸上答题无效。

一、单项选择题:本题共8小题,每小题3分,共计24分。

每小题只有一个选项符合题意。

1.已知23490Th的半衰期为24天,4g23490Th经过72天还剩下23490Th的质量为A.0.5gB.1gC.2gD.3.5g2.如图所示为运动员跳高时的精彩瞬间,下列说法正确的是A.运动员起跳时地面对他的支持力等于他所受的重力B.运动员起跳以后在上升过程中处于失重状态C.运动员在最高点处于平衡状态D.运动员在下降过程中处于超重状态3.如图所示,一束由红光和紫光组成的复色光,垂直等边三棱镜ABC的一边入射形成了如图所示的光路图。

下列说法正确的是A.光线一定是沿EO的方向入射的B.光线OF、OE均为单色光C.沿OF方向的光线在棱镜的临界角较小D.沿OF方向的光线在三棱镜中传播速度较大4.水枪是孩子们喜爱的玩具,常见的气压式水枪储水罐示意如图。

从储水罐充气口充入气体,达到一定压强后,关闭充气口,扣动扳机将阀门M打开,水即从枪口喷出,罐内气体可看作理想气体,若在水不断喷出的过程中,罐内气体温度始终保持不变,则罐内气体A.压强变大B.对外界不做功C.从外界吸热D.分子平均动能变小5.图甲为一列简谐横波在t=0时刻的波形图,P、Q分别是机械波上的两个质点,其平衡位置坐标分别为x P=2m、x Q=1m;图乙为质点P的振动图象。

从t=0时刻起,下列说法中正确的是A.t=0时,质点P的运动方向沿y轴正方向B.t=0.1s时,质点Q的加速度大于质点P的加速度C.t=0至t=0.15s,质点Q运动的路程为0.2mD.t=0至t=0.15s,质点P沿x轴的正方向迁移了3m6.如图所示为一现代仿制的地动仪,龙口中的铜珠到蟾蜍口的距离为h,某时刻,质量为m 的铜珠由静止离开龙口,落入蟾蜍口中(设速度立即变为零)。

江苏省苏州市2020┄2021届高三上学期期末调研测试化学试题Word版 含答案

江苏省苏州市2020┄2021届高三上学期期末调研测试化学试题Word版 含答案

苏州市2021年高三调研测试化学2注意事项:1.本试卷分为选择题和非选择题两部分,共120分。

考试时间100分钟。

2.请把选择题的答案涂在答题卡的相应位置上,非选择题的答案填写在答题卡的指定栏目内。

可能用到的相对原子质量:H-1 C-12 N-14 O-16 S-32 Fe-56 Ba-137选择题(共40分)单项选择题:本题包括10小题,每小题2分,共计20分。

每小题只有一个选项......符合题意。

1.下列说法不符合...人与自然和谐相处的是A.用电动汽车代替燃油汽车B.将聚乙烯等塑料垃圾深埋或倾入海中C.用沼气、太阳能、风能等能源替代化石燃料D.大力实施矿物燃料的脱硫脱硝技术以减少SO2、NO x的排放2.下列有关化学用语表示正确的是A.CO2的电子式:B.Cl—的结构示意图:C.乙醇的结构式:C2H6O D.中子数为53、质子数为78的碘原子:13153I3.常温下,下列各组离子在指定溶液中一定能大量共存的是A.在0.01 mol·L—1Ba(OH)2溶液中:Al3+、NH错误!、NO错误!、HCO错误!B.在加入甲基橙显红色的溶液中:Mg2+、Fe2+、Cl—、NO错误!C.在含有苯酚的溶液中:K+、NH错误!、Br—、Fe3+D.在0.01mol·L—1HCl溶液中:K+、Na+、I—、SO错误!4.下列物质性质与相应结果或应用的对应关系正确的是A.酸性越强的含氧酸跟铁片反应产生氢气越快B.将草木灰和硫铵混合施用,可使肥效更高C.Mg(OH)2和Al(OH)3受热易分解,常用它们作阻燃剂D.某地雨水经过一段时间,其pH由4.68降为4.28,因为水中溶解了较多的CO2 5.下列关于各实验装置与对应现象或结论的叙述均正确的是A.图1装置:可用于分离石油,分别得到汽油、煤油和柴油等各种纯净物B.图2装置:可用于吸收NH3或HCl气体,并防止倒吸C.图3装置:如果“a进b出”可用于收集NO2,如果“b进a出”可用于收集NH3 D.图4装置:持续通入CO2气体,现象是先出现白色沉淀,后变澄清6.设N0表示阿伏加德罗常数的值。

