2016年广州市16中2016年一模
2016年广东广州越秀区十六中一模数学试卷答案
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/12/03i ka ng .c om2018/12/03D.,.45∘∠AOB =155∠COD =155−90−30=35B.C.如图是一无盖的正方体盒子,下列展开图不能折叠成无盖正方体的是( )C. D.的正方形纸片剪去两个小矩形,得到一个“”的图案,如图②所示,再将剪下的两个小矩形拼成一个新的矩形,如图③所示,则新矩形的周长可表示为( ).2a −4b4a −10b 编辑只有①③D.,则的值是( =1−a a2j i ao sh i.i zh i 已知,如图,点、、、在同一直线上,,试说明:B F C E BF =EC AB =DE编辑(3))的条件下,连接和,则OB ′BB ′△OBB 6∴一共有种等可能的结果,两次摸出的球恰好颜色不同的有∴两次摸出的球恰好颜色不同的概率为9教师版 答案版/12/03的延长线于点,在其它条件不变的情况下,判断四边形中补全图象并证明你的结论.,−r E018/12/03运动,点同时从点出发,以速度沿向分别是线段,上的动点,连结并延长交正方形的边于,AC CD DE DCN =90∘D E A cm/s 2√ACj i ao sh i .i zh ik an g.co m2018/12/03/12/031判断命题“当点是边中点时,则点是边的三等分点”的真假,并说明理由.答 案解 析2连结、,能否为等腰三角形?若能,请写出,之间的关系.若不能,请说明理由.答 案解 析该命题是真命题.该命题是真命题.理由如下:当点是边中点时,则.∵,∴,∴,∴,则,∴.则,∴点为边的三等分点.当或时,能够成为等腰三角形.能.理由如下:易证,∴,即,得.易证,∴,即,得.∴,.若为等腰三角形,则可能有三种情形:()若,则由知≌,∴,即,得,不合题意.∴此种情形不存在.()若,由知,,∴,∴,此时点与点重合.()若,显然此时点在边上,如下图所示:由,得,∴,∴,由,得,∴,∴,在和中,∵,∴≌,∴.又由,∴,即,∴.∴,∴,此时点与点重合.综上所述,当或时,能够成为等腰三角形.F AB M CD F AB AF =AB =CD 1212AB //CD △AFE ∽△CDE ==AE EC AF CD 12AE =EC 12AE =AC =a 132√3t ==a AE 2√13CM =1⋅t =a =CD 1313M CD FM FN △MNF a t t =a t =a 12△MNF △AFE ∽△CDE =AF CD AE EC =AF a t 2√a −t2√a √AF =ata −t △MND ∽△DFA =ND AF DM AD =ND at a −ta −ta ND =t ND =CM =t AN =DM =a −t △MNF i FN =MN AN =DM △FAN △NDM AF =ND =t ata −t t =0ii FN =FM MN ⊥DF HN =HM DN =DM =MC t =a 12F B iii FM =MN F BC △CEF ∽△AED =CF AD CEAE=CFa a −t 2√2√t2√CF =a (a −t )t △DNM ∽△CDF =DM CF DNDC=a −ta (a −t )tDN aDN =t =CM Rt △MFC △NMD {ND =CMFM =MN△MFC △NMD FC =DM =a −t △NDM ∽△DCF =DN DM DC FC =t a −t aFCFC =a (a −t )t =a −t a (a −t )tt =a F C t =a t =a 12△MNF 学生版 教师版 答案版编辑E F 最小,并求出这个最小值.目录选择题(本大题共10小题,每小题3分,…填空题(本大题共6小题,每小题3分,…解答题(本大题共9小题,共102分)。
广东省广州市番禺区16中考一模化学试卷(答案图片版)
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反应中甲、乙的分子个数之比是 ( 4)废旧钢铁表面的铁锈可用盐酸除去,其化学方程式是
。 ____________________ 。
22.( 6 分)利用海水提取粗盐的过程如下图所示,回答有关问题
(1)一定质量的海水,通过贮水池引入到蒸发池中,在没有引入结晶池之前的蒸发过程中,蒸发池
中氯化钠的质量会
(3)新型材料纳米铁粉具有广泛的用途,它比普通铁粉更易与氧气反应,其制备的主要流程如下 图所示。
FeCl2、 H2
高温反应器
HCl 和纳米级铁粉
① 纳米级铁粉遇氧气无需加热就能燃烧,生成物的化学式为
。
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A .FeCO3 中 Fe、 C、O 元素的质量比是 1:1:3
B .FeCO3 中 Fe、 C、O 的原子个数比是 56:12:48
C. FeCO3 中 Fe 元素的质量分数是
降到室温。 于是,同学们设计实验来探究 “一定质量的锌粒和同体积盐酸反应快慢的影响因素”
。
测得实验数据如下:
一定质量的锌粒与同体积盐酸溶液反应实验数据表
盐酸溶液 浓度 5% 10% 15% 5% 10% 15%
反应开始时酸溶液的 温度 20℃ 20℃ 20℃ 35℃ 35℃ 35℃
反应开始到 2 分钟产生的 气体体积 10 mL 19 mL 28 mL 28 mL 72 mL 103 mL
选项 实验目的
①和④
D.
实验方法
①和⑤
A
检验一瓶气体是否为 CO 2
广东省广州市2016年普通高中毕业班综合测试(一模)理综试题(mord文字版)
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2016广州理科综合测试(一)物理试卷第Ⅰ卷二、选择题:本题共8小题,每小题6分。
在每小题给出的四个选项中,第14~18题只有一项符合题目要求,第19~21题有多项符合题目要求。
全部选对的得6分,选对但不全的得3分,有选错的得0分。
14.物理学史上是哪位科学家、由于哪项贡献而人们称为“能称出地球质量的人” A .阿基米德,发现了杠杆原理 B .牛顿,发现了万有引力定律 C .伽利略,测出了重力加速度的值 D .卡文迪许,测出了万有引力常量 15.不计重力的两个带电粒子M 和N 沿同一方向经小孔S 垂直进入匀强磁场,在磁场中的径迹如图。
分别用v M 与v N , t M 与t N ,M Mm q 与NN m q 表示它们的速率、在磁场中运动的时间、荷质比,则A .如果M M m q =NNm q ,则v M > v N B .如果M M m q =NNm q ,则t M < t N C .如果v M = v N ,则M Mm q >NN m q D .如果t M = t N ,则M Mm q >NN m q 16.如图a ,理想变压器原、副线圈的匝数比为2∶1,与副线圈相连的两个灯泡完全相 同、电表都为理想电表。
原线圈接上如图b 所示的正弦交流电,电路正常工作。
闭合开关后,A .电压表示数增大B .电流表示数增大C .变压器的输入功率增大D .经过灯泡的电流频率为25 Hz17.如图,窗子上、下沿间的高度H=1.6m ,墙的厚度d=0.4m ,某人在离墙壁距离L=1.4m 、距窗子上沿h=0.2m 处的P 点,将可视为质点的小物件以v 的速度水平抛出,小物件直接穿过窗口并落在水平地面上,取g=10m/s 2。
则v 的取值范围是A .7>v m/sB .32.v <m/sC .7m/s m/s 3<<vD .3m/s m/s 32<<v .ab18.电梯经过启动、匀速运行和制动三个过程,从低楼层到达高楼层,启动和制动可看作是匀变速直线运动。
2016年广州一模理科数学答案
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教
3 , OA1 AA12 OA2 1.………………6 分
则 B 1,0,0 , C 0, 3, 0 , A 0, 3, 0 , A 1 0,0,1 ,
州
所以 BB1 AA1 0, 3,1 ,OB1 OB + BB1 1, 3,1 .………………………7 分 设平面 OBB1 的法向量为 n x, y, z ,
教
tr .e
所以 AD 的长为 5 . …………………………………………………………………6 分
研
解得 x 5 .
du
.c n
/
AB 2 BC 2 AC 2 13x 2 100 .…………4 分 2 AB BC 6 x 4 x 2 25
解法三:因为 AD 的长为 5 , 所以 cosCDB = 所以 S ADC
6 5
.…………………………………………9 分
tr .e
du
.c n
C
/
所以 cos CKH
KH CK
6 4
.……………………………………………………11 分
所以二面角 B OB1 C 的余弦值为
6 4
.……………………………………12 分
(20) (Ⅰ)解法一:设椭圆 C 的方程为
A1
tp :/
x 0, x 3 y z 0.
/w
D O A B x
C
y
令 y 1,
得 n 0,1, 3 .…………………………………………………………9 分
ht
同理可求得平面 OCB1 的法向量为 m 1,0, 1 .………………………………10 分 所以 cos n, m
【广州】2016-2017广州越秀区第十六中学初三一模【解析版】
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第一部分选择题(共40分)一、单选题(本题包括20小题,每小题2分,共40分)1.下列物质的变化,前者属于物理变化,后者属于化学变化的是()A.面包发霉、鸡蛋煮熟B.干冰升华、冰雪融化C.酒精挥发、酒精燃烧D.铁钉生锈、光合作用【答案】C【解析】A.面包发霉是化学变化,鸡蛋煮熟是化学变化,故A错误;B.干冰升华是物理变化,冰雪融化是物理变化,故B错误;C.酒精挥发是物理变化,酒精燃烧是化学变化,故C正确;D.铁钉生锈是化学变化,光合作用是化学变化,故D错误;故本题选C。
2.下列化学符号所表示的意义最多的是()A.Fe B.O C.H+ D.2H2O【答案】A【解析】A.Fe可以表示Fe元素、Fe原子、Fe单质;B.O可以表示O元素、O原子;C.H+表示氢离子;D.2H2O表示2个水分子;综上,Fe表示的意义最多,故本题选A。
3.小明不慎被蜜蜂蜇伤。
蜜蜂的刺液是酸性的,下列物品中可以用来涂抹在蜇伤处减轻疼痛的是()A.苹果汁(pH约为3)B.牛奶(pH约为6.5)C.矿泉水(pH约为7)D.肥皂水(pH约为10)【答案】D【解析】A.苹果汁是酸性的,不能减轻疼痛,故A错误;B.牛奶是弱酸性的,不能减轻疼痛,故B错误;C.矿泉水是中性的,不能减轻疼痛,故C错误;D.肥皂水是碱性的,可以中和蜜蜂的酸性刺液,故D正确;故本题选D。
4.地壳中含量最多的金属元素和非金属元素形成的化合物是()A.SiO2 B.H2O C.Fe2O3 D.Al2O3【答案】C【解析】地壳中含量最多的金属元素是Al,非金属元素是O,它们形成的化合物是Al2O3。
故本题选D。
5.下列物质的性质与化学性质无关的是()A.用氮气作食品包装袋的填充气B.用熟石灰改良酸性土壤C.用干冰人工降雨D.用含氢氧化铝药物治疗胃酸过多【答案】C【解析】A.用N2作填充气是利用了其在常温下化学性质较稳定,是化学性质,故A错误;B.用Ca(OH)2改良酸性土壤是利用了Ca(OH)2的碱性,是化学性质,故B正确;C.用干冰人工降雨是利用了干冰升华吸热的性质,是物理性质,故C正确;D.用Al(OH)3治疗胃酸过多是利用了Al(OH)3的碱性,是化学性质,故D错误;故本题选C。
2016年广东省广州市一模语文试卷及答案
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2016年广州市普通高中毕业班综合测试(一)语文2016.3注意事项:1.本试卷共8页,18题,满分为150分,考试用时150分钟;分第Ⅰ卷(阅读题)和第Ⅱ卷(表达题)两部分;答卷前,考生务必将自己的姓名、准考证号、试室号、座位号填写在答题卡上,并用铅笔在答题卡上的相应位置填涂考生号。
2.作答时,将答案写在答题卡上。
写在本试卷上无效。
3.考试结束后,将本试卷和答题卡一并交回。
第I卷阅读题甲必考题一、现代文阅读(9分,每小题3分)国内外学界在讨论中国古代对外关系时,首先就会想到古代的朝贡制度以及中国中心主义,由此关注起中国儒家的天下观。
不过,天下观只是儒家的世界秩序学说,在涉外实践中如何实现理想的世界秩序,儒家学者们还提出了一套涉外理念与之配合。
儒家的天下观旨在构建理想的“天下”秩序。
要使“天下”有序,就要“协和万邦”。
《尚书〃尧典》中记载,帝尧家族内部关系融洽后,又先后在各部落以及更远的外邦间次第推行德治与仁爱,使各部落以及外部邦国和平有序。
儒家把“和”看作是处理中国与外国关系的思想准则。
“和也者,天下之达道也。
”即“和”是天下通行的道理,是天下各安其所的交往方式。
而“和”的本质是“仁”,“仁”不仅适用于人际关系,也适合于国家间的关系。
《左传》将这种“仁”推及国家间的关系,认为“亲仁善邻,国之宝也”。
儒家崇尚和谐,强调“和为贵”。
如何达到“和为贵”?其中的重要途径是“和而不同”。
孔子说“君子和而不同,小人同而不和”。
“和而不同”,在处理国家间的关系上,就是要允许、承认并尊重各国间的文化、信仰和制度的不同,求同存异,从而达到和谐共处。
尤其值得指出的是,尽管儒家主张“天下一家”,但后世儒者却多主张“王者不治夷狄”。
他们旨在阐述,“中国”帝王不要去直接统治“夷狄”,应与“夷狄”各守其境,和平相处。
所以,即使是明朝派遣郑和率领庞大水军巡游东南亚以及印度洋诸国时,他们也是秉持着“圣王”对于“夷狄之邦,则以不治治之”的坚定理念,来处理与这些国家间的政治关系。
广州市黄埔区2016年中考数学一模试卷附答案解析
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2016年广东省广州市黄埔区中考数学一模试卷一、选择题(本大题共10小题,每小题3分,满分30分,在每小题给出的四个选项中,只有一项是符合题目要求的.)1.在﹣3,﹣2,2,1四个实数中,最大的实数是()A.﹣3 B.﹣2 C.2 D.12.下列图形中不是轴对称图形的是()A.B.C.D.3.一个几何体的三视图如图所示,那么这个几何体是()A.B.C.D.4.下列运算正确的是()A.x2•x3=x6B.(x2)3=x6C.x2+x3=x5D.x2+x2=2x45.数据0,1,1,3,3,4的中位数和平均数分别是()A.2和2 B.2和2.4 C.1和2 D.3和26.将分式方程去分母后得到正确的整式方程是()A.x﹣2=x B.x2﹣2x=2x C.x﹣2=2x D.x=2x﹣47.抛物线y=﹣(x+2)2﹣3向右平移了3个单位,那么平移后抛物线的顶点坐标是()A.(﹣5,﹣3)B.(﹣2,0)C.(﹣1,﹣3)D.(1,﹣3)8.下列命题中正确的是()A.对角线相等的四边形是菱形B.对角线互相垂直的四边形是菱形C.对角线相等的平行四边形是菱形D.对角线互相垂直的平行四边形是菱形9.已知函数y=(k﹣3)x2+2x+1的图象与x轴有交点,则k的取值范围是()A.k<4 B.k≤4 C.k<4且k≠3 D.k≤4且k≠310.如图,AB是⊙O的直径,CD是⊙O的切线,切点为D,DC与AB的延长线交于点C,∠A=30°,给出下面3个结论:∠BDC=∠A;AB=2BC;AD2=3BC2;其中正确结论的个数是()A.0 B.1 C.2 D.3二、填空题(本大题共6小题,每小题3分,满分18分.)11.如图,在△ABC中,D是AB延长线上一点,∠A=30°,∠CBD=130°,则∠ACB=.12.某校九年级共390名学生参加模拟考试,随机抽取60名学生的数学成绩进行统计,其中有20名学生的数学成绩在135分以上,据此估计该校九年级学生在这次模拟考试中数学成绩在135分以上的大约有名学生.13.分解因式:x2﹣4y2=.14.若点M(m,1)在一次函数y=x﹣2的图象上,则m=.15.如图,在△ABC中,AB=5,AC=3,AD、AE分别是其角平分线和中线,过点C作CG⊥AD 于F,交AB于G,连接EF,则线段EF的长为.16.如图,已知△ABC和△AED均为等边三角形,点D在BC边上,DE与AB相交于点F,如果AC=12,CD=4,那么BF的长度为.三、解答题(本大题共9小题,满分102分.解答应写出文字说明、证明过程或演算步骤)17.解不等式组:,并把解集在数轴上表示出来.18.解方程.19.如图,在Rt△ABC中,∠ACB=90°.(1)利用直尺和圆规按下列要求作图,并在图中标明相应的字母.(保留作图痕迹,不写作法)①作AC的垂直平分线,交AB于点O,交AC于点D;②以O为圆心,OA为半径作圆,交OD的延长线于点E.(2)在(1)所作的图形中,解答下列问题.①点B与⊙O的位置关系是;(直接写出答案)②若DE=2,AC=8,求⊙O的半径.20.如图,在平面直角坐标系xOy中,直线经过第一、二、四象限,与y轴交于点B,点A(2,m)在这条直线上,连结AO,△AOB的面积等于2.(1)求b的值;(2)如果反比例函数(k是常量,k≠0)的图象经过点A,求这个反比例函数的解析式.21.如图,正方形的边长为2,中心为O,从O、A、B、C、D五点中任取两点.(1)求取到的两点间的距离为2的概率;(2)求取到的两点间的距离为的概率;(3)求取到的两点间的距离为的概率.22.甲乙两人各加工30个零件,甲比乙少用1小时完成任务;乙改进操作方法,使生产效率提高了一倍,结果乙完成30个零件的时间比甲完成24个零件所用的时间少1小时.问甲乙两人原来每小时各加工多少个零件.23.如图,在边长为4的菱形ABCD中,BD=4,E、F分别是AD、CD上的动点(包含端点),且AE+CF=4,连接BE、EF、FB.(1)试探究BE与BF的数量关系,并证明你的结论;(2)求EF的最大值与最小值.24.如图,AB是⊙O的直径,AC是⊙O的切线,BC交⊙O于点E,连接AE.(1)若D为AC的中点,连接DE,证明:DE是⊙O的切线;(2)若BE=3EC,求tan∠ABC.25.如图,在平面直角坐标系中,抛物线y=﹣x2+bx+c与x轴交于A(﹣3,0)、B(1,0)两点,与y轴交于点C,D是抛物线的顶点,E是对称轴与x轴的交点.(1)求抛物线的解析式,并在﹣4≤x≤2范围内画出此抛物线的草图;(2)若点F和点D关于x轴对称,点P是x轴上的一个动点,过点P作PQ∥OF交抛物线于点Q,是否存在以点O、F、P、Q为顶点的平行四边形?若存在,求出点P坐标;若不存在,请说明理由.2016年广东省广州市黄埔区中考数学一模试卷参考答案与试题解析一、选择题(本大题共10小题,每小题3分,满分30分,在每小题给出的四个选项中,只有一项是符合题目要求的.)1.在﹣3,﹣2,2,1四个实数中,最大的实数是()A.﹣3 B.﹣2 C.2 D.1【考点】实数大小比较.【分析】在数轴上表示出各数,根据数轴的特点即可得出结论.【解答】解:如图所示,,由图可知,﹣3<﹣2<1<2,即最大的实数是2.故选C.2.下列图形中不是轴对称图形的是()A.B.C.D.【考点】轴对称图形.【分析】根据轴对称图形的概念求解.【解答】解:A、不是轴对称图形,故本选项正确;B、是轴对称图形,故本选项错误;C、是轴对称图形,故本选项错误;D、是轴对称图形,故本选项错误.故选:A.3.一个几何体的三视图如图所示,那么这个几何体是()A.B.C.D.