【电子科技大学】2015下数字逻辑设计(作业题)Chapter 4 Exercise Solutions(对应老教材第3章题号)
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Chapter 4
【以下为老版教材(John F. Wakerly著)的题号】
3.1 The Stub Series Terminated low Voltage logic (SSTV) family, used for SDRAM modules, defines a LOW signal to be in the range 0.0~0.7V, and a HIGH signal to be in the range 1.7~2.5V. Under a positive-logic convention, indicate the logic value associated with each of the following signal levels:
(a) 0.0V (b) 0.7V (c) 1.7V (d) -0.6V
(e) 1.6V (f) -2.0V (g) 2.5V (h) 3.3V
(a) 0 (b) 0 (c) 1 (d) undefined
(e) undefined (f) undefined (g) 1 (h) undefined
3.2 Repeat exercise 3.1 using a negative-logic convention.
(a) 1 (b) 1 (c) 0 (d) undefined
(e) undefined (f) undefined (g) 0 (h) undefined
3.5 True or false: For a given set of input values, a NAND gate produces the opposite output as a NOR gate.
When the two inputs are different, it will be ture.
3.9 For a given silicon area, which is likely to be faster, a CMOS NAND gate or a CMOS NOR?
CMOS NAND will be faster than CMOS NOR.
3.11 The circuit in Figure 3-1 is a type of CMOS AND-OR-INVERT gate. Try to wirte its logic expression and draw its logic diagram using the method Mr. yuan told you with AND and OR gates and inverters.
Figure 3-1
A B C D Z 0 X 0 0 1 X 0 0 0 1 -- -- -- -- 0
∵ A • B = 0 且 (C + D) = 0 即 A • B + (C + D) = 0 ∴ Logic expression: Z = ( A • B + C + D )’
Logic diagram:
3.16 Which has fewer transistors, a CMOS inverting gate or a noninverting gate?
CMOS inverting gate has fewer transistors.
3.21 How much high-state DC noise margin is available in an inverter whose transfer characteristic under worst-case conditions is shown in Figure 3-2? How much low-state DC noise margin is available? Assume 1.5V and 3.5V thresholds for LOW and HIGH. (Hints : The thresholds voltage means a input voltage. That is to say: V ILmax =1.5V ,V IHmin =3.5V )
Figure 3-2
从图中可以看出,在输入为0~1.5V 的有效低态范围内,输出的高态范围为4.75~5V ,即V OHmin =4.75V ,在输入为3.5V~5V 的有效高态范围内,输出的低态范围为0~0.25V ,即V OLmax =0.25V 。
High-state DC noise margin = V OHmin - V IHmin = 4.75 - 3.5 = 1.25 (V)
Low-state DC noise margin = V ILmax - V OLmax = 1.5 - 0.25 = 1.25 (V)
(C + D) A • B 且
3.27 For each of the following resistive loads, determine whether the output drive specifications of the 74HC00 over the commercial operating range are exceeded (use V OLmax = 0.33V ,V OHmin = 3.84V and V CC = 5.0 V). You may not exceed I OLmax (4mA) or I OHmax (4mA) in any state.
(d) 470 Ω to V CC and 470 Ω to GND (f) 1.2k Ω to V CC and 820 Ω to GND
(d) V Thev = Vcc ×R2 / (R1+R2)
= 5 / 2 = 2.5V
I Short = Vcc / R1 R Thev = V Thev / I Short = R1×R2 / (R1+R2) = 470 / 2
= 235 Ω
∵V OHmin = 3.84V ∴ I OH = (V OHmin -V Thev
Thev OHmax ∵V OLmax = 0.33V ∴ I OL = (V Thev - V OLmax ) / R Thev ≈ 9.2 mA
> I OLmax = 4 mA 因此,超出了商用工作范围,不能驱动负载。
(f) V Thev = Vcc ×R2 / (R1+R2)
= 5×820 / (1200+820)
≈ 2.03V I Short = Vcc / R1
R Thev = V Thev / I Short = R1×R2 / (R1+R2)
= 1200×820 / (1200+820)
≈ 487.13 Ω
∵V OHmin = 3.84V ∴ I OH = (V OHmin -V Thev ) / R Thev ≈ 3.7 mA < I OHmax = 4 mA ∵V OLmax = 0.33V ∴ I OL = (V Thev - V OLmax ) / R Thev ≈ 3.5 mA < I OLmax = 4 mA 因此,没有超出商用工作范围,可以正常驱动负载。
3.37 A particular Schmitt-trigger inverter has V ILmax = 0.8 V, V IHmin = 2.0 V, V T+ =1.7 V, and V T - = 1.2 V. How much hysteresis does it have?
Hysteresis = V T+ - V T - = 1.7-1.2 = 0.5V
3.39 Discuss the pros and cons of larger versus smaller pull-up resistors for open-drain CMOS outputs.
较小的上拉电阻:优点是输出电平在上升时较快,使得其工作运行的速度较快;缺点是在输出低电平时电源对地的电流较大,使得其功耗较大。
较大的上拉电阻:优点是在输出低电平时电源对地的电流较小,使得其功耗较小;缺点是输出电平在上升时较慢,使得其工作运行的速度较慢。
3.47 How many diodes are required for an n -input diode AND gate?
n diodes are required.