2020-2021学年江苏省四市高三教学调研(二)数学试卷及答案解析

2020-2021学年江苏省四市高三教学调研(二)数学试卷及答案解析

江苏省四市高三教学情况调研(二)数 学 Ⅰ 试 题注意事项:1.本试卷共4页,包括填空题(第1题~第14题)、解答题(第15题~第20题)两部分.本试卷满分160分,考试时间120分钟.2.答题前,请您务必将自己的姓名、考试号用0.5毫米黑色字迹的签字笔填写在答题卡的指定位置.3.答题时,必须用0.5毫米黑色字迹的签字笔填写在答题卡的指定位置,在其它位置作答一律无效.4.如有作图需要,可用2B 铅笔作答,并请加黑加粗,描写清楚.5. 请保持答题卡卡面清洁,不要折叠、破损.一律不准使用胶带纸、修正液、可擦洗的圆珠笔.一、填空题:本大题共14小题,每小题5分,共70分.不需要写出解答过程,请把答案直接填在答题卡相应位置上......... 1.已知集合{}13A x x =-<<,{}2B x x =<,则A B =I ▲ . 2.已知i 为虚数单位,复数13i z y =+()R y ∈,22i z =-,且121i z z =+,则y = ▲ .3.下表是一个容量为10的样本数据分组后的频数分布.若利用组中值近似计算本组数据的平均数x ,则x 的值为 ▲.4.已知直线20x -=为双曲线22221(0,0)x y a b a b-=>>的一条渐近线,则该双曲线的离心率的值为 ▲ .5.据记载,在公元前3世纪,阿基米德已经得出了前n 个自然数平方和的一般公式.右图是一个求前n 个自然数平方和的算法流程图,若输入x 的值为1,则输出S 的值为 ▲ . 6.已知1Ω是集合{}22(,)1x y x y +„所表示的区域,2Ω是集合{}(,)x y y x „所表示的区域,向区域1Ω内随机的投一个点,则该点落在区域2Ω内的概率为 ▲ .7.已知等比数列{}n a 的前n 项和为n S ,公比3q =,34533S S +=,则3a = ▲ .8.已知直四棱柱底面是边长为2的菱形,侧面对角线的长为面积为 ▲ .9.已知α是第二象限角,且sin α=,tan()2αβ+=-,则tan β= ▲ .10.已知直线l :210mx y m +--=,圆C :22240x y x y +--=,当直线l 被圆C 所截得的弦长最短时,实数m = ▲ .11.在△ABC 中,角,,A B C 对边分别是,,a b c,若满足2cos =2b A c ,则角B 的大小为 ▲ .12.在△ABC 中,AB AC ⊥,1AB t=,AC t =,P 是△ABC 所在平面内一点,若4||||AB ACAP AB AC =+u u u r u u u ru u u r u u ur u u u r ,则△PBC 面积的最小值为 ▲ . 13.已知函数24,0,()3,0,x x x f x x x⎧-⎪=⎨<⎪⎩…若函数()()3g x f x x b =-+有三个零点,则实数b 的取值范围为 ▲ .14.已知,a b 均为正数,且20ab a b --=,则22214a b a b-+-的最小值为 ▲ .二、解答题:本大题共6小题,共90分.请在答题卡指定区域.......内作答,解答时应写出必要的文字说明、证明过程或演算步骤. 15.(本小题满分14分)已知向量m ,1)x =-,n 2(sin ,cos )x x =.(1)当π3x =时,求⋅m n 的值;(2)若π0,4x ⎡⎤∈⎢⎥⎣⎦,且⋅mn 12=-,求cos2x 的值.16.(本小题满分14分)如图,在四面体ABCD 中,平面ABC ⊥平面ACD , E ,F ,G 分别为AB ,AD ,AC 的中点,AC BC =,90ACD ∠=︒.(1)求证:AB ⊥平面EDC ;(2)若P 为FG 上任一点,证明EP ∥平面BCD .17.(本小题满分14分)某科研小组研究发现:一棵水蜜桃树的产量w (单位:百千克)与肥料费用x (单位:百元)满足如下关系:341w x =-+,且投入的肥料费用不超过5百元.此外,还需要投入其他成本(如施肥的人工费等)2x 百元.已知这种水蜜桃的市场售价为16元/千克(即16百元/百千克),且市场需求始终供不应求.记该棵水蜜桃树获得的利润为()L x (单位:百元).(1)求利润函数()L x 的函数关系式,并写出定义域;(2)当投入的肥料费用为多少时,该水蜜桃树获得的利润最大?最大利润是多少?18.(本小题满分16分)已知函数3()ln f x a x bx =-,a ,b 为实数,0b ≠, e 为自然对数的底数,e 2.71828≈….(1)当0a <,1b =-时,设函数()f x 的最小值为()g a ,求()g a 的最大值; (2)若关于x 的方程()=0f x 在区间(1e],上有两个不同实数解,求ab的取值范围.19.(本小题满分16分)已知椭圆2222:1(0)x y C a b a b+=>>的左焦点为(1,0)F -,左准线方程为2x =-. (1)求椭圆C 的标准方程;(2)已知直线l 交椭圆C 于A ,B 两点. ①若直线l 经过椭圆C 的左焦点F ,交y 轴于点P ,且满足PA AF λ=u u u r u u u r,PB BF μ=u u u r u u u r.求证:λμ+为定值;②若A ,B 两点满足OA OB ⊥(O 为坐标原点),求△AOB 面积的取值范围.20.(本小题满分16分)已知数列{}n a 满足21141,2n n n n a a a a a λμ+++==+,其中*N n ∈,λ,μ为非零常数.(1)若3,8λμ==,求证:{}1n a +为等比数列,并求数列{}n a 的通项公式; (2)若数列{}n a 是公差不等于零的等差数列. ①求实数,λμ的值;②数列{}n a 的前n 项和n S 构成数列{}n S ,从{}n S 中取不同的四项按从小到大排列组成四项子数列.试问:是否存在首项为1S 的四项子数列,使得该子数列中的所有项之和恰好为2017?若存在,求出所有满足条件的四项子数列;若不存在,请说明理由.数学Ⅱ(附加)试题注意事项:1.本试卷只有解答题,供理工方向考生使用.本试卷第21题有4个小题供选做,每位考生在4个选做题中选答2题,如多答,则按选做题中的前2题计分.第22,23题为必答题.每小题10分,共40分.考试用时30分钟.2.答题前,请您务必将自己的姓名、考试号用0.5毫米黑色字迹的签字笔填写在试卷的指定位置.3.答题时,必须用0.5毫米黑色字迹的签字笔填写在试卷的指定位置,在其它位置作答一律无效.4.如有作图需要,可用2B 铅笔作答,并请加黑加粗,描写清楚.5.请保持答题卡卡面清洁,不要折叠、破损.一律不准使用胶带纸、修正液、可擦洗的圆珠笔.21.【选做题】本题包括A ,B ,C ,D 四小题,每小题10分. 请选定其中两题......,并.在相应的....答题区域....内作答...,若多做,则按作答的前两题评分.解答时应写出必要的文字说明、证明过程或演算步骤. A .(选修4-1:几何证明选讲)如图,直线DE 切圆O 于点D ,直线EO 交圆O 于,A B 两点,DC OB ⊥于点C , 且2DE BE =,求证:23OC BC =.B .(选修4—2:矩阵与变换)已知矩阵M 13a b ⎡⎤=⎢⎥⎣⎦的一个特征值11λ=-及对应的特征向量e 11⎡⎤=⎢⎥-⎣⎦. 求矩阵M 的逆矩阵.C .(选修4—4:坐标系与参数方程)在平面直角坐标系xO y 中,以O 为极点,x 轴的正半轴为极轴,取相同的单位长度,建立极坐标系.已知曲线1C 的参数方程为[]2cos (0,2π,32sin x y αααα⎧=⎪∈⎨=+⎪⎩,为参数),曲线2C 的极坐标方程为πsin()3a ρθ+=(R a ∈).若曲线1C 与曲线2C 有且仅有一个公共点,求实数a 的值.D.(选修4—5:不等式选讲)已知,,a b c 为正实数,求证:222b c a a b c a b c++++….【必做题】第22,23题,每小题10分,共20分. 请把答案写在答题卡的指定区域内,解答时应写出文字说明、证明过程或演算步骤. 22.(本小题满分10分)已知袋中装有大小相同的2个白球、2个红球和1个黄球.一项游戏规定:每个白球、红球和黄球的分值分别是0分、1分和2分,每一局从袋中一次性取出三个球,将3个球对应的分值相加后称为该局的得分,计算完得分后将球放回袋中.当出现第n 局得n 分(*N n ∈)的情况就算游戏过关,同时游戏结束,若四局过后仍未过关,游戏也结束.(1)求在一局游戏中得3分的概率;(2)求游戏结束时局数X 的分布列和数学期望()E X .23.(本小题满分10分)已知01()(1)(1)()(1)()n n k k n n nn n nn n n f x C x C x C x k C x n =--++--++--L L , 其中*,R N N x n k k n ∈∈∈,,…. (1)试求1()f x ,2()f x ,3()f x 的值;(2)试猜测()n f x 关于n 的表达式,并证明你的结论.数学参考答案一、填空题.1.{}12x x -<<2.1 3.19.7 45.14 6.347.3 8.9.1710.-1 11.π612.3213.1(,6)(,0]4-∞--U14.7二、解答题:本大题共6小题,共计90分.15.解:(1)当π3x =时,m 1)=-,n 1)4=, ……………………………4分所以⋅m n 311442=-=.…………………………………………………………6分(2)⋅m n 2sin cos x x x -=11π12cos2sin(2)2262x x x --=--, ………………………8分若⋅m n 12=,则π1sin(2)1262x =---,即πsin(2)6x -=,因为π[0,]4x ∈,所以πππ2663x --剟,所以πcos(2)6x -=, (10)分则ππππ1cos2cos[(2)]cos(2)sin(2)66662x x x x =-+=--⨯ (12)分1=. (14)2分16.(1)因为平面ABC⊥平面ACD,90∠=︒,即CD⊥AC,ACD平面ABC I平面ACD=AC,CD⊂平面ACD,所以CD⊥平面ABC, (3)分又AB⊂平面ABC,所以CD⊥AB,………………………………………………4分因为AC BC=,E为AB的中点,所以CE⊥AB, (6)分又CE CD CI,CD⊂平面EDC,CE⊂平面EDC,=所以AB⊥平面EDC. (7)分(2)连EF,EG,因为E,F分别为AB,AD的中点,所以EF∥BD,又BD⊂平面BCD,EF⊄平面BCD,所以EF∥平面BCD,………………………………………………………………10分同理可证EG∥平面BCD,且EF I EG=E,EF⊂平面BCD,EG⊂平面BCD,所以平面EFG∥平面BCD, (12)分又P 为FG 上任一点,所以EP ⊂平面EFG ,所以EP ∥平面BCD .……………14分 17.解:(1)348()164264311L x x x x x x ⎛⎫=---=-- ⎪++⎝⎭(05x 剟).………………4分(2)法一:()4848()643673111L x x x x x ⎛⎫=--=-++ ⎪++⎝⎭6743-….……………………………………8分当且仅当()48311x x =++时,即3x =时取等号..................................10分 故()max 43L x =.........................................................................12分 答:当投入的肥料费用为300元时,种植该果树获得的最大利润是4300元. (14)分法二:()()24831L x x '=-+,由()0L x '=得,3x =.……………………………7分故当()0,3x ∈时,()0L x '>,()L x 在()0,3上单调递增;当()3,10x ∈时,()0L x '<,()L x 在()3,5上单调递减;.....................10分 故()max 43L x =. (12)分答:当投入的肥料费用为300元时,种植该果树获得的最大利润是4300元. (14)分18.解:(1)当1b =-时,函数3()ln f x a x x =+,则323()3a a x f x x x x+'=+=, (2)分令()0f x '=,得x =0a <0>,所以()ln()3333a a a ag a f a ===--, (4)分令()ln t x x x x =-+,则()ln t x x '=-,令()0t x '=,得1x =, 且当1x =时,()t x 有最大值1,所以()g a 的最大值为1(表格略),(分段写单调性即可),此时3a =-.………6分 (2)由题意得,方程3ln 0a x bx -=在区间(1e],上有两个不同实数解, 所以3ln a x b x=在区间(1e],上有两个不同的实数解,即函数1ay b =图像与函数3()ln x m x x =图像有两个不同的交点,…………………9分因为22(3ln 1)()(ln )x x m x x -'=,令()0m x '=,得x =14分当e]x ∈时,3()(3e,e ]m x ∈, 所以,a b 满足的关系式为 33e e a b <…,即ab 的取值范围为33e e ](,.