【考点】由三视图判断几何体.【分析】主视图、左视图、俯视图是分别从物体正面、左面和上面看,所得到的图形.【解答】解:由于俯视图为三角形.主视图为两个长方形和左视图为长方形可得此几何体为三棱柱.故选:A.4.下列运算正确的是()A.x2•x3=x6B.(x2)3=x6C.x2+x3=x5D.x2+x2=2x4【考点】幂的乘方与积的乘方;合并同类项;同底数幂的乘法.【分析】根据同底数幂的乘法、幂的乘方、合并同类项进行计算即可.【解答】解:A、x2•x3=x5,故A错误;B、(x2)3=x6,故B正确;C、x2+x3=x5,不能合并,故C错误;D、x2+x2=2x2,故D错误;故选B.5.数据0,1,1,3,3,4的中位数和平均数分别是()A.2和2 B.2和2.4 C.1和2 D.3和2【考点】中位数;算术平均数.【分析】根据中位数和平均数的概念求解.【解答】解:由题意得,中位数为:=2,平均数为:=2.故选A.6.将分式方程去分母后得到正确的整式方程是()A.x﹣2=x B.x2﹣2x=2x C.x﹣2=2x D.x=2x﹣4【考点】解分式方程.【分析】分式方程去分母转化为整式方程,即可作出判断.【解答】解:去分母得:2x=x﹣2.故选C.7.抛物线y=﹣(x+2)2﹣3向右平移了3个单位,那么平移后抛物线的顶点坐标是()A.(﹣5,﹣3)B.(﹣2,0)C.(﹣1,﹣3)D.(1,﹣3)【考点】二次函数图象与几何变换.【分析】根据二次函数图象左加右减,上加下减的平移规律进行解答.【解答】解:抛物线y=﹣(x+2)2﹣3的顶点坐标是(﹣2,﹣3),向右平移3个单位后,所得抛物线的顶点坐标是(﹣2+3,﹣3),即(1,﹣3).故选:D.8.下列命题中正确的是()A.对角线相等的四边形是菱形B.对角线互相垂直的四边形是菱形C.对角线相等的平行四边形是菱形D.对角线互相垂直的平行四边形是菱形【考点】菱形的判定.【分析】根据菱形对角线互相垂直平分的判定方法进行解答.【解答】解:对角线互相垂直平分的四边形是菱形;对角线互相垂直的平行四边形是菱形;故选:D.9.已知函数y=(k﹣3)x2+2x+1的图象与x轴有交点,则k的取值范围是()A.k<4 B.k≤4 C.k<4且k≠3 D.k≤4且k≠3【考点】抛物线与x轴的交点;根的判别式;一次函数的性质.【分析】分为两种情况:①当k﹣3≠0时,(k﹣3)x2+2x+1=0,求出△=b2﹣4ac=﹣4k+16≥0的解集即可;②当k﹣3=0时,得到一次函数y=2x+1,与x轴有交点;即可得到答案.【解答】解:①当k﹣3≠0时,(k﹣3)x2+2x+1=0,△=b2﹣4ac=22﹣4(k﹣3)×1=﹣4k+16≥0,k≤4;②当k﹣3=0时,y=2x+1,与x轴有交点.故选B.10.如图,AB是⊙O的直径,CD是⊙O的切线,切点为D,DC与AB的延长线交于点C,∠A=30°,给出下面3个结论:∠BDC=∠A;AB=2BC;AD2=3BC2;其中正确结论的个数是()A.0 B.1 C.2 D.3【考点】切线的性质.【分析】要想证明∠BDC=∠A,只要证明三角形ADB和三角形CDO的对应角相等即可;要想证明AB=2BC,只要证明BC等于半径即可;要证明AD2=3BC2只要说明AD、AB、BD之间的关系即可.【解答】解:∵AB是⊙O的直径,CD是⊙O的切线,切点为D,∴∠ADB=∠ODC=90°,∵∠A=30°,∴∠DBO=60°,∵OB=OD,∴△OBD是等边三角形,∴∠ODB=60°,∠BDC=∠ADO,又∵OA=OD,∴∠A=∠ADO,∴∠BDC=∠A;∵∠ODC=90°,∠C=30°,∴OC=2OD,∴AB=2OC,BC=OA,∴AB=2BC;∵∠ADB=90°,∠A=30°,∴AB=2BD,AD=,∴AD2=3BD2,即AD2=3BC2;故选D.二、填空题(本大题共6小题,每小题3分,满分18分.)11.如图,在△ABC中,D是AB延长线上一点,∠A=30°,∠CBD=130°,则∠ACB=100°.【考点】三角形的外角性质.【分析】根据三角形的一个外角等于和它不相邻的两个内角的和计算即可.【解答】解:∵∠A=30°,∠CBD=130°,∴∠ACD=∠CBD﹣∠A=100°,故答案为:100°.12.某校九年级共390名学生参加模拟考试,随机抽取60名学生的数学成绩进行统计,其中有20名学生的数学成绩在135分以上,据此估计该校九年级学生在这次模拟考试中数学成绩在135分以上的大约有130名学生.【考点】用样本估计总体.【分析】先求出随机抽取的60名学生中成绩达到110分以上的所占的百分比,再乘以九年级所有人数,即可得出答案.【解答】解:根据题意得:390×=130(名).答:该校九年级学生在这次模拟考试中数学成绩在135分以上的大约有130名学生.故答案为:130.13.分解因式:x2﹣4y2=(x+2y)(x﹣2y).【考点】因式分解-运用公式法.【分析】直接利用平方差公式分解因式得出答案.【解答】解:x2﹣4y2=(x+2y)(x﹣2y).故答案为:(x+2y)(x﹣2y).14.若点M(m,1)在一次函数y=x﹣2的图象上,则m=3.【考点】一次函数图象上点的坐标特征.【分析】把y=1代入解析式解答即可.【解答】解:把y=1代入y=x﹣2,可得:x=3,故答案为:315.如图,在△ABC中,AB=5,AC=3,AD、AE分别是其角平分线和中线,过点C作CG⊥AD 于F,交AB于G,连接EF,则线段EF的长为1.【考点】三角形中位线定理;等腰三角形的判定与性质.【分析】首先证明△ACG是等腰三角形,则AG=AC=3,FG=CF,则EF是△BCG的中位线,利用三角形的中位线定理即可求解.【解答】解:∵AD为△ABC的角平分线,CG⊥AD,∴△ACG是等腰三角形,∴AG=AC,∵AC=3,∴AG=AC=3,FG=CF,∵AE为△ABC的中线,∴EF是△BCG的中位线,∴EF=BG,∵AB=5,∴BG=AB﹣AG=5﹣3=2.∴EF=1.故答案为1.16.如图,已知△ABC和△AED均为等边三角形,点D在BC边上,DE与AB相交于点F,如果AC=12,CD=4,那么BF的长度为.【考点】相似三角形的判定与性质;等边三角形的性质.【分析】先利用等边三角形的性质得到∠C=∠ADE=∠B=60°,AB=BC=AC=12,再利用三角形外角性质证明∠BDF=∠CAD,则可判断△DBF∽△ACD,然后利用相似比计算BF的长.【解答】解:∵△ABC和△AED均为等边三角形,∴∠C=∠ADE=∠B=60°,AB=BC=AC=12,∵∠ADB=∠DAC+∠C,而∠ADB=∠ADE+∠BDF,∴∠BDF=∠CAD,∴△DBF∽△ACD,∴BF:CD=BD:AC,即BF:4=8:12,解得BF=.故答案为.三、解答题(本大题共9小题,满分102分.解答应写出文字说明、证明过程或演算步骤)17.解不等式组:,并把解集在数轴上表示出来.【考点】解一元一次不等式组;在数轴上表示不等式的解集.【分析】分别求出两个不等式的解集,然后在数轴上表示出两个不等式解集的公共部分即可.【解答】解:解不等式(1),得x≥﹣1,解不等式(2),得x≤4,把不等式(1)和(2)的解集在数轴上表示出来,如图所示.从上图可以找出两个不等式解集的公共部分,得不等式组的解集为:﹣1≤x≤4.18.解方程.【考点】解分式方程.【分析】分式方程去分母转化为整式方程,求出整式方程的解得到x的值,经检验即可得到分式方程的解.【解答】解:方程两边乘(x+1)(x﹣1),得:x﹣1=2,解得:x=3,检验:当x=3时,(x+1)(x﹣1)=8≠0,则x=3是原分式方程的解.19.如图,在Rt△ABC中,∠ACB=90°.(1)利用直尺和圆规按下列要求作图,并在图中标明相应的字母.(保留作图痕迹,不写作法)①作AC的垂直平分线,交AB于点O,交AC于点D;②以O为圆心,OA为半径作圆,交OD的延长线于点E.(2)在(1)所作的图形中,解答下列问题.①点B与⊙O的位置关系是点B在⊙O上;(直接写出答案)②若DE=2,AC=8,求⊙O的半径.【考点】作图—复杂作图;点与圆的位置关系.【分析】(1)先作AC的垂直平分线,然后作⊙O;(2)①通过证明OB=OA来判断点在⊙O上;②设⊙O的半径为r,在Rt△AOD中利用勾股定理得到r2=42+(r﹣2)2,然后解方程求出r即可.【解答】解:(1)如图所示;(2)①连结OC,如图,∵OD垂直平分AC,∴OA=OC,∴∠A=∠ACO,∵∠A+∠B=90°,∠OCB+∠ACO=90°,∴∠B=∠OCB,∴OC=OB,∴OB=OA,∴点B在⊙O上;故答案为点B在⊙O上②∵OD⊥AC,且点D是AC的中点,∴AD=AC=4,设⊙O的半径为r,则OA=OE=r,OD=OE﹣DE=r﹣2,在Rt△AOD中,∵OA2=AD2+OD2,即r2=42+(r﹣2)2,解得r=5.∴⊙O的半径为5.20.如图,在平面直角坐标系xOy中,直线经过第一、二、四象限,与y轴交于点B,点A(2,m)在这条直线上,连结AO,△AOB的面积等于2.(1)求b的值;(2)如果反比例函数(k是常量,k≠0)的图象经过点A,求这个反比例函数的解析式.【考点】反比例函数与一次函数的交点问题.【分析】(1)作AC⊥y轴,C为垂足,则AC是OB边上的高,根据A的坐标可知AC=2,由一次函数的解析式得出B(0,b),则OB=b,然后根据三角形的面积列出方程,解方程求得即可;(2)把A(2,m)代入求出m,得出A的坐标,代入根据待定系数法即可求得.【解答】解:(1)∵直线与y轴交于点B,∴点B的坐标为(0,b).作AC⊥y轴,C为垂足,则AC是OB边上的高,∵点A的坐标为(2,m),∴AC=2.又∵△AOB的面积等于2,∴,∴b=2.(2)∵点A(2,m)在直线∴,∴A的坐标为(2,﹣1).又∵反比例函数(k是常量,k≠0)的图象经过点A,∴,即k=﹣2,∴这个反比例函数的解析式为.21.如图,正方形的边长为2,中心为O,从O、A、B、C、D五点中任取两点.(1)求取到的两点间的距离为2的概率;(2)求取到的两点间的距离为的概率;(3)求取到的两点间的距离为的概率.【考点】几何概率.【分析】(1)先求出两点间的距离为2的所有情况,再根据概率公式除以总的情况数即可;(2)先求出两点间的距离为2的所有情况,再根据概率公式计算即可;(3)先求出两点间的距离为的所有情况,再根据概率公式进行计算即可;【解答】解:(1)从O 、A 、B 、C 、D 五点中任取两点,所有等可能出现的结果有: AB 、AC 、AD 、BC 、BD 、CD 、OA 、OB 、OC 、OD ,共有10种, 满足两点间的距离为2的结果有AB 、BC 、CD 、AD 这4种,则P (两点间的距离为2)==.(2)满足两点间的距离为的结果有AC 、BD 这2种.则P (两点间的距离为)==.(3)满足两点间的距离为的结果有OA 、OB 、OC 、OD 这4种.则P (两点间的距离为)==.22.甲乙两人各加工30个零件,甲比乙少用1小时完成任务;乙改进操作方法,使生产效率提高了一倍,结果乙完成30个零件的时间比甲完成24个零件所用的时间少1小时.问甲乙两人原来每小时各加工多少个零件.【考点】分式方程的应用;二元一次方程组的应用.【分析】设甲乙两人原来每小时各加工零件分别为x 个、y 个,根据各加工30个零件甲比乙少用1小时完成任务,改进操作方法之后,乙完成30个零件的时间比甲完成24个零件所用的时间少1小时,列方程组求解.【解答】解:设甲乙两人原来每小时各加工零件分别为x 个、y 个,由题意得,,解得:.经检验它是原方程的组解,且符合题意.答:甲乙两人原来每小时各加工零件分别为6个、5个.23.如图,在边长为4的菱形ABCD 中,BD=4,E 、F 分别是AD 、CD 上的动点(包含端点),且AE +CF=4,连接BE 、EF 、FB .(1)试探究BE与BF的数量关系,并证明你的结论;(2)求EF的最大值与最小值.【考点】菱形的性质;全等三角形的判定与性质.【分析】(1)由在边长为4的菱形ABCD中,BD=4,易得△ABD、△CBD都是边长为4的正三角形,继而证得△BDE≌△BCF(SAS),则可证得结论;(2)由△BDE≌△BCF,易证得△BEF是正三角形,继而可得当动点E运动到点D或点A时,BE的最大,当BE⊥AD,即E为AD的中点时,BE的最小.【解答】解:(1)BE=BF,证明如下:∵四边形ABCD是边长为4的菱形,BD=4,∴△ABD、△CBD都是边长为4的正三角形,∵AE+CF=4,∴CF=4﹣AE=AD﹣AE=DE,又∵BD=BC=4,∠BDE=∠C=60°,在△BDE和△BCF中,,∴△BDE≌△BCF(SAS),∴BE=BF;(2)∵△BDE≌△BCF,∴∠EBD=∠FBC,∴∠EBD+∠DBF=∠FBC+∠DBF,∴∠EBF=∠DBC=60°,又∵BE=BF,∴△BEF是正三角形,∴EF=BE=BF,当动点E运动到点D或点A时,BE的最大值为4,当BE⊥AD,即E为AD的中点时,BE的最小值为,∵EF=BE,∴EF的最大值为4,最小值为.24.如图,AB是⊙O的直径,AC是⊙O的切线,BC交⊙O于点E,连接AE.(1)若D为AC的中点,连接DE,证明:DE是⊙O的切线;(2)若BE=3EC,求tan∠ABC.【考点】切线的判定.【分析】(1)连接OE,由AB是⊙O的直径,AC是圆⊙O的切线,推得AE⊥BC,AC⊥AB,在直角△AEC中,由D为AC的中点,证得DE=DC,进而证得∠DEC=∠DCE,从而证得∠DEC+∠OEB=∠DCE+∠OBE=90°,故有∠DEO=180°﹣90°=90°,可证得结论;(2)由∠EAC+∠EAB=90°,∠EBA+∠EAB=90°,证得∠EAC=∠EBA,可证得△EAC∽△EBA,根据相似三角形的性质可求出,根据正切函数的定义即可求得tan∠ABC的值.【解答】证明:(1)连接OE,∵AB是⊙O的直径,AC是圆⊙O的切线,∴AE⊥BC,AC⊥AB,在直角△AEC中,∵D为AC的中点,∴DE=DC,∴∠DEC=∠DCE,∵∠OEB=∠OBE,∠ABC+∠ACB=90°,∴∠DEC+∠OEB=∠DCE+∠OBE=90°,∴∠DEO=180°﹣90°=90°,∴OE⊥DE,∴DE 是⊙O的切线;(2)在直角△EAC与直角△EBA中,∵∠EAC+∠EAB=90°,∠EBA+∠EAB=90°,∴∠EAC=∠EBA,∴△EAC∽△EBA,∴,EA2=EB•EC,设EC=1,则EB=3,EA2=EB•EC=3,,在直角△AEB中,.25.如图,在平面直角坐标系中,抛物线y=﹣x2+bx+c与x轴交于A(﹣3,0)、B(1,0)两点,与y轴交于点C,D是抛物线的顶点,E是对称轴与x轴的交点.(1)求抛物线的解析式,并在﹣4≤x≤2范围内画出此抛物线的草图;(2)若点F和点D关于x轴对称,点P是x轴上的一个动点,过点P作PQ∥OF交抛物线于点Q,是否存在以点O、F、P、Q为顶点的平行四边形?若存在,求出点P坐标;若不存在,请说明理由.【考点】二次函数综合题.【分析】(1)用待定系数法求出抛物线解析式,再利用求顶点坐标的公式即可;(2)由条件确定出Q点纵坐标的绝对值,再分情况解一元二次方程即可.【解答】解:(1)根据题意得:解得:,∴解析式为y=﹣x2﹣2x+3.当x=﹣=﹣1时,y=4,∴顶点D的坐标为(﹣1,4),∴点F的坐标为(﹣1,﹣4).此抛物线的草图如图所示(2)若以O、F、P、Q为顶点的平行四边形存在,则点Q(x,y)必须满足|y|=|EF|=4.①当y=﹣4时,﹣x2﹣2x+3=﹣4,解得,x=﹣1±2,∴Q1(﹣1﹣2,﹣4),Q2(﹣1+2,﹣4)∴P1(﹣2,0),P2(2,0).②当y=4时,﹣x2﹣2x+3=4,解得,x=﹣1,∴Q3(﹣1,4),∴P3(﹣2,0),综上所述,符合条件的点有三个即:P 1(﹣2,0),P2(2,0),P3(﹣2,0).2017年2月18日。
2016年广州市海珠区中考一模数学试卷及答案
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2016年广州市海珠区中考一模数学试卷及答案2016广州市海珠区中考一模数学试卷及答案时间:120分钟,满分:150分 成绩姓名: 分发日:201 年 月 日;回收日201 年 月 日 一、选择题(10小题,共30分)1、实灵敏-3的绝对值是( )A 、3B 、-3C 、0D 、±3 2、下面汽车标志中,属于轴对称图形的是( )3、如图,在平行四边形ABCD 中,如果∠A=50°,则∠C=( ) A 、40° B 、50° C 、130° D 、150°4、下列运算中,错误的题是( ) A 、2a-3a=-a B 、3)(ab -=-33b a C 、6a÷2a=4a D 、a ·2a =2a 5、方程组⎩⎨⎧=+=-31y x y x 的解是( )A 、⎩⎨⎧==21y xB 、⎩⎨⎧==31y xC 、⎩⎨⎧==13y xD 、⎩⎨⎧==12y x6、为了解当地气温变化情况,某研究小组纪录了寒假 期间连续4天的最高气温,结果如下(单位:°C ): 5, -1,-3,-1.则下列结论错误的是( ) A 、方差是8 B 、中位数是-1 C 、众数是-1 D 、平均数是07、某几何体的三视图如图所示,则侧面积是( ) A 、12π B 、6πC 、4πD 、68、已知一元二次方程0352=+-x x ,则该方程根的情况是( ) A 、有二个不相等的实数根 B 、有两个相等的实数根 C 、无实数根 D 、无法确定9、如图,在纸上剪下一个圆形和一个扇形的纸片,使之恰好能围成一个圆锥模型,若圆的半径为r,扇形的半径为R ,扇形的圆心角 等于90°,则r 与R 之间的关系是( ) A 、R=2r B 、R=3r C 、R=4r D 、R=5rACBD 第7题图232主视图左视图俯视图A B C DR10、将抛物线342+-=x x y 向上平移至顶点落在x 轴上,如图所示,则两条抛物线、 对称轴和y 轴围成的图形的面积S (图中阴影部分)是( )A 、1B 、2C 、3D 、4二、填空题11、已知∠α=25°,那么∠α的余角= 度。
16年广州越秀一模
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2016年广州市越秀区中考一模英语试卷九年级英语问卷一、语法选择(共15小题;每小题1分,满分15分)阅读下面短文,按照句子结构的语法性和上下文连贯的要求,从1~15各题所给的A、B、C和D项中,选出最佳选项,并在答题卡上将该项涂黑。