…………16分19.解:(1)由题设知=e ,22222==+a c b c ,即222=a b ,……………………1分(1,2代入椭圆C 得到2211122+=b b,则21=b ,22=a ,…………………2分∴22:12x C y +=. (3)分(2)①由题设知直线l 的斜率存在,设直线l 的方程为(1)y k x =+,则(0,)P k .设1122(,),(,)A x y B x y ,直线l 代入椭圆得2222(1)2x k x ++=,整理得,2222(12)4220k x k x k +++-=,∴22121222422,1212k k x x x x k k--+==++. ……………5分由λ=u u u r u u u r PA AF ,μ=u u u r u u u r PB BF 知,1212,11x x x x λμ--==++, ……………………………7分∴222212122212122244424121244221111212k k x x x x k k k k x x x x k k λμ--+++-+++=-=-=-=---+++-++++(定值).………9分②当直线,OA OB 分别与坐标轴重合时,易知△AOB的面积S =,……………10分当直线,OA OB 的斜率均存在且不为零时,设1:,:OA y kx OB y x k ==-,设1122(,),(,)A x y B x y ,将y kx =代入椭圆C 得到22222x k x +=,∴222112222,2121k x y k k ==++,同理222222222,22k x y k k==++, …………………12分△AOB 的面积2OA OBS ⋅== (13)分令[)211,t k =+∈+∞,S ==, 令1(0,1)u t=∈,则23S ⎡=⎢⎣⎭. ……………15分综上所述,23S ⎡∈⎢⎣⎦. (16)分20.解:(1)当3,8λμ==时,21384(32)(2)3222n n n n n n n n a a a a a a a a +++++===+++,∴113(1)n n a a ++=+.……………………………………………………………………2分又10n a +≠,不然110a +=,这与112a +=矛盾,…………………………………3分∴{}1n a +为2为首项,3为公比的等比数列,∴1123n n a -+=⋅,∴1231n n a -=⋅-. …………………………………………………4分(2)①设1(1)1n a a n d dn d =+-=-+, 由2142n n n n a a a a λμ+++=+得21(2)4n n n n a a a a λμ++=++,∴2(3)(1)(1)(1)4dn d dn dn d dn d λμ-++=-++-++, …………………………5分∴222222(4)3(2(1))(1)(1)4d n d d n d d n d dn d d λλμλμ⋅+--+=+-++-+-+ 对任意*∈N n 恒成立. ………………………………………………………………7分∴22224(2(1))3(1)(1)4d d d d d d d d d λλμλμ⎧=⎪-=-+⎨⎪-+=-+-+⎩,,,即122λ=⎧⎪=+⎨⎪=⎩u d d ,,,∴1,4,2λ===u d . (9)分综上,14,21n a n λμ===-,. ……………………………………………………10分②由①知2(121)2n n n S n +-==. 设存在这样满足条件的四元子列,观察到2017为奇数,这四项或者三个奇数一个偶数、或者一个奇数三个偶数.ο1若三个奇数一个偶数,设121212,,,x y z S S S S ++是满足条件的四项,则2221(21)(21)42017x y z +++++=,∴2222()1007x x y y z ++++=,这与1007为奇数矛盾,不合题意舍去. ……11分ο2若一个奇数三个偶数,设1222,,,x y z S S S S 是满足条件的四项,则222214442017x y z +++=,∴222504x y z ++=. ……………………………12分由504为偶数知,,,x y z 中一个偶数两个奇数或者三个偶数. 1)若,,x y z 中一个偶数两个奇数,不妨设111221,21,x x y y z z ==+=+,则222111112()251x y y z z ++++=,这与251为奇数矛盾. ………………………13分2)若,,x y z 均为偶数,不妨设1112,2,2x x y y z z ===,则222111126x y z ++=,继续奇偶分析知111,,x y z 中两奇数一个偶数,不妨设122x x =,1221y y =+,1221z z =+,则2222222231x y y z z ++++=. …14分因为2222(1),(1)y y z z ++均为偶数,所以2x 为奇数,不妨设220y z 剟,当21x =时,22222230y y z z +++=,22214y y +„,检验得20y =,25z =,21x =, 当23x =时,22222222y y z z +++=,22210y y +„,检验得21y =,24z =,23x =, 当25x =时,2222226y y z z +++=,2222y y +„,检验得20y =,22z =,25x =, 即14844,,,S S S S 或者1122436,,,S S S S 或者142040,,,S S S S 满足条件,综上所述,{}14844,,,S S S S ,{}1122436,,,S S S S ,{}142040,,,S S S S 为全部满足条件的四元子列.…………………………………………………………………………………………16分(第Ⅱ卷 理科附加卷)21.【选做题】本题包括A ,B ,C ,D 四小题,每小题10分. A .(选修4-1 几何证明选讲).解:连结OD ,设圆的半径为R ,BE x =,则OD R =,22DE BE x ==. …………2分在Rt △ODE 中,∵DC OB ⊥,∴2OD OC OE =g,即2()R OC R x =+g ,① 又∵直线DE 切圆O 于点D ,则2DE BE OE =g,即24()x x R x =+g ,② ………6分∴23R x =,代入①,22()3R R OC R =+g ,35ROC =, ……………………………8分∴BC OB OC =-35R R =-25R=, ∴23OC BC =. (10)分B .(选修4—2:矩阵与变换)解:由题知,111111113131131a a a b b b ---=-⎧⎡⎤⎡⎤⎡⎤⎡⎤⎡⎤⋅==-⋅=⇒⎨⎢⎥⎢⎥⎢⎥⎢⎥⎢⎥----=⎣⎦⎣⎦⎣⎦⎣⎦⎣⎦⎩,,……………………4分∴2,2a b ==,1232M ⎡⎤=⎢⎥⎣⎦.…………………………………………………………6分 12det()1223432M ==⨯-⨯=-, …………………………………………………8分∴111223144M -⎡⎤-⎢⎥=⎢⎥⎢⎥-⎢⎥⎣⎦. ………………………………………………………………10分C .(选修4—4:坐标系与参数方程)解:2222((3)4cos 4sin 4x y αα+-=+=,∴曲线C 的普通方程为22(1)(3)4x y ++-=. ……………………………………4分1sin()sin cos 32a a πρθρθθ+=⇒=,∴曲线D20y a +-=, ……………………………………6分曲线C 圆心到直线D的距离为2d ==, (8)分∴32-=a ,∴1=a 或5a =.………………………………10分(少一解,扣一分)D .(选修4—5:不等式选讲) 解法一:基本不等式∵22b a b a +…,22c b c b +…,22a c a c +…,∴222b c a a b c a b c +++++222a b c ++…, ………………………………………6分∴222b c a a b c a b c++++..., (10)分解法二:柯西不等式2222()()()b c a a b c b c a a b c++++++…,∴222b c a a b c a b c++++..., (10)分【必做题】第22,23题,每小题10分,计20分. 22.解:(1)设在一局游戏中得3分为事件A ,则111221352()5C C C P A C ==.… …………………………………………………………2分答:在一局游戏中得3分的概率为25.………………………………………………3分(2)X 的所有可能取值为1,2,3,4.在一局游戏中得2分的概率为1221222135310C C C C C +=,…………………………………5分2122351(1)5C C P X C ===; 436(2)51025P X ==⨯=; 43228(3)(1)5105125P X ==⨯-⨯=; 43342(4)(1)5105125P X ==⨯-⨯=.所以………………………………………………………………………………………………8分∴162842337()1234525125125125E X =⨯+⨯+⨯+⨯=.…………………………………10分23.解:(1)01111()(1)11f x C x C x x x =--=-+=; (1)分0212222222()(1)(2)f x C x C x C x =--+-2222(21)(44)2x x x x x =--++-+=; (2)分0313233333333()(1)(2)(3)f x C x C x C x C x =--+---33333(1)3(2)(3)6x x x x =--+---=. (3)分(2)猜测:()!n f x n =. (4)分而!!!()!(1)!()!kn n n kC kk n k k n k ==---,11(1)!!(1)!()!(1)!()!k n n n nC nk n k k n k ---==----, 所以11k k n n kC nC --=. (5)分用数学归纳法证明结论成立.①当1n =时,1()1f x =,所以结论成立.②假设当n k =时,结论成立,即01()(1)(1)()!k k k k k k k kk f x C x C x C x k k =--++--=L . 当1n k =+时,01111111111()(1)(1)(1)k k k k k k k k k f x C x C x C x k +++++++++=--++---L 0111111111(1)(1)(1)()()(1)(1)k k k k k k k k k k k k C x C x x C x k x k C x k ++++++++=---++---+---L 011111211111111[(1)(1)()][(1)2(2)(1)()](1)(1)k k k k k k k k k k k k k k k k k k k k x C x C x C x k C x C x kC x k C x k +++++++++++=--++--+---+--+---L L0101111111[()(1)(1)()()](1)[(1)(2)(1)()](1)(1)(1)k k k k k k k k k k k kk k k k k k kkkk x C x C C x C C x k k x C x Cx k Cx k x k -+-+++=-+-++-+-++---+--+-----L L0101111111[(1)(1)()][(1)(1)()](1)[(1)(2)(1)()](1)(1)(1)(1)(1)k k k k k k k k k k k k k k k k k k k k k k k k k kk x C x C x C x k x C x C x k k x C x C x k x C x k k x k --+-++=--++----++--++---+--+----+---L L L010-11111[(1)(1)()][(1)(1)()(1)(1)](1)[(1)(2)(1)()(1)(1)]k k k k k k k k k k k k k k k k k k k k k k k k k k k x C x C x C x k x C x C x k C x k k x C x C x k x k ---=--++----++--+---++---+--+---L L L ()由归纳假设知()式等于!!(1)!(1)!x k x k k k k ⋅-⋅++⋅=+. 所以当1n k =+时,结论也成立.综合①②,()!n f x n 成立. ………………………………………………………10分。