Once upon a time, there was a lazy poor man living in a small house with spider webs(网) on the walls and mice running around. People 1 coming into such a dirty place and the poor man was lonely and 2 every day. He thought he was unhappy 3 poverty(贫穷).One day, the poor man dropped in on 4 wise old man and asked him for advice about 5 his life. The old man gave him a vase and said, “This is a magic vase 6 will bring you 7 .The poor man looked at the vase 8 . He wondered 9 a vase in his poor house. 10 , he didn’t want to throw away such a beautiful vase, so he brought it home and put it on the table.“ 11 not right for something 12 beautiful to be empty.” The poor old man looked at the vase and thought. Then some flowers 13 into it. That made the vase even 14 . “How can I have the vase next to a spider web?” he continued. At this, he started to clean the house and paint the walls. His house turned 15 a comfortable place immediately.The old man cheered up and he suddenly realized why he was unhappy. From then on, he worked hard and his life got better and better.1. A. avoid B. avoids C. avoided D. have avoided2. A. sadly B. sad C. sadness D. sadder3. A. because B. as C. since D. because of4. A. a B. an C. the D. /5. A. to change B. changes C. changed D. changing6. A. / B. that C. what D. who7. A. happy B. happier C. happily D. happiness8. A. in surprise B. surprising C. surprised D. surprise9. A. why would he need B. why will he needC. why he would needD. why he needs10. A. But B. Or C. However D. So11. A. It’s B. Its C. It D. It was12. A. very B. such C. quite D. so13. A. were putting B. were put C. have put D. had put14. A. beautifully B. beautiful C. more beautiful D. more beautifully15. A. in B. into C. on D. Around二、完形填空(共10小题;每题1.5分,满分15分)阅读下面短文,掌握其大意,然后从16~25各题所给的A、B、C和D项中,选出最佳选项,并在答题卡上将该项涂黑。
2016广州市十六中一模真题卷
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广州市第16中2012-2013学年初三下第二次模拟试题二、综合知识及运用第一节单项选择16._____ the night of May 1st, we had an argument with his life.A. inB. atC. onD. for17. ---Did Mrs. King leave a message?--- Yes. She wanted to know_____ this Sunday.A. who you would go shoppingB. if you would go shopping with herC. that you will go shoppingD. when will you go shopping with her18. Judy, you_____ play with the knife. You_____ hurt yourself.A. won‟t; canB. mustn‟t; mayC. shouldn‟t ; needD. can‟t; should19. John is one of the students in the class ______ have ever been to China.A. whoB. whoseC. whichD. whom20. --- Did you go to Jim‟s party?--- No, I _____.A. haven‟t invitedB. didn‟t inviteC. am not invitedD. wasn‟t invited21. --- Why don‟t you ______ the correct spelling of the word?--- I haven‟t got a Chinese—English dictionary at hand.A. look forB. look downC. look upD. look at22. --- Would you please tell me how long ____?--- For ten years.A. you‟ve moved to the cityB. you‟ve joined the leagueC. you‟ve been friends with JaneD. you‟ve got married23. The cakes in the shop taste______ and they _____ very quickly.A. delicious; were soldB. wonderfully; sold outC. nice; are sold outD. well; sold24. --- Tom admitted______ to us this morning.--- That‟s nothing. Remind him ______ lies again.A. lying; not to tellB. to lie; not tellingC. lying; don‟t tellD. to lie; not to tell25. ______ of the money _____ been spent recycling the rubbish.A. Three fifths; haveB. Third fifth; hasC. Third fifths; haveD. Three fifths; has第二节语法选择As teenagers, you have many dreams. These dreams can be very big, such as winning the Nobel Prize, ___26__ they can be very small. You may just want to become one of the ten best students in your class.Once you find a dream, what do you do with it? Do you ever try to make your dream__27___?“Follow Your Heart” by Australian writer Andrew Matthews tells us that making our dreams real is life‟s biggest challenge.You may think that you‟re not very good at some school subjects, or that it is impossible for you ___28__ a writer. These kinds of thoughts stop you from getting your dream, the book says.In fact, everyone can make ___29___ dream come true. ___30__ first thing you must do is to remember what your dream is.Don‟t let i t leave your heart. Keep __31__ yourself what you want. Do this step by step and your dream will come true faster because a big dream is made up of many small ones.There __ 32___ difficulties on the road to your dream. But the biggest one __33__ from yourself. You need to decide what is the most important. Studying instead of watching TV will lead ___34__ better exam, while saving five yuan instead of buying a toy means you can buy a new book. As you get ___35__ to your dream, it may change a little. This is good as you have the chance to learn more skills and find new interests.26. A. as B. but C. for D. or27. A. real B. reality C. really D. realize28. A. becomes B. to become C. becoming D. become29. A. his B. its C. their D. him30. A. A B. Some C. The D. /31. A. to tell B. tells C. telling D. told32. A. will be B. will have C. have D. has33. A. come B. has come C. came D. comes34. A. by B. to C. in D. with35. A. closely B. closing C. closed D. closer三. 完形填空Oliver and Gillian Schonrock come from London. Recently, they have become a topic of conversation for local people, because they let their 8-year-old daughter and 5-year-old son go to school by __36___.The school and teachers were very ___37__with Mr. and Mrs. Schonrock‟s decision. They thought that Mr. and Mrs. Schonrock were putting their children at the risk of ___38__. However, Mrs. Schonrock believes that their children can benefit __39___ from this experience.London mayor, Boris Johnson, also __40__Mr. and Mrs. Schonrock‟s decision. "If they have carefully looked at the road and considered the advantages and disadvantages, they should be given the freedom to make the decision," he said. "___41__ parents have the wrong idea of what is safe and what is dangerous for children."Two years ago, a study carried out __42__ England criticized parents who were stifling the chance for their children to bike to school. The study covered more than 1,000 parents. In fact, four out of five children of those parents were not allowed to bike to school. The study also said that this __43___ decision could lead children to cycle only on t heir own road and their neighbor‟s roads.One of the people who did the study said, "These days, children can do__44__ unless it‟s planned. Parents should try their best to let their children ___45__ theirlives and teach them about the risks of life."36. A. bus B. bike C. train D. car37. A. pleased B. careful C. unkind D. unhappy38. A. danger B. death C. life D. safety39. A. much B. more C. many D. most40. A. disagreed B. allowed C. against D. supported41. A. Many B. Few C. Fewer D. Less42. A. through B. by C. for D. about43. A. right B. true C. wrong D. hard44. A. nothing B. everything C. anything D. something45. A. worry B. enjoy C. scare D. obey四、阅读理解.(A)Some people believe that dreams can tell them what will happen in the future. Nobody knows why, but there are many stories about people who have had dreams that came true. One of these people was a man called John Chapman, who lived in the small town of Swaffham in England. He dreamed that he was standing on London Bridge and a man told him how to become rich. John Chapman was poor man and he needed money, so the next day he set off for London Bridge. There were plenty of people on the bridge, but they were not interested in him. They all ignored. After three days, he decided to go home, but before he could do this, a shopkeeper approached him.“ I‟ve been watching you,” the shopkeeper said. “Are you waiting for someone?”“Yes,” said John. “I had a dream about a man on London Bridge. He was going to lead me to a lot of money.”“Oh,” said the shopkeeper. “You shouldn‟t believe in dreams. If I believe in dreams, I‟d be in Swaffham right now. I had a dream about a few days age about aman from Swaffham. His name was John Chapman and he had gold in his garden near an old apple tree.”John was amazed and immediately headed for home. As soon as he arrived, he dug in his garden near the apple tree. He soon found many pieces of gold. He was so delighted that he gave some of the gold to his local church. He was a rich man for the rest of his life.46. Swaffham is the name of a .A. gardenB. bridgeC. churchD. small town47. John Chapman went to London because he .A. had a friend thereB. knew a shopkeeperC. was poorD. thought his dream would come true there48. The underlined phrase “headed for” in Para 5 means “”.A left B. went C. passed D. hid49. According to the story, John Chapman was away from his town for at least________ daysA. threeB. fourC. fiveD. six50. What happened to John Chapman probably at the end of the sroty?A. He found nothing and remained poorB. He found gold and gave some to others in needC. He found gold and kept it on his ownD. He found nothing and gave his dream up(B)The practice of students endlessly copying letters and sentences from a blackboard is a thing of the past. With the coming of new technologies like computers and smart phone, writing by hand has become something of nostalgic (怀旧的)skill. However, while today‟s educators are using more and more technology in theirteaching, many believe basic handwriting skills are still necessary for students to be successful---both in school and in life.Virginia Berninger, professor of educational psychology at the University of Washington, says it‟s important to continue teaching handwriting and help children acquire the skill of writing by hand.Berninger and her colleagues conducted a study that looked at the ability of students to complete various writing tasks---both on a computer and by hand. The study, published in 2009, found that when writing with a pen and paper, participants wrote longer essays and more complete sentences and had a faster word production rate.In a more recent study, Berninger looked at what role spelling plays in a student‟s writing skills and found that how well children spell is tied to know well they can write. “Spelling makes some of the thinking parts of the brain active which helps us access our vocabulary, word meaning and concepts. It is allowing our written language to connect with ideas.” Berninger said.Spelling helps students translate ideas into words in their mind first and then to transcribe(转换) “those words in the mind written symbols on paper or keyboard and screen,” the study said. Seeing the words in the “mind‟s eye” helps children not only to turn their ideas into words, says Berninger, but also to spot(发现) spelling mistakes when they write the words down and to correct then over time.“In our computer age, some people believe that we don‟t have to teach spelling because we have spell checks,” she said. “But until a child has a functional spelling ability of about a fifth grade level, they won‟t have the knowledge to choose the correct spelling among t he options given by the computer.”51. What makes writing by hand a thing of the past?A. The absence of blackboard in classroom.B. The lack of practice in handwriting.C. The use of new technologies in teaching.D. The popular use of smartphones.52. Berninger‟s study published in 2009 ___________.A. focused on the difference between writing by hand and on a computer.B. indicated that students prefer to write with a pen and paper.C. found that good essays are made up of long sentences.D. discussed the importance of writing speed.53. Which of the following best shows the role of spelling?A. Spelling improves one‟s memory of words.B. Spelling ability is closely related to writing ability.C. Spelling benefits the translation from words into ideas.D. Spelling slows down finding exact words to express ideas.54. What does “mind‟s eye” in paragraph 5 mea n?A. Window.B. SoulC. Picture.D. Imagination.55. What conclusion could be drawn from the passage?A. Computers can help people with their choice of words.B. Spell checks can take the place of spelling teaching.C. Handwriting still has a place in today‟s classrooms.D. Functional spelling ability develops fast in the fifth grade.(C)Do you know of anyone who uses the truth to deceive(欺骗)?When someone tells you something that is true, but leaves out important information that should be included, he can give you a false picture.For example, someone might say, “I just won a hundred dollars on the lottery(彩票).It was great. I took that dollar ticket back to the store and turned it in for one hundred dollars!”This guy‟s a winner, right? Maybe, maybe not. We then discover that he bought $200 worth of tickets, and only one was a winner. He‟s really a big loser!He didn‟t say anything th at was false, but he left out important information on purpose. That‟s called a half-truth. Half-truths are not technically lies, but they are just as dishonest.Some politicians often use this trick. Let‟s say that during Governor Smith‟s last term, her state lost one million jobs and gained three million jobs. Then she seeks another term. One of her opponents(对手) says,“ During Governor Smith‟s term, the state lost one million jobs!”That‟s true. However, an honest statement would have been, “During Governor Smith‟s term, the state had a net gain of two million jobs.”Advertisers(广告商) will sometimes use half-truths. It‟s against the law to make false statements so they try to mislead you with the truth. An advertisement might say,“ Nine out of ten doctor s advised their patients to take Yucky Pills to cure toothache.”It fails to mention that they only asked ten doctors and nine of them work for the Yucky Company.This kind of deception happens too often. It‟s a sad fact of life: Lies are lies, and sometimes the truth can lie as well.56.How much did the lottery winner lose?A. One hundred dollars.B. Two hundred dollars.C. Three hundred dollars.D. Four hundred dollars.57.We may infer that the author believes people should _________.A. buy lottery ticketsB. make use of half-truthsC. not take anything at face valueD. not trust the Yucky Company58.How many examples does the writer give to show how the truth is used to deceive?A. OneB. TwoC. ThreeD. Four59. Which of the following is true according to the passage?A. Using half truths is against the lawB. Technically, the truths are in fact liesC. Yucky Pills is a very good medicine for toothacheD. Governor Smith did a good job during her last term60. Which of the following best express the main idea of the passage?A. He is really a big loserB. Sometimes the truth can lie as wellC. Advertisers will sometimes use half truthsD. It‟s against the law to make false statement(D)Doing experiments can be interesting, and you may try the following experiments at home. Make sure that you‟ll do them with an adult.61. How many experiments are there in the picture?A. TwoB. ThreeC. SixD. Seven62. Which instruction is for …step 2‟ in the Experiment A?A. Pour 3/4 of the water awayB. Pour some hot water into the bottleC. Pour some cool water into the bottleD. Let the air out of the bottle63. What can you see in the bottle at last in the Experiment A?A. some iceB. some waterC. some ice and waterD. some cloud and water64. Which o f the following isn‟t needed before these experiments?A. waterB. iceC. cloudD. balloon65. In what class can you see these experiments?A. BiologyB. PhysicsC. ChemistryD. Computer五. 写作第一节:单词拼写66. Mark is always sleepy in class and a__________ in sports.67. Please don‟t make any n__________. The students are having exams now.68. You cannot l__________ your son at home by himself. He is too young.69. We really enjoyed the b__________ of nature on the peaceful island.70. I don‟t know when the letter will come. P__________ it will come today.第二节完成句子71. 我直到在街上碰到Sara 才想起要还书给她。
2016年16中初三一模语文试卷答案
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2016年广州市初中毕业生学业考试语文模拟试题(一)答案1.B(3分)2.D(3分)3.C(3分)4.D(3分)5.B(3分)6.①损害利益②浪费资源③污染环境④败坏风气⑤不利反腐(5分)7.(10分)(1)BE(4分)(2)①风正一帆悬②老木沧波无限悲③闲来垂钓碧溪上④眉眼盈盈处⑤生子当如孙仲谋⑥泉香而酒洌(六题选四题作答,共4分)(3)晴空一鹤排云上,便引诗情到碧霄。
(2分)(4)山回路转不见君,雪上空留马行处。
(2分)8.(5分,每小题1分)(1)家庭集会(2)益处(3)潜游在水中的鱼(4)光艳美丽(5)通“缺”,缺点9.B(3分)10.(1)这就是岳阳楼的雄伟景象,前人的记述已经很详尽了。
(2分)(2)我曾经探求古时品德高尚的人们的心思,或许不同于(以上)两种心情。
(2分)11.B(3分)12.(1)金鳞:像金色的鱼鳞;声不起:形容鼓声低沉;不响亮。
(2分)(2)引用战国时期燕昭王置千金于黄金台上以招贤才的典故,表现了将士们誓死杀敌、报效朝廷的决心。
(3分)13.C(3分)14.①价格便宜;②产品设计注重人性化;③“匠人文化”追求完美细节;④日用品“高端精品化”。
(4分)15.运用举例子和列数字的说明方法,写出小泉仁左卫门家族制造铁水壶的时间之长,突出其手工制造铁水壶做工之精细,具体体现“匠人文化”追求完美细节的特质,增强说服力。
(4分)16.示例:不正确。
“爆买”马桶盖的行为使日本电器店马桶盖几乎处于断货状态,又令店员感到恐惧,1。
2016年广州市16中2016年一模