2020~2021学年度苏锡常镇四市高三教学情况调研(二)英语试题及参考答案

2020~2021学年度苏锡常镇四市高三教学情况调研(二)英语试题及参考答案

20202021202105150120(30)(5 1.57.5)5A B C10()1. How soon will the package arrive with EMS?A. In about two weeks.B. In less than two days.C. In more than three days. ()2. What will the man do next week?A. Give a report.B. Make a presentation.C. Take a rest.()3. What does the woman advise the man to do?A. Find the article at the reference desk.B. Read the article on the computer.C. Turn to the librarians for help.()4. What will the woman probably do?A. Cancel her membership.B. Rush to catch a bus.C. Call the man back later. ()5. What do we learn from the conversation?A. The woman didn't like classical music.B. The man didn't think highly of the conductor.C. The conductor didn't like the choice of the music.(15 1.522.5)5A B C55667()6. Why does the man make the call?A. To make an enquiry about a new car.B. To buy an insurance for his car.C. To make a complaint about the service.()7. How much does the Red Flag company charge monthly?A.$30.B.$40.C.$48.789()8. What did the man find in the library?A. A ticket for a festival.B. A book about Spanish music.C. A brochure about a music festival.()9. What's the probable relationship between the speakers?A. Husband and wife.B. Manager and secretary.C. Teacher and student.81012()10. What are the two speakers talking about?A. Advice on having an interview.B. Tips on choosing a job.C. Ways of learning English.()11. What does the man advise the woman to do?A. Remember her answers in advance.B. Be natural when she speaks.C. Use as many English words as possible.()12. How does the woman feel about the man's suggestions?A. Not practical.B. A bit confusing.C. Quite valuable.91316()13. Where does this conversation probably take place?A. On th e ph one.B. At th e airport.C. In Milton.()14. How far is Milton from Toronto Airport?A. Less than 150 miles.B. More than 150 miles.C. Exactly 150 miles.()15. Why doesn't the woman rent a car?A. She can't drive herself.B. She doesn't feel like driving.C. She doesn't have enough money.()16. What's the woman's final decision?A. Taking a taxi from the airport.B. Taking the airport shuttle bus.C. Taking a Greyhound bus.101720()17. What is the speaker?A. A guide.B. A teach er.C. A coach.()18. What does the speaker mainly talk about?A. Factors deciding the choice of goods.B. Consumers' choice of cars.C. Products with high quality.()19. What do people think of reliability nowadays?A. It's getting more attention.B. It's still important.C. It's the deciding factor.()20. Where can people get access to more information?A. From newspapers.B. From a website.C. From a book.(50)(15 2.537.5)A B C DATh e UCLA (University of California, Los Angeles)Volunteer Center works with many external partners to provide th is list of current volunteer opportunities. Search h ere for an opportunity in the community that suits your interests or skills. Good luck!Medical Volunteer Abroad ProgramsVolunteering Solutions have been organizing medical volunteer abroad programs in different countries for 12 years. Participants (preferably medical students) joining these programs will work under th e guidance of professional doctors and nurses. Th e medical volunteering opportunities, offered in different areas like Emergency and General Medicine, are available throughout the year with flexible start dates and durations.Answer Crisis Calls at a HelplineCommunity Helpline currently has opportunities for students as a Volunteer Crisis Listener. It provides a non judgmental listening ear to the callers, while also assisting individuals in coping with mental h ealth issues to prevent serious crises. No previous experience is required, but completion of a five week training program is required. The crisis line is open from 8 am to 8 pm every single day. A“shift”consists of 3 hours and we ask that you sign up for 1 shift a week.Youth Education Volunteers NeededYouth Education Volunteers at LINC Cares serve at after sch ool programs and summer camps that provide fun recreational activities, support strong educational habits, and promote good health and positive social development for children from families.Volunteers serve at the program one weekday per week from 230 pm to 530 pm.()21. What do we know about Medical Volunteer Abroad Programs?A. Volunteers will work domestically.B. There are various volunteering areas.C. Volunteers will work independently.D. There is a fixed volunteering time.()22. What is a Volunteer Crisis Listener required to do?A. Judge the caller when listening.B. Be capable of stopping crises.C. Complete a training program.D. Work twelve hours per day.()23. What's the passage mainly about?A. Volunteer programs.B. Educational courses.C. Recreational activities.D. Ch arity work.BIan McKenna was in third grade when he learned that many kids at his Austin school weren't getting enough to eat at home. He wanted to help, but local volunteer organizations turned him away, saying he was too young. So he decided to find his own solution. For years, he had been gardening with h is moth er, and th ey often distributed th eir extra vegetables to th e neigh bors.“Why not give the produce to a soup kitchen Then I thought, I'm good at gardening” says McKenna, now 16.“Wh y not plant a garden at sch ool, so th at kids in need could take food h omeMcKenna persuaded his school to set aside space for a garden; then he asked the community for donations of seeds and equipment. Oth er students donated th eir time. With in month s, McKenna's garden was producing lettuces, tomatoes, cucumbers and squash for students and their families. Now, seven years later, McKenna's Giving Garden project h as expanded to five area schools in addition to his own backyard garden, and he has provided organic produce, enough for 25000 meals, to Austin families.For most of his gardening activities, McKenna wears the same T shirt in different colors, with his personal motto on it: BE A GOOD HUMAN. To him, that means helping in any way you can, no matter what your age.“Even a smile might change someone's life”h e says.“It lets them know that they are important. It can make their day.”When COVID19 hit the U S., McKenna redoubled his efforts, cooking up to 100 meals to distribute to th e h ungry on th e weekends. Wh en social distancing meant th at volunteers couldn't work on community garden plots, h e started offering online classes and a gardening h otline so families could grow at h ome. Wh ile gardening is h is core focus, McKenna says h e is always looking for new ways to help the hungry.()24. What caused Ian's decision to help the kids in his own way?A. Being rejected by volunteer groups.B. Being good at gardening.C. A soup kitchen's support.D. His mother's suggestions.()25. What do we know about the Giving Garden project?A. It helps students only.B. It was started with joint efforts.C. It is funded by schools.D. It earns great profits every year.()26. Which of the following can best explain Ian's personal motto?A. Where there is a will, there is a way.B. A small gesture makes a difference.C. One good turn deserves another.D. Love can break all the barriers.()27. What is the best title of the passage?A. Ian McKenna, Growing a Food BankB. Ian Mckenna, an Experienced GardenerC. Giving Garden Project, an Impossible MissionD. Giving Garden Project, a Universal SolutionCStreaming() first became popular in 2005, thanks to YouTube. Nowadays nearly three quarters of American households subscribe to at least one video streaming service. With almost 200 million subscribers worldwide and a billion hours of content viewed each week, Netflix is by far the biggest paid service. No.2 is Amazon Prime Video. But for every Goliath,__there are a hundred Davids. Many smaller streaming services sh ow noth ing but sports, classic movies, or Japanese anime().In th e early days of streaming, th e appeal was th e lower cost, and it still is. Th e average streamer spends $37 a month (and subscribes to th ree streaming platforms), wh ile th e average cable() user pays more than $200 per month. Still, streaming has become more expensive in recent years. In 2019, Netflix raised the price of its basic service 12.5 percent, to $8.99 a month.A quarter of its subscribers, wh o protested price increases, said th ey would cancel th eir subscriptions. Few did.A major reason: Streaming networks h ave become h ome to many of th e most popular TV series, including recent Emmy winners. They offer full length feature films as well, and last year, Netflix received more Oscar nominations() than any other media company. In fact, streaming has changed the Oscar competition, at least for this year. Usually only films shown in theaters are considered, but because of the coronavirus, all movies released online in 2020 are qualified for the 2021 Academy Awards. That shift is especially good news for Disney, which is putting the much anticipated movie Mulan on its new streaming service, Disney. But watching Mulan from your own home will cost $29.99—on top of the service's monthly fee of $6.99.Too much streaming can have its disadvantages, however. There are those who binge watch, a term Merriam Webster added in 2017 with the definition“to watch many or all episodes of (a TV series) on end.” Alejandro Fragoso from New York holds the Guinness World Record: 94 straight hours.