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16中2015学年第二学期初三质量调研检测(二)英语试题一、语法选择(共15小题;每小题1分,满分15分)Have you ever looked at someone and wondered what is going on inside his or her head? Disney Pixar’s new movieInside Out __1__ you there to find out!The movie is mainly about Riley, 11, __2__ has just moved to a new city __3__ started a new school. Inside her mind, __4__ known as “headquarters,” there is a control center. There, five emotions—Joy, Fear, Anger, Disgust, and Sadness—are hard at __5__ . Joy’s task is to make sure Riley stays happy. Fear controls safety. __6__ Riley is trying to get along with her new environment, Joy and Fear suddenly __7__ into the back of Riley’s mind. That leaves __8__ three to work and brings about a lot of funny things.Director Pete Docter, who won an Oscar(奥斯卡奖)__9__ his film Up, says the idea came to him while __10__ his own kids turn into teenagers. His daughter, Ellie, who was the voice of young Ellie in Up, was __11__ energetic kid. But she started to become more __12__ as she grew up. “Young kids are __13__ of energy and then they get a little older and get a little quiet and shy,” Docter said. “I thought ‘What’s going on inside __14__ heads?’ That is __15__ leads to this film.”1. A. takes B. take C. taking D. took2. A. which B. that C. who D. what3. A. so B. and C. but D. if4. A. either B. neither C. also D. too5. A. works B. work C. worked D. to work6. A. while B. if C. before D. after7. A. put B. are put C. is put D. are putting8. A. another B. other C. others D. the other9. A. for B. of C. in D. to10. A. watch B. watched C. watching D. are watching11. A. a B. an C. the D. /12. A. silent B. silently C. silence D. silenced13. A. fill B. filled C. full D. fully14. A. your B. our C. his D. their15. A. what B. how C. when D. why二、完形填空(共10小题;每小题1.5分,满分15分)There were once two doors in the same house. One was a beautiful living-room door, and the other was just a/an __16__ bathroom door.They both had terrible lives. The house was full of __17__ children who were always slamming(摔门)and kicking the doors. Each night, when everyone was asleep, the doors would talk about their poor __18__. The living-room door was always ready to shout with anger, but the bathroom door would calm him down, saying, “Don’t worry. They’re children. They’ll soon learn. Be patient and things will __19__.”And so the living-room door would calm down for a while. But one day, after a big party and much slamming and kicking of the doors, the living-room door __20__ lost his temper, saying, “That’s enough! The next time someone slams me, I’m going to __21__, and they’ll learn how important I am.”The next day, the first time he was slammed, the living-room door broke. This caused great __22__ in the house, and the children were punished. But after a few days, the house owners didn’t want to have a broken door. Instead of __23__ it, they decided to buy a new one. The old door was thrown into the rubbish.By then the beautiful living-room door regretted what he had done. For not being __24__enough, he was now abandoned(抛弃), waiting to be turned into firewood. Meanwhile, his friend, the ordinary bathroom door, remained in his place, and the children were treating him with greater __25__.16. A. new B. heavy C. ordinary D. silent17. A. naughty B. curious C. nervous D. polite18. A. dream B. appearance C. house D. luck19. A. matter B. improve C. repeat D. suffer20. A. seldom B. fortunately C. happily D. finally21. A. break B. teach C. work D. shout22. A. joy B. benefit C. trouble D. doubt23. A. selling B. repairing C. painting D. finding24. A. beautiful B. careful C. patient D. friendly25. A. force B. anger C. peace D. care三、阅读(满分45分)第一节阅读理解(共20小题;每小题2分,满分40分)阅读下面短文,从每题所给的A、B、C和D项中,选出最佳选项并在答题卡上将该项涂黑。
2016年广州市“一模”试题(文科)(精品含解析)
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1绝密 ★ 启用前2016年广州市普通高中毕业班综合测试(一)文科数学注意事项:1.本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。
答卷前,考生务必将自己的姓名和考生号、试室号、座位号填写在答题卡上,并用铅笔在答题卡上的相应位置填涂考生号。
2.回答第Ⅰ卷时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦干净后,再选涂其它答案标号。
写在本试卷上无效。
3.回答第Ⅱ卷时,将答案写在答题卡上。
写在本试卷上无效。
4.考试结束后,将本试卷和答题卡一并交回。
第Ⅰ卷一.选择题:本大题共12小题,每小题5分,在每小题给出的四个选项中,只有一项是符合题目要求的.(1)已知集合{}11A x x =-≤≤,{}220B x x x =-≤,则A B =(A ){}12x x -≤≤(B ){}10x x -≤≤(C ){}12x x ≤≤(D ){}01x x ≤≤ (2)已知复数3i1iz +=+,其中i 为虚数单位,则复数z 所对应的点在 (A )第一象限(B )第二象限 (C )第三象限(D )第四象限(3)已知函数()2,1,1,1,1x x x f x x x ⎧-≤⎪=⎨>⎪-⎩则()()2f f -的值为(A )12(B )15(C )15-(D )12-(4)设P 是△ABC 所在平面内的一点,且2CP PA =,则△PAB 与△PBC 的面积之比是(A )13(B )12(C )23(D )34(5)如果函数()cos 4f x x ωπ⎛⎫=+⎪⎝⎭()0ω>的相邻两个零点之间的距离为6π,则ω的值为 (A )3(B )6 (C )12 (D )24 (6)执行如图所示的程序框图,如果输入3x =,则输出k 的值为 (A )6(B )8 (C )10 (D )122(7)在平面区域(){},0112x y x y ≤≤≤≤,内随机投入一点P ,则点P 的坐标(),x y 满足2y x ≤的概率为 (A )14(B )12(C )23 (D )34(8)已知()sin 6f x x π⎛⎫=+⎪⎝⎭,若3sin 5α=2πα⎛⎫<<π ⎪⎝⎭,则12f απ⎛⎫+= ⎪⎝⎭(A)B)C(D(9)如果1P ,2P ,…,n P 是抛物线C :24y x =上的点,它们的横坐标依次为1x ,2x ,…,n x ,F 是抛物线C 的焦点,若1210n x x x +++= ,则12n PF P F P F +++= (A )10n +(B )20n +(C )210n + (D )220n +(10)一个六棱柱的底面是正六边形,侧棱垂直于底面,所有棱的长都为1,顶点都在同一个球面上,则该球的体积为(A )20π(B(C )5π (D(11)已知下列四个命题:1p :若直线l 和平面α内的无数条直线垂直,则l α⊥;2p :若()22x x f x -=-,则x ∀∈R ,()()f x f x -=-; 3p :若()11f x x x =++,则()00,x ∃∈+∞,()01f x =; 4p :在△ABC 中,若A B >,则sin sin A B >.其中真命题的个数是(A )1(B )2 (C )3(D )4(12)如图,网格纸上小正方形的边长为1,粗线画出的是某个四面体的三视图,则该四面体的表面积为 (A)8+B)8+(C)2+D)1224++第Ⅱ卷3本卷包括必考题和选考题两部分.第13题~第21题为必考题,每个试题考生都必须做答.第22题~第24题为选考题,考生根据要求做答. 二.填空题:本大题共4小题,每小题5分. (13)函数()33f x x x =-的极小值为.(14)设实数x ,y 满足约束条件230,230,3x y x y x --≤⎧⎪+-≤⎨⎪≥-⎩, 则23z x y =-+的取值范围是.(15)已知双曲线C :22221x y a b-=()0,0a b >>的左顶点为A ,右焦点为F ,点()0,B b ,且0B AB F =,则双曲线C 的离心率为.(16)在△ABC 中,点D 在边AB 上,CD BC ⊥,AC =5CD =,2BD AD =,则AD 的长为.三.解答题:解答应写出文字说明,证明过程或演算步骤. (17)(本小题满分12分)已知数列{}n a 是等比数列,24a =,32a +是2a 和4a 的等差中项. (Ⅰ)求数列{}n a 的通项公式;(Ⅱ)设22log 1n n b a =-,求数列{}n n a b 的前n 项和n T .(18)(本小题满分12分)4从某企业生产的某种产品中抽取100件,测量这些产品的质量指标值,由测量结果得到如图所示的频率分布直方图,质量指标值落在区间[)55,65,[)65,75,[]75,85内的频率之比为4:2:1. (Ⅰ)求这些产品质量指标值落在区间[]75,85(Ⅱ)用分层抽样的方法在区间[)45,75内抽取一个容量为6的样本,将该样本看成一个总体,从中任意抽取2件 产品,求这2件产品都在区间[)45,65内的概率.(19)(本小题满分12分)如图,四棱柱1111ABCD A BC D -的底面ABCD 是菱形,AC BD O = ,1AO ⊥底面ABCD ,21==AA AB .(Ⅰ)证明:BD ⊥平面1ACO ; (Ⅱ)若60BAD ∠=,求点C 到平面5(20)(本小题满分12分)已知椭圆C 的中心在坐标原点,焦点在x 轴上,左顶点为A ,左焦点为()120F -,,点(B 在椭圆C 上,直线()0y kx k =≠与椭圆C 交于E ,F 两点,直线AE ,AF 分别与y 轴交于点M ,N . (Ⅰ)求椭圆C 的方程;(Ⅱ)在x 轴上是否存在点P ,使得无论非零实数k 怎样变化,总有MPN ∠为直角?若存在,求出点P 的坐标;若不存在,请说明理由.(21)(本小题满分12分)已知函数()e ln 1xf x m x =--.(Ⅰ)当1m =时,求曲线()y f x =在点()()11f ,处的切线方程; (Ⅱ)当1m ≥时,证明:()1f x >.请考生在第22、23、24题中任选一题做答,如果多做,则按所做的第一题计分.做答时请写清题号.6(22)(本小题满分10分)选修4-1:几何证明选讲如图所示,△ABC 内接于⊙O ,直线AD 与⊙O 相切于点A ,交BC 的延长线于点D ,过点D 作DE CA 交BA 的延长线于点E .(Ⅰ)求证:2DE AE BE = ;(Ⅱ)若直线EF 与⊙O 相切于点F ,且4EF =,2EA =,求线段AC(23)(本小题满分10分)选修4-4:坐标系与参数方程在平面直角坐标系xOy 中,以坐标原点O 为极点,x 轴正半轴为极轴建立极坐标系,曲线C 的极坐标方程为θρsin 2=,[)0,2θ∈π. (Ⅰ)求曲线C 的直角坐标方程;(Ⅱ)在曲线C 上求一点D ,使它到直线l :32x y t ⎧=⎪⎨=-+⎪⎩(t 为参数,t ∈R )的距离最短,并求出点D 的直角坐标.(24)(本小题满分10分)选修4-5:不等式选讲设函数()f x x x =+--. (Ⅰ)当1a =时,求不等式()12f x ≥的解集; (Ⅱ)若对任意[]0,1a ∈,不等式()f x b ≥的解集为空集,求实数b 的取值范围.绝密 ★ 启用前2016年广州市普通高中毕业班综合测试(一)7文科数学试题答案及评分参考评分说明:1.本解答给出了一种或几种解法供参考,如果考生的解法与本解答不同,可根据试题的主要考查内容比照评分参考制订相应的评分细则.2.对计算题,当考生的解答在某一步出现错误时,如果后继部分的解答未改变该题的内容和难度,可视影响的程度决定后继部分的给分,但不得超过该部分正确解答应得分数的一半;如果后继部分的解答有较严重的错误,就不再给分.3.解答右端所注分数,表示考生正确做到这一步应得的累加分数. 4.只给整数分数.选择题不给中间分.一.选择题(1)D (2)D (3)C (4)B (5)B (6)C (7)A (8)B(9)A(10)D(11)B(12)A二.填空题(13)2- (14)[]6,15- (15(16)5三.解答题(17)解:(Ⅰ)设数列{}n a 的公比为q ,因为24a =,所以34a q =,244a q =.…………………………………………1分因为32a +是2a 和4a 的等差中项,所以()32422a a a +=+.……………………2分 即()224244q q +=+,化简得220q q -=.因为公比0q ≠,所以2q =.………………………………………………………4分 所以222422n n n n a a q --==⨯=(*n ∈N ).…………………………………………5分 (Ⅱ)因为2n na =,所以22log 121n nb a n =-=-.所以()212n n n a b n =-.……………………………………………………………7分 则()()231123252232212n n n T n n -=⨯+⨯+⨯+⋅⋅⋅+-+-, ① ()()23412123252232212n n n T n n +=⨯+⨯+⨯+⋅⋅⋅+-+-.②………………9分8①-②得,()2312222222212n n n T n +-=+⨯+⨯+⋅⋅⋅+⨯--……………………………………10分 ()()()11142221262321212n n n n n ++-=+⨯--=-----,所以()16232n n T n +=+-.……………………………………………………………12分(18)解:(Ⅰ)设区间[]75,85内的频率为x ,则区间[)55,65,[)65,75内的频率分别为4x 和2x .…………………………1分 依题意得()0.0040.0120.0190.03010421x x x +++⨯+++=,……………3分 解得0.05x =.所以区间[]75,85内的频率为0.05.………………………………………………4分(Ⅱ)由(Ⅰ)得,区间[)45,55,[)55,65,[)65,75内的频率依次为0.3,0.2,0.1.用分层抽样的方法在区间[)45,75内抽取一个容量为6的样本,则在区间[)45,55内应抽取0.3630.30.20.1⨯=++件,记为1A ,2A ,3A .在区间[)55,65内应抽取0.2620.30.20.1⨯=++件,记为1B ,2B . 在区间[)65,75内应抽取0.1610.30.20.1⨯=++件,记为C .…………………6分 设“从样本中任意抽取2件产品,这2件产品都在区间[)45,65内”为事件M , 则所有的基本事件有:{}12,A A ,{}13,A A ,{}11,A B ,{}12,AB ,{}1,AC ,{}23,A A , {}21,A B ,{}22,A B ,{}2,A C ,{}31,A B ,{}32,A B ,{}3,A C ,{}12,B B ,{}1,B C ,{}2,B C ,共15种.…………………………………………………………………8分事件M 包含的基本事件有:{}12,A A ,{}13,A A ,{}11,A B ,{}12,AB ,{}23,A A , {}21,A B ,{}22,A B ,{}31,A B ,{}32,A B ,{}12,B B ,共10种.…………10分9所以这2件产品都在区间[)45,65内的概率为102153=.………………………12分 (19)(Ⅰ)证明:因为1AO ⊥平面ABCD ,BD ⊂平面ABCD , 所以1AO ⊥BD .……………………………………………………………………1分 因为ABCD 是菱形,所以CO ⊥BD .……………………………………………2分 因为1AO CO O = ,1AO ,CO ⊂平面1ACO , 所以BD ⊥平面1ACO .……………………………………………………………3分 (Ⅱ)解法一:因为底面ABCD 是菱形,AC BD O = ,21==AA AB ,60BAD ∠=,所以1OB OD ==,OA OC ==4分 所以OBC ∆的面积为112212OBC S OB OC ∆==⨯=⨯⨯5分 因为1AO ⊥平面ABCD ,AO ⊂平面ABCD , 所以1AO AO ⊥,11AO =.………………………………………6分因为11A B 平面ABCD ,所以点1B 到平面ABCD 的距离等于点1A 到平面ABCD 的距离1AO .…………7分 由(Ⅰ)得,BD ⊥平面1A AC .因为1A A ⊂平面1A AC ,所以BD ⊥1A A .因为11A A B B ,所以BD ⊥1B B .………………………………………………8分 所以△1OBB 的面积为111121212OBB S OB BB ∆=⨯⨯==⨯⨯.……………………9分 设点C 到平面1OBB 的距离为d , 因为11C OBB B OBC V V --=,所以111133OBB OBC S d S A O D D =gg .………………………………………………10分10所以111212OBC OBBS AO d S ∆∆⋅===.