()28. What do the underlined words“Goliath” and“David” in Paragraph 1 refer to?A. TV viewers.B. TV programs.C. Streaming subscribers.D. Streaming services.()29. Why did most Netflix subscribers continue their subscriptions?A. They cannot go without it.B. They think the low cost is a thing of the past.C. Netflix has controlled the market.D. They think it is good value for money.()30. What does the good news in Paragraph 3 mean to Disney?A. The movie Mulan can be released on Disney.B. The movie Mulan will generate great profits.C. The movie Mulan can compete for an Oscar.D. The movie Mulan will win an Oscar award.()31. What do tend to do?A. They start a new life.B. They watch TV series continuously.C. They break world records.D. They watch TV series aimlessly.DNot long ago, Linda Khan was sitting by a hospital bed in Houston, feeling ill at ease. Beside h er lay h er fath er wh o needed a h eart surgery. Th e two of th em h ad engaged in noth ing but depressing small talk. Then, her eye fell on a pile of books. She picked up one, and started to read it out loud.“Righ t away it ch anged th e mood and atmosph ere”sh e says. Reading gave th e daughter a way to connect with her father. Listening allowed the father to travel on the sound of his daughter's voice into a place where he felt himself again.“From then on”Kh an says,“I always read to him.”In a 2010 survey in the United Kingdom, elderly adults who joined weekly read aloud groups reported better concentration, less anxiety, and an improved ability to socialize. The survey authors owed these improvements in large part to the“rich, varied diet of serious literature”th at group members consumed, with fiction encouraging feelings of relaxation and calm, poetry fostering focused concentration, and narratives giving rise to cognitive()th ough ts, feelings, and memories. In truth, almost any kind of reading to another person can be beneficial.Readers get rewards too. For Neil Bush, the late life hospitalizations of his famous parents, George H W. and Barbara Bush, became opportunities to repay a debt of gratitude.“When I was a kid, they would read to me”he said. With his parents in and out of care,“We've been reading books about Dad's foreign policy and, more recently, Mom's autobiography.”Bush went on, h is voice thick with emotion,“And to read their amazing life to them has been a remarkable blessing to me, personally, as their son.”To many people, reading to parents may seem so far outside th e normal range of regular activities, and it may even feel odd and improper. However, there are still a great many people who brave the momentary strangeness of reading to elderly adults and both readers and listeners are, to borrow a phrase from Wordsworth, surprised by the joy of it.()32. What did reading offer to Linda and her father?A. A way to establish a bond.B. A way to travel together in reality.C. A way to treat the disease.D. A way to engage in learning.()33. What is Paragraph 2 mainly about?A. Improvements in mental health.B. Benefits of reading to others.C. Changes in cognitive process.D. Development of social skills.()34. What does Neil Bush's experience prove?A. Reading benefits more than the listener.B. Parents should read more to their kids.C. Children should show their gratitude.D. Reading to parents is children's duty.()35. How does the author feel about reading to an elderly adult?A. Improper and odd.B. Abnormal but worthy.C. Rewarding and joyful.D. Interesting but unnecessary.(5 2.512.5)Rushing to work, watching the stock() market drop daily, working long into the night on a project, all of th ese situations can build up stress. Stress in such situations means pressure, conflict, loss of control, and uncertainty. These feelings can lead to a variety of problems.__36__ Wh at is stress? Stress is your body's ph ysical and psych ological response to anyth ing you regard as overpowering. Th is may be viewed as a result of life's demands, and your lack of resources to meet them.__37__ This additional energy cannot be destroyed. If not used, it creates an imbalance within your system. Somehow the energy must be channeled into responses to regain a balance.__38__ With out some stress you would lose your energy for living. You will do well on certain amounts; but too much or too little stress will limit your effectiveness. Ideally, you find your best level of stress—the balance at which you are most motivated.__39__ It can make you spend your efforts on not being unh appy, rath er th an on being happy.You can become negatively influenced in your attitudes and feelings about your life more easily.In addition, medical research estimates as much as 90 percent of illness and disease is stress related.__40__ High blood pressure and h eart disease h ave been linked to stress factors. Most health professionals agree stress can be a contributing factor in making existing medical problems worse.A. These different attitudes influence a person's reaction to stressful situations.B. That is why stress has such an ugly ring.C. Stress is a natural part of your life.D. In each person's life there are uncertainties.E. When stressed, your body creates extra energy to protect itself.F. Stress can have a bad effect on your physical functioning and bodily processes.G. Too much stress influences your daily life.(30)(15115)A B C DIt was the next morning after we arrived in Cambridge. Dr. Kerry appeared and __41__ that we'd been invited to take a tour of the church.When I stepped inside the church, my __42__ caught in my chest. The room was very large. We were __43__ through a small wooden door, then up a narrow staircase. __44__ the staircase opened onto the roof. I climbed up and __45__ along the ridge(), letting the __46__ take me as I stared out at the broad streets.“You're not afraid of __47__” a voice said. I turned. It was Dr. Kerry. He had __48__ me.I ran down the ridge. Still, Dr. Kerry was behind me but his steps were __49__. Rather than walk facing forward, he moved __50__. I offered him an arm for the last few steps and he took it.“Here you stand, upright, hands in your pockets”h e __51__ toward th e oth er students.“See them Everyone else was holding __52__ to the stone wall, knees bent, backs arched.“It's as if you've been __53__ this roof all your life”he said. He stared at me, waiting for a(n)__54__“I'm just standing”I said.“You are all trying to get your bodies lower because th e __55__ scares you. But if you could just control your panic, this wind would be nothing.”()41. A. th ough t B. suggested C. promised D. announced()42. A. breath B. feeling C. mind D. sigh t()43. A. h it B. led C. drawn D. sent()44. A. Luckily B. Certainly C. Entirely D. Finally()45. A. rolled B. jumped C. walked D. slid()46. A. wind B. anxiety C. terror D. sky()47. A. sh aking B. falling C. moving D. failing()48. A. invited B. caugh t C. watch ed D. followed()49. A. h eavy B. firm C. strange D. fast()50. A. downward B. sideways C. backwards D. upward()51. A. waved B. ran C. pointed D. h eaded()52. A. tigh tly B. randomly C. easily D. carelessly()53. A. in B. on C. under D. with()54. A. instruction B. reflection C. solution D. explanation()55. A. h eigh t B. length C. width D. depth(10 1.515)1Wearing blue jeans, Gary stood in front of an expensive __56__(tailor) shop. After hesitating for several moments, he finally went in and asked to see the suit in the window. The shop assistant looked __57__ on Gary because of the way he __58__(dress). Glancing at him __59__(impatient), h e wh ispered to th e owner nearby. With th e owner's __60__(permit), h e said th at th e suit h ad already been sold. Gary was angry that he was judged by __61__ he was wearing. The next day he returned to the same shop, dressed more properly this time. After seeking out __62__ assistant, he asked to see an expensive looking suit on an upper shelf. Not realizing who Gary was, the assistant was eager to carry out his duty properly this time. With great patience and difficulty, he climbed up to bring the suit down, __63__(apologize) for keeping Gary waiting. The moment Gary looked at it more closely, __64__h e said h e did not like it. He enjoyed__65__(he), making the assistant bring almost everything in the shop to him before he finally settled on buying a tie. Would you do the same if you were Gary?(40)(15)1. 2. 3.1.802.Science Festival goes off with a bang!________________________________________________________________________ ________________________________________________________________________(25)I was still a th ief wh en I met Anil. And th ough only 15, I was an experienced and fairly successful hand.Anil was about 25—a tall, thin fellow—and he looked easy going, kind and simple enough for my purpose. I might be able to get into his confidence.I gave him my most appealing smile.“I want to work for you”I said.“But I can't pay you.”Perhaps I had misjudged the man. I asked“Can you feed me“Can you cook“I can cook”I lied.“If you can cook, then I can feed you.”The meal I cooked that night must have been terrible because Anil gave it to a stray dog and told me to be off. But I just hung around, smiling in my most appealing way, and he couldn't help laughing.Later, he patted me on the head and said never mind, he'd teach me to cook. He also taught me to write my name and said he would soon teach me to write whole sentences and to add numbers. I was grateful.I knew that once I could write like an educated man, there would be no limit to what I could achieve.One evening he came home with a small bundle of notes, saying he had just sold a book to a publisher. At night, I saw him put the money under the mattress().It's time I did some real work, I told myself. After all, he doesn't even pay me.Anil was asleep.I crept up to the bed. Anil was sleeping peacefully.My hand slid under the mattress, searching for the notes. When I found them, I drew them out without a sound. Anil sighed in his sleep and turned on his side, towards me. I was frightened and quickly crawled out of the room.I began to run, holding the notes by the string of my pajamas(). But I slowed down and sat down in the shelter of the clock tower. I should go back to Anil, I told myself, if only to learn to read and write.1.1502.Paragraph 1I hurried back to the room feeling very nervous. ________________________________________________________________________ ________________________________________________________________________________________________________________________________________________________________________________________________________________________Paragraph 2I awoke late next morning to find t h at Anil h ad already made t h e tea. ________________________________________________________________________ ________________________________________________________________________________________________________________________________________________20202021()15BACCB610BBCAA1115BCAAB1620CBABB2123BCA2427ABBA2831DDCB3235ABAC3640BECGF4145DABDC4650ABDCB5155CABDA56. tailor's57. down58. was dressed59. impatiently60. permission61. what62. the63. apologizing64. however65. himselfOne possible versionScience Festival goes off with a bang!Our annual school Science Festival finished on Friday and once again it was amazing fun.To encourage students to take an interest in space exploration, th is year's th eme was “Space”. On Monday afternoon, we attended a lecture about wh eth er life can exist on oth er planets. In Thursday's Science Workshop, students tried different experiments with great interest. On Friday afternoon, every class decorated their classroom and designed activities according to the theme of space.Th e festival attracted much interest from students and everyone is looking forward to next year's Science Festival.One possible versionParagraph 1Ihurriedbacktotheroomfeeling v eryner v ous. It is much easier to steal something than to return it undetected. I opened the door quietly, then stood in the doorway, in clouded moonlight. Anil was still asleep. I crept to the head of the bed, my hand coming up with the notes. I felt his breath on my hand. I remained still for a minute. Then my hand found the edge of the mattress, and slipped under it with the notes.Paragraph 2Ia w okelatenextmorningtofindthatAnilhadalreadymadethetea. He stretc h ed out h is h and towards me with a note between his fingers. My heart sank. I thought I had been discovered.“I made some money yesterday”h e explained.“Now you'll be paid regularly.” My spirits rose.“Today we'll start writing sentences”he said. He knew. But neither his lips nor his eyes showed anything. I smiled at Anil in my most appealing way.W: If I send this package third class, how long will it take to arrive?M: About two weeks. If you use EMS, it is $35 more expensive, but it can get there within two days.Text 2M: I'm sorry I have a bad cough, but I'll manage to make my presentation.W: Thank you for your spirit. But let's not take a risk. You'll need to rest your voice for next week's report.Text 3M: I don't think I'm ever going to find the article that my professor told me about.W: Go to the reference desk. The librarians there can tell you how to track it down with the help of the computer.Text 4M: Jennifer, would you be interested in serving on the membership committee this year?W: Uh, I'm on a bus and can't catch you very clearly. Can I get back to you on that?Text 5W: How did you like the concert? I found it really moving. The conductor almost burst into tears in the end.M: I love classical music, but the conductor seemed a bit inexperienced.Text 6W: Hello... motor insurance department...M: Oh hello... I'd like to ask about insurance for my car.W: Yes, of course. I'll just take a few details. What's your name?M: Patrick Jones.W: And your address?M: It's 40 Bank Road.W: When would you like to start the insurance?M: I'll need it from the 30th of January.W: Right. Mr Jones. I'm getting a couple of quotes coming up on the computer now, and the best bet looks like being with a company called Red Flag. And that comes out at $480 per year.M: Well, that seems OK. It's quite a bit lower than I've been paying.Text 7W: Hi, George! Glad you're back. Crowds of people have phoned you.M: Really?W: I felt just like your secretary!M: Sorry! I went into th e library th is afternoon to look at a newspaper and I came across something really interesting.W: What? A book?M: No, a brochure from a summer festival—mainly Spanish music. Look, I've got it here.W: Spanish music? I really love it! Shall we go then? Spoil ourselves?M: Okay. The only problem is there aren't any cheap seats. It's all one price.W: Well, in that case we could sit right at the front—we'd have a really good view.M: Yeah, though I think that if you sit at the back you actually hear the whole thing better.W: Yes. Anyway, let's decide when we get there first.W: Hi, Sam. I'm thinking of applying for a job with a multinational company, but I'm worried about having an interview in English. Can you give me any good tips?M: Hum. That's a tough question. I guess the first thing is to try to make a good impression.W: All the people say that! But I just don't know what to do!M: Well, let me see. You should learn a little bit about the company before the interview. Find out wh at th ey do, wh at th eir business concept is, th at kind of th ing. You sh ould also anticipate possible questions, and think about how you will answer.W: Should I memorize my answer beforehand?M: No, definitely not! You should be natural when you speak.W: I never th ought about th at before. But wh at sh ould I do if I can't remember an English word when answering a question?M: In that case, you can use other words to explain what you want to say.W: That's very helpful, Sam.Text 9M: Hello, this is Land Transport Information at Toronto Airport. How may I help you?W: Oh, good morning. Um, I'm flying to Toronto Airport next week, and I need to get to a town called, um, Milton. Could you tell me how I can get there?M: Milton, did you say? Let me see. I think that's about 150 miles of here. In fact it's 147 miles to be exact, so it'll take you at least—say, three to four hours by road.W: Wow! Is it as far as that?M: Yes, I'm afraid so. But you have a number of options to get there and you can always rent a car right here at the airport, of course.W: Right. Well, I don't really want to drive myself, so I'd like more information about public transport.M: OK. In that case the quickest and most comfortable is a taxi. But it'll cost you. You can also take a Greyhound bus to Milton.W: Hmmm, I think for that kind of distance a taxi would be way beyond my budget. But the bus sounds OK. Can you tell me how much that would cost?M: Sure. Let's see, that would be $15 one way, or $27.50 return... that's on the Greyhound.W: Oh, that's quite cheap. Great!Text 10Welcome to our business class. Today we will discuss if a consumer has to choose between two products of the same price, what factor determines the choice. They choose the one they think is of higher quality. Business analysts usually speak of two major factors of quality—one factor is reliability, and the other is what we call features.First of all, what's reliability? A product is reliable if it can maintain a reasonable amount of time with out needing repairs. Wh en people th ough t about product quality, th ey used to th ink mainly about reliability. Today it's different. But don't get me wrong. People do still care about reliability. It's just th at manufacturing standards are now so h igh th at ... take cars for example, today's cars are all very reliable. So reliability is important, but it's not the deciding factor.Features are gaining more attention—the things a product has that aren't really necessary but make it easier to use or make it cool. For example, new cars today are loaded with features like electric windows, sun roofs and so on. When people are comparing products today, they look at。