所以点C 到平面1OBB12分 解法二:由(Ⅰ)知BD因为BD ⊂平面11BB D D 所以平面1ACO ⊥平面连接11AC 与11B D 交于点连接1CO ,1OO ,因为11AA CC =,11//AA CC ,所以11CAAC 为平行四边形. 又O ,1O 分别是AC ,11AC 的中点,所以11OAO C 为平行四边形. 所以111OC OA ==.…………………………………………………………………6分 因为平面11OAO C 与平面11BB D D 交线为1OO , 过点C 作1CH OO ⊥于H ,则CH ⊥平面11BB D D .………………………………8分 因为11O C A O ,1AO ⊥平面ABCD ,所以·1O C ⊥平面ABCD . 因为OC ⊂平面ABCD ,所以·1O C ⊥OC ,即△1OCO 为直角三角形.………10分 所以1122O C OC CH OO ⋅===.所以点C 到平面1OBB 212分(20)(Ⅰ)解法一:设椭圆C 的方程为22221(0)x y a b a b+=>>,因为椭圆的左焦点为()120F -,,所以224a b -=.……………………………1分 设椭圆的右焦点为()220F ,,已知点(2B 在椭圆C 上,11由椭圆的定义知122BF BF a +=,所以2a ==.………………………………………………………2分所以a =2b =.………………………………………………………3分所以椭圆C 的方程为22184x y +=.………………………………………………4分 解法二:设椭圆C 的方程为22221(0)x y a b a b+=>>,因为椭圆的左焦点为()120F -,,所以224a b -=. ①…………………1分因为点(2B 在椭圆C 上,所以22421a b+=. ②…………………2分由①②解得,a =2b =.…………………………………………………3分所以椭圆C 的方程为22184x y +=.………………………………………………4分 (Ⅱ)解法一:因为椭圆C 的左顶点为A ,则点A的坐标为()-.…………5分因为直线(0)y kx k =≠与椭圆22184x y +=交于两点E ,F , 设点()00,E x y (不妨设00x >),则点()00,F x y --.联立方程组22,184y kx x y =⎧⎪⎨+=⎪⎩消去y 得22812x k =+.所以0x =0y =6分所以直线AE的方程为y x =+.……………………………7分因为直线AE 与y 轴交于点M ,令0x =得y =M ⎛⎫⎝.……………………8分同理可得点N ⎛⎫ ⎝.…………………………………………………9分12假设在x 轴上存在点(,0)P t ,使得MPN ∠为直角,则0MP NP ⋅=.………10分即20t =,即240t -=.………………………11分解得2t =或2t =-.故存在点()2,0P 或()2,0P -,无论非零实数k 怎样变化,总有MPN ∠为直角. ………………………………12分 解法二: 因为椭圆C 的左端点为A ,则点A的坐标为()-.……………5分因为直线(0)y kx k =≠与椭圆22184x y +=交于两点E ,F , 设点00(,)E x y ,则点00(,)F x y --.所以直线AE的方程为y x =+.………………………………6分 因为直线AE 与y 轴交于点M ,令0x =得y =,即点M ⎛⎫ ⎝.……………………………7分同理可得点N ⎛⎫⎝.……………………………………………………8分假设在x 轴上存在点(),0P t ,使得MPN ∠为直角,则0MP NP ⋅=.即20t =,即222808y t x +=-. (※)…………9分 因为点00(,)E x y 在椭圆C 上,所以2200184x y +=,即220082x y -=.……………………………………………10分 将220082x y -=代入(※)得240t -=.………………………………………11分解得2t =或2t =-.13故存在点()2,0P 或()2,0P -,无论非零实数k 怎样变化,总有MPN ∠为直角. ………………………………12分 解法三:因为椭圆C 的左顶点为A ,则点A的坐标为()-.……………5分因为直线(0)y kx k =≠与椭圆22184x y +=交于两点E ,F ,设点(),2sin E θθ(0θ<<π),则点(),2sin F θθ--.……6分 所以直线AE的方程为y x =+.………………………7分因为直线AE 与y 轴交于点M , 令0x =得2sin cos 1y θθ=+,即点2sin 0,cos 1M θθ⎛⎫⎪+⎝⎭.………………………………8分 同理可得点2sin 0,cos 1N θθ⎛⎫⎪-⎝⎭.………………………………………………………9分假设在x 轴上存在点(,0)P t ,使得MPN ∠为直角,则0MP NP ⋅=.………10分即22sin 2sin 0cos 1cos 1t θθθθ--+⨯=+-,即240t -=.…………………………………11分解得2t =或2t =-.故存在点()2,0P 或()2,0P -,无论非零实数k 怎样变化,总有MPN ∠为直角. ………………………………12分(21)(Ⅰ)解:当1m =时,()e ln 1xf x x =--,所以1()e xf x x'=-.………………………………………………………………1分 所以(1)e 1f =-,(1)e 1f '=-. …………………………………………………2分 所以曲线()y f x =在点()()11f ,处的切线方程为(e 1)(e 1)(1)y x --=--. 即()e 1y x =-.………………………………………………………………………3分 (Ⅱ)证法一:当1m ≥时,()e ln 1e ln 1xxf x m x x =--≥--.14要证明()1f x >,只需证明e ln 20xx -->.……………………………………4分以下给出三种思路证明e ln 20xx -->.思路1:设()e ln 2xg x x =--,则1()e xg x x'=-. 设1()e xh x x =-,则21()e 0xh x x'=+>, 所以函数()h x =1()e xg x x'=-在0+∞(,)上单调递增.…………………………6分 因为121e 202g ⎛⎫'=-< ⎪⎝⎭,(1)e 10g '=->,所以函数1()e xg x x '=-在0+∞(,)上有唯一零点0x ,且01,12x ⎛⎫∈ ⎪⎝⎭.…………8分 因为0()0g x '=时,所以01ex x =,即00ln x x =-.………………………………9分 当()00,x x ∈时,()0g x '<;当()0,x x ∈+∞时,()0g x '>.所以当0x x =时,()g x 取得最小值()0g x .……………………………………10分 故()000001()=e ln 220xg x g x x x x ≥--=+->. 综上可知,当1m ≥时,()1f x >.………………………………………………12分 思路2:先证明e 1xx ≥+()x ∈R .………………………………………………5分设()e 1xh x x =--,则()e 1xh x '=-.因为当0x <时,()0h x '<,当0x >时,()0h x '>,所以当0x <时,函数()h x 单调递减,当0x >时,函数()h x 单调递增. 所以()()00h x h ≥=.所以e 1xx ≥+(当且仅当0x =时取等号).………………………………………7分所以要证明e ln 20xx -->,15只需证明()1ln 20x x +-->.……………………………………………………8分 下面证明ln 10x x --≥. 设()ln 1p x x x =--,则()111x p x x x-'=-=. 当01x <<时,()0p x '<,当1x >时,()0p x '>,所以当01x <<时,函数()p x 单调递减,当1x >时,函数()p x 单调递增. 所以()()10p x p ≥=.所以ln 10x x --≥(当且仅当1x =时取等号).………………………………10分 由于取等号的条件不同, 所以e ln 20xx -->.综上可知,当1m ≥时,()1f x >.………………………………………………12分 (若考生先放缩ln x ,或e x、ln x 同时放缩,请参考此思路给分!)思路3:先证明e ln 2xx ->.因为曲线e xy =与曲线ln y x =的图像关于直线y x =对称,设直线x t =()0t >与曲线e xy =,ln y x =分别交于点A ,B ,点A ,B 到直线y x =的距离分别为1d ,2d ,则)12AB d d =+.其中1t d =2d ()0t >.①设()e t h t t =-()0t >,则()e 1t h t '=-. 因为0t >,所以()e 10t h t '=->.所以()h t 在()0,+∞上单调递增,则()()01h t h >=.所以1t d =>16②设()ln g t t t =-()0t >,则()111t g t t t-'=-=.因为当01t <<时,()0g t '<;当1t >时,()0g t '>,所以当01t <<时,()ln g t t t =-单调递减;当1t >时,()ln g t t t =-单调递增. 所以()()11g t g ≥=.所以2d =≥所以)122AB d d +=⎭. 综上可知,当1m ≥时,()1f x >.………………………………………………12分证法二:因为()e ln 1xf x m x =--,要证明()1f x >,只需证明e ln 20xm x -->.…………………………………4分以下给出两种思路证明e ln 20xm x -->.思路1:设()e ln 2xg x m x =--,则1()e xg x m x'=-. 设1()e xh x m x =-,则21()e 0xh x m x'=+>. 所以函数()h x =()1e xg x m x'=-在()0+∞,上单调递增.……………………6分因为11221e 2e 202m m g m m m m ⎛⎫⎛⎫'=-=-< ⎪ ⎪⎝⎭⎝⎭,()1e 10g m '=->, 所以函数1()e xg x m x '=-在()0+∞,上有唯一零点0x ,且01,12x m ⎛⎫∈ ⎪⎝⎭.……8分 因为()00g x '=,所以01ex m x =,即00ln ln x x m =--.……………………9分 当()00,x x ∈时,()0g x '<;当()0,x x ∈+∞时,()0g x '>.所以当0x x =时,()g x 取得最小值()0g x .……………………………………10分17故()()000001e ln 2ln 20xg x g x m x x m x ≥=--=++->. 综上可知,当1m ≥时,()1f x >.………………………………………………12分 思路2:先证明e 1()xx x ≥+∈R ,且ln 1(0)x x x ≤+>.……………………5分设()e 1xF x x =--,则()e 1x F x '=-.因为当0x <时,()0F x '<;当0x >时,()0F x '>, 所以()F x 在(,0)-∞上单调递减,在(0,)+∞上单调递增. 所以当0x =时,()F x 取得最小值(0)0F =.所以()(0)0F x F ≥=,即e 1xx ≥+(当且仅当0x =时取等号).……………7分由e 1()xx x ≥+∈R ,得1ex x -≥(当且仅当1x =时取等号).………………8分所以ln 1(0)x x x ≤->(当且仅当1x =时取等号).……………………………9分 再证明e ln 20xm x -->.因为0x >,1m ≥,且e 1xx ≥+与ln 1x x ≤-不同时取等号,所以()()e ln 2112x m x m x x -->+---()()11m x =-+0≥.综上可知,当1m ≥时,()1f x >.………………………………………………12分(22)(Ⅰ)证明:因为AD 是⊙O 的切线,所以DAC B ∠=∠(弦切角定理).………………1分 因为DE CA ,所以DAC EDA ∠=∠.……………………………2分 所以EDA B ∠=∠.18因为AED DEB ∠=∠(公共角),所以△AED ∽△DEB .……………………………………………………………3分 所以DE AE BEDE=.即2DE AE BE = .…………………………………………………………………4分 (Ⅱ)解:因为EF 是⊙O 的切线,EAB 是⊙O 的割线,所以2EF EA EB = (切割线定理).……………………………………………5分 因为4EF =,2EA =,所以8EB =,6AB EB EA =-=.…………………7分 由(Ⅰ)知2DE AE BE = ,所以4DE =.………………………………………8分因为DE CA ,所以△BAC ∽△BED . ………………………………………9分 所以BA ACBEED=.所以6438BA ED AC BE⋅⨯===. …………………………………………………10分(23)(Ⅰ)解:由θρsin 2=,[)0,2θ∈π,可得22sin ρρθ=.…………………………………………………………………1分 因为222x y ρ=+,sin y ρθ=,…………………………………………………2分所以曲线C 的普通方程为2220x y y +-=(或()2211x y +-=). …………4分(Ⅱ)解法一:因为直线的参数方程为32x y t ⎧=+⎪⎨=-+⎪⎩(t 为参数,t ∈R ),消去t 得直线l的普通方程为5y =+. ……………………………………5分因为曲线C :()2211x y +-=是以G ()1,0为圆心,1为半径的圆,设点()00,D x y ,且点D 到直线l:5y =+的距离最短, 所以曲线C 在点D 处的切线与直线l:5y =+平行.19即直线GD 与l 的斜率的乘积等于1-,即(0011y x -⨯=-.………………7分 因为()220011x y +-=,解得02x =-或02x =. 所以点D的坐标为122⎛⎫-⎪ ⎪⎝⎭,或322⎛⎫ ⎪ ⎪⎝⎭,.……………………………………9分由于点D到直线5y =+的距离最短,所以点D 的坐标为322⎛⎫⎪ ⎪⎝⎭,.……………………………………………………10分 解法二:因为直线l的参数方程为32x y t ⎧=⎪⎨=-+⎪⎩(t 为参数,t ∈R ),消去t 得直线l50y +-=.……………………………………5分因为曲线C ()2211x y +-=是以G ()1,0为圆心,1为半径的圆,因为点D 在曲线C 上,所以可设点D ()cos ,1sin ϕϕ+[)()0,2ϕ∈π.………7分 所以点D 到直线l的距离为d =2sin 3ϕπ⎛⎫=-+ ⎪⎝⎭.………………………………8分因为[)0,2ϕ∈π,所以当6ϕπ=时,min 1d =.…………………………………9分 此时D 322⎛⎫ ⎪ ⎪⎝⎭,,所以点D 的坐标为322⎛⎫⎪ ⎪⎝⎭,.……………………………10分(24)(Ⅰ)解:当1a =时,()12f x ≥等价于112x x +-≥.……………………1分 ①当1x ≤-时,不等式化为112x x --+≥,无解;20②当10x -<<时,不等式化为112x x ++≥,解得104x -≤<; ③当0x ≥时,不等式化为112x x +-≥,解得0x ≥.…………………………3分 综上所述,不等式()1≥x f 的解集为1,4⎡⎫-+∞⎪⎢⎣⎭.………………………………4分 (Ⅱ)因为不等式()f x b ≥的解集为空集,所以()max b f x >⎡⎤⎣⎦.…………………5分以下给出两种思路求()f x 的最大值. 思路1:因为()f x x x =--()01a ≤≤,当x ≤()f x x x =-=0<.当x <时,()f x x x =2x =≤=当x ≥()f x x x ==所以()max f x ⎡⎤⎣⎦=7分思路2:因为()f x x x =+--x x ≤++==当且仅当x ≥ 所以()max f x ⎡⎤⎣⎦=7分因为对任意[]0,1a ∈,不等式()f x b ≥的解集为空集,21所以max b >.………………………………………………………8分以下给出三种思路求()g a =. 思路1:令()g a =所以()21g a =+2212≤++=.=12a =时等号成立. 所以()max g a =⎡⎤⎣⎦所以b的取值范围为)∞.…………………………………………………10分 思路2:令()g a =因为01a ≤≤,所以可设2cos a θ=02θπ⎛⎫≤≤⎪⎝⎭, 则()g a=cos sin 4θθθπ⎛⎫=+=+≤ ⎪⎝⎭, 当且仅当4θπ=时等号成立. 所以b的取值范围为)∞.…………………………………………………10分 思路3:令()g a =因为01a ≤≤,设x y ìï=ïíï=ïî则221x y +=()01,01x y ##. 问题转化为在221x y +=()01,01x y ##的条件下,求z x y =+的最大值.利用数形结合的方法容易求得z 此时2x y ==. 所以b 的取值范围为)∞.…………………………………………………10分22。
2016年广一模文综地理试题(Word版含答案)
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2016年广一模文综地理试题(Word版含答案)2016年广州市普通高中毕业班综合测试(一)文科综合(地理部分)2016,3.17第I卷本卷共35个小题,每小题4分,共140分。
在每小题给出的四个选项中,只有一项是符合题目要求的。
从“南粮北运”到“北粮南运”,中国农业经历千年形成的粮食产销格局在最近的30年间被彻底改变了。
下图为中国粮食产销格局示意图,读图完成1~3题。
1.引起“南粮北运”向“北粮南运”转变的最主要原因是A.全球气候变化B.城市化地区差异C.人口分布变化D.土地生产力差异2.影响东北地区成为我国最大商品粮基地的最主要原因是A.人均耕地多B.高速铁路的建设C.全球变暖、热量条件改善D.新品种、新技术广泛应用3.当前,制约“北粮南运”的最主要因素是A.气候条件B.铁路运输C.生产水平D.市场需求一对英国夫妇1月3日从佛得角群岛(约17°N,23°W)出发,驾驶游艇前往安提瓜岛(约17°02'N,61°50'W),如下图所示。
1月9日航程近半时,游艇发生动力故障,只能随水漂流,30天后在M地被救起。
运用所学知识,完成4~6题:4.佛得角群岛上的植被主要是A.热带雨林B.常绿硬叶林C.热带荒漠D.热带季雨林5.出发地与计划目的地之间的最短距离约为A.2100公里B.4100公里C.6100公里D.8100公里6.M地最可能位于A.安提瓜岛B.亚马孙河口C.直布罗陀海峡D.百慕大群岛下图为2010年上海人口年龄结构示意图,读图完成7~9题。
7.上海流人人口比例最大的年龄段是A.20~24岁B.25~29岁C.30~34岁D.35~39岁8.上海是我国人口老龄化程度下降最快的城市之一,主要原因是A.出生率大幅下降B.死亡率迅速上升C.大量年轻劳力流入D.大量老龄人口迁出9.目前上海市流动人口正处在A.劳动力个体流动阶段B.老人跟着孩子流动阶段C.夫妻带着孩子流动阶段D.农村流动人口回流阶段下图是北德维纳河流域示意图,该流域的地形是宽阔的、多丘陵的平原,据此完成10~11题。
广州市南沙区2016届中考一模数学试题含答案(WORD版)
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2016年初中毕业班综合测试(一)数 学本试卷分选择题和非选择题两部分,共三大题25小题,满分150分.考试用时120分钟. 注意事项:1.答卷前,考生务必在答题卡第1面、第3面、第5面上用黑色字迹的钢笔或签字笔填写自己的考生号、姓名;填写考场试室号、座位号,再用2B 铅笔把对应这两个号码的标号涂黑.2.选择题每小题选出答案后,用2B 铅笔把答题卡上对应题目的答案标号涂黑;如需改动,用橡皮擦干净后,再选涂其他答案标号;不能答在试卷上.3.非选择题必须用黑色字迹的钢笔或签字笔作答,涉及作图的题目,用2B 铅笔画图.答 案必须写在答题卡各题指定区域内的相应位置上;如需改动,先划掉原来的答案,然后再写上新的答案;改动的答案也不能超出指定的区域.不准使用铅笔、圆珠笔和涂改液.不按以上要求作答的答案无效。
4.考生必须保持答题卡的整洁,考试结束后,将本试卷和答题卡一并交回.第一部分 选择题(共30分)一、选择题(本大题共10小题,每小题3分,满分30分.在每小题给出的四个选项中只有一项是符合题目要求的)1.在﹣2,1,5,0这四个数中,最大的数是(*) A .﹣2 B .1 C .5 D .0 2.下列计算正确的是(*)A .222)(b a b a +=+B .22)(ab ab =C .523)(a a =D .32a a a =⋅3.下列图形中,既是轴对称图形又是中心对称图形的是(*)4.如图,已知)3,1(A ,将线段OA 绕原点O 顺时针旋转90后得到'OA ,则'OA 的长度是(*) A .10 B .3 C .22 D .15.如图,一个透明的玻璃正方体表面嵌有一根黑色的铁丝,这根铁丝在正方体俯视图中的ABCD第8题图形状是(*).A. B .C . D6.如图所示,三角形纸片中,有一个角为60,剪去这个角后,得到一个四边形,则21∠+∠的度数为(*)A.120 B.180 C. 240D.3007.已知点)2,1(+-a a P 在平面直角坐标系的第二象限内,则a 的取值范围在数轴上可表示为(阴影部分)(*)8.如图,在△ABC 中,已知B ADE ∠=∠,则下列等式成立的是(*)A .AD AE = B .AD AE = C .DE AE = D .DE AD= 10.在平面直角坐标系中,第一个正方形ABCD 的位置如图所示,点A 的坐标为(2,0),点D 的坐标为(0,4).延长CB 交x 轴于点A 1,作第二个正方形A 1B 1C 1C ;延长C 1B 1交xA B C D 第4题图第9题图60°21第6题图轴于点A 2,作第三个正方形A 2B 2C 2C 1,…,按这样的规律进行下去,第2016个正方形的面积为(*)A.40302320⎪⎭⎫ ⎝⎛⨯ B.40322320⎪⎭⎫⎝⎛⨯C.20162320⎪⎭⎫⎝⎛⨯ D.20152320⎪⎭⎫⎝⎛⨯第二部分 非选择题(共120分)二、填空题(本大题共6小题,每小题3分,满分18分.)11.地球上的海洋面积约为2361 000 000km ,则科学记数法可表示为 * 2km ;12.如图,在菱形ABCD 中,30=∠BAC ,则B ∠= * 度。
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16中2015学年第二学期初三质量调研检测(二)英语试题一、语法选择(共15小题;每小题1分,满分15分)Have you ever looked at someone and wondered what is going on inside his or her head? Disney Pixar‟s new movie Inside Out __1__ you there to find out!The movie is mainly about Riley, 11, __2__ has just moved to a new city __3__ started a new school. Inside her mind, __4__ known as “headquarters,” there is a control center. There, five emotions—Joy, Fear, Anger, Disgust, and Sadness—are hard at __5__ . Joy‟s task is to make sure Riley stays happy. Fear controls safety. __6__ Riley is trying to get along with her new environment, Joy and Fear suddenly __7__ into the back of Riley‟s mind. That leaves __8__ three to work and brings about a lot of funny things.Director Pete Docter, who won an Oscar(奥斯卡奖)__9__ his film Up, says the idea came to him while __10__ his own kids turn into teenagers. His daughter, Ellie, who was the voice of young Ellie in Up, was __11__ energetic kid. But she started to become more __12__ as she grew up. “Young kids are __13__ of energy and then they get a little older and get a little quiet and shy,” Docter said. “I thought …What‟s going on inside __14__ heads?‟ That is __15__ leads to this film.”1. A. takes B. take C. taking D. took2. A. which B. that C. who D. what3. A. so B. and C. but D. if4. A. either B. neither C. also D. too5. A. works B. work C. worked D. to work6. A. while B. if C. before D. after7. A. put B. are put C. is put D. are putting8. A. another B. other C. others D. the other9. A. for B. of C. in D. to10. A. watch B. watched C. watching D. are watching11. A. a B. an C. the D. /12. A. silent B. silently C. silence D. silenced13. A. fill B. filled C. full D. fully14. A. your B. our C. his D. their15. A. what B. how C. when D. why二、完形填空(共10小题;每小题1.5分,满分15分)There were once two doors in the same house. One was a beautiful living-room door, and the other was just a/an__16__ bathroom door.They both had terrible lives. The house was full of __17__ children who were always slamming(摔门)and kicking the doors. Each night, when everyone was asleep, the doors would talk about their poor __18__. The living-room door was always ready to shout with anger, but the bathroom door would calm him down, saying, “Don‟t worry. They‟re children. They‟ll soon learn. Be patient and things will __19__.”And so the living-room door would calm down for a while. But one day, after a big party and much slamming and kicking of the doors, the living-room door __20__ lost his temper, saying, “That‟s enough! The next time someone slams me, I‟m going to __21__, and they‟ll learn how important I am.”The next day, the first time he was slammed, the living-room door broke. This caused great __22__ in the house, and the children were punished. But after a few days, the house owners didn‟t want to have a broken door. Instead of __23__ it, they decided to buy a new one. The old door was thrown into the rubbish.By then the beautiful living-room door regretted what he had done. For not being __24__enough, he was now abandoned(抛弃), waiting to be turned into firewood. Meanwhile, his friend, the ordinary bathroom door, remained in his place, and the children were treating him with greater __25__.16. A. new B. heavy C. ordinary D. silent17. A. naughty B. curious C. nervous D. polite18. A. dream B. appearance C. house D. luck19. A. matter B. improve C. repeat D. suffer20. A. seldom B. fortunately C. happily D. finally21. A. break B. teach C. work D. shout22. A. joy B. benefit C. trouble D. doubt23. A. selling B. repairing C. painting D. finding24. A. beautiful B. careful C. patient D. friendly25. A. force B. anger C. peace D. care三、阅读(满分45分)第一节阅读理解(共20小题;每小题2分,满分40分)阅读下面短文,从每题所给的A、B、C和D项中,选出最佳选项并在答题卡上将该项涂黑。
AHere is something about an American high school and its students.An American high school has a few large buildings and it‟s big enough for about 1,500 students. Each student has a locker(储物柜)in the classroom. When they are at school, they get their textbooks and outdoor clothes out. Because American textbooks are expensive, the school libraries usually loan them to students. But they must pay for them if they lose them.American students usually take a yellow school bus to school. Sometimes their parents drive them to school. When they are 16, most of them take a free driving class at school. Then they can drive by themselves to school.Each day, students must take science, math and English classes. They can also choose(选择)art, fashion and other classes. They usually go to different classrooms for one subject because the teachers have their own classrooms.The school day usually ends early in the afternoon. After school, more than half of the students take after-school activities such as sports and some school clubs.26. Where is the locker of a student?A. In his/ her home.B. In his/ her classroom.C. In his/ her bedroom.D. In the school library.27. What color is the school bus in America?A. YellowB. RedC. WhiteD. Blue28. What does the underlined word “loan” mean in English?A. BuyB. PushC. FollowD. Lend29. Which of the follow is TRUE about American high school students?A. They have all the classes in the same classroom.B. Students must pay for textbooks if they lose them.C. A small number of them love after-class activities.D. All of them take a school bus to school every day.30. The passage mainly talks about_______.A. an American high schoolB. school clubsC. a class activityD. education in AmericaBMany parents display their children‟s artwork on the refrigerator, but Kieron Williamson‟s paintings have been on display in professional galleries since he was 6 years old.Kieron‟s artwork, though, extends far beyond child-like stick figures or finger painting. In fact, the child from Norfolk, England, ha s been called “the boy who paints like an old master.”According to his parents, Kieron was a typical toddler(初学走路的孩子)who like finding bugs and playing in the mud. But on a 2008 family vacation to the beach, the 5-year-old kid was inspired by the boats and scenery and asked his parents for a sketch pad(速写本). His first drawings could have been done by any young child, but after the family returned home, Kieron continued drawing and began to display a gift for art.When he started asking about the process of putting a painting together, his parents realized he needed professional instruction. Soon after, he began taking lessons, and his progress amazed everyone as the young boy produced impressive landscapes(风景)and watercolors.In 2009, when the 6-year-old child had a chance to exhibit his work in a gallery, he sold 19 paintings for 14,000 pounds, becoming famous overnight. From then on, he was surrounded by buyers from France, Japan, Greece and other countries. Theyoung artist held another exhibit three months after the first one and sold 16 paintings for over 17,000 pounds, followed by a third sale, earning 150,000 pounds. For the fourth exhibit, Kieron took the day off from school but ended up returning to school early. His entire collection had sold