2020年10月江苏省苏州市相城区2021届高三毕业班阶段性诊断测试化学试题及答案

2020年10月江苏省苏州市相城区2021届高三毕业班阶段性诊断测试化学试题及答案

绝密★启用前江苏省苏州市相城区普通高中2021届高三毕业班上学期阶段性诊断测试化学试题2020年10月注意事项:1.本试卷分为选择题和非选择题两部分,选择题36分,非选择题64分,共100分。

考试时间90分钟。

2.将选择题的答案填涂在答题卡的对应位置上,非选择题的答案写在答题卡的指定栏目内。

可能用到的相对原子质量:H 1 O 16 Na 23 S 32 Cl 35.5 K 39 Fe 56 I 127选择题(共36分)单项选择题:本题包括8小题,每小题2分,共计16分。

每小题只有一个选项符合题意。

1.化学与生活密切相关。

下列说法中不.正确的是A.漂白粉的有效成分为Ca(ClO)2B.碳酸氢钠可用于治疗胃酸过多C.酸中毒病人可输入0.9%的氯化铵溶液D.工业上可利用油脂的碱性水解制取肥皂2.下列有关化学用语表示正确的是A.原子核内有10个中子的氧原子:1810O B.硫离子的结构示意图:C.次氯酸钠的电子式:D.葡萄糖分子的结构简式:C6H12 O63.下列有关物质性质与用途具有对应关系的是A.SO2具有氧化性,常用于漂白秸秆、织物B.明矾水解形成Al(OH)3胶体,可用作水处理中的净水剂C.石英坩埚耐高温,可用来加热熔化烧碱、纯碱等固体D.次氯酸有酸性,可用于自来水的杀菌消毒4.常温下,下列各组离子能大量共存的是A.pH=12的溶液中K+、Na+、Br-、AlO2-B.c(Fe3+)=0.1 mol·L-1的溶液中:Na+、K+、Cl-、CO3-C.0.1 mol·L-1 NaHCO3溶液:Na+、Ba2+、NO3-、OH-D.由水电离出的c(OH)=1.0×10-13mol·L-1的溶液中:Na+、NH4+、SO42-、HCO3-5.下列实验操作正确的是6.下列解释事实的方程式正确的是A..用稀硫酸除去硫酸钠溶液中少量的硫代硫酸钠:Na2S2O3+2H+=SO2↑+S↓+2Na++H2OB.氢氧化亚铁暴露于空气中会变色:4Fe(OH)2+O2+2H2O=4Fe(OH)3C.向Ca(ClO)2溶液中通入过量CO2制取次氯酸:Ca2+ClO-+H2O+CO2=2HClO+CaCO3↓D.氯气用于自来水消毒:Cl2+H2O2H++Cl-+ClO-7.短周期主族元素X、Y、Z、W原子序数依次增大,X、W同主族,Y+与X2-具有相同的电子层结构,Z原子的最外层电子数等于X原子最外层电子数的一半,则下列叙述正确的是A.Y2X2中阴阳离子的个数比为1:1B.原子半径的大小顺序:r(W)>r(Z)>r(Y)>r(X)C.X和W形成的常见化合物WX2为直线型分子D.Y、Z的最高价氧化物的水化物之间能发生反应8.α-氰基丙烯酸异丁酯可用作医用胶,其结构简式如下图,下列关于α-氰基丙烯酸异丁酯的说法错误的是。

2020年9月江苏省苏州四市五区2021届高三上学期期初调研测试英语试题及答案

2020年9月江苏省苏州四市五区2021届高三上学期期初调研测试英语试题及答案

绝密★启用前江苏省苏州四市五区2021届高三年级上学期期初调研测试英语试题2020年9月注意事项:1.本试卷满分150分,考试时间 120分钟。

2.答题前,务必将自己的学校、姓名、考试号等相关信息写在答题卡上规定的地方。

3.回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动,用橡皮擦净后,再选涂其他答案标号,回答非选择题时,将答案写在答题卡上,写在本试卷上无效。

第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。

录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What does the man want the woman to do?A.Attend the party.B.Invite more people.C.Prepare the food.2.What are the couple talking about?A.Drinking tea.B.Buying a gift.C.Having a habit.3.When will they ask Ken for dinner?A.Next Friday.B.This Thursday.C.This Friday.4.How much did the woman pay?A.100 dollars.B.80 dollars.C.50 dollars.5.Where does the conversation probably take place?A.In a supermarket.B.In a hospital.C.In a restaurant.第二节(共15题;每小题1.5分,满分22.5分)听下面5段对话或独白。

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苏州市2021年高三教学调研测试(附答案)化学注意事项:l.本试卷分为第1卷(选择题)和第Ⅱ卷(非选择题)两部分,共150分。

考试时间120分钟。

2.请把第Ⅰ卷的答案涂在答题卡上,第Ⅱ卷的答案写在答题卷的指定栏目内内可能用到的相对原子质量:H—1 C—12 O—16 Cl—35.5 Cl—35.5 Pd—106.4第 I 卷(选择题共64分)选项符合题一、单项选择题(本题包括8小题,每小题4分,共32分。

每小题只有一个....意).1.生活中的问题常涉及到化学知识,下列叙述中正确的是A.硫酸钡是一种难溶于水和酸的盐,可用作X光透视肠胃的药剂B.使用明矾可以对水进行消毒、杀菌C.铁制品在干燥的空气中易生锈D.棉花、蚕丝和人造丝的主要成分是纤维素2.《科学》杂志评出2021年十大科技突破,其中“火星上‘找’到水的影子”名列第一。

下列关于水的说法中正确的是A.若火星有水就具探寻生命踪迹的意义 B.弱酸的酸式盐一定能促进水的电离C.催化剂能提高水分解的转化率 D.金属的电化腐蚀与水无关的是3.下列化学用语错误..A.铵根离子的结构式 B.二氧化碳的电子式C.S2—的结构示意图 D,乙烯的最简式CH2的是4.下列关于工业生产的叙述中,错误..A.用离子交换膜法电解饱和食盐水制烧碱B,目前合成氨,没有采用更高温度、更大压强是从设备和动力要求方面考虑的C.采用电解熔融氯化铝的方法制取金属铝D.生产硫酸时,接触室内热交换器的作用是预热进入的炉气和冷却反应生成的气体5.纤维素被称为第七营养素。

食物中的纤维素虽然不能为人体直接提供能量,但能促进肠道蠕动,粘附并带出有害物质。

从纤维素的化学成分看,它是一种A.二糖 B.多糖 C.氨基酸 D.脂肪6.现有下列物质:①氯水②溴水③碘水④臭氧⑤二氧化氮⑥稀硝酸,其中能使淀粉碘化钾溶液变蓝的是A.①②⑥ B.④⑤ C.除③外 D.全部7.下列实验能达到预期效果的是①用乙醇和浓硫酸除去乙酸乙酯中的少量乙酸②将氯气的制备和性质实验联合进行以减少对空气的污染⑧用食醋和澄清石灰水验证蛋壳中含有碳酸盐④用硝酸钡溶液鉴别硫酸根离子与亚硫酸根离子⑤用溴水检验汽油中含有不饱和烃A.①②③ B.①③④C.②③⑤ D.②④⑤8.城市环境污染是当前突出的环境问题。

如图甲所示,X河流经某工业城市,其中a处在上游,附近有丰富的黄铁矿资源,d处在下游,有多个企业以硫酸为原料。

根据某月该市环保局监测站对X河水质检测的结果,绘制成图乙。

根据甲、乙两图,判断下列说法的是中错误..A.造成X河污染的主要污染源最可能分布在bc段B.工业、生活污水和固体废弃物等可能是造成X河污染的污染源C.d处污染程度减小,可能是某些污染物的离子间发生反应所致D.该城市建造硫酸厂时,综合考虑诸多因素选址在b处最合理选项二、不定项选择题(本题包括8小题,每小题4分,共32分。

每小题有一个或两个.....符合题意。

若正确答案只包括一个选项,多选时,该题为0分;若正确答案包括两个选项,只选一个且正确的得2分。

选两个且都正确的得满分,但只要选错一个该小题就为0分)9.某混合气体G可能含有CO、CO2、SO2、H2O等气体,用a.无水CuSO4、b.澄清石灰水、c.灼热CuO、d.碱石灰、e.酸性品红溶液、f.酸性高锰酸钾溶液等药品可将其一一检出,检出的正确顺序是A.G→a→e→b→f→d→c B.G→c→d→b→e→f→aC.G→a→e→f→b→d→c D.G→b→e→f→a→d→c10.高铁酸钾(K2FeO4)是一种新型、高效、多功能水处理剂,其与水的离子反应是: 4FeO42—+10H2O=4Fe(OH)3(胶体)+3O2↑+8OH—工业上先制得高铁酸钠,然后在低温下,向高铁酸钠溶液中加入一定量的KOH就可制得高铁酸钾。

制备高铁酸钠的两种方法的主要反应原理如下:湿法制备——2Fe(OH)3+3ClO—+4OH—=2FeO42—+3Cl—+5H2O;干法制备——2FeSO4 +6Na2O2=2Na2FeO4+2Na2O+2Na2SO4+O2↑。

下列有关说法中错误的是..A.高铁酸钾与水反应时,水发生还原反应B.湿法中每生成1mol Na2FeO4共转移3mol电子C.干法中每生成1mol Na2FeO4共转移4mol电子D.K2FeO4处理水时,不仅能杀菌,还能除去H2S、NH3等,并使悬浮杂质沉降11.下列关于试剂保存方法的叙述错误的是..A.氢氧化钠固体保存在配有橡皮塞的细口瓶中B.溴水盛放在配有橡皮塞的细口瓶中C.金属钾浸没在盛有煤油的广口瓶中D.白磷密封在盛满冷水的广口瓶中12.一定能在下列溶液中大量共存的离子组是A.滴加石蕊试液显红色的溶液:Fe3+、NH4+、C1—、SCN—B.pH为1的盐酸溶液:Ca2+、Na+、Mg2+、NO3—C.与铝反应放出氢气的溶液:K+、SO32—、Br—、,Na+D.亚硫酸钠溶液:K+、SO42—、NO3—、H+13.阿伏加德罗常数约为6.02×1023mol—1,下列说法中正确的是A.将通常状况下分子数为6.02×1023的NO2和N2O4气体变至标准状况肘其体积为22.4LB.7.1g氯气与足量石灰乳充分反应转移电子数为0.2×6.02×1023C.常温常压下体积均为11.2L的CO2和SO2所含有的氧原子数都是6.02×1023D.新戊烷与异戊烷的混合物7.2g中所含共价键数目为1.6×6.02×102314.化学家们合成了如下图所示的一系列的星烷,如三星烷、四星烷、五星烷等。

下列说法正确的是A.它们的一氯代物均只有三种B.它们之间互为同系物C.三星烷与乙苯互为同分异构体D.六星烷的化学式为C18H2415.已知甲为恒温恒压容器,乙为恒温恒容容器。

初始时,两容器的温度、体积相同,两容器中均充入2molSO 2和lmolO2,且发生反应为2SO2(g)+O2(g)2SO3(g);△H<0;当两容器都达到平衡后,为使两者中的SO2在平衡混合物中的物质的量分数相同,下列措施中可行的是A.向甲容器中再充人一定量的氦气 B.向乙容器中再充人2mol的SO3气体C.适当降低乙容器的温度 D.缩小甲容器的体积16.在15mL0.1 mol·L-1KOH溶液中逐滴加入0.2 mol·L-1甲酸溶液,溶液pH和加入的甲酸的体积关系曲线如下图所示,有关粒子浓度大小关系正确的是A.在A、B间任意一点:c(K+)>c(HCOO—)>c(OH—)>c(H+)B.在B点:c(K+)=c(HCOO—)>c(OH—)=c(H+),且a=7.5C.在C点:c(HCOO—)>c(K+)>c(OH—)>c(H+)D.在D点:c(HCOO—)+c(HCOOH)>2c(K+)第Ⅱ卷(非选择题共86分)三、(本题包括2小题。

共19分)17.(6分)下列有关实验的叙述,正确的是(选填字母序号)。

A.制备乙酸乙酯时,将乙醇和乙酸依次倒入到浓硫酸中B.用干燥且沽净的玻璃棒蘸取待测液滴到放在表面皿上的pH试纸上C.滴定管洗净后,经蒸馏水润洗即可注入标准液进行滴定D.铜片跟稀硝酸反应产生的气体可用排水法收集E.用浓氨水洗涤做过银镜反应的试管F.在溴水中滴入少量苯酚溶液有白色沉淀生成18.(13分)海带中含有丰富的碘。

为了从海带中提取碘,某研究性学习小组设汁并进行了以下实验:请填写下列空白:(1)步骤①灼烧海带时,除需要三脚架外,还需要用到的实验仪器是(从下列仪器中选出所需的仪器,用标号字母填写在空白处)。

A.烧杯 B.坩埚 C.表面皿 D.泥三角 E.酒精灯 F.干燥器(2)步骤③的实验操作名称是;步骤⑥的目的是从含碘苯溶液中分离出单质碘和回收苯,该步骤的实验操作名称是(3)步骤④反应的离子方程式是(反应后Mn以Mn2+存在)。

(4)步骤⑤中,某学生选择用苯来提取碘的理由是(5)请设计一种检验提取碘后的水溶液中是否还含有单质碘的简单方法:四、(本题包括2小题。

共17分)19.(6分)科学家认为,氢气是一种高效而无污染的理想能源,近20年来,对以氢气作为未来的动力燃料氢能源的研究获得了迅速发展。

(1)为了有效发展民用氢能源,首先必须制得廉价的氢气,下列可供开发又较经济且资源可持续利用的制氢气的方法是A.电解水 B.锌和稀硫酸反应 C.光解海水 D.以石油、天然气为原料(2)用氢作为能源亟待解决的又一问题是贮氢材料的开发,研究表明某些过渡金属镧(La)、钯(Pd)能与氢原子形成氢化物,氢原子填充在金属晶体内的间隙之间,其组成不固定,通常是非化学计量的,如镧的氢化物的化学式可表示为LaH2.76 。

已知钯粉的密度为10.64g /cm3,1体积的钯粉大约可吸附标准状况下896体积的氢气,则钯的氢化物的化学式为(3)因氢气易燃易爆,贮运安全极为重要。

已知氢气的燃烧热为285.8kJ·mol—1.写出其完全燃烧的热化学方程式:20.(11分)有原子序数依次增大的4种短周期元素X、Y、Z、W,已知:①X与Z、 Y与W分别同主族;②X、Z、W分别与Y都能形成两种常见的化合物;③Y的阴离子与Z的阳离子的核外电子排布相同,,试根据以上叙述填空。

(1)写出由Y与Z形成的化合物Z2Y2的电子式,其化学键类型有(2)写出由X、Z、W三种元素组成的盐溶于水呈碱性的离子方程式(3)写出均由这4种元素组成的两种化合物在水溶液中发生反应的离子方程式(4)X、Y两种元素的单质已被应用于字宙飞船的燃料电池中,如右图所示,两个电极均由多孔性碳构成,通入的两种单质由孔隙逸出并在电极表面放电。

①b是电池的极②a电极上的电极反应式是五、(本题包括l小题,共12分)21.(12分)1919年,Langmuir提出:原子数相同、电子数相同的分子,互称为等电子体。

等电子体的结构相似、物理性质相近,称为等电子原理。

后来,该原理被推广使用于一些具有特殊功能的晶体的发现和人工合成等诸多领域。

如:X是一种新型无机材料,它与碳化硅(SiC)结构相似、物理性质相近,符合该原理。

X有如下的转变:其中:C是一种能使湿润的红色石蕊试纸变蓝的无色气体,D为白色沉淀,E溶液在焰色反应中的火焰呈黄色。

回答以下问题:(1)写出X的化学式,X属于晶体(选填“原子”或“分子”或“离子”)。

(2)写出X与A溶液反应的化学方程式:写出K与J反应的化学方程式:(3)最近科学家研究出一种新物质与氮气反应制备X和SiC的方法,该反应原理如下:+2N2 高温4X+SiC+3C(试在横线上填新物质的化学式)。

六、(本题包括2小题。

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