out in 10 minutes to collectors from around the world. Now he has a waiting list of more than 5,000 people who have ordered his paintings.He has appeared in interviews before millions, and he has been compared to Pablo Picasso. Yet Kieron doesn‟t seem to be fazed by all the attention, still making time for football and maintaining excellent grades at school.He does have one goal he gets excited about: “I‟d like the Queen to have a collection of my work.” With his popularity climbing, this young artist may realize his wish one day.31. According to the passage, which of the following statements is TRUE?A. Kieron‟s paintings are just as childish as other children‟s.B. Kieron‟s first drawings suggested that he would be an art master.C. Kieron became much better from professional instruction.D. Before displaying a gift for art, Kieron received professional training.32. Paragraph 5 is mainly intended to tell us ____________.A. the four exhibits of his paintingsB. the process of his wealth accumulationC. the high quality of his paintingsD. the increasing popularity of his paintings33. Why did Kieron go back to school early on the day of his fourth exhibit?A. Because his mind was focused on study.B. Because the exhibit was put off.C. Because he wanted to gain praise from teachers.D. Because his paintings were sold out earlier than expected.34. The underlined word “fazed” in Paragraph 6 probably means _____.A. frustratedB. affectedC. encouragedD. defeated35. What can be inferred from the last paragraph?A. Kieron respects and admires the Queen very much.B. Kieron likes to earn money from the Queen.C. Kieron is sure he will realize his dream.D. Kieron‟s goal is unlikely to come true.CKidZui is a new browser(浏览器)and online service that lets kids aged 3 to 12 explore more than 500,000 websites, pictures and videos. The idea for KidZui came about when one of the founders, Vidar Vignission, saw how difficult it was for his children to enjoy the power and promise of the Internet in a safe way. Together with Cliff Boro and Thomas Broadhead, they decided to do something.KidZui was first tested by 8,000 kids and their parents. Lisa Rebena, a parent whose child tested KidZui, said, “My 4-year-old daughter gets into KidZui, reads news and watches videos all by herself, generally doing what she pleases, I‟m much more relaxed now when my daughter is on the computer.”Content(内容)in KidZui has been reviewed by a team of more than 200 trained teachers and parents. They make sure that kids see content that is proper for their age in terms of developmental level and reading ability. New websites, pictures and videos are added to KidZui every day. When a young user tries to watch a video outside of KidZui, it will be reviewed and, if proper, added—often within a matter of hours.Besides, parents can change the content available, add and take out some websites and see what their kids are viewing online. And KidZui sends out a weekly report of their kids‟ recent searches and interests so that parents can plan family activities around their kid‟s interests. After a 30-day free trial(试用)period, parents who sign up can take advantage of our special rates of $4.95 per month or $49.95 per year, a 50 percent discount(折扣)from standard rates of $9.95 per month or $99.95 per year.36. According to the text, KidZui ______.A. is mainly designed for teenagersB. offers children 500,000 websitesC. helps children surf the Internet safelyD. is thought to be unimportant by Vidar Vignisson37. What is Lisa Rebena‟s attitude towards KidZui?A. She has high hopes for it.B. She has doubts about it.C. She considers it useless.D. She is not interested in it.38. KidZui allows parents to ______.A. teach their kids to add videosB. watch some of the videos it providesC. use the browser for free for half a monthD. keep in touch with their kids‟ online activities39. How much can you save a year if you sign up for KidZui?A. $5B.$45C. $50D. $9040. How many founders are there on this new browser and online service?A. 4B. 3C. 5D. 6DWhen you got up this morning, your Mom probably asked you to make your bed and put your dirty dishes in the sink(洗碗池), but did she tell you to take care of the goats? Tha t‟s just what Emery Jonas, 13, and his brother Greyden, 10, were asked to do! The brothers help out on the family farm in Indiana by caring for 41 goats and making soap from their milk.Emery and Greyden have worked with them every day for four years and were even there when many of them were born.After waking up, Emery and Greyden lead the goats into the milking room and provide them with whole oats(全麦). After milking the goats, they take them out and feed them with alfalfa pellets(颗粒饲料).“A lot of people use grains or mixtures of grains,” said Emery. “We don‟t do that because in a lot of the grains, there is molasses(糖蜜)to hold it all together, and Mom says too much molasses is not good for the goats.”Caring for the goats every day may seem like a huge c hore, but Emery said, “Raising goats is much easier than other things. You can train them to do a lot of things. As I did - I trained them to open doors.”“They just grab it with their teeth and use their tongues to open it,” Greyden said.Of the 41 goats that Emery and Greyden care for, 16 are babies.“All the babies this year were born while I was there, so they‟ve known me just about all their lives,” Emery said. “With the babies, Greyden is the mommy because he does everything for them. He feeds them, lets them out into the woods and does all the stuff that they need.”41. The main purpose of the first paragraph is to _____.A. introduce the topicB. question the readersC. describe the author‟s lifeD. compare different kids‟ life42. Emery and Greyden lead the goats into the milking room to _____.A. feed the baby goatsB. feed them with milkC. draw milk from themD. clean them with soap43. Emery and Greyden think caring for the goats every day is actually _____.A. pretty funB. quite hardC. rather boringD. very dangerous44. According to Emery, which of the following best describes Greyden?A. Wise.B. Honest.C. Generous.D. Responsible45. Which of the following is TRUE?A. Greyden‟s mother asked him to make his bed when he got up in the morning.B. When Greyden was eight, he started to do the job of taking care of the goats.C. Greyden trained his goats to open doors by their feet.D. Greyden made every effort to attend the baby goats.第二节阅读填空(共5小题;每小题1分,满分5分)Hi, everyone! I am Paul Hawking, the trip leader for this weekend‟s activity.It‟s that time of the year again when the days are long and it is nice to sit outside and enjoy some oysters(牡蛎). We plan to head out to the Mission Bay this Sunday for a beach picnic. 46._____ and you just need to pay $6 to $l0 foreach dozen, depending on the size. It‟s on Sunday, June 30.47._____The driving time is one and a half to two hours, and the time of return is still uncertain. 48._____The oyster farm has a small picnic area with chairs and barbecue grills (烧烤架). Bring some briquettes (煤球) if you like to grill. Except for oysters, oysters and oysters, little is available there. 49._____ And of course, if you have any special oyster recipes (食谱), bring them, make them and share them! The weather forecast says it's going to sunny and around 26C this weekend. My telephone number is 4088963228.50._____ Remember to finish your homework before we leave for the picnic.A. We will meet at the Student Center at 9:00 a.m. and all go together.B. Come and join us in what must now be the 4th or 5th such trip for the Outing Club.C. Please feel free to call me if you have any questions.D. So please bring your own food and drinks.E. You can buy fresh oysters at the Mission Bay Oyster Company四、写作(共三节,满分35分)第一节单词拼写(共6小题;每小题1分,满分6分)51. Now, the most important thing you need to think about is how to s__________ the problem.52. His wonderful speech received a lot of applause from the a__________.53. I taught disabled children to sing because music can bring them j__________ and peace.54. Nowadays, more and more Chinese students go to study in f___________ country.55. Many wild animals are in danger. They should not be on our m ___________. We mustn't eat them.56. I can h___________ understand what you said. Would you please repeat it?第二节完成句子(共7小题;每小题2分,满分14分)57. 第一次见面要给人留下好印象,关键是什么呢?What‟s the ___________ ___________ ___________a good ____________ on others when you first meet them?58. 他们建造了一家外形像一艘帆船的七星级酒店。